id stringlengths 25 25 | question stringlengths 45 1.01k | chain stringlengths 75 4.11k | result stringclasses 5 values | result_float float64 -4,212 100B | question_without_options stringlengths 6 962 | options dict | annotated_formula stringlengths 7 6.48k | linear_formula stringlengths 8 925 | rationale stringlengths 1 2.74k | category stringclasses 6 values |
|---|---|---|---|---|---|---|---|---|---|---|
math_qa__WksOKCHthgXZULO8 | Sandy walked 20 meters towards south. Then Sandy turned to her left and walked 20 meters. She then turned to her left and walked 20 meters. She then turned to her right and walked 10 meters. What distance is she from the starting point and in which direction?
Pick one
A) 35 m east B) 35 m north C) 30 m west D) 45 m west E) 30 m east | <gadget id="calculator">20 + 10</gadget>
<output>30</output>
<result>E</result> | E | 30 | Sandy walked 20 meters towards south. Then Sandy turned to her left and walked 20 meters. She then turned to her left and walked 20 meters. She then turned to her right and walked 10 meters. What distance is she from the starting point and in which direction? | {
"A": "35 m east",
"B": "35 m north",
"C": "30 m west",
"D": "45 m west",
"E": "30 m east"
} | add(20, 10) | add(n0,n3)| | "the net distance is 20 + 10 = 30 meters to the east . the answer is e ." | physics |
math_qa__V4XMXLp4mC7SHChh | Income and expenditure of a person are in the ratio 3 : 2. If the income of the person is Rs. 21000, then find his savings? Choose the correct choice from the following answers: A) 6000 B) 7000 C) 8000 D) 9000 E) 10000 | <gadget id="calculator">2 / 3</gadget>
<output>2/3 = around 0.666667</output>
<gadget id="calculator">(2/3) * 21_000</gadget>
<output>14_000</output>
<gadget id="calculator">21_000 - 14_000</gadget>
<output>7_000</output>
<result>B</result> | B | 7,000 | Income and expenditure of a person are in the ratio 3 : 2. If the income of the person is Rs. 21000, then find his savings? | {
"A": "6000",
"B": "7000",
"C": "8000",
"D": "9000",
"E": "10000"
} | subtract(21000, multiply(divide(2, 3), 21000)) | divide(n1,n0)|multiply(n2,#0)|subtract(n2,#1) | let the income and the expenditure of the person be rs . 3 x and rs . 2 x respectively . income , 3 x = 21000 = > x = 7000 savings = income - expenditure = 3 x - 2 x = x so , savings = rs . 7000 . answer : b | other |
math_qa__czTg25yNbnmxuCJ6 | In how many ways 4 boys and 3 girls can be seated in a row so that they are alternate.
Choose the correct choice from the following choices: A) 144 B) 288 C) 12 D) 256 E) none | <gadget id="calculator">factorial(4)</gadget>
<output>24</output>
<gadget id="calculator">factorial(3)</gadget>
<output>6</output>
<gadget id="calculator">24 * 6</gadget>
<output>144</output>
<result>A</result> | A | 144 | In how many ways 4 boys and 3 girls can be seated in a row so that they are alternate. | {
"A": "144",
"B": "288",
"C": "12",
"D": "256",
"E": "none"
} | multiply(factorial(4), factorial(3)) | factorial(n0)|factorial(n1)|multiply(#0,#1)| | "solution : let the arrangement be , b g b g b g b 4 boys can be seated in 4 ! ways . girl can be seated in 3 ! ways . required number of ways , = 4 ! * 3 ! = 144 . answer : option a" | probability |
math_qa__K2WZWnbGCEpf8egC | The ratio of the radius of two circles is 4: 3, and then the ratio of their areas is? Select the correct option:
A) 1 : 8 B) 1 : 6 C) 1 : 9 D) 16 : 9 E) 1 : 2 | <gadget id="calculator">pi * (4 ** 2)</gadget>
<output>16*pi = around 50.265482</output>
<gadget id="calculator">pi * (3 ** 2)</gadget>
<output>9*pi = around 28.274334</output>
<gadget id="calculator">(16*pi) / (9*pi)</gadget>
<output>16/9 = around 1.777778</output>
<result>D</result> | D | 1.777778 | The ratio of the radius of two circles is 4: 3, and then the ratio of their areas is? | {
"A": "1 : 8",
"B": "1 : 6",
"C": "1 : 9",
"D": "16 : 9",
"E": "1 : 2"
} | divide(circle_area(4), circle_area(3)) | circle_area(n0)|circle_area(n1)|divide(#0,#1)| | "r 1 : r 2 = 4 : 3 π r 12 : π r 22 r 12 : r 22 = 16 : 9 answer : d" | geometry |
math_qa__W4dGLVbenmGGQnpB | In a Function, every person shakes hand with every other person. If there was a total of 28 handshakes in the function, how many persons were present in the Function? Choose the correct option: A) 8 B) 7 C) 2 D) 6 E) 5 | <gadget id="calculator">28 - 10</gadget>
<output>18</output>
<gadget id="calculator">18 - 10</gadget>
<output>8</output>
<result>A</result> | A | 8 | In a Function, every person shakes hand with every other person. If there was a total of 28 handshakes in the function, how many persons were present in the Function? | {
"A": "8",
"B": "7",
"C": "2",
"D": "6",
"E": "5"
} | subtract(subtract(28, const_10), const_10) | subtract(n0,const_10)|subtract(#0,const_10) | suppose there are nn persons present in a function and every person shakes hand with every other person . then , total number of handshakes = nc 2 = n ( n − 1 ) / 2 n ( n − 1 ) = 28 × 2 n ( n − 1 ) = 56 n = 8 answer a 8 | general |
math_qa__S3FbSEj3p6zIl5V8 | 3*16 + 3*17 + 3*20 + 11 = ? Pick one: A) 121 B) 129 C) 138 D) 152 E) 170 | <gadget id="calculator">3 * 16</gadget>
<output>48</output>
<gadget id="calculator">3 * 17</gadget>
<output>51</output>
<gadget id="calculator">48 + 51</gadget>
<output>99</output>
<gadget id="calculator">3 * 20</gadget>
<output>60</output>
<gadget id="calculator">99 + 60</gadget>
<output>159</output>
<gadget id="calculator">159 + 11</gadget>
<output>170</output>
<result>E</result> | E | 170 | 3*16 + 3*17 + 3*20 + 11 = ? | {
"A": "121",
"B": "129",
"C": "138",
"D": "152",
"E": "170"
} | add(add(add(multiply(3, 16), multiply(3, 17)), multiply(3, 20)), 11) | multiply(n0,n1)|multiply(n0,n3)|multiply(n0,n5)|add(#0,#1)|add(#3,#2)|add(n6,#4)| | "3 * 16 + 3 * 17 + 3 * 20 + 11 = 48 + 51 + 60 + 11 = 170 the answer is e ." | general |
math_qa__yhJGrWgLhxz8a7Pe | If x = -2 and y = -4, what is the value of 5(x-y)^2 - xy ? Choose the correct choice from the following options.
A) 12
B) 13
C) 15
D) 18
E) 22 | <gadget id="calculator">-2</gadget>
<output>-2</output>
<gadget id="calculator">-4</gadget>
<output>-4</output>
<gadget id="calculator">(-2) - (-4)</gadget>
<output>2</output>
<gadget id="calculator">2 ** 2</gadget>
<output>4</output>
<gadget id="calculator">4 * 5</gadget>
<output>20</output>
<gadget id="calculator">(-2) * (-4)</gadget>
<output>8</output>
<gadget id="calculator">20 - 8</gadget>
<output>12</output>
<result>A</result> | A | 12 | If x = -2 and y = -4, what is the value of 5(x-y)^2 - xy ? | {
"A": "12",
"B": "13",
"C": "15",
"D": "18",
"E": "22"
} | subtract(multiply(power(subtract(negate(2), negate(4)), 2), 5), multiply(negate(2), negate(4))) | negate(n0)|negate(n1)|multiply(#0,#1)|subtract(#0,#1)|power(#3,n3)|multiply(n2,#4)|subtract(#5,#2)| | "x = - 2 and y = - 4 x - y = - 2 - ( - 4 ) = - 2 + 4 = 2 x * y = - 2 * - 4 = 8 now we apply it in the equation 5 ( x - y ) ^ 2 - xy = 5 ( 2 ) ^ 2 - 8 = = > 5 * 4 - 8 = 20 - 8 = 12 answer : a" | general |
math_qa__I1Ij55P8T76rrm06 | A library has an average of 660 visitors on Sundays and 240 on other days. The average number of visitors per day in a month of 30 days beginning with a Sunday is: Choose the correct choice from the following choices.
A) 250 B) 276 C) 280 D) 310 E) none | <gadget id="calculator">3 + 4</gadget>
<output>7</output>
<gadget id="calculator">30 / 7</gadget>
<output>30/7 = around 4.285714</output>
<gadget id="calculator">floor(30/7)</gadget>
<output>4</output>
<gadget id="calculator">4 + 1</gadget>
<output>5</output>
<gadget id="calculator">5 * 660</gadget>
<output>3_300</output>
<gadget id="calculator">30 - 5</gadget>
<output>25</output>
<gadget id="calculator">25 * 240</gadget>
<output>6_000</output>
<gadget id="calculator">3_300 + 6_000</gadget>
<output>9_300</output>
<gadget id="calculator">9_300 / 30</gadget>
<output>310</output>
<result>D</result> | D | 310 | A library has an average of 660 visitors on Sundays and 240 on other days. The average number of visitors per day in a month of 30 days beginning with a Sunday is: | {
"A": "250",
"B": "276",
"C": "280",
"D": "310",
"E": "none"
} | divide(add(multiply(add(floor(divide(30, add(const_3, const_4))), const_1), 660), multiply(subtract(30, add(floor(divide(30, add(const_3, const_4))), const_1)), 240)), 30) | add(const_3,const_4)|divide(n2,#0)|floor(#1)|add(#2,const_1)|multiply(n0,#3)|subtract(n2,#3)|multiply(n1,#5)|add(#4,#6)|divide(#7,n2)| | "since the month begins with sunday , to there will be five sundays in the month average required = ( 660 x 5 + 240 x 25 ) / 30 ) = 310 answer : option d" | general |
math_qa__Wn7xQZLE4G6IShJY | At the faculty of Aerospace Engineering, 312 students study Random-processing methods, 232 students study Scramjet rocket engines and 114 students study them both. If every student in the faculty has to study one of the two subjects, how many students are there in the faculty of Aerospace Engineering? Choose the most appropriate option
A) 438 B) 436 C) 430 D) 442 E) 444 | <gadget id="calculator">114 / 2</gadget>
<output>57</output>
<gadget id="calculator">312 - 57</gadget>
<output>255</output>
<gadget id="calculator">232 - 57</gadget>
<output>175</output>
<gadget id="calculator">255 + 175</gadget>
<output>430</output>
<result>C</result> | C | 430 | At the faculty of Aerospace Engineering, 312 students study Random-processing methods, 232 students study Scramjet rocket engines and 114 students study them both. If every student in the faculty has to study one of the two subjects, how many students are there in the faculty of Aerospace Engineering? | {
"A": "438",
"B": "436",
"C": "430",
"D": "442",
"E": "444"
} | add(subtract(312, divide(114, const_2)), subtract(232, divide(114, const_2))) | divide(n2,const_2)|subtract(n0,#0)|subtract(n1,#0)|add(#1,#2) | 312 + 232 - 114 ( since 112 is counted twice ) = 430 c is the answer | other |
math_qa__Suk5K6O0D1r3Jqgn | Two boats are heading towards each other at constant speeds of 5 miles/hr and 25 miles/hr respectively. They begin at a distance 20 miles from each other. How far are they (in miles) one minute before they collide ? Choose the correct choice from the following options: A) 1 / 12 B) 5 / 12 C) 1 / 6 D) 1 / 2 E) 1 / 5 | <gadget id="calculator">25 + 5</gadget>
<output>30</output>
<gadget id="calculator">30 / 60</gadget>
<output>1/2 = around 0.5</output>
<result>D</result> | D | 0.5 | Two boats are heading towards each other at constant speeds of 5 miles/hr and 25 miles/hr respectively. They begin at a distance 20 miles from each other. How far are they (in miles) one minute before they collide ? | {
"A": "1 / 12",
"B": "5 / 12",
"C": "1 / 6",
"D": "1 / 2",
"E": "1 / 5"
} | divide(add(25, 5), const_60) | add(n0,n1)|divide(#0,const_60)| | "the question asks : how far apart will they be 1 minute = 1 / 60 hours before they collide ? since the combined rate of the boats is 5 + 25 = 30 mph then 1 / 60 hours before they collide they ' ll be rate * time = distance - - > 30 * 1 / 60 = 1 / 2 miles apart . answer : d ." | physics |
math_qa__Rd612yeHiB6ogpqh | Excluding stoppages, the speed of a train is 45 kmph and including stoppages it is 32 kmph. Of how many minutes does the train stop per hour? Choose the correct choice from the following:
A) 17 B) 83 C) 12 D) 83 E) 28 | <gadget id="calculator">32 / 45</gadget>
<output>32/45 = around 0.711111</output>
<gadget id="calculator">60 * (32/45)</gadget>
<output>128/3 = around 42.666667</output>
<gadget id="calculator">60 - (128/3)</gadget>
<output>52/3 = around 17.333333</output>
<result>A</result> | A | 17 | Excluding stoppages, the speed of a train is 45 kmph and including stoppages it is 32 kmph. Of how many minutes does the train stop per hour? | {
"A": "17",
"B": "83",
"C": "12",
"D": "83",
"E": "28"
} | subtract(const_60, multiply(const_60, divide(32, 45))) | divide(n1,n0)|multiply(#0,const_60)|subtract(const_60,#1)| | "explanation : t = 13 / 45 * 60 = 17 answer : option a" | physics |
math_qa__69Qrs2TmCQdXqn1i | A and B together can do a piece of work in 8 days. If A alone can do the same work in 12 days, then B alone can do the same work in? Choices
A) 49 B) 99 C) 24 D) 88 E) 21 | <gadget id="calculator">1 / 8</gadget>
<output>1/8 = around 0.125</output>
<gadget id="calculator">1 / 12</gadget>
<output>1/12 = around 0.083333</output>
<gadget id="calculator">(1/8) - (1/12)</gadget>
<output>1/24 = around 0.041667</output>
<gadget id="calculator">1 / (1/24)</gadget>
<output>24</output>
<result>C</result> | C | 24 | A and B together can do a piece of work in 8 days. If A alone can do the same work in 12 days, then B alone can do the same work in? | {
"A": "49",
"B": "99",
"C": "24",
"D": "88",
"E": "21"
} | inverse(subtract(inverse(8), inverse(12))) | inverse(n0)|inverse(n1)|subtract(#0,#1)|inverse(#2)| | b = 1 / 8 – 1 / 2 = 1 / 24 = > 24 days answer : c | physics |
math_qa__Ac6mtCIGFLOQaPH1 | In a fuel station the service costs $2.05 per car, every liter of fuel costs 0.6$. Assuming that you fill up 3 mini-vans and 2 trucks, how much money will the fuel cost to all the cars owners total, if a mini- van's tank is 65 liters and a truck's tank is 120% bigger and they are all empty-?
Choose the correct choice:
A) 122.6 $ B) 128.9 $ C) 243.7 $ D) 298.85 $ E) 312.12 $ | <gadget id="calculator">65 * 120</gadget>
<output>7_800</output>
<gadget id="calculator">7_800 / 100</gadget>
<output>78</output>
<gadget id="calculator">65 + 78</gadget>
<output>143</output>
<gadget id="calculator">143 * 2</gadget>
<output>286</output>
<gadget id="calculator">286 * 0.6</gadget>
<output>171.6</output>
<gadget id="calculator">65 * 3</gadget>
<output>195</output>
<gadget id="calculator">195 * 0.6</gadget>
<output>117</output>
<gadget id="calculator">171.6 + 117</gadget>
<output>288.6</output>
<result>D</result> | D | 298.85 | In a fuel station the service costs $2.05 per car, every liter of fuel costs 0.6$. Assuming that you fill up 3 mini-vans and 2 trucks, how much money will the fuel cost to all the cars owners total, if a mini- van's tank is 65 liters and a truck's tank is 120% bigger and they are all empty-? | {
"A": "122.6 $",
"B": "128.9 $",
"C": "243.7 $",
"D": "298.85 $",
"E": "312.12 $"
} | add(multiply(multiply(add(65, divide(multiply(65, 120), const_100)), 2), 0.6), multiply(multiply(65, 3), 0.6)) | multiply(n4,n5)|multiply(n2,n4)|divide(#0,const_100)|multiply(n1,#1)|add(n4,#2)|multiply(n3,#4)|multiply(n1,#5)|add(#6,#3)| | "mini van cost = 65 * 0.6 + 2.05 truck capacity = 65 ( 1 + 120 / 100 ) = 143 lts . cost of truck = 143 + 0.6 + 2.05 total cost = 3 * 41.05 ( car ) + 2 * 87.85 ( truck ) = 298.85 answer : d" | general |
math_qa__el2UmnPOMk5Gacrt | By selling 95 pens, a trader gains the cost of 19 pens. Find his gain percentage?
Answers:
A) 20 % B) 21 % C) 22 % D) 23 % E) 24 % | <gadget id="calculator">19 / 95</gadget>
<output>1/5 = around 0.2</output>
<gadget id="calculator">(1/5) * 100</gadget>
<output>20</output>
<result>A</result> | A | 20 | By selling 95 pens, a trader gains the cost of 19 pens. Find his gain percentage? | {
"A": "20 %",
"B": "21 %",
"C": "22 %",
"D": "23 %",
"E": "24 %"
} | multiply(divide(19, 95), const_100) | divide(n1,n0)|multiply(#0,const_100)| | "let the cp of each pen be rs . 1 . cp of 95 pens = rs . 95 profit = cost of 19 pens = rs . 19 profit % = 19 / 95 * 100 = 20 % answer : a" | gain |
math_qa__JXF9e6BAoxZuuUXJ | There are 193 items that are members of set U. Of these items, 41 are members of set B, 59 are not members of either of set A or set B, and 23 are members of both sets A and B. How many of the members of set U are members of set A ?
Options
A) 116 B) 85 C) 94 D) 98 E) 108 | <gadget id="calculator">193 - 59</gadget>
<output>134</output>
<gadget id="calculator">134 + 23</gadget>
<output>157</output>
<gadget id="calculator">157 - 41</gadget>
<output>116</output>
<result>A</result> | A | 116 | There are 193 items that are members of set U. Of these items, 41 are members of set B, 59 are not members of either of set A or set B, and 23 are members of both sets A and B. How many of the members of set U are members of set A ? | {
"A": "116",
"B": "85",
"C": "94",
"D": "98",
"E": "108"
} | subtract(add(subtract(193, 59), 23), 41) | subtract(n0,n2)|add(n3,#0)|subtract(#1,n1)| | "you had the answer almost right . the x = 93 refers to only set a . however what ' s being asked is how many members are part of set a . this will include : 1 . only set a 2 . set a and set b so the answer is set a = 93 + set ab = 93 + 23 = 116 a" | other |
math_qa__gN7rWPHCZF3AzhDV | A machine can filled a tank in 25 minutes and another machine can empty it in 50 minutes. If the tank is already half full and both the taps are opened together, then the tank is filled in how many minutes?
Select the correct option.
A) 25 min
B) 20 min
C) 10 min
D) 15 min
E) 30 min | <gadget id="calculator">1 / 25</gadget>
<output>1/25 = around 0.04</output>
<gadget id="calculator">1 / 50</gadget>
<output>1/50 = around 0.02</output>
<gadget id="calculator">(1/25) - (1/50)</gadget>
<output>1/50 = around 0.02</output>
<gadget id="calculator">1 / (1/50)</gadget>
<output>50</output>
<gadget id="calculator">50 / 2</gadget>
<output>25</output>
<result>A</result> | A | 25 | A machine can filled a tank in 25 minutes and another machine can empty it in 50 minutes. If the tank is already half full and both the taps are opened together, then the tank is filled in how many minutes? | {
"A": "25 min",
"B": "20 min",
"C": "10 min",
"D": "15 min",
"E": "30 min"
} | divide(divide(const_1, subtract(divide(const_1, 25), divide(const_1, 50))), const_2) | divide(const_1,n0)|divide(const_1,n1)|subtract(#0,#1)|divide(const_1,#2)|divide(#3,const_2) | t = 1 / 2 ( 25 * 50 / 50 - 25 ) = 25 minutes tank is filled in 25 minutes answer is a | physics |
math_qa__dH260IRYaK87TZPn | A hall 36m long and 15m broad is to be paved with stones, each measuring 8dm by 5 dm. The number of stones required is: Choices:
A) 180 B) 1800 C) 18 D) 18000 E) 1350 | <gadget id="calculator">36 * 15</gadget>
<output>540</output>
<gadget id="calculator">8 * 5</gadget>
<output>40</output>
<gadget id="calculator">40 / 100</gadget>
<output>2/5 = around 0.4</output>
<gadget id="calculator">540 / (2/5)</gadget>
<output>1_350</output>
<result>E</result> | E | 1,350 | A hall 36m long and 15m broad is to be paved with stones, each measuring 8dm by 5 dm. The number of stones required is: | {
"A": "180",
"B": "1800",
"C": "18",
"D": "18000",
"E": "1350"
} | divide(multiply(36, 15), divide(multiply(8, 5), const_100)) | multiply(n0,n1)|multiply(n2,n3)|divide(#1,const_100)|divide(#0,#2)| | "area of the hall = 3600 * 1500 area of each stone = ( 80 * 50 ) therefore , number of stones = ( 3600 * 1500 / 80 * 50 ) = 1350 answer : e" | physics |
math_qa__Gi7IGpSdn3Fx3gYd | At Company X, senior sales representatives visit the home office once every 16 days, and junior sales representatives visit the home office once every 12 days. The number of visits that a junior sales representative makes in a 2-year period is approximately what percent greater than the number of visits that a senior representative makes in the same period?
Options:
A) 10 % B) 25 % C) 33 % D) 50 % E) 67 % | <gadget id="calculator">1 + 10</gadget>
<output>11</output>
<gadget id="calculator">16 - 12</gadget>
<output>4</output>
<gadget id="calculator">4 - 1</gadget>
<output>3</output>
<gadget id="calculator">11 * 3</gadget>
<output>33</output>
<result>C</result> | C | 33 | At Company X, senior sales representatives visit the home office once every 16 days, and junior sales representatives visit the home office once every 12 days. The number of visits that a junior sales representative makes in a 2-year period is approximately what percent greater than the number of visits that a senior representative makes in the same period? | {
"A": "10 %",
"B": "25 %",
"C": "33 %",
"D": "50 %",
"E": "67 %"
} | multiply(add(const_1, const_10), subtract(subtract(16, 12), const_1)) | add(const_1,const_10)|subtract(n0,n1)|subtract(#1,const_1)|multiply(#0,#2) | each 48 - day period , senior representatives visit the home office 3 times while junior representatives visit 4 times , thus 33 % more . the answer is c . | general |
math_qa__OObrYJYU5MjNsDJY | In N is a positive integer less than 200, and 14N/60 is an integer, then N has how many different positive prime factors Q? Select the correct option:
A) 2 B) 3 C) 5 D) 6 E) 8 | <gadget id="calculator">1 + 4</gadget>
<output>5</output>
<gadget id="calculator">60 / 2</gadget>
<output>30</output>
<gadget id="calculator">30 / 2</gadget>
<output>15</output>
<gadget id="calculator">15 / 3</gadget>
<output>5</output>
<gadget id="calculator">5 / 5</gadget>
<output>1</output>
<gadget id="calculator">1 + 2</gadget>
<output>3</output>
<result>B</result> | B | 3 | In N is a positive integer less than 200, and 14N/60 is an integer, then N has how many different positive prime factors Q? | {
"A": "2",
"B": "3",
"C": "5",
"D": "6",
"E": "8"
} | add(divide(add(const_1, const_4), divide(divide(divide(60, const_2), const_2), const_3)), const_2) | add(const_1,const_4)|divide(n2,const_2)|divide(#1,const_2)|divide(#2,const_3)|divide(#0,#3)|add(#4,const_2)| | "i like to put the numbers in prime factors so it is easier and faster to visualize . 14 * n / 60 if we write the factors of 14 - - > 2 , 7 , and the factors of 60 - - > 2 , 2 , 3 , 5 , we have ( 2 * 7 * n ) / ( 2 ^ 2 * 3 * 5 ) simplifying 7 * n / ( 2 * 3 * 5 ) the only way the equation above has an integer value is if n has at least the factors 2 , 3 and 5 , so we can simplify again and we have the number 7 . the number could be 2 * 3 * 5 , or 2 * 3 * 5 * 2 , or 2 * 3 * 5 * . . . . . however to be less than 200 we can not add any prime number . 2 * 3 * 5 = 120 if we added the next prime factor 7 , we would have q = 2 * 3 * 5 * 7 = 840 thus , answer b ." | general |
math_qa__O9UlVdWpn2qHNKXn | The two lines y=x and x=-9 intersect on the coordinate plane. What is the value of the area of the figure formed by the intersecting lines and the x-axis?
Choose the correct choice from the following choices:
A) 32.5 B) 36.5 C) 40.5 D) 44.5 E) 48.5 | <gadget id="calculator">9 * 9</gadget>
<output>81</output>
<gadget id="calculator">81 / 2</gadget>
<output>81/2 = around 40.5</output>
<result>C</result> | C | 40.5 | The two lines y=x and x=-9 intersect on the coordinate plane. What is the value of the area of the figure formed by the intersecting lines and the x-axis? | {
"A": "32.5",
"B": "36.5",
"C": "40.5",
"D": "44.5",
"E": "48.5"
} | divide(multiply(9, 9), const_2) | multiply(n0,n0)|divide(#0,const_2) | the point of intersection is ( - 9 , - 9 ) . the triangle has a base of length 9 and a height of 9 . area = ( 1 / 2 ) * base * height = ( 1 / 2 ) * 9 * 9 = 40.5 the answer is c . | general |
math_qa__qihWOrS1bbcTv342 | At a certain food stand, the price of each apple is 40¢ and the price of each orange is 60¢. Mary selects a total of 10 apples and oranges from the food stand, and the average (arithmetic mean) price of the 10 pieces of fruit is 54¢. How many oranges must Mary put back so that the average price of the pieces of fruit that she keeps is 50¢? Select the correct option.
A) 1 B) 2 C) 3 D) 4 E) 5 | <gadget id="calculator">60 * 10</gadget>
<output>600</output>
<gadget id="calculator">54 * 10</gadget>
<output>540</output>
<gadget id="calculator">600 - 540</gadget>
<output>60</output>
<gadget id="calculator">60 - 40</gadget>
<output>20</output>
<gadget id="calculator">60 / 20</gadget>
<output>3</output>
<gadget id="calculator">3 * 40</gadget>
<output>120</output>
<gadget id="calculator">10 - 3</gadget>
<output>7</output>
<gadget id="calculator">7 * 60</gadget>
<output>420</output>
<gadget id="calculator">120 + 420</gadget>
<output>540</output>
<gadget id="calculator">50 * 10</gadget>
<output>500</output>
<gadget id="calculator">540 - 500</gadget>
<output>40</output>
<gadget id="calculator">60 - 50</gadget>
<output>10</output>
<gadget id="calculator">40 / 10</gadget>
<output>4</output>
<result>D</result> | D | 4 | At a certain food stand, the price of each apple is 40¢ and the price of each orange is 60¢. Mary selects a total of 10 apples and oranges from the food stand, and the average (arithmetic mean) price of the 10 pieces of fruit is 54¢. How many oranges must Mary put back so that the average price of the pieces of fruit that she keeps is 50¢? | {
"A": "1",
"B": "2",
"C": "3",
"D": "4",
"E": "5"
} | divide(subtract(add(multiply(divide(subtract(multiply(60, 10), multiply(54, 10)), subtract(60, 40)), 40), multiply(subtract(10, divide(subtract(multiply(60, 10), multiply(54, 10)), subtract(60, 40))), 60)), multiply(50, 10)), subtract(60, 50)) | multiply(n1,n2)|multiply(n2,n4)|multiply(n2,n5)|subtract(n1,n0)|subtract(n1,n5)|subtract(#0,#1)|divide(#5,#3)|multiply(n0,#6)|subtract(n2,#6)|multiply(n1,#8)|add(#7,#9)|subtract(#10,#2)|divide(#11,#4)| | "if the average price is 54 , then mary has 7 oranges and 3 apples ( a ratio of 7 : 3 ) . for the average price to be 50 , the ratio should be 1 : 1 . mary must put back 4 oranges . the answer is d ." | general |
math_qa__HWuzonvzlhHEQCyy | m and n are the x and y coordinates, respectively, of a point in the coordinate plane. If the points (m, n) and (m + p, n + 9) both lie on the line defined by the equation x = (y/3) - (2/5), what is the value of p? Choose the correct option.
A) 1
B) 2
C) 3
D) 4
E) 5 | <gadget id="calculator">9 / 3</gadget>
<output>3</output>
<result>C</result> | C | 3 | m and n are the x and y coordinates, respectively, of a point in the coordinate plane. If the points (m, n) and (m + p, n + 9) both lie on the line defined by the equation x = (y/3) - (2/5), what is the value of p? | {
"A": "1",
"B": "2",
"C": "3",
"D": "4",
"E": "5"
} | divide(9, 3) | divide(n0,n1)| | "x = ( y / 3 ) - ( 2 / 5 ) , and so y = 3 x + 6 / 5 . the slope is 3 . ( n + 9 - n ) / ( m + p - m ) = 3 p = 3 the answer is c ." | general |
math_qa__VVR7Mamdisf23LKX | At an international conference, “Red” world countries and “Blue” world countries are the only participants. The ratio of “Red” world participants to “Blue” world participants is 5:5. If one-third of “Red” world participants are left-handed and two-thirds of “Blue” world participants are left-handed, then what is the fraction of the participants who are left-handed?
Choose one.
A) 1 / 4 B) 1 / 8 C) 1 / 6 D) 1 / 2 E) 1 | <gadget id="calculator">1 / 3</gadget>
<output>1/3 = around 0.333333</output>
<gadget id="calculator">5 * (1/3)</gadget>
<output>5/3 = around 1.666667</output>
<gadget id="calculator">2 / 3</gadget>
<output>2/3 = around 0.666667</output>
<gadget id="calculator">5 * (2/3)</gadget>
<output>10/3 = around 3.333333</output>
<gadget id="calculator">(5/3) + (10/3)</gadget>
<output>5</output>
<gadget id="calculator">5 + 5</gadget>
<output>10</output>
<gadget id="calculator">5 / 10</gadget>
<output>1/2 = around 0.5</output>
<result>D</result> | D | 0.5 | At an international conference, “Red” world countries and “Blue” world countries are the only participants. The ratio of “Red” world participants to “Blue” world participants is 5:5. If one-third of “Red” world participants are left-handed and two-thirds of “Blue” world participants are left-handed, then what is the fraction of the participants who are left-handed? | {
"A": "1 / 4",
"B": "1 / 8",
"C": "1 / 6",
"D": "1 / 2",
"E": "1"
} | divide(add(multiply(5, const_0_33), multiply(5, divide(const_2, const_3))), add(5, 5)) | add(n0,n1)|divide(const_2,const_3)|multiply(n0,const_0_33)|multiply(n1,#1)|add(#2,#3)|divide(#4,#0)| | "red : blue = 5 : 5 let red = 5 x and blue = 5 x 1 / 3 of red are left handed = > 1 / 3 * 5 x = 5 x / 3 red left handed 2 / 3 of blue are left handed = > 2 / 3 * 5 x = 10 x / 3 blue left handed fraction of participants who are left handed = total left handed / total participants = ( red left handed + blue left handed ) / total participants = ( 5 x / 3 + 10 x / 3 ) / ( 5 x + 5 x ) = ( 15 x / 30 x ) = 1 / 2 answer : d" | other |
math_qa__GTtxvlFInkPMEoRP | 1 + 2 + 3 + ... + 12 = ? Choose the correct option.
A) 76 B) 68 C) 78 D) 66 E) 67 | <gadget id="calculator">12 + 1</gadget>
<output>13</output>
<gadget id="calculator">12 * 13</gadget>
<output>156</output>
<gadget id="calculator">156 / 2</gadget>
<output>78</output>
<result>C</result> | C | 78 | 1 + 2 + 3 + ... + 12 = ? | {
"A": "76",
"B": "68",
"C": "78",
"D": "66",
"E": "67"
} | divide(multiply(12, add(12, 1)), 2) | add(n0,n3)|multiply(n3,#0)|divide(#1,n1) | 1 + 2 + 3 + ⋯ + n = ∑ n = n ( n + 1 ) / 2 1 + 2 + 3 + ⋯ + 12 = n ( n + 1 ) / 2 = ( 12 ( 12 + 1 ) ) / 2 = ( 12 × 13 ) / 2 = 6 × 13 = 78 answer is c | general |
math_qa__gi6Mci0Qss0lRtWt | 7 people average age is 30. youngest person age is 6. find average of the people when youngest was born. Choose the correct choice from the following.
A) 23 B) 24 C) 25 D) 26 E) 27 | <gadget id="calculator">30 * 7</gadget>
<output>210</output>
<gadget id="calculator">6 * 7</gadget>
<output>42</output>
<gadget id="calculator">210 - 42</gadget>
<output>168</output>
<gadget id="calculator">168 / 7</gadget>
<output>24</output>
<result>B</result> | B | 24 | 7 people average age is 30. youngest person age is 6. find average of the people when youngest was born. | {
"A": "23",
"B": "24",
"C": "25",
"D": "26",
"E": "27"
} | divide(subtract(multiply(30, 7), multiply(6, 7)), 7) | multiply(n0,n1)|multiply(n0,n2)|subtract(#0,#1)|divide(#2,n0)| | "average age of people = 30 so have total age = 210 before 7 years we have to deduct each person age by seven years 210 - 42 = 161 so average age would be 161 / 7 = 24 answer : b" | general |
math_qa__uLEIAi2jK83PNF9g | If 4 men can reap 40 acres of land in 15 days, how many acres of land can 16 men reap in 30 days? Pick one:
A) 320
B) 240
C) 369
D) 489
E) 125 | <gadget id="calculator">16 / 4</gadget>
<output>4</output>
<gadget id="calculator">30 / 15</gadget>
<output>2</output>
<gadget id="calculator">4 * 2</gadget>
<output>8</output>
<gadget id="calculator">40 * 8</gadget>
<output>320</output>
<result>A</result> | A | 320 | If 4 men can reap 40 acres of land in 15 days, how many acres of land can 16 men reap in 30 days? | {
"A": "320",
"B": "240",
"C": "369",
"D": "489",
"E": "125"
} | multiply(40, multiply(divide(16, 4), divide(30, 15))) | divide(n3,n0)|divide(n4,n2)|multiply(#0,#1)|multiply(n1,#2)| | "4 men 40 acres 15 days 16 men ? 30 days 40 * 16 / 4 * 30 / 15 40 * 4 * 2 40 * 8 = 320 answer : a" | physics |
math_qa__VOepKrya5J5J8q7V | In the Excel Manufacturing Company, 46 percent of the employees are men. If 60 percent of the employees are unionized and 70 percent of these are men, what percent of the non-union employees are women? Choose the correct choice from the following.
A) 90 % B) 87.5 % C) 66.7 % D) 50 % E) 36 % | <gadget id="calculator">100 - 46</gadget>
<output>54</output>
<gadget id="calculator">70 / 100</gadget>
<output>7/10 = around 0.7</output>
<gadget id="calculator">(7/10) * 60</gadget>
<output>42</output>
<gadget id="calculator">60 - 42</gadget>
<output>18</output>
<gadget id="calculator">54 - 18</gadget>
<output>36</output>
<gadget id="calculator">100 - 60</gadget>
<output>40</output>
<gadget id="calculator">36 / 40</gadget>
<output>9/10 = around 0.9</output>
<gadget id="calculator">(9/10) * 100</gadget>
<output>90</output>
<result>A</result> | A | 90 | In the Excel Manufacturing Company, 46 percent of the employees are men. If 60 percent of the employees are unionized and 70 percent of these are men, what percent of the non-union employees are women? | {
"A": "90 %",
"B": "87.5 %",
"C": "66.7 %",
"D": "50 %",
"E": "36 %"
} | multiply(divide(subtract(subtract(const_100, 46), subtract(60, multiply(divide(70, const_100), 60))), subtract(const_100, 60)), const_100) | divide(n2,const_100)|subtract(const_100,n0)|subtract(const_100,n1)|multiply(n1,#0)|subtract(n1,#3)|subtract(#1,#4)|divide(#5,#2)|multiply(#6,const_100) | lets say there are total 100 employees then men = 46 & women = 54 unionized emp = 60 & non unionized emp = 40 men unionized = . 7 * 60 = 42 women unionized = 18 women non - unionized = 54 - 18 = 36 percentage of women non unionized = 36 / 40 * 100 = 90 % the answer is option a | general |
math_qa__tpzaPJfTsgik01QV | A library branch originally contained 18360 volumes, 30% of which were fiction novels. 1/3 of the volumes were transferred to another location and 1/4 of the volumes transferred were fiction novels. What percent of the remaining collection was fiction novels? Choose the correct option:
A) 2.5 % B) 17.67 % C) 28.3 % D) 45.2 % E) 32.5 % | <gadget id="calculator">30 / 100</gadget>
<output>3/10 = around 0.3</output>
<gadget id="calculator">1 / 4</gadget>
<output>1/4 = around 0.25</output>
<gadget id="calculator">1 - (1/4)</gadget>
<output>3/4 = around 0.75</output>
<gadget id="calculator">(3/10) * (3/4)</gadget>
<output>9/40 = around 0.225</output>
<gadget id="calculator">1 / 3</gadget>
<output>1/3 = around 0.333333</output>
<gadget id="calculator">1 - (1/3)</gadget>
<output>2/3 = around 0.666667</output>
<gadget id="calculator">(9/40) / (2/3)</gadget>
<output>27/80 = around 0.3375</output>
<gadget id="calculator">(27/80) * 100</gadget>
<output>135/4 = around 33.75</output>
<result>E</result> | E | 32.5 | A library branch originally contained 18360 volumes, 30% of which were fiction novels. 1/3 of the volumes were transferred to another location and 1/4 of the volumes transferred were fiction novels. What percent of the remaining collection was fiction novels? | {
"A": "2.5 %",
"B": "17.67 %",
"C": "28.3 %",
"D": "45.2 %",
"E": "32.5 %"
} | multiply(divide(multiply(divide(30, const_100), subtract(1, divide(1, 4))), subtract(1, divide(1, 3))), const_100) | divide(n1,const_100)|divide(n2,n5)|divide(n2,n3)|subtract(n2,#1)|subtract(n2,#2)|multiply(#0,#3)|divide(#5,#4)|multiply(#6,const_100)| | "fiction novels = 5,508 transferred to another location = 6,120 transferred fiction novels = 1,530 non transferred fiction novels = 3,978 percent of the remaining collection was fiction novels = 3978 / ( 18360 - 6120 ) * 100 = > 32.5 % hence answer will be ( e )" | gain |
math_qa__8CvWrGSLE7y9aMQu | A man was asked to state his age in years. His reply was , "Take my age 6 years hence, multiply it by 6 and subtract 6 times my age 6 years ago and you will know how old I am." What was the age of the person ? Choose the correct choice.
A) 18 B) 92 C) 72 D) 26 E) 19 | <gadget id="calculator">6 + 6</gadget>
<output>12</output>
<gadget id="calculator">12 * 6</gadget>
<output>72</output>
<result>C</result> | C | 72 | A man was asked to state his age in years. His reply was , "Take my age 6 years hence, multiply it by 6 and subtract 6 times my age 6 years ago and you will know how old I am." What was the age of the person ? | {
"A": "18",
"B": "92",
"C": "72",
"D": "26",
"E": "19"
} | multiply(add(6, 6), 6) | add(n0,n0)|multiply(n0,#0) | explanation : let the present age of person be x years . then , 6 ( x + 6 ) - 6 ( x - 6 ) = x < = > ( 6 x + 36 ) - ( 6 x - 36 ) = x < = > x = 72 . . answer : c | general |
math_qa__wFB37zlPCrURFJv9 | A, B and C started a business with capitals of Rs. 8000, Rs. 10000 and Rs. 12000 respectively. At the end of the year, the profit share of B is Rs. 1800. The difference between the profit shares of A and C is?
Choose the correct option:
A) 720 B) 266 C) 155 D) 600 E) 441 | <gadget id="calculator">12_000 / 10_000</gadget>
<output>6/5 = around 1.2</output>
<gadget id="calculator">8_000 / 10_000</gadget>
<output>4/5 = around 0.8</output>
<gadget id="calculator">(6/5) - (4/5)</gadget>
<output>2/5 = around 0.4</output>
<gadget id="calculator">(2/5) * 1_800</gadget>
<output>720</output>
<result>A</result> | A | 720 | A, B and C started a business with capitals of Rs. 8000, Rs. 10000 and Rs. 12000 respectively. At the end of the year, the profit share of B is Rs. 1800. The difference between the profit shares of A and C is? | {
"A": "720",
"B": "266",
"C": "155",
"D": "600",
"E": "441"
} | multiply(subtract(divide(12000, 10000), divide(8000, 10000)), 1800) | divide(n2,n1)|divide(n0,n1)|subtract(#0,#1)|multiply(n3,#2)| | "ratio of investments of a , b and c is 8000 : 10000 : 12000 = 4 : 5 : 6 and also given that , profit share of b is rs . 1800 = > 5 parts out of 15 parts is rs . 1800 now , required difference is 6 - 4 = 2 parts required difference = 2 / 5 ( 1800 ) = rs . 720 answer : a" | gain |
math_qa__h4694iPVvQGnYFUX | The length of a bridge in meters, which a train 120-meters long and traveling at 45 km/hr can cross in 30 seconds is? Select the correct option
A) 255 B) 285 C) 315 D) 345 E) 375 | <gadget id="calculator">45 * 1_000</gadget>
<output>45_000</output>
<gadget id="calculator">45_000 / 3_600</gadget>
<output>25/2 = around 12.5</output>
<gadget id="calculator">(25/2) * 30</gadget>
<output>375</output>
<gadget id="calculator">375 - 120</gadget>
<output>255</output>
<result>A</result> | A | 255 | The length of a bridge in meters, which a train 120-meters long and traveling at 45 km/hr can cross in 30 seconds is? | {
"A": "255",
"B": "285",
"C": "315",
"D": "345",
"E": "375"
} | subtract(multiply(divide(multiply(45, const_1000), const_3600), 30), 120) | multiply(n1,const_1000)|divide(#0,const_3600)|multiply(n2,#1)|subtract(#2,n0)| | "45 km / h = 45000 m / 3600 s = 12.5 m / s in 30 seconds , the train can go 30 ( 12.5 ) = 375 meters let x be the length of the bridge . x + 120 = 375 meters x = 255 meters the answer is a ." | physics |
math_qa__sRXLSTr9sNXAzs1a | Of 70 players on a football team, 49 are throwers. The rest of the team is divided so one third are left- handed and the rest are right handed. Assuming that all throwers are right handed, how many right- handed players are there total? Choose the correct choice from the following
A) 54
B) 59
C) 63
D) 71
E) 92 | <gadget id="calculator">1 / 3</gadget>
<output>1/3 = around 0.333333</output>
<gadget id="calculator">1 - (1/3)</gadget>
<output>2/3 = around 0.666667</output>
<gadget id="calculator">70 - 49</gadget>
<output>21</output>
<gadget id="calculator">(2/3) * 21</gadget>
<output>14</output>
<gadget id="calculator">14 + 49</gadget>
<output>63</output>
<result>C</result> | C | 63 | Of 70 players on a football team, 49 are throwers. The rest of the team is divided so one third are left- handed and the rest are right handed. Assuming that all throwers are right handed, how many right- handed players are there total? | {
"A": "54",
"B": "59",
"C": "63",
"D": "71",
"E": "92"
} | add(multiply(subtract(const_1, divide(const_1, const_3)), subtract(70, 49)), 49) | divide(const_1,const_3)|subtract(n0,n1)|subtract(const_1,#0)|multiply(#2,#1)|add(n1,#3) | total = 70 thrower = 49 rest = 70 - 49 = 21 left handed = 21 / 3 = 7 right handed = 14 if all thrower are right handed then total right handed is 49 + 14 = 63 so c . 63 is the right answer | general |
math_qa__UEWKWoCcv7fPEW60 | jack has two dice , one has 6 equally probable sides , labeled 1 , 2 , 3 , 4 , 5 , 6 , and the other has 7 equally probable sides , labeled 1 , 2 , 3 , 4 , 5 , 6 , 7 . if jack rolls both dice what is the probability that both of the numbers will be 3 ? Choose the correct option:
A) 3 / 14 B) 2 / 7 C) 1 / 3 D) 1 / 42 E) 12 / 21 | <gadget id="calculator">1 / 6</gadget>
<output>1/6 = around 0.166667</output>
<gadget id="calculator">1 / 7</gadget>
<output>1/7 = around 0.142857</output>
<gadget id="calculator">(1/6) * (1/7)</gadget>
<output>1/42 = around 0.02381</output>
<result>D</result> | D | 0.02381 | jack has two dice , one has 6 equally probable sides , labeled 1 , 2 , 3 , 4 , 5 , 6 , and the other has 7 equally probable sides , labeled 1 , 2 , 3 , 4 , 5 , 6 , 7 . if jack rolls both dice what is the probability that both of the numbers will be 3 ? | {
"A": "3 / 14",
"B": "2 / 7",
"C": "1 / 3",
"D": "1 / 42",
"E": "12 / 21"
} | multiply(divide(const_1, 6), divide(const_1, 7)) | divide(const_1,n0)|divide(const_1,n7)|multiply(#0,#1) | method - 1 probability that the number on first die is 3 = 1 / 6 probability that the number on second die is 3 = 1 / 7 probability that both dice result in odd numbers = ( 1 / 6 ) * ( 1 / 7 ) = 1 / 42 answer : option d | other |
math_qa__EqMcWTJEQrGM0Mfg | A person walks at a speed of 4 km/hr and runs at a speed of 8 km/hr. How many hours will the person require to cover a distance of 16 km, if the person completes half of the distance by walking and the other half by running? Choose the correct choice: A) 2 B) 2.5 C) 3 D) 3.5 E) 4 | <gadget id="calculator">16 / 2</gadget>
<output>8</output>
<gadget id="calculator">8 / 4</gadget>
<output>2</output>
<gadget id="calculator">8 / 8</gadget>
<output>1</output>
<gadget id="calculator">2 + 1</gadget>
<output>3</output>
<result>C</result> | C | 3 | A person walks at a speed of 4 km/hr and runs at a speed of 8 km/hr. How many hours will the person require to cover a distance of 16 km, if the person completes half of the distance by walking and the other half by running? | {
"A": "2",
"B": "2.5",
"C": "3",
"D": "3.5",
"E": "4"
} | add(divide(divide(16, const_2), 4), divide(divide(16, const_2), 8)) | divide(n2,const_2)|divide(#0,n0)|divide(#0,n1)|add(#1,#2) | time = 8 / 4 + 8 / 8 = 3 hours the answer is c . | physics |
math_qa__tS6eQyUxWMp4AJ1V | Change the below lagarithm log255 = 1/2 to exponential form Pick
A) 5
B) 8
C) 7
D) 10
E) 11 | <gadget id="calculator">255 - 100</gadget>
<output>155</output>
<gadget id="calculator">155 - 100</gadget>
<output>55</output>
<gadget id="calculator">10 * 4</gadget>
<output>40</output>
<gadget id="calculator">55 - 40</gadget>
<output>15</output>
<gadget id="calculator">15 - 10</gadget>
<output>5</output>
<result>A</result> | A | 5 | Change the below lagarithm log255 = 1/2 to exponential form | {
"A": "5",
"B": "8",
"C": "7",
"D": "10",
"E": "11"
} | subtract(subtract(subtract(subtract(255, const_100), const_100), multiply(const_10, const_4)), const_10) | multiply(const_10,const_4)|subtract(n0,const_100)|subtract(#1,const_100)|subtract(#2,#0)|subtract(#3,const_10) | solution : log 255 = 251 / 2 = 5 answer is a | general |
math_qa__2yw0svvw5d7IGeWX | By selling 16 pencils for a rupee a man loses 10%. How many for a rupee should he sell in order to gain 20%? Choose the correct choice from the following answers:
A) 8
B) 9
C) 12
D) 89
E) 81 | <gadget id="calculator">100 + 20</gadget>
<output>120</output>
<gadget id="calculator">100 - 10</gadget>
<output>90</output>
<gadget id="calculator">1 / 90</gadget>
<output>1/90 = around 0.011111</output>
<gadget id="calculator">120 * (1/90)</gadget>
<output>4/3 = around 1.333333</output>
<gadget id="calculator">1 / (4/3)</gadget>
<output>3/4 = around 0.75</output>
<gadget id="calculator">(3/4) * 16</gadget>
<output>12</output>
<result>C</result> | C | 12 | By selling 16 pencils for a rupee a man loses 10%. How many for a rupee should he sell in order to gain 20%? | {
"A": "8",
"B": "9",
"C": "12",
"D": "89",
"E": "81"
} | multiply(divide(const_1, multiply(add(const_100, 20), divide(const_1, subtract(const_100, 10)))), 16) | add(n2,const_100)|subtract(const_100,n1)|divide(const_1,#1)|multiply(#0,#2)|divide(const_1,#3)|multiply(n0,#4)| | "90 % - - - 16 120 % - - - ? 90 / 120 * 16 = 12 answer : c" | gain |
math_qa__vTYqsTQmjePRrdAV | If it takes a machine 2⁄3 minute to produce one item, how many items will it produce in 1 hours?
Choose the correct choice.
A) 1 ⁄ 3 B) 4 ⁄ 3 C) 90 D) 120 E) 180 | <gadget id="calculator">1 * 60</gadget>
<output>60</output>
<gadget id="calculator">2 / 3</gadget>
<output>2/3 = around 0.666667</output>
<gadget id="calculator">60 / (2/3)</gadget>
<output>90</output>
<result>C</result> | C | 90 | If it takes a machine 2⁄3 minute to produce one item, how many items will it produce in 1 hours? | {
"A": "1 ⁄ 3",
"B": "4 ⁄ 3",
"C": "90",
"D": "120",
"E": "180"
} | divide(multiply(1, const_60), divide(2, 3)) | divide(n0,n1)|multiply(n2,const_60)|divide(#1,#0)| | "1 item takes 2 / 3 min so it takes 60 min to produce x 2 x / 3 = 60 the x = 90 answer : c" | physics |
math_qa__HRbVK2ETLGmLp1YJ | A batsman makes a score of 65 runs in the 17th inning and thus increases his average by 3. Find his average after 17th inning. Choices:
A) 17
B) 39
C) 42
D) 45
E) none of the above | <gadget id="calculator">17 * 3</gadget>
<output>51</output>
<gadget id="calculator">65 - 51</gadget>
<output>14</output>
<gadget id="calculator">14 + 3</gadget>
<output>17</output>
<result>A</result> | A | 17 | A batsman makes a score of 65 runs in the 17th inning and thus increases his average by 3. Find his average after 17th inning. | {
"A": "17",
"B": "39",
"C": "42",
"D": "45",
"E": "none of the above"
} | add(subtract(65, multiply(17, 3)), 3) | multiply(n1,n2)|subtract(n0,#0)|add(n2,#1) | let the average after 17 th inning = x . then , average after 16 th inning = ( x – 3 ) . ∴ 16 ( x – 3 ) + 65 = 17 x or x = ( 65 – 48 ) = 17 . answer a | general |
math_qa__f5gxK5xp7PF4zkWO | A student got twice as many sums wrong as he got right. If he attempted 54 sums in all, how many did he solve correctly ?
Choose one:
A) 12
B) 16
C) 18
D) 24
E) 26 | <gadget id="calculator">1 + 2</gadget>
<output>3</output>
<gadget id="calculator">54 / 3</gadget>
<output>18</output>
<result>C</result> | C | 18 | A student got twice as many sums wrong as he got right. If he attempted 54 sums in all, how many did he solve correctly ? | {
"A": "12",
"B": "16",
"C": "18",
"D": "24",
"E": "26"
} | divide(54, add(const_1, const_2)) | add(const_1,const_2)|divide(n0,#0)| | "explanation : suppose the boy got x sums right and 2 x sums wrong . then , x + 2 x = 54 3 x = 54 x = 18 . answer : c" | general |
math_qa__suPy6fLEll2NeXyY | The instructions state that Deepthi needs 4/17 square yards of one type of material and 3/10 square yards of another type of material for a project. She buys exactly that amount. After finishing the project, however, she has 9/30 square yards left that she did not use. What is the total amount of square yards of material Deepthi used? Choose the most appropriate option
A) 1 / 12 B) 4 / 17 C) 2 / 3 D) 1 1 / 9 E) 2 1 / 9 | <gadget id="calculator">4 / 17</gadget>
<output>4/17 = around 0.235294</output>
<gadget id="calculator">3 / 10</gadget>
<output>3/10 = around 0.3</output>
<gadget id="calculator">(4/17) + (3/10)</gadget>
<output>91/170 = around 0.535294</output>
<gadget id="calculator">9 / 30</gadget>
<output>3/10 = around 0.3</output>
<gadget id="calculator">(91/170) - (3/10)</gadget>
<output>4/17 = around 0.235294</output>
<result>B</result> | B | 0.235294 | The instructions state that Deepthi needs 4/17 square yards of one type of material and 3/10 square yards of another type of material for a project. She buys exactly that amount. After finishing the project, however, she has 9/30 square yards left that she did not use. What is the total amount of square yards of material Deepthi used? | {
"A": "1 / 12",
"B": "4 / 17",
"C": "2 / 3",
"D": "1 1 / 9",
"E": "2 1 / 9"
} | subtract(add(divide(4, 17), divide(const_3, const_10)), divide(9, 30)) | divide(n0,n1)|divide(const_3,const_10)|divide(n4,n5)|add(#0,#1)|subtract(#3,#2) | total bought = 4 / 17 + 3 / 10 left part 9 / 30 - - - > 3 / 10 so used part 4 / 17 + 3 / 10 - 3 / 10 = 4 / 17 answer : b | general |
math_qa__zGO1pNfYYoLYRm7P | Company P had 15 percent more employees in December than it had in January. If Company P had 470 employees in December, how many employees did it have in January? Choices.
A) 391
B) 408
C) 410
D) 423
E) 445 | <gadget id="calculator">15 / 100</gadget>
<output>3/20 = around 0.15</output>
<gadget id="calculator">1 + (3/20)</gadget>
<output>23/20 = around 1.15</output>
<gadget id="calculator">470 / (23/20)</gadget>
<output>9_400/23 = around 408.695652</output>
<result>B</result> | B | 408 | Company P had 15 percent more employees in December than it had in January. If Company P had 470 employees in December, how many employees did it have in January? | {
"A": "391",
"B": "408",
"C": "410",
"D": "423",
"E": "445"
} | divide(470, add(const_1, divide(15, const_100))) | divide(n0,const_100)|add(#0,const_1)|divide(n1,#1)| | "d = number of employees in december j = number of employees in january j x 1.15 = d j x 1.15 = 470 j = 470 / 1.15 j = 47,000 / 115 = 408 thus b is the correct answer ." | gain |
math_qa__iKvbZFaGP6qxqxOS | Find the annual income derived by investing $ 6800 in 60% stock at 136. Choose the correct choice.
A) 550
B) 3000
C) 250
D) 300
E) 400 | <gadget id="calculator">6_800 * 60</gadget>
<output>408_000</output>
<gadget id="calculator">408_000 / 136</gadget>
<output>3_000</output>
<result>B</result> | B | 3,000 | Find the annual income derived by investing $ 6800 in 60% stock at 136. | {
"A": "550",
"B": "3000",
"C": "250",
"D": "300",
"E": "400"
} | divide(multiply(6800, 60), 136) | multiply(n0,n1)|divide(#0,n2)| | "by investing $ 136 , income obtained = $ 60 . by investing $ 6800 , income obtained = $ [ ( 60 / 136 ) * 6800 ] = $ 3000 . answer b ." | gain |
math_qa__EPC12j2saXDrwTiu | Jerry’s average (arithmetic mean) score on the first 3 of 4 tests is 81. If Jerry wants to raise his average by 2 points, what score must he earn on the fourth test? Choose the correct choice from the following options:
A) 87
B) 89
C) 90
D) 93
E) 95 | <gadget id="calculator">81 + 2</gadget>
<output>83</output>
<gadget id="calculator">4 * 83</gadget>
<output>332</output>
<gadget id="calculator">81 * 3</gadget>
<output>243</output>
<gadget id="calculator">332 - 243</gadget>
<output>89</output>
<result>B</result> | B | 89 | Jerry’s average (arithmetic mean) score on the first 3 of 4 tests is 81. If Jerry wants to raise his average by 2 points, what score must he earn on the fourth test? | {
"A": "87",
"B": "89",
"C": "90",
"D": "93",
"E": "95"
} | subtract(multiply(4, add(81, 2)), multiply(81, 3)) | add(n2,n3)|multiply(n0,n2)|multiply(n1,#0)|subtract(#2,#1)| | "total score on 3 tests = 81 * 3 = 243 jerry wants the average to be = 83 hence total score on 4 tests should be = 83 * 4 = 332 score required on the fourth test = 332 - 243 = 89 option b" | general |
math_qa__9UGJ2IcKtfl6oixj | A rectangular field is to be fenced on three sides leaving a side of 20 feet uncovered. If the area of the field is 390 sq. feet, how many feet of fencing will be required?
Pick one.
A) 34 B) 59 C) 68 D) 88 E) 92 | <gadget id="calculator">390 / 20</gadget>
<output>39/2 = around 19.5</output>
<gadget id="calculator">(39/2) * 2</gadget>
<output>39</output>
<gadget id="calculator">39 + 20</gadget>
<output>59</output>
<result>B</result> | B | 59 | A rectangular field is to be fenced on three sides leaving a side of 20 feet uncovered. If the area of the field is 390 sq. feet, how many feet of fencing will be required? | {
"A": "34",
"B": "59",
"C": "68",
"D": "88",
"E": "92"
} | add(multiply(divide(390, 20), const_2), 20) | divide(n1,n0)|multiply(#0,const_2)|add(n0,#1) | given that length and area , so we can find the breadth . length x breadth = area 20 x breadth = 390 breadth = 19.5 feet area to be fenced = 2 b + l = 2 ( 19.5 ) + 20 = 59 feet answer : b | geometry |
math_qa__i4gBmc4jqkWhSZem | What is the smallest positive integer that can be multiplied by 1,008 to make it a perfect square? Pick one.
A) 2 B) 3 C) 5 D) 7 E) 11 | <gadget id="calculator">3 + 4</gadget>
<output>7</output>
<result>D</result> | D | 7 | What is the smallest positive integer that can be multiplied by 1,008 to make it a perfect square? | {
"A": "2",
"B": "3",
"C": "5",
"D": "7",
"E": "11"
} | add(const_3, const_4) | add(const_3,const_4) | 1008 = 2 ^ 4 x 3 ^ 2 x 7 . therefore the smallest integer to multiplied to 1008 to make it a perfect square is 7 . answer d . | geometry |
math_qa__SEZ5vGKSDIavi93s | A palindrome is a number that reads the same front-to-back as it does back-to-front (e.g. 202, 575, 1991, etc.) p is the smallest integer greater than 300 that is both a prime and a palindrome. What is the sum of the digits of p? Pick
A) 3 B) 4 C) 5 D) 6 E) 7 | <gadget id="calculator">3 + 3</gadget>
<output>6</output>
<result>D</result> | D | 6 | A palindrome is a number that reads the same front-to-back as it does back-to-front (e.g. 202, 575, 1991, etc.) p is the smallest integer greater than 300 that is both a prime and a palindrome. What is the sum of the digits of p? | {
"A": "3",
"B": "4",
"C": "5",
"D": "6",
"E": "7"
} | add(const_3, const_3) | add(const_3,const_3) | given that p is smallest integer greater than 300 - assume there is a 3 - digit that satisfies the above conditions . let the number be xyx ; question asks us the values of 2 x + y we can straight away cross out options a ) and d ) - sum of digits 3 or 6 implies it is divisible by 3 - - - > we know that p is a prime number coming to option b ) 2 x + y = 4 - - > only x = 2 and y = 0 satisfy this equation ( x > 2 will never give sum of digits = 4 ) ; but 202 is divisible by 2 ; we know that p is a prime number similarly option c ) 2 x + y = 5 - - > only x = 2 and y = 1 satisfy this equation ( x > 2 will never give sum of digits = 5 ) ; but 212 is divisible by 2 ; we know that p is a prime number therefore answer option should be e - - - > can be verified by taking 2 x + y = 7 - - - > x = 3 and y = 1 ; gives 313 d | general |
math_qa__Vz907gF6PfryebZN | A sucrose solution contains 10 grams of sucrose per 100 cubic centimeters of solution. If 60 cubic centimeters of the solution were poured into an empty container, how many grams of sucrose would be in the container? Choose the correct choice from the following choices
A) 4.00 B) 6.00 C) 5.50 D) 6.50 E) 6.75 | <gadget id="calculator">60 * 10</gadget>
<output>600</output>
<gadget id="calculator">600 / 100</gadget>
<output>6</output>
<result>B</result> | B | 6 | A sucrose solution contains 10 grams of sucrose per 100 cubic centimeters of solution. If 60 cubic centimeters of the solution were poured into an empty container, how many grams of sucrose would be in the container? | {
"A": "4.00",
"B": "6.00",
"C": "5.50",
"D": "6.50",
"E": "6.75"
} | divide(multiply(60, 10), 100) | multiply(n0,n2)|divide(#0,n1) | we are given that a sucrose solution contains 10 grams of sucrose per 100 cubic centimeters of solution . since we are dealing with a solution , we know that the grams of sucrose is proportional to the number of cubic centimeters of solution . thus , to determine how many grams of sucrose would be in the container when we have 60 cubic centimeters of solution , we can set up a proportion . we can say : “ 10 grams of sucrose is to 100 cubic centimeters of solution as x grams of sucrose is to 60 cubic centimeters of solution . ” let ’ s now set up the proportion and solve for x . 10 / 100 = x / 60 when we cross multiply we obtain : ( 10 ) ( 60 ) = 100 x 600 = 100 x 6.00 = x there are 6.00 grams of sucrose in the solution in the container . the answer is b . | physics |
math_qa__FmA8JDyDKRiU3KRM | A crate measures 6 feet by 8 feet by 12 feet on the inside. A stone pillar in the shape of a right circular cylinder must fit into the crate for shipping so that it rests upright when the crate sits on at least one of its six sides. What is the radius, in feet, of the pillar with the largest volume that could still fit in the crate? Pick one.
A) 2 B) 4 C) 6 D) 8 E) 12 | <gadget id="calculator">8 * 12</gadget>
<output>96</output>
<gadget id="calculator">96 * 6</gadget>
<output>576</output>
<gadget id="calculator">576 / 12</gadget>
<output>48</output>
<gadget id="calculator">48 / 8</gadget>
<output>6</output>
<result>C</result> | C | 6 | A crate measures 6 feet by 8 feet by 12 feet on the inside. A stone pillar in the shape of a right circular cylinder must fit into the crate for shipping so that it rests upright when the crate sits on at least one of its six sides. What is the radius, in feet, of the pillar with the largest volume that could still fit in the crate? | {
"A": "2",
"B": "4",
"C": "6",
"D": "8",
"E": "12"
} | divide(divide(multiply(multiply(8, 12), 6), 12), 8) | multiply(n1,n2)|multiply(n0,#0)|divide(#1,n2)|divide(#2,n1)| | "we can find the radius of all the three cases of cylinders . the only crux to find the answer faster is that : voulme is pi * r ^ 2 * h . the volume is a function of r ^ 2 . so r has to be the highest to find the largest volume . so r = 6 for the surface 8 * 12 face . volume = 216 pi answer c" | geometry |
math_qa__bVc1Xh9Stementp8 | A and B go around a circular track of length 1200 m on a cycle at speeds of 36 kmph and 54 kmph. After how much time will they meet for the first time at the starting point? Choose the correct option.
A) 240 sec B) 165 sec C) 186 sec D) 167 sec E) 168 sec | <gadget id="calculator">10 / 36</gadget>
<output>5/18 = around 0.277778</output>
<gadget id="calculator">54 * (5/18)</gadget>
<output>15</output>
<gadget id="calculator">36 * (5/18)</gadget>
<output>10</output>
<gadget id="calculator">15 - 10</gadget>
<output>5</output>
<gadget id="calculator">1_200 / 5</gadget>
<output>240</output>
<result>A</result> | A | 240 | A and B go around a circular track of length 1200 m on a cycle at speeds of 36 kmph and 54 kmph. After how much time will they meet for the first time at the starting point? | {
"A": "240 sec",
"B": "165 sec",
"C": "186 sec",
"D": "167 sec",
"E": "168 sec"
} | divide(1200, subtract(multiply(54, const_0_2778), multiply(36, const_0_2778))) | multiply(n2,const_0_2778)|multiply(n1,const_0_2778)|subtract(#0,#1)|divide(n0,#2)| | "time taken to meet for the first time at the starting point = lcm { length of the track / speed of a , length of the track / speed of b } = lcm { 1200 / ( 36 * 5 / 18 ) , 1200 / ( 54 * 5 / 18 ) } = lcm ( 120 , 80 ) = 240 sec . answer : a" | physics |
math_qa__Hc4yBxtDXWHvrZRJ | If the number is decreased by 5 and divided by 7 the result is 7. What would be the result if 24 is subtracted and divided by 10?
Pick one.
A) 4 B) 7 C) 8 D) 5 E) 3 | <gadget id="calculator">7 * 7</gadget>
<output>49</output>
<gadget id="calculator">49 + 5</gadget>
<output>54</output>
<gadget id="calculator">54 - 24</gadget>
<output>30</output>
<gadget id="calculator">30 / 10</gadget>
<output>3</output>
<result>E</result> | E | 3 | If the number is decreased by 5 and divided by 7 the result is 7. What would be the result if 24 is subtracted and divided by 10? | {
"A": "4",
"B": "7",
"C": "8",
"D": "5",
"E": "3"
} | divide(subtract(add(multiply(7, 7), 5), 24), 10) | multiply(n1,n1)|add(n0,#0)|subtract(#1,n3)|divide(#2,n4)| | "explanation : let the number be x . then , ( x - 5 ) / 7 = 7 = > x - 5 = 49 x = 54 . : ( x - 24 ) / 10 = ( 54 - 24 ) / 10 = 3 answer : option e" | general |
math_qa__QelUObJ7fC8nYr9w | John bought 9.25m of cloth for $407. Find the cost price per metre.
Choose the correct choice from the following:
A) 46
B) 47
C) 58
D) 44
E) 54 | <gadget id="calculator">407 / 9.25</gadget>
<output>44</output>
<result>D</result> | D | 44 | John bought 9.25m of cloth for $407. Find the cost price per metre. | {
"A": "46",
"B": "47",
"C": "58",
"D": "44",
"E": "54"
} | divide(407, 9.25) | divide(n1,n0)| | "cloth bought by john = 9.25 m cost of 9.25 m = $ 407 cost per metre = 407 ÷ 9.25 the cost of the cloth per metre = $ 44 answers : d" | physics |
math_qa__DNJLXkKMCX6JB5J7 | On the xy-plane, each point on circle C has coordinates such
that x 0 and y 0. If the center of circle C is the point (3; 9),
what is the maximum possible area of C? Choose the correct choice from the following options:
A) 6
B) 9
C) 24
D) 32
E) 64 | <gadget id="calculator">3 ** 2</gadget>
<output>9</output>
<gadget id="calculator">4 ** 2</gadget>
<output>16</output>
<gadget id="calculator">9 + 16</gadget>
<output>25</output>
<gadget id="calculator">25 - 2</gadget>
<output>23</output>
<result>C</result> | C | 24 | On the xy-plane, each point on circle C has coordinates such
that x 0 and y 0. If the center of circle C is the point (3; 9),
what is the maximum possible area of C? | {
"A": "6",
"B": "9",
"C": "24",
"D": "32",
"E": "64"
} | subtract(add(power(3, const_2), power(const_4, const_2)), const_2) | power(n2,const_2)|power(const_4,const_2)|add(#0,#1)|subtract(#2,const_2) | i think that theintentof this question is that the circle will have no co - ordinates that fit the following 2 forms : ( 0 , y ) or ( x , 0 ) . in real basic terms , this circle will neither touch ( nor cross ) the x - axis nor will it touch ( nor cross ) the y - axis . with a center at ( 3,8 ) , the longest possible radius would almost touch the x - axis , so the radius would be a little less than 3 . if the radius was 3 exactly , then the area would be 9 pi , which is approximately 28.26 since the circle ca n ' t touch the x - axis , the area has to be less than approximately 28.26 as it ' s written , none of the answers is clearly the correct one . c | geometry |
math_qa__Uls1zsBE2Yrs67Kc | In a school 10% of the boys are same in number as 1/5th of the girls. what is the ratio of boys to the girls in the school? Choose the correct choice from the following answers.
A) 5 : 2 B) 2 : 3 C) 1 : 2 D) 3 : 7 E) 2 : 5 | <gadget id="calculator">10 / 100</gadget>
<output>1/10 = around 0.1</output>
<gadget id="calculator">1 / 5</gadget>
<output>1/5 = around 0.2</output>
<gadget id="calculator">(1/10) / (1/5)</gadget>
<output>1/2 = around 0.5</output>
<result>C</result> | C | 0.5 | In a school 10% of the boys are same in number as 1/5th of the girls. what is the ratio of boys to the girls in the school? | {
"A": "5 : 2",
"B": "2 : 3",
"C": "1 : 2",
"D": "3 : 7",
"E": "2 : 5"
} | divide(divide(10, const_100), divide(1, 5)) | divide(n0,const_100)|divide(n1,n2)|divide(#0,#1) | 10 % of b = 1 / 5 g 10 b / 100 = g / 5 b = g / 2 b / g = 1 / 2 b : g = 1 : 2 answer is c | other |
math_qa__dKgdJY9fzfLROQYE | In a certain Parallelogram the degree measure of one angle exceeds that of the other by 40 what is the degree measure of the smaller angle? Choose the correct choice
A) 70 B) 80 C) 85 D) 90 E) 95 | <gadget id="calculator">3_600 / 10</gadget>
<output>360</output>
<gadget id="calculator">40 * 2</gadget>
<output>80</output>
<gadget id="calculator">360 - 80</gadget>
<output>280</output>
<gadget id="calculator">280 / 4</gadget>
<output>70</output>
<result>A</result> | A | 70 | In a certain Parallelogram the degree measure of one angle exceeds that of the other by 40 what is the degree measure of the smaller angle? | {
"A": "70",
"B": "80",
"C": "85",
"D": "90",
"E": "95"
} | divide(subtract(divide(const_3600, const_10), multiply(40, const_2)), const_4) | divide(const_3600,const_10)|multiply(n0,const_2)|subtract(#0,#1)|divide(#2,const_4)| | "in a parallelogram opposite angles are equal and the angles at each side are supplementary to each other ( supplementary angles are two angles that add up to 180 ° ) . given : x + ( x + 40 ) = 180 - - > x = 70 . answer : a ." | geometry |
math_qa__9zxSSOkt3drhs1Ir | A farmer built a fence around his square plot. He used 27 fence poles on each side of the square. How many poles did he need altogether ? Select the correct option
A) 100 B) 104 C) 108 D) 112 E) none of these | <gadget id="calculator">27 - 2</gadget>
<output>25</output>
<gadget id="calculator">25 * 4</gadget>
<output>100</output>
<gadget id="calculator">100 + 4</gadget>
<output>104</output>
<result>B</result> | B | 104 | A farmer built a fence around his square plot. He used 27 fence poles on each side of the square. How many poles did he need altogether ? | {
"A": "100",
"B": "104",
"C": "108",
"D": "112",
"E": "none of these"
} | add(multiply(subtract(27, const_2), const_4), const_4) | subtract(n0,const_2)|multiply(#0,const_4)|add(#1,const_4) | one side = 2 corners ( 1 nd 1 each ) plus 25 . . . 1 25 1 25 25 1 25 1 der 4 ans = 25 * 4 + 4 = 104 answer : b | geometry |
math_qa__LUwn60aARSoGIF1S | 45 x ? = 40% of 900 Choose the correct choice from the following:
A) 16.2
B) 4
C) 5
D) 500
E) 8 | <gadget id="calculator">40 / 100</gadget>
<output>2/5 = around 0.4</output>
<gadget id="calculator">(2/5) * 900</gadget>
<output>360</output>
<gadget id="calculator">360 / 45</gadget>
<output>8</output>
<result>E</result> | E | 8 | 45 x ? = 40% of 900 | {
"A": "16.2",
"B": "4",
"C": "5",
"D": "500",
"E": "8"
} | divide(multiply(divide(40, const_100), 900), 45) | divide(n1,const_100)|multiply(n2,#0)|divide(#1,n0)| | "answer let 45 x a = ( 40 x 900 ) / 100 ∴ a = ( 40 x 9 ) / 45 = 8 correct option : e" | general |
math_qa__JItm91yd4bZhYhQu | Ramu bought an old car for Rs. 42000. He spent Rs. 13000 on repairs and sold it for Rs. 64900. What is his profit percent?
Choose the correct choice from the following answers
A) 22
B) 77
C) 18
D) 77
E) 65 | <gadget id="calculator">42_000 + 13_000</gadget>
<output>55_000</output>
<gadget id="calculator">64_900 - 55_000</gadget>
<output>9_900</output>
<gadget id="calculator">9_900 / 55_000</gadget>
<output>9/50 = around 0.18</output>
<gadget id="calculator">(9/50) * 100</gadget>
<output>18</output>
<result>C</result> | C | 18 | Ramu bought an old car for Rs. 42000. He spent Rs. 13000 on repairs and sold it for Rs. 64900. What is his profit percent? | {
"A": "22",
"B": "77",
"C": "18",
"D": "77",
"E": "65"
} | multiply(divide(subtract(64900, add(42000, 13000)), add(42000, 13000)), const_100) | add(n0,n1)|subtract(n2,#0)|divide(#1,#0)|multiply(#2,const_100)| | "total cp = rs . 42000 + rs . 13000 = rs . 55000 and sp = rs . 64900 profit ( % ) = ( 64900 - 55000 ) / 55000 * 100 = 18 % answer : c" | gain |
math_qa__0Hvjf03VIyGkkqZc | A honey bee flies for 10 seconds, from a daisy to a rose. It immediately continues to a poppy, flying for 6 additional seconds. The distance the bee passed, flying from the daisy to the rose is 8 meters longer than the distance it passed flying from the rose to the poppy. The bee flies to the poppy at 3 meters per second faster than her speed flying to the rose. The bee flies how many meters per second from the daisy to the rose? Choose the correct choice.
A) 2.6 B) 5.6 C) 6.3 D) 8 E) 10 | <gadget id="calculator">6 * 3</gadget>
<output>18</output>
<gadget id="calculator">18 + 8</gadget>
<output>26</output>
<gadget id="calculator">26 / 10</gadget>
<output>13/5 = around 2.6</output>
<result>A</result> | A | 2.6 | A honey bee flies for 10 seconds, from a daisy to a rose. It immediately continues to a poppy, flying for 6 additional seconds. The distance the bee passed, flying from the daisy to the rose is 8 meters longer than the distance it passed flying from the rose to the poppy. The bee flies to the poppy at 3 meters per second faster than her speed flying to the rose. The bee flies how many meters per second from the daisy to the rose? | {
"A": "2.6",
"B": "5.6",
"C": "6.3",
"D": "8",
"E": "10"
} | divide(add(multiply(6, 3), 8), 10) | multiply(n1,n3)|add(n2,#0)|divide(#1,n0) | let the speed be ' s ' and let the distance between rose and poppy be ' x ' the problem boils down to : rose to poppy : s + 3 = x / 6 - - - - - - - 1 daisy to rose : s = ( x + 8 ) / 10 - - - - - - 2 so from 1 we can re write x as x = 6 s + 18 substitute the value of x in 2 gives us s = 2.6 m / s a | physics |
math_qa__JovOEkW1MXxwoIQp | If in a race of 90m, A covers the distance in 20 seconds and B in 25 seconds, then A beats B by: Pick one: A) 20 m B) 16 m C) 11 m D) 10 m E) 18 m | <gadget id="calculator">25 - 20</gadget>
<output>5</output>
<gadget id="calculator">5 / 25</gadget>
<output>1/5 = around 0.2</output>
<gadget id="calculator">(1/5) * 90</gadget>
<output>18</output>
<result>E</result> | E | 18 | If in a race of 90m, A covers the distance in 20 seconds and B in 25 seconds, then A beats B by: | {
"A": "20 m",
"B": "16 m",
"C": "11 m",
"D": "10 m",
"E": "18 m"
} | multiply(divide(subtract(25, 20), 25), 90) | subtract(n2,n1)|divide(#0,n2)|multiply(n0,#1) | explanation : the difference in the timing of a and b is 5 seconds . hence , a beats b by 5 seconds . the distance covered by b in 5 seconds = ( 90 * 5 ) / 25 = 18 m hence , a beats b by 18 m . answer e | physics |
math_qa__nPz42cIlKS0PalJR | The sum of all two digit numbers divisible by 9 is
Choose one
A) 910 B) 585 C) 785 D) 685 E) 885 | <gadget id="calculator">9 + 9</gadget>
<output>18</output>
<gadget id="calculator">18 + 9</gadget>
<output>27</output>
<gadget id="calculator">18 + 27</gadget>
<output>45</output>
<gadget id="calculator">27 + 9</gadget>
<output>36</output>
<gadget id="calculator">45 + 36</gadget>
<output>81</output>
<gadget id="calculator">36 + 9</gadget>
<output>45</output>
<gadget id="calculator">81 + 45</gadget>
<output>126</output>
<gadget id="calculator">45 + 9</gadget>
<output>54</output>
<gadget id="calculator">126 + 54</gadget>
<output>180</output>
<gadget id="calculator">54 + 9</gadget>
<output>63</output>
<gadget id="calculator">180 + 63</gadget>
<output>243</output>
<gadget id="calculator">63 + 9</gadget>
<output>72</output>
<gadget id="calculator">243 + 72</gadget>
<output>315</output>
<gadget id="calculator">72 + 9</gadget>
<output>81</output>
<gadget id="calculator">315 + 81</gadget>
<output>396</output>
<gadget id="calculator">81 + 9</gadget>
<output>90</output>
<gadget id="calculator">396 + 90</gadget>
<output>486</output>
<gadget id="calculator">90 + 9</gadget>
<output>99</output>
<gadget id="calculator">486 + 99</gadget>
<output>585</output>
<result>B</result> | B | 585 | The sum of all two digit numbers divisible by 9 is | {
"A": "910",
"B": "585",
"C": "785",
"D": "685",
"E": "885"
} | add(add(add(add(add(add(add(add(add(add(9, 9), add(add(9, 9), 9)), add(add(add(9, 9), 9), 9)), add(add(add(add(9, 9), 9), 9), 9)), add(add(add(add(add(9, 9), 9), 9), 9), 9)), add(add(add(add(add(add(9, 9), 9), 9), 9), 9), 9)), add(add(add(add(add(add(add(9, 9), 9), 9), 9), 9), 9), 9)), add(add(add(add(add(add(add(add(9, 9), 9), 9), 9), 9), 9), 9), 9)), add(add(add(add(add(add(add(add(add(9, 9), 9), 9), 9), 9), 9), 9), 9), 9)), add(add(add(add(add(add(add(add(add(add(9, 9), 9), 9), 9), 9), 9), 9), 9), 9), 9)) | add(n0,n0)|add(n0,#0)|add(#0,#1)|add(n0,#1)|add(#2,#3)|add(n0,#3)|add(#4,#5)|add(n0,#5)|add(#6,#7)|add(n0,#7)|add(#8,#9)|add(n0,#9)|add(#10,#11)|add(n0,#11)|add(#12,#13)|add(n0,#13)|add(#14,#15)|add(n0,#15)|add(#16,#17) | required numbers are 18,27 . . . . . 99 this is an a . p . in which a = 18 , d = 9 and l = 99 . let the number of terms in it be n . then t = 99 so a + ( n - 1 ) d = 99 . 18 + ( n - 1 ) * 9 = 99 , 18 + 9 n - 9 = 99 9 + 9 n = 99 9 n = 99 - 9 n = 90 / 9 then n = 10 . required sum = n / 2 ( a + l ) = 10 / 2 ( 18 + 99 ) = 585 answer is b . | general |
math_qa__QAm5vvmj21jT6gkB | Find the least number must be subtracted from 899830 so that remaining no.is divisible by 16? Choose the correct choice from the following options:
A) 5 B) 8 C) 7 D) 6 E) 9 | <gadget id="calculator">899_830 / 16</gadget>
<output>449_915/8 = around 56_239.375</output>
<gadget id="calculator">floor(449_915/8)</gadget>
<output>56_239</output>
<gadget id="calculator">56_239 * 16</gadget>
<output>899_824</output>
<gadget id="calculator">899_830 - 899_824</gadget>
<output>6</output>
<result>D</result> | D | 6 | Find the least number must be subtracted from 899830 so that remaining no.is divisible by 16? | {
"A": "5",
"B": "8",
"C": "7",
"D": "6",
"E": "9"
} | subtract(899830, multiply(floor(divide(899830, 16)), 16)) | divide(n0,n1)|floor(#0)|multiply(n1,#1)|subtract(n0,#2)| | "on dividing 899830 by 16 we get the remainder 6 , so 6 should be subtracted d" | general |
math_qa__9Tr29STrVMRWYmA9 | At 3:40, the hour hand and the minute hand of a clock form an angle of: Choose the correct choice from the following:
A) 130
B) 125
C) 140
D) 154
E) 145 | <gadget id="calculator">60 * 3</gadget>
<output>180</output>
<gadget id="calculator">180 * 2</gadget>
<output>360</output>
<gadget id="calculator">40 / 60</gadget>
<output>2/3 = around 0.666667</output>
<gadget id="calculator">360 * (2/3)</gadget>
<output>240</output>
<gadget id="calculator">360 / 3</gadget>
<output>120</output>
<gadget id="calculator">120 / 4</gadget>
<output>30</output>
<gadget id="calculator">(2/3) + 3</gadget>
<output>11/3 = around 3.666667</output>
<gadget id="calculator">30 * (11/3)</gadget>
<output>110</output>
<gadget id="calculator">240 - 110</gadget>
<output>130</output>
<result>A</result> | A | 130 | At 3:40, the hour hand and the minute hand of a clock form an angle of: | {
"A": "130",
"B": "125",
"C": "140",
"D": "154",
"E": "145"
} | subtract(multiply(multiply(multiply(const_60, const_3), const_2), divide(40, const_60)), multiply(divide(divide(multiply(multiply(const_60, const_3), const_2), const_3), const_4), add(divide(40, const_60), 3))) | divide(n1,const_60)|multiply(const_3,const_60)|add(n0,#0)|multiply(#1,const_2)|divide(#3,const_3)|multiply(#0,#3)|divide(#4,const_4)|multiply(#2,#6)|subtract(#5,#7) | angle traced by hour hand in 12 hrs . = 360 â ° . abgle traced it in 11 / 3 hrs = ( 360 / 12 * 11 / 3 ) = 110 angle traced by min hand in 60 min = 360 angle traced by it in 40 min = ( 360 / 60 * 40 ) = 240 req ( 240 - 110 ) = 130 d | physics |
math_qa__2qzknlFgQ5LurxP9 | Express 60 mps in kmph? Choose the correct choice from the following answers
A) 200
B) 182
C) 216
D) 127
E) 400 | <gadget id="calculator">60 / 1_000</gadget>
<output>3/50 = around 0.06</output>
<gadget id="calculator">(3/50) * 3_600</gadget>
<output>216</output>
<result>C</result> | C | 216 | Express 60 mps in kmph? | {
"A": "200",
"B": "182",
"C": "216",
"D": "127",
"E": "400"
} | multiply(divide(60, const_1000), const_3600) | divide(n0,const_1000)|multiply(#0,const_3600)| | "60 * 18 / 5 = 216 kmph answer : c" | physics |
math_qa__Mwz2b4Ske9Ppx886 | set a : { 1 , 3 , 4 , 6 , 9 , 12 , 15 } if 3 numbers are randomly selected from set a without replacement , what is the probability that the sum of the 3 numbers is divisible by 3 ?
Choices:
A) 3 / 14 B) 2 / 7 C) 9 / 14 D) 5 / 7 E) 11 / 14 | <gadget id="calculator">4 + 1</gadget>
<output>5</output>
<gadget id="calculator">factorial(5)</gadget>
<output>120</output>
<gadget id="calculator">5 - 3</gadget>
<output>2</output>
<gadget id="calculator">factorial(2)</gadget>
<output>2</output>
<gadget id="calculator">factorial(3)</gadget>
<output>6</output>
<gadget id="calculator">2 * 6</gadget>
<output>12</output>
<gadget id="calculator">120 / 12</gadget>
<output>10</output>
<gadget id="calculator">4 + 3</gadget>
<output>7</output>
<gadget id="calculator">factorial(7)</gadget>
<output>5_040</output>
<gadget id="calculator">factorial(4)</gadget>
<output>24</output>
<gadget id="calculator">24 * 6</gadget>
<output>144</output>
<gadget id="calculator">5_040 / 144</gadget>
<output>35</output>
<gadget id="calculator">10 / 35</gadget>
<output>2/7 = around 0.285714</output>
<result>B</result> | B | 0.285714 | set a : { 1 , 3 , 4 , 6 , 9 , 12 , 15 } if 3 numbers are randomly selected from set a without replacement , what is the probability that the sum of the 3 numbers is divisible by 3 ? | {
"A": "3 / 14",
"B": "2 / 7",
"C": "9 / 14",
"D": "5 / 7",
"E": "11 / 14"
} | divide(divide(factorial(add(4, 1)), multiply(factorial(subtract(add(4, 1), 3)), factorial(3))), divide(factorial(add(4, 3)), multiply(factorial(4), factorial(3)))) | add(n0,n2)|add(n1,n2)|factorial(n1)|factorial(n2)|factorial(#0)|factorial(#1)|multiply(#3,#2)|subtract(#0,n1)|divide(#5,#6)|factorial(#7)|multiply(#9,#2)|divide(#4,#10)|divide(#11,#8) | probability of an event = ( # of favorable outcomes ) / ( total # of outcomes ) . there are 5 numbers you can choose from ( 3 , 6 , 9 , 12 , 15 ) so that the sum to be divisible by 3 and there are total of 7 numbers so p = c 35 c 37 = 27 p = c 53 c 73 = 27 . answer : b . | general |
math_qa__E8gUv5X6VWoaWYB0 | The banker's gain on a sum due 3 years hence at 12% per year is Rs. 270. The banker's discount is: Choose the correct choice
A) 960
B) 840
C) 1020
D) 760
E) 920 | <gadget id="calculator">270 * 100</gadget>
<output>27_000</output>
<gadget id="calculator">12 * 3</gadget>
<output>36</output>
<gadget id="calculator">27_000 / 36</gadget>
<output>750</output>
<gadget id="calculator">270 + 750</gadget>
<output>1_020</output>
<result>C</result> | C | 1,020 | The banker's gain on a sum due 3 years hence at 12% per year is Rs. 270. The banker's discount is: | {
"A": "960",
"B": "840",
"C": "1020",
"D": "760",
"E": "920"
} | add(270, divide(multiply(270, const_100), multiply(12, 3))) | multiply(n2,const_100)|multiply(n0,n1)|divide(#0,#1)|add(n2,#2)| | "t . d . = ( b . g . x 100 / r x t ) = rs . ( 270 x 100 / 12 x 3 ) = rs . 750 . therefore , b . d . = rs . ( 750 + 270 ) = rs . 1020 . answer is c" | gain |
math_qa__rwnSsPqBE7W5Ejt5 | A rectangular lawn of dimensions 80 m * 60 m has two roads each 10 m wide running in the middle of the lawn, one parallel to the length and the other parallel to the breadth. What is the cost of traveling the two roads at Rs.4 per sq m?
Choose the correct option: A) 2288 B) 2779 C) 2779 D) 5200 E) 2781 | <gadget id="calculator">80 + 60</gadget>
<output>140</output>
<gadget id="calculator">140 - 10</gadget>
<output>130</output>
<gadget id="calculator">130 * 10</gadget>
<output>1_300</output>
<gadget id="calculator">1_300 * 4</gadget>
<output>5_200</output>
<result>D</result> | D | 5,200 | A rectangular lawn of dimensions 80 m * 60 m has two roads each 10 m wide running in the middle of the lawn, one parallel to the length and the other parallel to the breadth. What is the cost of traveling the two roads at Rs.4 per sq m? | {
"A": "2288",
"B": "2779",
"C": "2779",
"D": "5200",
"E": "2781"
} | multiply(multiply(subtract(add(80, 60), 10), 10), 4) | add(n0,n1)|subtract(#0,n2)|multiply(n2,#1)|multiply(n3,#2)| | "area = ( l + b â € “ d ) d ( 80 + 60 â € “ 10 ) 10 = > 1300 m 2 1300 * 4 = rs . 5200 answer : d" | geometry |
math_qa__oDU2G6nGyKkRqv5i | -88*49+100=?
Choose the correct option:
A) - 4212 B) 4601 C) - 4801 D) - 3471 E) none of these | <gadget id="calculator">-88</gadget>
<output>-88</output>
<gadget id="calculator">(-88) * 49</gadget>
<output>-4_312</output>
<gadget id="calculator">(-4_312) + 100</gadget>
<output>-4_212</output>
<result>A</result> | A | -4,212 | -88*49+100=? | {
"A": "- 4212",
"B": "4601",
"C": "- 4801",
"D": "- 3471",
"E": "none of these"
} | add(multiply(negate(88), 49), 100) | negate(n0)|multiply(n1,#0)|add(n2,#1)| | "= > - 88 * ( 50 - 1 ) + 100 ; = > - ( 88 * 50 ) + 88 + 100 ; = > - 4400 + 188 = - 4212 . correct option : a" | general |
math_qa__EzpiJUZibzNTYxNk | How many digits 2^200 has? Pick one
A) 31 B) 61 C) 50 D) 99 E) 101 | <gadget id="calculator">log(2)</gadget>
<output>log(2) = around 0.693147</output>
<gadget id="calculator">log(10)</gadget>
<output>log(10) = around 2.302585</output>
<gadget id="calculator">log(2) / log(10)</gadget>
<output>log(2)/log(10) = around 0.30103</output>
<gadget id="calculator">(log(2)/log(10)) * 200</gadget>
<output>200*log(2)/log(10) = around 60.205999</output>
<gadget id="calculator">1 + (200*log(2)/log(10))</gadget>
<output>1 + 200*log(2)/log(10) = around 61.205999</output>
<gadget id="calculator">floor(1 + 200*log(2)/log(10))</gadget>
<output>61</output>
<result>B</result> | B | 61 | How many digits 2^200 has? | {
"A": "31",
"B": "61",
"C": "50",
"D": "99",
"E": "101"
} | floor(add(const_1, multiply(divide(log(2), log(const_10)), 200))) | log(n0)|log(const_10)|divide(#0,#1)|multiply(n1,#2)|add(#3,const_1)|floor(#4)| | "2 ^ 10 = 1.024 * 10 ^ 3 = > 2 ^ 100 = ( 1.024 ) ^ 10 * 10 ^ 60 therefore 61 digits would be my best guess b" | general |
math_qa__OKugEKbuSSwRqM33 | In an intercollegiate competition that lasted for 3 days, 175 students took part on day 1, 210 on day 2 and 150 on day 3. If 80 took part on day 1 and day 2 and 70 took part on day 2 and day 3 and 20 took part on all three days, how many students took part only on day 1? Choose the most appropriate option
A) 25 B) 45 C) 55 D) 70 E) 30 | <gadget id="calculator">20 + 80</gadget>
<output>100</output>
<gadget id="calculator">80 + 70</gadget>
<output>150</output>
<gadget id="calculator">150 + 20</gadget>
<output>170</output>
<gadget id="calculator">210 - 170</gadget>
<output>40</output>
<gadget id="calculator">20 + 40</gadget>
<output>60</output>
<gadget id="calculator">60 / 2</gadget>
<output>30</output>
<gadget id="calculator">100 + 30</gadget>
<output>130</output>
<gadget id="calculator">175 - 130</gadget>
<output>45</output>
<result>B</result> | B | 45 | In an intercollegiate competition that lasted for 3 days, 175 students took part on day 1, 210 on day 2 and 150 on day 3. If 80 took part on day 1 and day 2 and 70 took part on day 2 and day 3 and 20 took part on all three days, how many students took part only on day 1? | {
"A": "25",
"B": "45",
"C": "55",
"D": "70",
"E": "30"
} | subtract(175, add(add(20, 80), divide(add(20, subtract(210, add(add(80, 70), 20))), 2))) | add(n7,n13)|add(n7,n10)|add(n13,#1)|subtract(n3,#2)|add(n13,#3)|divide(#4,n4)|add(#0,#5)|subtract(n1,#6) | day 1 & 2 = 80 ; only day 1 & 2 ( 80 - 20 ) = 60 , day 2 & 3 = 70 ; only day 2 & 3 ( 70 - 20 ) = 50 , only day 1 = 175 - ( 60 + 50 + 20 ) = 45 answer : b | physics |
math_qa__6nMr3etHYiY8qAtv | The Shopkeeper increased the price of a product by 25% so that customer finds it difficult to purchase the required amount. But somehow the customer managed to purchase only 68% of the required amount. What is the net difference in the expenditure on that product? Options: A) 12.5 % B) 13 % C) 16 % D) 15 % E) 19 % | <gadget id="calculator">100 * 100</gadget>
<output>10_000</output>
<gadget id="calculator">100 + 25</gadget>
<output>125</output>
<gadget id="calculator">125 * 68</gadget>
<output>8_500</output>
<gadget id="calculator">10_000 - 8_500</gadget>
<output>1_500</output>
<gadget id="calculator">1_500 * 100</gadget>
<output>150_000</output>
<gadget id="calculator">150_000 / 10_000</gadget>
<output>15</output>
<result>D</result> | D | 15 | The Shopkeeper increased the price of a product by 25% so that customer finds it difficult to purchase the required amount. But somehow the customer managed to purchase only 68% of the required amount. What is the net difference in the expenditure on that product? | {
"A": "12.5 %",
"B": "13 %",
"C": "16 %",
"D": "15 %",
"E": "19 %"
} | divide(multiply(subtract(multiply(const_100, const_100), multiply(add(const_100, 25), 68)), const_100), multiply(const_100, const_100)) | add(n0,const_100)|multiply(const_100,const_100)|multiply(n1,#0)|subtract(#1,#2)|multiply(#3,const_100)|divide(#4,#1)| | "quantity x rate = price 1 x 1 = 1 0.68 x 1.25 = 0.85 decrease in price = ( 0.15 / 1 ) × 100 = 15 % d )" | general |
math_qa__EhnX3frFf2JSV2zZ | A store reduced the price of all items in the store by 10% on the first day and by another 14% on the second day. The price of items on the second day was what percent of the price before the first reduction took place? Answers:
A) 80.0 B) 80.9 C) 77.4 D) 81.1 E) 81.9 | <gadget id="calculator">100 - 10</gadget>
<output>90</output>
<gadget id="calculator">90 / 100</gadget>
<output>9/10 = around 0.9</output>
<gadget id="calculator">100 - 14</gadget>
<output>86</output>
<gadget id="calculator">86 / 100</gadget>
<output>43/50 = around 0.86</output>
<gadget id="calculator">(9/10) * (43/50)</gadget>
<output>387/500 = around 0.774</output>
<gadget id="calculator">(387/500) * 100</gadget>
<output>387/5 = around 77.4</output>
<result>C</result> | C | 77.4 | A store reduced the price of all items in the store by 10% on the first day and by another 14% on the second day. The price of items on the second day was what percent of the price before the first reduction took place? | {
"A": "80.0",
"B": "80.9",
"C": "77.4",
"D": "81.1",
"E": "81.9"
} | multiply(multiply(divide(subtract(const_100, 10), const_100), divide(subtract(const_100, 14), const_100)), const_100) | subtract(const_100,n0)|subtract(const_100,n1)|divide(#0,const_100)|divide(#1,const_100)|multiply(#2,#3)|multiply(#4,const_100)| | "consider price of the all items as $ 100 after a initial reduction of 10 % price becomes = 0.9 * 100 = $ 90 after the final reduction of 14 % price becomes = 0.86 * 90 = $ 77.4 price of all items on second day is 77.4 % of price on first day correct answer option c" | gain |
math_qa__sNnC9R8dU64wpvsx | If 25% of(x-y) = 15% of(x+y), then what percent of x is y? Choose the correct option
A) 20 % B) 15 % C) 30 % D) 25 % E) none of these | <gadget id="calculator">25 - 15</gadget>
<output>10</output>
<gadget id="calculator">25 + 15</gadget>
<output>40</output>
<gadget id="calculator">10 / 40</gadget>
<output>1/4 = around 0.25</output>
<gadget id="calculator">(1/4) * 100</gadget>
<output>25</output>
<result>D</result> | D | 25 | If 25% of(x-y) = 15% of(x+y), then what percent of x is y? | {
"A": "20 %",
"B": "15 %",
"C": "30 %",
"D": "25 %",
"E": "none of these"
} | multiply(divide(subtract(25, 15), add(25, 15)), const_100) | add(n0,n1)|subtract(n0,n1)|divide(#1,#0)|multiply(#2,const_100)| | "explanation : solution : 25 % of ( x - y ) = 15 % of ( x + y ) 25 ( x - y ) / 100 = 15 ( x + y ) / 100 5 ( x - y ) = 3 ( x + y ) x = 4 y . . ' . required percentage = ( y * 100 / x ) % = y * 100 / 4 y = 25 % answer : d" | general |
math_qa__T0ykhl4iklkClF6g | the average weight of 3 men a , b and c is 84 kg . the average weight becomes 80 kg when d joins them . if e whose weight is 3 kg more than d joins the group replacing a , then the average weight of b , c , d and e becomes 79 kg . the weight of a is : Options:
A) 65 kg B) 70 kg C) 75 kg D) 80 kg E) 85 kg | <gadget id="calculator">80 * 4</gadget>
<output>320</output>
<gadget id="calculator">79 * 4</gadget>
<output>316</output>
<gadget id="calculator">84 * 3</gadget>
<output>252</output>
<gadget id="calculator">320 - 252</gadget>
<output>68</output>
<gadget id="calculator">68 + 3</gadget>
<output>71</output>
<gadget id="calculator">316 - 71</gadget>
<output>245</output>
<gadget id="calculator">320 - 245</gadget>
<output>75</output>
<result>C</result> | C | 75 | the average weight of 3 men a , b and c is 84 kg . the average weight becomes 80 kg when d joins them . if e whose weight is 3 kg more than d joins the group replacing a , then the average weight of b , c , d and e becomes 79 kg . the weight of a is : | {
"A": "65 kg",
"B": "70 kg",
"C": "75 kg",
"D": "80 kg",
"E": "85 kg"
} | subtract(multiply(80, const_4), subtract(multiply(79, const_4), add(subtract(multiply(80, const_4), multiply(84, 3)), 3))) | multiply(n2,const_4)|multiply(n4,const_4)|multiply(n0,n1)|subtract(#0,#2)|add(n0,#3)|subtract(#1,#4)|subtract(#0,#5) | wt of abc = 84 * 3 = 252 kg wt of abcd = 80 * 4 = 320 kg wt of d = 68 kg wt of e = 71 kg wt of abcde = 320 + 71 = 391 kg wt of bcde = 79 * 4 = 316 kg wt of a = 391 - 316 = 75 kg answer : c | general |
math_qa__lV0Qq3e4UndlejbD | the ratio of the present ages of two friends is 2 : 3 and 6 years back , the ratio was 1 : 3 . what will be the ratio of their ages after 4 years ? Choose the correct option:
A) 1 : 4
B) 3 : 4
C) 1 : 2
D) 3 : 1
E) 3 : 2 | <gadget id="calculator">2 / 3</gadget>
<output>2/3 = around 0.666667</output>
<gadget id="calculator">6 * 3</gadget>
<output>18</output>
<gadget id="calculator">18 - 6</gadget>
<output>12</output>
<gadget id="calculator">1 * 3</gadget>
<output>3</output>
<gadget id="calculator">3 * (2/3)</gadget>
<output>2</output>
<gadget id="calculator">2 - 1</gadget>
<output>1</output>
<gadget id="calculator">12 / 1</gadget>
<output>12</output>
<gadget id="calculator">(2/3) * 12</gadget>
<output>8</output>
<gadget id="calculator">8 + 4</gadget>
<output>12</output>
<gadget id="calculator">12 + 4</gadget>
<output>16</output>
<gadget id="calculator">12 / 16</gadget>
<output>3/4 = around 0.75</output>
<result>B</result> | B | 0.75 | the ratio of the present ages of two friends is 2 : 3 and 6 years back , the ratio was 1 : 3 . what will be the ratio of their ages after 4 years ? | {
"A": "1 : 4",
"B": "3 : 4",
"C": "1 : 2",
"D": "3 : 1",
"E": "3 : 2"
} | divide(add(multiply(divide(2, 3), divide(subtract(multiply(6, 3), 6), subtract(multiply(multiply(const_1, const_3), divide(2, 3)), 1))), 4), add(divide(subtract(multiply(6, 3), 6), subtract(multiply(multiply(const_1, const_3), divide(2, 3)), 1)), 4)) | divide(n0,n1)|multiply(n1,n2)|multiply(const_1,const_3)|multiply(#0,#2)|subtract(#1,n2)|subtract(#3,n3)|divide(#4,#5)|add(n5,#6)|multiply(#0,#6)|add(n5,#8)|divide(#9,#7) | let the ages be 2 x , 3 x 6 yrs back , so 2 x - 6 / 3 x - 6 = 1 / 3 x = 4 after 4 yrs 2 x + 43 x + 4 2 ( 4 ) + 43 ( 4 ) + 4 12 : 16 3 : 4 answer : b | other |
math_qa__FB9K7NBjFkFwqSog | The perimeter of a triangle is 24 cm and the inradius of the triangle is 2.5 cm. What is the area of the triangle? Options
A) 30 cm 2 B) 85 cm 2 C) 65 cm 2 D) 45 cm 2 E) 35 cm 2 | <gadget id="calculator">(2.5 * 24) / 2</gadget>
<output>30</output>
<result>A</result> | A | 30 | The perimeter of a triangle is 24 cm and the inradius of the triangle is 2.5 cm. What is the area of the triangle? | {
"A": "30 cm 2",
"B": "85 cm 2",
"C": "65 cm 2",
"D": "45 cm 2",
"E": "35 cm 2"
} | triangle_area(2.5, 24) | triangle_area(n0,n1)| | "area of a triangle = r * s where r is the inradius and s is the semi perimeter of the triangle . area of triangle = 2.5 * 24 / 2 = 30 cm 2 answer : a" | geometry |
math_qa__rJCFUAGj6nS1HNSA | if 85% of the population of an ant colony is red, and of these 45% are females, then what % of the total ant population are male red ants?
Pick:
A) 46.75
B) 40
C) 33.66
D) 66.66
E) 66.86 | <gadget id="calculator">45 / 100</gadget>
<output>9/20 = around 0.45</output>
<gadget id="calculator">1 - (9/20)</gadget>
<output>11/20 = around 0.55</output>
<gadget id="calculator">85 / 100</gadget>
<output>17/20 = around 0.85</output>
<gadget id="calculator">(11/20) * (17/20)</gadget>
<output>187/400 = around 0.4675</output>
<gadget id="calculator">(187/400) * 100</gadget>
<output>187/4 = around 46.75</output>
<result>A</result> | A | 46.75 | if 85% of the population of an ant colony is red, and of these 45% are females, then what % of the total ant population are male red ants? | {
"A": "46.75",
"B": "40",
"C": "33.66",
"D": "66.66",
"E": "66.86"
} | multiply(multiply(subtract(const_1, divide(45, const_100)), divide(85, const_100)), const_100) | divide(n0,const_100)|divide(n1,const_100)|subtract(const_1,#1)|multiply(#0,#2)|multiply(#3,const_100) | 55 % are males percentage of male red ants is 55 * . 85 = 46.75 answer : a | gain |
math_qa__CSrsshEVP9Npmt3A | A train 210 metres long is moving at a speed of 25 kmph. It will cross a man coming from the opposite direction at a speed of 2 km per hour in :
Select the correct option:
A) 28 sec
B) 32 sec
C) 36 sec
D) 38 sec
E) 40 sec | <gadget id="calculator">210 / 1_000</gadget>
<output>21/100 = around 0.21</output>
<gadget id="calculator">25 + 2</gadget>
<output>27</output>
<gadget id="calculator">(21/100) / 27</gadget>
<output>7/900 = around 0.007778</output>
<gadget id="calculator">3_600 * (7/900)</gadget>
<output>28</output>
<result>A</result> | A | 28 | A train 210 metres long is moving at a speed of 25 kmph. It will cross a man coming from the opposite direction at a speed of 2 km per hour in : | {
"A": "28 sec",
"B": "32 sec",
"C": "36 sec",
"D": "38 sec",
"E": "40 sec"
} | multiply(const_3600, divide(divide(210, const_1000), add(25, 2))) | add(n1,n2)|divide(n0,const_1000)|divide(#1,#0)|multiply(#2,const_3600)| | "relative speed = ( 25 + 2 ) km / hr = 27 km / hr = ( 27 × 5 / 18 ) m / sec = 15 / 2 m / sec . time taken by the train to pass the man = ( 210 × 2 / 15 ) sec = 28 sec answer : a" | physics |
math_qa__IqDiEilVqhc2lrhn | in 3 annual examinations , of which the aggregate marks of each was 500 , a student secured average marks 45 % and 55 % in the first and the second yearly examinations respectively . to secure 40 % average total marks , it is necessary for him in third yearly examination to secure marks : Choose the correct choice from the following: A) 100 B) 350 C) 400 D) 450 E) 500 | <gadget id="calculator">3 * 500</gadget>
<output>1_500</output>
<gadget id="calculator">1_500 * 40</gadget>
<output>60_000</output>
<gadget id="calculator">60_000 / 100</gadget>
<output>600</output>
<gadget id="calculator">500 * 55</gadget>
<output>27_500</output>
<gadget id="calculator">27_500 / 100</gadget>
<output>275</output>
<gadget id="calculator">500 * 45</gadget>
<output>22_500</output>
<gadget id="calculator">22_500 / 100</gadget>
<output>225</output>
<gadget id="calculator">275 + 225</gadget>
<output>500</output>
<gadget id="calculator">600 - 500</gadget>
<output>100</output>
<result>A</result> | A | 100 | in 3 annual examinations , of which the aggregate marks of each was 500 , a student secured average marks 45 % and 55 % in the first and the second yearly examinations respectively . to secure 40 % average total marks , it is necessary for him in third yearly examination to secure marks : | {
"A": "100",
"B": "350",
"C": "400",
"D": "450",
"E": "500"
} | subtract(divide(multiply(multiply(3, 500), 40), const_100), add(divide(multiply(500, 55), const_100), divide(multiply(500, 45), const_100))) | multiply(n0,n1)|multiply(n1,n3)|multiply(n1,n2)|divide(#1,const_100)|divide(#2,const_100)|multiply(n4,#0)|add(#3,#4)|divide(#5,const_100)|subtract(#7,#6) | total marks : 1500 for three exams 40 % of 1500 = 600 first exam marks = 45 % of 500 = 225 second exam marks = 55 % of 500 = 275 let x be the third exam marks 225 + 275 + x = 600 x = 100 answer : a | general |
math_qa__wBHw6RzTlMDMpCcl | A man has some hens and cows. If the number of heads be 46 and the number of feet equals 140, then the number of hens will be: Choose the correct choice from the following options.
A) 22 B) 23 C) 24 D) 26 E) 28 | <gadget id="calculator">46 * 4</gadget>
<output>184</output>
<gadget id="calculator">184 - 140</gadget>
<output>44</output>
<gadget id="calculator">44 / 2</gadget>
<output>22</output>
<result>A</result> | A | 22 | A man has some hens and cows. If the number of heads be 46 and the number of feet equals 140, then the number of hens will be: | {
"A": "22",
"B": "23",
"C": "24",
"D": "26",
"E": "28"
} | divide(subtract(multiply(46, const_4), 140), const_2) | multiply(n0,const_4)|subtract(#0,n1)|divide(#1,const_2)| | "let hens be x and cows be y now , feet : x * 2 + y * 4 = 140 heads : x * 1 + y * 1 = 46 implies , 2 x + 4 y = 140 and x + y = 46 solving these two equations , we get x = 22 and y = 24 therefore , hens are 22 . answer : a" | general |
math_qa__vhsiUXzcmtomusaZ | Two negative numbers are multiplied to give a product of 48. If the lesser number is 10 less than thrice the greater number, what is the greater number? Choose the most appropriate option:
A) - 6
B) - 8
C) - 5
D) - 9
E) - 10 | <gadget id="calculator">10 ** 2</gadget>
<output>100</output>
<gadget id="calculator">-48</gadget>
<output>-48</output>
<gadget id="calculator">(-48) * 3</gadget>
<output>-144</output>
<gadget id="calculator">(-144) * 4</gadget>
<output>-576</output>
<gadget id="calculator">100 - (-576)</gadget>
<output>676</output>
<gadget id="calculator">676 ** (1/2)</gadget>
<output>26</output>
<gadget id="calculator">-26</gadget>
<output>-26</output>
<gadget id="calculator">(-26) - 10</gadget>
<output>-36</output>
<gadget id="calculator">2 * 3</gadget>
<output>6</output>
<gadget id="calculator">(-36) / 6</gadget>
<output>-6</output>
<result>A</result> | A | -6 | Two negative numbers are multiplied to give a product of 48. If the lesser number is 10 less than thrice the greater number, what is the greater number? | {
"A": "- 6",
"B": "- 8",
"C": "- 5",
"D": "- 9",
"E": "- 10"
} | divide(subtract(negate(sqrt(subtract(power(10, const_2), multiply(multiply(negate(48), const_3), const_4)))), 10), multiply(const_2, const_3)) | multiply(const_2,const_3)|negate(n0)|power(n1,const_2)|multiply(#1,const_3)|multiply(#3,const_4)|subtract(#2,#4)|sqrt(#5)|negate(#6)|subtract(#7,n1)|divide(#8,#0) | test the options . the options give you the greater number . ( a ) - 6 triple of - 6 is - 18 and 10 less is - 8 . - 8 * - 6 = 48 ( correct ) correct answer ( a ) | general |
math_qa__2tSRP1qYawWcFNeD | Light glows for every 13 seconds . How many times did it between 1:57:58 and 3:20:47 am Choose one:
A) 381
B) 382
C) 383
D) 384
E) 385 | <gadget id="calculator">2 + 47</gadget>
<output>49</output>
<gadget id="calculator">2 + 60</gadget>
<output>62</output>
<gadget id="calculator">20 + 62</gadget>
<output>82</output>
<gadget id="calculator">82 * 60</gadget>
<output>4_920</output>
<gadget id="calculator">49 + 4_920</gadget>
<output>4_969</output>
<gadget id="calculator">4_969 / 13</gadget>
<output>4_969/13 = around 382.230769</output>
<result>C</result> | C | 383 | Light glows for every 13 seconds . How many times did it between 1:57:58 and 3:20:47 am | {
"A": "381",
"B": "382",
"C": "383",
"D": "384",
"E": "385"
} | divide(add(add(const_2, 47), multiply(add(20, add(const_2, const_60)), const_60)), 13) | add(n6,const_2)|add(const_2,const_60)|add(n5,#1)|multiply(#2,const_60)|add(#0,#3)|divide(#4,n0) | the diff in sec between 1 : 57 : 58 and 3 : 20 : 47 is 4969 sec , 4969 / 13 = 382 . so total 383 times light ll glow answer : c | physics |
math_qa__YfJKPeuwCyzBakjE | if 7 men and 2 boys working together , can do 6 times as much work per hour as a man and a boy together . find the ratio of the work done by a man and that of a boy for a given time ?
Select the correct option: A) 2 : 5 B) 2 : 3 C) 1 : 8 D) 4 : 1 E) 3 : 2 | <gadget id="calculator">2 + 2</gadget>
<output>4</output>
<gadget id="calculator">4 / 1</gadget>
<output>4</output>
<result>D</result> | D | 4 | if 7 men and 2 boys working together , can do 6 times as much work per hour as a man and a boy together . find the ratio of the work done by a man and that of a boy for a given time ? | {
"A": "2 : 5",
"B": "2 : 3",
"C": "1 : 8",
"D": "4 : 1",
"E": "3 : 2"
} | divide(add(2, 2), const_1) | add(n1,n1)|divide(#0,const_1) | 7 m + 2 b = 6 ( 1 m + 1 b ) 7 m + 2 b = 6 m + 6 b 1 m = 4 b the required ratio of work done by a man and a boy = 4 : 1 answer : d | physics |
math_qa__Kld3IjNUky4YACC7 | If x is 20 percent greater than 52, then x = Choose the correct answer:
A) 68 B) 62.4 C) 86 D) 72.8 E) 108 | <gadget id="calculator">20 / 100</gadget>
<output>1/5 = around 0.2</output>
<gadget id="calculator">(1/5) * 52</gadget>
<output>52/5 = around 10.4</output>
<gadget id="calculator">52 + (52/5)</gadget>
<output>312/5 = around 62.4</output>
<result>B</result> | B | 62.4 | If x is 20 percent greater than 52, then x = | {
"A": "68",
"B": "62.4",
"C": "86",
"D": "72.8",
"E": "108"
} | add(52, multiply(divide(20, const_100), 52)) | divide(n0,const_100)|multiply(n1,#0)|add(n1,#1)| | "x is 20 % greater than 52 means x is 1.2 times 52 ( in other words 52 + 20 / 100 * 52 = 1.2 * 52 ) therefore , x = 1.2 * 88 = 62.4 answer : b" | general |
math_qa__b13R2H79Ln3pEeET | A girl was asked to multiply a certain number by 43. She multiplied it by 34 and got his answer less than the correct one by 1215. Find the number to be multiplied. Choose the correct choice from the following choices:
A) 130 B) 132 C) 135 D) 136 E) 138 | <gadget id="calculator">43 - 34</gadget>
<output>9</output>
<gadget id="calculator">1_215 / 9</gadget>
<output>135</output>
<result>C</result> | C | 135 | A girl was asked to multiply a certain number by 43. She multiplied it by 34 and got his answer less than the correct one by 1215. Find the number to be multiplied. | {
"A": "130",
"B": "132",
"C": "135",
"D": "136",
"E": "138"
} | divide(1215, subtract(43, 34)) | subtract(n0,n1)|divide(n2,#0) | let the required number be x . then , 43 x – 34 x = 1215 or 9 x = 1215 or x = 135 . required number = 135 answer : c | general |
math_qa__xKFgz2WcPtRhg2iW | There is 60 lit of milk and water in which milk forms 84%.Howmuch water must be added to this solution to make it solution in which milk forms 64% Options: A) 18.75 B) 19.75 C) 20.75 D) 21.75 E) 22.75 | <gadget id="calculator">100 / 64</gadget>
<output>25/16 = around 1.5625</output>
<gadget id="calculator">60 * 84</gadget>
<output>5_040</output>
<gadget id="calculator">5_040 / 100</gadget>
<output>252/5 = around 50.4</output>
<gadget id="calculator">(25/16) * (252/5)</gadget>
<output>315/4 = around 78.75</output>
<gadget id="calculator">(315/4) - 60</gadget>
<output>75/4 = around 18.75</output>
<result>A</result> | A | 18.75 | There is 60 lit of milk and water in which milk forms 84%.Howmuch water must be added to this solution to make it solution in which milk forms 64% | {
"A": "18.75",
"B": "19.75",
"C": "20.75",
"D": "21.75",
"E": "22.75"
} | subtract(multiply(divide(const_100, 64), divide(multiply(60, 84), const_100)), 60) | divide(const_100,n2)|multiply(n0,n1)|divide(#1,const_100)|multiply(#0,#2)|subtract(#3,n0)| | "60 * 84 / 100 = 50.40 lit milk that is 9.60 lit water let x lit water will be added then ( 60 + x ) * 64 / 100 = 50.40 so x = 18.75 answer : a" | gain |
math_qa__OYJqjyiqGE1ZTp34 | If x+y=-10, and x=25/y, what is the value of x^2+y^2? Choose one
A) 55 B) 65 C) 50 D) 75 E) 85 | <gadget id="calculator">10 ** 2</gadget>
<output>100</output>
<gadget id="calculator">2 * 25</gadget>
<output>50</output>
<gadget id="calculator">100 - 50</gadget>
<output>50</output>
<result>C</result> | C | 50 | If x+y=-10, and x=25/y, what is the value of x^2+y^2? | {
"A": "55",
"B": "65",
"C": "50",
"D": "75",
"E": "85"
} | subtract(power(10, 2), multiply(2, 25)) | multiply(n1,n2)|power(n0,n2)|subtract(#1,#0)| | "x ^ 2 + y ^ 2 should make you think of these formulas : ( x + y ) ( x + y ) = x ^ 2 + y ^ 2 + 2 xy we already know ( x + y ) = - 10 and x * y = 25 ( x + y ) ( x + y ) = ( - 10 ) ( - 10 ) = x ^ 2 + y ^ 2 + 2 * ( 25 ) x ^ 2 + y ^ 2 = 100 - 50 = 50 answer : c" | general |
math_qa__yWnZ4Rm3K3m1zhhs | A type R machine can complete a job in 5 hours and a type B machine can complete the job in 7 hours. How many hours will it take 2 type R machines and 3 type B machines working together and independently to complete the job?
Pick.
A) 1 / 5 B) 29 / 35 C) 5 / 6 D) 35 / 29 E) 35 / 12 | <gadget id="calculator">2 / 5</gadget>
<output>2/5 = around 0.4</output>
<gadget id="calculator">3 / 7</gadget>
<output>3/7 = around 0.428571</output>
<gadget id="calculator">(2/5) + (3/7)</gadget>
<output>29/35 = around 0.828571</output>
<gadget id="calculator">1 / (29/35)</gadget>
<output>35/29 = around 1.206897</output>
<result>D</result> | D | 1.206897 | A type R machine can complete a job in 5 hours and a type B machine can complete the job in 7 hours. How many hours will it take 2 type R machines and 3 type B machines working together and independently to complete the job? | {
"A": "1 / 5",
"B": "29 / 35",
"C": "5 / 6",
"D": "35 / 29",
"E": "35 / 12"
} | divide(const_1, add(divide(2, 5), divide(3, 7))) | divide(n2,n0)|divide(n3,n1)|add(#0,#1)|divide(const_1,#2) | now d should be the answer . r need 5 hours to complete and b needs 7 hours to compete so 2 r + 3 b will complete 2 / 5 + 3 / 7 or 29 / 35 portion of the job in 1 hour so the whole job will take 35 / 29 hours . . . . = d | physics |
math_qa__AlAOoR70jwU17drn | The speed of a boat in still water in 42 km/hr and the rate of current is 6 km/hr. The distance travelled downstream in 44 minutes is: Pick.
A) 86.6 km B) 46.6 km C) 35.2 km D) 35.6 km E) 26.6 km | <gadget id="calculator">42 + 6</gadget>
<output>48</output>
<gadget id="calculator">44 / 60</gadget>
<output>11/15 = around 0.733333</output>
<gadget id="calculator">48 * (11/15)</gadget>
<output>176/5 = around 35.2</output>
<result>C</result> | C | 35.2 | The speed of a boat in still water in 42 km/hr and the rate of current is 6 km/hr. The distance travelled downstream in 44 minutes is: | {
"A": "86.6 km",
"B": "46.6 km",
"C": "35.2 km",
"D": "35.6 km",
"E": "26.6 km"
} | multiply(add(42, 6), divide(44, const_60)) | add(n0,n1)|divide(n2,const_60)|multiply(#0,#1)| | "speed downstream = ( 42 + 6 ) = 48 kmph time = 44 minutes = 44 / 60 hour = 11 / 15 hour distance travelled = time × speed = 11 / 15 × 48 = 35.2 km answer : c" | physics |
math_qa__Lu0Gi67p7brcAoPL | A basketball team composed of 12 players scored 100 points in a particular contest. If none of the individual players scored fewer than 7 points, what is the greatest number of points L that an individual player might have scored? Select the correct option
A) 7 B) 13 C) 16 D) 21 E) 23 | <gadget id="calculator">12 * 7</gadget>
<output>84</output>
<gadget id="calculator">100 - 84</gadget>
<output>16</output>
<gadget id="calculator">16 + 7</gadget>
<output>23</output>
<result>E</result> | E | 23 | A basketball team composed of 12 players scored 100 points in a particular contest. If none of the individual players scored fewer than 7 points, what is the greatest number of points L that an individual player might have scored? | {
"A": "7",
"B": "13",
"C": "16",
"D": "21",
"E": "23"
} | add(subtract(100, multiply(12, 7)), 7) | multiply(n0,n2)|subtract(n1,#0)|add(n2,#1)| | "general rule for such kind of problems : to maximize one quantity , minimize the others ; to minimize one quantity , maximize the others . thus to maximize the number of points of one particular player minimize the number of points of all other 11 players . minimum number of points for a player is 7 , so the minimum number of points of 11 players is 7 * 11 = 77 . therefore , the maximum number of points l for 12 th player is 100 - 77 = 23 . answer : e ." | general |
math_qa__HrBnyusQPPUrx9WP | Find the value of log y(x4) if logx(y3) = 2 Choose the correct choice from the following answers: A) 2 B) 4 C) 6 D) 8 E) 9 | <gadget id="calculator">4 + 2</gadget>
<output>6</output>
<result>C</result> | C | 6 | Find the value of log y(x4) if logx(y3) = 2 | {
"A": "2",
"B": "4",
"C": "6",
"D": "8",
"E": "9"
} | add(4, 2) | add(n0,n2) | logx ( y 3 ) = 2 : given x 2 = y 3 : rewrite in exponential form x 4 = y 6 : square both sides x 4 = y 6 : rewrite the above using the log base y logy ( x 4 ) = logy ( y 6 ) = 6 correct answer c | general |
math_qa__e4ntS6e1yzAGIZJd | Arun and Tarun can do a work in 10 days.After 4 days tarun went to his village.How many days are required to complete the remaining work by Arun alone.Arun can do the work alone in 70 days. Choose the correct choice from the following options
A) 16 days . B) 17 days . C) 18 days . D) 19 days . E) 42 days . | <gadget id="calculator">70 / 10</gadget>
<output>7</output>
<gadget id="calculator">7 * 4</gadget>
<output>28</output>
<gadget id="calculator">70 - 28</gadget>
<output>42</output>
<result>E</result> | E | 42 | Arun and Tarun can do a work in 10 days.After 4 days tarun went to his village.How many days are required to complete the remaining work by Arun alone.Arun can do the work alone in 70 days. | {
"A": "16 days .",
"B": "17 days .",
"C": "18 days .",
"D": "19 days .",
"E": "42 days ."
} | subtract(70, multiply(divide(70, 10), 4)) | divide(n2,n0)|multiply(n1,#0)|subtract(n2,#1)| | "they together completed 4 / 10 work in 4 days . balance 6 / 10 work will be completed by arun alone in 70 * 6 / 10 = 42 days . answer : e" | physics |
math_qa__4Ow2lJayx1wfae8Y | A 100-litre mixture of milk and water contains 36 litres of milk. 'x' litres of this mixture is removed and replaced with an equal quantum of water. If the process is repeated once, then the concentration of the milk stands reduced at 16%. What is the value of x? Choose the correct choice from the following options:
A) 37.5 litres B) 36.67 litres C) 37.67 litres D) 36.5 litres E) 33.33 litres | <gadget id="calculator">16 / 36</gadget>
<output>4/9 = around 0.444444</output>
<gadget id="calculator">(4/9) ** (1/2)</gadget>
<output>2/3 = around 0.666667</output>
<gadget id="calculator">1 - (2/3)</gadget>
<output>1/3 = around 0.333333</output>
<gadget id="calculator">100 * (1/3)</gadget>
<output>100/3 = around 33.333333</output>
<result>E</result> | E | 33.33 | A 100-litre mixture of milk and water contains 36 litres of milk. 'x' litres of this mixture is removed and replaced with an equal quantum of water. If the process is repeated once, then the concentration of the milk stands reduced at 16%. What is the value of x? | {
"A": "37.5 litres",
"B": "36.67 litres",
"C": "37.67 litres",
"D": "36.5 litres",
"E": "33.33 litres"
} | multiply(100, subtract(const_1, sqrt(divide(16, 36)))) | divide(n2,n1)|sqrt(#0)|subtract(const_1,#1)|multiply(n0,#2)| | "working formula . . . initial concentration * initial volume = final concentration * final volume . let x is the part removed from 100 lts . 36 % ( 1 - x / 100 ) ^ 2 = 16 % * 100 % ( 1 - x / 100 ) ^ 2 = 16 / 36 - - - - - - > ( 1 - x / 100 ) ^ 2 = ( 4 / 6 ) ^ 2 100 - x = 400 / 6 x = 33.33 . . . ans e" | general |
math_qa__kTeOAC7syoOBGB5D | A man’s current age is (2/5) of the age of his father. After 5 years, he will be (1/2) of the age of his father. What is the age of father at now? Choose the correct answer:
A) 40 B) 25 C) 38 D) 50 E) 39 | <gadget id="calculator">1 / 2</gadget>
<output>1/2 = around 0.5</output>
<gadget id="calculator">5 * (1/2)</gadget>
<output>5/2 = around 2.5</output>
<gadget id="calculator">5 - (5/2)</gadget>
<output>5/2 = around 2.5</output>
<gadget id="calculator">2 / 5</gadget>
<output>2/5 = around 0.4</output>
<gadget id="calculator">(1/2) - (2/5)</gadget>
<output>1/10 = around 0.1</output>
<gadget id="calculator">(5/2) / (1/10)</gadget>
<output>25</output>
<result>B</result> | B | 25 | A man’s current age is (2/5) of the age of his father. After 5 years, he will be (1/2) of the age of his father. What is the age of father at now? | {
"A": "40",
"B": "25",
"C": "38",
"D": "50",
"E": "39"
} | divide(subtract(5, multiply(5, divide(1, 2))), subtract(divide(1, 2), divide(2, 5))) | divide(n3,n0)|divide(n0,n1)|multiply(n2,#0)|subtract(#0,#1)|subtract(n2,#2)|divide(#4,#3)| | "let , father â € ™ s current age is a years . then , man â € ™ s current age = [ ( 2 / 5 ) a ] years . therefore , [ ( 2 / 5 ) a + 5 ] = ( 1 / 2 ) ( a + 5 ) 2 ( 2 a + 25 ) = 5 ( a + 8 ) a = 25 b" | general |
math_qa__xlHtfeHA0GcBrQRi | After an ice began to melt out from the freezer, in the first hour lost 3/4, in the second hour lost 3/4 of its remaining. If after two hours, the volume is 0.75 cubic inches, what is the original volume of the cubic ice, in cubic inches? Choose the correct choice from the following answers:
A) 2.5 B) 3.0 C) 4.0 D) 6.5 E) 12.0 | <gadget id="calculator">1 / 4</gadget>
<output>1/4 = around 0.25</output>
<gadget id="calculator">0.75 / (1/4)</gadget>
<output>3</output>
<gadget id="calculator">3 / (1/4)</gadget>
<output>12</output>
<result>E</result> | E | 12 | After an ice began to melt out from the freezer, in the first hour lost 3/4, in the second hour lost 3/4 of its remaining. If after two hours, the volume is 0.75 cubic inches, what is the original volume of the cubic ice, in cubic inches? | {
"A": "2.5",
"B": "3.0",
"C": "4.0",
"D": "6.5",
"E": "12.0"
} | divide(divide(0.75, const_0_25), const_0_25) | divide(n4,const_0_25)|divide(#0,const_0_25)| | "let initial volume of ice be = x ice remaining after 1 hour = x - 0.75 x = 0.25 x ice remaining after 2 hour = ( 1 / 4 ) x - ( 3 / 4 * 1 / 4 * x ) = ( 1 / 16 ) x ( 1 / 16 ) x = 0.75 x = 12 alternate solution : try to backsolve . initial volume = 12 after one hour - - > ( 1 / 4 ) 12 = 3 after two hours - - > ( 1 / 4 ) 3 = 0.75 answer : e" | physics |
math_qa__P0zwlAJiotwimEVN | A shopkeeper bought 600 oranges and 400 bananas. He found 15% of oranges and 3% of bananas were rotten. Find the percentage of fruits in good condition?
Choose the correct option: A) 92.5 % B) 89.8 % C) 85.2 % D) 96.8 % E) 78.9 % | <gadget id="calculator">600 + 400</gadget>
<output>1_000</output>
<gadget id="calculator">15 / 100</gadget>
<output>3/20 = around 0.15</output>
<gadget id="calculator">600 * (3/20)</gadget>
<output>90</output>
<gadget id="calculator">3 / 100</gadget>
<output>3/100 = around 0.03</output>
<gadget id="calculator">400 * (3/100)</gadget>
<output>12</output>
<gadget id="calculator">90 + 12</gadget>
<output>102</output>
<gadget id="calculator">1_000 - 102</gadget>
<output>898</output>
<gadget id="calculator">898 / 1_000</gadget>
<output>449/500 = around 0.898</output>
<gadget id="calculator">(449/500) * 100</gadget>
<output>449/5 = around 89.8</output>
<result>B</result> | B | 89.8 | A shopkeeper bought 600 oranges and 400 bananas. He found 15% of oranges and 3% of bananas were rotten. Find the percentage of fruits in good condition? | {
"A": "92.5 %",
"B": "89.8 %",
"C": "85.2 %",
"D": "96.8 %",
"E": "78.9 %"
} | multiply(divide(subtract(add(600, 400), add(multiply(600, divide(15, const_100)), multiply(400, divide(3, const_100)))), add(600, 400)), const_100) | add(n0,n1)|divide(n2,const_100)|divide(n3,const_100)|multiply(n0,#1)|multiply(n1,#2)|add(#3,#4)|subtract(#0,#5)|divide(#6,#0)|multiply(#7,const_100) | total number of fruits shopkeeper bought = 600 + 400 = 1000 number of rotten oranges = 15 % of 600 = 15 / 100 × 600 = 9000 / 100 = 90 number of rotten bananas = 3 % of 400 = 12 therefore , total number of rotten fruits = 90 + 12 = 102 therefore number of fruits in good condition = 1000 - 102 = 898 therefore percentage of fruits in good condition = ( 898 / 1000 × 100 ) % = ( 89800 / 1000 ) % = 89.8 % answer : b | gain |
math_qa__Nvy0iAaxqKqf8CUH | Bruce purchased 9kg of grapes at the rate of 70 per kg and 9 kg of mangoes at the rate of 55 per kg. How much amount did he pay to the shopkeeper? Pick
A) 1040
B) 1050
C) 1055
D) 1065
E) 1125 | <gadget id="calculator">9 * 70</gadget>
<output>630</output>
<gadget id="calculator">9 * 55</gadget>
<output>495</output>
<gadget id="calculator">630 + 495</gadget>
<output>1_125</output>
<result>E</result> | E | 1,125 | Bruce purchased 9kg of grapes at the rate of 70 per kg and 9 kg of mangoes at the rate of 55 per kg. How much amount did he pay to the shopkeeper? | {
"A": "1040",
"B": "1050",
"C": "1055",
"D": "1065",
"E": "1125"
} | add(multiply(9, 70), multiply(9, 55)) | multiply(n0,n1)|multiply(n2,n3)|add(#0,#1)| | "cost of 9 kg grapes = 70 × 9 = 630 . cost of 9 kg of mangoes = 55 × 9 = 495 total cost he has to pay = 630 + 495 = 1125 e" | gain |
math_qa__tWuLExqVPiGPayqx | The batting average of a particular batsman is 60 runs in 46 innings. If the difference in his highest and lowest score is 180 runs and his average excluding these two innings is 58 runs, find his highest score. Choose the correct choice from the following answers
A) 179 B) 194 C) 269 D) 177 E) 191 | <gadget id="calculator">60 * 46</gadget>
<output>2_760</output>
<gadget id="calculator">46 - 2</gadget>
<output>44</output>
<gadget id="calculator">58 * 44</gadget>
<output>2_552</output>
<gadget id="calculator">2_760 - 2_552</gadget>
<output>208</output>
<gadget id="calculator">180 + 208</gadget>
<output>388</output>
<gadget id="calculator">388 / 2</gadget>
<output>194</output>
<result>B</result> | B | 194 | The batting average of a particular batsman is 60 runs in 46 innings. If the difference in his highest and lowest score is 180 runs and his average excluding these two innings is 58 runs, find his highest score. | {
"A": "179",
"B": "194",
"C": "269",
"D": "177",
"E": "191"
} | divide(add(180, subtract(multiply(60, 46), multiply(58, subtract(46, const_2)))), const_2) | multiply(n0,n1)|subtract(n1,const_2)|multiply(n3,#1)|subtract(#0,#2)|add(n2,#3)|divide(#4,const_2)| | "explanation : total runs scored by the batsman = 60 * 46 = 2760 runs now excluding the two innings the runs scored = 58 * 44 = 2552 runs hence the runs scored in the two innings = 2760 â € “ 2552 = 208 runs . let the highest score be x , hence the lowest score = x â € “ 180 x + ( x - 180 ) = 208 2 x = 388 x = 194 runs answer : b" | general |
math_qa__3xMzX0pmXnhL2yZi | The average weight of 19 students is 15kg. by the admission of a new student the average weight is reduced to 14.8 kg. the weight of the new student is ?
Choose the correct choice from the following choices.
A) 10.6 kg
B) 10.8 kg
C) 11 kg
D) 14.9 kg
E) none | <gadget id="calculator">19 + 1</gadget>
<output>20</output>
<gadget id="calculator">20 * 14.8</gadget>
<output>296</output>
<gadget id="calculator">19 * 15</gadget>
<output>285</output>
<gadget id="calculator">296 - 285</gadget>
<output>11</output>
<result>C</result> | C | 11 | The average weight of 19 students is 15kg. by the admission of a new student the average weight is reduced to 14.8 kg. the weight of the new student is ? | {
"A": "10.6 kg",
"B": "10.8 kg",
"C": "11 kg",
"D": "14.9 kg",
"E": "none"
} | subtract(multiply(add(19, const_1), 14.8), multiply(19, 15)) | add(n0,const_1)|multiply(n0,n1)|multiply(n2,#0)|subtract(#2,#1) | answer weight of new student = total weight of all 20 students - total weight of initial 19 students = ( 20 x 14.8 - 19 x 15 ) kg = 11 kg . correct option : c | general |
math_qa__cebhPypO79MV24QQ | The total age of A and B is 16 years more than the total age of B and C. C is how many year younger than A Answers
A) 11 B) 16 C) 13 D) 14 E) 15 | <gadget id="calculator">16 * 1</gadget>
<output>16</output>
<result>B</result> | B | 16 | The total age of A and B is 16 years more than the total age of B and C. C is how many year younger than A | {
"A": "11",
"B": "16",
"C": "13",
"D": "14",
"E": "15"
} | multiply(16, const_1) | multiply(n0,const_1)| | "explanation : given that a + b = 16 + b + c = > a ? c = 16 + b ? b = 16 = > c is younger than a by 16 years answer : option b" | general |
math_qa__NxJOKAK5TB87w2rJ | If 6 men and 8 boys can do a piece of work in 10 days while 26 men and 48 boys can do the same in 2 days, the time taken by 15 men and 20 boys in doing the same type of work will be: Choose the correct choice from the following choices: A) 4 days B) 5 days C) 6 days D) 8 days E) 2 days | <gadget id="calculator">6 + 4</gadget>
<output>10</output>
<gadget id="calculator">10 * 10</gadget>
<output>100</output>
<gadget id="calculator">15 + 10</gadget>
<output>25</output>
<gadget id="calculator">100 / 25</gadget>
<output>4</output>
<result>A</result> | A | 4 | If 6 men and 8 boys can do a piece of work in 10 days while 26 men and 48 boys can do the same in 2 days, the time taken by 15 men and 20 boys in doing the same type of work will be: | {
"A": "4 days",
"B": "5 days",
"C": "6 days",
"D": "8 days",
"E": "2 days"
} | divide(multiply(add(6, const_4), 10), add(15, 10)) | add(n0,const_4)|add(n2,n6)|multiply(n2,#0)|divide(#2,#1) | let 1 man ' s 1 day ' s work = x and 1 boy ' s 1 day ' s work = y . then , 6 x + 8 y = 1 / 10 and 26 x + 48 y = 1 / 2 solving these two equations , we get : x = 1 / 100 and y = 1 / 200 ( 15 men + 20 boy ) ' s 1 day ' s work = ( 15 / 100 + 20 / 200 ) = 1 / 4 . 15 men and 20 boys can do the work in 4 days . answer : a | physics |
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