id stringlengths 25 25 | question stringlengths 45 1.01k | chain stringlengths 75 4.11k | result stringclasses 5 values | result_float float64 -4,212 100B | question_without_options stringlengths 6 962 | options dict | annotated_formula stringlengths 7 6.48k | linear_formula stringlengths 8 925 | rationale stringlengths 1 2.74k | category stringclasses 6 values |
|---|---|---|---|---|---|---|---|---|---|---|
math_qa__CVaemBw6EqcgYOMT | What profit percent is made by selling an article at a certain price, if by selling at 2/3rd of that price, there would be a loss of 10%? Choose the correct choice from the following answers
A) 20 %
B) 28 %
C) 27 %
D) 35 %
E) 70 % | <gadget id="calculator">100 - 10</gadget>
<output>90</output>
<gadget id="calculator">2 / 3</gadget>
<output>2/3 = around 0.666667</output>
<gadget id="calculator">90 / (2/3)</gadget>
<output>135</output>
<gadget id="calculator">135 - 100</gadget>
<output>35</output>
<result>D</result> | D | 35 | What profit percent is made by selling an article at a certain price, if by selling at 2/3rd of that price, there would be a loss of 10%? | {
"A": "20 %",
"B": "28 %",
"C": "27 %",
"D": "35 %",
"E": "70 %"
} | subtract(divide(subtract(const_100, 10), divide(2, 3)), const_100) | divide(n0,n1)|subtract(const_100,n2)|divide(#1,#0)|subtract(#2,const_100)| | "sp 2 = 2 / 3 sp 1 cp = 100 sp 2 = 90 2 / 3 sp 1 = 90 sp 1 = 135 100 - - - 35 = > 35 % answer : d" | gain |
math_qa__QN7I5abkn559x4ny | Out of 40 applicants to a law school, 15 majored in political science, 20 had a grade point average higher than 3.0, and 10 did not major in political science and had a GPA equal to or lower than 3.0. How many W applicants majored in political science and had a GPA higher than 3.0? Choose one
A) 5 B) 10 C) 15 D) 25 E) 35 | <gadget id="calculator">10 + 15</gadget>
<output>25</output>
<gadget id="calculator">40 - 25</gadget>
<output>15</output>
<gadget id="calculator">20 - 15</gadget>
<output>5</output>
<result>A</result> | A | 5 | Out of 40 applicants to a law school, 15 majored in political science, 20 had a grade point average higher than 3.0, and 10 did not major in political science and had a GPA equal to or lower than 3.0. How many W applicants majored in political science and had a GPA higher than 3.0? | {
"A": "5",
"B": "10",
"C": "15",
"D": "25",
"E": "35"
} | subtract(20, subtract(40, add(10, 15))) | add(n1,n4)|subtract(n0,#0)|subtract(n2,#1)| | "total applicants = 40 political science = 15 and non political science = 40 - 15 = 25 gpa > 3.0 = 20 and gpa < = 3.0 = 20 10 non political science students had gpa < = 3.0 - - > 15 non political science students had gpa > 3.0 gpa > 3.0 in political science = total - ( gpa > 3.0 in non political science ) w = 20 - 15 = 5 answer : a" | general |
math_qa__rS3vBVW09prxMNC3 | The price of a car and AC are in the ratio 3:2. If the scooter costs $500 more than the AC. then the price of the AC?
Choose the correct choice from the following options.
A) 1500 B) 200 C) 1700 D) 2000 E) 2500 | <gadget id="calculator">500 * 3</gadget>
<output>1_500</output>
<result>A</result> | A | 1,500 | The price of a car and AC are in the ratio 3:2. If the scooter costs $500 more than the AC. then the price of the AC? | {
"A": "1500",
"B": "200",
"C": "1700",
"D": "2000",
"E": "2500"
} | multiply(500, const_3) | multiply(n2,const_3) | let the price of the car and ac is 3 x and 2 x 3 x - 2 x = 500 x = 500 price of ac = 3 * 500 = $ 1500 answer is a | other |
math_qa__k5lu4Nop45wQST0c | A shopkeeper sold an article offering a discount of 4% and earned a profit of 44%. What would have been the percentage of profit earned if no discount was offered?
Select:
A) 24
B) 28
C) 30
D) 32
E) 50 | <gadget id="calculator">100 + 44</gadget>
<output>144</output>
<gadget id="calculator">144 * 100</gadget>
<output>14_400</output>
<gadget id="calculator">100 - 4</gadget>
<output>96</output>
<gadget id="calculator">14_400 / 96</gadget>
<output>150</output>
<gadget id="calculator">150 - 100</gadget>
<output>50</output>
<result>E</result> | E | 50 | A shopkeeper sold an article offering a discount of 4% and earned a profit of 44%. What would have been the percentage of profit earned if no discount was offered? | {
"A": "24",
"B": "28",
"C": "30",
"D": "32",
"E": "50"
} | subtract(divide(multiply(add(const_100, 44), const_100), subtract(const_100, 4)), const_100) | add(n1,const_100)|subtract(const_100,n0)|multiply(#0,const_100)|divide(#2,#1)|subtract(#3,const_100)| | "let c . p . be rs . 100 . then , s . p . = rs . 144 let marked price be rs . x . then , 96 / 100 x = 144 x = 14400 / 96 = rs . 150 now , s . p . = rs . 150 , c . p . = rs . 100 profit % = 50 % . answer : e" | gain |
math_qa__JY24BFPeBE9AmbBm | The cost per pound of green tea and coffee were the same in June. In July, the price of coffee shot up by 100% and that of green tea dropped by 70%. If in July, a mixture containing equal quantities of green tea and coffee costs $3.45 for 3lbs, how much did a pound of green tea cost in July? Choices
A) $ 4 B) $ 0.3 C) $ 1 D) $ 3 E) $ 1.65 | <gadget id="calculator">100 + 100</gadget>
<output>200</output>
<gadget id="calculator">200 / 100</gadget>
<output>2</output>
<gadget id="calculator">3 / 2</gadget>
<output>3/2 = around 1.5</output>
<gadget id="calculator">2 * (3/2)</gadget>
<output>3</output>
<gadget id="calculator">100 - 70</gadget>
<output>30</output>
<gadget id="calculator">30 / 100</gadget>
<output>3/10 = around 0.3</output>
<gadget id="calculator">(3/2) * (3/10)</gadget>
<output>9/20 = around 0.45</output>
<gadget id="calculator">3 + (9/20)</gadget>
<output>69/20 = around 3.45</output>
<gadget id="calculator">(69/20) / 3.45</gadget>
<output>1</output>
<gadget id="calculator">1 * (3/10)</gadget>
<output>3/10 = around 0.3</output>
<result>B</result> | B | 0.3 | The cost per pound of green tea and coffee were the same in June. In July, the price of coffee shot up by 100% and that of green tea dropped by 70%. If in July, a mixture containing equal quantities of green tea and coffee costs $3.45 for 3lbs, how much did a pound of green tea cost in July? | {
"A": "$ 4",
"B": "$ 0.3",
"C": "$ 1",
"D": "$ 3",
"E": "$ 1.65"
} | multiply(divide(add(multiply(divide(add(100, 100), 100), divide(3, const_2)), multiply(divide(3, const_2), divide(subtract(100, 70), 100))), 3.45), divide(subtract(100, 70), 100)) | add(n0,n0)|divide(n3,const_2)|subtract(n0,n1)|divide(#0,n0)|divide(#2,n0)|multiply(#3,#1)|multiply(#1,#4)|add(#5,#6)|divide(#7,n2)|multiply(#8,#4) | lets assume price of coffee in june = 100 x price of green tea in june = 100 x price of coffee in july = 200 x ( because of 100 % increase in price ) price of green tea in july = 30 x ( because of 70 % decrease in price ) price of 1.5 pound of coffee 1.5 pound of green tea in july will be = 300 x + 45 x = 345 x as per question 345 x = 3.45 $ x = 0.01 s so the price of tea in july = 30 x = 30 x 0.01 = 0.3 $ / pound answer b | general |
math_qa__JTD7bIUG93cH9SiB | The average weight of 10 oarsmen in a boat is increased by 1.8 kg when one of the crew, who weighs 53 kg is replaced by a new man. Find the weight of the new man. Choose the correct choice
A) 69 B) 72 C) 75 D) 71 E) none of them | <gadget id="calculator">1.8 * 10</gadget>
<output>18</output>
<gadget id="calculator">18 + 53</gadget>
<output>71</output>
<result>D</result> | D | 71 | The average weight of 10 oarsmen in a boat is increased by 1.8 kg when one of the crew, who weighs 53 kg is replaced by a new man. Find the weight of the new man. | {
"A": "69",
"B": "72",
"C": "75",
"D": "71",
"E": "none of them"
} | add(multiply(1.8, 10), 53) | multiply(n0,n1)|add(n2,#0)| | "total weight increased = ( 1.8 x 10 ) kg = 18 kg . : . weight of the new man = ( 53 + 18 ) kg = 71 kg . answer is d" | general |
math_qa__a90jqQ3T4Se2nwqH | Bill made a profit of 10% by selling a product. If he had purchased that product for 10% less and sold it at a profit of 30%, he would have received $ 49 more. What was his original selling price? Choose the correct choice from the following answers: A) $ 770 B) $ 660 C) $ 700 D) $ 1100 E) $ 840 | <gadget id="calculator">10 / 100</gadget>
<output>1/10 = around 0.1</output>
<gadget id="calculator">1 - (1/10)</gadget>
<output>9/10 = around 0.9</output>
<gadget id="calculator">30 / 100</gadget>
<output>3/10 = around 0.3</output>
<gadget id="calculator">1 + (3/10)</gadget>
<output>13/10 = around 1.3</output>
<gadget id="calculator">(9/10) * (13/10)</gadget>
<output>117/100 = around 1.17</output>
<gadget id="calculator">1 + (1/10)</gadget>
<output>11/10 = around 1.1</output>
<gadget id="calculator">(117/100) - (11/10)</gadget>
<output>7/100 = around 0.07</output>
<gadget id="calculator">49 / (7/100)</gadget>
<output>700</output>
<gadget id="calculator">700 * (11/10)</gadget>
<output>770</output>
<result>A</result> | A | 770 | Bill made a profit of 10% by selling a product. If he had purchased that product for 10% less and sold it at a profit of 30%, he would have received $ 49 more. What was his original selling price? | {
"A": "$ 770",
"B": "$ 660",
"C": "$ 700",
"D": "$ 1100",
"E": "$ 840"
} | multiply(divide(49, subtract(multiply(subtract(const_1, divide(10, const_100)), add(const_1, divide(30, const_100))), add(const_1, divide(10, const_100)))), add(const_1, divide(10, const_100))) | divide(n0,const_100)|divide(n2,const_100)|add(#0,const_1)|add(#1,const_1)|subtract(const_1,#0)|multiply(#3,#4)|subtract(#5,#2)|divide(n3,#6)|multiply(#2,#7) | let the original purchase price be x so original selling price at 10 % profit = 1.1 x if product is purchased at 10 % less of original = 0.9 x profit of 30 % on this price = 1.3 ( 0.9 x ) he would have received $ 49 more in second scenario = > 1.3 ( 0.9 x ) - 1.1 x = 49 = > 0.07 x = 49 = > x = $ 700 original purchase price = $ 700 hence , original selling price ( at 10 % of profit ) = 1.1 ( 700 ) = $ 770 option a | general |
math_qa__DDnQStoBZ2FS4jor | On a sum of money, the S.I. for 2 years is $600, while the C.I. is $612, the rate of interest being the same in both the cases. The rate of interest is? Choose the correct choice from the following answers.
A) 3 % B) 4 % C) 5 % D) 6 % E) 7 % | <gadget id="calculator">612 - 600</gadget>
<output>12</output>
<gadget id="calculator">100 * 12</gadget>
<output>1_200</output>
<gadget id="calculator">600 / 2</gadget>
<output>300</output>
<gadget id="calculator">1_200 / 300</gadget>
<output>4</output>
<result>B</result> | B | 4 | On a sum of money, the S.I. for 2 years is $600, while the C.I. is $612, the rate of interest being the same in both the cases. The rate of interest is? | {
"A": "3 %",
"B": "4 %",
"C": "5 %",
"D": "6 %",
"E": "7 %"
} | divide(multiply(const_100, subtract(612, 600)), divide(600, 2)) | divide(n1,n0)|subtract(n2,n1)|multiply(#1,const_100)|divide(#2,#0) | difference in c . i . and s . i for 2 years = $ 612 - $ 600 = $ 12 s . i for one year = $ 300 s . i . on $ 300 for 1 year = $ 12 rate = ( 100 * 12 ) / ( 300 ) = 4 % the answer is b . | gain |
math_qa__rAiDPglheEs2siHm | 3 numbers which are co - prime to each other are such that the product of the first two is 551 and that of the last two is 1073 . the sum of the 3 numbers is : Pick:
A) 81 B) 82 C) 85 D) 90 E) 95 | <gadget id="calculator">gcd(551, 1_073)</gadget>
<output>29</output>
<gadget id="calculator">551 / 29</gadget>
<output>19</output>
<gadget id="calculator">19 + 29</gadget>
<output>48</output>
<gadget id="calculator">1_073 / 29</gadget>
<output>37</output>
<gadget id="calculator">48 + 37</gadget>
<output>85</output>
<result>C</result> | C | 85 | 3 numbers which are co - prime to each other are such that the product of the first two is 551 and that of the last two is 1073 . the sum of the 3 numbers is : | {
"A": "81",
"B": "82",
"C": "85",
"D": "90",
"E": "95"
} | add(add(divide(551, gcd(551, 1073)), gcd(551, 1073)), divide(1073, gcd(551, 1073))) | gcd(n1,n2)|divide(n1,#0)|divide(n2,#0)|add(#1,#0)|add(#3,#2) | since the numbers are co - prime , they contain only 1 as the common factor . also , the given two products have the middle number in common . so , middle number = h . c . f of 551 and 1073 = 29 ; first number = 551 / 29 = 19 third number = 1073 / 29 = 37 . required sum = 19 + 29 + 37 = 85 . answer : c | general |
math_qa__HFBaABO0Sxlix4Ju | Two trains, each 100 m long, moving in opposite directions, cross other in 8 sec. If one is moving twice as fast the other, then the speed of the faster train is? Select the correct option
A) 26 km / hr
B) 17 km / hr
C) 60 km / hr
D) 77 km / hr
E) 46 km / hr | <gadget id="calculator">100 + 100</gadget>
<output>200</output>
<gadget id="calculator">1 + 2</gadget>
<output>3</output>
<gadget id="calculator">8 * 3</gadget>
<output>24</output>
<gadget id="calculator">200 / 24</gadget>
<output>25/3 = around 8.333333</output>
<gadget id="calculator">(25/3) * 2</gadget>
<output>50/3 = around 16.666667</output>
<gadget id="calculator">(50/3) * 3_600</gadget>
<output>60_000</output>
<gadget id="calculator">60_000 / 1_000</gadget>
<output>60</output>
<result>C</result> | C | 60 | Two trains, each 100 m long, moving in opposite directions, cross other in 8 sec. If one is moving twice as fast the other, then the speed of the faster train is? | {
"A": "26 km / hr",
"B": "17 km / hr",
"C": "60 km / hr",
"D": "77 km / hr",
"E": "46 km / hr"
} | divide(multiply(multiply(divide(add(100, 100), multiply(8, add(const_1, const_2))), const_2), const_3600), const_1000) | add(n0,n0)|add(const_1,const_2)|multiply(n1,#1)|divide(#0,#2)|multiply(#3,const_2)|multiply(#4,const_3600)|divide(#5,const_1000)| | "let the speed of the slower train be x m / sec . then , speed of the train = 2 x m / sec . relative speed = ( x + 2 x ) = 3 x m / sec . ( 100 + 100 ) / 8 = 3 x = > x = 25 / 3 . so , speed of the faster train = 50 / 3 = 50 / 3 * 18 / 5 = 60 km / hr . answer : c" | physics |
math_qa__E68Xizg6eWAbok6c | I flew my tiny seaplane to visit my mother. On the flight up, I flew at 110 mph. On the way home, I flew 88 mph. What was my average speed for the trip? Answers
A) 198 mph B) 110 mph C) 88 mph D) 100 mph E) 99 mph | <gadget id="calculator">110 + 88</gadget>
<output>198</output>
<gadget id="calculator">198 / 2</gadget>
<output>99</output>
<result>E</result> | E | 99 | I flew my tiny seaplane to visit my mother. On the flight up, I flew at 110 mph. On the way home, I flew 88 mph. What was my average speed for the trip? | {
"A": "198 mph",
"B": "110 mph",
"C": "88 mph",
"D": "100 mph",
"E": "99 mph"
} | divide(add(110, 88), const_2) | add(n0,n1)|divide(#0,const_2)| | "( 110 mph + 88 mph ) / 2 = 99 mph correct answer is : e" | physics |
math_qa__mS1MKfsYC1cOZb8H | A person is traveling at 65 km/hr and reached his destiny in 3 hr then find the distance?
Choose the most appropriate option.
A) 205 km B) 195 km C) 295 km D) 115 km E) 215 km | <gadget id="calculator">65 * 3</gadget>
<output>195</output>
<result>B</result> | B | 195 | A person is traveling at 65 km/hr and reached his destiny in 3 hr then find the distance? | {
"A": "205 km",
"B": "195 km",
"C": "295 km",
"D": "115 km",
"E": "215 km"
} | multiply(65, 3) | multiply(n0,n1)| | "t = 3 hrs d = t * s = 65 * 3 = 195 km answer is b" | physics |
math_qa__8RvMatGqY4X2tBS7 | Find the area of a parallelogram with base 12 cm and height 8 cm? Choose one:
A) 96 cm 2 B) 104 cm 2 C) 78 cm 2 D) 86 cm 2 E) 76 cm 2 | <gadget id="calculator">12 * 8</gadget>
<output>96</output>
<result>A</result> | A | 96 | Find the area of a parallelogram with base 12 cm and height 8 cm? | {
"A": "96 cm 2",
"B": "104 cm 2",
"C": "78 cm 2",
"D": "86 cm 2",
"E": "76 cm 2"
} | multiply(12, 8) | multiply(n0,n1)| | "area of a parallelogram = base * height = 12 * 8 = 96 cm 2 answer : a" | geometry |
math_qa__A5IoKGKqaVKpy0QD | The sum of the squares of the first 15 positive integers (1^2 + 2^2 + 3^2 + . . . + 15^2) is equal to 1260. What is the sum of the squares of the second 15 positive integers (16^2 + 17^2 + 18^2 + . . . + 30^2) ? Pick one:
A) 2480 B) 3490 C) 6785 D) 8235 E) 9255 | <gadget id="calculator">30 + 1</gadget>
<output>31</output>
<gadget id="calculator">30 * 31</gadget>
<output>930</output>
<gadget id="calculator">2 * 30</gadget>
<output>60</output>
<gadget id="calculator">60 + 1</gadget>
<output>61</output>
<gadget id="calculator">930 * 61</gadget>
<output>56_730</output>
<gadget id="calculator">3 + 3</gadget>
<output>6</output>
<gadget id="calculator">56_730 / 6</gadget>
<output>9_455</output>
<gadget id="calculator">9_455 - 1_260</gadget>
<output>8_195</output>
<result>D</result> | D | 8,235 | The sum of the squares of the first 15 positive integers (1^2 + 2^2 + 3^2 + . . . + 15^2) is equal to 1260. What is the sum of the squares of the second 15 positive integers (16^2 + 17^2 + 18^2 + . . . + 30^2) ? | {
"A": "2480",
"B": "3490",
"C": "6785",
"D": "8235",
"E": "9255"
} | subtract(divide(multiply(multiply(30, add(30, 1)), add(multiply(2, 30), 1)), add(3, 3)), 1260) | add(n17,n1)|add(n5,n5)|multiply(n17,n2)|add(#2,n1)|multiply(n17,#0)|multiply(#3,#4)|divide(#5,#1)|subtract(#6,n9)| | "you ' ll never need a formula for the sums of squares on the actual gmat . you do n ' t need to use that formula here , though it ' s not all that straightforward to solve without one . two different approaches : 16 ^ 2 + 17 ^ 2 + 18 ^ 2 + . . . + 30 ^ 2 = ( 15 + 1 ) ^ 2 + ( 15 + 2 ) ^ 2 + ( 15 + 3 ) ^ 2 + . . . + ( 15 + 15 ) ^ 2 now we can expand each square ; they are all in the ( x + y ) ^ 2 = x ^ 2 + 2 xy + y ^ 2 pattern . = ( 15 ^ 2 + 2 * 15 + 1 ^ 2 ) + ( 15 ^ 2 + 4 * 15 + 2 ^ 2 ) + ( 15 ^ 2 + 6 * 15 + 3 ^ 2 ) + . . . + ( 15 ^ 2 + 30 * 15 + 15 ^ 2 ) now we have fifteen 15 ^ 2 terms , so adding these gives 15 * 15 ^ 2 = 15 ^ 3 = 3375 . we also have the entire sum 1 ^ 2 + 2 ^ 2 + . . . + 15 ^ 2 , which we know is equal to 1240 . finally adding the middle terms , we have : 2 * 15 + 4 * 15 + 6 * 15 + . . . + 30 * 15 = 15 ( 2 + 4 + 6 + . . . . + 30 ) = 15 * 2 * ( 1 + 2 + 3 + . . . + 15 ) = 15 * 2 * 8 * 15 = 3600 so the sum must be 3375 + 1240 + 3600 = 8215 alternatively , we can use a different factoring pattern . we want to find the value of 30 ^ 2 + 29 ^ 2 + . . . + 17 ^ 2 + 16 ^ 2 . well if we subtract 15 ^ 2 + 14 ^ 2 + . . . . + 2 ^ 2 + 1 ^ 2 from this , the answer will be 1240 less than what we want to find . so if we can find the value of 30 ^ 2 + 29 ^ 2 + . . . + 17 ^ 2 + 16 ^ 2 - ( 15 ^ 2 + 14 ^ 2 + . . . . + 2 ^ 2 + 1 ^ 2 ) then we can add 1240 to get the answer . now grouping the terms above to get differences of squares , we have = ( 30 ^ 2 - 15 ^ 2 ) + ( 29 ^ 2 - 14 ^ 2 ) + . . . + ( 16 ^ 2 - 1 ^ 2 ) and factoring each of these using x ^ 2 - y ^ 2 = ( x + y ) ( x - y ) , we have = 45 * 15 + 43 * 15 + 41 * 15 + . . . + 17 * 15 = 15 ( 45 + 43 + 41 + . . . + 17 ) in brackets we have an equally spaced sum with fifteen terms , which we can evaluate using the familiar formula . so the above equals 15 * 15 * 62 / 2 = 6975 and adding back the 1260 , we get the answer of 8235 . ( ans d )" | general |
math_qa__pZiOh3VHWpySfUih | If the annual increase in the population of a town is 4% and the present number of people is 15625, what will the population be in 3 years? Choose the most appropriate option: A) 15265 B) 16458 C) 25600 D) 17576 E) 14785 | <gadget id="calculator">4 + 100</gadget>
<output>104</output>
<gadget id="calculator">104 / 100</gadget>
<output>26/25 = around 1.04</output>
<gadget id="calculator">(26/25) * 15_625</gadget>
<output>16_250</output>
<gadget id="calculator">16_250 * (26/25)</gadget>
<output>16_900</output>
<result>D</result> | D | 17,576 | If the annual increase in the population of a town is 4% and the present number of people is 15625, what will the population be in 3 years? | {
"A": "15265",
"B": "16458",
"C": "25600",
"D": "17576",
"E": "14785"
} | multiply(multiply(divide(add(4, const_100), const_100), 15625), divide(add(4, const_100), const_100)) | add(n0,const_100)|divide(#0,const_100)|multiply(n1,#1)|multiply(#1,#2)| | "the required population is = 15625 ( 1 + 4 / 100 ) ^ 3 = 15625 * 26 / 25 * 26 / 25 * 26 / 25 = 17576 answer is d" | gain |
math_qa__rOc9xzBhQ4cM60wK | n is a whole number which when divided by 4 gives 3 as remainder. What will be the remainder when 2n is divided by 4 ? Pick one
A) 3 B) 2 C) 1 D) 0 E) 5 | <gadget id="calculator">3 * 2</gadget>
<output>6</output>
<gadget id="calculator">6 % 4</gadget>
<output>2</output>
<result>B</result> | B | 2 | n is a whole number which when divided by 4 gives 3 as remainder. What will be the remainder when 2n is divided by 4 ? | {
"A": "3",
"B": "2",
"C": "1",
"D": "0",
"E": "5"
} | reminder(multiply(3, 2), 4) | multiply(n1,n2)|reminder(#0,n0)| | "explanation : let n = 4 q + 3 . then 2 n = 8 q + 6 = 4 ( 2 q + 1 ) + 2 . thus , when 2 n is divided by 4 , the remainder is 2 . answer : b" | general |
math_qa__gv51y28IHoARlkPZ | A sports retailer ordered white and yellow tennis balls in equal number but the dispatch clerk of the tennis ball company erred and dispatched 70 extra yellow balls and making ratio of white balls to yellow balls 8/13. How many tennis balls did the retailer order originally. Choose the most appropriate option:
A) 180
B) 130
C) 140
D) 160
E) 224 | <gadget id="calculator">8 * 70</gadget>
<output>560</output>
<gadget id="calculator">13 - 8</gadget>
<output>5</output>
<gadget id="calculator">560 / 5</gadget>
<output>112</output>
<gadget id="calculator">112 * 2</gadget>
<output>224</output>
<result>E</result> | E | 224 | A sports retailer ordered white and yellow tennis balls in equal number but the dispatch clerk of the tennis ball company erred and dispatched 70 extra yellow balls and making ratio of white balls to yellow balls 8/13. How many tennis balls did the retailer order originally. | {
"A": "180",
"B": "130",
"C": "140",
"D": "160",
"E": "224"
} | multiply(divide(multiply(8, 70), subtract(13, 8)), const_2) | multiply(n0,n1)|subtract(n2,n1)|divide(#0,#1)|multiply(#2,const_2)| | "white : yellow = x : ( x + 70 ) = 8 : 13 - - > 13 x = 8 x + 560 - - > x = 112 . the total # of balls originally x + x = 112 + 112 = 224 . answer : e ." | general |
math_qa__fLcA5rQnFEByAGoy | Find the number of shares that can be bought for Rs.8200 if the market value is Rs.20 each with brokerage being 3.2%. Pick one: A) 237 B) 270 C) 177 D) 166 E) 397.2 | <gadget id="calculator">3.2 / 100</gadget>
<output>0.032</output>
<gadget id="calculator">20 + 0.032</gadget>
<output>20.032</output>
<gadget id="calculator">8_200 / 20.032</gadget>
<output>409.345048</output>
<gadget id="calculator">floor(409.345048)</gadget>
<output>409</output>
<result>E</result> | E | 397.2 | Find the number of shares that can be bought for Rs.8200 if the market value is Rs.20 each with brokerage being 3.2%. | {
"A": "237",
"B": "270",
"C": "177",
"D": "166",
"E": "397.2"
} | floor(divide(8200, add(20, divide(3.2, const_100)))) | divide(n2,const_100)|add(n1,#0)|divide(n0,#1)|floor(#2)| | "explanation : cost of each share = ( 20 + 3.2 % of 20 ) = rs . 20.64 therefore , number of shares = 8200 / 20.64 = 397.2 answer : e" | gain |
math_qa__TGUyIYRgAgGBsa7R | In a school of 850 boys, 44% of Muslims, 14% Hindus, 10% Sikhs and the remaining of other communities. How many belonged to the other communities? Pick.
A) 125
B) 627
C) 153
D) 721
E) 272 | <gadget id="calculator">44 + 14</gadget>
<output>58</output>
<gadget id="calculator">58 + 10</gadget>
<output>68</output>
<gadget id="calculator">100 - 68</gadget>
<output>32</output>
<gadget id="calculator">850 * 32</gadget>
<output>27_200</output>
<gadget id="calculator">27_200 / 100</gadget>
<output>272</output>
<result>E</result> | E | 272 | In a school of 850 boys, 44% of Muslims, 14% Hindus, 10% Sikhs and the remaining of other communities. How many belonged to the other communities? | {
"A": "125",
"B": "627",
"C": "153",
"D": "721",
"E": "272"
} | divide(multiply(850, subtract(const_100, add(add(44, 14), 10))), const_100) | add(n1,n2)|add(n3,#0)|subtract(const_100,#1)|multiply(n0,#2)|divide(#3,const_100)| | "44 + 14 + 10 = 68 % 100 – 68 = 32 % 850 * 32 / 100 = 272 answer : e" | gain |
math_qa__WyMA89CQcmAbLUPn | The diagonals of a rhombus are 13 cm and 20 cm. Find its area? Choose the correct choice from the following
A) 176
B) 130
C) 150
D) 179
E) 172 | <gadget id="calculator">(13 * 20) / 2</gadget>
<output>130</output>
<result>B</result> | B | 130 | The diagonals of a rhombus are 13 cm and 20 cm. Find its area? | {
"A": "176",
"B": "130",
"C": "150",
"D": "179",
"E": "172"
} | rhombus_area(13, 20) | rhombus_area(n0,n1)| | "1 / 2 * 13 * 20 = 130 answer : b" | geometry |
math_qa__h6zYv7o5iwCtDyEi | What could be the range of a set consisting of odd multiples of 11? Select the correct option:
A) 21 B) 24 C) 44 D) 62 E) 70 | <gadget id="calculator">11 * 4</gadget>
<output>44</output>
<result>C</result> | C | 44 | What could be the range of a set consisting of odd multiples of 11? | {
"A": "21",
"B": "24",
"C": "44",
"D": "62",
"E": "70"
} | multiply(11, const_4) | multiply(n0,const_4) | range = the difference between the greatest and the smallest numbers in the sequence . our sequence is odd and is a multiple of 7 . every number in that sequence can be represented like this : 11 * ( 2 n + 1 ) where n is any positive integer . range = 11 * ( 2 m + 1 ) - 11 * ( 2 n + 1 ) = 11 * 2 * ( m - n ) = 22 * ( m - n ) . m , n - any positive integers the answer must be divisible by 22 , which is only 44 . the correct answer is c | general |
math_qa__W8ERzsWGFuPIHfoU | A no.when divided by 242 gives a remainder 100, what remainder will be obtainedby dividingthe same no.18? Pick:
A) 15
B) 16
C) 17
D) 18
E) 19 | <gadget id="calculator">242 + 100</gadget>
<output>342</output>
<gadget id="calculator">342 / 18</gadget>
<output>19</output>
<result>E</result> | E | 19 | A no.when divided by 242 gives a remainder 100, what remainder will be obtainedby dividingthe same no.18? | {
"A": "15",
"B": "16",
"C": "17",
"D": "18",
"E": "19"
} | divide(add(242, 100), 18) | add(n0,n1)|divide(#0,n2)| | "242 + 100 = 342 / 18 = 19 ( remainder ) e" | general |
math_qa__gVCC1umCtliWsQE7 | Two pipes can fill a tank in 18 minutes and 20 minutes. An outlet pipe can empty the tank in 45 minutes. If all the pipes are opened when the tank is empty, then how many minutes will it take to fill the tank?
Select
A) 1 / 15 B) 1 / 16 C) 1 / 11 D) 1 / 10 E) 1 / 12 | <gadget id="calculator">1 / 18</gadget>
<output>1/18 = around 0.055556</output>
<gadget id="calculator">1 / 20</gadget>
<output>1/20 = around 0.05</output>
<gadget id="calculator">(1/18) + (1/20)</gadget>
<output>19/180 = around 0.105556</output>
<gadget id="calculator">1 / 45</gadget>
<output>1/45 = around 0.022222</output>
<gadget id="calculator">(19/180) - (1/45)</gadget>
<output>1/12 = around 0.083333</output>
<result>E</result> | E | 0.083333 | Two pipes can fill a tank in 18 minutes and 20 minutes. An outlet pipe can empty the tank in 45 minutes. If all the pipes are opened when the tank is empty, then how many minutes will it take to fill the tank? | {
"A": "1 / 15",
"B": "1 / 16",
"C": "1 / 11",
"D": "1 / 10",
"E": "1 / 12"
} | subtract(add(divide(const_1, 18), divide(const_1, 20)), divide(const_1, 45)) | divide(const_1,n0)|divide(const_1,n1)|divide(const_1,n2)|add(#0,#1)|subtract(#3,#2)| | "part of the filled by all the three pipes in one minute = 1 / 18 + 1 / 21 - 1 / 45 = 1 / 12 so , the tank becomes full in 12 minutes . answer : e" | physics |
math_qa__ourzoW9Yin51aPms | A box contains 23 electric bulbs, out of which 4 are defective. Two bulbs are chosen at random from this box. The probability that at least one of these is defective is Choose the correct choice from the following answers:
A) 4 / 19
B) 7 / 19
C) 12 / 37
D) 21 / 95
E) none | <gadget id="calculator">23 - 4</gadget>
<output>19</output>
<gadget id="calculator">binomial(19, 2)</gadget>
<output>171</output>
<gadget id="calculator">binomial(23, 2)</gadget>
<output>253</output>
<gadget id="calculator">171 / 253</gadget>
<output>171/253 = around 0.675889</output>
<gadget id="calculator">1 - (171/253)</gadget>
<output>82/253 = around 0.324111</output>
<result>C</result> | C | 0.324324 | A box contains 23 electric bulbs, out of which 4 are defective. Two bulbs are chosen at random from this box. The probability that at least one of these is defective is | {
"A": "4 / 19",
"B": "7 / 19",
"C": "12 / 37",
"D": "21 / 95",
"E": "none"
} | subtract(const_1, divide(choose(subtract(23, 4), const_2), choose(23, const_2))) | choose(n0,const_2)|subtract(n0,n1)|choose(#1,const_2)|divide(#2,#0)|subtract(const_1,#3) | solution p ( none is defective ) = 19 c 2 / 23 c 2 = 25 / 37 . p ( at least one is defective ) = ( 1 - 25 / 37 ) = 12 / 37 . answer c | probability |
math_qa__oOxdwqavtjJddXnv | Aarti can do a piece of work in 5 days. In how many days will she complete three time of work of same type? Choose the correct answer: A) 6 days B) 18 days C) 21 days D) 3 days E) 15 days | <gadget id="calculator">3 * 5</gadget>
<output>15</output>
<result>E</result> | E | 15 | Aarti can do a piece of work in 5 days. In how many days will she complete three time of work of same type? | {
"A": "6 days",
"B": "18 days",
"C": "21 days",
"D": "3 days",
"E": "15 days"
} | multiply(const_3, 5) | multiply(n0,const_3) | we have the important relation , more work , more time ( days ) a piece of work can be done in 5 days . three times of work of same type can be done in 5 x 3 = 15 days answer e | physics |
math_qa__hWCsFCuyqcMYV5EG | A rectangular lawn 70 m × 30 m has two roads each 5 metres wide, running in the middle of it, one parallel to the length and the other parallel to the breadth. Find the cost of gravelling the road at the rate of 4 per square metre. Select
A) 2,000 B) 1,800 C) 1,900 D) 1,700 E) none of these | <gadget id="calculator">70 * 5</gadget>
<output>350</output>
<gadget id="calculator">30 * 5</gadget>
<output>150</output>
<gadget id="calculator">350 + 150</gadget>
<output>500</output>
<gadget id="calculator">5 * 5</gadget>
<output>25</output>
<gadget id="calculator">500 - 25</gadget>
<output>475</output>
<gadget id="calculator">475 * 4</gadget>
<output>1_900</output>
<result>C</result> | C | 1,900 | A rectangular lawn 70 m × 30 m has two roads each 5 metres wide, running in the middle of it, one parallel to the length and the other parallel to the breadth. Find the cost of gravelling the road at the rate of 4 per square metre. | {
"A": "2,000",
"B": "1,800",
"C": "1,900",
"D": "1,700",
"E": "none of these"
} | multiply(subtract(add(multiply(70, 5), multiply(30, 5)), multiply(5, 5)), 4) | multiply(n0,n2)|multiply(n1,n2)|multiply(n2,n2)|add(#0,#1)|subtract(#3,#2)|multiply(n3,#4) | total area of road = area of road which parallel to length + area of road which parallel to breadth – overlapped road = 70 × 5 + 30 × 5 – 5 × 5 = 350 + 150 – 25 = 500 – 25 = 475 m 2 ∴ cost of gravelling the road = 475 × 4 = 1900 answer c | geometry |
math_qa__fuK2vU0YFySrPsFU | in a bus left side are 15 seats available,3 few seats in right side because in rear exit door .Each seat hold 3 people.In addition ,there is a seat back can sit 11 people all together .how many people can sit in a bus? Choose one: A) 52 B) 92 C) 95 D) 88 E) 66 | <gadget id="calculator">15 - 3</gadget>
<output>12</output>
<gadget id="calculator">15 + 12</gadget>
<output>27</output>
<gadget id="calculator">27 * 3</gadget>
<output>81</output>
<gadget id="calculator">81 + 11</gadget>
<output>92</output>
<result>B</result> | B | 92 | in a bus left side are 15 seats available,3 few seats in right side because in rear exit door .Each seat hold 3 people.In addition ,there is a seat back can sit 11 people all together .how many people can sit in a bus? | {
"A": "52",
"B": "92",
"C": "95",
"D": "88",
"E": "66"
} | add(multiply(add(15, subtract(15, 3)), 3), 11) | subtract(n0,n1)|add(n0,#0)|multiply(n1,#1)|add(n3,#2)| | "right side = 15 seat left side = 15 - 3 ( 3 few seat in right side ) = 12 seat total = 15 + 12 = 27 people can seat in 27 seat = 27 * 3 = 81 people can seat in last seat = 11 total people can seat = 81 + 11 = 92 answer : b" | general |
math_qa__ialBFedkKh6Q1iWa | Two cars, one from Austin to Dallas and the other from Dallas to Austin, start simultaneously. After they meet, the cars reach their destinations after 4 hours and 9 hours respectively The ratio of their speeds is Choose the correct choice from the following:
A) 2 : 3 B) 4 : 3 C) 3 : 6 D) 4 : 5 E) none | <gadget id="calculator">4 ** (1/2)</gadget>
<output>2</output>
<gadget id="calculator">9 ** (1/2)</gadget>
<output>3</output>
<gadget id="calculator">2 / 3</gadget>
<output>2/3 = around 0.666667</output>
<result>A</result> | A | 0.666667 | Two cars, one from Austin to Dallas and the other from Dallas to Austin, start simultaneously. After they meet, the cars reach their destinations after 4 hours and 9 hours respectively The ratio of their speeds is | {
"A": "2 : 3",
"B": "4 : 3",
"C": "3 : 6",
"D": "4 : 5",
"E": "none"
} | divide(sqrt(4), sqrt(9)) | sqrt(n0)|sqrt(n1)|divide(#0,#1) | solution let us name the cars as a and b . = ( car a ' s speed ) : ( car b ' s speed ) = â ˆ š b : â ˆ š a = â ˆ š 4 : â ˆ š 9 = 2 : 3 answer a | physics |
math_qa__NfIHjnBSuJbw0KP1 | Chlorination is used in industry for the purification of water; 1gm solution of chlorine will remove half of the germs in 1 liter of water. If water containing less than 0.09% of germs is considered clean, what is the minimum amount of chlorine required to purify 150 liter of water containing 0.3 liter of harmful substances?
Choose the correct answer: A) 1 B) 2 C) 3 D) 4 E) 5 | <gadget id="calculator">150 * 0.09</gadget>
<output>13.5</output>
<gadget id="calculator">13.5 * 0.3</gadget>
<output>4.05</output>
<gadget id="calculator">4.05 / 2</gadget>
<output>2.025</output>
<result>B</result> | B | 2 | Chlorination is used in industry for the purification of water; 1gm solution of chlorine will remove half of the germs in 1 liter of water. If water containing less than 0.09% of germs is considered clean, what is the minimum amount of chlorine required to purify 150 liter of water containing 0.3 liter of harmful substances? | {
"A": "1",
"B": "2",
"C": "3",
"D": "4",
"E": "5"
} | divide(multiply(multiply(150, 0.09), 0.3), const_2) | multiply(n2,n3)|multiply(n4,#0)|divide(#1,const_2) | assuming that it ' s supposed to state ` ` 0.3 ' ' liters of harmful substances , here ' s how you can answer this question . first , we have to figure out what . 09 % of 150 liters is . . . 1 % = . 01 . 1 % = . 001 . 09 % = . 0009 so , . 0009 ( 150 ) = . 135 liters we need enough doses of chlorine to get the 0.3 liters down to less than . 135 liters . each ` ` dose ' ' of chlorine will remove half of the harmful substances . . . start = 0.3 liters after 1 st dose = . 15 liters after 2 nd dose = . 075 liters we ' re now below the . 135 liters that we need to be less than . final answer : b | gain |
math_qa__LCrG2Zf8NSjSp0Wx | On a purchase of $127, a store offered a payment plan consisting of a $27 down payment and 12 monthly payments of $10 each. What percent of the purchase price, to the nearest tenth of a percent, did the customer pay in interest by using this plan? Choose the correct choice from the following options:
A) 18.3 %
B) 15.3 %
C) 21.3 %
D) 22.3 %
E) 25.3 % | <gadget id="calculator">10 * 12</gadget>
<output>120</output>
<gadget id="calculator">120 + 27</gadget>
<output>147</output>
<gadget id="calculator">147 - 120</gadget>
<output>27</output>
<gadget id="calculator">27 / 127</gadget>
<output>27/127 = around 0.212598</output>
<gadget id="calculator">(27/127) * 100</gadget>
<output>2_700/127 = around 21.259843</output>
<result>C</result> | C | 21.3 | On a purchase of $127, a store offered a payment plan consisting of a $27 down payment and 12 monthly payments of $10 each. What percent of the purchase price, to the nearest tenth of a percent, did the customer pay in interest by using this plan? | {
"A": "18.3 %",
"B": "15.3 %",
"C": "21.3 %",
"D": "22.3 %",
"E": "25.3 %"
} | multiply(divide(subtract(add(multiply(10, 12), 27), multiply(10, 12)), 127), const_100) | multiply(n2,n3)|add(n1,#0)|subtract(#1,#0)|divide(#2,n0)|multiply(#3,const_100)| | "12 * 10 + 27 = 147 ( 27 / 127 ) * 100 = 21.3 answer : c" | gain |
math_qa__zQf6opHC9tHK6w3h | In how many R ways can 5 people from a group of 6 people be seated around a circular table Choose the correct option
A) 56 B) 80 C) 100 D) 120 E) 144 | <gadget id="calculator">5 - 1</gadget>
<output>4</output>
<gadget id="calculator">factorial(4)</gadget>
<output>24</output>
<gadget id="calculator">24 * 6</gadget>
<output>144</output>
<result>E</result> | E | 144 | In how many R ways can 5 people from a group of 6 people be seated around a circular table | {
"A": "56",
"B": "80",
"C": "100",
"D": "120",
"E": "144"
} | multiply(factorial(subtract(5, const_1)), 6) | subtract(n0,const_1)|factorial(#0)|multiply(n1,#1) | r = 6 c 5 * ( 5 - 1 ) ! ( select 5 out of 6 and arrange them in circular manner ) = 6 * 4 ! = 6 * 24 = 144 answer - e | geometry |
math_qa__3DyImG4C2OWOdwpF | 50 men do a work in 100days. How many men are needed to finish the work in 20days? Choose the correct choice from the following
A) 50 B) 100 C) 250 D) 300 E) 400 | <gadget id="calculator">50 * 100</gadget>
<output>5_000</output>
<gadget id="calculator">5_000 / 20</gadget>
<output>250</output>
<result>C</result> | C | 250 | 50 men do a work in 100days. How many men are needed to finish the work in 20days? | {
"A": "50",
"B": "100",
"C": "250",
"D": "300",
"E": "400"
} | divide(multiply(50, 100), 20) | multiply(n0,n1)|divide(#0,n2) | men required to finish the work in 2 days = 50 * 100 / 20 = 250 answer is c | physics |
math_qa__hHFAQEb9AJJYrTgD | What is the rate percent when the simple interest on Rs.900 amount to Rs.160 in 4 Years?
Choose the correct choice from the following choices.
A) 4.44 B) 5.44 C) 6.44 D) 7.44 E) 8.44 | <gadget id="calculator">100 * 160</gadget>
<output>16_000</output>
<gadget id="calculator">900 * 4</gadget>
<output>3_600</output>
<gadget id="calculator">16_000 / 3_600</gadget>
<output>40/9 = around 4.444444</output>
<result>A</result> | A | 4.44 | What is the rate percent when the simple interest on Rs.900 amount to Rs.160 in 4 Years? | {
"A": "4.44",
"B": "5.44",
"C": "6.44",
"D": "7.44",
"E": "8.44"
} | divide(multiply(const_100, 160), multiply(900, 4)) | multiply(n1,const_100)|multiply(n0,n2)|divide(#0,#1)| | "160 = ( 900 * 4 * r ) / 100 r = 4.44 % answer : a" | gain |
math_qa__Nhvc0KFFpEDNgHWt | A car takes 6 hours to cover a distance of 432 Km. how much should the speed in Kmph be maintained to cover the same direction in 3/2th of the previous time? Choose the correct choice from the following choices
A) 48 kmph B) 50 kmph C) 52 kmph D) 56 kmph E) 60 kmph | <gadget id="calculator">6 * 3</gadget>
<output>18</output>
<gadget id="calculator">18 / 2</gadget>
<output>9</output>
<gadget id="calculator">432 / 9</gadget>
<output>48</output>
<result>A</result> | A | 48 | A car takes 6 hours to cover a distance of 432 Km. how much should the speed in Kmph be maintained to cover the same direction in 3/2th of the previous time? | {
"A": "48 kmph",
"B": "50 kmph",
"C": "52 kmph",
"D": "56 kmph",
"E": "60 kmph"
} | divide(432, divide(multiply(6, 3), 2)) | multiply(n0,n2)|divide(#0,n3)|divide(n1,#1)| | "time = 6 distence = 432 3 / 2 of 6 hours = 6 * 3 / 2 = 9 hours required speed = 432 / 9 = 48 kmph a" | physics |
math_qa__MdIBsrar3ONno5CR | The scoring system in a certain football competition goes as follows: 3 points for victory, 1 point for a draw, and 0 points for defeat. Each team plays 20 matches. If a team scored 14 points after 5 games, what is the least number of the remaining matches it has to win to reach the 40-point mark by the end of the tournament? Choose the correct choice from the following choices
A) 6
B) 7
C) 8
D) 9
E) 10 | <gadget id="calculator">40 - 14</gadget>
<output>26</output>
<gadget id="calculator">20 - 5</gadget>
<output>15</output>
<gadget id="calculator">26 - 15</gadget>
<output>11</output>
<gadget id="calculator">11 / 2</gadget>
<output>11/2 = around 5.5</output>
<gadget id="calculator">floor(11/2)</gadget>
<output>5</output>
<gadget id="calculator">5 + 1</gadget>
<output>6</output>
<result>A</result> | A | 6 | The scoring system in a certain football competition goes as follows: 3 points for victory, 1 point for a draw, and 0 points for defeat. Each team plays 20 matches. If a team scored 14 points after 5 games, what is the least number of the remaining matches it has to win to reach the 40-point mark by the end of the tournament? | {
"A": "6",
"B": "7",
"C": "8",
"D": "9",
"E": "10"
} | add(floor(divide(subtract(subtract(40, 14), subtract(20, 5)), const_2)), 1) | subtract(n6,n4)|subtract(n3,n5)|subtract(#0,#1)|divide(#2,const_2)|floor(#3)|add(#4,n1)| | "to get 40 points as end of season we need another 26 points or more from remaining 15 matches : option a = 6 * 3 + 9 * 1 = 27 hence option a - 6" | general |
math_qa__KTnaVCJTTuCs4c3g | Find large number from below question The difference of two numbers is 1390. On dividing the larger number by the smaller, we get 6 as quotient and the 15 as remainder Choose the correct choice from the following answers.
A) 1245 B) 1345 C) 1455 D) 1577 E) 1665 | <gadget id="calculator">1_390 - 15</gadget>
<output>1_375</output>
<gadget id="calculator">6 - 1</gadget>
<output>5</output>
<gadget id="calculator">1_375 / 5</gadget>
<output>275</output>
<gadget id="calculator">275 * 6</gadget>
<output>1_650</output>
<result>E</result> | E | 1,665 | Find large number from below question The difference of two numbers is 1390. On dividing the larger number by the smaller, we get 6 as quotient and the 15 as remainder | {
"A": "1245",
"B": "1345",
"C": "1455",
"D": "1577",
"E": "1665"
} | multiply(divide(subtract(1390, 15), subtract(6, const_1)), 6) | subtract(n0,n2)|subtract(n1,const_1)|divide(#0,#1)|multiply(n1,#2)| | "let the smaller number be x . then larger number = ( x + 1390 ) . x + 1390 = 6 x + 15 5 x = 1375 x = 275 large number = 275 + 1390 = 1665 e" | general |
math_qa__XAsaTfyDNHW59SOV | For the past n days, the average (arithmetic mean) daily production at a company was 50 units. If today's production of 105 units raises the average to 55 units per day, what is the value of n? Choose the correct option
A) 8 B) 10 C) 12 D) 14 E) 16 | <gadget id="calculator">105 - 50</gadget>
<output>55</output>
<gadget id="calculator">55 - 50</gadget>
<output>5</output>
<gadget id="calculator">55 / 5</gadget>
<output>11</output>
<gadget id="calculator">11 - 1</gadget>
<output>10</output>
<result>B</result> | B | 10 | For the past n days, the average (arithmetic mean) daily production at a company was 50 units. If today's production of 105 units raises the average to 55 units per day, what is the value of n? | {
"A": "8",
"B": "10",
"C": "12",
"D": "14",
"E": "16"
} | subtract(divide(subtract(105, 50), subtract(55, 50)), const_1) | subtract(n1,n0)|subtract(n2,n0)|divide(#0,#1)|subtract(#2,const_1)| | "the daily production was raised by 5 units for n days , which has a weighting of 5 n . 5 n = 105 - 55 = 50 n = 10 the answer is b ." | general |
math_qa__tUKRLvQTog0zgHje | A company sells pens and pencils. The Revenue from pens in 2007 was up 5% from 2006. The revenue from pencils declined 13% over the same period. Overall revenue was down 1% from 06 to 07. What was the ratio of pencil revenue to pen revenue in 2006 Select
A) 1 / 2
B) 1 / 3
C) 1 / 4
D) 1 / 5
E) 1 / 6 | <gadget id="calculator">5 + 100</gadget>
<output>105</output>
<gadget id="calculator">100 - 1</gadget>
<output>99</output>
<gadget id="calculator">105 - 99</gadget>
<output>6</output>
<gadget id="calculator">100 - 13</gadget>
<output>87</output>
<gadget id="calculator">99 - 87</gadget>
<output>12</output>
<gadget id="calculator">6 / 12</gadget>
<output>1/2 = around 0.5</output>
<result>A</result> | A | 0.5 | A company sells pens and pencils. The Revenue from pens in 2007 was up 5% from 2006. The revenue from pencils declined 13% over the same period. Overall revenue was down 1% from 06 to 07. What was the ratio of pencil revenue to pen revenue in 2006 | {
"A": "1 / 2",
"B": "1 / 3",
"C": "1 / 4",
"D": "1 / 5",
"E": "1 / 6"
} | divide(subtract(add(5, const_100), subtract(const_100, 1)), subtract(subtract(const_100, 1), subtract(const_100, 13))) | add(n1,const_100)|subtract(const_100,n4)|subtract(const_100,n3)|subtract(#0,#1)|subtract(#1,#2)|divide(#3,#4) | let the revenue of pens be ' x ' let the revenue of pencils be ' y ' the revenue of pens up from 2006 by 5 % = > 105 % the revenue of pencils down from 2006 by 13 % = > 87 % overall revenue down by 1 % = > 99 % hence the ratio of pencils to pens = 6 / 12 = 1 / 2 answer : a | other |
math_qa__iHuo2Q69dwQ9krXk | A family made a down payment of $300
and borrowed the balance on a set of
encyclopedias that cost $750. The
balance with interest was paid in 9
monthly payments of $57 each and a
final payment of $21. The amount of
interest paid was what percent of the
amount borrowed?
Select.
A) 6 %
B) 12 %
C) 14 %
D) 18.66 %
E) 20 % | <gadget id="calculator">9 * 57</gadget>
<output>513</output>
<gadget id="calculator">513 + 21</gadget>
<output>534</output>
<gadget id="calculator">750 - 300</gadget>
<output>450</output>
<gadget id="calculator">534 - 450</gadget>
<output>84</output>
<gadget id="calculator">84 / 450</gadget>
<output>14/75 = around 0.186667</output>
<gadget id="calculator">(14/75) * 100</gadget>
<output>56/3 = around 18.666667</output>
<result>D</result> | D | 18.66 | A family made a down payment of $300
and borrowed the balance on a set of
encyclopedias that cost $750. The
balance with interest was paid in 9
monthly payments of $57 each and a
final payment of $21. The amount of
interest paid was what percent of the
amount borrowed? | {
"A": "6 %",
"B": "12 %",
"C": "14 %",
"D": "18.66 %",
"E": "20 %"
} | multiply(divide(subtract(add(multiply(9, 57), 21), subtract(750, 300)), subtract(750, 300)), const_100) | multiply(n2,n3)|subtract(n1,n0)|add(n4,#0)|subtract(#2,#1)|divide(#3,#1)|multiply(#4,const_100) | interest paid = 57 * 9 + 21 - 450 = 84 % off the balance = ( 84 / 450 ) * 100 = 18.66 % answer is d . | gain |
math_qa__hwJiYHiTRQnrzZNb | There are 10 teams in a certain league and each team plays each of the other teams exactly once. What is the total number of games played? Choose the correct choice from the following answers.
A) 30 B) 36 C) 42 D) 45 E) 50 | <gadget id="calculator">10 - 1</gadget>
<output>9</output>
<gadget id="calculator">10 * 9</gadget>
<output>90</output>
<gadget id="calculator">90 / 2</gadget>
<output>45</output>
<result>D</result> | D | 45 | There are 10 teams in a certain league and each team plays each of the other teams exactly once. What is the total number of games played? | {
"A": "30",
"B": "36",
"C": "42",
"D": "45",
"E": "50"
} | divide(multiply(10, subtract(10, const_1)), const_2) | subtract(n0,const_1)|multiply(n0,#0)|divide(#1,const_2)| | "10 c 2 = 45 the answer is d ." | general |
math_qa__jdbS1lxJV5CsaNln | If X is to be chosen at random from the integers between 1 to 5, inclusive, and Y is to be chosen at random from the integers between 7 and 10, inclusive, what is the probability that X + Y will be even? Select the correct option:
A) 1 / 2 B) 2 / 3 C) 3 / 4 D) 4 / 5 E) 5 / 6 | <gadget id="calculator">2 * 2</gadget>
<output>4</output>
<gadget id="calculator">3 * 2</gadget>
<output>6</output>
<gadget id="calculator">4 + 6</gadget>
<output>10</output>
<gadget id="calculator">5 - 1</gadget>
<output>4</output>
<gadget id="calculator">5 * 4</gadget>
<output>20</output>
<gadget id="calculator">10 / 20</gadget>
<output>1/2 = around 0.5</output>
<result>A</result> | A | 0.5 | If X is to be chosen at random from the integers between 1 to 5, inclusive, and Y is to be chosen at random from the integers between 7 and 10, inclusive, what is the probability that X + Y will be even? | {
"A": "1 / 2",
"B": "2 / 3",
"C": "3 / 4",
"D": "4 / 5",
"E": "5 / 6"
} | divide(add(multiply(const_2, const_2), multiply(const_3, const_2)), multiply(5, subtract(5, const_1))) | multiply(const_2,const_2)|multiply(const_2,const_3)|subtract(n1,const_1)|add(#0,#1)|multiply(n1,#2)|divide(#3,#4) | x + y will be even if x and y are both even or both odd . p ( x and y are both even ) = 2 / 5 * 2 / 4 = 1 / 5 p ( x and y are both odd ) = 3 / 5 * 2 / 4 = 3 / 10 p ( x + y is even ) = 1 / 5 + 3 / 10 = 1 / 2 the answer is a . | general |
math_qa__J3yD6AiQ2WnNAJG4 | The perimeter of a rhombus is 52 units. One of its diagonal is 24 units. What is its second diagonals length? Choose the most appropriate option.
A) 5 B) 10 C) 15 D) 20 E) 25 | <gadget id="calculator">52 / 4</gadget>
<output>13</output>
<gadget id="calculator">13 ** 2</gadget>
<output>169</output>
<gadget id="calculator">24 / 2</gadget>
<output>12</output>
<gadget id="calculator">12 ** 2</gadget>
<output>144</output>
<gadget id="calculator">169 - 144</gadget>
<output>25</output>
<gadget id="calculator">25 ** (1/2)</gadget>
<output>5</output>
<gadget id="calculator">5 * 2</gadget>
<output>10</output>
<result>B</result> | B | 10 | The perimeter of a rhombus is 52 units. One of its diagonal is 24 units. What is its second diagonals length? | {
"A": "5",
"B": "10",
"C": "15",
"D": "20",
"E": "25"
} | multiply(sqrt(subtract(power(divide(52, const_4), const_2), power(divide(24, const_2), const_2))), const_2) | divide(n0,const_4)|divide(n1,const_2)|power(#0,const_2)|power(#1,const_2)|subtract(#2,#3)|sqrt(#4)|multiply(#5,const_2) | when the perimeter of a triangle is 52 units each side is 13 units next , the diagonal of a rhombus bisect each other at 90 degree thus the half of the diagonal is 12 units now in a right angle triangle so formed , the perpendicular is 12 and the hypptenuse is 13 ( that is the side of the triangle ) finding the base ( which is half of the other diagonal ) : 13 ^ 2 - 12 ^ 2 = 25 thus half of the diagonal is 5 and the diagonal is 10 units answer : b | physics |
math_qa__5KVgrvASFcwgEswR | How much is 60% of 40 is greater than 4/5 of 25? Pick one:
A) 4
B) 6
C) 10
D) 8
E) 13 | <gadget id="calculator">60 / 100</gadget>
<output>3/5 = around 0.6</output>
<gadget id="calculator">40 * (3/5)</gadget>
<output>24</output>
<gadget id="calculator">4 / 5</gadget>
<output>4/5 = around 0.8</output>
<gadget id="calculator">(4/5) * 25</gadget>
<output>20</output>
<gadget id="calculator">24 - 20</gadget>
<output>4</output>
<result>A</result> | A | 4 | How much is 60% of 40 is greater than 4/5 of 25? | {
"A": "4",
"B": "6",
"C": "10",
"D": "8",
"E": "13"
} | subtract(multiply(40, divide(60, const_100)), multiply(divide(4, 5), 25)) | divide(n0,const_100)|divide(n2,n3)|multiply(n1,#0)|multiply(n4,#1)|subtract(#2,#3)| | "60 / 100 ) * 40 â € “ ( 4 / 5 ) * 25 24 - 20 = 4 answer : a" | general |
math_qa__MEuouOA7zv8Vmnwu | If x and y are integers, what is the least positive number of 24x+18y? Answers
A) 3 B) 6 C) 9 D) 12 E) 15 | <gadget id="calculator">24 - 18</gadget>
<output>6</output>
<result>B</result> | B | 6 | If x and y are integers, what is the least positive number of 24x+18y? | {
"A": "3",
"B": "6",
"C": "9",
"D": "12",
"E": "15"
} | subtract(24, 18) | subtract(n0,n1)| | "24 x + 21 y = 6 ( 4 x + 3 y ) which will be a minimum positive number when 4 x + 3 y = 1 . 4 ( 1 ) + 3 ( - 1 ) = 1 then 6 ( 4 x + 3 y ) can have a minimum positive value of 6 . the answer is b ." | general |
math_qa__YOjknOXxiCStdjJX | The jogging track in a sports complex is 726 m in circumference. Suresh and his wife start from the same point and walk in opposite direction at 4.5 km/hr and 3.75 km/hr respectively. They will meet for the first time in? Select:
A) 5.2 minutes B) 5.21 minutes C) 5.25 minutes D) 5.28 minutes E) 6 minutes | <gadget id="calculator">4.5 * 1_000</gadget>
<output>4_500</output>
<gadget id="calculator">3.75 * 1_000</gadget>
<output>3_750</output>
<gadget id="calculator">4_500 + 3_750</gadget>
<output>8_250</output>
<gadget id="calculator">8_250 / 60</gadget>
<output>275/2 = around 137.5</output>
<gadget id="calculator">726 / (275/2)</gadget>
<output>132/25 = around 5.28</output>
<result>D</result> | D | 5.28 | The jogging track in a sports complex is 726 m in circumference. Suresh and his wife start from the same point and walk in opposite direction at 4.5 km/hr and 3.75 km/hr respectively. They will meet for the first time in? | {
"A": "5.2 minutes",
"B": "5.21 minutes",
"C": "5.25 minutes",
"D": "5.28 minutes",
"E": "6 minutes"
} | divide(726, divide(add(multiply(4.5, const_1000), multiply(3.75, const_1000)), const_60)) | multiply(n1,const_1000)|multiply(n2,const_1000)|add(#0,#1)|divide(#2,const_60)|divide(n0,#3) | let both of them meet after tt min 4500 m are covered by suresh in 60 m . in tt min he will cover 4500 t 604500 t 60 likewise , in tt min suresh ' s wife will cover 3750 t 603750 t 60 given , 4500 t 60 + 3750 t 60 = 7264500 t 60 + 3750 t 60 = 726 tt = 5.28 minutes option ( d ) is correct | general |
math_qa__fwQ5vwSqVsiXNOUM | A boatman goes 3 km against the current of the stream in 3 hour and goes 1 km along the current in 30 minutes. How long will it take to go 3 km in stationary water? Choose the correct choice from the following choices:
A) 5 hours B) 4 hours C) 3 hours D) 2 hours E) 1 hours | <gadget id="calculator">1 / 30</gadget>
<output>1/30 = around 0.033333</output>
<gadget id="calculator">(1/30) * 60</gadget>
<output>2</output>
<gadget id="calculator">3 / 3</gadget>
<output>1</output>
<gadget id="calculator">2 + 1</gadget>
<output>3</output>
<gadget id="calculator">3 / 2</gadget>
<output>3/2 = around 1.5</output>
<gadget id="calculator">3 / (3/2)</gadget>
<output>2</output>
<result>D</result> | D | 2 | A boatman goes 3 km against the current of the stream in 3 hour and goes 1 km along the current in 30 minutes. How long will it take to go 3 km in stationary water? | {
"A": "5 hours",
"B": "4 hours",
"C": "3 hours",
"D": "2 hours",
"E": "1 hours"
} | divide(3, divide(add(multiply(divide(1, 30), const_60), divide(3, 3)), const_2)) | divide(n0,n0)|divide(n2,n3)|multiply(#1,const_60)|add(#0,#2)|divide(#3,const_2)|divide(n4,#4)| | "explanation : speed upstream = 3 / 3 = 1 km / hr speed downstream = 1 / ( 30 / 60 ) = 2 km / hr speed in still water = 1 / 2 ( 2 + 1 ) = 3 / 2 km / hr time taken to travel 3 km in still water = 3 / ( 3 / 2 ) = 6 / 3 = 2 hours answer : option d" | physics |
math_qa__RPeHJ7ugiqX7KnFz | The average age of 8 men increases by 2 years when two women are included in place of two men of ages 20 and 24 years. Find the average age of the women?
Answers:
A) 39 B) 27 C) 30 D) 26 E) 29 | <gadget id="calculator">20 + 24</gadget>
<output>44</output>
<gadget id="calculator">8 * 2</gadget>
<output>16</output>
<gadget id="calculator">44 + 16</gadget>
<output>60</output>
<gadget id="calculator">60 / 2</gadget>
<output>30</output>
<result>C</result> | C | 30 | The average age of 8 men increases by 2 years when two women are included in place of two men of ages 20 and 24 years. Find the average age of the women? | {
"A": "39",
"B": "27",
"C": "30",
"D": "26",
"E": "29"
} | divide(add(add(20, 24), multiply(8, 2)), const_2) | add(n2,n3)|multiply(n0,n1)|add(#0,#1)|divide(#2,const_2)| | "20 + 24 + 8 * 2 = 60 / 2 = 30 answer : c" | general |
math_qa__V4c6yqLQ2nshbp3h | How many paying stones, each measuring 2 1/2 m * 2 m are required to pave a rectangular court yard 20 m long and 16 1/2 m board? Choose one:
A) 66 B) 18 C) 16 D) 10 E) 15 | <gadget id="calculator">1 / 2</gadget>
<output>1/2 = around 0.5</output>
<gadget id="calculator">16 + (1/2)</gadget>
<output>33/2 = around 16.5</output>
<gadget id="calculator">20 * (33/2)</gadget>
<output>330</output>
<gadget id="calculator">2 + (1/2)</gadget>
<output>5/2 = around 2.5</output>
<gadget id="calculator">(5/2) * 2</gadget>
<output>5</output>
<gadget id="calculator">330 / 5</gadget>
<output>66</output>
<result>A</result> | A | 66 | How many paying stones, each measuring 2 1/2 m * 2 m are required to pave a rectangular court yard 20 m long and 16 1/2 m board? | {
"A": "66",
"B": "18",
"C": "16",
"D": "10",
"E": "15"
} | divide(multiply(20, add(16, divide(1, 2))), multiply(add(2, divide(1, 2)), 2)) | divide(n1,n0)|add(n5,#0)|add(n0,#0)|multiply(n4,#1)|multiply(n0,#2)|divide(#3,#4)| | "20 * 33 / 2 = 5 / 2 * 2 * x = > x = 66 answer : a" | general |
math_qa__Zr9hBWoXS0xJKy0A | A corporation paid $5 million in federal taxes on its first $50 million of gross profits and then $30 million in federal taxes on the next $150 million in gross profits. By approximately what percent did the ratio of federal taxes to gross profits increase from the first $50 million in profits to the next $150 million in profits? Choose one.
A) 6 % B) 14 % C) 20 % D) 140 % E) 43 % | <gadget id="calculator">30 + 5</gadget>
<output>35</output>
<gadget id="calculator">35 / 150</gadget>
<output>7/30 = around 0.233333</output>
<gadget id="calculator">5 / 50</gadget>
<output>1/10 = around 0.1</output>
<gadget id="calculator">(7/30) - (1/10)</gadget>
<output>2/15 = around 0.133333</output>
<gadget id="calculator">(2/15) / (1/10)</gadget>
<output>4/3 = around 1.333333</output>
<gadget id="calculator">(4/3) * 100</gadget>
<output>400/3 = around 133.333333</output>
<result>D</result> | D | 140 | A corporation paid $5 million in federal taxes on its first $50 million of gross profits and then $30 million in federal taxes on the next $150 million in gross profits. By approximately what percent did the ratio of federal taxes to gross profits increase from the first $50 million in profits to the next $150 million in profits? | {
"A": "6 %",
"B": "14 %",
"C": "20 %",
"D": "140 %",
"E": "43 %"
} | multiply(divide(subtract(divide(add(30, 5), 150), divide(5, 50)), divide(5, 50)), const_100) | add(n0,n2)|divide(n0,n1)|divide(#0,n3)|subtract(#2,#1)|divide(#3,#1)|multiply(#4,const_100) | difference in ratios = ( 30 / 150 ) - ( 5 / 50 ) = ( 5 / 50 ) % change = ( change ( 5 / 50 ) / original ratio ( 7 / 50 ) ) * 100 = 140 % answer - d | gain |
math_qa__o7B9HZCBLIH1wXRy | A textile manufacturing firm employees 70 looms. It makes fabrics for a branded company. The aggregate sales value of the output of the 70 looms is Rs 5,00,000 and the monthly manufacturing expenses is Rs 1,50,000. Assume that each loom contributes equally to the sales and manufacturing expenses are evenly spread over the number of looms. Monthly establishment charges are Rs 75000. If one loom breaks down and remains idle for one month, the decrease in profit is:
Choose the correct answer:
A) 13000 B) 7000 C) 10000 D) 5000 E) none of these | <gadget id="calculator">5 * 1_000</gadget>
<output>5_000</output>
<gadget id="calculator">5_000 * 100</gadget>
<output>500_000</output>
<gadget id="calculator">75_000 * 2</gadget>
<output>150_000</output>
<gadget id="calculator">150_000 + 75_000</gadget>
<output>225_000</output>
<gadget id="calculator">500_000 - 225_000</gadget>
<output>275_000</output>
<gadget id="calculator">70 - 1</gadget>
<output>69</output>
<gadget id="calculator">69 / 70</gadget>
<output>69/70 = around 0.985714</output>
<gadget id="calculator">(69/70) * 500_000</gadget>
<output>3_450_000/7 = around 492_857.142857</output>
<gadget id="calculator">150_000 * (69/70)</gadget>
<output>1_035_000/7 = around 147_857.142857</output>
<gadget id="calculator">(3_450_000/7) - (1_035_000/7)</gadget>
<output>345_000</output>
<gadget id="calculator">345_000 - 75_000</gadget>
<output>270_000</output>
<gadget id="calculator">275_000 - 270_000</gadget>
<output>5_000</output>
<result>D</result> | D | 5,000 | A textile manufacturing firm employees 70 looms. It makes fabrics for a branded company. The aggregate sales value of the output of the 70 looms is Rs 5,00,000 and the monthly manufacturing expenses is Rs 1,50,000. Assume that each loom contributes equally to the sales and manufacturing expenses are evenly spread over the number of looms. Monthly establishment charges are Rs 75000. If one loom breaks down and remains idle for one month, the decrease in profit is: | {
"A": "13000",
"B": "7000",
"C": "10000",
"D": "5000",
"E": "none of these"
} | subtract(subtract(multiply(multiply(5, const_1000), const_100), add(multiply(75000, const_2), 75000)), subtract(subtract(multiply(divide(subtract(70, 1), 70), multiply(multiply(5, const_1000), const_100)), multiply(multiply(75000, const_2), divide(subtract(70, 1), 70))), 75000)) | multiply(n2,const_1000)|multiply(n6,const_2)|subtract(n0,n4)|add(n6,#1)|divide(#2,n0)|multiply(#0,const_100)|multiply(#4,#5)|multiply(#4,#1)|subtract(#5,#3)|subtract(#6,#7)|subtract(#9,n6)|subtract(#8,#10) | explanation : profit = 5 , 00,000 â ˆ ’ ( 1 , 50,000 + 75,000 ) = rs . 2 , 75,000 . since , such loom contributes equally to sales and manufacturing expenses . but the monthly charges are fixed at rs 75,000 . if one loan breaks down sales and expenses will decrease . new profit : - = > 500000 ã — ( 69 / 70 ) â ˆ ’ 150000 ã — ( 69 / 70 ) â ˆ ’ 75000 . = > rs 2 , 70,000 . decrease in profit = > 2 , 75,000 â ˆ ’ 2 , 70,000 = > rs . 5,000 . answer : d | general |
math_qa__ltbV6I0iqp2wjgJG | there are 5 thieves , each loot a bakery one after the other such that the first one takes 1 / 2 of the total no . of the breads plus 1 / 2 of a bread . similarly 2 nd , 3 rd , 4 th and 5 fth also did the same . after the fifth one no . of breads remained are 3 . initially how many breads were there ? Choose the correct choice from the following answers.
A) 124 B) 125 C) 126 D) 127 E) 128 | <gadget id="calculator">5 * 4</gadget>
<output>20</output>
<gadget id="calculator">5 * 20</gadget>
<output>100</output>
<gadget id="calculator">100 + 20</gadget>
<output>120</output>
<gadget id="calculator">120 + 5</gadget>
<output>125</output>
<gadget id="calculator">125 + 2</gadget>
<output>127</output>
<result>D</result> | D | 127 | there are 5 thieves , each loot a bakery one after the other such that the first one takes 1 / 2 of the total no . of the breads plus 1 / 2 of a bread . similarly 2 nd , 3 rd , 4 th and 5 fth also did the same . after the fifth one no . of breads remained are 3 . initially how many breads were there ? | {
"A": "124",
"B": "125",
"C": "126",
"D": "127",
"E": "128"
} | add(add(add(multiply(5, multiply(5, 4)), multiply(5, 4)), 5), 2) | multiply(n0,n7)|multiply(n0,#0)|add(#1,#0)|add(n0,#2)|add(n2,#3) | let the number of breads initial be x you should go in reverse order as left bread is 3 i . e x = ? after 1 st person ate a = x - ( x / 2 ) - ( 1 / 2 ) i . e a = ( 2 x - x ) / 2 - ( 1 / 2 ) i . e a = ( x / 2 ) - ( 1 / 2 ) i . e a = ( 2 x - 2 ) / 4 i . e a = ( x - 1 ) / 2 like wise - - - - after 2 nd person ate b = ( a - 1 ) / 2 like wise - - - - after 3 rd person ate c = ( b - 1 ) / 2 like wise - - - - after 4 th person ate d = ( c - 1 ) / 2 like wise - - - - after 5 th person ate e = ( d - 1 ) / 2 now as after 5 th person ate the value of remaining bread is - - - 3 therefore the value of e = 3 ; now go reverse from botom to top to get the value of x after calcuating value of d = 7 value of c = 15 value of b = 31 value of a = 63 value of x = 127 so the final answer is 127 breads were there answer : d | general |
math_qa__A7rEZ80E5dU5roZY | In an examination 35% of the students passed and 260 failed. How many students appeared for the examination? Choose the correct choice from the following answers.
A) 540 B) 400 C) 700 D) 650 E) 840 | <gadget id="calculator">260 * 100</gadget>
<output>26_000</output>
<gadget id="calculator">100 - 35</gadget>
<output>65</output>
<gadget id="calculator">26_000 / 65</gadget>
<output>400</output>
<result>B</result> | B | 400 | In an examination 35% of the students passed and 260 failed. How many students appeared for the examination? | {
"A": "540",
"B": "400",
"C": "700",
"D": "650",
"E": "840"
} | divide(multiply(260, const_100), subtract(const_100, 35)) | multiply(n1,const_100)|subtract(const_100,n0)|divide(#0,#1)| | "let the number of students appeared be x then , 65 % of x = 260 65 x / 100 = 260 x = 260 * 100 / 65 = 400 answer is b" | gain |
math_qa__kp48eM31q2w6HADX | If 8 women can color 400 m long cloth in 5 days, then 10 women can color 500 m long cloth in?
Choose the correct choice from the following answers: A) 6 days B) 4 days C) 5 days D) 15 days E) 10 days | <gadget id="calculator">8 * 5</gadget>
<output>40</output>
<gadget id="calculator">400 / 40</gadget>
<output>10</output>
<gadget id="calculator">10 * 10</gadget>
<output>100</output>
<gadget id="calculator">500 / 100</gadget>
<output>5</output>
<result>C</result> | C | 5 | If 8 women can color 400 m long cloth in 5 days, then 10 women can color 500 m long cloth in? | {
"A": "6 days",
"B": "4 days",
"C": "5 days",
"D": "15 days",
"E": "10 days"
} | divide(500, multiply(10, divide(400, multiply(8, 5)))) | multiply(n0,n2)|divide(n1,#0)|multiply(n3,#1)|divide(n4,#2)| | "the length of cloth painted by one woman in one day = 400 / 8 × 5 = 10 m no . of days required to paint 500 m cloth by 10 women = 500 / 10 × 10 = 5 days answer : c" | physics |
math_qa__KUzlIiOsVgYKgyJz | average of 6 numbers comes out to be 3.95 . average of two of the numbers is 3.4 while the average of other two is 3.85 . determine the average of the two numbers left .
Choose the correct choice from the following answers
A) 4.7 B) 4.8 C) 4.3 D) 4.6 E) 4.9 | <gadget id="calculator">2 / 6</gadget>
<output>1/3 = around 0.333333</output>
<gadget id="calculator">3.4 * (1/3)</gadget>
<output>1.133333</output>
<gadget id="calculator">3.85 * (1/3)</gadget>
<output>1.283333</output>
<gadget id="calculator">1.133333 + 1.283333</gadget>
<output>2.416666</output>
<gadget id="calculator">3.95 - 2.416666</gadget>
<output>1.533334</output>
<gadget id="calculator">1.533334 / (1/3)</gadget>
<output>4.600002</output>
<result>D</result> | D | 4.6 | average of 6 numbers comes out to be 3.95 . average of two of the numbers is 3.4 while the average of other two is 3.85 . determine the average of the two numbers left . | {
"A": "4.7",
"B": "4.8",
"C": "4.3",
"D": "4.6",
"E": "4.9"
} | divide(subtract(3.95, add(multiply(3.4, divide(const_2, 6)), multiply(3.85, divide(const_2, 6)))), divide(const_2, 6)) | divide(const_2,n0)|multiply(n2,#0)|multiply(n3,#0)|add(#1,#2)|subtract(n1,#3)|divide(#4,#0) | explanation : in the given question we have taken average of 6 numbers taken 2 at a time which makes 3 numbers . = > 3.95 ( average of 1 st and 2 nd number ) = > 3.85 ( average of 3 rd and 4 th number ) = > 3.4 ( average of 5 th and 6 th number ) 3.95 = ( 3.4 + 3.85 + x ) / 3 x = 4.6 answer d | general |
math_qa__JVOVTgcFIgQrioQi | The average weight of 8 person's increases by 4 kg when a new person comes in place of one of them weighing 55 kg. What might be the weight of the new person? Choose the correct choice from the following answers.
A) 80 kg B) 87 kg C) 90 kg D) 100 kg E) 110 kg | <gadget id="calculator">8 * 4</gadget>
<output>32</output>
<gadget id="calculator">32 + 55</gadget>
<output>87</output>
<result>B</result> | B | 87 | The average weight of 8 person's increases by 4 kg when a new person comes in place of one of them weighing 55 kg. What might be the weight of the new person? | {
"A": "80 kg",
"B": "87 kg",
"C": "90 kg",
"D": "100 kg",
"E": "110 kg"
} | add(multiply(8, 4), 55) | multiply(n0,n1)|add(n2,#0)| | "total weight increased = ( 8 x 4 ) kg = 32 kg . weight of new person = ( 55 + 32 ) kg = 87 kg . b )" | general |
math_qa__QhRdp2VcHpSiC6LQ | A 900 m long train crosses a platform in 39 sec while it crosses a signal pole in 18 sec. What is the length of the platform? Pick one: A) 1000 B) 1050 C) 1060 D) 370 E) 380 | <gadget id="calculator">900 / 18</gadget>
<output>50</output>
<gadget id="calculator">50 * 39</gadget>
<output>1_950</output>
<gadget id="calculator">1_950 - 900</gadget>
<output>1_050</output>
<result>B</result> | B | 1,050 | A 900 m long train crosses a platform in 39 sec while it crosses a signal pole in 18 sec. What is the length of the platform? | {
"A": "1000",
"B": "1050",
"C": "1060",
"D": "370",
"E": "380"
} | subtract(multiply(speed(900, 18), 39), 900) | speed(n0,n2)|multiply(n1,#0)|subtract(#1,n0)| | "speed = 900 / 18 = 50 / 1 m / sec . let the length of the platform be x meters . then , ( x + 300 ) / 39 = 50 / 1 = > x = 1950 m . l = 1950 - 900 = 1050 answer : option b" | physics |
math_qa__fDtqvKzC32Las5wC | A horse is tethered to one corner of a rectangular grassy field 40 m by 24 m with a rope 14 m long. Over how much area of the field can it graze? Pick
A) 154 cm 2 B) 308 m 2 C) 150 m 2 D) 407 m 2 E) none of these | <gadget id="calculator">14 ** 2</gadget>
<output>196</output>
<gadget id="calculator">196 * pi</gadget>
<output>196*pi = around 615.75216</output>
<gadget id="calculator">(196*pi) / 4</gadget>
<output>49*pi = around 153.93804</output>
<result>A</result> | A | 154 | A horse is tethered to one corner of a rectangular grassy field 40 m by 24 m with a rope 14 m long. Over how much area of the field can it graze? | {
"A": "154 cm 2",
"B": "308 m 2",
"C": "150 m 2",
"D": "407 m 2",
"E": "none of these"
} | divide(multiply(power(14, const_2), const_pi), const_4) | power(n2,const_2)|multiply(#0,const_pi)|divide(#1,const_4) | area of the shaded portion = 1 ⁄ 4 × π × ( 14 ) 2 = 154 m 2 answer a | geometry |
math_qa__En3WM2lDnk80En9Z | Reeya obtained 55, 67, 76, 82 and 55 out of 100 in different subjects, What will be the average Choose one.
A) 70
B) 75
C) 67
D) 85
E) 90 | <gadget id="calculator">55 + 67</gadget>
<output>122</output>
<gadget id="calculator">122 + 76</gadget>
<output>198</output>
<gadget id="calculator">198 + 82</gadget>
<output>280</output>
<gadget id="calculator">280 + 55</gadget>
<output>335</output>
<gadget id="calculator">4 + 1</gadget>
<output>5</output>
<gadget id="calculator">335 / 5</gadget>
<output>67</output>
<result>C</result> | C | 67 | Reeya obtained 55, 67, 76, 82 and 55 out of 100 in different subjects, What will be the average | {
"A": "70",
"B": "75",
"C": "67",
"D": "85",
"E": "90"
} | divide(add(add(add(add(55, 67), 76), 82), 55), add(const_4, const_1)) | add(n0,n1)|add(const_1,const_4)|add(n2,#0)|add(n3,#2)|add(n4,#3)|divide(#4,#1)| | "explanation : ( 55 + 67 + 76 + 82 + 55 / 5 ) = 67 option c" | general |
math_qa__Pvgdini87upur9bh | A circular garden is surrounded by a fence of negligible width along the boundary. If the length of the fence is 1/8 of th area of the garden. What is the radius of the circular garden? Select: A) 1 B) 2 C) 4 D) 8 E) 16 | <gadget id="calculator">8 ** 2</gadget>
<output>64</output>
<gadget id="calculator">64 ** (1/2)</gadget>
<output>8</output>
<gadget id="calculator">2 * 8</gadget>
<output>16</output>
<result>E</result> | E | 16 | A circular garden is surrounded by a fence of negligible width along the boundary. If the length of the fence is 1/8 of th area of the garden. What is the radius of the circular garden? | {
"A": "1",
"B": "2",
"C": "4",
"D": "8",
"E": "16"
} | multiply(const_2, sqrt(power(8, const_2))) | power(n1,const_2)|sqrt(#0)|multiply(#1,const_2) | as per the question - - width is negligible now , let l be the length of the fence = 2 pir l = 1 / 8 ( pir ^ 2 ) pir ^ 2 = 16 pir r = 16 answer : e | geometry |
math_qa__xxbIsy27NMJXF6zi | At the end of the first quarter, the share price of a certain mutual fund was 20 percent higher than it was at the beginning of the year. At the end of the second quarter, the share price was 60 percent higher than it was at the beginning of the year. What was the percent increase in the share price from the end of the first quarter to the end of the second quarter? Select:
A) 20 % B) 25 % C) 30 % D) 33.33 % E) 40 % | <gadget id="calculator">100 + 60</gadget>
<output>160</output>
<gadget id="calculator">100 + 20</gadget>
<output>120</output>
<gadget id="calculator">160 / 120</gadget>
<output>4/3 = around 1.333333</output>
<gadget id="calculator">(4/3) - 1</gadget>
<output>1/3 = around 0.333333</output>
<gadget id="calculator">(1/3) * 100</gadget>
<output>100/3 = around 33.333333</output>
<result>D</result> | D | 33.33 | At the end of the first quarter, the share price of a certain mutual fund was 20 percent higher than it was at the beginning of the year. At the end of the second quarter, the share price was 60 percent higher than it was at the beginning of the year. What was the percent increase in the share price from the end of the first quarter to the end of the second quarter? | {
"A": "20 %",
"B": "25 %",
"C": "30 %",
"D": "33.33 %",
"E": "40 %"
} | multiply(subtract(divide(add(const_100, 60), add(const_100, 20)), const_1), const_100) | add(n1,const_100)|add(n0,const_100)|divide(#0,#1)|subtract(#2,const_1)|multiply(#3,const_100)| | "another method is to use the formula for 2 successive percentage changes : total = a + b + ab / 100 60 = 20 + b + 20 b / 100 b = 33.33 answer ( d )" | gain |
math_qa__05RZbwnCmPjs8rUn | Find the area of a cuboid of length 4cm , breadth 6 cm . and height 5cm. Options.
A) 120 cm cube B) 110 cm cube C) 220 cm cube D) 430 cm cube E) 480 cm cube | <gadget id="calculator">4 * 6</gadget>
<output>24</output>
<gadget id="calculator">24 * 5</gadget>
<output>120</output>
<result>A</result> | A | 120 | Find the area of a cuboid of length 4cm , breadth 6 cm . and height 5cm. | {
"A": "120 cm cube",
"B": "110 cm cube",
"C": "220 cm cube",
"D": "430 cm cube",
"E": "480 cm cube"
} | multiply(multiply(4, 6), 5) | multiply(n0,n1)|multiply(n2,#0) | area of a cuboid = lxbxh = 4 cm x 6 cm x 5 cm = 120 cm cube answer : a | physics |
math_qa__mocnO73mFawQBr7J | A man traveled a total distance of 1800 km. He traveled one-third of the whole trip by plane and the distance traveled by train is two-thirds of the distance traveled by bus. If he traveled by train, plane and bus, how many kilometers did he travel by bus? Choose the correct choice from the following choices:
A) 660
B) 680
C) 720
D) 760
E) 800 | <gadget id="calculator">1_800 * 2</gadget>
<output>3_600</output>
<gadget id="calculator">3_600 / 3</gadget>
<output>1_200</output>
<gadget id="calculator">1_200 * 3</gadget>
<output>3_600</output>
<gadget id="calculator">2 + 3</gadget>
<output>5</output>
<gadget id="calculator">3_600 / 5</gadget>
<output>720</output>
<result>C</result> | C | 720 | A man traveled a total distance of 1800 km. He traveled one-third of the whole trip by plane and the distance traveled by train is two-thirds of the distance traveled by bus. If he traveled by train, plane and bus, how many kilometers did he travel by bus? | {
"A": "660",
"B": "680",
"C": "720",
"D": "760",
"E": "800"
} | divide(multiply(divide(multiply(1800, const_2), const_3), const_3), add(const_2, const_3)) | add(const_2,const_3)|multiply(n0,const_2)|divide(#1,const_3)|multiply(#2,const_3)|divide(#3,#0)| | "total distance traveled = 1800 km . distance traveled by plane = 600 km . distance traveled by bus = x distance traveled by train = 2 x / 3 x + 2 x / 3 + 600 = 1800 5 x / 3 = 1200 x = 720 km the answer is c ." | physics |
math_qa__nDWXqaaUvASpGoFJ | A, B and C enter into a partnership. A invests 3 times as much as B invests and 2/3 of what C invests. At the end of the year, the profit earned is Rs. 55000. What is the share of C? Choose the correct choice from the following options.
A) rs . 12250 B) rs . 13375 C) rs . 16750 D) rs . 15000 E) none of these | <gadget id="calculator">2 / 3</gadget>
<output>2/3 = around 0.666667</output>
<gadget id="calculator">(2/3) * 3</gadget>
<output>2</output>
<gadget id="calculator">(2/3) + 2</gadget>
<output>8/3 = around 2.666667</output>
<gadget id="calculator">(8/3) + 1</gadget>
<output>11/3 = around 3.666667</output>
<gadget id="calculator">1 / (11/3)</gadget>
<output>3/11 = around 0.272727</output>
<gadget id="calculator">55_000 * (3/11)</gadget>
<output>15_000</output>
<result>D</result> | D | 15,000 | A, B and C enter into a partnership. A invests 3 times as much as B invests and 2/3 of what C invests. At the end of the year, the profit earned is Rs. 55000. What is the share of C? | {
"A": "rs . 12250",
"B": "rs . 13375",
"C": "rs . 16750",
"D": "rs . 15000",
"E": "none of these"
} | multiply(55000, inverse(add(add(divide(2, 3), multiply(divide(2, 3), 3)), const_1))) | divide(n1,n0)|multiply(n0,#0)|add(#0,#1)|add(#2,const_1)|inverse(#3)|multiply(n3,#4) | explanation : let the investment of c be rs . x . the inverstment of b = rs . ( 2 x / 3 ) the inverstment of a = rs . ( 3 × ( 2 / 3 ) x ) = rs . ( 2 x ) ratio of capitals of a , b and c = 2 x : 2 x / 3 : x = 6 : 2 : 3 c ' s share = rs . [ ( 3 / 11 ) × 55000 ] = rs . 15000 answer : option d | gain |
math_qa__djSv55SNjjvw8PKz | A certain sum is invested at simple interest at 18% p.a. for two years instead of investing at 12% p.a. for the same time period. Therefore the interest received is more by Rs. 600. Find the sum? Choose the correct answer:
A) 7000 B) 7029 C) 2778 D) 2800 E) 5000 | <gadget id="calculator">18 - 12</gadget>
<output>6</output>
<gadget id="calculator">6 * 2</gadget>
<output>12</output>
<gadget id="calculator">12 / 100</gadget>
<output>3/25 = around 0.12</output>
<gadget id="calculator">600 / (3/25)</gadget>
<output>5_000</output>
<result>E</result> | E | 5,000 | A certain sum is invested at simple interest at 18% p.a. for two years instead of investing at 12% p.a. for the same time period. Therefore the interest received is more by Rs. 600. Find the sum? | {
"A": "7000",
"B": "7029",
"C": "2778",
"D": "2800",
"E": "5000"
} | divide(600, divide(multiply(subtract(18, 12), const_2), const_100)) | subtract(n0,n1)|multiply(#0,const_2)|divide(#1,const_100)|divide(n2,#2)| | "let the sum be rs . x . ( x * 18 * 2 ) / 100 - ( x * 12 * 2 ) / 100 = 600 = > 36 x / 100 - 24 x / 100 = 600 = > 12 x / 100 = 600 = > x = 5000 . answer : e" | gain |
math_qa__8dCwSuRqmUJ3T0WL | there are 100 freshmen at a particular college , all of whom must take at least one of the 3 core classes : art , biology , and calculus . of these freshmen , 17 take only biology , 10 take only calculus , 9 take all 3 classes , and 20 take art and exactly one of the other two core classes . if the number of freshmen who take only art is 3 times the number of freshmen who take every core class except art , how many freshmen take art ? Choose the correct answer:
A) 25 B) 32 C) 36 D) 48 E) 62 | <gadget id="calculator">17 + 10</gadget>
<output>27</output>
<gadget id="calculator">27 + 9</gadget>
<output>36</output>
<gadget id="calculator">36 + 20</gadget>
<output>56</output>
<gadget id="calculator">100 - 56</gadget>
<output>44</output>
<gadget id="calculator">44 * 3</gadget>
<output>132</output>
<gadget id="calculator">132 / 4</gadget>
<output>33</output>
<gadget id="calculator">33 + 20</gadget>
<output>53</output>
<gadget id="calculator">53 + 9</gadget>
<output>62</output>
<result>E</result> | E | 62 | there are 100 freshmen at a particular college , all of whom must take at least one of the 3 core classes : art , biology , and calculus . of these freshmen , 17 take only biology , 10 take only calculus , 9 take all 3 classes , and 20 take art and exactly one of the other two core classes . if the number of freshmen who take only art is 3 times the number of freshmen who take every core class except art , how many freshmen take art ? | {
"A": "25",
"B": "32",
"C": "36",
"D": "48",
"E": "62"
} | add(add(divide(multiply(subtract(100, add(add(add(17, 10), 9), 20)), 3), const_4), 20), 9) | add(n2,n3)|add(n4,#0)|add(n6,#1)|subtract(n0,#2)|multiply(n1,#3)|divide(#4,const_4)|add(n6,#5)|add(n4,#6) | make a venn diagram to get a clear picture . look at the diagram : each letter represents only one color . b represents the people who take only art . d represents people who take only art and bio etc . d + f = 20 ( people who take art and one other class ) b = 3 e ( people who take only art is 3 times the people who take bio and calculus ) 17 + 10 + 9 + b + d + e + f = 100 ( total people ) b + b / 3 = 44 b = 33 number of freshmen who take art = 33 + 20 + 9 = 62 answer e | general |
math_qa__5TFpC6dGqQnO56jK | A goods train runs at the speed of 72 km/hr and crosses a 250 m long platform in 26 sec. What is the length of the goods train? Choose one.
A) 228 B) 2000 C) 267 D) 270 E) 274 | <gadget id="calculator">72 / 3_600</gadget>
<output>1/50 = around 0.02</output>
<gadget id="calculator">(1/50) * 1_000</gadget>
<output>20</output>
<gadget id="calculator">20 * 26</gadget>
<output>520</output>
<gadget id="calculator">520 - 250</gadget>
<output>270</output>
<result>D</result> | D | 270 | A goods train runs at the speed of 72 km/hr and crosses a 250 m long platform in 26 sec. What is the length of the goods train? | {
"A": "228",
"B": "2000",
"C": "267",
"D": "270",
"E": "274"
} | subtract(multiply(multiply(divide(72, const_3600), const_1000), 26), 250) | divide(n0,const_3600)|multiply(#0,const_1000)|multiply(n2,#1)|subtract(#2,n1)| | "speed = 72 * 5 / 18 = 20 m / sec . time = 26 sec . let the length of the train be x meters . then , ( x + 250 ) / 26 = 20 x = 270 m . answer : d" | physics |
math_qa__dQygKzjvQxlTXi7L | A goods train runs at the speed of 72 km/hr and crosses a 150 m long platform in 26 sec. What is the length of the goods train?
Choose the correct option.
A) 299 B) 277 C) 276 D) 370 E) 281 | <gadget id="calculator">72 / 3_600</gadget>
<output>1/50 = around 0.02</output>
<gadget id="calculator">(1/50) * 1_000</gadget>
<output>20</output>
<gadget id="calculator">20 * 26</gadget>
<output>520</output>
<gadget id="calculator">520 - 150</gadget>
<output>370</output>
<result>D</result> | D | 370 | A goods train runs at the speed of 72 km/hr and crosses a 150 m long platform in 26 sec. What is the length of the goods train? | {
"A": "299",
"B": "277",
"C": "276",
"D": "370",
"E": "281"
} | subtract(multiply(multiply(divide(72, const_3600), const_1000), 26), 150) | divide(n0,const_3600)|multiply(#0,const_1000)|multiply(n2,#1)|subtract(#2,n1)| | "speed = 72 * 5 / 18 = 20 m / sec . time = 26 sec . let the length of the train be x meters . then , ( x + 150 ) / 26 = 20 x = 370 m . answer : d" | physics |
math_qa__qCLWVRfwJ0FOOAyK | If W is the set of all the integers between 49 and 76, inclusive, that are either multiples of 3 or multiples of 2 or multiples of both, then W contains how many numbers? Choose the correct answer.
A) 19 B) 91 C) 41 D) 18 E) 14 | <gadget id="calculator">76 - 49</gadget>
<output>27</output>
<gadget id="calculator">27 / 3</gadget>
<output>9</output>
<gadget id="calculator">floor(9)</gadget>
<output>9</output>
<gadget id="calculator">27 / 2</gadget>
<output>27/2 = around 13.5</output>
<gadget id="calculator">9 + (27/2)</gadget>
<output>45/2 = around 22.5</output>
<gadget id="calculator">2 * 3</gadget>
<output>6</output>
<gadget id="calculator">27 / 6</gadget>
<output>9/2 = around 4.5</output>
<gadget id="calculator">floor(9/2)</gadget>
<output>4</output>
<gadget id="calculator">(45/2) - 4</gadget>
<output>37/2 = around 18.5</output>
<result>A</result> | A | 19 | If W is the set of all the integers between 49 and 76, inclusive, that are either multiples of 3 or multiples of 2 or multiples of both, then W contains how many numbers? | {
"A": "19",
"B": "91",
"C": "41",
"D": "18",
"E": "14"
} | subtract(add(floor(divide(subtract(76, 49), 3)), divide(subtract(76, 49), 2)), floor(divide(subtract(76, 49), multiply(2, 3)))) | multiply(n3,n2)|subtract(n1,n0)|divide(#1,n3)|divide(#1,n2)|divide(#1,#0)|floor(#3)|floor(#4)|add(#2,#5)|subtract(#7,#6)| | "official solution : number of multiples of 3 step 1 . subtract the extreme multiples of 3 within the range ( the greatest is 75 , the smallest is 51 ) : 75 - 51 = 24 step 2 . divide by 3 : 24 / 3 = 8 step 3 . add 1 : 8 + 1 = 9 . so there are 9 multiples of 3 within the range : examples are 51 , 54 , 57 , 60 , etc . number of multiples of 2 step 1 . subtract the extreme multiples of 2 within the range ( the greatest is 76 , the smallest is 50 ) : 76 - 50 = 26 step 2 . divide by 2 : 26 / 2 = 13 step 3 . add 1 : 13 + 1 = 14 . so there are 14 multiples of 2 within the range : examples are 50 , 52 , 54 , 56 , 58 , 60 etc . add the 9 multiples of 3 and the 14 multiples of 2 : 9 + 14 = 23 . however , by adding the multiples of 2 and the multiples of 3 , we are effectively counting several numbers twice : for example , 54 and 60 are parts of both the lists above . so we ca n ' t just take 9 + 14 = 23 . find the number of multiples of 6 ( which are the double counted , as 6 is divisible by both 2 and 3 ) , and subtract it from 23 : step 1 . subtract the extreme multiples of 6 within the range ( the greatest is 72 , the smallest is 54 ) : 72 - 54 = 18 step 2 . divide by 6 : 18 / 6 = 3 step 3 . add 1 : 3 + 1 = 4 . so there are 4 multiples of 6 within the range : we counted 4 numbers twice . subtract the 4 multiples of 6 from the sum of the multiples of 2 and 3 : = 9 + 14 - 4 = 23 - 4 = 19 therefore , the final number of multiples of 2 , 3 or 6 is 19 . hence , this is the correct answer . ( a )" | other |
math_qa__dU73GR6RThWBYgjn | The ratio between the sale price and the cost price of an article is 10:7. What is the ratio between the profit and the cost price of that article? Choose the correct answer.
A) 2 : 9 B) 2 : 5 C) 3 : 7 D) 2 : 0 E) 2 : 1 | <gadget id="calculator">10 - 7</gadget>
<output>3</output>
<gadget id="calculator">3 / 7</gadget>
<output>3/7 = around 0.428571</output>
<result>C</result> | C | 0.428571 | The ratio between the sale price and the cost price of an article is 10:7. What is the ratio between the profit and the cost price of that article? | {
"A": "2 : 9",
"B": "2 : 5",
"C": "3 : 7",
"D": "2 : 0",
"E": "2 : 1"
} | divide(subtract(10, 7), 7) | subtract(n0,n1)|divide(#0,n1)| | "let c . p . = rs . 7 x and s . p . = rs . 10 x . then , gain = rs . 3 x required ratio = 3 x : 7 x = 3 : 7 answer : c" | other |
math_qa__y4am0j2T7taeMelI | Two cyclist start on a circular track from a given point but in opposite direction with speeds of 7m/s and 8m/s. If the circumference of the circle is 300meters, after what time will they meet at the starting point? Choose the correct choice from the following answers:
A) 20 sec
B) 15 sec
C) 30 sec
D) 50 sec
E) 1 min | <gadget id="calculator">8 + 7</gadget>
<output>15</output>
<gadget id="calculator">300 / 15</gadget>
<output>20</output>
<result>A</result> | A | 20 | Two cyclist start on a circular track from a given point but in opposite direction with speeds of 7m/s and 8m/s. If the circumference of the circle is 300meters, after what time will they meet at the starting point? | {
"A": "20 sec",
"B": "15 sec",
"C": "30 sec",
"D": "50 sec",
"E": "1 min"
} | divide(300, add(8, 7)) | add(n0,n1)|divide(n2,#0) | they meet every 300 / 7 + 8 = 20 sec answer is a | physics |
math_qa__mJ2iZ9Q3k8ncvLbD | City X has a population 5 times as great as the population of City Y, which has a population twice as great as the population of City Z. What is the ratio of the population of City X to the population of City Z? Choose the correct choice from the following answers
A) 1 : 8 B) 1 : 4 C) 2 : 1 D) 4 : 1 E) 10 : 1 | <gadget id="calculator">5 * 2</gadget>
<output>10</output>
<result>E</result> | E | 10 | City X has a population 5 times as great as the population of City Y, which has a population twice as great as the population of City Z. What is the ratio of the population of City X to the population of City Z? | {
"A": "1 : 8",
"B": "1 : 4",
"C": "2 : 1",
"D": "4 : 1",
"E": "10 : 1"
} | multiply(5, const_2) | multiply(n0,const_2)| | "x = 5 y , y = 2 * z x : y , y : z 5 : 1 , 2 : 1 10 : 2 , 2 : 1 so , x : z = 10 : 1 ( e )" | general |
math_qa__AKIz6OQn0IhvPbV3 | A working mom wakes up every day at 7 am and goes to sleep at 11 pm. She works 8 hours a day. Spends 2 hours working out at the gym. She spends 1.5 hours cooking dinner and doing dishes. She spends .5 of an hour giving her daughter a bath. She spends 1 hour helping with homework and getting her daughter ready for bed. She spends another. 5 of an hour packing lunches for the family for the next day. She spends .5 of an hour cleaning the house and 2 hours taking a shower and reading or watching t.v. before she goes to sleep. What percent of her day does she spend at work?
Choices:
A) 60
B) 50
C) 70
D) 55
E) 40 | <gadget id="calculator">3 * 4</gadget>
<output>12</output>
<gadget id="calculator">12 - 7</gadget>
<output>5</output>
<gadget id="calculator">5 + 11</gadget>
<output>16</output>
<gadget id="calculator">8 / 16</gadget>
<output>1/2 = around 0.5</output>
<gadget id="calculator">(1/2) * 100</gadget>
<output>50</output>
<result>B</result> | B | 50 | A working mom wakes up every day at 7 am and goes to sleep at 11 pm. She works 8 hours a day. Spends 2 hours working out at the gym. She spends 1.5 hours cooking dinner and doing dishes. She spends .5 of an hour giving her daughter a bath. She spends 1 hour helping with homework and getting her daughter ready for bed. She spends another. 5 of an hour packing lunches for the family for the next day. She spends .5 of an hour cleaning the house and 2 hours taking a shower and reading or watching t.v. before she goes to sleep. What percent of her day does she spend at work? | {
"A": "60",
"B": "50",
"C": "70",
"D": "55",
"E": "40"
} | multiply(divide(8, add(subtract(multiply(const_3, const_4), 7), 11)), const_100) | multiply(const_3,const_4)|subtract(#0,n0)|add(n1,#1)|divide(n2,#2)|multiply(#3,const_100) | 8 + 2 + 1.5 + . 5 + 1 + . 5 + . 5 + 2 = 16 = total number of hours 8 / 16 = . 05 = 50 percemt the answer is b | physics |
math_qa__s79Qgzb1uhwM3v9s | In an office in Singapore there are 60% female employees. 50 % of all the male employees are computer literate. If there are total 62% employees computer literate out of total 1400 employees, then the no. of female employees who are computer literate ? Choose the correct choice from the following:
A) 588 B) 674 C) 672 D) 960 E) none | <gadget id="calculator">62 / 100</gadget>
<output>31/50 = around 0.62</output>
<gadget id="calculator">60 / 100</gadget>
<output>3/5 = around 0.6</output>
<gadget id="calculator">1 - (3/5)</gadget>
<output>2/5 = around 0.4</output>
<gadget id="calculator">50 / 100</gadget>
<output>1/2 = around 0.5</output>
<gadget id="calculator">(2/5) * (1/2)</gadget>
<output>1/5 = around 0.2</output>
<gadget id="calculator">(31/50) - (1/5)</gadget>
<output>21/50 = around 0.42</output>
<gadget id="calculator">(21/50) * 1_400</gadget>
<output>588</output>
<result>A</result> | A | 588 | In an office in Singapore there are 60% female employees. 50 % of all the male employees are computer literate. If there are total 62% employees computer literate out of total 1400 employees, then the no. of female employees who are computer literate ? | {
"A": "588",
"B": "674",
"C": "672",
"D": "960",
"E": "none"
} | multiply(subtract(divide(62, const_100), multiply(subtract(const_1, divide(60, const_100)), divide(50, const_100))), 1400) | divide(n2,const_100)|divide(n1,const_100)|divide(n0,const_100)|subtract(const_1,#2)|multiply(#1,#3)|subtract(#0,#4)|multiply(n3,#5)| | "solution : total employees , = 1400 female employees , 60 % of 1400 . = ( 60 * 1400 ) / 100 = 840 . then male employees , = 560 50 % of male are computer literate , = 280 male computer literate . 62 % of total employees are computer literate , = ( 62 * 1400 ) / 100 = 868 computer literate . thus , female computer literate = 868 - 280 = 588 . answer : option a" | gain |
math_qa__UytFRPwUPIpMAOVh | Sales price is $81, gross profit is 170% of cost, what is the value of gross profit? Choose the correct choice:
A) 32 B) 33 C) 39 D) 40 E) 51 | <gadget id="calculator">170 / 100</gadget>
<output>17/10 = around 1.7</output>
<gadget id="calculator">1 + (17/10)</gadget>
<output>27/10 = around 2.7</output>
<gadget id="calculator">81 / (27/10)</gadget>
<output>30</output>
<gadget id="calculator">81 - 30</gadget>
<output>51</output>
<result>E</result> | E | 51 | Sales price is $81, gross profit is 170% of cost, what is the value of gross profit? | {
"A": "32",
"B": "33",
"C": "39",
"D": "40",
"E": "51"
} | subtract(81, divide(81, add(const_1, divide(170, const_100)))) | divide(n1,const_100)|add(#0,const_1)|divide(n0,#1)|subtract(n0,#2)| | "cost + profit = sales cost + ( 170 / 100 ) cost = 81 cost = 30 profit = 81 - 30 = 51 answer ( e )" | gain |
math_qa__uIUOjwUGdykdSXMd | If the product of two numbers is 17820 and their H.C.F. is 12, find their L.C.M.
Select
A) 2574
B) 2500
C) 1485
D) 1574
E) none of these | <gadget id="calculator">17_820 / 12</gadget>
<output>1_485</output>
<result>C</result> | C | 1,485 | If the product of two numbers is 17820 and their H.C.F. is 12, find their L.C.M. | {
"A": "2574",
"B": "2500",
"C": "1485",
"D": "1574",
"E": "none of these"
} | divide(17820, 12) | divide(n0,n1)| | "explanation : hcf * lcm = 17820 , because we know product of two numbers = product of hcf and lcm lcm = 17820 / 12 = 1485 option c" | physics |
math_qa__YT3JLaoxLRirrnEp | Thabo owns exactly 160 books, and each book is either paperback fiction, paperback nonfiction, or hardcover nonfiction. If he owns 20 more paperback nonfiction books than hardcover nonfiction books, and twice as many paperback fiction books as paperback nonfiction books, how many hardcover books nonfiction books does Thabo own? Choices:
A) 10 B) 25 C) 35 D) 46 E) 50 | <gadget id="calculator">160 + 20</gadget>
<output>180</output>
<gadget id="calculator">180 / 4</gadget>
<output>45</output>
<gadget id="calculator">45 - 20</gadget>
<output>25</output>
<result>B</result> | B | 25 | Thabo owns exactly 160 books, and each book is either paperback fiction, paperback nonfiction, or hardcover nonfiction. If he owns 20 more paperback nonfiction books than hardcover nonfiction books, and twice as many paperback fiction books as paperback nonfiction books, how many hardcover books nonfiction books does Thabo own? | {
"A": "10",
"B": "25",
"C": "35",
"D": "46",
"E": "50"
} | subtract(divide(add(160, 20), const_4), 20) | add(n0,n1)|divide(#0,const_4)|subtract(#1,n1) | i think we can use double - matrix method and solve using only one variable . our goal is to find the number of hardcover nonfiction books . let that number be x . we are given that all 140 books are either paperback fiction , paperback nonfiction , or hardcover nonfiction . this implies that number of hardcover fiction books is 0 . double - matrix : p = paperback ; h = hardcover ; f = fiction ; nf = nonfiction p h total f 2 x + 40 0 nf x + 20 x total 3 x + 60 x 160 3 x + 60 + x = 160 x = 25 answer ( b . ) | general |
math_qa__ENoFUtjUCOHIR9F3 | Evaluate 100 / .25 Pick one:
A) 400
B) 510
C) 500
D) none of these
E) 506 | <gadget id="calculator">25 / 100</gadget>
<output>1/4 = around 0.25</output>
<gadget id="calculator">100 / (1/4)</gadget>
<output>400</output>
<result>A</result> | A | 400 | Evaluate 100 / .25 | {
"A": "400",
"B": "510",
"C": "500",
"D": "none of these",
"E": "506"
} | divide(100, divide(25, const_100)) | divide(n1,const_100)|divide(n0,#0) | explanation : 100 / . 25 = 10000 / 25 = 400 option a | general |
math_qa__5zx7CUI1OD1EP6NN | What is the smallest integer that is the sum of 2 distinct prime integers, each greater than 70 ? Pick one
A) 147 B) 142 C) 173 D) 144 E) 186 | <gadget id="calculator">70 + 1</gadget>
<output>71</output>
<gadget id="calculator">70 + 3</gadget>
<output>73</output>
<gadget id="calculator">71 + 73</gadget>
<output>144</output>
<result>D</result> | D | 144 | What is the smallest integer that is the sum of 2 distinct prime integers, each greater than 70 ? | {
"A": "147",
"B": "142",
"C": "173",
"D": "144",
"E": "186"
} | add(add(70, const_1), add(70, const_3)) | add(n1,const_1)|add(n1,const_3)|add(#0,#1) | a prime number ( or a prime ) is a natural number greater than 1 that has no positive divisors other than 1 and itself . here are the first few prime numbers : 2 , 3 , 5 , 7 , 11 , 13 , 17 , 19 , 23 , 29 , 31 , 37 , 41 , 43 , 47 , 53 , 59 , 61 , 67 , 71 , 73 , 79 , 83 , 89 , 97 , 101 , 103 , 107 , 109 , 113 , 127 , 131 , 137 , 139 , 149 , 151 , 157 , 163 , 167 , 173 , 179 , 181 , 191 , 193 , 197 , 199 , etc . immediate two prime numbers after 70 are - 71 and 73 sum = 71 + 73 = 144 answer - d | general |
math_qa__wfVBBwGmIuVt2yu7 | For any integer k > 1, the term “length of an integer” refers to the number of positive prime factors, not necessarily distinct, whose product is equal to k. For example, if k = 24, the length of k is equal to 4, since 24 = 2 × 2 × 2 × 3. If x and y are positive integers such that x > 1, y > 1, and x + 3y < 940, what is the maximum possible sum of the length of x and the length of y? Pick one:
A) 24 B) 22 C) 16 D) 18 E) 20 | <gadget id="calculator">4 + 3</gadget>
<output>7</output>
<gadget id="calculator">4 + 4</gadget>
<output>8</output>
<gadget id="calculator">8 + 1</gadget>
<output>9</output>
<gadget id="calculator">7 + 9</gadget>
<output>16</output>
<result>C</result> | C | 16 | For any integer k > 1, the term “length of an integer” refers to the number of positive prime factors, not necessarily distinct, whose product is equal to k. For example, if k = 24, the length of k is equal to 4, since 24 = 2 × 2 × 2 × 3. If x and y are positive integers such that x > 1, y > 1, and x + 3y < 940, what is the maximum possible sum of the length of x and the length of y? | {
"A": "24",
"B": "22",
"C": "16",
"D": "18",
"E": "20"
} | add(add(4, 3), add(add(4, 4), 1)) | add(n2,n7)|add(n2,n2)|add(n0,#1)|add(#0,#2)| | "we know that : x > 1 , y > 1 , and x + 3 y < 940 , and it is given that length means no of factors . for any value of x and y , the max no of factors can be obtained only if factor is smallest noall factors are equal . hence , lets start with smallest no 2 . 2 ^ 1 = 2 2 ^ 2 = 4 2 ^ 3 = 8 2 ^ 4 = 16 2 ^ 5 = 32 2 ^ 6 = 64 2 ^ 7 = 128 2 ^ 8 = 256 2 ^ 9 = 512 2 ^ 10 = 1024 ( opps / / it exceeds 1000 , so , x ca n ' t be 2 ^ 10 ) so , max value that x can take is 2 ^ 9 , for which haslength of integeris 9 . now , since x = 512 , x + 3 y < 940 so , 3 y < 428 = = > y < 428 / 3 so , y can take any value which is less than 428 / 3 . and to get the maximum no of factors of smallest integer , we can say y = 2 ^ 7 for 2 ^ 7 has length of integer is 7 . so , combined together : 9 + 7 = 16 . c" | general |
math_qa__75F2JynO0nfa60qr | The perimeter of a semi circle is 162 cm then the radius is? Choose the correct choice from the following:
A) 31.5 B) 28 C) 98 D) 37 E) 13 | <gadget id="calculator">2 + pi</gadget>
<output>2 + pi = around 5.141593</output>
<gadget id="calculator">162 / (2 + pi)</gadget>
<output>162/(2 + pi) = around 31.507747</output>
<result>A</result> | A | 31.5 | The perimeter of a semi circle is 162 cm then the radius is? | {
"A": "31.5",
"B": "28",
"C": "98",
"D": "37",
"E": "13"
} | divide(162, add(const_2, const_pi)) | add(const_2,const_pi)|divide(n0,#0)| | "36 / 7 r = 162 = > r = 31.5 answer : a" | physics |
math_qa__kUFWzSUwFEEgcpCo | Together, 15 type A machines and 7 type B machines can complete a certain job in 4 hours. Together 8 type B machines and 15 type C machines can complete the same job in 11 hours. How many hours R would it take one type A machine, one type B machine, and one type C machine working together to complete the job (assuming constant rates for each machine)? Choose one:
A) 22 hours
B) 30 hours
C) 44 hours
D) 60 hours
E) it can not be determined from the information above . | <gadget id="calculator">1 / 4</gadget>
<output>1/4 = around 0.25</output>
<gadget id="calculator">1 / 11</gadget>
<output>1/11 = around 0.090909</output>
<gadget id="calculator">(1/4) + (1/11)</gadget>
<output>15/44 = around 0.340909</output>
<gadget id="calculator">(15/44) / 15</gadget>
<output>1/44 = around 0.022727</output>
<gadget id="calculator">1 / (1/44)</gadget>
<output>44</output>
<result>C</result> | C | 44 | Together, 15 type A machines and 7 type B machines can complete a certain job in 4 hours. Together 8 type B machines and 15 type C machines can complete the same job in 11 hours. How many hours R would it take one type A machine, one type B machine, and one type C machine working together to complete the job (assuming constant rates for each machine)? | {
"A": "22 hours",
"B": "30 hours",
"C": "44 hours",
"D": "60 hours",
"E": "it can not be determined from the information above ."
} | divide(const_1, divide(add(divide(const_1, 4), divide(const_1, 11)), 15)) | divide(const_1,n2)|divide(const_1,n5)|add(#0,#1)|divide(#2,n0)|divide(const_1,#3)| | "say the rates of machines a , b and c are a , b , and c , respectively . together 15 type a machines and 7 type b machines can complete a certain job in 4 hours - - > 15 a + 7 b = 1 / 4 ; together 8 type b machines and 15 type c machines can complete the same job in 11 hours - - > 8 b + 15 c = 1 / 11 . sum the above : 15 a + 15 b + 15 c = 1 / 4 + 1 / 11 = 15 / 44 - - > reduce by 15 : a + b + c = 1 / 44 - - > so , the combined rate of the three machines is 1 / 44 job / hour - - > time is reciprocal of the rate , thus machines a , b and c can do the job r in 44 hours . answer : c ." | physics |
math_qa__eRT3JJqsdDGM9Ejm | The cricket team of 11members is 28yrs old & the wicket keeper is 3 yrs older. If the ages ofthese 2are excluded, the average age of theremaining players is 1 year less than the average age of the whole team. What is the average age of the team ? Choose the correct choice from the following answers: A) 21 B) 22 C) 23 D) 25 E) 28 | <gadget id="calculator">28 + 3</gadget>
<output>31</output>
<gadget id="calculator">31 + 28</gadget>
<output>59</output>
<gadget id="calculator">11 - 2</gadget>
<output>9</output>
<gadget id="calculator">59 - 9</gadget>
<output>50</output>
<gadget id="calculator">11 - 9</gadget>
<output>2</output>
<gadget id="calculator">50 / 2</gadget>
<output>25</output>
<result>D</result> | D | 25 | The cricket team of 11members is 28yrs old & the wicket keeper is 3 yrs older. If the ages ofthese 2are excluded, the average age of theremaining players is 1 year less than the average age of the whole team. What is the average age of the team ? | {
"A": "21",
"B": "22",
"C": "23",
"D": "25",
"E": "28"
} | divide(subtract(add(add(28, 3), 28), subtract(11, 2)), subtract(11, subtract(11, 2))) | add(n1,n2)|subtract(n0,n3)|add(n1,#0)|subtract(n0,#1)|subtract(#2,#1)|divide(#4,#3)| | "let the average age of the whole team be x years . 11 x - ( 28 + 31 ) = 9 ( x - 1 ) = > 11 x - 9 x = 50 = > 2 x = 50 = > x = 25 . so , average age of the team is 25 years . d" | general |
math_qa__XL5M1MwPvzOMPgcO | A reduction of 30% in the price of apples would enable a man to obtain 54 more for Rs.30, what is reduced price per dozen? Choose the correct choice from the following answers:
A) 1 B) 2 C) 6 D) 7 E) 10 | <gadget id="calculator">30 * 30</gadget>
<output>900</output>
<gadget id="calculator">900 / 100</gadget>
<output>9</output>
<gadget id="calculator">9 / 54</gadget>
<output>1/6 = around 0.166667</output>
<gadget id="calculator">(1/6) * 12</gadget>
<output>2</output>
<result>B</result> | B | 2 | A reduction of 30% in the price of apples would enable a man to obtain 54 more for Rs.30, what is reduced price per dozen? | {
"A": "1",
"B": "2",
"C": "6",
"D": "7",
"E": "10"
} | multiply(divide(divide(multiply(30, 30), const_100), 54), const_12) | multiply(n0,n2)|divide(#0,const_100)|divide(#1,n1)|multiply(#2,const_12)| | "b 30 * ( 30 / 100 ) = 9 - - - 54 ? - - - 12 = > rs . 2" | gain |
math_qa__jPQ8riCUksNMKc9c | A certain psychologist charges $35 more for the first hour of therapy than for each additional hour. If the total charge to a patient who receives 5 hours of therapy is $350, what is the total charge to a patient who receives only 2 hours of therapy ?
Choose the most appropriate option:
A) $ 120 B) $ 135 C) $ 161 D) $ 165 E) $ 192 | <gadget id="calculator">350 - 35</gadget>
<output>315</output>
<gadget id="calculator">315 / 5</gadget>
<output>63</output>
<gadget id="calculator">63 * 2</gadget>
<output>126</output>
<gadget id="calculator">126 + 35</gadget>
<output>161</output>
<result>C</result> | C | 161 | A certain psychologist charges $35 more for the first hour of therapy than for each additional hour. If the total charge to a patient who receives 5 hours of therapy is $350, what is the total charge to a patient who receives only 2 hours of therapy ? | {
"A": "$ 120",
"B": "$ 135",
"C": "$ 161",
"D": "$ 165",
"E": "$ 192"
} | add(multiply(divide(subtract(350, 35), 5), 2), 35) | subtract(n2,n0)|divide(#0,n1)|multiply(n3,#1)|add(n0,#2)| | "let the charge for first hour = x + 35 then charge for each additional hour = x x + 35 + 4 x = 350 = > 5 x = 315 = > x = 63 total charge for patient for 3 hours of therapy = x + 35 + x = 2 x + 35 = 161 $ answer c" | general |
math_qa__36357qu3WTkGZXMf | The average length of 6 ropes is 80 cm. If the average length of one third of the ropes measure to 70 cm, what is the average of the other ropes?
Choose the correct option:
A) 75 .
B) 85 .
C) 90 .
D) 94 .
E) 100 . | <gadget id="calculator">70 * 2</gadget>
<output>140</output>
<gadget id="calculator">140 / 6</gadget>
<output>70/3 = around 23.333333</output>
<gadget id="calculator">80 - (70/3)</gadget>
<output>170/3 = around 56.666667</output>
<gadget id="calculator">6 / 4</gadget>
<output>3/2 = around 1.5</output>
<gadget id="calculator">(170/3) * (3/2)</gadget>
<output>85</output>
<result>B</result> | B | 85 | The average length of 6 ropes is 80 cm. If the average length of one third of the ropes measure to 70 cm, what is the average of the other ropes? | {
"A": "75 .",
"B": "85 .",
"C": "90 .",
"D": "94 .",
"E": "100 ."
} | multiply(subtract(80, divide(multiply(70, const_2), 6)), divide(6, const_4)) | divide(n0,const_4)|multiply(n2,const_2)|divide(#1,n0)|subtract(n1,#2)|multiply(#0,#3) | edit : given ( x 1 + x 2 . . . + x 6 ) / 6 = 80 ( x 1 + x 2 . . . + x 6 ) = 480 - - > eq 1 . now given avg length of one third ropes is 70 . that means out 6 / 3 = 2 ropes . let the avg length of two ropes be ( x 1 + x 2 ) / 2 = 70 . ( x 1 + x 2 ) = 140 . - - > eq 2 . now we are asked to find the average of the remaining i . e . ( x 3 + x 4 + x 5 + x 6 ) substitute eq 2 in eq 1 then we get 140 + x 3 + x 4 + x 5 + x 6 = 480 = > x 3 + x 4 + x 5 + x 6 = 340 now divide 340 by 4 we get 85 . = > ( x 3 + x 4 + x 5 + x 6 ) / 4 = 85 = avg length of remaining ropes . imo correct option is b . | general |
math_qa__QCu616WuKBGb7Zik | X and Y are two towns. Ganesh covers the distance from X to Y at an average speed of 44 Km/hr. However, he covers the distance from Y to X at an average speed of 36 Km/hr. His average speed during the whole journey in km/hr. is : Select the correct option
A) 39.6 B) 43 C) 40 D) 38 E) 29 | <gadget id="calculator">44 - 10</gadget>
<output>34</output>
<gadget id="calculator">34 + 100</gadget>
<output>134</output>
<gadget id="calculator">134 + 134</gadget>
<output>268</output>
<gadget id="calculator">134 / 44</gadget>
<output>67/22 = around 3.045455</output>
<gadget id="calculator">134 / 36</gadget>
<output>67/18 = around 3.722222</output>
<gadget id="calculator">(67/22) + (67/18)</gadget>
<output>670/99 = around 6.767677</output>
<gadget id="calculator">268 / (670/99)</gadget>
<output>198/5 = around 39.6</output>
<result>A</result> | A | 39.6 | X and Y are two towns. Ganesh covers the distance from X to Y at an average speed of 44 Km/hr. However, he covers the distance from Y to X at an average speed of 36 Km/hr. His average speed during the whole journey in km/hr. is : | {
"A": "39.6",
"B": "43",
"C": "40",
"D": "38",
"E": "29"
} | divide(add(add(subtract(44, const_10), const_100), add(subtract(44, const_10), const_100)), add(divide(add(subtract(44, const_10), const_100), 44), divide(add(subtract(44, const_10), const_100), 36))) | subtract(n0,const_10)|add(#0,const_100)|add(#1,#1)|divide(#1,n0)|divide(#1,n1)|add(#3,#4)|divide(#2,#5)| | "solution : average speed = 2 xy / x + y = 2 * 44 * 36 / 44 + 36 = 39.6 answer : a" | general |
math_qa__80CikShimhe9Yt4g | If the cost price is 95% of selling price then what is the profit percentage. Choose the correct choice from the following choices:
A) 5.26 B) 5.16 C) 5.61 D) 5.52 E) 5 | <gadget id="calculator">100 - 95</gadget>
<output>5</output>
<gadget id="calculator">5 / 95</gadget>
<output>1/19 = around 0.052632</output>
<gadget id="calculator">(1/19) * 100</gadget>
<output>100/19 = around 5.263158</output>
<result>A</result> | A | 5.26 | If the cost price is 95% of selling price then what is the profit percentage. | {
"A": "5.26",
"B": "5.16",
"C": "5.61",
"D": "5.52",
"E": "5"
} | multiply(divide(subtract(const_100, 95), 95), const_100) | subtract(const_100,n0)|divide(#0,n0)|multiply(#1,const_100)| | "selling price = rs 100 : then cost price = rs 95 : profit = rs 5 . profit = { ( 5 / 95 ) * 100 } % = 5.26 % answer is a ." | gain |
math_qa__pIto7CRfKG7EbMbZ | One fourth of a solution that was 10% sugar by weight was replaced by a second solution resulting in a solution that was 20 percent sugar by weight. The second solution was what percent sugar by weight?
Choose one.
A) 65 % B) 50 % C) 22 % D) 18 % E) 8.5 % | <gadget id="calculator">20 / 100</gadget>
<output>1/5 = around 0.2</output>
<gadget id="calculator">100 * (1/5)</gadget>
<output>20</output>
<gadget id="calculator">1 / 4</gadget>
<output>1/4 = around 0.25</output>
<gadget id="calculator">(1/4) * 100</gadget>
<output>25</output>
<gadget id="calculator">100 - 25</gadget>
<output>75</output>
<gadget id="calculator">10 / 100</gadget>
<output>1/10 = around 0.1</output>
<gadget id="calculator">75 * (1/10)</gadget>
<output>15/2 = around 7.5</output>
<gadget id="calculator">20 - (15/2)</gadget>
<output>25/2 = around 12.5</output>
<gadget id="calculator">(25/2) / 25</gadget>
<output>1/2 = around 0.5</output>
<gadget id="calculator">(1/2) * 100</gadget>
<output>50</output>
<result>B</result> | B | 50 | One fourth of a solution that was 10% sugar by weight was replaced by a second solution resulting in a solution that was 20 percent sugar by weight. The second solution was what percent sugar by weight? | {
"A": "65 %",
"B": "50 %",
"C": "22 %",
"D": "18 %",
"E": "8.5 %"
} | multiply(divide(subtract(multiply(const_100, divide(20, const_100)), multiply(subtract(const_100, multiply(divide(const_1, const_4), const_100)), divide(10, const_100))), multiply(divide(const_1, const_4), const_100)), const_100) | divide(n1,const_100)|divide(n0,const_100)|divide(const_1,const_4)|multiply(#0,const_100)|multiply(#2,const_100)|subtract(const_100,#4)|multiply(#1,#5)|subtract(#3,#6)|divide(#7,#4)|multiply(#8,const_100)| | "say the second solution ( which was 1 / 4 th of total ) was x % sugar , then 3 / 4 * 0.1 + 1 / 4 * x = 1 * 0.20 - - > x = 0.5 . alternately you can consider total solution to be 100 liters and in this case you ' ll have : 75 * 0.1 + 25 * x = 100 * 0.20 - - > x = 0.5 . answer : b ." | gain |
math_qa__GlkmR9sLfJwLQbHT | In a division sum, the quotient is 120, the divisor 456 and the remainder 333, find the dividend? Choose the correct choice from the following answers: A) 55287 B) 29887 C) 27768 D) 55053 E) 17191 | <gadget id="calculator">120 * 456</gadget>
<output>54_720</output>
<gadget id="calculator">54_720 + 333</gadget>
<output>55_053</output>
<result>D</result> | D | 55,053 | In a division sum, the quotient is 120, the divisor 456 and the remainder 333, find the dividend? | {
"A": "55287",
"B": "29887",
"C": "27768",
"D": "55053",
"E": "17191"
} | add(multiply(120, 456), 333) | multiply(n0,n1)|add(n2,#0)| | "explanation : 120 * 456 + 333 = 55053 answer : d" | general |
math_qa__VYBE55xP6b1Qxl0O | What is the remainder when (71)(73) is divided by 9?
Choose the correct choice from the following choices
A) 1 B) 2 C) 4 D) 6 E) 8 | <gadget id="calculator">73 * 71</gadget>
<output>5_183</output>
<gadget id="calculator">5_183 % 9</gadget>
<output>8</output>
<result>E</result> | E | 8 | What is the remainder when (71)(73) is divided by 9? | {
"A": "1",
"B": "2",
"C": "4",
"D": "6",
"E": "8"
} | reminder(multiply(73, 71), 9) | multiply(n0,n1)|reminder(#0,n2)| | "( 71 ) ( 73 ) = ( 72 - 1 ) ( 72 + 1 ) = 72 ^ 2 - 1 which is 1 less than a multiple of 9 . then the remainder will be 8 . the answer is e ." | general |
math_qa__1NFmL3r7VuNtnuci | What is the probability that a number selected from number 1 to 30 is prime number,when each of the given numbers is equally likely to be selected? Choose the correct option:
A) 10 / 30 B) 20 / 30 C) 1 D) 5 / 30 E) 15 / 30 | <gadget id="calculator">5 * 2</gadget>
<output>10</output>
<gadget id="calculator">10 / 30</gadget>
<output>1/3 = around 0.333333</output>
<result>A</result> | A | 0.333333 | What is the probability that a number selected from number 1 to 30 is prime number,when each of the given numbers is equally likely to be selected? | {
"A": "10 / 30",
"B": "20 / 30",
"C": "1",
"D": "5 / 30",
"E": "15 / 30"
} | divide(multiply(const_5, const_2), 30) | multiply(const_2,const_5)|divide(#0,n1) | x = { 2,3 , 5,7 , 11,13 , 17,19 , 23,29 } n ( x ) = 10 n ( s ) = 30 hence required probability = n ( x ) / n ( s ) = 10 / 30 option a is answer | probability |
math_qa__SuzEq9ZacMWA17CB | A grocer purchased a quantity of bananas at 3 pounds for $0.50 and sold the entire quantity at 4 pounds for $1.00. How many pounds did the grocer purchase if the profit from selling the bananas was $8.00? Choose the correct choice from the following options:
A) 40 B) 60 C) 96 D) 120 E) 240 | <gadget id="calculator">1 / 4</gadget>
<output>1/4 = around 0.25</output>
<gadget id="calculator">0.5 / 3</gadget>
<output>0.166667</output>
<gadget id="calculator">(1/4) - 0.166667</gadget>
<output>0.083333</output>
<gadget id="calculator">8 / 0.083333</gadget>
<output>96.000384</output>
<result>C</result> | C | 96 | A grocer purchased a quantity of bananas at 3 pounds for $0.50 and sold the entire quantity at 4 pounds for $1.00. How many pounds did the grocer purchase if the profit from selling the bananas was $8.00? | {
"A": "40",
"B": "60",
"C": "96",
"D": "120",
"E": "240"
} | divide(8.00, subtract(divide(1.00, 4), divide(0.50, 3))) | divide(n3,n2)|divide(n1,n0)|subtract(#0,#1)|divide(n4,#2)| | "cost price of 1 pound of bananas = 0.5 / 3 = 1 / 6 selling price of 1 pound of bananas = 1 / 4 profit per pound = ( 1 / 4 - 1 / 6 ) = ( 1 / 12 ) total profit is given as 8 ( 1 / 12 ) * x = 8 x = 96 answer : c" | gain |
math_qa__hjaQruAbptwGsncG | The volume of a certain substance is always directly proportional to its weight. If 48 cubic inches of the substance weigh 112 ounces, what is the volume, in cubic inches, of 53 ounces of this substance? Options
A) 27 B) 36 C) 42 D) 22 E) 147 | <gadget id="calculator">48 / 112</gadget>
<output>3/7 = around 0.428571</output>
<gadget id="calculator">(3/7) * 53</gadget>
<output>159/7 = around 22.714286</output>
<result>D</result> | D | 22 | The volume of a certain substance is always directly proportional to its weight. If 48 cubic inches of the substance weigh 112 ounces, what is the volume, in cubic inches, of 53 ounces of this substance? | {
"A": "27",
"B": "36",
"C": "42",
"D": "22",
"E": "147"
} | multiply(divide(48, 112), 53) | divide(n0,n1)|multiply(n2,#0)| | "112 ounces of a substance has a volume of 48 cubic inches 53 ounces of a substance has a volume of ( 48 / 112 ) * 53 = 22 cubic inches answer d" | geometry |
math_qa__ZpEMVyZt3V62qS1s | Two trains running in opposite directions cross a man standing on the platform in 27 seconds and 17 seconds respectively . If they cross each other in 22 seconds, what is the ratio of their speeds? Choose the correct choice from the following answers.
A) 1 : 1 B) 3 : 1 C) 2 : 3 D) 3 : 2 E) 3 : 4 | <gadget id="calculator">27 - 22</gadget>
<output>5</output>
<gadget id="calculator">22 - 17</gadget>
<output>5</output>
<gadget id="calculator">5 / 5</gadget>
<output>1</output>
<result>A</result> | A | 1 | Two trains running in opposite directions cross a man standing on the platform in 27 seconds and 17 seconds respectively . If they cross each other in 22 seconds, what is the ratio of their speeds? | {
"A": "1 : 1",
"B": "3 : 1",
"C": "2 : 3",
"D": "3 : 2",
"E": "3 : 4"
} | divide(subtract(27, 22), subtract(22, 17)) | subtract(n0,n2)|subtract(n2,n1)|divide(#0,#1) | let the speed of the trains be x and y respectively length of train 1 = 27 x length of train 2 = 17 y relative speed = x + y time taken to cross each other = 22 s = ( 27 x + 17 y ) / ( x + y ) = 22 = ( 27 x + 17 y ) / = 22 ( x + y ) = 5 x = 5 y = x / y = 5 / 5 = 1 / 1 i . e 1 : 1 answer : a | physics |
math_qa__IFWrC8KuXGt5o9zY | Roses can be purchased individually for $5.30, one dozen for $36, or two dozen for $50. What is the greatest number of roses that can be purchased for $680?
Choose one: A) 156 B) 162 C) 317 D) 324 E) 325 | <gadget id="calculator">680 / 50</gadget>
<output>68/5 = around 13.6</output>
<gadget id="calculator">floor(68/5)</gadget>
<output>13</output>
<gadget id="calculator">12 * 2</gadget>
<output>24</output>
<gadget id="calculator">13 * 24</gadget>
<output>312</output>
<gadget id="calculator">13 * 50</gadget>
<output>650</output>
<gadget id="calculator">680 - 650</gadget>
<output>30</output>
<gadget id="calculator">30 / 5.3</gadget>
<output>5.660377</output>
<gadget id="calculator">floor(5.660377)</gadget>
<output>5</output>
<gadget id="calculator">312 + 5</gadget>
<output>317</output>
<result>C</result> | C | 317 | Roses can be purchased individually for $5.30, one dozen for $36, or two dozen for $50. What is the greatest number of roses that can be purchased for $680? | {
"A": "156",
"B": "162",
"C": "317",
"D": "324",
"E": "325"
} | add(multiply(floor(divide(680, 50)), multiply(const_12, const_2)), floor(divide(subtract(680, multiply(floor(divide(680, 50)), 50)), 5.30))) | divide(n3,n2)|multiply(const_12,const_2)|floor(#0)|multiply(n2,#2)|multiply(#2,#1)|subtract(n3,#3)|divide(#5,n0)|floor(#6)|add(#7,#4)| | "buy as many $ 50 deals as possible . we can by 650 / 50 = 13 two dozen roses , thus total of 13 * 24 = 312 roses . we are left with 680 - 650 = $ 30 . we can buy 30 / 5.3 = ~ 5 roses for that amount . total = 312 + 5 = 317 . answer : c ." | general |
math_qa__uj9AFgX2lnE0tcBz | the salaries of a and b together is rs . 14000 . a spend 80 % of his salary and b spends 85 % of his salary . what is the salary of b if their savings are equal ? Choose the correct choice: A) rs . 6000 B) rs . 8000 C) rs . 7500 D) rs . 6500 E) rs . 8500 | <gadget id="calculator">80 / 100</gadget>
<output>4/5 = around 0.8</output>
<gadget id="calculator">14_000 * (4/5)</gadget>
<output>11_200</output>
<gadget id="calculator">14_000 - 11_200</gadget>
<output>2_800</output>
<gadget id="calculator">1 + 1</gadget>
<output>2</output>
<gadget id="calculator">2 - (4/5)</gadget>
<output>6/5 = around 1.2</output>
<gadget id="calculator">85 / 100</gadget>
<output>17/20 = around 0.85</output>
<gadget id="calculator">(6/5) - (17/20)</gadget>
<output>7/20 = around 0.35</output>
<gadget id="calculator">2_800 / (7/20)</gadget>
<output>8_000</output>
<result>B</result> | B | 8,000 | the salaries of a and b together is rs . 14000 . a spend 80 % of his salary and b spends 85 % of his salary . what is the salary of b if their savings are equal ? | {
"A": "rs . 6000",
"B": "rs . 8000",
"C": "rs . 7500",
"D": "rs . 6500",
"E": "rs . 8500"
} | divide(subtract(14000, multiply(14000, divide(80, const_100))), subtract(subtract(add(const_1, const_1), divide(80, const_100)), divide(85, const_100))) | add(const_1,const_1)|divide(n1,const_100)|divide(n2,const_100)|multiply(n0,#1)|subtract(#0,#1)|subtract(n0,#3)|subtract(#4,#2)|divide(#5,#6) | let the salaries of a and b are x and y respectively x + y = 14000 savings of a = 20 x / 100 = savings of b = 15 y / 100 x = ¾ y 3 / 4 y + y = 14000 , 7 y / 4 = 14000 , y = 8000 answer : b | gain |
math_qa__3fhx91cGurdFg2OZ | Two equally sized jugs full of water are each emptied into two separate unequally sized empty jugs, X and Y. Now, jug X is 1/6 full, while jug Y is 2/3 full. If water is poured from jug X into jug Y until jug Y is filled, what fraction of jug X then contains water? Choose the correct choice from the following answers
A) 0 B) 1 / 12 C) 2 / 15 D) 1 / 10 E) 2 / 10 | <gadget id="calculator">1 / 6</gadget>
<output>1/6 = around 0.166667</output>
<gadget id="calculator">2 / 3</gadget>
<output>2/3 = around 0.666667</output>
<gadget id="calculator">1 - (2/3)</gadget>
<output>1/3 = around 0.333333</output>
<gadget id="calculator">(1/3) / (2/3)</gadget>
<output>1/2 = around 0.5</output>
<gadget id="calculator">(1/6) * (1/2)</gadget>
<output>1/12 = around 0.083333</output>
<result>B</result> | B | 0.083333 | Two equally sized jugs full of water are each emptied into two separate unequally sized empty jugs, X and Y. Now, jug X is 1/6 full, while jug Y is 2/3 full. If water is poured from jug X into jug Y until jug Y is filled, what fraction of jug X then contains water? | {
"A": "0",
"B": "1 / 12",
"C": "2 / 15",
"D": "1 / 10",
"E": "2 / 10"
} | multiply(divide(1, 6), divide(subtract(1, divide(2, 3)), divide(2, 3))) | divide(n0,n1)|divide(n2,n3)|subtract(n0,#1)|divide(#2,#1)|multiply(#0,#3)| | "suppose the water in each jug is l liters cx x ( 1 / 6 ) = l cx = 6 l liters cx is capacity of x cy x ( 2 / 3 ) = l cy = 3 l / 2 liters cy is capacity of y now , y is 3 l / 2 - l empty = l / 2 empty so , we can put only l / 2 water in jug y from jug x jug x ' s remaining water = l - l / 2 = l / 2 fraction of x which contains water = water / cx = ( l / 2 ) / 6 l = 1 / 12 answer will be b" | general |
math_qa__Z2b5RqRwGbpDGQaY | A man buys 52 pens at marked price of 46 pens from a whole seller. If he sells these pens giving a discount of 1% , what is the profit percent?
Choices:
A) 7.6 % B) 7.7 % C) 11.32 % D) 11.91 % E) 7.8 % | <gadget id="calculator">100 - 1</gadget>
<output>99</output>
<gadget id="calculator">52 * 99</gadget>
<output>5_148</output>
<gadget id="calculator">46 * 100</gadget>
<output>4_600</output>
<gadget id="calculator">5_148 - 4_600</gadget>
<output>548</output>
<gadget id="calculator">548 / 4_600</gadget>
<output>137/1_150 = around 0.11913</output>
<gadget id="calculator">100 * (137/1_150)</gadget>
<output>274/23 = around 11.913043</output>
<result>D</result> | D | 11.91 | A man buys 52 pens at marked price of 46 pens from a whole seller. If he sells these pens giving a discount of 1% , what is the profit percent? | {
"A": "7.6 %",
"B": "7.7 %",
"C": "11.32 %",
"D": "11.91 %",
"E": "7.8 %"
} | multiply(const_100, divide(subtract(multiply(52, subtract(const_100, 1)), multiply(46, const_100)), multiply(46, const_100))) | multiply(n1,const_100)|subtract(const_100,n2)|multiply(n0,#1)|subtract(#2,#0)|divide(#3,#0)|multiply(#4,const_100)| | "explanation : let marked price be re . 1 each c . p . of 52 pens = rs . 46 s . p . of 52 pens = 99 % of rs . 52 = rs . 51.48 profit % = ( profit / c . p . ) x 100 profit % = ( 5.48 / 46 ) x 100 = 11.91 % answer : d" | gain |
math_qa__0iNTOVtMYyb8lAbi | Express 50 mps in kmph? Choose the correct choice from the following answers:
A) 172 B) 160 C) 150 D) 180 E) 120 | <gadget id="calculator">50 / 1_000</gadget>
<output>1/20 = around 0.05</output>
<gadget id="calculator">(1/20) * 3_600</gadget>
<output>180</output>
<result>D</result> | D | 180 | Express 50 mps in kmph? | {
"A": "172",
"B": "160",
"C": "150",
"D": "180",
"E": "120"
} | multiply(divide(50, const_1000), const_3600) | divide(n0,const_1000)|multiply(#0,const_3600)| | "25 * 18 / 5 = 180 kmph answer : d" | physics |
math_qa__YO9VS6tNTCuWrSR3 | The total price of a kilogram each of Shimla apples and Red Delicious apples is 250 rupees more than the total price of a kilogram each of Red Delicious apples and Fuji apples. Fuji apples is how much cheaper than Shimla apples? Options
A) 250 B) 125 C) 500 D) 100 E) 80 | <gadget id="calculator">250 * 1</gadget>
<output>250</output>
<result>A</result> | A | 250 | The total price of a kilogram each of Shimla apples and Red Delicious apples is 250 rupees more than the total price of a kilogram each of Red Delicious apples and Fuji apples. Fuji apples is how much cheaper than Shimla apples? | {
"A": "250",
"B": "125",
"C": "500",
"D": "100",
"E": "80"
} | multiply(250, const_1) | multiply(n0,const_1) | ( shimla + red delicious ) - ( red delicious + fuji ) = 250 shimla - fuji = 250 answer : a | general |
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