role stringclasses 2
values | content stringlengths 0 2.1k | session_id int64 10 21.7k | sequence_id int64 0 2.38k | annotations listlengths 0 8 |
|---|---|---|---|---|
volunteer | great! | 12,860 | 17 | [] |
volunteer | now how much do you know about the unit circle? | 12,860 | 18 | [] |
student | not much, im pretty bad at it | 12,860 | 19 | [] |
volunteer | thats fine | 12,860 | 20 | [] |
volunteer | so ill just draw it rq | 12,860 | 21 | [] |
volunteer | a trick that we can use is that we only need to memorize the first quadrant | 12,860 | 22 | [] |
volunteer | and then flip the sin and cos values based on the theta values that are given | 12,860 | 23 | [] |
volunteer | so do you know the values in the first quadrant? | 12,860 | 24 | [] |
volunteer | not quite | 12,860 | 25 | [] |
volunteer | so ill write them out for you | 12,860 | 26 | [] |
volunteer | so when getting sin and cos | 12,860 | 27 | [] |
volunteer | think sin as y value | 12,860 | 28 | [] |
volunteer | and cos as x value | 12,860 | 29 | [] |
volunteer | those are the values of theta | 12,860 | 30 | [] |
volunteer | so if you put cos(ppi/6) | 12,860 | 31 | [] |
volunteer | you would get sqrt(3)/2 | 12,860 | 32 | [] |
volunteer | and if you put sin(pi/6) you would get .5 | 12,860 | 33 | [] |
student | sorry i just couldnt tell what values were under pi | 12,860 | 34 | [] |
volunteer | so another thing you can use is that cos and sin will either be sqrt(3)/2 or 1/2 as long as the denominator is not 4 | 12,860 | 35 | [] |
volunteer | oh ok | 12,860 | 36 | [] |
student | thank you sorry | 12,860 | 37 | [] |
volunteer | no worries, if something isnt clear feel free to tell me | 12,860 | 38 | [] |
volunteer | if the denominator is 4 for the theta value, then the value of sin and cos will either be -sqty(2)/2 or sqrt(2)/2 | 12,860 | 39 | [] |
volunteer | an example would be theta = 5pi/4 | 12,860 | 40 | [] |
volunteer | or this line | 12,860 | 41 | [] |
volunteer | what we can do to think about the sin and cos values would be flipping the line theta = pi/4 over the y axis | 12,860 | 42 | [] |
volunteer | then flip it again over the x axis | 12,860 | 43 | [] |
volunteer | if you flip over the x axis, you multiply the y value by -1 | 12,860 | 44 | [] |
volunteer | and if you flip over the y axis, you multiply the x value by -1 | 12,860 | 45 | [] |
volunteer | does that kind of make sense | 12,860 | 46 | [] |
student | yes | 12,860 | 47 | [] |
volunteer | great! | 12,860 | 48 | [] |
volunteer | now once we get our sin and/or cos value, we can plug them into the other trig functons | 12,860 | 49 | [] |
volunteer | so how about you try question 50? | 12,860 | 50 | [] |
student | ok | 12,860 | 51 | [] |
volunteer | how are you doing so far with this question? | 12,860 | 52 | [] |
volunteer | oh sorry i didnt see you work down there | 12,860 | 53 | [] |
volunteer | alright, so not quite | 12,860 | 54 | [] |
volunteer | do you remember what happens if we raise something to the power of 0? | 12,860 | 55 | [] |
student | it turns into 0 | 12,860 | 56 | [] |
student | o wait 1 | 12,860 | 57 | [] |
volunteer | yeaa | 12,860 | 58 | [] |
volunteer | also, is tanx = (cosx/sinx)? | 12,860 | 59 | [] |
student | no.... :( sin(x)/cos(x) | 12,860 | 60 | [] |
volunteer | yeaa | 12,860 | 61 | [] |
volunteer | lets go back to the unit circle rq | 12,860 | 62 | [] |
volunteer | can you use a colored line to show where theta= 0 is | 12,860 | 63 | [] |
volunteer | nicee | 12,860 | 64 | [] |
volunteer | so what would the cos value be? | 12,860 | 65 | [] |
volunteer | yup | 12,860 | 66 | [] |
volunteer | now if cos 0 is 1, what is sin0 | 12,860 | 67 | [] |
volunteer | yup | 12,860 | 68 | [] |
volunteer | so using that, what would sec0 be and what would tan0 be | 12,860 | 69 | [] |
volunteer | tan0 is correct | 12,860 | 70 | [] |
volunteer | but lets check sec again | 12,860 | 71 | [] |
volunteer | what is secx? | 12,860 | 72 | [] |
volunteer | now what would we get if we put in 0 for secx | 12,860 | 73 | [] |
volunteer | yeaa | 12,860 | 74 | [] |
volunteer | so what is our final answeR> | 12,860 | 75 | [] |
volunteer | answer?* | 12,860 | 76 | [] |
student | 4? | 12,860 | 77 | [] |
volunteer | nice! | 12,860 | 78 | [] |
volunteer | do you want to try 49? | 12,860 | 79 | [] |
student | yes please | 12,860 | 80 | [] |
student | i will take a second | 12,860 | 81 | [] |
volunteer | looks right to me | 12,860 | 82 | [] |
volunteer | is it fine if I erase the board? | 12,860 | 83 | [] |
student | Yes | 12,860 | 84 | [] |
volunteer | great | 12,860 | 85 | [] |
volunteer | now lets move onto 52 | 12,860 | 86 | [] |
volunteer | let me work it out myself then ill get back to you | 12,860 | 87 | [] |
student | ok | 12,860 | 88 | [] |
volunteer | sorry for the wait | 12,860 | 89 | [] |
student | that totally ok | 12,860 | 90 | [] |
volunteer | did you try while i was solving it? | 12,860 | 91 | [] |
student | *is | 12,860 | 92 | [] |
student | kinda | 12,860 | 93 | [] |
volunteer | alright | 12,860 | 94 | [] |
volunteer | so I did this in a more complex way than needed, but I think I know the easier way | 12,860 | 95 | [] |
volunteer | so what was your first step? | 12,860 | 96 | [] |
student | my teacher said it was wrong | 12,860 | 97 | [] |
volunteer | said what was wrong? | 12,860 | 98 | [] |
student | and after that i had no idea what to do | 12,860 | 99 | [] |
student | my answer to this question | 12,860 | 100 | [] |
volunteer | ah | 12,860 | 101 | [] |
student | its an old test im looking over | 12,860 | 102 | [] |
volunteer | well it would help to see exactly where you got it wrong so that we can fix that error | 12,860 | 103 | [] |
student | here I can upload it onto my screen really quick | 12,860 | 104 | [] |
volunteer | alright | 12,860 | 105 | [] |
student | its on there, but I can't rotate it | 12,860 | 106 | [] |
volunteer | i see the question, but II dont see your work | 12,860 | 107 | [] |
volunteer | ah i see | 12,860 | 108 | [] |
volunteer | you put in 2 instead of a | 12,860 | 109 | [] |
volunteer | since the limit was where x goes to a | 12,860 | 110 | [] |
volunteer | also with substitution, you got 0/0 which is an indeterminate form | 12,860 | 111 | [] |
student | the pencil is me and the blue -2 and slash mark are from my teachers | 12,860 | 112 | [] |
student | *teacher | 12,860 | 113 | [] |
volunteer | good to know | 12,860 | 114 | [] |
volunteer | I do see that you subbed in 2 for x though | 12,860 | 115 | [] |
student | ? | 12,860 | 116 | [] |
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