role stringclasses 2
values | content stringlengths 0 2.1k | session_id int64 10 21.7k | sequence_id int64 0 2.38k | annotations listlengths 0 8 |
|---|---|---|---|---|
volunteer | Do you see the link? | 13,553 | 595 | [] |
student | Uh, well. | 13,553 | 596 | [] |
student | Yeah | 13,553 | 597 | [] |
volunteer | Uh, I can put it here too on the chat. Do you see it now? | 13,553 | 598 | [] |
volunteer | I put it on the board too | 13,553 | 599 | [] |
student | Oh yeah | 13,553 | 600 | [] |
student | Wait, can I like | 13,553 | 601 | [] |
student | OK, yeah, I can | 13,553 | 602 | [] |
volunteer | You can copy on the board, yeah. | 13,553 | 603 | [] |
student | Can I open the thing up | 13,553 | 604 | [] |
student | Yeah. | 13,553 | 605 | [] |
volunteer | Uh, you learn to copy paste it | 13,553 | 606 | [] |
student | Yeah | 13,553 | 607 | [] |
student | No, like I already like copy and pasted it. | 13,553 | 608 | [] |
volunteer | Oh, OK, yeah, you can open it up. So it, it gives an explanation of how to solve it also. | 13,553 | 609 | [] |
student | OK. | 13,553 | 610 | [] |
student | Yeah, but why aren't they making us do the quadratic. | 13,553 | 611 | [] |
student | Like it seems weird, no? Or | 13,553 | 612 | [] |
volunteer | What do you mean? Why they're doing the | 13,553 | 613 | [] |
student | like why don't, why don't they just let us do the quadratic formula, so just to get uh both versions of X | 13,553 | 614 | [] |
volunteer | I didn't get the question, sorry | 13,553 | 615 | [] |
student | Wait, like, cause in this, they're making us do like all of that stuff. | 13,553 | 616 | [] |
student | But like we can also use the quadratic formula to get X on | 13,553 | 617 | [] |
volunteer | So you're saying that can we use the other method like the formula that you already have. | 13,553 | 618 | [] |
student | Yeah | 13,553 | 619 | [] |
volunteer | Yeah, yeah, you can use that too. Uh, that's the other way. So if you see. | 13,553 | 620 | [] |
volunteer | I think the equation is | 13,553 | 621 | [] |
student | Like I was just like saying that because like it seemed like it could be simpler to do that. | 13,553 | 622 | [] |
student | Like the math might not be as simple, but like I just feel like the process is like | 13,553 | 623 | [] |
student | it's less | 13,553 | 624 | [] |
student | like complicated I guess | 13,553 | 625 | [] |
volunteer | x = [-b ± √(b^2 - 4ac)]/2a | 13,553 | 626 | [] |
volunteer | Yeah, yeah, I mean, you can use, if you want to use the roots, that's fine because, but you need to figure out then the like you're talking about this one, right? I just typed it on the screen. | 13,553 | 627 | [] |
volunteer | Do you see it? | 13,553 | 628 | [] |
student | Mhm. Yeah | 13,553 | 629 | [] |
volunteer | Is that the one you're referring to | 13,553 | 630 | [] |
student | Uh, see, yeah. | 13,553 | 631 | [] |
student | Well | 13,553 | 632 | [] |
volunteer | Oxycod minus B, that one. | 13,553 | 633 | [] |
student | yeah | 13,553 | 634 | [] |
volunteer | Yeah, yeah, yeah, you can use that too. I mean, uh, if that's easier for you, that's a quick way of solving as well. | 13,553 | 635 | [] |
volunteer | But I, I think they're trying to show you alternate methods of the same thing because if you just put a formula, you don't know what you're really doing, right? But if you, if you do it this way, that you know you know that your factorizing. | 13,553 | 636 | [] |
volunteer | the quarter day equation | 13,553 | 637 | [] |
student | Oh, no, no, I don't, I don't forget it either way. | 13,553 | 638 | [] |
student | I'm just like trying to figure out | 13,553 | 639 | [] |
student | how to like remember how to do this, but like, once I do it more, I, I think I will try to, or like I will start understanding it though. | 13,553 | 640 | [] |
student | It's like I've only done it once. | 13,553 | 641 | [] |
student | like | 13,553 | 642 | [] |
volunteer | Yeah, yeah, I mean, once you start doing factorization, I think you will continue doing this and you will not go back to that uh formula. | 13,553 | 643 | [] |
student | becomes more fun. | 13,553 | 644 | [] |
student | OK | 13,553 | 645 | [] |
volunteer | because this becomes more fun, I think, at least in my mind, but yeah, give it a shot and see if it works for you, because putting the formula is more mechanical, you know, you're not applying your brand. | 13,553 | 646 | [] |
student | Yeah | 13,553 | 647 | [] |
volunteer | But if you like that, that's the way to go to. | 13,553 | 648 | [] |
student | OK, so | 13,553 | 649 | [] |
student | yeah | 13,553 | 650 | [] |
volunteer | Because sometimes when you go to trigonometry, you will start applying this formulas. You won't be applying, uh, you know, methodology. | 13,553 | 651 | [] |
volunteer | So yeah. | 13,553 | 652 | [] |
student | So you get the similar factors of a times c which | 13,553 | 653 | [] |
student | uh in that, in the first problem would be 20, and then | 13,553 | 654 | [] |
student | hm | 13,553 | 655 | [] |
student | 20 | 13,553 | 656 | [] |
volunteer | Yeah, in the second one, if you wanna talk through it, that's fine too. I can, I think I have some time now, um. | 13,553 | 657 | [] |
student | wait | 13,553 | 658 | [] |
student | cause you do like uh 3 | 13,553 | 659 | [] |
student | X and then X or entheses X + 6 + 2 | 13,553 | 660 | [] |
volunteer | Mhm. | 13,553 | 661 | [] |
student | times X plus or minus + -6 and then you convert that into | 13,553 | 662 | [] |
student | X + 6 times 3 X plus 2. | 13,553 | 663 | [] |
student | But uh where does the the 18 come in? Like | 13,553 | 664 | [] |
volunteer | 18 and 2 in the addition that makes it 20. | 13,553 | 665 | [] |
student | yeah, oh, OK, OK. But | 13,553 | 666 | [] |
student | why is it actually matter that we do that then because couldn't we just | 13,553 | 667 | [] |
volunteer | Otherwise, you won't be | 13,553 | 668 | [] |
student | oh wait wait, cause you're | 13,553 | 669 | [] |
student | we | 13,553 | 670 | [] |
student | Yeah | 13,553 | 671 | [] |
student | Yeah, yeah, OK, cause you're converting the 3 X | 13,553 | 672 | [] |
student | 2 plus 18x, and then you're converting that into | 13,553 | 673 | [] |
volunteer | yeah | 13,553 | 674 | [] |
student | yeah, OK, OK, I see what you're doing, you know, cause the plus is still in the parentheses. So you're basically just simplifying X. You're basically just doing um | 13,553 | 675 | [] |
volunteer | I'm factor that factor. | 13,553 | 676 | [] |
volunteer | Yeah | 13,553 | 677 | [] |
volunteer | Right. | 13,553 | 678 | [] |
student | 3, yeah, yeah, you're doing, yeah, you're factorizing it. You're just doing 3 X X plus 6, which is the same thing as 3 X plus H X. OK. | 13,553 | 679 | [] |
volunteer | right | 13,553 | 680 | [] |
student | clear | 13,553 | 681 | [] |
volunteer | So the same way you should think about this A.CS 40, I think you started writing that. So A.C is -10 and 4 is 40. | 13,553 | 682 | [] |
volunteer | And, and | 13,553 | 683 | [] |
student | I'm gonna dig a screenshot of the, of the beautiful work. | 13,553 | 684 | [] |
student | OK | 13,553 | 685 | [] |
student | Hm | 13,553 | 686 | [] |
student | OK. And that's X | 13,553 | 687 | [] |
student | And then | 13,553 | 688 | [] |
volunteer | Mhm | 13,553 | 689 | [] |
student | one last thing before we go. So for question 2, I just want to do that really quickly. Like, so 8, some of the factors for it | 13,553 | 690 | [] |
student | A times C. | 13,553 | 691 | [] |
student | So you would do AC that would be -40, and then the factors | 13,553 | 692 | [] |
volunteer | Mm | 13,553 | 693 | [] |
student | that would be equal to actually question now, would they be equal to 3 or -3, 3, right? | 13,553 | 694 | [] |
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