role stringclasses 2
values | content stringlengths 0 2.1k | session_id int64 10 21.7k | sequence_id int64 0 2.38k | annotations listlengths 0 8 |
|---|---|---|---|---|
volunteer | we have here | 15,082 | 424 | [] |
student | if we do, 1 = a [(x+1) (x+2)] + b, will we get same thing? | 15,082 | 425 | [] |
volunteer | right there | 15,082 | 426 | [] |
volunteer | I think we will | 15,082 | 427 | [] |
volunteer | Um, actually, I think you would need more | 15,082 | 428 | [] |
volunteer | I mean, I think we will get the same thing just because, you know, we're still talking about, for example, an apple | 15,082 | 429 | [] |
volunteer | right, we're still talking about the same thing. We're just kind of trying to rewrite it differently. | 15,082 | 430 | [] |
volunteer | but I think we'd still end up with the same result. | 15,082 | 431 | [] |
volunteer | Like if you were to | 15,082 | 432 | [] |
volunteer | divide it all out, you'd still get the same thing. | 15,082 | 433 | [] |
volunteer | Um | 15,082 | 434 | [] |
volunteer | one equals A, let me go back. | 15,082 | 435 | [] |
volunteer | I'm jumping too much | 15,082 | 436 | [] |
volunteer | Too many hoops. There we go. | 15,082 | 437 | [] |
volunteer | So you said | 15,082 | 438 | [] |
volunteer | 1 equals | 15,082 | 439 | [] |
volunteer | A X + 1, X + 2 + B. So you're saying, what if we didn't separate the denominator? | 15,082 | 440 | [] |
volunteer | Actually, let's do it your way. Do it on the board. | 15,082 | 441 | [] |
volunteer | Let's see if you can prove that they're the same. | 15,082 | 442 | [] |
volunteer | When in doubt, do it out | 15,082 | 443 | [] |
student | okay | 15,082 | 444 | [] |
volunteer | You have the board | 15,082 | 445 | [] |
volunteer | You can't see me, but I'm flourishing my hand as a showman. | 15,082 | 446 | [] |
volunteer | Did you get 2 x + 3? | 15,082 | 447 | [] |
volunteer | Where did you get it | 15,082 | 448 | [] |
volunteer | Uh, yes, yes, yes, yes, yes, yes, I see it. | 15,082 | 449 | [] |
volunteer | Continue, please | 15,082 | 450 | [] |
volunteer | Wait, wait, wait. Wouldn't it be the other way around? Wouldn't it be 3X? | 15,082 | 451 | [] |
volunteer | Ah no, you're right. I'm sorry, I'm sorry. I'm way off. | 15,082 | 452 | [] |
volunteer | No, you can be 01 | 15,082 | 453 | [] |
volunteer | not 0 | 15,082 | 454 | [] |
student | it became problem | 15,082 | 455 | [] |
volunteer | Right | 15,082 | 456 | [] |
volunteer | So now you see why they did it the way they did. | 15,082 | 457 | [] |
volunteer | because really the only way to do it | 15,082 | 458 | [] |
student | right | 15,082 | 459 | [] |
volunteer | Or, I mean, you would, you would need | 15,082 | 460 | [] |
volunteer | more variables if you're doing it your way. | 15,082 | 461 | [] |
volunteer | But you have too many equations. | 15,082 | 462 | [] |
volunteer | I'm sorry, too little equations | 15,082 | 463 | [] |
volunteer | but it is what it is. So, it's good exercise. | 15,082 | 464 | [] |
student | b needs a equation | 15,082 | 465 | [] |
student | yeah, understood | 15,082 | 466 | [] |
volunteer | I mean, technically, you have what, 12, | 15,082 | 467 | [] |
volunteer | you have 3 equations, technically. | 15,082 | 468 | [] |
volunteer | cause you have a | 15,082 | 469 | [] |
volunteer | you have the X square term, you have the X term, and then you have the X to the 0 term. So you have 3 equations technically. So you could, you could have up to 3. | 15,082 | 470 | [] |
volunteer | um, variables. | 15,082 | 471 | [] |
volunteer | All right, that was fun | 15,082 | 472 | [] |
volunteer | Now we can do | 15,082 | 473 | [] |
volunteer | um | 15,082 | 474 | [] |
volunteer | an improper fraction. | 15,082 | 475 | [] |
volunteer | So example 12 is | 15,082 | 476 | [] |
volunteer | an improper fraction | 15,082 | 477 | [] |
volunteer | Oh, I'm sorry, can you see the screen? | 15,082 | 478 | [] |
volunteer | Actually, are you ready to move on? Do you have any more questions? | 15,082 | 479 | [] |
volunteer | um, about why they're not using the previous chapter's methodology. Actually, let me go back. | 15,082 | 480 | [] |
volunteer | We we were talking about it so much. Why don't they have DX in there? | 15,082 | 481 | [] |
volunteer | Um | 15,082 | 482 | [] |
volunteer | um, so if you go back | 15,082 | 483 | [] |
volunteer | or if you're looking at the screen, you see in the integral | 15,082 | 484 | [] |
volunteer | integral DX over AX2 + BX + C, and you see that you have all these coefficients, right? | 15,082 | 485 | [] |
volunteer | But what's the first thing they do? | 15,082 | 486 | [] |
student | right | 15,082 | 487 | [] |
volunteer | is they factor out A | 15,082 | 488 | [] |
volunteer | and you know, why is this important? | 15,082 | 489 | [] |
volunteer | Well | 15,082 | 490 | [] |
volunteer | if they didn't factor out A | 15,082 | 491 | [] |
volunteer | and you have this um | 15,082 | 492 | [] |
volunteer | AX | 15,082 | 493 | [] |
volunteer | you try to rewrite, and you try to rewrite these expressions, you'd have, like, as you have here, um | 15,082 | 494 | [] |
volunteer | yeah, if you have A piece and you try to | 15,082 | 495 | [] |
volunteer | uh factor it | 15,082 | 496 | [] |
volunteer | you would still end up with this kind of A over B and, and sorry B over A and C over A, um. | 15,082 | 497 | [] |
volunteer | then when you do your substitution for tea. | 15,082 | 498 | [] |
volunteer | right? And you had this AX term here. | 15,082 | 499 | [] |
volunteer | then your | 15,082 | 500 | [] |
volunteer | you, then you'd end up with A times DX equals dT. So you don't have to worry about this 1/8 term again and again. | 15,082 | 501 | [] |
volunteer | which would, which would result in this | 15,082 | 502 | [] |
volunteer | but they just find it easier to have | 15,082 | 503 | [] |
volunteer | um DX equals DT straight up, but you already have this 1/8 term that they factored out. So it, it's, it'd be the same. | 15,082 | 504 | [] |
volunteer | They just um find it easier to do it. | 15,082 | 505 | [] |
volunteer | this way | 15,082 | 506 | [] |
volunteer | or they just prefer, I'm not sorry, not easy, they prefer to do it this way. | 15,082 | 507 | [] |
volunteer | So they're already accounting for this one over a term. | 15,082 | 508 | [] |
student | yeah, right | 15,082 | 509 | [] |
volunteer | Yeah, and the method they used here was completing the squares. | 15,082 | 510 | [] |
volunteer | not like um | 15,082 | 511 | [] |
volunteer | the chapter we're on, which they don't use completing the squares, they prefer | 15,082 | 512 | [] |
volunteer | having two separate terms, two separate expressions. | 15,082 | 513 | [] |
volunteer | right? X minus A, X minus B. | 15,082 | 514 | [] |
volunteer | So that's another difference | 15,082 | 515 | [] |
student | this also kinda easy too | 15,082 | 516 | [] |
volunteer | I mean | 15,082 | 517 | [] |
volunteer | don't speak too soon | 15,082 | 518 | [] |
volunteer | All right. You haven't, we haven't really done many problems. | 15,082 | 519 | [] |
volunteer | But the methodology, I guess, is simpler. You don't have to carry about the | 15,082 | 520 | [] |
volunteer | um substitution method | 15,082 | 521 | [] |
student | yeah, | 15,082 | 522 | [] |
volunteer | So that is, but that is a little easier, but you do have to do more, um, yeah, I guess you don't have to think as much. | 15,082 | 523 | [] |
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