Split (1)

train · 116k rows

role stringclasses 2 values	content stringlengths 0 2.1k	session_id int64 10 21.7k	sequence_id int64 0 2.38k	annotations listlengths 0 8
volunteer	kind of frustration to go back and read the theory.	15,082	924	[]
volunteer	to figure out the conditions, yeah.	15,082	925	[]
volunteer	All right	15,082	926	[]
student	right,	15,082	927	[]
student	i'll do it again	15,082	928	[]
volunteer	I believe in you	15,082	929	[]
student	done	15,082	930	[]
volunteer	All right, now that you get	15,082	931	[]
volunteer	the expression they got.	15,082	932	[]
volunteer	the solution they got	15,082	933	[]
student	i have cofficient switched for log	15,082	934	[]
volunteer	You mean you got	15,082	935	[]
volunteer	the 5, you got the 10 going with X minus 2.	15,082	936	[]
volunteer	and the 5 going with X minus 3.	15,082	937	[]
student	yeah	15,082	938	[]
volunteer	OK, well, that's not right.	15,082	939	[]
volunteer	I think you	15,082	940	[]
volunteer	may have just I think you just may have switched your coefficients.	15,082	941	[]
volunteer	cause that solution um is not the same.	15,082	942	[]
volunteer	Your methodology is probably right, but I think you just	15,082	943	[]
volunteer	probably switched your solutions	15,082	944	[]
volunteer	So did you get something of this form?	15,082	945	[]
volunteer	A over X minus 2 and B over x minus 3.	15,082	946	[]
student	oh understood, i did got same form. but when integrating, i did a/x-3	15,082	947	[]
volunteer	Right	15,082	948	[]
volunteer	So the, remember it has to be the opposite term	15,082	949	[]
volunteer	opposite expression	15,082	950	[]
volunteer	Your coefficient is multiplied by the opposite expression to find what your coefficient is.	15,082	951	[]
volunteer	Yeah, that's what I assumed you did. That's all you did was just swap the coefficients.	15,082	952	[]
volunteer	but just know that you would get the wrong answer.	15,082	953	[]
student	yeah, understood	15,082	954	[]
volunteer	OK	15,082	955	[]
volunteer	And then we can do, how many examples are there? 1415 looks good fun.	15,082	956	[]
volunteer	This is kind of what we're talking about earlier.	15,082	957	[]
volunteer	rig inside our	15,082	958	[]
volunteer	um inner grains	15,082	959	[]
volunteer	Uh, then there's 16, so they have	15,082	960	[]
volunteer	looks like they have examples for each form in the table.	15,082	961	[]
volunteer	Well, close enough. They probably don't, I don't think they have one for problems too.	15,082	962	[]
volunteer	but they definitely have one for 3 and	15,082	963	[]
volunteer	4	15,082	964	[]
volunteer	Right	15,082	965	[]
volunteer	Um, I think that's enough. Well, we should have done.	15,082	966	[]
volunteer	sample 15. We can do example 15.	15,082	967	[]
volunteer	and then move on to, I don't know if you have time to do.	15,082	968	[]
volunteer	any examples	15,082	969	[]
volunteer	We can do	15,082	970	[]
volunteer	I'm sorry, exercises	15,082	971	[]
volunteer	Well, I guess you can work on that on your own, but	15,082	972	[]
student	i'll do it	15,082	973	[]
volunteer	it'll be good to handle something like	15,082	974	[]
volunteer	where did they get tangent? Oh, dissolutions.	15,082	975	[]
volunteer	The solution, sir. All right, so	15,082	976	[]
volunteer	for example 15.	15,082	977	[]
volunteer	Now we have	15,082	978	[]
volunteer	expressions that need to be rewritten.	15,082	979	[]
student	right, let's try it	15,082	980	[]
volunteer	All right, let it rip	15,082	981	[]
volunteer	Now they give you, well, I guess you don't want to look at the solution. I said they give you what	15,082	982	[]
volunteer	the parameter is	15,082	983	[]
volunteer	They say why here.	15,082	984	[]
volunteer	By the way, this symbol	15,082	985	[]
volunteer	um, with the zero with the vertical slash, it's called phi. It's a Greek letter.	15,082	986	[ { "pii_type": "NRP", "surrogate": "Greek", "start": 67, "end": 72 } ]
volunteer	This becomes more prevalent when you start talking about um	15,082	987	[]
volunteer	radio coordinates in 3 dimensions.	15,082	988	[]
volunteer	They it's, I think it's actually spherical coordinates. Yeah, it's spherical coordinates.	15,082	989	[]
volunteer	Anyway	15,082	990	[]
student	done	15,082	991	[]
student	you there?	15,082	992	[]
volunteer	Oh, sorry	15,082	993	[]
volunteer	I was distracted. Yeah, um, let's see. Did you get	15,082	994	[]
volunteer	3 log 22 minus sign there, um, plus 4/2 minus sine theta.	15,082	995	[]
volunteer	When do I have	15,082	996	[]
volunteer	oh, they flipped it	15,082	997	[]
volunteer	to get rid of the absolute value.	15,082	998	[]
volunteer	Yeah, cause this is what I got.	15,082	999	[]
student	i got sin fi - 2	15,082	1,000	[]
volunteer	sci 5 minus 2. Yeah, that's, that's basically this form. They just rewrote it.	15,082	1,001	[]
volunteer	because you have a negative term here. So they changed the Y minus 2 to 2 minusy, and they changed the absolute value here.	15,082	1,002	[]
volunteer	um because fee can never be greater than one.	15,082	1,003	[]
volunteer	They changed it to 2 minus 5.	15,082	1,004	[]
volunteer	just to kind of solve the absolute value.	15,082	1,005	[]
student	no, in log	15,082	1,006	[]
volunteer	So you're right	15,082	1,007	[]
volunteer	wait in long, yeah, yeah, 2 minus.	15,082	1,008	[]
volunteer	sine 5 minus 2. So the absolute value of Si phi minus 2.	15,082	1,009	[]
volunteer	is only ever between	15,082	1,010	[]
volunteer	I think, 3 and -1.	15,082	1,011	[]
volunteer	So	15,082	1,012	[]
volunteer	to change the absolute value, they distributed the negative	15,082	1,013	[]
volunteer	So you have 2 minus sign data sign phi, right? Sign only fluctuates between -1 and 1.	15,082	1,014	[]
volunteer	So 2 minus -1 is 3 and 2 minus 1 is 1, so they keep it this form to get rid of absolute value.	15,082	1,015	[]
volunteer	But this form is still acceptable.	15,082	1,016	[]
student	ohh, understood	15,082	1,017	[]
volunteer	Yeah.	15,082	1,018	[]
volunteer	Cause remember whenever we do the natural oulo that they include the absolute value because log, natural log can never be um 0 or less than 0.	15,082	1,019	[]
volunteer	So with the district restriction on that domain.	15,082	1,020	[]
volunteer	you can modify the expression.	15,082	1,021	[]
volunteer	cause we're considering absolute value.	15,082	1,022	[]
volunteer	Right? And in this instance, there's only one	15,082	1,023	[]

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