role
stringclasses
2 values
content
stringlengths
0
2.1k
session_id
int64
10
21.7k
sequence_id
int64
0
2.38k
annotations
listlengths
0
8
student
right
15,912
829
[]
volunteer
To, to be honest, that looks like a um
15,912
830
[]
volunteer
uh, a trig identity.
15,912
831
[]
volunteer
It could be
15,912
832
[]
volunteer
kind of seek and squared plus 1 equals tangent squared, or it could be
15,912
833
[]
volunteer
um
15,912
834
[]
volunteer
kind of a half angle or double angle.
15,912
835
[]
student
did you got the answer?
15,912
836
[]
volunteer
No, I didn't.
15,912
837
[]
volunteer
I'll be honest, I did not get it.
15,912
838
[]
student
oh okay
15,912
839
[]
volunteer
That's why I was getting a little frustrated. Uh
15,912
840
[]
volunteer
I mean, you work
15,912
841
[]
volunteer
is good
15,912
842
[]
volunteer
one over.
15,912
843
[]
student
i got it
15,912
844
[]
volunteer
I, I
15,912
845
[]
volunteer
cause one over
15,912
846
[]
volunteer
signed one of sign cosine XL but I probably would have used 1/2 sign 2 theta 1 sine 2 x is what I was trying.
15,912
847
[]
volunteer
I got stuck with cosine 2 theta.
15,912
848
[]
volunteer
or cosine too, right, yeah, co-sequent.
15,912
849
[]
volunteer
2 X
15,912
850
[]
volunteer
D X
15,912
851
[]
volunteer
which
15,912
852
[]
volunteer
which the others, there is
15,912
853
[]
volunteer
Yeah, hmm
15,912
854
[]
volunteer
is a log of Marcus get X minus cotangent X.
15,912
855
[ { "pii_type": "PERSON", "surrogate": "Marcus", "start": 12, "end": 18 } ]
volunteer
which wouldn't help us.
15,912
856
[]
volunteer
TQ
15,912
857
[]
volunteer
Oh, you're right
15,912
858
[]
volunteer
It'd be 1/3 then
15,912
859
[]
volunteer
or I'm sorry, -3
15,912
860
[]
volunteer
No, you're right. I'm sorry
15,912
861
[]
volunteer
Yeah, that's what it was
15,912
862
[]
volunteer
Good catch
15,912
863
[]
volunteer
I don't know why I didn't see it.
15,912
864
[]
student
is that right now?
15,912
865
[]
volunteer
Yeah, that's it. 1/2.
15,912
866
[]
volunteer
Yeah, that's right.
15,912
867
[]
volunteer
Wait, wait
15,912
868
[]
volunteer
Yeah, cause they, the one
15,912
869
[]
volunteer
the one gets included in the C, so that's right.
15,912
870
[]
volunteer
All the constants just get thrown into the C term.
15,912
871
[]
student
ohh
15,912
872
[]
volunteer
All I care about is all you care about are the um X terms.
15,912
873
[]
student
right
15,912
874
[]
volunteer
cause the C is arbitrary
15,912
875
[]
volunteer
without
15,912
876
[]
volunteer
a specific point.
15,912
877
[]
volunteer
on a function. It's arbitrary.
15,912
878
[]
volunteer
or a range
15,912
879
[]
volunteer
domain.
15,912
880
[]
student
yeah, right
15,912
881
[]
volunteer
OK
15,912
882
[]
volunteer
We got like
15,912
883
[]
volunteer
15 minutes left.
15,912
884
[]
volunteer
We can kind of ram through.
15,912
885
[]
volunteer
not ram through, it's not, not the right term.
15,912
886
[]
volunteer
We can address section 7.4 if you like, which just seems to be um
15,912
887
[]
volunteer
some more memorization
15,912
888
[]
volunteer
These examples you can kind of work through on your own, but look, they just, they just literally just give you a bunch of um
15,912
889
[]
volunteer
you know, formulas to memorize.
15,912
890
[]
volunteer
which I'm pretty, yeah, I'm pretty sure this is in that's inverse tangent, that's right.
15,912
891
[]
volunteer
And then there's the inverse sign.
15,912
892
[]
student
do i have to memorize them?
15,912
893
[]
volunteer
You don't have to memorize them. They're typically like
15,912
894
[]
volunteer
either in a textbook or you can just look them up.
15,912
895
[]
volunteer
It's just good, it's just good to
15,912
896
[]
volunteer
um
15,912
897
[]
volunteer
be able to look at them and be like, hey, I think that's
15,912
898
[]
volunteer
you know, if you're dealing with some
15,912
899
[]
volunteer
ratio where you have x or some positive
15,912
900
[]
volunteer
exponent in the bottom.
15,912
901
[]
volunteer
with some um
15,912
902
[]
volunteer
I forget what the term is.
15,912
903
[]
volunteer
shift
15,912
904
[]
volunteer
I mean, it could just be like x minus 3, that's still A could still um work that way.
15,912
905
[]
volunteer
But it's just, it's just a way of knowing just like, hey, but this actually already has solutions.
15,912
906
[]
volunteer
without you having to go through the whole um
15,912
907
[]
volunteer
substitution, integration by substitution method.
15,912
908
[]
volunteer
That's pretty much it
15,912
909
[]
volunteer
which is a lot to say a little
15,912
910
[]
student
okay, so i can solve without these formulas
15,912
911
[]
volunteer
And then, oh, they actually used the
15,912
912
[]
volunteer
innovation by part
15,912
913
[]
volunteer
Yes
15,912
914
[]
volunteer
All you care about is the results.
15,912
915
[]
volunteer
right?
15,912
916
[]
volunteer
That like the, the integral of one over x + a is just the inverse tangent.
15,912
917
[]
volunteer
That's all you care about, um, stuff like that.
15,912
918
[]
volunteer
Just like we used for the
15,912
919
[]
volunteer
integra integral of like tangent and sequent. You didn't need to do it yourself. All you need to do is just be able to go back and refer to it. Like, basically like
15,912
920
[]
volunteer
you gotta know when to use the tools.
15,912
921
[]
volunteer
These, these are all just tools.
15,912
922
[]
volunteer
You gotta know when to use it. That's the main thing, like the, the methodology, the process.
15,912
923
[]
student
too much tools for small toolbox, they might drop out.
15,912
924
[]
volunteer
when and how. I guess it's the best way to say it.
15,912
925
[]
volunteer
This this is also true. This is why the textbooks are so thick.
15,912
926
[]
volunteer
I mean, look at it, you have this this class 12 textbook had to be split in half and still the second book is still 540 pages. This is easily like
15,912
927
[]
volunteer
700 pages of textbook.
15,912
928
[]