Split (1)

train · 116k rows

role stringclasses 2 values	content stringlengths 0 2.1k	session_id int64 10 21.7k	sequence_id int64 0 2.38k	annotations listlengths 0 8
volunteer	do you wanna work on 21 yourself? Just kind of prove where I went wrong.	15,912	629	[]
volunteer	Or do you want to keep going through it together?	15,912	630	[]
volunteer	Just to be honest, it's kind of helping my self-esteem after looking at your exam problems.	15,912	631	[]
student	are you upset due to those problems?	15,912	632	[]
volunteer	A little bit	15,912	633	[]
volunteer	It may just be	15,912	634	[]
volunteer	too early in the morning	15,912	635	[]
volunteer	Not really, but	15,912	636	[]
volunteer	um	15,912	637	[]
volunteer	those are also on the tip of my tongue. I just	15,912	638	[]
volunteer	anyway, I didn't, I didn't, um, I kind of followed you on the previous problem. I had no, I was so confused	15,912	639	[]
volunteer	I've always struggled with the um	15,912	640	[]
volunteer	with rig, uh	15,912	641	[]
volunteer	with these kind of trigger identities	15,912	642	[]
volunteer	or struggle is a strong word, but	15,912	643	[]
volunteer	tougher than most	15,912	644	[]
volunteer	I didn't really find any errors in your	15,912	645	[]
volunteer	formulation for number 19.	15,912	646	[]
volunteer	21. Let me	15,912	647	[]
student	it's fine. there were easier problem too. you 'd plenty of them	15,912	648	[]
volunteer	let me retry that property. So if we say sign of.	15,912	649	[]
volunteer	you don't have to try to soothe my soap, my, my ego here. I'm fine.	15,912	650	[]
volunteer	Um	15,912	651	[]
volunteer	so they say 9, so you said 90, say pie or two.	15,912	652	[]
volunteer	minus X Where does that come from?	15,912	653	[]
volunteer	This would give us negative cosine.	15,912	654	[]
volunteer	What about	15,912	655	[]
volunteer	sign of	15,912	656	[]
volunteer	X minus 52.	15,912	657	[]
volunteer	This would also give us negative cosine.	15,912	658	[]
volunteer	Does it though	15,912	659	[]
volunteer	of course I your device.	15,912	660	[]
volunteer	minus	15,912	661	[]
student	no, really. my teacher said to us try to do easier problem, you won't able to finish all of them due to time.	15,912	662	[]
volunteer	Oh, for the exam	15,912	663	[]
volunteer	Yeah	15,912	664	[]
volunteer	That's basically what you do for the SATs as well. Anything that's timed really.	15,912	665	[]
volunteer	You get the low hanging fruit, then you can focus on the harder problems.	15,912	666	[]
volunteer	Um	15,912	667	[]
volunteer	cosine is an even function.	15,912	668	[]
volunteer	So this becomes	15,912	669	[]
volunteer	one, so this just becomes cosine of X.	15,912	670	[]
volunteer	and then co-sign 5 to 0.	15,912	671	[]
volunteer	Huh	15,912	672	[]
volunteer	So that's the identity. So I got it wrong.	15,912	673	[]
volunteer	It's not	15,912	674	[]
volunteer	um X + y or 2 should be 2 minus X.	15,912	675	[]
student	i think both identities are right, but they went for second one.	15,912	676	[]
volunteer	Oh yeah, you're right	15,912	677	[]
volunteer	They're both right	15,912	678	[]
volunteer	Well, there you go	15,912	679	[]
volunteer	And I'm, I was	15,912	680	[]
volunteer	also surprised on oak. Shoot, what was the page number again? It's like 32.	15,912	681	[]
volunteer	Oh, so close	15,912	682	[]
volunteer	Um, I was also surprised why there was only one	15,912	683	[]
volunteer	inverse	15,912	684	[]
volunteer	problem	15,912	685	[]
volunteer	It was kind of, it, it kind of made it a little suspicious. I was like, are they just that difficult or are they that supposed to be easy?	15,912	686	[]
volunteer	But it seemed it's more towards the	15,912	687	[]
volunteer	easy side	15,912	688	[]
volunteer	to me to scratch that. Let me not say that because this is a very, this is one problem out of, you know, however many difficult problems there are.	15,912	689	[]
volunteer	may not generalize	15,912	690	[]
volunteer	Let me not generalize.	15,912	691	[]
student	there's another way to do it too. Gimme a min to think	15,912	692	[]
volunteer	Oh, really? Oh, I wanna, I wanna see your	15,912	693	[]
volunteer	Mm.	15,912	694	[]
volunteer	live in this one.	15,912	695	[]
volunteer	Oops sorry	15,912	696	[]
student	im unable to remember it.	15,912	697	[]
volunteer	What do you think it was?	15,912	698	[]
volunteer	Or what did I have	15,912	699	[]
volunteer	to do with	15,912	700	[]
student	i think it was letting such cos theta = x	15,912	701	[]
student	sin theta d theta = dx	15,912	702	[]
volunteer	But then you'd be stuck with the extras sign the term.	15,912	703	[]
volunteer	sine theta term.	15,912	704	[]
volunteer	I saw you working earlier.	15,912	705	[]
volunteer	You were um	15,912	706	[]
volunteer	trying that approach, but it just kind of dead ends.	15,912	707	[]
student	im not getting sin thetea in numerator	15,912	708	[]
student	yeah, not seem to work	15,912	709	[]
volunteer	Yeah, that's where I was getting stuck to.	15,912	710	[]
volunteer	Um	15,912	711	[]
volunteer	because once you have	15,912	712	[]
volunteer	your, your parameter, your D parameter where you just say T equal to	15,912	713	[]
volunteer	something	15,912	714	[]
volunteer	DX	15,912	715	[]
volunteer	If you can't rewrite this something in terms of tea.	15,912	716	[]
volunteer	say GFT, then	15,912	717	[]
volunteer	you can't really use it	15,912	718	[]
volunteer	in your inner gra	15,912	719	[]
volunteer	Ingra	15,912	720	[]
student	yeah, right. we need dt	15,912	721	[]
volunteer	right? And you need and you really need is um DX by itself.	15,912	722	[]
student	yeah	15,912	723	[]
volunteer	because it becomes kind of useless.	15,912	724	[]
volunteer	if you	15,912	725	[]
volunteer	introduce this parameter term, but then you get stuck	15,912	726	[]
volunteer	with some	15,912	727	[]
volunteer	you know, original ex term inside your	15,912	728	[]

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