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8
volunteer
Yeah, basically
16,453
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[]
volunteer
and like, you know how the quadratics and like X^2 point the same direction?
16,453
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[]
student
Mhm
16,453
715
[]
volunteer
Yes.
16,453
716
[]
volunteer
All right, we can move on now.
16,453
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student
Well, can I read this, the leading coefficient is negative.
16,453
718
[]
student
when and behavior is, what did I mean write down, look up.
16,453
719
[]
student
Oh. Yeah, yeah.
16,453
720
[]
volunteer
You notice how the right side is pointing down, and on this side pointing out, yes.
16,453
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[]
volunteer
That's why
16,453
722
[]
volunteer
Uh-huh.
16,453
723
[]
student
Wait, can I, can I say one more question on this just to make sure I got it.
16,453
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[]
volunteer
This would be uh, this would be a, um, even one though.
16,453
725
[]
student
So negative. So, I mean, odd.
16,453
726
[]
student
since it's both like.
16,453
727
[]
volunteer
So, well, first of all, let's find the degree.
16,453
728
[]
student
OK
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729
[]
volunteer
So how many times does it cross the X-axis.
16,453
730
[]
student
Um
16,453
731
[]
volunteer
OK, I have noticed a new thing, so I'm just gonna tell you this now. You see how it's going into
16,453
732
[]
volunteer
a
16,453
733
[]
volunteer
X value at a curve.
16,453
734
[]
student
right here
16,453
735
[]
volunteer
Yes, that would mean that that's cubed, the multiplicity would be 3.
16,453
736
[]
student
Oh.
16,453
737
[]
volunteer
You see how it's going into that like swooping motion.
16,453
738
[]
student
Mhm
16,453
739
[]
volunteer
Yes, that would mean that the X value.
16,453
740
[]
volunteer
to the power of 3
16,453
741
[]
volunteer
So take that into account when you're counting the times it crosses the x-axis.
16,453
742
[]
volunteer
So that
16,453
743
[]
student
Oh, OK. So when
16,453
744
[]
volunteer
mhm
16,453
745
[]
student
2
16,453
746
[]
volunteer
Good
16,453
747
[]
student
3
16,453
748
[]
volunteer
Yup
16,453
749
[]
student
6
16,453
750
[]
volunteer
Yes
16,453
751
[]
student
so even
16,453
752
[]
volunteer
Yup
16,453
753
[]
student
The leading coefficient, uh, negative.
16,453
754
[]
volunteer
Good. And do you know why it's negative?
16,453
755
[]
student
cause they're facing now
16,453
756
[]
volunteer
Good
16,453
757
[]
student
and there are different zeros.
16,453
758
[]
volunteer
Yup, because there's a multiplicity of 3
16,453
759
[]
volunteer
on this
16,453
760
[]
student
and to maximums.
16,453
761
[]
volunteer
Is there 2? Yep.
16,453
762
[]
volunteer
Good job. See, you do it.
16,453
763
[]
student
Was, OK. OK, I got it. OK, so, OK.
16,453
764
[]
student
So I'm, I'm trying to write this down.
16,453
765
[]
volunteer
No problem. Take your time.
16,453
766
[]
student
OK
16,453
767
[]
volunteer
All right. So, plot the X intercepts and make a signed chart that represents the functions shown below. All right, so you see it's negative, X + 2 x minus 1.
16,453
768
[]
volunteer
and x minus 6
16,453
769
[]
student
a negative X minus 2.
16,453
770
[]
volunteer
So what would that be
16,453
771
[]
student
Would that be equals 2.
16,453
772
[]
volunteer
I think so
16,453
773
[]
student
or
16,453
774
[]
volunteer
I've never seen it written like that, but that seems correct.
16,453
775
[]
student
or X equals -2.
16,453
776
[]
volunteer
Right, negative X
16,453
777
[]
volunteer
minus 2
16,453
778
[]
volunteer
Yes, so the X would equal 2.
16,453
779
[]
student
OK, so
16,453
780
[]
student
hold on
16,453
781
[]
student
Well, it'll be negative too, negative X minus 2.
16,453
782
[]
volunteer
Yeah, well, yeah, if you distribute the negative, it would be negative X minus 2, which would just be 2, right?
16,453
783
[]
student
X minus 2
16,453
784
[]
volunteer
Yep.
16,453
785
[]
student
Oh, I thought it would be, um, I thought it would be.
16,453
786
[]
volunteer
Well, well, what would negative X minus 2? How would negative X minus 2 equals 0.
16,453
787
[]
student
1 X is.
16,453
788
[]
student
2
16,453
789
[]
student
Oh wait, no
16,453
790
[]
volunteer
Yes
16,453
791
[]
student
So it was you
16,453
792
[]
volunteer
Look, because X
16,453
793
[]
volunteer
minus 2
16,453
794
[]
volunteer
-x - 2 = 0
16,453
795
[]
volunteer
equals 0, right
16,453
796
[]
student
Yeah
16,453
797
[]
volunteer
And so, if X is equal to -2
16,453
798
[]
volunteer
that would just be
16,453
799
[]
student
Mm.
16,453
800
[]
volunteer
2 minus 2 equals 0. So yeah, you would just basically ignore that negative because it's not attached to an X or anything.
16,453
801
[]
student
So
16,453
802
[]
volunteer
and you just focus on the functions.
16,453
803
[]
student
this will be X
16,453
804
[]
student
equals 1
16,453
805
[]
volunteer
Yup
16,453
806
[]
student
Wouldn't this be 2 times, so.
16,453
807
[]
student
yeah
16,453
808
[]
volunteer
It would be a multiplicity, but I'm pretty sure if it's a number chart, you would just do it once.
16,453
809
[]
volunteer
And now we do a sign chart
16,453
810
[]
student
uh.
16,453
811
[]
volunteer
So do you know how to do this?
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