role stringclasses 2
values | content stringlengths 0 2.1k | session_id int64 10 21.7k | sequence_id int64 0 2.38k | annotations listlengths 0 8 |
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volunteer | which means that you know how the function is changing for any point in for any point X | 16,993 | 348 | [] |
volunteer | inside the function | 16,993 | 349 | [] |
volunteer | So you could predictively model | 16,993 | 350 | [] |
volunteer | you would like just with the derivative function, you would know exactly how the function is changing at any point in time. | 16,993 | 351 | [] |
volunteer | Yeah, that's, that's the all real numbers are. | 16,993 | 352 | [] |
volunteer | So this is, so this is just to prove that like, you know, it's | 16,993 | 353 | [] |
volunteer | an effective | 16,993 | 354 | [] |
volunteer | inaccurate way to predict the behavior of F. | 16,993 | 355 | [] |
volunteer | the function F, that this derivative, this derivative function. | 16,993 | 356 | [] |
volunteer | Um, all that to say is that, you know, this is what we did the derivative. Now we want to figure out what is an effective and accurate way of predicting, of knowing the behavior | 16,993 | 357 | [] |
volunteer | of the area under the curve, of being able to find the value under the curve. | 16,993 | 358 | [] |
volunteer | which you'll be able to tell us because, you know, because it's the antiderivative, this is saying that like, OK, we have this function F. | 16,993 | 359 | [] |
volunteer | uh, you get the | 16,993 | 360 | [] |
volunteer | if you go back up to the | 16,993 | 361 | [] |
volunteer | the first graph I did, you say we have this, we have this graph F. | 16,993 | 362 | [] |
volunteer | OK. We want to know, assuming this is like, let's just say this is F. | 16,993 | 363 | [] |
volunteer | right? This is the derivative function | 16,993 | 364 | [] |
volunteer | and we want to know if, since this is the, this, this tells us the change in the behavior of F. We want to know, is it possible to | 16,993 | 365 | [] |
volunteer | take the, like, take the and derivative, do the opposite derivative, and using the change in the behavior to be able to find out what F is. | 16,993 | 366 | [] |
volunteer | But we in the way we do that is we kind of take several approaches and which are just approximations and we try to see | 16,993 | 367 | [] |
volunteer | uh by taking the limit or by summing up all the infinitesimal values. Is this an accurate representation | 16,993 | 368 | [] |
volunteer | of the function | 16,993 | 369 | [] |
volunteer | And we know that for the derivative, any value, any Y value, | 16,993 | 370 | [] |
volunteer | in the derivative tells you the slope at any point in, in the origin the parent function F. | 16,993 | 371 | [] |
volunteer | But when we do that, we can say that the change, you go to Delta X and X | 16,993 | 372 | [] |
volunteer | XI and Xi + 1. | 16,993 | 373 | [] |
volunteer | using the trapezoid rule | 16,993 | 374 | [] |
volunteer | and we say | 16,993 | 375 | [] |
volunteer | if we find the average | 16,993 | 376 | [] |
volunteer | of the two, let's say, um, let's see. | 16,993 | 377 | [] |
volunteer | Yeah, they say average | 16,993 | 378 | [] |
volunteer | F, right, over some range delta X. | 16,993 | 379 | [] |
volunteer | right? You see how this makes little. | 16,993 | 380 | [] |
volunteer | Yeah, we can say that this is an approximation | 16,993 | 381 | [] |
volunteer | to | 16,993 | 382 | [] |
volunteer | the uh | 16,993 | 383 | [] |
volunteer | change in F. | 16,993 | 384 | [] |
volunteer | right? | 16,993 | 385 | [] |
volunteer | Because we know that um | 16,993 | 386 | [] |
volunteer | since the F is the slope. | 16,993 | 387 | [] |
volunteer | Let me try to, let me get some space. Let me move that graph a little lower. | 16,993 | 388 | [] |
volunteer | Oh, I can't grab everything | 16,993 | 389 | [] |
volunteer | I | 16,993 | 390 | [] |
volunteer | very frustrating | 16,993 | 391 | [] |
volunteer | Mm | 16,993 | 392 | [] |
volunteer | All right | 16,993 | 393 | [] |
volunteer | move this | 16,993 | 394 | [] |
volunteer | down so I can | 16,993 | 395 | [] |
volunteer | remove all of this. | 16,993 | 396 | [] |
volunteer | up. | 16,993 | 397 | [] |
volunteer | Right | 16,993 | 398 | [] |
volunteer | there, close enough | 16,993 | 399 | [] |
volunteer | right | 16,993 | 400 | [] |
volunteer | And you got room in the bottom | 16,993 | 401 | [] |
volunteer | All right. So we know | 16,993 | 402 | [] |
volunteer | F | 16,993 | 403 | [] |
volunteer | F of X, any point is just the slope M at any point X | 16,993 | 404 | [] |
volunteer | All right, just a slope | 16,993 | 405 | [] |
volunteer | And we know that the slope is just equal to our change in F, right? The change and the elevation. | 16,993 | 406 | [] |
volunteer | divided by the change in our X | 16,993 | 407 | [] |
volunteer | And we want to know, is this area under the curve? Can we approximate the area under the curve cause we want to know what Delta F is. | 16,993 | 408 | [] |
volunteer | because that's, that's our change in the function. | 16,993 | 409 | [] |
volunteer | right? | 16,993 | 410 | [] |
volunteer | So we do, so using the trapezoid rule, you're right, trapezoid. | 16,993 | 411 | [] |
volunteer | Trapezoidal rule | 16,993 | 412 | [] |
volunteer | right | 16,993 | 413 | [] |
volunteer | So we can say um using our average F, right? Over the, over the step size of Delta F. | 16,993 | 414 | [] |
volunteer | We say that Delta F is approximately equal to our | 16,993 | 415 | [] |
volunteer | average step size, which this one would be F of X_I, X of XI. | 16,993 | 416 | [] |
volunteer | plus F of XI + 1. | 16,993 | 417 | [] |
volunteer | over 2 | 16,993 | 418 | [] |
volunteer | times our step | 16,993 | 419 | [] |
volunteer | right | 16,993 | 420 | [] |
volunteer | is approximately equal to Delta F. | 16,993 | 421 | [] |
volunteer | which is the area under the curve. | 16,993 | 422 | [] |
volunteer | like the entire, the full area under the curve from X1 to Xn. | 16,993 | 423 | [] |
volunteer | is what our integral would be. | 16,993 | 424 | [] |
volunteer | But you notice that this is missing | 16,993 | 425 | [] |
volunteer | Let me use a different color | 16,993 | 426 | [] |
volunteer | Um, like green, you know, that this is missing. | 16,993 | 427 | [] |
volunteer | this gap right here | 16,993 | 428 | [] |
volunteer | So this is our | 16,993 | 429 | [] |
volunteer | our error value | 16,993 | 430 | [] |
volunteer | right? And that's why there's Delta F remains an approximation. | 16,993 | 431 | [] |
volunteer | But again, if we um | 16,993 | 432 | [] |
volunteer | if we take the limit | 16,993 | 433 | [] |
volunteer | of delta X as it approaches 0, right? | 16,993 | 434 | [] |
volunteer | of this delta F function. | 16,993 | 435 | [] |
volunteer | right? | 16,993 | 436 | [] |
volunteer | Then we can reasonably get | 16,993 | 437 | [] |
volunteer | hopefully | 16,993 | 438 | [] |
volunteer | this, the accurate del delta F. | 16,993 | 439 | [] |
volunteer | right? Now you notice in the equation it's multiplied, so it'd probably be equal to 0. | 16,993 | 440 | [] |
volunteer | but we would, uh | 16,993 | 441 | [] |
volunteer | figure out, try to figure out, I guess it'd be | 16,993 | 442 | [] |
volunteer | the minute it goes | 16,993 | 443 | [] |
volunteer | as the error function goes to the, we'd be there, evaluate the error function. | 16,993 | 444 | [] |
volunteer | the secondary error function. | 16,993 | 445 | [] |
volunteer | We would want, so we, as a limit of De tax budget there are stepsize gets infinitesimally small. We want our error function. | 16,993 | 446 | [] |
volunteer | to be zero | 16,993 | 447 | [] |
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