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8
volunteer
Sharp
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student
yup!
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volunteer
Bye.
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student
Get well soon! bye
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volunteer
Was that you? I'm ready now
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volunteer
Hello
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volunteer
How may I help you?
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student
Hi Chris
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[ { "pii_type": "PERSON", "surrogate": "Chris", "start": 3, "end": 8 } ]
student
I have doubt in question of quadratic equation
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volunteer
Can you show me the problem you are working on?
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student
If f(x)=9x−8 sqr root x such that g(x)=f(x)−1, then which one of the following is correct?
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student
(a) g(x)=0 has no real roots (b) g(x)=0 has only one real root which is an integer (c) g(x)=0 has two real roots which are integers (d) g(x)=0 has only one real root which is not an integer
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volunteer
I am not quite sure of the equations. did I write them correctly?
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student
it is right
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volunteer
You should start by writing the equation for g(x)
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student
ok
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student
g(x) = 9x - 8 sqr root (x) - 1
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volunteer
OK, we need to solve that for x
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student
yes
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student
I took 1 on right side, and square both sides
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volunteer
Usually in this kind of equation, you get the √x on one side by itself and then square both sides. That gets rid of the square roots
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student
ok, got it!
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student
so, do i keep "1" on LHS or take it RHS?
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volunteer
If you brought the 1 over to the RHS, then when you squared both sides, you would still have a square root term
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volunteer
now, when you square both sides, there will be no square root terms at all. Make sense?
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student
I got the first para, that taking "1" on RHS will have root x remain in equation
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student
i didnot understand second one
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volunteer
Let's square both sides now
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student
ok
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student
ohhh
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student
you took 8 root x other side.
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student
Got it!
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volunteer
Now you will end up with a quadratic equations with no square roots anywhere.
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student
yes, that's right
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volunteer
But when you square things, you must be very careful to check your answers in the original equation, because you can introduce extraneous roots
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volunteer
can you solve that equation, do you think?
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student
yes, I did it.
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student
I am getting two values for x
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student
x = 81/3 and 1
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student
sorry, x = 1/81
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volunteer
You need to check them in the original equation
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volunteer
Do they both work?
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student
x = 1/81 , doesnt make equation equal to 0
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student
but x = 1 statisfies the equation
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volunteer
Right, 1/81 is an extraneous root.
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volunteer
so x =1 is the only root
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student
what is extraneous root? root which doesn't satisfy the equation?
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volunteer
An extra root that doesn't satisfy the original equation. WHen you square equations, you can introduce roots that don't actually satisfy the original equation. Those are called extraneous roots
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student
Ohh, ok, understood.
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student
so, for this question, it will be option (b)
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volunteer
Yes, I believe so.
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student
yes, it is right!
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student
I have one more question
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volunteer
ok
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student
can I erase the board? and write question there?
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volunteer
Yes, or you can also upload an image
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student
I upload the picture, is it visible?
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volunteer
yes
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volunteer
I don't know what they mean by AP, GP, and HP
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student
it is arithmeic progresion, Geometric Progression, harmonic progression
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student
We can leave this question, then.
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student
I have its second part which is only related to quadratic
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volunteer
My first impession is that Descartes's rules would be helpful here, but I will have to work it out.
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[ { "pii_type": "PERSON", "surrogate": "Descartes", "start": 27, "end": 36 } ]
student
i tried to apply it but I didn't understand how to solve it further
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volunteer
Yes, it uses Descartes's rules
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[ { "pii_type": "PERSON", "surrogate": "Descartes", "start": 13, "end": 22 } ]
volunteer
The sum of the two roots equals -b/a for ax^2 +bx +c
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student
yes
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volunteer
but they tell us that alpha=beta
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student
how did you know alpha=beta?
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volunteer
Because it says that the roots of the equation are equal
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student
yes right! I didn't read it properly
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student
understood!
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student
I have one more question
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volunteer
ok
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student
can you explain like how do i approach such questions? what should I be thinking first? I donot understand these type of questions
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volunteer
What kind of curve is x^2 +2x+11 ?
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volunteer
Not sure?
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student
wait a min
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student
is this right?
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volunteer
So what is the minimum value of the quadratic?
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student
will we take lowest value of x here?
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student
as minimum value?
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volunteer
what is the minimum value of the quadratic?
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student
I donot know
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volunteer
Yes, you do. You have written it on your graph.
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student
-1?
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volunteer
-1 is the x coordinate of the quadratic. But the minimum VALUE of the quadratic (that is, the y value) is 10
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volunteer
Any questions about that?
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student
so, the lowest value of y coordinate is minimum value
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volunteer
WHen we talk about the "value" of a function, we are talking about y, not x
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volunteer
so the minimum value of the quadratic is 10
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student
oh, so when we talk about x, how do we say it?
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volunteer
x is the x coordinate.
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volunteer
So now you need to calculate the log base 10 of 10
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student
that will be 1
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student
option (b) is right answer.
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volunteer
yes
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student
I got one more question
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volunteer
How many more questions do you have?
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student
One one last question, but that's is of intergral calculus
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