role stringclasses 2
values | content stringlengths 0 2.1k | session_id int64 10 21.7k | sequence_id int64 0 2.38k | annotations listlengths 0 8 |
|---|---|---|---|---|
volunteer | Sharp | 21,191 | 792 | [] |
student | yup! | 21,191 | 793 | [] |
volunteer | Bye. | 21,191 | 794 | [] |
student | Get well soon! bye | 21,191 | 795 | [] |
volunteer | Was that you? I'm ready now | 21,191 | 796 | [] |
volunteer | Hello | 21,539 | 0 | [] |
volunteer | How may I help you? | 21,539 | 1 | [] |
student | Hi Chris | 21,539 | 2 | [
{
"pii_type": "PERSON",
"surrogate": "Chris",
"start": 3,
"end": 8
}
] |
student | I have doubt in question of quadratic equation | 21,539 | 3 | [] |
volunteer | Can you show me the problem you are working on? | 21,539 | 4 | [] |
student | If f(x)=9x−8 sqr root x such that g(x)=f(x)−1, then which one of the following is correct? | 21,539 | 5 | [] |
student | (a) g(x)=0 has no real roots
(b) g(x)=0 has only one real root which is an integer
(c) g(x)=0 has two real roots which are integers
(d) g(x)=0 has only one real root which is not an integer | 21,539 | 6 | [] |
volunteer | I am not quite sure of the equations. did I write them correctly? | 21,539 | 7 | [] |
student | it is right | 21,539 | 8 | [] |
volunteer | You should start by writing the equation for g(x) | 21,539 | 9 | [] |
student | ok | 21,539 | 10 | [] |
student | g(x) = 9x - 8 sqr root (x) - 1 | 21,539 | 11 | [] |
volunteer | OK, we need to solve that for x | 21,539 | 12 | [] |
student | yes | 21,539 | 13 | [] |
student | I took 1 on right side, and square both sides | 21,539 | 14 | [] |
volunteer | Usually in this kind of equation, you get the √x on one side by itself and then square both sides. That gets rid of the square roots | 21,539 | 15 | [] |
student | ok, got it! | 21,539 | 16 | [] |
student | so, do i keep "1" on LHS or take it RHS? | 21,539 | 17 | [] |
volunteer | If you brought the 1 over to the RHS, then when you squared both sides, you would still have a square root term | 21,539 | 18 | [] |
volunteer | now, when you square both sides, there will be no square root terms at all. Make sense? | 21,539 | 19 | [] |
student | I got the first para, that taking "1" on RHS will have root x remain in equation | 21,539 | 20 | [] |
student | i didnot understand second one | 21,539 | 21 | [] |
volunteer | Let's square both sides now | 21,539 | 22 | [] |
student | ok | 21,539 | 23 | [] |
student | ohhh | 21,539 | 24 | [] |
student | you took 8 root x other side. | 21,539 | 25 | [] |
student | Got it! | 21,539 | 26 | [] |
volunteer | Now you will end up with a quadratic equations with no square roots anywhere. | 21,539 | 27 | [] |
student | yes, that's right | 21,539 | 28 | [] |
volunteer | But when you square things, you must be very careful to check your answers in the original equation, because you can introduce extraneous roots | 21,539 | 29 | [] |
volunteer | can you solve that equation, do you think? | 21,539 | 30 | [] |
student | yes, I did it. | 21,539 | 31 | [] |
student | I am getting two values for x | 21,539 | 32 | [] |
student | x = 81/3 and 1 | 21,539 | 33 | [] |
student | sorry, x = 1/81 | 21,539 | 34 | [] |
volunteer | You need to check them in the original equation | 21,539 | 35 | [] |
volunteer | Do they both work? | 21,539 | 36 | [] |
student | x = 1/81 , doesnt make equation equal to 0 | 21,539 | 37 | [] |
student | but x = 1 statisfies the equation | 21,539 | 38 | [] |
volunteer | Right, 1/81 is an extraneous root. | 21,539 | 39 | [] |
volunteer | so x =1 is the only root | 21,539 | 40 | [] |
student | what is extraneous root? root which doesn't satisfy the equation? | 21,539 | 41 | [] |
volunteer | An extra root that doesn't satisfy the original equation. WHen you square equations, you can introduce roots that don't actually satisfy the original equation. Those are called extraneous roots | 21,539 | 42 | [] |
student | Ohh, ok, understood. | 21,539 | 43 | [] |
student | so, for this question, it will be option (b) | 21,539 | 44 | [] |
volunteer | Yes, I believe so. | 21,539 | 45 | [] |
student | yes, it is right! | 21,539 | 46 | [] |
student | I have one more question | 21,539 | 47 | [] |
volunteer | ok | 21,539 | 48 | [] |
student | can I erase the board? and write question there? | 21,539 | 49 | [] |
volunteer | Yes, or you can also upload an image | 21,539 | 50 | [] |
student | I upload the picture, is it visible? | 21,539 | 51 | [] |
volunteer | yes | 21,539 | 52 | [] |
volunteer | I don't know what they mean by AP, GP, and HP | 21,539 | 53 | [] |
student | it is arithmeic progresion, Geometric Progression, harmonic progression | 21,539 | 54 | [] |
student | We can leave this question, then. | 21,539 | 55 | [] |
student | I have its second part which is only related to quadratic | 21,539 | 56 | [] |
volunteer | My first impession is that Descartes's rules would be helpful here, but I will have to work it out. | 21,539 | 57 | [
{
"pii_type": "PERSON",
"surrogate": "Descartes",
"start": 27,
"end": 36
}
] |
student | i tried to apply it but I didn't understand how to solve it further | 21,539 | 58 | [] |
volunteer | Yes, it uses Descartes's rules | 21,539 | 59 | [
{
"pii_type": "PERSON",
"surrogate": "Descartes",
"start": 13,
"end": 22
}
] |
volunteer | The sum of the two roots equals -b/a for ax^2 +bx +c | 21,539 | 60 | [] |
student | yes | 21,539 | 61 | [] |
volunteer | but they tell us that alpha=beta | 21,539 | 62 | [] |
student | how did you know alpha=beta? | 21,539 | 63 | [] |
volunteer | Because it says that the roots of the equation are equal | 21,539 | 64 | [] |
student | yes right! I didn't read it properly | 21,539 | 65 | [] |
student | understood! | 21,539 | 66 | [] |
student | I have one more question | 21,539 | 67 | [] |
volunteer | ok | 21,539 | 68 | [] |
student | can you explain like how do i approach such questions? what should I be thinking first? I donot understand these type of questions | 21,539 | 69 | [] |
volunteer | What kind of curve is x^2 +2x+11 ? | 21,539 | 70 | [] |
volunteer | Not sure? | 21,539 | 71 | [] |
student | wait a min | 21,539 | 72 | [] |
student | is this right? | 21,539 | 73 | [] |
volunteer | So what is the minimum value of the quadratic? | 21,539 | 74 | [] |
student | will we take lowest value of x here? | 21,539 | 75 | [] |
student | as minimum value? | 21,539 | 76 | [] |
volunteer | what is the minimum value of the quadratic? | 21,539 | 77 | [] |
student | I donot know | 21,539 | 78 | [] |
volunteer | Yes, you do. You have written it on your graph. | 21,539 | 79 | [] |
student | -1? | 21,539 | 80 | [] |
volunteer | -1 is the x coordinate of the quadratic. But the minimum VALUE of the quadratic (that is, the y value) is 10 | 21,539 | 81 | [] |
volunteer | Any questions about that? | 21,539 | 82 | [] |
student | so, the lowest value of y coordinate is minimum value | 21,539 | 83 | [] |
volunteer | WHen we talk about the "value" of a function, we are talking about y, not x | 21,539 | 84 | [] |
volunteer | so the minimum value of the quadratic is 10 | 21,539 | 85 | [] |
student | oh, so when we talk about x, how do we say it? | 21,539 | 86 | [] |
volunteer | x is the x coordinate. | 21,539 | 87 | [] |
volunteer | So now you need to calculate the log base 10 of 10 | 21,539 | 88 | [] |
student | that will be 1 | 21,539 | 89 | [] |
student | option (b) is right answer. | 21,539 | 90 | [] |
volunteer | yes | 21,539 | 91 | [] |
student | I got one more question | 21,539 | 92 | [] |
volunteer | How many more questions do you have? | 21,539 | 93 | [] |
student | One one last question, but that's is of intergral calculus | 21,539 | 94 | [] |
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