Split (1)

train · 116k rows

role stringclasses 2 values	content stringlengths 0 2.1k	session_id int64 10 21.7k	sequence_id int64 0 2.38k	annotations listlengths 0 8
volunteer	Yes sorry for the delay I think my computer is having some connections issues	18,440	9	[]
student	Its ok, maybe try and refresh	18,440	10	[]
student	that usually works	18,440	11	[]
volunteer	So sorry my page keeps going in and out I am going to end the chat and try to find my router. I really apologize for the confusion	18,440	12	[]
student	Hi Hi Ben!!	18,447	0	[ { "pii_type": "PERSON", "surrogate": "Hi Ben!", "start": 3, "end": 10 } ]
volunteer	Hey! How's it going?	18,447	1	[]
student	Pretty good, you?	18,447	2	[]
volunteer	I'm doing well!	18,447	3	[]
student	That’s good!	18,447	4	[]
volunteer	What can I help you with today?	18,447	5	[]
student	Okay so im working on a homework assignment rn, and i was wondering if you could help me through it	18,447	6	[]
volunteer	Sure!	18,447	7	[]
student	How would i go about solving this?	18,447	8	[]
volunteer	So you would take (2x+23)+(9x-5) and make it equal to 95 then solve for x	18,447	9	[]
volunteer	Then once you find x you will plug it into 2x+23 to get ABD	18,447	10	[]
student	Ohhh okay	18,447	11	[]
student	Ben	18,447	12	[ { "pii_type": "PERSON", "surrogate": "Ben", "start": 0, "end": 3 } ]
volunteer	Of course!	18,447	13	[]
volunteer	Is there anything else I can help you with?	18,447	14	[]
student	Nope!	18,447	15	[]
volunteer	Ok! goodbye!	18,447	16	[]
volunteer	Hi, how can I help you?	18,488	0	[]
student	hi	18,488	1	[]
student	I need help on number 29	18,488	2	[]
volunteer	Alright	18,488	3	[]
volunteer	I'll write the steps on the whiteboard	18,488	4	[]
student	ok	18,488	5	[]
volunteer	So let's factor out the numerators and denominators	18,488	6	[]
student	ok	18,488	7	[]
volunteer	So we know that x^2 is just x times x	18,488	8	[]
volunteer	Do you know how to factor out expressions?	18,488	9	[]
student	yeah	18,488	10	[]
student	not when the leading term is 1	18,488	11	[]
volunteer	Okay, i'll show you a step by step on how to factor	18,488	12	[]
volunteer	So when it starts with 1, we know that inside the parenthesis will have one in both because 1 times 1 is 1	18,488	13	[]
student	ok	18,488	14	[]
student	the probelm is i only know how do when x is first term not second	18,488	15	[]
volunteer	Use this formula a^2-b^2=(a-b)(a+b)	18,488	16	[]
volunteer	So for 1-x^2, it would be (1-x)(1+x)	18,488	17	[]
student	oh i like x as first	18,488	18	[]
volunteer	Ok you can write that as (-x+1)(x+1)	18,488	19	[]
student	ok	18,488	20	[]
volunteer	Do you know how to factor this next one: 1 + x^2	18,488	21	[]
student	well what i did for first term is i did'	18,488	22	[]
student	-(x^2-1)	18,488	23	[]
student	which is same as -x^2+1	18,488	24	[]
volunteer	I see. When it says factor, we want to get rid of any powers on the x as much as we can	18,488	25	[]
student	yeah but cany we do -(x^2-1)	18,488	26	[]
volunteer	x^2 can be simplified more which is why we use the method of two separate parenthesis	18,488	27	[]
student	and then do -(x+1)(x-1)	18,488	28	[]
student	ye	18,488	29	[]
volunteer	Yes, you would get the same result. You can do this method!	18,488	30	[]
student	ok	18,488	31	[]
volunteer	So now what about 1+x^2? Can you factor this out?	18,488	32	[]
student	(x+1)(x-1)	18,488	33	[]
student	i mean no	18,488	34	[]
volunteer	You can't factor this expression, it's already in it's simplest form	18,488	35	[]
volunteer	So we'll keep this as is	18,488	36	[]
student	yep	18,488	37	[]
volunteer	So let's move onto the next fraction	18,488	38	[]
volunteer	Let's factor x^3 + x	18,488	39	[]
student	ok	18,488	40	[]
volunteer	So we have a cubed root which is also x^2 times x	18,488	41	[]
student	yeah	18,488	42	[]
volunteer	So lets make a parenthesis, and we lets take an x out	18,488	43	[]
student	ok	18,488	44	[]
volunteer	x(x^2+1) is the simplest form for this expression.	18,488	45	[]
volunteer	Now we have the denominator x^3-x	18,488	46	[]
volunteer	Let's use the same process	18,488	47	[]
student	yep	18,488	48	[]
volunteer	Instead of a positive 1, we use a negative 1 because we have a negative x	18,488	49	[]
student	ok	18,488	50	[]
volunteer	Now, let's set everything up again	18,488	51	[]
student	ok	18,488	52	[]
volunteer	But before we write down this last denominator, we can see that this can be split up more	18,488	53	[]
volunteer	We can further factor x^2-1 into x-1 times x+1	18,488	54	[]
student	ok	18,488	55	[]
student	so we cancel now?	18,488	56	[]
volunteer	Yes!	18,488	57	[]
volunteer	What can we cancel out first?	18,488	58	[]
student	the x	18,488	59	[]
volunteer	Yes! Great job	18,488	60	[]
volunteer	Let's combine this all into one fraction	18,488	61	[]
student	ok	18,488	62	[]
volunteer	So we have 1-x in the numerator which can be rewritten as -(x-1)	18,488	63	[]
volunteer	Let's rewrite again	18,488	64	[]
student	yeah	18,488	65	[]
volunteer	x+1 is the same as 1+x	18,488	66	[]
volunteer	And x^2+1 is the same as 1+x^2	18,488	67	[]
student	yes	18,488	68	[]
volunteer	So we have duplicates of x-1, x+1, and x^2+1. Lets cancel out these terms	18,488	69	[]
student	ok	18,488	70	[]
volunteer	All we are left is with is a - which can be rewritten as -1	18,488	71	[]
volunteer	So -1 is our final answer!	18,488	72	[]
student	ok	18,488	73	[]
student	what about domaims	18,488	74	[]
student	domains	18,488	75	[]
volunteer	Domains in general ?	18,488	76	[]
student	no for this problem	18,488	77	[]
student	we need to find domain	18,488	78	[]

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