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NationalTutoringObservatory
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MathEd-PII

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volunteer
Great, now we need to multiply that number by what?
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student
10?
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volunteer
Yup!
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student
So it's 4.16
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volunteer
Perfect!
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volunteer
Is that all you needed?
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student
Yep
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student
Thank you !
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volunteer
No problem, enjoy your evening!
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volunteer
Hey there!
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student
Hi ace
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student
I need help with a math problem
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volunteer
Hey! What do you need help with?
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volunteer
Ok can you put a photo of it or type it in the chat?
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student
Ioodie-133 has a half-life of 8 days how much is the original 40-gram sample would be left after 40 days
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student
that the question
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volunteer
Hm, are you able to put a photo of it on the paper
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student
ok
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student
if you could flip it Idk how to do that
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volunteer
no worries, let me take a look
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student
ok
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student
I know the method for it
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student
A=a(0.5)^x
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volunteer
Hi Leo
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[ { "pii_type": "PERSON", "surrogate": "Leo", "start": 3, "end": 6 } ]
student
hi
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student
so I was asked to solve for this using partial fractions
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student
and im not sure if I'm doing it right
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volunteer
I'm checking your calculation...
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volunteer
Can you give me 2 minutes to solve, to see if your solution is correct?
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student
ok
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volunteer
We can start. Do you see what I boxed in blue color?
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student
yes
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volunteer
This is one method of solution for partial fractions.
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volunteer
By assuming that x=-a, we quickly find the value of A, as I'll show on the board.
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volunteer
Then, we assume x = -b, and we get the value of B.
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student
ohh ok
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volunteer
There are other methods, but what I'm showing works well.
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student
ok
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volunteer
Anything else I can help you with?
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student
not tat the moment no
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student
thanks for the help:)
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volunteer
Hello
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student
hi, I'm trying to do the problem on the board but it seems like no matter which way I try it i cant do it
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student
the first one is labeled 1 with an explanation of why it didn't work the second one I started but also didn't finish because it didndt work
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volunteer
so what are u trying to do in the first one
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volunteer
are u trying to find the zeros or the vertex
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student
in the first one I distribute the negative 1 before trying to complete the square
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student
the vertex
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volunteer
ok so for complete the square ill show you how to do it and compare it with what you did
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student
ok
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volunteer
let’s find the zeros first because that is what complete the square is mainly used for, so we set it equal to zero
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volunteer
mainly, the negative sign is the part that causes the confusion so we can remove that by dividing both sides by -1
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volunteer
so now the left side becomes positive
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student
so would this be the function in standard form then?
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volunteer
yes so this is the function in standard form
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volunteer
what would be the vertex based on the standard form
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student
1,-16
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student
its supposed to be (1,16) tho according to my answer key
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volunteer
yes because you know how e divided by negative 1 in the beginning
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volunteer
thats the remove the negative to make complete the square much easier
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volunteer
but when we write it back in standard form we have to multiply the negative 1 back
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volunteer
so the equation would become -(x-1)^2+16
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volunteer
which would make the vertex (1,16)
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volunteer
does that make sesne
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student
shouldn't the negative 1 multiply to the entire thing tho, not just the -16?
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volunteer
yeah sorry in the text the negative appears in the line up for some reason
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volunteer
does this make sense
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student
yea I think so. but the don't you have to multiply the - to what's in the parentheses
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volunteer
no because muiplying it out of the parenthesis is the same thing as multiplying each term in the parenthesis by -1 so we keep the eat i’ve sign on the outside
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volunteer
does this make sense
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student
not really
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student
would it make it not in standard form anymore?
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volunteer
its still in standard form cause standard form is written as a(x-h)^2+k where a can be any constant and (h,k) is the vertex
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volunteer
in this case a is -1
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volunteer
so this is in standard form
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student
so if e distribute the negative one, it wouldn't be in standard form anymore eis what ur saying
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volunteer
yes cause the parenthesis is being raised the the power so if you wanna distribute you have to do (x-1)^2 then distribute the negative 1 but if we do that it wouldn’t be in standard form anymore
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student
could you do that and get it back to standard form or no
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volunteer
no cause if you put it back in standard form you’ll end up with whatever we started with originally. the x in the parenthesis must be positive for standard form as well so making it negative will not get you standard orm
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student
got it
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student
and what was wrong about what I was doing earlier? I was doing it how my teacher was doing it
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volunteer
its just the negative is causing problems to we have to distribute it back out
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volunteer
ill show you how
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student
it doesn't look like the negative caused any problems. am I not seeing it right?
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volunteer
for me what i learned was o multiply the negative 1 later but based on what ur teacher is doing treat the -1 as a coefficient of x^2 to be factored out
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volunteer
its just in my opinion a lot ore confusing to have the negative 1 in there which is what i learned in school
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volunteer
so my teacher taught e to divide the negative 1 out then multiply it later
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student
wait so then would you be able to teach me how to do it correctly my teachers way?
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student
taking taking it out as a coefficient
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volunteer
yes so look at the bottom and ill show the steps
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student
ohh ok thanks. idk why that was so hard for me to do
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volunteer
it’s fine everyone makes mistakes
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student
that was all. thank you for helping me
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volunteer
no problem
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student
have a good rest of your evening
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student
bye
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volunteer
bye
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volunteer
hey!
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volunteer
how are ya?
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student
Good
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