role stringclasses 2
values | content stringlengths 0 2.1k | session_id int64 10 21.7k | sequence_id int64 0 2.38k | annotations listlengths 0 8 |
|---|---|---|---|---|
volunteer | The first question asks for the X values, and the second question asks for the Y values. | 15,224 | 70 | [] |
volunteer | So you just have to type | 15,224 | 71 | [] |
volunteer | minus 2 and 3 for the first question, and minus 3 and 0 for the second question. That was it. | 15,224 | 72 | [] |
volunteer | Do you understand now? | 15,224 | 73 | [] |
student | yes | 15,224 | 74 | [] |
volunteer | okay then great job | 15,224 | 75 | [] |
volunteer | Do you have any other questions? | 15,224 | 76 | [] |
student | no | 15,224 | 77 | [] |
volunteer | alright | 15,224 | 78 | [] |
volunteer | HI! How can I help you? | 15,239 | 0 | [] |
student | hiii | 15,239 | 1 | [] |
student | I need help with 5 problems including this one | 15,239 | 2 | [] |
volunteer | sounds great! just for some background info, which theorems are you familiar with that you can use for this problem | 15,239 | 3 | [] |
volunteer | ? | 15,239 | 4 | [] |
student | Tangent, Sin, and Cos | 15,239 | 5 | [] |
volunteer | can you use law of sines? | 15,239 | 6 | [] |
student | no | 15,239 | 7 | [] |
volunteer | hmm ok | 15,239 | 8 | [] |
volunteer | well | 15,239 | 9 | [] |
volunteer | would you like to try using it? It's very simple! | 15,239 | 10 | [] |
student | sure | 15,239 | 11 | [] |
student | I said no cause SINE = opposite / hypotenuse | 15,239 | 12 | [] |
volunteer | ok so basically - it is about how angles correlate with opposite sides | 15,239 | 13 | [] |
student | and 8 is adjacent and x = hypotenuse | 15,239 | 14 | [] |
volunteer | wait actually you're right - we don't need law of sines? | 15,239 | 15 | [] |
volunteer | *! | 15,239 | 16 | [] |
volunteer | could you tell me what m<JKL is? | 15,239 | 17 | [] |
student | 58 deg | 15,239 | 18 | [] |
volunteer | close! I meant the upper angle! | 15,239 | 19 | [] |
volunteer | yk how all angles in a triangle add up 180 | 15,239 | 20 | [] |
volunteer | ? | 15,239 | 21 | [] |
student | would it something like 90 - 58 or somthn like that to find the missing angle | 15,239 | 22 | [] |
volunteer | almost! | 15,239 | 23 | [] |
volunteer | Since there 180 degrees in a triangle | 15,239 | 24 | [] |
volunteer | wait omg I'm so sry we don't need to do that lol | 15,239 | 25 | [] |
volunteer | but just for reference the other angle would 180 - (90+58)! | 15,239 | 26 | [] |
volunteer | but anyways | 15,239 | 27 | [] |
volunteer | you know how | 15,239 | 28 | [] |
volunteer | cos is adjacent over hypotenuse? | 15,239 | 29 | [] |
student | ok | 15,239 | 30 | [] |
volunteer | so we can apply that to the side | 15,239 | 31 | [] |
volunteer | do you know what cos 58 would be? | 15,239 | 32 | [] |
volunteer | in terms of x and 8? | 15,239 | 33 | [] |
volunteer | No problem if you don't - let me know! | 15,239 | 34 | [] |
student | let me solve | 15,239 | 35 | [] |
volunteer | sounds good! | 15,239 | 36 | [] |
student | so it would be Cos (58) = 8/x | 15,239 | 37 | [] |
volunteer | yesss | 15,239 | 38 | [] |
volunteer | do you have a calculator? | 15,239 | 39 | [] |
volunteer | because now that we do that | 15,239 | 40 | [] |
volunteer | we have to isolate x | 15,239 | 41 | [] |
volunteer | so since you have that equation - could you tell me what x is in terms of cos (58) and 8? | 15,239 | 42 | [] |
student | ok hold on | 15,239 | 43 | [] |
student | I got this | 15,239 | 44 | [] |
student | 15.097 | 15,239 | 45 | [] |
volunteer | yesss | 15,239 | 46 | [] |
volunteer | but also | 15,239 | 47 | [] |
volunteer | the question is asking for 2 decimal places | 15,239 | 48 | [] |
volunteer | so the number is right! but what would it be with just 2 decimal places? | 15,239 | 49 | [] |
student | ok hold on | 15,239 | 50 | [] |
student | 15.10 | 15,239 | 51 | [] |
volunteer | Awesome!!!! | 15,239 | 52 | [] |
volunteer | great job!!! | 15,239 | 53 | [] |
student | yayyy!!! | 15,239 | 54 | [] |
volunteer | do you want to move on to the next problem? | 15,239 | 55 | [] |
student | yes | 15,239 | 56 | [] |
volunteer | sounds great! | 15,239 | 57 | [] |
volunteer | ok I got it! | 15,239 | 58 | [] |
volunteer | so we can use the same method as before | 15,239 | 59 | [] |
student | ok | 15,239 | 60 | [] |
volunteer | which trig operation could we use regarding 43 degrees? | 15,239 | 61 | [] |
student | either tan or sin? | 15,239 | 62 | [] |
volunteer | yess | 15,239 | 63 | [] |
volunteer | which one do u want to use? | 15,239 | 64 | [] |
volunteer | either one is fine | 15,239 | 65 | [] |
student | idk | 15,239 | 66 | [] |
volunteer | ok well we can use tan! | 15,239 | 67 | [] |
volunteer | so that's opposite over adjacent | 15,239 | 68 | [] |
volunteer | so what would tan 43 be equal to in terms of 36 and y? | 15,239 | 69 | [] |
student | Tan(43) =36/y | 15,239 | 70 | [] |
volunteer | yess | 15,239 | 71 | [] |
volunteer | so what would y be equal to? | 15,239 | 72 | [] |
student | 38.60 and rounded two decimal place is 38.6 | 15,239 | 73 | [] |
volunteer | Right | 15,239 | 74 | [] |
volunteer | when u did ur calculation | 15,239 | 75 | [] |
volunteer | it should be 38.605 | 15,239 | 76 | [] |
volunteer | so when u round the 5 up | 15,239 | 77 | [] |
volunteer | the 0 becomes one | 15,239 | 78 | [] |
volunteer | so it would be 38.61 | 15,239 | 79 | [] |
volunteer | but great great job u still did it! | 15,239 | 80 | [] |
student | ok | 15,239 | 81 | [] |
volunteer | and now we can do the same for x | 15,239 | 82 | [] |
volunteer | we can use m<QRP which is 90 degrees | 15,239 | 83 | [] |
student | wait what | 15,239 | 84 | [] |
volunteer | or actually we can still do 43 degees | 15,239 | 85 | [] |
volunteer | degrees | 15,239 | 86 | [] |
volunteer | because we need to find x | 15,239 | 87 | [] |
volunteer | so since it includes x | 15,239 | 88 | [] |
volunteer | the hypotnuse | 15,239 | 89 | [] |
volunteer | that means that we can use either sin or cos | 15,239 | 90 | [] |
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