role stringclasses 2
values | content stringlengths 0 2.1k | session_id int64 10 21.7k | sequence_id int64 0 2.38k | annotations listlengths 0 8 |
|---|---|---|---|---|
volunteer | does that make sense? | 15,239 | 91 | [] |
student | ok then would we do cos(43) = 38.61 /x? | 15,239 | 92 | [] |
volunteer | yes! However, I would suggest doing sin 43=36/x since it is more precise since you already know those values are exact | 15,239 | 93 | [] |
volunteer | because when rounded, the answer when it comes to dividing can be a bit off, so by using the exact numbers provided, you can ensure that the answer is more precise | 15,239 | 94 | [] |
student | ok | 15,239 | 95 | [] |
student | 52.8 | 15,239 | 96 | [] |
volunteer | yess - except remember that it wants 2 decimal places! so it would be 52.79! | 15,239 | 97 | [] |
volunteer | great job!! | 15,239 | 98 | [] |
student | oh cause when I calculated it said 52.78 | 15,239 | 99 | [] |
volunteer | well when you calculate it fully, you have to look at the 3rd decimal since it can affect your answer | 15,239 | 100 | [] |
volunteer | so It was 52.786 | 15,239 | 101 | [] |
volunteer | and since 6 means rounding up | 15,239 | 102 | [] |
volunteer | then the 8 goes up by 1 | 15,239 | 103 | [] |
volunteer | so it would be 52.79 | 15,239 | 104 | [] |
volunteer | does that make sense? | 15,239 | 105 | [] |
student | yes | 15,239 | 106 | [] |
student | so x = what again | 15,239 | 107 | [] |
volunteer | x=52.79 | 15,239 | 108 | [] |
student | ok | 15,239 | 109 | [] |
student | and y = 38.61 | 15,239 | 110 | [] |
volunteer | yess | 15,239 | 111 | [] |
student | ok | 15,239 | 112 | [] |
student | I can do 1 more before my computer dies | 15,239 | 113 | [] |
volunteer | sounds good! | 15,239 | 114 | [] |
volunteer | what are the following questions? | 15,239 | 115 | [] |
student | oops | 15,239 | 116 | [] |
student | lem'me get that | 15,239 | 117 | [] |
volunteer | dw lol | 15,239 | 118 | [] |
volunteer | ok so first we can figure out m<B | 15,239 | 119 | [] |
volunteer | do you know how to find it? | 15,239 | 120 | [] |
student | uuuuuuuhh nope | 15,239 | 121 | [] |
volunteer | well like we did before, there 180 degrees in a triangle | 15,239 | 122 | [] |
volunteer | since one angle is 90 and another is 75 | 15,239 | 123 | [] |
volunteer | m<B=180 - (75+90) | 15,239 | 124 | [] |
student | got it | 15,239 | 125 | [] |
volunteer | great! do you want to move on the problem b? | 15,239 | 126 | [] |
student | m<B = 15 degrees | 15,239 | 127 | [] |
volunteer | yes!! | 15,239 | 128 | [] |
volunteer | wanna find bc now? | 15,239 | 129 | [] |
student | yea | 15,239 | 130 | [] |
volunteer | sounds good | 15,239 | 131 | [] |
volunteer | ok so we can give it a variable name | 15,239 | 132 | [] |
volunteer | BC=x | 15,239 | 133 | [] |
volunteer | now we can take the angle 75 degrees | 15,239 | 134 | [] |
student | ok | 15,239 | 135 | [] |
volunteer | and use an operation that has both its opposite and adjacent | 15,239 | 136 | [] |
student | Tangent | 15,239 | 137 | [] |
volunteer | yess | 15,239 | 138 | [] |
volunteer | so tan 75 = x/23! | 15,239 | 139 | [] |
volunteer | so what would x be? | 15,239 | 140 | [] |
student | x = 85.84 | 15,239 | 141 | [] |
volunteer | yes!!!!! | 15,239 | 142 | [] |
volunteer | and since x=BC | 15,239 | 143 | [] |
volunteer | BC=85.84!!! | 15,239 | 144 | [] |
volunteer | now we can move on to AB | 15,239 | 145 | [] |
volunteer | I'll make AB=y | 15,239 | 146 | [] |
volunteer | so we can use 75 again | 15,239 | 147 | [] |
volunteer | what operation uses adjacent and hypotnuse? | 15,239 | 148 | [] |
student | cos | 15,239 | 149 | [] |
volunteer | yess | 15,239 | 150 | [] |
volunteer | so what would your equation be? | 15,239 | 151 | [] |
student | cos (75) =23/y? | 15,239 | 152 | [] |
volunteer | yes!!! | 15,239 | 153 | [] |
student | yayyy! | 15,239 | 154 | [] |
volunteer | so what would y be? | 15,239 | 155 | [] |
student | y = 88.87 | 15,239 | 156 | [] |
volunteer | YESSSS great job!!!! | 15,239 | 157 | [] |
volunteer | and since y=AB | 15,239 | 158 | [] |
volunteer | AB=88.87 | 15,239 | 159 | [] |
volunteer | congratulations Pat did all of them!! | 15,239 | 160 | [
{
"pii_type": "PERSON",
"surrogate": "Pat",
"start": 16,
"end": 19
}
] |
student | thank you soo much!! | 15,239 | 161 | [] |
volunteer | no problem I'm glad I could help!! | 15,239 | 162 | [] |
volunteer | make sure to charge your computer haha | 15,239 | 163 | [] |
student | I will! | 15,239 | 164 | [] |
student | byyee!! | 15,239 | 165 | [] |
volunteer | bye!! | 15,239 | 166 | [] |
volunteer | hey | 15,295 | 0 | [] |
volunteer | what do u need help with | 15,295 | 1 | [] |
student | Hi! I need a bit help with this | 15,295 | 2 | [] |
volunteer | ok | 15,295 | 3 | [] |
volunteer | so first of all do u know how to rewrite a negative exponent | 15,295 | 4 | [] |
volunteer | for example like 2^-1 | 15,295 | 5 | [] |
student | mhm | 15,295 | 6 | [] |
student | so for a | 15,295 | 7 | [] |
student | its all diff variables | 15,295 | 8 | [] |
volunteer | yea | 15,295 | 9 | [] |
volunteer | we can work through it together in steps | 15,295 | 10 | [] |
student | oh so i do | 15,295 | 11 | [] |
volunteer | im gonna write it below the screenshot | 15,295 | 12 | [] |
student | -4 times 2 | 15,295 | 13 | [] |
student | 6 times 2 | 15,295 | 14 | [] |
student | 3 times 2? | 15,295 | 15 | [] |
volunteer | yea | 15,295 | 16 | [] |
volunteer | don't forget the coefficient though | 15,295 | 17 | [] |
student | mhm | 15,295 | 18 | [] |
volunteer | do you know the next step after this | 15,295 | 19 | [] |
student | i solved it | 15,295 | 20 | [] |
student | give me one sec Emily writing on paper | 15,295 | 21 | [
{
"pii_type": "PERSON",
"surrogate": "Emily",
"start": 16,
"end": 21
}
] |
volunteer | ok | 15,295 | 22 | [] |
student | ok next one | 15,295 | 23 | [] |
Subsets and Splits
No community queries yet
The top public SQL queries from the community will appear here once available.