role stringclasses 2
values | content stringlengths 0 2.1k | session_id int64 10 21.7k | sequence_id int64 0 2.38k | annotations listlengths 0 8 |
|---|---|---|---|---|
volunteer | bye. | 15,468 | 72 | [] |
student | bye | 15,468 | 73 | [] |
volunteer | hello! | 15,655 | 0 | [] |
student | hi, I am having problems with my rationals test review | 15,655 | 1 | [] |
volunteer | okay great! can you give me an example? | 15,655 | 2 | [] |
volunteer | so you have to simplify? | 15,655 | 3 | [] |
student | The question for that equation is what is the EBA? | 15,655 | 4 | [] |
volunteer | im sorry, can you define EBA? | 15,655 | 5 | [] |
student | EBA = end behavior asymptote | 15,655 | 6 | [] |
volunteer | ahh i see | 15,655 | 7 | [] |
volunteer | so that basically means the horizontal asymptote | 15,655 | 8 | [] |
student | Yes, that is the umbrella that the HA is under | 15,655 | 9 | [] |
volunteer | okay greay | 15,655 | 10 | [] |
volunteer | great* | 15,655 | 11 | [] |
volunteer | so let me teach you a little trick | 15,655 | 12 | [] |
volunteer | look at the highest degree of numerator and denominator | 15,655 | 13 | [] |
volunteer | wait do you want to factor or find the HA first? | 15,655 | 14 | [] |
student | I was taught to factor then find HA | 15,655 | 15 | [] |
volunteer | okay, lets factor first | 15,655 | 16 | [] |
volunteer | so we would objectively want to cancel out the numerator and the denominator | 15,655 | 17 | [] |
volunteer | are you familiar with the ac method? | 15,655 | 18 | [] |
student | Yes, and the A and M method | 15,655 | 19 | [] |
volunteer | okay, i like the ac method so lets do that | 15,655 | 20 | [] |
volunteer | so we are left with 3x+1 | 15,655 | 21 | [] |
student | I just don't know where to go from there | 15,655 | 22 | [] |
volunteer | so think about it on a graph | 15,655 | 23 | [] |
volunteer | its just a regular line that goes up | 15,655 | 24 | [] |
volunteer | as it goes to positive infinity, its going to go up up up | 15,655 | 25 | [] |
volunteer | and goes down when going to negative infinity | 15,655 | 26 | [] |
student | Yes, how did you get the graph from your factored form? | 15,655 | 27 | [] |
volunteer | well the graph i just did is 3x+1 | 15,655 | 28 | [] |
volunteer | because the (x-5) cancelled out on the numerator and denominator | 15,655 | 29 | [] |
student | Ahh, those are your zeros? | 15,655 | 30 | [] |
student | That you graphed? | 15,655 | 31 | [] |
volunteer | no | 15,655 | 32 | [] |
volunteer | its the same thing as f(x) but there is a hole at x=5 | 15,655 | 33 | [] |
volunteer | if you cancel out the factors, then youre left with the basic graph (3x+1) | 15,655 | 34 | [] |
volunteer | okay, lets take a step back | 15,655 | 35 | [] |
volunteer | did you understand how i did the ac method, right? | 15,655 | 36 | [] |
student | sort of | 15,655 | 37 | [] |
volunteer | what part is a bit confusing? | 15,655 | 38 | [] |
student | how you got to -15 | 15,655 | 39 | [] |
volunteer | so the standard form of a quadratic is: | 15,655 | 40 | [] |
volunteer | ax^2+bx+c | 15,655 | 41 | [] |
student | ok | 15,655 | 42 | [] |
volunteer | a in the numerator is 3 and c is -5 | 15,655 | 43 | [] |
volunteer | so a times c (ac) is -15 | 15,655 | 44 | [] |
student | ok, that makes a lot more sense. I may have forgotten how to do the ac method . that was s along time ago | 15,655 | 45 | [] |
volunteer | yeah,haha me too | 15,655 | 46 | [] |
volunteer | but practice just engraved it into my brain | 15,655 | 47 | [] |
volunteer | what class is this for again? | 15,655 | 48 | [] |
student | pre-cal | 15,655 | 49 | [] |
volunteer | okay cool | 15,655 | 50 | [] |
volunteer | so lets go back to the problem | 15,655 | 51 | [] |
student | ok | 15,655 | 52 | [] |
volunteer | so the factors of -15 that make up -14 are 1 and -15 | 15,655 | 53 | [] |
volunteer | because you add the factors together to get b | 15,655 | 54 | [] |
volunteer | -15+1=-14 | 15,655 | 55 | [] |
student | yes, that is very obvious now | 15,655 | 56 | [] |
volunteer | haha, okay so then i expanded the original polynomial into 3x^2-15x+x-5 | 15,655 | 57 | [] |
volunteer | i think its best to group the biggest number with Sarah because it always works | 15,655 | 58 | [
{
"pii_type": "PERSON",
"surrogate": "Sarah",
"start": 50,
"end": 55
}
] |
volunteer | so thats why 3x^2 and -15x are togehter | 15,655 | 59 | [] |
student | ok | 15,655 | 60 | [] |
volunteer | what is the largest common factor between those two terms? | 15,655 | 61 | [] |
student | 5 | 15,655 | 62 | [] |
volunteer | no, 5 is not a factor of 3x^2 | 15,655 | 63 | [] |
student | 3x | 15,655 | 64 | [] |
volunteer | yes! | 15,655 | 65 | [] |
volunteer | so then you group it as i did on the board | 15,655 | 66 | [] |
volunteer | so it looks like 3x(x-5) | 15,655 | 67 | [] |
student | and then you devid | 15,655 | 68 | [] |
volunteer | not yet | 15,655 | 69 | [] |
volunteer | because you need to group it | 15,655 | 70 | [] |
volunteer | since we already have (x-5) of the other side, we can add what is multiplying (x-5) together to make it a term itself | 15,655 | 71 | [] |
volunteer | so 3x(x-5) +1(x-5) | 15,655 | 72 | [] |
volunteer | we can just add the outsides | 15,655 | 73 | [] |
student | ok | 15,655 | 74 | [] |
volunteer | 3x+1 | 15,655 | 75 | [] |
volunteer | yes | 15,655 | 76 | [] |
volunteer | and thenn you can divide | 15,655 | 77 | [] |
volunteer | (3x+1)(x-5)/(x-5) | 15,655 | 78 | [] |
volunteer | is just 3x+1 | 15,655 | 79 | [] |
student | ohhh, then you set 3x+1 equal to 0? | 15,655 | 80 | [] |
volunteer | you do not need to set anything equal to zero | 15,655 | 81 | [] |
student | well how did you get the point on the graph? | 15,655 | 82 | [] |
volunteer | oh for the graph? i guess so | 15,655 | 83 | [] |
volunteer | but the graph isnt too revelant, it was just to help you visualize | 15,655 | 84 | [] |
volunteer | but just think about y=3x+1 | 15,655 | 85 | [] |
volunteer | and then thats the graph | 15,655 | 86 | [] |
student | ok, I understand | 15,655 | 87 | [] |
volunteer | okay, so using the graph to help you visualize, what are the end behaviors? | 15,655 | 88 | [] |
student | down, up | 15,655 | 89 | [] |
volunteer | could you explain | 15,655 | 90 | [] |
student | that would be the end behavior? | 15,655 | 91 | [] |
volunteer | yes! | 15,655 | 92 | [] |
volunteer | okay | 15,655 | 93 | [] |
volunteer | do you wanna see an easier way? | 15,655 | 94 | [] |
student | yes!!!!!! | 15,655 | 95 | [] |
volunteer | okay | 15,655 | 96 | [] |
volunteer | can you erase the part under the function | 15,655 | 97 | [] |
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