role stringclasses 2
values | content stringlengths 0 2.1k | session_id int64 10 21.7k | sequence_id int64 0 2.38k | annotations listlengths 0 8 |
|---|---|---|---|---|
student | It’s called trigonometric functions of acute angles | 17,773 | 4 | [] |
student | That’s the topic name | 17,773 | 5 | [] |
volunteer | ok. Can you show me a problem that you are working on? | 17,773 | 6 | [] |
student | Can you teach me topic wise my school just started | 17,773 | 7 | [] |
volunteer | What have you learned so far? | 17,773 | 8 | [] |
student | Supplementary and complementary angles standard position quadrant of an angle | 17,773 | 9 | [] |
volunteer | Sorry, I don't have a lesson planned for this. As a tutor, I usually help students with their homework. It might be better if you made another request. Sorry. | 17,773 | 10 | [] |
student | I can get back to you tomorrow with the homework | 17,773 | 11 | [] |
volunteer | Sounds good. | 17,773 | 12 | [] |
volunteer | Have a good evening. | 17,773 | 13 | [] |
student | You too thanks | 17,773 | 14 | [] |
volunteer | you are welcome. | 17,773 | 15 | [] |
volunteer | bye | 17,773 | 16 | [] |
student | hi! how are you? | 17,782 | 0 | [] |
volunteer | Liam! | 17,782 | 1 | [
{
"pii_type": "PERSON",
"surrogate": "Liam",
"start": 0,
"end": 4
}
] |
volunteer | good how r u? | 17,782 | 2 | [] |
student | I'm good too | 17,782 | 3 | [] |
volunteer | what do u need help with? | 17,782 | 4 | [] |
student | I was wondering if you could help me with an algebra assignment | 17,782 | 5 | [] |
volunteer | yea sure | 17,782 | 6 | [] |
volunteer | do u know how long it will take | 17,782 | 7 | [] |
volunteer | aprox | 17,782 | 8 | [] |
student | I only have one question I need help with | 17,782 | 9 | [] |
volunteer | oh ok | 17,782 | 10 | [] |
volunteer | what is it? | 17,782 | 11 | [] |
volunteer | can u make it a ittle bigger? | 17,782 | 12 | [] |
volunteer | thanks | 17,782 | 13 | [] |
volunteer | do u know what to do to find x-intercepts? | 17,782 | 14 | [] |
student | she didn't really explain it well when I was in class | 17,782 | 15 | [] |
volunteer | set y=0 | 17,782 | 16 | [] |
volunteer | or in this case f(x) | 17,782 | 17 | [] |
student | ok | 17,782 | 18 | [] |
volunteer | so u can solve for x | 17,782 | 19 | [] |
volunteer | ill write it | 17,782 | 20 | [] |
volunteer | can u see that? | 17,782 | 21 | [] |
student | yes | 17,782 | 22 | [] |
volunteer | can u solve for x? | 17,782 | 23 | [] |
student | k | 17,782 | 24 | [] |
student | 7/3 and -3 | 17,782 | 25 | [] |
volunteer | yes!! | 17,782 | 26 | [] |
volunteer | so thats ur answer for A B and C | 17,782 | 27 | [] |
volunteer | does it make sense? | 17,782 | 28 | [] |
student | yes | 17,782 | 29 | [] |
volunteer | do u want to try doing D by urself? | 17,782 | 30 | [] |
volunteer | or do u need help? | 17,782 | 31 | [] |
student | -7? | 17,782 | 32 | [] |
volunteer | Yes!! | 17,782 | 33 | [] |
student | :) | 17,782 | 34 | [] |
volunteer | u got it!! | 17,782 | 35 | [] |
student | thank you! | 17,782 | 36 | [] |
volunteer | does it make sense tho? | 17,782 | 37 | [] |
student | yes | 17,782 | 38 | [] |
volunteer | ok :) | 17,782 | 39 | [] |
student | I hope you have a good night | 17,782 | 40 | [] |
volunteer | u too | 17,782 | 41 | [] |
student | hi could you help me out with this? | 17,825 | 0 | [] |
volunteer | Hi How are you? | 17,825 | 1 | [] |
student | good | 17,825 | 2 | [] |
volunteer | Ok. Let's see your integral. | 17,825 | 3 | [] |
student | this is all ive got so far | 17,825 | 4 | [] |
volunteer | Ok. Give me a couple of minutes to think on this. | 17,825 | 5 | [] |
student | ok | 17,825 | 6 | [] |
volunteer | It's clear that the base can be represented by r^2 + y^2, since it is a circle. Do you agree? | 17,825 | 7 | [] |
student | yea | 17,825 | 8 | [] |
volunteer | Now each "square" It seems to me, has a side equal to 2r. What do you think about that? | 17,825 | 9 | [] |
student | yea i agree | 17,825 | 10 | [] |
volunteer | Ok. So I think we need another relation ship to set up the integral. Any thoughts? | 17,825 | 11 | [] |
student | that area of the squares is s^2 | 17,825 | 12 | [] |
volunteer | So. In this case each "square" has an area of 4r^2. | 17,825 | 13 | [] |
student | why | 17,825 | 14 | [] |
volunteer | Well, if we agree that each side of the square is 2r, then the area of a representative square would be (2r)(2r) = 4r^2 | 17,825 | 15 | [] |
student | ohh yes ok | 17,825 | 16 | [] |
volunteer | Now. We already know that r^2 = x^2 + y^2 | 17,825 | 17 | [] |
volunteer | What we need is some relationship between x and y so that we can integrate over one variable. | 17,825 | 18 | [] |
volunteer | Give me a couple of minutes to ponder that please, | 17,825 | 19 | [] |
student | ok | 17,825 | 20 | [] |
volunteer | Alright. I think we were close. Just a bit off. | 17,825 | 21 | [] |
volunteer | So the circle is x^2 + y^2 = r^2 | 17,825 | 22 | [] |
volunteer | But the side of each square is really 2y, not 2r. r is a constant, so that doesn't work. Do you follow? | 17,825 | 23 | [] |
student | ohh yea i see | 17,825 | 24 | [] |
student | so the vertical y values change | 17,825 | 25 | [] |
volunteer | Exactly. | 17,825 | 26 | [] |
volunteer | So let's set up our integral to be a(x) = (2y)^2 = 4y^2 dx. | 17,825 | 27 | [] |
volunteer | But y^2 = (r^2 - x^2) | 17,825 | 28 | [] |
volunteer | So. You get Int(r^2 - x^2) dx over the limits. | 17,825 | 29 | [] |
volunteer | Would you write the integral on the whiteboard please? | 17,825 | 30 | [] |
student | ok | 17,825 | 31 | [] |
student | like this? | 17,825 | 32 | [] |
volunteer | Excellent. Let's talk about the limits now. | 17,825 | 33 | [] |
student | im still kind of confused why we got 2y again where did the 2 come from | 17,825 | 34 | [] |
volunteer | Ok let's back up. | 17,825 | 35 | [] |
volunteer | Take a look at the diagram again and focus on the squares. | 17,825 | 36 | [] |
student | ok | 17,825 | 37 | [] |
volunteer | Each one varies as shown by the vertical slices in the diagram. | 17,825 | 38 | [] |
student | yea | 17,825 | 39 | [] |
volunteer | Now. If you focus on a typical square, especially the one at the center, you will see that it is the same as the diameter of the circle. That one is 2r for each side. | 17,825 | 40 | [] |
volunteer | The other ones are smaller, as you look at slices off the center. | 17,825 | 41 | [] |
volunteer | The relationship to determine the length of the other ones is (r^2 - y^2)^(1/2). | 17,825 | 42 | [] |
volunteer | Is that making any sense? | 17,825 | 43 | [] |
student | yes so that's = x? | 17,825 | 44 | [] |
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