Split (1)

train · 116k rows

role stringclasses 2 values	content stringlengths 0 2.1k	session_id int64 10 21.7k	sequence_id int64 0 2.38k	annotations listlengths 0 8
volunteer	over the adjacent	8,595	161	[]
student	Mhm	8,595	162	[]
volunteer	and the adjacent is gonna 5000. We'll keep it in feet.	8,595	163	[]
volunteer	And the opposite is always gonna 1000 + 600T.	8,595	164	[]
volunteer	Oops, no, I have to reset.	8,595	165	[]
volunteer	Excuse me here, let me see if I can do it again.	8,595	166	[]
volunteer	No	8,595	167	[]
volunteer	I'm sorry	8,595	168	[]
volunteer	One more time with feeling	8,595	169	[]
student	So	8,595	170	[]
volunteer	Let me lengthen this	8,595	171	[]
volunteer	1000	8,595	172	[]
volunteer	I can't write very well, 5000.	8,595	173	[]
volunteer	OK	8,595	174	[]
student	OK	8,595	175	[]
volunteer	So if we think about it	8,595	176	[]
volunteer	iste as the number of seconds that go by. We started at 0.	8,595	177	[]
volunteer	then the tangent of the angle is going to be 15%, right?	8,595	178	[]
volunteer	1000 /.	8,595	179	[]
volunteer	5000	8,595	180	[]
student	Yeah	8,595	181	[]
volunteer	As, as each second picks by.	8,595	182	[]
volunteer	the the tangent of the angle is gonna get bigger and bigger.	8,595	183	[]
student	Mm	8,595	184	[]
volunteer	um after 1 2nd, it'll be 1600 over	8,595	185	[]
volunteer	5000. 2 seconds, it'll be	8,595	186	[]
volunteer	2200	8,595	187	[]
volunteer	/5000 and on up, right?	8,595	188	[]
student	Mm	8,595	189	[]
volunteer	Does that make sense to you	8,595	190	[]
student	You mean?	8,595	191	[]
volunteer	I'm sorry	8,595	192	[]
student	You mean? What, what did you mean?	8,595	193	[]
volunteer	OK	8,595	194	[]
volunteer	So let's, let's just look at this expression.	8,595	195	[]
volunteer	tangent of the angle = . I, I'm sorry about my writing. It's 1000 + 600T / 5000.	8,595	196	[]
volunteer	So at time equals 0	8,595	197	[]
student	Mm.	8,595	198	[]
volunteer	if T is equal to 0, 600 times 0 is 0, and we would end up 1000 /, 5000, excuse me.	8,595	199	[]
student	Mhm	8,595	200	[]
volunteer	If it at time T equals 1 2nd, we would be 1600 /	8,595	201	[]
volunteer	5000, right?	8,595	202	[]
student	Yeah	8,595	203	[]
volunteer	At time T equals 2 seconds, we would be at	8,595	204	[]
volunteer	2200 / 5000, and so forth.	8,595	205	[]
student	Yup	8,595	206	[]
volunteer	So we have a, we now have an expression, if we've done this correctly	8,595	207	[]
volunteer	of the tangent of the angle	8,595	208	[]
volunteer	in terms of tea	8,595	209	[]
volunteer	And that's pretty good because now we can use our	8,595	210	[]
volunteer	knowledge of derivatives	8,595	211	[]
volunteer	to find the theta DT.	8,595	212	[]
student	All right, real quick, can we, can I ask, wait, why, why is it plus and not like times?	8,595	213	[]
volunteer	It is time	8,595	214	[]
volunteer	but we're starting out in	8,595	215	[]
student	Don't 1000 + 600.	8,595	216	[]
volunteer	Yeah, I'm sorry about my writing. I really apologize.	8,595	217	[]
volunteer	It's a 1000 + 600T.	8,595	218	[]
volunteer	Can you see that or	8,595	219	[]
student	No, I can see that I'm just saying like why is it that way?	8,595	220	[]
volunteer	OK	8,595	221	[]
volunteer	So think about that angle	8,595	222	[]
student	Mhm.	8,595	223	[]
volunteer	If we're just starting out	8,595	224	[]
volunteer	do you agree that the angle, the tangent of the angle is 1000 / 5000.	8,595	225	[]
student	Yes, I agree	8,595	226	[]
volunteer	OK.	8,595	227	[]
volunteer	If you, if you plug in T equals 0 into the formula, we would get 600 times 0, right?	8,595	228	[]
student	Yeah	8,595	229	[]
volunteer	And we would end up 1000 / 5000 when we're starting.	8,595	230	[]
volunteer	After 1 2nd	8,595	231	[]
volunteer	if we just choose an arbitrary value 1 2nd.	8,595	232	[]
volunteer	what would the numerator be?	8,595	233	[]
volunteer	if I plug in 1 2nd	8,595	234	[]
student	led to 1600	8,595	235	[]
volunteer	adding to 1000, yes, 1000 + 600 times 1 2nd, right?	8,595	236	[]
student	Yeah	8,595	237	[]
volunteer	So we would end up 1600, correct?	8,595	238	[]
student	Yeah, I'll get that part. I'm just saying like the 1000 + 600. Like why is 1000 + 600 and now 1000 times 600.	8,595	239	[]
volunteer	OK.	8,595	240	[]
volunteer	So that	8,595	241	[]
volunteer	we're, we're gonna	8,595	242	[]
student	or minus 600	8,595	243	[]
volunteer	we're, we're, the rocket is going up.	8,595	244	[]
student	Mhm	8,595	245	[]
volunteer	We have to multiply by the 6 6001 times the tea, if that helps clear that up. So,	8,595	246	[]
student	Yeah, that part is clear	8,595	247	[]
volunteer	OK.	8,595	248	[]
volunteer	So	8,595	249	[]
volunteer	if you think about where the rocket is vertically.	8,595	250	[]
volunteer	We can't multiply 600T. It's starting out 1000 ft.	8,595	251	[]
student	Mm	8,595	252	[]
volunteer	So we always just start out 1000 ft.	8,595	253	[]
student	Mhm	8,595	254	[]
volunteer	and after what, after 1 2nd for for example, we will be 1600 ft. Do you agree with that?	8,595	255	[]
student	Right	8,595	256	[]
volunteer	and the way I got that was after 1 2nd	8,595	257	[]
volunteer	the velocity 600 ft per second.	8,595	258	[]
volunteer	times the time	8,595	259	[]
volunteer	is 1 2nd	8,595	260	[]

Subsets and Splits

No community queries yet

The top public SQL queries from the community will appear here once available.