role stringclasses 2
values | content stringlengths 0 2.1k | session_id int64 10 21.7k | sequence_id int64 0 2.38k | annotations listlengths 0 8 |
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volunteer | what we have is we're saying sequin squared theta d theta dt. | 8,595 | 361 | [] |
volunteer | equals | 8,595 | 362 | [] |
volunteer | 6/50 | 8,595 | 363 | [] |
student | Mhm | 8,595 | 364 | [] |
volunteer | right? | 8,595 | 365 | [] |
volunteer | All right | 8,595 | 366 | [] |
student | Mhm | 8,595 | 367 | [] |
volunteer | Um | 8,595 | 368 | [] |
volunteer | now | 8,595 | 369 | [] |
volunteer | the question is, how could, if we solve for the theta dT, which is what they're asking for in the problem. | 8,595 | 370 | [] |
student | Yeah | 8,595 | 371 | [] |
volunteer | we | 8,595 | 372 | [] |
volunteer | um, we, we would take 6 | 8,595 | 373 | [] |
volunteer | um | 8,595 | 374 | [] |
volunteer | so hold on a minute, let me think about this. | 8,595 | 375 | [] |
volunteer | So we still have to divide by | 8,595 | 376 | [] |
volunteer | we saw for uh defeated DP. | 8,595 | 377 | [] |
volunteer | um, seeking to | 8,595 | 378 | [] |
volunteer | one over cosign, right | 8,595 | 379 | [] |
student | Mhm. | 8,595 | 380 | [] |
volunteer | So we would have | 8,595 | 381 | [] |
volunteer | um | 8,595 | 382 | [] |
volunteer | so now the question becomes, how do I find out what sequin squared theta is. | 8,595 | 383 | [] |
volunteer | What | 8,595 | 384 | [] |
student | So we can't let our um answer with chicken squirt. Oh no, because you want the DDT on its own. | 8,595 | 385 | [] |
volunteer | right, exactly | 8,595 | 386 | [] |
student | Right. | 8,595 | 387 | [] |
volunteer | So now the the problem we're facing is what is sequin squared beta. | 8,595 | 388 | [] |
volunteer | Um | 8,595 | 389 | [] |
student | Yeah | 8,595 | 390 | [] |
volunteer | it, yeah. | 8,595 | 391 | [] |
volunteer | well, it | 8,595 | 392 | [] |
volunteer | skin square theta times def theta dt is 6/50. | 8,595 | 393 | [] |
student | I | 8,595 | 394 | [] |
volunteer | Um. | 8,595 | 395 | [] |
volunteer | so I've, now we need to think about what sequin squared theta, if there's anything we can do to get that to some kind of | 8,595 | 396 | [] |
volunteer | expression | 8,595 | 397 | [] |
volunteer | Um | 8,595 | 398 | [] |
volunteer | so, let me think here a minute. | 8,595 | 399 | [] |
student | Yeah. | 8,595 | 400 | [] |
volunteer | So this may be where we might have to | 8,595 | 401 | [] |
volunteer | use a little | 8,595 | 402 | [] |
volunteer | Pythagorean theorem. So, | 8,595 | 403 | [] |
volunteer | take is | 8,595 | 404 | [] |
volunteer | one over cosine, right? | 8,595 | 405 | [] |
student | Yeah | 8,595 | 406 | [] |
volunteer | So | 8,595 | 407 | [] |
volunteer | the cosine squared of | 8,595 | 408 | [] |
volunteer | So if we saw for the fatedta DT. | 8,595 | 409 | [] |
volunteer | equals 6/50. | 8,595 | 410 | [] |
volunteer | times | 8,595 | 411 | [] |
volunteer | cosine square | 8,595 | 412 | [] |
volunteer | theta | 8,595 | 413 | [] |
student | Wait, | 8,595 | 414 | [] |
student | Well, so what did you do on the left side? Did you divide by 2 square? | 8,595 | 415 | [] |
volunteer | Right, exactly right. | 8,595 | 416 | [] |
student | So you divide it by, OK, you divide a second square and you divide it on the other side. | 8,595 | 417 | [] |
volunteer | So if I divide both sides by seek and squared. | 8,595 | 418 | [] |
student | Yeah | 8,595 | 419 | [] |
volunteer | I get | 8,595 | 420 | [] |
volunteer | the theta ET equals 6/50 times the cosine squared of theta. | 8,595 | 421 | [] |
volunteer | right? | 8,595 | 422 | [] |
volunteer | If I haven't made a mistake | 8,595 | 423 | [] |
volunteer | um | 8,595 | 424 | [] |
student | Well, let me think about it for a second. | 8,595 | 425 | [] |
volunteer | Sure, let me think as well because we need, we need to make sure. | 8,595 | 426 | [] |
student | Yeah, cause 6 or 50 divided by 1 over cosine is um | 8,595 | 427 | [] |
student | 5000 times co-signed over 1. | 8,595 | 428 | [] |
student | So it's basically 6500 co-sign. | 8,595 | 429 | [] |
volunteer | co-sign | 8,595 | 430 | [] |
student | Cosine squad | 8,595 | 431 | [] |
volunteer | right | 8,595 | 432 | [] |
volunteer | So now this | 8,595 | 433 | [] |
student | So, yeah. | 8,595 | 434 | [] |
volunteer | is, this is starting, starting to come back to what you were talking about. Do I need to | 8,595 | 435 | [] |
volunteer | I, do I, what, how am I gonna figure out how, what the cosine square | 8,595 | 436 | [] |
volunteer | is doing | 8,595 | 437 | [] |
volunteer | Um | 8,595 | 438 | [] |
volunteer | so let me think as well for a minute here. Divative tangent sequin square. | 8,595 | 439 | [] |
volunteer | faded deeply | 8,595 | 440 | [] |
student | But before you think for a second, I just wanna know why are we like changing it to one of our cos I, we can't just keep that again square. | 8,595 | 441 | [] |
volunteer | Well, if you want to, you could use 5000 divided by sequin squares, right? | 8,595 | 442 | [] |
student | Oh, but it's just like the vision, right? That's why we don't want that. | 8,595 | 443 | [] |
volunteer | Right, you, if we divide both sides by sequin squared theta. | 8,595 | 444 | [] |
volunteer | then we get defeta DT on the left. | 8,595 | 445 | [] |
volunteer | "6/50" | 8,595 | 446 | [] |
volunteer | divided by sequin square | 8,595 | 447 | [] |
volunteer | which should be cosine square. | 8,595 | 448 | [] |
student | OK | 8,595 | 449 | [] |
volunteer | Um | 8,595 | 450 | [] |
volunteer | Correct me if I'm wrong | 8,595 | 451 | [] |
volunteer | 1 over cosigners seekin, right? | 8,595 | 452 | [] |
volunteer | Sometimes I get that | 8,595 | 453 | [] |
student | Yeah, it's. | 8,595 | 454 | [] |
volunteer | All right | 8,595 | 455 | [] |
student | it is. | 8,595 | 456 | [] |
volunteer | Um | 8,595 | 457 | [] |
volunteer | so we, we have a problem still because we don't know what cosine square to theta is as a function of time. | 8,595 | 458 | [] |
volunteer | And | 8,595 | 459 | [] |
volunteer | it would be nice | 8,595 | 460 | [] |
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