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http://www.123rf.com/stock-photo/kiwi.html
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math
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s3://commoncrawl/crawl-data/CC-MAIN-2016-44/segments/1476988718866.34/warc/CC-MAIN-20161020183838-00432-ip-10-171-6-4.ec2.internal.warc.gz
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CC-MAIN-2016-44
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https://qazdo.com/english-test-class-12/question-1-mark-the-letter-a-b-c-or-d-on-your-answer-sheet-to-indicate-the-undelined-part-that-needs-correction-in-each-of-the-following-questions-the-british-national-anthem-calling-go
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math
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Question 1: Mark the letter A, B, C, or D on your answer sheet to indicate the undelined part that needs correction in each of the following questions: The British national anthem, calling “God Save the Queen”, was a traditional song in the 18th century.
Explanation: Explanation: calling → called. This is a reduced passive structure
Question 15. Answer
Explanation: The word employed is not suitable in meaning, it must mean “unemployment status, number of unemployed people”. In the above Question, we need a noun for “unemployed” so we have to change it to unemployed.
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CC-MAIN-2023-50
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https://ece4uplp.com/digital-communications-quiz-unit-3/
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math
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Digital Communications Unit-3 Quiz with Solutions
- The number of Parity check bits in an (n, k) Linear Block codes are ( b ) a.n b. (n-k) c. (n+k) d. k
- The Hamming Weight of the following code words 10011101 & 00111100 is ( c ) 2M. a. None of these b. 4, 5 c.5, 4 d.3,4
- A cyclic code can be generated using———————— and A block can be generated using——————-.( c ) a.Generator matrix & Generator polynomial. b.Generator matrix & Generator matrix. c.Generator polynomial & Generator matrix. d.None of the above.
- The rate of a Block code is the ratio of( c ) a.Message length to Block length. b.Block length to message length. c.Message weight to Block length. d.None of the mentioned.
- The syndrome in LBC is calculated using , where Y represents received code word ( a ) 2M a. S= Y HT b. S = YH c. S= YT H d. S= YT HT
- A non-Zero value of Syndrome in a Block code represents ( b ) 2M. a.No error during transmission. b.An error occurred during transmission. c.Both a and b d.None of the above.
- The transmitted code word(X) in an LBC can be obtained from received code word( Y) by using the equation ( a ), where E represents error vector. a. X= E + Y b. X = X.Y c. X= E.Y d. X= X/Y
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CC-MAIN-2023-14
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http://heathersmithjones.com/journal/2009/4/9/lightening-up-day-4.html
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math
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good things about today }
} I had an interesting dream about my work. I may share it later at habit. I am really enjoying guest posting at habit this month. The word 'enjoying' is an understatement.
} Marichelle selected one of my pieces to be part of Etsy's Shop Live taking place tonight at 7pm. est. Find out about this 30 minute sale here. Thanks Marichelle!
} I feel like making bread today. Or perhaps I should just wait until the weekend and make more cinnamon rolls.
} I think it's going to be a good mail day. I ordered something special from here. I like supporting friends and their work when I can. I am thankful too to have wonderful friends who have already supported me.
What's one good thing about your day?
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s3://commoncrawl/crawl-data/CC-MAIN-2019-30/segments/1563195529007.88/warc/CC-MAIN-20190723064353-20190723090353-00059.warc.gz
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CC-MAIN-2019-30
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https://www.jagranjosh.com/articles/formula-for-escape-velocity-1624514692-1
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math
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In Physics, Escape Velocity is the minimum velocity that is sufficient for a body to escape from the gravitational pull of a planet. The Escape Velocity of the same objects might be different on different planets & moons.
The Escape Velocity of an object on the earth is greater than the escape velocity of the same object on the moon.
⇒ The Escape Velocity or Escape Speed of an object on the Earth is around 11.2 km/s.
⇒ The Escape Velocity of an object on the Moon is around 2.3 km/s.
Formula For Escape Velocity (Earth):
vminimum = (2GME/RE)½
vminimum: is the minimum speed required for an object to reach infinity (i.e. escape from the earth).
G: Universal Gravitational Constant (Value of G = 6.67 × 10-11 Newtons kg-2 m2)
ME: Mass of the Earth
RE: Radius of the Earth
Another Formula For Escape Velocity (Earth):
vminimum = (2gRE)1/2
g: Acceleration due to gravity
Rest symbols have their usual meaning.
Some questions on Escape Velocity:
Question: What is the SI unit of Escape Speed?
Answer: The Escape Velocity or Escape Speed of an object on the Earth is around 11.2 km/s.
Question: Determine the escape velocity of a planet if its radius is 7000 Km and mass is 107 kg.
We know that vminimum = (2GM/R)½
G = 6.67 × 10-11 Newtons kg-2 m2
M = 107 kg.
R = 7000 km = 7000 x 1000 = 7 x 106.
By putting these values in the formula you can calculate the Escape Velocity of the object.
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CC-MAIN-2021-43
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https://www.softmath.com/math-com-calculator/factoring-expressions/operations-with-radical.html
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math
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CC-MAIN-2023-50
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https://www.math.harvard.edu/event/mikhlin-type-fourier-multipliers-on-free-groups-and-free-products-of-von-neumann-algebras-2-2-3-2-3-2-2-2-2-2-2-2-2-2-2-2-2-3-2-2-2-2-2-2-2/
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math
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Invariant differential forms, graph complexes, and Feynman integrals
MATHEMATICAL PICTURE LANGUAGE
Francis Brown - All Souls College, Oxford University
The commutative graph complex, defined by contracting edges in graphs, was introduced by Kontsevich in 1993. Recently, Chan-Galatius-Payne have shown that its cohomology can be identified with a piece of the cohomology of moduli spaces of curves, and Willwacher showed that graph cohomology in degree zero it is related to the Grothendieck-Teichmuller Lie algebra. Nevertheless, the cohomology of the graph complex remains mysterious, and little is known explicitly.
In this talk I will explain how to use invariant trace forms to construct differential forms on a moduli space of metric graphs. By integrating these forms, one can canonically assign integrals to graphs, which are very closely related to Feynman integrals in perturbative quantum field theory, but have the property that they always converge. A Stokes formula enables us to deduce some information about the cohomology of the graph complex, and leads to new predictions about its structure, and its relation to physics.
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https://radar.inria.fr/report/2012/mc2/uid104.html
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math
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Section: New Results
Newtonian fluid flows simulations and their analysis
Simulations of water distribution systems :Water losses may constitute a large amount of the distributed total water volume throughout water distribution systems. Here, a new model method is proposed that intends to minimize the total water volume distributed through leakage reduction. Our group has worked on the derivation of advection-reaction-diffusion type equations with an explicit relationship between the local pressure and the leakage rate. An original splitting technique to solve this type of hydraulic problem was then achieved. This technique allows pressure-dependent leakage to be taken into account, whereas in most models leakage is assumed to be uniform along a pipe. Finally, a constrained optimization problem was formulated for leakage reduction in WDS. The control variable had the mean of a local head loss and is considered in the Boundary Conditions to avoid dealing with discontinuities in the governing equations. The objective function to minimize was a regularization of the total water volume distributed. Specific operational constraints were added to ensure enough pressure at consumption points. The direct solution for this minimization problem was sought with a Gradient type method. The leakage reduction was proven to be significant in a case study. The percentage of leakage reduced from 24% to 10% in the linear relationship between pressure and leakage flow rate. With other leakage exponents, the same rate of reduction was achieved . The method was applied on a real network in the South-West of France. Controlling the pressure at two different strategic points permits a significant amount of the total distributed water to be saved (5%). This work was performed in collaboration with Cemagref Bordeaux . Future work will consist of applying a sensibility analysis of control location points to optimize the method.
Incompressible flows : modeling and simulation of moving and deformable bodies. The incompressible Navier-Stokes equations are discretized in space onto a fixed cartesian mesh. The deformable bodies are taken into using a first order penalization method and/or second order immersed boundary method. The interface between the solid and the fluid is tracked using a level-set description so that it is possible to simulate several bodies freely evolving in the fluid. A turbulence model based on Samgorinsky model has been added to the numerical code. The numerical code written in the C langage is massively parallel. The large linear systems (over than 100 millions of dofs) are solved using the Petsc Library. As an illustration of the methods, fish-like locomotion is analyzed in terms of propulsion efficiency. Underwater maneuvering and school swimming are also explored. We were able to simulate the three-dimensional flow about a swimmer for realistic physical configurations. Another application is the turbulent 3D flow around complex wind turbine (see http://www.math.u-bordeaux1.fr/~mbergman and http://www.math.u-bordeaux1.fr/MAB/mc2/analysis.html for simulation movies). Wake flows generated by boat propellers are also modeled and simulated.
We recently take in account a simplified elasticity model of the swimmer (elastic caudal tail of a fish). Some elastic parameters allows to increase the swimming efficiency around 20%-30%. Recent developments on multiphase flows have been performed. We are able to simulate water/air interactions with interface regularization. The interface with a boat is also taken into account. See http://www.math.u-bordeaux1.fr/~mbergman for simulations.
ANR Cyclobulle lead by Hamid Kellay Soap hemi-bubble film experiments have shown some links between the formation of vortices when the hemi-bubble is heated at the equator and the formation of tornados in the earth atmosphere. Two-dimensional simulations using a stereographic map are used to compare to these experimental results and confirm the results when Coriolis force and heat source terms are added.
Compressible flows: Immersed boundary methods. We are concerned with immersed boundary methods, i.e., integration schemes where the grid does not fit the geometry, and among this class of methods, more specifically with cartesian grid methods, where the forcing accounting for the presence of boundaries is performed at the discrete level. We have developed a simple globally second order scheme inspired by ghost cell approaches to solve compressible flows, inviscid as well as viscous. In the fluid domain, away from the boundary, we use a classical finite-volume method based on an approximate Riemann solver for the convective fluxes and a centered scheme for the diffusive term. At the cells located on the boundary, we solve an ad hoc Riemann problem taking into account the relevant boundary condition for the convective fluxes by an appropriate definition of the contact discontinuity speed. This method can easily be implemented in existing codes and is suitable for massive parallelization. It has been validated in two dimensions for Euler and Navier-Stokes equations, and in three dimensions for Euler equations. The order of convergence is two in norm for all variables, and between one and two in depending on the variables. The 3D code has been parallelized with MPI. The case of a moving solid has been tested (flapping wing) and gives results for the drag and the lift in agreement with the references in the literature.
The Oldroyd B constitutive model is used to study the role of the viscoelasticity of dilute polymer solutions in two-dimensional flows past a bluff body using numerical simulations. This investigation is motivated by the numerous experimental results obtained in quasi two dimensional systems such as soap film channels. The numerical modeling is novel for this case and therefore a comprehensive comparison is carried out to validate the present penalization method and artificial boundary conditions. In particular we focus on flow past a circular object for various values of the Reynolds number, Weissenberg number, and polymer viscosity ratio. Drag enhancement and drag reduction regimes are discussed in detail along with their flow features such as the pattern of vortex shedding, the variation of lift as well as changes in pressure, elongational rates, and polymer stress profiles. A comprehensive study of the flow behavior and energy balance are carefully carried out for high Reynolds numbers. Flow instabilities in both numerical and experimental results are discussed for high Weissenberg numbers .
Elliptic problems: We have developed a new cartesian method to solve elliptic problems with immersed interfaces. These problems appear in numerous applications, among them: heat transfer, electrostatics, fluid dynamics, but also tumour growth modelling, or modelling of electric potential in biological cells This method is second order accurate in the whole domain, notably near the interface. The originality of the method lies on the use of additionnal unknows located on interface points, on which are expressed flux equalities. Special care is dedicated to the discretization near the interface, in order to recover a stable second order accuracy. Actually, a naive discretization could lead to a first order scheme, notably if enough accuracy in the discretization of flux transmission condtions is not provided. Interfaces are represented with a distance level-set function discretized on the grid points. The method has been validated on several test-cases with complex interfaces in 2D. A parallel version has been developed using the PETSC library.
Simulations of fluid-solid interactions : The interaction of an elastic structure and an fluid occurs in many phenomena in physics. To avoid the difficulty of coupling lagrangian elasticity with an eulerian fluid we consider a whole eulerian formulation. The elasticity of the structure is computed with retrograde caracteristics which satisfy a vectorial transport equation. We derive the associated fluid-structure models for incompressible and compressible media. The equations are discretized on a cartesian mesh with finite differences and finite volumes schemes. The applications concern the bio-locomotions and the study of air-elastic interaction.
Vortex methods : The aim of this work is to couple vortex methods with the penalization methods in order to take advantage from both of them. This immersed boundary approach maintains the efficiency of vortex methods for high Reynolds numbers focusing the computational task on the rotational zones and avoids their lack on the no-slip boundary conditions replacing the vortex sheet method by the penalization of obstacles. This method that is very appropriate for bluff-body flows is validated for the flow around a circular cylinder on a wide range of Reynolds numbers. Its validation is now extended to moving obstacles (axial turbine blades) and three-dimensional bluff-bodies (flow around a sphere). See . Moreover, using the global properties of the penalization method, this technique permits to include porous media simultaneously in the flow computation. We aim to adapt the porous media flows to our new method and to apply it in order to implement passive control techniques using porous layers around bluff-bodies.
Domain decomposition : Domain decomposition methods are a way to parallelize the computation of numerical solutions to PDE. To be efficient, domain decompositions methods should converge independently on the number of subdomains. The classical convergence result for the additive Schwarz preconditioner with coarse grid is based on a stable decomposition. The result holds for discrete versions of the Schwarz preconditioner, and states that the preconditioned operator has a uniformly bounded condition number that depends only on the number of colors of the domain decomposition, and the ratio between the average diameter of the subdomains and the overlap width. Constants are usually non explicit and are only asserted to depend on the "shape regularity" of the domain decomposition.
two years ago, we showed the result holds the additive Schwarz preconditioner can also be defined at the continuous level and provided completely explicits estimates. Last year, we established that a similar result also holds for non shape regular domain decompositions where the diameter of the smallest subdomain is significantly smaller than the diameter of the largest subdomain. The constants are also given explicitely and are independent of the ratio between the diameter of the largest sudomain and the diameter of the smallest subdomain.
This year, we have studied explored new coarse spaces algorithms for domain decomposition methods. Coarse spaces are necessary to get a scalable algorithm whose convergence speed does not deteriorate when the number of subdomains increases. For domains decomposition methods with discontinuous iterates, we showed that continuous coarse spaces can never be an optimal choice. As an alternative, we introduced both the use of discontinuous coarse spaces(DCS) and a new coarse space algorithm using these discontinuous coarse spaces.
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https://gradehunters.net/economics-price-theory/
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math
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Demand for a good can be characterized by P = 100 − Q. There are two firms: Firm 1 and Firm 2. They have identical cost functions.
TC1 =5+10q1 TC2 =5+10q2
1. Suppose that each firm make the output decision simultaneously (Cournot model). What are the equilibrium outputs by each firm, q1 and q2? What is the equilibrium price? What are each firm’s profits? (3 points)
2. Suppose that both firm collude with each other and share the profits equally (Monopoly model). What is the equilibrium output and price in this market? What are each firm’s profits? (3 points)
Suppose that Jake considers two alternative investment plans of $1,000 for one-year. Investment A is a no-risk plan: deposit into a bank account with interest rates with 5%. That is, it makes $1,050 in a year for sure. Investment B is a risky plan: buying stocks. This plan could make $1,500 in a year if the economy is good, but if the economy is bad in a year, it could make only $600. According to recent forecases by economists, the probability that the economy is good in a year is 1/2.
1. Find the expected income and standard deviation of Investment B. (3 points)
Suppose Jake’s utility function is U = √I, where I is the income. Find the expected utility from each investment. (3 points)
Which investment would Jake choose? Why?(2 points)
Is Jake risk-loving? Explain why shortly. (2 points)
(Bonus Questions) How much of certain income would he give up to avoid risk? (Hint: What is a certain income that yields the same utility as an uncertain income yields?) (4 points)
Michael has the following utility function:
U(X,Y ) = log(X) + log(Y ),
where the price of X is $3 and the price of Y is $1. He has decided to allocate $120 on X and Y. What is his utility maximizing combination of X and Y? (5 points)
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https://www.recordingblogs.com/wiki/enigmatic-scale-on-guitar
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math
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The following are examples of the enigmatic scale in C at selected positions on the guitar neck. These examples use standard guitar tuning (E, A, D, G, B, E open guitar strings lowest to highest). These scale patterns can be transposed to other positions on the neck to produce other enigmatic scales.
The horizontal lines in each example are the guitar strings, where the lowest guitar string is at the bottom. The vertical lines are the guitar frets. The fret numbers are at the top of each pattern. The white notes are the tonic of the scale (the first note). The gray notes are the dominant of the scale (the fifth note).
It should be noted that the dominant in the enigmatic scale is not a perfect fifth of the tonic (i.e., in this example, the perfect fifth of the tonic C is G, but the note used in the enigmatic scale is G#). The fifth on the enigmatic scale is an augmented fifth, as there are eight semitones between it and the tonic, instead of the seven semitones in a perfect fifth. Similarly, the fourth note of the enigmatic scale (the subdominant) is an augmented fourth and not a perfect fourth. There are six semitones between the C and the F# in the example below, instead of the five semitones in a perfect fourth. The perfect fourth (F in the example below) is sometimes used in the descending enigmatic scale. This note is also shown below.
The enigmatic scale is such that there are very few patterns that are comfortable on the guitar neck and do not require too much movement of the guitar neck hand. The scale consists essentially of two sets of notes: (1) four notes that are a semitone from each other (A#, B, C, and Db in the example) and (2) three notes that are two semitones from each other and two and three semitones from the set of four notes (E, F#, and G# in this example). The patterns selected below recognize this and place the set of four notes on one string and the set of three notes on the next string. Other patterns are possible, but this is the most comfortable construction for playing the scale on the guitar, with the exception of the construction around the beginning of the neck, where free strings can be used.
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http://www.wyzant.com/Chandler_Heights_AZ_tutoring_jobs.aspx
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math
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I am interested math tutoring for my son. He is in 10th grade doing Algebra 2.
I am looking for a tutor for my son. He is honors chemistry this year and its starting to get overwhelming.
I am looking for a tutor for when I take my SAT on October 11th.
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I am looking for help with college level calculus.
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I am looking for a math tutor for my daughter. She is in tenth grade and needs help with geometry.
I am into my 2nd week of Spanish 102 and it has been 1 1/2 years since my first class. I definitely need weekly help and I need it now.
I am looking for a tutor for my 3rd grader. He need help with Reading and Math (e.g., division, multiplication, reading comprehension, etc.).
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https://figurethis.nctm.org/challenges/c58/think_about.htm
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math
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three grapefruit cost
$1.00, why does one cost $0.34?
How can pictures
help you solve math problems?
Is it easier to use words
or symbols when describing
Why do people use letters, such as FBI
to identify organizations?
In math and science,
certain letters and symbols are commonly used to refer
to specific quantities, such as d
What are some other letters and symbols that are used?
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CC-MAIN-2022-40
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https://www.wilnecotejnrandheathfieldsinf.co.uk/maths-27/
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math
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Today can you explore subtraction facts?
Last week we looked at our addition facts. You can use these to help you with you subtraction facts.
I know that 9+1= 10, this means that 10-9=1 and 10-1=9. My number facts (or number bonds) to 10 also help me with my number facts to 20. I know that 10-1=9 so 20-1=19.
Challenge: Can you work systematically (in order) to make sure you have got them all?
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https://onlineessay-writer.com/2021/04/20/how-to-solve-this-math-problem-step-by-step_bj/
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math
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Quickmath allows paper writing services for college students students to get instant solutions how to solve this math problem step by step to all kinds of math problems, from algebra and equation solving right through to calculus and matrices solving algebra word problems is useful in helping you to solve earthly problems. you can also make how to solve this math problem step by step a drawing of the problem to help you figure out what it's asking you to do. it is essential define timed paragraph essay solving how to solve this math problem step by step rpoblems a math problem carefully before any other steps can be problems nursing research paper topic to solve the problem. solve math problems step by step for free – free math problem solver. with that in solve, read on how to solve a math problem how to solve this math problem step by step using pemdas: back in the good old days before computer and smartphones apps, the only way to solve an unsolvable mathematical step is to ask your math teacher step-by-step calculator solve problems from pre algebra to calculus step-by-step. get the cymath math solving app on your smartphone! anyone who has taught for for any length of time will know how difficult it help be to how to solve this math problem step by step teach pupils proble, solve maths problems out of context ideas for argumentative essay solve calculus and algebra problems online with cymath math problem solver with steps to show your work. help me solve this math problem step by step, how to write song names in an essay, an essay concerning how grateful am i to the family., research paper career path essay hot topics your apollo 13 problem solving demands no matter what kind of assignment most important thing in my life essay you may need or what topic you might be struggling with, essayhelp.org will always make how to write research background your student life easier. there are several math functions problem play, as children have to wrestle with their knowledge of maths vocabulary, transport business plan free operations, and often basic comprehension skills these types of problem test your logic and math skills, as well as alliteration in writing your reading comprehension how to solve this math problem step by step and attention to detail. jacob wednesday the 7th. however, the steps below will be helpful for primary source essay most logic problems writing examples essay that you encounter how to solve math problems step by step – microsoft rhetorical analysis essay example of a speech math solver – math problem solver & calculator. consumer behavior research paper the math operation involve addition, subtraction, math problem answers are solved here step-by-step to keep the explanation clear to the students 5 easy steps to solve any word problem in math. mathematics deals with numbers and relations among them. google.
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https://laramellortraining.co.uk/absolutereferencing
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math
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We are talking about calculations here and how they behave when you autofill them. Before we move on to absolute referencing it’s worth going back to basics with relative referencing.
Normally when you create a calculation in Excel you want it so that if you autofill down the cell references move down and if you autofill across the cell references move across. This also applies to copying and moving cells. This moving of the cells is called relative referencing or relative addressing.
For example, if I have the calculation =B2*C2 in cell D2 and autofill it down the cell references move in relation to the direction we are autoflling to become = B3*C3
Sometimes you need the calculations to behave a little differently when you autofill so the cells stay fixed and do not move. This is called absolute referencing or absolute addressing. This is done by using dollar signs. The dollar goes before the direction it needs to fix. A dollar before the letter fixes the column and a dollar before the number fixes the row.
For example, if I have the calculation =D2*$G$1 in cell E2 and autofill it down the D2 will move relative as before and the $G$1 will stay fixed becoming =D3*$G$1. This is often useful for percentage increases when the percentage is stored in an individual cell but is also used in a range of functions to stop ranges of data moving.
Les frequently used, but no less useful if required is mixed referencing. This is a mixture of fixing the row but not the column or vice versa
For example, with the calculation =$B8*C$6 when it is autofilled down becomes =$B9*C$6. In $B8 the column is fixed but not the row so autofilling down the row number moves while C$6 the row is fixed so it stays on C$6. In contrast, if we autofill across $B8 will not move as the column is fixed but c$6 will because the column is not fixed becoming =$B8*D$6
Now we all love a good shortcut and there is a cracker here that toggles between the 4 options above. If we are editing the calculation the F4 Key will apply firstly absolute referencing, then will fix the row, then the column before return to relative referencing for every subsequent time it is pressed. This works for individual cells if the cursor is clicked in the cell reference but can be applied to the whole calculation if that is selected instead. This is far quicker and less fiddly than typing the dollar signs in.
Want to see how this can be used effectively in functions then contact me at email@example.com to discuss your needs.
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http://www.authorstream.com/Presentation/freylerl-211956-lesson-1-4-adding-real-numbers-lesson1-education-ppt-powerpoint/
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math
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logging in or signing up Lesson 1.4 - Adding Real Numbers freylerl Download Post to : URL : Related Presentations : Share Add to Flag Embed Email Send to Blogs and Networks Add to Channel Uploaded from authorPOINT lite Insert YouTube videos in PowerPont slides with aS Desktop Copy embed code: Embed: Flash iPad Dynamic Copy Does not support media & animations Automatically changes to Flash or non-Flash embed WordPress Embed Customize Embed URL: Copy Thumbnail: Copy The presentation is successfully added In Your Favorites. Views: 1006 Category: Education License: All Rights Reserved Like it (1) Dislike it (0) Added: July 09, 2009 This Presentation is Public Favorites: 0 Presentation Description No description available. Comments Posting comment... Premium member Presentation Transcript Properties : Properties Identity Property of Addition Examples: 0 + 5 = 5 -5 + 0 = -5 Inverse Property of Addition Examples: 17 + (-17) = 0 -17 + 17 = 0 Adding Real Numbers : Start at –3. Move right 5 units. Start at 3. a. 3 + (–5) b. –3 + 5 3 + (–5) = –2 Use a number line to simplify each expression. Move left 5 units. ALGEBRA 1 LESSON 1-4 Adding Real Numbers 1-4 -3 + 5 = 2 Rules : Rules Adding Numbers With the Same Sign Add their absolute values and give the sum the same sign Examples: 2 + 6 = 8 -2 + (-6) = -8 Adding Numbers With Different Signs *Subtract the absolute values and give the answer the same sign as the greatest absolute value. Examples: -2 + 6 = 4 2 + (-6) = -4 Adding Real Numbers : Simplify each expression. 12 + (–23) b. –6.4 + (–8.6) The difference of the absolute values is 11. The negative addend has the greater absolute value, so the sum is negative. Since both addends are negative, add their absolute values. The sum is negative. ALGEBRA 1 LESSON 1-4 Adding Real Numbers 1-4 You try: : You try: Find the sum: (a.) -7 + (-4) -11 (b.) -26.3 + 8.9 -17.4 Real World Problem Solving : The water level in a lake rose 6 inches and then fell 11 inches. Write an addition statement to find the total change in water level. 6 + (–11) = –5 The water level fell 5 inches. ALGEBRA 1 LESSON 1-4 Real World Problem Solving 1-4 You try: : You try: The temperature falls 15 degrees and then rises 18 degrees. Use addition to find the change in temperature. -15 + 18 = 3, 3° is the change in temperature Evaluating Expressions : Evaluate 3.6 + (–t) for t = –1.7. 3.6 + (–t) 3.6 + (–(–1.7)) Substitute –1.7 for t. 3.6 + [1.7] –(–1.7) means the opposite of –1.7, which is 1.7. 5.3 Simplify. ALGEBRA 1 LESSON 1-4 Evaluating Expressions 1-4 You try: : You try: Evaluate the expression for t = -7.1 -t + 7.49 -(-7.1) + 7.49 7.1 + 7.49 14.59 Real-World Problem Solving : A scuba diver who is 88 ft below sea level begins to ascend to the surface. Define: Let r = the number of feet the diver rises. a. Write an expression to represent the diver’s depth below sea level after rising any number of feet. Think: 88 ft below sea level plus feet diver rises Write: –88 + r –88 + r ALGEBRA 1 LESSON 1-4 Real-World Problem Solving 1-4 Problem Continued: : Problem Continued: b. Find the new depth of the scuba diver after rising 37 ft. –88 + r –88 + 37 Substitute 37 for r. – 51 Simplify. The scuba diver is 51 ft below sea level. You try: : You try: The temperature one winter morning is -14°F. Define a variable and write an expression to find the temperature after it changes. Then evaluate your expression for a decrease of 11 degrees Fahrenheit. C = change in temperature -14 + c -14 + c -14 + (-11) -25 The temperature decreased -25°F Adding Matrices : ALGEBRA 1 LESSON 1-4 Adding Matrices 1-4 You Try: : You Try: Find the sum: You do not have the permission to view this presentation. In order to view it, please contact the author of the presentation.
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https://www.freemathhelp.com/forum/threads/3d-geometry-and-projection.124924/
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math
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Should that be 1.5 meters above the floor??
I'm afraid you're right and i made a mistake, it must be 1.5 meters above the floor.Should that be 1.5 meters above the floor??
Please show what you have tried, as we request:
Welcome to our tutoring boards! :) This page summarizes some main points from our posting guidelines. As our name implies, we provide math help (primarily to students with homework). We do not generally post immediate answers or step-by-step solutions. We prefer to help by having a...www.freemathhelp.com
It will also be helpful if you tell us what you have learned that might be applied to this problem, even if you don't see how. Context is very important. I'm guessing that the only measurements from the picture that will be useful are the angles, so I expect you to list some theorems concerning angles in a projection.
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CC-MAIN-2020-40
| 845
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http://quiltfever3.blogspot.com/2010/07/americana-star.html
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math
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A while back I posted that I won a copy of Quilt Blocks on American Barns. Well I made a project from the book. But I changed it just a little. In the book this idea was a vertical wall hanging. I set the blocks for horizontal and made a table runner.
I think it works for a runner.
Then I made four more blocks and made a wall quilt. :o}
I like this one it's nice and cheery in my hall way.
Hope you have a great day. :o}
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https://www.cfd-online.com/Forums/main/92191-unsteady-flow-matlab-loop-questions.html
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math
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|September 5, 2011, 19:03||
unsteady flow - matlab - for loop questions
Join Date: Jun 2010
Posts: 111Rep Power: 8
I am writing a code for an unsteady flow in maltab. This code is over simplified just to realize where I am going wrong and understand the basic first...
n = number of time steps
h = number of cells
v1 = zeros(h,n+1); %v1(x,t)
v1(1,= 0; %boundary condition
for j = 1: n+1
for j = 1: h
v1(i,j+1) = v1(i,j) + dt*eye(h,h)*2*v(i,j); %Euler time stepping
v1(end,j+1)=1; %boundary condition
Obviously this code does not work. But hopefully it will help in understanding my questions:
1) v1 is mean to be a (h,1) matrix at each time step. but when I apply
eye(h,h)*2*v(i,j), the code tries to multiply a (h,h) matrix with a (h,j) matrix, and not a (h,1) matrix. so I get errors. I am not sure how to change that so that eye(h,h) is multiplied by that v of each time...
2) In general, is this a reasonable approach to solve an unsteady flow problem.
Thank you in advance!
|Thread||Thread Starter||Forum||Replies||Last Post|
|Airfoil conditions for unsteady flow||Dave||Main CFD Forum||3||April 24, 2008 17:11|
|Unsteady simulation of flow past wheel||Tom||FLUENT||8||January 18, 2006 11:54|
|Unsteady flow in FLUENT||Vidya Raja||FLUENT||2||November 2, 2005 17:29|
|Unsteady Flow in FLUENT||Vidya Raja||FLUENT||0||November 1, 2005 18:54|
|Initial Conditions in unsteady turbulent flow||Z. Zeng||Main CFD Forum||5||April 28, 1999 17:38|
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https://www.exploratorium.edu/structures/claybeams5.html
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math
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Beams and Columns
| 2 | 3 |
4 | 5
When building clay trees and
animals with large versus small clay trunks or legs, your students find
a number of differences. Have them bring in pictures of actual large and
small trees and animals to look for similar differences.
If the more open-ended activity is done in a center as suggested above,
it is best to have students write about their experience. Have them respond
to some of the questions on the previous page.
For the demonstration part of this activity, ask your students what they
observed when looking at the large and small clay beams. Which was stiffer?
Which was stronger? Which bent over the fastest? Ask them why they think
the clay beams behaved differently on the two scales.
Ask them how much more clay there is in the big beam (64 times as much).
Ask them how much more the big beam weighs (64 times the weight). Ask them
how much greater the area of the base (or cross-sectional area) is for the
big beam (16 times the area). Ask them how much stronger the big beam is
(16 times as strong). Then ask if this helps explain why things were different
on the two scales.
The linear dimensions of the big clay beams are 4 times that of the small
clay beams. They are 4 times as long, 4 times as wide, and 4 times as thick.
This means that the volume of the big beam is 4 X 4 X 4 = 64 times the volume
of the small beam. This means 64 times as much clay which is 64 times as
The area of the big beam is 4 X 4 = 16 times the area of the small beam.
Since strength depends on the area of the cross-section of a beam or column,
the big clay beam is 16 times as strong as the little clay beam. The increase
of the volume (64 times) of the big clay beam over the little clay beam
is 4 times as great as the increase of area (16 times). This means that
the increase in weight of the big beam over the little beam is 4 times as
great as the increase in strength. The big beam cannot easily support its
own weight and collapses and bends much more than the small beam.
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http://rvcourseworklzoq.larryclark.us/maximum-power-transfer.html
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math
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Maximum power transfer
3 learn more about 37: maximum power transfer theorem on globalspec. Aim of experiment: to prove maximum power transfer theorem practically apparatus 1 dc circuit training system 2 set of wires 3 dc power supply 4 digital avo meter theory the power transferred from a supply source to a load is at its maximum when. Consider an ac voltage source is placed in series with a complex impedance (z) and a load impedance the maximum power transfer to the load impedance occurs when the load impedance equals the complex. 1 maximum power transfer problem statements network of sources and resistors i l r l o o a b + v l- what's the maximum power that can be delivered to a load.
The technology interface/spring 2008 cartwright 1 non-calculus derivation of the maximum power transfer theorem by kenneth v cartwright, phd. Hello, i'd just like to know why does the maximum power occur when the load resistance equals the source resistance, can it be explained verbally without matching or calculus also, why does maximum power transfer occur when the voltage across the load is equal to half the value. Suppose a 12 volt lead-acid battery has an internal resistance of 20 milli-ohms (20 m ): if a short-circuit were placed across the terminals of this large battery, the fault current would be quite large: 600 amps now suppose three of these batteries were connected directly in parallel with one. Th venin's and norton's theorems can be used to analyze complex circuits by focusing on the source and load circuits one application of th venin's and norton's theorems is to calculate the maximum power for a load circuit the power p coming from the source circuit to be delivered to. Maximum power transfer maximize the power delivered to a resistive load ece 201 circuit theory i ece 201 circuit theory i consider the general case a resistive network contains independent and dependent sources. Ab82 introduction ab82 is a compact, ready to use thevenin's theorem maximum power transfer theorem experiment board this is useful for students to study.
Maximum power transfer theorem (r bolton - 2012) physics 1553: introduction to electricity and magnetism 1 maximum power transfer theorem physics, 7th edition, cutnell & johnson. Ece 202 - experiment 8 - lab report transformers and maximum power transfer your name_____ gta's signature_____ lab meeting time_____. Maximum power transfer is another useful analysis method to ensure that the maximum amount of power will be dissipated in the load resistance when the value of the load resistance is exactly equal to the resistance of the power source. For the purpose of this laboratory experiment, the given complex dc circuit should be constructed and analyzed by taking measurements as well as by doing calculations. Th evenin's, norton's, and maximum power transfer theorems this worksheet and all related les are licensed under the creative commons attribution license.
The power that can be taken from a homogeneous magnetic field b is dependent on the induced voltage uind in the used receiver coil. 1 eece202 network analysis i dr charles j kim class note 13: maximum power transfer a maximum power transfer 1 in many practical situations, a circuit is designed to provide power to a load. In electrical engineering, the maximum power transfer theorem states that, to obtain maximum external power from a source with a finite internal resistance, the resistance of the load must equal the resistance of the source as viewed from its output terminals.
Maximum power transfer
Answer: c explanation: the maximum power is delivered from a source to its load when the load resistance is equal to the source resistance the maximum power transfer theorem can be applied to both dc and ac circuits. The maximum power-transfer problem for iz ports when the load impedance matrix is required to be passive, and it is further required that the network obtained by inter- connecting z, and be solvable for our purposes, an n x n. Back to basics: impedance matching (part 1) lou frenzel 1 | oct 24, 2011 the maximum power-transfer theorem says that to transfer the maximum amount of power from a source to a load, the load impedance should match the source impedance.
- Maximize power delivered to circuits the first derivative is used to maximize the power delivered to a load in electronic circuits so in order to have maximum power transfer from the electronic circuit to the load r, the resistance of r has to be equal to r.
- Maximum power transfer, and the load voltage v r at which this occurs (hint: recall the maximum power transfer theorem from your basic circuits course) medium line (50-150 mi) ee 340 - transmission lines author: yahia created date.
- Solved example of maximum power transfer theorem for ac & dc circuits application and limitation of maximum power transfer theorem max power to load trans.
- Te 2 s - total electrical energy solution also known as maximum power transfer solution (mpts) or industrial power optimization control (ipoc.
- Maximum power transfer theorem suppose we have a voltage source or battery that's internal resistance is r i and a load resistance r l is connected across this battery.
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https://www.jiskha.com/display.cgi?id=1173668374
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math
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posted by bobpursley .
First the slope. Perpendicular to a slope of -3 means a line slope of 1/3
y= 1/3 x + b.
Now put in the x,y point and solve for b.
write the equation of a line that has a y intercept (0,5) and is perpendicular to the line with equation y=-3x+1
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https://web.math.princeton.edu/~caseyk/
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math
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I am a mathematics National Science Foundation postdoctoral fellow at Princeton University. In June 2012 I graduated from the Blended Masters and Bachelors program in Mathematics at California Polytechnic State University at San Luis Obispo. In July 2017 I acquired my PhD in mathematics at University of California, Irvine.
I do research in geometric analysis with a focus on studying geometric flows. In addition to mathematics, I enjoy generally being outside and creating multimedia artwork.Curriculum Vitae
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CC-MAIN-2020-10
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http://www.sfu.ca/chaos/book.html
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math
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Control Theory for Physicists
AUTHOR: John Bechhoefer, Simon Fraser University, British Columbia
Cambridge University Press, 2021.
• Mathematical Appendix, Solutions Manual, and associated
Mathematica notebooks at CUP (see "Resources").
• From Adilson Motter's review in IEEE Control Systems Magazine (October 2022)
- "This is a rare example of a textbook that is concise yet clear, math dense yet very accessible, and rigorous yet beautifully written."
• From Michael Hinczewski's review in The Biophysicist (July 2022)
- "Together with information theory, control theory is the area of engineering that has the most fundamental lessons to teach physicists, and John Bechhoefer's recent textbook, Control Theory for Physicists, is an excellent place to start learning them."
• The book has a featured post on the Wolfram Community website. The post is a Mathematica notebook, of course!
OrderCambridge University Press Amazon Canada Amazon USA
ErrataCorrections through October 25, 2022
Revised NotebooksProb. 3.2, 4.9, 7.15, 7.18, 7.19, 8.7
Cover image: Guy Immega, 2020
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CC-MAIN-2023-06
| 1,080
| 14
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https://book.pdfchm.net/matlab-programming-for-engineers/9780495244493/
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math
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MATLAB® (short for MATrix LABoratory) is a special-purpose computer program
optimized to perform engineering and scientific calculations. It started life
as a program designed to perform matrix mathematics, but over the years it has
grown into a flexible computing system capable of solving essentially any technical
The MATLAB program implements the MATLAB language and provides a
very extensive library of predefined functions to make technical programming
tasks easier and more efficient. This extremely wide variety of functions makes it
much easier to solve technical problems in MATLAB than in other languages
such as Fortran or C. This book introduces the MATLAB language and shows
how to use it to solve typical technical problems.
This book teaches MATLAB as a technical programming language, showing
students how to write clean, efficient, and documented programs. It makes no pretense
at being a complete description of all of MATLAB’s hundreds of functions.
Instead, it teaches the student how to use MATLAB as a computer language and how
to locate any desired function with MATLAB’s extensive on-line help facilities.
The first six chapters are designed to serve as the text for an “Introduction to
Programming/Problem Solving” course for freshman engineering students. This
material should fit comfortably into a 9-week, 3-hour course. The remaining
chapters cover advanced topics such as I/O and graphical user interfaces. These
chapters may be covered in a longer course or employed as a reference by engineering
students or practicing engineers who use MATLAB as a part of their
coursework or employment.
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CC-MAIN-2020-40
| 1,630
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https://www.colleenhindsley.com/home/tags/90s-stuff
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math
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#77 A Still Life Calls for a Change
#76 You Got Me Coming Up With Answers
#75 One Man's Trash, That's Another Man's Come Up
#52 This Is the Way to Turn Your World Around
Your details were sent successfully!
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s3://commoncrawl/crawl-data/CC-MAIN-2023-40/segments/1695233505362.29/warc/CC-MAIN-20230921073711-20230921103711-00144.warc.gz
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CC-MAIN-2023-40
| 206
| 5
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https://brainmass.com/business/flow-to-equity/fte-cclculations-staff-scheduling-calculation-problem-146279
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math
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Calculate the FTE's required for a unit with 6 nurses 24/7. What is a replacement factor to cover three weeks vacation and 5 sick days per year per nurse?
You have asked for some assistance with calculations for the Full Time Equivalent needed to staff a unit with 6 nurses 24 hours a day and seven days a week.
First calculate the total hours needed for ONE person to cover all these hours by multiplying 24 by 7. This gives you 168 hours (which is the total number of hours in one calendar week).
Next, since you need 6 nurses on the unit for all of these hours, multiply the total hours in a week (168) by the total number of nurses needed (6). 168 x 6= 1008. Now you know that you need to cover 1008 hours each week to have the desired staffing level.
Next you need to determine how many hours your nurses will work each ...
This solution demonstrates how to calculate the FTE's (Full Time Equivalent) required for a health care unit with 6 nurses 24 hours a day 7 days a week. It also shows what the replacement factor will be to cover three weeks vacation and 5 sick days per year per nurse. This solution is approximately 500 words.
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s3://commoncrawl/crawl-data/CC-MAIN-2018-17/segments/1524125945143.71/warc/CC-MAIN-20180421110245-20180421130245-00158.warc.gz
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CC-MAIN-2018-17
| 1,139
| 6
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http://www.wyzant.com/Genesee_County_MI_algebra_2_tutors.aspx
|
math
|
Flushing, MI 48433
Middle and High school Math/Physics teacher
...am a certified Teacher with 12+ years of experience teaching middle school and high school Math and Physics.
Subjects include: Physics, Pre-algebra, algebra 1, algebra 2
, geometry, calculus, trigonometry, and AP calculus.
I am intelligent, hard working, patient,...
| 10 other subjects
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s3://commoncrawl/crawl-data/CC-MAIN-2014-41/segments/1410657121288.75/warc/CC-MAIN-20140914011201-00183-ip-10-196-40-205.us-west-1.compute.internal.warc.gz
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CC-MAIN-2014-41
| 352
| 7
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http://ned.ipac.caltech.edu/level5/Sept01/Reeves/Reeves1.html
|
math
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The first scientific evidence for a non-static universe came with the formulation of the theory of General Relativity by Einstein in 1915, following a completely new interpretation of the nature of the gravitational force. The basic idea is that the presence of matter alters the geometry of space-time. Test-particles follows the geodesics in space-time, which determine their orbits.
Quantitatively this idea is expressed by equating a geometry tensor Gµ (which incorporates the ten curvature terms required to specify the geometry) to a matter tensor Tµ which contains all the information (ten terms) about the mass-energy present in the manifold. (G is Newton's constant)
In a simplified model in which the universe is represented as an homogeneous isotropic fluid (an approximation suggested by the homogeneous distribution of galaxies in space) this equation reduces to a much simpler equation for R: the distance between any two objects (galaxies for instance) in the universe. (Here (R0) is the time derivative of R).
The space-time curvature terms are on the left-hand side of the equation. The first term: (R0/R)2 is the time curvature while the second one: k/R2 is the space curvature. The value of k is normalized to take one of the three values: k = 0 (flat universe), +1 (closed universe) or -1 (open universe). The gravitational effect of matter is represented by the energy density . The last term is the famous cosmological constant. Mathematically it is a sort of a priori undetermined constant of integration.
It is this equation which historically gave the first indication that our universe may not be static. It equates the time derivative of the scale factor R(R0) to a sum of terms which has no obvious reason to be zero.
Einstein decided to give to the exact numerical value required to obtain R0 = 0. This decision was most unfortunate. Einstein failed to make the important discovery that the universe is not static. Furthermore it was soon shown that his solution is not stable. Even if is (arbitrarily) chosen to neutralize the time derivative of R today, any density perturbation would suffice to bring the fluid out of this unstable equilibrium and induce a general motion one way or the other (contraction or expansion).
After 1930, thanks to the work of Edwin Hubble, the systematic motion (recession) of the galaxies was detected. The observations gave the relation R0/R = cst = H, where H is the Hubble constant. The value of H is still uncertain by a factor of two. It lies between 50 and 100 km/sec/megaparsec. The inverse of this parameter has the dimension of a time: the time scale of the universal expansion. Its value lies between 10 and 20 billion years.
Soon after this detection, models of the expanding universe were presented by Friedman, Lemaitre, and Alpher, Herman, Gamov. Assuming an homogeneous fluid of ideal gases, the Tµ simplifies to its diagonal form containing (, - P, - P, - P) where P is the pressure and the density of the fluid. The dynamics is given by eq. 2. The energy-momentum conservation expression, Tµ; = 0, simplifies to the following equation:
The equation Tµ; = 0 implies that the entropy per comoving volume S = sR3 remains constant which, in turn, requires that:
The entropy per unit volume s, given by s = ( + P)/T, decreases with R-3, just as the number-density of particles.
One should be careful about these two last equations. They assume that entropy generating processes are operating in the fluid. In the standard mode this is guaranteed by the hypothesis of a fluid of pure non-interacting particles (except by gravitational interactions). In the real world these equations are valid only when entropy generating processes are negligibly small. This is correct most of the time. There are important chapters of cosmic expansion when this is not true, and appropriate corrections have to be made.
Eqs. (3, 4) need to be completed by an equation of state for the fluid. Three regimes are important during cosmic expansion: radiation, matter, and vacuum.
A) When the universe is radiation dominated, i.e., when the largest contribution to the energy density is due to relativistic particles (kT >> Mc2), we have T4 and the pressure term is one-third the density term (P = 1/3). From eqs. (3, 4) we get: R-4 or R 1/T as expected from entropy conservation. The entropy density s is proportional to the number-density of relativistic particles, with a numerical factor of 7.1.
This regime applies to the early hot universe. Consider eqs. ((3, 4) again. Through the work of Hubble we know that R increases with time. At early moments, the density term R-4 dominates the k/R2 and the cosmological constant. Thus we have (R0/R) R-2 or R t1/2 where t is the timescale of the universe.
B) For a matter dominated (cold) universe the pressure of the non-relativistic particles is negligible compared to their mass density. P = 0.
Using eqs. (3, 4) again, we find R-3 T3. This time we have R t2/3.
C) In recent works, a third regime has been shown to be of great importance in the early universe. At certain times, the energy-density is dominated by the so-called vacuum energy terms associated with various physical phase transitions. These terms, which do not appear in the standard classical fluid model described before, are related to the quantum field description of matter. The undetermined cosmological constant of Einstein has become a convenient way to introduce these terms in the formalism. The equation of state of this regime is (P = -), hence = cst from eqs. (3, 4) (note the strange result that the vacuum density does not change during the expansion ...). And we have R exp(t/t0); an exponential rate of expansion called inflation.
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https://www.coursehero.com/file/6112166/2010SPRING-HW2/
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math
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ECO 320L-HW2 Due March 23, 2010 Classtime 1. Consider the consumption-saving problem of a consumer. His current income is y and his future income is y0 . The real interest rate is r . Consumer’s utility function is ln( C ) + ln( C0 ) . The government taxes capital income to raise tax revenues. There are no other taxes. The capital income tax is t k (i.e. Consumer pays t k units of consumption good for each unit he earns from savings). (a) Write down the first period and second period budget constraint for the consumer. (b) Write down the lifetime budget constraint. (c) What is the relative price of future consumption in terms of current consumption? How does it depend capital income tax t k ? (d) Write down the optimality condition. (e) Using the optimality condition and the lifetime budget constraint, solve the optimal C , C0 , and savings s as functions of y,y0 ,r, and t k . (f) Now assume that y = 100 and y0 = 50 . r = 20% and t k = 50% . Calculate C , C0 , s, and government’s tax revenue in the future period. 2. Consider the consumption-saving problem of a consumer. His current income is
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access the rest of the document.
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https://brainmass.com/business/accounting/activity-based-costing-and-special-order-60723
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math
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#1. Widgets Incorporated produces 2 types of widgets: the Basic Widget and the Delux Widget. The company has recently adopted an activity based costing (ABC) system with the following activities and cost drivers related to overhead costs.
Activity Total Costs Cost Driver Units of Cost Driver
Material ordering $400,000 # of purchase orders 8,000
Material inspection $150,000 # of receiving reports 6,000
Equipment setup $250,000 # of setups 2,000
Quality Control $300,000 # of inspections 10,000
Total overhead $1,100,000
Below is specific cost information for the Basic Widget and the Deluxe Widget.
Cost Driver Basic Widget Deluxe Widget
Purchase orders 3,500 4,500
Receiving reports 2,800 3,200
Setups 950 1050
Inspections 4,100 5,900
Direct Materials $400,000 $500,000
Direct Labor $240,000 $260,000
Direct Labor Hours 80,000 120,000
1. What is the cost per unit for each of the following cost drivers?
a. Purchase orders
b. Receiving reports
2. Using activity based costing, what are the total overhead costs assigned to the Basic Widget?
3. Using activity based costing, what are the total overhead costs assigned to the Basic Widget?
4. Using a traditional costing system that assigns overhead based on direct labor hours, what are the total overhead costs assigned to the Basic Widget?
5. Using a traditional costing system that assigns overhead based on direct labor hours, what are the total overhead costs assigned to the Delux Widget
#2. The Tie Company manufactures ties. When 18,000 ties are produced, the costs per unit are:
Direct Materials $0.60
Direct Labor $3.00
Variable Overhead $1.20
Fixed Overhead $1.60
Variable Selling Expenses $0.80
Fixed Selling Expenses $1.10
The ties normally sell for $13 each, however, the Tie Company has received a special order for 2,000 ties at $6.00 per tie. Assume the Tie Company has excess capacity.
1. By how much would operating income change if the Tie Company accepted the special order?© BrainMass Inc. brainmass.com June 3, 2020, 6:26 pm ad1c9bdddf
The solution has 2 problems. One dealing with the use of activity based costing for cost allocation and the second one relating to special order
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http://maa.org/programs/maa-awards/writing-awards/the-evolution-of-the-isoperimetric-problem?device=mobile
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math
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Year of Award: 2006
Award: Lester R. Ford
Publication Information: The American Mathematical Monthly, vol. 112, (2005), pp. 526-566
Summary: Explains the history of the Isoperimetric Problem.
About the Author: [from The American Mathematical Monthly, (2005)] Viktor Blåsjö recently received his undergraduate degree from Stockholm University. Seeing his work warmly received by the MONTHLY, he feels that perhaps there is a place in this world after all for a humble student who just wants to understand things.
Explains the history of the solution to the Isoperimetric Problem.
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https://puzzling.stackexchange.com/questions/112746/the-two-combined
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math
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The answer is 14 letters in total. Good luck!
The answer is
As solved by cap and Rand al'Thor,
The first step is the rebus:
We have the atomic number of Gallium 31 (although I'm more familiar with the atomic number being written in the lower left and mass number in the upper left)
Picture of THOR
Electron symbolizing negative charge, or in this case subtraction -
Hydrogen, i.e., H
All of this in the mirror gives ROT13
So, using ROT13 for the 5x3 rectangle of letters, we have
?BEEE TSIRA HAAHG
Now, the first picture also has a 5x3 rectangle of grids, where the shaded cells for all the grids combined form a triangle. Putting the letters from the last step in the corresponding positions in the triangle, we get this
B R A A E S T ? A E H G I E H
From the above triangle, moving spirally, we can read
BASE, HEIGHT, AREA?
The third picture also tells us that all of the letters have a unit area and that we should try to find the smallest triangle where we can fit this triangle of letter squares. An isosceles triangle with base 6 and height 6 will obviously do the trick and also has the minimum area of any triangle covering the letters. The answers are then
Base=SIX, height=SIX, area=EIGHTEEN
Finally, finding these letters from the small letters of the 4x4 letter squares and picking the corresponding big letters, we get
six->SQU, six->ARE, eighteen->TRIANGLE.
So, the final answer is
since we have a triangle made out of squares covered by yet another triangle!
Firstly, the rebus in the second row:
69.72 is the atomic mass of GALLIUM, that's a picture of THOR and then an ELECTRON (negative charge), then 1.008 is the atomic mass and 1 the atomic number of HYDROGEN. So we get ... 31THOR-H. Put that in a mirror and it becomes ROT-13 (after removing the H from THOR).
Thanks to @cap for the correct symbolic interpretation of the first and third symbols.
Now, the first and third rows:
The highlighted cells in the rectangles in the first row show the positions into which we should place the letters from the box in the third row to form a triangle:
N R F
G ? N R
U T V R U
After using ROT-13 from the previous row, this becomes:
A E S
T ? A E
H G I E H
(Note to self: when N and R are the most common letters appearing in stuff, maybe ROT-13 is involved somewhere.)
Going around the triangle in a spiral starting from the top, we get BASE, HEIGHT, AREA, ?
However, I'm not sure where to go from here. Something about "minimum" needs to be used for this triangle, and presumably the number "1" from the left also needs to be used. Then we need to figure out how to apply it to the fourth row to get the final answer.
The fourth row contains three 4x4 squares of letters, in which each cell contains two letters, one big and one small. I'm wondering if we should extract some meaning for the base, height, and area of each of these squares, and also if the spiral pattern for the triangle is significant too - maybe we should be reading the squares in a spiral pattern?
For what it's worth, ROT-13ing all the big letters in the fourth row gives:
N Z V Y W U O R - Z C B N
M F O R T F G O - T E W G
S B E D R B N X - S H V U
H C Y S E Z H Y - Y J R A
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https://www.barnesandnoble.com/w/classical-finite-transformation-semigroups-olexandr-ganyushkin/1101312982
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math
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The aim of this monograph is to give a self-contained introduction to the modern theory of finite transformation semigroups with a strong emphasis on concrete examples and combinatorial applications. It covers the following topics on the examples of the three classical finite transformation semigroups: transformations and semigroups, ideals and Green's relations, subsemigroups, congruences, endomorphisms, nilpotent subsemigroups, presentations, actions on sets, linear representations, cross-sections and variants. The book contains many exercises and historical comments and is directed, first of all, to both graduate and postgraduate students looking for an introduction to the theory of transformation semigroups, but should also prove useful to tutors and researchers.
Table of Contents
Ordinary and Partial Transformations.- The Semigroups T n, PT n, and IS n.- Generating Systems.- Ideals and Green ' s Relations.- Subgroups and Subsemigroups.- Other Relations on Semigroups.- Endomorphisms.- Nilpotent Subsemigroups.- Presentation.- Transitive Actions.- Linear Representations.- Cross-Sections.- Variants.- Order-Related Subsemigroups.
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https://naukarus.com/introduction-to-cosmology
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math
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ЯДЕРНАЯ ФИЗИКА, 2010, том 73, № 5, с. 846-878
= ЭЛЕМЕНТАРНЫЕ ЧАСТИЦЫ И ПОЛЯ
INTRODUCTION TO COSMOLOGY
©2010 A. D. Dolgov*
Institute for Theoretical and Experimental Physics, Moscow, Russia; University of Ferrara, Italy
Received August 28, 2009
An introductory review on cosmology for students specializing in particle physics is presented. Many important subjects are not covered because of lack of space but hopefully the review may serve as a starting point for further studies.
Modern cosmology is vast interdisciplinary science and it is impossible to cover it in any considerable detail in a short review. Planning this review, I have prepared the following short list of subjects, which is surely will be made much shorter at this course, but hopefully it may be useful for the students who would like to continue studying this field. So the idealistic content could be the following:
1. A little about general relativity and its role in cosmology.
2. Four basic cosmological equations and expansion regimes.
3. The Universe today and in the past.
4. Kinetics in hot expanding world and freezing of species.
5. Inflation: kinematics, models, the Universe heating, and generation of density perturbations and gravitational waves.
6. Big Bang nucleosynthesis.
7. Field theory at nonzero temperature and cos-mological phase transitions.
8. Baryogenesis and cosmological antimatter.
9. Neutrino in cosmology (bounds on mass, oscillations, magnetic moment, and anomalous interactions).
10. Dark matter and large scale structure.
11. Vacuum and dark energies.
12. Cosmic microwave radiation and cosmological parameters.
In reality only a half of this plan was fulfilled. Nevertheless, the list presented above may be helpful as a guiding line for further studies.
We will start from some nontechnical introduction to general relativity and relations between the latter
and cosmology in Section 2. Next, in Section 3 we will derive the basic cosmological equations in a rather naive way studying motion of nonrelativistic test body in spherically symmetric gravitational field. There we also talk about realistic regimes of the Universe expansion and basic cosmological parameters. In the next Section 4, the Universe history is very briefly presented. Section 5 is dedicated to thermodynamics and kinetics in the early Universe. Section 6 is dedicated to freezing of species and cosmological limit on neutrino mass. Big Bang nucleosynthesis (BBN) is presented in Section 7. In Section 8 the role of neutrinos in BBN is described. Neutrino oscillations in the early Universe are considered in Section 9. In Section 10 inlationary cosmology is discussed, and the last Section 11 is dedicated to cosmological baryogenesis.
2. GRAVITY AND COSMOLOGY
Two simple observations that the sky is dark at night and that there are shining stars lead to the conclusion that the Universe is finite in space and time. The first one is the well known Olbers' paradox, based on the estimate of the sky luminosity, which in infinite homogeneous static Universe must be infinitely high. Shining stars should exhaust their fuel in finite time and thus cannot exist in the infinitely old Universe — thermal death of the Universe. General relativity (GR) successfully hit both targets leading to the notion of expanding Universe of finite age, but created instead its own very interesting problems which we discuss in what follows.
Newtonian theory of gravity has an evident shortcoming that it has action-at-a-distance property. In other words, gravitation acts instantaneously, at any distance. On the other hand, in the spirit of contemporary wisdom interactions are always mediated by some bosonic fields and are relativistically invariant. If we wished today to generalize Newtonian theory of
gravity to relativistic theory we could take, a priori as a mediator of interactions scalar, vector, or tensor intermediate bosons, confining ourselves to lower spins.
Since we know that gravity operates at astronomically large distances, the mass of the intermediate boson should be zero or very small. Indeed, massless bosons create static Coulomb type potential U ~ 1/r while massive bosons lead to exponentially cutoff Yukawa potential U ~ exp(-mr)/r.
Interactions mediated by vector field are odd with respect to charge parity transformation, C-transformation, and as one can see from the vector boson propagator, such interactions induce matterantimatter attraction and matter—matter repulsion, recall electromagnetic interactions. Hence, vector field cannot mediate attractive gravitational force.
Scalar and tensor mediators lead to attraction of matter—matter and matter—antimatter and both are a priori allowed. According to nonrelativistic Newtonian theory the source of gravity is mass. Possible relativistic generalisation for scalars should be a scalar quantity coinciding in nonrelativistic limit with mass. The only known such source is the trace of the energy—momentum tensor of matter Ttf. The relativistic equation of motion for scalar gravity should have the form:
d2$ = 8nGN Tff,
where GN is the Newtonian gravitational coupling constant. Such theory is rejected by the observed light bending in gravitational field, since for photons: T^ = 0. A small admixture of scalar gravity to tensor one, i.e. Brans—Dicke theory , is allowed.
There remains massless tensor theory with the source which may be only the energy—momentum tensor of matter T^v. In first approximation the equation of motion takes the form:
d2V =8nGNT^ • (2)
This equation is valid in the weak field approximation because the energy—momentum of h¡v itself should be included to ensure conservation of the total energy—momentum.
Massless particles, as, e.g., gravitons, must interact with a conserved source. Otherwise theory becomes infrared pathological. The energy—momentum tensor of matter is conserved only if the energy transfer to gravitational field is neglected. Taking into account energy leak into gravity leads to nonlinear equations of motion and allows to reconstruct GR order by order. For a discussion of this approach see papers .
Historically, Einstein did not start from field-theoretical approach but formulated GR in an elegant and economical way as geometrical theory
postulating that matter makes space—time curved and that the motion of matter in gravitational field is simply free fall along geodesics of this curved manifold. This construction is heavily based on the universality of gravitational action on all types of matter — the famous equivalence principle, probably first formulated by Galileo Galilei. The least action principle for GR was formulated by Hilbert with the action given by
J R + An
where R is the curvature scalar of 4D space—time and Am is the matter action, written in arbitrary curved coordinates. Gravitational field is identified with the metric tensor g¡v of the curved space—time. The curvature is created by matter through equations of motion:
Rfiv — — 8irG^Tf
where R^V is the Ricci tensor. There is no space here to stop on technicalities of Riemann geometry. A good introduction can be found, e.g., in where one can find definition and properties of the Christoffel symbols , Riemann tensor R^av?, Ricci tensor
R^V = gafiR^av?, scalar curvature R = g^VR¡v, co-variant derivatives in curved space—time D^, etc.
The source of gravity is the energy—momentum tensor of matter taken in this curved space—time:
The impact of gravity on matter is included into T V due to its dependence on metric and in some more complicated cases on the curvature tensors. Let us repeat that the motion of matter in the gravitational field is simply the free fall, i.e. motion along geodesics.
Classical tensor theory of gravity agrees with all available data and is a self-consistent, very beautiful and economic theory. It is essentially based on one principle of general covariance, which is a generalization of Galilei principle of relativity to arbitrary coordinate frames. Invariance with respect to general coordinate transformation (which is called general covariance) is a natural framework which ensures vanishing of the graviton mass mg. Even if the underlying classical theory is postulated to be massless, quantum corrections should generally induce nonzero mass if they are not prevented from that by some symmetry principle. This is another advantage of tensor gravity with respect to scalar one for which no principle which forbids nonzero mass is known. Though quantum gravity is not yet understood, it is natural to expect that quantum corrections should induce mg = 0 in absence of general covariance.
An important property of equations of motion (4) is that their r. h. s. is covariantly conserved:
Dß ( RßV - \gßVR I = o
Accordingly, the energy—momentum tensor must be conserved too:
Dß = 0.
DßVv = OßVv - r«vV«.
in the early stage, as indicated by isotropy of cosmic microwave background radiation (CMB), and even now at large scales. Correspondingly the metric can be taken as homogeneous and isotropic one (Friedmann—Robertson—Walker (FRW) metric ):
ds2 = dt2 - a2(t) f (r)dr2 + r2dti\,
Here, D^ is covariant derivative, as we have already mentioned. To those not familiar with Riemann geometry it may be instructive to mention that covariant derivative appears when one differentiates in curved coordinate system, e.g., in spherical one, even in flat space—time. From another point of view, covariant derivative in curved space—time, which, e.g., is acting on vector field, looks as
It is similar to covariant derivative in gauge theories, because the latter includes gauge field, A^ analogous to ra
According to the Noether theorem, the conservation of T1V follows from the least action principle if the matter action is invariant with respect to general coordinate transformation. So the gravitationa
Для дальнейшего прочтения статьи необходимо приобрести полный текст. Статьи высылаются в формате PDF на указанную при оплате почту. Время доставки составляет менее 10 минут. Стоимость одной статьи — 150 рублей.
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https://www.cmu.edu/math/people/faculty/nicolaides.html
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math
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Department of Mathematical Sciences
Carnegie Mellon University
5000 Forbes Avenue
Pittsburgh, PA 15213
Ph.D., University of London
My main interest lies in getting accurate information from mathematical models using partial differential equations. In recent times I have worked on models from electrodynamics, fluid mechanics, materials science and mathematical finance. The techniques used most are finite difference and finite element methods and, for integral equations, moment methods. This type of mathematics has a practical side (developing algorithms, writing programs and nicely displaying the results) and a theoretical side (mainly, proving rates of convergence and obtaining complexity estimates for many different kinds of algorithms). These two aspects are—or should be—inseparable and I hope that this is reflected in my research activities and those of my students.
R. A. Nicolaides et. al. (eds.) Compatible Spatial Discretizations, Springer (2006).
T. G. Campbell, R. A. Nicolaides and M. Salas (eds.) Computational Electromagnetics and its Applications, Kluwer (1997)
R. A. Nicolaides and N. Walkington. MAPLE-A Comprehensive Introduction, Cambridge University Press (1996)
M. D. Gunzburger and R. A. Nicolaides (eds.) Incompressible Computational Fluid Dynamics—Trends and Advances, Cambridge University Press (1994)
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https://www.cfd-online.com/Forums/phoenics/52279-ask-question-about-fixed-flux-boundary-condition-print.html
|
math
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ask a question about Fixed Flux Boundary Condition
When I read polis about Fixed Flux Boundary Condition,I meet a problem.In the polis,it says that V should be setted to source/C.In the latter example, Heat source in block:-10 MW/m**3,then PATCH(HEATEDBL,VOLUME,NX/4+1,3*NX/4,NY/4+1,3*NY/4,1,1,1,1) COVAL(HEATEDBL,TEM1,FIXFLU,1.0E7) I find V=1.0e7 rather than 1.0e7/fixflu.Does phoenics change it automatically? Another question, does VOlUME mentioned in the PATCH represent the Volume of a cell?
Thank you. waiting for your answers.
Re: ask a question about Fixed Flux Boundary Condi
Hello Mahe, Sources with Fixflu have a special treatment, they are written as:
Sphi = Fixflu * (Val /Fixflu - Phi) in such a way that the final source introdude in the equations is: Sphi = Val - Fixflu * PHI (there is an error of the order of fixflu*phi (fixflu=1.e-10). This done automatically and only for Fixflu. If one wants to do the same thing with a smaller coefficient, he needs to divide the value he wants to impose by the coefficient. Hope this help, Jalil
|All times are GMT -4. The time now is 01:28.|
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https://robofablab.com/h21a1-optical-sensor/
|
math
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Overview H21a1 optical sensor
The H21A1 optical sensor is composed of a gallium arsenide infrared emitting diode that is connected with a silicon phototransistor and housed in a plastic container. The sensor design incorporates factors such as maximizing the mechanical resolution, coupling efficiency, ambient light rejection, cost, and reliability, among other characteristics. Having a gap in the housing allows for signal interruption with opaque material and switching the output from on to off state, which is useful in some applications.
Specifications of optical sensor:
• The sensing distance is 3 millimeters.
• Transmissive sensing is the way of detection.
• Phototransistor is one of the output configurations.
• The maximum breakdown voltage of the emitter collector is 30V.
• The maximum DC forward current is 50 milliamps.
• The maximum collector current is 20 milliamps.
• Response time is between 8 and 15 minutes.
• The mounting method is through hole.
• Slotted packaging is available.
- 1* H21a1 optical sensor
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CC-MAIN-2023-06
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https://www.coursera.org/lecture/physics-101-energy-momentum/momentum-conservation-demo-xw6WE
|
math
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Now, I'm going to demonstrate conservation of momentum, but you need two bodies to demonstrate that. So I'm going to bring in undergraduate, Cena. Hello, world. Okay. Cena should be studying English lit or some lesser subject right now, but I asked him and he agreed to come do this demo with me. I was actually bullied into doing this, for the record. No. No. No. This is total voluntary. So what we're going to do is we're going to be on our little carts here and Cena will be here, all happy undergraduate and I will be here. I've seen some stuff. I've been through it. So neither one of us are going to be moving, zero velocity, so our momentum is zero. My momentum is zero, his momentum is zero, the total momentum is zero. Then we're going to push off of each other and see what happens. So let's find these up here, and this. Get back on yours, and 3, 2, 1. All right. So after we pushed, we both started moving, right? We've got a velocity. So Cena is going this way with what we'll call V_Cena, and I am going this way with what we'll call V_Jay, V for Jason. Now, it looks like we've created momentum. It looks like we've forgot to conserve momentum. How do we explain this, Cena? Well, momentum actually acts like a vectors you see by the arrows on top of the labels, so it doesn't act like a scaler. So MV_Jason plus MV_Cena must be zero. But right, since they're opposite directions, if you did it in 1D, you would think of 1 is negative. You could say minus M, the magnitude of my velocity. If I call me the negative direction plus the magnitude of Cena's velocity. If you call him the positive direction, would be equal to zero. Yeah, so it's because momentum adds as a vector, right? What did I do? I left off my notation exactly and Cena the needs that because he's about to tell us, calculate for us, it looks like we're going about the same speed. But should we go the same speed? What speed should we both be going here? Let's see how much freshmen physics I remember. So on this other side, we have as for Jason. Right. Cena, so you should have been going, how fast? Solve for you. Cena, M_J, right. So his velocity should have been a factor of the ratio of our masses more than my velocity. So now, we get a little bit personal. The ratio of our masses. I don't know if you want to get into this, or whisper how much you weight right now? Thirty eight. Yeah. Okay. Yeah a little bit more, a little more. So this factor here is about 1.15. So we'd say that my velocity with a cursive J, they don't teach cursive anymore, his velocity would be 1.15 times my velocity, like that. So that's not a huge noticeable difference. If you watch closely, you might be able to tell that he was recoiling faster than I was. So what I'm going to do is, I'm going to gain 30 pounds real quick. Now, one way would be where should we go eat real quick? Whataburger. Okay. Camera guy can stay. We'll go to Whataburger. No, let's not do that. What I'll do is, I'll throw on 30 kilos of weight onto my cart. So let's re-setup. Burger. Now with an extra 30 kilos, that ratio should go up quite a bit. Hopefully, you'll be able to see this scene, it doesn't need move quite a bit faster. I'm also going to push them really hard. So that will also help us see. No, I can't get sideways. Here we go. Let's re-align it up. Three, two, one, there you go. He went much faster than I do.
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https://senseis.xmp.net/?topic=125
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math
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34 high approach, two space high pincer, bump permissible? [#125]
220.127.116.11: 34 high approach, two space high pincer, bump permissible?
(2005-11-02 06:41) [#313]
ladders are good for white. can white play this way if she wants to keep black low on the left side?
: ((no subject))
(2005-11-10 06:26) [#428]
this is technically a 'quick question' but i think it's more in the spirit of a wiki if you just create a branch for this on our wonderful, massive joseki tree.
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https://www.wyzant.com/Thornton_CO_Hindi_tutors.aspx
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math
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...Urdu is very close to Hindi in its spoken form. I have taken the Defense Language Proficiency Language test and scored the highest possible marks. I am currently tutoring a student who is writing...
...I have been tutoring privately for some years now. I am really good at teaching Prealgebra. I have been teaching Precalculus for a few years now.
Hindi is my mother tongue. I am from India. During...
...Also if you are trying to learn English or sit for some academic exams/ certifications in English, I could help you by explaining the grammar in Hindi.
I am an energetic and a fun teacher with more...
Call our team of experts now for one-on-one guidance:
1(877) 999-26811(877) 999-2681
Math, Physics, and Engineering tutor
My undergraduate degree is in electrical engineering and I majored in Math and Physics. I have been teaching as well as tutoring Math (Algebra, Calculus, Statistics) , Physics, and Electrical Engineering...
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s3://commoncrawl/crawl-data/CC-MAIN-2016-22/segments/1464049270134.8/warc/CC-MAIN-20160524002110-00122-ip-10-185-217-139.ec2.internal.warc.gz
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CC-MAIN-2016-22
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https://www.nagwa.com/en/videos/538162952376/
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math
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Given that vector 𝐀 is equal to
negative one, negative eight, find three 𝐀.
Multiplying a vector by any real
number, as in this case, is known as scalar multiplication. In order to perform scalar
multiplication, we multiply each component of the vector by the scalar. In this question, we need to
multiply the vector negative one, negative eight by three. Multiplying a positive number by a
negative number gives a negative answer. Therefore, three multiplied by
negative one is negative three. Three multiplied by negative eight
is equal to negative 24. Three multiplied by the vector 𝐀
or the vector three 𝐀 is equal to negative three, negative 24.
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s3://commoncrawl/crawl-data/CC-MAIN-2023-14/segments/1679296949642.35/warc/CC-MAIN-20230331113819-20230331143819-00746.warc.gz
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https://mattstillwell.net/what-are-the-3-formulas-for-the-area-of-a-triangle/
|
math
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What are the 3 formulas for the area of a triangle?
The area of a triangle is defined as the total region that is enclosed by the three sides of any particular triangle. Basically, it is equal to half of the base times height, i.e. A = 1/2 × b × h. Hence, to find the area of a tri-sided polygon, we have to know the base (b) and height (h) of it.
What is triangular formula?
The basic formula for the area of a triangle is equal to half the product of its base and height, i.e., A = 1/2 × b × h. This formula is applicable to all types of triangles, whether it is a scalene triangle, an isosceles triangle, or an equilateral triangle.
What are the 5 ways to prove the Pythagorean Theorem?
Other proofs of the theorem
- Proof using similar triangles.
- Euclid’s proof.
- Proofs by dissection and rearrangement.
- Einstein’s proof by dissection without rearrangement.
- Proof by area-preserving shearing.
- Algebraic proofs.
- Proof using differentials.
Does a2 b2 c2 work for all triangles?
Pythagorean theorem: If a triangle is a right triangle (has a right angle), then a2+b2=c2. Converse: If a2+b2=c2 in a triangle with c is the longest side, then a triangle is a right triangle.
How many different triangle formulas are there?
Types of Triangle
|Based on the Sides||Based on the Angles|
|Scalene Triangle||Acute angled Triangle|
|Isosceles Triangle||Right angle Triangle|
|Equilateral Triangle||Obtuse-angled Triangle|
How many types of triangle and its formula?
Six Types of Triangles
|Based on their Sides||Based on their Angles|
|Scalene Triangle||Acute Triangle|
|Isosceles Triangle||Obtuse Triangle|
|Equilateral Triangle||Right Triangle|
What are the first 7 triangular numbers?
List Of Triangular Numbers. 0, 1, 3, 6, 10, 15, 21, 28, 36, 45, 55, 66, 78, 91, 105, 120,136, 153, 171, 190, 210, 231, 253, 276, 300, 325, 351, 378, 406, 435, 465, 496, 528, 561, 595, 630, 666, 703, 741, 780, 820, 861, 903, 946, 990, 1035, 1081, 1128, 1176, 1225, 1275, 1326, 1378, 1431, and so on.
How many formulas are in a triangle?
A triangle is a 3-sided closed shape. There are two important formulas related to triangles, i.e., the Heron’s formula and Pythagoras theorem. The sum of the interior angles of a triangle is 180° and is expressed as ∠1 + ∠2 + ∠3 = 180°.
Does Pythagorean Theorem work on all triangles?
Pythagoras’ theorem only works for right-angled triangles, so you can use it to test whether a triangle has a right angle or not.
What is a Pythagorean triple give 3 examples?
Integer triples which satisfy this equation are Pythagorean triples. The most well known examples are (3,4,5) and (5,12,13). Notice we can multiple the entries in a triple by any integer and get another triple. For example (6,8,10), (9,12,15) and (15,20,25).
Why is Pythagorean Theorem a2 b2 c2?
The Pythagorean Theorem describes the relationship among the three sides of a right triangle. In any right triangle, the sum of the areas of the squares formed on the legs of the triangle equals the area of the square formed on the hypotenuse: a2 + b2 = c2.
How do you find 2 in Pythagorean Theorem?
2.Pythagorean Theorem find a or b – YouTube
What are the 7 types of triangles?
To learn about and construct the seven types of triangles that exist in the world: equilateral, right isosceles, obtuse isosceles, acute isosceles, right scalene, obtuse scalene, and acute scalene.
What are the 12 types of triangles?
Is 666 a triangular number?
, i.e. 1 + 2 + 3 + + 34 + 35 + 36 = 666), and thus it is a triangular number. Because 36 is also triangular, 666 is a doubly triangular number. Also, 36 = 15 + 21; 15 and 21 are also triangular numbers, and 152 + 212 = 225 + 441 = 666.
Is 0 A triangular number?
Why Pythagoras theorem is used in right angle triangle?
No, the Pythagorean theorem can only be applied to a right-angled triangle since the Pythagorean theorem expresses the relationship between the sides of the triangle where the square of the two legs is equal to the square of the third side which is the hypotenuse.
Why Pythagoras theorem is used in right triangle?
Pythagoras theorem states that “In a right-angled triangle, the square of the hypotenuse side is equal to the sum of squares of the other two sides“. The sides of this triangle have been named Perpendicular, Base and Hypotenuse. Here, the hypotenuse is the longest side, as it is opposite to the angle 90°.
What is the formula of Pythagorean triples Class 8?
Pythagorean triples are a2+b2 = c2 where a, b and c are the three positive integers.
What are the first 10 Pythagorean triples?
, are (3, 4, 5), (6, 8,10), (5, 12, 13), (9, 12, 15), (8, 15, 17), (12, 16, 20), (15, 20, 25), (7, 24, 25), (10, 24, 26), (20, 21, 29), (18, 24, 30), (16, 30, 34), (21, 28, 35).
Which formula is this A² B² C² *?
The Pythagorean theorem helps find the lengths of the sides of a right triangle. It states that a²+b²=c², where a and b are the sides around the right angle and c is the hypotenuse.
What is c2 a2 b2 2abcosC?
The law of cosines (often abbreviated LoC) states: For △ABC with sides a,b,c, the following relationships hold: c2=a2+b2−2abcosC a2=b2+c2−2abcosA b2=c2+a2−2cacosB This gives us a way to find the third side of a triangle, given two sides and the angle measure between them.
How do you find C in a triangle?
The hypotenuse is opposite the right angle and can be solved by using the Pythagorean theorem. In a right triangle with cathetus a and b and with hypotenuse c , Pythagoras’ theorem states that: a² + b² = c² . To solve for c , take the square root of both sides to get c = √(b²+a²) .
How do you find Pythagorean theorem with 3 numbers?
Pythagorean Triples – MathHelp.com- Geometry Help – YouTube
What is 180 degree triangle called?
Angles that are 180 degrees (θ = 180°) are known as straight angles. Angles between 180 and 360 degrees (180°< θ < 360°) are called reflex angles.
Who discovered Heron’s formula?
Heron of Alexandria
Heron’s formula, formula credited to Heron of Alexandria (c. 62 ce) for finding the area of a triangle in terms of the lengths of its sides. In symbols, if a, b, and c are the lengths of the sides: Area = Square root of√s(s – a)(s – b)(s – c) where s is half the perimeter, or (a + b + c)/2.
What does S mean in Heron’s formula?
The s in Heron’s formula denotes the semi-perimeter of a triangle, whose area has to be evaluated. Semi-perimeter is equal to the sum of all three sides of the triangle divided by 2.
How accurate is Heron’s formula?
Heron’s formula computes the area of a triangle given the length of each side. If you have a very thin triangle, one where two of the sides approximately equal s and the third side is much shorter, a direct implementation Heron’s formula may not be accurate.
How do you find the missing side of a triangle?
How To Calculate The Missing Side Length of a Triangle – YouTube
What is square formula?
The Formula for the Area of A Square
The area of a square is equal to (side) × (side) square units. The area of a square when the diagonal, d, is given is d2÷2 square units. For example, The area of a square with each side 8 feet long is 8 × 8 or 64 square feet (ft2).
Who invented pi?
Archimedes of Syracuse
The first calculation of π was done by Archimedes of Syracuse (287–212 BC), one of the greatest mathematicians of the ancient world.
Who invented zero?
“Zero and its operation are first defined by [Hindu astronomer and mathematician] Brahmagupta in 628,” said Gobets. He developed a symbol for zero: a dot underneath numbers.
Who invented maths?
But Archimedes is known as the father of mathematics.
Why area of square is a2?
Why is the area of a square a side square? A square is a 2D figure in which all the sides are of equal measure. Since all the sides are equal, the area would be length times width, which is equal to side × side. Hence, the area of a square is side square.
Can herons formula be used for all triangles?
Heron’s formula can be applied to any type of triangle. Since, Heron’s formula is used to calculate the area of a triangle and every type of triangle in this world will have some area. So, for a triangle, if the three sides are known, you can directly calculate the area using Heron’s formula.
How do I find the third side of a triangle?
How to Determine the Length of the Third Side of a Triangle When You
How do you find the third side of a triangle without angles?
Pythagorean Theorem for the Third Side of a Right Angle Triangle. The Pythagorean Theorem is used for finding the length of the hypotenuse of a right triangle. So, as long as you are given two lengths, you can use algebra and square roots to find the length of the missing side.
What are the 7 properties of rectangle?
The fundamental properties of rectangles are:
- A rectangle is a quadrilateral.
- The opposite sides are parallel and equal to each other.
- Each interior angle is equal to 90 degrees.
- The sum of all the interior angles is equal to 360 degrees.
- The diagonals bisect each other.
- Both the diagonals have the same length.
What is side formula?
The side angle side formula is the SAS area formula which means we can find the area of a triangle if the length of two sides of a triangle and its included angle is known. The SAS formula is expressed as: Area of a triangle = (1/2) × side1 × side2 × sin (included angle)
What is the 100th digit of pi?
The value of pi starts with a 3 followed by a decimal point. Since pi is an irrational number, the digits after the decimal point are infinite. The 100th digit after the decimal point is 9.
What is the 1000000 digits of pi?
3.14159265358979323846264338327950288419716939937510 etc. Before you click remember – it’s a byte a digit! The first 1000000 decimal places contain: 99959 0s, 99758 1s, 100026 2s, 100229 3s, 100230 4s, 100359 5s, 99548 6s, 99800 7s, 99985 8s and 100106 9s.
Who is the father of maths?
The Father of Math is the great Greek mathematician and philosopher Archimedes. Perhaps you have heard the name before–the Archimedes’ Principle is widely studied in Physics and is named after the great philosopher.
Who created math?
Archimedes is considered the Father of Mathematics for his significant contribution to the development of mathematics. His contributions are being used in great vigour, even in modern times.
Who found zero?
Who is the father of Math?
What is area formula?
Area = length × lengthArea = l2. Area = length x breadthArea = l × b. Area = π × radius × radiusArea = π × r2(π = 3.14) Using these formulas, area for different quadrilaterals (a special case of polygons with four sides and angles ≠ 90o) is also calculated. Application.
What is S in a triangle?
Another is Heron’s formula which gives the area in terms of the three sides of the triangle, specifically, as the square root of the product s(s – a)(s – b)(s – c) where s is the semiperimeter of the triangle, that is, s = (a + b + c)/2.
How do you find the unknown side of a triangle?
What is the sine of θ?
Formulas for right triangles
If θ is one of the acute angles in a triangle, then the sine of theta is the ratio of the opposite side to the hypotenuse, the cosine is the ratio of the adjacent side to the hypotenuse, and the tangent is the ratio of the opposite side to the adjacent side.
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CC-MAIN-2023-40
| 11,336
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http://mathoverflow.net/revisions/46517/list
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math
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Both methods are obviously useful, and I may have under appreciated one of them, but on the relative value of generalization versus specialization in problem solving, I agree with offer the following opinion from Hilbert:
"If we do not succeed in solving a mathematical problem, the reason frequently consists in our failure to recognize the more general standpoint from which the problem before us appears only as a single link in a chain of related problems. After finding this standpoint, not only is this problem frequently more accessible to our investigation, but at the same time we come into possession of a method which is applicable also to related problems. The introduction of complex paths of integration by Cauchy and of the notion of the IDEALS ideals in number theory by Kummer may serve as examples. This way for finding general methods is certainly the most practicable and the most certain; for he who seeks for methods without having a definite problem in mind seeks for the most part in vain.
In dealing with mathematical problems, specialization plays, as I believe, a still more important part than generalization. Perhaps in most cases where we seek in vain the answer to a question, the cause of the failure lies in the fact that problems simpler and easier than the one in hand have been either not at all or incompletely solved. All depends, then, on finding out these easier problems, and on solving them by means of devices as perfect as possible and of concepts capable of generalization. This rule is one of the most important levers for overcoming mathematical difficulties and it seems to me that it is used almost always, though perhaps unconsciously."
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s3://commoncrawl/crawl-data/CC-MAIN-2013-20/segments/1368701281163/warc/CC-MAIN-20130516104801-00056-ip-10-60-113-184.ec2.internal.warc.gz
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CC-MAIN-2013-20
| 1,686
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http://eprints.soton.ac.uk/263296/
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math
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Kukush, A., Markovsky, I. and Van Huffel, S.
Consistency of the structured total least squares estimator in a multivariate errors-in-variables model.
Journal of Statistical Planning and Inference, 133, (2), .
The structured total least squares estimator, defined via a constrained optimization problem, is a generalization of the total least squares estimator when the data matrix and the applied correction satisfy given structural constraints. In the paper, an affine structure with additional assumptions is considered. In particular, Toeplitz and Hankel structured, noise free and unstructured blocks are allowed simultaneously in the augmented data matrix. An equivalent optimization problem is derived that has as decision variables only the estimated parameters. The cost function of the equivalent problem is used to prove consistency of the structured total least squares estimator. The results for the general affine structured multivariate model are illustrated by examples of special models. Modification of the results for block-Hankel/Toeplitz structures is also given. As a by-product of the analysis of the cost function, an iterative algorithm for the computation of the structured total least squares estimator is proposed.
Actions (login required)
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s3://commoncrawl/crawl-data/CC-MAIN-2017-09/segments/1487501170614.88/warc/CC-MAIN-20170219104610-00131-ip-10-171-10-108.ec2.internal.warc.gz
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CC-MAIN-2017-09
| 1,266
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https://www.jiskha.com/display.cgi?id=1264307230
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math
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posted by HELP! PLEASE! .
1. It is believed that in the Archeaneon (2.5-4 billion years ago) the sun’s radiative output was 30% less than it is today.
(i) What would the temperature of the sun have been at that time?
(ii) At what wavelength would the peak emission from the sun have been?
(iii) Ignoring the effects of the atmosphere, what would the temperature of the Earth have been at this time (i.e. the effective radiative temperature)? Assume that the Earth’s albedo was 0.3, the same as today.
i) Use the Stefan-Boltzmann formula, and assume an emissivity of 1. You will need the sun's current output.
You can use a simpler method if you know the sun's current surface temperature is 5800 K. You reduce the output 30%, T^4 has to be reduced by a factor 0.7.
(Told/Tnew)^4 = 0.7
Told/Tnew = 0.915
Told = 0.915*5800 = 5300 K
ii) Use the Wien displacement law. If you haven't learned it yet, learn it now. (Lamdamax)*T = 0.29 cm* K
iii) Write a radiation balance equation that says the received radiation from the sun (which is proportional to Tsun^4) equals the radiation emitted by the earth which is proportional to Tearth^4. Solve for Tearth. You will need the solid angle subtended by the sun. You can find online references of how this is done for the sun's actual temperature.
The earth's temperature should also end up being about 0.915 of its present average value (which is about 290K), making it about 265 K.
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CC-MAIN-2018-05
| 1,427
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https://www.ias.edu/scholars/ana-pires
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math
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Funding provided by the National Science Foundation
Field of Study
Ana Rita Pires is working on symplectic geometry, in particular hamiltonian group actions on symplectic manifolds and on manifolds with a symplectic structure with controlled singularities. At IAS, she plans to study connections with and applications to toric geometry and topology.
Dates at IAS
School of Mathematics
Massachusetts Institute of Technology
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CC-MAIN-2023-23
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https://stat.osu.edu/events/seminar-series-dena-asta
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math
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Speaker: Dena M. Asta, Department of Statistics, The Ohio State University
Title: Non-Parametric Manifold Learning
Graph Laplacians are certain matrices defined in terms of samples of random vectors drawn from a latent, unknown subspace of Euclidean space. The use of graph Laplacians to partially learn the geometry of a latent manifold is one of the dominant paradigms in machine learning. However, graph Laplacians as they are currently used can never completely recover the latent manifold in a non-parametric setting.
The goal of this talk is to show how graph Laplacians can actually be used to obtain a consistent estimator for intrinsic latent manifold distances between sample points, and in particular, a non-parametric but computable method of completely recovering the manifold. There are two main insights behind this method: 1) graph Laplacians can be regarded not just as linear operators but something we might call quadratic operators; and 2) a fundamental result from non-commutative geometry reformulates manifold distance purely in terms of such quadratic operators. This latter reformulation is a special case of the Kontorovich dual reformulation of Wasserstein distances known as Connes' Distance Formula.
This talk reviews existing work in manifold learning and does not assume any prior knowledge of manifolds, manifold distances, Connes' Distance Formula, or graph Laplacians.
Seminars are open to public.
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s3://commoncrawl/crawl-data/CC-MAIN-2022-21/segments/1652662604495.84/warc/CC-MAIN-20220526065603-20220526095603-00628.warc.gz
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CC-MAIN-2022-21
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https://www.iai.int/es/article/detail/socio-economic-and-environmental-proxies-for-comparing-aquatic-ecosystem-service-threats-across-international-sitesa-diagnostic-approach
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math
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|Publicado en||Water 10(11):1578|
Harmon T RL Smyth S Chandra D Conde R Dhungel J Escobar N Hoyos JP Lozoya M Nin GM Perillo S Pincetl MC Piccolo B Reid JA Rusak F Scordo MI Velez SR Villamizar BWemple M Zilio
|Año de publicación||2018|
Thomas C. Harmon 1,, Robyn L. Smyth 2 , Sudeep Chandra 3, Daniel Conde 4,18, Ramesh Dhungel 5, Jaime Escobar 6,7 , Natalia Hoyos 8 , Juan Pablo Lozoya 4, Mariana Nin 4, Gerardo M.E. Perillo 9, Stephanie Pincetl 10, M. Cintia Piccolo 9, Brian Reid 11, James A. Rusak 12,13 , Facundo Scordo 9, Maria I. Velez 14, Sandra R. Villamizar 15, Beverley Wemple 16 and Mariana Zilio 17
1 Environmental Systems Graduate Program, Department of Civil & Environmental Engineering,
|Proyecto||CRN3038 - SAFER (Sensing the Americas’ Freshwater|
|Harmon et al.pdf|
In this work, we develop and test proxy-based diagnostic tools for comparing freshwater ecosystem services (FWES) risks across an international array of freshwater ecosystems. FWES threats are increasing rapidly under pressure from population, climate change, pollution, land use change, and other factors. We identified spatially explicit FWES threats estimates (referred to as threat benchmarks) and extracted watershed-specific values for an array of aquatic ecosystems in the Western Hemisphere (Ramsar sites). We compared these benchmark values to values extracted for sites associated with an international FWES threat investigation. The resulting benchmark threats appeared to provide a meaningful context for the diagnostic assessment of study site selection by revealing gaps in coverage of the underlying socio-environmental problem. In an effort to simplify the method, we tested regularly updated environmental and socioeconomic metrics as potential proxies for the benchmark threats using regression analysis. Three category proxies, aggregated from (i) external (global to regional, climate-related), (ii) internal (watershed management-related), and (iii) socioeconomic and governance related proxies produced strong relationships with water supply threat benchmarks, but only weak relationships with biodiversity-related and nutrient regulation benchmark threats. Our results demonstrate the utility of advancing global FWES status and threat benchmarks for organizing coordinated research efforts and prioritizing decisions with regard to international socio-environmental problems.
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CC-MAIN-2022-33
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https://papers.ssrn.com/sol3/papers.cfm?abstract_id=239469
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math
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Arbitrage and Optimal Portfolio Choice with Financial Constraints
36 Pages Posted: 13 Oct 2000
Date Written: December 1999
We analyze the pricing of risky income streams in a world with competitive security markets where investors are constrained by restrictions on possible portfolio holdings. We investigate how we can transfer concepts and pricing techniques from a world without frictions to such a more realistic situation. We show that basically two new aspects arise: First, portfolio constraints can lead to situations where not all arbitrage opportunities are necessarily eliminated in equilibrium. For a world with portfolio constraints the concept of no arbitrage has to be replaced by a weaker concept which we call no unlimited arbitrage. Second, though we can characterize prices which allow no unlimited arbitrage by the existence of certain state prices as in the unconstrained case, additional computational work is needed for deriving from this fact a pricing theory for contingent claims. We propose a technique which can achieve this task and which renders itself for a computationally simple implementation for many constraint situations which are of practical interest. The power of no arbitrage techniques is preserved in the sense that no specific assumptions about utility functions of investors have to be made. We relate our analysis to the optimal decision problem of an investor and show the various relations between the properties of an optimal solution to this problem and the arbitrage-free values of risky income streams. This opens a unified view on the different approaches to asset pricing under portfolio constraints used in the literature and conveys their common underlying logic.
JEL Classification: G12, G11, C61, C63
Suggested Citation: Suggested Citation
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s3://commoncrawl/crawl-data/CC-MAIN-2020-24/segments/1590348492295.88/warc/CC-MAIN-20200604223445-20200605013445-00197.warc.gz
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CC-MAIN-2020-24
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https://www.bhavinionline.com/2017/07/comes-next-sequence-97895-45638-32156-18101/
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math
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Look at the series of numbers given in the riddle and find the logic behind them.
What comes next in the sequence:
97895 , 45638 , 32156 , 18101 , ?
Riddle contributed by Manguexa Wagle.
If you get the correct answer, please share it with your friends and family on WhatsApp, Facebook and other social networking sites.
The logic that the series follows is as follows;
Multiply 1st and 5th digit, then 2nd and 4th digit and the center number becomes the middle number.
So for the first 2 numbers in the series;
97895 => 9 x 5, 7 x 9, 8 => 45, 63, 8 =>45638 =>2nd number in the series
Similarly to find the last number;
18101 => 1 x 1, 0 x 8, 1 => 1, 0, 1 => 101 => Missing number in the series.
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s3://commoncrawl/crawl-data/CC-MAIN-2017-39/segments/1505818696696.79/warc/CC-MAIN-20170926212817-20170926232817-00156.warc.gz
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CC-MAIN-2017-39
| 694
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https://support.esri.com/en/technical-article/000011259
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math
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FAQ: What is the drawing order of elements in a map?
What is the drawing order of elements in a map?
The following list describes the order in which map elements are drawn.
Elements in Data View:
• Topmost: Graphics selection
• Clip border*
• Feature selection
• Map annotation
• Graphic objects**
• Layer labels
• Layers (raster or vector)
• Bottommost: Map background***
* Optional border symbol that can be used when clipping a data frame; see Data Frame Properties > Data Frame > Clip Options > Clip to shape > Border
** Drawn with Drawing tools or inserted from external sources.
*** Set in Data Frame Properties > Frame > Background
Elements in Layout View:
• Topmost: Snap guides
• Graphics selection
• Elements in the layout‡
• Snap grid
• Print margins
• Bottommost: Paper outline
‡ Data frame(s), map surround elements (legend, north arrow, etc.), and other graphics added to layout.
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https://daslot.fr/2024/03/05/10-budget-diy-projects-that-look-expensive-home-hacks/
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math
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10 Budget DIY Projects That LOOK Expensive | Home Hacks
# Top 10 Affordable DIY Home Improvement Ideas
## 1. Coffered Ceiling
Are you looking to add a touch of elegance to your home? Consider installing a coffered ceiling. Contrary to popular belief, this project can be a DIY endeavor. With just a brad nailer, a Kreg crown molding jig, and a miter saw, you can transform your ceiling. Start by designing your layout and marking it on the ceiling. Attach frame pieces to the ceiling joists and hang the vertical trim pieces. Finish off with bottom pieces, crown molding, and some finishing touches like filling holes and painting. This project can completely revamp a room for a fraction of the cost of hiring a professional.
## 2. Update Light Fixtures
Minor electrical work can go a long way in updating the look of a room. Consider swapping out outdated light fixtures for modern alternatives. You can find affordable options on websites like Amazon or Wayfair. If you’re feeling creative, you can even build your own unique light fixture. Travis shares his experience of creating a custom light fixture using old barn wood and parts from Amazon, saving hundreds of dollars in the process.
## 3. LED-Lit Handrail
Enhance the ambiance of your home with an LED-lit handrail. By incorporating low-voltage LED wiring into your handrail, you can create a stunning visual effect. Travis demonstrates how he installed an LED light controller to automate the lighting based on motion detection, all for an affordable price.
## 4. Glass Mosaic Backsplash
Upgrade your kitchen with a glass mosaic backsplash. This project can be completed on a budget using simple tools like a tile cutter. Attach the tiles to the wall using mastic or double-sided sticky mats. Finish off with grout and caulking for a polished look.
## 5. Under Cabinet Lighting
Illuminate your countertops with under cabinet lighting. Travis showcases how LED light strips can be installed for a fraction of the cost of professional installation. By connecting the lighting to a smart home hub, you can easily control the ambiance of your kitchen.
## 6. Floating Flooring
For a major home improvement project, consider installing floating flooring. Travis shares his experience of installing bamboo engineered hardwood flooring and vinyl plank flooring, providing a durable and allergy-friendly alternative to carpet. Floating flooring allows for easy installation and removal, making it a versatile choice for homeowners.
## 7. Upgrade Baseboards and Door Casings
Enhance the look of your home by upgrading baseboards and door casings. Travis demonstrates the process of removing old trim and installing new baseboards for a fresh look. This affordable upgrade can elevate the appearance of any room.
## 8. Crown Molding
Add a touch of sophistication to your home with crown molding. Travis shows how crown molding can be added to rooms for under $150, instantly elevating the space. Consider accenting tray ceilings with crown molding and LED lighting for a luxurious touch.
## 9. Faux Shiplap Accent Wall
Create a statement wall with a faux shiplap accent wall. Using quarter-inch plywood and some paint, you can achieve the look of shiplap without the hassle. Travis demonstrates how he created an accent wall for under $100, making it a cost-effective way to add character to a room.
## 10. Paint
Lastly, don’t underestimate the power of paint. Painting walls, trim, doors, and ceilings can completely transform a room. Travis emphasizes the affordability and impact of a fresh coat of paint, making it an accessible DIY project for any homeowner.
By incorporating these affordable DIY home improvement ideas, you can enhance the look and feel of your space without breaking the bank. Get creative and start transforming your home today!
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https://raphaelvanlaer.wordpress.com/2012/02/22/peak-uncertainty-when-will-we-run-out-of-fossil-fuels/
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math
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All we do is draw little arrows…
A couple of weeks ago I read somewhere that we have got enough coal left for over 200 years. So despite the greenhouse gas emissions that it entails, we needn’t worry about our immediate energy supply. Coal can be converted to oil through the Fischer-Tropsch process , securing even oil for the next decades. Good news I thought, there is more time to develop renewables without jeopardizing an already frail economy.
Yet then the inquisitive merry-go-round in my brain got going: how did they get that number? For over 200 years of coal? Is this a lower bound? An upper bound? What if the coal price rises? What if there are new discoveries? How can they predict how much coal we will use for the next 200 years? In short, they can’t. In long, they still can’t. But hey, let’s give it a try.
Energy companies, governments and since short also bloggers around the world estimate how much fossil fuels are left. The remaining technically extractible volume of a certain fossil fuel, be it oil, coal or natural gas, is called the remaining resource. Some resources are proven (90% certainty), others just probable (50%) or possible (10%). The reserves constitute that part of the resources that is not only technically but also economically extractible. Hence the proven reserves are those resources available profitably with a 90% probability. Changing economical and technical conditions impact the amount of fuel in each category.
Once you know the size of the reserves (R) and production (P), you are just a division away from the number of years those reserves would last if production wouldn’t change. This is called the R/P-ratio. The R/P-ratios at the end of 2009 were:
The effect of growth
The numbers above are for the proven reserves. Accordingly, today’s proven reserves of oil would be depleted in 2055 if today’s production of oil wouldn’t change. In fact production does change. In the last 45 years the annual growth rate of oil production has swayed between 10% and -5.8%. Clearly the growth rate affects how long the fossil fuel reserves last. How large is this effect? Knowledge of the growth rate straightforwardly leads to the depletion date, but I’ll spare you the math.
The average growth rates since 1981 amount to 1%, 2.6% and 2.2% for oil, natural gas and coal respectively. These points are marked on the graph. If these rates would be constant, the proven reserves would be depleted in 2046 (oil and natural gas) and 2068 (coal), much earlier than if there would be no growth.
Luckily (or not), considerable uncertainty surrounds the depletion dates, arising from (1) the uncertainty in growth rate and (2) the uncertainty in reserves. The reserves in the figure displayed above were only the proven reserves. Potential reserves might be up to a factor 4 larger. What happens to the depletion dates if we take this into account? Let’s consider oil.
Oil depletion: earliest and latest date
For an estimate of when oil reserves might be depleted, take a look at the figure above. To calculate the earliest possible date, I use the proven reserves (the least amount of oil we expect to have, blue curve), with a high growth rate of 4.7% annually. There is nothing to indicate that actual production might grow this fast, but it is warranted as an upper bound as it is the largest growth on record since 1986. Thus the earliest date we arrive at is 2033.
For the latest date, we need to know how large potential reserves might be. The U.S. Geological Survey estimates the total remaining oil reserves to be at least twice as big as currently proven reserves with a 95% probability, and even up to 3-4 times as big with just a 5% chance (green curve). Consequently, I assume we can maximally extract about 3 times the currently proven reserves, with on average no growth in production. That’s how I determine the upper bound of 2146. The shaded area indicates all possible depletion dates in the range 2033-2146. The green curve is dashed because it is based on less sound numbers.
Except for Fischer-Tropsch, we can be confident the world will stop using oil in 2033-2146. Alas, in return for this confidence we have given up precision. The range 2033-2146 is quite certain and strikingly unsatisfactory. Surely we can do better! If so, it is only by reducing either (1) the uncertainty in growth rate or (2) the uncertainty in reserves.
Fighting uncertainty: the world energy model
The growth rate depends on complex socioeconomic factors such as policy-making, fuel prices, demographics, technical advancements and so on. Obviously, no one has figured out how to predict these, right? Forecasting one person’s actions is out of reach, let alone the blend of thousands of people’s fears, expectations and decisions.
Yet this is precisely what the World Energy Model, developed by the International Energy Agency, tries to do. It is a mathematical construct, comprising nearly 16000 equations, whose main goal is to replicate how energy markets work. Let’s not take the credibility of this model for granted, it produces projections – not predictions. As for any model, its output is no more trustworthy than its input. In this case one inputs some assumptions about economic growth, fuel prices and technological development. In return one gets quantities like energy demand, production growth and carbon dioxide emissions.
Putting these remarks aside, let’s just go ahead and use the model’s numbers. For oil it projects an average annual growth rate of 1% in the period 2007-2030. Remarkably this is the same rate as in the last 30 years. Let’s also allow for the possibility that this growth rate is off by a certain margin. Not having a clue how to estimate this margin, I just take the interval 0.7%-1.3% and regard it as reasonable. Over the period 2007-2030 this interval corresponds to a total growth of 17%-35%, compared to the 26% the IEA projects. The figure below illustrates this method.
Abusing the world energy model’s numbers, I find some evidence for the conclusion that oil will be depleted in 2070-2105. I get the lower bound by taking a growth rate of 1.3% (assuming the model is 0.3% wrong on the high side), based on a total potential reserve twice as big (purple curve) as the currently proven reserves. According to the USGS, there is a 95% chance that there is at least that much oil, but I still drew the curve dashed since there might be more oil by unconventional means: oil sands, oil shales, deepwater oil, etc. are not included in these graphs.
The upper bound is calculated by assuming a 0.7% growth (the model is 0.3% wrong on the low side) with potential reserves three times bigger than currently proven reserves (green curve again).
Summary of the numbers
Here’s a summary of the numbers. After each date I provide the assumed growth rate and reserves in the form (average growth rate, size of reserves relative to currently proven reserves). For instance “2146 (0%, 3)” means that I calculated the date 2146 assuming a 0% average annual production growth, with remaining reserves 3 times bigger than currently proven reserves.
So far I have concentrated on obtaining reliable ranges for the depletion dates. In reality, fossil fuels will probably never be truly depleted. A couple of years, a decade, several decades – who knows – before a depletion date is reached, prices most likely go through the roof. We will run out of cheap oil before we run out of oil. In this sense, the depletion date is irrelevant. Still, it might help us get an idea of the timescale we are faced with.
At the moment, little coal is converted to oil because of the large investments needed for the plants. The OPEC ensures that the oil price stays low enough to price Fischer-Tropsch plants out of the market (and high enough to make money).
International Energy Agency Statistics
Europe’s energy portal
U.S. Energy Information Administration
U.S. Geological Survey: World Petroleum Assessment
U.K. Energy Research Centre
BP Statistical Review
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http://dat.perdomani.net/2008/09/10/usain-bolt-record-mondiale-a-955/trackback/index.html
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math
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Velocity dispersions in a cluster of stars: How fast could Usain Bolt have run?
Since that very memorable day at the Beijing 2008 Olympics, a big question on every sports commentator’s mind has been “What would the 100 meter dash world record have been, had Usain Bolt not celebrated at the end of his race?” Glen Mills, Bolt’s coach suggested at a recent press conference that the time could have been 9.52 seconds or better. We revisit this question by measuring Bolt’s position as a function of time using footage of the run, and then extrapolate into the last two seconds based on two different assumptions. First, we conservatively assume that Bolt could have maintained Richard Thompson’s, the runner-up, acceleration during the end of the race. Second, based on the race development prior to the celebration, we assume that he could also have kept an acceleration of 0.5 m/s^2 higher than Thompson. In these two cases, we find that the new world record would have been 9.61 +/- 0.04 and 9.55 +/- 0.04 seconds, respectively, where the uncertainties denote 95% statistical errors. (http://arxiv.org/abs/0809.0209)
quando si dice “non passa proprio un cazzo”
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https://discourse.mcneel.com/t/connect-divide-curves/112116
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math
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Connect Divide Curves
November 12, 2020, 3:47pm
1189×653 241 KB
I’d like to know how can I resolve this case?:
I need to connect the divide curves on these points.
I would be so grateful with you guys. Thank you!
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https://www.howmanysyllables.com/syllables/quarrelsome
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math
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What is the plural of
You can win $250 for your students.
Prize awarded to a teacher each month.
Stewardesses is typed using
only the left hand.
Parents, Teachers, StudentsDo you have a grammar question?
Need help finding a syllable count?
Want to say thank you?
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http://necropolis.irk.ru/library/theory-of-markov-processes-dover-books-on-mathematics
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math
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By E. B. Dynkin
An research of the logical foundations of the idea at the back of Markov random methods, this article explores subprocesses, transition features, and stipulations for boundedness and continuity. instead of targeting chance measures separately, the paintings explores connections among capabilities. An ordinary seize of the speculation of Markov strategies is believed. 1961 edition.
Read or Download Theory of Markov Processes (Dover Books on Mathematics) PDF
Best probability books
Ross's vintage bestseller, creation to likelihood versions, has been used widely by way of pros and because the basic textual content for a primary undergraduate path in utilized likelihood. It presents an creation to straight forward likelihood thought and stochastic procedures, and indicates how likelihood conception might be utilized to the examine of phenomena in fields akin to engineering, machine technological know-how, administration technological know-how, the actual and social sciences, and operations study.
This paper checks of the easiest and preferred buying and selling rules-moving typical and buying and selling diversity break-by using the Dow Jones Index from 1897 to 1986. commonplace statistical research is prolonged by utilizing bootstrap concepts. total, our effects offer powerful aid for the technical recommendations.
Amstat information requested 3 evaluation editors to price their best 5 favourite books within the September 2003 factor. equipment of Multivariate research was once between these selected. while measuring numerous variables on a posh experimental unit, it's always essential to research the variables at the same time, instead of isolate them and look at them separately.
- Schaum's Outline of Probability, Random Variables, and Random Processes
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Extra resources for Theory of Markov Processes (Dover Books on Mathematics)
13 True or false: the height of the bars of a histogram are equal to the relative frequency with which observations fall into the respective bins. 14 True or false: kernel density estimates must always take on a value between 0 and 1. (Hint: Which quantity connected with the density function has to be equal to 1? 76. 54 1 Comparison of Batches 1. Find the corresponding five-number summary. 2. Construct the boxplot. 3. Draw a histogram for this data set. 19) that contain unemployment rates of all German Federal States using various descriptive techniques.
22 The last coordinate X6 shows two different subgroups. 23. One sees an overlap of the coordinate values for indices 1–3 and an increased separability for the indices 4–6. 44 1 Comparison of Batches Summary → Parallel coordinates plots overcome the visualization problem of the Cartesian coordinate system for dimensions greater than 4. → Outliers are visible as outlying polygon curves. → The order of variables is still important, for example, for detection of subgroups. → Subgroups may be screened by selective coloring in an interactive manner.
The question arises whether a better separation could be achieved using not only the diagonals but one or two more variables of the data set. The estimation of higher dimensional densities is analogous to that of one-dimensional. 10. The contour lines indicate the height of the density. One sees two separate distributions in this higher dimensional space, but they still overlap to some extent. 11. Contours of the density of X4 , X5 , X6 of genuine and counterfeit bank notes. xpl We can add one more dimension and give a graphical representation of a three dimensional density estimate, or more precisely an estimate of the joint distribution of X4 , X5 and X6 .
Theory of Markov Processes (Dover Books on Mathematics) by E. B. Dynkin
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https://www.shalom-education.com/courses/gcse-physics/lessons/energy-2/topic/energy-efficiency-2/?ld-topic-page=8693-1
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math
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Energy can be transferred from one form of energy to another. However, it is not always transferred to the form of energy that we want. A device is said to be efficient if it can convert a large amount of input energy into useful energy.
Efficiency is calculated in terms of energy. So, to calculate the efficiency of a device, we use the formula below:
This means that the efficiency of a device is just the proportion of input energy that is transferred to useful energy output.
To calculate the percentage efficiency, the equation is:
Let’s look at an example:
If a microwave has an efficiency of 0.7 and has a total power input of 600 W, work out the useful power output.
No device is 100% efficient, which would mean that the total input energy is transferred into useful energy. Also, no device has an efficiency greater than 100%. As this would mean that energy is being created, which breaks the law of conservation of energy.
However, certain devices, especially those with moving parts, can be made more efficient using lubrication.
Lubrication is a substance (often a liquid) that reduces friction and wear between moving objects or surfaces. We can use lubrication to increase efficiency.
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http://list.seqfan.eu/pipermail/seqfan/2010-February/018245.html
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math
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[seqfan] What do you call an algorithm that is inefficient overall in some cases?
Alonso Del Arte
alonso.delarte at gmail.com
Sun Feb 7 23:51:12 CET 2010
What do you call an algorithm that is inefficient overall in some cases, but
never at the level of an individual step? For example, the algorithm
described in A112687 fails to find 2-square solutions for numbers like 32
and 244. But it does work for numbers like 50 and 82. I've looked up both
"greedy algorithm" and "myopic algorithm" in the Oxford Math Dictionary but
neither term seems to apply here.
P. S. PrimeFan's listing of Waring representations remains incomplete even
after the move to Tripod http://primefan.tripod.com/PowerSumsDraft.html. It
seems like he was calculating those by hand but never completed the task.
P. P. S.: I've written my own program (in Mathematica, of course) and
it suggests the following values may be missing from A112687: 167, 192, 219,
248, 279, 288. But given that Luis says he came up with the sequence while
writing a program, I believe that my implementation of the algorithm may be
different in some way.
More information about the SeqFan
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https://www.clutchprep.com/chemistry/practice-problems/144046/part-b-a-potential-energy-curve-is-displayed-in-the-simulation-similar-to-the-on
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math
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Part B. A potential energy curve is displayed in the simulation similar to the one displayed below. The points A through E represent the position of the moving atom.
Identify how increasing the atom diameter will impact the forces experienced by the atoms at each of the five points (A to E) shown.
Drag the appropriate items to their respective bins.
Valence bond theory explains that a bond is formed when two atomic orbitals overlap.
The graph that compares the distance between atoms (x axis) versus the potential energy of the atoms (y axis) is known as the potential energy curve. This potential energy curve shows how the potential energy of the system changes as the two atoms come together to form a chemical bond This curve is unique for every set of atoms that form a bond.
In the potential energy curve created for you in the simulation, consider the gray line parallel to the x axis to be a potential energy of zero. The potential energy is negative below the gray line and positive above the gray line. The potential energy minimum (lowest point) indicates where a chemical bond is formed. The bond length is the distance between the two atoms when the potential energy is lowest in the potential energy curve.
Frequently Asked Questions
What scientific concept do you need to know in order to solve this problem?
Our tutors have indicated that to solve this problem you will need to apply the Valence Shell Electron Pair Repulsion Theory concept. If you need more Valence Shell Electron Pair Repulsion Theory practice, you can also practice Valence Shell Electron Pair Repulsion Theory practice problems.
What professor is this problem relevant for?
Based on our data, we think this problem is relevant for Professor Gonzalez's class at CSUF.
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https://www.onlinemathlearning.com/grade6-algebra-word-problems.html
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math
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These lessons look at solving Grade 6 algebra word problems by writing equations and expressions that matches the situation? The following are some examples and solutions for algebra word problems that you will commonly encounter in Grade 6.
Grade 6 Algebra Word Problems
How to write one-step equations for grade 6 algebra word problems?
Anna wants to celebrate her birthday by eating pizza with her friends. For $42.50 total, they can buy p boxes of pizza. Each box of pizza costs $8.50.
Write an equation that matches the situation.
Mr. Herman’s class is selling candy for a school fundraiser. The class has a goal of raising $500 by selling c boxes of candy. Foe every box they sell, they make $2.75.
Write an equation that the students could solve to figure out how many boxes of candy they need to sell.
Grade 6 Algebra Word Problems
How to write algebraic expressions from word problems?
The price of a visit to the dentist is $50. If the dentist fills any cavities, an additional charge of $100 per cavity gets added to the bill
If the dentist finds v cavities, what will the cost of the visit be? Write your answer as an expression.
Sunny earns $12 per hour delivering cakes. She worked for x hours this week. Unfortunately, she was charged $15 for a late delivery on Tuesday.
How much money did Sunny earn this week? Write your answer as an expression.
There are c players on the Cougars hockey team. The team scored a total of 36 goals this season. One of the players, Matthew, scored 2 more goals than the average per player.
How many goals did Matthew score? Write your answer as an expression.
Hannah has 127 books in her collection. Her school is hosting a book donation. There are z students at her school, and they each plan to donate the same amount of books and reach a total donation of 300 books.
How many books will Hannah have in her collection after her donation. Write your answer as an expression.
Grade 6 Algebra Word Problems - Rate, Distance, Time
Suzie ran a race. She ran 5 miles per hour, and the race took t hours to complete.
How long was the race? Write your answer as an expression.
The Running Aces card team won $548 playing in poker tournaments last year. The winnings were split among the p players.
How much money did each player receive? Write your answer as an expression.
Phil received a prize of x dollars from a poker tournament. The tournament cost him 100 dollars to enter.
What were Phil’s net winnings from the tournament? Write your answer as an expression.
Hillary made 48 chocolate chip cookies and y sugar cookies
How many total cookies did Hillary make? Write your answer as an expression.
Try the free Mathway calculator and
problem solver below to practice various math topics. Try the given examples, or type in your own
problem and check your answer with the step-by-step explanations.
We welcome your feedback, comments and questions about this site or page. Please submit your feedback or enquiries via our Feedback page.
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http://renegadepoetics.com/lib/algorithms-and-theory-in-filtering-and-control-part-1
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math
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By Sorensen D.C., Wets R.J.-B. (eds.)
Read Online or Download Algorithms and Theory in Filtering and Control, part 1 PDF
Best algorithms books
Estate checking out algorithms convey a desirable connection among international houses of gadgets and small, neighborhood perspectives. Such algorithms are "ultra"-efficient to the level that they simply learn a tiny section of their enter, and but they come to a decision even if a given item has a undeniable estate or is considerably diversified from any item that has the valuables.
Complicated databases should be understood good with visible illustration. A graph is a truly intuitive and rational constitution to visually characterize such databases. Graph facts version (GDM) proposed via the writer formalizes info illustration and operations at the info by way of the graph thought. The GDM is an extension of the relational version towards structural illustration.
This textbook is a radical, available advent to electronic Fourier research for undergraduate scholars within the sciences. starting with the rules of sine/cosine decomposition, the reader walks throughout the rules of discrete Fourier research earlier than achieving the cornerstone of sign processing: the quick Fourier remodel.
- Graph Drawing and Applications for Software and Knowledge Engineers
- Algorithms in Bioinformatics: 8th International Workshop, WABI 2008, Karlsruhe, Germany, September 15-19, 2008. Proceedings
- Computer-Based Problem Solving Process
- Handbook of Algorithms and Data Structures in Pascal and C
- Evolutionary Algorithms for Embedded System Design
Additional resources for Algorithms and Theory in Filtering and Control, part 1
It not only queries for the error points (or points having low margin) but also a number of other points far from the separating hyperplane (interior points). Thus, even if a current hypothesis is erroneous there is a scope for its being corrected owing to the interior points. If only error points were selected the hypothesis might have actually been worse. The ratio of selected points having low margin and those far from the hyperplane is decided by the confidence factor, which varies adaptively with iteration.
An advanced condensation algorithm should include information from all samples in the reduction process. Some widely studied schemes for data condensation are built upon classification-based approaches, in general, and the k-NN rule, in particular . The effectiveness of the condensed set is measured in terms of the classification accuracy. , a minimal set which correctly classifies all the original samples. The very first development of this kind is the condensed nearest neighbor rule (CNN) of Hart .
Some representative groups are mentioned below: 1. , linear discriminants [59, 92]) 2. , Bayesian networks ) 3. , CART ) 4. , PROGOL and FOIL ) 5. , nearest neighbor , lazy learning and case based reasoning [122, 208] methods ) 6. Neural network based models [44, 46, 148, 266] 7. Fuzzy set theoretic models [16, 23, 43, 217] 8. Rough set theory based models [137, 123, 227, 176] 9. Genetic algorithm based models [68, 106] 10. Hybrid and soft computing models The data mining algorithms determine both the flexibility of the model in representing the data and the interpretability of the model in human terms.
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https://www.physicsforums.com/threads/conversions-from-hp-to-kwh.362622/
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math
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A car needs 40 hp to move continuously at 60 mph. How long would 1 kg of hydrogen (talking about hydrogen fuel cells) move such a car, hence how many miles at 60 mph, if 1 kg of hydrogen provides 16 kWh of motive energy?
1 hp = 746 W
1 kW = 1000 W
The Attempt at a Solution
40 hp = 29.8 kW and we have 16 kWh of power
I don't know where to factor in the 60 mph, though.
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http://openstudy.com/updates/4f78fea9e4b0ddcbb89e842f
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math
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The local zoo is filling two water tanks for the elephant exhibit. One water tank contains 34 gal of water and is filled at a constant rate of 4 gal/h. The second water tank contains 30 gal of water and is filled at a constant rate of 2 gal/h. Explain. Let x = the number of hours the tanks are filling and let y = the number of gallons in the tank. What are the constraints on the system?
Stacey Warren - Expert brainly.com
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y = 4x , and y = 2x since x is a natural variable to choose for "h"ours ....
the constraints tho ... i dunno what thats actually asking for
A. both x0, y0
B. x0 only
C. y0 only
D. There are no constraints on the system.
Not the answer you are looking for? Search for more explanations.
well, we dont want to go over and waste water id assume so we would have to have a constraint on how long to run the water (xo), which implies a constraint on how much water you can get (yo).
if i were to take a guess, I would say A; but thats only a guess.
Which ordered pair is a solution of the inequality?
y>=4x - 5
im sure your given options with that, so just plug in the values to see which one fits.
A. (3, 4)
B. (2, 1)
C. (3, 0)
D. (1, 1)
i dont really know this kind of stuff
its simple if you can add and multiply .... the notation might be whats wierd tho
an ordered pair is formed from x and y values and are displayed as (x,y)
the number on the left is your x value; the number on the right is your y value.
plug in each ordered pair one at a time into the "equation" and see if the results make sense or not
@RYSSA2K10, it is more appropriate to post only one question per thread.
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http://auto-jaa.fun/4544486609/2248/kilogram-force-meter.html
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math
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Do a quick conversion: 1 kilopascals = 101.97162129779 kilograms-force/square meter using the online calculator for metric conversions Convert Newton meter to Kilogram meter, nm to kg·m conversion, 1 newton meter = 0.102 kilogram meter, Calculator newton meter to kilogram meter Conversion Kilogram meter to Newton meter. A kilogram-meter (kg·m) is a unit of torque. One kilogram-meter is the torque created by one kilogram force acting at a.
2. (Units) the basic SI unit of mass, equal to the mass of the international prototype held by the Bureau International des Poids et Mesures. One kilogram is. This on the web one-way conversion tool converts torque or moment of force units from kilogram force meters ( kgf m ) into newton meters ( N m ) instantly online. 1.
The newton (symbol: N) is the SI unit of force. It is named after Sir Isaac Newton because of his work on classical mechanics. A newton is how much force is required. .
tabelle delle conversioni delle unità di misura Conversioni da: a: moltiplicare per: carat, metric: kilogram (kg) 2.0 E-04: carat, metri a unit of force and weight, equal to the force that produces an acceleration of 9.80665 meters per second per second when acting on a mass of one kilogram The kilogram, also kilogramme, is the base unit of mass in the metric system, formally the International System of Units (SI), having the unit symbol kg All Conversions - Conversion for length, mass, power, pressure, speed, volume, energy, bytes, force, density, area, temperature, metric, imperia
Pressure conversion calculator for several SI (metric) and other frequently used pressure units. The pressure units in the converter: atmosphere (atm, standard. Convert metric, imperial and SI units like volume, pressure, length, surface, area, temperature, weight, mass, energy, force Many different power conversions. Did you find us useful? Please consider supporting the site with a small donation Instant free online tool for kilogram to stone (UK) conversion or vice versa. The kilogram [kg] to stone (UK) conversion table and conversion steps are also listed
Calculator solving for aircraft airplane wing lift force given coefficient, air density, velocity and are Many units of measure have been defined in terms of artifacts. For example, until 1960 the international definition of the meter was an artifact based on a platinum. Pressure - the amount of force that is applied to an area where the force is distributed. The metric system unit used to describe pressure is the pascal (Pa) which.
A useful interactive conversion tool, with many more units, is Engineering Exchange's online Unit Conversions program. Another tool, by Joshua Madison. On Monday, May 20 — World Metrology Day — humanity will have a new definition of the kilogram, the standard unit of mass Physics is what we say it is. Physics is a funny thing. Despite dictating the behaviors and states of everything from atoms to stars, our interpretation of. Converter provides units and measures conversions. For scientific, educational and general purposes to convert from one unit to another. For science and education
How to Measure Force. Force is a physics term that is defined as an influence that causes an object to change its rate or direction of movement or rotation Explore the forces at work when pulling against a cart, and pushing a refrigerator, crate, or person. Create an applied force and see how it makes objects move How many kilogram-force meter in 1 j? 1 kilogram-force meter is equal to 9.80665 joule. Note that rounding errors may occur, so always check the results This is a conversion chart for kilogram-force meter (Metric). To switch the unit simply find the one you want on the page and click it. You can also go to the universal conversion page
The kilogram-force (kgf or kgF), or kilopond (kp, from Latin pondus meaning weight), is a gravitational metric unit of force. It is equal to the magnitude of the force exerted on one kilogram of mass in a 9.80665 m/s2 gravitational field.. Kilogram-force meter [kgf·m] Kilowatt [kW] Lusec Megawatt [MW] Metric horsepower Microwatt Finally choose the unit you want the value to be converted to, in this case 'Kilogram-force meter.. ..Kilogram-force meter (kgf·m) Kilonewton meter (kN·m) Kilopond meter (kp·m) Pound-force kaki (lbf·ft) Pound-force inci (lbf·in) Meganewton meter (MN·m) Newton meter (Nm).. kg/m2 is the pressure exterted by one kilogram force being applied to an area of one square meter. 193746.08 kg/m2. Bar. Kilogram force per square meter Specific kilogram force meter to newton meter Conversion Results. Enter a New kilogram force meter Amount to Convert From. * Whole number, decimal or fraction ie: 6, 5.33, 17 3/8 * Precision is..
Bookmark kilogram-force meter to newton meter Conversion Calculator - you will probably need it in the future. Download Moment of Force Unit Converter our powerful software utility that helps you.. Type the number of Kilogram-force metre you want to convert in the text box, to see the results in the table. Micronewton metre (µN·m) Millinewton metre Newton metre (Nm) Kilonewton metre (kN·m)..
Select kilogram force meter to other torque measurement units conversion table. Relation and formulas between this and other torque units Kiloramm-force meter kg · m - is off-system unit of mechanical work and energy, it is the work performed by the force of one kilogram-force on a body moving at a distance of one meter » Kilogram-force/meter Unit Conversions
Online energy conversions from Kilogram force meter to other measuring unit The kilogram-force meter [kgf*m] to newton meter [N*m] conversion table and conversion steps are also listed. Also, explore tools to convert kilogram-force meter or newton meter to other moment of.. To use this kilogram-force meters to Btu converter, simply type the kilogram-force meter value in the box at left (input). The conversion result in Btu will immediately appear in the box at right
Instantly Convert Meter Kilograms (m kg) to Inch-pounds Force (in lbf) and Many More Torque Conversions Online. Meter Kilograms Conversion Charts. Many Other Conversions Kilonewton/Square Meter : The kilonewton per square meter (kN/m2) is a non-SI unit for pressure. Kilogram-force/Square Centimeter : A kilogram-force per square centimeter (kgf/cm2), often just.. Find out information about Kilogram-Force-Meter. a unit of energy and work in the mks system. Its abbreviated designations are as follows: Russian, kgs. m or kGm; international, kgf.m or kG.m.. Full Name: kilogram-force meter. Category: Fuel Economy. Symbol: kgf m. Scale Factor: 9.80665. Definition: We dont have a definition for Kilogram-force Meter yet. It will be added soon
This question isn't just about kilogram-meters, it's about multiplied units in general. I have a good mental conception of divided units, e.g. meters per second or grams per cubic meter online torque conversions, kilogram force centimeter, kilonewton meter, newton meter. Kilogram Force Centimeter [kgf∙cm] Kilonewton Meter [kN∙m] Newton Meter [N∙m] Ounce Force Inch [ozf∙in]..
Torque conversion online Fast online units and measurements conversion system for metric conversion and not only. 1 kilogram-force meter is equal t kilogram-force meter [kgf*m] kilogram-force centimeter [kgf*cm] joule [J] gigajoule [GJ] megajoule [MJ] kilojoule [kJ] millijoule [mJ] microjoule [µJ] nanojoule [nJ] attojoule [aJ] megaelectron-volt [MeV].. Kilogram force metre is a unit of torque. One kilogram force meter is equal to the torque resulting from a force of one kilogram applied perpendicularly to a moment arm which is one metre long Kilogram-force per square centimeter to centimeter of mercury Second: kilogram metre per second (kgf m/s) is unit of power. 0.10 kgf m/s is converted to 1 of what? The kilograms force meter/second unit number 0.10 kgf m/s converts to 1 W, one watt
kilogram-force-meter: 3 phrases in 1 subject Kilogram-force meter birimini de dönüştürebilen birim dönüştürücü. Bu da, örneğin, şu şekilde görünecektir: '97 Kilogram-force meter + 291 Kilogram-force meter' ya da '2mm x 38cm x 84dm.. Automatic translation: meter-kilogram force. Showing page 1. Found 1 sentences matching phrase meter-kilogram force.Found in 2 ms. Translation memories are created by human, but computer.. Q: How many Kilogram-force Meter in 200 Joules feet-pound force inch-pound force meter kilogram-force newton meter. input. convert. Metric system SI. Meter kilogram-force Conversion
Kilogram-meter definition, a meter-kilogram-second unit of work or energy, equal to the work done by a force of one kilogram when its point of application moves through a distance of one meter in the.. One newton metre, sometimes hyphenated newton-metre, is equal to the torque resulting from a force of one 1 newton meter ≈ 0.102 kilogram meter. The user must fill one of the two fields and the.. Kilogram-force is a non-standard unit and does not comply with the SI Metric System. The gram-force and kilogram-force were never well-defined units until the CGPM adopted a standard.. This tool converts Kilogram-force metre (kgf·m) to Metre kilogram-force. Value
kilogram force-meter的相关资料： 临近单词 meter—kilogram-force—second systems of units. A metric system used by engineers, who are much more concerned with force than with mass as such, and so prefer to work in a system with base units.. Our description of kilogram-force-meter includes its symbol, three metric (SI) equivalents, metric (SI) dimensions, a description in terms of other units and constants, and a link to the units in its physical..
kgf m kilogram-force metre. kcal kilo-calorie. ch h metric horsepower hour. ft. lbf (foot pound-force). Btu (British thermal unit). 1 To from megapascals to kilogram-force per square meter, you just need to multiply the value in megapascals by 101971.62129779. (It is called the conversion factor) The kilogram-force (kgf or kgF), or kilopond (kp, from Latin pondus meaning weight), is a Kilogram-force is a non-standard unit and is classified in SI Metric System as a unit that is.. ..(kilogram force millimeter) kgf.cm (kilogram force centimeter) kgf.m (kilogram force meter) ozf.in (ounce force inch). The torque value 40 kgf.m (kilogram force meter) in words is fourty kgf.m.. In all over the world, kilogram-force meter is widely used for personal, commercial and scientific purposes. When measuring a quantity, the units we use are just as important as the obtained..
..kilogram-force meter/hour kilogram-force meter/minute kilogram-force meter/second kilopond Power units conversion calculator for metric (SI), US Customary and imperial measurement systems kilogram-force meter (kgf · m). Answer in newton meter (N · m). m) is equivalent to 9.806 newton meter (N · m). To calculate just use formula 9.806 newton meter (N · m) * kilogram-force meter (kgf.. dyne centimeter (dyn cm) kilogram force meter(kgf/m) newton meters (Nm) ounce force inch pound force foot (lbf/ft) pound force inch (lbf/in)
Please select Target Unit (convert to) for Power Conversion. Convert Power from 'Kilogram force Meter hour » Kilopond Meter per minute » Kilopond Meter per second » Kilovolt Ampere » Kilowatt.. Kilogram-force — A kilogram force (kgf or kgF), or kilopond (kp, from latin pondus meaning Metre per second squared — The metre (or meter) per second squared is the unit of acceleration in the..
..kilogram-force meter/second kilopond meter/hour kilopond meter/minute kilopond meter/second kilowatt megawatt microwatt million Btu/hour [I.T.] milliwatt nanowatt newton meter/hour newton..
We found one dictionary with English definitions that includes the word meter kilogram force: Click on the first link on a line below to go directly to a page where meter kilogram force is defined kilogram-force meter is a measurement unit of energy(). Get more details about kilogram-force meter, its symbol andkilogram-force meter conversions to otherenergy measurement units kilogram force-meter 千克力米. A unit of magnetomotive force in the meter-kilogram-second system equal to the magnetomotive force around a path linking one turn of a conducting loop carrying.. Kilogram-force — A kilogram force (kgf or kgF), or kilopond (kp, from latin pondus meaning weight), is a gravitational Similarly, one kilogram force per square meter is equal to 9.806 65 pascals
Kilogram-force is a non-standard unit and is classified in SI Metric System as a unit that is The gram-force and kilogram-force were never well-defined units until the CGPM adopted a standard.. Kilogram-forceUnit systemGravitational metric systemUnit ofForc. Kilogram-force is a non-standard unit and is classified in SI Metric System as a unit that is unacceptable for use with SI. 1 kilogram force (kgf) was the force of gravity, which is pushing a mass of 1 kg at one place in the world on the ground; calculated according to Newton's law force = mass × acceleration
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https://nitro.horse/@andreas/103197516320234030
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math
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Oh this is awesome:
> Legit is a complementary command-line interface for #Git, optimized for workflow simplicity.
$ git switch <branch>
# Switches to branch. Stashes and restores unstaged changes.
$ git sync
# Synchronizes current branch. Auto-merge/rebase, un/stash.
$ git publish <branch>
# Publishes branch to remote server.
$ git branches [wildcard pattern]
# Nice & pretty list of branches + publication status.
The social network of the future: No ads, no corporate surveillance, ethical design, and decentralization! Own your data with Mastodon!
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https://www.wired.com/2014/05/how-big-is-godzillas-femur/
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math
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Dinosaurs were big (well, many of them were big but not all). There is a recent photo of a human laying next to a femur fossil of a titanosaur and the bone just looks ginormous. Of course it's big, but apparently this is about how big these things get.
Of course I can't just look at a picture and say "oh, cool". No, that's not good enough. I have to take it just one step too far. Really, that's what I do. So, here is the question: what would it look like if I was laying next to the femur from Godzilla. Oh, not just any Godzilla. No, I am talking about the most recent version from the 2014 movie (Godzilla gets bigger every year). But how big is the new Godzilla? I'm not exactly sure, but for my previous post on an ice skating Godzilla I used a height of 130 meters.
So, how big would Godzilla's femur actually be? Ok, first let me say that Godzilla probably isn't real - probably. Also, he most likely isn't a dinosaur (but I am going to use dinosaur data). Finally, he is most likely proportioned wrong. When things get that big, their mass gets huge much faster than the cross sections of their legs (mass is proportional to height cubed but area is proportional to height squared). This means that in order to not have crushed bones, you would need much wider legs than a smaller "dinosaur". Ok, I feel better after saying that.
Now for some data. What is the relationship between femur size and dinosaur height? Some very helpful internet people have created a whole bunch of nice diagrams of dinosaurs. Just try an image search for "dinosaur scale". You'll find these awesome illustrations of dinosaurs with measuring grids (and probably a human for scale). Using this, I can measure the height and then estimate the size of the femur. And fyi - I'm just guessing on these femurs. I tried to measure from the bottom of the torso thingy to about the knee thingy. One more tip - if you need to make image measurements, I recommend doing it with Tracker Video Analysis - it's not just for videos.
I tried to get a variety of dinosaurs (and I even added a mammoth for fun). For the height, I measured the height as they were shown in the image - it was to whatever point was the tallest. For some, it was the head and others it was the back. Now for the data. Here is a plot of femur size vs. height.
I'm not quite sure this should be a linear function, but I fit a linear function anyway. With this, I get a the height of a dinosaur (approximately) once I know the femur size. Here, I am calling the height h and the femur size f. Of course, I want to put in a height and get the femur size - just a little bit of algebra gives:
Using Godzilla's height of 130 meters, I get a femur size of 33 meters. Yes. I know that this function probably doesn't stay linear all the way out to a femur size of over 30 meters. However, I'm just going with it.
Now for the magic. Here is an image (not real) of me next to Godzilla's femur.
Now THAT's a big bone.
One more thing. I have a plan to estimate the size of Godzilla. It's just a plan right now, so you will have to wait for it.
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https://www.slideserve.com/aadi/10-6-more-angle-arc-theorems
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math
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10.6 More Angle Arc Theorems After studying this section, you will be able to recognize congruent inscribed and tangent-chord angles; determine the measure of an angle inscribed in a semicircle and apply the relationship between the measures of a tangent-tangent angles and its minor arc..
A C B O O E D Theorem If two inscribed or tangent chord angles intercept the same arc, then they are congruent. Theorem If two inscribed or tangent-chord angles intercept congruent arcs, then they are congruent.
Theorem The sum of the measures of a tangent- tangent angle and its minor arc is 180. Minor arc DE = 130 find the measure of angle F. D O 130 F E
Example 1 Given circle O N Conclusions Triangle LVE is similar to triangle NSE L E O S V
Example 2 In circle O, segment BC is a diameter and the radius of the circle is 20.5 mm. Chord AC has a length of 40 mm. Find AB. A B O C
Example 3 B A Given: circle O with tangent at B D C O Prove:
Summary Summarize what you have learned in this lesson. Homework: worksheet
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https://jingleyanqiu.wordpress.com/2010/02/11/
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math
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Wow, Hi, How R U?
I am such a lucky person, I did not do much for others, but these wonderful people pile me with honors and flowers…..I am still hot under this sunshine, which is beautiful, cute, and fun. Yet I need to be fair to those who have the heart to toss this flower my way. I must share my friends with U all and pass this to those who fully deserve it and may need it.
The following six (6) blogger have nominated me for sunshine award:
7th sunshine from sparrowsong, awesome poetry blog, read it and u become smarter…
8th sunshine from J. Ruth Kelly’s Blog, a blog filled with humor, wit, and joy.
9th sunshine from Laugh Hard great blog for a laughter, cool stuff.
10th sunshine from Datsme, she is new but full of beautiful thoughts and inspirational poems.
11th sunshine from JP the Beaty, comic that are witty and fun, poems are fresh and beautiful.
12th sunshine from The “Good” Doctor, high intelligence, smart poems and uplifting notes. http://drj3kyll.wordpress.com/2010/02/08/sunshine-and-super-bowl/
Thank U for your kindness, I appreciate it very much! 😉 😉 😉
Rules to Accept the Award:
- Put the logo on your blog in your post.
- Pass the award onto 12 bloggers.
- Link the nominees within your post.
- Let the nominees know they have received this award by commenting on their blogs.
- Share the love and link to the person from whom you received this award.
Here is What Jingle Did: It is difficult to choose, everyone is cool and full of love out there, I wish I could list all of U. Since I have six blogger nominated me, thus for each award, I pass to 12 each, thus 12 times 6 is 72, which is impossible! Sorry, I have to cut it in half, I am doing 72 divide by 2=36, skipping 13th, thus 36=37-1=12X3=6X6, beautiful math, right?
The end number is 37, so 10=3+7, perfect!
Here is my nominees for my 6th-12th sunshine award nominations. (3 more in stock yet)
#1: goodgirl A So Called Good Girl’s Input On Anything
#2: rebelliousangel Rebellious angel
#3: jamiemacnab Jamie MacNab’s blog
#4: Jan Freeman Jan Freeman’s Wonderings-Let Nature Be Your Guide
#5: Sam Views
#6: Lindsey Petersen: http://5kidswdisabilities.wordpress.com
#7: Mark William Jackson Mark William Jackson
#9: poetryperspectives Poetry Perspective’s Blog
#11: Reader Wil
#12: sunshineonthesewertop City of trees
#13: ——————–No award unless U want it…
#16: Half Pint The Pint’s Half Full
#17: Brian Truth is freedom
#18: Jean Has Been Shopping Jean Has been shopping
#19: me Decomondo
#20: Happysurfer From Where I am
#21: suzicate The Water Witch’s Daughter
#24: inspiredsyntax Inspired Dsyntax’s Blog
#26: Tacy Fashionspeaks
#27: gman1212 Inspiration Blog
#29: Anna Cork
#30: Bryan Borland
#31: kirkschwarz Kirk Schwarz’s blog
#32: yanangski coffee cup adventures
#33: R L Burns the white rose
#34: Tammy The windows of the soul
#35: Renee Khan circling my head
#36: Heather Kephart Happy Making
#37: Tu sais que
very special friends: thisrainykitten
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https://researchconnections.org/research-tools/research-glossary?page=6
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math
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The research glossary defines terms used in conducting social science and policy research, for example those describing methods, measurements, statistical procedures, and other aspects of research; the child care glossary defines terms used to describe aspects of child care and early education practice and policy.
The change in the dependent variable which is resulted from the influence of the research environment. This influence is external to the experiment itself.
A variable that, in theory, can take on any value within a range. The opposite of continuous is discrete or categorical, which can have only a particular set of values. For example, a person's height could be 5 feet 1 inch, 5 feet 1.1 inches, 5 feet 1.11 inches, and so one, and thus it is continuous. The type of child care setting where a child spends the greatest number of hours each week (e.g., center-based care, relative and nonrelative care) is a discrete or categorical variable.
The processes of making research conditions uniform or constant, so as to isolate the effect of the experimental condition. When it is not possible to control research conditions, statistical controls often will be implemented in the analysis.
In an experiment, the control group does not receive the intervention or treatment under investigation. This group may also be referred to as the comparison group.
A variable that is not of interest to the researcher, but which interferes with the statistical analysis. In statistical analyses, control variables are held constant or their impact is removed to better analyze the relationship between the outcome variable and other variables of interest. For example, if one wanted to examine the impact of education on political views, a researcher would control income in the statistical analysis. This removes the impact of income on political views from the analysis.
A form of scientific investigation in which one variable, termed the independent variable, is manipulated to reveal the effect on another variable, termed the dependent or responding variable, while all other variables in the system are held fixed.
A sampling strategy that uses the most easily accessible people (or objects) to participate in a study. This is not a random sample, and the results cannot be generalized to individuals who did not participate in the research.
In survey research, this is the percentage of persons who answer a survey or complete an interview out of all persons who were contacted and asked to complete the survey or interview.
The degree to which two variables are associated. Variables are positively correlated if they both tend to increase at the same time. For example, height and weight are positively correlated because as height increases weight also tends to increases. Variables are negatively correlated if as one increases the other decreases. For example, number of police officers in a community and crime rates are negatively correlated because as the number of police officers increases the crime rate tends to decrease.
A measure of the degree to which two variables are related. A correlation coefficient in always between -1 and +1. If the correlation coefficient is between 0 and +1 then the variables are positively correlated. If the correlation coefficient is between 0 and -1 then the variables are negatively correlated.
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http://westgatehouse.com/time-cycles-25.html
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math
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24. THE 360 + 5 DAY YEAR CALENDARS
The oldest records of man's past show such diverse peoples as the Chinese and Egyptians using 360 + 5 mean solar day calendars, and not for brief intervals, but over thousands of years. These were agrarian peoples dependent upon the seasons of the tropical year for survival. They could easily determine the solstices and equinoxes using horizon markers, gnomons, and the like. The 360 + 5 day year deviates so grossly from the tropical year, that it is unlikely to have ever been used to measure the seasons. A much more practical use of the 360 + 5 day year is for chronological and astronomical purposes, the same as the Julian year of 365.25 mean solar days and the Julian century of 36525 mean solar days are used today.
We have shown that the year of 360 + 6 Earth revolutions has a precise astronomical basis, which may be inferred from the structure of Hindu cosmological time cycles.
However, for the purposes of practical chronology, mean solar days are more practical units for reckoning civil time than diurnal revolutions of the Earth. Since, using the relations established by Hindu cosmological time cycles,
by using leap days corresponding to the 126 cycles of the 3rd mean motion of the Sun in a week of precessional years, the year of 360 + 5 mean solar days may be used interchangeably with the year of 360 + 6 Earth revolutions. We intercalate a leap day every 1440 years with an additional leap day intercalated every 180000 years. Thus, 0.0007(1440) = 1.008 mean solar days, and 0.008(180000/1440) = 1 mean solar day for a total of 126 leap days in 180000 years.
366 --------- - 1 7 1 - ----- 366 diurnal revolutions 10000 of the Earth = 366 · ------------- 366 --------- 7 1 - ----- 10000 7 = 365 ----- mean solar days, 10000
The Chinese order both days and years in cycles of sixty. We have shown that cycles of sixty days and sixty years as well as the sexagesimal number system are derived from the interaction between the first and second mean motions of the Sun intrinsic to Hindu cosmological time cycles.
The ancient Egyptians are known to have counted the cycle of the third mean motion of the Sun separately, using the heliacal rising of Sirius to mark the beginning of their sidereal year. The duration of this cycle is 1428+ sidereal years. Hindu cosmological time cycles prominently represent this same cycle by the factor 1428 in the infrastructure of the kalpa period, and also, at the heliacal rising of Sirius the initial point of Hindu cosmological time cycles is on the midheaven.
These considerations, together with the superior astronomical foundation of Hindu cosmological time cycles, strongly support the conclusion that the 360 + 5 day calendars of the Chinese and Egyptians were derived from the Hindu original.
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http://mathforum.org/library/topics/algebraic_g/?keyid=39607365&start_at=1&num_to_see=50
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math
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Browse and Search the Library
: Math Topics
: Algebraic Geom.
Library Home ||
Full Table of Contents ||
Suggest a Link ||
(see also All Sites in this category)
- Algebraic Geometry -
Dave Rusin; The Mathematical Atlas
A short article designed to provide an introduction to algebraic geometry, which combines the algebraic with the geometric for the benefit of both. Thus the recent proof of "Fermat's Last Theorem" - ostensibly a statement in number theory - was proved with geometric tools. Conversely, the geometry of sets defined by equations is studied using quite sophisticated algebraic machinery. This is an enticing area but the important topics are quite deep. This area includes elliptic curves. Applications and related fields and subfields; textbooks, reference works, and tutorials; software and tables; other web sites with this focus.
- The Algebraic Geometry Notebooks - Aksel Sogstad
For non-experts. Contents: What is algebraic geometry?; What can algebraic geometry be used for?; Classification of curves in the Weierstrass familiy; Bezout's Theorem; Varieties, orbits and orbit-spaces; Automatic theorem proving using Singular.
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https://www.rcsb.org/structure/3krr
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math
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Potent and Selective Inhibition of Polycythemia by the Quinoxaline JAK2 Inhibitor NVP-BSK805Baffert, F., Regnier, C.H., De Pover, A., Pissot-Soldermann, C., Tavares, G.A., Blasco, F., Brueggen, J., Chene, P., Drueckes, P., Erdmann, D., Furet, P., Gerspacher, M., Lang, M., Ledieu, D., Nolan, L., Ruetz, S., Trappe, J., Vangrevelinghe, E., Wartmann, M., Wyder, L., Hofmann, F., Radimerski, T.
(2010) Mol.Cancer Ther. 9: 1945-1955
- PubMed: 20587663
- DOI: 10.1158/1535-7163.MCT-10-0053
- PubMed Abstract:
The recent discovery of an acquired activating point mutation in JAK2, substituting valine at amino acid position 617 for phenylalanine, has greatly improved our understanding of the molecular mechanism underlying chronic myeloproliferative neoplasms ...
The recent discovery of an acquired activating point mutation in JAK2, substituting valine at amino acid position 617 for phenylalanine, has greatly improved our understanding of the molecular mechanism underlying chronic myeloproliferative neoplasms. Strikingly, the JAK2(V617F) mutation is found in nearly all patients suffering from polycythemia vera and in roughly every second patient suffering from essential thrombocythemia and primary myelofibrosis. Thus, JAK2 represents a promising target for the treatment of myeloproliferative neoplasms and considerable efforts are ongoing to discover and develop inhibitors of the kinase. Here, we report potent inhibition of JAK2(V617F) and JAK2 wild-type enzymes by a novel substituted quinoxaline, NVP-BSK805, which acts in an ATP-competitive manner. Within the JAK family, NVP-BSK805 displays more than 20-fold selectivity towards JAK2 in vitro, as well as excellent selectivity in broader kinase profiling. The compound blunts constitutive STAT5 phosphorylation in JAK2(V617F)-bearing cells, with concomitant suppression of cell proliferation and induction of apoptosis. In vivo, NVP-BSK805 exhibited good oral bioavailability and a long half-life. The inhibitor was efficacious in suppressing leukemic cell spreading and splenomegaly in a Ba/F3 JAK2(V617F) cell-driven mouse mechanistic model. Furthermore, NVP-BSK805 potently suppressed recombinant human erythropoietin-induced polycythemia and extramedullary erythropoiesis in mice and rats.
Disease Area Oncology, Novartis Institutes for BioMedical Research, 4057 Basel, Switzerland.
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https://libdl.ir/book/50245/calculus-volume-ii-multi-variable-calculus-and-linear-algebra-with-applications-to-differential-equations-and-probabilit
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math
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Summary and Info
Volume II of "Calculus", contained in this work, presents multi-variable calculus and linear algebra, with applications to differential equations and probability. Volume I, sold separately, presents one-variable calculus with an introduction to linear algebra.
More About the Author
Tom Mike Apostol (August 20, 1923 – May 8, 2016) was an American analytic number theorist and professor at the California Institute of Technology, best known as the author of widely used mathematical textbooks.
Review and Comments
Rate the Book
Calculus, Volume II: Multi-Variable Calculus and Linear Algebra, with Applications to Differential Equations and Probability 0 out of 5 stars based on 0 ratings.
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https://studylib.net/doc/25274131/3.2-solve-by-substitution
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math
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Algebra 2 Name___________________________________ ID: 1 ©Z P2^0g1b9H bKMuStJat JSmo`fWtNwBaIrWee RLBLeCc.w S IA[lKlS wrViHglhwtZsR orIewsReorYvceIdr. 3.2 Solve by Substitution Date________________ Period____ Solve each system by substitution. 1) y = 2x - 17 y = -2x + 15 2) y = 7x - 15 y=x+3 3) y = 7x - 8 y = -7x + 20 4) y = 8x - 5 y = -5x - 5 5) 3x - 2 y = 12 y=3 6) -4x + 4 y = 8 y = 4x + 5 7) -2x + 6 y = 4 y = -3x + 24 8) y = 2x + 22 -4x - 5 y = -12 9) Two classmates, Vera and Alec, plan to meet in the computer lab to type up their research papers. Vera can type at a speed of 1 page per hour, whereas Alec can type 3 pages per hour. So far, Vera already has 9 pages typed up, compared to Alec's 7 pages. Once they sit down and start typing together, the two students will reach the same page count before too long. How long will that take? What will the page count be? 10) Leo and his little sister are saving up money to buy a joint birthday present for their mother. Leo already has $23 saved and plans to save $17 per week from his allowance. His sister has $25 saved so far and will save $16 per week from hers. The two siblings will soon have saved the same amount towards their mother's gift. How long will that take? How much will each one have saved? Worksheet by Kuta Software LLC ©R q2c0_1s9W ZKyuUtqao kSEo\fTtUwQamrdeM bLxLXCU.W g SAilGlr crwifgXhytAsp PrveQs[eXrKvre\dy.N B sMUagdbeM dwPi`tmhU GIBnhf[i`nbiVtCew ^AMlugoe`b`rfa_ C2I.
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| 1,455
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https://allnurses.com/profile/1137021-meeni-tobi/
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math
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So i forgot where I saw it but a CCRN question was stated as such and for the life of my I cant figure out the answer and/or reasoning for answer. the question is something like this:
An operating room report/review found an increase of infections pertaining to a specific surgical line/group. To best address the issue what should the nurse do 1st?
A. - Speak with surgical group/team
B. - Notify with Nurse Manager
C. - Review surgical cases
D. - Discuss at staff meeting
What do you guys think the answer would be and why to this question? any ideas
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https://www.physicsforums.com/threads/hydrogen-atom-photon-emission-wavelength-formula.867442/
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math
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I am trying to calculate the Lyman-alpha wavelengths of photons emitted from different hydrogen-like atoms such as deuterium and positive helium ion 4He+, using the relation 1/λ = R*|1/ni^2 - 1/nf^2|, where R is the Rydberg constant and ni and nf are integer numbers corresponding to the initial and final energy levels, which, for Lyman-alpha wavelength, are 2 and 1, respectively. The expression for Rydberg constant is R = me/(4πħ3c)*(e2/4πε0)2. My question is: what changes in these two expressions when we are dealing with different hydrogen-like atoms?replace electron mass me with new reduced mass μ? atomic number Z (but it is not included in any of the two expressions)? Any help will be appreciated!
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http://www.scottfrickcpa.com/kindle/lie-algebras-and-algebraic-groups-springer-monographs-in-mathematics
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math
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By Patrice Tauvel,Rupert W. T. Yu
Read or Download Lie Algebras and Algebraic Groups (Springer Monographs in Mathematics) PDF
Best group theory books
Translation of the French variation
This booklet bargains a accomplished creation to the final concept of C*-algebras and von Neumann algebras. starting with the fundamentals, the speculation is built via such themes as tensor items, nuclearity and exactness, crossed items, K-theory, and quasidiagonality. The presentation rigorously and accurately explains the most good points of every a part of the speculation of operator algebras; most vital arguments are at the least defined and plenty of are offered in complete element.
Those notes deal with in complete element the speculation of representations of the gang of automorphisms of a homogeneous tree. The unitary irreducible representations are labeled in 3 varieties: a continuing sequence of round representations; unique representations; and a countable sequence of cuspidal representations as outlined through G.
This is often the second one of 3 volumes dedicated to common finite p-group conception. just like the 1st quantity, enormous quantities of vital effects are analyzed and, in lots of instances, simplified. very important themes offered during this monograph contain: (a) class of p-groups all of whose cyclic subgroups of composite orders are basic, (b) type of 2-groups with precisely 3 involutions, (c) proofs of Ward's theorem on quaternion-free teams, (d) 2-groups with small centralizers of an involution, (e) type of 2-groups with precisely 4 cyclic subgroups of order 2n > 2, (f) new proofs of Blackburn's theorem on minimum nonmetacyclic teams, (g) type of p-groups all of whose subgroups of index p2 are abelian, (h) category of 2-groups all of whose minimum nonabelian subgroups have order eight, (i) p-groups with cyclic subgroups of index p2 are categorized.
- Conformal Symmetry Breaking Operators for Differential Forms on Spheres (Lecture Notes in Mathematics)
- Combinatorial Number Theory and Additive Group Theory (Advanced Courses in Mathematics - CRM Barcelona)
- Group Theory
- Punctured Torus Groups and 2-Bridge Knot Groups (I) (Lecture Notes in Mathematics)
Extra resources for Lie Algebras and Algebraic Groups (Springer Monographs in Mathematics)
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https://papers.ssrn.com/sol3/papers.cfm?abstract_id=2592889
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math
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Speeding Up MCMC by Efficient Data Subsampling
Sveriges Riksbank Working Paper Series No. 297
39 Pages Posted: 14 Apr 2015
Date Written: March 1, 2015
The computing time for Markov Chain Monte Carlo (MCMC) algorithms can be prohibitively large for datasets with many observations, especially when the data density for each observation is costly to evaluate. We propose a framework where the likelihood function is estimated from a random subset of the data, resulting in substantially fewer density evaluations. The data subsets are selected using an efficient Probability Proportional-to-Size (PPS) sampling scheme, where the inclusion probability of an observation is proportional to an approximation of its contribution to the log-likelihood function. Three broad classes of approximations are presented. The proposed algorithm is shown to sample from a distribution that is within O(m−½) of the true posterior, where m is the subsample size. Moreover, the constant in the O(m−½) error bound of the likelihood is shown to be small and the approximation error is demonstrated to be negligible even for a small m in our applications.We propose a simple way to adaptively choose the sample size m during the MCMC to optimize sampling efficiency for a fixed computational budget. The method is applied to a bivariate probit model on a data set with half a million observations, and on a Weibull regression model with random effects for discrete-time survival data.
Keywords: Bayesian inference, Markov Chain Monte Carlo, Pseudo-marginal MCMC, Big Data, Probability Proportional-to-Size sampling, Numerical integration
JEL Classification: C11, C13, C15, C55, C83
Suggested Citation: Suggested Citation
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https://jamesoray.com/2020/08/14/is-it-smaller-on-the-inside-bag-of-holding-minor-pathfinder-1e/
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math
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So… a player in my current Pathfinder 1E game made an observation that made me scratch my head a bit. He came to the conclusion that the item Minor Bag of Holding is “smaller on the inside”.
To be honest I had never paid this item, originally printed in Pathfinder Chronicles: Classic Treasures Revisited, any attention. It has a purchase cost is 1,000 gp and a meager 50 pounds or 6 cubic feet of capacity. At least to me a Minor Bag of Holding never seems to not be a very worthwhile investment, when I could just wait a while and buy a Handy Haversack or a Bag of Holding Type I. Due to this myopia on my part, I never noticed something interesting about this item and it breaks down as follows:
- Like a normal bag of holding it “appears to be a common cloth sack”.
- Cloth sacks are basically cylindrical in shape while full.(not really, but more on this later)
- “It measures 2 feet by 4 feet”
- The player made the assumption that the above dimensions were for an inflated/opened bag of holding rather than a flat one. I also made this assumption at first.
- The volume of a cylinder is given by this formula: V=πr2h
The conclusion that the player and I reached based on the above above was that the volume of a bag with a Minor Bag of Holding’s listed dimensions should be 12.57 cubic feet, better than double the volume of the internal extradimensional space listed for the items. From this perspective the item’s only really use would be as a weight saving measure.
Not quite satisfied with this answer I decided to dig a bit deeper. Remember, that I noted that a filled sack is not really a cylinder and that the above is based on the assumption that the measurements are for an inflated bag of holding. I began to wonder if perhaps the given dimensions were for a flat bag. This of course made me scratch my head and wonder how to calculate such a thing, but by the might of Google I found this: The Paper bag problem . In short the paper bag problem is the question of how to calculate the maximum filled volume of a rectangular bag, and the answer for a bag with an open edge is the following: V=w3(h/(πw)-0.071(1-10(-2h/w)))
Plugging everything in we come up with: 23(4/(π2)-0.071(1-10(-8/2)))= 4.53 cubic feet
We end up with 6 cubic feet of space residing inside of a 4.53 cubic feet bag. It turns out that the Minor Bag of Holding is indeed bigger on the inside than its external dimensions would indicate.
The moral of this story is that things that seem quite simple can be complicated once you start digging into them.
FYI: The aforementioned Pathfinder 1E game is a mix of Crisis of the World Eater from LPJ Designs and Legendary Planet from Legendary Games.
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https://www.pinterest.de/explore/rechtwinkliges-dreieck-winkel-berechnen/
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math
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Number Theory Math Unit Contents: Math Definitions Math Divisibility Rules Prime or Composite Factors Prime Factorization Greatest Common Factor methods!) Least Common Multiple Math Number Theory Practice and Enrichment Sheets
An Apple For The Teacher: My Students are Kicking Their Math Facts & Learning Them Too! Fun and motivating way to help students learn their math facts! Could be done with addition/subtraction for younger kiddos.
Students will learn how to Add on a Number line. This worksheet assess students ability to use a number line to help them add numbers together. This worksheet addresses the standard adding and subtracting within
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http://radiobiglove.ro/bitcoin-penny-stock-349372.php
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math
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Learn Accounting Accounting Basics Economics Lessons Math Lessons Simple Math Basic Math Math Formula Chart Maths Solutions Physics And Mathematics Simple Interest Formula video lessons, examples and solutions How to calculate the Simple Interest Formula, how to solve interest problems using the simple interest formula, How to use the formula for simple interest to find the principal, the rate or the time, compound interest formulas, continuously compounded interest formulas, How to solve simple interest problems in real life, compound interest problems, continuously compounded interest problems, and determining the effective rate of return, with video lessons, examples and step-by-step solutions.
Be able to forecast the price of any asset and make great profits on daily basis. We've got bitcoin penny stock covered.
Check out this comprehensive guide. Price chart, trade volume, market cap, and more. Discover new cryptocurrencies to add to your portfolio.
AMC STOCK \u0026 CRYPTO - THE TRUTH!
Listen, smile, agree. FOMO helps encourage this phase by selling bottoms and buying tops.
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https://gradestack.com/GRE-Prep/-Q-Determine-which/6-467-14276-2860-test-wtst
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math
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Register To Attempt Complete Test
Q. Determine which of the two expressions below is larger, whether they are equal, or whether there is not enough information to decide.
x(x – y) – z(x – y)
(x – y)(x – z)
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https://www.cakecentral.com/forum/t/638008/anyone-know-if-you-can
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math
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airbrush on one of those edible image wraps? you know the ones with the beautiful scrolls or damask print? I have a bride that wants the scroll, and I would like the white background to look the same color as the fondant it will be applied to. Any help would be truly appreciated. She is actually coming for a consult in about 1 hour, and I would like to give her some sort of an answer. Thanks.
Sorry, I'm not sure what you mean but hopefully someone here knows how!!! *bump*
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https://www.hackmath.net/en/example/1554
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math
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Four cooks cleaned 5 kg of potatoes for 10 minutes. How many cook would have to work clean 9 kg of potatoes for 12 minutes?
Leave us a comment of example and its solution (i.e. if it is still somewhat unclear...):
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It was 102 people on the bus. 28 girls had two dogs. A 11 girls had one dog. At the next stop seceded 5 dogs (even with their owners). They got two boys together with three dogs. The bus drove one driver. How many foot were in bus?
- Passenger boat
Two-fifths of the passengers in the passenger boat were boys. 1/3 of them were girls and the rest were adult. If there were 60 passengers in the boat, how many more boys than adult were there?
On the bowl were a few cakes. Jane ate one-third of them, Dana ate a quarter of those cakes that remained. a) What part (of the original number of cakes) Dana ate? b) At least how many cakes could be (initially) on thebowl?
- The result
How many times I decrease the number 1144 to get the result 22?
- Math classification
In 3A class are 27 students. One-third got a B in math and the rest got A. How many students received a B in math?
In the city operates 171 doctors. The city has 128934 citizens. How many citizens are per one doctor?
Children break chocolate first to third and then every part of another half. What kind got each child? Draw a picture. What part would have received if each piece have halved?
- Pizza 5
You have 2/4 of a pizza and you want to share it equally between 2 people how much pizza does each person get?
- Ratio 11
Simplify this ratio 10 : 1/4
Honza had three cages (black, silver, gold) and three animals (guinea pig, rat and puppy). There was one animal in each cage. The golden cage stood to the left of the black cage. The silver cage stood on the right of the guinea pig cage. The rat was in the
Zdeněk picked up 15 l of water from a 100-liter full-water barrel. Write a fraction of what part of Zdeněk's water he picked.
- Fraction and a decimal
Write as a fraction and a decimal. One and two plus three and five hundredths
- Pizza 4
Marcus ate half pizza on monday night. He than ate one third of the remaining pizza on Tuesday. Which of the following expressions show how much pizza marcus ate in total?
Teacher Rem bought 360 pieces of cupcakes for the outreach program of their school. 5/9 of the cupcakes were chocolate flavor and 1/4 wete pandan flavor and the rest were vanilla flavor. How much more chocolate flavor cupcakes than vanilla flavor?
- Fraction to decimal
Write the fraction 3/22 as a decimal.
- Addition of Roman numbers
Added together and write as decimal number: LXXXV + CDXXI
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https://nutritionalassessment.mumc.nl/en/calculating-energy-expenditure
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math
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For the measurement of the energy expenditure in adults, the Harris and Benedict formula or the revised Roza and Shizgal formula are used.
Harris and Benedict formula (1919)
For men: 66,4730 + (13,7516 X W) + (5,0033 X H) - (6,7550 X A)
: 655,0955 + (9,5634 X W) + (1,8496 X H) - (4,6756 X A)
Energy expenditure in male adults
Energy expenditure in female adults
Roza and Shizgal formula (1984)
In 1984 Roza and Shizgal revised the original formula by Harris and Benedict to calculate energy expenditure. This revised formule is currently used by dieticians of the Maastricht UMC+.
For men: 88,362 + (13,397 X W) + (4,799 X H) - (5,677 X A)
For women: 447,593 + (9,247 X W) + (3,098 X H) - (4,33 X A)
For this formula a bigger group of persons is used. They where measured by Harris and Benedict themselves 1928 en 1935.
Energy expenditure in male adults, revised version
Energy expenditure in female adults, revised version
Legend (both formulas)
Bodyweight (W) in kilogram
Height (H) in meter
Age (A) in years
The (updated) Harris and Benedict calculates the resting energy metabolism, including diet induced thermogenesis (in short 'DIT'). Because the (updated) Harris and Benedict formula is known to overestimate the resting energy metabolism, it's often used as a calculation of the basal energy metabolism.
To calculate total energy expenditure, extra percentages need to be taken into account. You can find these in this document.
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http://www.pims.math.ca/scientific-event/130207-wentsdq
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math
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West End Number Theory Seminar: de Quehen
- Date: 02/07/2013
University of Calgary
The Hirzeburch Compactification of Hibert Modular Surfaces
In this talk we will give a non-singular compactification of Hilbert modular surfaces by constructing a particular toric variety for each cusp. Other than the familiar compactification of modular curves this illustrative example is the simplest case of Mumford's theory of toroidal compactifications.
2:00 pm at MS 337
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https://player.fm/series/mop-swingers/mop-swingers-episode-35
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math
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This series is archived ("Inactive feed" status)Please note series archiving is a new, experimental, feature of Player FM with the aim of helping users understand how we fetch series and report on any issues.
When? This feed was archived on May 28, 2018 02:24 (). Last successful fetch was on March 13, 2018 18:10 ()
Why? Inactive feed status. Our servers were unable to retrieve a valid podcast feed for a sustained period.
What now? You might be able to find a more up-to-date version using the search function. This series will no longer be checked for updates. If you believe this to be in error, please check if the publisher's feed link below is valid and contact support to request the feed be restored or if you have any other concerns about this.
Manage episode 195765086 series 1577371
Excerpt, “You know who has a weird filmography? David Aire.”
You walked into a spiderweb. “One could say it is a spectacular display of mediocrity. He did U571. Then he did Fast and Furious. Then he did Sabotage. Then he did Deep Blue.”
46 episodes available. A new episode about every 3 days averaging 9 mins duration .
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https://www.slideserve.com/Jims/drift-diffusion-modeling
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math
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Drift-Diffusion Modeling. Prepared by Dragica Vasileska Professor Arizona State University. Outline of the Lecture. Classification of PDEs Why Numerical Analysis? Numerical Solution Sequence Flow-Chart of Equilibrium Poisson Equation Solver Discretization of the Continuity Equation
Download Policy: Content on the Website is provided to you AS IS for your information and personal use and may not be sold / licensed / shared on other websites without getting consent from its author.While downloading, if for some reason you are not able to download a presentation, the publisher may have deleted the file from their server.
Arizona State University
Different mathematical and physical
System of coupled equations for several
General form of second-order PDEs ( 2 variables)
(Diffusion / dispersion)
D. Vasileska and S.M. Goodnick, Computational Electronics, published by Morgan & Claypool , 2006.
S. Selberherr: "Analysis and Simulation of Semiconductor Devices“, Springer, 1984.
No knowledge of solving of PDEs
With knowledge for solving of PDEs
Method of images
Green’s function method
Method of separation of variables
Governing Equations ICS/BCS
System of Algebraic Equations
Equation (Matrix) Solver
Discrete Nodal Values
D. Vasileska, EEE533 Semiconductor Device and Process Simulation Lecture Notes,
Arizona State University, Tempe, AZ.
The course of action taken in three steps is dictated by the nature of the problembeing solved, the solution region, and the boundary conditions. The mostcommonlyused grid patterns for two-dimensional problems are
Common grid patterns: (a) rectangular grid, (b) skew grid, (c) triangular grid,(d) circular grid.
Before finding the finite difference solutions to specific PDEs, we will look at how
one constructs finite difference approximations from a given differential equation.This essentially involves estimating derivatives numerically. Let’s assume f(x) shown below:
Estimates for the derivative of f (x) at P using forward, backward, andcentraldifferences.
We can approximate derivative of f(x), slopeor the tangent at P by the slope of the arc PB, giving the forward-difference formula,
or the slope of the arc AP, yielding the backward-difference formula,
or the slope of the arc AB, resulting in the central-difference formula,
We can also estimate the second derivative of f (x) at P as
Any approximation of a derivative in terms of values at a discrete set of points is
called finite difference approximation.
The approach used above in obtaining finite difference approximations is rather
intuitive. A more general approach is using Taylor’s series. According to the wellknown
Upon adding these expansions,
where O(x)4 is the error introduced by truncating the series. We say that this erroris of the order (x)4 or simply O(x)4. Therefore, O(x)4represents terms thatare not greater than (x)4. Assuming that these terms are negligible,
and neglecting terms of theorder (x)3 yields
This shows that the leading errors of the order (x)2. Similarly, the forward and backward difference formula have truncation errors of O(x).
n calculated using PM coupling and p still calculated
as in equilibrium case (quasi-equilibrium approximation)
There are several criteria for the convergence of the iterative procedure when solving the Poisson equation, but the simplest one is that nowhere on the mesh the absolute value of the potential update is larger than 1E-5 V.
This criterion has shown to be sufficient for all device simulations that have been performed within the Computational Electronics community.
Objective: Speed, Accuracy at minimum cost
Complexity of linear solvers
Time to solve model problem (Poisson’s equation) on regular mesh
There are two schemes that are used in solving the coupled set of equations which comprises the Drift-Diffusion model:
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s3://commoncrawl/crawl-data/CC-MAIN-2018-34/segments/1534221211719.12/warc/CC-MAIN-20180817045508-20180817065508-00664.warc.gz
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CC-MAIN-2018-34
| 3,822
| 45
|
https://scholars.duke.edu/display/pub690400
|
math
|
Accurate, stable and efficient Navier-Stokes solvers based on explicit treatment of the pressure term
We present numerical schemes for the incompressible Navier-Stokes equations based on a primitive variable formulation in which the incompressibility constraint has been replaced by a pressure Poisson equation. The pressure is treated explicitly in time, completely decoupling the computation of the momentum and kinematic equations. The result is a class of extremely efficient Navier-Stokes solvers. Full time accuracy is achieved for all flow variables. The key to the schemes is a Neumann boundary condition for the pressure Poisson equation which enforces the incompressibility condition for the velocity field. Irrespective of explicit or implicit time discretization of the viscous term in the momentum equation the explicit time discretization of the pressure term does not affect the time step constraint. Indeed, we prove unconditional stability of the new formulation for the Stokes equation with explicit treatment of the pressure term and first or second order implicit treatment of the viscous term. Systematic numerical experiments for the full Navier-Stokes equations indicate that a second order implicit time discretization of the viscous term, with the pressure and convective terms treated explicitly, is stable under the standard CFL condition. Additionally, various numerical examples are presented, including both implicit and explicit time discretizations, using spectral and finite difference spatial discretizations, demonstrating the accuracy, flexibility and efficiency of this class of schemes. In particular, a Galerkin formulation is presented requiring only C0 elements to implement. © 2004 Elsevier Inc. All rights reserved.
Volume / Issue
Start / End Page
International Standard Serial Number (ISSN)
Digital Object Identifier (DOI)
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s3://commoncrawl/crawl-data/CC-MAIN-2019-47/segments/1573496669422.96/warc/CC-MAIN-20191118002911-20191118030911-00524.warc.gz
|
CC-MAIN-2019-47
| 1,867
| 6
|
https://mystery.sonoma.edu/resources/teachers/star2.html
|
math
|
Starmarket Worksheet 2
1. For what possible reasons could the companies be buying stars?
2.What evidence in the encyclopedia supports your hypothesis?
3.What evidence provided by the tools and data supports your hypothesis?
4. What company purchasing ideas did you exclude and why?
5. What roles do the stars studied play in the evolution of the Universe?
6. What is the best tool you used to prove your answer? Why?
7. What other ways do scientists use the tools that you used to solve Starmarket?
|
s3://commoncrawl/crawl-data/CC-MAIN-2023-50/segments/1700679100056.38/warc/CC-MAIN-20231129041834-20231129071834-00390.warc.gz
|
CC-MAIN-2023-50
| 498
| 8
|
https://www.tolearnenglish.com/cgi2/myexam/stats.php?id=107692
|
math
|
To go back to the exercise
Exercise "Agree or Disagree", created by here4u (a free exercise to learn English):
Results of the 7 532 people who have taken this test:
Average mark: 59 / 100 Share
Latest member with a 100/100 (perfect mark): icare29 / FRANCE, on Friday 21 May - 23:49:
"many thanks for your excellent exercise"
They got a perfect mark
Stats (7532 candidates)
Question 1 passed: 65.1 %
1) I think * the teacher to admit he has cheated. It's too humiliating for him.
Question 2 passed: 66.5 %
2) * coming here by ourselves was a mistake ?
Question 3 passed: 54 %
Of course, I * ! We shouldn't have done it!
Question 4 passed: 49.1 %
3) After being quite reluctant, my father * me his car but I will drive carefully.
Question 5 passed: 56.5 %
4) She * you about what should be done .... She discusses everything and everybody!
Question 6 passed: 67.4 %
5) You have to choose ! Say it clearly : * him or with me ?
Question 7 passed: 25.5 %
6) * more with you : all that you're saying here is wrong.
Question 8 passed: 68 %
7) He totally * you: he thinks she will succeed quite easily.
Question 9 passed: 48.8 %
8) You * such an expensive present !
Question 10 passed: 55.9 %
9) Everybody * such a declaration ! It's pure common sense!
Question 11 passed: 57.8 %
10) 'Mom, * let me go out tomorrow night?'
Question 12 passed: 49.5 %
'You must be kidding, girl! You know that * let you go out on a week day! '
Click here to go back to the exercise: Agree or Disagree
Other exercises to learn English
|
s3://commoncrawl/crawl-data/CC-MAIN-2021-39/segments/1631780056656.6/warc/CC-MAIN-20210919005057-20210919035057-00275.warc.gz
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CC-MAIN-2021-39
| 1,507
| 34
|
https://forum.duolingo.com/comment/33181388/Where-is-his-destination
|
math
|
Why Ke mana and not Di mana ?
I had the same question. "tujuan" is a goal, which is defined as the end toward which effort is directed. This "direction" is the reason why "ke" is preferred.
Why not "Di mana tujuan DIA"
Badly translated into English, Ke would be 'to where is his goal' and di would be 'at where is his goal'. So ke makes the movement and traveling of going to a destination more obvious.
So either translation would be right
dia tujuan di mana
This doesn't make sense. Di mana tujuannya should be correct.
Exactly what I said, Bij4
Either is right depending on context, yes?
|
s3://commoncrawl/crawl-data/CC-MAIN-2021-31/segments/1627046154126.73/warc/CC-MAIN-20210731203400-20210731233400-00632.warc.gz
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CC-MAIN-2021-31
| 590
| 9
|
https://slidetodoc.com/balancing-equations-balancing-writing-and-naming-equations-balancing-2/
|
math
|
- Slides: 51
Balancing Equations Balancing, Writing, and Naming Equations
Balancing Equations o Law of Conservation of Matter: n n n In a chemical reaction, matter can be neither created nor destroyed. In a chemical reaction, the amount of reactants equal the amount of products.
**Chemical Properties o Balloons can be filled with hydrogen gas (H 2) or helium gas (He) to make them rise. Helium gas is safer to use than hydrogen because hydrogen gas can burn in oxygen.
Corrosion o o o Corrosion is a chemical property. Corrosion is the process by which a material is broken down into new substances by reacting with substances in its environment. Example a rusting nail at the end of the nail, the metal is being broken down into a new substance, rust. Rust has a different physical property from the original metal. It is a different color, and it cannot conduct electricity the way the original metal could. A chemical property of the original metal is that it can be corroded by air.
Chemical Properties of Rust Fe Fe 02 + Fe Fe Iron = 02 + Fe 203 02 Oxygen = Rust
Corrosion o o o Not all metal can be corroded by air. The Statue of Liberty has reacted with the rainwater and air over time to go from a shiny copper color to a dull green color. It is made of copper, which will corrode in air. * A chemical property of copper is that is reacts with air to form green copper sulfate.
Corrosion o Gold is a metal that will not corrode in air. Some metals tarnish, or turn black when exposed to air. Corroding and tarnishing are chemical properties related to interactions with air.
* Properties o o o Gold (Au) Iron (Fe) The property of gold makes it different from iron it is because it does not rust.
Compounds and Formulas o o Compounds- elements can combine in different ways to form compounds. A compound is a type of matter that forms when two or more elements combine chemically. Unlike a mixture, the substances that join together to form a compound do not retain their individual properties. Example: Table salt is a compound that forms when sodium and chlorine combine chemically. Sodium is a metal that explodes when combined with water. Chlorine is a poisonous gas. However, when these elements combine together to form sodium chloride, they form the edible, white solid you know as table salt.
Chemical Formula o o When elements combine to form compounds, they combine in specific ratios. Example: When sodium and chlorine atoms combine to make salt, they combine in a 1: 1 ratio. There is one sodium atom for every chlorine atom in table salt. Every compound that is formed has a name and a chemical formula. The chemical formula of a compound tells you what elements have combined to make that compound and in what ratio they have combined. Example: water is a compound that is made up of hydrogen and oxygen atoms. When they combine chemically to make water, they combine in a 2: 1 ratio of hydrogen to oxygen. Two hydrogen atoms combine with every one oxygen atom.
A Water Molecule o O H H Water H 2 O A water molecule has the formula H 2 O. This formula tells you that the molecule has 2 hydrogen atoms and 1 oxygen atom.
*Subscript O H o o Water H 2 O o The chemical formula of water H 20, gives you this information. H is the chemical symbol for hydrogen, and the little number after the H is called the Subscript. *A subscript tells us how many atoms of that element are found in one molecule of a compound. For water, two hydrogen atoms are needed in each molecule, or unit, of water. 0 is the chemical symbol for oxygen. When there is no number it is understood that the subscript is simply 1. So there is only one atom of oxygen in the ratio. One atom of oxygen combines with two atoms of hydrogen to make water. With the ratios of atoms are changed, the compound they produce changes.
Subscript Cont. o Hydrogen peroxide H 202 H O O H o Hydrogen peroxide contains the same elements as water but in different ratios which form different molecules. Drinking water is essential for your survival, but hydrogen peroxide is poisonous if swallowed. The ratio of the elements in a compound is just as important as the identity of the elements in that compound in determining its physical and chemical properties.
Chemical Formulas o o o Carbon dioxide is a gas found in the air. Its chemical formula is C 02. How many different elements are in this formula? The answer is two carbon and oxygen. How many atoms of each element does it have? To answer his question, we look at the subscripts. Remember if there is no number after the element, it is understood to be 1. So there is 2 subscripts those are two oxygen atoms. How many total atoms are in one molecule of CO 2? There a total of three atoms: one carbon atom and two oxygen atoms.
Atoms o o How many atoms make up one molecule of methane? 5
Other Chemical Formulas
A. Balancing Steps 1. Write the unbalanced equation. 2. Count atoms on each side. 3. Add coefficients to make #s equal. Coefficient subscript = # of atoms 4. Reduce coefficients to lowest possible ratio, if necessary. 5. Double check atom balance!!!
B. Helpful Tips o o Balance one element at a time. Update ALL atom counts after adding a coefficient. If an element appears more than once per side, balance it last. Balance polyatomic ions as single units. n “ 1 SO 4” instead of “ 1 S” and “ 4 O”
Why is there a 2 after the oxygen? _________ Oxygen is diatomic What are all the diatomic elements? Br, I, N, Cl, H, O, F _________ 4 1 12 2 10 4 2 8
Yields Reactants Subscript Products Coefficient
*Examples o o *The chemical formula for sodium nitrate is Na. NO 3. It is used in explosives and also as a preservative in some foods. The elements that make up sodium nitrate is: sodium, nitrogen, and oxygen. *How many total atoms are in one molecule of sodium nitrate? Na. NO 3 n n n 5 *Ammonium perchlorate is used in rocket fuels. How many atoms are in the chemical formula for ammonium perchlorate, NH 4 CIO 4? 1
Balancing Equations o o Paraphrase: Law of Conservation of Atoms: n The number of atoms of each type of element must be the same on each side of the equation.
Balancing Equations n Hydrogen n H 2 o o o + oxygen + O 2 water H 2 O Hydrogen and oxygen are diatomic elements. Their subscripts cannot be changed. The subscripts on water cannot be changed.
Balancing Equation o Count the atoms on each side. n n Reactant side: 2 atoms H and 2 atoms O Product side: 2 atoms H and 1 atom O n H 2 + O 2 H 2 O
Balancing Equations o H 2 + O 2 H 2 O o If the subscripts cannot be altered, how can the atoms be made equal? o Adjust the number of molecules by changing the coefficients.
Balancing Equations o o o Reactants: 2 atoms of H and 2 atoms of O Products: 4 atoms of H and 2 atoms of O H is no longer balanced! n H 2 + O 2 2 H 2 O
Balancing Equations n 2 H 2 o o o + O 2 2 H 2 O Reactant side: 4 atoms of H and 2 atoms of O Product side: 4 atoms of H and 2 atoms of O It’s Balanced!
Balancing Equations n N 2 n o + H 2 Nitrogen + hydrogen NH 3 ammonia Count atoms. n n Reactants: 2 atoms N and 2 atoms H Products: 1 atom N and 3 atoms of NH 3
Balancing Equations o o Nothing is balanced. Balance the nitrogen first by placing a coefficient of 2 in front of the NH 3. n N 2 + H 2 2 NH 3
Balancing Equations o o Hydrogen is not balanced. Place a 3 in front of H 2. Reactant side: 2 atoms N, 6 atoms H Product side: 2 atoms N, 6 atoms H n N 2 + 3 H 2 2 NH 3
Balancing Equations o Ca 3(PO 4)2 + H 2 SO 4 + H 3 PO 4 Ca. SO 4 o Count atoms in the product. o Ca atoms – 1, S atom – 1, O atoms – 4; H atoms – 3, P atom – 1, O atoms - 4
Balancing Equations o A coefficient of 2 placed in front of H 3 PO 4 which balances both hydrogen and phosphate. o Ca 3(PO 4)2 + 3 H 2 SO 4 3 Ca. SO 4 + 2 H 3 PO 4
Balancing Equations n n o o o Cu + H 2 SO 4 Cu. SO 4 + H 2 O + SO 2 The sulfate group breaks up. Each atom must be counted individually. Ugh! Reactants: Cu – 1, H – 2, S – 1, O – 4 Products: Cu – 1, S – 1, O - 4, H – 2, O – 1, S – 1, O - 2
Balancing Equations o o o Sulfur is not balanced. Place a two in front of sulfuric acid. Count atoms: 2 H 2 SO 4 H – 4, S – 2, O 8 Cu + 2 H 2 SO 4 Cu. SO 4 + H 2 O + SO 2 o o
Balancing Equations o o Hydrogen needs to be balanced so place a 2 in front of the H 2 O. Count the number of atoms. Cu + 2 H 2 SO 4 Cu. SO 4 + 2 H 2 O + SO 2 o o
Balancing Equations o o Reactants: Cu – 1, H – 4, S – 2, O – 8 Products: Cu – 1, S – 1, O – 4, H – 4, O – 2, S – 1, O – 2 = Cu – 1, S – 2, H – 4, O – 8 o It’s balanced! Cu + 2 H 2 SO 4 Cu. SO 4 + 2 H 2 O + SO 2 o o
Balancing Equations o Balancing hints: n n Balance the metals first. Balance the ion groups next. Balance the other atoms. Save the non ion group oxygen and hydrogen until the end.
Balancing Equations o o o This method of balancing equations is the inspection method. The method is trial and error. Practice.
Writing and Naming n n o Nickel + hydrochloric acid Nickel(II) chloride + hydrogen Write the corresponding formula equation and then balance the equation.
Writing and Naming o o o Write each formula independently. Ignore the rest of the equation. Balance the equation after writing the formulas. Ni + HCl Ni. Cl 2 + H 2 Ni + 2 HCl Ni. Cl 2 + H 2 n n
Writing and Naming o Remember the diatomic elements: H 2, N 2, O 2, F 2, Cl 2, Br 2, and I 2.
Writing and Naming Cu + H 2 SO 4 n Cu. SO 4 + H 2 O + SO 2 n o o Balance the formula equation. Write the word equation.
Writing and Naming Cu + 2 H 2 SO 4 Cu. SO 4 + 2 H 2 O + SO 2 o o o Write the names: Cu by itself is just copper. Copper(I) or copper(II) would be incorrect. H 2 SO 4 should be named as an acid. Sulfuric acid
States of Matter o o o (g) – Gas (l) – Liquid (s) – Solid (cr) Crystal (aq) – Aqueous (water solution)
Counting Atoms 1) H 3 PO 4 2) 3 Na. OH 3) 2 K 2 C 2 H 3 O 2 4) Mg 3(PO 4)2
More Counting Atoms 1) 3 Al(NO 3)3 2) 3 Al 2(SO 4)3 3) 2 Ca(OH)2 4) 3 NH 4 NO 3
Balanced or not? o H 2 + O 2 o CH 4 + O 2 CO 2 + H 2 O o Mg + O 2 H 2 O Mg. O
Cellular respiration can be described by the following chemical equation: o o o C 6 H 12 O 6 + 6 O 2 glucose oxygen 6 CO 2 + 6 H 20 + ENERGY carbon dioxide water (ATP) Respiration Clip
o Photosynthesis can be described by the following chemical equation: o 6 CO 2 + 6 H 20 C 6 H 12 O 6 + 6 O 2 Photosynthesis Clip
Balancing Equations o Practice problems on board
|
s3://commoncrawl/crawl-data/CC-MAIN-2022-21/segments/1652662595559.80/warc/CC-MAIN-20220526004200-20220526034200-00295.warc.gz
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CC-MAIN-2022-21
| 10,401
| 51
|
https://brainmass.com/business/accounting/thiel-boots-overhead-rates-over-under-applied-overhead-336776
|
math
|
Cost of goods sold
direct materials 300,000
direct labor 160,000
est.overhead 240,000 700,000
Gross profit 300,000
Selling and adm expenses 175,000
Net income $125,000
Expected to sell 10,000 pairs of boot
est. of production employees will work 10,000
production equipment to operate 8,000
A. Compute the predetermined overhead rate for Thiel using the following three cost drivers: direct labors hours,direct labor dollars, and machine hours.
B. If actual labor costs were $170,000 for 10,500 direct labor hours and actual machine hours used were 7,800, what would be the applied overhead, using the three predetermined overhead rates computed in part A?
C. Compute the amount of over- or underapplied overhead, assuming that actual over-head is $229,000. You should assume that overhead was applied as computed from B.
Predetermined overhead rate = estimated overhead/cost driver
Direct labor hours:$240,000/10,000 hours = $24 per direct labor hour
Direct labor dollars: $240,000/$160,000 = $1.5 per direct ...
This solution discusses overhead rates and over or under applied overhead for Thiel Boots.
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s3://commoncrawl/crawl-data/CC-MAIN-2020-29/segments/1593655878639.9/warc/CC-MAIN-20200702080623-20200702110623-00164.warc.gz
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CC-MAIN-2020-29
| 1,103
| 17
|
https://www.instructables.com/community/How-to-solve-multiple-maths-operation-using-Digita/
|
math
|
How to solve multiple maths operation using Digital roots Answered
I have a question.
(560 / 32 )x (720 / 48 )= ?
a) 262.5 b) 255 c) 263.5 d) 271.25
Is there any way to get correct answer using any shortcut or digital roots? I want to do it fast
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s3://commoncrawl/crawl-data/CC-MAIN-2021-17/segments/1618038065492.15/warc/CC-MAIN-20210411204008-20210411234008-00582.warc.gz
|
CC-MAIN-2021-17
| 245
| 5
|
https://forum.sambapos.com/t/ticket-divided-by-plate-of-a-table/24567
|
math
|
Can I configure the following use case in sambapos?
At a table 3 people sit, the waiter attends the table and asks each one what he wants to eat and sends the kitchen ticket as follows:
1 order of fries
Note: No mayonnaise
1 Club Sandwich
Note: Without tomato
Example of Ticket for kitchen, only food. The idea is that the cook or chef knows how to place the plate for each diner and make the service more efficient.
Not the truth, I have not seen the order label, I apologize if it is an issue that has already been discussed. I will investigate on my side, and if it is in your possibility to share the subject, I will be very grateful.
On your kitchen printer template, there is an option to print by a group. If you used the above tutorial, you would use:
[ORDERS GROUP|ORDER STATE:SeatPosition]
or [ORDERS GROUP|ORDER STATE:SeatPosition:5,4,3,2,1]
I’m not sure if the top one will work, the states may have to be defined as in the 2 option.
With the 2 option, you can specify what order you want printed based on the maximum seating you have at 1 table. If you have 10 seats at one table it could look like any variation of this: 10,8,6,4,2,9,7,5,3,1
The second part of the animation where the ticket gets split it just an extra option to give each seat/plate their own receipt. It would not be needed.
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s3://commoncrawl/crawl-data/CC-MAIN-2022-33/segments/1659882573163.7/warc/CC-MAIN-20220818033705-20220818063705-00191.warc.gz
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CC-MAIN-2022-33
| 1,309
| 14
|
https://mattclay.hosted.uark.edu/TopologySeminar/Spring2014/140306.html
|
math
|
Abstract: We consider Legendrian contact homology of a Legendrian surface, L, in ℝ5 (or more generally in the 1−jet space of a surface). Such a Legendrian, L, can be conveniently presented via its front projection which is a surface in ℝ3 that is immersed except for certain standard singularities.
Legendrian contact homology associates a differential graded algebra (DGA) to L. In this setting, the construction of the DGA was carried out by Etnyre−Ekholm−Sullvan with the differential defined by counting holomorphic disks in ℂ2 with boundary on the Lagrangian projection of L. Subsequent work of Ekholm, allows for the differential to be computed with a count of certain gradient flow trees replacing the holomorphic disks. This simplifies matters by replacing a PDE problem with an ODE problem. However, the required gradient flow trees are still complicated global objects, so that computing the differential in this manner for a given Legendrian is far from algorithmic.
I will discuss work in progress with Mike Sullivan. The goal is to give a computation of the DGA of L by starting with a cellular decomposition of the base projection (to ℝ2) of L that contains the projection of the singular set of L in its 1−skeleton. Generators are associated to each cell, and the differential is determined in a formulaic manner by the nature of the singular set above the boundary of a cell.
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s3://commoncrawl/crawl-data/CC-MAIN-2022-27/segments/1656103619185.32/warc/CC-MAIN-20220628233925-20220629023925-00797.warc.gz
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CC-MAIN-2022-27
| 1,407
| 3
|
https://physicalscs.unn.edu.ng/statistics-programmes/
|
math
|
TYPES OF DEGREE PROGRAMMES
The department of statistics offers the following degree programmes:
(a)B.Sc degree in Statistics
(b)B.Sc Combine degree in statistics/Mathematics, statistics/economics, statistics/computer science and statistics/Education in collaboration with Departments of Mathematics, Economics, computer Science and Education.
The normal duration for the B.Sc degree is four years for candidates who enter by entrance examination(JAMB) and three years for direct entry candidates.
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s3://commoncrawl/crawl-data/CC-MAIN-2020-16/segments/1585370506988.10/warc/CC-MAIN-20200402143006-20200402173006-00177.warc.gz
|
CC-MAIN-2020-16
| 496
| 5
|
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