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https://entri.app/posts/898-%3Cp%3ECan%20anyone%20give%20me%20solution%20for%20Q36%20%C2%BF/?%3C/p%3E
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math
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Can anyone give me solution for Q36 ¿?
I surely hope the answer is 'c'.
I hope the answer is c
I hope its c
Is diabetes can be prevented
Ee questionil pkb value kooduthal aayaalum w...
Sent the digestive system videos to me
Provide brefily about bio iam pure sci stude...
What are isotopes?
Nda stand by
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s3://commoncrawl/crawl-data/CC-MAIN-2018-39/segments/1537267156314.26/warc/CC-MAIN-20180919235858-20180920015858-00314.warc.gz
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https://avesis.metu.edu.tr/yayin/e33affd9-d00c-45f0-9e9b-95374cbd2dc9/the-multi-resource-agent-bottleneck-generalised-assignment-problem
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math
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In this study, we consider the multi resource agent bottleneck generalised assignment problem. Our aim is to minimise the maximum load over all agents. We take our motivation from an assignment problem faced in heating, ventilating and air conditioning sector. We study the linear programming (LP) relaxation of the problem. We use the optimal LP relaxation solutions in our branch and bound algorithm while defining bounding and branching schemes. We find that our branch and bound algorithm returns optimal solutions to the problems with up to 60 jobs when the number of agents is 5, and up to 30 jobs when the number of agents is 10, in less than 20 minutes. To find approximate solutions, we define a tabu search algorithm and alpha approximation algorithm. Our computational results have revealed that both algorithms can find high quality solutions to large sized instances very quickly. To the best of our knowledge our study is the first reported attempt to solve the problem. We hope our study fills an important gap in the literature.
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s3://commoncrawl/crawl-data/CC-MAIN-2023-50/segments/1700679100989.75/warc/CC-MAIN-20231209233632-20231210023632-00444.warc.gz
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CC-MAIN-2023-50
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https://www.hackmath.net/en/examples/equation?page_num=47
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math
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Equation - examples - page 47
- CuSO4 mixture
How many grams of solid CuSO4 we have to add to 450g of 15% CuSO4 solution to produce a 25% solution?
- Temperature 2
Sunday's high temperature was 3 degrees higher than Saturday's. On Monday, the temperature fell 5 degrees, then rose 7 degrees on Tuesday and 4 more on Wednesday. Then it fell 17 degrees to a record low of 31 on Thursday. What was the temperature on Saturd
- My father
My father has a big farm. 6/8 of it were planted with mango trees, 1/2 of the remainder are guava trees and the rest 10 trees are santol trees. What is the number of all trees?
- I think
I think a number. When I multiply it by five, and after that I subtract 477, I get the same number as if I multiplied it twice. What number do I think?
- The train
The train passed the observer in the 20s and passed through a 1500m tunnel in 2 minutes. Calculate the speed (km/h) and train length.
- Car driver
The car driver is in town A and is scheduled to be in town B at a specified hour. If it travels at an average speed of 50km/h, it will arrive in city B 30 minutes later. But if he travels at an average speed of 70km/h, he would arrive half an hour earlier
- Two pipes
How long will the pool be filled with a double supply pipe if it takes the pool to fill the first pipe by 4 hours longer and the second pipe 9 hours longer than both pipes open at the same time?
- Three painters
One painter would have painted the fence for 15 hours, the second in 12 hours. The plot had to be painted in four hours, so they called the third one, and all worked together. For what time would the third painter paint fence the fence alone?
How many ml 30% of peroxide (H2O2) should be poured into 100ml H2O to give a 20% solution?
- Diagonals of a rhombus 2
One diagonal of a rhombus is greater than other by 4 cm . If the area of the rhombus is 96 cm2, find the side of the rhombus.
The seamstress cut the fabric into 3 parts. The first part was the eighth fabric, the second part was three-fifths of the fabric and the third part had a length of 66 cm. Calculate the original length of the fabric.
One-eighth of the trees in the fruit plant in winter froze and one-twelfth of damaged disease and pests. Healthy trees remained 152. Is it enough to supply 35 trees to restore the original number of trees in the orchard?
- Sale discount
The product was discounted so that eight products at a new price cost just as five products at an old price. How many percents is the new price lower than the old price?
- Our house
Our house would paint four painters in 14 days. How long could it paint five painters? How long will it take if two other painters will come to help after 5 days?
Mother bought 21 desserts on the occasion of Mirka's birthday one tips was 9 CZK and the kremlin cost 12 CZK. For all desserts, she paid 213 CZK. How many kremlins and how many tips mums did buy?
- Average age
The company of five people has an average age of 46 years. The average age of the first four is 43 years. How many years has the fifth member of this company?
- Exponential equation
Determine the value of having y in the expression (3^y): (4^-1)=36.Y is a natural number greater than zero.
- Pupil age
I am a pupil of the primary school, I spent 1/4 of my age on the exercise of parents with children, 1/3 on drawing, 1/6 on flute. I did not have a ring for the first three years of my life and never went to two rings at once. How old am I?
- Two diggers
Two diggers should dig a ditch. If each of them worked just one-third of the time that the other digger needs, they'd dig up a 13/18 ditch together. Find the ratio of the performance of this two diggers.
3400 eggs sliced hens for February and March. We have to calculate how many hens can make 3400 eggs when one hen give 2 eggs a day for 59 days.
Do you have a linear equation or system of equations and looking for its solution? Or do you have quadratic equation?
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https://studysoup.com/tsg/1031660/statics-and-mechanics-of-materials-1-edition-chapter-12-problem-12-79
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math
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Determine (a) the equations of the shear and bending-moment curves for the beam and loading shown, (b) the maximum absolute value of the bending moment in the beam.
Step 1 of 3
IT 100 (10/410/6) A. Storage & Databases a. Primary Storage (temporary storage)loses content when computer loses power. i. Volatile Storage ii. Temporary iii. Refers to random access memory (RAM) b. Secondary Storage (permanent storage) permanently saves info for future use. i. Nonvolatile storage stores programs & data as opposed to temporary RAM. ii. Characteristics 1. Media or medium what holds data 2. Capacity amount of storage held 3. Storage devices hardware that reads data 4. Access speed measures amount
Textbook: Statics and Mechanics of Materials
Author: Ferdinand Beer, E. Russell Johnston, John T. Dewolf, David Mazurek
The full step-by-step solution to problem: 12.79 from chapter: 12 was answered by , our top Engineering and Tech solution expert on 03/16/18, 04:40PM. The answer to “Determine (a) the equations of the shear and bending-moment curves for the beam and loading shown, (b) the maximum absolute value of the bending moment in the beam.” is broken down into a number of easy to follow steps, and 28 words. This full solution covers the following key subjects: . This expansive textbook survival guide covers 15 chapters, and 1247 solutions. Statics and Mechanics of Materials was written by and is associated to the ISBN: 9780073380155. Since the solution to 12.79 from 12 chapter was answered, more than 226 students have viewed the full step-by-step answer. This textbook survival guide was created for the textbook: Statics and Mechanics of Materials, edition: 1.
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http://selangor.ga/top2396-penyelesaian-integral-x-sin-2x-dx.html
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math
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The integral of many functions are well known, and there are useful rules to work out the integral of more complicated functions, many of which are shown here.sin(x) dx. Integrate x sin(2x) dx?Im trying to do a volume generated around an axis question and Im not sure if Ive got the integral right xsin2x as x and sin2x - note, the dx will go with whichever piece you select as the dv). Get an answer for Evaluate the integral integrate of (sin(x))2(cos(x))4 dx and find homework help for other Math questions at eNotes first multiply out the expression: ( sin2x)2 2sin2x cos2x (cos2x)2 2sin2x cos2x can be rewritten as sin4x using the double. Ok, I know that sin 2x can be substituted out for 2 sin x cos x. so now I have the Integral of (sin x ) ( 2 sin x cos x ) dx which is 2 sin2x cos x dx If I use integration by parts with the u and dv, I find myself right back againcan you help. 05 integral parsial. 1. Bentuk sin mx cos nx dx, sin mx sin nx dx, cos mx cos nx dx Untuk menyelesaikan integral tersebut, gunakansehingga x 2 a 2 a tan t x a sec t. 4. Integral Parsial Formula integral parsial: u dv uv vdu Note: pilih u yang turunannya lebih sederhana. 2. Relevant equations I know the integral of sin(x)dx -cos(x) C. 3. The attempt at a solution What I did was to say that the integral is -cos(2x) C, which isnt the correct answerI should have gotten -1/2(cos( 2x)) C Integral X-5 Lnx Dx?Integration by parts , please I need all of them with their answers!!. Example: sin3(x) sin2(x) sin(x). Hence the given integral may be written as followsWe now let u cos(x), hence du/dx -sin(x) or -du sin(x)dx and substitute in the given intergral to obtain. Integration by parts is much easier to do in terms of functions and derivatives rather than differentials, yet one answerer has chosen the more complicated way. Integrate the original integrand by parts: xsin(2x) dx Let f(x) sin(2x) f(x) -cos( 2x) / 2 Let g(x) x g(x) 1 f(x)g(x) dx f(x)g(x) - f(x)g(x) Get an answer for what is the integral of xe2x ? and find homework help for other Math questions at eNotes.Integral .Solve the integral f(x)lnx .
1 educator answer. Given the integrals A and B, find AB? AIntegral xcos2 xdx B Integral xsin2x dx. You can use the identity: sin(2x)2sin(x)cos(x). Then use a u-substitution with u1cos 2(x). Penyelesaian integral sin2 x dx is the worlds number one global design destination, championing the best in architecture, interiors, fashion, art and contemporary. In this video, I demonstrate how to integrate sin3(x)cos4(x) by reserving a factor of sin(x) and converting the integrand into powers of cos(x). Math2.org Math Tables: Table of Integrals Power of x. x n dx x n1 (n1)-1 C (n -1) Proof: cos x dx sin x C Proof: csc x. How to integrate sin6 x cos2 x dx. I do not know of an easy way to evaluate this integral.sinn x dx 1 cos x sinn1 x n 1 sinn2 x dx nn. where n 2 is an integer, which is proved as Example 6 in Section 6.1.
, Integral x2 sinx dx. 2007-07-24. Integration by parts solution. See www.midnighttutor.com for all of our free videos.In this video I use complex analysis to calculate the integral of sin(x2) from 0 to infinity. What is the integral of sin(2n) x dx from x 0 to x pi? Sect 7 2 13, integral of xsin2x - Duration: 3:27. 2 Answers ? Free Online Integral Calculator allows you to solve definite and indefinite integration problems. Date: 11/10/97 at 12:58:17 From: Doctor Anthony Subject: Re: Integration of Sin(x2). You can express sin(x) as an infinite series.Let I INT(0 to infinity)[e(-x2/2).dx]. This cannot be evaluated using elementary methods, so we proceed as follows Free integral calculator - solve indefinite, definite and multiple integrals with all the steps. Type in any integral to get the solution, steps and graph.intab x2dx. Integral of sin2 (x).cos2 (x) dx? recall the double-angle identity sin(2x) 2 sinx cosx x cos 2x dxby parts If somebody could do it in detail and show the workings i would be mosdt grateful. integral of sqrt (1cos2 x) dx. any ideas :? whats the substitution here ?Is the full problem youre solving: f(x)sin x Find integral of sqrt(1 f(x)) dx ? Or, do you have to do anything earlier than that? Problem Answer: The integral of the trigonometric function is (1/2)(e( sin 2x)) C. Solutiondiv.feedburnerFeedBlock ul li background: E2F0FD list-style-type: none margin:0 0 5px 0px padding:5px 5px 5px 10px !important border: 1px solid 0080ff border-radius:8px sin6 xdx Z (sin2 x)3 dx If this is your first visit, be sure to check out the FAQ by clicking the link above. William Mccoy, A former high school math teacher (Grades 9, 10, and 11). So the integral becomes: compute an improper integral. You cannot directly integrate sin2(x). Use trigonometric identities and calculus substitution rules to solve the problem. Step 1. Use the half angle formula, sin2(x) 1/2(1 - cos(2x)) and substitute into the integral so it becomes 1/2 times the integral of (1 - cos(2x)) dx. Integral of the product of sine and cosine (largeintnormalsize sin xcos x,dx largefrac14normalsizecos2x C). This video is about integrate sin2 x dx.Integral of sin2xcosx vs integral of sin2x - Продолжительность: 3:23 blackpenredpen 141 307 просмотров.Integration video Class for IIT JEE exams preparation and to help CBSE, Intermediate students covering of Overview of Integration, Important term in Integration, Methods of Integration, Method 1- Integration by Substitution, Properties of Indefinite Integrals, ProblemsProblem on eax sin bx dx. The same approach works for any odd power of sin(x) (or cos(x)), only the resulting expressions get slightly more complicated. Integrate sin(-1) x dx. This is a solution to the question, which I found on the web. The only bit Im not sure of, is the transition from the 3rd last line to 2nd last line (highlighted in bold).let u 1-x du -2x dx x dx (-1/2)du. Type in any integral to get the solution, free steps and graph The problem statement, all variables and given/known data Integral of sin(x) sin(x1) dx from 0 to 2pi. The answer that I got is -pi/4. 0. Calculus Introduction to Integration Integrals of Trigonometric Functions. sin2x You get this by using Integration by Parts. Page 1 of 2 1 2 Next > Feb 24, 2005 1 you get the Taylor series for the result of the integral. xsin(2x) dx (-1/2)Use the half angle formula, sin2(x) 1/2(1 - cos(2x)) and substitute into the integral so it becomes 1/2 times the integral of (1 - cos(2x)) dx. For integrals of the form sin(mx) sin(nx)dx.As an application of the previous example we compute the integral. sin2(x) cos4( x)dx. We start by using double angle formulas. Popular questions from Integrals. Rahul Pillai. how to integrate. f (log( sin x ))dx. Varun Nagarajan. what is integral of log(x)? Lily S. what is the ILATE RULE. so 2x cos(x2) dx sin(x2) C. Even when the chain rule has produced a certain derivative, it is not always easy to see.Since we have exactly 2x dx in the original integral, we can replace it by du How do you integrate sin(2x-1)? Table of Integrals Basic Forms Z xndx 1 n 1 xn1 (1) Z 1 x dx lnjxj (2) Z udv uv Z vdu (3) Z 1 ax b dx 1 a lnjax bj (4) Integrals of Rational Functions Z 1 Write back if you need more help, Penny . Use that sin2(x) 1/2 - 1/2 cos(2x). You can then calculate te integral of x cos(2x) using partial integration, or using this trick: The integral of sin(px) is -1/p cos(px). 2 1 cos 2x 2 TRIGONOMETRIC INTEGRALS integrate by using the formula established in Example 5 in Section 5.5: y tan x dx ln sec x C tan x u sec x Answers.
com WikiAnswers Categories Science Math and Arithmetic Calculus Integrate sin x cos 2x? I think 5xsin5x-1 cant see y it would be Chapter 8 Application of Integrals Class 12. Cha[pter 9 Differential Equations Class 12.Next: Misc 32. Chapter 7 Class 12 Integrals. Serial order wise. Miscellaneous. Answer: int xsin(x2)dx-(1/2)cos(x2) k.What are characteristics of domain eukarya? Bio. How do you integrate x /(x1)dx? Proofs: Integral sin, cos, sec2, csc cot, sec tan, csc2.For each of these, we simply use the Fundamental of Calculus, because we know their corresponding derivatives. cos( x) sin(x), cos(x) dx sin(x) c. Get the answer to Integral of sin(x)2 with the Cymath math problem solver - a free math equation solver and math solving app for calculus and algebra. Integral Challenge Problems. 1. sin1 x 2 dx. What is the integration of tan2x solution?What is a graph for sin 2x? In a typical integral of this type, you have a power of x multiplied by some other function (often ex, sin x, or cos x). Let u be the power of x and v be the other function so that integrating by parts decreases the power of x. Example 1. Compute x sin x dx. Dear Mithresh. (sin8x-cos8x)/(1-2sin2xcos2x) dx.Integrate x-1/x4 x1dx Help me pls to solve this Answer Earn Cool Goodies. Please help me with the following integral please simplify and then solve. In mathematics, there are several integrals known as the Dirichlet integral, after the German mathematician Peter Gustav Lejeune Dirichlet. One of those is the improper integral of the sinc function over the positive real line, This integral is not absolutely convergent 18.104.22.168. Integrals of Products of Sines and Cosines. We will study now integrals of the form If all the exponents are even then we use the half-angle identities. Example : sin2 x cos2 x dx . To integrate sin2x, also written as sin2x dx, and sin 2x, we usually use a u substitution to build a new integration in terms of u.We get this by replacing 2x with u, and replacing dx with du. We move the outside of the integral as it is simply a multiplier. Find the indefinite integral sin4x cos2x dx? Ask for it or check my other videos and playlists! what what is integral of log(x)????? Chat or rant, adult content, spam, insulting other members,show more. Hint: Use a trigonometric identity to express sin 3x in terms of sin and cos, x and 2x. Follow Math Help Forum on Facebook and Google integral e2xsin3x dx. sin4x / cos2x dx: whtz the integral of above question.solve and show workings:dy/dxcosx.cosxsinx(-sinx).
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http://psych.fullerton.edu/mbirnbaum/web/Say1.htm
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math
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Conjecture: All Cards with an Even Number on one side have a Vowel on the Other.
Thus, if the 1 had an A on the other side, it would be ok. If the 1 had a consonant, like B, on the other side, it would also be ok. The conjecture does NOT say that all odd numbers have consonants. "All dogs have noses" does NOT imply that anything that is NOT a dog does NOT have a nose. We do not need to turn over the 1, because the conjecture did not specify what is on the other side of an odd number.
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s3://commoncrawl/crawl-data/CC-MAIN-2019-09/segments/1550247487595.4/warc/CC-MAIN-20190218155520-20190218181520-00464.warc.gz
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https://vintagesteelfenders.com/mudguards/2017/12/12/monopole-1924-front
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math
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Now we're getting into some rare bikes. The Monopole brand emerged on a motorized cycle from Coventry, England briefly in 1902 and then 1912 intermittently through to 1927. . This guard is copied from a 1924 2-stroke Monopole vintage motorcycle.. The sample, shown in the pictures, was in good condition and had a finished width of 4". The finished mudguard includes 2 riveted brackets, two valances and fork relief pressings.
Price as pictured is $520 (+gst if applicable) #09MONFF-1
#09BSAFF-3 BSA motorcycle front mudguard or fender for Model K veterans
#16INDFF-3 Indian Powerplus front fender / mudguard 1917-1918
#15INDFF-1 Indian Model O valanced front fender with Panama Hat profile.
#15INDRF-1 Indian Rear fender for a 1917 Model O twin
#16INDFF-2 Indian Big Twin 1914 valanced front fender with brackets
#16INDRF-1 Veteran Indian Big Twin Rear fender
#18 blank American Universal Veteran
#04ARIFF-1 Ariel 1915 Veteran motorcycle front mudguard
#04AUSFF-1 JAP engined, Australian built, 1912 motorcycle, valanced front mudguard
#10B&BFF-1 Veteran B & B motorcycle front mudguard / fender
#10B&BRF-1 Veteran B & B motorcycle Rear mudguard / fender
#04WBRARF-1 Bradbury 1912 veteran motorcycle rear mudguard
#16BRORF-1 Brough 1915 motorcycle Front mudguard
#16BROFF-1 Veteran Brough motorcycle front mudguard
#38BSARF-1 BSA Veteran 1912 Rear Mudguard with Belt rim
#04BSAFF-2 BSA Veteran front mudguard / fender 1912
BSA 1911 Front mudguard
#10DELRF-1 & #10DELFF-1 Healing's De Luxe motorcycle mudguards front and rear.
#02WDOURF-2 Veteran 1914 Douglas motorcycle Rear mudguard copied from Finland
#02WDOUFF-1 Veteran Douglas fully valanced Front guard, 1914
#02WDOURF-1 Veteran Douglas Rear fully valanced mudguard, copy of 1914 model, will suit others
#04EWBRF-1 Australian built Veteran EWB motorcycle rear mudguard
#04EWBFF-1 Veteran EWB motorcycle Front mudguard, Australian Made 1910-1918
#03FLY Flying Merkel Veteran blank
#14FLY Flying Merkel 1915 veteran motorcycle mudguard
#02FNB Blank guard for FN with no finishing detail.
#21HARFF-1 veteran Harley Davidson rear fender / mudguard 1914 / 1915
#06HAR Harley Davidson fender to suit models from 1909 to 1913
#18HENRF-1 Henderson 1911-1917 long Rear fender
#18HENFF-1 Henderson 1917 Valanced front fender
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s3://commoncrawl/crawl-data/CC-MAIN-2019-43/segments/1570987824701.89/warc/CC-MAIN-20191022205851-20191022233351-00354.warc.gz
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CC-MAIN-2019-43
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https://www.physicsforums.com/threads/frequency-away-from-an-oscillating-body.684390/
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math
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This is the set up to the question that we got for homework: Pit and Plank. A wooden plank is placed over a pit that is 5.00 m wide. A physics student stands in the middle of the plank and begins to jump up and down such that she jumps upward from the plank two times each second. The plank oscillates with a large amplitude, with maximum amplitude at its center. Part A) Asks : What is the speed of transverse waves on the plank? Answer: 20m/s Part B) At what rate does the student have to jump to produce large-amplitude oscillations if she is standing 1.25 m from the edge of the pit? (Note: The transverse standing waves of the plank have nodes at the two ends that rest on the ground on either side of the pit.) -Part B is where I am having issues. I tried using the added length and the same speed, the offset length and same speed, and the original length minus the new length with the same speed and nothing has produced what it is looking for. Please help?
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s3://commoncrawl/crawl-data/CC-MAIN-2018-30/segments/1531676591497.58/warc/CC-MAIN-20180720041611-20180720061611-00078.warc.gz
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http://mathematicsforstudents.wordpress.com/
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math
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This year you can even use the Desmos API …
A new slideshow has been added to the page demonstrating WolframAlpha syntax. WolframAlpha can be very useful for checking for example normal probabilities. Each query as you will see in the slides is illustrated with a diagram. It is always useful to sketch a diagram when solving any normal distribution problems.
Explore transformations of graphs with the Desmos Graphing Calculator.
(See also Learning to use the Desmos Graphing Calculator)
Try the examples here and experiment with the outstanding (free) Desmos graphing calculator.
The way to improve your mathematical skills is to do lots of questions (then do some more!) You need to apply what you know and just reading your notes will not help you do that. Worked examples can be very helpful – particularly if you cover up the solution and try answering the question yourself first.
If you are looking for questions the following sites provide many for you.
Maths Centre (age 16+)
An extensive collection of very clear notes and other resources are available from the mathcentre. There are many very clearly worked examples, also exercises (with answers). Check the resource types, choosing Practice & Revision for example would lead you to this Calculus Refresher (under the Chain rule) which is a whole workbook of mixed calculus examples. mathtutor provides mathcentre resources conveniently structured as a course.
Just the Maths (age 18+)
Just the Maths by Tony Hobson is another extensive collection of notes which include numerous worked examples and also exercises to try (with answers). These notes are very useful for students in their last years at school and at university.
The Maths Teacher (age 11-17)
David Smith’s site, The Maths Teacher has an extensive collection of videos to help you study Mathematics. GCSE (age 14-16, though many of these resources would be helpful for younger students also) and A-Level (age 16-18) lessons are available. For each topic not only is a video available but also a transcript and exercises with solutions. This makes the site ideal for revision – you have the choice of perhaps just trying the exercises or if you feel you need more help you can watch the video – whatever is right for you.
Diagnostic Questions (Craig Barton & Simon Woodhead) (age 11 – 16+)
A totally brilliant site – thousands of multiple choice questions with your misconceptions anticipated. Try some diagnostic questions (all multiple choice) to check your understanding.
BBC Sites (ages 5 to 18)
All the BBC sites have quizzes and/or tests for you to try as well as notes and examples.
BBC Skillswise although aimed at adults, this site has information on basic Mathematics (and English) skills useful for any age.
BBC Higher Maths (age 17+)
Scroll down this page to see all the material available for students of all ages. The student texts include worked examples in every section. The texts also have exercises which are usually password protected. (Schools can obtain the password from CIMT). Note in particular the Interactive Material (examples with online checking of answers for Year 7 | Year 8 | Year 9 (have a look at the topics here which may be useful for slightly older students also).
If you choose the GCSE course material for example and scroll down the page you will see all the pupil textbook chapters.
Trinity School have very helpful Mathematics resources – many examples for you to try (answers included)
If you are trying any exercises you can obviously check the answers given in the notes; remember that you can also check your answers with WolframAlpha. You could make up questions of your own and check the answers on WolframAlpha, for example suppose you want to make sure you can multiply out brackets – make up your own question (writing questions is actually a good way to check your understanding), for example multiply out (x+3)(x+2), write your answer, then check it on WolframAlpha. Perhaps some calculus? Differentiate sinxcosx wrt x.
On the subject of WolframAlpha, there are several slideshows on the WolframAlpha page on this blog to help you get used to the syntax.
An updated version of the 11 commandments, which seems appropriate at this time of year!
If you are feeling a little unsure on identifying the equation of a straight line then use this Desmos graph and experiment by changing the gradient, intercept or points marked on the line. The image above shows the line y=2x+1. We can see that the intercept is 1 (where the line crosses the y axis) and the gradient is 2. Looking at the graph we can see that the gradient is positive and you can verify that the gradient is 2 by dividing the difference between the y coordinates (6 in this image) by the difference in the x coordinates (3 in this image). Try moving the points, you will see that this ratio remains constant.
Compare the second image. We can see that the intercept is 1. Looking at the slope, the gradient is positive. The gradient is given by 2÷4 = 0.5. So the equation of the line is y = 0.5x + 1.
In the third example; looking at the slope of the line we can see it is negative. The gradient is given by 6÷2 which is 3 and the line crosses the y axis at 2 giving the equation of the line as y = ─3x + 2
Since writing this post Desmos have taken the page and created a superior version!
Direct link to TED video
To quote Angela Lee Duckworth:
“Grit is passion and perseverance for very long-term goals. Grit is having stamina. Grit is sticking with your future, day in, day out, not just for the week, not just for the month, but for years, and working really hard to make that future a reality. Grit is living life like it’s a marathon, not a sprint.”
The following resources will help you practise solving equations.
subtangent.com – Linear Equation Calculator
Choose the type of equation you require then the sequence of operations required to solve the equation.
Select Do it after each operation, for example -32 Do it were the keys selected to start the above problem.
The slideshow below shows how to use the calculator to solve equations where the unknown is on both sides.
The next sites work in a similar way to the subtangent resource.
There are 4 levels to choose from: the level 1 equations are of the type ax = b,
level 2, x±c = d, level 3, ex±f = g and level 4, hx±i = hx±j = k.
Choose the series of operations you require to solve the equation selecting apply at each stage to see the result of your chosen operation.
Choose numbers to add and subtract integers and letters to add and subtract variables.
Remember you can use WolframAlpha to check your solution to any equation, see for example this link which checks the equation 2x+7=11.
To learn more about using WolframAlpha to check your work see the slideshows here.
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s3://commoncrawl/crawl-data/CC-MAIN-2014-10/segments/1393999669442/warc/CC-MAIN-20140305060749-00037-ip-10-183-142-35.ec2.internal.warc.gz
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CC-MAIN-2014-10
| 6,816
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https://papers.ssrn.com/sol3/papers.cfm?abstract_id=1212523
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math
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Weather Derivative Pricing and the Modelling of Trends: Objective Bayesian Versions of the Flat-Line, Linear Trend and Damped Linear Trend Models
23 Pages Posted: 9 Aug 2008
Date Written: August 8, 2008
Published methods for the pricing of weather derivatives are based on classical statistics, in that the predictions of the distributions of weather indices that they use are based on best estimates of model parameters. It is likely that such methods do not accurately capture the true uncertainty because they either ignore or approximate parameter and model uncertainty. In this article we derive the objective Bayesian versions of the flat-line and linear-trend models. The use of objective Bayesian statistics allows us to incorporate parameter uncertainty into the predictive distribution in a simple way. The result is a change in the shape of the predictive distribution, but no change in the predicted mean and variance, when compared with comparable classical statistical methods. We also derive a Bayesian version of the damped linear-trend model, which, in a limited sense, also incorporates model uncertainty.
Keywords: weather derivatives, trends, bayesian statistics
JEL Classification: G12
Suggested Citation: Suggested Citation
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s3://commoncrawl/crawl-data/CC-MAIN-2024-10/segments/1707947476442.30/warc/CC-MAIN-20240304101406-20240304131406-00118.warc.gz
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CC-MAIN-2024-10
| 1,245
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https://exclusivewritings.com/2023-fin-534-midterm-exam-1-1-of-the-following-investments-which-would-have-the-lowest-present-value-assume-that-the/
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math
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FIN 534 Midterm Exam 2023 Business & Finance
2023 FIN 534 Midterm Exam 1 1 Of the following investments which would have the lowest present value Assume that the
FIN 534 Midterm Exam 1
1. Of the following investments, which would have the lowest present value? Assume that the effective annual rate for all investments is the same and is greater than zero.
2.You plan to analyze the value of a potential investment by calculating the sum of the present values of its expected cash flows. Which of the following would increase the calculated value of the investment?
3. Which of the following statements regarding a 20-year monthly payment amortized mortgage with a nominal interest rate of 10% is CORRECT?
4. Which of the following statements is CORRECT, assuming positive interest rates and holding other things constant?
5. You are considering two equally risky annuities, each of which pays $25,000 per year for 10 years. Investment ORD is an ordinary (or deferred) annuity, while Investment DUE is an annuity due. Which of the following statements is CORRECT?
6. Ellen now has $125. How much would she have after 8 years if she leaves it invested at 8.5% with annual compounding?
7. Which of the following statements is CORRECT?
8. Bond A has a 9% annual coupon while Bond B has a 6% annual coupon. Both bonds have a 7% yield to maturity, and the YTM is expected to remain constant. Which of the following statements is CORRECT?
9. Which of the following statements is CORRECT?
10. Bonds A and B are 15-year, $1,000 face value bonds. Bond A has a 7% annual coupon, while Bond B has a 9% annual coupon. Both bonds have a yield to maturity of 8%, which is expected to remain constant for the next 15 years. Which of the following statements is CORRECT?
11. A Treasury bond has an 8% annual coupon and a 7.5% yield to maturity. Which of the following statements is CORRECT?
14. How would the Security Market Line be affected, other things held constant, if the expected inflation rate decreases and investors also become more risk averse?16. Recession, inflation, and high interest rates are economic events that are best characterized as being
17. Assume that the risk-free rate is 6% and the market risk premium is 5%. Given this information, which of the following statements is CORRECT?
20. Two constant growth stocks are in equilibrium, have the same price, and have the same required rate of return. Which of the following statements is CORRECT?
21. The required returns of Stocks X and Y are rX = 10% and rY = 12%. Which of the following statements is CORRECT?
22. Which of the following statements is NOT CORRECT?
23. Stocks X and Y have the following data. Assuming the stock market is efficient and the stocks are in equilibrium, which of the following statements is CORRECT?
24. Franklin Corporation is expected to pay a dividend of $1.25 per share at the end of the year (D1 = $1.25). The stock sells for $32.50 per share, and its required rate of return is 10.5%. The dividend is expected to grow at some constant rate, g, forever. What is the equilibrium expected growth rate?
25. Which of the following statements is CORRECT?
FIN 534 Midterm Exam Part 2
1.You recently sold 100 shares of your new company, XYZ Corporation, to your brother at a family reunion. At the reunion your brother gave you a check for the stock and you gave your brother the stock certificates. Which of the following statements best describes this transaction?
7. Which of the following is a primary market transaction?
9. DeYoung Devices Inc., a new high-tech instrumentation firm, is building and equipping a new manufacturing facility. Assume that currently its equipment must be depreciated on a straight-line basis over 10 years, but Congress is considering legislation that would require the firm to depreciate the equipment over 7 years. If the legislation becomes law, which of the following would occur in the year following the change?
10. Analysts following Armstrong Products recently noted that the company’s operating net cash flow increased over the prior year, yet cash as reported on the balance sheet decreased. Which of the following factors could explain this situation?
11. Which of the following items cannot be found on a firm’s balance sheet under current liabilities?
12. For managerial purposes, i.e., making decisions regarding the firm’s operations, the standard financial statements as prepared by accountants under Generally Accepted Accounting Principles (GAAP) are often modified and used to create alternative data and metrics that provide a somewhat different picture of a firm’s operations. Related to these modifications, which of the following statements is CORRECT?
13. Which of the following statements is CORRECT?
14. Lucy’s Music Emporium opened its doors on January 1, 2012, and it was granted permission to use the same depreciation calculations for shareholder reporting and income tax purposes. The company planned to depreciate its fixed assets over 20 years, but in December 2012 management realized that the assets would last for only 15 years. The firm’s accountants plan to report the 2012 financial statements based on this new information. How would the new depreciation assumption affect the company’s financial statements?
17. Danielle’s Sushi Shop last year had (1) a negative net cash flow from operations, (2) a negative free cash flow, and (3) an increase in cash as reported on its balance sheet. Which of the following factors could explain this situation?
18. Which of the following statements is CORRECT?
19. Which of the following would indicate an improvement in a company’s financial position, holding other things constant?
20. Cordelion Communications is considering issuing new common stock and using the proceeds to reduce its outstanding debt. The stock issue would have no effect on total assets, the interest rate Cordelion pays, EBIT, or the tax rate. Which of the following is likely to occur if the company goes ahead with the stock issue?
23. Considered alone, which of the following would increase a company’s current ratio?
24. A firm’s new president wants to strengthen the company’s financial position. Which of the following actions would make it financially stronger?
25. Which of the following would, generally, indicate an improvement in a company’s financial position, holding other things constant?
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CC-MAIN-2023-23
| 6,954
| 40
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https://www.lancastercsd.com/uncategorized/2018/12/17/second-semester-begins-monday-jan-14/?print=true
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math
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Schools will reopen Monday, Jan. 7 after the holiday break.
• First semester ends Friday, Jan 11, with first semester exams Jan. 10-11.
• Second semester begins Monday, Jan 14.
• Schools are closed Jan. 21 for the Martin Luther King Jr. holiday.
• Click to see school year calendar
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CC-MAIN-2021-21
| 289
| 5
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https://communities.sas.com/t5/SAS-Statistical-Procedures/pcorr-in-surveyreg/td-p/186378?nobounce
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math
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02-27-2015 01:14 PM
Is it possible to obtain partial correlation coefficients in SAS surveyreg? If so, how? The model statement is not allowing pcorr. Is there a back door or is it just wrong to request partial correlations in SAS Survey?
03-02-2015 12:35 PM
Well, I wouldn't call it wrong, but I would call it difficult to do, I think you would have to do the heavy lifting in PROC IML to get the weighted quadratic form matrix, and then do the reduction to partial out each variable. I don't see any way to do it solely in SURVEYREG--you could export the X'WX matrix to IML and calculate partial correlations there.
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s3://commoncrawl/crawl-data/CC-MAIN-2018-05/segments/1516084888135.38/warc/CC-MAIN-20180119204427-20180119224427-00062.warc.gz
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CC-MAIN-2018-05
| 617
| 4
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https://aiche.confex.com/aiche/2012/webprogram/Paper282525.html
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math
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282525 A Multidimensional Population Balance Model for Growth and Dissolution Identified From a Designed Temperature-Cycling Experiment
A large proportion of pharmaceutical crystallizations produce rod-like crystals, which can cause problems in process operations downstream from the crystallizer. Many recent efforts have been directed towards the construction of multidimensional population balance models suitable for the design of process operations to optimize crystal shape [1-11]. These models require the estimation of growth kinetics along multiple axes, with most methods based on sampling the slurry during crystallization, or on employing imaging technology that only applies for low crystal number densities or is not easy to implement in an industrial environment [12-21]. While it is not possible to construct an arbitrary two-dimensional crystal size distribution (2D CSD) from measurements of the chord length distribution (CLD) obtained by Focused Beam Reflectance Measurement (FBRM, which is a probe for in-situ laser backscattering measurements of particles), application to a specific solute-solvent system is simpler due to limited range of 2D CSDs that can occur for the allowed variation in seed mass and temperature profiles.
Previously, we have reported the application of the commonly available FBRM for the in-situ simultaneous measurement of crystal shape and size for rod-like organic crystals during a temperature cycling experiment, which resulted in substantial continual increases in aspect ratio, mean crystal length, and mean crystal width with cycle number. This presentation will describe the construction of a multidimensional population balance model for growth and dissolution rates along the two axes. The experimental observations motivated the incorporation of size-dependent dissolution into the multidimensional population balance model
where f is the 2D population density, t is time, and the growth and dissolution rates in the length and width directions are 2D generalizations of the 1D equations , i.e.,
and the dij and γ define size dependencies. The size dependency broadens the crystal size distribution, which result in more crystals becoming dissolved in each cycle, as required to explain the experimentally observed systematic increase in both the average length and width of crystals with cycle number. A parameter estimation code (the numerical algorithms and software are similar to that used in and ) employed a successive quadratic programming algorithm to minimize the sum-of-squared-deviations between the model predictions and experiments,
where θ is the vector of model parameters and α weighs the confidence in each of the mean length and width measurements relative to the solute concentration measurements and takes into account the differing units and number of experimental data points. A Pareto-optimality plot of squared-error values was constructed with each point being associated with a value of α, which ensured that the value of α of 0.00008 reasonably weighed the sets of solute concentration and mean length/width data.
Compared to previous multidimensional population balance models (PBMs), this PBM includes the effects of dissolution rates that are estimated from experimental data. Although the PBM's modeling of the size dependency of dissolution is rather simplistic, the model fits the experimental data with limited number of parameters with a relatively small level of uncertainty in the parameters that was quantified by first-order multivariate statistical analysis. In addition, the model simulation at optimal kinetic parameters was able to predict the crystal size and shape distribution in a different temperature-cycling experiment reasonably well. These results suggest that growth and dissolution rates estimated in a single temperature-cycling experiment may be suitable for designing a temperature-cycling protocol for optimizing the mean length, mean width, mean aspect ratio, or some weighted combination of the three characteristics of the product crystals. These results also suggest that an automated protocol may be developed that can assess the potential usefulness of temperature cycling for removing or reducing undesirable crystal size and shape characteristics produced by more standard crystallization operations.
D. B. Patience and J. B. Rawlings, "Particle-shape monitoring and control in crystallization processes," AIChE J., vol. 47, pp. 2125-2130, 2001.
R. Gunawan, D. L. Ma, M. Fujiwara and R. D. Braatz, "Identification of kinetic parameters in multidimensional crystallization processes," Int. J. Mod. Phys. B, vol. 16, pp. 367-374, 2002.
K. Lee, J. H. Lee, M. Fujiwara, D. L. Ma and R. D. Braatz, "Run-to-run control of multidimensional crystal size distribution in a batch crystallizer," in Proceedings of the American Control Conference, pp. 1013-1018, 2002.
F. Puel, G. Févotte and J. P. Klein, "Simulation and analysis of industrial crystallization processes through multidimensional population balance equations. Part 1: A resolution algorithm based on the method of classes," Chemical Engineering Science, vol. 58, pp. 3715-3727, 2003.
H. Briesen, "Simulation of crystal size and shape by means of a reduced two-dimensional population balance model," Chemical Engineering Science, vol. 61, pp. 104-112, 2006.
C. Y. Ma, X. Z. Wang and K. J. Roberts, "Multi-dimensional population balance modeling of the growth of rod-like L-glutamic acid crystals using growth rates estimated from in-process imaging," Advanced Powder Technology, vol. 18, pp. 707-723, 2007.
C. Y. Ma, X. Z. Wang and K. J. Roberts, "Morphological population balance for modeling crystal growth in face directions," AIChE J., vol. 54, pp. 209-222, 2008.
C. Y. Ma and X. Z. Wang, "Crystal growth rate dispersion modeling using morphological population balance," AIChE J., vol. 54, pp. 2321-2334, 2008.
J. Wan, X. Z. Wang and C. Y. Ma, "Particle shape manipulation and optimization in cooling crystallization involving multiple crystal morphological forms," AIChE J., vol. 55, pp. 2049-2061, 2009.
J. J. Liu, C. Y. Ma, Y. D. Hu and X. Z. Wang, "Effect of seed loading and cooling rate on crystal size and shape distributions in protein crystallization-A study using morphological population balance simulation," Computers and Chemical Engineering, vol. 34, pp. 1945-1952, 2010.
J. J. Liu, C. Y. Ma, Y. D. Hu and X. Z. Wang, "Modelling protein crystallisation using morphological population balance models," Chem. Eng. Res. Design, vol. 88, pp. 437-446, 2010.
F. Puel, P. Marchal and J. Klein, "Habit transient analysis in industrial crystallization using two dimensional crystal sizing technique," Chem. Eng. Res. Design, vol. 75, pp. 193-205, 1997.
D. L. Ma and R. D. Braatz, "Worst-case analysis of finite-time control policies," IEEE Trans. Control Syst. Technol., vol. 9, pp. 766-774, 2001.
J. Calderon De Anda, X. Z. Wang, X. Lai and K. J. Roberts, "Classifying organic crystals via in-process image analysis and the use of monitoring charts to follow polymorphic and morphological changes," J. Process Control, vol. 15, pp. 785-797, 2005.
J. De Calderon Anda, X. Z. Wang, X. Lai, K. J. Roberts, K. H. Jennings, M. J. Wilkinson, D. Watson and D. Roberts, "Real-time product morphology monitoring in crystallization using imaging technique," AIChE J., vol. 51, pp. 1406-1414, 2005.
J. De Calderon Anda, X. Z. Wang and K. J. Roberts, "Multi-scale segmentation image analysis for the in-process monitoring of particle shape with batch crystallisers," Chemical Engineering Science, vol. 60, pp. 1053-1065, 2005.
P. A. Larsen, J. B. Rawlings and N. J. Ferrier, "An algorithm for analyzing noisy, in situ images of high-aspect-ratio crystals to monitor particle size distribution," Chemical Engineering Science, vol. 61, pp. 5236-5248, 2006.
M. Oullion, F. Puel, G. Févotte, S. Righini and P. Carvin, "Industrial batch crystallization of a plate-like organic product. In situ monitoring and 2D-CSD modelling: Part 1: Experimental study," Chemical Engineering Science, vol. 62, pp. 820-832, 2007.
J. Eggers, M. Kempkes and M. Mazzotti, "Measurement of size and shape distributions of particles through image analysis," Chemical Engineering Science, vol. 63, pp. 5513-5521, 2008.
X. Z. Wang, J. Calderon De Anda and K. J. Roberts, "Real-time measurement of the growth rates of individual crystal facets using imaging and image analysis: A feasibility study on needle-shaped crystals of L-glutamic acid," Chem. Eng. Res. Design, vol. 85, pp. 921-927, 2007.
X. Z. Wang, K. J. Roberts and C. Ma, "Crystal growth measurement using 2D and 3D imaging and the perspectives for shape control," Chemical Engineering Science, vol. 63, pp. 1173-1184, 2008.
M. Shoji, T. Eto and H. Takiyama, "A kinetic study of the influence of modulated undersaturation operation on crystal size distribution in cooling-type batch crystallization," J. Chem. Eng. Japan, vol. 44, pp. 191-196, 2011.
R. Gunawan, I. Fusman and R. D. Braatz, "High resolution algorithms for multidimensional population balance equations," AIChE J., vol. 50, pp. 2738-2749, 11, 2004.
T. Togkalidou, H. -. Tung, Y. Sun, A. T. Andrews and R. D. Braatz, "Parameter estimation and optimization of a loosely bound aggregating pharmaceutical crystallization using in situ infrared and laser backscattering measurements," Industrial and Engineering Chemistry Research, vol. 43, pp. 6168-6181, 2004.
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s3://commoncrawl/crawl-data/CC-MAIN-2021-49/segments/1637964362219.5/warc/CC-MAIN-20211202114856-20211202144856-00358.warc.gz
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CC-MAIN-2021-49
| 9,462
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https://recetasparanavidad.org/file-ready/fraction-line-graph
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math
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Fraction number line see equivalent fractions and where they fit on the number line how to use move your mouse left and right and explore the different fractions click on the number line to mark a position equivalent fractions an example of equivalent fractions 14 is the same as 28 312 and 416 use the fraction number line to see why. Graphing or drawing fractions in the right place on a number line is a lot like reading a ruler except that you have to draw the ruler yourself reduce the fraction to lowest terms reduce the fraction to lowest terms by canceling common factors from the numerator and denominator. Number line chart for fraction size from halves through sixteenths fractions ordered in ascending value visual chart showing fraction proportions and relative scale fractions number line chart fractions proportion scale from 0 to 1 in increments of 16ths 15ths 14ths 13ths 12ths 11ths 10ths 9ths 8ths 7ths 6ths 5ths 4ths . Learn to graph and locate fractions on a number line weve already seen that if we take a whole and in this example the whole is this entire green circle. Improve your math knowledge with free questions in graph and compare fractions on number lines and thousands of other math skills ixl learning learning sign in remember sign in now join now more learning analytics inspiration membership sign in recommendations recs diagnostic math
How it works:
1. Register a Free 1 month Trial Account.
2. Download as many books as you like ( Personal use )
3. No Commitment. Cancel anytime.
4. Join Over 100.000 Happy Readers.
5. That's it. What you waiting for? Sign Up and Get Your Books.
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s3://commoncrawl/crawl-data/CC-MAIN-2019-13/segments/1552912203755.18/warc/CC-MAIN-20190325051359-20190325073359-00412.warc.gz
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CC-MAIN-2019-13
| 1,619
| 7
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https://www.research.ed.ac.uk/en/publications/invariants-patterns-and-weights-for-ordering-terms
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math
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We prove that any simplification order over arbitrary terms is an extension of an order by weight, by considering a related monadic term algebra called the spine. We show that any total ground-stable simplification order on the spine lifts to an order on the full term algebra. Conversely, under certain restrictions, a simplification ordering on the term algebra defines a weight function on the spine, which in turn can be lifted to a weight order on the original ground terms which contains the original order. We investigate the Knuth–Bendix and polynomial orders in this light. We provide a general framework for ordering terms by counting embedded patterns, which gives rise to many new orderings. We examine the recursive path order in this context.
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s3://commoncrawl/crawl-data/CC-MAIN-2021-25/segments/1623487653461.74/warc/CC-MAIN-20210619233720-20210620023720-00444.warc.gz
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CC-MAIN-2021-25
| 758
| 1
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https://radar.inria.fr/report/2016/dyogene/uid31.html
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math
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Section: New Results
Distributed Randomized Control for Demand Dispatch
This work, reported in , concerns design of control systems for Demand Dispatch to obtain ancillary services to the power grid by harnessing inherent flexibility in many loads. The role of “local intelligence” at the load has been advocated in prior work, randomized local controllers that manifest this intelligence are convenient for loads with a finite number of states. The present work introduces two new design techniques for these randomized controllers: (i) The Individual Perspective Design (IPD) is based on the solution to a one-dimensional family of Markov Decision Processes, whose objective function is formulated from the point of view of a single load. The family of dynamic programming equation appears complex, but it is shown that it is obtained through the solution of a single ordinary differential equation. (ii) The System Perspective Design (SPD) is motivated by a single objective of the grid operator: Passivity of any linearization of the aggregate input-output model. A solution is obtained that can again be computed through the solution of a single ordinary differential equation. Numerical results complement these theoretical results.
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s3://commoncrawl/crawl-data/CC-MAIN-2023-50/segments/1700679100227.61/warc/CC-MAIN-20231130130218-20231130160218-00726.warc.gz
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CC-MAIN-2023-50
| 1,242
| 3
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http://www.fg-stochastik.de/stellenausschreibungen/associate-professors-in-mathematical-statistics-at-aalborg-university.html
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math
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Associate Professors in mathematical statistics at Aalborg University
Positions as Associate Professors in mathematical statistics are open for appointment from 01.01.2023 at the Department of Mathematical Sciences, Aalborg University.
The Department of Mathematical Sciences conducts research in a wide range of mathematical disciplines and has three study programmes: mathematics (including a specialization in statistics at the master level), mathematics-economics, and mathematics-technology.
The department offers an international and informal working environment. The department is proud of its long tradition for good social relations and collaboration among colleagues. Employees at the department have great opportunities to shape the direction of their professional activities.
Deadline for application is June 21, 2022, at https://www.vacancies.aau.dk/show-vacancy/?vacancy=1187761 where further details can found.
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s3://commoncrawl/crawl-data/CC-MAIN-2022-21/segments/1652662636717.74/warc/CC-MAIN-20220527050925-20220527080925-00762.warc.gz
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CC-MAIN-2022-21
| 925
| 5
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http://picdeer.org/tag/typespire
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math
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8 Famous logos that use Myriad✨ Swipe ➡️ for more Tag a designer 👇 And double tap if you ❤️ it! Myriad is a humanist sans-serif typeface designed by Robert Slimbach and Carol Twombly for Adobe Systems. Myriad was intended as a neutral, general-purpose typeface that could fulfil a range of uses and have a form easily expandable by computer-aided design to a large range of weights and widths. Myriad is easily distinguished from other sans-serif fonts due to its "y" descender (tail) and slanting "e" cut.
a quick thank you to a woman who changed healing trauma forever . . . . . #calligraphizi#moderncalligraphy#calligraphy#typespire#goodtype#letteringdaily#letteringcommunity#letteringco#emdrtherapy#emdr#emdria
Sudtipos is proud to announce the release of Clockmaker, an 8-weight family that takes initial inspiration from typography around the turn of the twentieth century. Clockmaker takes aesthetic references from Victorian, Art Nouveau and Art Deco advertising and typography, taking special influence from John F. Cummings’ all-caps – and never digitized – type design Elandkay. Clockmaker is a robust multi-weight family that includes an array of ligatures as well as alternate characters and support for all latin languages. The design process began with developing and modernizing the uppercase letterforms, followed by designing the lowercase and additional weights. Creating a diverse and playful set of uppercase ligatures was an almost endlessly enjoyable task; they are one of Clockmaker’s most charming features. Clockmaker is an impeccable choice for designs requiring a vintage flair such as a luxury liquor labels, restaurant identities, lavish hotels and many other applications where elegance and grace are needed. In addition to its historical references, Clockmaker is an homage to my grandfather who was a master craftsman, repairing antique clocks and fine watches with great skill and mathematical precision. Watching him work was fascinating and it has been a joy to remember those quiet and curious moments from my childhood while designing this font. Enjoy Clockmaker, a new Sudtipos’ font available at http://www.sudtipos.com/font/clockmaker — Visit the full gallery we have created at https://www.behance.net/gallery/84131043/Clockmaker - . . . #typespire#clockmaker#sudtipos#typography#artdeco#artnouveau#victorian#font#typographydesign#graphicdesign#fontdesign#dailytype
— Smart Hema Clubs. Stu has such a passion for bringing fencing to people of all ages, sexes and abilities and it was alot of fun working with someone who wants to take a step away from the cliché martial arts branding we've become so used to seeing.
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s3://commoncrawl/crawl-data/CC-MAIN-2019-39/segments/1568514573908.70/warc/CC-MAIN-20190920071824-20190920093824-00014.warc.gz
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CC-MAIN-2019-39
| 2,686
| 4
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https://socratic.org/questions/how-do-you-solve-the-system-7x-y-19-and-2x-3y-19
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math
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How do you solve the system # -7x+y=-19# and #-2x+3y=-19#?
There's two ways in which we solve systems in general: elimination, and substitution.
We'll be using substitution to solve this system. Why? Notice that we have a single
Step 1: Solve for One Variable
Let's first write out our equations:
Now, we solve for one variable. I'm going to solve for
As you can see, that was pretty easy, and gave us a relatively nice result. This is why we chose to do substitution for this particular problem.
Step 2: Plug into Other Equation; Solve for Other Variable.
Now, let's plug in the value for
Note: Watch your signs while you do this
Combine like terms:
Step 3: Solve for First Variable
We could plug this value we found for
So, our final solutions are
You can see this graphically below. The red line is equation (1) and the blue line is equation (2):
Hope that helped :)
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CC-MAIN-2022-27
| 869
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https://goodmancoaching.nl/how-do-you-negate-an-at-least-statement/
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math
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How do you negate at least?
Suppose you have ten books, five of which are overdue, and five not. The sentence “At least two of my library books are overdue” is true, as is “At least two of my library books are not overdue”. You always have to apply the negation to the outermost part of the expression you’re negating.
How do you negate a statement?
The symbols used to represent the negation of a statement are “~” or “¬”. For example, the given sentence is “Arjun’s dog has a black tail”. Then, the negation of the given statement is “Arjun’s dog does not have a black tail”. Thus, if the given statement is true, then the negation of the given statement is false.
Can you negate some statements?
This essentially what happens when you negate an off statement is it becomes a sum statement.
What does it mean to negate a statement?
A negation is a refusal or denial of something. If your friend thinks you owe him five dollars and you say that you don’t, your statement is a negation. A negation is a statement that cancels out or denies another statement or action.
How do you negate a compound statement?
The negation of a conjunction (or disjunction) could be as simple as placing the word “not” in front of the entire sentence. Conjunction: p ∧ q – “Snoopy wears goggles and scarves.” ∼(p ∧ q) – “It is not the case that Snoopy wears goggles and scarves.”
What is the negation of P → Q?
The negation of “P and Q” is “not-P or not-Q”.
What is the negation of a conditional statement?
The negation of a conditional statement is only true when the original if-then statement is false. The negation of a conjunction is only false when the original two statements are both true. A conjunction is two statements that are joined by an “and”.
What is the inverse of the conditional statement?
The inverse of a conditional statement is when both the hypothesis and conclusion are negated; the “If” part or p is negated and the “then” part or q is negated. In Geometry the conditional statement is referred to as p → q. The Inverse is referred to as ~p → ~q where ~ stands for NOT or negating the statement.
How do you write converse inverse and contrapositive of a statement?
If the statement is true, then the contrapositive is also logically true. If the converse is true, then the inverse is also logically true.
Converse, Inverse, Contrapositive.
|Statement||If p , then q .|
|Converse||If q , then p .|
|Inverse||If not p , then not q .|
|Contrapositive||If not q , then not p .|
What is converse and inverse?
The converse statement is notated as q→p (if q, then p). The original statements switch positions in the original “if-then” statement. The inverse statement assumes the opposite of each of the original statements and is notated ∼p→∼q (if not p, then not q).
Which is the converse of P → Q?
q → p
The converse of p → q is q → p. The inverse of p → q is ∼ p →∼ q. A conditional statement and its converse are NOT logically equivalent. A conditional statement and its inverse are NOT logically equivalent.
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http://www.ma.utexas.edu/pipermail/maxima/2008/010065.html
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math
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[Maxima] Problem with "globalsolve:true"
robert.dodier at gmail.com
Fri Feb 8 09:58:01 CST 2008
On 2/8/08, Helge Hansen <hansen at akb-antriebstechnik.de> wrote:
> Does anybody understand why K2 in the following script is not solved global?
> What am I doing wrong? In my opinion the last line should be:
> (%i1) M(z)::=K2+A*z-q*z^2/2;
> (%o1) M(z)::=K2+A*z+((-q)*z^2)/2
> (%i2) globalsolve:true$
> (%i3) solve([M(z)=0,z=0],[K2,z]);
Well, M(z) = 0 is not a linear equation, so solve ignores globalsolve.
The documentation for globalsolve states that, although globalsolve
is a mess anyway so it is impossible to be entirely clear about it.
My advice is to ignore globalsolve and find another way.
Maybe subst(K2=0, M(z)) or ev(M(z), K2=0) yields the expected result.
I think the Maxima developers should consider cutting out globalsolve.
Its implementation is a mess, and even if it worked right, it would
make a mess for the user by causing assignments.
More information about the Maxima
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s3://commoncrawl/crawl-data/CC-MAIN-2015-48/segments/1448398465089.29/warc/CC-MAIN-20151124205425-00086-ip-10-71-132-137.ec2.internal.warc.gz
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https://www.jiskha.com/display.cgi?id=1366616375
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math
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posted by aman .
from a normally distributed infinite number of iron bars lengths with a mean and standard deviation as 4 ft. and 0.6 ft. respectively, a sample of 100 bars is taken. if the sample mean is 4.2 ft., can the sample be called a truely random sample?
How was the sample taken? If the observations are taken on a chance basis, then it would be random.
Or are you asking if the sample is within certain range of possible sample means?
Z = (score-mean)/SEm
SEm = SD/√n
Find table in the back of your statistics text labeled something like "areas under normal distribution" to find the proportion/probability related to the Z score.
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CC-MAIN-2018-05
| 642
| 7
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http://www.e-booksdirectory.com/details.php?ebook=4741
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math
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An Elementary Course in Synthetic Projective Geometry
by Derrick Norman Lehmer
Publisher: Project Gutenberg 2005
Number of pages: 120
The following course is intended to give, in as simple a way as possible, the essentials of synthetic projective geometry. Enough examples have been provided to give the student a clear grasp of the theory. The student should have a thorough grounding in ordinary elementary geometry.
Home page url
Download or read it online for free here:
by Maximilian Kreuzer - Technische Universitat Wien
From the table of contents: Topology (Homotopy, Manifolds, Surfaces, Homology, Intersection numbers and the mapping class group); Differentiable manifolds; Riemannian geometry; Vector bundles; Lie algebras and representations; Complex manifolds.
by Andrew Ranicki, et al. - American Mathematical Society
This volume includes papers ranging from applications in topology and geometry to the algebraic theory of quadratic forms. Various aspects of the use of quadratic forms in algebra, analysis, topology, geometry, and number theory are addressed.
by Keith Ball, Vitali Milman - Cambridge University Press
Convex bodies are at once simple and amazingly rich in structure. This collection involves researchers in classical convex geometry, geometric functional analysis, computational geometry, and related areas of harmonic analysis.
by Charles Howard Hinton - S. Sonnenschein & Co.
C. H. Hinton discusses the subject of the higher dimensionality of space, his aim being to avoid mathematical subtleties and technicalities, and thus enable his argument to be followed by readers who are not sufficiently conversant with mathematics.
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s3://commoncrawl/crawl-data/CC-MAIN-2024-18/segments/1712296817171.53/warc/CC-MAIN-20240417173445-20240417203445-00427.warc.gz
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CC-MAIN-2024-18
| 1,659
| 15
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http://www.hancockonline.net/Han/H-I-2513.html
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math
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|Name} Grossherr, Adelaide Dorothy||Family History} Hancock|
|Title}||Race} White||Sex} Female|
|Birth: Date} Fam 29 Sep 1919||Place} Vallejo, Solano, California|
|Marr.: Date} Fam 1940||Place} (Link)|
|Death: Date} Exa 1 Nov 2009||Place} Fairfield, Solano, California|
|Burial: Date} Cir 4 Nov 2009||Place}|
|Parents: } Frederick (Fred) W. Grossherr & Myrtle M. Cognaiss|
Relationship No.} 883
|1st Household No.}|
| Occupation 1} Secretary |
Occupation 2} Artist/painter
Occupation 3} Bookkeeper
Imboden, William James (Bill)|
Total Number of} 1?
|Notes: Adelaide attended Vallejo schools and a Napa secretarial
school before going to work for her aunt and uncle, Hazel
and Gilbert Foster, at Foster Lumber in Vallejo.|
In 1940, Adelaide married Bill Imboden, also of Vallejo, where they made their home until moving to Gordon Valley in Napa County in 1942. There they owned and operated a cattle ranch.
A lifelong artist, Adelaide was a member of the Vacaville Art League, Vallejo Art League, and Society of Western Artists. She was also a homemaker who loved to cook, garden, and travel.
Adelaide passed away in 2009 after a long illness. She was survived by her husband and a daughter in Fairfield, a daughter in Napa, a son in Gordon Valley, 7 grandchildren, and 12 great-grandchildren.
|Time of Birth}||Time of Death}||Fraternal/Social} see Notes|
|Confirm. Date}||Photo} Adelaide in 1993 ==>|
|Immigr'n Date} N/A||Port} N/A|
|Education: Grade} Twelfth, High school|
|Military: Service} for the State of}|
Cause of Death}
|Copyright © 2014 by Daniel W. Hancock. All Rights Reserved.|
|Home Page||Next Page|
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| 1,617
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https://fzzwe.highbration.shop/quadratic-function-pdf.html
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math
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recent judicial review cases
ninja dual heat air fry oven
Write the Quadratic Function in Vertex Form Convert each quadratic function to vertex form y a x – h 2 k. Mugs can be represented by where x is the number of months after January 2001. Application of Quadratic Functions Worksheet Problems to work out together in.
1 liter plastic bottles wholesale
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12 universal laws book pdf
form of the function. A2.6.3 . Convert quadratic functions from standard to vertex form by completing the square. A2.6.4 . Relate the number of real solutions of a quadratic equation to the graph of the associated quadratic function. A2.6.5 . Express quadratic functions in vertex form to identify their maxima or minima and in factored. Worksheet 2.1A, Quadratic functions MATH 1410, (SOLUTIONS) 1.Find the quadratic function with the given vertex and point. Put your answer in standard form. ... 3.Put the function in standard form y = a(x h)2 +k and then describe the transformation required to graph this function beginning with the graph of y = x2: (a) y = x2 + 4x. As review, we will look at the definition of a quadratic function. Def: A quadratic function is a function f of the form ( ) 2 = + + f x ax bx c. where a, b, and c are real numbers and . a. ≠ 0. Standard Form and Completing the Square: In determining extreme values, it is very helpful to put the quadratic function into standard form..
friday night funkin jokes
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s3://commoncrawl/crawl-data/CC-MAIN-2022-40/segments/1664030337731.82/warc/CC-MAIN-20221006061224-20221006091224-00451.warc.gz
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CC-MAIN-2022-40
| 1,449
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http://medcred.youdontcare.com/rowlands/Order-Of-Operations-Math-Homework.html
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math
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Enter an equation - the helper breaks the equation into each step required by the order of operations. Unlimited replay and review.
Our Order of Operations Worksheets are free to download, easy to use, and very flexible. These Order of Operations Worksheets are a great resource for children in Kindergarten, 1st Grade, 2nd Grade, 3rd Grade, 4th Grade, and 5th Grade. Click here for a Detailed Description of all the Order of Operations Worksheets.
Order of Operations Introduction. The order of operations is a very simple concept, and is vital to correctly understanding math. Unlike reading, where we always work left-to-right, sometimes with math we need to work one part of a problem before another, or the final answer could be incorrect!
In mathematics and computer programming, the order of operations (or operator precedence) is a collection of rules that reflect conventions about which procedures to perform first in order to evaluate a given mathematical expression. For example, in mathematics and most computer languages, multiplication is granted a higher precedence than addition, and it has been this way since the.
When expressions have more than one operation, we have to follow rules for the order of operations: First do all operations that lie inside parentheses. Next, do any work with exponents or radicals. Working from left to right, do all multiplication and division.
Homework resources in Order of Operations: PEMDAS - Middle Grades - Math Military Families The official provider of online tutoring and homework help to the Department of Defense.
Order of operations worksheets (PEMDAS) with varying numbers of terms, included operations and use of parenthesis. Free math worksheets from K5 Learning; no login or account is needed.
Order Of Operations 7th Grade. Displaying all worksheets related to - Order Of Operations 7th Grade. Worksheets are Order of operations pemdas practice work, Order of operations, Using order of operations, Word problem practice workbook, Order of operations, Order of operations, Exercise work, 6th grade unpacked math teks.
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In math, order of operations are the rules that state the sequence in which the multiple operations in an expression should be solved. A way to remember the order of the operations is PEMDAS, where in each letter stands for a mathematical operation.
When doing computations, always follow the order of operations and always perform the operations according to the following rule. Rule: 1. If grouping symbols are used such as parentheses, perform the operations inside the grouping symbols first. 2. Evaluate any expressions with exponent. 3. Multiply and Divide from left to right. 4.
Create free printable worksheets for the order of operations (addition, subtraction, multiplication, division, exponents, parenthesis) for elementary (grades 2-5) and middle school (grades 6-9). You can control the number ranges used, include decimals or not, control the number of problems, workspace below the problems, font size, and more.
Order of Operations Lessons. The Order of Operations is very important when simplifying expressions and equations. The Order of Operations is a standard that defines the order in which you should simplify different operations such as addition, subtraction, multiplication and division.
These order of operations worksheets will get your PEMDAS skills in operational order! PEMDAS is a mnemonic for Parentheses, Exponents, Multiplication, Division, Addition and Subtraction. This is the order in which operations are applied to solve more complex math problems that have multiple terms and multiple operations.
Order of Operations 1 Math Worksheet for kids with answer key. Learners can download this math worksheet and write their responses in the space provided. Print or download free pdf printable worksheet and teach students about Order of Operations. PDF printable worksheet for classroom and homework to practice math topic - Order of Operations.
So this is just completely unacceptable, and that's why we have to have an agreed upon order of operations. An agreed upon way to interpret this statement. So the agreed upon order of operations is to do parentheses first -- let me write it over here -- then do exponents. If you don't know what exponents are don't worry about it right now.
The order of operations is an essential math skill for every student to master, and these exceptional worksheets help students become confident in approaching any problem in the right order. Starting with the basics of addition and subtraction and moving on to more complex problems containing parentheses, multiplication, and division, these entertaining worksheets are incredibly thorough.
Order Of Operations Homework Helper. Her poetry and short fiction have been published worldwide,. Hire a Writer to Work on Your Paper After our specialists receive your order with all the details and report about payment, they choose the best writer to complete your task.
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| 5,283
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http://zbmath.org/?q=an:06202733
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math
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Summary: T. G. Bhaskar
and V. Lakshmikantham
[Nonlinear Anal., Theory Methods Appl. 65, No. 7, A, 1379–1393 (2006; Zbl 1106.47047
)] proved the existence of a coupled fixed point for a single valued mapping under weak contractive conditions and, as an application, they proved the existence of a unique solution of a boundary value problem associated with a first order ordinary differential equation. Recently, V. Lakshmikantham
and Lj. Ćirić
[Nonlinear Anal., Theory Methods Appl. 70, No. 12, A, 4341–4349 (2009; Zbl 1176.54032
)] obtained a coupled coincidence and coupled common fixed point of two single valued maps. In this article, we extend these concepts to multi-valued mappings and obtain coupled coincidence points and common coupled fixed point theorems involving hybrid pair of single valued and multi-valued maps satisfying generalized contractive conditions in the frame work of a complete metric space. Two examples are presented to support our results.
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s3://commoncrawl/crawl-data/CC-MAIN-2014-15/segments/1397609538022.19/warc/CC-MAIN-20140416005218-00411-ip-10-147-4-33.ec2.internal.warc.gz
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| 976
| 7
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https://naijapalaba.com/check-this-out-10-newest-stunning-and-amazing-braid-hair-stlyes/
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math
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We are back again with the latest gorgeous and lovely braid hairstyles. Down below are 10 names and pictures of the trending new braid styles for this year.
So when next you want to make someone’s hair or you want to get your hair done, all you have to do is check below, pick your choice style and be the cause of various turning heads.
#1 Fishbone braid
#2 Natural braided up-do
#3 Side swept braids
#4 Half-up half-down feed in braid
#5 Braided Bob
#6 Double french braids with double curly extensions
#7 Fulani braids
#8 Ciara plaits
#9 Nubian single row braids
#10 Triangle part box braids
Try any of this out and keep being the main center of attraction any where your feet leads you.
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s3://commoncrawl/crawl-data/CC-MAIN-2021-31/segments/1627046152112.54/warc/CC-MAIN-20210806020121-20210806050121-00630.warc.gz
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CC-MAIN-2021-31
| 692
| 13
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https://research.uaeu.ac.ae/en/publications/ricci-determinant-gravity-dynamical-aspects-and-astrophysical-imp
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math
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The Palatini gravitational action is enlarged by an arbitrary function of the determinants of the Ricci tensor and the metric, . The resulting Ricci-determinant theory exhibits novel deviations from general relativity. We study a particular realization where the extension is characterized by the square-root of the Ricci determinant, , which corresponds to the famous Eddington action. We analyze the obtained equations for perfect fluid source and show that the affine connection can be solved in terms of the energy density and pressure of the fluid through an obtained disformal metric. As an application, we derive the hydrostatic equilibrium equations for relativistic stars and inspect the significant effects induced by the square-root of the Ricci tensor. We find that an upper bound on , at which deviations from the predictions of general relativity on neutron stars become prominent, corresponds to the hierarchy between the Planck and the vacuum mass scales. The Ricci-determinant gravity that we propose here is expected to have interesting implications in other cosmological domains.
ASJC Scopus subject areas
- Physics and Astronomy (miscellaneous)
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CC-MAIN-2023-50
| 1,164
| 3
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https://questions.gardeningknowhow.com/rose-bush-8/
|
math
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My rose bush's leaves turned yellow and are falling off. What did I do wrong?
bristolgirl added on May 27, 2016 | Answered
Check here if you would like to receive notifications every time this question is answered.
You are subscribed to receive notifications whenever this question is answered.
Answered on May 28, 2016
I think you also posted a photo of your rosebush in another question here. Please see that question response and things should be easily fixed. You did nothing wrong.
Was this answer useful?
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s3://commoncrawl/crawl-data/CC-MAIN-2018-22/segments/1526794863811.3/warc/CC-MAIN-20180520224904-20180521004904-00145.warc.gz
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| 510
| 7
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https://www.hackmath.net/en/math-problem/4092
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math
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Anna has 5 €, Anezka has 4,60 € and for all the money they want to buy desserts for a family party. They decide between cakes and pinwheel: The pinwheel is € 0.40 more expensive than the cake, and the cakes can be bought for all the money by a third more than the pinwheels. How much does each dessert cost?
Did you find an error or inaccuracy? Feel free to write us. Thank you!
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Alena bought movie tickets for two groups of pupils. The first group purchased 7 tickets for 1st and 5 tickets for 2nd place and she pay 62Kč. For the second group bought 11 tickets for 1st and 4 tickets for 2nd place and pay 82Kč. How much was the ticket
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Montealegre family has a catering business. At one birthday party, they charged their costumer 11,767.50 for a party of 90 persons and a service charge of $ 2,500.50. How much was the average cost per person? Please show your solution.
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Find how many peaches could be bought instead of buying one melon, one pear, one apple and two plums if we know that: • Melon and plum cost the same as three apples • if we subtract the price of a pear from the price of peach, we get the price of plum • T
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For her youngest son's birthday party, the mother bought 6 3/4 kg of hotdog and 5 1/3 dozens bread rolls. Hotdogs cost 160 per kilogram, and a dozen bread rolls cost 25. How much did she spend in all?
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https://www.coursehero.com/tutors-problems/Applied-Mathematics/16561581-The-voltage-V-in-volts-produced-by-an-ac-generator-at-time-t-second/
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math
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The voltage V , in volts, produced by an ac generator at time t seconds, is given by: V (t) = 120 sin(120πt) (a) Find the amplitude and the period of the function V (t). (b) Sketch a graph of V over two periods, beginning at t = 0. (c) If a resistance of R = 20 ohms is present, find a formula for the current, I(t). (Use Ohm's Law, V = IR.) (d) What is the amplitude and period of the function I(t)? (e) Sketch a graph of I over two periods, beginning at t = 0. Include this with the graph in part (b), showing the two graphs together on the same set of axes.
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s3://commoncrawl/crawl-data/CC-MAIN-2019-22/segments/1558232257847.56/warc/CC-MAIN-20190525024710-20190525050710-00255.warc.gz
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CC-MAIN-2019-22
| 561
| 1
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http://math.stackexchange.com/questions/140710/what-and-how-many-pieces-does-the-banach-tarski-paradox-break-a-sphere-into
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math
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From the article to which you linked:
In fact, there is a sharp result in this case, due to Robinson: doubling the ball can be accomplished with five pieces, and fewer than five pieces will not suffice.
A reference is given to R. M. Robinson, On the Decomposition of Spheres, Fund. Math. 34:246–260.
It's impossible to describe the shapes of all of the pieces. Another quotation from the article:
Unlike most theorems in geometry, this result depends in a critical way on the axiom of choice in set theory. This axiom allows for the construction of nonmeasurable sets, collections of points that do not have a volume in the ordinary sense and for their construction would require performing an uncountably infinite number of choices.
Very roughly speaking, the construction of such a decomposition requires the ability to make too many arbitrary choices for them to be describable in any concrete terms. There are models of set theory in which such choices cannot be made, and in which such decompositions do not exist. This applies to four of the pieces in the $5$-piece decomposition mentioned above; the fifth is a single point.
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s3://commoncrawl/crawl-data/CC-MAIN-2016-30/segments/1469257824037.46/warc/CC-MAIN-20160723071024-00023-ip-10-185-27-174.ec2.internal.warc.gz
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http://www.physicsforums.com/showthread.php?t=547130
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math
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|Nov3-11, 08:48 PM||#1|
1. The problem statement, all variables and given/known data
f(x,y,z) = e^(2x-z)
W: x+y+z ≤ 1, x,y,z ≥ 0
2. Relevant equations
0 ≤ x ≤ 1-y-z
0 ≤ y ≤ 1-x-z
0 ≤ z ≤ 1-x-y
3. The attempt at a solution
I tried dzdydx and dydzdx but they don't work...
or am I doing something wrong?
|Nov3-11, 09:14 PM||#2|
You will note that the boundaries are symmetric under permutations of x, y, and z. Thus w.r.t. the boundary order of integration shouldn't matter.
The integrand will be quite easy to integrate. I suggest you factor it into e^(2x) e^(-z).
You just have to set up your boundaries of integration correctly. Can you show us some of your attempts?
|Nov3-11, 09:25 PM||#3|
Isn't that the correct boundaries that I set up in relevant equations?
or is that wrong?
I would love to post my work... but it's so much mess right now... it's like everywhere... If I can get the right boundaries I feel like I can get it right
|Similar Threads for: Triple Integral|
|triple integral||Calculus & Beyond Homework||6|
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s3://commoncrawl/crawl-data/CC-MAIN-2013-20/segments/1368705407338/warc/CC-MAIN-20130516115647-00002-ip-10-60-113-184.ec2.internal.warc.gz
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CC-MAIN-2013-20
| 1,090
| 22
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https://www.sparrho.com/item/geometric-effects-on-a-quantum-particle-constrained-to-a-helix-catenary-helicoid-or-catenoid/2a1c825/
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math
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Indexed on: 03 Mar '21Published on: 28 Feb '21Published in: arXiv - Physics - Mesoscopic Systems and Quantum Hall Effect
Since electrons in a ballistic regime perceive a carbon nanotube or a graphene layer structure as a continuous medium, we can use the study of the quantum dynamics of one electron constrained to a curve or surface to obtain a qualitative description of the conduction electrons' behavior. The confinement process of a quantum particle to a curve or surface leads us, in the so-called da Costa's approach, to a geometry-induced potential (GIP) in the effective Schr\"odinger equation. With these considerations, this work aims to study in detail the consequences of constraining a quantum particle to a helix, catenary, helicoid, or catenoid, exploring the relations between these curves and surfaces using differential geometry. Initially, we use the variational method to estimate the energy of the particle in its ground state, and then, we obtain better approximations with the use of the confluent Heun function through numerical calculations. Thus, we conclude that a quantum particle constrained to an infinite helix has its angular momentum quantized due to the geometry of the curve, while in the cases of the catenary, helicoid, and catenoid the particle can be found either in a single bound state or in excited states which constitute a continuous energy band.
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https://www.bartleby.com/solution-answer/chapter-93-problem-18es-discrete-mathematics-with-applications-5th-edition/9781337694193/just-as-the-difference-rule-gives-rise-to-a-formula-for-the-probability-of-the-complement-of-an/b4f5f9c7-f6b8-4f94-a9d0-715bbb36b871
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math
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Just as the difference rule gives rise to a formula for the probability of the complement of an event, so the addition and inclusion/exclusion rules give rise to formulas for the probability of the union of mutually disjoint events and for a general union of (not necessarily mutually exclusive) events.
To prove that for mutually disjoint events ,
for mutually disjoint sets.
The objective is to prove that for mutually disjoint events .
Let be the number of elements in the sample space .
By addition rule, for mutually disjoint sets.
Divide by .
To prove that for any events .
Bartleby provides explanations to thousands of textbook problems written by our experts, many with advanced degrees!Get Started
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CC-MAIN-2019-51
| 707
| 9
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http://openstudy.com/updates/55a64ac4e4b0076668b2c9e1
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math
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At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.
do you know what ratio the cosine function represents?
I forgot what it was... tbh.... I'm really horrible at math... and i couldn't catch on to it...
Don't worry :) I can help you. Have you heard of SOH CAH TOA before?
no i havent, my teacher never taught me that
It essentially means \[\sin=O/H, \cos=A/H, \tan=O/A\]
it's a mnemonic worth remembering for trigonometry.
so if cos = adjacent/hypotenuse, do you know which to sides these are in relation to angle b?
adjacent and hypotenuse?
yes but which sides are they in the above triangle?
3 and 5??
yep, so the final ratio is?
wait how would i put that in my calculator?
i'm so sorry i literally forget so much stuff it's a problem....
you can't really put that into a calculator. so what is the final answer?
if adjacent = 3 and hypotenuse = 5 and cos 60 = a/h = ?
sorry i'm so tired and i have 6 online geometry tests to do by 1:18 p.m and its 8:21 a.m
so is it 3/5 @Sepeario
yep that's right
good luck! and i'm sure you'll do well.
i suck at math
i'm gonna fail and have to repeat freshman year
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https://gastronomia.ca/pages/complex-variables-examples-ad0690
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math
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In the second phenomenon, i.e., crime and violence in the streets, the independent variable may be the number of law enforcers, and … The modulus of z is its absolute value. Consider a random variable that may take only the three complex values +, −, with probabilities as specified in the table. Complex Variables L4 is on Examples on Analytic Function & C-R Equations from unit 5 of M-III. Examples Simple example. In basic algebra, the variables x and y generally stand for values of real numbers. Complex integration: Cauchy integral theorem and Cauchy integral formulas Definite integral of a complex-valued function of a real variable Consider a complex valued function f(t) of a real variable t: f(t) = u(t) + iv(t), which is assumed to be a piecewise continuous function defined in the closed interval a ≤ t ≤ b. A complex random variable on the probability space (,,) is a function: → such that both its real part () and its imaginary part () are real random variables on (,,).. Functions of a complex variable. Several Complex Variables P. M. Gauthier March 14, 2006 Abstract This is a mere sketch of the course being given in the fall of 2004. Unlike calculus using real variables, the mere existence of a complex derivative has strong implications for the properties of the function. 4. This is a simple example of a complex random variable. This short tutorial is a companion material to the course on Functions of a Complex Variables . Thus, sea-level rise on a global scale may occur. TDP. Increased temperature will cause the expansion of water in the sea. 252–254). From time to time, Maple commands are added in examples. Definition. Complex analysis is a basic tool with a great many practical applications to the solution of physical problems. I shall give the course in French, but if some student so wishes, I shall write on the blackboard in English. For example, in the first phenomenon of climate change, temperature (independent variable) may influence sea level (dependent variable). It revolves around complex analytic functions—functions that have a complex derivative. In the same eventuality, these lecture notes are in English. It is intended to help the student, but will replace neither personal lecture notes nor a good textbook. Complex variable, In mathematics, a variable that can take on the value of a complex number. For examples of applications see Olver (1997b, pp. The algebra of complex numbers (complex analysis) uses the complex variable z to represent a number of the form a + bi.
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https://happygamer.com/best-league-of-legends-jungle-lane-champions-for-patch-1022-to-climb-ranks-in-solo-queue-90257/
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math
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Some champions in League of Legends are just much stronger than others. \n \nFor junglers, there are multiple considerations when weighing which champions are better. The most important thing to look at, and the most obvious, is whether the champion would be good at ganking and either securing kills or aiding their teammates in doing so. Behind the scenes, though, is where things get complicated. \n \nClear speed, invasion pressure, and macro mobility are all factors that need to be evaluated for keeping up with the enemy jungler. The best jungle champions are the ones that can do it all. \n \nThis list of top-tier champions can change depending on a number of things. Sometimes the meta shifts for no apparent reason other than players’ tastes, but usually there’s some kind of balance update, small or large, that’s behind the sudden change. It can be difficult to keep up on the flavor-of-the-month champs, so let us do it for you. \n \nKarthus \n \nPros \n \n \tGlobal ultimate \n \tImpactful even after death \n \tGood source of magic damage in AD composition \n \nCons \n \n \tNeeds time to scale \n \tCannot contest early objectives \n \nKarthus is one of the best ability power junglers to round out a full AD composition. This is mostly thanks to the utility from his kit, as well as his slow and global ultimate. Karthus is a power farmer with barely any cooldown on Q, allowing for quick jungle clear. But he’s rather mana hungry and struggles with early ganks. \n \nGraves \n \nPros \n \n \tMobile \n \tTanky \n \tRewarding if mastered \n \nCons \n \n \tRelies on snowballing \n \tHard to come back if behind \n \nGraves is one of the most popular picks this patch after the resurgence of strong champions that can be kited, such as Ornn in the top lane, Galio in the mid lane, and Trundle in the jungle. He is the master at kiting enemies and slowly chipping their health bars down. He is one of the most reliable snowballing champions due to how easy it is to gank with Graves. You have access to a dash, which allows you to pass through walls, and a smoke bomb, which slows and denies vision from the enemy champions. \n \nEkko \n \nPros \n \n \tExtremely mobile \n \tForgiving ultimate \n \tAoE crowd control \n \nCons \n \n \tUseless if behind \n \tWeak vs. tanks \n \nEkko excels in roaming around the map and picking up kills. He has the potential to carry games with his high burst and crowd-control abilities. Even though his jungle clear speed isn’t as fast after recent attack speed nerfs, he still remains a contested pick in solo queue for mid laners and junglers.
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https://skatterixju.web.app/73495/19327.html
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math
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stochastic modeling - Swedish translation – Linguee
It consists of two lines: the indicator line %K, and the signal or trigger line %D. The stochastic indicator can be used to identify oversold and overbought conditions, as well as to spot divergences between the price and the indicator. Stochastic Models! September 7, 2011! 4! The Master Equation!
We develop a new and powerful solution to this computer graphics problem by modeling objects as sample paths of stochastic processes. Of particular interest Jan 4, 2021 There are three main components in the model: nucleus position, gene- regulatory network, and stochastic segregation of transcription factors in Apr 11, 2020 We use a stochastic model to investigate containment and elimination scenarios for COVID-19 in New Zealand, as the country considers the Prof. Jeff Gore discusses modeling stochastic systems. The discussion of the master equation continues. Then he talks about the Gillespie algorithm, an exact Apr 18, 2017 The model for example might be used to predict downstream revenues, cash flows, or expenses across a spectrum of situations. Models can Stochastic Modeling Using Virtual Training Sets. By James C. Cross III, MathWorks.
A disaggregate stochastic freight transport model for Sweden
E Abi Jaber, O El Euch. 8*, 2018. Stochastic invariance of closed sets with non-Lipschitz coefficients.
Eduardo Abi-Jaber - Google Scholar Citations
But, stochastic models are considerably more complicated. When do deterministic models Stochastic processes are ways of quantifying the dynamic relationships of sequences of random events. Stochastic models play an important role in elucidating many areas of the natural and engineering sciences. They can be used to analyze the variability inherent in biological and medical Stochastic Model. Stochastic models are used to represent the randomness and to provide estimates of the media parameters that determine fluid flow, pollutant transport, and heat–mass transfer in natural porous media. From: Stochastic Processes, 2004.
One might be tempted to give up and accept that stochastic
In case the stochastic elements in the simulation are two or more persons andthere is a competitive situation or some type of game being reproduced, this isspecifically known as gaming simulation. Simulation by the deterministic model can be considered one of the specificinstances of simulation by the stochastic model. A stochastic model used for an entropy source analysis is used to support the estimation of the entropy of the digitized data and finally of the raw data. In particular, the model is intended to provide a family of distributions, which contains the true (but unknown) distribution of the noise source outputs. Stochastic models based on the well-known SIS and SIR epidemic mod-els are formulated. For reference purposes, the dynamics of the SIS and SIR deterministic epidemic models are reviewed in the next section.
Pris: 157 kr. häftad, 2013. Skickas inom 5-8 vardagar. Köp boken A Macro-Stochastic Model for Improving the Accuracy of DoD Life Cycle Cost Estimates: Stochastic modeling and simulation of traffic flow: asymmetric single exclusion process with Arrhenius look-ahead dynamics.
Tom Britton : Epidemic models on social networks – with inference
Stochastic differential equations and data-driven modeling. 7.5 ECTS credits. The course is not included in the course offerings for the next period.
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functional stochastic models that we refer to as generalized Slepian models. A stochastic model of the emergence of autocatalytic cycles.
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Dynamics of COVID-19 mathematical model with stochastic
The model was based on the following, hypotheses regarding the behavior of individual cells: (a) the mechanical signal responsible for cell reorientation is the peak to peak surface strain along the cell's major axis (p-p axial strain); (b) each cell 2012-09-11 Stochastic modeling is a form of financial model that is used to help make investment decisions. This type of modeling forecasts the probability of various outcomes under different conditions, A stochastic model is a tool for estimating probability distributions of potential outcomes by allowing for random variation in one or more inputs over time. The random variation is usually based on fluctuations observed in historical data for a selected period using standard time-series techniques. What is Stochastic Modeling? Understanding Stochastic Models. For a model to be stochastic, it must have a random variable where a level of Stochastic vs.
View PDF - PubsOnLine
Please provide any comments and contributions on the stochastic model to: email@example.com Many translated example sentences containing "stochastic model" – Swedish-English dictionary and search engine for Swedish translations. The baseline price assumptions for the EU27 are the result of world energy modelling (using the PROMETHEUS stochastic world energy model) that derives A Stochastic Model Predictive Control (SMPC) problemis formulated using a Linear Parameter Varying Bicycle Model, state- A stochastic model based on a probability density function (PDF) was developed for the investigation of different conditions that determine knock in spark ignition A stochastic model based on a probability density function (PDF) approach was developed for the investigation of spark ignition (SI) engine knock conditions.
Original wrappers. (Transactions of the Westermarck Society, vol VII.) 60 SEK Research interests: Stochastic processes, stochastic dynamics, random fields, long-range dependence, interacting systems, stochastic models in genetics and Model reduction for stochastic chemical systems with abundant species Molecular finite-size effects in stochastic models of equilibrium chemical systems. Image Processing: Stochastic Model Based: Stochastic Model Based Approach: K. Seetharaman: Amazon.se: Books.
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https://collegephysicsanswers.com/openstax-solutions/object-2-meters-front-flat-mirror-ray-1-object-travels-direction-toward-mirror
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math
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An object is 2 meters in front of a flat mirror. Ray 1 from the object travels in a direction toward the mirror and normal to the mirror’s surfacRay 2 from the object travels at an angle of 5° from the direction of ray 1, and it also reflects off the mirror’s surfacAt what distance behind the mirror do these two reflected rays appear to converge to form an image?
- 0.2 m
- 0.5 m
- 2 m
- 4 m
This is College Physics Answers with Shaun Dychko. An object is two meters in front of a flat mirror and Ray one is traveling normal to the mirror. And so it's angle of incidence is going to be the same of as it’s angle of reflection. And so it's going to bounce straight back at also at 90 degrees. And then Ray two is going at an angle five degrees with respect to the first Ray and it'll hit the mirror and then bounce-off with the same angle of reflection as it had for the angle of incidence. So the angle of incidence is five degrees and this dotted line is a normal to the mirror 90 degrees to the mirror and this angle between the normal and the ray is, these are interior opposite angles between parallel lines Ray one being parallel to this normal here. And so these angles here are both Theta so this Theta is in here and this Theta is there and then we're going to show that these two triangles are congruent by the way. This is what we're building up to here this triangle and this triangle are congruent and we're going to show that by the angle-side-angle rule and then after knowing that they're congruent we can then conclude that the image distance must be the same as the object distance because corresponding sides are equal in congruent triangles. So we can establish that this angle equals this angle in the green and blue triangles because they're both 90 degrees and then they share this common side. So those sides are equal between the two triangles and then we have to show that this angle here equals this angle here. And now given that this is Theta this is an opposite angle to this one. And so it's also Theta . And now this angle which you might call Red Dot angle plus Theta has to make 90 on this side and likewise on the other side the Red Dot plus Theta has to make 90. And so that means these two angles these red dots angles are the same and so these triangles are therefore congruent and because the congruent corresponding sides are equal and so the side opposite the Red Dot angle have to be equal and so the image distance then because that's what this side represents, the image distance is there for two meters behind the mirror.
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http://mathhelpforum.com/geometry/182583-height-isosceles-triangle-easy-question.html
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math
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This problem has not been solved. It can be done using coordinate geometry.I suggest you use an even integer base and when you get that answer convert by ratio to terms of rad2
I've been kind of confused about how to get the height of an triangle only by the base and the angle of two intersecting medians.
Here is the question
Find the height of the isosceles triangle that has base of sqrt2; the medians to the legs form two right angles.
Calling P the point where the medians intersect we can get a right triangle on the base, with height sqrt2/2 (that goes to point P) and base sqrt2.
I can't remember exactly what to do to get the missing part of the height.
Ok, I got it, this one was easy!
In a isosceles triangle the median of the base is equal to the height.
And the centroid is exactly two thirds of the median!
So sqrt2/2 1/3
I don't get it.
Why wouldn't the centroid theorem work here?
It works regardless of the triangle type.
If you can calculate the height of the point of the centroid, it's easy to calculate the rest of the height.
"The centroid is exactly two-thirds the way along each median. Put another way, the centroid divides each median into two segments whose lengths are in the ratio 2:1, with the longest one nearest the vertex."
Can you prove it otherwise?
Maybe by using coordinate geometry.
I agree that the height of a equilateral triangle is s*(sqrt3)/2.
If this is the case, we can assume that this triangle I am looking for is equilateral
This is what the question states:
The base of an isosceles triangle is ; medians to the legs intersect at right angles. The area of the triangle is:
The centroid(yes, again) thing can't be false here.
If we trace a line in the height here, it will equal the median to the base. So we can consider it to be the centroid!
bjhopper, I searched over for your coordinate geometry idea, and I couldn't find anything on Google. Can you make yourself clearer, please?
How would you do this question?
The triangle you are looking for is isosceles and not equilateral. It has special properties. Can you graph ?Draw a line equal to 12 units on the x axis . This gives you two points (0,0) and (12,0)Draw two 45 degree lines from these points so that they cross above the axis. They intersect at 90 deg. Erect the perpendicular bisector of the 12 base.Where the lines meet go up higher and find a segment equal to 3 units parallel to base that fits between the 45 line and the perpendicular.Connect a line from base point (12,0) to the intersection of the segment and 45 deg line. Extend it to meet perpendicular.This intersection is the apex of the required isosceles triangle .Measure the height and then by factor find result in terms of rad2
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s3://commoncrawl/crawl-data/CC-MAIN-2016-50/segments/1480698542693.41/warc/CC-MAIN-20161202170902-00388-ip-10-31-129-80.ec2.internal.warc.gz
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https://typedrawers.com/discussion/2823/s-shaped-question-mark
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math
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What's your first thought?
As much as I experienced type around me, and as I could investigate, virtually all typefaces feature question marks pointing down, i.e. towards their dots. This approach makes perfect sense as it resonates with the exclamation mark and is easy to carry over to darker weights.
I also suppose a lot of people write their "?" like that? What about you? I can't recall being taught how to write it at school, nor seeing it in a primer. It just appeared unexpectedly, or rather unnoticeably, as something as simple as a squiggly line with a dot, and whatever, who cares as long as it can be read. But somehow I write my "?" as a reversed "S" shape unless I'm being particularly typographic/calligraphic. I also sense this is the prevalent form in Poland.
Edit: I think it was in a primer after all. And S-shaped... So this makes it an infant form?
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s3://commoncrawl/crawl-data/CC-MAIN-2021-39/segments/1631780057496.18/warc/CC-MAIN-20210924020020-20210924050020-00281.warc.gz
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https://www.wisc-online.com/arcade/games/mathematics2?gameTypes=SPINWIN_SQUIDHUNT_JEOPARDY_BASEBALL_MATCHING
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math
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Chinese and English: Math Vocabulary
Math vocabulary for ESL students featuring clues in Chinese and English.
Solving 1 and 2 Step Equations Intro
Solving 1 and 2 step equations
Common Core Math Vocabulary
Are you as smart as a fourth grader? Test your basic Common Core Math vocabulary and find out!
Know the language of Multiplication
Addition of Single Digits
General Math: Section 2 Practice Sheet 1
Steines Squid Hunter - Algebra
Students will practice solving basic equations with this game.
Let's see if you still remember what we have learnt in Term 1!
Build your math fluency by hitting the math ball correctly.
Around the Circle
Identify the different parts of a circle along with the terms associated with it.
TriviaFriendzie: Math, Reading, Science, Social Studies
Something like Jeopardy, used to study for tests.
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s3://commoncrawl/crawl-data/CC-MAIN-2023-40/segments/1695233511000.99/warc/CC-MAIN-20231002132844-20231002162844-00151.warc.gz
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https://tutorme.com/tutors/246221/interview/
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math
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Tutor profile: Abigail A.
Subject: Study Skills
Why can't I get As in my classes that have a cumulative (or covering all past topics) tests when I study 4 hours straight every single day?
It's because you're studying 4 hours straight. After a certain amount of time, your brain will, for the most part tune out of new information. Instead of focusing on doing a solid 4 hours, try doing at most 25 minute study sessions with a minute long break that are focused on certain topics. Now your studying is more focused, and your less overwhelmed by large amounts of information. Hint: If 25 minutes is too much for you, try 20 or 15. Different people need different amounts of time and that's ok.
The black peppered moth is on decline while the white peppered moth is making a comeback. Why is that a good thing for the environment?
The black peppered moth is a type of moth that is discolored. When there is low pollution, it is easy for them to be seen by bird that eat them as they live on light colored lichen. When there is high pollution the moths are less likely to be seen on trees. The black peppered moths being in decline is positive because were successful because of high pollution. Without high pollution they are no longer as successful. Therefore, their decline is a good thing for the environment because it shows a decline of pollution levels.
Johnny has 36 apples and buys 1 every day. He eats 14 apples a week. How many days does it take for him to finish all the apples?
Step 1 making everything the same There is one number that isn't the same as the others. 14 apples per week. We need everything to be either in days or in weeks. Since our answer is going to be in days, we're going to change 14 apples per week into it's apples per day form. To do this we do I heart math. 14 apples 1 week ________ x ______ 1 week 7 days 14 is on the top because we're trying to find apples per day. 1 week/ 7 days is our conversion factor. 1 week equals 7 days. so 1 week/7 days. We have 1 week on the top because we want to have weeks on the top and weeks on the bottom. If we were trying to find how many days in a week, we'd use 7 days/ 1 week instead, or 7. When we multiply this fraction together we get: 14 apples x 1 week ______________ 1 week x 7 days and cancel out 1 week is on the top and the bottom so they cancel out, and they leave us with 14 apples ________ 7 days After we simplify, we're left with 2 apples/day Step 2 Now we make an equation x is our amount of days 36 is the amount of apples that Johnny had. -2x is the amount of apples he ate over x amount of days +1x is the amount of apples he bought over x amount of days 0 is for the amount of apples left This leaves us with the equation: 0= 36- 2x+1x ((EXTRA EXPLANATION -2x and 1 x have an x next to them because, remember 2 and 1 were the amount of apples Johnny bought and ate per day. To turn that speed of eating into actual apples you have to times it by the amount of days that passed. But, because we don't know how many days have passed, we'll leave them with an x, for now. -2x is being subtracted because that's what he's taking out of his kitchen versus 1x, which is added because he'd adding those apples to his kitchen )) Step 3: Simplify again 0=36-2x+1x can be simplified. -2x and 1x are the same, therefore, we can simply leaving us with: 0= 36-1x Step 4, X needs to be alone Now that the equation is the simplest it can be, we are going to move all the x's to the same side. In this case, we'll do it, via, addition. 0= 36-1x +1x= +1x The -1x and the +1x cancel out on the 36 side and the x and 1x add up together, leaving you with: x=36 Step 4 Recheck Now the second most important part. Check your work. We'll do that by putting 36 everywhere x was. So the equation will be: 0=36-2x36+1x36 0= 36-72+36 0 = 0 With that, you have the answer to the question: 36 days. Step 5 Reread the question. What is the question asking you to find? It's days, so we're done. Our answer is 36.
needs and Abigail will reply soon.
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s3://commoncrawl/crawl-data/CC-MAIN-2021-04/segments/1610704832583.88/warc/CC-MAIN-20210127183317-20210127213317-00268.warc.gz
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CC-MAIN-2021-04
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https://www.jiskha.com/display.cgi?id=1359587996
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math
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posted by Ashley .
Calculate the kinetic energy that the earth has because of (a) its rotation about its own axis and (b) its motion around the sun. Assume that the earth is a uniform sphere and that its path around the sun is circular. For comparison, the total energy used in the United States in one year is about 1.1 x 1020 J.
(a) KE(rot) =I ω²/2
ω=2π/24•3600 = ...(rad/ s)
Earth’s mass is M = 5.97•10²⁴kg,
Earth’s radius is R = 6.378•10⁶ m.
Linear velocity of the Earth is
v=ωr = 2π• 1.496•10¹¹ /365•24•3600 = …m/s
KE=Mv²/2 =5.97•10²⁴• (2π• 1.496•10¹¹ /365•24•3600)²/2 = …J
Thanks!! Clears up everything
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s3://commoncrawl/crawl-data/CC-MAIN-2017-34/segments/1502886104631.25/warc/CC-MAIN-20170818082911-20170818102911-00175.warc.gz
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https://demonstrations.wolfram.com/DistributionsOfOrderStatistics/
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math
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Distributions of Order Statistics
If independent values are drawn from some distribution and ordered from smallest to largest, the value is the order statistic. The distribution of this value depends on both the underlying distribution and the size of the sample, . In this Demonstration, you can choose among four probability distributions on the unit interval and view the distributions of the order statistics for that distribution for samples of various sizes. Mouse over the curves to view the means of the various distributions in the image.
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s3://commoncrawl/crawl-data/CC-MAIN-2024-10/segments/1707947474650.85/warc/CC-MAIN-20240226030734-20240226060734-00874.warc.gz
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CC-MAIN-2024-10
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https://zeyroon.com/qa/how-many-pennies-are-in-100.html
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math
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- How many pennies is in $20?
- How many dollars is 30000 pennies?
- How many pennies is 1000?
- How much money is 2 million pennies?
- How much money is 27000 pennies?
- How much money is a billion pennies?
- How much money is 40000 pennies?
- Where can I get $100 in pennies?
- How much is 50 lbs of pennies worth?
- How many pennies does it take to make $100?
- What does 100000 pennies weigh?
- How much is a water jug full of pennies?
- How much is 1 penny a day doubled for 30 days?
- How many pennies is 500 dollars?
- How much does 100 dollars worth of pennies weigh in pounds?
- How much would a 5 gallon bucket of pennies be worth?
- How many pennies is a dollar?
- How much does a 5 gallon bucket of pennies weigh?
How many pennies is in $20?
2,000 penniesThere are 2,000 pennies in 20 dollars.
To figure this out, start with the fact that there are 100 pennies in one dollar..
How many dollars is 30000 pennies?
30000 pennies also equals to:300 dollars30000 penny ÷ 100 = 300 dollars600 half-dollars30000 penny ÷ 50 = 600 half-dollars1200 quarters30000 penny ÷ 25 = 1200 quarters30000 cents30000 penny × 1 = 30000 cents
How many pennies is 1000?
The amount of dollars that 1,000 pennies is equal to is $10. To find this, we use the following fact: 100 pennies = $1.
How much money is 2 million pennies?
We’ll save you from math: a million pennies is $10,000. The fundraising approach make cents, er, sense, organizers said. It’s a lot easier to ask folks to donate pennies than any other amount, said Eleanor Hutchins, the club’s past president and current secretary. “We don’t want your money.
How much money is 27000 pennies?
There are 100 pennies in one dollar, 200 pennies is two dollars, so 2700 pennies is 27 dollars. Add the 23 cents and you get 27 dollars and 23 cents ( $27.23 ).
How much money is a billion pennies?
One billion pennies’ worth, to be exact. Proudly Pennies is a student-led fundraising initiative to raise one billion pennies, which translates to $10 million by 2013.
How much money is 40000 pennies?
It took over 40,000 pennies, which equates to around $400, but the end product is worth way more than that! The amount of time and effort it took this guy to do this to his kitchen is really amazing to behold.
Where can I get $100 in pennies?
Of course you can get $100 in pennies from a bank, provided that they know you want it ahead of time so they have the stock available to you. Call them and ask and they can order it.As for the size, a single penny is 360 cubic millimeters. … Assuming you are talking about recent pennies, they weigh about 2.5g each.
How much is 50 lbs of pennies worth?
you get roughly 90 Dollars and 72 cents in your pocket. Use it to pay bills or credit in bank, nice way to annoy those punks.
How many pennies does it take to make $100?
It takes exactly 100 pennies to make 100. 100 x 100 = 10,000 pennies.
What does 100000 pennies weigh?
New, unused or uncirculated copper cents weigh about 3.11 grams each or about 145 copper pennies per pound. New zinc cents are much lighter and weigh only 2.5 grams each yielding about 180 zinc pennies in a pound.
How much is a water jug full of pennies?
If you want to find out how many pennies it costs to fill the jug with water, the average price of simple, filtered water is $1.50, or 150 pennies. Originally Answered: How many pennies fit in a 5-gallon water bottle?
How much is 1 penny a day doubled for 30 days?
If you took a single penny and doubled it everyday, by day 30, you would have $5,368,709.12. However, it’s important to note that it’s all about the power of doubling – if you asked the same question, but changed the doubling time to just 27 days, you would only have $671,088.64.
How many pennies is 500 dollars?
There are 100 pennies in $1 so in $500 you’d multiply 500 by 100 or just take the 2 zeroes of 100 and add to 500 + 00 = 50,000. It takes 50,000 pennies to make $500.
How much does 100 dollars worth of pennies weigh in pounds?
First you have to calculate how many pennies it takes to make a pound and then multiply that by 100: New, unused or uncirculated copper cents weigh about 3.11 grams each or about 145 copper pennies per pound.
How much would a 5 gallon bucket of pennies be worth?
pennies diameter is 0.75″, thickness is 1.55 mm) the above computation would give a volume of about 0.029727 cu in, or about 7771 pennies per gallon. Hence five gallons can contain up to 7771 * 5 = 38,855 pennies.
How many pennies is a dollar?
100 penniesAnswer: 100 pennies, 20 nickels, 10 dimes, or 4 quarters; each = 1 dollar.
How much does a 5 gallon bucket of pennies weigh?
That means 731.28 or 731 rolls of pennies could fit into each bucket. Each roll being . 275 of a pound would be 201.02 pounds of pennies, thus turning the bucket from leak protection to strongman competition prop.
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s3://commoncrawl/crawl-data/CC-MAIN-2021-17/segments/1618038069267.22/warc/CC-MAIN-20210412210312-20210413000312-00376.warc.gz
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CC-MAIN-2021-17
| 4,852
| 55
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http://blog.philbirnbaum.com/2008/12/do-nba-general-managers-outperform.html
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math
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Do NBA general managers outperform sabermetric stats?
Last December, David Lewin and Dan Rosenbaum released a working version of a fascinating APBRmetrics paper. It's called "The Pot Calling the Kettle Black – Are NBA Statistical Models More Irrational than "Irrational" Decision Makers?"
Basically, the paper compares the state-of-the-art basketball sabermetric statistics to more naive factors that, presumably, uneducated GMs use when deciding who to sign and how much to pay. You'd expect that the sabermetric stats should correlate much better with winning. But, as it turns out, they don't, at least not by much.
Here's what the authors did. For each team, they computed various statistics, sabermetric and otherwise, for each player. Let me list them:
-- Minutes per game
-- Points per game
Except for the first two, the study adjusted each stat by normalizing it to the position average. More importantly, they normalized all six stats so that the sum of a team's individual stats would sum to the team's actual efficiency (points per possession minus points against per possession).
That team adjustment is important. I can phrase the result of that adjustment a different way: the authors took the team's performance (as measured by efficiency) and *allocated it among the players* six different ways, corresponding to the six different statistics listed above. (Kind of like six different versions of Win Shares, I guess).
For the most "naive" stat, minutes per game: suppose the team, on average, scored five more points per 100 possessions than its opponent. And suppose one player played half-time (24 minutes per game). That means he's responsible for one-tenth of his team's minutes, so he'd be credited with 0.5 points per game.
So the authors did this for all six statistics. Now, for the current season, all the teams will sum to their actual efficiency, because that's the way the stats were engineered. So you can't learn anything about the relative worth of the stats by using the current season.
But what if you use *next* season? Now, you can evaluate how well stats predict wins. That's because some players will have moved around. Suppose a team loses players A, B, and C off-season, but sign players X, Y, and Z.
Using minutes per game, maybe A, B, and C were worth +1 win, and players X, Y and Z were worth +2 wins. In that case, the team "should" – if minutes per game is a good stat – gain one win over last year.
But, using Wins Produced, maybe A, B and C were worth 1.5 wins, and X, Y and Z are also worth 1.5 wins. Then, if Wins Produced is accurate, the team should finish the same as last year.
By running this analysis on all six stats, and all teams, you should be able to figure out which stat is best. And you'd expect that the naive methods should be the worst – if sabermetric analysis is worth anything, wouldn't you think it should be able to improve on "minutes per game" in telling us which players are best?
But, surprisingly, the naive methods weren't that much worse than the sabermetric ones. Lewin and Rosenbaum regressed last year's player stats on this year's wins, and here are the correlation coefficients (r) he got:
0.823 -- Minutes per game
0.817 -- Points per game
0.820 -- NBA Efficiency
0.805 -- Player Efficiency Rating
0.803 -- Wins Produced
0.829 -- Alternate Win Score
It turns out that the method you'd think was least effective – minutes per game – outperformed almost all the other stats. The worst predictor was "Wins Produced," the carefully derived stat featured in "The Wages of Wins." (BTW, not all the differences in correlations were statistically significant, but the more extreme ones were.)
And repeating the analysis on teams two years forward, and three years forward, the authors find the results to be very similar.
So what's going on? Are general managers actually better at evaluating NBA players than existing sabermetric analysis? The authors think so:
"Our findings ... suggest that models that assume simplistic NBA decision-making often outperform more sophisticated statistical models."
I agree. But I don't think it's because GMs are omniscient – I think it's because even the best statistics measure only part of the game.
All of the above measures are based on "box score statistics" – things that are actually counted during the game. And there are more things counted on offense than on defense. For instance, shooting percentage factors into most of the above stats, but what about *opponent's* shooting percentage? That isn't considered at all, but we could all agree that forcing your opponent to take low-percentage shots is a major part of the defense's job. That's factored into the player ratings as part of the team adjustment, but all players get equal credit for it.
So: if coaches and general managers know how good a player is on defense (which presumably they do), and Wins Produced doesn't, then it's no surprise that GMs outperform stats.
Take a baseball analogy. In the National League, what correlates better to team wins summed at the player level – wOBA, or GM's evaluations? It would definitely be GM's evaluations. Why? Because of pitching. The GM would certainly take pitching into account, but wOBA doesn't. That doesn't mean that wOBA is a bad stat, just that it doesn’t measure *total* goodness, just hitting goodness.
Another one, and more subtle: what would correlate better with wins – wOBA or At Bats? It could go either way, again because of pitching. Better pitchers have playing time, and therefore more AB, so good pitching correlates with AB (albeit weakly). But good pitchers don't necessarily have a better wOBA. So AB would be better for measuring pitching prowess (although, of course, it would still be a very poor measure).
That means that if you run a regression using AB, you get a worse measure for hitters, and a better measure for batters. If you use wOBA, you get a better measure for hitters, but a worse measure for pitchers. Which would give you a better correlation with wins? We can't tell without trying.
What Lewin and Rosenbaum are saying is that, in basketball right now, sabermetric measures aren't good enough to compete with the judgments of GMs, and that APBRmetricians' confidence in their methods is unjustified. I agree. However, I'd argue that it's not that the new statistical methods are completely wrong, or bad, just that they don't measure enough of what needs to be measured.
If I wanted to reliably evaluate baskeball players, I'd start with the most reliable of the above six sabermetric measures – Alternate Win Score. Then, I'd list all the areas of the game that AWS doesn't measure, like various aspects of defensive play. I'd ask the GMs, or knowlegeable fans, to rate each player in each of those areas. Then, after combining those evaluations with the results of AWS, I'd bet I'd wind up with a rating that kicks the other methods' respective butts.
But, until then, I have to agree with the authors of this paper – the pot is indeed calling the kettle black. It looks like humans *are* better at evaluating talent than any of the widely available stats.
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s3://commoncrawl/crawl-data/CC-MAIN-2017-17/segments/1492917119642.3/warc/CC-MAIN-20170423031159-00395-ip-10-145-167-34.ec2.internal.warc.gz
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CC-MAIN-2017-17
| 7,152
| 34
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https://www.finchtheatre.com/contact-us
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math
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122 E. Lincoln Ave. • LINCOLN, KS 67455 785-524-4350
Have a question? Please use the following form to submit your
question to Finch Theatre.
Dec 2 - Dec 4
Strange World (PG)
Fri. & Sat.: 7 PM
Sun.: 3 PM
Running Time: 1 hr 42 mins
The legendary Clades are a family of explorers whose differences threaten to topple their latest and most crucial mission.
Running Time: 1 hr 42 mins
Genre: Animation, Action, Adventure
Director: Don Hall, Qui Nguyen
Cast: Jake Gyllenhaal, Jaboukie Young-White, Gabrielle Union, Alan Tudyk
Official Site: https://disney.fandom.com/wiki/Strange_World
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s3://commoncrawl/crawl-data/CC-MAIN-2022-49/segments/1669446710710.91/warc/CC-MAIN-20221129164449-20221129194449-00601.warc.gz
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CC-MAIN-2022-49
| 592
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http://www.chegg.com/homework-help/questions-and-answers/roller-coaster-car-may-represented-ablock-mass-500--car-released-rest-height-570-ground-sl-q189668
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math
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A roller-coaster car may be represented by ablock of mass 50.0 . The car is released from rest at a height = 57.0 above the ground and slides along a frictionless track.The car encounters a loop of radius = 19.0 at ground level, as shown. As you will learn in thecourse of this problem, the initial height 57.0 is great enough so that the car never loses contact withthe track.
1. Find an expression for the kinetic energyof the car at the top of the loop.
(Express the kinetic energynumerically, in joules.)
2. Find the minimum initial height at which the car can be released that still allows thecar to stay in contact with the track at the top of the loop.
(Express your answer numerically, inmeters.)
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s3://commoncrawl/crawl-data/CC-MAIN-2016-07/segments/1454701987329.64/warc/CC-MAIN-20160205195307-00327-ip-10-236-182-209.ec2.internal.warc.gz
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CC-MAIN-2016-07
| 704
| 5
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https://school.careers360.com/cbse/cbse-previous-year-question-papers-class-10-maths-2016?ici=school-view_related-news-articles&icn=article-view
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math
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CBSE Class 10 Maths Question Paper 2016 with Solutions
CBSE Class 10 Maths Question Paper 2016 with Solutions - Are you looking for CBSE 10 maths question paper 2016, then you are at the right place. Solving CBSE previous year question papers Class 10 Maths 2016 is an important part of the strategy for the board exam preparation. Students will get to know the exam pattern by referring to CBSE previous year papers and feel more confident to face the exam after solving CBSE class 10 maths question paper 2016. Here, you will get detailed analysis and solutions of CBSE previous year question papers Class 10 Maths 2016 for all the sets. Students should refer to CBSE class 10 maths question paper 2016 with solutions a one month before the exam.
Also, check CBSE previous year papers of Class 10 maths with solutions
CBSE class 10 maths 2016 question paper set-wise
CBSE 10 Class 2016 Paper: 030 set 1 Maths
CBSE 10 Class 2016 Paper: 030 set 2 Maths
CBSE 10 Class 2016 Paper: 030 set 3 Maths
Also read -
- CBSE Class 10 Maths Question Paper 2019 with Solutions
- CBSE Class 10 Maths Question Paper 2017 with Solutions
- CBSE Class 10 Maths Question Paper 2018 with Solutions
- CBSE Class 10 Maths Preparation Tips
How to Solve CBSE Class 10 Maths Question Paper 2016 with Solutions?
- First, try to solve CBSE previous year question papers Class 10 Maths 2016 on your own within the given time period.
- If you find difficulties while solving them, you can take help from these CBSE class 10 maths question paper 2016 with solutions provided in this article.
- Solutions of CBSE 10 maths question paper 2016 are prepared and explained in a detailed manner which can be understood easily.
After completing the entire syllabus of NCERT class 10 maths, you must practice the previous 5 years Class 10 CBSE question paper. It will also help you in the complete the final board paper on time and score well in the exam. In CBSE class 10 maths chapter 'Geometry' is considered to be the difficult chapter where most of the students feel trouble. Solving more problems from these chapters will help you to get command on these chapters.
CBSE Class 10 Maths 2016 Question Paper Pattern
CBSE Class 10 Maths Question Paper 2016 consists of 31 questions divided into four sections A, B, C, D. All these questions are compulsory.
CBSE 10 maths question paper 2016 contains four questions of one mark each where you need to answer in one word or one sentence as per the exact requirement of the question.
Section B of CBSE class 10 maths question paper 2016 with solutions contains six short answer type questions of two marks each where you need to answer as per the exact requirement of the question.
CBSE class 10 maths question paper 2016 section C contains 10 questions of three marks each where you need to provide complete solutions for each question.
Section D of the CBSE previous year question papers Class 10 Maths 2016 contains 11 long answer type questions of four marks each where you need to write a step-by-step complete solution for each question.
Note:- There is no internal choice given in CBSE 10 maths question paper 2016.
CBSE Class 10 Maths Question Paper 2016 with Solutions - Section-wise Division
Number of questions
CBSE class 10 maths 2016 question paper analysis
CBSE has conducted class 10 maths paper on the 19th March 2016 from 10.15 a.m. to 10.30 a.m. The starting 15 minute time has been allotted to read this question paper. This year's paper was considered to be tougher than the last year. Although most of the questions were directly taken from the NCERT or similar to the NCERT. Chater-wise marks distributions are tabulated below.
CBSE Class 10 Maths Question Paper 2016 Analysis
Pair of Linear Equations in Two Variables
Introduction to Trigonometry
Some Applications of Trigonometry
Areas Related to Circles
Surface Areas and Volumes
From the above analysis you can see that chapter 'Circles' has the highest weightage followed by the 'Surface area and volumes' in this paper. Only about 10% of the questions were difficult. Overall this paper was an average level but a little lengthier. Students who have conceptual clarity can score full marks also. Some students found it lengthy and weren't able to complete this paper on time. Students who have practiced well and solved some previous year's papers were able to complete this paper on time. An average student can score above 80 percent marks in this paper easily.
CBSE 10th Result 2021 - CBSE will release the Class 10 board e...
NCERT Solutions for Class 10 Science Chapter 14 Sources of Ene...
CBSE Class 10 Toppers Answer Sheet 2021 - CBSE Board will rele...
CBSE Class 10 Toppers 2021 - CBSE board will release the CBSE ...
Best Reference Books for CBSE Class 10 Mathematics - Know the ...
Questions related to CBSE Class 10th
Age criteria to appear in class 10 CBSE exam
According to guidelines of CBSE, minimum age to appear for class x must be 14 years. There is no upper limit to appear for class x cbse board.
A candidate can appear for maximum three attempts.
Some candidates give private exams or sometimes students fail in standard ix then they privately appear for class x then their age must be more than 14 years. Sometimes students appear for x class after one year gap of passing class ix then also their age would be 15 or 16 as there is no upper limit age.
My child is supposed to make another attempt at compartment exam of 10th cbse Missed last date for applying. since the boards are postponed to May 4th can I pay her fees and apply now.
Hello sir I'm sorry to inform you but now you're not eligible to fill the registration form as last date to fill the registration Form was 9th December 2020. Yes examination gets postponed to May but portal to fill the registration form is not open , in case if the registration form portal will open again you can fill the registration form and make the payment.
Feel free to comment if you've any doubt
i want to know the sample paper and marking scheme of 10 th science
To get the sample papers for CBSE Class 10th, you should visit the official CBSE website. There you can get all the papers. Solving the previous year papers, will be very beneficial for you. So, solve as much papers as you can.
As per the latest CBSE Class 10 exam pattern 2020-21, the theory paper will be of 80 marks, while 20 marks will be for internal assessment. To know more about exam pattern, please visit the link given below.
Check out the papers here:
will the 2021 board exams for grade 10 conducted online or offline
The 10th CBSE board exam will be conducted in offline mode only, These board exams will not be conducted in online mode. Central Board of Secondary Education conducts class 10th board examination for regular and private students. The exams of CBSE 10th 2021 will be conducted in February and March 2021. Candidates can fill CBSE 10th application form 2021 online on cbse.nic.in from October 24 to November 11, 2020.
is unit exam marks taken into consideration for cbse internal marks grade 10.
Your concern completely depends upon school. School management plans the division of marks. For few schools they must consider even class test on the other hand some just focus on mid and end . So the division of marks vary from school to school. What the school do is continuous access the student and then give marks accorrdingly. In my opinion focus on each and every test. Apart from internals it work for you in finals as well.
All the best
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s3://commoncrawl/crawl-data/CC-MAIN-2021-10/segments/1614178369553.75/warc/CC-MAIN-20210304235759-20210305025759-00023.warc.gz
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CC-MAIN-2021-10
| 7,492
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https://bostonrockproject.com/free-online-casino/kelly-criterion.php
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math
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Strategien, Tipps und Tricks, alles über das Kelly Criterion bei Mr Green. Finden Sie eine ausgewogenere Art der Verwaltung Ihrer Bankroll in Sportwetten. Die Kelly-Formel, auch Kelly-Kriterium genannt, dient der Gewinnmaximierung von Wetten mit positiver Gewinnerwartung. Sie geht auf den Wissenschaftler John Larry Kelly jr. zurück, der sie veröffentlichte. Die Kelly-Einsatzgröße wird ermittelt, indem der erwartete Wert des Logarithmus des Vermögens maximiert wird, was der Maximierung der.
Kelly-FormelErweiterte Suche. Springer Professional. Zurück zum Suchergebnis. Das Kelly-Kelly-Kriterium: eine Risikobewertung. Consider a gamble with known odds and. Die Kelly-Einsatzgröße wird ermittelt, indem der erwartete Wert des Logarithmus des Vermögens maximiert wird, was der Maximierung der. Download Citation | The Kelly Criterion: implementation, simulation and backtest | In dieser Masterarbeit wird das asymptotisch optimale Kelly Portfolio.
Kelly Criterion Other Betting Calculators VideoKelly Criterion Trading Strategy : Used by Buffett, Munger, Pabrai Because the Kelly Criterion seeks to calculate the optimum stake for any value bet so as to maximise that value as well as maximise the growth of your betting bankroll. In other words, the Kelly Criterion takes into account both the size of your advantage (I.e the value available) and the size of your bankroll, so as to minimise risk and maximise your advantage. The Kelly criterion is a formula used in estimating the growth of capital, it also calculates the expected value of wealth over a long period of time. The Kelly criterion was developed in by John L. Kelly, Jr and since then has been a strategy used in betting to determine the amount individuals should stake. In probability theory and intertemporal portfolio choice, the Kelly criterion (or Kelly strategy or Kelly bet), also known as the scientific gambling method, is a formula for bet sizing that leads almost surely to higher wealth compared to any other strategy in the long run (i.e. approaching the limit as the number of bets goes to infinity). The Kelly Criterion is a bet-sizing technique which balances both risk and reward for the advantage gambler. The same principle would work for any investment with an expectation of being profitable. For the gambler/investor with average luck bankroll and a fixed bet size, the expected bankroll growth after one bet is. The Kelly Criterion is a mathematical formula that helps investors and gamblers calculate what percentage of their money they should allocate to each investment or bet. The Kelly Criterion was.
A 3, 4, 9, 10, or 11 still pay 1 to 1 and every other total loses. Then the expected bankroll growth per bet would be:. This product is maximized by Kelly betting.
Kelly betting also minimizes the expected number of bets required to double the bankroll, when bet sizing is always in proportion to the current bankroll.
The Kelly bet amount is the optimal amount for maximizing the expected bankroll growth, for the gambler with average luck. While betting more than Kelly will produce greater expected gains on a per-bet basis, the greater volatility causes long-term bankroll growth to decline compared to exact Kelly bet sizing.
Betting double Kelly results in zero expected growth. Anything greater than double Kelly results in expected bankroll decline.
What is more commonly seen is betting less than the full Kelly amount. This system will help you to diversify your portfolio efficiently, but there are many things that it can't do.
It cannot pick winning stocks for you or predict sudden market crashes although it can lighten the blow.
There is always a certain amount of "luck" or randomness in the markets which can alter your returns. Money management cannot ensure that you always make spectacular returns, but it can help you limit your losses and maximize your gains through efficient diversification.
The Kelly Criterion is one of many models that can be used to help you diversify. Tools for Fundamental Analysis.
Ultimately, the Kelly Criterion calculator, if you are accurate with your assessed probability should increase your value and profit over a long-term period.
The Kelly criterion is a formula used in estimating the growth of capital , it also calculates the expected value of wealth over a long period of time.
The Kelly criterion was developed in by John L. Kelly, Jr and since then has been a strategy used in betting to determine the amount individuals should stake.
Taking expectations of the logarithm:. Thorp arrived at the same result but through a different derivation. Confusing this is a common mistake made by websites and articles talking about the Kelly Criterion.
Without loss of generality, assume that investor's starting capital is equal to 1. According to the Kelly criterion one should maximize.
Thus we reduce the optimization problem to quadratic programming and the unconstrained solution is. There is also a numerical algorithm for the fractional Kelly strategies and for the optimal solution under no leverage and no short selling constraints.
Although the Kelly strategy's promise of doing better than any other strategy in the long run seems compelling, some economists have argued strenuously against it, mainly because an individual's specific investing constraints may override the desire for optimal growth rate.
Even Kelly supporters usually argue for fractional Kelly betting a fixed fraction of the amount recommended by Kelly for a variety of practical reasons, such as wishing to reduce volatility, or protecting against non-deterministic errors in their advantage edge calculations.
From Wikipedia, the free encyclopedia. Bell System Technical Journal. The formula is used to determine the optimal amount of money to put into a single trade or bet.
Some argue that an individual investor's constraints can affect the formula's usefulness. Compare Accounts. The offers that appear in this table are from partnerships from which Investopedia receives compensation.
Related Terms Martingale System Definition The Martingale system is a system in which the dollar value of trades increases after losses, or position size increases with a smaller portfolio size.
Anti-Martingale System Definition The anti-Martingale system is a trading method that involves halving a bet each time there is a trade loss, and doubling it each time there is a gain.
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s3://commoncrawl/crawl-data/CC-MAIN-2021-43/segments/1634323585025.23/warc/CC-MAIN-20211016200444-20211016230444-00577.warc.gz
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CC-MAIN-2021-43
| 6,416
| 23
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http://www.huntingtonherald.com/2019/suggestions-to-decide-a-grade-point-average.htm
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math
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The quickest approach to calculate a Grade Point Average would most likely be to utilize a College Grade Point Average Calculator. There are great deals of kinds of College or university Grade Point Average Calculators and then there is just one for the each. There is fixed price College Grade Point Average Calculator, a university Grade Point Average Calculator, an adjustable selling price College Grade Point Average Calculator, a balloon School Grade Point Average Calculator, a re-financing GPA, an APR College GPA Calculator and a lot much more. A Fixed Price Calculator is one of the most continual calculators on the web. This may be used to calculate a GPA using a set rate of interest. The value referred to as for here would likely be the money expression, your backing measurements, along with the interest rate.
If You Want to Determine a Grade Point Average pay back, regular monthly, goes into the amount the company is probably to auto loan you personally and the repayment timetable you might surely like. Do you rather have a day-to-day, a regular, per month-to-month, or perhaps an annual estimation? An adaptable price Calculator needs a variety of ideals and info from a predetermined College GPA Calculator. Through a variable value Grade Point Average, the customer begins with a much lessened interest rate nevertheless bears the opportunity for possible boosts in Grade Point Average Calculator College. About the various other hands, if Grade Point Average costs fall, the customer achieves the advantages. Owning an amortization plan potential modifications may possibly moreover be calculated with a known as customization interest rate. A balloon Grade Point Average, typically, is actually a 10 Years plan. Through the length, the customer could include a little bit % of the GPA.
Using a balloon University or college grade calculator final it is possible to determine a GPA remainder when the GPA balloons in example you addresses merely a certain amount monthly. Using a refinancing College or university Grade Point Average Calculator, you might discover simply how much your possible cost savings will most likely be; along with the level of months it could earlier you would undoubtedly crack even on shutting prices. APR or rate of interest indicates the complete rate of a GPA by positioning into the solution not simply the curiosity but additionally various other points and costs. In the event you want to figure out a Grade Point Average as well as its real rate to the debtor, employ an APR College Grade Point Average Calculator.
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s3://commoncrawl/crawl-data/CC-MAIN-2024-10/segments/1707947474669.36/warc/CC-MAIN-20240226225941-20240227015941-00431.warc.gz
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CC-MAIN-2024-10
| 2,575
| 3
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http://en.bab.la/dictionary/turkish-english/cpt
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math
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"CPT" English translation
Suggest new Turkish to English translation
In the two input fields below you can add new Turkish translation suggestions to be included in the Turkish-English dictionary. Perhaps you know of a particular Turkish regional expression or a Turkish colloquial term. This is your chance to share what you know with everyone else through the Turkish-English dictionary.
Latest word suggestions by users: adhan, funfair, date sent, recurrence, illiterate
Çözümleme · çözümlemeli · Çözümlendi · Çözümlenen · Çözümleniyor · çözümleyici · çözünmek · çözünülürlük · çözünürlük · cpl · cpt · CRAC · Creole · crl'ler · CRS · crsel/props · crt · crt/tv · csma · csma/ca · csma/cd
Moreover bab.la provides the Dutch-English dictionary for more translations.
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CC-MAIN-2017-04
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https://dml.cz/handle/10338.dmlcz/118706
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math
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analytic function; $\Cal I$-density continuous; $\Cal I$-density topology
A real function is $\Cal I$-density continuous if it is continuous with the $\Cal I$-density topology on both the domain and the range. If $f$ is analytic, then $f$ is $\Cal I$-density continuous. There exists a function which is both $C^\infty $ and convex which is not $\Cal I$-density continuous.
Aversa V., Wilczyński W.: Homeomorphisms preserving $\Cal I$-density points
. Boll. Un. Mat. Ital. B(7)1 (1987), 275-285. MR 0895464
Ciesielski K., Larson L.: The space of density continuous functions
. Acta Math. Hung. 58 (1991), 289-296. MR 1153484
| Zbl 0757.26006
Poreda W., Wagner-Bojakowska E., Wilczyński W.: A category analogue of the density topology
. Fund. Math. 75 (1985), 167-173. MR 0813753
Wilczyński W.: A generalization of the density topology. Real Anal. Exchange 8(1) (1982-83), 16-20.
Wilczyński W.: A category analogue of the density topology, approximate continuity, and the approximate derivative
. Real Anal. Exchange 10 (1984-85), 241-265. MR 0790803
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CC-MAIN-2023-14
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https://aubtu.biz/51709/
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math
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Autocorrect function has been around for ages. And fairly to say, people have got more troubles with it rather than benefits. Ever since it was introduced to IOS in 2007, autocorrect has been the true culprit behind countless mother ducking incorrect text messages. Instead of suggesting the right option for your words, this function usually alters your text in an inexplicably weird sense. And as a result, people have a lot of cry-laughing situations, sending messages with the wrong meaning.
Even though we’ve already had a fair share of autocorrect mishaps, these things never stop being funny. And here, we have collected some tweets where people humiliate this amazing function and what it has done to them. Well, something that runs by codes cannot be as good as a human’s brain, right? We know this gets so silly sometimes, but what can we do? At least, it brings some fun to us on gloomy days. That’s good enough. Now, let’s scroll down and enjoy the time with us!
#1 Why don’t you let me enjoy my food
#2 True wise word
#3 Blame the autocorrect for it
#4 Rare case when autocorrect does correct a message
#5 Don’t make me sound like I’m really that excited
#6 High hope
#7 Don’t really know who corrects who here
#8 It’s secretly laughing behind our backs
#9 You can’t hide from autocorrect
#10 Pretty good, indeed
#11 Poor man got fooled
#12 If something can go wrong, it will go wrong
#13 Autocorrect knows what’s up
#14 Now that we know your secret
#15 Got it!
#16 I like to have both
#17 Don’t make up my words like that
#18 It’s a hint!
#19 Now that everyone will never look at you the same, ever
#20 Now that I believe autocorrect has intelligence
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CC-MAIN-2022-33
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http://cms.math.ca/cjm/kw/vector%20bundle
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math
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1. CJM 2014 (vol 66 pp. 961)
|Moduli Spaces of Vector Bundles over a Real Curve: $\mathbb Z/2$-Betti Numbers|
Moduli spaces of real bundles over a real curve arise naturally as Lagrangian submanifolds of the moduli space of semi-stable bundles over a complex curve. In this paper, we adapt the methods of Atiyah-Bott's ``Yang-Mills over a Riemann Surface'' to compute $\mathbb Z/2$-Betti numbers of these spaces.
Keywords:cohomology of moduli spaces, holomorphic vector bundles
2. CJM 2011 (vol 63 pp. 616)
|A Modular Quintic Calabi-Yau Threefold of Level 55|
In this note we search the parameter space of Horrocks-Mumford quintic threefolds and locate a Calabi-Yau threefold that is modular, in the sense that the $L$-function of its middle-dimensional cohomology is associated with a classical modular form of weight 4 and level 55.
Keywords: Calabi-Yau threefold, non-rigid Calabi-Yau threefold, two-dimensional Galois representation, modular variety, Horrocks-Mumford vector bundle
Categories:14J15, 11F23, 14J32, 11G40
3. CJM 2010 (vol 62 pp. 1201)
|Criteria for Very Ampleness of Rank Two Vector Bundles over Ruled Surfaces|
Very ampleness criteria for rank $2$ vector bundles over smooth, ruled surfaces over rational and elliptic curves are given. The criteria are then used to settle open existence questions for some special threefolds of low degree.
Keywords:vector bundles, very ampleness, ruled surfaces
4. CJM 2005 (vol 57 pp. 871)
|Hermitian Yang-_Mills--Higgs Metrics on\\Complete Kähler Manifolds |
In this paper, first, we will investigate the Dirichlet problem for one type of vortex equation, which generalizes the well-known Hermitian Einstein equation. Secondly, we will give existence results for solutions of these vortex equations over various complete noncompact K\"ahler manifolds.
Keywords:vortex equation, Hermitian Yang--Mills--Higgs metric,, holomorphic vector bundle, Kähler manifolds
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CC-MAIN-2014-35
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https://calculator.info/x-intercept-calculator/
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math
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The X and Y Intercept calculator is a free to be used calculator available on the digital space that gives you the intercepts for any given straight line equation (given by y = mx + c). The specific point or the coordinates where the line intersects with the axis of the graph is called an intercept that has both X and Y values.
If a point crosses the x-axis, then it is known as the x-intercept. Likewise, where a point crosses the y-axis is the y-intercept. The standard equation for the straight line is:
Ax + By = C, where A is the coefficient of x, B is the coefficient of y, and C is a constant independent of x and y values.
The procedure to use x and y-intercept calculator is as follows:
Step 1: First you are supposed to enter the coefficients of the straight line equation A, B and C in the input fields.
Step 2: Next, you must click the button “solve” to get the output.
Step 3: Eventually, the result will be displayed in the corresponding x and y-intercept fields.
The x-intercept occurs when y=0 and the y-intercept occurs when x = 0.
To find the x-intercept using the straight-line equation, substitute y=0 and solve for x. To find the y-intercept, substitute x=0 and solve for y.
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CC-MAIN-2024-18
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https://nrich.maths.org/public/topic.php?code=71&cl=3&cldcmpid=5888
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math
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These formulae are often quoted, but rarely proved. In this article, we derive the formulae for the volumes of a square-based pyramid and a cone, using relatively simple mathematical concepts.
Imagine two identical cylindrical pipes meeting at right angles and think about the shape of the space which belongs to both pipes. Early Chinese mathematicians call this shape the mouhefanggai.
Show that among the interior angles of a convex polygon there cannot be more than three acute angles.
A huge wheel is rolling past your window. What do you see?
Can you see how this picture illustrates the formula for the sum of the first six cube numbers?
The picture illustrates the sum 1 + 2 + 3 + 4 = (4 x 5)/2. Prove the general formula for the sum of the first n natural numbers and the formula for the sum of the cubes of the first n natural. . . .
A little bit of algebra explains this 'magic'. Ask a friend to pick 3 consecutive numbers and to tell you a multiple of 3. Then ask them to add the four numbers and multiply by 67, and to tell you. . . .
Do you know how to find the area of a triangle? You can count the squares. What happens if we turn the triangle on end? Press the button and see. Try counting the number of units in the triangle now. . . .
Is it possible to rearrange the numbers 1,2......12 around a clock face in such a way that every two numbers in adjacent positions differ by any of 3, 4 or 5 hours?
If you can copy a network without lifting your pen off the paper and without drawing any line twice, then it is traversable. Decide which of these diagrams are traversable.
Can you make sense of these three proofs of Pythagoras' Theorem?
Spotting patterns can be an important first step - explaining why it is appropriate to generalise is the next step, and often the most interesting and important.
Can you use the diagram to prove the AM-GM inequality?
A circle has centre O and angle POR = angle QOR. Construct tangents at P and Q meeting at T. Draw a circle with diameter OT. Do P and Q lie inside, or on, or outside this circle?
A standard die has the numbers 1, 2 and 3 are opposite 6, 5 and 4 respectively so that opposite faces add to 7? If you make standard dice by writing 1, 2, 3, 4, 5, 6 on blank cubes you will find. . . .
Pick a square within a multiplication square and add the numbers on each diagonal. What do you notice?
Construct two equilateral triangles on a straight line. There are two lengths that look the same - can you prove it?
Can you discover whether this is a fair game?
We are given a regular icosahedron having three red vertices. Show that it has a vertex that has at least two red neighbours.
Prove Pythagoras' Theorem using enlargements and scale factors.
Eight children enter the autumn cross-country race at school. How many possible ways could they come in at first, second and third places?
Choose a couple of the sequences. Try to picture how to make the next, and the next, and the next... Can you describe your reasoning?
Kyle and his teacher disagree about his test score - who is right?
This shape comprises four semi-circles. What is the relationship between the area of the shaded region and the area of the circle on AB as diameter?
Can you find the areas of the trapezia in this sequence?
Janine noticed, while studying some cube numbers, that if you take three consecutive whole numbers and multiply them together and then add the middle number of the three, you get the middle number. . . .
Three points A, B and C lie in this order on a line, and P is any point in the plane. Use the Cosine Rule to prove the following statement.
Can you cross each of the seven bridges that join the north and south of the river to the two islands, once and once only, without retracing your steps?
Here are some examples of 'cons', and see if you can figure out where the trick is.
Which hexagons tessellate?
Toni Beardon has chosen this article introducing a rich area for practical exploration and discovery in 3D geometry
Four jewellers share their stock. Can you work out the relative values of their gems?
Patterns that repeat in a line are strangely interesting. How many types are there and how do you tell one type from another?
Take any rectangle ABCD such that AB > BC. The point P is on AB and Q is on CD. Show that there is exactly one position of P and Q such that APCQ is a rhombus.
Euler discussed whether or not it was possible to stroll around Koenigsberg crossing each of its seven bridges exactly once. Experiment with different numbers of islands and bridges.
It is impossible to trisect an angle using only ruler and compasses but it can be done using a carpenter's square.
This is the second article on right-angled triangles whose edge lengths are whole numbers.
Points A, B and C are the centres of three circles, each one of which touches the other two. Prove that the perimeter of the triangle ABC is equal to the diameter of the largest circle.
The first of two articles on Pythagorean Triples which asks how many right angled triangles can you find with the lengths of each side exactly a whole number measurement. Try it!
If you know the sizes of the angles marked with coloured dots in this diagram which angles can you find by calculation?
Prove that the shaded area of the semicircle is equal to the area of the inner circle.
Find the area of the annulus in terms of the length of the chord which is tangent to the inner circle.
Semicircles are drawn on the sides of a rectangle. Prove that the sum of the areas of the four crescents is equal to the area of the rectangle.
Consider the equation 1/a + 1/b + 1/c = 1 where a, b and c are natural numbers and 0 < a < b < c. Prove that there is only one set of values which satisfy this equation.
Is the mean of the squares of two numbers greater than, or less than, the square of their means?
Prove that, given any three parallel lines, an equilateral triangle always exists with one vertex on each of the three lines.
Some puzzles requiring no knowledge of knot theory, just a careful inspection of the patterns. A glimpse of the classification of knots and a little about prime knots, crossing numbers and. . . .
It is obvious that we can fit four circles of diameter 1 unit in a square of side 2 without overlapping. What is the smallest square into which we can fit 3 circles of diameter 1 unit?
When number pyramids have a sequence on the bottom layer, some interesting patterns emerge...
What does logic mean to us and is that different to mathematical logic? We will explore these questions in this article.
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http://hzessayachl.representcolumb.us/theory-and-percentage-change.html
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math
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Price elasticity is calculated by taking the percentage change in quantity divided by the percentage change game theory game theory introduction: nash equilibrium. In change management, it is very important to understand the fuller range of stakeholders. Fact or theory by john p i've found it helps me much more to always have a reason for the change, which is to test my current theory separate observations from. This is the aptitude questions and answers section on percentage with explanation for various interview, competitive examination and entrance test solved examples.
Elasticity of scale or output elasticity measures the percentage change in output induced by a collective percent change in the usages of all inputs a production. Herzberg’s two-factor theory illustrates the percentage of learner recall that is associated with various approaches change management. This pack of eco 316 week 1 chapter 5 the theory of portfolio allocation comprises: the wealth elasticity of demand describes the percentage change in 14). Full explanation of this strategic innovation and communication model and change the innovation adoption curve of rogers is a model of innovations theory.
Percents - gmat math study guide when a percentage is represented as a decimal, percent change percents are commonly used to measure or report the change. In mathematics, a percentage is a number or ratio expressed as a fraction of 100 it is often denoted using the percent sign, percentage change references. Learn why implementing a research-based change management strategy for project initiatives drives results. The change curve demonstrates how we as individuals, react to change and typically what phases we go through, until we accept the change this guide will help. Theory one of the many , that only a small percentage of the world’s likely to take you as you are than try to change you into what they thought.Math explained in easy language, plus puzzles, games, quizzes, worksheets and a forum for k-12 kids, teachers and parents. Theory of the consumer inflation is defined as a rise in the overall price level, if the percentage change in the gdp deflator over some period is a. Casino mathematics casino is trying to change his deviation can be predicted from statistical theory) the actual win percentage is just. Some of the specific measures used to explore these elements of population change are discussed below while demography theory describing the percentage. Scientific consensus on human-caused global warming as compared to global climate change' and 'global warming' published theory to the highest. Free theory test practice using official dvsa test questions our guide gives you all the information needed to pass the theory test. The early atmosphere scientists believe that the earth was formed about 45 billion years ago its early atmosphere was probably formed from the gases given out by. Start studying quizes 10-15 learn vocabulary, according to keynesian theory, the percentage change in real gdp from one period to another is called.
Estimated 40 percent of scientists doubt manmade global warming estimated 40 percent of scientists doubt manmade global panel on climate change. Percentage change and percent difference when looking at a table or a graph, it is useful to understand the meaning between changes in different data points. Smart behavior change outcome objectives step 42: write specific, measurable objectives for each intervention activity outcome objectives specify the kind and. Vital signs of the planet: global climate change and global warming partial list of leading scientific organizations endorsing human-induced climate change, along.
Titrimetric determination of acetic acid in vinegar as we are dealing with solutions that have their concentrations listed as mass percentage, color change. Elasticity and its application as the percentage change in the quantity demanded divided by the percentage change in price price elasticity = percentage change in qd. Driving tests and learning to drive or ride popular services book your theory test book your driving test change your driving test appointment. 1 an introduction to consumer price index it provides a summary of the relevant theory and practice of index number the percentage change,.
All ipcc definitions taken from climate change 2007: holding the accepted theory to the highest standard is what a scientist is supposed to do.Download
2018. Term Papers.
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CC-MAIN-2018-43
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https://www.simiode.org/tags/heat
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math
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Potential Scenario Ideas : nuclear fusion for electric power generation?
17 Jan 2022 | Contributor(s):: Andrew M Ross
It occurred to me that students thinking about climate change might want to take a look at electric power generation via nuclear fusion. I know very little about this area, but perhaps someone out there does? I think students would be interested in just about any of the proposed technologies:...
31 Aug 2020 | | Contributor(s):: Jeremy Cristman, Kenneth Luther, Michael Karls
The goals of this project are to compare a conceptual one-dimensional groundwater flow model to observations made in a laboratory setting, and to discuss the differences. We derive the initial groundwater flow equation, and guide students through a solution. We describe the laboratory set up and...
2014-Monagan, Michael - The House Warming Model. Department of Mathematics
05 Apr 2020 | | Contributor(s):: Brian Winkel
Monagan, Michael. 2014. The House Warming Model. Department of Mathematics, Simon Fraser UniversitySee http://www.cecm.sfu.ca/~mmonagan/papers/HouseReporter.pdf .Maple commands: s o l v e , c o l l e c t , d s o l v e , o d e p l o t , D E p l o tIntroduction:...
2012-Bech, Michael Møller; Morten Lykkegaard Christensen; Lars Diekhöner; Christian Frier; Olav Geil; Erik Lund; Peter Nielsen; Thomas Garm Pedersen; Bo Rosbjerg - ResourcesForEngineeringApplicationsOfMath
01 Apr 2020 | | Contributor(s):: Brian Winkel
Bech, Michael Møller, Morten Lykkegaard Christensen, Lars Diekhöner, Christian Frier, Olav Geil,Erik Lund, Peter Nielsen, Thomas Garm Pedersen, Bo Rosbjerg. 2012. APPLICATIONS OF MATHEMATICSIN ENGINEERING AND SCIENCE. School of Engineering and Science, Aalborg University. 26...
2006-Lingefjard, Thomas - Faces of mathematical modeling
25 Mar 2020 | | Contributor(s):: Brian Winkel
Lingefjard, Thomas. 2006. Faces of mathematical modeling. ZDM. 38(2): 96-112.See https://subs.emis.de/journals/ZDM/zdm062a3.pdf .Abstract: In this paper I will discuss and exemplify my perspectives on how to teach mathematical modeling, as well as discuss quite different faces of...
2016-Moura, Scott - Chapter 1: Modeling ad Systems Analysis. Class Notes for CE 295
20 Mar 2020 | | Contributor(s):: Brian Winkel
Moura, Scott. 2016. Chapter 1: Modeling ad Systems Analysis. Class Notes for CE 295 — Energy Systems and Control, University of California, Berkeley. 20 pp.Overview: The fundamental step in performing systems analysis and control design in energy systems is mathematical...
14 Oct 2019 | | Contributor(s):: Kimberly Spayd, James Puckett
This project guides students through experimental, analytical, and numerical techniques for understanding the heat (diffusion) equation with nonhomogeneous boundary conditions. In particular, students collect data and model a physical scenario in which heat energy diffuses through a long, thin...
13 Aug 2019 | | Contributor(s):: Kurt Bryan
This project uses the steady-state heat equation to model the temperature distribution in an industrial furnace used for metal production, for example, a blast furnace.The heat flow is assumed to be steady-state, so that only an elementary ordinary differential equation (ODE) is needed, and...
31 Mar 2019 | | Contributor(s):: Mitaxi Pranlal Mehta
Differential equations and Laplace transforms are an integral part of control problems in engineering systems. However a clear explanation of the relationship of Laplace transforms with the differential equation formalism is difficult to find for coupled differential equations. Here we describe...
22 Aug 2018 | | Contributor(s):: Norman Loney
We present a differential equation model for the temperature of a mercury thermometer which is sitting in a stream of water whose temperature oscillates. We suggest a solving strategy which uses Laplace Transforms.
18 Aug 2018 | | Contributor(s):: Suruchi Singh
The heat equation is an important partial differential equation (PDE) which describes the distribution of heat in a given region over time. Here we learn to solve a heat equation numerically. It is difficult to study the behavior of temperature in problems with interfaces analytically so...
30 Jan 2018 | | Contributor(s):: Kurt Bryan
This project concerns the heating of a house. In particular, if one is going away for awhile, is it more economical to leave a house at a desired temperature or reheat it upon return? Both scenarios are analyzed in a series of exercises.
2005-Lie, Knut–Andreas - Introduction to Mathematical Modelling: Ordinary Differential Equations and Heat Equations
10 Sep 2017 | | Contributor(s):: Brian Winkel
Lie, Knut–Andreas. 2005. Introduction to Mathematical Modelling: Ordinary Differential Equations and Heat Equations. SINTEF ICT, Dept. Applied Mathematics PowerPoint slide. 45 slides. www.uio.no/studier/emner/matnat/ifi/INF2340/v05/foiler/sim02.pdf . Accessed 9 September...
2017-Gustafson, G. B. - Differential Equations Course Materials
08 Sep 2017 | | Contributor(s):: Brian Winkel
This material is from a wealth of other material authored by Grant B. Gustafson in the Mathematics Department at the University of Utah. See http://www.math.utah.edu/~gustafso/ for up to date information on his productivity! One could spend hours looking through here for examples,...
A Three-Fold Approach to the Heat Equation: Data, Modeling, Numerics
13 Oct 2016 |
Posted by Brian Winkel
James Puckett and Kimberly Spayd have authored a wonderful article in the current issue of PRIMUS with full citation:
Spayd, K. and J. Puckett. 2016. A Three-Fold Approach to the Heat Equation:...
1981-Berresford, Geoffrey C. - Differential Equations and Root Cellars
25 Jun 2015 | | Contributor(s):: Geoffrey C. Berresford
Berresford, Geoffrey C. 1981. Differential Equations and Root Cellars. UMAP Unit 554. 23 pp. 23 pp. Available from http://www.comap.com.This is a classic module from UMAP in which the heat equation in one dimension is fully developed by using the standard technique of measuring the heat...
02 Jun 2015 | | Contributor(s):: Brian Winkel
We offer data on the temperature of water in a beaker which resides in a room of constant temperature and also in an environment of nonconstant temperature. Students are encouraged to consider both empirical and analytic modeling approaches. We offer additional data sets in Excel spreadsheets...
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https://snucongo.org/what-is-73-as-a-fraction/
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math
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Scroll under to customize the precision point enabling .73 come be broken down come a specific variety of digits. The page also includes 2-3D graphical representations of .73 as a fraction, the different species of fractions, and also what type of portion .73 is when converted.
You are watching: What is 73 as a fraction
Graph representation of .73 together a FractionPie chart representation of the fractional component of .73
Level the Precision because that .73 as a Fraction
The level of precision room the variety of digits to ring to. Select a lower precision suggest below to rest decimal .73 down additional in fraction form. The default precision allude is 5.If the last rolling digit is "5" you have the right to use the "round half up" and also "round half down" choices to round the digit increase or down as soon as you adjust the precision point.For example 0.875 through a precision point of 2 rounded fifty percent up = 88/100, rounded fifty percent down = 87/100.select a precision point:123456789 round fifty percent up round fifty percent down
Enter a Decimal Value: this.maxLength)this.value=this.value.slice(0,this.maxLength);">Show as a fraction
Is73/100 a Mixed, whole Number or proper fraction?A blended number is comprised of a entirety number (whole numbers have actually no spring or decimal part) and also a proper fraction part (a fraction where the numerator (the peak number) is much less than the denominator (the bottom number). In this situation the whole number worth is empty and also the proper fraction value is 73/100.
Can every decimals it is in converted into a fraction?
Not every decimals have the right to be converted into a fraction. There space 3 an easy types which include:Terminating decimals have a limited number of digits after the decimal point.Example:2332.9819 = 2332 9819/10000Recurring decimals have one or an ext repeating numbers after the decimal suggest which continue on infinitely.Example:9429.3333 = 9429 3333/10000 = 333/1000 = 33/100 = 1/3 (rounded)Irrational decimals walk on forever and also never kind a repeating pattern. This form of decimal cannot be expressed together a fraction.Example: 0.216773948.....
See more: Quick Answer: Does Play Doh Dissolve In Water ? Quick Answer: Does Play Doh Dissolve In Water
Fraction right into DecimalYou can also see the reverse conversion I.e. How fraction 73/100is converted right into a decimal.
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https://www.bontegames.com/2021/01/indiana-hat-and-temple-of-puzz-browser.html
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math
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Indiana Hat and the Temple of Puzz is the companion game to the puzzle game below, another new puzzlescript puzzler by Thinky Collective, a collaborative game starting from the same first level by a group of developers passing on the game. (Z key to undo a move, R key to restart a level)
I'm already stuck at level 2. Anybody got a clue? Maybe I get the twist then. Thanks. ;-)
hint level 2 : start by pushing left box on the left
need a hint for level 7
How do you know what level you're at?
@Megan : there's a "level select" in the menu (press "escape")
I'm stuck on #6
hint level 6 : you need to put a box next to the one up there
Anyone figure out level 7? I've been working on it since yesterday.
re: level 6, I tried that! Argh!
I'm out. Moving around is way too twitch sensitive for me.
For 7 don't leave anything on the left hand side, make a couple of "knock off" moves from the middle low hanging wall, try to gain access to the upper row of ladders. Remember two horizontal pieces stick and it doesn't matter what vertical position they are in.
I1m stuck at level #13. Can't seem to pick up the ring AND not be burned in lava.
How did you get #12 ? can't figure the trick
power of posting, got #12.
level #13 : you can throw away the ring pressing down
@anonymous Thank you!
aaand, now I'm stuck at #14...
#14: solved, forgot, then resolved with a bit of frustration... one of the states I thought was doomed turned out to be easily it with one extra loop around.
you never have to leave the lower section to solve the main part of the puzzle, which is coming up with both blocks. the upper section just ensures you have both blocks, but doesn't grant you any other meaningful choices.
maybe this is too spoilery of a hint, but there's only one meaningful state that has a block at y=2 (taking floor blocks as y=0 and lava blocks as y=-1). you can then climb down the blocks
finally got level 7, so now i have 1-18...
i thought earlier anonymous's hints was stuff i already knew, but turns out that i had focused on the wrong part of the sentence.
an additional hint i'd give is that if you play around a lot, you'll notice that there's a particular method of stacking blocks that gives you probably the maximum of possibilities. so, what if you just did that as much as possible?
I still don't understand level 14. Can anybody offer any tips?
Oh, never mind! I will just clarify that you only need one of the blocks and the ring to solve level 14
^^ yes, i misspoke because I thought of a ring as a block. obviously the ring is required to open the door
I'm still stuck on #14. Can't seem to find out how to be able to bring a box up.
Power of posting...
Once you get the block up the ladder in #14, how do you get it off your head?
OK, never mind... how about #15?
#15 stack on ring on top of the other to start.
any hints for 19?
For 19 make a column of blocks and rings in order so if you were to walk to the right and jump the rings line up with the sockets.
Finally finished, good game, and probably overthought a few levels. There is a walkthrough for level 7 available for those still stuck on that one. The above hints all helped with the other levels so thanks all.
Walkthrough here : https://youtu.be/kA_x2J_oaEI
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http://www.c-130hercules.net/store/category/15-stickers/?view=list
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“I highly recommend Casey for his prints. He really made sure I got exactly what I wanted for a description and history of my plane. Anyone even thinking about one; go for it. I'm sure you will be happy.” Mark K.
“The print arrived in the mail yesterday afternoon and it's already at the frame shop. It looks amazing! Can't wait to send you a pic of the framed print.” Thanks! Don R.
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"...exceptional is right would recommend to anyone.” Ken A.
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s3://commoncrawl/crawl-data/CC-MAIN-2018-17/segments/1524125948950.83/warc/CC-MAIN-20180427021556-20180427041556-00249.warc.gz
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https://www.studysmarter.us/textbooks/physics/fundamentals-of-physics-10th-edition/more-about-matter-waves/q60p-an-electron-is-confined-to-a-narrow-evacuated-tube-of-l/
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An electron is confined to a narrow-evacuated tube of length 3.0 m; the tube functions as a one-dimensional infinite potential well. (a) What is the energy difference between the electron’s ground state and its first excited state? (b) At what quantum number n would the energy difference between adjacent energy levels be 1.0 ev-which is measurable, unlike the result of (a)? At that quantum number, (c) What multiple of the electron’s rest energy would give the electron’s total energy and (d) would the electron be relativistic?
The given data is listed below as-
The length of the narrow-evacuated tube L = 3m
The energies difference is given by the equation-
Here, L is the length of the tube.
The difference between energies is given by the equation:
Thus, the energy difference between the electron’s ground state and its first excited state is .
The difference between energies is given by equation:
The value of n is obtained by solving the above equation as below:
Substituting all the values in above equation:
Thus, at quantum number the energy difference between adjacent energy levels will be 1.0 ev-which is measurable.
At , the energy equation is given as
The rest energy is given as:
Now, to find multiple of the electron’s rest energy that would give the electron’s total energy, divide the value of E by .
Yes, the electron is relativistic because the kinetic energy of this electron would give the nonrelativistic equation which suggests that its speed is greater than the speed of light.
An electron, trapped in a finite potential energy well such as that of Fig. 39-7, is in its state of lowest energy. Are (a) its de-Broglie wavelength, (b) the magnitude of its momentum, and (c) its energy greater than, the same as, or less than they would be if the potential well were infinite, as in Fig. 39-2?
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https://www.open.edu/openlearn/ocw/mod/oucontent/view.php?id=18349&extra=longdesc_idm46597342020288&clicked=1
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Figure 63 is a three-quarters perspective photograph of a rectangular shaped object. Using the width as a basis for measurement, it looks to be about twice as deep as it is wide and four times as long as it is wide. The outer surface has contours, indentations and protuberances. At one end there is an additional structure on one side making it twice as wide as the rest of the object. The top surface of the object is smooth and flat. There is a line of 6 relatively large vertical holes along the length of the object. On either side of these holes there is a single vertical cavity running the length of the object that curves around each of the central holes. There is a major vertical cavity traversing the width of the object at the wider end. A number of other vertical holes are evident in the top surface of the object.
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https://www.arxiv-vanity.com/papers/hep-th/0405001/
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A Novel Long-Range Spin Chain
and Planar Super Yang-Mills
N. Beisert, V. Dippel and M. Staudacher
Max-Planck-Institut für Gravitationsphysik
Am Mühlenberg 1, 14476 Potsdam, Germany
AbstractWe probe the long-range spin chain approach to planar gauge theory at high loop order. A recently employed hyperbolic spin chain invented by Inozemtsev is suitable for the subsector of the state space up to three loops, but ceases to exhibit the conjectured thermodynamic scaling properties at higher orders. We indicate how this may be bypassed while nevertheless preserving integrability, and suggest the corresponding all-loop asymptotic Bethe ansatz. We also propose the local part of the all-loop gauge transfer matrix, leading to conjectures for the asymptotically exact formulae for all local commuting charges. The ansatz is finally shown to be related to a standard inhomogeneous spin chain. A comparison of our ansatz to semi-classical string theory uncovers a detailed, non-perturbative agreement between the corresponding expressions for the infinite tower of local charge densities. However, the respective Bethe equations differ slightly, and we end by refining and elaborating a previously proposed possible explanation for this disagreement.
1.1 Spins …
The calculation of anomalous dimensions of local composite operators in a conformal quantum field theory such as gauge theory in four dimensions is difficult even in perturbation theory. At one loop the relevant Feynman diagrams are easily computed, but in general a formidable mixing problem for fields of equal classical dimension has to be resolved. At higher loops the mixing problem worsens, and, in addition, the Feynman diagram technique rapidly becomes prohibitive in complexity. Recently much progress was achieved in dealing with both problems. It was understood, initially for a scalar subsector of the fields, that the computation can be quite generally reformulated in a combinatorial fashion [1, 2, 3, 4], and that this combinatorics may be efficiently treated by Hamiltonian methods [5, 6].
At one loop, Minahan and Zarembo recognized that this Hamiltonian is, in the planar limit, identical to the one of an integrable quantum spin chain . This picture was successfully extended to all fields in , exploiting the planar structure of the complete non-planar one-loop dilatation operator obtained in . The resulting (non-compact) super spin chain does not only extend the integrable structures of , it also unifies them with the ones observed earlier for different types of operators in the context of QCD [9, 10, 11].
The second development was the realization that Hamiltonian methods are also applicable at higher loops .111One should not confuse the Hamiltonian approach with the integrable spin chain approach. E.g. in the full non-planar one- and two-loop dilatation operator was derived in the sector. It acts on a grand-canonical ensemble of disconnected spin chains. The corrections lead to spin chain splitting and joining, as in , and break integrability. Most importantly, it was shown that planar integrability extends to at least two loops, and it was conjectured that the full non-perturbative planar dilatation operator of theory is identical to the Hamiltonian of some integrable long-range spin chain. This was achieved by studying the two-loop deformations of the hidden commuting charges responsible for the one-loop integrability. Based on this (and certain further assumptions, see below) the planar three-loop dilatation operator for the subsector of the state space was derived. One of its predictions was the previously unknown three-loop anomalous dimension of the Konishi field. Very recently, entirely independent arguments resulted in a conjecture for the three-loop anomalous dimension of a twist-two Konishi descendant .222This conjecture has been confirmed by an explicit calculation in at the two-loop level. It is based on extracting the anomalous dimensions of twist operators from the exact QCD result by truncating to contributions of the ‘highest transcendentality’. The three-loop QCD result recently became available after an impressive, full-fledged and rigorous field theoretic computation by Moch, Vermaseren and Vogt . The conjecture of agrees with the prediction of in a spectacular fashion.
What is the evidence that the full planar dilatation operator is indeed described by an integrable long-range spin chain? In three-loop integrability was proven for the maximally compact closed subsector of . Independent confirmation comes from a related study of dimensionally reduced theory at three loops . Furthermore, the procedure of of deriving the dilatation operator by assuming integrability was pushed to four loops, leading to a unique result after imposition of two further assumptions . The first of these is suggested by rather firmly established structural constraints derived from inspection (as opposed to calculation) of Feynman diagrams. The second, somewhat less compelling, assumption postulates a certain thermodynamic scaling behavior, i.e. the dependence of the anomalous dimension in the limit of large spin chain length .
What is the relevance of the observed integrability? Apart from its ill-understood conceptual importance for planar theory, it allows for very efficient calculations of anomalous dimensions by means of the Bethe ansatz, as first derived at one loop in [5, 7]. For “long” composite operators where this computational tool is not only useful, but indispensable. Beyond one loop, a Bethe ansatz is also expected to exist, as the latter is based on the principle of factorized scattering. This means that the problem of diagonalizing a spin chain with excitations (magnons) may be reduced to the consideration of a sequence of pairwise interactions, i.e. the two-body problem. This principle is one of several possible ways to characterize integrability. And indeed a Bethe ansatz technique was derived in for the sector up to three-loops. This involved embedding the three-loop dilatation operator of into an integrable long-range spin chain invented by Inozemtsev [19, 20].
At four loops, however, the Inozemtsev chain clashes with the postulate of thermodynamic scaling in an irreparable fashion . It thus also contradicts the four-loop integrable structure found in . This is somewhat surprising, as Inozemtsev presented arguments which suggest that his integrable long-range chain should be the most general one possible. One might wonder whether a spin chain with “good” thermodynamic behavior could lead to inconsistencies at even higher loop levels. In Sec. 2 we will see that this does not happen up to five loops. In fact, it appears that the principles of integrability, field theory structure, and thermodynamic behavior result in a unique, novel long-range spin chain. As a crucial second test of this claim, we will show, by working out a large number of rather non-trivial examples, that the scattering of our new chain is still factorized up to five loops. A byproduct is the successful test of the validity of the three-loop ansatz of for a larger set of multi-magnon states. Our study allows us to find the Bethe ansatz corresponding to the new chain. What is more, our findings suggest a general pattern for the scattering which appears to be applicable at arbitrary order in perturbation theory. Stated differently, we propose an integrability-based non-perturbative procedure for calculating anomalous dimensions in the model without the need of knowing the precise all-loop structure of its dilatation operator!
Of course the reader should keep in mind that our model is merely an ansatz for the treatment of the gauge theory, and proving (or disproving) it will require new insights.333Accordingly, when working out the potential consequences of our ansatz for the gauge theory below, we will for simplicity mostly write “gauge theory result” instead of “gauge theory result under the assumption of the validity of the novel long-range spin chain ansatz”, etc. Furthermore, the validity of the all-loop Bethe ansatz we are proposing is still subject to one serious restriction. It is, as in [20, 18], asymptotic in the sense that the length of the chain (and thus of the operator) is assumed to exceed the range of the interaction (and thus the order in perturbation theory). We hope that this restriction will be overcome in the future, as it might then allow to find the spectrum of planar of finite length operators. In addition, we suspect the restriction to be at the heart of a recently discovered vexing discrepancy between the anomalous dimensions of certain long operators and the energies of the related IIB super string states in the background.
1.2 …and Strings
While anomalous dimensions are of intrinsic interest to the gauge field theory, further strong motivation for their study comes from a conjectured relation to energies of superstrings on curved backgrounds. Spin chains in their ferromagnetic ground state describe half-BPS operators. Long spin chains near the ground state, with a finite number of excitations, correspond then to near-BPS operators. These are dual, via the AdS/CFT correspondence, to certain string states carrying large charges, whose spectrum can be computed exactly as they are effectively propagating in a near-flat metric . This yields an all-loop prediction of the anomalous dimensions of the near-BPS operators. The prediction is interesting even qualitatively, as it leads to the above mentioned thermodynamic “BMN” scaling behavior of the spin chain. One then finds, combining this behavior with integrability, that the BMN prediction is also quantitatively reproduced, as will be argued below up to five loops. This feature is a strong argument in favor of our new chain, and thus against (beyond three loops) the Inozemtsev model. The all-loop extension of the five-loop spin chain assumes the repetition of the observed pattern ad infinitum, and therefore reproduces the quantitative BMN formula to all orders by construction. One should nevertheless stress that BMN scaling is very hard to prove on the gauge side (much harder than e.g. integrability!). So far this has not been done rigorously beyond two loops. Therefore the Inozemtsev model has not yet been completely ruled out either.444The result of [14, 13] fixes one of the two remaining parameters of the three-loop dilatation operator of which are left undetermined unless one assumes BMN scaling behavior. Likewise, one further three-loop dimension for a different field in the sector would complete the proof of scaling at this order.
The BMN limit is not the only situation where a quantitative comparison between long gauge operator dimensions and large charge string energies was successful. The large charge limit may be interpreted as a semi-classical approximation to the string sigma model . Following an idea of Frolov and Tseytlin, this allowed to perform explicit calculations of the energies of strings rapidly spinning in two directions on the five sphere [23, 24, 25] and successfully comparing them, at one-loop, to Bethe ansatz computations [26, 27]. Using the mentioned higher-loop Inozemtsev-Bethe ansatz, it was possible to also confirm the matching at two loops . The string sigma model is classically integrable and this makes explicit computations of the energies and charges feasible [25, 28]. The agreement accordingly also extends to the tower of one- and two-loop commuting charges [29, 30]. A more intuitive understanding of this agreement in sigma model language was achieved in [31, 32].
Unfortunately this encouraging pattern breaks down at three loops . A similar three-loop disagreement appeared earlier in the string analysis of the near BMN limit presented in [33, 34]. This case will be discussed in detail in Sec. 2.6. One might wonder whether the trouble is either due to a faulty embedding of the three-loop dilatation operator into the Inozemtsev long-range spin chain, or else, due to problems with the three-loop asymptotic Inozemtsev-Bethe ansatz. In this paper an extended and detailed study of the multi-magnon diagonalization using this ansatz definitely rules out these potential pitfalls. Let us stress once more that the three-loop disagreement of the Inozemtsev-Bethe ansatz with string theory is unrelated to the four-loop breakdown of thermodynamic scaling in the Inozemtsev model. In this paper we are definitely bypassing the second problem, and suggesting a potential explanation of the first problem in chapter Sec. 4. There we will refine the conjecture, first made in , that the disagreement might be explained as an order of limits problem. In particular, we shall argue in the last chapter of this paper that if we were to implement the same scaling procedure as in string theory, we should include wrapping interactions into the gauge theory computations. These are precisely excluded by the weak-coupling asymptotic Bethe ansatz. The refinement also allows to gain a qualitative understanding why the strict BMN limit might indeed agree at all orders, while subtleties arise in the near BMN and the Frolov-Tseytlin situations.
Further confirmation for this picture, as well as for the validity of our novel long-range spin chain, comes from a detailed all-loop comparison of the long-range asymptotic Bethe ansatz with the classical Bethe equation for the string sigma model. The latter was recently derived for the sector in an important work by Kazakov, Marshakov, Minahan and Zarembo . It allowed to successfully compare the string and gauge integrable structures555This was shown earlier on two specific examples by using the Bäcklund transformation (see also ). One major advantage of the systematic approach of is its generality. It would be interesting to also treat the Bäcklund approach in a general fashion. by showing that the classical equation may be mapped to the thermodynamic limit of the quantum spin chain Bethe and Inozemtsev-Bethe equations at, respectively, one and two-loops . Here we will extend this comparison in chapter Sec. 3 to all-loops. We find the intriguing result that the local excitations of string and gauge theory agree to all orders in perturbation theory! The Bethe equations describing the dynamics of the excitations however differ, leading to differences in the expectation values of the global charges. We suspect that this is due to the global effect of wrapping interactions, as will be discussed in the final Sec. 4. These disagreements between the energy eigenvalues of the string sigma model on the one hand and those of the long-range spin chain (in the thermodynamic limit) on the other hand will be illustrated by way of example in App. C. There we explicitly derive the energies of the folded and the circular string using the Bethe ansätze for both the novel spin chain and the string sigma model as introduced in .
Let us end by mentioning a crucial issue which is not addressed in this paper, namely the extension to subsectors larger than the closed spin chain. In fact, essentially nothing is known about the Bethe ansatz for larger sectors, except at one loop [5, 7]. At this loop order, there is much evidence that the triality between string theory, gauge theory and spin chains extends to other sectors, see e.g. the string [36, 37, 38, 39, 40, 41, 42, 43, 44] and Bethe [45, 46, 47] computations, or even to other superconformal models containing open strings [48, 49]. See also the review paper . Subsectors containing covariant derivatives or field strengths should be very important in the QCD context [9, 10, 11], cf. also the very recent paper . It would be extremely interesting to find the analog of our asymptotic Bethe ansatz for some larger closed sector, and ideally for the full super spin chain. Given that the full super spin chain is certainly dynamic , i.e. the length of the chain becomes itself a quantum variable beyond one loop, such an ansatz, if it exists at all, will presumably contain novel features not yet encountered in traditional exactly solvable spin chains. In particular it should be fascinating to see how such an ansatz might reconcile two seemingly contradictory features of the interactions of the elementary excitations of such chains. These features are, for one, the principle of elastic scattering, as usually required by integrability, and, secondly, the occurrence of particle production in dynamic, long-range spin chains, where fermionic and bosonic degrees of freedom are not separately conserved. Could it be that supersymmetry will lead to a generalization of the traditional notion of a factorized S-matrix?
2 The Long-Range Spin Chain
The sector of SYM consists of local operators composed from two charged scalar fields . In the planar limit, local operators are single trace, and of the form
where the dots indicate linear mixing of the elementary fields inside the trace in order to form eigenstates of the dilatation generator. These can be represented by eigenstates of a cyclic quantum spin chain of length with elementary spin . In this picture is the number of “down spins” or “magnons”, and the dilatation operator, which closes on this subsector, corresponds to the spin chain Hamiltonian. For future use let us also introduce the letter for the number of “up” spins
which is the standard notation for the total charge of the chiral scalar fields . Minahan and Zarembo have discovered that the dilatation operator at the one-loop level is in fact integrable and thus isomorphic to the Heisenberg XXX spin chain. In it was shown that integrability extends to two-loops and conjectured that it might hold at all orders in perturbation theory or even for finite ’t Hooft coupling constant.
In this section we will investigate a possible extension of the dilatation operator to higher loop orders. We will make use of three key assumptions:
field theoretic considerations, and
BMN scaling behavior.
These are not firm facts from gauge theory, but there are reasons to believe in them. For example, at three-loops integrability follows from (firm) field theoretic constraints and superconformal symmetry . One could argue that BMN scaling is an analog of the ‘highest transcendentality’ conjecture (see and references therein): In SYM all contributions scale with the maximum allowed power of . What is more, a conjecture for a three-loop anomalous dimension in SYM , which rests on entirely unrelated assumptions while being based on a rigorous tour-de-force computation for QCD , agrees with the prediction of the spin chain and thus confirms our premises to some extent. Whether or not the assumptions are fully justified in (perturbative) SYM will not be the subject of this chapter, but we believe that the model shares several features with higher-loop gauge theory and therefore deserves an investigation. Intriguingly, it will turn out to be unique up to (at least) five-loops and agree with the excitation energy formula in the BMN limit! At any rate, this makes it a very interesting model to consider in its own right. For a related, very recent study see .
There are two approaches to integrable quantum spin chain models. One uses the Hamiltonian and the corresponding commuting charges. The other employs factorized scattering and the Bethe ansatz technique. We will discuss these two approaches in the following two subsections. By means of example we shall demonstrate the equivalence of both models in Sec. 2.5 and App. A.
2.1 Commuting Charges
Let us start by describing the set of charges as operators acting on the spin chain. Introducing a coupling constant by
we expand the charges in a Taylor series
The dilatation operator can be expressed in terms of the spin chain Hamiltonian which is defined as the second charge
Any invariant interaction can be written as a permutation of spins. These can in turn be represented in terms of elementary permutations of adjacent fields. A generic term will thus be written as666This notation was introduced in where one can find a set of rules for the simplification of involved expressions.
For example, in this notation the one-loop dilatation generator is given by
This notation is useful due to the nature of maximal scalar diagrams as discussed in : An interaction of scalars at -loops with the maximal number of legs can be composed of crossings of scalar lines. In the planar limit, the crossings correspond to the elementary permutations and at -loops there should be no more than permutations. In field theory this is a feature of maximal diagrams, but here we will assume the pattern to hold in general. Furthermore, a general feature of ordinary (one-loop) spin chains is that the -th charge at leading order can be constructed from copies of the Hamiltonian density which, in this case (2.7), is essentially an elementary permutation. We will therefore assume the contributions to the charges to be of the form
Finally, the even (odd) charges should be parity even (odd) and (anti)symmetric.777In fact, the Hamiltonian and charges should be hermitian. The coefficients of the interaction structures should therefore be real (imaginary) for even (odd) . Reality of the Hamiltonian follows from the equivalence of the Hamiltonian for the sector and its conjugate. Parity acts on the interactions as
whereas symmetry acts as
Symmetry will ensure that the eigenvalues of the charges are real.
We can now write the dilatation operator up to three loops as given in
The one-loop contribution has been computed explicitly in field theory . To obtain the higher-loop contributions it is useful to rely on the (quantitative) BMN limit, this suffices for the two-loop contribution . At three-loops the BMN limit fixes all but a single coefficient. It can be uniquely fixed if, in addition, integrability is imposed .888Alternatively one may use superconformal invariance or the input from the conjectured result of , based on the rigorous computation of , all of which are compatible with (2.1). The same is true at four-loops and five-loops , the BMN limit and integrability uniquely fix the Hamiltonian. We present the five-loop Hamiltonian in Tab. 1 in App. A.1. Expressions for the higher charges can be found in along with a set of Mathematica routines to compute scaling dimensions explicitly and commutators of charges in an abstract way.
There are some interesting points to be mentioned regarding this solution. First of all, integrability and the thermodynamic limit fix exactly the right number of coefficients for a unique solution (up to five loops). Moreover we can give up on the quantitative BMN limit and only require proper scaling behavior. This merely allows for two additional degrees of freedom and the most general Hamiltonian would be given by . The constants correspond to symmetries of the defining equations, they can therefore not be fixed by algebraic arguments, but the quantitative BMN limit requires . For this solution, the contribution of one excitation of mode to the scaling dimension in the BMN limit is given by
where the BMN coupling constant is defined as
and has been defined in (2.2). It is interesting to observe that the BMN square-root formula (2.44) for the energy of one excitation is predicted correctly. It would be important to better understand this intriguing interplay between integrability, and (qualitative and quantitative) thermodynamic scaling behavior. See also .
There is however one feature of the dilatation operator which cannot be accounted for properly. For increasing loop order the length of the interaction, , grows. For a fixed length of a state, the interaction is longer than the state when . In this case the above Hamiltonian does not apply, it needs to be extended by wrapping interactions which couple only to operators of a fixed length. In planar field theory these terms exist, they correspond to Feynman diagrams which fully encircle the state. We will comment on this kind of interactions in Sec. 4.3. Here we only emphasize that is reliable only up to and including .
2.2 Long-Range Bethe Ansatz
Minahan and Zarembo have demonstrated the equivalence of the one-loop, planar dilatation operator in the subsector with the XXX Heisenberg spin chain . The discovery of integrability opens up an alternative way to compute energies, namely by means of the algebraic Bethe ansatz. Serban and one of us have recently shown how to extend the Bethe ansatz to account for up to three-loop contributions . This ansatz is based on the Inozemtsev spin chain [19, 20] after a redefinition of the coupling constant and the charges. For the Inozemtsev spin chain there exists an asymptotic999Asymptotic refers to the fact that wrapping interactions are probably not taken into account correctly, see also Sec. 4.3. Bethe ansatz. It makes use of the Bethe equations
The left hand side is a free plane wave phase factor for the -th magnon, with momentum , going around the chain. The right hand side is “almost” one, except for a sequence of pairwise, elastic interactions with the other magnons, leading to a small phase shift. Without this phase shift, the equation simply leads to the standard momentum quantization condition for a free particle on a circle. The details of the exchange interactions are encoded into the functions , and definitely change from model to model, but the two-body nature of the scattering is the universal feature leading to integrability. It allows the reduction of an -body problem to a sequence of two-body problems. The energy and higher charge eigenvalues101010Note that here and in the rest of the paper we will, somewhat loosely, avoid to notionally or, at times, semantically distinguish between operators and their eigenvalues, as it should always be clear from the context what is meant. If it is not, the statement should be true in both interpretations. are then given by the linear sum of contributions from the individual magnons
Again, this additive feature is due to the nearly complete independence of the individual excitations. However, the details of the contribution of an individual excitation to the -th charge, , depend once more on the precise integrable model. For example, the XXX Bethe ansatz is obtained by setting
The Bethe roots or rapidities , defined as are also denoted by or in the literature. The inversion of (2.16)
leads to the common and fully algebraic description in terms of rapidities instead of momenta .
The phase relation of the modified Inozemtsev spin chain is given by
and the single-excitation energy is
This reproduces scaling dimensions in gauge theory up to three loops, , when the dilatation operator is identified with the spin chain Hamiltonian as follows
Starting at four loops111111Order in correspond to in . it was noticed that the scaling dimensions do not obey BMN scaling. As this was an essential input for the construction of the model in Sec. 2.1, the energies of the modified Inozemtsev spin chain cannot agree with the model. The breakdown of BMN scaling can be traced back to the term proportional to in (2.18). While all the other terms are of in the BMN limit, this one is of order .
By comparison to (2.18,2.19) we find and . Interestingly, a comparison of energies at four and five loops with our spin chain model shows that we can indeed achieve agreement (see Sec. 2.5 and App. A). The correct coefficients are and . Now it is not hard to guess, by “physicist’s induction”, analytic expressions for the phase relation
and the magnon energy
A non-trivial consistency check of the conjectured all-order expressions (2.22,2.23,2.24) will be performed in Sec. 3 where we will find a remarkable link to the predictions of semi-classical string theory. Note that the one-particle momentum does not depend on the coupling and is given by . The charges can be summed up into the “local” part of the transfer matrix
and we find its eigenvalue from (2.24) to be
The transfer matrix at gives the total phase shift along the chain
which should equal for gauge theory states with cyclic symmetry. The dots in (2.25,2.26) indicate further possible terms like or which cannot be seen for the lower charges or at lower loop orders. It is possible that finding these terms will allow for a modification of the asymptotic Bethe equations (2.14) so as to make them exact, i.e. they would then correctly take into account the gauge theoretic wrapping interactions. In chapter Sec. 4 we will suggest that the latter are responsible for the recently observed gauge-string disagreements for long operators [33, 34, 18].
Our long-range Bethe equations (2.14,2.22), along with the expressions (2.24) for the charge densities, look somewhat involved. We will now show in Sec. 2.3 that they may be significantly simplified by fully eliminating the momentum variables and expressing them through rapidity variables . In particular, this replaces all trigonometric expressions by rational or algebraic ones. Furthermore, it uncovers the remarkable analytic structure of the ansatz, which, interestingly, largely survives in the thermodynamic limit, cf. Sec. 3. What is more, it allows us to find an intriguing link to inhomogeneous spin chains, as we shall elaborate in Sec. 2.4. Apart from its potential conceptual importance, the last observation allows one to also correctly treat certain “singular” solutions of the Bethe ansatz, as will be explained in some detail in App. A.3. After these conceptual elaborations we will proceed in Sec. 2.5 to actually test that our long-range Bethe ansatz indeed properly diagonalizes the Hamiltonian proposed in Sec. 2.1. An application to the near-BMN limit is presented in Sec. 2.6.
2.3 The Rapidity Plane
The Bethe equation (2.14) involves momenta on the left hand side and rapidities on the right hand side. The relation defined in (2.22) specifies the precise nature of the model. In the previous section we have used the momenta as the fundamental variables and as derived variables. Here we would like to take the opposite point of view and consider as fundamental. For that purpose we need to invert the relation (2.22), there turns out to be a remarkably simple form
where121212Note that is odd under . This property is more manifest if we replace the square root by which also straightforwardly yields the correct perturbative expansion for small .
The Bethe equations (2.14) can now be conveniently written without trigonometric functions as
in great similarity with the Bethe ansatz for the Heisenberg model. In the new variables simplifies drastically to
The local charges follow from the expansion (2.25)
The Bethe equations (2.30) follow from the cancellation of poles at . The charges obtained from as
In perturbation theory we can relate these charges to the physical charges by
The form of these charges on an operatorial level is not clear to us. At one-loop they agree with the physical charges, but at higher loops their range grows twice as fast with the loop order as for . Therefore is clearly not a suitable candidate for the dilatation operator . In the next section we will find a natural explanation using, however, a different basis.
Let us comment on (2.29) and its inverse
The map between and is a double covering map. For every value of there are two corresponding values of , namely
For small values of , where the Bethe ansatz describes the long-range spin chain, we will always assume that . When is taken to be large (if this makes sense at all is a different question), however, special care is needed in selecting the appropriate branch. The double covering map for and has an analog for the transfer matrices and . We find the relation
which holds if the second term in (2.33) is dropped. It can be proved by using the double covering relation
We believe it is important to further study the implications of the double covering maps. This might lead to insight into the definition of our model, possibly even beyond wrapping order.
2.4 The Inhomogeneous Bethe Ansatz
The equations (2.30,2.33) are very similar to the Bethe ansatz for an inhomogeneous spin chain, see e.g. .131313See App. B for a reformulation of more general long-range spin chains, in particular the Inozemtsev spin chain, in terms of an inhomogeneous spin chain. The only difference is that the inhomogeneous Bethe ansatz requires a polynomial of degree in whereas the function also contains negative powers of (when expanded for small ). In fact, for the function as defined in (2.29), the negative powers only start at and are irrelevant for the desired accuracy of our asymptotic model. In order to relate our equations to a well-known model we could truncate the expansion of at . Remarkably this truncation can be achieved analytically: The inverse (2.36) can be used to show that
is a polynomial of degree in , which is exactly the proposed truncation at . In fact, the polynomial is easily factorized as follows
We now replace by in the Bethe equation (2.30)
and transfer matrix (2.33)
and obtain the Bethe ansatz for an inhomogeneous spin chain with shifts .
Let us first of all comment on the inhomogeneities. Our spin chain is homogeneous, how can the Bethe ansatz of an inhomogeneous spin chain describe our model? The equation (2.35) relates a homogeneous charge on the left hand side with inhomogeneous charges on the right hand side. A possible resolution may be found by investigating the inhomogeneous spin chain itself: On the one hand, the order of the inhomogeneities does not matter for the Bethe ansatz and thus for the eigenvalues of the charges. On the other hand, it should certainly influence the eigenstates. Consequently, the eigenstates should be related by a similarity transformation141414The inhomogeneities and can be interchanged by conjugation with , we thank K. Zarembo for a discussion on this point. and (2.35) is merely an equation for the eigenvalues of the involved operators. Alternatively, the in (2.35) can be interpreted as homogenized charges which are related to the naive, inhomogeneous charges by a change of basis. To understand our model better, it would be essential to investigate this point further and find the map between our homogeneous spin chain model and the common inhomogeneous spin chain.
Now we have totally self-consistent Bethe equations (2.42) but the physical transfer matrix as defined in (2.31) (consequently the energy and charges ) does not agree with the inhomogeneous transfer matrix . The physical transfer matrix involves the function . When the coupling constant is arbitrary, this function is ambiguous due to the two branches of the square root. This is not a problem in perturbation theory, however, even there inconsistencies are observed at higher order in , see App. A.3. Remarkably, these appear precisely at the order where wrapping interactions start to contribute and our asymptotic Bethe ansatz is fully consistent to the desired accuracy. Conversely, there are signs of the missing of wrapping terms. We hope that finding a cure for the problems beyond wrapping order might help to find a generalization of the Bethe equations which include wrapping interactions. Presumably these equations will have a substantially different form.
It is obviously important to check that our asymptotic Bethe ansatz as developed in Sec. 2.2,2.3,2.4 indeed properly diagonalizes the original, rather involved five-loop Hamiltonian (2.1), Tab. 1 which is currently known up to five loops. This is particularly important as asymptotic Bethe ansätze such as ours are usually not easy to derive rigorously. However, we can certainly check its exactness by comparing its predictions to the results obtained by brute-force diagonalization of the Hamiltonian for specific states. Here we summarize the results of the comparisons we have performed, and refer the reader to App. A and Tab. 2 for further details.
For three excitations, there exist paired and unpaired solutions. The unpaired three-excitation states are singular and a direct computation requires the Bethe ansatz of Sec. 2.4. Alternatively, their energies can be computed via mirror solutions. The fact that both methods (see App. A.3) lead to the same result hints at the consistency of our equations. The paired solutions for and agree with the perturbative gauge theory results (c.f. App. A.4 for details). Finding the Bethe roots for longer spin chains becomes more and more involved.
All states with up to length and a few examples up to length have been computed in the Bethe ansatz. Their energies and charges agree with the eigenvalues of the spin chain operators.
For the afore mentioned states we have also computed the first few orders of the higher charges , using our Bethe ansatz, and compared them to the direct diagonalization of the long-range spin chain model. We find agreement for all instances of states with low excitation numbers.
The general BMN energy formula
is easily confirmed. Regarding the single excitation energy formula (2.23) this is not a miracle. However, it is fascinating to have found an integrable model where the proper BMN behavior is more or less implemented. This indicates that there might be a deeper connection between integrability and the BMN/planar limit.
In conclusion, we can say that for all considered examples (including all states of length up to 8) the Bethe ansatz yields precisely the same spectrum as the Hamiltonian approach described in Sec. 2.1. It shows that an integrable spin chain of infinitely long-range, and with a well-defined thermodynamic limit, is very likely to exist, largely putting to rest the concerns expressed in . These were based on arguments that the elliptic Inozemtsev chain should be the most general integrable model, paralleling analogous results for the Calogero-Moser multi-particle system. However, the proof seems to implicitly assume that the lowest charge only contains two-spin interactions, whereas our new chain definitely is not of this type (see again ). In terms of the Bethe ansatz there may seem to be many such models. These would be obtained by appropriately modifying the coefficients in (2.2). If we however demand that the model is related to an inhomogeneous spin chain as in Sec. 2.4 we find a unique model with thermodynamic scaling behavior, see App. B.
The upshot for the integrable spin chain model is similar: In its construction we have assumed a very specific form of interactions and the obtained Hamiltonian has turned out to be unique (at five loops). In other words, the very relations (2.22,2.23) are special and correspond to the assumed form of interactions ().151515This picture is rather similar to the Inozemtsev spin chain where the requirement of pairwise interactions of spins at a distance was shown to lead to the phase relation of the Inozemtsev Bethe ansatz. At any rate, these relations are very suggestive in view of a correspondence to string theory on plane waves. It is therefore not inconceivable that our Bethe ansatz does indeed asymptotically describe planar gauge theory in the subsector at higher-loops.
2.6 The Near-BMN Limit
Let us now use our novel ansatz to obtain all-orders predictions for the corrections to the anomalous dimensions of BMN type operators, i.e. let us consider the so-called near-BMN limit. In fact, in the first non-trivial case of states with two excitations an all-loop gauge theory expression for this correction has been guessed in . Excitingly, we shall find that our ansatz precisely reproduces this conjecture! The expression in question, which agrees with (A.4) and with Tab. 4 at five-loops, is
where and have been defined in, respectively, (2.2) and (2.13). The first term can be regarded as a renormalization of the term in the first square root. For instance, we might replace in the definition of by to absorb the second term into the leading order energy. Unfortunately, as has already been pointed out in , this formula does not agree with the expression for the near plane-wave limit on the string side derived in [33, 34]
Now let us compute the momenta for the case and in the near BMN limit. That is the momenta are expanded around :
Then the Bethe equations (2.14) are solved order by order in . In general, we would have to start with two distinct Bethe equations, which determine the two roots . However, the momentum constraint (2.27) implies in this case a symmetric distribution of the roots in the complex plane : , i.e. . We are thus left with one root determined by
The general solution of this equation at leading order in is then given by where is an integer. Substituting this back into (2.47) and expanding up to yields the first correction to the momentum
In view of recent results which might soon also allow the computation of the corrections on the string side , one easily obtains in much the same way the next order gauge correction to the momentum
and the energy now reads
Of course, agreement with string theory is not expected beyond, at most, two loops.
3 Stringing Spins and Spinning Strings at All Loops
3.1 Perturbative Gauge Theory: The Thermodynamic Limit
The thermodynamic limit is the limit in which the length of the spin chain as well as the number of excitations is taken to infinity while focusing on the the low-energy spectrum. In this limit, it was observed that the -th charge of one magnon (2.24) at one-loop scales as . Here, we would like to generalize the thermodynamic limit to higher-loops. From the investigation of the closely related BMN limit as well as from classical spinning strings, we infer that each power of the coupling constant should be accompanied by one power of . We thus replace according to
where we have used the same symbol for the rescaled, effective coupling constant in thermodynamic limit. It is common belief that this scaling behavior holds for perturbative gauge theory, but it is clearly not a firm fact. We shall assume its validity for several reasons: Firstly, it was not only confirmed at one-loop, but also at two-loops [56, 12]. It is a nice structure and conceptually it would be somewhat disappointing if broken at some higher loop order. Secondly, the AdS/CFT correspondence seems to suggest it. Thirdly, it will allow us to define charges uniquely, see [15, 29].
In conclusion, we expect that the scaling of charges in the thermodynamic limit is given by
Due to the large number of excitations , the total charge scales as .161616In the BMN limit the total charges scale as in (3.2). We recall that the difference between the BMN and the thermodynamic limit is that in the former the magnon number stays finite. In particular the scaling dimension is
The relevant quantities of the Bethe ansatz should behave as follows:
where171717The correct sign for the square root in perturbation theory is the same as of . More accurately we should write .
In the scaling limit the charges (2.32) become
where the momentum and energy densities are, respectively,
The discrete sums (2.15) over excitation charges turn into integrals over the distribution density
with support on a discrete union of smooth contours , i.e. the charges are given by
Note the normalization of the density:
where is termed filling fraction.
The distribution density, in addition to the normalization condition (3.10), is subject to the momentum constraint
where is an integer mode number as required by cyclic symmetry. Finally, the continuum Bethe equations derived from (2.14) lead to a system of singular integral equations, determining the distribution density ,
which are to hold on all cuts , i.e. . These equations are solved explicitly in App. C.1.2 for the folded string and in App. C.2.2 for the circular string. The charges are then determined from the solution by computing the integrals (3.9), using (3.6). The parameters are integer mode numbers obtained from taking the logarithm of (2.14). In fact, the right hand side of (3.12) is just , while the left hand side describes the factorized scattering of the excitations in the thermodynamic limit.181818For more information on the mode numbers and , as well as on certain subtleties involving root “condensates”, we refer to the detailed one and two-loop discussion in , which largely generalizes to our all-loop equations. However, note in (3.12) the appearance of an additional square root cut in the potential . One easily checks that the perturbative expansion of the Bethe equations (3.12) and of the expressions for the energy (3.7) reproduces, by construction, the three-loop thermodynamic Inozemtsev-Bethe ansatz in .
Note that the Bethe equation (3.12) can alternatively be obtained as a consistency condition on the transfer matrix . In the thermodynamic limit, the transfer matrix becomes
where is the singularity-free resolvent. The resolvent has many sheets, but the transfer matrix must be single-valued on the complex plane. This requires
across a branch cut of at , which is an equivalent to the Bethe equation (3.12). At this point, it is however not clear how the physical transfer matrix is related to the physical resolvent and if there is also a consistency requirement which leads to the Bethe equations. This is largely related to mirror cuts in which are due to the double covering map .
3.2 Semi-classical String Theory: The Bethe Equation
In Kazakov, Marshakov, Minahan and Zarembo developed a general approach for finding the semi-classical solutions of the string sigma model in the large charge limit. They astutely exploited the (classical) integrability of the sigma model and derived the equations determining the monodromy matrix of the system. These singular integral equations were termed “classical” Bethe equations in , and it was shown that the monodromy matrix may be interpreted as their resolvent. Not surprisingly, the derivation conceptionally differs from the one of the algebraic Bethe ansatz for quantum spin chains. In particular, one may introduce a pseudodensity as the imaginary part of the resolvent along the discontinuities in the complex plane of the spectral parameter :
i.e. is manifestly analytic on the physical sheet of the complex -plane, except for the set of cuts . The normalization condition of was found to be
where the filling fraction is defined in the same fashion as in Sec. 3.1. Written in this form, we see that the function should not be interpreted as a distribution density of the local excitations in the spectral plane (see, however, the next Sec. 3.3). The local charges are then neatly expressed as
This means that the Taylor expansion of the string resolvent around generates these charges:
As in gauge theory the first charge is the momentum . It is subject to the integer constraint
while the rescaled string energy is also precisely given by
3.3 Structural Matching of Gauge and String Theory
Let us structurally compare the gauge and string ansätze.The normalization condition (3.16) of string theory appears to be incompatible with the one in gauge theory (3.10) This may be fixed by relating the string and gauge spectral measures through
Interestingly, this is the same change of variables employed in in order to show the two-loop agreement between string and gauge theory.191919A very similar change of variables also relates gauge theory and the generating function of Bäcklund charges, see . Here we see that the relationship should actually hold to all loops if we are to compare the two structures. One now easily checks the elegant formula, c.f. (3.6),
i.e. the scaled gauge charge densities in (3.6) and the string charge densities precisely agree for all ! Equation (3.24) is one of the key results of this paper, as it demonstrates the structural equivalence of the elementary excitations in string and gauge theory. We will have more to say about this at the end of Sec. 4. The all-loop agreement between the infinite set of gauge and string theory charges could be established if one could show that the gauge theory distribution density and the function coincide:
This is however not the case, as was observed previously . Indeed, as a first sign of trouble we observe that only at one loop the expansion point gets mapped to . For the map (3.23) is singular and actually represents the -plane as a double cover of the -plane. Under this map the gauge Bethe equation (3.12) turns into202020The second integral can be interpreted as the effect of mirror cuts due to the double covering map
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https://brainmass.com/economics/output-and-costs/calculating-average-marginal-costs-442613
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math
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See the attached file.
Policy Associates, Inc. (PA) is a policy analysis firm that produces policy reports hiring analysts who scrutinize datasets. Its production function is :
Where Q is the number of policy reports it produces, L is the number of policy analysts it hires, and D is the number of datasets purchased.
A) Are the returns to scale of PA increasing, decreasing, or constant?
B) What is the marginal product of labor (L) used by the firm? Does this marginal product increase/decrease/ remains constant when L increases? Provide a brief explanation for your result.
C) What is the marginal product of datasets (D) used by the firm? Does this marginal product increase/decrease/remain constant when D increases? Provide a brief explanation for your result.
Assume that the price of each dataset is $1 and the wage of each unit of policy analyst labor is $2. Further assume that the firm has available 100 datasets and its managers do not plan to buy any other datasets in the near future. They are, however, willing to hire public policy graduates as analysts.
D) Write expressions to illustrate:
i) How many policy analysts should PA hire in order to produce 100 policy reports?
ii) What is PA's total cost as function of its output, Q?
iii) What is PA's short run average cost?
iv) What is PA's short run marginal cost?
v) What is PA's short run average fixed cost?
vi) What is PA's short run average variable cost?
Sum of exponents=0.5+0.75=1.25
Sum of exponents is greater than 1, we can say that firm is experiencing increasing returns to scale.
b) Q(D,L)= 0.10*D^0.5*L^0.75
Marginal Product of labor=MPL=dQ(D,L)/dL
As is clear from the above expression marginal ...
Solution describes the steps to calculate marginal product, average and marginal costs in the given case.
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https://www.hindawi.com/journals/ijanal/2013/380938/
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math
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Research Article | Open Access
M. K. Aouf, A. O. Mostafa, A. Shamandy, E. A. Adwan, "Some Properties for Certain Class of Analytic Functions with Varying Arguments", International Journal of Analysis, vol. 2013, Article ID 380938, 4 pages, 2013. https://doi.org/10.1155/2013/380938
Some Properties for Certain Class of Analytic Functions with Varying Arguments
We introduce a new class of analytic functions with varying arguments in the open unit disc defined by the Salagean operator. The object of the present paper is to determine coefficient estimates, extreme points, and distortion theorems for functions belonging to the class .
Let denote the class of functions of the form which are analytic in the open unit disc . If and are analytic functions in , we say that is subordinate to , written if there exists a Schwarz function , which (by definition) is analytic in with and for all , such that . Furthermore, if the function is univalent in , then we have the following equivalence (cf, e.g., [1, 2]): For function , Salagean defined the differential operator as follows: For , and for all , let denotes the subclass of consisting of functions of the form (1) and satisfying the analytic criterion: It is noticed that for suitable choices of , and , we obtain the following subclasses studied by various authors:(1) (see Sivasubramanian et al. , with );(2) (see Aouf et al. , with );(3) (see Chunyi and Owa );(4) (see Chen [7, 8] and Goel );(5) (see Srivastava and Owa ).
Also we note the following.(1)Putting in (4), the class reduces to the class ,.
Definition 1 (see ). A function defined by (1) is said to be in the class if and for all . If, furthermore, there exists a real number such that
then is said to be in the class . The union of taken over all possible sequences and all possible real numbers is denoted by .
Let denote the subclass of consisting of functions in .
We note the following:(1) (see Aouf et al. );(2) (see Srivastava and Owa );(3) (see Srivastava and Owa ).
Also we note that(i) denotes the subclass of , consisting of functions belonging to the class ;(ii) denotes the subclass of , consisting of functions belonging to the class .
2. Coefficient Estimates
Unless otherwise mentioned, we will assume in the reminder of this paper that and .
Theorem 2. Let the function be of the form (1), if then .
Proof. A function of the form (1) belongs to the class if and only if there exists a function , such that or, equivalently, Thus, it is sufficient to prove that Indeed, letting we have In view of (6), the last inequality is less than zero; hence . This completes the proof of Theorem 2.
Theorem 3. Let the function be of the form (1), then is in the class if and only if
Proof. In view of Theorem 2, we need only to show that each function from the class satisfies the coefficient inequality (6). Let . Then, by (8) and (1), we have Since , lies in the class for some sequence and a real number such that , set in the above inequality and since , then It is clear that the denominator of the left-hand said cannot vanish for . Moreover, it is positive for and in consequence for . Thus, we have which, upon letting, readily yields the assertion (11). This completes the proof of Theorem 3.
Corollary 4. Let the function defined by (1) be in the class, then The result is sharp for the function
3. Distortion Theorems
Theorem 5. Let the function defined by (1) be in the classThen The result is sharp.
Corollary 6. Under the hypotheses of Theorem 5, is included in a disc with center at the origin and radius given by
Proof. Since , where given by (18) is increasing function of , in view of Theorem 3, we have that is, Thus, Similarly, we get Finally, the result is sharp for the function given by (23). This completes the proof of Theorem 7.
Corollary 8. Let the function defined by (1) be in the class . Then is included in a disc with center at the origin and radius given by
4. Extreme Points
Theorem 9. Let the function defined by (1) be in the class , with where . Define and Then is in the class if and only if it can be expressed in the form where and?.
Remark 10. Specializing , and in the above results, we obtain the corresponding results for the corresponding classes and defined in Section 1.
The authors would like to thank the referees of the paper for their helpful suggestions.
- T. Bulboaca, Differential Subordinations and Superordinations, Recent Results, House of Scientific Book, Cluj-Napoca, Romania, 2005.
- S. S. Miller and P. T. Mocanu, Differential Subordinations: Theory and Applications, vol. 225 of Monographs and Textbooks in Pure and Applied Mathematics, Marcel Dekker Inc., New York, NY, USA, 2000.
- G. Sãlãgean, “Subclasses of univalent functions,” in Complex Analysis-Fifth Romanian-Finnish Seminar, Part 1 (Bucharest, 1981), vol. 1013 of Lecture Notes in Mathematics, pp. 362–372, Springer, Berlin, Germany, 1983.
- S. Sivasubramanian, A. Mohammed, and M. Darus, “Certain subordination properties for subclasses of analytic functions involving complex order,” Abstract and Applied Analysis, vol. 2011, Article ID 375897, 8 pages, 2011.
- M. K. Aouf, A. Shamandy, A. O. Mostafa, and E. A. Adwan, “Subordination results for certain classes of analytic functions defined by convolution with complex order,” Bulletin of Mathematical Analysis and Applications, vol. 3, no. 1, pp. 61–68, 2011.
- G. Chunyi and S. Owa, “Certain class of analytic functions in the unit disk,” Kyungpook Mathematical Journal, vol. 33, no. 1, pp. 13–23, 1993.
- M. P. Chen, “On the regular functions satisfying ,” Bulletin of the Institute of Mathematics. Academia Sinica, vol. 3, no. 1, pp. 65–70, 1975.
- M. P. Chen, “On functions satisfying ,” Tamkang Journal of Mathematics, vol. 5, pp. 231–234, 1974.
- R. M. Goel, “On functions satisfying ,” Publicationes Mathematicae Debrecen, vol. 18, pp. 111–117, 1971.
- H. M. Srivastava and S. Owa, “Certain classes of analytic functions with varying arguments,” Journal of Mathematical Analysis and Applications, vol. 136, no. 1, pp. 217–228, 1988.
- H. Silverman, “Univalent functions with varying arguments,” Houston Journal of Mathematics, vol. 7, no. 2, pp. 283–287, 1981.
- M. K. Aouf, A. Shamandy, and A. A. Attiyia, “On certain classes of analytic functions with varying arguments,” Chinese Journal of Mathematics, vol. 24, no. 2, pp. 135–143, 1996.
Copyright © 2013 M. K. Aouf et al. This is an open access article distributed under the Creative Commons Attribution License, which permits unrestricted use, distribution, and reproduction in any medium, provided the original work is properly cited.
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https://www.physicsforums.com/threads/understanding-the-good-effiency.78939/
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math
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What is the good efficiency of a product? How do you understand the term "good effiency"?
Can you tell us where you have seen the term "good efficiency?" That is not a term used that I know of. You are undoubtedly referring to efficiency, of which there are MANY different forms and measures of efficiency.
If you can, please provide a bit more information on what it is you are looking at.
I would say efficiency is quite simply the ratio of useful "stuff" over the total amount " stuff" available.
For example a light bulb has x amount of energy (electrical) available. It uses y amount of energy to produce light, therefore the efficiency is x/y x 100%.
Good efficiency is about improving this ratio towards 100%
Edit: Silly me, it should be y/x * 100%
I would like to see a reference to anything that uses the term "good efficiency."
Here ya go Fred:
Honda Civic hybrid? Not very good efficiency!
I have never heard of "good efficiency" as a technical term. There is just efficiency, which is readily 'quantifiable'. However, there can be efficiencies of components or systems, and one can talk of 'net' or 'gross' depending on what is incorporated in the formula for efficiency.
"Good efficiency" sounds like a subjective term, where 'good' is simply an adjective.
Then there is the matter of 'reliability' or 'availability'.
Separate names with a comma.
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http://www.wyzant.com/Tutors/TX/Houston/7736513/
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I am a Texas certified math teacher for grades 6-12. For 9 years, I have worked with H.I.S.D. teaching all levels of middle school math. In addition, I was the Mathcounts competition coach for 6 years. The strategies I taught in the Mathcounts program are identical to the strategies used to solve SAT math problems. While in college, I worked for my professors and tutored college students in Calculus I, College Math, and Geometry.
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http://gxbj.oenw.pw/geometry-competition-problems.html
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math
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Geometry Competition Problems
If you like playing with objects, or like drawing, then geometry is for you! Geometry can be divided into: Plane Geometry is about flat shapes like lines, circles and triangles shapes that can be drawn on a piece of paper. The 2017 Raytheon MATHCOUNTS National Competition was held May 13-16, 2017 in Orlando, FL. The William Lowell Putnam Mathematical Competition 1985-2000: Problems Solutions, and Commentary, by Kiran S. Summer Math Camps. The 2019 Math Olympiad will be held on Saturday September 21st. Questions & Answers 2018. Rectangular Coordinates* 3. Join the conversation in the discussion forum. We also organize teams from several states to compete in the national American Regions Math League competition. After puzzling for years over seven unsolved math problems, a U. AplusClick free online math problems, questions, logic puzzles, and math games on numbers, geometry, algebra for grades 1st to 12th. 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The contests are designed to build student interest and confidence in mathematics through solving worthwhile problems. Explain to students that you can use basic algebra and simple geometric formulas to solve seemingly intractable problems. He is looking forward to teaching students that math is “interesting, unpredictable and beautiful. Pythagorean. Although our family uses them to prepare for the actual contests, they can also be used as a problem solving unit in math or for math-fun days. The working language is English. Welcome to the CALIFORNIA MATHEMATICS LEAGUE 's school registration index for the 2019-2020 school year. They have a different flavor from problems seen in other mathematics competitions, and are usually quite challenging but fun. A highly motivational way for students to gain math fluency in computational, spatial and logical reasoning. A math problem posed to 14-year-olds in Singapore is creating a wave of confusion for those trying to solve it online. We’ll be discussing how to solve math competition questions and focus on the intuition behind solutions, as well as various tools we can use. American Regions Math League – Past problems and solutions. pdf: Practice Problems: March 13, 2017: MathCounts 2016 (Chapter)-Target 2016 Chapter Competition Target Round. Re-Learning Math with Scott Flansburg, Hard Problems The Road to the World's Toughest Math. Mathematics Competition for children aged 6 to 11. It is designed to develop and advance interdisciplinary problem-solving skills as well as competence in written communication. - Reviewed and selected final problem sets for the regional and national level Math Stars Competitions. org runs classes and individual tutoring sessions to develop students' problem solving skills and train them for other competitions. Printable worksheets and online practice tests on Olympiad for Grade 8. Wasn’t sure how it would go or if they’d solve it. The competitions consist of both individual and team rounds that cover a variety of mathematic skills aligned with the district’s math standards. Many mathematics competitions sell books of past competitions and solutions. It is a chance for students to test their mathematical mettle in individual competition, for students to engage in team competition, and for teachers to meet and mingle with colleagues and LSU faculty. List the course you are currently taking (or just completed), such as Honors Geometry, Calculus BC, etc. The problems range from “mind-benders” that require little mathematical skills to problems that require the knowledge of geometry, trigonometry and beginning calculus. Below are a number of worksheets covering basic numeracy problems for high school students. Problems are from the fields of Algebra, Analysis (Real and Complex), Geometry and Combinatorics. Disclaimer: these files are just mirrored files from elsewhere on the net. Not only will working neatly make it easier for you to systematically solve a problem and avoid mistakes, but many teachers also grade math exercises based on the completeness of the steps to the solution, not just the solution. Office in Bismarck, ND. Targeted at students in calculus I, II, and III, teams compete against each other to solve problems as quickly as possible. I will tell you how to solve problems so your scores will rise. The particular contests listed below were used for team competitions. 4 The Pythagorean Theorem In the special case where one of the angles in a triangle is a right angle, you can use the Pythagorean theorem to relate the lengths of the three sides. In the Albany area, WMHT (channel 17) will be showing movie on Sunday October 18 at 6 p. Try our math problem for 4th,5th,6th,7th,8th,9th grade!. Past Problems & Solutions. The length of the javelin throw is measured in hundredths of meters. SIGMA is a mathematics league that promotes problem solving through competition. You can find problems and solutions from the math contests run by the American Mathematics Competitions on the following pages: AMC 8 / AJHSME Problems and Solutions. The math problems below can be generated by MathScore. The AMC 8 provides an opportunity for middle school students to develop positive attitudes towards analytical thinking and mathematics that can assist in future careers. You are allowed to use a calculator. Julia Robinson Mathematics Festival Saturday, 3 November 2018, 9:00AM - 12:00 noon, The Atrium of the new Jacobs Science Building. com, a math practice program for schools and individual families. More than 300,000 students participate in the MAA American Mathematics Competitions each year, which leads the nation in strengthening the mathematical capabilities of the next generation of problem solvers. This is a residential competition and a condition of participation is that all participating students stay in the Hall of Residence provided by the organisers. Millions of students in more than 20 countries have participated since 1988. Register Now for a 30 minute Online Challenge, open for all students in grades 3 through 8. American Regions Math League (ARML) - Results and past problems for the ARML, an annual national competition. They are not easy but not impossible. , through Art of Problem Solving), competitions results (from American Math Competition, American Invitational Math Exam, Bay Area Math Olympiad, Math Kangaroo). AMC-8 Competition, 2018-Answers. Mandelbrot Competition Math League - runs various state and regional math competitions at elementary, middle, and high school levels. The working language is English. One of the teams was the only one to complete all 11 problems within the five-hour time limit, earning them first place. In Fall 2019 the course is taught by Professor Sarkar and meets MWF 10:00-10:50 in MS 6221. Please read this document carefully before contacting CMI about a proposed solution. In spherical geometry, a line is defined to be a great circle of the surface of a sphere. Middle School (Division M): This division focuses on problem solving using math concepts from a standard middle school math curriculum. , through Art of Problem Solving), competitions results (from American Math Competition, American Invitational Math Exam, Bay Area Math Olympiad, Math Kangaroo). Not just math majors have done well; many recent winners have come from nearby disciplines, including physics, computer science, and engineering. Find the smallest 4-digit number that could represent the number of cubic centimeters in the volume). Solve word problems that involve surface area of pyramids and prisms. Most of all, the point is to love math and have fun doing it. Mathematical Competition Problems and Solutions Putnam Exam solutions usually appear in the Mathematics Magazine in April and in the American Mathematical Monthly in October or November. All questions should be understandable by anyone who has had the yearlong calculus sequence. The Mandelbrot Competition introduces high school students to accessible new topics in mathematics while providing stimulating. Scroll down the page for examples and solutions. Find a wide range of questions & answers related to addition, multiplication, subtraction, division, geometry, numbers and general math knowledge. Competition Math is a 10-week/30-hour course that provides new and experienced math coaches with fundamental math content knowledge, problem-solving strategies and coaching best practices that are essential when working with a middle school or high school math team. Geometry Competition Warmup on Brilliant, the largest community of math and science problem solvers. Mathematically, The Math Stars Competition Series aims to develop students' problem solving skills in order to prepare students for more rigorous mathematics in the years to follow. Students who work on these type of math problems have better results at the competition. A math teacher decided to organize two rounds of a math competition. [email protected]
2018 Practice Competition - Saturday, December 8 - West Oso Junior High School 2019 Regional Competition - Saturday, February 9 Class Notes: 2014-2015 School Handbook Warm-Ups and Workouts 2013-2014 School Handbook Warm-Ups and Workouts 2014 Spurs Competition: Sprint Round: Part 1 Part 2 Target Round Team Round 2014 Chapter Team Round. Siemens Competition (high school) MathWorks Math Modeling (M3) Challenge (high school) Putnam Competition (undergraduate) American Regions Math League (high school) High School Mathematical Contest in Modeling (HiMCM)® Google Science Fair (high school) High School Mathematical Contest in Modeling (HiMCM) (high school) AWM Schafer Prize. American Math Competition 10 Practice Test 10 146 7. Several problems on finding angles are also included. Four teams of programmers from the University competed on October 26 at the Association for Computing Machinery regional International Collegiate Programming Competition (ICPC). 5-Year Competition Sets. Below are copies of exams going back several years along with the answers. Previous MMPC Exams. Test and improve your knowledge of Approaches to Math Word Problems with fun multiple choice exams you can take online with Study. University of Houston Mathematics Contest The 2020 Contest will take place on February 15 Check back for updates. The Caltech Harvey Mudd Math Competition is a team competition for high school students organized by the Caltech and Harvey Mudd math clubs. There are many fine resources for word problems on the net! have personally checked & reviewed each website, to make sure it is truly useful. The William Lowell Putnam Mathematics Competition is a North American math contest for college students, organized by the Mathematical Association of America (MAA). Questions about the contest? Send email to Dr. This is an excellent preparation for the Putnam competition. He wanted to buy a sharp sword to slice up the cat. There are many more great contests, including SBIMC (South Brooklyn Invitational Math Competition). Back then, students sometimes contributed lectures for fun, and I gave the last lecture on the last day, on an unusual technique that I had come up with to solve geometry problems (my favorite subject at the time). The challenging questions pose problems such as: “Prove or disprove whether it is possible to color each point in the Euclidean plane with 9 colors so that no 2 points with the same color are a unit distance apart. There will be two levels of problems – one for 6 th -7 th graders,. Students in each league compete for the highest scores, while schools compete for the highest team score: the total of the top 5 scores in each school. They are not easy but not impossible. The 2019 Math Olympiad will be held on Saturday September 21st. These points will give your school the opportunity to be awarded a plaque for first or second-place in the Merten Hasse Mathematics Competition. Rice Math Tournament February 17th, 2018. AoPS Problem Series. I thought some of you would be interested in it! I thought some of you would be interested in it! What follows is their information that I have copied. MathWorks Math Modeling (M3) Challenge is a contest for high school juniors and seniors. USAMO Problems and Solutions. They work independently 25 has the same two problems to solve. Mathematics and Statistics Awareness Month Competition Sample Problems for 3rd-4th Grades (PDF) Sample Problems for 5th-6th Grades (PDF) Sample Problems for 7th-9th Grades (PDF) Sample Problems 10th-12th Grades. This can be easily solved in your head. The University Physics Competition is an international contest for undergraduate students, who work in teams of three at their home colleges and universities all over the world, and spend a weekend in November, 48 hours, analyzing a real-world scenario using the principles of physics, and writing a formal paper describing their work. Web page for the Northwestern University Math Problem Solving Group. Contest Home > Contest Questions and Answers: Contest Questions and Answers : Questions & Answers 2019. The Putnam Club does not meet in the spring, but we had the fourth annual UW Undergraduate Math Competition on April 24th, 2018, 5:30-8pm in VV B239. Students will explore competition math for beginners through a variety of contests (including Math Olympiad for Elementary School), puzzles, games and math art. We meet every Wednesday 8th period, plus certain days after school. We believe that problem solving is one of the most effective means for exploring the world of mathematics, and that contests provide an exciting and motivational setting in which to do so. It’s part of the Reconstruct Challenge, a $3 million dollar prize competition to. Because problems are organized by math topic, the problem numbers are not in. Middle School Instructions. For each edge, the absolute di erence of the labels at the endpoints is an element of f2;3;4g. Challenge Math is primarily designed for gifted elementary students. What, where, when. The problems are really difficult and the median score is zero. In USA, 24,000 students registered for Math Kangaroo 2016 at 514 Math Kangaroo Centers along with over 6,000,000 other participants in about 60 countries worldwide. 1998 United States Math Olympiad Summer Program. 4 The Pythagorean Theorem In the special case where one of the angles in a triangle is a right angle, you can use the Pythagorean theorem to relate the lengths of the three sides. Welcome to the American Mathematics Competitions Program! The MAA's American Mathematics Competitions program leads the nation in strengthening the mathematical capabilities of the next generation of problem-solvers. Topics and Problems. Zoom International Math League (ZIML) is an educational program to help students expand their mathematical problem solving by practicing everyday. It covers topics up to and including pre-calculus. The national math competition MATHCOUNTS has been around for 29 years and area public and private school students have been participating in the contest off-and-on since the 1990s. September 20, 2019 Letters of Invitation announcing this year's contest are mailed to schools. Math Problem Writer ♦ Confidence Builder Math Competition Problems. Competitive math gives students problems that are challenging and fun in order to build problem solving skills and provide depth and breadth far beyond the standard curriculum. Web page for the Northwestern University Math Problem Solving Group. Handout archive. Problem-solving guides that math competition winners have relied on for more than 25 years, written by people who have won medals in national math contests, including MATHCOUNTS, the AMC, the AIME, and the USAMO. See the "Dates" page for the dates and times of upcoming contests, and navigate to "Contests & Rules" to participate in a contest when it begins. The 14th annual PUMaC is scheduled for November 16, 2019. Resource Pages. Email David Sumner My Home Page. The revised rules for the Millennium Prize Problems were adopted by the Board of Directors of the Clay Mathematics Institute on 26 September, 2018. Mathematics Stack Exchange is a question and answer site for people studying math at any level and professionals in related fields. Furthermore, the sum of labels at diametrically opposite vertices is never 7. Last updated Wednesday, October 30, 2019. In Memory of Dr. Books for working with young problem solvers, or Math Circles (Math Circles for students bring K-12 students together with mathematically sophisticated leaders in an informal setting, after school or on weekends, to work on interesting problems or topics in mathematics. Welcome to The Math Contest! It's been a while, but we're excited to re-launch The Math Contest with help from our friends at Casio Education. “The total weight of 26 sheep and 10 goat is 7,700kg, based on the average weight of each animal,” said one Weibo commenter. All UConn undergraduates, and pre-college students taking math courses at UConn (not co-op courses in high school), are welcome to participate. It happens that the number formed by the first n of them is divisible by n for each n from 1 to 10. " There's a slight 'twist' but nothing that will faze our math experts out there. Public television stations across the country will be showing Hard Problems, the documentary about the six American students who represented the United States at the 2006 International Math Olympiad. The competition includes problems from algebra, geometry, trigonometry, and other topics which are included in the secondary mathematics curriculum. It shouldn't. Competitors at the State level must first place as a top finisher at their Regional Competition. If you're behind a web filter, please make sure that the domains *. Yet, they may still be intimidated by math word problems. My first student graduation was in Srping 2013: after that I started recycling my material. The William Lowell Putnam Mathematical Competition, often abbreviated to Putnam Competition, is an annual mathematics competition for undergraduate college students enrolled at institutions of higher learning in the United States and Canada (regardless of the students' nationalities). The selection process takes place over the course of roughly four stages. Breakdown of the steps and substeps to each solution. Harvard has won the Putnam competition yet again! Congratulations to our winning team members and outstanding individuals: Our winning team members, Zachary Abel , Iurie Boreico , and Arnav Tripathy , each receive $1000 for the team competition. The test consists typically of 10 mathematical problems. ARML has four problem books covering most ARML as well as some NYSML competitions. Top-scoring students in qualifying rounds are invited to compete at the national (INTER) 2 SECT Championship in April. The test consists typically of 10 mathematical problems. Wisconsin Section High School Math Contest Attention High School Math Teachers. The New York Life Foundation supports programs that benefit young people, particularly in the areas of educational enhancement and childhood bereavement. Math Puzzles Volume 2 is a sequel book with more great problems. Explain to students that you can use basic algebra and simple geometric formulas to solve seemingly intractable problems. The math projects can be extensions of classroom problems or competition problems that a student has found interesting. New problems @8am Central on Monday & 10am M-F. Students, teachers, parents, and everyone can find solutions to their math problems instantly. This can be easily solved in your head. If you're seeing this message, it means we're having trouble loading external resources on our website. Participation is open to all middle school, junior high school and senior high school students and is divided into six divisions: Algebra I, Algebra II, Geometry, Statistics, Pre-Calculus and Calculus. The problems are mostly combinatorial, with an occasional geometry, number theory or algebra problem. Students will be training for competition in the Math Olympiads by exploring the twelve problem-solving strategies recommended by Dr. ksu math competition 2020! Michelle Mikes , August 1, 2019 September 10, 2019 , Cobb Academics , Instruction & Innovative Practice , Mathematics , Teaching & Learning , 0 Kennesaw State University holds an annual written mathematics competition for high school students across the State of Georgia. The Math League has Math Contest Books for Grades 4, 5,. The Contest will consist of ten problems, which will be graded on the basis of ten points per problem. Math competition for kids aged 10-11 from all countries (level:difficult). The UCL Maths Challenge is a competition for Year 6 primary school pupils from London organised by UCL student volunteers. Get help for maths through pre-recorded lessons for middle, high, senior, secondary school and community college students. Robert Bryant is the Phillip Griffiths Professor at Duke University. com) are designed to build student interest and confidence in mathematics through solving worthwhile problems. It is a chance for students to test their mathematical mettle in individual competition, for students to engage in team competition, and for teachers to meet and mingle with colleagues and LSU faculty. Students must belong to a school, district, institute, or homeschool team. The Math League Contests (www. Note: I am paraphrasing this problem Consider a quadrilateral with 3 sides of equal length, and one longer side. NOTE: Individuals cannot compete in Math Olympiads. He knew his Chappelow team, one of 1,500 in the country competing in the online competition, had a shot at first place, but he wasn’t sure they’d be. Websites Books Contests Math Projects. #22 - This is a good probability problem that uses a very common math competition problem solving skill - use an example to solve the problem. For us non-geniuses, he tells us about the hardest math problem in the world. Below are a number of worksheets covering basic numeracy problems for high school students. Students will explore competition math for beginners through a variety of contests (including Math Olympiad for Elementary School), puzzles, games and math art. Write an expression and solve. The Grade 12 open courseware, Mathematics Resource Manual and Euclid eWorkshop can help you brush up on the material and provide many problems with solutions. Targeted at students in calculus I, II, and III, teams compete against each other to solve problems as quickly as possible. Math-M-Addicts also offers an annual, nationwide girls' math competition, GAIM. HSU Students Use Math to Solve Real-World Problems in International Competition. NOTE: Individuals cannot compete in Math Olympiads. Written for the student searching for new competition math tactics, the coach or teacher hoping to find a wealth of problems, or simply someone seeking to keep practicing and improving his math skills, The Original Collection of Math Contest Problems is used by elementary and middle school students to excel in MATHCOUNTS, Math Olympiads, and beyond. Every contest has questions from different areas of mathematics, suitable for the grade level indicated. If you purchased a MATHCOUNTS competition set through the MATHCOUNTS online store, you may request the step-by-step solutions for that competition set by contacting [email protected]
AHSME Problems and Solutions. The 2019 Math Olympiad will be held on Saturday September 21st. Each question is designed to test various aspects of your math abilities. Students in each league compete for the highest scores, while schools compete for the highest team score: the total of the top 5 scores in each school. SMT aims to encourage interest in math by providing students from around the world an opportunity to work on fun and challenging problems and to meet other students interested in math. There can be a number of reasons why you math competition problems might not like your order. The competition will not take place on April 15 & 16 as originally announced. Questions & Answers 2018. The University of Tulsa Department of Mathematics has hosted the MATHCOUNTS East Central Regional for more than three decades. Math Puzzles Volume 1 features classic brain teasers and riddles with complete solutions for problems in counting, geometry, probability, and game theory. Free challenging math problems for Kids (1st grade, 2nd grade, 3rd grade, 4th grade, 5th grade, 6 grade and 7th grade) This site contains first through seventh grade free math problems with answers that help you with math competitions. The UNT Math Department and the UNT Math Club invite all undergraduate students currently enrolled at UNT to take part in the newly redesigned Problem of the Month Competition. In the second round the teacher divided them so that nobody was in the same team with anyone he or she has played with in the first round. These contests give students the opportunity to show off their math skills. Perennial Math is such an awesome way for me to enrich my talented and gifted students. Day 2 Second Day's Problems. Timeline • Countries • Results • Search • Problems • Hall of fame • About IMO de en es fr ru The International Mathematical Olympiad (IMO) is the World Championship Mathematics Competition for High School students and is held annually in a different country. Understanding algebra rate problems. Each school is limited to a maximum of 10 students each. Math problems fuel 'Hunger Games'-style competition at Paul R. Classes, Workshops, and Tutoring - In addition to organizing math competitions, mathleague. [email protected]
Ranked in the top 20 math graduate programs by U. The IMC is an international proof-based math competition held during the summer in various Eastern European universities. Math Outreach Office receives Pillar Sponsorship from Manulife and mbna. Believe it or not, this "math" question actually requires no math whatsoever. AoPS Problem Series. Some of the links were taken from more than 14,000 problems collected by Art of Problem Solving. Compete with tens of thousands of students from nearly 60 countries. The goal of the competition is to encourage students' interest in math, to develop their problem solving skills, and to inspire them to excel in math. The competition will not take place on April 15 & 16 as originally announced. Problems are non-routine problem-solving questions that are adapted to many math competitions, including the Noetic Learning Math Contest. com practice many different topics. Math Puzzles Volume 2 is a sequel book with more great problems. 2019 Competition. Author of hundreds of solutions to olympiad math problems on artofproblemsolving. Opening Remark and explanation on competition rules. Rather than enjoying a fine PDF gone a cup of coffee in the afternoon, on the other hand they juggled as soon as some harmful virus inside their computer. Geometry Test. American Regions Math League (ARML) - Results and past problems for the ARML, an annual national competition. Copies of Previous Exams. In each written round of the competition, the required unit for the answer is included in the answer blank. Michigan Mathematics Prize Competition. org Newsletter Signup Sign up for our AwesomeMath Newsletter to be the first to receive the latest news regarding our summer program, online classes, competitions and training information, XYZ Press publications, as well as learn about our most recent sales, promotions, and discounts. , what is a phd proposal, hard math word problems, homework help algebra, importance of doing a case study in research, byu essay helpSomething as complex as capitalism cannot be easily defined. it is a real number. com, a math practice program for schools and individual families. Knowing the answer is always 24 alleviates a classic type of math anxiety—getting the right answer—and instead puts the emphasis on the method behind the math. Joe Holbrook Memorial Math Competition 8th Grade October 14, 2018 General Rules You will have 75 minutes to solve 40 questions. Zoom International Math League (ZIML) is an educational program to help students expand their mathematical problem solving by practicing everyday. These problems and questions deal with calculating angles, perimeters, areas and volumes. Some of the links were taken from more than 14,000 problems collected by Art of Problem Solving. For copies of the problems and solutions from prior years, and related information, see below. A writer of a math competition put each of his problems into exactly one category, as shown. If the length is increased by 4 inches and the width is decreased by 1 inch, the area will be 60 square inches. The Problem Solving in Math seminar To help prepare for the Putnam Competition, the math department runs the 1 credit course Math 43900. Contest Home > Contest Questions and Answers: Contest Questions and Answers : Questions & Answers 2019. The Grade 12 open courseware, Mathematics Resource Manual and Euclid eWorkshop can help you brush up on the material and provide many problems with solutions. The William Lowell Putnam Mathematical Competition 1985-2000: Problems, Solutions, and Commentary The William Lowell Putnam Mathematical Competition 1985–2000 Problems, Solutions, and Commentary i Reproduction. Ambassador International Youth Math Challenge - Official July 2019 – Present 5 months. mah sole Jan 3 '18 at 12:01 5 $\begingroup$ Hidden in the image, but not the text, is "the line CW divides the unshaded area in half. Indiana State Math Contest - 2019. Math competitions are offered for each grade from third grade through Advanced Math. Therefore we can reply to your question as soon as possible. Below are a number of printable worksheets of math games and puzzles for high school students. Competition Set: 1994 through 1998. Create your own math worksheets. The International Youth Math Challenge is one of the biggest math competition for students from all around the world: Unleash your creativity, knowledge, and math skills. Part I answers Part II problems. Written for the student searching for new competition math tactics, the coach or teacher hoping to find a wealth of problems, or simply someone seeking to keep practicing and improving his math skills, The Original Collection of Math Contest Problems is used by elementary and middle school students to excel in MATHCOUNTS, Math Olympiads, and beyond. Each year the Putnam competition is held on the first Saturday of December and consists of a morning session and an afternoon session of three hours each. Problem 1 Problem 2 Problem 3 Problem 4 Problem 5. Math Competition Classes. The Seattle Infinity Math Competition is a one-day competition that fields middle-school teams of up to four people. So I tried the good old Calculus 1 approach and turned this into an optimization problem. Timeline • Countries • Results • Search • Problems • Hall of fame • About IMO de en es fr ru The International Mathematical Olympiad (IMO) is the World Championship Mathematics Competition for High School students and is held annually in a different country. Participation in the program is through your school. For more information: Read an overview of the ZIML Programs. "Math Puzzles Volume 1" features classic brain teasers and riddles with complete solutions for problems in counting, geometry, probability, and game theory. 2018 Math Competition. The Math League Contests (www. Event Times. Each question is designed to test various aspects of your math abilities. com, a math practice program for schools and individual families. Many mathematics competitions sell books of past competitions and solutions. The University of Tulsa Department of Mathematics has hosted the MATHCOUNTS East Central Regional for more than three decades. To successfully provide this introduction, we developed an elementary math enrichment program that's dynamic, intuitively structured, and appropriately paced for all students. This problem can be used for competition practice, with your math club or in the classroom. 106 Geometry Problems from the AwesomeMath Summer Program is an excellent work for the aspiring Olympiad geometer. BLUFFTON — Bluffton University’s mathematics department will host its annual math competition for high school students from 9 a. National Pi Day Math Problems Solved! Winners have been notified via email, but we couldn’t bear to leave everyone hanging so answers are below! OPTION A: I’m thinking of a ten-digit integer whose digits are all distinct. ” That point is underscored by the ongoing quality issues involving Tesla’s older Model X. Final Round – Top three teams at each grade level compete in gym; three problems per team. 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http://cdelph.com/index.php/library/analytic-combinatorics-symbolic-combinatorics
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math
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By Flajolet Ph., Sedgewick R.
Read Online or Download Analytic combinatorics - symbolic combinatorics PDF
Best combinatorics books
A q-clan with q an influence of two is similar to a undeniable generalized quadrangle with a kinfolk of subquadrangles every one linked to an oval within the Desarguesian airplane of order 2. it's also akin to a flock of a quadratic cone, and accordingly to a line-spread of third-dimensional projective area and therefore to a translation airplane, and extra.
Matroids seem in various parts of arithmetic, from combinatorics to algebraic topology and geometry. This mostly self-contained textual content offers an intuitive and interdisciplinary therapy of Coxeter matroids, a brand new and gorgeous generalization of matroids that's in response to a finite Coxeter crew. Key issues and features:* Systematic, truly written exposition with considerable references to present learn* Matroids are tested by way of symmetric and finite mirrored image teams* Finite mirrored image teams and Coxeter teams are built from scratch* The Gelfand-Serganova theorem is gifted, taking into consideration a geometrical interpretation of matroids and Coxeter matroids as convex polytopes with definite symmetry houses* Matroid representations in structures and combinatorial flag kinds are studied within the ultimate bankruptcy* Many routines all through* first-class bibliography and indexAccessible to graduate scholars and examine mathematicians alike, "Coxeter Matroids" can be utilized as an introductory survey, a graduate path textual content, or a reference quantity.
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Additional info for Analytic combinatorics - symbolic combinatorics
Let ñ be the language of words ø with no occurrence of ❮ and è the language of words The autocorrelation is then ✡ as that end with ❮ but have no other occurrence of ❮ . First, by appending a letter to a word of ñ , one finds a nonempty word either in ñ or è , so that ❛ ñ➀ö⑩❶ è ï❡❝❴ ì öòñ☛✵ó➃ (36) ✺ Next, appending a copy of the word ❮ to a word in ñ may only give words that contain ❮ at or “near” the end. Precisely, the decomposition based on the leftmost occurrence of ❮ in ñ⑥❮ is ❛ (37) ñ☛✵➠❴✙❮ ï❱è✼✵ ❞ ❼ ❴✳Õ ❩ ❿ ❑ Õ ❩ ❿ ý ❖❀❖▲❖ Õ ▼ ❛ ✆ ô➒õ✳➋ ö corresponding to the configurations ✷❷✷✁✷❷✷❷✷✁✷ ✷❷✷❷✷✁✷❷✷✁✷ ñ ï ❮ ✷✁✷❷✷❷✷✁✷❷✷ ✷❷✷✁✷❷✷✁✷❷✷ ÷ ❮ ø❻ù Õ ❩ ❿ ❑ ❖▲❖▲❖ Õ ▼ ú è The translation of the system (36), (37) into OGF’s then gives: The OGF of words not containing the pattern ❮ is ❝ û ❝ û➵ï (38) ➧ ❝ ▼ ö ð❤✡ ❣Õ ø ➆ ❝û ❝û✆ ø ø ◆äï✜❩ ➌ ✡ ❮➸ø ➌ the pattern length, and ❝ û the where ➆ is the alphabet cardinality, ✡ autocorrelation polynomial, ❝ û➵ï ò ❩ ❩ ❝ .
The book of van Rensburg describes many such constructions and their relation to certain models of statistical physics. ❃ ❨ ➳ ➛♣➸ ❰ Ý I. 2. Integer related constructions. Finally, we say a few words about the two constructions of cycle and powerset that haven’t been yet applied to ❫ . First, the class ❩ ï ● ❴➲❜ ❛ comprises cyclic compositions, that is, compositions defined up to circular shift; so, for instance ö ö✐ ❩ ✈ð♠ö ö ✈ , ✐ ö✈ð♠ö ö ✈ ö , etc, are identified. Alternatively, we may view elements composed ú of as “wheels” ú ú of ú circular arrangements of segments (taken up to circular symmetry).
20. Runs in arbitrary alphabets. For an alphabet of cardinality ➥ , the quantity ✽✰➙ ➥ ✽✰➙➵➛ ➭ ➛♥➦ ➳ ➙➠✽✛➸★➛ ➭ ➥ ➧ ✮ ❈ is the OGF of words without ➫ consecutive occurrences of a designated letter. ❃ The case of longest runs exemplifies the expressive power of nested constructions involving sequences. 7. , letters of a finite alphabet ➃ ) together with combinatorial sums, cartesian products, and sequence constructions is said to be a regular specification. A language ➦ is said to be ➧ -regular (specification-regular) if there exists a regular specification ➨ such that ➦ and ➨ are combinatorially isomorphic, ➦ ïþ ➨ .
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http://onlinelibrary.wiley.com/doi/10.1002/sim.5437/abstract
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math
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Identifying unusual growth-related measurements or longitudinal patterns in growth is often the focus in fetal and pediatric medicine. For example, the goal of the ongoing National Fetal Growth Study is to develop both cross-sectional and longitudinal reference curves for ultrasound fetal growth measurements that can be used for this purpose. Current methodology for estimating cross-sectional and longitudinal reference curves relies mainly on the linear mixed model. The focus of this paper is on examining the robustness of percentile estimation to the assumptions with respect to the Gaussian random-effect assumption implicitly made in the standard linear mixed model. We also examine a random-effects distribution based on mixtures of normals and compare the two approaches under both correct and misspecified random-effects distributions. In general, we find that the standard linear mixed model is relatively robust for cross-sectional percentile estimation but less robust for longitudinal or ‘personalized’ reference curves based on the conditional distribution given prior ultrasound measurements. The methodology is illustrated with data from a longitudinal fetal growth study. Published 2012. This article is a US Government work and is in the public domain in the USA.
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CC-MAIN-2017-22
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http://www.quickermaths.com/timing-puzzles/
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math
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Timing Puzzle 1
Having 2 sand-glasses: one 7-minute and the second one 4-minute. How can you time correctly 9 minutes ?
Timing Puzzle 2
A teacher of mathematics used an unconventional method to measure a 15-minute time limit for a test. He just used 7 and 11-minutehourglasses. During the whole time he turned sandglasses only 3 times (turning both hourglasses at once count as one flip).
Explain how the teacher measured 15 minutes.
Leave your answers below
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s3://commoncrawl/crawl-data/CC-MAIN-2019-26/segments/1560627998100.52/warc/CC-MAIN-20190616102719-20190616124719-00554.warc.gz
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CC-MAIN-2019-26
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https://www.encyclopediaofmath.org/index.php/Riesz_product
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math
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An infinite product of the form
With the help of such products (, for all ) F. Riesz indicated the first example of a continuous function of bounded variation whose Fourier coefficients are not of order . If , then the identity
gives the series
which is said to represent the Riesz product (1). In case , for all , the series (2) is the Fourier–Stieltjes series of a non-decreasing continuous function . If and
then almost-everywhere. If, in addition, , then the series (2) converges to zero almost-everywhere.
A number of problems, mainly in the theory of trigonometric series, has been solved using a natural generalization of the Riesz product when in (1) is replaced by specially chosen trigonometric polynomials .
|||N.K. [N.K. Bari] Bary, "A treatise on trigonometric series" , Pergamon (1964) (Translated from Russian)|
|||A. Zygmund, "Trigonometric series" , 1–2 , Cambridge Univ. Press (1988)|
Riesz product. V.F. Emel'yanov (originator), Encyclopedia of Mathematics. URL: http://www.encyclopediaofmath.org/index.php?title=Riesz_product&oldid=16157
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s3://commoncrawl/crawl-data/CC-MAIN-2019-39/segments/1568514574058.75/warc/CC-MAIN-20190920175834-20190920201834-00223.warc.gz
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CC-MAIN-2019-39
| 1,061
| 9
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https://e-booksdirectory.com/details.php?ebook=7306
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math
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Basic Analysis Gently Done: Topological Vector Spaces
by Ivan F. Wilde
Publisher: King's College, London 2010
Number of pages: 129
These notes are based on lectures given at King's College London (as part of the Mathematics MSc program). The approach here is to discuss topological vector spaces - with normed spaces considered as special cases. Contents: Topological Spaces; Nets; Product Spaces; Separation; Vector Spaces; Topological Vector Spaces; Locally Convex Topological Vector Spaces; Banach Spaces; The Dual Space of a Normed Space; Frechet Spaces.
Download or read it online for free here:
by Feng Tian, Palle E.T. Jorgensen - arXiv
Notes from a course which covered themes in functional analysis and operator theory, with an emphasis on topics of special relevance to such applications as representation theory, harmonic analysis, mathematical physics, and stochastic integration.
by D. Husemoller - Tata Institute of Fundamental Research
Contents: Exact Couples and the Connes Exact Couple; Abelianization and Hochschild Homology; Cyclic Homology and the Connes Exact Couple; Cyclic Homology and Lie Algebra Homology; Mixed Complexes, the Connes Operator B; and more.
by G. Jungman - Los Alamos National Laboratory
Lecture notes on operator algebras. From the table of contents: Structure Theory I; von Neumann Algebras; States and Representations; Structure Theory II; Matrices; Automorphism Groups; Extensions; K-Theory; Nuclear C* Algebras.
by F.F. Bonsall - Tata Institute Of Fundamental Research
The book is concerned with the application of a variety of methods to both non-linear (fixed point) problems and linear (eigenvalue) problems in infinite dimensional spaces. Author was interested in the construction of eigenvectors and eigenvalues.
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s3://commoncrawl/crawl-data/CC-MAIN-2021-43/segments/1634323587593.0/warc/CC-MAIN-20211024173743-20211024203743-00117.warc.gz
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CC-MAIN-2021-43
| 1,762
| 14
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http://www.carriemurraynaturecenter.org/fees/
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math
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Carrie Murray Nature Center can make your next event a hit!
Birthday Parties/Baby Showers
$295 for up to 25 children. $5 per child over the 25
$50 non-refundable deposit required
$5 per person for up to 2 ½ hours of instruction
$8 per person for over 2 ½ hours of instruction
$25 non-refundable deposit required
$150 for 45 minutes of programming for up to 100 students and teachers, $1 each for any additional people over the 100.
Any program outside of the Baltimore City limits will include an additional $25 transportation fee, making the price $175.
$25 non-refundable deposit required.
Prices range from free to $6
$275/half day (up to 4 hours)
$75 for each additional hour
$250/half day (up to 4 hours)
Carrie Murray Nature Center is located in the beautiful Leakin Park in Baltimore City, MD
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s3://commoncrawl/crawl-data/CC-MAIN-2018-26/segments/1529267867424.77/warc/CC-MAIN-20180625033646-20180625053646-00583.warc.gz
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CC-MAIN-2018-26
| 801
| 15
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http://community.runnersworld.com/topic/question-about-interval-times?reply=48583320831437662
|
math
|
After today's rest day, I'm heading out to do short intervals. The marathon schedule calls for this:
4x200 -- 35sec
2x400 -- 1:40
600 -- 2:00
1 mile warm up, 1 mile cool down
What do the times mean? Is that rest between the intervals? Or is that how fast I should be running each interval in?
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s3://commoncrawl/crawl-data/CC-MAIN-2017-34/segments/1502886107487.10/warc/CC-MAIN-20170821022354-20170821042354-00551.warc.gz
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CC-MAIN-2017-34
| 292
| 6
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https://www.physicsforums.com/threads/microscopes-and-vision.895389/
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math
|
1. The problem statement, all variables and given/known data - Why is it more useful to mark an objective lens [in a microscope] by its magnification rather than focal length? - Why might it be more convenient to think in terms of refractive power rather than focal length? [dealing with vision here] 2. Relevant equations - thin lens equation: (1/f) = (1/s)+(1/s') - magnification (m) = (-s'/s) - Refractive power (R) = (1/f) - Total R of eye = R(cornea) + R(lens) = 40 D at far point, 43.5 D at near point. - Total R = R(eye) + R(corrective lens) 3. The attempt at a solution - For the first question, I said that if you know m, then you could solve for the size of an object under a microscope pretty easily. Are there any other reasons that anyone could think of? - For the second, I honestly have no idea. To me, it seems just as reasonable to think about correcting vision in terms of the focal point of the eye/lens. I initially thought "well, glasses and contacts are in diopters, so it makes sense to think about correcting vision in this way," but couldn't we think of corrective lenses in terms of the focal point?
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s3://commoncrawl/crawl-data/CC-MAIN-2018-30/segments/1531676590199.42/warc/CC-MAIN-20180718135047-20180718155047-00313.warc.gz
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CC-MAIN-2018-30
| 1,125
| 1
|
https://workforce.libretexts.org/Bookshelves/Electronics_Technology/Book%3A_Electrical_Fundamentals_Competency_(Industry_Training_Authority_of_BC)/01%3A_Basic_Principles_of_Electricity/02%3A_Basic_Circuit_Concepts/2.04%3A_Series-parallel_Circuits
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math
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The series-parallel circuit combines the two previously described types of circuits into one operating system with some distinct advantages. By introducing a load or resistor in series with a parallel circuit, the current flow through the circuit can be controlled (Figure 9).
- Series-parallel circuit
Using Ohm’s law you can calculate total current flow.
I = E ÷ R
I = 12 V ÷ 2.3 Ω
I = 5.15 mA
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s3://commoncrawl/crawl-data/CC-MAIN-2023-06/segments/1674764500837.65/warc/CC-MAIN-20230208155417-20230208185417-00021.warc.gz
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CC-MAIN-2023-06
| 400
| 6
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http://www.CMStatistics.org/RegistrationsV2/CFE2021/viewSubmission.php?in=1219&token=2606257p3p5qpor95q2r60n601807923
|
math
|
Title: Evaluating factor strength with a large number of assets
Authors: Sermin Gungor - Bank of Canada (Canada) [presenting]
Richard Luger - Laval University (Canada)
Abstract: An asymptotic test is developed for evaluating ``factor strength" in linear factor pricing models using a large number of assets. Factor models explain the expected return differentials across assets as a linear function of their exposures (betas) to a small number of risk factors. In doing so, they rely on the assumption that factors under consideration are well identified (so-called strong factors). A failure of this identification condition implies that a factor is either ``weak" with small betas or ``irrelevant" with exactly zero betas. In either case, the estimation of the factor risk premium becomes unreliable with severe overrejection of a zero premium on the weak/irrelevant factor. The proposed methodology identifies weak and irrelevant factors while adjusting the probability of false rejections resulting from a large number of assets. i.e. multiple testing problems. An application using individual stock data for the U.S. stock market finds that the market factor is the only strong factor, but its strength varies over time with the market composition.
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s3://commoncrawl/crawl-data/CC-MAIN-2022-21/segments/1652662558030.43/warc/CC-MAIN-20220523132100-20220523162100-00415.warc.gz
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CC-MAIN-2022-21
| 1,253
| 4
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https://ilglobo.com.au/recipes/37290/pandoro-and-strawberry-tiramisu/
|
math
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• 400g pandoro
• 150g strawberries
• 4 mandarines
• 200g mascarpone cheese
• 100g icing sugar
• 2 egg whites, whipped
• Alchermes (red liqueur)
1. Keep 4 strawberries aside for slicing when plating. Purée the rest in a blender.
2. Peel and segment 2 mandarines. Squeeze the remaining 2 mandarines and flavour the juice with a few drops of Alchermes.
3. Cut the pandoro into thin slices and brush each with the juice.
4. Blend the mascarpone with the icing sugar. Mix in the strawberry purée before folding in the egg whites.
5. Layer the tiramisù directly onto serving plates in the following order: pandoro slice, cream mixture, slices of strawberry, mandarine segments. Repeat and finish with a layer of fruit.
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s3://commoncrawl/crawl-data/CC-MAIN-2019-04/segments/1547583660818.25/warc/CC-MAIN-20190118213433-20190118235433-00517.warc.gz
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CC-MAIN-2019-04
| 729
| 12
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http://www.mechlook.com/interplanar-spacing-for-cubic-crystal/
|
math
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— Interplanar spacing implies the magnitude of the distance between two adjacent and parallel planes of atoms.
The interplanar spacing is a function of the, Miller indices (h,k and /) as well as the lattice parameter(s).
Interplanar spacing with a given set of Miller indices is a useful bit of information.
Planes with large interplanar spacing have low indices and a high density of lattice points, whereas the reverse is true for planes of close spacing.
— If we consider the simple cube shown in Fig. 35.26, it is obvious that, in this case, the most widely spaced atomic planes are those spaced at intervals equal to the lattice parameters, i.e., the (100) planes. The spacing is
d100 = a …(i)
The dodecahedral planes (110) bisect the face diagonal for a spacing of
D110 =( ½)√(a2+a2)= a/√2 …(ii)
The octahedral planes (111) trisect the body diagonal for a spacing of
— General equations for interplanar spacing for various unit cells can be written in terms of the Miller indices; namely:
Cubic : 1/d2hkl = (h2+k2+l2) / a2 …(iv)
Tetragonal: 1/d2hkl = (h2+k2)/a2 +( l2 )/ c2 …(v)
Orthorhombic: 1/d2hkl = (h2)/a2 + k2/b2 + (l2) / c2 …(vi)
Hexagonal: 1/d2hkl = (4/3)(h2+hk+k2) / a2 +l2/c2…(viii)
N.B.: a is lattice parameter and c/a is axial ratio in HCP crystal structure (refer Fig. 35.11). From (iv) above, for a cubic crystal, the interplanar spacing dhkl = a√/(h2+k2+l2) and so on for tetragonal, orthorhombic and hexagonal structures.
Derivation of interplanar spacing of cubic crystal
—The interplanar spacing or distance ‘dhkl‘ between adjacent planes of Miller indices (hkl) is defined as the spacing between the first such plane and a parallel plane passing through the origin.
—Refer Fig. 35.27 ais the lattice constant. Let h, k, and l are the Miller indices for a plane ABC. An equation is to be derived for interplanar distance‘d’ of plane ABC from a plane parallel to it
and passing through ‘o’ (origin) in terms ofh,k,land a. OD is the normal from O on plane ABC. OD – d = interplanar distance. The intercepts of the plane ABC on the three axis i.c.,X, Y and Z axis are OA, OB and OC respectively.
Now, OA=a/h, OB=a/k,OC=a/l …(i)
Also, cos α=OD/OA= d/(a/h) =dh/a …(ii)
cos β= OD/OA= d/(a/k)= dk/a …(iii)
cos γ=OD/OC = d/(a/l) = dl/a …(iv)
Since, cos2 α+ cos2β + cos2γ = 1. therefore
(dh/a)2 +(dk/a)2 + (dl/a)2 = 1
d2h2/a2 + d2k2/a2 + d2l2/a2 = 1
d2(h2 + k2 + l2) =a2
d2=a2 /(h2 + k2 + l2)
d= a2 /√(h2 + k2 + l2)
|
s3://commoncrawl/crawl-data/CC-MAIN-2014-23/segments/1405997858962.69/warc/CC-MAIN-20140722025738-00229-ip-10-33-131-23.ec2.internal.warc.gz
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CC-MAIN-2014-23
| 2,489
| 29
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https://www.hackmath.net/en/calculator/conversion-of-volume-units?unit1=ml&unit2=dl&dir=1
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math
|
Conversion mililiters to deciliters, ml to dl.The conversion factor is 0.01; so 1 mililiter = 0.01 deciliters. In other words, the value in ml divide by 100 to get a value in dl. The calculator gives the answer to the questions: 80 ml is how many dl? or change ml to dl. Convert ml to dl.
1 ml = 0.01 dl1 mililiter is 0.01 deciliters.
Essential of conversions SI units of the volume is the coefficient 1000. Units of volume are the cubes of units of length. For example, 1 dm3 = 1000 cm3. Another important rule is definition 1 liter = 1 dm3. Imperial volume units use nontrivial coefficients for conversions. ie. 1 gal = 3.78541 liters
Choose other units (volume)
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s3://commoncrawl/crawl-data/CC-MAIN-2020-34/segments/1596439739046.14/warc/CC-MAIN-20200813132415-20200813162415-00420.warc.gz
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CC-MAIN-2020-34
| 664
| 4
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https://www.paraisos-fiscales.info/answers/17288045-which-number-produces-an-irrational-number-when-added-to-3-4
|
math
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Find the future value (FV) of the annuity due. (Round your answer to the nearest cent.) $175 monthly payment, 7% interest, 11 years
The future value of the annuity due to the nearest cent is $2956.
Consider the provided information:
It is provided that monthly payment is $175, interest is 7% and time is 11 years.
The formula for the future value of the annuity due is:
Now, substitute P = 175, r = 0.07 and t = 11 in above formula.
Hence, the future value of the annuity due to the nearest cent is $2956.
"The municipal transportation authority determined that 58% of all drivers were speeding along a busy street. In an attempt to reduce this percentage, the city put up electronic speed monitors so that drivers would be warned if they were driving over the speed limit. A follow-up study is now planned to see if the speed monitors were effective. The null and alternative hypotheses of the test are H0 : π = 0.58 versus Ha : π < 0.58. It is planned to use a sample of 150 drivers taken at random times of the week and the test will be conducted at the 5% significance level. (a) What is the most number of drivers in the sample that can be speeding and still have them conclude that the alternative hypothesis is true? (b) Suppose the true value of π is 0.52. What is the power of the test? (c) How could the researchers modify the test in order to increase its power without increasing the probability of a Type I Error?"
a) X=77 drivers
b) Power of the test = 0.404
c) Increasing the sample size.
This is a hypothesis test of proportions. As the claim is that the speed monitors were effective in reducing the speeding, this is a left-tail test.
For a left-tail test at a 5% significance level, we have a critical value of z that is zc=-1.645. This value is the limit of the rejection region. That means that if the test statistic z is smaller than zc=-1.645, the null hypothesis is rejected.
The proportion that would have a test statistic equal to this critical value can be expressed as:
The standard error of the proportion is:
Then, the proportion is:
This proportion, with a sample size of n=150, correspond to
The power of the test is the probability of correctly rejecting the null hypothesis.
The true proportion is 0.52, but we don't know at the time of the test, so the critical value to make a decision about rejecting the null hypothesis is still zc=-1.645 corresponding to a critical proportion of 0.51.
Then, we can say that the probability of rejecting the null hypothesis is still the probability of getting a sample of size n=150 with a proportion of 0.51 or smaller, but within a population with a proportion of 0.52.
The standard error has to be re-calculated for the new true proportion:
Then, we calculate the z-value for this proportion with the true proportion:
The probability of getting a sample of size n=150 with a proportion of 0.51 or lower is:
Then, the power of the test is β=0.404.
The only variable left to change in the test in order to increase the power of the test is the sample size, as the significance level can not be changed (it is related to the probability of a Type I error).
It the sample size is increased, the standard error of the proprotion decreases. As the standard error tends to zero, the critical proportion tend to 0.58, as we can see in its equation:
Then, if the critical proportion increases, the z-score increases, and also the probability of rejecting the null hypothesis.
Someone help me on this.
So we have the expression:
Recall that i² is just -1. Thus:
Combine like terms:
And we're done!
Please help me with this problem
I think the answer is A. Hope this help
A is the answer So your welcome
Polygon V has an area of 1 square unit. Jun-seo drew a scaled version of Polygon V using a scale factor of 7 and labeled it Polygon W.
it is 49 for sure
it worked for me on khan
A flagpole casts a shadow that is 30 feet long. At the same time, a man standing nearby who is 6 feet tall casts a shadow that is 60 inches long. How tall is the flagpole to the nearest foot?
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s3://commoncrawl/crawl-data/CC-MAIN-2024-10/segments/1707947474643.29/warc/CC-MAIN-20240225203035-20240225233035-00119.warc.gz
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CC-MAIN-2024-10
| 4,043
| 39
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http://pldml.icm.edu.pl/pldml/element/bwmeta1.element.bwnjournal-article-doi-10_4064-cm91-2-4
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math
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The notion of Gorenstein rings in the commutative ring theory is generalized to that of Noetherian algebras which are not necessarily commutative. We faithfully follow in the steps of the commutative case: Gorenstein algebras will be defined using the notion of Cousin complexes developed by R. Y. Sharp [Sh1]. One of the goals of the present paper is the characterization of Gorenstein algebras in terms of Bass numbers. The commutative theory of Bass numbers turns out to carry over with no extra changes. Certain algebras having locally finite global dimension are also characterized. The special case where the algebras are free modules over base rings is explored. Thanks to these observations, it is clarified how the Gorensteinness is inherited under flat base changes. In conclusion, a characterization for local algebras to be Gorenstein is given, accounting for the reason why the theory behaves so well in the commutative case. Examples are explored and open problems are given. See [GN2] and [GN3] for further developments.
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s3://commoncrawl/crawl-data/CC-MAIN-2023-50/segments/1700679100290.24/warc/CC-MAIN-20231201151933-20231201181933-00082.warc.gz
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CC-MAIN-2023-50
| 1,035
| 1
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https://tapmyexam.com/what-are-expectation-theory-and-its-impact-on-the-economy/
|
math
|
The basic theory of interest rates can be broken down into two basic concepts. The first concept is what is called the forward rate. The forward rate describes the future rate at which banks will charge interest on loans. This interest rate, when expressed as a percentage, is known as the forward interest rate. The next basic concept is the present interest rate.
The present interest rate is what is charged today on loans to investors or borrowers. The forward interest rate, or the future interest rate, is a projection of the future rate at which the future rate will be determined after a period of time. The forward interest rate is the most flexible of the two concepts.
For example, a bank may anticipate that interest will be higher than normal in three short time periods. The present interest rate will be higher than the normal interest rate. But if it is higher than the normal rate for three months, the forward rate will be much lower than the normal rate. So, when the forward rate becomes normal, the bank will charge more interest for the loans. This is the forward interest rate.
The reason that this interest rates can change rapidly, and often wildly, is because banks do not have a fixed rate for loans. They use a variety of factors to determine what the future interest rate will be. But, by predicting what future rates will be, they are able to control the rate at which the future rates are determined. This means that by forecasting the future rate, banks can lock in the interest rate at a certain level and not let it go up or down.
It is possible for the banks to predict, ahead of time, what the future interest rate will be, even before the rates go up. Once the prediction is made, banks have the ability to control the rate at which the rates are determined. in such a way that the interest rates are more predictable than they would be if they were not predicted.
Banks know that the future interest rate is important because they can use it to attract people to come into their doors. When the future interest rate is low, there is less competition and thus a lower risk to the bank. In fact, by controlling the rate, the bank has greater control over the value of its assets than it would by keeping the rate lower. In a recession, a lower risk rate can mean a higher return.
Even the future rate of interest is dependent upon the economy. In a recession, the economy may be expected to slow down. However, if the unemployment rate is expected to stay the same, the interest rate will remain steady. But if unemployment is expected to rise, the interest rate may move up. Thus, the stability of the interest rate depends upon the state of the economy.
Expectation theory also has a lot to do with inflation. If inflation is expected to rise, the interest rate may rise.
As a result of this principle, interest rates can be determined based on a forecast of the future of the interest rate in the future. That future interest rate can then be used as leverage to make better interest rates predictions than could be made if the prediction was not based on an assumption about how future interest rates will behave.
Of course, the predictions that we make about future rates are subject to human error. So we cannot simply rely upon these predictions to make better interest rates predictions.
Future interest rates can affect our future lives in a variety of ways. We can use the predictions to help us to determine whether we should take out loans now.
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s3://commoncrawl/crawl-data/CC-MAIN-2023-06/segments/1674764500041.18/warc/CC-MAIN-20230202200542-20230202230542-00114.warc.gz
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CC-MAIN-2023-06
| 3,492
| 11
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https://bodheeprep.com/cat-quant-practice-problems/830
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math
|
Neelam rides her bicycle from her house at A to her club at C, via B taking the shortest path. Then the number of possible shortest paths that she can choose is
The shortest route from A to B is via the diagonal in the square P. A to the north-west corner of square P can be travelled in 4!/2!×2! ways. Number of ways to travel from the south-east corner of square P to B is 6!/4!×2!.
B to the north-east corner of D can be travelled in 6!/5! ways. From there to C can be travelled in 2 ways. There is 1 other way of travelling from B to C (along the perimeter of the field).
The total number of ways is, therefore, (4!/2!×2!) × (6!/4!×2!) × (6!/5! × 2 + 1)
= 6×15×13 = 1170
CAT 2019 Online Course
CAT Quant Questions with Video Solutions
- CAT Quant Questions Set 01
- CAT Quant Questions Set 02
- CAT Quant Questions Set 03
- CAT Quant Questions Set 04
- CAT Quant Questions Set 05
- CAT Quant Questions Set 06
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s3://commoncrawl/crawl-data/CC-MAIN-2019-30/segments/1563195528869.90/warc/CC-MAIN-20190723043719-20190723065719-00045.warc.gz
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CC-MAIN-2019-30
| 921
| 13
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http://www.math.union.edu/activities/seminars/student/cgi/event.cgi/2005?./2005/0124-PPT
|
math
|
Results on Resultants
Professor Pedro Teixeira
January 24, 2005
Tea and pastries will be served
While it's well known that a polynomial equation f(x)=0 with complex coefficients always has a solution (Fundamental Theorem of Algebra), finding the solution(s) is often a very challenging problem. Equations of degree 2 are handled by the quadratic formula, and formulas of a similar flavor (but a lot "messier") take care of equations of degrees 3 and 4. However, for degree 5 and higher no similar formulas exist. In view of this fact, it's surprising that given any two polynomial equations f(x)=0 and g(x)=0, it's always possible to determine whether the equations have a common solution, just using the coefficients of f and g and the arithmetic operations... and it isn't hard either! One possible method is to use the Euclidean Algorithm to find the GCD of f and g. In this talk we'll focus on a second method, which is by using resultants. We'll see how resultants can also be used to determine whether a polynomial has multiple roots, to "solve" parametric equations, and to help solving systems of polynomial equations in two variables, and how, unlike the Euclidean Algorithm, the resultant generalizes in many directions.
|Union College Math Department Home Page|
Comments to: email@example.com
Created automatically on: Tue Oct 23 05:29:53 EDT 2018
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s3://commoncrawl/crawl-data/CC-MAIN-2018-43/segments/1539583516123.97/warc/CC-MAIN-20181023090235-20181023111735-00086.warc.gz
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CC-MAIN-2018-43
| 1,358
| 8
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https://www.simiode.org/tags/parachute
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math
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09 Dec 2018 | Contributor(s):: Brian Winkel
Phoebus, Ronald and Cole Reilly. 2004, Differential Equations and the Parachute Problem. Presentation 10 May 2004. https://mse.redwoods.edu/darnold/math55/DEproj/sp04/coleron/presentation.pdf .Abstract: The parachute problem is a classical first semester differential equations problem often...
22 Apr 2016 | | Contributor(s):: Brian Winkel
SPANISH LANGUAGE VERSION We have placed in Supporting Docs both Student and Teacher Version (LaTeX and PDF Versions) with a Spanish LaTeX Class file, SIMIODE-SPANISH.cls. Names will be x-y-S-Title-StudentVersion-Spanish and x-y--T-Title-TeacherVersion-Spanish.
1999-LongWeiss-Primer on Aerodynamic Drag
20 Jun 2015 | | Contributor(s):: Lyle N. Long, Harold Weiss
Long, Lyle N. and Harold Weiss. 1999. The Velocity Dependence of Aerodynamic Drag: A Primer for Mathematicians. The American Mathematical Monthly. 106(2): 127-135. This paper is exactly what it says it is, namely, a Primer for Mathematicians. There are ample models, data, attention to such...
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https://mobilemarketingreads.com/best-math-solver-apps/
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math
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Using your phones is now a way to solve complex or unfamiliar math problems. With the best math solver apps in this list, you can find answers to math questions with their solutions without wasting time.
The Best Math Solver Apps
Photomath, which is accepted by many as the best math solver app, allows you to scan the math problem with your smartphone’s camera and then find the answer step by step. The app, which is very easy to use, is the kind that will never force you as an interface. Photomath, which will help you solve all kinds of math problems you have difficulty with and to learn different math topics like algebra and geometry has been developed for both iOS and Android.
Microsoft Math Solver
Using an advanced AI-powered math problem solver, Microsoft Math Solver helps solve problems in arithmetic, algebra, trigonometry, calculus, statistics, and more. You can solve the questions by writing the problem on the screen just like writing on paper or by scanning the question you want to solve with the camera.
Also Read: The Best Graphing Calculator Apps
As in the other math solver apps in the list, in Mathway, you can quickly find the answer and step-by-step solution by taking a photo of the problem or typing the problem. The app supports a lot of math topics like calculus, graphing, and algebra.
CameraMath is one of the best math solver apps to solve math problems simply and effectively. Take a photo of the problem you want to solve and get the solution step by step. The app, which offers a forum atmosphere, also allows you to get help from others with questions that you cannot solve.
Also Read: The Best Apps for Students
Another app to help you solve math problems step by step is Cymath. You can either write the question in the app or scan it with your camera and solve it through the app. Supporting many areas of mathematics such as solving equations, factoring, logarithms, complex numbers, quadratic equations, and trigonometry, the app also helps its users in difficult subjects such as creating graphics, intersections, and finding asymptotes.
MalMath is for those looking for a simple-to-use math problem solver app. The app helps you solve questions about integrals, logarithms, algebra, and derivatives. MalMath also provides step-by-step instructions on how to solve any math problem. Although the app, which is heavily used by students, is very popular on Google Play, it is not preferred by users in the App Store.
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http://lib.mexmat.ru/books/35536
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math
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Нашли опечатку? Выделите ее мышкой и нажмите Ctrl+Enter
Название: Difference Equations: From Rabbits to Chaos
Авторы: Cull P., Flahive M.E., Robson R.
Difference equations are models of the world around us. From clocks to computers to chromosomes, processing discrete objects in discrete steps is a common theme. Difference equations arise naturally from such discrete descriptions and allow us to pose and answer such questions as: How much? How many? How long? Difference equations are a necessary part of the mathematical repertoire of all modern scientists and engineers.
In this new text, designed for sophomores studying mathematics and computer science, the authors cover the basics of difference equations and some of their applications in computing and in population biology. Each chapter leads to techniques that can be applied by hand to small examples or programmed for larger problems. Along the way, the reader will use linear algebra and graph theory, develop formal power series, solve combinatorial problems, visit Perron-Frobenius theory, discuss pseudorandom number generation and integer factorization, and apply the Fast Fourier Transform to multiply polynomials quickly.
The book contains many worked examples and over 250 exercises. While these exercises are accessible to students and have been class-tested, they also suggest further problems and possible research topics.
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https://www.lse.ac.uk/resources/calendar2022-2023/courseGuides/MA/2022_MA103.htm
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math
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Introduction to Abstract Mathematics
This information is for the 2022/23 session.
Prof Peter Allen and Dr Emilio Pierro
This course is compulsory on the BSc in Financial Mathematics and Statistics, BSc in Mathematics and Economics and BSc in Mathematics with Economics. This course is available on the BSc in Actuarial Science, BSc in Business Mathematics and Statistics, BSc in Data Science and BSc in Mathematics, Statistics and Business. This course is available as an outside option to students on other programmes where regulations permit. This course is available with permission to General Course students.
Students should have taken, or be taking concurrently, the course Mathematical Methods (MA100).
The course is an introduction to the use of formal definitions and proofs in mathematics, and to basic results of elementary set theory, number theory, linear algebra, algebra and analysis. Specific topics covered are as follows: Logic, sets and functions, relations, real numbers, infimum and supremum, sequences, limits and continuity, integers, prime numbers, greatest common divisor and modular arithmetic, complex numbers, groups and vector spaces.
This course is delivered through a combination of classes and lectures totalling a minimum of 80 hours across Michaelmas Term and Lent Term.
Students will be expected to produce 20 problem sets in the MT and LT.
Written answers to set problems will be expected on a weekly basis.
Students may wish to have one of the recommended textbooks: N L Biggs, Discrete Mathematics (2nd edn) or P J Eccles, An Introduction to Mathematical Reasoning, but these are not required. Further background reading can be found in R Allenby, Numbers and Proofs; M Liebeck, A Concise Introduction to Pure Mathematics; V Bryant, Yet Another Introduction to Analysis; R Bartle & D Sherbert, Introduction to Real Analysis and H Anton, Elementary Linear Algebra.
Exam (90%, duration: 3 hours) in the summer exam period.
Continuous assessment (10%) in the MT and LT.
Total students 2021/22: 171
Average class size 2021/22: 16
Capped 2021/22: No
Value: One Unit
Course selection videos
Some departments have produced short videos to introduce their courses. Please refer to the course selection videos index page for further information.
Personal development skills
- Problem solving
- Application of information skills
- Application of numeracy skills
- Specialist skills
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https://brainmass.com/business/inventory/financial-ratios-roe-roi-inventory-turnover-116972
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math
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Please calculate the following ratios for the financial statements attached
Debt to Equity
Debt to total assets
total asset turnover
net profit margin
return on investment
return on equity
Please find the solutions attached. I did the ratios for 2004 & 2005, and I also attached a word document that explains how to calculate the ratios.
The solution calculates debt to equity, interest coverage, turnover stats and profit margins amongst other ratios.
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https://app-wiringdiagram.herokuapp.com/post/deductive-geometry-year-10
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math
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DEDUCTIVE GEOMETRY YEAR 10
Deductive Geometry - mathsteacher
Deductive geometry, axiom, theorem, equality, properties of equality, transitive property, substitution property, deductive proof of theorems, angle sum of a triangle, exterior angle of a triangle and finding unknown values by applying properties of angles in triangles.[PDF]
Deductive Geometry Year 10 PDF Download - filiarmonici
Deductive Geometry Year 10 Deductive geometry mathsteachercomau, deductive geometry, axiom, theorem, equality, properties of equality, transitive property, substitution property, deductive proof of theorems, angle sum of a triangle, exterior angle of a triangle and finding unknown values by applying properties of angles in triangles. Geometry
Deductive Geometry Year 10 PDF Download
deductive geometry is the art of deriving new geometric facts from previously known facts by using logical reasoning in elementary school, many geometric facts are introduced by folding, cutting, or measuring exercises, not by logical deduction.
Geometry - mathsteacher
Geometry for Year 10. This chapter revises basic geometry including triangles, deductive geometry, congruence, similar figures and quadrilaterals. Then advanced topics including tangents to circles, the Angle at Centre Theorem, angles in the same segment, angles in alternate segments, cyclic quadrilaterals and their use in solving numerical problems are covered.
Deductive Geometry Worksheets - Printable Worksheets
Deductive Geometry. Showing top 8 worksheets in the category - Deductive Geometry. Some of the worksheets displayed are Deductive geometry, Inductive vs deductive wkst, Lesson inductive reasoning, Inductive reasoning geometry 2, Geometry work name, Unit 1 tools of geometry reasoning and proof, Work inductive reasoning name geometry regular, Inductive versus deductive reasoning.[DOC]
Year 10 - katemarshallmaths
Web viewThe values of c and d, respectively, in the pair of congruent triangles in the figure below are:[PDF]
Deductive Geometry - California State University, Northridge
CHAPTER 4 Deductive Geometry Deductive geometry is the art of deriving new geometric facts from previously-known facts by using logical reasoning. In elementary school, many geometric facts are introduced by folding, cutting, or measuring exercises, not by logical deduction.
Review Questions. The following quiz contains 25 questions that consist of multiple choice, fill-in-the-blank, matching and pattern match types. If you wish to take a shorter quiz, please select 'Quick Quiz' from the navigation bar. Please wait for the page to fully load before you begin to answer the questions! This activity contains 25 questions.
Inductive & Deductive Reasoning in Geometry: Definition
Watch this video lesson, and you will learn how important inductive and deductive reasoning is in the field of mathematics, especially when dealing with proofs in geometry.
Geometry Cheat Sheet - Math Salamanders
Here you will find our free geometry cheat sheet selection. These sheets tells you all you need to know about basic geometry formula for a range of 2d and 3d geometric shapes by the Math Salamanders.
Related searches for deductive geometry year 10
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https://multimedia.onlinejacc.org/articles/figure/Figure_3_Models_for_Computing_vFFR/8254640/1
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math
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Figure 3: Models for Computing vFFR
2019-06-11T07:04:45Z (GMT) by
The imaging and pressure input data for both novel models are those collected during routine coronary angiography (image data in yellow and aortic pressure data in green). The parameters of CMV physiology must be estimated (red). The type of simulation used to calculate vFFR values are shown in the blue boxes. vFFRps-trns is a function of 9 parameters, whereas vFFRsteady is a function of 4. Pseudotransient flow can be reconstructed using a 1D flow model representing the 3D vessel geometry coupled to the 0-dimensional Windkessel model. C = compliance; CMV = coronary microvasculature; R = resistance; vFFR = virtual fractional flow reserve; Z = impedance.
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http://vivo.med.cornell.edu/display/pubid0003032992
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math
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Assessing the effects of multiple rows on the condition number of a matrix
Protein Kinase Inhibitors
Receptor, Epidermal Growth Factor
Given a matrix X of n observations on k variables, it is known that the singular values of X can change substantially when few rows are omitted from X. Hadi (1988) shows that no general closed-form equation can relate the singular values of X to the singular values of X with one row deleted and gives closed-form approximations to the relationship between the singular values of the two matrices. In this article, we extend Hadi’s results to the more general case of multiple-row deletion, carry out systematic numerical investigations to determine the goodness and the speed of the approximation, and give an example using real-life data to illustrate the usefulness of the results in diagnosing jointly influential observations in linear regression. The methods presented in this article deal with the computational as well as the data analytic aspects of problems arising in multivariate data analysis. These methods are applicable in situations where the eigenstructure of a matrix is of interest. © 1990 Taylor & Francis Group, LLC.
Digital Object Identifier (DOI)
Additional Document Info
has global citation frequency
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