prefix stringlengths 0 918k | middle stringlengths 0 812k | suffix stringlengths 0 962k |
|---|---|---|
//You are given a 2 dimensional data, as a nested arrays,
// which is similar to matrix, however, unlike matrices,
// each row may contain a different number of columns.
// Given lst, and integer x, find integers x in the array,
// and return array of arrays, [(x1, y1), (x2, y2) ...] such that
// each array is a coordi... | if (lst[i][j] === x){ | coordinates.push([i, j]);
}
}
}
return coordinates.sort(function(a, b){
return a[0] - b[0] || b[1] - a[1];
});
}
|
import java.util.*;
import java.lang.reflect.*;
import org.javatuples.*;
import java.security.*;
import java.math.*;
import java.io.*;
import java.util.stream.*;
class Problem {
// You have been tasked to write a function that receives
// a hexadecimal number as a string and counts the number of hexadecimal
... | } | |
from typing import List
def by_length(arr: List[int]) -> List[str]:
"""
Given an array of integers, sort the integers that are between 1 and 9 inclusive,
reverse the resulting array, and then replace each digit by its corresponding name from
"One", "Two", "Three", "Four", "Five", "Six", "Seven", "Eight... | digits.sort() | digits.reverse()
for i in range(len(digits)):
digits[i] = ['One', 'Two', 'Three', 'Four', 'Five', 'Six', 'Seven', 'Eight', 'Nine'][digits[i] - 1]
return digits
|
def anti_shuffle(s: str) -> str:
"""
Write a function that takes a string and returns an ordered version of it.
Ordered version of string, is a string where all words (separated by space)
are replaced by a new word where all the characters arranged in
ascending order based on ascii value.
Note: ... | return ' '.join(shuffled_words) | |
import java.util.*;
import java.lang.reflect.*;
import org.javatuples.*;
import java.security.*;
import java.math.*;
import java.io.*;
import java.util.stream.*;
class Problem {
// Return array list of prime factors of given integer in the order from smallest to largest.
// Each of the factors should be array l... | while (n % d == 0) { | factors.add(d);
n /= d;
}
}
if (n > 1)
factors.add(n);
return factors;
}
} |
from typing import List
def max_element(l: List[int]) -> int:
"""Return maximum element in the list.
>>> max_element([1, 2, 3])
3
>>> max_element([5, 3, -5, 2, -3, 3, 9, 0, 123, 1, -10])
123
"""
max_elem = l[0]
for i in range(1, len(l)): | if l[i] > max_elem: | max_elem = l[i]
return max_elem
|
//For a given string, flip lowercase characters to uppercase and uppercase to lowercase.
// >>> flip_case("Hello")
// "hELLO"
function flip_case(string){
var result = "";
for(var i = 0; i < string.length; i++){
if(string[i] == string[i].toUpperCase()){
result += string[i].toLowerCase();
}else{ | result += string[i].toUpperCase(); | }
}
return result;
}
|
//You'll be given a string of words, and your task is to count the number
// of boredoms. A boredom is a sentence that starts with the word "I".
// Sentences are delimited by '.', '?' or '!'.
// For example:
// >>> is_bored("Hello world")
// 0
// >>> is_bored("The sky is blue. The sun is shining. I love this weather")
... | } | |
//For a given number n, find the largest number that divides n evenly, smaller than n
// >>> largest_divisor(15)
// 5
function largest_divisor(n){
let ld = 0; | for(i=1; i<n; i++){ | if(n%i===0){
if(i>ld){
ld = i;
}
}
}
return ld;
} |
//Write a function that accepts an array of strings.
// The array contains different words. Return the word with maximum number
// of unique characters. If multiple strings have maximum number of unique
// characters, return the one which comes first in lexicographical order.
// >>> find_max(["name", "of", "string"])
/... | var max_unique = {}; | var max_unique_word = "";
for(var i = 0; i < words.length; i++){
var unique_word = {};
var word = words[i];
for(var j = 0; j < word.length; j++){
var char = word[j];
if(unique_word[char] === undefined){
unique_word[char] = 1;
}
... |
//prime_fib returns n-th number that is a Fibonacci number and it's also prime.
// >>> prime_fib(1)
// 2
// >>> prime_fib(2)
// 3
// >>> prime_fib(3)
// 5
// >>> prime_fib(4)
// 13
// >>> prime_fib(5)
// 89
function prime_fib(n){
function isPrime(number){
if(number <= 3){
return number > 1;
... | return b; | }
var res = 0;
var fibNum = 0;
while(res < n){
if(isPrime(fib(fibNum))){
res++;
}
fibNum++;
}
return fib(fibNum - 1);
} |
from typing import Union
def compare_one(a: Union[int, float, str], b: Union[int, float, str]) -> Union[int, float, str, None]:
"""
Create a function that takes integers, floats, or strings representing
real numbers, and returns the larger variable in its given variable type.
Return None if the values ... | return b | else:
return None
elif isinstance(a, str) and isinstance(b, int):
a_tmp = a.replace(',', '.')
if float(a_tmp) > b:
return a
elif float(a_tmp) < b:
return b
else:
return None
elif isinstance(a, int) and isinstance(b, str):
... |
//For a given string, flip lowercase characters to uppercase and uppercase to lowercase.
// >>> flip_case("Hello")
// "hELLO"
function flip_case(string){
| var result = ""; | for(var i = 0; i < string.length; i++){
if(string[i] == string[i].toUpperCase()){
result += string[i].toLowerCase();
}else{
result += string[i].toUpperCase();
}
}
return result;
}
|
from typing import List
def separate_paren_groups(paren_string: str) -> List[str]:
""" Input to this function is a string containing multiple groups of nested parentheses. Your goal is to
separate those group into separate strings and return the list of those.
Separate groups are balanced (each open brace ... | if open_count == 0: | groups.append(group)
group = ''
return groups
|
import java.util.*;
import java.lang.reflect.*;
import org.javatuples.*;
import java.security.*;
import java.math.*;
import java.io.*;
import java.util.stream.*;
class Problem {
// Given an array array list of positive integers x. return a sorted array list of all
// elements that hasn't any even digit.
//... | ArrayList<Long> b = new ArrayList<Long>(); | for (int i = 0; i < x.size(); i++) {
if (x.get(i) < 0) {
x.set(i, x.get(i)*(long)-1);
}
boolean unique = true;
long z = x.get(i);
while (z > 0) {
long y = z % 10;
if (y % 2 == 0) {
uni... |
import java.util.*;
import java.lang.reflect.*;
import org.javatuples.*;
import java.security.*;
import java.math.*;
import java.io.*;
import java.util.stream.*;
class Problem {
// You are given a string s.
// if s[i] is a letter, reverse its case from lower to upper or vise versa,
// otherwise keep it as ... | } | if (letterNotFound) {
return sb.reverse().toString();
}
return sb.toString();
}
} |
import java.util.*;
import java.lang.reflect.*;
import org.javatuples.*;
import java.security.*;
import java.math.*;
import java.io.*;
import java.util.stream.*;
class Problem {
// Create a function that returns true if the last character
// of a given string is an alphabetical character and is not
// a par... | if (len == 1) { | return true;
}
if (txt.substring(len - 2, len - 1).matches(" ")) {
return true;
}
}
return false;
}
} |
import java.util.*;
import java.lang.reflect.*;
import org.javatuples.*;
import java.security.*;
import java.math.*;
import java.io.*;
import java.util.stream.*;
class Problem {
// I think we all remember that feeling when the result of some long-awaited
// event is finally known. The feelings and thoughts you ... | } | }
return result;
}
} |
//We have an array 'arr' of N integers arr[1], arr[2], ..., arr[N].The
// numbers in the array will be randomly ordered. Your task is to determine if
// it is possible to get an array sorted in non-decreasing order by performing
// the following operation on the given array:
// You are allowed to perform right shift o... | } | }
if(diff_count > 1){
return false;
}
else{
return true;
}
} |
//You are given a word. Your task is to find the closest vowel that stands between
// two consonants from the right side of the word (case sensitive).
// Vowels in the beginning and ending doesn't count. Return empty string if you didn't
// find any vowel met the above condition.
// You may assume that the given stri... | } | } |
//You'll be given a string of words, and your task is to count the number
// of boredoms. A boredom is a sentence that starts with the word "I".
// Sentences are delimited by '.', '?' or '!'.
// For example:
// >>> is_bored("Hello world")
// 0
// >>> is_bored("The sky is blue. The sun is shining. I love this weather")
... | let boredoms = 0; | for (let line of lines){
if(line.match(/^\s*I /)){
boredoms++;
}
}
return boredoms;
}
|
def count_upper(s: str) -> int:
"""
Given a string s, count the number of uppercase vowels in even indices.
For example:
>>> count_upper('aBCdEf')
1
>>> count_upper('abcdefg')
0
>>> count_upper('dBBE')
0
"""
vowel_set = set('AEIOU')
count = 0 | for i in range(0, len(s), 2): | if s[i] in vowel_set:
count += 1
return count
"""
D.1 Recursion
Given a positive integer n, write a recursive function that returns the sum of the squares of the
positive odd integers smaller than n. Assume n is greater than or equal to 3.
""" |
//Given two arrays operator, and operand. The first array has basic algebra operations, and
// the second array is an array of integers. Use the two given arrays to build the algebric
// expression and return the evaluation of this expression.
// The basic algebra operations:
// Addition ( + )
// Subtraction ( - )
... | operator.splice(0, 1); | }
return answer;
}
|
from typing import List, Optional
def next_smallest(lst: List[int]) -> Optional[int]:
"""
You are given a list of integers.
Write a function next_smallest() that returns the 2nd smallest element of the list.
Return None if there is no such element.
>>> next_smallest([1, 2, 3, 4, 5])
2
>>> n... | min2 = min1 | min1 = lst[i]
elif lst[i] < min2:
min2 = lst[i]
return min2 if min1 != min2 else None
|
//Circular shift the digits of the integer x, shift the digits right by shift
// and return the result as a string.
// If shift > number of digits, return digits reversed.
// >>> circular_shift(12, 1)
// "21"
// >>> circular_shift(12, 2)
// "12"
function circular_shift(x, shift){
var str = x.toString(); | var len = str.length; | var res = '';
if(len < shift){
for(var i = len-1; i >= 0; i--){
res += str[i];
}
}else{
res = str.substring(len-shift) + str.substring(0, len-shift);
}
return res;
}
|
import java.util.*;
import java.lang.reflect.*;
import org.javatuples.*;
import java.security.*;
import java.math.*;
import java.io.*;
import java.util.stream.*;
class Problem {
// Create a function encrypt that takes a string as an argument and
// returns a string encrypted with the alphabet being rotated.
... | } | } |
//You are given a rectangular grid of wells. Each row represents a single well,
// and each 1 in a row represents a single unit of water.
// Each well has a corresponding bucket that can be used to extract water from it,
// and all buckets have the same capacity.
// Your task is to use the buckets to empty the wells.
... | var r = grid.length; | var c = grid[0].length;
for(var i = 0; i < r; i++){
sum = 0;
for(var j = 0; j < c; j++){
sum += grid[i][j];
}
maxFill += Math.ceil(sum/capacity);
}
return maxFill;
}
|
//Evaluate whether the given number n can be written as the sum of exactly 4 positive even numbers
// Example
// >>> is_equal_to_sum_even(4)
// false
// >>> is_equal_to_sum_even(6)
// false
// >>> is_equal_to_sum_even(8)
// true
function is_equal_to_sum_even(n){
let m =0;
for(let i=2;i<n;i+=2){
for(let ... | } | else{
return false;
}
} |
//Write a function that takes a message, and encodes in such a
// way that it swaps case of all letters, replaces all vowels in
// the message with the letter that appears 2 places ahead of that
// vowel in the english alphabet.
// Assume only letters.
// Examples:
// >>> encode("test")
// "TGST"
// >>> encode("Th... | return result; | } |
import java.util.*;
import java.lang.reflect.*;
import org.javatuples.*;
import java.security.*;
import java.math.*;
import java.io.*;
import java.util.stream.*;
class Problem {
// You will be given the name of a class (a string) and an array array list of extensions.
// The extensions are to be used to load ad... | String strongest = ""; | for (String s : extensions) {
int cap = (int)s.chars().filter(c -> Character.isUpperCase(c)).count();
int sm = (int)s.chars().filter(c -> Character.isLowerCase(c)).count();
int diff = cap - sm;
if (diff > strength) {
strength = diff;
... |
//Return the number of times the digit 7 appears in integers less than n which are divisible by 11 or 13.
// >>> fizz_buzz(50)
// 0
// >>> fizz_buzz(78)
// 2
// >>> fizz_buzz(79)
// 3
function fizz_buzz(n){
let result = 0;
for(let i = 0; i < n; i++){
if(i % 11 === 0 || i % 13 === 0){
let arr... | for(let j = 0; j < arr.length; j++){ | if(arr[j] === '7'){
result++;
}
}
}
}
return result;
}
|
import java.util.*;
import java.lang.reflect.*;
import org.javatuples.*;
import java.security.*;
import java.math.*;
import java.io.*;
import java.util.stream.*;
class Problem {
// The Brazilian factorial is defined as:
// brazilian_factorial(n) = n! * (n-1)! * (n-2)! * ... * 1!
// where n > 0
// For ex... | while (n > 0) { | long local_result = 1;
long temp = n;
while (temp > 0) {
local_result *= temp;
temp--;
}
result *= local_result;
n--;
}
return result;
}
} |
import java.util.*;
import java.lang.reflect.*;
import org.javatuples.*;
import java.security.*;
import java.math.*;
import java.io.*;
import java.util.stream.*;
class Problem {
// Given a positive integer, obtain its roman numeral equivalent as a string,
// and return it in lowercase.
// Restrictions: 1 <=... | return ""; | while (num >= 1000) {
res += "m";
num -= 1000;
}
if (num >= 900) {
res += "cm";
num -= 900;
}
if (num >= 500) {
res += "d";
num -= 500;
}
if (num >= 400) {
res += "cd";
... |
from typing import Tuple
def even_odd_count(num: int) -> Tuple[int, int]:
"""Given an integer. return a tuple that has the number of even and odd digits respectively.
Example:
>>> even_odd_count(-12)
(1, 1)
>>> even_odd_count(123)
(1, 2)
"""
num_str = str(abs(num))
even_count = 0
... | if digit % 2 == 0: | even_count += 1
else:
odd_count += 1
return even_count, odd_count
|
import java.util.*;
import java.lang.reflect.*;
import org.javatuples.*;
import java.security.*;
import java.math.*;
import java.io.*;
import java.util.stream.*;
class Problem {
// You will be given the name of a class (a string) and an array array list of extensions.
// The extensions are to be used to load ad... | } | |
//Given a positive integer n, return an array that has the number of even and odd
// integer palindromes that fall within the range(1, n), inclusive.
// Example 1:
// >>> even_odd_palindrome(3)
// [1, 2]
// Explanation:
// Integer palindrome are 1, 2, 3. one of them is even, and two of them are odd.
// Example 2:
// >>... | var odd = 0; | var even = 0;
for(var i = 0; i < pal.length; i++){
if(pal[i] % 2 == 0){
even++;
}
else{
odd++;
}
}
return [even, odd];
} |
import java.util.*;
import java.lang.reflect.*;
import org.javatuples.*;
import java.security.*;
import java.math.*;
import java.io.*;
import java.util.stream.*;
class Problem {
// Evaluate whether the given number n can be written as the sum of exactly 4 positive even numbers
// Example
// >>> isEqualToSum... | if (2 * x + y < n) { | minX = x + 1;
} else if (2 * x + y > n) {
maxX = x - 1;
} else {
return true;
}
}
return false;
}
} |
from typing import List
def maximum(arr: List[int], k: int) -> List[int]:
"""
Given an array arr of integers and a positive integer k, return a sorted list
of length k with the maximum k numbers in arr.
Example 1:
>>> maximum([-3, -4, 5], 3)
[-4, -3, 5]
Example 2:
>>> maximum([4, -... | return [max_num] + get_max(arr, k - 1) |
return sorted(get_max(arr, k))
|
//prime_fib returns n-th number that is a Fibonacci number and it's also prime.
// >>> prime_fib(1)
// 2
// >>> prime_fib(2)
// 3
// >>> prime_fib(3)
// 5
// >>> prime_fib(4)
// 13
// >>> prime_fib(5)
// 89
function prime_fib(n){
function isPrime(number){
if(number <= 3){
return number > 1;
... | var res = 0; | var fibNum = 0;
while(res < n){
if(isPrime(fib(fibNum))){
res++;
}
fibNum++;
}
return fib(fibNum - 1);
} |
//Implement the function f that takes n as a parameter,
// and returns an array of size n, such that the value of the element at index i is the factorial of i if i is even
// or the sum of numbers from 1 to i otherwise.
// i starts from 1.
// the factorial of i is the multiplication of the numbers from 1 to i (1 * 2 * ... | factorial *= j; | }
result.push(factorial);
factorial = 1;
}else{
for(var k = 1; k <= i; k++){
sum += k;
}
result.push(sum);
sum = 0;
}
}
return result;
} |
//You are given an array of two strings, both strings consist of open
// parentheses '(' or close parentheses ')' only.
// Your job is to check if it is possible to concatenate the two strings in
// some order, that the resulting string will be good.
// A string S is considered to be good if and only if all parentheses... | const close = ')'; | const is_good = (s) => {
let stack = [];
for (let p of s){
if (p === open){
stack.push(p);
} else if (p === close){
if (stack.length === 0){
return false;
}
stack.pop();
}
}
return stack.length === 0;
};
const str1 = lst[0];
const str2 = lst[1];
if (is_good(str1 + str2)){
re... |
def is_palindrome(text: str) -> bool:
"""
Checks if given string is a palindrome
>>> is_palindrome('')
True
>>> is_palindrome('aba')
True
>>> is_palindrome('aaaaa')
True
>>> is_palindrome('zbcd')
False
"""
| length = len(text) | for i in range(length):
if text[i] != text[-i - 1]:
return False
return True
|
import java.util.*;
import java.lang.reflect.*;
import org.javatuples.*;
import java.security.*;
import java.math.*;
import java.io.*;
import java.util.stream.*;
class Problem {
// You are given 2 words. You need to return true if the second word or any of its rotations is a substring in the first word
// >>> c... | boolean found = false; | for (int i = 0; i < len; i++) {
b = b.substring(1) + b.charAt(0);
found = a.contains(b);
if (found) break;
}
return found;
}
} |
//Given an array of numbers, return whether or not they are sorted
// in ascending order. If array has more than 1 duplicate of the same
// number, return false. Assume no negative numbers and only integers.
// Examples
// >>> is_sorted([5])
// true
// >>> is_sorted([1, 2, 3, 4, 5])
// true
// >>> is_sorted([1, 3, 2, 4... | return true; | }
|
//brackets is a string of "(" and ")".
// return true if every opening bracket has a corresponding closing bracket.
// >>> correct_bracketing("(")
// false
// >>> correct_bracketing("()")
// true
// >>> correct_bracketing("(()())")
// true
// >>> correct_bracketing(")(()")
// false
function correct_bracketing(brackets)... | } | }
}
if (opens.length == 0){
return true;
}
else {
return false;
}
} |
import java.util.*;
import java.lang.reflect.*;
import org.javatuples.*;
import java.security.*;
import java.math.*;
import java.io.*;
import java.util.stream.*;
class Problem {
// Input to this function is a string containing multiple groups of nested parentheses. Your goal is to
// separate those group into s... | return output; | }
} |
from typing import List, Tuple
def find_closest_elements(numbers: List[float]) -> Tuple[float, float]:
""" From a supplied list of numbers (of length at least two) select and return two that are the closest to each
other and return them in order (smaller number, larger number).
>>> find_closest_elements([1... | if abs(numbers[i] - numbers[j]) < temp: | temp = abs(numbers[i] - numbers[j])
temp_index = i
temp2_index = j
elif abs(numbers[i] - numbers[j]) == temp:
if numbers[i] > numbers[j]:
temp = abs(numbers[i] - numbers[j])
temp_index = i
... |
//Return true if a given number is prime, and false otherwise.
// >>> is_prime(6)
// false
// >>> is_prime(101)
// true
// >>> is_prime(11)
// true
// >>> is_prime(13441)
// true
// >>> is_prime(61)
// true
// >>> is_prime(4)
// false
// >>> is_prime(1)
// false
function is_prime(n){
if (n==1) {
return fals... | var limit = Math.sqrt(n); | for (var i = 3; i <= limit; i += 2) {
if (n%i==0) {
return false;
}
}
return true;
}
|
import java.util.*;
import java.lang.reflect.*;
import org.javatuples.*;
import java.security.*;
import java.math.*;
import java.io.*;
import java.util.stream.*;
class Problem {
// Given a positive integer, obtain its roman numeral equivalent as a string,
// and return it in lowercase.
// Restrictions: 1 <=... | if (num >= 900) { | res += "cm";
num -= 900;
}
if (num >= 500) {
res += "d";
num -= 500;
}
if (num >= 400) {
res += "cd";
num -= 400;
}
while (num >= 100) {
res += "c";
num -= 100;
}
... |
//Given an object, return true if all keys are strings in lower
// case or all keys are strings in upper case, else return false.
// The function should return false is the given object is empty.
// Examples:
// >>> check_dict_case({"a": "apple", "b": "banana"})
// true
// >>> check_dict_case({"a": "apple", "A": "bana... | else if (case_type == 0){ | if (key != key.toLowerCase()){
return false;
}
}
}
else{
return false;
}
}
return true;
} |
from typing import List
def minPath(grid: List[List[int]], k: int) -> List[int]:
"""
Given a grid with N rows and N columns (N >= 2) and a positive integer k,
each cell of the grid contains a value. Every integer in the range [1, N * N]
inclusive appears exactly once on the cells of the grid.
You... | for i, j in (row - 1, col), (row + 1, col), (row, col - 1), (row, col + 1): | if 0 <= i < len(grid) and 0 <= j < len(grid[0]) and grid[i][j] < min_val:
min_val = grid[i][j]
row = i
col = j
path.append(min_val)
return path |
from typing import List
def by_length(arr: List[int]) -> List[str]:
"""
Given an array of integers, sort the integers that are between 1 and 9 inclusive,
reverse the resulting array, and then replace each digit by its corresponding name from
"One", "Two", "Three", "Four", "Five", "Six", "Seven", "Eight... | return digits | |
//"
// This function will take an array of integers. For all entries in the array, the function shall square the integer entry if its index is a
// multiple of 3 and will cube the integer entry if its index is a multiple of 4 and not a multiple of 3. The function will not
// change the entries in the array whose inde... | var len = lst.length; | for (var i = 0; i < len; i++){
if (i % 3 == 0){
sum += lst[i]*lst[i];
} else if (i % 4 == 0){
sum += lst[i]*lst[i]*lst[i];
} else {
sum += lst[i];
}
}
return sum;
} |
//Task
// We are given two strings s and c, you have to deleted all the characters in s that are equal to any character in c
// then check if the result string is palindrome.
// A string is called palindrome if it reads the same backward as forward.
// You should return an array containing the result string and true/fa... | } | return result;
} |
//Given a string s, count the number of uppercase vowels in even indices.
// For example:
// >>> count_upper("aBCdEf")
// 1
// >>> count_upper("abcdefg")
// 0
// >>> count_upper("dBBE")
// 0
function count_upper(s){
var index;
var result = 0;
var vowel = ['A', 'E', 'I', 'O', 'U'];
for (index = 0; index ... | } | |
//Create a function that takes integers, floats, or strings representing
// real numbers, and returns the larger variable in its given variable type.
// Return undefined if the values are equal.
// Note: If a real number is represented as a string, the floating point might be . or ,
// >>> compare_one(1, 2.5)
// 2.5
//... | return a; | } else if (a < b[0]){
return b;
} else {
return undefined;
}
}
}
|
import java.util.*;
import java.lang.reflect.*;
import org.javatuples.*;
import java.security.*;
import java.math.*;
import java.io.*;
import java.util.stream.*;
class Problem {
// Write a function that accepts an array array list of strings.
// The array list contains different words. Return the word with maxi... | } | } |
def correct_bracketing(brackets: str) -> bool:
""" brackets is a string of "(" and ")".
return True if every opening bracket has a corresponding closing bracket.
>>> correct_bracketing('(')
False
>>> correct_bracketing('()')
True
>>> correct_bracketing('(()())')
True
>>> correct_bra... | count -= 1 | if count < 0:
return False
return count == 0
|
import java.util.*;
import java.lang.reflect.*;
import org.javatuples.*;
import java.security.*;
import java.math.*;
import java.io.*;
import java.util.stream.*;
class Problem {
// pairs_sum_to_zero takes an array array list of integers as an input.
// it returns true if there are two distinct elements in the a... | return true; | }
}
}
return false;
}
} |
from typing import Union
def compare_one(a: Union[int, float, str], b: Union[int, float, str]) -> Union[int, float, str, None]:
"""
Create a function that takes integers, floats, or strings representing
real numbers, and returns the larger variable in its given variable type.
Return None if the values ... | if float(a_tmp) > b: | return a
elif float(a_tmp) < b:
return b
else:
return None
elif isinstance(a, int) and isinstance(b, str):
b_tmp = b.replace(',', '.')
if a > float(b_tmp):
return a
elif a < float(b_tmp):
return b
else:
... |
//There are eight planets in our solar system: the closerst to the Sun
// is Mercury, the next one is Venus, then Earth, Mars, Jupiter, Saturn,
// Uranus, Neptune.
// Write a function that takes two planet names as strings planet1 and planet2.
// The function should return an array containing all planets whose orbit... | var temp = position1; | position1 = position2;
position2 = temp;
}
var res = [];
for(var i = position1 + 1; i < position2; i++){
res.push(keys[i]);
}
return res;
} |
import java.util.*;
import java.lang.reflect.*;
import org.javatuples.*;
import java.security.*;
import java.math.*;
import java.io.*;
import java.util.stream.*;
class Problem {
// Given a positive integer, obtain its roman numeral equivalent as a string,
// and return it in lowercase.
// Restrictions: 1 <=... | res += "xc"; | num -= 90;
}
if (num >= 50) {
res += "l";
num -= 50;
}
if (num >= 40) {
res += "xl";
num -= 40;
}
while (num >= 10) {
res += "x";
num -= 10;
}
if (num >= 9) {
r... |
//Input to this function is a string representing musical notes in a special ASCII format.
// Your task is to parse this string and return array of integers corresponding to how many beats does each
// not last.
// Here is a legend:
// 'o' - whole note, lasts four beats
// 'o|' - half note, lasts two beats
// '.|' - qu... | if(s === 'o'){ | song.push(4);
}else if(s === 'o|'){
song.push(2);
}else if(s === '.|'){
song.push(1);
}
});
return song;
}
|
//Return the number of times the digit 7 appears in integers less than n which are divisible by 11 or 13.
// >>> fizz_buzz(50)
// 0
// >>> fizz_buzz(78)
// 2
// >>> fizz_buzz(79)
// 3
function fizz_buzz(n){
let result = 0;
for(let i = 0; i < n; i++){
if(i % 11 === 0 || i % 13 === 0){
let arr... | return result; | }
|
import java.util.*;
import java.lang.reflect.*;
import org.javatuples.*;
import java.security.*;
import java.math.*;
import java.io.*;
import java.util.stream.*;
class Problem {
// Given two array lists operator, and operand. The first array list has basic algebra operations, and
// the second array list is an... | else if (op.get(i).equals("*")) | list.set(list.size() - 1, list.get(list.size() - 1) * operand.get(i + 1));
else if (op.get(i).equals("//"))
list.set(list.size() - 1, list.get(list.size() - 1) / operand.get(i + 1));
else if (op.get(i).equals("**"))
list.set(list.size() - 1, (long)... |
//From a given array of integers, generate an array of rolling maximum element found until given moment
// in the sequence.
// >>> rolling_max([1, 2, 3, 2, 3, 4, 2])
// [1, 2, 3, 3, 3, 4, 4]
function rolling_max(numbers){
let max = [];
let tempMax = 0;
for(let i = 0; i < numbers.length; i++){
if(tem... | max.push(tempMax); | }
return max;
}
|
//triples_sum_to_zero takes an array of integers as an input.
// it returns true if there are three distinct elements in the array that
// sum to zero, and false otherwise.
// >>> triples_sum_to_zero([1, 3, 5, 0])
// false
// >>> triples_sum_to_zero([1, 3, -2, 1])
// true
// >>> triples_sum_to_zero([1, 2, 3, 7])
// fal... | } | }
}
return false;
}
|
import java.util.*;
import java.lang.reflect.*;
import org.javatuples.*;
import java.security.*;
import java.math.*;
import java.io.*;
import java.util.stream.*;
class Problem {
// The Fib4 number sequence is a sequence similar to the Fibbonacci sequnece that's defined as follows:
// fib4(0) -> 0
// fib4(1)... | } | } |
def is_multiply_prime(a: int) -> bool:
"""Write a function that returns true if the given number is the multiplication of 3 prime numbers
and false otherwise.
Knowing that (a) is less then 100.
Example:
>>> is_multiply_prime(30)
True
30 = 2 * 3 * 5
"""
| n = a | d = 2
prime_factors = []
while d * d <= n:
if n % d == 0:
prime_factors.append(d)
n //= d
else:
d += 1
if n > 1:
prime_factors.append(n)
if len(prime_factors) == 3:
return True
else:
return False
|
import java.util.*;
import java.lang.reflect.*;
import org.javatuples.*;
import java.security.*;
import java.math.*;
import java.io.*;
import java.util.stream.*;
class Problem {
// Create a function which takes a string representing a file's name, and returns
// 'Yes' if the the file's name is valid, and return... | String result = "No"; | String[] tokens = file_name.split("\\.");
if (tokens.length != 2) {
return result;
}
String extension = tokens[1];
if (!(extension.equals("txt") || extension.equals("exe") || extension.equals("dll"))) {
return result;
}
String name = tokens... |
import java.util.*;
import java.lang.reflect.*;
import org.javatuples.*;
import java.security.*;
import java.math.*;
import java.io.*;
import java.util.stream.*;
class Problem {
// "Given an array array list representing a branch of a tree that has non-negative integer nodes
// your task is to pluck one of the ... | return newArr; | }
} |
import java.util.*;
import java.lang.reflect.*;
import org.javatuples.*;
import java.security.*;
import java.math.*;
import java.io.*;
import java.util.stream.*;
class Problem {
// This function takes an array array list l and returns an array array list l' such that
// l' is identical to l in the odd indicies,... | ArrayList<Long> res = new ArrayList<Long>(); | ArrayList<Long> evenIndexed = new ArrayList<Long>();
int index = 0;
for (Long num : l) {
if (index % 2 == 0) {
evenIndexed.add(num);
}
index++;
}
Collections.sort(evenIndexed);
index = 0;
for (Long num : l) {
... |
//Write a function that accepts an array of strings.
// The array contains different words. Return the word with maximum number
// of unique characters. If multiple strings have maximum number of unique
// characters, return the one which comes first in lexicographical order.
// >>> find_max(["name", "of", "string"])
/... | } | else if(Object.keys(unique_word).length > Object.keys(max_unique).length){
max_unique_word = word;
max_unique = unique_word;
}
else if(Object.keys(unique_word).length === Object.keys(max_unique).length){
if(word < max_unique_word){
max_unique_w... |
//Write a function that accepts two arrays of strings and returns the array that has
// total number of chars in the all strings of the array less than the other array.
// if the two arrays have the same number of chars, return the first array.
// Examples
// >>> total_match([], [])
// []
// >>> total_match(["hi", "ad... | let sum_lst2 = 0; | for(let item of lst1){
sum_lst1 += item.length;
}
for(let item of lst2){
sum_lst2 += item.length;
}
if(sum_lst1 > sum_lst2){
return lst2;
}
else{
return lst1;
}
}
|
import java.util.*;
import java.lang.reflect.*;
import org.javatuples.*;
import java.security.*;
import java.math.*;
import java.io.*;
import java.util.stream.*;
class Problem {
// Given a string representing a space separated lowercase letters, return a hash map
// of the letter with the most repetition and co... | } | }
}
return s;
}
} |
from typing import Union
def compare_one(a: Union[int, float, str], b: Union[int, float, str]) -> Union[int, float, str, None]:
"""
Create a function that takes integers, floats, or strings representing
real numbers, and returns the larger variable in its given variable type.
Return None if the values ... | else: | return None
elif isinstance(a, str) and isinstance(b, int):
a_tmp = a.replace(',', '.')
if float(a_tmp) > b:
return a
elif float(a_tmp) < b:
return b
else:
return None
elif isinstance(a, int) and isinstance(b, str):
b_tmp = ... |
//Return array with elements incremented by 1.
// >>> incr_list([1, 2, 3])
// [2, 3, 4]
// >>> incr_list([5, 3, 5, 2, 3, 3, 9, 0, 123])
// [6, 4, 6, 3, 4, 4, 10, 1, 124]
function incr_list(l){
var new_list = [];
for(var i = 0; i < l.length; i++){
new_list.push(l[i] + 1);
}
return new_list; | } | |
//Given an object, return true if all keys are strings in lower
// case or all keys are strings in upper case, else return false.
// The function should return false is the given object is empty.
// Examples:
// >>> check_dict_case({"a": "apple", "b": "banana"})
// true
// >>> check_dict_case({"a": "apple", "A": "bana... | } | }
}
else{
return false;
}
}
return true;
} |
//Write a function vowels_count which takes a string representing
// a word as input and returns the number of vowels in the string.
// Vowels in this case are 'a', 'e', 'i', 'o', 'u'. Here, 'y' is also a
// vowel, but only when it is at the end of the given word.
// Example:
// >>> vowels_count("abcde")
// 2
// >>> vo... | if(s[s.length-1]=='y'){ | count++;
}
return count;
}
|
//"
// This function will take an array of integers. For all entries in the array, the function shall square the integer entry if its index is a
// multiple of 3 and will cube the integer entry if its index is a multiple of 4 and not a multiple of 3. The function will not
// change the entries in the array whose inde... | return sum; | } |
from typing import List
def pluck(arr: List[int]) -> List[int]:
"""
"Given an array representing a branch of a tree that has non-negative integer nodes
your task is to pluck one of the nodes and return it.
The plucked node should be the node with the smallest even value.
If multiple nodes with the ... | return [min(evens), arr.index(min(evens))] | |
//Given a string representing a space separated lowercase letters, return an object
// of the letter with the most repetition and containing the corresponding count.
// If several letters have the same occurrence, return all of them.
// Example:
// >>> histogram("a b c")
// {"a": 1, "b": 1, "c": 1}
// >>> histogram("a ... | for (var i = 0; i < lst.length; i++){ | if (count[lst[i]]){
count[lst[i]] += 1;
}
else{
count[lst[i]] = 1;
}
}
console.log(count);
var max = 0;
var result = {};
for (var key in count){
if (count[key] > max){
max = count[key];
result = {};
result[key] = max;
}
else if (count[key] === max){
... |
//xs represent coefficients of a polynomial.
// xs[0] + xs[1] * x + xs[2] * x^2 + ....
// Return derivative of this polynomial in the same form.
// >>> derivative([3, 1, 2, 4, 5])
// [1, 4, 12, 20]
// >>> derivative([1, 2, 3])
// [2, 6]
function derivative(xs){
let coeff = [];
for(let i = 1; i < xs.length; i++)... | return coeff; | }
|
from typing import List
def strange_sort_list(lst: List[int]) -> List[int]:
"""
Given list of integers, return list in strange order.
Strange sorting, is when you start with the minimum value,
then maximum of the remaining integers, then minimum and so on.
Examples:
>>> strange_sort_list([1, 2... | if not lst: | break
out.append(lst.pop())
return out |
import java.util.*;
import java.lang.reflect.*;
import org.javatuples.*;
import java.security.*;
import java.math.*;
import java.io.*;
import java.util.stream.*;
class Problem {
// Create a function that returns true if the last character
// of a given string is an alphabetical character and is not
// a par... | return false; | }
int len = txt.length();
if (txt.substring(len - 1, len).matches("[A-Z]") || txt.substring(len - 1, len).matches("[a-z]")) {
if (len == 1) {
return true;
}
if (txt.substring(len - 2, len - 1).matches(" ")) {
return true;
... |
import java.util.*;
import java.lang.reflect.*;
import org.javatuples.*;
import java.security.*;
import java.math.*;
import java.io.*;
import java.util.stream.*;
class Problem {
// Imagine a road that's a perfectly straight infinitely long line.
// n cars are driving left to right; simultaneously, a different ... | return nSquared.longValue(); | }
} |
//Given a grid with N rows and N columns (N >= 2) and a positive integer k,
// each cell of the grid contains a value. Every integer in the range [1, N * N]
// inclusive appears exactly once on the cells of the grid.
// You have to find the minimum path of length k in the grid. You can start
// from any cell, and in e... | if(curr < startCell){ | startCell = curr;
}
}
}
let currCell = startCell;
for(let l = 0; l < k; l++){
path.push(currCell);
let neighbours = [];
let x = null;
let y = null;
for(let i = 0; i < n; i++){
for(let j = 0; j < n; j++){
... |
import java.util.*;
import java.lang.reflect.*;
import org.javatuples.*;
import java.security.*;
import java.math.*;
import java.io.*;
import java.util.stream.*;
class Problem {
// For a given number n, find the largest number that divides n evenly, smaller than n
// >>> largestDivisor((15l))
// (5l)
pu... | } | } |
def make_palindrome(string: str) -> str:
""" Find the shortest palindrome that begins with a supplied string.
Algorithm idea is simple:
- Find the longest postfix of supplied string that is a palindrome.
- Append to the end of the string reverse of a string prefix that comes before the palindromic suffi... | return string | |
from typing import List
def pluck(arr: List[int]) -> List[int]:
"""
"Given an array representing a branch of a tree that has non-negative integer nodes
your task is to pluck one of the nodes and return it.
The plucked node should be the node with the smallest even value.
If multiple nodes with the ... | return [] | evens = [e for e in arr if e % 2 == 0]
if len(evens) == 0:
return []
return [min(evens), arr.index(min(evens))]
|
import java.util.*;
import java.lang.reflect.*;
import org.javatuples.*;
import java.security.*;
import java.math.*;
import java.io.*;
import java.util.stream.*;
class Problem {
// Return 2^n modulo p (be aware of numerics).
// >>> modp((3l), (5l))
// (3l)
// >>> modp((1101l), (101l))
// (2l)
//... | } | return (sqrt * 2) % p;
}
} |
import java.util.*;
import java.lang.reflect.*;
import org.javatuples.*;
import java.security.*;
import java.math.*;
import java.io.*;
import java.util.stream.*;
class Problem {
// Your task is to implement a function that will simplify the expression
// x * n. The function returns true if x * n evaluates to a ... | int n_num = Integer.parseInt(n_nums[0]); | int x_denom = Integer.parseInt(nums[1]);
int n_denom = Integer.parseInt(n_nums[1]);
int res_num = x_num * n_num;
int res_denom = x_denom * n_denom;
return (res_num % res_denom == 0);
}
} |
import java.util.*;
import java.lang.reflect.*;
import org.javatuples.*;
import java.security.*;
import java.math.*;
import java.io.*;
import java.util.stream.*;
class Problem {
// "
// This function will take an array array list of integers. For all entries in the array list, the function shall square the inte... | } | }
long ans = 0;
for (int i = 0; i < sz; i++) {
ans += lst.get(i);
}
return ans;
}
} |
def x_or_y(n: int, x: int, y: int) -> int:
"""A simple program which should return the value of x if n is
a prime number and should return the value of y otherwise.
Examples:
>>> x_or_y(7, 34, 12)
34
>>> x_or_y(15, 8, 5)
5
"""
| if n < 2: | return y
for i in range(2, n):
if n % i == 0:
return y
return x
|
//Given a grid with N rows and N columns (N >= 2) and a positive integer k,
// each cell of the grid contains a value. Every integer in the range [1, N * N]
// inclusive appears exactly once on the cells of the grid.
// You have to find the minimum path of length k in the grid. You can start
// from any cell, and in e... | x = i; | y = j;
}
}
}
if(x > 0){
neighbours.push(grid[x - 1][y]);
}
if(x < n - 1){
neighbours.push(grid[x + 1][y]);
}
if(y > 0){
neighbours.push(grid[x][y - 1]);
}
if(y < n - 1){
... |
import java.util.*;
import java.lang.reflect.*;
import org.javatuples.*;
import java.security.*;
import java.math.*;
import java.io.*;
import java.util.stream.*;
class Problem {
// Return a greatest common divisor of two integers a and b
// >>> greatestCommonDivisor((3l), (5l))
// (1l)
// >>> greatestCo... | return a; | }
return greatestCommonDivisor(b, a % b);
}
} |
def prime_length(string: str) -> bool:
"""Write a function that takes a string and returns True if the string
length is a prime number or False otherwise
Examples
>>> prime_length('Hello')
True
>>> prime_length('abcdcba')
True
>>> prime_length('kittens')
True
>>> prime_length('or... | for i in range(2, num): | if (num % i) == 0:
return False
else:
return True
else:
return False
pass
|
//Input to this function is a string represented multiple groups for nested parentheses separated by spaces.
// For each of the group, output the deepest level of nesting of parentheses.
// E.g. (()()) has maximum two levels of nesting while ((())) has three.
// >>> parse_nested_parens("(()()) ((())) () ((())()())")
//... | result.push(maxlevel); | maxlevel = 0;
level = 0;
}
}
result.push(maxlevel);
return result;
}
|
import java.util.*;
import java.lang.reflect.*;
import org.javatuples.*;
import java.security.*;
import java.math.*;
import java.io.*;
import java.util.stream.*;
class Problem {
// Input to this function is a string representing musical notes in a special ASCII format.
// Your task is to parse this string and r... | char[] chars = music_string.toCharArray(); | for (int i = 0; i < chars.length; i++) {
if (chars[i] == 'o') {
if (i + 1 < chars.length && chars[i + 1] == '|') {
res.add((long)2l);
i += 1;
} else {
res.add((long)4l);
}
} else i... |
import java.util.*;
import java.lang.reflect.*;
import org.javatuples.*;
import java.security.*;
import java.math.*;
import java.io.*;
import java.util.stream.*;
class Problem {
// "
// This function will take an array array list of integers. For all entries in the array list, the function shall square the inte... | lst.set(i, lst.get(i) * lst.get(i) * lst.get(i)); | }
}
long ans = 0;
for (int i = 0; i < sz; i++) {
ans += lst.get(i);
}
return ans;
}
} |
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