prefix stringlengths 0 918k | middle stringlengths 0 812k | suffix stringlengths 0 962k |
|---|---|---|
def correct_bracketing(brackets: str) -> bool:
""" brackets is a string of "(" and ")".
return True if every opening bracket has a corresponding closing bracket.
>>> correct_bracketing('(')
False
>>> correct_bracketing('()')
True
>>> correct_bracketing('(()())')
True
>>> correct_bra... | if char == '(': | count += 1
elif char == ')':
count -= 1
if count < 0:
return False
return count == 0
|
//Filter given array of any jsthon values only for integers
// >>> filter_integers(["a", 3.14, 5])
// [5]
// >>> filter_integers([1, 2, 3, "abc", {}, []])
// [1, 2, 3]
function filter_integers(values){
var result = [];
values.forEach(function(value){
if(typeof value === "number" && value % 1 === 0){
result.push(... | return result; | }
|
import java.util.*;
import java.lang.reflect.*;
import org.javatuples.*;
import java.security.*;
import java.math.*;
import java.io.*;
import java.util.stream.*;
class Problem {
// You are given a non-empty array list of positive integers. Return the greatest integer that is greater than
// zero, and has a fre... | Long max = (long)-1; | for (int i = 0; i < lst.size(); i++) {
long val = lst.get(i);
if (map.containsKey(val)) {
map.put(val, map.get(val) + 1);
} else {
map.put(val, (long)1);
}
if (map.get(val) >= val && val > max) {
max = va... |
//Given an array of numbers, return the sum of squares of the numbers
// in the array that are odd. Ignore numbers that are negative or not integers.
// >>> double_the_difference([1, 3, 2, 0])
// 10
// >>> double_the_difference([-1, -2, 0])
// 0
// >>> double_the_difference([9, -2])
// 81
// >>> double_the_difference([... | } | }
return sum;
}
|
import java.util.*;
import java.lang.reflect.*;
import org.javatuples.*;
import java.security.*;
import java.math.*;
import java.io.*;
import java.util.stream.*;
class Problem {
// Evaluate whether the given number n can be written as the sum of exactly 4 positive even numbers
// Example
// >>> isEqualToSum... | } | long minX = d;
long maxX = n / 4;
while (minX <= maxX) {
long x = (minX + maxX) / 2;
long y = n - 2 * x;
if (y % 2 == 1) {
y--;
}
if (2 * x + y < n) {
minX = x + 1;
} else if (2 * x + y > n) {... |
import java.util.*;
import java.lang.reflect.*;
import org.javatuples.*;
import java.security.*;
import java.math.*;
import java.io.*;
import java.util.stream.*;
class Problem {
// This function takes two positive numbers x and y and returns the
// biggest even integer number that is in the range [x, y] inclusi... | chosen = i; | }
}
return chosen;
}
} |
//Input to this function is a string containing multiple groups of nested parentheses. Your goal is to
// separate those group into separate strings and return the array of those.
// Separate groups are balanced (each open brace is properly closed) and not nested within each other
// Ignore any spaces in the input stri... | for (var i = 0; i < paren_string.length; i++){ | if (paren_string[i] === '('){
count++;
group += paren_string[i];
} else if (paren_string[i] === ')'){
count--;
group += paren_string[i];
}
if (count === 0 && group){
groups.push(group);
group = '';
}
}
... |
//Implement a function that takes an non-negative integer and returns an array of the first n
// integers that are prime numbers and less than n.
// for example:
// >>> count_up_to(5)
// [2, 3]
// >>> count_up_to(11)
// [2, 3, 5, 7]
// >>> count_up_to(0)
// []
// >>> count_up_to(20)
// [2, 3, 5, 7, 11, 13, 17, 19]
// >... | } | if (prime) output.push(i);
}
return output;
}
|
from typing import List
def get_positive(l: List[int]) -> List[int]:
"""Return only positive numbers in the list.
>>> get_positive([-1, 2, -4, 5, 6])
[2, 5, 6]
>>> get_positive([5, 3, -5, 2, -3, 3, 9, 0, 123, 1, -10])
[5, 3, 2, 3, 9, 123, 1]
"""
p = [] | for i in l: | if i > 0:
p.append(i)
return p
|
//For a given array of integers, return an array consisting of a sum and a product of all the integers in an array.
// Empty sum should be equal to 0 and empty product should be equal to 1.
// >>> sum_product([])
// [0, 1]
// >>> sum_product([1, 2, 3, 4])
// [10, 24]
function sum_product(numbers){
| if(numbers.length == 0){ | return [0, 1];
}
let sum = 0;
let product = 1;
for(let i = 0; i < numbers.length; i++){
sum += numbers[i];
product *= numbers[i];
}
return [sum, product];
}
|
//There are eight planets in our solar system: the closerst to the Sun
// is Mercury, the next one is Venus, then Earth, Mars, Jupiter, Saturn,
// Uranus, Neptune.
// Write a function that takes two planet names as strings planet1 and planet2.
// The function should return an array containing all planets whose orbit... | 'Neptune':8 | }
if(!planets[planet1] || !planets[planet2]){
return [];
}
var keys = Object.keys(planets);
var position1 = keys.indexOf(planet1);
var position2 = keys.indexOf(planet2);
if(position1 > position2){
var temp = position1;
position1 = position2;
position2 = temp;
... |
//You are given an array of two strings, both strings consist of open
// parentheses '(' or close parentheses ')' only.
// Your job is to check if it is possible to concatenate the two strings in
// some order, that the resulting string will be good.
// A string S is considered to be good if and only if all parentheses... | const str1 = lst[0]; | const str2 = lst[1];
if (is_good(str1 + str2)){
return 'Yes';
}
if (is_good(str2 + str1)){
return 'Yes';
}
return 'No';
} |
//Find how many times a given substring can be found in the original string. Count overlaping cases.
// >>> how_many_times("", "a")
// 0
// >>> how_many_times("aaa", "a")
// 3
// >>> how_many_times("aaaa", "aa")
// 3
function how_many_times(string, substring){
var i = 0;
var count = 0;
while(string.indexOf(substring... | } | |
import java.util.*;
import java.lang.reflect.*;
import org.javatuples.*;
import java.security.*;
import java.math.*;
import java.io.*;
import java.util.stream.*;
class Problem {
// Task
// Write a function that takes a string as input and returns the sum of the upper characters only'
// ASCII codes.
// ... | } | } |
//From a supplied array of numbers (of length at least two) select and return two that are the closest to each
// other and return them in order (smaller number, larger number).
// >>> find_closest_elements([1.0, 2.0, 3.0, 4.0, 5.0, 2.2])
// [2.0, 2.2]
// >>> find_closest_elements([1.0, 2.0, 3.0, 4.0, 5.0, 2.0])
// [2.... | let b = numbers[1]; | for (let i = 0; i < numbers.length; i++) {
for (let j = i + 1; j < numbers.length; j++) {
if (Math.abs(numbers[i] - numbers[j]) < closest) {
closest = Math.abs(numbers[i] - numbers[j]);
a = numbers[i];
b = numbers[j];
}
}
}
return a > b ? [b, a] : [a, b];
}
|
//Given a grid with N rows and N columns (N >= 2) and a positive integer k,
// each cell of the grid contains a value. Every integer in the range [1, N * N]
// inclusive appears exactly once on the cells of the grid.
// You have to find the minimum path of length k in the grid. You can start
// from any cell, and in e... | let startCell = grid[0][0]; | for(let i = 0; i < n; i++){
for(let j = 0; j < n; j++){
let curr = grid[i][j];
if(curr < startCell){
startCell = curr;
}
}
}
let currCell = startCell;
for(let l = 0; l < k; l++){
path.push(currCell);
let neighbours = [];... |
import java.util.*;
import java.lang.reflect.*;
import org.javatuples.*;
import java.security.*;
import java.math.*;
import java.io.*;
import java.util.stream.*;
class Problem {
// The FibFib number sequence is a sequence similar to the Fibbonacci sequnece that's defined as follows:
// fibfib(0) == 0
// fib... | memo[i] = memo[i - 1] + memo[i - 2] + memo[i - 3]; | }
return memo[(int) n];
}
} |
//You are given a string representing a sentence,
// the sentence contains some words separated by a space,
// and you have to return a string that contains the words from the original sentence,
// whose lengths are prime numbers,
// the order of the words in the new string should be the same as the original one.
// Ex... | return isPrime; | }).join(' ');
} |
import java.util.*;
import java.lang.reflect.*;
import org.javatuples.*;
import java.security.*;
import java.math.*;
import java.io.*;
import java.util.stream.*;
class Problem {
// Input to this function is a string represented multiple groups for nested parentheses separated by spaces.
// For each of the group... | } | } |
import java.util.*;
import java.lang.reflect.*;
import org.javatuples.*;
import java.security.*;
import java.math.*;
import java.io.*;
import java.util.stream.*;
class Problem {
// Write a function vowels_count which takes a string representing
// a word as input and returns the number of vowels in the string.
... | sum++; | }
}
return sum;
}
} |
from typing import List, Any
def filter_integers(values: List[Any]) -> List[int]:
""" Filter given list of any python values only for integers
>>> filter_integers(['a', 3.14, 5])
[5]
>>> filter_integers([1, 2, 3, 'abc', { }, []])
[1, 2, 3]
"""
| return [n for n in values if isinstance(n, int)] | |
from typing import List
def sort_even(l: List[int]) -> List[int]:
"""This function takes a list l and returns a list l' such that
l' is identical to l in the odd indicies, while its values at the even indicies are equal
to the values of the even indicies of l, but sorted.
>>> sort_even([1, 2, 3])
[... | temp.append(l[i]) | temp.sort()
for i in range(0, len(l), 2):
l[i] = temp[i // 2]
return l |
//Given a string representing a space separated lowercase letters, return an object
// of the letter with the most repetition and containing the corresponding count.
// If several letters have the same occurrence, return all of them.
// Example:
// >>> histogram("a b c")
// {"a": 1, "b": 1, "c": 1}
// >>> histogram("a ... | result[key] = max; | }
else if (count[key] === max){
result[key] = max;
}
}
return result;
}
|
import java.util.*;
import java.lang.reflect.*;
import org.javatuples.*;
import java.security.*;
import java.math.*;
import java.io.*;
import java.util.stream.*;
class Problem {
// Given a positive integer n, return the count of the numbers of n-digit
// positive integers that start or end with 1.
public st... | for (long i = lower; i <= upper; i++) { | String s = "" + i;
if (s.startsWith("1") || s.endsWith("1"))
count++;
}
return count;
}
} |
//Create a function which returns the largest index of an element which
// is not greater than or equal to the element immediately preceding it. If
// no such element exists then return -1. The given array will not contain
// duplicate values.
// Examples:
// >>> can_arrange([1, 2, 4, 3, 5])
// 3
// >>> can_arrange([1,... | res = i; | }else{
max = arr[i];
}
}
return res;
}
|
from typing import List
def sort_array(array: List[int]) -> List[int]:
"""
Given an array of non-negative integers, return a copy of the given array after sorting,
you will sort the given array in ascending order if the sum( first index value, last index value) is odd,
or sort it in descending order if... | return sorted(array, reverse=True) if (array[0] + array[-1]) % 2 == 0 else sorted(array) | return array |
//For a given array of input numbers, calculate Mean Absolute Deviation
// around the mean of this dataset.
// Mean Absolute Deviation is the average absolute difference between each
// element and a centerpoint (mean in this case):
// MAD = average | x - x_mean |
// >>> mean_absolute_deviation([1.0, 2.0, 3.0, 4.0])
//... | return sum_abs_diff / numbers.length; | }
|
from typing import List
def minSubArraySum(nums: List[int]) -> int:
"""
Given an array of integers nums, find the minimum sum of any non-empty sub-array
of nums.
Example
>>> minSubArraySum([2, 3, 4, 1, 2, 4])
1
>>> minSubArraySum([-1, -2, -3])
-6
"""
for i in range(1, len(nums))... | nums[i] = min(nums[i], nums[i] + nums[i - 1]) | return min(nums)
|
//Given an array of integers, sort the integers that are between 1 and 9 inclusive,
// reverse the resulting array, and then replace each digit by its corresponding name from
// "One", "Two", "Three", "Four", "Five", "Six", "Seven", "Eight", "Nine".
// For example:
// >>> by_length([2, 1, 1, 4, 5, 8, 2, 3])
// ["Eight"... | arr3.push("Eight"); | }
else if(num == 9){
arr3.push("Nine");
}
}
return arr3;
} |
//Write a function count_nums which takes an array of integers and returns
// the number of elements which has a sum of digits > 0.
// If a number is negative, then its first signed digit will be negative:
// e.g. -123 has signed digits -1, 2, and 3.
// >>> count_nums([])
// 0
// >>> count_nums([-1, 11, -11])
// 1
// >... | } | return count;
} |
//It is the last week of the semester and the teacher has to give the grades
// to students. The teacher has been making her own algorithm for grading.
// The only problem is, she has lost the code she used for grading.
// She has given you an array of GPAs for some students and you have to write
// a function that ca... | } | else if (grades[i] > 2.0){
grades_array.push("C+");
}
else if (grades[i] > 1.7){
grades_array.push("C");
}
else if (grades[i] > 1.3){
grades_array.push("C-");
}
else if (grades[i] > 1.0){
grades_array.push("D+");
... |
import java.util.*;
import java.lang.reflect.*;
import org.javatuples.*;
import java.security.*;
import java.math.*;
import java.io.*;
import java.util.stream.*;
class Problem {
// Check if two words have the same characters.
// >>> sameChars(("eabcdzzzz"), ("dddzzzzzzzddeddabc"))
// (true)
// >>> sameC... | } | } |
//Return true if a given number is prime, and false otherwise.
// >>> is_prime(6)
// false
// >>> is_prime(101)
// true
// >>> is_prime(11)
// true
// >>> is_prime(13441)
// true
// >>> is_prime(61)
// true
// >>> is_prime(4)
// false
// >>> is_prime(1)
// false
function is_prime(n){
if (n==1) {
return fals... | } |
if (n%2==0) {
return false;
}
var limit = Math.sqrt(n);
for (var i = 3; i <= limit; i += 2) {
if (n%i==0) {
return false;
}
}
return true;
}
|
import java.util.*;
import java.lang.reflect.*;
import org.javatuples.*;
import java.security.*;
import java.math.*;
import java.io.*;
import java.util.stream.*;
class Problem {
// Write a function that accepts an array array list of strings.
// The array list contains different words. Return the word with maxi... | for (String word : words) { | Set<Character> uniqueCharacters = new HashSet<Character>();
for (char c : word.toCharArray()) {
uniqueCharacters.add(c);
}
wordsToUniqueCharacters.put(word, uniqueCharacters.size());
}
words.sort(new Comparator<String>() {
@Over... |
//Filter an input array of strings only for ones that contain given substring
// >>> filter_by_substring([], "a")
// []
// >>> filter_by_substring(["abc", "bacd", "cde", "array"], "a")
// ["abc", "bacd", "array"]
function filter_by_substring(strings, substring){
var filtered = [];
for(var i = 0; i < strings.len... | if(strings[i].includes(substring)){ | filtered.push(strings[i]);
}
}
return filtered;
} |
//Given the lengths of the three sides of a triangle. Return true if the three
// sides form a right-angled triangle, false otherwise.
// A right-angled triangle is a triangle in which one angle is right angle or
// 90 degree.
// Example:
// >>> right_angle_triangle(3, 4, 5)
// true
// >>> right_angle_triangle(1, 2, 3... | } else { | return false;
}
}
|
import java.util.*;
import java.lang.reflect.*;
import org.javatuples.*;
import java.security.*;
import java.math.*;
import java.io.*;
import java.util.stream.*;
class Problem {
// Given an array array list of integers, sort the integers that are between 1 and 9 inclusive,
// reverse the resulting array array l... | } | } |
//Given an array of non-negative integers, return a cojs of the given array after sorting,
// you will sort the given array in ascending order if the sum( first index value, last index value) is odd,
// or sort it in descending order if the sum( first index value, last index value) is even.
// Note:
// * don't change t... | if(sum % 2 === 0){ | newArr = array.sort(function(a, b){return b - a;});
}else{
newArr = array.sort(function(a, b){return a - b;});
}
return newArr;
} |
//Given a positive integer n, return a sorted array that has the odd numbers in collatz sequence.
// The Collatz conjecture is a conjecture in mathematics that concerns a sequence defined
// as follows: start with any positive integer n. Then each term is obtained from the
// previous term as follows: if the previous ... | for(var i = 0; i < collatz_sequence.length; i++){ | if(collatz_sequence[i]%2 == 0){
collatz_sequence.push(collatz_sequence[i]/2)
}
else if(collatz_sequence[i]%2 == 1){
collatz_sequence.push(collatz_sequence[i]*3+1)
}
if(collatz_sequence[i]%2 == 1){
odd_numbers.push(collatz_sequence[i])
... |
import java.util.*;
import java.lang.reflect.*;
import org.javatuples.*;
import java.security.*;
import java.math.*;
import java.io.*;
import java.util.stream.*;
class Problem {
// Input to this function is a string containing multiple groups of nested parentheses. Your goal is to
// separate those group into s... | temp.append(c); | } else if (c == ')') {
open_paren--;
temp.append(c);
if (open_paren == 0) {
output.add(temp.toString());
}
}
}
return output;
}
} |
//Input is a space-delimited string of numberals from 'zero' to 'nine'.
// Valid choices are 'zero', 'one', 'two', 'three', 'four', 'five', 'six', 'seven', 'eight' and 'nine'.
// Return the string with numbers sorted from smallest to largest
// >>> sort_numbers("three one five")
// "one three five"
function sort_number... | "eight": 8, | "nine": 9
};
numString.sort(function(a, b){
return numMap[a] - numMap[b];
});
numString = numString.join(" ");
return numString;
} |
import java.util.*;
import java.lang.reflect.*;
import org.javatuples.*;
import java.security.*;
import java.math.*;
import java.io.*;
import java.util.stream.*;
class Problem {
// Insert a number 'delimeter' between every two consecutive elements of input array list `numbers'
// >>> intersperse((new ArrayList<... | } | }
return result;
}
} |
//Given a positive integer n, return a sorted array that has the odd numbers in collatz sequence.
// The Collatz conjecture is a conjecture in mathematics that concerns a sequence defined
// as follows: start with any positive integer n. Then each term is obtained from the
// previous term as follows: if the previous ... | else if(collatz_sequence[i]%2 == 1){ | collatz_sequence.push(collatz_sequence[i]*3+1)
}
if(collatz_sequence[i]%2 == 1){
odd_numbers.push(collatz_sequence[i])
odd_count += 1
}
if(collatz_sequence[i] == 1){
break
}
}
if(odd_count != 0){
odd_numbers.sort(fun... |
//You are given an array of integers.
// Write a function next_smallest() that returns the 2nd smallest element of the array.
// Return undefined if there is no such element.
// >>> next_smallest([1, 2, 3, 4, 5])
// 2
// >>> next_smallest([5, 1, 4, 3, 2])
// 2
// >>> next_smallest([])
// undefined
// >>> next_smallest(... | } | var smallest=Math.min(...lst);
var second_smallest=Number.MAX_VALUE;
for(var i in lst){
if(lst[i]>smallest&&lst[i]<second_smallest){
second_smallest=lst[i];
}
}
if(second_smallest==Number.MAX_VALUE){
return undefined;
}
return second_smallest;
} |
//Given two arrays operator, and operand. The first array has basic algebra operations, and
// the second array is an array of integers. Use the two given arrays to build the algebric
// expression and return the evaluation of this expression.
// The basic algebra operations:
// Addition ( + )
// Subtraction ( - )
... | return answer; | }
|
import java.util.*;
import java.lang.reflect.*;
import org.javatuples.*;
import java.security.*;
import java.math.*;
import java.io.*;
import java.util.stream.*;
class Problem {
// Implement the function f that takes n as a parameter,
// and returns an array array list of size n, such that the value of the elem... | } else { | v = (i * (i + 1l)) / 2l;
}
ret.add(v);
}
return ret;
}
} |
import java.util.*;
import java.lang.reflect.*;
import org.javatuples.*;
import java.security.*;
import java.math.*;
import java.io.*;
import java.util.stream.*;
class Problem {
// Given an array array list of positive integers x. return a sorted array list of all
// elements that hasn't any even digit.
//... | Collections.sort(b); | return b;
}
} |
//You have to write a function which validates a given date string and
// returns true if the date is valid otherwise false.
// The date is valid if all of the following rules are satisfied:
// 1. The date string is not empty.
// 2. The number of days is not less than 1 or higher than 31 days for months 1,3,5,7,8,10,12... | } | return true;
}
return false;
}
|
//Write a function that takes an integer a and returns true
// if this ingeger is a cube of some integer number.
// Note: you may assume the input is always valid.
// Examples:
// >>> iscube(1)
// true
// >>> iscube(2)
// false
// >>> iscube(-1)
// true
// >>> iscube(64)
// true
// >>> iscube(0)
// true
// >>> iscube(... | } | } |
//You are given 2 words. You need to return true if the second word or any of its rotations is a substring in the first word
// >>> cycpattern_check("abcd", "abd")
// false
// >>> cycpattern_check("hello", "ell")
// true
// >>> cycpattern_check("whassup", "psus")
// false
// >>> cycpattern_check("abab", "baa")
// true
... | result = result || a.includes(b); | b = b.slice(1) + b[0];
}
return result;
}
|
import java.util.*;
import java.lang.reflect.*;
import org.javatuples.*;
import java.security.*;
import java.math.*;
import java.io.*;
import java.util.stream.*;
class Problem {
// You are given a string s.
// if s[i] is a letter, reverse its case from lower to upper or vise versa,
// otherwise keep it as ... | if (Character.isLetter(s.charAt(i))) { | letterNotFound = false;
if (Character.isUpperCase(s.charAt(i))) {
sb.append(Character.toLowerCase(s.charAt(i)));
} else {
sb.append(Character.toUpperCase(s.charAt(i)));
}
} else {
sb.appen... |
from typing import List
def triples_sum_to_zero(l: List[int]) -> bool:
"""
triples_sum_to_zero takes a list of integers as an input.
it returns True if there are three distinct elements in the list that
sum to zero, and False otherwise.
>>> triples_sum_to_zero([1, 3, 5, 0])
False
>>> tripl... | assert len(l) > 0, "The input list cannot be empty" | l.sort()
for i in range(len(l)):
for j in range(i + 1, len(l)):
for k in range(j + 1, len(l)):
if l[i] + l[j] + l[k] == 0:
return True
return False
|
//Return array of all prefixes from shortest to longest of the input string
// >>> all_prefixes("abc")
// ["a", "ab", "abc"]
function all_prefixes(string){
var result = [];
for (var i = 1; i <= string.length; i++){
result.push(string.slice(0, i));
} | return result; | }
|
//Implement the function f that takes n as a parameter,
// and returns an array of size n, such that the value of the element at index i is the factorial of i if i is even
// or the sum of numbers from 1 to i otherwise.
// i starts from 1.
// the factorial of i is the multiplication of the numbers from 1 to i (1 * 2 * ... | } | result.push(sum);
sum = 0;
}
}
return result;
} |
from typing import List
def separate_paren_groups(paren_string: str) -> List[str]:
""" Input to this function is a string containing multiple groups of nested parentheses. Your goal is to
separate those group into separate strings and return the list of those.
Separate groups are balanced (each open brace ... | group = '' | open_count = 0
for c in paren_string:
if c == '(':
open_count += 1
elif c == ')':
open_count -= 1
group += c
if open_count == 0:
groups.append(group)
group = ''
return groups
|
import java.util.*;
import java.lang.reflect.*;
import org.javatuples.*;
import java.security.*;
import java.math.*;
import java.io.*;
import java.util.stream.*;
class Problem {
// Input to this function is a string containing multiple groups of nested parentheses. Your goal is to
// separate those group into s... | if (open_paren == 0) { | output.add(temp.toString());
}
}
}
return output;
}
} |
//We have an array 'arr' of N integers arr[1], arr[2], ..., arr[N].The
// numbers in the array will be randomly ordered. Your task is to determine if
// it is possible to get an array sorted in non-decreasing order by performing
// the following operation on the given array:
// You are allowed to perform right shift o... | } | else{
return true;
}
} |
//Given an array of strings, where each string consists of only digits, return an array.
// Each element i of the output should be "the number of odd elements in the
// string i of the input." where all the i's should be replaced by the number
// of odd digits in the i'th string of the input.
// >>> odd_count(["1234567... | for (var i = 0; i < lst.length; i++){ | var word = lst[i];
var odd_sum = 0;
for (var j = 0; j < word.length; j++){
if (word[j] % 2 == 1){
odd_sum += 1;
}
}
var odd_word = "the number of odd elements " + odd_sum + "n the str" + odd_sum + "ng " + odd_sum + " of the " + odd_sum + "n... |
import java.util.*;
import java.lang.reflect.*;
import org.javatuples.*;
import java.security.*;
import java.math.*;
import java.io.*;
import java.util.stream.*;
class Problem {
// Implement a function that takes an non-negative integer and returns an array array list of the first n
// integers that are prime n... | if (isPrime) { | arrayList.add(i);
}
}
return arrayList;
}
} |
//Given an array of integers, sort the integers that are between 1 and 9 inclusive,
// reverse the resulting array, and then replace each digit by its corresponding name from
// "One", "Two", "Three", "Four", "Five", "Six", "Seven", "Eight", "Nine".
// For example:
// >>> by_length([2, 1, 1, 4, 5, 8, 2, 3])
// ["Eight"... | var arr2 = []; | for(var i = 0; i < arr.length; i++){
var num = arr[i];
if(num > 0 && num < 10){
arr2.push(num);
}
}
arr2.sort();
arr2.reverse();
var arr3 = [];
for(var i = 0; i < arr2.length; i++){
var num = arr2[i];
if(num == 1){
arr3.push("One");... |
//It is the last week of the semester and the teacher has to give the grades
// to students. The teacher has been making her own algorithm for grading.
// The only problem is, she has lost the code she used for grading.
// She has given you an array of GPAs for some students and you have to write
// a function that ca... | } | else if (grades[i] > 1.7){
grades_array.push("C");
}
else if (grades[i] > 1.3){
grades_array.push("C-");
}
else if (grades[i] > 1.0){
grades_array.push("D+");
}
else if (grades[i] > 0.7){
grades_array.push("D");
... |
from typing import List
def add_elements(arr: List[int], k: int) -> int:
"""
Given a non-empty array of integers arr and an integer k, return
the sum of the elements with at most two digits from the first k elements of arr.
Example:
>>> add_elements([111, 21, 3, 4000, 5, 6, 7, 8, 9], 4)
24
... | total += num | return total
|
//Given an array of numbers, return the sum of squares of the numbers
// in the array that are odd. Ignore numbers that are negative or not integers.
// >>> double_the_difference([1, 3, 2, 0])
// 10
// >>> double_the_difference([-1, -2, 0])
// 0
// >>> double_the_difference([9, -2])
// 81
// >>> double_the_difference([... | } | return sum;
}
|
//Write a function that takes a string and returns an ordered version of it.
// Ordered version of string, is a string where all words (separated by space)
// are replaced by a new word where all the characters arranged in
// ascending order based on ascii value.
// Note: You should keep the order of words and blank sp... | strings.forEach(function(str){ | var temp = str.split("");
temp.sort();
result.push(temp.join(""));
});
return result.join(" ");
} |
import java.util.*;
import java.lang.reflect.*;
import org.javatuples.*;
import java.security.*;
import java.math.*;
import java.io.*;
import java.util.stream.*;
class Problem {
// Given array list of integers, return array list in strange order.
// Strange sorting, is when you start with the minimum value,
... | min++; | if (min <= max) {
result.add(sorted.get(max));
max--;
}
}
return result;
}
} |
from typing import List
def rescale_to_unit(numbers: List[float]) -> List[float]:
""" Given list of numbers (of at least two elements), apply a linear transform to that list,
such that the smallest number will become 0 and the largest will become 1
>>> rescale_to_unit([1.0, 2.0, 3.0, 4.0, 5.0])
[0.0, 0... | return [(val - _min) / (_max - _min) for val in numbers] | |
//Insert a number 'delimeter' between every two consecutive elements of input array `numbers'
// >>> intersperse([], 4)
// []
// >>> intersperse([1, 2, 3], 4)
// [1, 4, 2, 4, 3]
function intersperse(numbers, delimeter){
var result = [];
for(var i = 0; i < numbers.length; i++){
result.push(numbers[i]);
if(i ... | } | |
import java.util.*;
import java.lang.reflect.*;
import org.javatuples.*;
import java.security.*;
import java.math.*;
import java.io.*;
import java.util.stream.*;
class Problem {
// Implement a function that takes an non-negative integer and returns an array array list of the first n
// integers that are prime n... | return arrayList; | }
} |
import java.util.*;
import java.lang.reflect.*;
import org.javatuples.*;
import java.security.*;
import java.math.*;
import java.io.*;
import java.util.stream.*;
class Problem {
// remove_vowels is a function that takes string and returns string without vowels.
// >>> removeVowels((""))
// ("")
// >>> r... | if (vowels.indexOf(text.charAt(i)) == -1) { | newText += text.charAt(i);
}
}
return newText;
}
} |
//This function takes two positive numbers x and y and returns the
// biggest even integer number that is in the range [x, y] inclusive. If
// there's no such number, then the function should return -1.
// For example:
// >>> choose_num(12, 15)
// 14
// >>> choose_num(13, 12)
// -1
function choose_num(x, y){
var num ... | return num; | }
|
def vowels_count(s: str) -> int:
"""Write a function vowels_count which takes a string representing
a word as input and returns the number of vowels in the string.
Vowels in this case are 'a', 'e', 'i', 'o', 'u'. Here, 'y' is also a
vowel, but only when it is at the end of the given word.
Example:
... | return count | |
//Write a function vowels_count which takes a string representing
// a word as input and returns the number of vowels in the string.
// Vowels in this case are 'a', 'e', 'i', 'o', 'u'. Here, 'y' is also a
// vowel, but only when it is at the end of the given word.
// Example:
// >>> vowels_count("abcde")
// 2
// >>> vo... | if(vowels.indexOf(s[i])!=-1){ | count++;
}
}
if(s[s.length-1]=='y'){
count++;
}
return count;
}
|
import java.util.*;
import java.lang.reflect.*;
import org.javatuples.*;
import java.security.*;
import java.math.*;
import java.io.*;
import java.util.stream.*;
class Problem {
// prime_fib returns n-th number that is a Fibonacci number and it's also prime.
// >>> primeFib((1l))
// (2l)
// >>> primeFib... | fib += prev; | prev = tmp;
if (BigInteger.valueOf(fib).isProbablePrime(1)) {
count++;
}
}
return fib;
}
} |
//You are given two intervals,
// where each interval is a pair of integers. For example, interval = (start, end) = (1, 2).
// The given intervals are closed which means that the interval (start, end)
// includes both start and end.
// For each given interval, it is assumed that its start is less or equal its end.
// Y... | let primes = [2, 3, 5, 7, 11, 13, 17, 19, 23, 29, 31, 37, 41, 43, 47, 53, 59, 61, 67, 71, 73, 79, 83, 89, 97]; | return primes.includes(length) ? "YES" : "NO";
}
|
import java.util.*;
import java.lang.reflect.*;
import org.javatuples.*;
import java.security.*;
import java.math.*;
import java.io.*;
import java.util.stream.*;
class Problem {
// For a given array list of input numbers, calculate Mean Absolute Deviation
// around the mean of this dataset.
// Mean Absolute... | return (float)numbers.stream().mapToDouble(n -> Math.abs(n - mean)).average().getAsDouble(); | }
} |
from typing import List
def sort_third(l: List[int]) -> List[int]:
"""This function takes a list l and returns a list l' such that
l' is identical to l in the indicies that are not divisible by three, while its values at the indicies that are divisible by three are equal
to the values of the corresponding ... | l[j], l[j + 3] = l[j + 3], l[j] | j -= 3
return l
|
from typing import List
def rolling_max(numbers: List[int]) -> List[int]:
""" From a given list of integers, generate a list of rolling maximum element found until given moment
in the sequence.
>>> rolling_max([1, 2, 3, 2, 3, 4, 2])
[1, 2, 3, 3, 3, 4, 4]
"""
| if len(numbers) == 0: | return []
else:
return [max(numbers[:i + 1]) for i in range(len(numbers))]
|
import java.util.*;
import java.lang.reflect.*;
import org.javatuples.*;
import java.security.*;
import java.math.*;
import java.io.*;
import java.util.stream.*;
class Problem {
// Input is a space-delimited string of numberals from 'zero' to 'nine'.
// Valid choices are 'zero', 'one', 'two', 'three', 'four', '... | } | String [] split = numbers.split(" ");
Arrays.sort(split, new Comparator<String>() {
@Override
public int compare(String s1, String s2) {
return indexMap.get(s1) - indexMap.get(s2);
}
});
return String.join(" ", split);
}
} |
//Given a positive integer N, return the total sum of its digits in binary.
// Example
// >>> solve(1000)
// "1"
// >>> solve(150)
// "110"
// >>> solve(147)
// "1100"
// Variables:
// @N integer
// Constraints: 0 ≤ N ≤ 10000.
// Output:
// a string of binary number
function solve(N){
| let newN = N.toString(); | let total = 0;
for(let i = 0; i < newN.length; i++){
let digit = newN[i];
total += parseInt(digit);
}
return total.toString(2);
} |
//Given a grid with N rows and N columns (N >= 2) and a positive integer k,
// each cell of the grid contains a value. Every integer in the range [1, N * N]
// inclusive appears exactly once on the cells of the grid.
// You have to find the minimum path of length k in the grid. You can start
// from any cell, and in e... | if(x < n - 1){ | neighbours.push(grid[x + 1][y]);
}
if(y > 0){
neighbours.push(grid[x][y - 1]);
}
if(y < n - 1){
neighbours.push(grid[x][y + 1]);
}
let nextCell = neighbours[0];
for(let i = 0; i < neighbours.length; i++){
let curr = ... |
import java.util.*;
import java.lang.reflect.*;
import org.javatuples.*;
import java.security.*;
import java.math.*;
import java.io.*;
import java.util.stream.*;
class Problem {
// Given an array array list arr of integers and a positive integer k, return a sorted array list
// of length k with the maximum k n... | return new ArrayList<Long>(arr.subList((int)(arr.size() - k), (int)(arr.size()))); | }
} |
//Given the lengths of the three sides of a triangle. Return true if the three
// sides form a right-angled triangle, false otherwise.
// A right-angled triangle is a triangle in which one angle is right angle or
// 90 degree.
// Example:
// >>> right_angle_triangle(3, 4, 5)
// true
// >>> right_angle_triangle(1, 2, 3... | } | |
from typing import List
def all_prefixes(string: str) -> List[str]:
""" Return list of all prefixes from shortest to longest of the input string
>>> all_prefixes('abc')
['a', 'ab', 'abc']
"""
| prefixes = [] | for i in range(len(string)):
prefixes.append(string[:i+1])
return prefixes
|
import java.util.*;
import java.lang.reflect.*;
import org.javatuples.*;
import java.security.*;
import java.math.*;
import java.io.*;
import java.util.stream.*;
class Problem {
// Given an array array list of numbers, return whether or not they are sorted
// in ascending order. If array list has more than 1 du... | int running_max = 0; | int previous_number = 0;
boolean first_time = true;
boolean seen_2_in_a_row = false;
for (Long number : lst) {
if (first_time) {
first_time = false;
previous_number = number.intValue();
running_ma... |
from typing import List
def triples_sum_to_zero(l: List[int]) -> bool:
"""
triples_sum_to_zero takes a list of integers as an input.
it returns True if there are three distinct elements in the list that
sum to zero, and False otherwise.
>>> triples_sum_to_zero([1, 3, 5, 0])
False
>>> tripl... | l.sort() | for i in range(len(l)):
for j in range(i + 1, len(l)):
for k in range(j + 1, len(l)):
if l[i] + l[j] + l[k] == 0:
return True
return False
|
from typing import List
def sort_array(array: List[int]) -> List[int]:
"""
Given an array of non-negative integers, return a copy of the given array after sorting,
you will sort the given array in ascending order if the sum( first index value, last index value) is odd,
or sort it in descending order if... | if array: | return sorted(array, reverse=True) if (array[0] + array[-1]) % 2 == 0 else sorted(array)
return array |
//Given two arrays operator, and operand. The first array has basic algebra operations, and
// the second array is an array of integers. Use the two given arrays to build the algebric
// expression and return the evaluation of this expression.
// The basic algebra operations:
// Addition ( + )
// Subtraction ( - )
... | operand.splice(count + 1, 1); | operator.splice(count, 1);
count = 0;
do_again = true;
break;
case '//':
operand[count] = Math.floor(operand[count] / operand[count + 1]);
operand.splice(count + 1, 1);
operator.splice(count, 1);
count = 0;
do_again = true;
break;
... |
import java.util.*;
import java.lang.reflect.*;
import org.javatuples.*;
import java.security.*;
import java.math.*;
import java.io.*;
import java.util.stream.*;
class Problem {
// Find the shortest palindrome that begins with a supplied string.
// Algorithm idea is simple:
// - Find the longest postfix of ... | String reverse = new StringBuilder(string).reverse().toString(); | for (int index = 0; index < string.length(); index++) {
if (string.substring(index).equals(reverse.substring(0, string.length() - index))) {
newString.append(reverse.substring(string.length() - index));
break;
}
}
return newString.toString(... |
import java.util.*;
import java.lang.reflect.*;
import org.javatuples.*;
import java.security.*;
import java.math.*;
import java.io.*;
import java.util.stream.*;
class Problem {
// Write a function that accepts an array array list of strings.
// The array list contains different words. Return the word with maxi... | Set<Character> uniqueCharacters = new HashSet<Character>(); | for (char c : word.toCharArray()) {
uniqueCharacters.add(c);
}
wordsToUniqueCharacters.put(word, uniqueCharacters.size());
}
words.sort(new Comparator<String>() {
@Override
public int compare(String o1, String o2) {
... |
import java.util.*;
import java.lang.reflect.*;
import org.javatuples.*;
import java.security.*;
import java.math.*;
import java.io.*;
import java.util.stream.*;
class Problem {
// Write a function that takes an array array list of numbers as input and returns
// the number of elements in the array array list ... | } | public long getLastDigit(long n) {
long[] digits = getDigits(n);
return digits[digits.length - 1];
}
public long[] getDigits(long n) {
ArrayList<Long> digits = new ArrayList<Long>();
while (n != 0) {
... |
import java.util.*;
import java.lang.reflect.*;
import org.javatuples.*;
import java.security.*;
import java.math.*;
import java.io.*;
import java.util.stream.*;
class Problem {
// Given an array array list of numbers, return whether or not they are sorted
// in ascending order. If array list has more than 1 du... | running_max = number.intValue(); | }
}
}
return true;
}
}
} |
from typing import List
def sort_array(arr: List[int]) -> List[int]:
"""
In this Kata, you have to sort an array of non-negative integers according to
number of ones in their binary representation in ascending order.
For similar number of ones, sort based on decimal value.
It must be implemented l... | return sorted(arr, key=lambda x: (bin(x).count('1'), x)) | |
import java.util.*;
import java.lang.reflect.*;
import org.javatuples.*;
import java.security.*;
import java.math.*;
import java.io.*;
import java.util.stream.*;
class Problem {
// There are eight planets in our solar system: the closerst to the Sun
// is Mercury, the next one is Venus, then Earth, Mars, Jupit... | indexMin = indexPlanet2; | indexMax = indexPlanet1;
}
ArrayList<String> planetsInBetween = new ArrayList<String>();
for (int i = indexMin + 1; i < indexMax; i++) {
planetsInBetween.add(planets.get(i));
}
return planetsInBetween;
} else {
... |
import java.util.*;
import java.lang.reflect.*;
import org.javatuples.*;
import java.security.*;
import java.math.*;
import java.io.*;
import java.util.stream.*;
class Problem {
// Given an array array list of integers nums, find the minimum sum of any non-empty sub-array array list
// of nums.
// Example
... | if (currSum < minSum) { | minSum = currSum;
}
for (int j = i + 1; j < nums.size(); j++) {
currSum += nums.get(j);
if (currSum < prevMinSum) {
prevMinSum = currSum;
}
if (currSum < minSum) {
minSum = cur... |
import java.util.*;
import java.lang.reflect.*;
import org.javatuples.*;
import java.security.*;
import java.math.*;
import java.io.*;
import java.util.stream.*;
class Problem {
// You are given a rectangular grid of wells. Each row represents a single well,
// and each 1 in a row represents a single unit of wa... | } | return count;
}
} |
import java.util.*;
import java.lang.reflect.*;
import org.javatuples.*;
import java.security.*;
import java.math.*;
import java.io.*;
import java.util.stream.*;
class Problem {
// Input to this function is a string containing multiple groups of nested parentheses. Your goal is to
// separate those group into s... | } | }
}
return output;
}
} |
import java.util.*;
import java.lang.reflect.*;
import org.javatuples.*;
import java.security.*;
import java.math.*;
import java.io.*;
import java.util.stream.*;
class Problem {
// Return a greatest common divisor of two integers a and b
// >>> greatestCommonDivisor((3l), (5l))
// (1l)
// >>> greatestCo... | } | |
import java.util.*;
import java.lang.reflect.*;
import org.javatuples.*;
import java.security.*;
import java.math.*;
import java.io.*;
import java.util.stream.*;
class Problem {
// There are eight planets in our solar system: the closerst to the Sun
// is Mercury, the next one is Venus, then Earth, Mars, Jupit... | for (int i = indexMin + 1; i < indexMax; i++) { | planetsInBetween.add(planets.get(i));
}
return planetsInBetween;
} else {
return new ArrayList<String>();
}
}
} |
import java.util.*;
import java.lang.reflect.*;
import org.javatuples.*;
import java.security.*;
import java.math.*;
import java.io.*;
import java.util.stream.*;
class Problem {
// Given a positive integer, obtain its roman numeral equivalent as a string,
// and return it in lowercase.
// Restrictions: 1 <=... | num -= 900; | }
if (num >= 500) {
res += "d";
num -= 500;
}
if (num >= 400) {
res += "cd";
num -= 400;
}
while (num >= 100) {
res += "c";
num -= 100;
}
if (num >= 90) {
res += "xc";
... |
import java.util.*;
import java.lang.reflect.*;
import org.javatuples.*;
import java.security.*;
import java.math.*;
import java.io.*;
import java.util.stream.*;
class Problem {
// Return the largest prime factor of n. Assume n > 1 and is not a prime.
// >>> largestPrimeFactor((13195l))
// (29l)
// >>> ... | x /= i; | i--;
}
}
if (x > 1) {
primes.add(x);
}
return primes.get(primes.size() - 1);
}
} |
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