prefix stringlengths 0 918k | middle stringlengths 0 812k | suffix stringlengths 0 962k |
|---|---|---|
//Change numerical base of input number x to base.
// return string representation after the conversion.
// base numbers are less than 10.
// >>> change_base(8, 3)
// "22"
// >>> change_base(8, 2)
// "1000"
// >>> change_base(7, 2)
// "111"
function change_base(x, base){
let r = x % base;
let q = Math.floor(x /... | if (q === 0) return r.toString(); | return change_base(q, base) + r.toString();
}
|
from typing import List
def maximum(arr: List[int], k: int) -> List[int]:
"""
Given an array arr of integers and a positive integer k, return a sorted list
of length k with the maximum k numbers in arr.
Example 1:
>>> maximum([-3, -4, 5], 3)
[-4, -3, 5]
Example 2:
>>> maximum([4, -... | """ | Returns the maximum k numbers in the given array
"""
if k == 0:
return []
elif k == 1:
return [max(arr)]
else:
max_num = max(arr)
arr.remove(max_num)
return [max_num] + get_max(arr, k - 1)
return sorted(get_max(arr,... |
import java.util.*;
import java.lang.reflect.*;
import org.javatuples.*;
import java.security.*;
import java.math.*;
import java.io.*;
import java.util.stream.*;
class Problem {
// Input to this function is a string representing musical notes in a special ASCII format.
// Your task is to parse this string and r... | } | }
}
return res;
}
} |
//Create a function that takes integers, floats, or strings representing
// real numbers, and returns the larger variable in its given variable type.
// Return undefined if the values are equal.
// Note: If a real number is represented as a string, the floating point might be . or ,
// >>> compare_one(1, 2.5)
// 2.5
//... | } | else if (typeof a === "string" && typeof b === "number"){
if (a[0] > b){
return a;
} else if (a[0] < b){
return b;
} else {
return undefined;
}
}
else if (typeof a === "number" && typeof b === "string"){
if (a > b[0]){
return a;
} else if (a < b[0]){
return b;... |
from typing import List
def move_one_ball(arr: List[int]) -> bool:
"""We have an array 'arr' of N integers arr[1], arr[2], ..., arr[N].The
numbers in the array will be randomly ordered. Your task is to determine if
it is possible to get an array sorted in non-decreasing order by performing
the followi... | elif arr[i-1] < arr[i]: | flag = False
return True
|
//This function takes an array l and returns an array l' such that
// l' is identical to l in the indicies that are not divisible by three, while its values at the indicies that are divisible by three are equal
// to the values of the corresponding indicies of l, but sorted.
// >>> sort_third([1, 2, 3])
// [1, 2, 3]
//... | } | else{
x[i]=l[i];
}
}
y.sort();
k=0;
for(let i=0;i<l.length;i++){
if(i%3==0){
x[i]=y[k];
k=k+1;
}
}
return x;
} |
//prime_fib returns n-th number that is a Fibonacci number and it's also prime.
// >>> prime_fib(1)
// 2
// >>> prime_fib(2)
// 3
// >>> prime_fib(3)
// 5
// >>> prime_fib(4)
// 13
// >>> prime_fib(5)
// 89
function prime_fib(n){
function isPrime(number){
if(number <= 3){
return number > 1;
... | else if(number % 2 == 0 || number % 3 == 0){ | return false;
}
else{
for(var i = 5; i * i <= number; i += 6){
if(number % i == 0 || number % (i + 2) == 0){
return false;
}
}
return true;
}
}
function fib(num){
var a = 1, b = 0,... |
//Given two arrays operator, and operand. The first array has basic algebra operations, and
// the second array is an array of integers. Use the two given arrays to build the algebric
// expression and return the evaluation of this expression.
// The basic algebra operations:
// Addition ( + )
// Subtraction ( - )
... | while(count < operator.length){ | switch(operator[count]){
case '*':
operand[count] = operand[count] * operand[count + 1];
operand.splice(count + 1, 1);
operator.splice(count, 1);
count = 0;
do_again = true;
break;
case '//':
operand[count] = Math.floor(operand[count] / operand[cou... |
import java.util.*;
import java.lang.reflect.*;
import org.javatuples.*;
import java.security.*;
import java.math.*;
import java.io.*;
import java.util.stream.*;
class Problem {
// There are eight planets in our solar system: the closerst to the Sun
// is Mercury, the next one is Venus, then Earth, Mars, Jupit... | int indexMax = 0; | if (indexPlanet1 >= 0 && indexPlanet2 >= 0) {
if (indexPlanet1 < indexPlanet2) {
indexMin = indexPlanet1;
indexMax = indexPlanet2;
} else {
indexMin = indexPlanet2;
indexMax = indexPlanet1;
}
ArrayLis... |
def words_in_sentence(sentence: str) -> str:
"""
You are given a string representing a sentence,
the sentence contains some words separated by a space,
and you have to return a string that contains the words from the original sentence,
whose lengths are prime numbers,
the order of the words in t... | for i in range(2, n): | if n % i == 0:
return False
return True
words = sentence.split()
prime_words = []
for word in words:
if is_prime(len(word)):
prime_words.append(word)
return ' '.join(prime_words) |
def flip_case(string: str) -> str:
""" For a given string, flip lowercase characters to uppercase and uppercase to lowercase.
>>> flip_case('Hello')
'hELLO'
"""
new_string = ""
for character in string:
if character.isupper():
new_string += character.lower()
else: | new_string += character.upper() | return new_string
|
def is_equal_to_sum_even(n: int) -> bool:
"""Evaluate whether the given number n can be written as the sum of exactly 4 positive even numbers
Example
>>> is_equal_to_sum_even(4)
False
>>> is_equal_to_sum_even(6)
False
>>> is_equal_to_sum_even(8)
True
"""
if n < 8:
return ... | return n % 2 == 0 | |
//Given two arrays operator, and operand. The first array has basic algebra operations, and
// the second array is an array of integers. Use the two given arrays to build the algebric
// expression and return the evaluation of this expression.
// The basic algebra operations:
// Addition ( + )
// Subtraction ( - )
... | let do_again; | let count = 0;
let temp;
let answer;
while(count < operator.length){
switch(operator[count]){
case '*':
operand[count] = operand[count] * operand[count + 1];
operand.splice(count + 1, 1);
operator.splice(count, 1);
count = 0;
do_again = true;
break;
... |
import java.util.*;
import java.lang.reflect.*;
import org.javatuples.*;
import java.security.*;
import java.math.*;
import java.io.*;
import java.util.stream.*;
class Problem {
// There are eight planets in our solar system: the closerst to the Sun
// is Mercury, the next one is Venus, then Earth, Mars, Jupit... | return planetsInBetween; | } else {
return new ArrayList<String>();
}
}
} |
//Return true if a given number is prime, and false otherwise.
// >>> is_prime(6)
// false
// >>> is_prime(101)
// true
// >>> is_prime(11)
// true
// >>> is_prime(13441)
// true
// >>> is_prime(61)
// true
// >>> is_prime(4)
// false
// >>> is_prime(1)
// false
function is_prime(n){
if (n==1) {
return fals... | } |
var limit = Math.sqrt(n);
for (var i = 3; i <= limit; i += 2) {
if (n%i==0) {
return false;
}
}
return true;
}
|
import java.util.*;
import java.lang.reflect.*;
import org.javatuples.*;
import java.security.*;
import java.math.*;
import java.io.*;
import java.util.stream.*;
class Problem {
// Create a function which takes a string representing a file's name, and returns
// 'Yes' if the the file's name is valid, and return... | } | }
if (count > 3) {
return result;
}
if (name.length() == 0) {
return result;
}
if (!Character.isLetter(name.charAt(0))) {
return result;
}
return "Yes";
}
} |
//You are given a positive integer n. You have to create an integer array a of length n.
// For each i (1 ≤ i ≤ n), the value of a[i] = i * i - i + 1.
// Return the number of triples (a[i], a[j], a[k]) of a where i < j < k,
// and a[i] + a[j] + a[k] is a multiple of 3.
// Example :
// >>> get_max_triples(5)
// 1
// Ex... | arr.push(i*i-i+1); | }
for(let i = 0; i<arr.length; i++){
for(let j = i+1; j<arr.length; j++){
for(let k = j+1; k<arr.length; k++){
if((arr[i]+arr[j]+arr[k])%3 === 0){
result++;
}
}
}
}
return result;
}
|
//Given a positive integer n, return a sorted array that has the odd numbers in collatz sequence.
// The Collatz conjecture is a conjecture in mathematics that concerns a sequence defined
// as follows: start with any positive integer n. Then each term is obtained from the
// previous term as follows: if the previous ... | } | }
|
import java.util.*;
import java.lang.reflect.*;
import org.javatuples.*;
import java.security.*;
import java.math.*;
import java.io.*;
import java.util.stream.*;
class Problem {
// Write a function that takes a message, and encodes in such a
// way that it swaps case of all letters, replaces all vowels in
... | } else { | arr[i] = Character.toUpperCase(arr[i]);
}
}
return new String(arr);
}
} |
def words_in_sentence(sentence: str) -> str:
"""
You are given a string representing a sentence,
the sentence contains some words separated by a space,
and you have to return a string that contains the words from the original sentence,
whose lengths are prime numbers,
the order of the words in t... | if n % i == 0: | return False
return True
words = sentence.split()
prime_words = []
for word in words:
if is_prime(len(word)):
prime_words.append(word)
return ' '.join(prime_words) |
from typing import List
def below_zero(operations: List[int]) -> bool:
""" You're given a list of deposit and withdrawal operations on a bank account that starts with
zero balance. Your task is to detect if at any point the balance of account fallls below zero, and
at that point function should return True... | for operation in operations: | balance += operation
if balance < 0:
return True
return False
print(below_zero([1, 2, 3]))
print(below_zero([1, 2, -4, 5])) |
//Input to this function is a string containing multiple groups of nested parentheses. Your goal is to
// separate those group into separate strings and return the array of those.
// Separate groups are balanced (each open brace is properly closed) and not nested within each other
// Ignore any spaces in the input stri... | } else if (paren_string[i] === ')'){ | count--;
group += paren_string[i];
}
if (count === 0 && group){
groups.push(group);
group = '';
}
}
return groups;
}
|
//In this problem, you will implement a function that takes two arrays of numbers,
// and determines whether it is possible to perform an exchange of elements
// between them to make lst1 an array of only even numbers.
// There is no limit on the number of exchanged elements between lst1 and lst2.
// If it is possible ... | while(num1 < lst1.length && exchange){ | if(lst1[num1] % 2 !== 0){
exchange = false;
if(num2 < lst2.length){
while(num2 < lst2.length && exchange == false){
if(lst2[num2] % 2 == 0){
lst1[num1] = lst2[num2];
exchange = true;
}... |
import java.util.*;
import java.lang.reflect.*;
import org.javatuples.*;
import java.security.*;
import java.math.*;
import java.io.*;
import java.util.stream.*;
class Problem {
// You will be given the name of a class (a string) and an array array list of extensions.
// The extensions are to be used to load ad... | return class_name; | }
int strength = Integer.MIN_VALUE;
String strongest = "";
for (String s : extensions) {
int cap = (int)s.chars().filter(c -> Character.isUpperCase(c)).count();
int sm = (int)s.chars().filter(c -> Character.isLowerCase(c)).count();
int diff = cap - sm;... |
//Write a function that accepts two arrays of strings and returns the array that has
// total number of chars in the all strings of the array less than the other array.
// if the two arrays have the same number of chars, return the first array.
// Examples
// >>> total_match([], [])
// []
// >>> total_match(["hi", "ad... | sum_lst1 += item.length; | }
for(let item of lst2){
sum_lst2 += item.length;
}
if(sum_lst1 > sum_lst2){
return lst2;
}
else{
return lst1;
}
}
|
from typing import List
def count_nums(arr: List[int]) -> int:
"""
Write a function count_nums which takes an array of integers and returns
the number of elements which has a sum of digits > 0.
If a number is negative, then its first signed digit will be negative:
e.g. -123 has signed digits -1, 2,... | s = -1 * int(str(i)[0]) | for j in str(i)[1:]:
s += int(j)
else:
s = 0
for j in str(i):
s += int(j)
if s > 0:
n += 1
return n
|
//Write a function that takes a string and returns an ordered version of it.
// Ordered version of string, is a string where all words (separated by space)
// are replaced by a new word where all the characters arranged in
// ascending order based on ascii value.
// Note: You should keep the order of words and blank sp... | temp.sort(); | result.push(temp.join(""));
});
return result.join(" ");
} |
import java.util.*;
import java.lang.reflect.*;
import org.javatuples.*;
import java.security.*;
import java.math.*;
import java.io.*;
import java.util.stream.*;
class Problem {
// Given a positive integer, obtain its roman numeral equivalent as a string,
// and return it in lowercase.
// Restrictions: 1 <=... | res += "iv"; | num -= 4;
}
while (num >= 1) {
res += "i";
num -= 1;
}
return res;
}
} |
from typing import Union
def compare_one(a: Union[int, float, str], b: Union[int, float, str]) -> Union[int, float, str, None]:
"""
Create a function that takes integers, floats, or strings representing
real numbers, and returns the larger variable in its given variable type.
Return None if the values ... | return b | else:
return None
elif isinstance(a, int) and isinstance(b, float):
if a > b:
return a
elif a < b:
return b
else:
return None
elif isinstance(a, float) and isinstance(b, int):
if a > b:
return a
elif a < ... |
import java.util.*;
import java.lang.reflect.*;
import org.javatuples.*;
import java.security.*;
import java.math.*;
import java.io.*;
import java.util.stream.*;
class Problem {
// Write a function that returns true if the object q will fly, and false otherwise.
// The object q will fly if it's balanced (it is ... | if (q.size() == 0) { | return false;
}
if (q.size() == 1) {
return true;
}
Long sum = 0l;
for (int i = 0; i < q.size(); i++) {
sum += q.get(i);
}
if (sum > w) {
return false;
}
for (int i = 0; i < q.size() / 2; i++) {
... |
def digitSum(s: str) -> int:
"""Task
Write a function that takes a string as input and returns the sum of the upper characters only'
ASCII codes.
Examples:
>>> digitSum('')
0
>>> digitSum('abAB')
131
>>> digitSum('abcCd')
67
>>> digitSum('helloE')
69
>>> digitSum('wo... | return sum(map(ord, filter(str.isupper, s))) | |
//brackets is a string of "<" and ">".
// return true if every opening bracket has a corresponding closing bracket.
// >>> correct_bracketing("<")
// false
// >>> correct_bracketing("<>")
// true
// >>> correct_bracketing("<<><>>")
// true
// >>> correct_bracketing("><<>")
// false
function correct_bracketing(brackets)... | else if (brackets[i] === ">") { | opens--;
}
if (opens < 0) {
return false;
}
}
return opens === 0;
}
|
//From a supplied array of numbers (of length at least two) select and return two that are the closest to each
// other and return them in order (smaller number, larger number).
// >>> find_closest_elements([1.0, 2.0, 3.0, 4.0, 5.0, 2.2])
// [2.0, 2.2]
// >>> find_closest_elements([1.0, 2.0, 3.0, 4.0, 5.0, 2.0])
// [2.... | for (let i = 0; i < numbers.length; i++) { | for (let j = i + 1; j < numbers.length; j++) {
if (Math.abs(numbers[i] - numbers[j]) < closest) {
closest = Math.abs(numbers[i] - numbers[j]);
a = numbers[i];
b = numbers[j];
}
}
}
return a > b ? [b, a] : [a, b];
}
|
import java.util.*;
import java.lang.reflect.*;
import org.javatuples.*;
import java.security.*;
import java.math.*;
import java.io.*;
import java.util.stream.*;
class Problem {
// Return median of elements in the array list l.
// >>> median((new ArrayList<Long>(Arrays.asList((long)3l, (long)1l, (long)2l, (long... | return ret; | }
} |
//From a supplied array of numbers (of length at least two) select and return two that are the closest to each
// other and return them in order (smaller number, larger number).
// >>> find_closest_elements([1.0, 2.0, 3.0, 4.0, 5.0, 2.2])
// [2.0, 2.2]
// >>> find_closest_elements([1.0, 2.0, 3.0, 4.0, 5.0, 2.0])
// [2.... | } | }
return a > b ? [b, a] : [a, b];
}
|
//Create a function that takes integers, floats, or strings representing
// real numbers, and returns the larger variable in its given variable type.
// Return undefined if the values are equal.
// Note: If a real number is represented as a string, the floating point might be . or ,
// >>> compare_one(1, 2.5)
// 2.5
//... | return undefined; | }
}
}
|
from typing import List
def select_words(s: str, n: int) -> List[str]:
"""Given a string s and a natural number n, you have been tasked to implement
a function that returns a list of all words from string s that contain exactly
n consonants, in order these words appear in the string s.
If the string ... | for char in word: | if char.lower() in CONSONANTS:
count += 1
if count == n:
result.append(word)
return result
|
//Given an object, return true if all keys are strings in lower
// case or all keys are strings in upper case, else return false.
// The function should return false is the given object is empty.
// Examples:
// >>> check_dict_case({"a": "apple", "b": "banana"})
// true
// >>> check_dict_case({"a": "apple", "A": "bana... | return false; | }
}
else if (case_type == 1){
if (key != key.toUpperCase()){
return false;
}
}
else if (case_type == 0){
if (key != key.toLowerCase()){
return false;
}
... |
//Given a grid with N rows and N columns (N >= 2) and a positive integer k,
// each cell of the grid contains a value. Every integer in the range [1, N * N]
// inclusive appears exactly once on the cells of the grid.
// You have to find the minimum path of length k in the grid. You can start
// from any cell, and in e... | } | if(y > 0){
neighbours.push(grid[x][y - 1]);
}
if(y < n - 1){
neighbours.push(grid[x][y + 1]);
}
let nextCell = neighbours[0];
for(let i = 0; i < neighbours.length; i++){
let curr = neighbours[i];
if(curr < nextCell){
... |
//Given a string of words, return an array of words split on whitespace, if no whitespaces exists in the text you
// should split on commas ',' if no commas exists you should return the number of lower-case letters with odd order in the
// alphabet, ord('a') = 0, ord('b') = 1, ... ord('z') = 25
// Examples
// >>> split... | } | }
}
return count;
}
} |
//"Given an array representing a branch of a tree that has non-negative integer nodes
// your task is to pluck one of the nodes and return it.
// The plucked node should be the node with the smallest even value.
// If multiple nodes with the same smallest even value are found return the node that has smallest index.
//... | if(result.length === 0 || result[0] > arr[i]){ | result = [arr[i], i];
}
}
}
return result;
}
|
def int_to_mini_roman(number: int) -> str:
"""
Given a positive integer, obtain its roman numeral equivalent as a string,
and return it in lowercase.
Restrictions: 1 <= num <= 1000
Examples:
>>> int_to_mini_roman(19)
'xix'
>>> int_to_mini_roman(152)
'clii'
>>> int_to_mini_roman(... | 1000: 'm', | 900: 'cm',
500: 'd',
400: 'cd',
100: 'c',
90: 'xc',
50: 'l',
40: 'xl',
10: 'x',
9: 'ix',
5: 'v',
4: 'iv',
1: 'i'
}
roman_numeral = ''
for key in sorted(roman_numerals.keys(), reverse=True):
roman_numeral ... |
//Given a positive integer n, return an array that has the number of even and odd
// integer palindromes that fall within the range(1, n), inclusive.
// Example 1:
// >>> even_odd_palindrome(3)
// [1, 2]
// Explanation:
// Integer palindrome are 1, 2, 3. one of them is even, and two of them are odd.
// Example 2:
// >>... | for(var i = 0; i < pal.length; i++){ | if(pal[i] % 2 == 0){
even++;
}
else{
odd++;
}
}
return [even, odd];
} |
//You are given a string s.
// if s[i] is a letter, reverse its case from lower to upper or vise versa,
// otherwise keep it as it is.
// If the string contains no letters, reverse the string.
// The function should return the resulted string.
// Examples
// >>> solve("1234")
// "4321"
// >>> solve("ab")
// "AB"
// >>... | } | return char;
});
return swapped.join('');
}
return s.split('').reverse().join('');
}
|
from typing import Tuple
def intersection(interval1: Tuple[int, int], interval2: Tuple[int, int]) -> str:
"""You are given two intervals,
where each interval is a pair of integers. For example, interval = (start, end) = (1, 2).
The given intervals are closed which means that the interval (start, end)
i... | if start > end: | return "NO"
return "YES" if end - start == 2 else "NO"
|
import java.util.*;
import java.lang.reflect.*;
import org.javatuples.*;
import java.security.*;
import java.math.*;
import java.io.*;
import java.util.stream.*;
class Problem {
// Write a function that returns true if the object q will fly, and false otherwise.
// The object q will fly if it's balanced (it is ... | return false; | }
if (q.size() == 1) {
return true;
}
Long sum = 0l;
for (int i = 0; i < q.size(); i++) {
sum += q.get(i);
}
if (sum > w) {
return false;
}
for (int i = 0; i < q.size() / 2; i++) {
if (q.get(i) != q.g... |
from typing import List
def count_nums(arr: List[int]) -> int:
"""
Write a function count_nums which takes an array of integers and returns
the number of elements which has a sum of digits > 0.
If a number is negative, then its first signed digit will be negative:
e.g. -123 has signed digits -1, 2,... | s = 0 | for j in str(i):
s += int(j)
if s > 0:
n += 1
return n
|
import java.util.*;
import java.lang.reflect.*;
import org.javatuples.*;
import java.security.*;
import java.math.*;
import java.io.*;
import java.util.stream.*;
class Problem {
// Input to this function is a string containing multiple groups of nested parentheses. Your goal is to
// separate those group into s... | temp = new StringBuffer(); | }
open_paren++;
temp.append(c);
} else if (c == ')') {
open_paren--;
temp.append(c);
if (open_paren == 0) {
output.add(temp.toString());
}
}
}
return output;
}
} |
from typing import List
def search(lst: List[int]) -> int:
"""
You are given a non-empty list of positive integers. Return the greatest integer that is greater than
zero, and has a frequency greater than or equal to the value of the integer itself.
The frequency of an integer is the number of times i... | if value >= key and key > maxValue: | maxValue = key
return maxValue
|
//Return a string containing space-delimited numbers starting from 0 upto n inclusive.
// >>> string_sequence(0)
// "0"
// >>> string_sequence(5)
// "0 1 2 3 4 5"
function string_sequence(n){
let arr = [];
for(let i = 0; i <= n; i++){
arr.push(i); | } | return arr.join(" ");
}
|
import java.util.*;
import java.lang.reflect.*;
import org.javatuples.*;
import java.security.*;
import java.math.*;
import java.io.*;
import java.util.stream.*;
class Problem {
// You are given an array array list of two strings, both strings consist of open
// parentheses '(' or close parentheses ')' only.
... | int c2 = 0; | for (int i = 0; i < s3.length(); i++) {
if (s3.charAt(i) == '(') c1 += 1;
else c1 -= 1;
if (c1 < 0) break;
}
for (int i = 0; i < s4.length(); i++) {
if (s4.charAt(i) == '(') c2 += 1;
else c2 -= 1;
if (c2 < 0) break;
... |
import java.util.*;
import java.lang.reflect.*;
import org.javatuples.*;
import java.security.*;
import java.math.*;
import java.io.*;
import java.util.stream.*;
class Problem {
// Given a string s and a natural number n, you have been tasked to implement
// a function that returns an array array list of all w... | String wordInLowerCase = word.toLowerCase(); | long consonants = 0l;
for (char c : wordInLowerCase.toCharArray()) {
switch (c) {
case 'a':
case 'e':
case 'i':
case 'o':
case 'u':
break;
... |
//Input to this function is a string containing multiple groups of nested parentheses. Your goal is to
// separate those group into separate strings and return the array of those.
// Separate groups are balanced (each open brace is properly closed) and not nested within each other
// Ignore any spaces in the input stri... | group = ''; | }
}
return groups;
}
|
//Write a function that accepts an array of strings as a parameter,
// deletes the strings that have odd lengths from it,
// and returns the resulted array with a sorted order,
// The array is always an array of strings and never an array of numbers,
// and it may contain duplicates.
// The order of the array should be... | } | return result.sort(function(a, b){
if(a.length < b.length){
return -1;
}
else if(a.length > b.length){
return 1;
}
else{
if(a < b){
return -1;
}
else if(a > b){
return 1;
}... |
def valid_date(date: str) -> bool:
"""You have to write a function which validates a given date string and
returns True if the date is valid otherwise False.
The date is valid if all of the following rules are satisfied:
1. The date string is not empty.
2. The number of days is not less than 1 or hi... | if not date: | return False
days_per_month = [31, 29, 31, 30, 31, 30, 31, 31, 30, 31, 30, 31]
date_list = [int(d) for d in date.split('-')]
if len(date_list) != 3:
return False
if date_list[0] < 1 or date_list[0] > 12:
return False
if date_list[1] < 1 or date_list[1] > days_per_month[date_l... |
import java.util.*;
import java.lang.reflect.*;
import org.javatuples.*;
import java.security.*;
import java.math.*;
import java.io.*;
import java.util.stream.*;
class Problem {
// Given array list of integers, return array list in strange order.
// Strange sorting, is when you start with the minimum value,
... | result.add(sorted.get(min)); | min++;
if (min <= max) {
result.add(sorted.get(max));
max--;
}
}
return result;
}
} |
import java.util.*;
import java.lang.reflect.*;
import org.javatuples.*;
import java.security.*;
import java.math.*;
import java.io.*;
import java.util.stream.*;
class Problem {
// You are given 2 words. You need to return true if the second word or any of its rotations is a substring in the first word
// >>> c... | b = b.substring(1) + b.charAt(0); | found = a.contains(b);
if (found) break;
}
return found;
}
} |
//Given a positive integer, obtain its roman numeral equivalent as a string,
// and return it in lowercase.
// Restrictions: 1 <= num <= 1000
// Examples:
// >>> int_to_mini_roman(19)
// "xix"
// >>> int_to_mini_roman(152)
// "clii"
// >>> int_to_mini_roman(426)
// "cdxxvi"
function int_to_mini_roman(number){
var r... | var key_list = Object.keys(roman_conversion).map(Number); | key_list.sort(function(a, b){return b-a});
for (var i = 0; i < key_list.length; i++){
if (key_list[i] <= number){
output += roman_conversion[key_list[i]];
number -= key_list[i];
break;
}
}
}
return output;
}
|
//sum_to_n is a function that sums numbers from 1 to n.
// >>> sum_to_n(30)
// 465
// >>> sum_to_n(100)
// 5050
// >>> sum_to_n(5)
// 15
// >>> sum_to_n(10)
// 55
// >>> sum_to_n(1)
// 1
function sum_to_n(n){
| var sum = 0; | for(var i = 1; i <= n; i++){
sum += i;
}
return sum;
}
|
def correct_bracketing(brackets: str) -> bool:
""" brackets is a string of "<" and ">".
return True if every opening bracket has a corresponding closing bracket.
>>> correct_bracketing('<')
False
>>> correct_bracketing('<>')
True
>>> correct_bracketing('<<><>>')
True
>>> correct_bra... | num_left_brackets -= 1 | if num_left_brackets < 0:
return False
return num_left_brackets == 0
|
//Input is a space-delimited string of numberals from 'zero' to 'nine'.
// Valid choices are 'zero', 'one', 'two', 'three', 'four', 'five', 'six', 'seven', 'eight' and 'nine'.
// Return the string with numbers sorted from smallest to largest
// >>> sort_numbers("three one five")
// "one three five"
function sort_number... | "three": 3, | "four": 4,
"five": 5,
"six": 6,
"seven": 7,
"eight": 8,
"nine": 9
};
numString.sort(function(a, b){
return numMap[a] - numMap[b];
});
numString = numString.join(" ");
return numString;
} |
import java.util.*;
import java.lang.reflect.*;
import org.javatuples.*;
import java.security.*;
import java.math.*;
import java.io.*;
import java.util.stream.*;
class Problem {
// You have to write a function which validates a given date string and
// returns true if the date is valid otherwise false.
// T... | } else { | if (day < 1 || day > 30) return valid_date;
}
valid_date = true;
} catch (Exception e) {
valid_date = false;
}
return valid_date;
}
} |
import java.util.*;
import java.lang.reflect.*;
import org.javatuples.*;
import java.security.*;
import java.math.*;
import java.io.*;
import java.util.stream.*;
class Problem {
// Find how many times a given substring can be found in the original string. Count overlaping cases.
// >>> howManyTimes((""), ("a"))... | while (index != -1) { | index = string.indexOf(substring, index);
if (index != -1) {
index++;
count++;
}
}
return count;
}
} |
//Given an object, return true if all keys are strings in lower
// case or all keys are strings in upper case, else return false.
// The function should return false is the given object is empty.
// Examples:
// >>> check_dict_case({"a": "apple", "b": "banana"})
// true
// >>> check_dict_case({"a": "apple", "A": "bana... | else if (case_type == 1){ | if (key != key.toUpperCase()){
return false;
}
}
else if (case_type == 0){
if (key != key.toLowerCase()){
return false;
}
}
}
else{
return false;
... |
import java.util.*;
import java.lang.reflect.*;
import org.javatuples.*;
import java.security.*;
import java.math.*;
import java.io.*;
import java.util.stream.*;
class Problem {
// You are given a rectangular grid of wells. Each row represents a single well,
// and each 1 in a row represents a single unit of wa... | for (ArrayList<Long> well : grid) { | long level = 0l;
for (Long unit : well) {
if (unit == 1l) {
level += 1l;
}
}
long units = level / capacity;
if (level % capacity != 0l) {
units += 1l;
}
count += units;... |
from typing import List
def match_parens(lst: List[str]) -> str:
"""
You are given a list of two strings, both strings consist of open
parentheses '(' or close parentheses ')' only.
Your job is to check if it is possible to concatenate the two strings in
some order, that the resulting string will b... | if open_parens: | open_parens -= 1
else:
close_parens += 1
if open_parens == 0 and close_parens == 0:
return 'Yes'
return 'No'
|
import java.util.*;
import java.lang.reflect.*;
import org.javatuples.*;
import java.security.*;
import java.math.*;
import java.io.*;
import java.util.stream.*;
class Problem {
// You are given a rectangular grid of wells. Each row represents a single well,
// and each 1 in a row represents a single unit of wa... | } | long units = level / capacity;
if (level % capacity != 0l) {
units += 1l;
}
count += units;
}
return count;
}
} |
//Input to this function is a string containing multiple groups of nested parentheses. Your goal is to
// separate those group into separate strings and return the array of those.
// Separate groups are balanced (each open brace is properly closed) and not nested within each other
// Ignore any spaces in the input stri... | } | }
return groups;
}
|
//Given an array of integers, sort the integers that are between 1 and 9 inclusive,
// reverse the resulting array, and then replace each digit by its corresponding name from
// "One", "Two", "Three", "Four", "Five", "Six", "Seven", "Eight", "Nine".
// For example:
// >>> by_length([2, 1, 1, 4, 5, 8, 2, 3])
// ["Eight"... | arr2.sort(); | arr2.reverse();
var arr3 = [];
for(var i = 0; i < arr2.length; i++){
var num = arr2[i];
if(num == 1){
arr3.push("One");
}
else if(num == 2){
arr3.push("Two");
}
else if(num == 3){
arr3.push("Three");
}
else i... |
import java.util.*;
import java.lang.reflect.*;
import org.javatuples.*;
import java.security.*;
import java.math.*;
import java.io.*;
import java.util.stream.*;
class Problem {
// Find the shortest palindrome that begins with a supplied string.
// Algorithm idea is simple:
// - Find the longest postfix of ... | for (int index = 0; index < string.length(); index++) { | if (string.substring(index).equals(reverse.substring(0, string.length() - index))) {
newString.append(reverse.substring(string.length() - index));
break;
}
}
return newString.toString();
}
} |
//You're given an array of deposit and withdrawal operations on a bank account that starts with
// zero balance. Your task is to detect if at any point the balance of account fallls below zero, and
// at that point function should return true. Otherwise it should return false.
// >>> below_zero([1, 2, 3])
// false
// >... | } | }
return false;
}
|
import java.util.*;
import java.lang.reflect.*;
import org.javatuples.*;
import java.security.*;
import java.math.*;
import java.io.*;
import java.util.stream.*;
class Problem {
// Return sorted unique common elements for two array lists.
// >>> common((new ArrayList<Long>(Arrays.asList((long)1l, (long)4l, (lon... | return new ArrayList<Long>( | l1.stream()
.filter(l2::contains)
.collect(Collectors.toSet())
);
}
} |
import java.util.*;
import java.lang.reflect.*;
import org.javatuples.*;
import java.security.*;
import java.math.*;
import java.io.*;
import java.util.stream.*;
class Problem {
// Given a positive integer, obtain its roman numeral equivalent as a string,
// and return it in lowercase.
// Restrictions: 1 <=... | res += "d"; | num -= 500;
}
if (num >= 400) {
res += "cd";
num -= 400;
}
while (num >= 100) {
res += "c";
num -= 100;
}
if (num >= 90) {
res += "xc";
num -= 90;
}
if (num >= 50) {
... |
import java.util.*;
import java.lang.reflect.*;
import org.javatuples.*;
import java.security.*;
import java.math.*;
import java.io.*;
import java.util.stream.*;
class Problem {
// Given an array array list of positive integers x. return a sorted array list of all
// elements that hasn't any even digit.
//... | } | if (unique) {
b.add(x.get(i));
}
}
Collections.sort(b);
return b;
}
} |
from typing import Tuple
def bf(planet1: str, planet2: str) -> Tuple[str, ...]:
"""
There are eight planets in our solar system: the closerst to the Sun
is Mercury, the next one is Venus, then Earth, Mars, Jupiter, Saturn,
Uranus, Neptune.
Write a function that takes two planet names as strings p... | planets = planets[start+1:end] | else:
planets = planets[end+1:start]
return tuple(planets) |
from typing import List
def has_close_elements(numbers: List[float], threshold: float) -> bool:
""" Check if in given list of numbers, are any two numbers closer to each other than
given threshold.
>>> has_close_elements([1.0, 2.0, 3.0], 0.5)
False
>>> has_close_elements([1.0, 2.8, 3.0, 4.0, 5.0, 2... | if abs(numbers[i] - numbers[j]) < threshold: | return True
return False
|
//This function takes an array l and returns an array l' such that
// l' is identical to l in the indicies that are not divisible by three, while its values at the indicies that are divisible by three are equal
// to the values of the corresponding indicies of l, but sorted.
// >>> sort_third([1, 2, 3])
// [1, 2, 3]
//... | for(let i=0;i<l.length;i++){ | if(i%3==0){
y[k]=l[i];
k=k+1;
}
else{
x[i]=l[i];
}
}
y.sort();
k=0;
for(let i=0;i<l.length;i++){
if(i%3==0){
x[i]=y[k];
k=k+1;
}
}
return x;
} |
import java.util.*;
import java.lang.reflect.*;
import org.javatuples.*;
import java.security.*;
import java.math.*;
import java.io.*;
import java.util.stream.*;
class Problem {
// "Given an array array list representing a branch of a tree that has non-negative integer nodes
// your task is to pluck one of the ... | } | }
}
ArrayList<Long> newArr = new ArrayList<Long>();
if (minIndex == -1) {
return newArr;
}
newArr.add(minValue);
newArr.add((long)minIndex);
return newArr;
}
} |
from typing import List
def add_elements(arr: List[int], k: int) -> int:
"""
Given a non-empty array of integers arr and an integer k, return
the sum of the elements with at most two digits from the first k elements of arr.
Example:
>>> add_elements([111, 21, 3, 4000, 5, 6, 7, 8, 9], 4)
24
... | for num in arr[:k]: | if num < 100:
total += num
return total
|
//Return the largest prime factor of n. Assume n > 1 and is not a prime.
// >>> largest_prime_factor(13195)
// 29
// >>> largest_prime_factor(2048)
// 2
function largest_prime_factor(n){
var result = 2;
while(n > result){
if(n % result == 0){
n = n / result;
}
else{
result = result + 1; | } | }
return result;
} |
import java.util.*;
import java.lang.reflect.*;
import org.javatuples.*;
import java.security.*;
import java.math.*;
import java.io.*;
import java.util.stream.*;
class Problem {
// It is the last week of the semester and the teacher has to give the grades
// to students. The teacher has been making her own algo... | } else if (currentGrade > 1.7f) { | letterGrades.add("C");
} else if (currentGrade > 1.3f) {
letterGrades.add("C-");
} else if (currentGrade > 1.0f) {
letterGrades.add("D+");
} else if (currentGrade > 0.7f) {
letterGrades.add("D");
} else if (c... |
//Given a grid with N rows and N columns (N >= 2) and a positive integer k,
// each cell of the grid contains a value. Every integer in the range [1, N * N]
// inclusive appears exactly once on the cells of the grid.
// You have to find the minimum path of length k in the grid. You can start
// from any cell, and in e... | } | currCell = nextCell;
}
return path;
} |
//Return a greatest common divisor of two integers a and b
// >>> greatest_common_divisor(3, 5)
// 1
// >>> greatest_common_divisor(25, 15)
// 5
function greatest_common_divisor(a, b){
let max = Math.max(a, b) | let min = Math.min(a, b) | if (max % min == 0) {
return min
} else {
return greatest_common_divisor(min, max % min)
}
}
|
def greatest_common_divisor(a: int, b: int) -> int:
""" Return a greatest common divisor of two integers a and b
>>> greatest_common_divisor(3, 5)
1
>>> greatest_common_divisor(25, 15)
5
"""
if a > b: | a, b = b, a | if a == 0:
return b
return greatest_common_divisor(b % a, a)
|
//Given an array arr of integers, find the minimum number of elements that
// need to be changed to make the array palindromic. A palindromic array is an array that
// is read the same backwards and forwards. In one change, you can change one element to any other element.
// For example:
// >>> smallest_change([1, 2, 3... | return changes; | } |
def check_if_last_char_is_a_letter(txt: str) -> bool:
"""
Create a function that returns True if the last character
of a given string is an alphabetical character and is not
a part of a word, and False otherwise.
Note: "word" is a group of characters separated by space.
Examples:
>>> check_... | if len(txt) == 0: | return False
elif txt[-1].isalpha() and (len(txt) == 1 or not txt[-2].isalpha()):
return True
else:
return False
|
def encode(message: str) -> str:
"""
Write a function that takes a message, and encodes in such a
way that it swaps case of all letters, replaces all vowels in
the message with the letter that appears 2 places ahead of that
vowel in the english alphabet.
Assume only letters.
Exampl... | return chr(ord(ch) + 2) | return ch
return ''.join(map(lambda ch: encode_vowel(swap_case(ch)), message))
|
//Implement the function f that takes n as a parameter,
// and returns an array of size n, such that the value of the element at index i is the factorial of i if i is even
// or the sum of numbers from 1 to i otherwise.
// i starts from 1.
// the factorial of i is the multiplication of the numbers from 1 to i (1 * 2 * ... | var sum = 0; | var factorial = 1;
for(var i = 1; i <= n; i++){
if(i % 2 == 0){
for(var j = 1; j <= i; j++){
factorial *= j;
}
result.push(factorial);
factorial = 1;
}else{
for(var k = 1; k <= i; k++){
sum += k;
... |
import java.util.*;
import java.lang.reflect.*;
import org.javatuples.*;
import java.security.*;
import java.math.*;
import java.io.*;
import java.util.stream.*;
class Problem {
// Given a non-empty array list of integers lst. add the even elements that are at odd indices..
// Examples:
// >>> add((new Arra... | return sum; | }
} |
import java.util.*;
import java.lang.reflect.*;
import org.javatuples.*;
import java.security.*;
import java.math.*;
import java.io.*;
import java.util.stream.*;
class Problem {
// triples_sum_to_zero takes an array array list of integers as an input.
// it returns true if there are three distinct elements in t... | int k = sortedList.size() - 1; | while (j < k) {
long currSum = sortedList.get(i) + sortedList.get(j) + sortedList.get(k);
if (currSum == 0) {
return true;
} else if (currSum < 0) {
j++;
} else {
k--;
... |
def correct_bracketing(brackets: str) -> bool:
""" brackets is a string of "<" and ">".
return True if every opening bracket has a corresponding closing bracket.
>>> correct_bracketing('<')
False
>>> correct_bracketing('<>')
True
>>> correct_bracketing('<<><>>')
True
>>> correct_bra... | elif bracket == '>': | num_left_brackets -= 1
if num_left_brackets < 0:
return False
return num_left_brackets == 0
|
//prime_fib returns n-th number that is a Fibonacci number and it's also prime.
// >>> prime_fib(1)
// 2
// >>> prime_fib(2)
// 3
// >>> prime_fib(3)
// 5
// >>> prime_fib(4)
// 13
// >>> prime_fib(5)
// 89
function prime_fib(n){
function isPrime(number){
if(number <= 3){
return number > 1;
... | } | return fib(fibNum - 1);
} |
import java.util.*;
import java.lang.reflect.*;
import org.javatuples.*;
import java.security.*;
import java.math.*;
import java.io.*;
import java.util.stream.*;
class Problem {
// The FibFib number sequence is a sequence similar to the Fibbonacci sequnece that's defined as follows:
// fibfib(0) == 0
// fib... | memo[1] = 0; | memo[2] = 1;
for (int i = 3; i <= n; i++) {
memo[i] = memo[i - 1] + memo[i - 2] + memo[i - 3];
}
return memo[(int) n];
}
} |
//You are given an array arr of integers and you need to return
// sum of magnitudes of integers multiplied by product of all signs
// of each number in the array, represented by 1, -1 or 0.
// Note: return undefined for empty arr.
// Example:
// >>> prod_signs([1, 2, 2, -4])
// 9
// >>> prod_signs([0, 1])
// 0
// >>> ... | if(arr[i] < 0){ | pro *= -1;
}
else if(arr[i] == 0){
pro *= 0;
}
}
total *= pro;
return total;
}
}
|
//Write a function count_nums which takes an array of integers and returns
// the number of elements which has a sum of digits > 0.
// If a number is negative, then its first signed digit will be negative:
// e.g. -123 has signed digits -1, 2, and 3.
// >>> count_nums([])
// 0
// >>> count_nums([-1, 11, -11])
// 1
// >... | } | |
import java.util.*;
import java.lang.reflect.*;
import org.javatuples.*;
import java.security.*;
import java.math.*;
import java.io.*;
import java.util.stream.*;
class Problem {
// Given an array array list of positive integers x. return a sorted array list of all
// elements that hasn't any even digit.
//... | } | Collections.sort(b);
return b;
}
} |
import java.util.*;
import java.lang.reflect.*;
import org.javatuples.*;
import java.security.*;
import java.math.*;
import java.io.*;
import java.util.stream.*;
class Problem {
// Write a function count_nums which takes an array array list of integers and returns
// the number of elements which has a sum of di... | if (sum > 0) { | result++;
}
}
return result;
}
} |
from typing import List
def intersperse(numbers: List[int], delimeter: int) -> List[int]:
""" Insert a number 'delimeter' between every two consecutive elements of input list `numbers'
>>> intersperse([], 4)
[]
>>> intersperse([1, 2, 3], 4)
[1, 4, 2, 4, 3]
"""
result = []
if len(numbers... | result.append(num) | return result
|
//For a given number n, find the largest number that divides n evenly, smaller than n
// >>> largest_divisor(15)
// 5
function largest_divisor(n){
let ld = 0;
for(i=1; i<n; i++){ | if(n%i===0){ | if(i>ld){
ld = i;
}
}
}
return ld;
} |
from typing import List
def exchange(lst1: List[int], lst2: List[int]) -> str:
"""In this problem, you will implement a function that takes two lists of numbers,
and determines whether it is possible to perform an exchange of elements
between them to make lst1 a list of only even numbers.
There is no l... | if y % 2 == 0: | count -= 1
if count > 0:
return "NO"
else:
return "YES" |
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