prefix
stringlengths
0
918k
middle
stringlengths
0
812k
suffix
stringlengths
0
962k
from typing import List, Optional def prod_signs(arr: List[int]) -> Optional[int]: """ You are given an array arr of integers and you need to return sum of magnitudes of integers multiplied by product of all signs of each number in the array, represented by 1, -1 or 0. Note: return None for empty a...
else:
sign_arr = [] for num in arr: if num > 0: sign_arr.append(1) elif num < 0: sign_arr.append(-1) else: sign_arr.append(0) return sum(map(abs, arr)) * product(sign_arr)
import java.util.*; import java.lang.reflect.*; import org.javatuples.*; import java.security.*; import java.math.*; import java.io.*; import java.util.stream.*; class Problem { // Change numerical base of input number x to base. // return string representation after the conversion. // base numbers are less...
return sb.reverse().toString();
} }
import java.util.*; import java.lang.reflect.*; import org.javatuples.*; import java.security.*; import java.math.*; import java.io.*; import java.util.stream.*; class Problem { // Given a non-empty array list of integers lst. add the even elements that are at odd indices.. // Examples: // >>> add((new Arra...
if (i % 2 == 1 && lst.get(i) % 2 == 0) {
sum += lst.get(i); } } return sum; } }
def is_multiply_prime(a: int) -> bool: """Write a function that returns true if the given number is the multiplication of 3 prime numbers and false otherwise. Knowing that (a) is less then 100. Example: >>> is_multiply_prime(30) True 30 = 2 * 3 * 5 """ n = a d = 2 prime_fact...
if n > 1:
prime_factors.append(n) if len(prime_factors) == 3: return True else: return False
import java.util.*; import java.lang.reflect.*; import org.javatuples.*; import java.security.*; import java.math.*; import java.io.*; import java.util.stream.*; class Problem { // There are eight planets in our solar system: the closerst to the Sun // is Mercury, the next one is Venus, then Earth, Mars, Jupit...
planetsInBetween.add(planets.get(i));
} return planetsInBetween; } else { return new ArrayList<String>(); } } }
//Insert a number 'delimeter' between every two consecutive elements of input array `numbers' // >>> intersperse([], 4) // [] // >>> intersperse([1, 2, 3], 4) // [1, 4, 2, 4, 3] function intersperse(numbers, delimeter){ var result = []; for(var i = 0; i < numbers.length; i++){ result.push(numbers[i]); if(i ...
return result;
}
import java.util.*; import java.lang.reflect.*; import org.javatuples.*; import java.security.*; import java.math.*; import java.io.*; import java.util.stream.*; class Problem { // You'll be given a string of words, and your task is to count the number // of boredoms. A boredom is a sentence that starts with th...
return boredoms;
} }
//You have been tasked to write a function that receives // a hexadecimal number as a string and counts the number of hexadecimal // digits that are primes (prime number, or a prime, is a natural number // greater than 1 that is not a product of two smaller natural numbers). // Hexadecimal digits are 0, 1, 2, 3, 4, ...
}
def special_factorial(n: int) -> int: """The Brazilian factorial is defined as: brazilian_factorial(n) = n! * (n-1)! * (n-2)! * ... * 1! where n > 0 For example: >>> special_factorial(4) 288 The function will receive an integer as input and should return the special factorial of this i...
return 1
else: return n * special_factorial(n-1) * factorial(n-1)
from typing import List def odd_count(lst: List[str]) -> List[str]: """Given a list of strings, where each string consists of only digits, return a list. Each element i of the output should be "the number of odd elements in the string i of the input." where all the i's should be replaced by the number ...
count = 0
for j in range(len(lst[i])): if int(lst[i][j]) % 2 != 0: count += 1 output.append(f"the number of odd elements {count}n the str{count}ng {count} of the {count}nput.") return output
from typing import List def smallest_change(arr: List[int]) -> int: """ Given an array arr of integers, find the minimum number of elements that need to be changed to make the array palindromic. A palindromic array is an array that is read the same backwards and forwards. In one change, you can change ...
start = 0
end = len(arr) - 1 count = 0 while start < end: if arr[start] != arr[end]: count += 1 start += 1 end -= 1 return count
import java.util.*; import java.lang.reflect.*; import org.javatuples.*; import java.security.*; import java.math.*; import java.io.*; import java.util.stream.*; class Problem { // Return maximum element in the array list. // >>> maxElement((new ArrayList<Long>(Arrays.asList((long)1l, (long)2l, (long)3l)))) ...
}
}
from typing import List, Tuple, Optional def largest_smallest_integers(lst: List[int]) -> Tuple[Optional[int], Optional[int]]: """ Create a function that returns a tuple (a, b), where 'a' is the largest of negative integers, and 'b' is the smallest of positive integers in a list. If there is no neg...
largest_negative = None
for num in lst: if num > 0: if smallest_positive is None or num < smallest_positive: smallest_positive = num elif num < 0: if largest_negative is None or num > largest_negative: largest_negative = num return (largest_negative, smallest_posi...
from typing import Union def compare_one(a: Union[int, float, str], b: Union[int, float, str]) -> Union[int, float, str, None]: """ Create a function that takes integers, floats, or strings representing real numbers, and returns the larger variable in its given variable type. Return None if the values ...
return a
elif float(a_tmp) < float(b_tmp): return b else: return None elif isinstance(a, int) and isinstance(b, float): if a > b: return a elif a < b: return b else: return None elif isinstance(a, float) and isinstance(b,...
import java.util.*; import java.lang.reflect.*; import org.javatuples.*; import java.security.*; import java.math.*; import java.io.*; import java.util.stream.*; class Problem { // Filter an input array list of strings only for ones that start with a given prefix. // >>> filterByPrefix((new ArrayList<String>(Ar...
return (ArrayList<String>)strings.stream().filter(s -> s.startsWith(prefix)).collect(Collectors.toList());
} }
//Implement a function that takes an non-negative integer and returns an array of the first n // integers that are prime numbers and less than n. // for example: // >>> count_up_to(5) // [2, 3] // >>> count_up_to(11) // [2, 3, 5, 7] // >>> count_up_to(0) // [] // >>> count_up_to(20) // [2, 3, 5, 7, 11, 13, 17, 19] // >...
if (n < 2) return [];
var output = [2]; for (var i = 3; i < n; i += 2){ var prime = true; for (var j = 3; j < i; j += 2){ if (i % j === 0){ prime = false; break; } } if (prime) output.push(i); } return output; }
//Out of array of strings, return the longest one. Return the first one in case of multiple // strings of the same length. Return undefined in case the input array is empty. // >>> longest([]) // undefined // >>> longest(["a", "b", "c"]) // "a" // >>> longest(["a", "bb", "ccc"]) // "ccc" function longest(strings){ va...
for (var i = 0; i < strings.length; i++) {
if (!result || strings[i].length > result.length) { result = strings[i]; } } return result; }
import java.util.*; import java.lang.reflect.*; import org.javatuples.*; import java.security.*; import java.math.*; import java.io.*; import java.util.stream.*; class Problem { // " // This function will take an array array list of integers. For all entries in the array list, the function shall square the inte...
}
return ans; } }
from typing import List def unique_digits(x: List[int]) -> List[int]: """Given a list of positive integers x. return a sorted list of all elements that hasn't any even digit. Note: Returned list should be sorted in increasing order. For example: >>> unique_digits([15, 33, 1422, 1]) [1, 1...
if temp%2==0:
s.append(i) break temp=temp//10 for i in s: x.remove(i) return sorted(x)
import java.util.*; import java.lang.reflect.*; import org.javatuples.*; import java.security.*; import java.math.*; import java.io.*; import java.util.stream.*; class Problem { // Change numerical base of input number x to base. // return string representation after the conversion. // base numbers are less...
}
StringBuilder sb = new StringBuilder(); while (x>0) { sb.append(x%base); x = x/base; } return sb.reverse().toString(); } }
from typing import List def strange_sort_list(lst: List[int]) -> List[int]: """ Given list of integers, return list in strange order. Strange sorting, is when you start with the minimum value, then maximum of the remaining integers, then minimum and so on. Examples: >>> strange_sort_list([1, 2...
out.append(lst.pop(0))
if not lst: break out.append(lst.pop()) return out
import java.util.*; import java.lang.reflect.*; import org.javatuples.*; import java.security.*; import java.math.*; import java.io.*; import java.util.stream.*; class Problem { // Given an array array list of positive integers x. return a sorted array list of all // elements that hasn't any even digit. //...
while (z > 0) {
long y = z % 10; if (y % 2 == 0) { unique = false; break; } z = z / 10; } if (unique) { b.add(x.get(i)); } } Collections.sort(b); return b; ...
import java.util.*; import java.lang.reflect.*; import org.javatuples.*; import java.security.*; import java.math.*; import java.io.*; import java.util.stream.*; class Problem { // Create a function that returns true if the last character // of a given string is an alphabetical character and is not // a par...
return false;
} }
//Filter an input array of strings only for ones that start with a given prefix. // >>> filter_by_prefix([], "a") // [] // >>> filter_by_prefix(["abc", "bcd", "cde", "array"], "a") // ["abc", "array"] function filter_by_prefix(strings, prefix){ return strings.filter( function(str){ return str.startsWith(pre...
});
}
import java.util.*; import java.lang.reflect.*; import org.javatuples.*; import java.security.*; import java.math.*; import java.io.*; import java.util.stream.*; class Problem { // This function takes an array array list l and returns an array array list l' such that // l' is identical to l in the indicies that...
int j = 0;
for (int i = 0; i < l.size(); i++) { if (i % 3 == 0) { l_s.add(l_e.get(j)); j++; } else { l_s.add(l_r.get(i - j)); } } return l_s; } }
//Given an array of integers, sort the integers that are between 1 and 9 inclusive, // reverse the resulting array, and then replace each digit by its corresponding name from // "One", "Two", "Three", "Four", "Five", "Six", "Seven", "Eight", "Nine". // For example: // >>> by_length([2, 1, 1, 4, 5, 8, 2, 3]) // ["Eight"...
}
} arr2.sort(); arr2.reverse(); var arr3 = []; for(var i = 0; i < arr2.length; i++){ var num = arr2[i]; if(num == 1){ arr3.push("One"); } else if(num == 2){ arr3.push("Two"); } else if(num == 3){ arr3.push("Three"); ...
//Given a grid with N rows and N columns (N >= 2) and a positive integer k, // each cell of the grid contains a value. Every integer in the range [1, N * N] // inclusive appears exactly once on the cells of the grid. // You have to find the minimum path of length k in the grid. You can start // from any cell, and in e...
}
if(x < n - 1){ neighbours.push(grid[x + 1][y]); } if(y > 0){ neighbours.push(grid[x][y - 1]); } if(y < n - 1){ neighbours.push(grid[x][y + 1]); } let nextCell = neighbours[0]; for(let i = 0; i < neighbours.length; i++){ ...
import java.util.*; import java.lang.reflect.*; import org.javatuples.*; import java.security.*; import java.math.*; import java.io.*; import java.util.stream.*; class Problem { // Add two numbers x and y // >>> add((2l), (3l)) // (5l) // >>> add((5l), (7l)) // (12l) public static long add(long ...
}
import java.util.*; import java.lang.reflect.*; import org.javatuples.*; import java.security.*; import java.math.*; import java.io.*; import java.util.stream.*; class Problem { // Implement a function that takes an non-negative integer and returns an array array list of the first n // integers that are prime n...
for (long j = 2l; j < i; j++) {
if (i % j == 0) { isPrime = false; break; } } if (isPrime) { arrayList.add(i); } } return arrayList; } }
//You are given a positive integer n. You have to create an integer array a of length n. // For each i (1 ≤ i ≤ n), the value of a[i] = i * i - i + 1. // Return the number of triples (a[i], a[j], a[k]) of a where i < j < k, // and a[i] + a[j] + a[k] is a multiple of 3. // Example : // >>> get_max_triples(5) // 1 // Ex...
}
import java.util.*; import java.lang.reflect.*; import org.javatuples.*; import java.security.*; import java.math.*; import java.io.*; import java.util.stream.*; class Problem { // You will be given a string of words separated by commas or spaces. Your task is // to split the string into words and return an arr...
while (st.hasMoreTokens()) {
al.add(st.nextToken()); } return al; } }
import java.util.*; import java.lang.reflect.*; import org.javatuples.*; import java.security.*; import java.math.*; import java.io.*; import java.util.stream.*; class Problem { // Add two numbers x and y // >>> add((2l), (3l)) // (5l) // >>> add((5l), (7l)) // (12l) public static long add(long ...
return x + y;
} }
from typing import List def minPath(grid: List[List[int]], k: int) -> List[int]: """ Given a grid with N rows and N columns (N >= 2) and a positive integer k, each cell of the grid contains a value. Every integer in the range [1, N * N] inclusive appears exactly once on the cells of the grid. You...
col = j
path.append(min_val) return path
import java.util.*; import java.lang.reflect.*; import org.javatuples.*; import java.security.*; import java.math.*; import java.io.*; import java.util.stream.*; class Problem { // I think we all remember that feeling when the result of some long-awaited // event is finally known. The feelings and thoughts you ...
}
}
import java.util.*; import java.lang.reflect.*; import org.javatuples.*; import java.security.*; import java.math.*; import java.io.*; import java.util.stream.*; class Problem { // You are given a word. Your task is to find the closest vowel that stands between // two consonants from the right side of the word...
if (consonants.indexOf(left) != -1 && consonants.indexOf(right) != -1) {
return String.valueOf(word.charAt(j)); } } return ""; } }
from typing import List def pairs_sum_to_zero(l: List[int]) -> bool: """ pairs_sum_to_zero takes a list of integers as an input. it returns True if there are two distinct elements in the list that sum to zero, and False otherwise. >>> pairs_sum_to_zero([1, 3, 5, 0]) False >>> pairs_sum_to_z...
return False
import java.util.*; import java.lang.reflect.*; import org.javatuples.*; import java.security.*; import java.math.*; import java.io.*; import java.util.stream.*; class Problem { // Given a string text, replace all spaces in it with underscores, // and if a string has more than 2 consecutive spaces, // the...
result = result.substring(0, i) + "-" + result.substring(i + 3);
} i++; } return result; } }
import java.util.*; import java.lang.reflect.*; import org.javatuples.*; import java.security.*; import java.math.*; import java.io.*; import java.util.stream.*; class Problem { // Given a string text, replace all spaces in it with underscores, // and if a string has more than 2 consecutive spaces, // the...
}
i++; } return result; } }
import java.util.*; import java.lang.reflect.*; import org.javatuples.*; import java.security.*; import java.math.*; import java.io.*; import java.util.stream.*; class Problem { // Write a function that takes an integer a and returns true // if this ingeger is a cube of some integer number. // Note: you ma...
return a==0l||(a>0l&&Math.pow(Math.round(Math.pow(a, 1.0/3.0)), 3)==a)||(a<0l&&Math.pow(Math.round(Math.pow(-a, 1.0/3.0)), 3)==-a);
} }
import java.util.*; import java.lang.reflect.*; import org.javatuples.*; import java.security.*; import java.math.*; import java.io.*; import java.util.stream.*; class Problem { // You are given a non-empty array list of positive integers. Return the greatest integer that is greater than // zero, and has a fre...
} else {
map.put(val, (long)1); } if (map.get(val) >= val && val > max) { max = val; } } return max; } }
import java.util.*; import java.lang.reflect.*; import org.javatuples.*; import java.security.*; import java.math.*; import java.io.*; import java.util.stream.*; class Problem { // Input is a space-delimited string of numberals from 'zero' to 'nine'. // Valid choices are 'zero', 'one', 'two', 'three', 'four', '...
HashMap<String, Integer> indexMap = new HashMap<>();
for (int i = 0; i < nums.length; i++) { indexMap.put(nums[i], i); } String [] split = numbers.split(" "); Arrays.sort(split, new Comparator<String>() { @Override public int compare(String s1, String s2) { return indexMap.get(s1) - index...
//You are given a string s. // if s[i] is a letter, reverse its case from lower to upper or vise versa, // otherwise keep it as it is. // If the string contains no letters, reverse the string. // The function should return the resulted string. // Examples // >>> solve("1234") // "4321" // >>> solve("ab") // "AB" // >>...
const swapped = s.split('').map(char => {
if(/[a-z]/i.test(char)) { return char === char.toLowerCase() ? char.toUpperCase() : char.toLowerCase(); } return char; }); return swapped.join(''); } return s.split('').reverse().join(''); }
import java.util.*; import java.lang.reflect.*; import org.javatuples.*; import java.security.*; import java.math.*; import java.io.*; import java.util.stream.*; class Problem { // Input to this function is a string representing musical notes in a special ASCII format. // Your task is to parse this string and r...
return res;
} }
//You are given a rectangular grid of wells. Each row represents a single well, // and each 1 in a row represents a single unit of water. // Each well has a corresponding bucket that can be used to extract water from it, // and all buckets have the same capacity. // Your task is to use the buckets to empty the wells. ...
sum = 0;
for(var j = 0; j < c; j++){ sum += grid[i][j]; } maxFill += Math.ceil(sum/capacity); } return maxFill; }
import java.util.*; import java.lang.reflect.*; import org.javatuples.*; import java.security.*; import java.math.*; import java.io.*; import java.util.stream.*; class Problem { // You are given an array array list of numbers. // You need to return the sum of squared numbers in the given array list, // roun...
return 0;
} long sum = 0; for (int i = 0; i < lst.size(); i++) { sum += (long)Math.ceil(lst.get(i)) * (long)Math.ceil(lst.get(i)); } return sum; } }
import java.util.*; import java.lang.reflect.*; import org.javatuples.*; import java.security.*; import java.math.*; import java.io.*; import java.util.stream.*; class Problem { // Your task is to implement a function that will simplify the expression // x * n. The function returns true if x * n evaluates to a ...
int n_denom = Integer.parseInt(n_nums[1]);
int res_num = x_num * n_num; int res_denom = x_denom * n_denom; return (res_num % res_denom == 0); } }
import java.util.*; import java.lang.reflect.*; import org.javatuples.*; import java.security.*; import java.math.*; import java.io.*; import java.util.stream.*; class Problem { // Return a greatest common divisor of two integers a and b // >>> greatestCommonDivisor((3l), (5l)) // (1l) // >>> greatestCo...
if (b == 0) {
return a; } return greatestCommonDivisor(b, a % b); } }
def correct_bracketing(brackets: str) -> bool: """ brackets is a string of "(" and ")". return True if every opening bracket has a corresponding closing bracket. >>> correct_bracketing('(') False >>> correct_bracketing('()') True >>> correct_bracketing('(()())') True >>> correct_bra...
count += 1
elif char == ')': count -= 1 if count < 0: return False return count == 0
import java.util.*; import java.lang.reflect.*; import org.javatuples.*; import java.security.*; import java.math.*; import java.io.*; import java.util.stream.*; class Problem { // Return a greatest common divisor of two integers a and b // >>> greatestCommonDivisor((3l), (5l)) // (1l) // >>> greatestCo...
return b;
} if (b == 0) { return a; } return greatestCommonDivisor(b, a % b); } }
//In this Kata, you have to sort an array of non-negative integers according to // number of ones in their binary representation in ascending order. // For similar number of ones, sort based on decimal value. // It must be implemented like this: // >>> sort_array([1, 5, 2, 3, 4]) // [1, 2, 3, 4, 5] // >>> sort_array([-...
} else {
return aBinary - bBinary; } }); }
from typing import List def skjkasdkd(lst: List[int]) -> int: """You are given a list of integers. You need to find the largest prime value and return the sum of its digits. Examples: >>> skjkasdkd([0, 3, 2, 1, 3, 5, 7, 4, 5, 5, 5, 2, 181, 32, 4, 32, 3, 2, 32, 324, 4, 3]) 10 >>> skjkasdkd([1, ...
return sum(int(j) for j in str(max(filter(lambda x: x != 1 and all(x % i for i in range(2, x // 2 + 1)), lst))))
//Imagine a road that's a perfectly straight infinitely long line. // n cars are driving left to right; simultaneously, a different set of n cars // are driving right to left. The two sets of cars start out being very far from // each other. All cars move in the same speed. Two cars are said to collide // when a c...
let num_collisions = 0;
let left_to_right = Array(n).fill(1); let right_to_left = Array(n).fill(1); for (let i = 0; i < left_to_right.length; i++) { for (let j = 0; j < right_to_left.length; j++) { if (left_to_right[i] == right_to_left[j]) { num_collisions++; } } } return num_collisions; }
//You are given an array of two strings, both strings consist of open // parentheses '(' or close parentheses ')' only. // Your job is to check if it is possible to concatenate the two strings in // some order, that the resulting string will be good. // A string S is considered to be good if and only if all parentheses...
return 'Yes';
} if (is_good(str2 + str1)){ return 'Yes'; } return 'No'; }
import java.util.*; import java.lang.reflect.*; import org.javatuples.*; import java.security.*; import java.math.*; import java.io.*; import java.util.stream.*; class Problem { // The Brazilian factorial is defined as: // brazilian_factorial(n) = n! * (n-1)! * (n-2)! * ... * 1! // where n > 0 // For ex...
long temp = n;
while (temp > 0) { local_result *= temp; temp--; } result *= local_result; n--; } return result; } }
//Given a non-empty array of integers, return the sum of all of the odd elements that are in even positions. // Examples // >>> solution([5, 8, 7, 1]) // 12 // >>> solution([3, 3, 3, 3, 3]) // 9 // >>> solution([30, 13, 24, 321]) // 0 function solution(lst){
let result = 0;
for (let i = 0; i < lst.length; i++){ if (i % 2 === 0){ if (lst[i] % 2 === 1){ result += lst[i]; } } } return result; }
import java.util.*; import java.lang.reflect.*; import org.javatuples.*; import java.security.*; import java.math.*; import java.io.*; import java.util.stream.*; class Problem { // Write a function that returns true if the given number is the multiplication of 3 prime numbers // and false otherwise. // Know...
return arr.size() == 3;
} }
//There are eight planets in our solar system: the closerst to the Sun // is Mercury, the next one is Venus, then Earth, Mars, Jupiter, Saturn, // Uranus, Neptune. // Write a function that takes two planet names as strings planet1 and planet2. // The function should return an array containing all planets whose orbit...
var position1 = keys.indexOf(planet1);
var position2 = keys.indexOf(planet2); if(position1 > position2){ var temp = position1; position1 = position2; position2 = temp; } var res = []; for(var i = position1 + 1; i < position2; i++){ res.push(keys[i]); } return res; }
def prime_length(string: str) -> bool: """Write a function that takes a string and returns True if the string length is a prime number or False otherwise Examples >>> prime_length('Hello') True >>> prime_length('abcdcba') True >>> prime_length('kittens') True >>> prime_length('or...
return False
else: return True else: return False pass
//You are given two intervals, // where each interval is a pair of integers. For example, interval = (start, end) = (1, 2). // The given intervals are closed which means that the interval (start, end) // includes both start and end. // For each given interval, it is assumed that its start is less or equal its end. // Y...
let length = end - start;
let primes = [2, 3, 5, 7, 11, 13, 17, 19, 23, 29, 31, 37, 41, 43, 47, 53, 59, 61, 67, 71, 73, 79, 83, 89, 97]; return primes.includes(length) ? "YES" : "NO"; }
import java.util.*; import java.lang.reflect.*; import org.javatuples.*; import java.security.*; import java.math.*; import java.io.*; import java.util.stream.*; class Problem { // Given an array array list of non-negative integers, return a cojava of the given array array list after sorting, // you will sort t...
}
}
import java.util.*; import java.lang.reflect.*; import org.javatuples.*; import java.security.*; import java.math.*; import java.io.*; import java.util.stream.*; class Problem { // You are given a word. Your task is to find the closest vowel that stands between // two consonants from the right side of the word...
if (j == 0 || j == word.length() - 1) continue;
char left = word.charAt(j - 1); char right = word.charAt(j + 1); if (consonants.indexOf(left) != -1 && consonants.indexOf(right) != -1) { return String.valueOf(word.charAt(j)); } } return ""; } }
import java.util.*; import java.lang.reflect.*; import org.javatuples.*; import java.security.*; import java.math.*; import java.io.*; import java.util.stream.*; class Problem { // The FibFib number sequence is a sequence similar to the Fibbonacci sequnece that's defined as follows: // fibfib(0) == 0 // fib...
if (n == 0) {
return 0; } if (n == 1) { return 0; } if (n == 2) { return 1; } long[] memo = new long[(int) n + 1]; memo[0] = 0; memo[1] = 0; memo[2] = 1; for (int i = 3; i <= n; i++) { memo[i] = memo[i - 1]...
//Given two arrays operator, and operand. The first array has basic algebra operations, and // the second array is an array of integers. Use the two given arrays to build the algebric // expression and return the evaluation of this expression. // The basic algebra operations: // Addition ( + ) // Subtraction ( - ) ...
switch(operator[count]){
case '*': operand[count] = operand[count] * operand[count + 1]; operand.splice(count + 1, 1); operator.splice(count, 1); count = 0; do_again = true; break; case '//': operand[count] = Math.floor(operand[count] / operand[count + 1]); operand.spl...
from typing import Dict def check_dict_case(dict: Dict[str, str]) -> bool: """ Given a dictionary, return True if all keys are strings in lower case or all keys are strings in upper case, else return False. The function should return False is the given dictionary is empty. Examples: >>> check_...
if any(not x.isupper() for x in dict.keys()):
return False return True
//Find the shortest palindrome that begins with a supplied string. // Algorithm idea is simple: // - Find the longest postfix of supplied string that is a palindrome. // - Append to the end of the string reverse of a string prefix that comes before the palindromic suffix. // >>> make_palindrome("") // "" // >>> make_pa...
}
i--; } return string; }
def count_upper(s: str) -> int: """ Given a string s, count the number of uppercase vowels in even indices. For example: >>> count_upper('aBCdEf') 1 >>> count_upper('abcdefg') 0 >>> count_upper('dBBE') 0 """ vowel_set = set('AEIOU')
count = 0
for i in range(0, len(s), 2): if s[i] in vowel_set: count += 1 return count """ D.1 Recursion Given a positive integer n, write a recursive function that returns the sum of the squares of the positive odd integers smaller than n. Assume n is greater than or equal to 3. """
//Given a positive integer, obtain its roman numeral equivalent as a string, // and return it in lowercase. // Restrictions: 1 <= num <= 1000 // Examples: // >>> int_to_mini_roman(19) // "xix" // >>> int_to_mini_roman(152) // "clii" // >>> int_to_mini_roman(426) // "cdxxvi" function int_to_mini_roman(number){ var r...
for (var i = 0; i < key_list.length; i++){
if (key_list[i] <= number){ output += roman_conversion[key_list[i]]; number -= key_list[i]; break; } } } return output; }
import java.util.*; import java.lang.reflect.*; import org.javatuples.*; import java.security.*; import java.math.*; import java.io.*; import java.util.stream.*; class Problem { // For a given number n, find the largest number that divides n evenly, smaller than n // >>> largestDivisor((15l)) // (5l) pu...
for (long i = 2; i <= Math.floor(Math.sqrt(n)); i++) {
if (n % i == 0) { return n / i; } } return 1; } }
//For a given array of integers, return an array consisting of a sum and a product of all the integers in an array. // Empty sum should be equal to 0 and empty product should be equal to 1. // >>> sum_product([]) // [0, 1] // >>> sum_product([1, 2, 3, 4]) // [10, 24] function sum_product(numbers){ if(numbers.length...
sum += numbers[i];
product *= numbers[i]; } return [sum, product]; }
//Your task is to write a function that returns true if a number x is a simple // power of n and false in other cases. // x is a simple power of n if n**int=x // For example: // >>> is_simple_power(1, 4) // true // >>> is_simple_power(2, 2) // true // >>> is_simple_power(8, 2) // true // >>> is_simple_power(3, 2) // fa...
if(x % n !== 0){
return false; } return is_simple_power(x/n, n); }
import java.util.*; import java.lang.reflect.*; import org.javatuples.*; import java.security.*; import java.math.*; import java.io.*; import java.util.stream.*; class Problem { // The FibFib number sequence is a sequence similar to the Fibbonacci sequnece that's defined as follows: // fibfib(0) == 0 // fib...
return 0;
} if (n == 1) { return 0; } if (n == 2) { return 1; } long[] memo = new long[(int) n + 1]; memo[0] = 0; memo[1] = 0; memo[2] = 1; for (int i = 3; i <= n; i++) { memo[i] = memo[i - 1] + memo[i - 2] + memo[...
def change_base(x: int, base: int) -> str: """Change numerical base of input number x to base. return string representation after the conversion. base numbers are less than 10. >>> change_base(8, 3) '22' >>> change_base(8, 2) '1000' >>> change_base(7, 2) '111' """ if x == 0:
return '0'
ans = [] while x != 0: ans.append(str(x % base)) x //= base return ''.join(ans[::-1])
//Given array of integers, return array in strange order. // Strange sorting, is when you start with the minimum value, // then maximum of the remaining integers, then minimum and so on. // Examples: // >>> strange_sort_list([1, 2, 3, 4]) // [1, 4, 2, 3] // >>> strange_sort_list([5, 5, 5, 5]) // [5, 5, 5, 5] // >>> str...
}
tmp.splice(tmp.indexOf(output[i]), 1); } return output; }
//Given a positive integer, obtain its roman numeral equivalent as a string, // and return it in lowercase. // Restrictions: 1 <= num <= 1000 // Examples: // >>> int_to_mini_roman(19) // "xix" // >>> int_to_mini_roman(152) // "clii" // >>> int_to_mini_roman(426) // "cdxxvi" function int_to_mini_roman(number){ var r...
500: "d",
400: "cd", 100: "c", 90: "xc", 50: "l", 40: "xl", 10: "x", 9: "ix", 5: "v", 4: "iv", 1: "i" }; var output = ""; while (number > 0){ var key_list = Object.keys(roman_conversion).map(Number); key_list.sort(function...
import java.util.*; import java.lang.reflect.*; import org.javatuples.*; import java.security.*; import java.math.*; import java.io.*; import java.util.stream.*; class Problem { // Input to this function is a string represented multiple groups for nested parentheses separated by spaces. // For each of the group...
current_depth += 1;
max_depth = Math.max(max_depth, current_depth); } else if (c == ')') { current_depth -= 1; } } result.add(max_depth); } return result; } }
def count_upper(s: str) -> int: """ Given a string s, count the number of uppercase vowels in even indices. For example: >>> count_upper('aBCdEf') 1 >>> count_upper('abcdefg') 0 >>> count_upper('dBBE') 0 """ vowel_set = set('AEIOU') count = 0 for i in range(0, le...
"""
//In this problem, you will implement a function that takes two arrays of numbers, // and determines whether it is possible to perform an exchange of elements // between them to make lst1 an array of only even numbers. // There is no limit on the number of exchanged elements between lst1 and lst2. // If it is possible ...
}
if(exchange){ return "YES"; }else{ return "NO"; } }
//Write a function that accepts an array of strings. // The array contains different words. Return the word with maximum number // of unique characters. If multiple strings have maximum number of unique // characters, return the one which comes first in lexicographical order. // >>> find_max(["name", "of", "string"]) /...
}
} } return max_unique_word; }
import java.util.*; import java.lang.reflect.*; import org.javatuples.*; import java.security.*; import java.math.*; import java.io.*; import java.util.stream.*; class Problem { // Filter an input array list of strings only for ones that contain given substring // >>> filterBySubstring((new ArrayList<String>(Ar...
return new ArrayList<String>(strings.stream().filter(s -> s.contains(substring)).collect(Collectors.toList()));
} }
def file_name_check(file_name: str) -> str: """Create a function which takes a string representing a file's name, and returns 'Yes' if the the file's name is valid, and returns 'No' otherwise. A file's name is considered to be valid if and only if all the following conditions are met: - There shoul...
s_count += 1
if i == '.': e_count += 1 if s_count > 3 or e_count != 1: return 'No' s_name = file_name.split('.')[0] e_name = file_name.split('.')[1] if not s_name or not e_name or not s_name[0].isalpha(): return 'No' if e_name not in ['txt', 'exe', 'dll']: return 'No' ...
//You are given a non-empty array of positive integers. Return the greatest integer that is greater than // zero, and has a frequency greater than or equal to the value of the integer itself. // The frequency of an integer is the number of times it appears in the array. // If no such a value exist, return -1. // Exam...
max = keys[i];
} } if (max == 0){ return -1; } return max; }
//Given array of integers, return array in strange order. // Strange sorting, is when you start with the minimum value, // then maximum of the remaining integers, then minimum and so on. // Examples: // >>> strange_sort_list([1, 2, 3, 4]) // [1, 4, 2, 3] // >>> strange_sort_list([5, 5, 5, 5]) // [5, 5, 5, 5] // >>> str...
}
var output = []; var tmp = lst.slice(); for(var i = 0; i < lst.length; i++){ if(i % 2 === 0){ output.push(Math.min.apply(null, tmp)); } else{ output.push(Math.max.apply(null, tmp)); } tmp.splice(tmp.indexOf(output[i]), 1); } return outp...
//This function takes an array l and returns an array l' such that // l' is identical to l in the odd indicies, while its values at the even indicies are equal // to the values of the even indicies of l, but sorted. // >>> sort_even([1, 2, 3]) // [1, 2, 3] // >>> sort_even([5, 6, 3, 4]) // [3, 6, 5, 4] function sort_ev...
l2.sort(function(a, b){return a - b})
for(var i = 0; i < l2.length; i++){ l[i * 2] = l2[i] } return l }
import java.util.*; import java.lang.reflect.*; import org.javatuples.*; import java.security.*; import java.math.*; import java.io.*; import java.util.stream.*; class Problem { // Return length of given string // >>> stringLength(("")) // (0l) // >>> stringLength(("abc")) // (3l) public static ...
}
//Given two arrays operator, and operand. The first array has basic algebra operations, and // the second array is an array of integers. Use the two given arrays to build the algebric // expression and return the evaluation of this expression. // The basic algebra operations: // Addition ( + ) // Subtraction ( - ) ...
case '**':
operand[count] = Math.pow(operand[count], operand[count + 1]); operand.splice(count + 1, 1); operator.splice(count, 1); count = 0; do_again = true; break; default: count++; do_again = false; } } answer = operand[0]; operand.splice(0, 1); ...
//Return true is array elements are monotonically increasing or decreasing. // >>> monotonic([1, 2, 4, 20]) // true // >>> monotonic([1, 20, 4, 10]) // false // >>> monotonic([4, 1, 0, -10]) // true function monotonic(l){ if(l.length <= 1){ return true; } if(l[0] < l[1]){ for(var i = 1; i < ...
if(l[i] > l[i + 1]){
return false; } } } else{ for(var i = 1; i < l.length - 1; i++){ if(l[i] < l[i + 1]){ return false; } } } return true; }
import java.util.*; import java.lang.reflect.*; import org.javatuples.*; import java.security.*; import java.math.*; import java.io.*; import java.util.stream.*; class Problem { // Your task is to implement a function that will simplify the expression // x * n. The function returns true if x * n evaluates to a ...
}
}
def right_angle_triangle(a: int, b: int, c: int) -> bool: """ Given the lengths of the three sides of a triangle. Return True if the three sides form a right-angled triangle, False otherwise. A right-angled triangle is a triangle in which one angle is right angle or 90 degree. Example: >>> ...
return a ** 2 + b ** 2 == c ** 2
//A simple program which should return the value of x if n is // a prime number and should return the value of y otherwise. // Examples: // >>> x_or_y(7, 34, 12) // 34 // >>> x_or_y(15, 8, 5) // 5 function x_or_y(n, x, y){ if(n<2){ return y; } for(var i=2; i<n; i++){
if(n%i==0){
return y; } } return x; }
//Return true if a given number is prime, and false otherwise. // >>> is_prime(6) // false // >>> is_prime(101) // true // >>> is_prime(11) // true // >>> is_prime(13441) // true // >>> is_prime(61) // true // >>> is_prime(4) // false // >>> is_prime(1) // false function is_prime(n){ if (n==1) { return fals...
}
from typing import List def find_max(words: List[str]) -> str: """Write a function that accepts a list of strings. The list contains different words. Return the word with maximum number of unique characters. If multiple strings have maximum number of unique characters, return the one which comes first ...
if unique_num > max_num:
max_num = unique_num max_word = word elif unique_num == max_num: if word < max_word: max_word = word return max_word
from typing import List def monotonic(l: List[int]) -> bool: """Return True is list elements are monotonically increasing or decreasing. >>> monotonic([1, 2, 4, 20]) True >>> monotonic([1, 20, 4, 10]) False >>> monotonic([4, 1, 0, -10]) True """ if l == sorted(l) or l == sorted(l, r...
return False
//In this task, you will be given a string that represents a number of apples and oranges // that are distributed in a basket of fruit this basket contains // apples, oranges, and mango fruits. Given the string that represents the total number of // the oranges and apples and an integer that represent the total numb...
let sum = num_of_apples + num_of_oranges;
return n - sum; }
//You have been tasked to write a function that receives // a hexadecimal number as a string and counts the number of hexadecimal // digits that are primes (prime number, or a prime, is a natural number // greater than 1 that is not a product of two smaller natural numbers). // Hexadecimal digits are 0, 1, 2, 3, 4, ...
result += 1;
} } return result; }
from typing import Tuple def intersection(interval1: Tuple[int, int], interval2: Tuple[int, int]) -> str: """You are given two intervals, where each interval is a pair of integers. For example, interval = (start, end) = (1, 2). The given intervals are closed which means that the interval (start, end) i...
return "YES" if end - start == 2 else "NO"
//You are given an array of integers. // You need to find the largest prime value and return the sum of its digits. // Examples: // >>> skjkasdkd([0, 3, 2, 1, 3, 5, 7, 4, 5, 5, 5, 2, 181, 32, 4, 32, 3, 2, 32, 324, 4, 3]) // 10 // >>> skjkasdkd([1, 0, 1, 8, 2, 4597, 2, 1, 3, 40, 1, 2, 1, 2, 4, 2, 5, 1]) // 25 // >>> skj...
let digits = String(max).split('');
let sum = 0; for (let i=0; i<digits.length; i++){ sum += Number(digits[i]); } return sum; }
//triples_sum_to_zero takes an array of integers as an input. // it returns true if there are three distinct elements in the array that // sum to zero, and false otherwise. // >>> triples_sum_to_zero([1, 3, 5, 0]) // false // >>> triples_sum_to_zero([1, 3, -2, 1]) // true // >>> triples_sum_to_zero([1, 2, 3, 7]) // fal...
return false;
}
import java.util.*; import java.lang.reflect.*; import org.javatuples.*; import java.security.*; import java.math.*; import java.io.*; import java.util.stream.*; class Problem { // Write a function that takes an array array list of numbers as input and returns // the number of elements in the array array list ...
public long[] getDigits(long n) {
ArrayList<Long> digits = new ArrayList<Long>(); while (n != 0) { digits.add(n % 10); n /= 10; } Collections.reverse(digits); return digits.stream().mapToLong(i -> i).toArray(); } }...
import java.util.*; import java.lang.reflect.*; import org.javatuples.*; import java.security.*; import java.math.*; import java.io.*; import java.util.stream.*; class Problem { // Given a positive integer n, you have to make a pile of n levels of stones. // The first level has n stones. // The number of st...
for (long i = 0; i < n; i++) {
levels.add(n + 2 * i); } return levels; } }
//Given a positive integer, obtain its roman numeral equivalent as a string, // and return it in lowercase. // Restrictions: 1 <= num <= 1000 // Examples: // >>> int_to_mini_roman(19) // "xix" // >>> int_to_mini_roman(152) // "clii" // >>> int_to_mini_roman(426) // "cdxxvi" function int_to_mini_roman(number){ var r...
};
var output = ""; while (number > 0){ var key_list = Object.keys(roman_conversion).map(Number); key_list.sort(function(a, b){return b-a}); for (var i = 0; i < key_list.length; i++){ if (key_list[i] <= number){ output += roman_conversion[key_list[i]]; ...