prefix stringlengths 0 918k | middle stringlengths 0 812k | suffix stringlengths 0 962k |
|---|---|---|
import java.util.*;
import java.lang.reflect.*;
import org.javatuples.*;
import java.security.*;
import java.math.*;
import java.io.*;
import java.util.stream.*;
class Problem {
// Write a function that accepts an array array list of strings.
// The array list contains different words. Return the word with maxi... | wordsToUniqueCharacters.put(word, uniqueCharacters.size()); | }
words.sort(new Comparator<String>() {
@Override
public int compare(String o1, String o2) {
int compareResult = wordsToUniqueCharacters.get(o2).compareTo(wordsToUniqueCharacters.get(o1));
if (compareResult == 0) {
return o1.com... |
def special_factorial(n: int) -> int:
"""The Brazilian factorial is defined as:
brazilian_factorial(n) = n! * (n-1)! * (n-2)! * ... * 1!
where n > 0
For example:
>>> special_factorial(4)
288
The function will receive an integer as input and should return the special
factorial of this i... | return n * special_factorial(n-1) * factorial(n-1) | |
import java.util.*;
import java.lang.reflect.*;
import org.javatuples.*;
import java.security.*;
import java.math.*;
import java.io.*;
import java.util.stream.*;
class Problem {
// Given two array lists operator, and operand. The first array list has basic algebra operations, and
// the second array list is an... | list.add(-operand.get(i + 1)); | else if (op.get(i).equals("*"))
list.set(list.size() - 1, list.get(list.size() - 1) * operand.get(i + 1));
else if (op.get(i).equals("//"))
list.set(list.size() - 1, list.get(list.size() - 1) / operand.get(i + 1));
else if (op.get(i).equals("**"))
... |
import java.util.*;
import java.lang.reflect.*;
import org.javatuples.*;
import java.security.*;
import java.math.*;
import java.io.*;
import java.util.stream.*;
class Problem {
// Evaluate whether the given number n can be written as the sum of exactly 4 positive even numbers
// Example
// >>> isEqualToSum... | if (n % 2 == 1) { | d = 1;
}
long minX = d;
long maxX = n / 4;
while (minX <= maxX) {
long x = (minX + maxX) / 2;
long y = n - 2 * x;
if (y % 2 == 1) {
y--;
}
if (2 * x + y < n) {
minX = x + 1;
... |
import java.util.*;
import java.lang.reflect.*;
import org.javatuples.*;
import java.security.*;
import java.math.*;
import java.io.*;
import java.util.stream.*;
class Problem {
// "Given an array array list representing a branch of a tree that has non-negative integer nodes
// your task is to pluck one of the ... | } | |
from typing import List, Tuple
def find_closest_elements(numbers: List[float]) -> Tuple[float, float]:
""" From a supplied list of numbers (of length at least two) select and return two that are the closest to each
other and return them in order (smaller number, larger number).
>>> find_closest_elements([1... | temp_index, temp2_index = 0, 1 | if numbers[0] > numbers[1]:
temp, temp2 = temp2, temp
temp_index, temp2_index = temp2_index, temp_index
for i in range(len(numbers)):
for j in range(i+1, len(numbers)):
if abs(numbers[i] - numbers[j]) < temp:
temp = abs(numbers[i] - numbers[j])
... |
import java.util.*;
import java.lang.reflect.*;
import org.javatuples.*;
import java.security.*;
import java.math.*;
import java.io.*;
import java.util.stream.*;
class Problem {
// Given a hash map, return true if all keys are strings in lower
// case or all keys are strings in upper case, else return false.
... | if (dict.isEmpty()) { | return false;
}
boolean allLowerCase = dict.keySet().stream().allMatch(k -> k.matches("^[a-z]+$"));
boolean allUpperCase = dict.keySet().stream().allMatch(k -> k.matches("^[A-Z]+$"));
return allLowerCase || allUpperCase;
}
} |
from typing import List
def sum_squares(lst: List[float]) -> int:
"""You are given a list of numbers.
You need to return the sum of squared numbers in the given list,
round each element in the list to the upper int(Ceiling) first.
Examples:
>>> lst([1.0, 2.0, 3.0])
14
>>> lst([1.0, 4.0, 9.0... | for i in range(len(lst)): | lst[i] = math.ceil(lst[i])
total = 0
for i in lst:
total += i**2
return total |
//Input to this function is a string representing musical notes in a special ASCII format.
// Your task is to parse this string and return array of integers corresponding to how many beats does each
// not last.
// Here is a legend:
// 'o' - whole note, lasts four beats
// 'o|' - half note, lasts two beats
// '.|' - qu... | } | });
return song;
}
|
//Given a positive integer, obtain its roman numeral equivalent as a string,
// and return it in lowercase.
// Restrictions: 1 <= num <= 1000
// Examples:
// >>> int_to_mini_roman(19)
// "xix"
// >>> int_to_mini_roman(152)
// "clii"
// >>> int_to_mini_roman(426)
// "cdxxvi"
function int_to_mini_roman(number){
var r... | 400: "cd", | 100: "c",
90: "xc",
50: "l",
40: "xl",
10: "x",
9: "ix",
5: "v",
4: "iv",
1: "i"
};
var output = "";
while (number > 0){
var key_list = Object.keys(roman_conversion).map(Number);
key_list.sort(function(a, b){return b-a})... |
import java.util.*;
import java.lang.reflect.*;
import org.javatuples.*;
import java.security.*;
import java.math.*;
import java.io.*;
import java.util.stream.*;
class Problem {
// Write a function count_nums which takes an array array list of integers and returns
// the number of elements which has a sum of di... | String str = String.valueOf(i); | int sum = 0;
if (str.startsWith("-")) {
sum = sum - (int) Character.getNumericValue(str.charAt(1));
for (int j = 2; j < str.length(); j++) {
sum = sum + (int) Character.getNumericValue(str.charAt(j));
}
} else {
... |
import java.util.*;
import java.lang.reflect.*;
import org.javatuples.*;
import java.security.*;
import java.math.*;
import java.io.*;
import java.util.stream.*;
class Problem {
// Given an array array list arr of integers, find the minimum number of elements that
// need to be changed to make the array array l... | } | |
import java.util.*;
import java.lang.reflect.*;
import org.javatuples.*;
import java.security.*;
import java.math.*;
import java.io.*;
import java.util.stream.*;
class Problem {
// You are given a positive integer n. You have to create an integer array array list a of length n.
// For each i (1 ≤ i ≤ n), the va... | for (int i = 0; i < arrayList.size(); i++) { | for (int j = i + 1; j < arrayList.size(); j++) {
for (int k = j + 1; k < arrayList.size(); k++) {
if ((arrayList.get(i) + arrayList.get(j) + arrayList.get(k)) % 3 == 0) {
count++;
}
}
}
}
... |
import java.util.*;
import java.lang.reflect.*;
import org.javatuples.*;
import java.security.*;
import java.math.*;
import java.io.*;
import java.util.stream.*;
class Problem {
// Given a string representing a space separated lowercase letters, return a hash map
// of the letter with the most repetition and co... | for (String sss : ss) { | if (hm.containsKey(sss)) {
hm.put(sss, hm.get(sss) + 1);
} else {
hm.put(sss, 1l);
}
}
long max = 0;
for (String key : hm.keySet()) {
if (hm.get(key) > max) {
m... |
//You are given two intervals,
// where each interval is a pair of integers. For example, interval = (start, end) = (1, 2).
// The given intervals are closed which means that the interval (start, end)
// includes both start and end.
// For each given interval, it is assumed that its start is less or equal its end.
// Y... | } | |
from typing import List
def below_threshold(l: List[int], t: int) -> bool:
"""Return True if all numbers in the list l are below threshold t.
>>> below_threshold([1, 2, 4, 10], 100)
True
>>> below_threshold([1, 20, 4, 10], 5)
False
"""
for num in l: | if num >= t: | return False
return True
|
import java.util.*;
import java.lang.reflect.*;
import org.javatuples.*;
import java.security.*;
import java.math.*;
import java.io.*;
import java.util.stream.*;
class Problem {
// For a given string, flip lowercase characters to uppercase and uppercase to lowercase.
// >>> flipCase(("Hello"))
// ("hELLO")
... | } | return answer;
}
} |
import java.util.*;
import java.lang.reflect.*;
import org.javatuples.*;
import java.security.*;
import java.math.*;
import java.io.*;
import java.util.stream.*;
class Problem {
// You are given a positive integer n. You have to create an integer array array list a of length n.
// For each i (1 ≤ i ≤ n), the va... | arrayList.add(i * i - i + 1); | }
for (int i = 0; i < arrayList.size(); i++) {
for (int j = i + 1; j < arrayList.size(); j++) {
for (int k = j + 1; k < arrayList.size(); k++) {
if ((arrayList.get(i) + arrayList.get(j) + arrayList.get(k)) % 3 == 0) {
count++;
... |
//In this problem, you will implement a function that takes two arrays of numbers,
// and determines whether it is possible to perform an exchange of elements
// between them to make lst1 an array of only even numbers.
// There is no limit on the number of exchanged elements between lst1 and lst2.
// If it is possible ... | num2++; | }
}
}
num1++;
}
if(exchange){
return "YES";
}else{
return "NO";
}
}
|
import java.util.*;
import java.lang.reflect.*;
import org.javatuples.*;
import java.security.*;
import java.math.*;
import java.io.*;
import java.util.stream.*;
class Problem {
// You have to write a function which validates a given date string and
// returns true if the date is valid otherwise false.
// T... | boolean valid_date = false; | if (date.equals("")) return valid_date;
String[] parts = date.split("-");
if (parts.length != 3) return valid_date;
try {
int month = Integer.parseInt(parts[0]);
int day = Integer.parseInt(parts[1]);
int year = Integer.parseInt(parts[2]);
i... |
from typing import List
def factorize(n: int) -> List[int]:
""" Return list of prime factors of given integer in the order from smallest to largest.
Each of the factors should be listed number of times corresponding to how many times it appeares in factorization.
Input number should be equal to the product... | while i <= n: | while n % i == 0:
factors.append(i)
n = n / i
i += 1
return factors
|
def greatest_common_divisor(a: int, b: int) -> int:
""" Return a greatest common divisor of two integers a and b
>>> greatest_common_divisor(3, 5)
1
>>> greatest_common_divisor(25, 15)
5
"""
| if a > b: | a, b = b, a
if a == 0:
return b
return greatest_common_divisor(b % a, a)
|
//Given a positive integer n, return the product of the odd digits.
// Return 0 if all digits are even.
// For example:
// >>> digits(1)
// 1
// >>> digits(4)
// 0
// >>> digits(235)
// 15
function digits(n){
if(!n){
return "error";
}
if(n < 0){
return "error";
}
var temp = 0;
va... | if(odd){ | return 0;
}
return prod;
}
|
import java.util.*;
import java.lang.reflect.*;
import org.javatuples.*;
import java.security.*;
import java.math.*;
import java.io.*;
import java.util.stream.*;
class Problem {
// You are given a string s.
// if s[i] is a letter, reverse its case from lower to upper or vise versa,
// otherwise keep it as ... | } | |
import java.util.*;
import java.lang.reflect.*;
import org.javatuples.*;
import java.security.*;
import java.math.*;
import java.io.*;
import java.util.stream.*;
class Problem {
// In this problem, you will implement a function that takes two array lists of numbers,
// and determines whether it is possible to p... | } | } |
import java.util.*;
import java.lang.reflect.*;
import org.javatuples.*;
import java.security.*;
import java.math.*;
import java.io.*;
import java.util.stream.*;
class Problem {
// This function takes an array array list l and returns an array array list l' such that
// l' is identical to l in the odd indicies,... | evenIndexed.add(num); | }
index++;
}
Collections.sort(evenIndexed);
index = 0;
for (Long num : l) {
if (index % 2 == 0) {
res.add(evenIndexed.get(0));
evenIndexed.remove(0);
} else {
res.add(num);
}
... |
import java.util.*;
import java.lang.reflect.*;
import org.javatuples.*;
import java.security.*;
import java.math.*;
import java.io.*;
import java.util.stream.*;
class Problem {
// Write a function that accepts an array array list of strings as a parameter,
// deletes the strings that have odd lengths from it,
... | } | return s1.length() - s2.length();
}
});
return result;
}
} |
def strlen(string: str) -> int:
""" Return length of given string
>>> strlen('')
0
>>> strlen('abc')
3
"""
length = 0 | for char in string: | length += 1
return length
|
import java.util.*;
import java.lang.reflect.*;
import org.javatuples.*;
import java.security.*;
import java.math.*;
import java.io.*;
import java.util.stream.*;
class Problem {
// Given array list of integers, return array list in strange order.
// Strange sorting, is when you start with the minimum value,
... | Collections.sort(sorted); | int min = 0;
int max = sorted.size() - 1;
while (min <= max) {
result.add(sorted.get(min));
min++;
if (min <= max) {
result.add(sorted.get(max));
max--;
}
}
return result;
}
} |
//Evaluate whether the given number n can be written as the sum of exactly 4 positive even numbers
// Example
// >>> is_equal_to_sum_even(4)
// false
// >>> is_equal_to_sum_even(6)
// false
// >>> is_equal_to_sum_even(8)
// true
function is_equal_to_sum_even(n){
let m =0;
for(let i=2;i<n;i+=2){
for(let ... | } | if(m==1){
return true;
}
else{
return false;
}
} |
import java.util.*;
import java.lang.reflect.*;
import org.javatuples.*;
import java.security.*;
import java.math.*;
import java.io.*;
import java.util.stream.*;
class Problem {
// You are given a word. Your task is to find the closest vowel that stands between
// two consonants from the right side of the word... | return String.valueOf(word.charAt(j)); | }
}
return "";
}
} |
def greatest_common_divisor(a: int, b: int) -> int:
""" Return a greatest common divisor of two integers a and b
>>> greatest_common_divisor(3, 5)
1
>>> greatest_common_divisor(25, 15)
5
"""
if a > b:
a, b = b, a
if a == 0: | return b | return greatest_common_divisor(b % a, a)
|
//Return a greatest common divisor of two integers a and b
// >>> greatest_common_divisor(3, 5)
// 1
// >>> greatest_common_divisor(25, 15)
// 5
function greatest_common_divisor(a, b){
let max = Math.max(a, b)
let min = Math.min(a, b)
if (max % min == 0) { | return min | } else {
return greatest_common_divisor(min, max % min)
}
}
|
import java.util.*;
import java.lang.reflect.*;
import org.javatuples.*;
import java.security.*;
import java.math.*;
import java.io.*;
import java.util.stream.*;
class Problem {
// Implement the function f that takes n as a parameter,
// and returns an array array list of size n, such that the value of the elem... | } | } else {
v = (i * (i + 1l)) / 2l;
}
ret.add(v);
}
return ret;
}
} |
from typing import Union
def compare_one(a: Union[int, float, str], b: Union[int, float, str]) -> Union[int, float, str, None]:
"""
Create a function that takes integers, floats, or strings representing
real numbers, and returns the larger variable in its given variable type.
Return None if the values ... | return None | elif isinstance(a, str) and isinstance(b, str):
a_tmp = a.replace(',', '.')
b_tmp = b.replace(',', '.')
if float(a_tmp) > float(b_tmp):
return a
elif float(a_tmp) < float(b_tmp):
return b
else:
return None
elif isinstance(a, int) and is... |
from typing import List
def parse_nested_parens(paren_string: str) -> List[int]:
""" Input to this function is a string represented multiple groups for nested parentheses separated by spaces.
For each of the group, output the deepest level of nesting of parentheses.
E.g. (()()) has maximum two levels of ne... | max_depth = 0 | current_depth = 0
for paren in parens:
if paren == '(':
current_depth += 1
max_depth = max(max_depth, current_depth)
elif paren == ')':
current_depth -= 1
result.append(max_depth)
return result
|
import java.util.*;
import java.lang.reflect.*;
import org.javatuples.*;
import java.security.*;
import java.math.*;
import java.io.*;
import java.util.stream.*;
class Problem {
// Return a string containing space-delimited numbers starting from 0 upto n inclusive.
// >>> stringSequence((0l))
// ("0")
/... | for (long i = 0; i <= n; i++) { | result += i + " ";
}
return result.trim();
}
} |
//Return the number of times the digit 7 appears in integers less than n which are divisible by 11 or 13.
// >>> fizz_buzz(50)
// 0
// >>> fizz_buzz(78)
// 2
// >>> fizz_buzz(79)
// 3
function fizz_buzz(n){
let result = 0;
for(let i = 0; i < n; i++){
if(i % 11 === 0 || i % 13 === 0){
let arr... | } | }
}
return result;
}
|
//Input to this function is a string containing multiple groups of nested parentheses. Your goal is to
// separate those group into separate strings and return the array of those.
// Separate groups are balanced (each open brace is properly closed) and not nested within each other
// Ignore any spaces in the input stri... | groups.push(group); | group = '';
}
}
return groups;
}
|
//This function takes an array l and returns an array l' such that
// l' is identical to l in the indicies that are not divisible by three, while its values at the indicies that are divisible by three are equal
// to the values of the corresponding indicies of l, but sorted.
// >>> sort_third([1, 2, 3])
// [1, 2, 3]
//... | if(i%3==0){ | x[i]=y[k];
k=k+1;
}
}
return x;
} |
from typing import Tuple
def intersection(interval1: Tuple[int, int], interval2: Tuple[int, int]) -> str:
"""You are given two intervals,
where each interval is a pair of integers. For example, interval = (start, end) = (1, 2).
The given intervals are closed which means that the interval (start, end)
i... | end = min(interval1[1], interval2[1]) | if start > end:
return "NO"
return "YES" if end - start == 2 else "NO"
|
//Input are two strings a and b consisting only of 1s and 0s.
// Perform binary XOR on these inputs and return result also as a string.
// >>> string_xor("010", "110")
// "100"
function string_xor(a, b){
var arrayA = [];
var arrayB = [];
var arrayXOR = [];
var result = '';
for (var i = 0; i < a.length; i++) {... | return result; | } |
from typing import List
def monotonic(l: List[int]) -> bool:
"""Return True is list elements are monotonically increasing or decreasing.
>>> monotonic([1, 2, 4, 20])
True
>>> monotonic([1, 20, 4, 10])
False
>>> monotonic([4, 1, 0, -10])
True
"""
| if l == sorted(l) or l == sorted(l, reverse=True): | return True
return False
|
import java.util.*;
import java.lang.reflect.*;
import org.javatuples.*;
import java.security.*;
import java.math.*;
import java.io.*;
import java.util.stream.*;
class Problem {
// Given an array array list arr of integers, find the minimum number of elements that
// need to be changed to make the array array l... | last--; | }
return count;
}
} |
//Write a function that takes a string and returns true if the string
// length is a prime number or false otherwise
// Examples
// >>> prime_length("Hello")
// true
// >>> prime_length("abcdcba")
// true
// >>> prime_length("kittens")
// true
// >>> prime_length("orange")
// false
function prime_length(string){
le... | return true; | } else {
return false;
}
} |
from typing import Union
def rounded_avg(n: int, m: int) -> Union[str, int]:
"""You are given two positive integers n and m, and your task is to compute the
average of the integers from n through m (including n and m).
Round the answer to the nearest integer and convert that to binary.
If n is greater... | return(bin(rounded_avg)) | else:
return(-1) |
//Task
// We are given two strings s and c, you have to deleted all the characters in s that are equal to any character in c
// then check if the result string is palindrome.
// A string is called palindrome if it reads the same backward as forward.
// You should return an array containing the result string and true/fa... | if (filterString === filterStringReverse) { | result.push(filterString, true);
} else {
result.push(filterString, false);
}
return result;
} |
//Given an array arr of integers, find the minimum number of elements that
// need to be changed to make the array palindromic. A palindromic array is an array that
// is read the same backwards and forwards. In one change, you can change one element to any other element.
// For example:
// >>> smallest_change([1, 2, 3... | if(arr[i] != arr[arr.length - 1 - i]){ | changes++;
}
}
return changes;
} |
//Return true is array elements are monotonically increasing or decreasing.
// >>> monotonic([1, 2, 4, 20])
// true
// >>> monotonic([1, 20, 4, 10])
// false
// >>> monotonic([4, 1, 0, -10])
// true
function monotonic(l){
if(l.length <= 1){
return true;
}
if(l[0] < l[1]){
for(var i = 1; i < ... | for(var i = 1; i < l.length - 1; i++){ | if(l[i] < l[i + 1]){
return false;
}
}
}
return true;
}
|
from typing import List
def parse_nested_parens(paren_string: str) -> List[int]:
""" Input to this function is a string represented multiple groups for nested parentheses separated by spaces.
For each of the group, output the deepest level of nesting of parentheses.
E.g. (()()) has maximum two levels of ne... | elif paren == ')': | current_depth -= 1
result.append(max_depth)
return result
|
def int_to_mini_roman(number: int) -> str:
"""
Given a positive integer, obtain its roman numeral equivalent as a string,
and return it in lowercase.
Restrictions: 1 <= num <= 1000
Examples:
>>> int_to_mini_roman(19)
'xix'
>>> int_to_mini_roman(152)
'clii'
>>> int_to_mini_roman(... | 500: 'd', | 400: 'cd',
100: 'c',
90: 'xc',
50: 'l',
40: 'xl',
10: 'x',
9: 'ix',
5: 'v',
4: 'iv',
1: 'i'
}
roman_numeral = ''
for key in sorted(roman_numerals.keys(), reverse=True):
roman_numeral += roman_numerals[key] * (number // k... |
//It is the last week of the semester and the teacher has to give the grades
// to students. The teacher has been making her own algorithm for grading.
// The only problem is, she has lost the code she used for grading.
// She has given you an array of GPAs for some students and you have to write
// a function that ca... | } | else if (grades[i] > 2.3){
grades_array.push("B-");
}
else if (grades[i] > 2.0){
grades_array.push("C+");
}
else if (grades[i] > 1.7){
grades_array.push("C");
}
else if (grades[i] > 1.3){
grades_array.push("C-");
... |
//Find how many times a given substring can be found in the original string. Count overlaping cases.
// >>> how_many_times("", "a")
// 0
// >>> how_many_times("aaa", "a")
// 3
// >>> how_many_times("aaaa", "aa")
// 3
function how_many_times(string, substring){
var i = 0;
var count = 0;
while(string.indexOf(substring... | count++; | i = string.indexOf(substring, i) + 1;
}
return count;
} |
import java.util.*;
import java.lang.reflect.*;
import org.javatuples.*;
import java.security.*;
import java.math.*;
import java.io.*;
import java.util.stream.*;
class Problem {
// Create a function which takes a string representing a file's name, and returns
// 'Yes' if the the file's name is valid, and return... | } | String name = tokens[0];
int count = 0;
for (int i = 0; i < name.length(); i++) {
if (Character.isDigit(name.charAt(i))) {
count++;
}
}
if (count > 3) {
return result;
}
if (name.length() == 0) {
retu... |
def circular_shift(x: int, shift: int) -> str:
"""Circular shift the digits of the integer x, shift the digits right by shift
and return the result as a string.
If shift > number of digits, return digits reversed.
>>> circular_shift(12, 1)
'21'
>>> circular_shift(12, 2)
'12'
"""
| temp = list(str(x)) | if shift > len(temp):
return ''.join(reversed(temp))
else:
return ''.join(temp[-shift:] + temp[:-shift])
|
//Create a function that returns true if the last character
// of a given string is an alphabetical character and is not
// a part of a word, and false otherwise.
// Note: "word" is a group of characters separated by space.
// Examples:
// >>> check_if_last_char_is_a_letter("apple pie")
// false
// >>> check_if_last_ch... | return false; | } |
from typing import List
def words_string(s: str) -> List[str]:
"""
You will be given a string of words separated by commas or spaces. Your task is
to split the string into words and return an array of the words.
For example:
>>> words_string('Hi, my name is John')
['Hi', 'my', 'name', 'is'... | return s.split() | |
//You are given an array of integers.
// You need to find the largest prime value and return the sum of its digits.
// Examples:
// >>> skjkasdkd([0, 3, 2, 1, 3, 5, 7, 4, 5, 5, 5, 2, 181, 32, 4, 32, 3, 2, 32, 324, 4, 3])
// 10
// >>> skjkasdkd([1, 0, 1, 8, 2, 4597, 2, 1, 3, 40, 1, 2, 1, 2, 4, 2, 5, 1])
// 25
// >>> skj... | return sum; | } |
//prime_fib returns n-th number that is a Fibonacci number and it's also prime.
// >>> prime_fib(1)
// 2
// >>> prime_fib(2)
// 3
// >>> prime_fib(3)
// 5
// >>> prime_fib(4)
// 13
// >>> prime_fib(5)
// 89
function prime_fib(n){
function isPrime(number){
if(number <= 3){
return number > 1;
... | } | var res = 0;
var fibNum = 0;
while(res < n){
if(isPrime(fib(fibNum))){
res++;
}
fibNum++;
}
return fib(fibNum - 1);
} |
def fib4(n: int) -> int:
"""The Fib4 number sequence is a sequence similar to the Fibbonacci sequnece that's defined as follows:
fib4(0) -> 0
fib4(1) -> 0
fib4(2) -> 2
fib4(3) -> 0
fib4(n) -> fib4(n-1) + fib4(n-2) + fib4(n-3) + fib4(n-4).
Please write a function to efficiently compute the n-... | elif n == 2: | return 2
elif n == 3:
return 0
else:
return fib4(n-1) + fib4(n-2) + fib4(n-3) + fib4(n-4)
|
//Given a positive integer, obtain its roman numeral equivalent as a string,
// and return it in lowercase.
// Restrictions: 1 <= num <= 1000
// Examples:
// >>> int_to_mini_roman(19)
// "xix"
// >>> int_to_mini_roman(152)
// "clii"
// >>> int_to_mini_roman(426)
// "cdxxvi"
function int_to_mini_roman(number){
var r... | 50: "l", | 40: "xl",
10: "x",
9: "ix",
5: "v",
4: "iv",
1: "i"
};
var output = "";
while (number > 0){
var key_list = Object.keys(roman_conversion).map(Number);
key_list.sort(function(a, b){return b-a});
for (var i = 0; i < key_list.length; i++){
... |
def largest_prime_factor(n: int) -> int:
"""Return the largest prime factor of n. Assume n > 1 and is not a prime.
>>> largest_prime_factor(13195)
29
>>> largest_prime_factor(2048)
2
"""
largest = 1
factor = 2
while factor < n:
if n % factor == 0: | largest = factor | while n % factor == 0:
n = n // factor
factor += 1
return max(largest, n)
|
def fib(n: int) -> int:
"""Return n-th Fibonacci number.
>>> fib(10)
55
>>> fib(1)
1
>>> fib(8)
21
"""
assert n >= 1 | f0, f1 = 0, 1 | for i in range(n - 1):
f0, f1 = f1, f0 + f1
return f1
|
//prime_fib returns n-th number that is a Fibonacci number and it's also prime.
// >>> prime_fib(1)
// 2
// >>> prime_fib(2)
// 3
// >>> prime_fib(3)
// 5
// >>> prime_fib(4)
// 13
// >>> prime_fib(5)
// 89
function prime_fib(n){
| function isPrime(number){ | if(number <= 3){
return number > 1;
}
else if(number % 2 == 0 || number % 3 == 0){
return false;
}
else{
for(var i = 5; i * i <= number; i += 6){
if(number % i == 0 || number % (i + 2) == 0){
return false;
... |
//Given an object, return true if all keys are strings in lower
// case or all keys are strings in upper case, else return false.
// The function should return false is the given object is empty.
// Examples:
// >>> check_dict_case({"a": "apple", "b": "banana"})
// true
// >>> check_dict_case({"a": "apple", "A": "bana... | } | else if (case_type == 1){
if (key != key.toUpperCase()){
return false;
}
}
else if (case_type == 0){
if (key != key.toLowerCase()){
return false;
}
}
}
... |
import java.util.*;
import java.lang.reflect.*;
import org.javatuples.*;
import java.security.*;
import java.math.*;
import java.io.*;
import java.util.stream.*;
class Problem {
// Given the lengths of the three sides of a triangle. Return the area of
// the triangle rounded to 2 decimal points if the three sid... | return (float)Math.round(area * 100) / 100; | }
return -1;
}
} |
def correct_bracketing(brackets: str) -> bool:
""" brackets is a string of "(" and ")".
return True if every opening bracket has a corresponding closing bracket.
>>> correct_bracketing('(')
False
>>> correct_bracketing('()')
True
>>> correct_bracketing('(()())')
True
>>> correct_bra... | return count == 0 | |
//You'll be given a string of words, and your task is to count the number
// of boredoms. A boredom is a sentence that starts with the word "I".
// Sentences are delimited by '.', '?' or '!'.
// For example:
// >>> is_bored("Hello world")
// 0
// >>> is_bored("The sky is blue. The sun is shining. I love this weather")
... | let lines = S.split(/[.?!]/); | let boredoms = 0;
for (let line of lines){
if(line.match(/^\s*I /)){
boredoms++;
}
}
return boredoms;
}
|
//Return length of given string
// >>> strlen("")
// 0
// >>> strlen("abc")
// 3
function strlen(string){
| return string.length; | }
|
def is_simple_power(x: int, n: int) -> bool:
"""Your task is to write a function that returns true if a number x is a simple
power of n and false in other cases.
x is a simple power of n if n**int=x
For example:
>>> is_simple_power(1, 4)
true
>>> is_simple_power(2, 2)
true
>>> is_sim... | return False | else:
while x > 1:
if x % n != 0:
return False
x /= n
return True
|
import java.util.*;
import java.lang.reflect.*;
import org.javatuples.*;
import java.security.*;
import java.math.*;
import java.io.*;
import java.util.stream.*;
class Problem {
// The Brazilian factorial is defined as:
// brazilian_factorial(n) = n! * (n-1)! * (n-2)! * ... * 1!
// where n > 0
// For ex... | result *= local_result; | n--;
}
return result;
}
} |
import java.util.*;
import java.lang.reflect.*;
import org.javatuples.*;
import java.security.*;
import java.math.*;
import java.io.*;
import java.util.stream.*;
class Problem {
// "Given an array array list representing a branch of a tree that has non-negative integer nodes
// your task is to pluck one of the ... | return newArr; | }
newArr.add(minValue);
newArr.add((long)minIndex);
return newArr;
}
} |
import java.util.*;
import java.lang.reflect.*;
import org.javatuples.*;
import java.security.*;
import java.math.*;
import java.io.*;
import java.util.stream.*;
class Problem {
// Write a function that accepts an array array list of strings.
// The array list contains different words. Return the word with maxi... | } | wordsToUniqueCharacters.put(word, uniqueCharacters.size());
}
words.sort(new Comparator<String>() {
@Override
public int compare(String o1, String o2) {
int compareResult = wordsToUniqueCharacters.get(o2).compareTo(wordsToUniqueCharacters.get(o1));
... |
import java.util.*;
import java.lang.reflect.*;
import org.javatuples.*;
import java.security.*;
import java.math.*;
import java.io.*;
import java.util.stream.*;
class Problem {
// Given an array array list arr of integers, find the minimum number of elements that
// need to be changed to make the array array l... | return count; | }
} |
import java.util.*;
import java.lang.reflect.*;
import org.javatuples.*;
import java.security.*;
import java.math.*;
import java.io.*;
import java.util.stream.*;
class Problem {
// Write a function that returns true if the object q will fly, and false otherwise.
// The object q will fly if it's balanced (it is ... | } | for (int i = 0; i < q.size() / 2; i++) {
if (q.get(i) != q.get(q.size() - 1 - i)) {
return false;
}
}
return true;
}
} |
//Given an array of integers nums, find the minimum sum of any non-empty sub-array
// of nums.
// Example
// >>> minSubArraySum([2, 3, 4, 1, 2, 4])
// 1
// >>> minSubArraySum([-1, -2, -3])
// -6
function minSubArraySum(nums){
let sum = 0;
let minSum = nums[0];
for(let i = 0; i < nums.length; i++){
s... | if(sum < minSum){ | minSum = sum;
}
if(sum > 0){
sum = 0;
}
}
return minSum;
}
|
import java.util.*;
import java.lang.reflect.*;
import org.javatuples.*;
import java.security.*;
import java.math.*;
import java.io.*;
import java.util.stream.*;
class Problem {
// Write a function that takes a message, and encodes in such a
// way that it swaps case of all letters, replaces all vowels in
... | char[] arr = message.toCharArray(); | char[] vowels = "AEIOUaeiou".toCharArray();
for (int i = 0; i < arr.length; i++) {
if (Arrays.binarySearch(vowels, arr[i]) > -1) {
arr[i] = (char) (arr[i] + 2);
}
if (Character.isUpperCase(arr[i])) {
arr[i] = Character.toLowerCase(arr[i... |
import java.util.*;
import java.lang.reflect.*;
import org.javatuples.*;
import java.security.*;
import java.math.*;
import java.io.*;
import java.util.stream.*;
class Problem {
// Imagine a road that's a perfectly straight infinitely long line.
// n cars are driving left to right; simultaneously, a different ... | BigInteger nBigInteger = BigInteger.valueOf(n); | BigInteger nSquared = nBigInteger.multiply(nBigInteger);
return nSquared.longValue();
}
} |
import java.util.*;
import java.lang.reflect.*;
import org.javatuples.*;
import java.security.*;
import java.math.*;
import java.io.*;
import java.util.stream.*;
class Problem {
// You are given an array array list of two strings, both strings consist of open
// parentheses '(' or close parentheses ')' only.
... | } | |
def correct_bracketing(brackets: str) -> bool:
""" brackets is a string of "(" and ")".
return True if every opening bracket has a corresponding closing bracket.
>>> correct_bracketing('(')
False
>>> correct_bracketing('()')
True
>>> correct_bracketing('(()())')
True
>>> correct_bra... | elif char == ')': | count -= 1
if count < 0:
return False
return count == 0
|
//Given a positive integer n, return an array that has the number of even and odd
// integer palindromes that fall within the range(1, n), inclusive.
// Example 1:
// >>> even_odd_palindrome(3)
// [1, 2]
// Explanation:
// Integer palindrome are 1, 2, 3. one of them is even, and two of them are odd.
// Example 2:
// >>... | var isPalindrome = function(x){ | var y = x.toString().split('').reverse().join('');
return y == x;
}
for(var i = 1; i <= n; i++){
if(isPalindrome(i)){
pal.push(i);
}
}
var odd = 0;
var even = 0;
for(var i = 0; i < pal.length; i++){
if(pal[i] % 2 == 0){
even++;
... |
import java.util.*;
import java.lang.reflect.*;
import org.javatuples.*;
import java.security.*;
import java.math.*;
import java.io.*;
import java.util.stream.*;
class Problem {
// You are given a word. Your task is to find the closest vowel that stands between
// two consonants from the right side of the word... | int j = idx.get(i); | if (j == 0 || j == word.length() - 1) continue;
char left = word.charAt(j - 1);
char right = word.charAt(j + 1);
if (consonants.indexOf(left) != -1 && consonants.indexOf(right) != -1) {
return String.valueOf(word.charAt(j));
}
}
... |
import java.util.*;
import java.lang.reflect.*;
import org.javatuples.*;
import java.security.*;
import java.math.*;
import java.io.*;
import java.util.stream.*;
class Problem {
// Given an array array list of strings, where each string consists of only digits, return an array array list.
// Each element i of t... | } | return res;
}
} |
//Write a function that accepts an array of strings.
// The array contains different words. Return the word with maximum number
// of unique characters. If multiple strings have maximum number of unique
// characters, return the one which comes first in lexicographical order.
// >>> find_max(["name", "of", "string"])
/... | max_unique_word = word; | max_unique = unique_word;
}
else if(Object.keys(unique_word).length === Object.keys(max_unique).length){
if(word < max_unique_word){
max_unique_word = word;
max_unique = unique_word;
}
}
}
return max_unique_word;
} |
from typing import List
def strange_sort_list(lst: List[int]) -> List[int]:
"""
Given list of integers, return list in strange order.
Strange sorting, is when you start with the minimum value,
then maximum of the remaining integers, then minimum and so on.
Examples:
>>> strange_sort_list([1, 2... | break | out.append(lst.pop())
return out |
import java.util.*;
import java.lang.reflect.*;
import org.javatuples.*;
import java.security.*;
import java.math.*;
import java.io.*;
import java.util.stream.*;
class Problem {
// Return median of elements in the array list l.
// >>> median((new ArrayList<Long>(Arrays.asList((long)3l, (long)1l, (long)2l, (long... | } | } |
//Write a function that takes a string and returns true if the string
// length is a prime number or false otherwise
// Examples
// >>> prime_length("Hello")
// true
// >>> prime_length("abcdcba")
// true
// >>> prime_length("kittens")
// true
// >>> prime_length("orange")
// false
function prime_length(string){
le... | if (primes.includes(length)){ | return true;
} else {
return false;
}
} |
import java.util.*;
import java.lang.reflect.*;
import org.javatuples.*;
import java.security.*;
import java.math.*;
import java.io.*;
import java.util.stream.*;
class Problem {
// You are given 2 words. You need to return true if the second word or any of its rotations is a substring in the first word
// >>> c... | } | } |
import java.util.*;
import java.lang.reflect.*;
import org.javatuples.*;
import java.security.*;
import java.math.*;
import java.io.*;
import java.util.stream.*;
class Problem {
// You are given a string s.
// if s[i] is a letter, reverse its case from lower to upper or vise versa,
// otherwise keep it as ... | return sb.toString(); | }
} |
import java.util.*;
import java.lang.reflect.*;
import org.javatuples.*;
import java.security.*;
import java.math.*;
import java.io.*;
import java.util.stream.*;
class Problem {
// A simple program which should return the value of x if n is
// a prime number and should return the value of y otherwise.
// E... | } | }
} |
//Input are two strings a and b consisting only of 1s and 0s.
// Perform binary XOR on these inputs and return result also as a string.
// >>> string_xor("010", "110")
// "100"
function string_xor(a, b){
var arrayA = [];
var arrayB = [];
var arrayXOR = [];
var result = '';
for (var i = 0; i < a.length; i++) {... | result = arrayXOR.join(''); | return result;
} |
//Input is a space-delimited string of numberals from 'zero' to 'nine'.
// Valid choices are 'zero', 'one', 'two', 'three', 'four', 'five', 'six', 'seven', 'eight' and 'nine'.
// Return the string with numbers sorted from smallest to largest
// >>> sort_numbers("three one five")
// "one three five"
function sort_number... | var numString = numbers.split(" "); | var numMap = {
"zero": 0,
"one": 1,
"two": 2,
"three": 3,
"four": 4,
"five": 5,
"six": 6,
"seven": 7,
"eight": 8,
"nine": 9
};
numString.sort(function(a, b){
return numMap[a] - numMap[b];
});
numString = numString.join(" ");
return numString;
} |
def int_to_mini_roman(number: int) -> str:
"""
Given a positive integer, obtain its roman numeral equivalent as a string,
and return it in lowercase.
Restrictions: 1 <= num <= 1000
Examples:
>>> int_to_mini_roman(19)
'xix'
>>> int_to_mini_roman(152)
'clii'
>>> int_to_mini_roman(... | roman_numerals = { | 1000: 'm',
900: 'cm',
500: 'd',
400: 'cd',
100: 'c',
90: 'xc',
50: 'l',
40: 'xl',
10: 'x',
9: 'ix',
5: 'v',
4: 'iv',
1: 'i'
}
roman_numeral = ''
for key in sorted(roman_numerals.keys(), reverse=True):
... |
from typing import List, Tuple
def get_row(lst: List[List[int]], x: int) -> List[Tuple[int, int]]:
"""
You are given a 2 dimensional data, as a nested lists,
which is similar to matrix, however, unlike matrices,
each row may contain a different number of columns.
Given lst, and integer x, find inte... | res = [(i, j) for i in range(len(lst)) for j in range(len(lst[i])) if lst[i][j] == x] | res.sort(key=lambda t: (t[0], -t[1]))
return res
|
import java.util.*;
import java.lang.reflect.*;
import org.javatuples.*;
import java.security.*;
import java.math.*;
import java.io.*;
import java.util.stream.*;
class Problem {
// prime_fib returns n-th number that is a Fibonacci number and it's also prime.
// >>> primeFib((1l))
// (2l)
// >>> primeFib... | } | } |
import java.util.*;
import java.lang.reflect.*;
import org.javatuples.*;
import java.security.*;
import java.math.*;
import java.io.*;
import java.util.stream.*;
class Problem {
// Return the largest prime factor of n. Assume n > 1 and is not a prime.
// >>> largestPrimeFactor((13195l))
// (29l)
// >>> ... | long x = n; | for (long i = 2; i * i <= x; i++) {
if (x % i == 0) {
primes.add(i);
x /= i;
i--;
}
}
if (x > 1) {
primes.add(x);
}
return primes.get(primes.size() - 1);
}
} |
import java.util.*;
import java.lang.reflect.*;
import org.javatuples.*;
import java.security.*;
import java.math.*;
import java.io.*;
import java.util.stream.*;
class Problem {
// prime_fib returns n-th number that is a Fibonacci number and it's also prime.
// >>> primeFib((1l))
// (2l)
// >>> primeFib... | while (count != n) { | long tmp = fib;
fib += prev;
prev = tmp;
if (BigInteger.valueOf(fib).isProbablePrime(1)) {
count++;
}
}
return fib;
}
} |
//You are given an array arr of integers and you need to return
// sum of magnitudes of integers multiplied by product of all signs
// of each number in the array, represented by 1, -1 or 0.
// Note: return undefined for empty arr.
// Example:
// >>> prod_signs([1, 2, 2, -4])
// 9
// >>> prod_signs([0, 1])
// 0
// >>> ... | } | total *= pro;
return total;
}
}
|
import java.util.*;
import java.lang.reflect.*;
import org.javatuples.*;
import java.security.*;
import java.math.*;
import java.io.*;
import java.util.stream.*;
class Problem {
// You are given 2 words. You need to return true if the second word or any of its rotations is a substring in the first word
// >>> c... | found = a.contains(b); | if (found) break;
}
return found;
}
} |
//You are given a word. Your task is to find the closest vowel that stands between
// two consonants from the right side of the word (case sensitive).
// Vowels in the beginning and ending doesn't count. Return empty string if you didn't
// find any vowel met the above condition.
// You may assume that the given stri... | if (!vowels.includes(word[i-1]) && !vowels.includes(word[i+1])) { | result.push(word[i]);
}
}
}
i--;
}
if (result.length === 0) {
return ""
} else {
return result[0];
}
}
} |
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