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//You are given an array arr of integers and you need to return // sum of magnitudes of integers multiplied by product of all signs // of each number in the array, represented by 1, -1 or 0. // Note: return undefined for empty arr. // Example: // >>> prod_signs([1, 2, 2, -4]) // 9 // >>> prod_signs([0, 1]) // 0 // >>> ...
}
else if(arr[i] == 0){ pro *= 0; } } total *= pro; return total; } }
import java.util.*; import java.lang.reflect.*; import org.javatuples.*; import java.security.*; import java.math.*; import java.io.*; import java.util.stream.*; class Problem { // You are given a non-empty array list of positive integers. Return the greatest integer that is greater than // zero, and has a fre...
map.put(val, (long)1);
} if (map.get(val) >= val && val > max) { max = val; } } return max; } }
//Return a string containing space-delimited numbers starting from 0 upto n inclusive. // >>> string_sequence(0) // "0" // >>> string_sequence(5) // "0 1 2 3 4 5" function string_sequence(n){
let arr = [];
for(let i = 0; i <= n; i++){ arr.push(i); } return arr.join(" "); }
def is_happy(s: str) -> bool: """You are given a string s. Your task is to check if the string is happy or not. A string is happy if its length is at least 3 and every 3 consecutive letters are distinct For example: >>> is_happy(a) False >>> is_happy(aa) False >>> is_happy(abcd) ...
return False
return True
//You are given an array of two strings, both strings consist of open // parentheses '(' or close parentheses ')' only. // Your job is to check if it is possible to concatenate the two strings in // some order, that the resulting string will be good. // A string S is considered to be good if and only if all parentheses...
stack.pop();
} } return stack.length === 0; }; const str1 = lst[0]; const str2 = lst[1]; if (is_good(str1 + str2)){ return 'Yes'; } if (is_good(str2 + str1)){ return 'Yes'; } return 'No'; }
import java.util.*; import java.lang.reflect.*; import org.javatuples.*; import java.security.*; import java.math.*; import java.io.*; import java.util.stream.*; class Problem { // Create a function which takes a string representing a file's name, and returns // 'Yes' if the the file's name is valid, and return...
return result;
} if (name.length() == 0) { return result; } if (!Character.isLetter(name.charAt(0))) { return result; } return "Yes"; } }
import java.util.*; import java.lang.reflect.*; import org.javatuples.*; import java.security.*; import java.math.*; import java.io.*; import java.util.stream.*; class Problem { // Given a positive integer, obtain its roman numeral equivalent as a string, // and return it in lowercase. // Restrictions: 1 <=...
}
}
from typing import List def get_positive(l: List[int]) -> List[int]: """Return only positive numbers in the list. >>> get_positive([-1, 2, -4, 5, 6]) [2, 5, 6] >>> get_positive([5, 3, -5, 2, -3, 3, 9, 0, 123, 1, -10]) [5, 3, 2, 3, 9, 123, 1] """ p = [] for i in l:
if i > 0:
p.append(i) return p
//Given a grid with N rows and N columns (N >= 2) and a positive integer k, // each cell of the grid contains a value. Every integer in the range [1, N * N] // inclusive appears exactly once on the cells of the grid. // You have to find the minimum path of length k in the grid. You can start // from any cell, and in e...
}
import java.util.*; import java.lang.reflect.*; import org.javatuples.*; import java.security.*; import java.math.*; import java.io.*; import java.util.stream.*; class Problem { // Circular shift the digits of the integer x, shift the digits right by shift // and return the result as a string. // If shift >...
}
return (digits.substring(digits.length() - (int)shift, digits.length()) + digits.substring(0, digits.length() - (int)shift)); } }
import java.util.*; import java.lang.reflect.*; import org.javatuples.*; import java.security.*; import java.math.*; import java.io.*; import java.util.stream.*; class Problem { // In this problem, you will implement a function that takes two array lists of numbers, // and determines whether it is possible to p...
return (lst1.stream().allMatch(x -> x % 2 == 0)) ? "YES" : "NO";
} }
//You are given an array arr of integers and you need to return // sum of magnitudes of integers multiplied by product of all signs // of each number in the array, represented by 1, -1 or 0. // Note: return undefined for empty arr. // Example: // >>> prod_signs([1, 2, 2, -4]) // 9 // >>> prod_signs([0, 1]) // 0 // >>> ...
if(len == 0){
return undefined; } else{ for(var i = 0; i < len; i++){ total += Math.abs(arr[i]); if(arr[i] < 0){ pro *= -1; } else if(arr[i] == 0){ pro *= 0; } } total *= pro; return total; } }
import java.util.*; import java.lang.reflect.*; import org.javatuples.*; import java.security.*; import java.math.*; import java.io.*; import java.util.stream.*; class Problem { // Write a function count_nums which takes an array array list of integers and returns // the number of elements which has a sum of di...
}
}
from typing import List def count_up_to(n: int) -> List[int]: """Implement a function that takes an non-negative integer and returns an array of the first n integers that are prime numbers and less than n. for example: >>> count_up_to(5) [2, 3] >>> count_up_to(11) [2, 3, 5, 7] >>> count...
if is_prime:
result.append(number) return result
//Find the shortest palindrome that begins with a supplied string. // Algorithm idea is simple: // - Find the longest postfix of supplied string that is a palindrome. // - Append to the end of the string reverse of a string prefix that comes before the palindromic suffix. // >>> make_palindrome("") // "" // >>> make_pa...
}
return string; }
def change_base(x: int, base: int) -> str: """Change numerical base of input number x to base. return string representation after the conversion. base numbers are less than 10. >>> change_base(8, 3) '22' >>> change_base(8, 2) '1000' >>> change_base(7, 2) '111' """ if x == 0: ...
while x != 0:
ans.append(str(x % base)) x //= base return ''.join(ans[::-1])
//Task // We are given two strings s and c, you have to deleted all the characters in s that are equal to any character in c // then check if the result string is palindrome. // A string is called palindrome if it reads the same backward as forward. // You should return an array containing the result string and true/fa...
} else {
result.push(filterString, false); } return result; }
//Write a function that accepts an array of strings as a parameter, // deletes the strings that have odd lengths from it, // and returns the resulted array with a sorted order, // The array is always an array of strings and never an array of numbers, // and it may contain duplicates. // The order of the array should be...
return result.sort(function(a, b){
if(a.length < b.length){ return -1; } else if(a.length > b.length){ return 1; } else{ if(a < b){ return -1; } else if(a > b){ return 1; } else{ retu...
import java.util.*; import java.lang.reflect.*; import org.javatuples.*; import java.security.*; import java.math.*; import java.io.*; import java.util.stream.*; class Problem { // Given an array array list of strings, where each string consists of only digits, return an array array list. // Each element i of t...
}
} res.add("the number of odd elements " + count + "n the str" + count + "ng " + count + " of the " + count + "nput."); } return res; } }
from typing import List def rolling_max(numbers: List[int]) -> List[int]: """ From a given list of integers, generate a list of rolling maximum element found until given moment in the sequence. >>> rolling_max([1, 2, 3, 2, 3, 4, 2]) [1, 2, 3, 3, 3, 4, 4] """ if len(numbers) == 0:
return []
else: return [max(numbers[:i + 1]) for i in range(len(numbers))]
//A simple program which should return the value of x if n is // a prime number and should return the value of y otherwise. // Examples: // >>> x_or_y(7, 34, 12) // 34 // >>> x_or_y(15, 8, 5) // 5 function x_or_y(n, x, y){
if(n<2){
return y; } for(var i=2; i<n; i++){ if(n%i==0){ return y; } } return x; }
//Write a function count_nums which takes an array of integers and returns // the number of elements which has a sum of digits > 0. // If a number is negative, then its first signed digit will be negative: // e.g. -123 has signed digits -1, 2, and 3. // >>> count_nums([]) // 0 // >>> count_nums([-1, 11, -11]) // 1 // >...
if(!arr.length) {
return 0; } var count = 0; for(var i = 0; i < arr.length; i++) { var sum = 0; var str = arr[i].toString(); if(str[0] === '-') { sum += Number(str[0] + str[1]); for(var j = 2; j < str.length; j++) { sum += Number(str[j]); } } else { for(var k = 0; k < str.length; k++) { sum += Number(str...
from typing import List def do_algebra(operator: List[str], operand: List[int]) -> int: """ Given two lists operator, and operand. The first list has basic algebra operations, and the second list is a list of integers. Use the two given lists to build the algebric expression and return the evaluation...
expr.append(str(operand[idx + 1]))
return eval("".join(expr))
//Input to this function is a string representing musical notes in a special ASCII format. // Your task is to parse this string and return array of integers corresponding to how many beats does each // not last. // Here is a legend: // 'o' - whole note, lasts four beats // 'o|' - half note, lasts two beats // '.|' - qu...
songs.forEach(s => {
if(s === 'o'){ song.push(4); }else if(s === 'o|'){ song.push(2); }else if(s === '.|'){ song.push(1); } }); return song; }
import java.util.*; import java.lang.reflect.*; import org.javatuples.*; import java.security.*; import java.math.*; import java.io.*; import java.util.stream.*; class Problem { // Return the number of times the digit 7 appears in integers less than n which are divisible by 11 or 13. // >>> fizzBuzz((50l)) ...
}
import java.util.*; import java.lang.reflect.*; import org.javatuples.*; import java.security.*; import java.math.*; import java.io.*; import java.util.stream.*; class Problem { // Given the lengths of the three sides of a triangle. Return the area of // the triangle rounded to 2 decimal points if the three sid...
float s = (a + b + c) / 2.0f;
float area = (float)Math.sqrt(s * (s - a) * (s - b) * (s - c)); return (float)Math.round(area * 100) / 100; } return -1; } }
import java.util.*; import java.lang.reflect.*; import org.javatuples.*; import java.security.*; import java.math.*; import java.io.*; import java.util.stream.*; class Problem { // Given an array array list of strings, where each string consists of only digits, return an array array list. // Each element i of t...
for (int i = 0; i < lst.size(); i++) {
int count = 0; for (int j = 0; j < lst.get(i).length(); j++) { if (Integer.parseInt(lst.get(i).substring(j, j + 1)) % 2 == 1) { count++; } } res.add("the number of odd elements " + count + "n the str" + count + "ng " + c...
import java.util.*; import java.lang.reflect.*; import org.javatuples.*; import java.security.*; import java.math.*; import java.io.*; import java.util.stream.*; class Problem { // From an array array list of integers, remove all elements that occur more than once. // Keep order of elements left the same as in ...
}
} return out; } }
def encode(message: str) -> str: """ Write a function that takes a message, and encodes in such a way that it swaps case of all letters, replaces all vowels in the message with the letter that appears 2 places ahead of that vowel in the english alphabet. Assume only letters. Exampl...
def encode_vowel(ch: str) -> str:
if ch.lower() in 'aeiou': if ch.lower() in 'wxyz': return ch.lower() return chr(ord(ch) + 2) return ch return ''.join(map(lambda ch: encode_vowel(swap_case(ch)), message))
//Given a positive integer n, return the count of the numbers of n-digit // positive integers that start or end with 1. function starts_one_ends(n){
let ones = [];
for(let i = Math.pow(10, n-1); i < Math.pow(10, n); i++){ if(i.toString().startsWith('1') || i.toString().endsWith('1')){ ones.push(i); } } return ones.length; }
//prime_fib returns n-th number that is a Fibonacci number and it's also prime. // >>> prime_fib(1) // 2 // >>> prime_fib(2) // 3 // >>> prime_fib(3) // 5 // >>> prime_fib(4) // 13 // >>> prime_fib(5) // 89 function prime_fib(n){ function isPrime(number){ if(number <= 3){ return number > 1; ...
res++;
} fibNum++; } return fib(fibNum - 1); }
import java.util.*; import java.lang.reflect.*; import org.javatuples.*; import java.security.*; import java.math.*; import java.io.*; import java.util.stream.*; class Problem { // You're given an array array list of deposit and withdrawal operations on a bank account that starts with // zero balance. Your task...
balance += op;
if (balance < 0) { return true; } } return false; } }
import java.util.*; import java.lang.reflect.*; import org.javatuples.*; import java.security.*; import java.math.*; import java.io.*; import java.util.stream.*; class Problem { // "Given an array array list representing a branch of a tree that has non-negative integer nodes // your task is to pluck one of the ...
int minIndex = -1;
long minValue = -1; for (int i = 0; i < arr.size(); i++) { if (arr.get(i) % 2 == 0) { if (minIndex == -1 || arr.get(i) < minValue) { minIndex = i; minValue = arr.get(i); } } } ArrayList<Long> ...
import java.util.*; import java.lang.reflect.*; import org.javatuples.*; import java.security.*; import java.math.*; import java.io.*; import java.util.stream.*; class Problem { // Create a function which takes a string representing a file's name, and returns // 'Yes' if the the file's name is valid, and return...
if (name.length() == 0) {
return result; } if (!Character.isLetter(name.charAt(0))) { return result; } return "Yes"; } }
def iscube(a: int) -> bool: """ Write a function that takes an integer a and returns True if this ingeger is a cube of some integer number. Note: you may assume the input is always valid. Examples: >>> iscube(1) True >>> iscube(2) False >>> iscube(-1) True >>> iscube(64)...
return True
return False pass
import java.util.*; import java.lang.reflect.*; import org.javatuples.*; import java.security.*; import java.math.*; import java.io.*; import java.util.stream.*; class Problem { // Check if two words have the same characters. // >>> sameChars(("eabcdzzzz"), ("dddzzzzzzzddeddabc")) // (true) // >>> sameC...
return s0.chars().distinct().sorted().boxed().collect(Collectors.toList()).equals(s1.chars().distinct().sorted().boxed().collect(Collectors.toList()));
} }
//Evaluate whether the given number n can be written as the sum of exactly 4 positive even numbers // Example // >>> is_equal_to_sum_even(4) // false // >>> is_equal_to_sum_even(6) // false // >>> is_equal_to_sum_even(8) // true function is_equal_to_sum_even(n){ let m =0; for(let i=2;i<n;i+=2){ for(let ...
else{
return false; } }
from typing import Optional def string_to_md5(text: str) -> Optional[str]: """ Given a string 'text', return its md5 hash equivalent string. If 'text' is an empty string, return None. >>> string_to_md5('Hello world') '3e25960a79dbc69b674cd4ec67a72c62' """ import hashlib
if not text:
return None else: return hashlib.md5(text.encode('utf-8')).hexdigest()
import java.util.*; import java.lang.reflect.*; import org.javatuples.*; import java.security.*; import java.math.*; import java.io.*; import java.util.stream.*; class Problem { // You have been tasked to write a function that receives // a hexadecimal number as a string and counts the number of hexadecimal ...
}
}
import java.util.*; import java.lang.reflect.*; import org.javatuples.*; import java.security.*; import java.math.*; import java.io.*; import java.util.stream.*; class Problem { // Given a non-empty array array list of integers arr and an integer k, return // the sum of the elements with at most two digits from...
}
def prime_length(string: str) -> bool: """Write a function that takes a string and returns True if the string length is a prime number or False otherwise Examples >>> prime_length('Hello') True >>> prime_length('abcdcba') True >>> prime_length('kittens') True >>> prime_length('or...
return True
else: return False pass
import java.util.*; import java.lang.reflect.*; import org.javatuples.*; import java.security.*; import java.math.*; import java.io.*; import java.util.stream.*; class Problem { // Given a positive integer n, return a sorted array list that has the odd numbers in collatz sequence. // The Collatz conjecture is a...
Long[] odds_arr = odds.toArray(new Long[odds.size()]);
ArrayList<Long> ans = new ArrayList<Long>(Arrays.asList(odds_arr)); Collections.sort(ans); return ans; } }
def valid_date(date: str) -> bool: """You have to write a function which validates a given date string and returns True if the date is valid otherwise False. The date is valid if all of the following rules are satisfied: 1. The date string is not empty. 2. The number of days is not less than 1 or hi...
if date_list[0] < 1 or date_list[0] > 12:
return False if date_list[1] < 1 or date_list[1] > days_per_month[date_list[0] - 1]: return False if len(str(date_list[2])) != 4: return False return True
import java.util.*; import java.lang.reflect.*; import org.javatuples.*; import java.security.*; import java.math.*; import java.io.*; import java.util.stream.*; class Problem { // You will be given a string of words separated by commas or spaces. Your task is // to split the string into words and return an arr...
}
import java.util.*; import java.lang.reflect.*; import org.javatuples.*; import java.security.*; import java.math.*; import java.io.*; import java.util.stream.*; class Problem { // Given a string representing a space separated lowercase letters, return a hash map // of the letter with the most repetition and co...
}
return s; } }
import java.util.*; import java.lang.reflect.*; import org.javatuples.*; import java.security.*; import java.math.*; import java.io.*; import java.util.stream.*; class Problem { // You will be given the name of a class (a string) and an array array list of extensions. // The extensions are to be used to load ad...
int strength = Integer.MIN_VALUE;
String strongest = ""; for (String s : extensions) { int cap = (int)s.chars().filter(c -> Character.isUpperCase(c)).count(); int sm = (int)s.chars().filter(c -> Character.isLowerCase(c)).count(); int diff = cap - sm; if (diff > strength) { ...
//The Fib4 number sequence is a sequence similar to the Fibbonacci sequnece that's defined as follows: // fib4(0) -> 0 // fib4(1) -> 0 // fib4(2) -> 2 // fib4(3) -> 0 // fib4(n) -> fib4(n-1) + fib4(n-2) + fib4(n-3) + fib4(n-4). // Please write a function to efficiently compute the n-th element of the fib4 number sequen...
if(n<prev.length){
return prev[n]; } for(var i=4;i<=n;i++){ var curr = prev[0]+prev[1]+prev[2]+prev[3]; prev[0] = prev[1]; prev[1] = prev[2]; prev[2] = prev[3]; prev[3] = curr; } return prev[3]; }
//This function takes an array l and returns an array l' such that // l' is identical to l in the odd indicies, while its values at the even indicies are equal // to the values of the even indicies of l, but sorted. // >>> sort_even([1, 2, 3]) // [1, 2, 3] // >>> sort_even([5, 6, 3, 4]) // [3, 6, 5, 4] function sort_ev...
l2.push(l[i])
} l2.sort(function(a, b){return a - b}) for(var i = 0; i < l2.length; i++){ l[i * 2] = l2[i] } return l }
//Return true is array elements are monotonically increasing or decreasing. // >>> monotonic([1, 2, 4, 20]) // true // >>> monotonic([1, 20, 4, 10]) // false // >>> monotonic([4, 1, 0, -10]) // true function monotonic(l){ if(l.length <= 1){ return true; } if(l[0] < l[1]){ for(var i = 1; i < ...
return false;
} } } else{ for(var i = 1; i < l.length - 1; i++){ if(l[i] < l[i + 1]){ return false; } } } return true; }
from typing import List def maximum(arr: List[int], k: int) -> List[int]: """ Given an array arr of integers and a positive integer k, return a sorted list of length k with the maximum k numbers in arr. Example 1: >>> maximum([-3, -4, 5], 3) [-4, -3, 5] Example 2: >>> maximum([4, -...
return []
elif k == 1: return [max(arr)] else: max_num = max(arr) arr.remove(max_num) return [max_num] + get_max(arr, k - 1) return sorted(get_max(arr, k))
//Write a function that takes an integer a and returns true // if this ingeger is a cube of some integer number. // Note: you may assume the input is always valid. // Examples: // >>> iscube(1) // true // >>> iscube(2) // false // >>> iscube(-1) // true // >>> iscube(64) // true // >>> iscube(0) // true // >>> iscube(...
}
//Input are two strings a and b consisting only of 1s and 0s. // Perform binary XOR on these inputs and return result also as a string. // >>> string_xor("010", "110") // "100" function string_xor(a, b){ var arrayA = [];
var arrayB = [];
var arrayXOR = []; var result = ''; for (var i = 0; i < a.length; i++) { arrayA.push(parseInt(a[i])); } for (var j = 0; j < b.length; j++) { arrayB.push(parseInt(b[j])); } for (var k = 0; k < arrayA.length; k++) { if (arrayA[k] !== arrayB[k]) { arrayXOR.push(1); } else { ar...
//Create a function that takes integers, floats, or strings representing // real numbers, and returns the larger variable in its given variable type. // Return undefined if the values are equal. // Note: If a real number is represented as a string, the floating point might be . or , // >>> compare_one(1, 2.5) // 2.5 //...
}
} else if (typeof a === "number" && typeof b === "string"){ if (a > b[0]){ return a; } else if (a < b[0]){ return b; } else { return undefined; } } }
//You are given a word. Your task is to find the closest vowel that stands between // two consonants from the right side of the word (case sensitive). // Vowels in the beginning and ending doesn't count. Return empty string if you didn't // find any vowel met the above condition. // You may assume that the given stri...
let i = word.length - 1;
let result = []; if (word.length === 1) { return "" } else { while (i >= 0) { if (vowels.includes(word[i])) { if (i > 0 && i < word.length - 1) { if (!vowels.includes(word[i-1]) && !vowels.includes(word[i+1])) { result.p...
import java.util.*; import java.lang.reflect.*; import org.javatuples.*; import java.security.*; import java.math.*; import java.io.*; import java.util.stream.*; class Problem { // You are given an array array list of integers. // You need to find the largest prime value and return the sum of its digits. //...
}
l++; } } if (counter == 2) { if (number > largestPrime) { largestPrime = number; } } } if (largestPrime == 0) { return 0l; } else { long out...
//Return the number of times the digit 7 appears in integers less than n which are divisible by 11 or 13. // >>> fizz_buzz(50) // 0 // >>> fizz_buzz(78) // 2 // >>> fizz_buzz(79) // 3 function fizz_buzz(n){ let result = 0; for(let i = 0; i < n; i++){ if(i % 11 === 0 || i % 13 === 0){ let arr...
}
} return result; }
//Given a positive integer n, return the count of the numbers of n-digit // positive integers that start or end with 1. function starts_one_ends(n){ let ones = []; for(let i = Math.pow(10, n-1); i < Math.pow(10, n); i++){ if(i.toString().startsWith('1') || i.toString().endsWith('1')){ ones.p...
}
return ones.length; }
import java.util.*; import java.lang.reflect.*; import org.javatuples.*; import java.security.*; import java.math.*; import java.io.*; import java.util.stream.*; class Problem { // Given an array array list of integers nums, find the minimum sum of any non-empty sub-array array list // of nums. // Example ...
}
} return minSum; } }
from typing import List def separate_paren_groups(paren_string: str) -> List[str]: """ Input to this function is a string containing multiple groups of nested parentheses. Your goal is to separate those group into separate strings and return the list of those. Separate groups are balanced (each open brace ...
open_count += 1
elif c == ')': open_count -= 1 group += c if open_count == 0: groups.append(group) group = '' return groups
import java.util.*; import java.lang.reflect.*; import org.javatuples.*; import java.security.*; import java.math.*; import java.io.*; import java.util.stream.*; class Problem { // Return maximum element in the array list. // >>> maxElement((new ArrayList<Long>(Arrays.asList((long)1l, (long)2l, (long)3l)))) ...
max = l.get(i);
} } return max; } }
from typing import List def intersperse(numbers: List[int], delimeter: int) -> List[int]: """ Insert a number 'delimeter' between every two consecutive elements of input list `numbers' >>> intersperse([], 4) [] >>> intersperse([1, 2, 3], 4) [1, 4, 2, 4, 3] """ result = []
if len(numbers) == 0:
return result result.append(numbers[0]) for num in numbers[1:]: result.append(delimeter) result.append(num) return result
//You are given a non-empty array of positive integers. Return the greatest integer that is greater than // zero, and has a frequency greater than or equal to the value of the integer itself. // The frequency of an integer is the number of times it appears in the array. // If no such a value exist, return -1. // Exam...
else{
h[x] = 1; } } var keys = Object.keys(h); var max = 0; for (var i=0; i<keys.length; i++){ if (keys[i] > max && h[keys[i]] >= keys[i]){ max = keys[i]; } } if (max == 0){ return -1; } return max; }
import java.util.*; import java.lang.reflect.*; import org.javatuples.*; import java.security.*; import java.math.*; import java.io.*; import java.util.stream.*; class Problem { // Given an array array list of numbers, return whether or not they are sorted // in ascending order. If array list has more than 1 du...
else {
if (running_max > number.intValue()) { return false; } else { if (previous_number == number.intValue()) { if (seen_2_in_a_row) { return false; ...
import java.util.*; import java.lang.reflect.*; import org.javatuples.*; import java.security.*; import java.math.*; import java.io.*; import java.util.stream.*; class Problem { // The Brazilian factorial is defined as: // brazilian_factorial(n) = n! * (n-1)! * (n-2)! * ... * 1! // where n > 0 // For ex...
temp--;
} result *= local_result; n--; } return result; } }
import java.util.*; import java.lang.reflect.*; import org.javatuples.*; import java.security.*; import java.math.*; import java.io.*; import java.util.stream.*; class Problem { // You are given an array array list of numbers. // You need to return the sum of squared numbers in the given array list, // roun...
long sum = 0;
for (int i = 0; i < lst.size(); i++) { sum += (long)Math.ceil(lst.get(i)) * (long)Math.ceil(lst.get(i)); } return sum; } }
//Imagine a road that's a perfectly straight infinitely long line. // n cars are driving left to right; simultaneously, a different set of n cars // are driving right to left. The two sets of cars start out being very far from // each other. All cars move in the same speed. Two cars are said to collide // when a c...
let left_to_right = Array(n).fill(1);
let right_to_left = Array(n).fill(1); for (let i = 0; i < left_to_right.length; i++) { for (let j = 0; j < right_to_left.length; j++) { if (left_to_right[i] == right_to_left[j]) { num_collisions++; } } } return num_collisions; }
import java.util.*; import java.lang.reflect.*; import org.javatuples.*; import java.security.*; import java.math.*; import java.io.*; import java.util.stream.*; class Problem { // You'll be given a string of words, and your task is to count the number // of boredoms. A boredom is a sentence that starts with th...
}
}
//Given two arrays operator, and operand. The first array has basic algebra operations, and // the second array is an array of integers. Use the two given arrays to build the algebric // expression and return the evaluation of this expression. // The basic algebra operations: // Addition ( + ) // Subtraction ( - ) ...
answer += operand[0];
break; case '-': answer -= operand[0]; break; } operand.splice(0, 1); operator.splice(0, 1); } return answer; }
import java.util.*; import java.lang.reflect.*; import org.javatuples.*; import java.security.*; import java.math.*; import java.io.*; import java.util.stream.*; class Problem { // Return the largest prime factor of n. Assume n > 1 and is not a prime. // >>> largestPrimeFactor((13195l)) // (29l) // >>> ...
if (x > 1) {
primes.add(x); } return primes.get(primes.size() - 1); } }
//From an array of integers, remove all elements that occur more than once. // Keep order of elements left the same as in the input. // >>> remove_duplicates([1, 2, 3, 2, 4]) // [1, 3, 4] function remove_duplicates(numbers){ let result = []; numbers.forEach(function(value){ if(numbers.indexOf(value) ===...
}
//In this problem, you will implement a function that takes two arrays of numbers, // and determines whether it is possible to perform an exchange of elements // between them to make lst1 an array of only even numbers. // There is no limit on the number of exchanged elements between lst1 and lst2. // If it is possible ...
var exchange = true;
while(num1 < lst1.length && exchange){ if(lst1[num1] % 2 !== 0){ exchange = false; if(num2 < lst2.length){ while(num2 < lst2.length && exchange == false){ if(lst2[num2] % 2 == 0){ lst1[num1] = lst2[num2]; ...
import java.util.*; import java.lang.reflect.*; import org.javatuples.*; import java.security.*; import java.math.*; import java.io.*; import java.util.stream.*; class Problem { // Write a function that accepts two array lists of strings and returns the array list that has // total number of chars in the all s...
for (String s : lst2) {
sum2 += s.length(); } if (sum1 <= sum2) { return lst1; } else { return lst2; } } }
def is_multiply_prime(a: int) -> bool: """Write a function that returns true if the given number is the multiplication of 3 prime numbers and false otherwise. Knowing that (a) is less then 100. Example: >>> is_multiply_prime(30) True 30 = 2 * 3 * 5 """ n = a d = 2 prime_fact...
prime_factors.append(d)
n //= d else: d += 1 if n > 1: prime_factors.append(n) if len(prime_factors) == 3: return True else: return False
from typing import List def sum_squares(lst: List[float]) -> int: """You are given a list of numbers. You need to return the sum of squared numbers in the given list, round each element in the list to the upper int(Ceiling) first. Examples: >>> lst([1.0, 2.0, 3.0]) 14 >>> lst([1.0, 4.0, 9.0...
return total
def words_in_sentence(sentence: str) -> str: """ You are given a string representing a sentence, the sentence contains some words separated by a space, and you have to return a string that contains the words from the original sentence, whose lengths are prime numbers, the order of the words in t...
return False
return True words = sentence.split() prime_words = [] for word in words: if is_prime(len(word)): prime_words.append(word) return ' '.join(prime_words)
import java.util.*; import java.lang.reflect.*; import org.javatuples.*; import java.security.*; import java.math.*; import java.io.*; import java.util.stream.*; class Problem { // Given a positive integer, obtain its roman numeral equivalent as a string, // and return it in lowercase. // Restrictions: 1 <=...
String res = "";
if (num == 0) return ""; while (num >= 1000) { res += "m"; num -= 1000; } if (num >= 900) { res += "cm"; num -= 900; } if (num >= 500) { res += "d"; num -= 500; } if (num >...
def fruit_distribution(s: str, n: int) -> int: """ In this task, you will be given a string that represents a number of apples and oranges that are distributed in a basket of fruit this basket contains apples, oranges, and mango fruits. Given the string that represents the total number of the ora...
pass
return n - sum(fruits)
import java.util.*; import java.lang.reflect.*; import org.javatuples.*; import java.security.*; import java.math.*; import java.io.*; import java.util.stream.*; class Problem { // Given array list of integers, return array list in strange order. // Strange sorting, is when you start with the minimum value, ...
return result;
} }
import java.util.*; import java.lang.reflect.*; import org.javatuples.*; import java.security.*; import java.math.*; import java.io.*; import java.util.stream.*; class Problem { // Return maximum element in the array list. // >>> maxElement((new ArrayList<Long>(Arrays.asList((long)1l, (long)2l, (long)3l)))) ...
for (int i = 0; i < l.size(); i += 1) {
if (l.get(i) > max) { max = l.get(i); } } return max; } }
import java.util.*; import java.lang.reflect.*; import org.javatuples.*; import java.security.*; import java.math.*; import java.io.*; import java.util.stream.*; class Problem { // triples_sum_to_zero takes an array array list of integers as an input. // it returns true if there are three distinct elements in t...
return true;
} else if (currSum < 0) { j++; } else { k--; } } } return false; } }
//Write a function that returns true if the object q will fly, and false otherwise. // The object q will fly if it's balanced (it is a palindromic array) and the sum of its elements is less than or equal the maximum possible weight w. // Example: // >>> will_it_fly([1, 2], 5) // false // # 1+2 is less than the maximum ...
}
for(let i = 0; i < q.length; i++){ if(q[i] !== q[q.length - 1 - i]){ balanced = false; break; } } return balanced && sum <= w; }
from typing import List def get_odd_collatz(n: int) -> List[int]: """ Given a positive integer n, return a sorted list that has the odd numbers in collatz sequence. The Collatz conjecture is a conjecture in mathematics that concerns a sequence defined as follows: start with any positive integer n. The...
while (current_num > 1):
collatz_list.append(current_num) if (current_num % 2 == 0): current_num = current_num // 2 else: current_num = current_num * 3 + 1 collatz_list.append(1) return sorted(list(set([x for x in collatz_list if x % 2 != 0])))
from typing import List def sum_squares(lst: List[int]) -> int: """" This function will take a list of integers. For all entries in the list, the function shall square the integer entry if its index is a multiple of 3 and will cube the integer entry if its index is a multiple of 4 and not a multiple of 3....
if index % 3 == 0:
lst[index] = lst[index] ** 2 elif index % 4 == 0: lst[index] = lst[index] ** 3 return sum(lst)
import java.util.*; import java.lang.reflect.*; import org.javatuples.*; import java.security.*; import java.math.*; import java.io.*; import java.util.stream.*; class Problem { // You're given an array array list of deposit and withdrawal operations on a bank account that starts with // zero balance. Your task...
return false;
} }
import java.util.*; import java.lang.reflect.*; import org.javatuples.*; import java.security.*; import java.math.*; import java.io.*; import java.util.stream.*; class Problem { // Given two array lists operator, and operand. The first array list has basic algebra operations, and // the second array list is an...
if (op.get(i).equals("+"))
list.add(operand.get(i + 1)); else if (op.get(i).equals("-")) list.add(-operand.get(i + 1)); else if (op.get(i).equals("*")) list.set(list.size() - 1, list.get(list.size() - 1) * operand.get(i + 1)); else if (op.get(i).equals("//")) ...
import java.util.*; import java.lang.reflect.*; import org.javatuples.*; import java.security.*; import java.math.*; import java.io.*; import java.util.stream.*; class Problem { // You are given a string representing a sentence, // the sentence contains some words separated by a space, // and you have to re...
StringBuilder ans = new StringBuilder();
String[] words = sentence.split(" "); int[] primes = {2, 3, 5, 7, 11, 13, 17, 19, 23, 29, 31, 37, 41, 43, 47, 53, 59, 61, 67, 71, 73, 79, 83, 89, 97}; boolean isPrime; for (String word : words) { isPrime = false; for (int prime : primes) { if (word...
def make_palindrome(string: str) -> str: """ Find the shortest palindrome that begins with a supplied string. Algorithm idea is simple: - Find the longest postfix of supplied string that is a palindrome. - Append to the end of the string reverse of a string prefix that comes before the palindromic suffi...
for i in range(len(string)):
if string[i:] == prefix[:len(string) - i]: return string + prefix[len(string) - i:] return string
import java.util.*; import java.lang.reflect.*; import org.javatuples.*; import java.security.*; import java.math.*; import java.io.*; import java.util.stream.*; class Problem { // xs represent coefficients of a polynomial. // xs[0] + xs[1] * x + xs[2] * x^2 + .... // Return derivative of this polynomial in...
ArrayList<Long> ans = new ArrayList<Long>();
for (int i = 1; i < xs.size(); i++) { ans.add(xs.get(i) * i); } return ans; } }
import java.util.*; import java.lang.reflect.*; import org.javatuples.*; import java.security.*; import java.math.*; import java.io.*; import java.util.stream.*; class Problem { // Your task is to implement a function that will simplify the expression // x * n. The function returns true if x * n evaluates to a ...
int x_denom = Integer.parseInt(nums[1]);
int n_denom = Integer.parseInt(n_nums[1]); int res_num = x_num * n_num; int res_denom = x_denom * n_denom; return (res_num % res_denom == 0); } }
import java.util.*; import java.lang.reflect.*; import org.javatuples.*; import java.security.*; import java.math.*; import java.io.*; import java.util.stream.*; class Problem { // Return true if all numbers in the array list l are below threshold t. // >>> belowThreshold((new ArrayList<Long>(Arrays.asList((lon...
if (a[i] >= t) {
return false; } } return true; } }
import java.util.*; import java.lang.reflect.*; import org.javatuples.*; import java.security.*; import java.math.*; import java.io.*; import java.util.stream.*; class Problem { // Given a string s and a natural number n, you have been tasked to implement // a function that returns an array array list of all w...
}
import java.util.*; import java.lang.reflect.*; import org.javatuples.*; import java.security.*; import java.math.*; import java.io.*; import java.util.stream.*; class Problem { // You have to write a function which validates a given date string and // returns true if the date is valid otherwise false. // T...
valid_date = true;
} catch (Exception e) { valid_date = false; } return valid_date; } }
import java.util.*; import java.lang.reflect.*; import org.javatuples.*; import java.security.*; import java.math.*; import java.io.*; import java.util.stream.*; class Problem { // Given a non-empty array list of integers, return the sum of all of the odd elements that are in even positions. // Examples // ...
for (int i = 0; i < lst.size(); i++) {
if (i % 2 == 0 && lst.get(i) % 2 == 1) { sum += lst.get(i); } } return sum; } }
//Given a positive integer n, return an array that has the number of even and odd // integer palindromes that fall within the range(1, n), inclusive. // Example 1: // >>> even_odd_palindrome(3) // [1, 2] // Explanation: // Integer palindrome are 1, 2, 3. one of them is even, and two of them are odd. // Example 2: // >>...
}
else{ odd++; } } return [even, odd]; }
import java.util.*; import java.lang.reflect.*; import org.javatuples.*; import java.security.*; import java.math.*; import java.io.*; import java.util.stream.*; class Problem { // The Fib4 number sequence is a sequence similar to the Fibbonacci sequnece that's defined as follows: // fib4(0) -> 0 // fib4(1)...
if (n == 2) return 2;
if (n == 3) return 0; return fib4(n-1) + fib4(n-2) + fib4(n-3) + fib4(n-4); } }
import java.util.*; import java.lang.reflect.*; import org.javatuples.*; import java.security.*; import java.math.*; import java.io.*; import java.util.stream.*; class Problem { // Return a string containing space-delimited numbers starting from 0 upto n inclusive. // >>> stringSequence((0l)) // ("0") /...
}
return result.trim(); } }
from typing import List def move_one_ball(arr: List[int]) -> bool: """We have an array 'arr' of N integers arr[1], arr[2], ..., arr[N].The numbers in the array will be randomly ordered. Your task is to determine if it is possible to get an array sorted in non-decreasing order by performing the followi...
flag = True
elif arr[i-1] < arr[i]: flag = False return True
import java.util.*; import java.lang.reflect.*; import org.javatuples.*; import java.security.*; import java.math.*; import java.io.*; import java.util.stream.*; class Problem { // Write a function that takes a string and returns an ordered version of it. // Ordered version of string, is a string where all word...
sb.deleteCharAt(sb.length() - 1);
return sb.toString(); } }
import java.util.*; import java.lang.reflect.*; import org.javatuples.*; import java.security.*; import java.math.*; import java.io.*; import java.util.stream.*; class Problem { // Given a positive integer, obtain its roman numeral equivalent as a string, // and return it in lowercase. // Restrictions: 1 <=...
num -= 4;
} while (num >= 1) { res += "i"; num -= 1; } return res; } }
import java.util.*; import java.lang.reflect.*; import org.javatuples.*; import java.security.*; import java.math.*; import java.io.*; import java.util.stream.*; class Problem { // You will be given a number in decimal form and your task is to convert it to // binary format. The function should return a string,...
}
}