input stringlengths 122 2.7k | output stringlengths 24 805 |
|---|---|
[INST] Here is a database schema:
book :
book_id [ INTEGER ] primary_key
title [ TEXT ]
isbn13 [ TEXT ]
language_id [ INTEGER ] book.language_id = book_language.language_id
num_pages [ INTEGER ]
publication_date [ DATE ]
publisher_id [ INTEGER ] book.publisher_id = publisher.publisher_id
order_line :
line_id [ INTEGER ... | SELECT T1.title FROM book AS T1 INNER JOIN order_line AS T2 ON T1.book_id = T2.book_id WHERE T2.order_id = 931; |
[INST] Here is a database schema:
book_language :
language_id [ INTEGER ] primary_key
language_code [ TEXT ]
language_name [ TEXT ]
book :
book_id [ INTEGER ] primary_key
title [ TEXT ]
isbn13 [ TEXT ]
language_id [ INTEGER ] book.language_id = book_language.language_id
num_pages [ INTEGER ]
publication_date [ DATE ]
p... | SELECT T2.language_name FROM book AS T1 INNER JOIN book_language AS T2 ON T1.language_id = T2.language_id WHERE T1.title = 'Zorro'; |
[INST] Here is a database schema:
customer :
customer_id [ INTEGER ] primary_key
first_name [ TEXT ]
last_name [ TEXT ]
email [ TEXT ]
cust_order :
order_id [ INTEGER ] primary_key
order_date [ DATETIME ]
customer_id [ INTEGER ]
shipping_method_id [ INTEGER ]
dest_address_id [ INTEGER ]
order_line :
line_id [ INTEGER ]... | SELECT DISTINCT T3.email FROM order_line AS T1 INNER JOIN cust_order AS T2 ON T2.order_id = T1.order_id INNER JOIN customer AS T3 ON T3.customer_id = T2.customer_id WHERE T1.price BETWEEN 3 AND 5; |
[INST] Here is a database schema:
book :
book_id [ INTEGER ] primary_key
title [ TEXT ]
isbn13 [ TEXT ]
language_id [ INTEGER ] book.language_id = book_language.language_id
num_pages [ INTEGER ]
publication_date [ DATE ]
publisher_id [ INTEGER ] book.publisher_id = publisher.publisher_id
order_line :
line_id [ INTEGER ... | SELECT T1.isbn13 FROM book AS T1 INNER JOIN order_line AS T2 ON T1.book_id = T2.book_id WHERE T2.price = 7.5; |
[INST] Here is a database schema:
author :
author_id [ INTEGER ] primary_key
author_name [ TEXT ]
publisher :
publisher_id [ INTEGER ] primary_key
publisher_name [ TEXT ]
book :
book_id [ INTEGER ] primary_key
title [ TEXT ]
isbn13 [ TEXT ]
language_id [ INTEGER ] book.language_id = book_language.language_id
num_pages ... | SELECT T4.publisher_name FROM book AS T1 INNER JOIN book_author AS T2 ON T1.book_id = T2.book_id INNER JOIN author AS T3 ON T3.author_id = T2.author_id INNER JOIN publisher AS T4 ON T4.publisher_id = T1.publisher_id WHERE T3.author_name = 'Alan Lee' GROUP BY T4.publisher_name; |
[INST] Here is a database schema:
customer :
customer_id [ INTEGER ] primary_key
first_name [ TEXT ]
last_name [ TEXT ]
email [ TEXT ]
book :
book_id [ INTEGER ] primary_key
title [ TEXT ]
isbn13 [ TEXT ]
language_id [ INTEGER ] book.language_id = book_language.language_id
num_pages [ INTEGER ]
publication_date [ DATE ... | SELECT SUM(T1.num_pages) FROM book AS T1 INNER JOIN order_line AS T2 ON T1.book_id = T2.book_id INNER JOIN cust_order AS T3 ON T3.order_id = T2.order_id INNER JOIN customer AS T4 ON T4.customer_id = T3.customer_id WHERE T4.first_name = 'Mick' AND T4.last_name = 'Sever'; |
[INST] Here is a database schema:
author :
author_id [ INTEGER ] primary_key
author_name [ TEXT ]
book :
book_id [ INTEGER ] primary_key
title [ TEXT ]
isbn13 [ TEXT ]
language_id [ INTEGER ] book.language_id = book_language.language_id
num_pages [ INTEGER ]
publication_date [ DATE ]
publisher_id [ INTEGER ] book.publi... | SELECT T3.author_name FROM book AS T1 INNER JOIN book_author AS T2 ON T1.book_id = T2.book_id INNER JOIN author AS T3 ON T3.author_id = T2.author_id ORDER BY T1.publication_date DESC LIMIT 1; |
[INST] Here is a database schema:
book_language :
language_id [ INTEGER ] primary_key
language_code [ TEXT ]
language_name [ TEXT ]
publisher :
publisher_id [ INTEGER ] primary_key
publisher_name [ TEXT ]
book :
book_id [ INTEGER ] primary_key
title [ TEXT ]
isbn13 [ TEXT ]
language_id [ INTEGER ] book.language_id = bo... | SELECT CAST(SUM(CASE WHEN T1.language_name = 'English' THEN 1 ELSE 0 END) AS REAL) * 100 / COUNT(*) FROM book_language AS T1 INNER JOIN book AS T2 ON T1.language_id = T2.language_id INNER JOIN publisher AS T3 ON T3.publisher_id = T2.publisher_id WHERE T3.publisher_name = 'Ace Book'; |
[INST] Here is a database schema:
book :
book_id [ INTEGER ] primary_key
title [ TEXT ]
isbn13 [ TEXT ]
language_id [ INTEGER ] book.language_id = book_language.language_id
num_pages [ INTEGER ]
publication_date [ DATE ]
publisher_id [ INTEGER ] book.publisher_id = publisher.publisher_id
order_line :
line_id [ INTEGER ... | SELECT SUM(CASE WHEN T1.num_pages < 500 THEN 1 ELSE 0 END) - SUM(CASE WHEN T1.num_pages > 500 THEN 1 ELSE 0 END) AS dif FROM book AS T1 INNER JOIN order_line AS T2 ON T1.book_id = T2.book_id WHERE T2.price < 1; |
[INST] Here is a database schema:
book_language :
language_id [ INTEGER ] primary_key
language_code [ TEXT ]
language_name [ TEXT ]
book :
book_id [ INTEGER ] primary_key
title [ TEXT ]
isbn13 [ TEXT ]
language_id [ INTEGER ] book.language_id = book_language.language_id
num_pages [ INTEGER ]
publication_date [ DATE ]
p... | SELECT DISTINCT T3.language_name, T2.title FROM order_line AS T1 INNER JOIN book AS T2 ON T1.book_id = T2.book_id INNER JOIN book_language AS T3 ON T3.language_id = T2.language_id WHERE T1.price * 100 < ( SELECT AVG(price) FROM order_line ) * 20; |
[INST] Here is a database schema:
employee :
employee_id [ INTEGER ] primary_key
first_name [ TEXT ]
last_name [ TEXT ]
address [ TEXT ]
city [ TEXT ]
state [ TEXT ]
zip [ INTEGER ]
phone [ TEXT ]
title [ TEXT ]
salary [ INTEGER ]
supervisor [ INTEGER ] employee.supervisor = employee.employee_id
Please write me a SQL ... | SELECT first_name, last_name FROM employee WHERE title = 'Sanitarian' AND supervisor = ( SELECT employee_id FROM employee WHERE first_name = 'Darlisha' AND last_name = 'Jacobs' ); |
[INST] Here is a database schema:
employee :
employee_id [ INTEGER ] primary_key
first_name [ TEXT ]
last_name [ TEXT ]
address [ TEXT ]
city [ TEXT ]
state [ TEXT ]
zip [ INTEGER ]
phone [ TEXT ]
title [ TEXT ]
salary [ INTEGER ]
supervisor [ INTEGER ] employee.supervisor = employee.employee_id
inspection :
inspection... | SELECT DISTINCT T1.first_name, T1.last_name FROM employee AS T1 INNER JOIN inspection AS T2 ON T1.employee_id = T2.employee_id WHERE strftime('%Y-%m', T2.inspection_date) = '2010-05' AND T1.title = 'Sanitarian'; |
[INST] Here is a database schema:
employee :
employee_id [ INTEGER ] primary_key
first_name [ TEXT ]
last_name [ TEXT ]
address [ TEXT ]
city [ TEXT ]
state [ TEXT ]
zip [ INTEGER ]
phone [ TEXT ]
title [ TEXT ]
salary [ INTEGER ]
supervisor [ INTEGER ] employee.supervisor = employee.employee_id
inspection :
inspection... | SELECT COUNT(T2.inspection_id) FROM employee AS T1 INNER JOIN inspection AS T2 ON T1.employee_id = T2.employee_id WHERE strftime('%Y', T2.inspection_date) = '2010' AND T1.first_name = 'Joshua' AND T1.last_name = 'Rosa'; |
[INST] Here is a database schema:
employee :
employee_id [ INTEGER ] primary_key
first_name [ TEXT ]
last_name [ TEXT ]
address [ TEXT ]
city [ TEXT ]
state [ TEXT ]
zip [ INTEGER ]
phone [ TEXT ]
title [ TEXT ]
salary [ INTEGER ]
supervisor [ INTEGER ] employee.supervisor = employee.employee_id
establishment :
license... | SELECT DISTINCT T3.dba_name FROM employee AS T1 INNER JOIN inspection AS T2 ON T1.employee_id = T2.employee_id INNER JOIN establishment AS T3 ON T2.license_no = T3.license_no WHERE T1.first_name = 'Joshua' AND T1.last_name = 'Rosa'; |
[INST] Here is a database schema:
establishment :
license_no [ INTEGER ] primary_key
dba_name [ TEXT ]
aka_name [ TEXT ]
facility_type [ TEXT ]
risk_level [ INTEGER ]
address [ TEXT ]
city [ TEXT ]
state [ TEXT ]
zip [ INTEGER ]
latitude [ REAL ]
longitude [ REAL ]
ward [ INTEGER ]
inspection :
inspection_id [ INTEGER ... | SELECT COUNT(DISTINCT T1.license_no) FROM inspection AS T1 INNER JOIN establishment AS T2 ON T1.license_no = T2.license_no WHERE strftime('%Y', T1.inspection_date) = '2010' AND T2.facility_type = 'Restaurant'; |
[INST] Here is a database schema:
establishment :
license_no [ INTEGER ] primary_key
dba_name [ TEXT ]
aka_name [ TEXT ]
facility_type [ TEXT ]
risk_level [ INTEGER ]
address [ TEXT ]
city [ TEXT ]
state [ TEXT ]
zip [ INTEGER ]
latitude [ REAL ]
longitude [ REAL ]
ward [ INTEGER ]
inspection :
inspection_id [ INTEGER ... | SELECT DISTINCT T2.latitude, T2.longitude FROM inspection AS T1 INNER JOIN establishment AS T2 ON T1.license_no = T2.license_no WHERE T1.inspection_date = '2010-05-11'; |
[INST] Here is a database schema:
establishment :
license_no [ INTEGER ] primary_key
dba_name [ TEXT ]
aka_name [ TEXT ]
facility_type [ TEXT ]
risk_level [ INTEGER ]
address [ TEXT ]
city [ TEXT ]
state [ TEXT ]
zip [ INTEGER ]
latitude [ REAL ]
longitude [ REAL ]
ward [ INTEGER ]
inspection :
inspection_id [ INTEGER ... | SELECT COUNT(DISTINCT T1.license_no) FROM inspection AS T1 INNER JOIN establishment AS T2 ON T1.license_no = T2.license_no WHERE strftime('%Y', T1.inspection_date) = '2010' AND T2.ward = 42; |
[INST] Here is a database schema:
employee :
employee_id [ INTEGER ] primary_key
first_name [ TEXT ]
last_name [ TEXT ]
address [ TEXT ]
city [ TEXT ]
state [ TEXT ]
zip [ INTEGER ]
phone [ TEXT ]
title [ TEXT ]
salary [ INTEGER ]
supervisor [ INTEGER ] employee.supervisor = employee.employee_id
establishment :
license... | SELECT DISTINCT T1.first_name, T1.last_name FROM employee AS T1 INNER JOIN inspection AS T2 ON T1.employee_id = T2.employee_id INNER JOIN establishment AS T3 ON T2.license_no = T3.license_no WHERE T3.dba_name = 'Burbank' AND T1.title = 'Sanitarian'; |
[INST] Here is a database schema:
establishment :
license_no [ INTEGER ] primary_key
dba_name [ TEXT ]
aka_name [ TEXT ]
facility_type [ TEXT ]
risk_level [ INTEGER ]
address [ TEXT ]
city [ TEXT ]
state [ TEXT ]
zip [ INTEGER ]
latitude [ REAL ]
longitude [ REAL ]
ward [ INTEGER ]
inspection :
inspection_id [ INTEGER ... | SELECT DISTINCT T2.dba_name FROM inspection AS T1 INNER JOIN establishment AS T2 ON T1.license_no = T2.license_no WHERE T1.results = 'Fail' AND strftime('%Y', T1.inspection_date) = '2010'; |
[INST] Here is a database schema:
employee :
employee_id [ INTEGER ] primary_key
first_name [ TEXT ]
last_name [ TEXT ]
address [ TEXT ]
city [ TEXT ]
state [ TEXT ]
zip [ INTEGER ]
phone [ TEXT ]
title [ TEXT ]
salary [ INTEGER ]
supervisor [ INTEGER ] employee.supervisor = employee.employee_id
establishment :
license... | SELECT T1.first_name, T1.last_name FROM employee AS T1 INNER JOIN inspection AS T2 ON T1.employee_id = T2.employee_id INNER JOIN establishment AS T3 ON T2.license_no = T3.license_no WHERE T2.inspection_date = '2010-05-11' AND T3.dba_name = 'AMUNDSEN HIGH SCHOOL' AND T1.title = 'Sanitarian'; |
[INST] Here is a database schema:
employee :
employee_id [ INTEGER ] primary_key
first_name [ TEXT ]
last_name [ TEXT ]
address [ TEXT ]
city [ TEXT ]
state [ TEXT ]
zip [ INTEGER ]
phone [ TEXT ]
title [ TEXT ]
salary [ INTEGER ]
supervisor [ INTEGER ] employee.supervisor = employee.employee_id
inspection :
inspection... | SELECT COUNT(T2.inspection_id) FROM employee AS T1 INNER JOIN inspection AS T2 ON T1.employee_id = T2.employee_id WHERE T2.results = 'Pass' AND T1.first_name = 'Joshua' AND T1.last_name = 'Rosa'; |
[INST] Here is a database schema:
establishment :
license_no [ INTEGER ] primary_key
dba_name [ TEXT ]
aka_name [ TEXT ]
facility_type [ TEXT ]
risk_level [ INTEGER ]
address [ TEXT ]
city [ TEXT ]
state [ TEXT ]
zip [ INTEGER ]
latitude [ REAL ]
longitude [ REAL ]
ward [ INTEGER ]
inspection :
inspection_id [ INTEGER ... | SELECT T1.followup_to FROM inspection AS T1 INNER JOIN establishment AS T2 ON T1.license_no = T2.license_no WHERE T2.dba_name = 'Azha Restaurant Inc.' AND T1.results = 'Pass' AND T1.inspection_date = '2010-01-21'; |
[INST] Here is a database schema:
establishment :
license_no [ INTEGER ] primary_key
dba_name [ TEXT ]
aka_name [ TEXT ]
facility_type [ TEXT ]
risk_level [ INTEGER ]
address [ TEXT ]
city [ TEXT ]
state [ TEXT ]
zip [ INTEGER ]
latitude [ REAL ]
longitude [ REAL ]
ward [ INTEGER ]
inspection :
inspection_id [ INTEGER ... | SELECT COUNT(DISTINCT T2.license_no) FROM inspection AS T1 INNER JOIN establishment AS T2 ON T1.license_no = T2.license_no WHERE strftime('%Y', T1.inspection_date) = '2010' AND T2.risk_level = 3; |
[INST] Here is a database schema:
employee :
employee_id [ INTEGER ] primary_key
first_name [ TEXT ]
last_name [ TEXT ]
address [ TEXT ]
city [ TEXT ]
state [ TEXT ]
zip [ INTEGER ]
phone [ TEXT ]
title [ TEXT ]
salary [ INTEGER ]
supervisor [ INTEGER ] employee.supervisor = employee.employee_id
inspection :
inspection... | SELECT CAST(SUM(CASE WHEN T2.inspection_date LIKE '2010%' THEN 1 ELSE 0 END) AS REAL) / SUM(CASE WHEN T1.salary > 70000 THEN 1 ELSE 0 END) FROM employee AS T1 INNER JOIN inspection AS T2 ON T1.employee_id = T2.employee_id; |
[INST] Here is a database schema:
inspection_point :
point_id [ INTEGER ] primary_key
Description [ TEXT ]
category [ TEXT ]
code [ TEXT ]
fine [ INTEGER ]
point_level [ TEXT ]
Please write me a SQL statement that answers the following question: What is the point level of "Refrigeration and metal stem thermometers pro... | SELECT point_level FROM inspection_point WHERE Description = 'Refrigeration and metal stem thermometers provided and conspicuous '; |
[INST] Here is a database schema:
employee :
employee_id [ INTEGER ] primary_key
first_name [ TEXT ]
last_name [ TEXT ]
address [ TEXT ]
city [ TEXT ]
state [ TEXT ]
zip [ INTEGER ]
phone [ TEXT ]
title [ TEXT ]
salary [ INTEGER ]
supervisor [ INTEGER ] employee.supervisor = employee.employee_id
inspection :
inspection... | SELECT T2.first_name, T2.last_name FROM inspection AS T1 INNER JOIN employee AS T2 ON T1.employee_id = T2.employee_id WHERE T1.inspection_id = 48224; |
[INST] Here is a database schema:
establishment :
license_no [ INTEGER ] primary_key
dba_name [ TEXT ]
aka_name [ TEXT ]
facility_type [ TEXT ]
risk_level [ INTEGER ]
address [ TEXT ]
city [ TEXT ]
state [ TEXT ]
zip [ INTEGER ]
latitude [ REAL ]
longitude [ REAL ]
ward [ INTEGER ]
inspection :
inspection_id [ INTEGER ... | SELECT COUNT(T2.inspection_id) FROM establishment AS T1 INNER JOIN inspection AS T2 ON T1.license_no = T2.license_no WHERE T1.facility_type = 'Restaurant' AND T1.dba_name = 'All Style Buffet'; |
[INST] Here is a database schema:
establishment :
license_no [ INTEGER ] primary_key
dba_name [ TEXT ]
aka_name [ TEXT ]
facility_type [ TEXT ]
risk_level [ INTEGER ]
address [ TEXT ]
city [ TEXT ]
state [ TEXT ]
zip [ INTEGER ]
latitude [ REAL ]
longitude [ REAL ]
ward [ INTEGER ]
inspection :
inspection_id [ INTEGER ... | SELECT MIN(T2.inspection_date) FROM establishment AS T1 INNER JOIN inspection AS T2 ON T1.license_no = T2.license_no WHERE T1.aka_name = 'WING HUNG CHOP SUEY RESTAURANT'; |
[INST] Here is a database schema:
establishment :
license_no [ INTEGER ] primary_key
dba_name [ TEXT ]
aka_name [ TEXT ]
facility_type [ TEXT ]
risk_level [ INTEGER ]
address [ TEXT ]
city [ TEXT ]
state [ TEXT ]
zip [ INTEGER ]
latitude [ REAL ]
longitude [ REAL ]
ward [ INTEGER ]
inspection :
inspection_id [ INTEGER ... | SELECT COUNT(T2.license_no) FROM establishment AS T1 INNER JOIN inspection AS T2 ON T1.license_no = T2.license_no WHERE T2.inspection_date = '2015-05-08' AND T1.facility_type = 'Restaurant'; |
[INST] Here is a database schema:
inspection_point :
point_id [ INTEGER ] primary_key
Description [ TEXT ]
category [ TEXT ]
code [ TEXT ]
fine [ INTEGER ]
point_level [ TEXT ]
violation :
inspection_id [ INTEGER ] violation.inspection_id = inspection.inspection_id
point_id [ INTEGER ] violation.point_id = inspection_p... | SELECT COUNT(T2.point_id) FROM inspection_point AS T1 INNER JOIN violation AS T2 ON T1.point_id = T2.point_id WHERE T2.inspection_id = '1454071' AND T1.category = 'Food Maintenance'; |
[INST] Here is a database schema:
establishment :
license_no [ INTEGER ] primary_key
dba_name [ TEXT ]
aka_name [ TEXT ]
facility_type [ TEXT ]
risk_level [ INTEGER ]
address [ TEXT ]
city [ TEXT ]
state [ TEXT ]
zip [ INTEGER ]
latitude [ REAL ]
longitude [ REAL ]
ward [ INTEGER ]
inspection :
inspection_id [ INTEGER ... | SELECT COUNT(T3.point_id) FROM establishment AS T1 INNER JOIN inspection AS T2 ON T1.license_no = T2.license_no INNER JOIN violation AS T3 ON T2.inspection_id = T3.inspection_id WHERE T2.inspection_date = '2015-05-08' AND T1.dba_name = 'ROYAL THAI CUISINE'; |
[INST] Here is a database schema:
establishment :
license_no [ INTEGER ] primary_key
dba_name [ TEXT ]
aka_name [ TEXT ]
facility_type [ TEXT ]
risk_level [ INTEGER ]
address [ TEXT ]
city [ TEXT ]
state [ TEXT ]
zip [ INTEGER ]
latitude [ REAL ]
longitude [ REAL ]
ward [ INTEGER ]
inspection :
inspection_id [ INTEGER ... | SELECT COUNT(T2.inspection_id) FROM establishment AS T1 INNER JOIN inspection AS T2 ON T1.license_no = T2.license_no WHERE T1.address = '3635 W DIVERSEY AVE ' AND T1.facility_type = 'Grocery Store'; |
[INST] Here is a database schema:
employee :
employee_id [ INTEGER ] primary_key
first_name [ TEXT ]
last_name [ TEXT ]
address [ TEXT ]
city [ TEXT ]
state [ TEXT ]
zip [ INTEGER ]
phone [ TEXT ]
title [ TEXT ]
salary [ INTEGER ]
supervisor [ INTEGER ] employee.supervisor = employee.employee_id
inspection :
inspection... | SELECT T.first_name, T.last_name FROM ( SELECT T2.employee_id, T2.first_name, T2.last_name, COUNT(T1.inspection_id) FROM inspection AS T1 INNER JOIN employee AS T2 ON T1.employee_id = T2.employee_id GROUP BY T2.employee_id, T2.first_name, T2.last_name ORDER BY COUNT(T1.inspection_id) DESC LIMIT 1 ) AS T; |
[INST] Here is a database schema:
employee :
employee_id [ INTEGER ] primary_key
first_name [ TEXT ]
last_name [ TEXT ]
address [ TEXT ]
city [ TEXT ]
state [ TEXT ]
zip [ INTEGER ]
phone [ TEXT ]
title [ TEXT ]
salary [ INTEGER ]
supervisor [ INTEGER ] employee.supervisor = employee.employee_id
inspection :
inspection... | SELECT COUNT(T1.inspection_id) FROM inspection AS T1 INNER JOIN employee AS T2 ON T1.employee_id = T2.employee_id WHERE T2.first_name = 'Lisa' AND T2.last_name = 'Tillman' AND T1.results = 'Out of Business'; |
[INST] Here is a database schema:
employee :
employee_id [ INTEGER ] primary_key
first_name [ TEXT ]
last_name [ TEXT ]
address [ TEXT ]
city [ TEXT ]
state [ TEXT ]
zip [ INTEGER ]
phone [ TEXT ]
title [ TEXT ]
salary [ INTEGER ]
supervisor [ INTEGER ] employee.supervisor = employee.employee_id
inspection :
inspection... | SELECT COUNT(T1.inspection_id) FROM inspection AS T1 INNER JOIN employee AS T2 ON T1.employee_id = T2.employee_id WHERE T2.address = '5000 N Wolcott Ave' AND T2.title = 'Sanitarian' AND strftime('%Y-%m', T1.inspection_date) = '2011-05'; |
[INST] Here is a database schema:
employee :
employee_id [ INTEGER ] primary_key
first_name [ TEXT ]
last_name [ TEXT ]
address [ TEXT ]
city [ TEXT ]
state [ TEXT ]
zip [ INTEGER ]
phone [ TEXT ]
title [ TEXT ]
salary [ INTEGER ]
supervisor [ INTEGER ] employee.supervisor = employee.employee_id
inspection :
inspection... | SELECT T2.phone FROM inspection AS T1 INNER JOIN employee AS T2 ON T1.employee_id = T2.employee_id WHERE T1.inspection_id = 634597 AND T2.title = 'Sanitarian'; |
[INST] Here is a database schema:
employee :
employee_id [ INTEGER ] primary_key
first_name [ TEXT ]
last_name [ TEXT ]
address [ TEXT ]
city [ TEXT ]
state [ TEXT ]
zip [ INTEGER ]
phone [ TEXT ]
title [ TEXT ]
salary [ INTEGER ]
supervisor [ INTEGER ] employee.supervisor = employee.employee_id
inspection :
inspection... | SELECT T1.salary FROM employee AS T1 INNER JOIN ( SELECT T.employee_id, COUNT(T.inspection_id) FROM inspection AS T GROUP BY T.employee_id ORDER BY COUNT(T.inspection_id) DESC LIMIT 1 ) AS T2 ON T1.employee_id = T2.employee_id; |
[INST] Here is a database schema:
establishment :
license_no [ INTEGER ] primary_key
dba_name [ TEXT ]
aka_name [ TEXT ]
facility_type [ TEXT ]
risk_level [ INTEGER ]
address [ TEXT ]
city [ TEXT ]
state [ TEXT ]
zip [ INTEGER ]
latitude [ REAL ]
longitude [ REAL ]
ward [ INTEGER ]
inspection :
inspection_id [ INTEGER ... | SELECT CAST(COUNT(T2.inspection_id) AS REAL) / COUNT(DISTINCT T1.license_no) FROM establishment AS T1 INNER JOIN inspection AS T2 ON T1.license_no = T2.license_no WHERE T1.risk_level = 3 AND T1.facility_type = 'TAVERN'; |
[INST] Here is a database schema:
establishment :
license_no [ INTEGER ] primary_key
dba_name [ TEXT ]
aka_name [ TEXT ]
facility_type [ TEXT ]
risk_level [ INTEGER ]
address [ TEXT ]
city [ TEXT ]
state [ TEXT ]
zip [ INTEGER ]
latitude [ REAL ]
longitude [ REAL ]
ward [ INTEGER ]
inspection :
inspection_id [ INTEGER ... | SELECT CAST(COUNT(CASE WHEN T2.results = 'Pass' THEN T2.inspection_id ELSE NULL END) AS REAL) * 100 / COUNT(T2.inspection_id) FROM establishment AS T1 INNER JOIN inspection AS T2 ON T1.license_no = T2.license_no WHERE T1.dba_name = 'POCKETS' AND T1.facility_type = 'Restaurant'; |
[INST] Here is a database schema:
employee :
employee_id [ INTEGER ] primary_key
first_name [ TEXT ]
last_name [ TEXT ]
address [ TEXT ]
city [ TEXT ]
state [ TEXT ]
zip [ INTEGER ]
phone [ TEXT ]
title [ TEXT ]
salary [ INTEGER ]
supervisor [ INTEGER ] employee.supervisor = employee.employee_id
Please write me a SQL ... | SELECT COUNT(employee_id) FROM employee WHERE zip = '60617'; |
[INST] Here is a database schema:
establishment :
license_no [ INTEGER ] primary_key
dba_name [ TEXT ]
aka_name [ TEXT ]
facility_type [ TEXT ]
risk_level [ INTEGER ]
address [ TEXT ]
city [ TEXT ]
state [ TEXT ]
zip [ INTEGER ]
latitude [ REAL ]
longitude [ REAL ]
ward [ INTEGER ]
Please write me a SQL statement that... | SELECT DISTINCT dba_name FROM establishment WHERE address = '2903 W IRVING PARK RD '; |
[INST] Here is a database schema:
employee :
employee_id [ INTEGER ] primary_key
first_name [ TEXT ]
last_name [ TEXT ]
address [ TEXT ]
city [ TEXT ]
state [ TEXT ]
zip [ INTEGER ]
phone [ TEXT ]
title [ TEXT ]
salary [ INTEGER ]
supervisor [ INTEGER ] employee.supervisor = employee.employee_id
Please write me a SQL ... | SELECT first_name, last_name FROM employee ORDER BY salary ASC LIMIT 1; |
[INST] Here is a database schema:
establishment :
license_no [ INTEGER ] primary_key
dba_name [ TEXT ]
aka_name [ TEXT ]
facility_type [ TEXT ]
risk_level [ INTEGER ]
address [ TEXT ]
city [ TEXT ]
state [ TEXT ]
zip [ INTEGER ]
latitude [ REAL ]
longitude [ REAL ]
ward [ INTEGER ]
Please write me a SQL statement that... | SELECT COUNT(license_no) FROM establishment WHERE risk_level = 2 AND dba_name = 'HOMEMADE PIZZA'; |
[INST] Here is a database schema:
violation :
inspection_id [ INTEGER ] violation.inspection_id = inspection.inspection_id
point_id [ INTEGER ] violation.point_id = inspection_point.point_id
fine [ INTEGER ]
inspector_comment [ TEXT ]
Please write me a SQL statement that answers the following question: How many inspec... | SELECT COUNT(inspection_id) FROM violation WHERE point_id = 3 AND fine = 500; |
[INST] Here is a database schema:
employee :
employee_id [ INTEGER ] primary_key
first_name [ TEXT ]
last_name [ TEXT ]
address [ TEXT ]
city [ TEXT ]
state [ TEXT ]
zip [ INTEGER ]
phone [ TEXT ]
title [ TEXT ]
salary [ INTEGER ]
supervisor [ INTEGER ] employee.supervisor = employee.employee_id
Please write me a SQL ... | SELECT COUNT(T1.employee_id) FROM employee AS T1 WHERE T1.supervisor = ( SELECT employee_id FROM employee WHERE first_name = 'Gregory' AND last_name = 'Cardenas' ); |
[INST] Here is a database schema:
establishment :
license_no [ INTEGER ] primary_key
dba_name [ TEXT ]
aka_name [ TEXT ]
facility_type [ TEXT ]
risk_level [ INTEGER ]
address [ TEXT ]
city [ TEXT ]
state [ TEXT ]
zip [ INTEGER ]
latitude [ REAL ]
longitude [ REAL ]
ward [ INTEGER ]
inspection :
inspection_id [ INTEGER ... | SELECT MIN(T2.inspection_date) FROM establishment AS T1 INNER JOIN inspection AS T2 ON T1.license_no = T2.license_no WHERE T1.dba_name = 'RENALDI''S PIZZA'; |
[INST] Here is a database schema:
employee :
employee_id [ INTEGER ] primary_key
first_name [ TEXT ]
last_name [ TEXT ]
address [ TEXT ]
city [ TEXT ]
state [ TEXT ]
zip [ INTEGER ]
phone [ TEXT ]
title [ TEXT ]
salary [ INTEGER ]
supervisor [ INTEGER ] employee.supervisor = employee.employee_id
inspection :
inspection... | SELECT T3.first_name, T3.last_name FROM ( SELECT T1.employee_id, COUNT(T1.inspection_id) FROM inspection AS T1 WHERE strftime('%Y-%m', T1.inspection_date) = '2016-03' GROUP BY T1.employee_id ORDER BY COUNT(T1.inspection_id) DESC LIMIT 1 ) AS T2 INNER JOIN employee AS T3 ON T2.employee_id = T3.employee_id; |
[INST] Here is a database schema:
establishment :
license_no [ INTEGER ] primary_key
dba_name [ TEXT ]
aka_name [ TEXT ]
facility_type [ TEXT ]
risk_level [ INTEGER ]
address [ TEXT ]
city [ TEXT ]
state [ TEXT ]
zip [ INTEGER ]
latitude [ REAL ]
longitude [ REAL ]
ward [ INTEGER ]
inspection :
inspection_id [ INTEGER ... | SELECT DISTINCT T2.dba_name FROM inspection AS T1 INNER JOIN establishment AS T2 ON T1.license_no = T2.license_no WHERE strftime('%Y-%m', T1.inspection_date) = '2012-05' AND T1.results = 'Pass w/ Conditions'; |
[INST] Here is a database schema:
employee :
employee_id [ INTEGER ] primary_key
first_name [ TEXT ]
last_name [ TEXT ]
address [ TEXT ]
city [ TEXT ]
state [ TEXT ]
zip [ INTEGER ]
phone [ TEXT ]
title [ TEXT ]
salary [ INTEGER ]
supervisor [ INTEGER ] employee.supervisor = employee.employee_id
inspection :
inspection... | SELECT COUNT(DISTINCT T2.license_no) FROM employee AS T1 INNER JOIN inspection AS T2 ON T1.employee_id = T2.employee_id WHERE T1.first_name = 'David' AND T1.last_name = 'Hodges' AND T1.employee_id = 153225 AND T2.inspection_type = 'Short Form Complaint' AND T2.results = 'Pass'; |
[INST] Here is a database schema:
establishment :
license_no [ INTEGER ] primary_key
dba_name [ TEXT ]
aka_name [ TEXT ]
facility_type [ TEXT ]
risk_level [ INTEGER ]
address [ TEXT ]
city [ TEXT ]
state [ TEXT ]
zip [ INTEGER ]
latitude [ REAL ]
longitude [ REAL ]
ward [ INTEGER ]
inspection :
inspection_id [ INTEGER ... | SELECT COUNT(DISTINCT T1.license_no) FROM establishment AS T1 INNER JOIN inspection AS T2 ON T1.license_no = T2.license_no WHERE T2.inspection_date BETWEEN '2010-01-01' AND '2015-12-31' AND T1.ward = 42 AND T1.license_no IN ( SELECT license_no FROM ( SELECT license_no FROM inspection WHERE results = 'Fail' GROUP BY lic... |
[INST] Here is a database schema:
employee :
employee_id [ INTEGER ] primary_key
first_name [ TEXT ]
last_name [ TEXT ]
address [ TEXT ]
city [ TEXT ]
state [ TEXT ]
zip [ INTEGER ]
phone [ TEXT ]
title [ TEXT ]
salary [ INTEGER ]
supervisor [ INTEGER ] employee.supervisor = employee.employee_id
inspection :
inspection... | SELECT T1.salary FROM employee AS T1 INNER JOIN ( SELECT employee_id, COUNT(inspection_id) FROM inspection GROUP BY employee_id ORDER BY COUNT(inspection_id) DESC LIMIT 1 ) AS T2 ON T1.employee_id = T2.employee_id; |
[INST] Here is a database schema:
establishment :
license_no [ INTEGER ] primary_key
dba_name [ TEXT ]
aka_name [ TEXT ]
facility_type [ TEXT ]
risk_level [ INTEGER ]
address [ TEXT ]
city [ TEXT ]
state [ TEXT ]
zip [ INTEGER ]
latitude [ REAL ]
longitude [ REAL ]
ward [ INTEGER ]
inspection :
inspection_id [ INTEGER ... | SELECT T.dba_name FROM ( SELECT T1.dba_name, SUM(T3.fine) FROM establishment AS T1 INNER JOIN inspection AS T2 ON T1.license_no = T2.license_no INNER JOIN violation AS T3 ON T2.inspection_id = T3.inspection_id WHERE strftime('%Y', T2.inspection_date) = '2014' GROUP BY T1.dba_name ORDER BY SUM(T3.fine) DESC LIMIT 1 ) AS... |
[INST] Here is a database schema:
establishment :
license_no [ INTEGER ] primary_key
dba_name [ TEXT ]
aka_name [ TEXT ]
facility_type [ TEXT ]
risk_level [ INTEGER ]
address [ TEXT ]
city [ TEXT ]
state [ TEXT ]
zip [ INTEGER ]
latitude [ REAL ]
longitude [ REAL ]
ward [ INTEGER ]
inspection :
inspection_id [ INTEGER ... | SELECT T1.latitude, T1.longitude FROM establishment AS T1 INNER JOIN ( SELECT license_no FROM inspection WHERE results = 'Fail' GROUP BY license_no ORDER BY COUNT(results) DESC LIMIT 1 ) AS T2 ON T1.license_no = T2.license_no; |
[INST] Here is a database schema:
establishment :
license_no [ INTEGER ] primary_key
dba_name [ TEXT ]
aka_name [ TEXT ]
facility_type [ TEXT ]
risk_level [ INTEGER ]
address [ TEXT ]
city [ TEXT ]
state [ TEXT ]
zip [ INTEGER ]
latitude [ REAL ]
longitude [ REAL ]
ward [ INTEGER ]
inspection :
inspection_id [ INTEGER ... | SELECT T3.inspector_comment FROM establishment AS T1 INNER JOIN inspection AS T2 ON T1.license_no = T2.license_no INNER JOIN violation AS T3 ON T2.inspection_id = T3.inspection_id WHERE T2.inspection_date = '2010-01-25' AND T1.dba_name = 'TAQUERIA LA FIESTA'; |
[INST] Here is a database schema:
establishment :
license_no [ INTEGER ] primary_key
dba_name [ TEXT ]
aka_name [ TEXT ]
facility_type [ TEXT ]
risk_level [ INTEGER ]
address [ TEXT ]
city [ TEXT ]
state [ TEXT ]
zip [ INTEGER ]
latitude [ REAL ]
longitude [ REAL ]
ward [ INTEGER ]
inspection :
inspection_id [ INTEGER ... | SELECT SUM(T3.fine) FROM establishment AS T1 INNER JOIN inspection AS T2 ON T1.license_no = T2.license_no INNER JOIN violation AS T3 ON T2.inspection_id = T3.inspection_id WHERE strftime('%Y-%m', T2.inspection_date) = '2014-02' AND T1.dba_name = 'RON OF JAPAN INC'; |
[INST] Here is a database schema:
employee :
employee_id [ INTEGER ] primary_key
first_name [ TEXT ]
last_name [ TEXT ]
address [ TEXT ]
city [ TEXT ]
state [ TEXT ]
zip [ INTEGER ]
phone [ TEXT ]
title [ TEXT ]
salary [ INTEGER ]
supervisor [ INTEGER ] employee.supervisor = employee.employee_id
establishment :
license... | SELECT DISTINCT T3.first_name, T3.last_name FROM establishment AS T1 INNER JOIN inspection AS T2 ON T1.license_no = T2.license_no INNER JOIN employee AS T3 ON T2.employee_id = T3.employee_id WHERE T1.dba_name = 'TAQUERIA LA PAZ'; |
[INST] Here is a database schema:
employee :
employee_id [ INTEGER ] primary_key
first_name [ TEXT ]
last_name [ TEXT ]
address [ TEXT ]
city [ TEXT ]
state [ TEXT ]
zip [ INTEGER ]
phone [ TEXT ]
title [ TEXT ]
salary [ INTEGER ]
supervisor [ INTEGER ] employee.supervisor = employee.employee_id
inspection :
inspection... | SELECT T.first_name, T.last_name FROM ( SELECT T1.first_name, T1.last_name, SUM(T3.fine) FROM employee AS T1 INNER JOIN inspection AS T2 ON T1.employee_id = T2.employee_id INNER JOIN violation AS T3 ON T2.inspection_id = T3.inspection_id GROUP BY T1.first_name, T1.last_name ORDER BY SUM(T3.fine) DESC LIMIT 1 ) t; |
[INST] Here is a database schema:
employee :
employee_id [ INTEGER ] primary_key
first_name [ TEXT ]
last_name [ TEXT ]
address [ TEXT ]
city [ TEXT ]
state [ TEXT ]
zip [ INTEGER ]
phone [ TEXT ]
title [ TEXT ]
salary [ INTEGER ]
supervisor [ INTEGER ] employee.supervisor = employee.employee_id
inspection :
inspection... | SELECT CAST(COUNT(DISTINCT T2.inspection_id) AS REAL) / 5, T1.first_name, T1.last_name FROM employee AS T1 INNER JOIN inspection AS T2 ON T1.employee_id = T2.employee_id WHERE T1.title = 'Sanitarian' ORDER BY T1.salary DESC LIMIT 5; |
[INST] Here is a database schema:
establishment :
license_no [ INTEGER ] primary_key
dba_name [ TEXT ]
aka_name [ TEXT ]
facility_type [ TEXT ]
risk_level [ INTEGER ]
address [ TEXT ]
city [ TEXT ]
state [ TEXT ]
zip [ INTEGER ]
latitude [ REAL ]
longitude [ REAL ]
ward [ INTEGER ]
inspection :
inspection_id [ INTEGER ... | SELECT T2.dba_name , CAST(SUM(CASE WHEN T1.results = 'Pass' THEN 1 ELSE 0 END) AS REAL) * 100 / COUNT(T1.inspection_id) AS percentagePassed , CAST(SUM(CASE WHEN T1.results = 'Fail' THEN 1 ELSE 0 END) AS REAL) * 100 / COUNT(T1.inspection_id) FROM inspection AS T1 INNER JOIN establishment AS T2 ON T1.license_no = T2.lice... |
[INST] Here is a database schema:
employee :
employee_id [ INTEGER ] primary_key
first_name [ TEXT ]
last_name [ TEXT ]
address [ TEXT ]
city [ TEXT ]
state [ TEXT ]
zip [ INTEGER ]
phone [ TEXT ]
title [ TEXT ]
salary [ INTEGER ]
supervisor [ INTEGER ] employee.supervisor = employee.employee_id
Please write me a SQL ... | SELECT last_name FROM employee WHERE address = '7211 S Hermitage Ave' AND city = 'Chicago' AND state = 'IL'; |
[INST] Here is a database schema:
employee :
employee_id [ INTEGER ] primary_key
first_name [ TEXT ]
last_name [ TEXT ]
address [ TEXT ]
city [ TEXT ]
state [ TEXT ]
zip [ INTEGER ]
phone [ TEXT ]
title [ TEXT ]
salary [ INTEGER ]
supervisor [ INTEGER ] employee.supervisor = employee.employee_id
establishment :
license... | SELECT T1.dba_name, T3.first_name, T3.last_name FROM establishment AS T1 INNER JOIN inspection AS T2 ON T1.license_no = T2.license_no INNER JOIN employee AS T3 ON T2.employee_id = T3.employee_id WHERE T2.inspection_date = '2010-05-05' AND T2.inspection_id = 44256; |
[INST] Here is a database schema:
establishment :
license_no [ INTEGER ] primary_key
dba_name [ TEXT ]
aka_name [ TEXT ]
facility_type [ TEXT ]
risk_level [ INTEGER ]
address [ TEXT ]
city [ TEXT ]
state [ TEXT ]
zip [ INTEGER ]
latitude [ REAL ]
longitude [ REAL ]
ward [ INTEGER ]
inspection :
inspection_id [ INTEGER ... | SELECT DISTINCT T1.address FROM establishment AS T1 INNER JOIN inspection AS T2 ON T1.license_no = T2.license_no WHERE strftime('%Y-%m', T2.inspection_date) = '2010-03' AND T2.results = 'Pass' AND T1.facility_type = 'School'; |
[INST] Here is a database schema:
employee :
employee_id [ INTEGER ] primary_key
first_name [ TEXT ]
last_name [ TEXT ]
address [ TEXT ]
city [ TEXT ]
state [ TEXT ]
zip [ INTEGER ]
phone [ TEXT ]
title [ TEXT ]
salary [ INTEGER ]
supervisor [ INTEGER ] employee.supervisor = employee.employee_id
inspection :
inspection... | SELECT DISTINCT T1.first_name, T1.last_name FROM employee AS T1 INNER JOIN inspection AS T2 ON T1.employee_id = T2.employee_id WHERE T2.inspection_date = '2010-03-09' AND T2.inspection_type = 'Canvass'; |
[INST] Here is a database schema:
establishment :
license_no [ INTEGER ] primary_key
dba_name [ TEXT ]
aka_name [ TEXT ]
facility_type [ TEXT ]
risk_level [ INTEGER ]
address [ TEXT ]
city [ TEXT ]
state [ TEXT ]
zip [ INTEGER ]
latitude [ REAL ]
longitude [ REAL ]
ward [ INTEGER ]
inspection :
inspection_id [ INTEGER ... | SELECT DISTINCT T2.inspection_id FROM establishment AS T1 INNER JOIN inspection AS T2 ON T1.license_no = T2.license_no WHERE T1.dba_name = 'PIZZA RUSTICA, INC'; |
[INST] Here is a database schema:
establishment :
license_no [ INTEGER ] primary_key
dba_name [ TEXT ]
aka_name [ TEXT ]
facility_type [ TEXT ]
risk_level [ INTEGER ]
address [ TEXT ]
city [ TEXT ]
state [ TEXT ]
zip [ INTEGER ]
latitude [ REAL ]
longitude [ REAL ]
ward [ INTEGER ]
inspection :
inspection_id [ INTEGER ... | SELECT COUNT(DISTINCT T1.license_no) FROM establishment AS T1 INNER JOIN inspection AS T2 ON T1.license_no = T2.license_no WHERE T1.risk_level = 3 AND T2.results = 'Pass' AND T1.facility_type = 'Restaurant'; |
[INST] Here is a database schema:
employee :
employee_id [ INTEGER ] primary_key
first_name [ TEXT ]
last_name [ TEXT ]
address [ TEXT ]
city [ TEXT ]
state [ TEXT ]
zip [ INTEGER ]
phone [ TEXT ]
title [ TEXT ]
salary [ INTEGER ]
supervisor [ INTEGER ] employee.supervisor = employee.employee_id
inspection :
inspection... | SELECT DISTINCT T1.first_name, T1.last_name FROM employee AS T1 INNER JOIN inspection AS T2 ON T1.employee_id = T2.employee_id INNER JOIN violation AS T3 ON T2.inspection_id = T3.inspection_id INNER JOIN inspection_point AS T4 ON T3.point_id = T4.point_id WHERE T4.category = 'Display of Inspection Report Summary'; |
[INST] Here is a database schema:
employee :
employee_id [ INTEGER ] primary_key
first_name [ TEXT ]
last_name [ TEXT ]
address [ TEXT ]
city [ TEXT ]
state [ TEXT ]
zip [ INTEGER ]
phone [ TEXT ]
title [ TEXT ]
salary [ INTEGER ]
supervisor [ INTEGER ] employee.supervisor = employee.employee_id
inspection :
inspection... | SELECT T1.title FROM employee AS T1 INNER JOIN inspection AS T2 ON T1.employee_id = T2.employee_id WHERE T2.inspection_id = 60332; |
[INST] Here is a database schema:
establishment :
license_no [ INTEGER ] primary_key
dba_name [ TEXT ]
aka_name [ TEXT ]
facility_type [ TEXT ]
risk_level [ INTEGER ]
address [ TEXT ]
city [ TEXT ]
state [ TEXT ]
zip [ INTEGER ]
latitude [ REAL ]
longitude [ REAL ]
ward [ INTEGER ]
inspection :
inspection_id [ INTEGER ... | SELECT COUNT(DISTINCT T1.license_no) FROM establishment AS T1 INNER JOIN inspection AS T2 ON T1.license_no = T2.license_no WHERE T1.risk_level = '1' AND T2.inspection_type = 'Complaint' AND T1.facility_type = 'Restaurant' AND T2.results = 'Fail'; |
[INST] Here is a database schema:
establishment :
license_no [ INTEGER ] primary_key
dba_name [ TEXT ]
aka_name [ TEXT ]
facility_type [ TEXT ]
risk_level [ INTEGER ]
address [ TEXT ]
city [ TEXT ]
state [ TEXT ]
zip [ INTEGER ]
latitude [ REAL ]
longitude [ REAL ]
ward [ INTEGER ]
inspection :
inspection_id [ INTEGER ... | SELECT DISTINCT T3.fine, T1.state, T1.city, T1.address FROM establishment AS T1 INNER JOIN inspection AS T2 ON T1.license_no = T2.license_no INNER JOIN violation AS T3 ON T2.inspection_id = T3.inspection_id WHERE T2.inspection_id = 48216; |
[INST] Here is a database schema:
inspection_point :
point_id [ INTEGER ] primary_key
Description [ TEXT ]
category [ TEXT ]
code [ TEXT ]
fine [ INTEGER ]
point_level [ TEXT ]
violation :
inspection_id [ INTEGER ] violation.inspection_id = inspection.inspection_id
point_id [ INTEGER ] violation.point_id = inspection_p... | SELECT T2.inspection_id FROM inspection_point AS T1 INNER JOIN violation AS T2 ON T1.point_id = T2.point_id WHERE T2.fine = 500 AND T1.point_level = 'Critical' AND T2.inspector_comment = 'CDI ON 5-17-10'; |
[INST] Here is a database schema:
inspection_point :
point_id [ INTEGER ] primary_key
Description [ TEXT ]
category [ TEXT ]
code [ TEXT ]
fine [ INTEGER ]
point_level [ TEXT ]
violation :
inspection_id [ INTEGER ] violation.inspection_id = inspection.inspection_id
point_id [ INTEGER ] violation.point_id = inspection_p... | SELECT T1.Description, T2.inspector_comment FROM inspection_point AS T1 INNER JOIN violation AS T2 ON T1.point_id = T2.point_id WHERE T2.inspection_id = 44247; |
[INST] Here is a database schema:
inspection_point :
point_id [ INTEGER ] primary_key
Description [ TEXT ]
category [ TEXT ]
code [ TEXT ]
fine [ INTEGER ]
point_level [ TEXT ]
violation :
inspection_id [ INTEGER ] violation.inspection_id = inspection.inspection_id
point_id [ INTEGER ] violation.point_id = inspection_p... | SELECT T2.inspector_comment, T1.code FROM inspection_point AS T1 INNER JOIN violation AS T2 ON T1.point_id = T2.point_id WHERE T2.inspection_id = 54216 AND T2.point_id = 34; |
[INST] Here is a database schema:
establishment :
license_no [ INTEGER ] primary_key
dba_name [ TEXT ]
aka_name [ TEXT ]
facility_type [ TEXT ]
risk_level [ INTEGER ]
address [ TEXT ]
city [ TEXT ]
state [ TEXT ]
zip [ INTEGER ]
latitude [ REAL ]
longitude [ REAL ]
ward [ INTEGER ]
inspection :
inspection_id [ INTEGER ... | SELECT CAST(COUNT(CASE WHEN T1.risk_level = 3 THEN T1.license_no END) AS REAL) * 100 / COUNT(T1.risk_level) FROM establishment AS T1 INNER JOIN inspection AS T2 ON T1.license_no = T2.license_no WHERE T2.results = 'Fail'; |
[INST] Here is a database schema:
employee :
employee_id [ INTEGER ] primary_key
first_name [ TEXT ]
last_name [ TEXT ]
address [ TEXT ]
city [ TEXT ]
state [ TEXT ]
zip [ INTEGER ]
phone [ TEXT ]
title [ TEXT ]
salary [ INTEGER ]
supervisor [ INTEGER ] employee.supervisor = employee.employee_id
inspection :
inspection... | SELECT SUM(CASE WHEN T3.fine = 100 THEN 1 ELSE 0 END) - SUM(CASE WHEN T3.fine = 500 THEN 1 ELSE 0 END) FROM employee AS T1 INNER JOIN inspection AS T2 ON T1.employee_id = T2.employee_id INNER JOIN violation AS T3 ON T2.inspection_id = T3.inspection_id WHERE T1.salary BETWEEN 75000 AND 80000; |
[INST] Here is a database schema:
inspection :
inspection_id [ INTEGER ] primary_key
inspection_date [ DATE ]
inspection_type [ TEXT ]
results [ TEXT ]
employee_id [ INTEGER ] inspection.employee_id = employee.employee_id
license_no [ INTEGER ] inspection.license_no = establishment.license_no
followup_to [ INTEGER ] in... | SELECT COUNT(inspection_id) FROM inspection WHERE strftime('%Y-%m', inspection_date) = '2011-01'; |
[INST] Here is a database schema:
inspection :
inspection_id [ INTEGER ] primary_key
inspection_date [ DATE ]
inspection_type [ TEXT ]
results [ TEXT ]
employee_id [ INTEGER ] inspection.employee_id = employee.employee_id
license_no [ INTEGER ] inspection.license_no = establishment.license_no
followup_to [ INTEGER ] in... | SELECT COUNT(inspection_id) FROM inspection WHERE strftime('%Y', inspection_date) = '2014' AND results = 'Fail'; |
[INST] Here is a database schema:
violation :
inspection_id [ INTEGER ] violation.inspection_id = inspection.inspection_id
point_id [ INTEGER ] violation.point_id = inspection_point.point_id
fine [ INTEGER ]
inspector_comment [ TEXT ]
Please write me a SQL statement that answers the following question: Calculate the p... | SELECT CAST(COUNT(CASE WHEN fine = 100 THEN inspection_id END) AS REAL) * 100 / COUNT(inspection_id) FROM violation; |
[INST] Here is a database schema:
inspection :
inspection_id [ INTEGER ] primary_key
inspection_date [ DATE ]
inspection_type [ TEXT ]
results [ TEXT ]
employee_id [ INTEGER ] inspection.employee_id = employee.employee_id
license_no [ INTEGER ] inspection.license_no = establishment.license_no
followup_to [ INTEGER ] in... | SELECT T2.point_id, T2.fine FROM inspection AS T1 INNER JOIN violation AS T2 ON T1.inspection_id = T2.inspection_id WHERE T1.inspection_date = '2010-08-07'; |
[INST] Here is a database schema:
inspection_point :
point_id [ INTEGER ] primary_key
Description [ TEXT ]
category [ TEXT ]
code [ TEXT ]
fine [ INTEGER ]
point_level [ TEXT ]
violation :
inspection_id [ INTEGER ] violation.inspection_id = inspection.inspection_id
point_id [ INTEGER ] violation.point_id = inspection_p... | SELECT COUNT(T1.inspection_id) FROM violation AS T1 INNER JOIN inspection_point AS T2 ON T1.point_id = T2.point_id WHERE T2.category = 'Personnel'; |
[INST] Here is a database schema:
establishment :
license_no [ INTEGER ] primary_key
dba_name [ TEXT ]
aka_name [ TEXT ]
facility_type [ TEXT ]
risk_level [ INTEGER ]
address [ TEXT ]
city [ TEXT ]
state [ TEXT ]
zip [ INTEGER ]
latitude [ REAL ]
longitude [ REAL ]
ward [ INTEGER ]
inspection :
inspection_id [ INTEGER ... | SELECT DISTINCT T1.dba_name, T2.results FROM establishment AS T1 INNER JOIN inspection AS T2 ON T1.license_no = T2.license_no WHERE T1.city = 'BURNHAM'; |
[INST] Here is a database schema:
inspection_point :
point_id [ INTEGER ] primary_key
Description [ TEXT ]
category [ TEXT ]
code [ TEXT ]
fine [ INTEGER ]
point_level [ TEXT ]
violation :
inspection_id [ INTEGER ] violation.inspection_id = inspection.inspection_id
point_id [ INTEGER ] violation.point_id = inspection_p... | SELECT COUNT(CASE WHEN T2.category = 'Toxic Items' THEN T1.inspection_id END) AS Tox_nums , COUNT(CASE WHEN T2.category = 'No Smoking Regulations' THEN T1.inspection_id END) AS NosmoNums FROM violation AS T1 INNER JOIN inspection_point AS T2 ON T1.point_id = T2.point_id; |
[INST] Here is a database schema:
employee :
employee_id [ INTEGER ] primary_key
first_name [ TEXT ]
last_name [ TEXT ]
address [ TEXT ]
city [ TEXT ]
state [ TEXT ]
zip [ INTEGER ]
phone [ TEXT ]
title [ TEXT ]
salary [ INTEGER ]
supervisor [ INTEGER ] employee.supervisor = employee.employee_id
establishment :
license... | SELECT DISTINCT T1.dba_name FROM establishment AS T1 INNER JOIN inspection AS T2 ON T1.license_no = T2.license_no INNER JOIN employee AS T3 ON T2.employee_id = T3.employee_id WHERE T2.inspection_date = '2012-11-20' AND T3.first_name = 'Sarah' AND T3.last_name = 'Lindsey'; |
[INST] Here is a database schema:
employee :
employee_id [ INTEGER ] primary_key
first_name [ TEXT ]
last_name [ TEXT ]
address [ TEXT ]
city [ TEXT ]
state [ TEXT ]
zip [ INTEGER ]
phone [ TEXT ]
title [ TEXT ]
salary [ INTEGER ]
supervisor [ INTEGER ] employee.supervisor = employee.employee_id
inspection :
inspection... | SELECT DISTINCT T4.category, T3.fine FROM inspection AS T1 INNER JOIN employee AS T2 ON T1.employee_id = T2.employee_id INNER JOIN violation AS T3 ON T1.inspection_id = T3.inspection_id INNER JOIN inspection_point AS T4 ON T3.point_id = T4.point_id WHERE T2.first_name = 'Lisa' AND T2.last_name = 'Tillman' AND strftime(... |
[INST] Here is a database schema:
inspection_point :
point_id [ INTEGER ] primary_key
Description [ TEXT ]
category [ TEXT ]
code [ TEXT ]
fine [ INTEGER ]
point_level [ TEXT ]
violation :
inspection_id [ INTEGER ] violation.inspection_id = inspection.inspection_id
point_id [ INTEGER ] violation.point_id = inspection_p... | SELECT COUNT(T2.inspection_id) FROM inspection_point AS T1 INNER JOIN violation AS T2 ON T1.point_id = T2.point_id WHERE T1.category = 'Display of Inspection Report Summary'; |
[INST] Here is a database schema:
establishment :
license_no [ INTEGER ] primary_key
dba_name [ TEXT ]
aka_name [ TEXT ]
facility_type [ TEXT ]
risk_level [ INTEGER ]
address [ TEXT ]
city [ TEXT ]
state [ TEXT ]
zip [ INTEGER ]
latitude [ REAL ]
longitude [ REAL ]
ward [ INTEGER ]
inspection :
inspection_id [ INTEGER ... | SELECT T2.inspection_type, T2.results FROM establishment AS T1 INNER JOIN inspection AS T2 ON T1.license_no = T2.license_no WHERE T1.facility_type = 'RIVERWALK CAFE'; |
[INST] Here is a database schema:
employee :
employee_id [ INTEGER ] primary_key
first_name [ TEXT ]
last_name [ TEXT ]
address [ TEXT ]
city [ TEXT ]
state [ TEXT ]
zip [ INTEGER ]
phone [ TEXT ]
title [ TEXT ]
salary [ INTEGER ]
supervisor [ INTEGER ] employee.supervisor = employee.employee_id
establishment :
license... | SELECT T3.first_name, T3.last_name, T2.results FROM establishment AS T1 INNER JOIN inspection AS T2 ON T1.license_no = T2.license_no INNER JOIN employee AS T3 ON T2.employee_id = T3.employee_id WHERE T1.dba_name = 'JEAN SAMOCKI'; |
[INST] Here is a database schema:
establishment :
license_no [ INTEGER ] primary_key
dba_name [ TEXT ]
aka_name [ TEXT ]
facility_type [ TEXT ]
risk_level [ INTEGER ]
address [ TEXT ]
city [ TEXT ]
state [ TEXT ]
zip [ INTEGER ]
latitude [ REAL ]
longitude [ REAL ]
ward [ INTEGER ]
inspection :
inspection_id [ INTEGER ... | SELECT SUM(T3.fine) FROM establishment AS T1 INNER JOIN inspection AS T2 ON T1.license_no = T2.license_no INNER JOIN violation AS T3 ON T2.inspection_id = T3.inspection_id WHERE T1.dba_name = 'HACIENDA LOS TORRES' AND T1.ward = 36 AND T2.results = 'Fail'; |
[INST] Here is a database schema:
inspection_point :
point_id [ INTEGER ] primary_key
Description [ TEXT ]
category [ TEXT ]
code [ TEXT ]
fine [ INTEGER ]
point_level [ TEXT ]
violation :
inspection_id [ INTEGER ] violation.inspection_id = inspection.inspection_id
point_id [ INTEGER ] violation.point_id = inspection_p... | SELECT SUM(T2.fine) FROM inspection_point AS T1 INNER JOIN violation AS T2 ON T1.point_id = T2.point_id WHERE T1.category = 'Food Equipment and Utensil'; |
[INST] Here is a database schema:
establishment :
license_no [ INTEGER ] primary_key
dba_name [ TEXT ]
aka_name [ TEXT ]
facility_type [ TEXT ]
risk_level [ INTEGER ]
address [ TEXT ]
city [ TEXT ]
state [ TEXT ]
zip [ INTEGER ]
latitude [ REAL ]
longitude [ REAL ]
ward [ INTEGER ]
inspection :
inspection_id [ INTEGER ... | SELECT T2.dba_name, T2.longitude, T2.latitude FROM inspection AS T1 INNER JOIN establishment AS T2 ON T1.license_no = T2.license_no WHERE T1.inspection_date = '2013-07-29' AND T1.results = 'Fail'; |
[INST] Here is a database schema:
establishment :
license_no [ INTEGER ] primary_key
dba_name [ TEXT ]
aka_name [ TEXT ]
facility_type [ TEXT ]
risk_level [ INTEGER ]
address [ TEXT ]
city [ TEXT ]
state [ TEXT ]
zip [ INTEGER ]
latitude [ REAL ]
longitude [ REAL ]
ward [ INTEGER ]
inspection :
inspection_id [ INTEGER ... | SELECT CAST(COUNT(CASE WHEN T2.results LIKE '%Pass%' THEN T2.inspection_id END) AS REAL) * 100 / COUNT(T2.inspection_id), COUNT(DISTINCT T2.license_no) FROM establishment AS T1 INNER JOIN inspection AS T2 ON T1.license_no = T2.license_no WHERE T1.city = 'CHICAGO'; |
[INST] Here is a database schema:
employee :
employee_id [ INTEGER ] primary_key
first_name [ TEXT ]
last_name [ TEXT ]
address [ TEXT ]
city [ TEXT ]
state [ TEXT ]
zip [ INTEGER ]
phone [ TEXT ]
title [ TEXT ]
salary [ INTEGER ]
supervisor [ INTEGER ] employee.supervisor = employee.employee_id
inspection :
inspection... | SELECT CAST(COUNT(CASE WHEN T1.first_name = 'Jessica' AND T1.last_name = 'Anthony' THEN T2.inspection_id ELSE 0 END) AS REAL) / 8 FROM employee AS T1 INNER JOIN inspection AS T2 ON T1.employee_id = T2.employee_id WHERE strftime('%Y', T2.inspection_date) BETWEEN '2010' AND '2017'; |
[INST] Here is a database schema:
employee :
employee_id [ INTEGER ] primary_key
first_name [ TEXT ]
last_name [ TEXT ]
address [ TEXT ]
city [ TEXT ]
state [ TEXT ]
zip [ INTEGER ]
phone [ TEXT ]
title [ TEXT ]
salary [ INTEGER ]
supervisor [ INTEGER ] employee.supervisor = employee.employee_id
inspection :
inspection... | SELECT T1.first_name FROM employee AS T1 INNER JOIN inspection AS T2 ON T1.employee_id = T2.employee_id WHERE T2.inspection_id = 48225; |
[INST] Here is a database schema:
employee :
employee_id [ INTEGER ] primary_key
first_name [ TEXT ]
last_name [ TEXT ]
address [ TEXT ]
city [ TEXT ]
state [ TEXT ]
zip [ INTEGER ]
phone [ TEXT ]
title [ TEXT ]
salary [ INTEGER ]
supervisor [ INTEGER ] employee.supervisor = employee.employee_id
inspection :
inspection... | SELECT T1.address FROM employee AS T1 INNER JOIN inspection AS T2 ON T1.employee_id = T2.employee_id WHERE T2.inspection_id = 52238; |
[INST] Here is a database schema:
employee :
employee_id [ INTEGER ] primary_key
first_name [ TEXT ]
last_name [ TEXT ]
address [ TEXT ]
city [ TEXT ]
state [ TEXT ]
zip [ INTEGER ]
phone [ TEXT ]
title [ TEXT ]
salary [ INTEGER ]
supervisor [ INTEGER ] employee.supervisor = employee.employee_id
inspection :
inspection... | SELECT T1.last_name FROM employee AS T1 INNER JOIN inspection AS T2 ON T1.employee_id = T2.employee_id WHERE T2.inspection_id = 52238; |
[INST] Here is a database schema:
employee :
employee_id [ INTEGER ] primary_key
first_name [ TEXT ]
last_name [ TEXT ]
address [ TEXT ]
city [ TEXT ]
state [ TEXT ]
zip [ INTEGER ]
phone [ TEXT ]
title [ TEXT ]
salary [ INTEGER ]
supervisor [ INTEGER ] employee.supervisor = employee.employee_id
inspection :
inspection... | SELECT DISTINCT T2.results FROM employee AS T1 INNER JOIN inspection AS T2 ON T1.employee_id = T2.employee_id WHERE T1.first_name = 'Thomas' AND T1.last_name = 'Langley'; |
[INST] Here is a database schema:
employee :
employee_id [ INTEGER ] primary_key
first_name [ TEXT ]
last_name [ TEXT ]
address [ TEXT ]
city [ TEXT ]
state [ TEXT ]
zip [ INTEGER ]
phone [ TEXT ]
title [ TEXT ]
salary [ INTEGER ]
supervisor [ INTEGER ] employee.supervisor = employee.employee_id
inspection :
inspection... | SELECT DISTINCT T1.address FROM employee AS T1 INNER JOIN inspection AS T2 ON T1.employee_id = T2.employee_id WHERE T2.inspection_date = '2010-11-05'; |
[INST] Here is a database schema:
employee :
employee_id [ INTEGER ] primary_key
first_name [ TEXT ]
last_name [ TEXT ]
address [ TEXT ]
city [ TEXT ]
state [ TEXT ]
zip [ INTEGER ]
phone [ TEXT ]
title [ TEXT ]
salary [ INTEGER ]
supervisor [ INTEGER ] employee.supervisor = employee.employee_id
inspection :
inspection... | SELECT DISTINCT T1.phone FROM employee AS T1 INNER JOIN inspection AS T2 ON T1.employee_id = T2.employee_id WHERE T2.inspection_type = 'Canvass'; |
[INST] Here is a database schema:
employee :
employee_id [ INTEGER ] primary_key
first_name [ TEXT ]
last_name [ TEXT ]
address [ TEXT ]
city [ TEXT ]
state [ TEXT ]
zip [ INTEGER ]
phone [ TEXT ]
title [ TEXT ]
salary [ INTEGER ]
supervisor [ INTEGER ] employee.supervisor = employee.employee_id
inspection :
inspection... | SELECT T1.title FROM employee AS T1 INNER JOIN inspection AS T2 ON T1.employee_id = T2.employee_id WHERE T2.inspection_id = 52269; |
[INST] Here is a database schema:
establishment :
license_no [ INTEGER ] primary_key
dba_name [ TEXT ]
aka_name [ TEXT ]
facility_type [ TEXT ]
risk_level [ INTEGER ]
address [ TEXT ]
city [ TEXT ]
state [ TEXT ]
zip [ INTEGER ]
latitude [ REAL ]
longitude [ REAL ]
ward [ INTEGER ]
inspection :
inspection_id [ INTEGER ... | SELECT DISTINCT T2.results FROM establishment AS T1 INNER JOIN inspection AS T2 ON T1.license_no = T2.license_no WHERE T1.dba_name = 'XANDO COFFEE & BAR / COSI SANDWICH BAR'; |
[INST] Here is a database schema:
establishment :
license_no [ INTEGER ] primary_key
dba_name [ TEXT ]
aka_name [ TEXT ]
facility_type [ TEXT ]
risk_level [ INTEGER ]
address [ TEXT ]
city [ TEXT ]
state [ TEXT ]
zip [ INTEGER ]
latitude [ REAL ]
longitude [ REAL ]
ward [ INTEGER ]
inspection :
inspection_id [ INTEGER ... | SELECT DISTINCT T2.inspection_type FROM establishment AS T1 INNER JOIN inspection AS T2 ON T1.license_no = T2.license_no WHERE T1.dba_name = 'JOHN SCHALLER'; |
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