input
stringlengths
122
2.7k
output
stringlengths
24
805
[INST] Here is a database schema: establishment : license_no [ INTEGER ] primary_key dba_name [ TEXT ] aka_name [ TEXT ] facility_type [ TEXT ] risk_level [ INTEGER ] address [ TEXT ] city [ TEXT ] state [ TEXT ] zip [ INTEGER ] latitude [ REAL ] longitude [ REAL ] ward [ INTEGER ] inspection : inspection_id [ INTEGER ...
SELECT T1.dba_name FROM establishment AS T1 INNER JOIN inspection AS T2 ON T1.license_no = T2.license_no WHERE T2.inspection_type = 'License';
[INST] Here is a database schema: establishment : license_no [ INTEGER ] primary_key dba_name [ TEXT ] aka_name [ TEXT ] facility_type [ TEXT ] risk_level [ INTEGER ] address [ TEXT ] city [ TEXT ] state [ TEXT ] zip [ INTEGER ] latitude [ REAL ] longitude [ REAL ] ward [ INTEGER ] inspection : inspection_id [ INTEGER ...
SELECT COUNT(T2.inspection_id) FROM establishment AS T1 INNER JOIN inspection AS T2 ON T1.license_no = T2.license_no WHERE strftime('%Y', T2.inspection_date) = '2010' AND T1.risk_level = 3;
[INST] Here is a database schema: establishment : license_no [ INTEGER ] primary_key dba_name [ TEXT ] aka_name [ TEXT ] facility_type [ TEXT ] risk_level [ INTEGER ] address [ TEXT ] city [ TEXT ] state [ TEXT ] zip [ INTEGER ] latitude [ REAL ] longitude [ REAL ] ward [ INTEGER ] inspection : inspection_id [ INTEGER ...
SELECT DISTINCT T1.dba_name FROM establishment AS T1 INNER JOIN inspection AS T2 ON T1.license_no = T2.license_no WHERE T2.results LIKE '%Pass%';
[INST] Here is a database schema: employee : employee_id [ INTEGER ] primary_key first_name [ TEXT ] last_name [ TEXT ] address [ TEXT ] city [ TEXT ] state [ TEXT ] zip [ INTEGER ] phone [ TEXT ] title [ TEXT ] salary [ INTEGER ] supervisor [ INTEGER ] employee.supervisor = employee.employee_id inspection : inspection...
SELECT SUM(T2.salary) FROM inspection AS T1 INNER JOIN employee AS T2 ON T1.employee_id = T2.employee_id WHERE T1.inspection_id BETWEEN 52270 AND 52272;
[INST] Here is a database schema: employee : employee_id [ INTEGER ] primary_key first_name [ TEXT ] last_name [ TEXT ] address [ TEXT ] city [ TEXT ] state [ TEXT ] zip [ INTEGER ] phone [ TEXT ] title [ TEXT ] salary [ INTEGER ] supervisor [ INTEGER ] employee.supervisor = employee.employee_id inspection : inspection...
SELECT AVG(T2.salary) FROM inspection AS T1 INNER JOIN employee AS T2 ON T1.employee_id = T2.employee_id WHERE T1.inspection_type = 'License Re-Inspection';
[INST] Here is a database schema: establishment : license_no [ INTEGER ] primary_key dba_name [ TEXT ] aka_name [ TEXT ] facility_type [ TEXT ] risk_level [ INTEGER ] address [ TEXT ] city [ TEXT ] state [ TEXT ] zip [ INTEGER ] latitude [ REAL ] longitude [ REAL ] ward [ INTEGER ] inspection : inspection_id [ INTEGER ...
SELECT DISTINCT T2.results, T1.zip FROM establishment AS T1 INNER JOIN inspection AS T2 ON T1.license_no = T2.license_no WHERE T1.license_no = 1222441;
[INST] Here is a database schema: establishment : license_no [ INTEGER ] primary_key dba_name [ TEXT ] aka_name [ TEXT ] facility_type [ TEXT ] risk_level [ INTEGER ] address [ TEXT ] city [ TEXT ] state [ TEXT ] zip [ INTEGER ] latitude [ REAL ] longitude [ REAL ] ward [ INTEGER ] inspection : inspection_id [ INTEGER ...
SELECT MIN(T2.inspection_date) FROM establishment AS T1 INNER JOIN inspection AS T2 ON T1.license_no = T2.license_no WHERE T1.dba_name = 'JOHN SCHALLER' AND strftime('%Y', T2.inspection_date) = '2010';
[INST] Here is a database schema: employee : employee_id [ INTEGER ] primary_key first_name [ TEXT ] last_name [ TEXT ] address [ TEXT ] city [ TEXT ] state [ TEXT ] zip [ INTEGER ] phone [ TEXT ] title [ TEXT ] salary [ INTEGER ] supervisor [ INTEGER ] employee.supervisor = employee.employee_id inspection : inspection...
SELECT DISTINCT T1.first_name, T1.last_name FROM employee AS T1 INNER JOIN inspection AS T2 ON T1.employee_id = T2.employee_id WHERE T2.license_no = 1334073;
[INST] Here is a database schema: employee : employee_id [ INTEGER ] primary_key first_name [ TEXT ] last_name [ TEXT ] address [ TEXT ] city [ TEXT ] state [ TEXT ] zip [ INTEGER ] phone [ TEXT ] title [ TEXT ] salary [ INTEGER ] supervisor [ INTEGER ] employee.supervisor = employee.employee_id establishment : license...
SELECT DISTINCT T3.dba_name FROM employee AS T1 INNER JOIN inspection AS T2 ON T1.employee_id = T2.employee_id INNER JOIN establishment AS T3 ON T2.license_no = T3.license_no WHERE T1.first_name = 'Joshua' AND T1.last_name = 'Rosa';
[INST] Here is a database schema: employee : employee_id [ INTEGER ] primary_key first_name [ TEXT ] last_name [ TEXT ] address [ TEXT ] city [ TEXT ] state [ TEXT ] zip [ INTEGER ] phone [ TEXT ] title [ TEXT ] salary [ INTEGER ] supervisor [ INTEGER ] employee.supervisor = employee.employee_id inspection : inspection...
SELECT COUNT(DISTINCT T1.employee_id) FROM employee AS T1 INNER JOIN inspection AS T2 ON T1.employee_id = T2.employee_id WHERE T2.results = 'Fail' AND T1.salary > 70000;
[INST] Here is a database schema: establishment : license_no [ INTEGER ] primary_key dba_name [ TEXT ] aka_name [ TEXT ] facility_type [ TEXT ] risk_level [ INTEGER ] address [ TEXT ] city [ TEXT ] state [ TEXT ] zip [ INTEGER ] latitude [ REAL ] longitude [ REAL ] ward [ INTEGER ] inspection : inspection_id [ INTEGER ...
SELECT DISTINCT T1.dba_name FROM establishment AS T1 INNER JOIN inspection AS T2 ON T1.license_no = T2.license_no WHERE strftime('%Y', T2.inspection_date) = '2010' AND T2.results = 'Pass' AND T1.facility_type = 'Liquor';
[INST] Here is a database schema: employee : employee_id [ INTEGER ] primary_key first_name [ TEXT ] last_name [ TEXT ] address [ TEXT ] city [ TEXT ] state [ TEXT ] zip [ INTEGER ] phone [ TEXT ] title [ TEXT ] salary [ INTEGER ] supervisor [ INTEGER ] employee.supervisor = employee.employee_id establishment : license...
SELECT DISTINCT T3.dba_name FROM employee AS T1 INNER JOIN inspection AS T2 ON T1.employee_id = T2.employee_id INNER JOIN establishment AS T3 ON T2.license_no = T3.license_no WHERE T1.first_name = 'Joshua' AND T1.last_name = 'Rosa';
[INST] Here is a database schema: establishment : license_no [ INTEGER ] primary_key dba_name [ TEXT ] aka_name [ TEXT ] facility_type [ TEXT ] risk_level [ INTEGER ] address [ TEXT ] city [ TEXT ] state [ TEXT ] zip [ INTEGER ] latitude [ REAL ] longitude [ REAL ] ward [ INTEGER ] inspection : inspection_id [ INTEGER ...
SELECT COUNT(DISTINCT T1.license_no) FROM establishment AS T1 INNER JOIN inspection AS T2 ON T1.license_no = T2.license_no WHERE strftime('%Y-%m', T2.inspection_date) = '2010-07' AND T2.results = 'Fail' AND T1.facility_type = 'Restaurant';
[INST] Here is a database schema: employee : employee_id [ INTEGER ] primary_key first_name [ TEXT ] last_name [ TEXT ] address [ TEXT ] city [ TEXT ] state [ TEXT ] zip [ INTEGER ] phone [ TEXT ] title [ TEXT ] salary [ INTEGER ] supervisor [ INTEGER ] employee.supervisor = employee.employee_id establishment : license...
SELECT DISTINCT T3.risk_level FROM employee AS T1 INNER JOIN inspection AS T2 ON T1.employee_id = T2.employee_id INNER JOIN establishment AS T3 ON T2.license_no = T3.license_no WHERE T1.first_name = 'Bob' AND T1.last_name = 'Benson';
[INST] Here is a database schema: employee : employee_id [ INTEGER ] primary_key first_name [ TEXT ] last_name [ TEXT ] address [ TEXT ] city [ TEXT ] state [ TEXT ] zip [ INTEGER ] phone [ TEXT ] title [ TEXT ] salary [ INTEGER ] supervisor [ INTEGER ] employee.supervisor = employee.employee_id establishment : license...
SELECT DISTINCT T3.dba_name, T2.results FROM employee AS T1 INNER JOIN inspection AS T2 ON T1.employee_id = T2.employee_id INNER JOIN establishment AS T3 ON T2.license_no = T3.license_no WHERE T1.first_name = 'Bob' AND T1.last_name = 'Benson' AND strftime('%Y', T2.inspection_date) = '2010';
[INST] Here is a database schema: employee : employee_id [ INTEGER ] primary_key first_name [ TEXT ] last_name [ TEXT ] address [ TEXT ] city [ TEXT ] state [ TEXT ] zip [ INTEGER ] phone [ TEXT ] title [ TEXT ] salary [ INTEGER ] supervisor [ INTEGER ] employee.supervisor = employee.employee_id inspection : inspection...
SELECT DISTINCT T1.title FROM employee AS T1 INNER JOIN inspection AS T2 ON T1.employee_id = T2.employee_id WHERE T2.license_no = 1576687;
[INST] Here is a database schema: inspection_point : point_id [ INTEGER ] primary_key Description [ TEXT ] category [ TEXT ] code [ TEXT ] fine [ INTEGER ] point_level [ TEXT ] violation : inspection_id [ INTEGER ] violation.inspection_id = inspection.inspection_id point_id [ INTEGER ] violation.point_id = inspection_p...
SELECT COUNT(DISTINCT T2.point_id) FROM inspection_point AS T1 INNER JOIN violation AS T2 ON T1.point_id = T2.point_id WHERE T1.point_level = 'Serious ' AND T2.fine = 0;
[INST] Here is a database schema: establishment : license_no [ INTEGER ] primary_key dba_name [ TEXT ] aka_name [ TEXT ] facility_type [ TEXT ] risk_level [ INTEGER ] address [ TEXT ] city [ TEXT ] state [ TEXT ] zip [ INTEGER ] latitude [ REAL ] longitude [ REAL ] ward [ INTEGER ] inspection : inspection_id [ INTEGER ...
SELECT CAST(COUNT(CASE WHEN T3.fine = 250 THEN T1.license_no END) AS REAL) * 100 / COUNT(T1.license_no) FROM establishment AS T1 INNER JOIN inspection AS T2 ON T1.license_no = T2.license_no INNER JOIN violation AS T3 ON T2.inspection_id = T3.inspection_id WHERE T1.facility_type = 'Restaurant';
[INST] Here is a database schema: establishment : license_no [ INTEGER ] primary_key dba_name [ TEXT ] aka_name [ TEXT ] facility_type [ TEXT ] risk_level [ INTEGER ] address [ TEXT ] city [ TEXT ] state [ TEXT ] zip [ INTEGER ] latitude [ REAL ] longitude [ REAL ] ward [ INTEGER ] inspection : inspection_id [ INTEGER ...
SELECT CAST(COUNT(CASE WHEN T1.risk_level = 1 THEN T1.license_no END) AS REAL) * 100 / COUNT(T1.license_no) FROM establishment AS T1 INNER JOIN inspection AS T2 ON T1.license_no = T2.license_no WHERE T2.results = 'Pass';
[INST] Here is a database schema: employee : employee_id [ INTEGER ] primary_key first_name [ TEXT ] last_name [ TEXT ] address [ TEXT ] city [ TEXT ] state [ TEXT ] zip [ INTEGER ] phone [ TEXT ] title [ TEXT ] salary [ INTEGER ] supervisor [ INTEGER ] employee.supervisor = employee.employee_id Please write me a SQL ...
SELECT address, city, state FROM employee WHERE first_name = 'Standard' AND last_name = 'Murray';
[INST] Here is a database schema: establishment : license_no [ INTEGER ] primary_key dba_name [ TEXT ] aka_name [ TEXT ] facility_type [ TEXT ] risk_level [ INTEGER ] address [ TEXT ] city [ TEXT ] state [ TEXT ] zip [ INTEGER ] latitude [ REAL ] longitude [ REAL ] ward [ INTEGER ] Please write me a SQL statement that...
SELECT facility_type FROM establishment WHERE dba_name = 'Kinetic Playground';
[INST] Here is a database schema: employee : employee_id [ INTEGER ] primary_key first_name [ TEXT ] last_name [ TEXT ] address [ TEXT ] city [ TEXT ] state [ TEXT ] zip [ INTEGER ] phone [ TEXT ] title [ TEXT ] salary [ INTEGER ] supervisor [ INTEGER ] employee.supervisor = employee.employee_id Please write me a SQL ...
SELECT salary FROM employee WHERE first_name = 'Jessica' AND last_name = 'Anthony';
[INST] Here is a database schema: establishment : license_no [ INTEGER ] primary_key dba_name [ TEXT ] aka_name [ TEXT ] facility_type [ TEXT ] risk_level [ INTEGER ] address [ TEXT ] city [ TEXT ] state [ TEXT ] zip [ INTEGER ] latitude [ REAL ] longitude [ REAL ] ward [ INTEGER ] Please write me a SQL statement that...
SELECT dba_name FROM establishment WHERE latitude = 41.9532864854 AND longitude = -87.7673790701422 AND facility_type = 'Restaurant';
[INST] Here is a database schema: employee : employee_id [ INTEGER ] primary_key first_name [ TEXT ] last_name [ TEXT ] address [ TEXT ] city [ TEXT ] state [ TEXT ] zip [ INTEGER ] phone [ TEXT ] title [ TEXT ] salary [ INTEGER ] supervisor [ INTEGER ] employee.supervisor = employee.employee_id Please write me a SQL ...
SELECT COUNT(employee_id) FROM employee WHERE title = 'Supervisor';
[INST] Here is a database schema: establishment : license_no [ INTEGER ] primary_key dba_name [ TEXT ] aka_name [ TEXT ] facility_type [ TEXT ] risk_level [ INTEGER ] address [ TEXT ] city [ TEXT ] state [ TEXT ] zip [ INTEGER ] latitude [ REAL ] longitude [ REAL ] ward [ INTEGER ] Please write me a SQL statement that...
SELECT address FROM establishment WHERE city = 'CHICAGO' AND dba_name = 'OLD TIMERS REST & LOUNGE' AND facility_type = 'Restaurant';
[INST] Here is a database schema: employee : employee_id [ INTEGER ] primary_key first_name [ TEXT ] last_name [ TEXT ] address [ TEXT ] city [ TEXT ] state [ TEXT ] zip [ INTEGER ] phone [ TEXT ] title [ TEXT ] salary [ INTEGER ] supervisor [ INTEGER ] employee.supervisor = employee.employee_id Please write me a SQL ...
SELECT COUNT(employee_id) FROM employee WHERE state = 'IL' AND city = 'Hoffman Estates';
[INST] Here is a database schema: establishment : license_no [ INTEGER ] primary_key dba_name [ TEXT ] aka_name [ TEXT ] facility_type [ TEXT ] risk_level [ INTEGER ] address [ TEXT ] city [ TEXT ] state [ TEXT ] zip [ INTEGER ] latitude [ REAL ] longitude [ REAL ] ward [ INTEGER ] Please write me a SQL statement that...
SELECT COUNT(license_no) FROM establishment WHERE risk_level = 3;
[INST] Here is a database schema: employee : employee_id [ INTEGER ] primary_key first_name [ TEXT ] last_name [ TEXT ] address [ TEXT ] city [ TEXT ] state [ TEXT ] zip [ INTEGER ] phone [ TEXT ] title [ TEXT ] salary [ INTEGER ] supervisor [ INTEGER ] employee.supervisor = employee.employee_id Please write me a SQL ...
SELECT first_name, last_name FROM employee WHERE salary = 82700;
[INST] Here is a database schema: employee : employee_id [ INTEGER ] primary_key first_name [ TEXT ] last_name [ TEXT ] address [ TEXT ] city [ TEXT ] state [ TEXT ] zip [ INTEGER ] phone [ TEXT ] title [ TEXT ] salary [ INTEGER ] supervisor [ INTEGER ] employee.supervisor = employee.employee_id inspection : inspection...
SELECT DISTINCT T1.last_name FROM employee AS T1 INNER JOIN inspection AS T2 ON T1.employee_id = T2.employee_id WHERE T2.inspection_id = 52256;
[INST] Here is a database schema: establishment : license_no [ INTEGER ] primary_key dba_name [ TEXT ] aka_name [ TEXT ] facility_type [ TEXT ] risk_level [ INTEGER ] address [ TEXT ] city [ TEXT ] state [ TEXT ] zip [ INTEGER ] latitude [ REAL ] longitude [ REAL ] ward [ INTEGER ] inspection : inspection_id [ INTEGER ...
SELECT DISTINCT T1.dba_name FROM establishment AS T1 INNER JOIN inspection AS T2 ON T1.license_no = T2.license_no INNER JOIN violation AS T3 ON T2.inspection_id = T3.inspection_id WHERE T1.facility_type = 'Tavern' AND T3.fine = 100;
[INST] Here is a database schema: inspection_point : point_id [ INTEGER ] primary_key Description [ TEXT ] category [ TEXT ] code [ TEXT ] fine [ INTEGER ] point_level [ TEXT ] violation : inspection_id [ INTEGER ] violation.inspection_id = inspection.inspection_id point_id [ INTEGER ] violation.point_id = inspection_p...
SELECT DISTINCT T1.point_level FROM inspection_point AS T1 INNER JOIN violation AS T2 ON T1.point_id = T2.point_id WHERE T2.fine = 0;
[INST] Here is a database schema: establishment : license_no [ INTEGER ] primary_key dba_name [ TEXT ] aka_name [ TEXT ] facility_type [ TEXT ] risk_level [ INTEGER ] address [ TEXT ] city [ TEXT ] state [ TEXT ] zip [ INTEGER ] latitude [ REAL ] longitude [ REAL ] ward [ INTEGER ] inspection : inspection_id [ INTEGER ...
SELECT DISTINCT T1.facility_type, T1.license_no FROM establishment AS T1 INNER JOIN inspection AS T2 ON T1.license_no = T2.license_no WHERE T1.risk_level = 1 AND T2.results = 'Fail';
[INST] Here is a database schema: employee : employee_id [ INTEGER ] primary_key first_name [ TEXT ] last_name [ TEXT ] address [ TEXT ] city [ TEXT ] state [ TEXT ] zip [ INTEGER ] phone [ TEXT ] title [ TEXT ] salary [ INTEGER ] supervisor [ INTEGER ] employee.supervisor = employee.employee_id inspection : inspection...
SELECT DISTINCT T2.results FROM employee AS T1 INNER JOIN inspection AS T2 ON T1.employee_id = T2.employee_id WHERE T2.inspection_date = '2010-02-24' AND T1.first_name = 'Arnold' AND T1.last_name = 'Holder';
[INST] Here is a database schema: establishment : license_no [ INTEGER ] primary_key dba_name [ TEXT ] aka_name [ TEXT ] facility_type [ TEXT ] risk_level [ INTEGER ] address [ TEXT ] city [ TEXT ] state [ TEXT ] zip [ INTEGER ] latitude [ REAL ] longitude [ REAL ] ward [ INTEGER ] inspection : inspection_id [ INTEGER ...
SELECT COUNT(DISTINCT T1.license_no) FROM establishment AS T1 INNER JOIN inspection AS T2 ON T1.license_no = T2.license_no WHERE strftime('%Y-%m', T2.inspection_date) = '2010-04' AND T1.facility_type = 'Restaurant' AND T2.results = 'Fail';
[INST] Here is a database schema: employee : employee_id [ INTEGER ] primary_key first_name [ TEXT ] last_name [ TEXT ] address [ TEXT ] city [ TEXT ] state [ TEXT ] zip [ INTEGER ] phone [ TEXT ] title [ TEXT ] salary [ INTEGER ] supervisor [ INTEGER ] employee.supervisor = employee.employee_id inspection : inspection...
SELECT DISTINCT T2.inspection_id FROM employee AS T1 INNER JOIN inspection AS T2 ON T1.employee_id = T2.employee_id WHERE T1.first_name = 'Rosemary' AND T1.last_name = 'Kennedy';
[INST] Here is a database schema: employee : employee_id [ INTEGER ] primary_key first_name [ TEXT ] last_name [ TEXT ] address [ TEXT ] city [ TEXT ] state [ TEXT ] zip [ INTEGER ] phone [ TEXT ] title [ TEXT ] salary [ INTEGER ] supervisor [ INTEGER ] employee.supervisor = employee.employee_id inspection : inspection...
SELECT DISTINCT T2.inspection_type FROM employee AS T1 INNER JOIN inspection AS T2 ON T1.employee_id = T2.employee_id WHERE T1.first_name = 'Lisa' AND T1.last_name = 'Tillman' AND T2.inspection_date = '2010-07-07';
[INST] Here is a database schema: inspection_point : point_id [ INTEGER ] primary_key Description [ TEXT ] category [ TEXT ] code [ TEXT ] fine [ INTEGER ] point_level [ TEXT ] violation : inspection_id [ INTEGER ] violation.inspection_id = inspection.inspection_id point_id [ INTEGER ] violation.point_id = inspection_p...
SELECT T2.inspection_id FROM inspection_point AS T1 INNER JOIN violation AS T2 ON T1.point_id = T2.point_id WHERE T2.inspector_comment = 'MUST CLEAN AND BETTER ORGANIZE HALLWAY AREA' AND T1.code = '7-38-030, 015, 010 (A), 005 (A)';
[INST] Here is a database schema: establishment : license_no [ INTEGER ] primary_key dba_name [ TEXT ] aka_name [ TEXT ] facility_type [ TEXT ] risk_level [ INTEGER ] address [ TEXT ] city [ TEXT ] state [ TEXT ] zip [ INTEGER ] latitude [ REAL ] longitude [ REAL ] ward [ INTEGER ] inspection : inspection_id [ INTEGER ...
SELECT DISTINCT T1.dba_name FROM establishment AS T1 INNER JOIN inspection AS T2 ON T1.license_no = T2.license_no WHERE T1.risk_level = 3 AND T2.results = 'Fail';
[INST] Here is a database schema: employee : employee_id [ INTEGER ] primary_key first_name [ TEXT ] last_name [ TEXT ] address [ TEXT ] city [ TEXT ] state [ TEXT ] zip [ INTEGER ] phone [ TEXT ] title [ TEXT ] salary [ INTEGER ] supervisor [ INTEGER ] employee.supervisor = employee.employee_id establishment : license...
SELECT T2.inspection_id FROM establishment AS T1 INNER JOIN inspection AS T2 ON T1.license_no = T2.license_no INNER JOIN employee AS T3 ON T2.employee_id = T3.employee_id WHERE T3.first_name = 'David' AND T3.last_name = 'Hodges' AND T1.dba_name = 'KAMAYAN EXPRESS';
[INST] Here is a database schema: employee : employee_id [ INTEGER ] primary_key first_name [ TEXT ] last_name [ TEXT ] address [ TEXT ] city [ TEXT ] state [ TEXT ] zip [ INTEGER ] phone [ TEXT ] title [ TEXT ] salary [ INTEGER ] supervisor [ INTEGER ] employee.supervisor = employee.employee_id inspection : inspection...
SELECT T1.salary, T3.salary FROM employee AS T1 INNER JOIN inspection AS T2 ON T1.employee_id = T2.employee_id INNER JOIN employee AS T3 WHERE T2.inspection_id = 58424 ORDER BY T1.salary, T3.salary DESC LIMIT 1;
[INST] Here is a database schema: inspection_point : point_id [ INTEGER ] primary_key Description [ TEXT ] category [ TEXT ] code [ TEXT ] fine [ INTEGER ] point_level [ TEXT ] violation : inspection_id [ INTEGER ] violation.inspection_id = inspection.inspection_id point_id [ INTEGER ] violation.point_id = inspection_p...
SELECT T2.inspection_id FROM inspection_point AS T1 INNER JOIN violation AS T2 ON T1.point_id = T2.point_id WHERE T1.category = 'Personnel' AND T2.inspector_comment = 'A certified food service manager must be present in all establishments at which potentially hazardous food is prepared or served.FOUND NO CITY OF CHICAG...
[INST] Here is a database schema: establishment : license_no [ INTEGER ] primary_key dba_name [ TEXT ] aka_name [ TEXT ] facility_type [ TEXT ] risk_level [ INTEGER ] address [ TEXT ] city [ TEXT ] state [ TEXT ] zip [ INTEGER ] latitude [ REAL ] longitude [ REAL ] ward [ INTEGER ] inspection : inspection_id [ INTEGER ...
SELECT COUNT(DISTINCT T1.license_no) FROM establishment AS T1 INNER JOIN inspection AS T2 ON T1.license_no = T2.license_no INNER JOIN violation AS T3 ON T2.inspection_id = T3.inspection_id WHERE T1.facility_type = 'Grocery Store' AND T3.fine = 250;
[INST] Here is a database schema: establishment : license_no [ INTEGER ] primary_key dba_name [ TEXT ] aka_name [ TEXT ] facility_type [ TEXT ] risk_level [ INTEGER ] address [ TEXT ] city [ TEXT ] state [ TEXT ] zip [ INTEGER ] latitude [ REAL ] longitude [ REAL ] ward [ INTEGER ] inspection : inspection_id [ INTEGER ...
SELECT DISTINCT T4.category FROM establishment AS T1 INNER JOIN inspection AS T2 ON T1.license_no = T2.license_no INNER JOIN violation AS T3 ON T2.inspection_id = T3.inspection_id INNER JOIN inspection_point AS T4 ON T3.point_id = T4.point_id WHERE T1.dba_name = 'J & J FOOD';
[INST] Here is a database schema: establishment : license_no [ INTEGER ] primary_key dba_name [ TEXT ] aka_name [ TEXT ] facility_type [ TEXT ] risk_level [ INTEGER ] address [ TEXT ] city [ TEXT ] state [ TEXT ] zip [ INTEGER ] latitude [ REAL ] longitude [ REAL ] ward [ INTEGER ] inspection : inspection_id [ INTEGER ...
SELECT DISTINCT T1.dba_name FROM establishment AS T1 INNER JOIN inspection AS T2 ON T1.license_no = T2.license_no INNER JOIN violation AS T3 ON T2.inspection_id = T3.inspection_id WHERE strftime('%Y-%m', T2.inspection_date) = '2010-01' AND T2.results = 'Fail' AND T1.facility_type = 'TAVERN';
[INST] Here is a database schema: inspection_point : point_id [ INTEGER ] primary_key Description [ TEXT ] category [ TEXT ] code [ TEXT ] fine [ INTEGER ] point_level [ TEXT ] violation : inspection_id [ INTEGER ] violation.inspection_id = inspection.inspection_id point_id [ INTEGER ] violation.point_id = inspection_p...
SELECT COUNT(DISTINCT T2.inspection_id) FROM inspection_point AS T1 INNER JOIN violation AS T2 ON T1.point_id = T2.point_id WHERE T1.point_level = 'Serious ' AND T2.fine = 0;
[INST] Here is a database schema: establishment : license_no [ INTEGER ] primary_key dba_name [ TEXT ] aka_name [ TEXT ] facility_type [ TEXT ] risk_level [ INTEGER ] address [ TEXT ] city [ TEXT ] state [ TEXT ] zip [ INTEGER ] latitude [ REAL ] longitude [ REAL ] ward [ INTEGER ] inspection : inspection_id [ INTEGER ...
SELECT DISTINCT T1.dba_name FROM establishment AS T1 INNER JOIN inspection AS T2 ON T1.license_no = T2.license_no INNER JOIN violation AS T3 ON T2.inspection_id = T3.inspection_id INNER JOIN inspection_point AS T4 ON T3.point_id = T4.point_id WHERE T4.category = 'No Smoking Regulations';
[INST] Here is a database schema: establishment : license_no [ INTEGER ] primary_key dba_name [ TEXT ] aka_name [ TEXT ] facility_type [ TEXT ] risk_level [ INTEGER ] address [ TEXT ] city [ TEXT ] state [ TEXT ] zip [ INTEGER ] latitude [ REAL ] longitude [ REAL ] ward [ INTEGER ] inspection : inspection_id [ INTEGER ...
SELECT COUNT(CASE WHEN T2.results = 'Pass' THEN T1.license_no END) - COUNT(CASE WHEN T2.results = 'Fail' THEN T1.license_no END) AS diff FROM establishment AS T1 INNER JOIN inspection AS T2 ON T1.license_no = T2.license_no WHERE T2.inspection_type = 'Canvass' AND T1.facility_type = 'Restaurant';
[INST] Here is a database schema: employee : employee_id [ INTEGER ] primary_key first_name [ TEXT ] last_name [ TEXT ] address [ TEXT ] city [ TEXT ] state [ TEXT ] zip [ INTEGER ] phone [ TEXT ] title [ TEXT ] salary [ INTEGER ] supervisor [ INTEGER ] employee.supervisor = employee.employee_id inspection : inspection...
SELECT DISTINCT T1.employee_id FROM employee AS T1 INNER JOIN inspection AS T2 ON T1.employee_id = T2.employee_id WHERE T2.results = 'Fail' AND strftime('%Y-%m', T2.inspection_date) = '2010-02' AND T1.salary > 0.7 * ( SELECT AVG(salary) FROM employee );
[INST] Here is a database schema: establishment : license_no [ INTEGER ] primary_key dba_name [ TEXT ] aka_name [ TEXT ] facility_type [ TEXT ] risk_level [ INTEGER ] address [ TEXT ] city [ TEXT ] state [ TEXT ] zip [ INTEGER ] latitude [ REAL ] longitude [ REAL ] ward [ INTEGER ] inspection : inspection_id [ INTEGER ...
SELECT CAST(COUNT(CASE WHEN T1.facility_type = 'Restaurant' THEN T1.license_no END) AS REAL) * 100 / COUNT(T1.facility_type) FROM establishment AS T1 INNER JOIN inspection AS T2 ON T1.license_no = T2.license_no INNER JOIN violation AS T3 ON T2.inspection_id = T3.inspection_id WHERE T3.fine = 500;
[INST] Here is a database schema: coins : id [ INTEGER ] primary_key name [ TEXT ] slug [ TEXT ] symbol [ TEXT ] status [ TEXT ] category [ TEXT ] description [ TEXT ] subreddit [ TEXT ] notice [ TEXT ] tags [ TEXT ] tag_names [ TEXT ] website [ TEXT ] platform_id [ INTEGER ] date_added [ TEXT ] date_launched [ TEXT ] ...
SELECT T1.name FROM coins AS T1 INNER JOIN historical AS T2 ON T1.id = T2.coin_id WHERE T2.date LIKE '2018%' AND T2.market_cap = ( SELECT MAX(market_cap) FROM historical WHERE STRFTIME('%Y', date) = '2018' );
[INST] Here is a database schema: coins : id [ INTEGER ] primary_key name [ TEXT ] slug [ TEXT ] symbol [ TEXT ] status [ TEXT ] category [ TEXT ] description [ TEXT ] subreddit [ TEXT ] notice [ TEXT ] tags [ TEXT ] tag_names [ TEXT ] website [ TEXT ] platform_id [ INTEGER ] date_added [ TEXT ] date_launched [ TEXT ] ...
SELECT T2.volume_24h FROM coins AS T1 INNER JOIN historical AS T2 ON T1.id = T2.coin_id WHERE T1.name = 'Argentum' AND T2.date = '2016-10-11';
[INST] Here is a database schema: coins : id [ INTEGER ] primary_key name [ TEXT ] slug [ TEXT ] symbol [ TEXT ] status [ TEXT ] category [ TEXT ] description [ TEXT ] subreddit [ TEXT ] notice [ TEXT ] tags [ TEXT ] tag_names [ TEXT ] website [ TEXT ] platform_id [ INTEGER ] date_added [ TEXT ] date_launched [ TEXT ] ...
SELECT T2.price FROM coins AS T1 INNER JOIN historical AS T2 ON T1.id = T2.coin_id WHERE T1.name = 'Zetacoin' AND T2.date BETWEEN '2013-11-01' AND '2013-11-07' UNION ALL SELECT AVG(T2.PRICE) FROM coins AS T1 INNER JOIN historical AS T2 ON T1.id = T2.coin_id WHERE T1.name = 'Zetacoin' AND T2.date BETWEEN '2013-11-01' AN...
[INST] Here is a database schema: coins : id [ INTEGER ] primary_key name [ TEXT ] slug [ TEXT ] symbol [ TEXT ] status [ TEXT ] category [ TEXT ] description [ TEXT ] subreddit [ TEXT ] notice [ TEXT ] tags [ TEXT ] tag_names [ TEXT ] website [ TEXT ] platform_id [ INTEGER ] date_added [ TEXT ] date_launched [ TEXT ] ...
SELECT T2.time_high, T2.time_low, T2.date FROM coins AS T1 INNER JOIN historical AS T2 ON T1.id = T2.coin_id WHERE T1.name = 'WARP' AND STRFTIME('%Y-%m', T2.date) = '2016-08';
[INST] Here is a database schema: coins : id [ INTEGER ] primary_key name [ TEXT ] slug [ TEXT ] symbol [ TEXT ] status [ TEXT ] category [ TEXT ] description [ TEXT ] subreddit [ TEXT ] notice [ TEXT ] tags [ TEXT ] tag_names [ TEXT ] website [ TEXT ] platform_id [ INTEGER ] date_added [ TEXT ] date_launched [ TEXT ] ...
SELECT T2.date FROM coins AS T1 INNER JOIN historical AS T2 ON T1.id = T2.coin_id WHERE T1.name = 'DigixDAO' ORDER BY T2.price DESC LIMIT 1;
[INST] Here is a database schema: coins : id [ INTEGER ] primary_key name [ TEXT ] slug [ TEXT ] symbol [ TEXT ] status [ TEXT ] category [ TEXT ] description [ TEXT ] subreddit [ TEXT ] notice [ TEXT ] tags [ TEXT ] tag_names [ TEXT ] website [ TEXT ] platform_id [ INTEGER ] date_added [ TEXT ] date_launched [ TEXT ] ...
SELECT T1.name, T2.DATE, T2.price FROM coins AS T1 INNER JOIN historical AS T2 ON T1.id = T2.coin_id WHERE T2.percent_change_24h = ( SELECT MAX(percent_change_24h) FROM historical );
[INST] Here is a database schema: coins : id [ INTEGER ] primary_key name [ TEXT ] slug [ TEXT ] symbol [ TEXT ] status [ TEXT ] category [ TEXT ] description [ TEXT ] subreddit [ TEXT ] notice [ TEXT ] tags [ TEXT ] tag_names [ TEXT ] website [ TEXT ] platform_id [ INTEGER ] date_added [ TEXT ] date_launched [ TEXT ] ...
SELECT CAST(SUM(T2.circulating_supply) AS REAL) / 12 FROM coins AS T1 INNER JOIN historical AS T2 ON T1.id = T2.coin_id WHERE T1.name = 'Frozen' AND STRFTIME('%Y', T2.date) = '2014';
[INST] Here is a database schema: coins : id [ INTEGER ] primary_key name [ TEXT ] slug [ TEXT ] symbol [ TEXT ] status [ TEXT ] category [ TEXT ] description [ TEXT ] subreddit [ TEXT ] notice [ TEXT ] tags [ TEXT ] tag_names [ TEXT ] website [ TEXT ] platform_id [ INTEGER ] date_added [ TEXT ] date_launched [ TEXT ] ...
SELECT T1.NAME, MAX(T2.DATE) FROM coins AS T1 INNER JOIN historical AS T2 ON T1.ID = T2.coin_id WHERE T1.status = 'inactive' ORDER BY T2.DATE DESC LIMIT 1;
[INST] Here is a database schema: coins : id [ INTEGER ] primary_key name [ TEXT ] slug [ TEXT ] symbol [ TEXT ] status [ TEXT ] category [ TEXT ] description [ TEXT ] subreddit [ TEXT ] notice [ TEXT ] tags [ TEXT ] tag_names [ TEXT ] website [ TEXT ] platform_id [ INTEGER ] date_added [ TEXT ] date_launched [ TEXT ] ...
SELECT AVG(T2.price) FROM coins AS T1 INNER JOIN historical AS T2 ON T1.id = T2.coin_id WHERE T1.name = 'Bitcoin' AND STRFTIME('%Y', T2.date) = '2016';
[INST] Here is a database schema: coins : id [ INTEGER ] primary_key name [ TEXT ] slug [ TEXT ] symbol [ TEXT ] status [ TEXT ] category [ TEXT ] description [ TEXT ] subreddit [ TEXT ] notice [ TEXT ] tags [ TEXT ] tag_names [ TEXT ] website [ TEXT ] platform_id [ INTEGER ] date_added [ TEXT ] date_launched [ TEXT ] ...
SELECT T2.date, T2.price FROM coins AS T1 INNER JOIN historical AS T2 ON T1.id = T2.coin_id WHERE T1.name = 'Bitcoin' ORDER BY T2.price LIMIT 1;
[INST] Here is a database schema: coins : id [ INTEGER ] primary_key name [ TEXT ] slug [ TEXT ] symbol [ TEXT ] status [ TEXT ] category [ TEXT ] description [ TEXT ] subreddit [ TEXT ] notice [ TEXT ] tags [ TEXT ] tag_names [ TEXT ] website [ TEXT ] platform_id [ INTEGER ] date_added [ TEXT ] date_launched [ TEXT ] ...
SELECT T1.status FROM coins AS T1 INNER JOIN historical AS T2 ON T1.id = T2.coin_id GROUP BY T1.name HAVING AVG(T2.price) > 1000;
[INST] Here is a database schema: coins : id [ INTEGER ] primary_key name [ TEXT ] slug [ TEXT ] symbol [ TEXT ] status [ TEXT ] category [ TEXT ] description [ TEXT ] subreddit [ TEXT ] notice [ TEXT ] tags [ TEXT ] tag_names [ TEXT ] website [ TEXT ] platform_id [ INTEGER ] date_added [ TEXT ] date_launched [ TEXT ] ...
SELECT T1.name, T2.date FROM coins AS T1 INNER JOIN historical AS T2 ON T1.id = T2.coin_id WHERE T2.percent_change_1h = ( SELECT MIN(percent_change_1h) FROM historical );
[INST] Here is a database schema: coins : id [ INTEGER ] primary_key name [ TEXT ] slug [ TEXT ] symbol [ TEXT ] status [ TEXT ] category [ TEXT ] description [ TEXT ] subreddit [ TEXT ] notice [ TEXT ] tags [ TEXT ] tag_names [ TEXT ] website [ TEXT ] platform_id [ INTEGER ] date_added [ TEXT ] date_launched [ TEXT ] ...
SELECT T1.name FROM coins AS T1 INNER JOIN historical AS T2 ON T1.id = T2.coin_id WHERE T1.category = 'token' ORDER BY T2.high - T2.low DESC LIMIT 1;
[INST] Here is a database schema: coins : id [ INTEGER ] primary_key name [ TEXT ] slug [ TEXT ] symbol [ TEXT ] status [ TEXT ] category [ TEXT ] description [ TEXT ] subreddit [ TEXT ] notice [ TEXT ] tags [ TEXT ] tag_names [ TEXT ] website [ TEXT ] platform_id [ INTEGER ] date_added [ TEXT ] date_launched [ TEXT ] ...
SELECT T1.name FROM coins AS T1 INNER JOIN historical AS T2 ON T1.id = T2.coin_id WHERE T2.date = '2020-06-22' GROUP BY T1.name HAVING AVG(T2.percent_change_24h) > T2.PRICE;
[INST] Here is a database schema: coins : id [ INTEGER ] primary_key name [ TEXT ] slug [ TEXT ] symbol [ TEXT ] status [ TEXT ] category [ TEXT ] description [ TEXT ] subreddit [ TEXT ] notice [ TEXT ] tags [ TEXT ] tag_names [ TEXT ] website [ TEXT ] platform_id [ INTEGER ] date_added [ TEXT ] date_launched [ TEXT ] ...
SELECT T1.name FROM coins AS T1 INNER JOIN historical AS T2 ON T1.id = T2.coin_id WHERE T2.date = '2013-04-28' AND T2.cmc_rank = 1;
[INST] Here is a database schema: coins : id [ INTEGER ] primary_key name [ TEXT ] slug [ TEXT ] symbol [ TEXT ] status [ TEXT ] category [ TEXT ] description [ TEXT ] subreddit [ TEXT ] notice [ TEXT ] tags [ TEXT ] tag_names [ TEXT ] website [ TEXT ] platform_id [ INTEGER ] date_added [ TEXT ] date_launched [ TEXT ] ...
SELECT T2.market_cap FROM coins AS T1 INNER JOIN historical AS T2 ON T1.id = T2.coin_id WHERE T2.date = '2013-04-28' AND T1.name = 'Bitcoin';
[INST] Here is a database schema: coins : id [ INTEGER ] primary_key name [ TEXT ] slug [ TEXT ] symbol [ TEXT ] status [ TEXT ] category [ TEXT ] description [ TEXT ] subreddit [ TEXT ] notice [ TEXT ] tags [ TEXT ] tag_names [ TEXT ] website [ TEXT ] platform_id [ INTEGER ] date_added [ TEXT ] date_launched [ TEXT ] ...
SELECT T1.name FROM coins AS T1 INNER JOIN historical AS T2 ON T1.id = T2.coin_id WHERE T2.date = '2013-05-03' AND T2.open IS NULL;
[INST] Here is a database schema: coins : id [ INTEGER ] primary_key name [ TEXT ] slug [ TEXT ] symbol [ TEXT ] status [ TEXT ] category [ TEXT ] description [ TEXT ] subreddit [ TEXT ] notice [ TEXT ] tags [ TEXT ] tag_names [ TEXT ] website [ TEXT ] platform_id [ INTEGER ] date_added [ TEXT ] date_launched [ TEXT ] ...
SELECT T2.close FROM coins AS T1 INNER JOIN historical AS T2 ON T1.id = T2.coin_id WHERE T2.date = '2013-04-29' AND T1.name = 'Bitcoin';
[INST] Here is a database schema: coins : id [ INTEGER ] primary_key name [ TEXT ] slug [ TEXT ] symbol [ TEXT ] status [ TEXT ] category [ TEXT ] description [ TEXT ] subreddit [ TEXT ] notice [ TEXT ] tags [ TEXT ] tag_names [ TEXT ] website [ TEXT ] platform_id [ INTEGER ] date_added [ TEXT ] date_launched [ TEXT ] ...
SELECT T2.time_high FROM coins AS T1 INNER JOIN historical AS T2 ON T1.id = T2.coin_id WHERE T2.date = '2013-04-29' AND T1.name = 'Bitcoin';
[INST] Here is a database schema: coins : id [ INTEGER ] primary_key name [ TEXT ] slug [ TEXT ] symbol [ TEXT ] status [ TEXT ] category [ TEXT ] description [ TEXT ] subreddit [ TEXT ] notice [ TEXT ] tags [ TEXT ] tag_names [ TEXT ] website [ TEXT ] platform_id [ INTEGER ] date_added [ TEXT ] date_launched [ TEXT ] ...
SELECT T2.high - T2.low FROM coins AS T1 INNER JOIN historical AS T2 ON T1.id = T2.coin_id WHERE T2.date = '2013-04-28' AND T1.name = 'Bitcoin';
[INST] Here is a database schema: coins : id [ INTEGER ] primary_key name [ TEXT ] slug [ TEXT ] symbol [ TEXT ] status [ TEXT ] category [ TEXT ] description [ TEXT ] subreddit [ TEXT ] notice [ TEXT ] tags [ TEXT ] tag_names [ TEXT ] website [ TEXT ] platform_id [ INTEGER ] date_added [ TEXT ] date_launched [ TEXT ] ...
SELECT T2.max_supply - T2.total_supply FROM coins AS T1 INNER JOIN historical AS T2 ON T1.id = T2.coin_id WHERE T2.date = '2013-04-28' AND T1.name = 'Bitcoin';
[INST] Here is a database schema: coins : id [ INTEGER ] primary_key name [ TEXT ] slug [ TEXT ] symbol [ TEXT ] status [ TEXT ] category [ TEXT ] description [ TEXT ] subreddit [ TEXT ] notice [ TEXT ] tags [ TEXT ] tag_names [ TEXT ] website [ TEXT ] platform_id [ INTEGER ] date_added [ TEXT ] date_launched [ TEXT ] ...
SELECT T1.name FROM coins AS T1 INNER JOIN historical AS T2 ON T1.id = T2.coin_id WHERE T2.date = '2016-01-08' AND T2.volume_24h = ( SELECT MAX(volume_24h) FROM historical WHERE date = '2016-01-08' );
[INST] Here is a database schema: coins : id [ INTEGER ] primary_key name [ TEXT ] slug [ TEXT ] symbol [ TEXT ] status [ TEXT ] category [ TEXT ] description [ TEXT ] subreddit [ TEXT ] notice [ TEXT ] tags [ TEXT ] tag_names [ TEXT ] website [ TEXT ] platform_id [ INTEGER ] date_added [ TEXT ] date_launched [ TEXT ] ...
SELECT T1.name FROM coins AS T1 INNER JOIN historical AS T2 ON T1.id = T2.coin_id WHERE T2.date = '2013-04-28' AND T2.total_supply > 10000000;
[INST] Here is a database schema: coins : id [ INTEGER ] primary_key name [ TEXT ] slug [ TEXT ] symbol [ TEXT ] status [ TEXT ] category [ TEXT ] description [ TEXT ] subreddit [ TEXT ] notice [ TEXT ] tags [ TEXT ] tag_names [ TEXT ] website [ TEXT ] platform_id [ INTEGER ] date_added [ TEXT ] date_launched [ TEXT ] ...
SELECT (CASE WHEN T2.percent_change_7d > 0 THEN 'INCREASED' ELSE 'DECREASED' END) FROM coins AS T1 INNER JOIN historical AS T2 ON T1.id = T2.coin_id WHERE T2.date = '2013-05-05' AND T1.name = 'Bitcoin';
[INST] Here is a database schema: coins : id [ INTEGER ] primary_key name [ TEXT ] slug [ TEXT ] symbol [ TEXT ] status [ TEXT ] category [ TEXT ] description [ TEXT ] subreddit [ TEXT ] notice [ TEXT ] tags [ TEXT ] tag_names [ TEXT ] website [ TEXT ] platform_id [ INTEGER ] date_added [ TEXT ] date_launched [ TEXT ] ...
SELECT T1.name FROM coins AS T1 INNER JOIN historical AS T2 ON T1.id = T2.coin_id WHERE T2.date = '2013-04-28' AND T1.name IN ('Bitcoin', 'Litecoin') ORDER BY T2.circulating_supply DESC LIMIT 1;
[INST] Here is a database schema: coins : id [ INTEGER ] primary_key name [ TEXT ] slug [ TEXT ] symbol [ TEXT ] status [ TEXT ] category [ TEXT ] description [ TEXT ] subreddit [ TEXT ] notice [ TEXT ] tags [ TEXT ] tag_names [ TEXT ] website [ TEXT ] platform_id [ INTEGER ] date_added [ TEXT ] date_launched [ TEXT ] ...
SELECT T2.price FROM coins AS T1 INNER JOIN historical AS T2 ON T1.id = T2.coin_id WHERE T2.date = '2013-04-28' AND T1.name = 'Bitcoin';
[INST] Here is a database schema: coins : id [ INTEGER ] primary_key name [ TEXT ] slug [ TEXT ] symbol [ TEXT ] status [ TEXT ] category [ TEXT ] description [ TEXT ] subreddit [ TEXT ] notice [ TEXT ] tags [ TEXT ] tag_names [ TEXT ] website [ TEXT ] platform_id [ INTEGER ] date_added [ TEXT ] date_launched [ TEXT ] ...
SELECT AVG(T2.price) FROM coins AS T1 INNER JOIN historical AS T2 ON T1.id = T2.coin_id WHERE STRFTIME('%Y', T2.date) = '2013' AND T1.name = 'Bitcoin';
[INST] Here is a database schema: coins : id [ INTEGER ] primary_key name [ TEXT ] slug [ TEXT ] symbol [ TEXT ] status [ TEXT ] category [ TEXT ] description [ TEXT ] subreddit [ TEXT ] notice [ TEXT ] tags [ TEXT ] tag_names [ TEXT ] website [ TEXT ] platform_id [ INTEGER ] date_added [ TEXT ] date_launched [ TEXT ] ...
SELECT CAST((SUM(T2.max_supply) - SUM(T2.total_supply)) AS REAL) / SUM(T2.total_supply) FROM coins AS T1 INNER JOIN historical AS T2 ON T1.id = T2.coin_id WHERE T2.date < '2018-04-28' AND T1.name = 'Bitcoin';
[INST] Here is a database schema: coins : id [ INTEGER ] primary_key name [ TEXT ] slug [ TEXT ] symbol [ TEXT ] status [ TEXT ] category [ TEXT ] description [ TEXT ] subreddit [ TEXT ] notice [ TEXT ] tags [ TEXT ] tag_names [ TEXT ] website [ TEXT ] platform_id [ INTEGER ] date_added [ TEXT ] date_launched [ TEXT ] ...
SELECT name FROM coins WHERE status = 'extinct';
[INST] Here is a database schema: coins : id [ INTEGER ] primary_key name [ TEXT ] slug [ TEXT ] symbol [ TEXT ] status [ TEXT ] category [ TEXT ] description [ TEXT ] subreddit [ TEXT ] notice [ TEXT ] tags [ TEXT ] tag_names [ TEXT ] website [ TEXT ] platform_id [ INTEGER ] date_added [ TEXT ] date_launched [ TEXT ] ...
SELECT description FROM coins WHERE name = 'BitBar';
[INST] Here is a database schema: coins : id [ INTEGER ] primary_key name [ TEXT ] slug [ TEXT ] symbol [ TEXT ] status [ TEXT ] category [ TEXT ] description [ TEXT ] subreddit [ TEXT ] notice [ TEXT ] tags [ TEXT ] tag_names [ TEXT ] website [ TEXT ] platform_id [ INTEGER ] date_added [ TEXT ] date_launched [ TEXT ] ...
SELECT COUNT(id) num FROM coins WHERE STRFTIME('%Y-%m', date_added) = '2013-05' UNION ALL SELECT name FROM coins WHERE STRFTIME('%Y-%m', date_added) = '2013-05';
[INST] Here is a database schema: coins : id [ INTEGER ] primary_key name [ TEXT ] slug [ TEXT ] symbol [ TEXT ] status [ TEXT ] category [ TEXT ] description [ TEXT ] subreddit [ TEXT ] notice [ TEXT ] tags [ TEXT ] tag_names [ TEXT ] website [ TEXT ] platform_id [ INTEGER ] date_added [ TEXT ] date_launched [ TEXT ] ...
SELECT name, symbol FROM coins WHERE date_added LIKE '2013-06-14%';
[INST] Here is a database schema: coins : id [ INTEGER ] primary_key name [ TEXT ] slug [ TEXT ] symbol [ TEXT ] status [ TEXT ] category [ TEXT ] description [ TEXT ] subreddit [ TEXT ] notice [ TEXT ] tags [ TEXT ] tag_names [ TEXT ] website [ TEXT ] platform_id [ INTEGER ] date_added [ TEXT ] date_launched [ TEXT ] ...
SELECT name FROM coins WHERE date_added LIKE '2014%' AND status = 'untracked';
[INST] Here is a database schema: coins : id [ INTEGER ] primary_key name [ TEXT ] slug [ TEXT ] symbol [ TEXT ] status [ TEXT ] category [ TEXT ] description [ TEXT ] subreddit [ TEXT ] notice [ TEXT ] tags [ TEXT ] tag_names [ TEXT ] website [ TEXT ] platform_id [ INTEGER ] date_added [ TEXT ] date_launched [ TEXT ] ...
SELECT name FROM coins WHERE LENGTH(tag_names) - LENGTH(replace(tag_names, ',', '')) = 2;
[INST] Here is a database schema: coins : id [ INTEGER ] primary_key name [ TEXT ] slug [ TEXT ] symbol [ TEXT ] status [ TEXT ] category [ TEXT ] description [ TEXT ] subreddit [ TEXT ] notice [ TEXT ] tags [ TEXT ] tag_names [ TEXT ] website [ TEXT ] platform_id [ INTEGER ] date_added [ TEXT ] date_launched [ TEXT ] ...
SELECT T1.name FROM coins AS T1 INNER JOIN historical AS T2 ON T1.id = T2.coin_id WHERE T2.price = ( SELECT MAX(price) FROM historical );
[INST] Here is a database schema: coins : id [ INTEGER ] primary_key name [ TEXT ] slug [ TEXT ] symbol [ TEXT ] status [ TEXT ] category [ TEXT ] description [ TEXT ] subreddit [ TEXT ] notice [ TEXT ] tags [ TEXT ] tag_names [ TEXT ] website [ TEXT ] platform_id [ INTEGER ] date_added [ TEXT ] date_launched [ TEXT ] ...
SELECT T1.name FROM coins AS T1 INNER JOIN historical AS T2 ON T1.id = T2.coin_id WHERE T2.date = '2013-04-29' AND T2.cmc_rank = 1;
[INST] Here is a database schema: coins : id [ INTEGER ] primary_key name [ TEXT ] slug [ TEXT ] symbol [ TEXT ] status [ TEXT ] category [ TEXT ] description [ TEXT ] subreddit [ TEXT ] notice [ TEXT ] tags [ TEXT ] tag_names [ TEXT ] website [ TEXT ] platform_id [ INTEGER ] date_added [ TEXT ] date_launched [ TEXT ] ...
SELECT T2.date FROM coins AS T1 INNER JOIN historical AS T2 ON T1.id = T2.coin_id WHERE T1.name = 'Bitcoin' ORDER BY T2.low LIMIT 1;
[INST] Here is a database schema: coins : id [ INTEGER ] primary_key name [ TEXT ] slug [ TEXT ] symbol [ TEXT ] status [ TEXT ] category [ TEXT ] description [ TEXT ] subreddit [ TEXT ] notice [ TEXT ] tags [ TEXT ] tag_names [ TEXT ] website [ TEXT ] platform_id [ INTEGER ] date_added [ TEXT ] date_launched [ TEXT ] ...
SELECT T1.name FROM coins AS T1 INNER JOIN historical AS T2 ON T1.id = T2.coin_id WHERE T2.volume_24h = ( SELECT MAX(volume_24h) FROM historical );
[INST] Here is a database schema: coins : id [ INTEGER ] primary_key name [ TEXT ] slug [ TEXT ] symbol [ TEXT ] status [ TEXT ] category [ TEXT ] description [ TEXT ] subreddit [ TEXT ] notice [ TEXT ] tags [ TEXT ] tag_names [ TEXT ] website [ TEXT ] platform_id [ INTEGER ] date_added [ TEXT ] date_launched [ TEXT ] ...
SELECT T1.name FROM coins AS T1 INNER JOIN historical AS T2 ON T1.id = T2.coin_id WHERE STRFTIME('%Y-%m', T2.date) = '2013-05' AND T2.open IS NULL;
[INST] Here is a database schema: coins : id [ INTEGER ] primary_key name [ TEXT ] slug [ TEXT ] symbol [ TEXT ] status [ TEXT ] category [ TEXT ] description [ TEXT ] subreddit [ TEXT ] notice [ TEXT ] tags [ TEXT ] tag_names [ TEXT ] website [ TEXT ] platform_id [ INTEGER ] date_added [ TEXT ] date_launched [ TEXT ] ...
SELECT T2.date FROM coins AS T1 INNER JOIN historical AS T2 ON T1.id = T2.coin_id WHERE T1.name = 'CHNCoin' ORDER BY T2.close DESC LIMIT 1;
[INST] Here is a database schema: coins : id [ INTEGER ] primary_key name [ TEXT ] slug [ TEXT ] symbol [ TEXT ] status [ TEXT ] category [ TEXT ] description [ TEXT ] subreddit [ TEXT ] notice [ TEXT ] tags [ TEXT ] tag_names [ TEXT ] website [ TEXT ] platform_id [ INTEGER ] date_added [ TEXT ] date_launched [ TEXT ] ...
SELECT T2.date FROM coins AS T1 INNER JOIN historical AS T2 ON T1.id = T2.coin_id WHERE T1.name = 'Peercoin' AND T2.cmc_rank = 5;
[INST] Here is a database schema: coins : id [ INTEGER ] primary_key name [ TEXT ] slug [ TEXT ] symbol [ TEXT ] status [ TEXT ] category [ TEXT ] description [ TEXT ] subreddit [ TEXT ] notice [ TEXT ] tags [ TEXT ] tag_names [ TEXT ] website [ TEXT ] platform_id [ INTEGER ] date_added [ TEXT ] date_launched [ TEXT ] ...
SELECT T2.date FROM coins AS T1 INNER JOIN historical AS T2 ON T1.id = T2.coin_id WHERE T1.name = 'Devcoin' ORDER BY T2.market_cap DESC LIMIT 1;
[INST] Here is a database schema: coins : id [ INTEGER ] primary_key name [ TEXT ] slug [ TEXT ] symbol [ TEXT ] status [ TEXT ] category [ TEXT ] description [ TEXT ] subreddit [ TEXT ] notice [ TEXT ] tags [ TEXT ] tag_names [ TEXT ] website [ TEXT ] platform_id [ INTEGER ] date_added [ TEXT ] date_launched [ TEXT ] ...
SELECT T1.name FROM coins AS T1 INNER JOIN historical AS T2 ON T1.id = T2.coin_id WHERE T2.date = '2014-01-01' AND T2.cmc_rank <= 5;
[INST] Here is a database schema: coins : id [ INTEGER ] primary_key name [ TEXT ] slug [ TEXT ] symbol [ TEXT ] status [ TEXT ] category [ TEXT ] description [ TEXT ] subreddit [ TEXT ] notice [ TEXT ] tags [ TEXT ] tag_names [ TEXT ] website [ TEXT ] platform_id [ INTEGER ] date_added [ TEXT ] date_launched [ TEXT ] ...
SELECT DISTINCT T2.date FROM coins AS T1 INNER JOIN historical AS T2 ON T1.id = T2.coin_id WHERE T1.name = 'Lebowskis' AND (T2.open IS NULL OR T2.open = 0);
[INST] Here is a database schema: coins : id [ INTEGER ] primary_key name [ TEXT ] slug [ TEXT ] symbol [ TEXT ] status [ TEXT ] category [ TEXT ] description [ TEXT ] subreddit [ TEXT ] notice [ TEXT ] tags [ TEXT ] tag_names [ TEXT ] website [ TEXT ] platform_id [ INTEGER ] date_added [ TEXT ] date_launched [ TEXT ] ...
SELECT T2.date FROM coins AS T1 INNER JOIN historical AS T2 ON T1.id = T2.coin_id WHERE T1.name = 'Terracoin' ORDER BY T2.price DESC LIMIT 1;
[INST] Here is a database schema: coins : id [ INTEGER ] primary_key name [ TEXT ] slug [ TEXT ] symbol [ TEXT ] status [ TEXT ] category [ TEXT ] description [ TEXT ] subreddit [ TEXT ] notice [ TEXT ] tags [ TEXT ] tag_names [ TEXT ] website [ TEXT ] platform_id [ INTEGER ] date_added [ TEXT ] date_launched [ TEXT ] ...
SELECT COUNT(T2.coin_id) FROM coins AS T1 INNER JOIN historical AS T2 ON T1.id = T2.coin_id WHERE T1.name = 'Bytecoin' AND STRFTIME('%Y-%m', T2.date) = '2013-06';
[INST] Here is a database schema: coins : id [ INTEGER ] primary_key name [ TEXT ] slug [ TEXT ] symbol [ TEXT ] status [ TEXT ] category [ TEXT ] description [ TEXT ] subreddit [ TEXT ] notice [ TEXT ] tags [ TEXT ] tag_names [ TEXT ] website [ TEXT ] platform_id [ INTEGER ] date_added [ TEXT ] date_launched [ TEXT ] ...
SELECT T1.name FROM coins AS T1 INNER JOIN historical AS T2 ON T1.id = T2.coin_id WHERE T2.date = '2018-04-28' AND T2.price > ( SELECT AVG(price) FROM historical WHERE date = '2018-04-28' );
[INST] Here is a database schema: coins : id [ INTEGER ] primary_key name [ TEXT ] slug [ TEXT ] symbol [ TEXT ] status [ TEXT ] category [ TEXT ] description [ TEXT ] subreddit [ TEXT ] notice [ TEXT ] tags [ TEXT ] tag_names [ TEXT ] website [ TEXT ] platform_id [ INTEGER ] date_added [ TEXT ] date_launched [ TEXT ] ...
SELECT T1.NAME FROM coins AS T1 INNER JOIN historical AS T2 ON T1.ID = T2.coin_id WHERE T2.DATE = '2013-05-29' AND T2.percent_change_1h > 0;
[INST] Here is a database schema: Employees : EmployeeID [ INTEGER ] primary_key LastName [ TEXT ] FirstName [ TEXT ] BirthDate [ DATE ] Photo [ TEXT ] Notes [ TEXT ] Please write me a SQL statement that answers the following question: How many employees have obtained a doctorate? [/INST] [/INST]
SELECT COUNT(EmployeeID) FROM Employees WHERE TitleOfCourtesy = 'Dr.';
[INST] Here is a database schema: Employees : EmployeeID [ INTEGER ] primary_key LastName [ TEXT ] FirstName [ TEXT ] BirthDate [ DATE ] Photo [ TEXT ] Notes [ TEXT ] Please write me a SQL statement that answers the following question: To whom does Nancy Davolio report? Please give that employee's full name. [/INST] [...
SELECT FirstName, LastName FROM Employees WHERE EmployeeID = ( SELECT ReportsTo FROM Employees WHERE LastName = 'Davolio' AND FirstName = 'Nancy' );
[INST] Here is a database schema: Employees : EmployeeID [ INTEGER ] primary_key LastName [ TEXT ] FirstName [ TEXT ] BirthDate [ DATE ] Photo [ TEXT ] Notes [ TEXT ] Please write me a SQL statement that answers the following question: Which phone number should I call if I want to reach Nancy Davolio's home? [/INST] [...
SELECT HomePhone FROM Employees WHERE LastName = 'Davolio' AND FirstName = 'Nancy';