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1374_E1. Reading Books (easy version)
Easy and hard versions are actually different problems, so read statements of both problems completely and carefully. Summer vacation has started so Alice and Bob want to play and joy, but... Their mom doesn't think so. She says that they have to read some amount of books before all entertainments. Alice and Bob will ...
{ "input": [ "8 4\n7 1 1\n2 1 1\n4 0 1\n8 1 1\n1 0 1\n1 1 1\n1 0 1\n3 0 0\n", "5 2\n6 0 0\n9 0 0\n1 0 1\n2 1 1\n5 1 0\n", "5 3\n3 0 0\n2 1 0\n3 1 0\n5 0 1\n3 0 1\n" ], "output": [ "18\n", "8\n", "-1\n" ] }
{ "input": [ "2 1\n7 1 1\n2 1 1\n", "5 1\n2 1 0\n2 0 1\n1 0 1\n1 1 0\n1 0 1\n", "6 2\n6 0 0\n11 1 0\n9 0 1\n21 1 1\n10 1 0\n8 0 1\n", "3 1\n3 0 1\n3 1 0\n3 0 0\n", "6 3\n7 1 1\n8 0 0\n9 1 1\n6 1 0\n10 1 1\n5 0 0\n", "8 4 3\n1 1 1\n3 1 1\n12 1 1\n12 1 1\n4 0 0\n4 0 0\n5 1 0\n5 0 1\n", "6 3 ...
IN-CORRECT
python3
n, k = map(int, input().split()) both = [] x = [] y = [] for i in range(n): t,a,b = map(int, input().split()) if(a == 1 and b == 1): both.append(t) elif(a == 1 and b == 0): x.append(t) elif(a == 0 and b == 1): y.append(t) if(min(len(x), len(y)) + len(both) != k): print(-1) el...
1374_E1. Reading Books (easy version)
Easy and hard versions are actually different problems, so read statements of both problems completely and carefully. Summer vacation has started so Alice and Bob want to play and joy, but... Their mom doesn't think so. She says that they have to read some amount of books before all entertainments. Alice and Bob will ...
{ "input": [ "8 4\n7 1 1\n2 1 1\n4 0 1\n8 1 1\n1 0 1\n1 1 1\n1 0 1\n3 0 0\n", "5 2\n6 0 0\n9 0 0\n1 0 1\n2 1 1\n5 1 0\n", "5 3\n3 0 0\n2 1 0\n3 1 0\n5 0 1\n3 0 1\n" ], "output": [ "18\n", "8\n", "-1\n" ] }
{ "input": [ "2 1\n7 1 1\n2 1 1\n", "5 1\n2 1 0\n2 0 1\n1 0 1\n1 1 0\n1 0 1\n", "6 2\n6 0 0\n11 1 0\n9 0 1\n21 1 1\n10 1 0\n8 0 1\n", "3 1\n3 0 1\n3 1 0\n3 0 0\n", "6 3\n7 1 1\n8 0 0\n9 1 1\n6 1 0\n10 1 1\n5 0 0\n", "8 4 3\n1 1 1\n3 1 1\n12 1 1\n12 1 1\n4 0 0\n4 0 0\n5 1 0\n5 0 1\n", "6 3 ...
IN-CORRECT
cpp
#include <bits/stdc++.h> using namespace std; long long n, k; long long a[200005]; long long b[200005]; long long t[200005]; bool used[200005]; long long min(long long a, long long b) { if (a < b) return a; return b; } int main() { ios_base::sync_with_stdio(0); cin.tie(0); cout.tie(0); cin >> n >> k; long...
1374_E1. Reading Books (easy version)
Easy and hard versions are actually different problems, so read statements of both problems completely and carefully. Summer vacation has started so Alice and Bob want to play and joy, but... Their mom doesn't think so. She says that they have to read some amount of books before all entertainments. Alice and Bob will ...
{ "input": [ "8 4\n7 1 1\n2 1 1\n4 0 1\n8 1 1\n1 0 1\n1 1 1\n1 0 1\n3 0 0\n", "5 2\n6 0 0\n9 0 0\n1 0 1\n2 1 1\n5 1 0\n", "5 3\n3 0 0\n2 1 0\n3 1 0\n5 0 1\n3 0 1\n" ], "output": [ "18\n", "8\n", "-1\n" ] }
{ "input": [ "2 1\n7 1 1\n2 1 1\n", "5 1\n2 1 0\n2 0 1\n1 0 1\n1 1 0\n1 0 1\n", "6 2\n6 0 0\n11 1 0\n9 0 1\n21 1 1\n10 1 0\n8 0 1\n", "3 1\n3 0 1\n3 1 0\n3 0 0\n", "6 3\n7 1 1\n8 0 0\n9 1 1\n6 1 0\n10 1 1\n5 0 0\n", "8 4 3\n1 1 1\n3 1 1\n12 1 1\n12 1 1\n4 0 0\n4 0 0\n5 1 0\n5 0 1\n", "6 3 ...
IN-CORRECT
java
import java.io.*; import java.util.*; import java.math.*; import java.lang.*; import static java.lang.Math.*; public class Solution implements Runnable { static class InputReader { private InputStream stream; private byte[] buf = new byte[1024]; private int curChar; private int numChars; private SpaceCharF...
1374_E1. Reading Books (easy version)
Easy and hard versions are actually different problems, so read statements of both problems completely and carefully. Summer vacation has started so Alice and Bob want to play and joy, but... Their mom doesn't think so. She says that they have to read some amount of books before all entertainments. Alice and Bob will ...
{ "input": [ "8 4\n7 1 1\n2 1 1\n4 0 1\n8 1 1\n1 0 1\n1 1 1\n1 0 1\n3 0 0\n", "5 2\n6 0 0\n9 0 0\n1 0 1\n2 1 1\n5 1 0\n", "5 3\n3 0 0\n2 1 0\n3 1 0\n5 0 1\n3 0 1\n" ], "output": [ "18\n", "8\n", "-1\n" ] }
{ "input": [ "2 1\n7 1 1\n2 1 1\n", "5 1\n2 1 0\n2 0 1\n1 0 1\n1 1 0\n1 0 1\n", "6 2\n6 0 0\n11 1 0\n9 0 1\n21 1 1\n10 1 0\n8 0 1\n", "3 1\n3 0 1\n3 1 0\n3 0 0\n", "6 3\n7 1 1\n8 0 0\n9 1 1\n6 1 0\n10 1 1\n5 0 0\n", "8 4 3\n1 1 1\n3 1 1\n12 1 1\n12 1 1\n4 0 0\n4 0 0\n5 1 0\n5 0 1\n", "6 3 ...
IN-CORRECT
cpp
#include <bits/stdc++.h> using namespace std; int main() { ios_base::sync_with_stdio(false); cin.tie(NULL); cout.tie(NULL); long long t = 1, i, j, k; for (long long ii = 1; ii <= t; ii++) { long long n, m; cin >> n >> m; vector<long long> a, b, c, ta(n), tb(n), tc(n); for (i = 0; i < n; i++) c...
1374_E1. Reading Books (easy version)
Easy and hard versions are actually different problems, so read statements of both problems completely and carefully. Summer vacation has started so Alice and Bob want to play and joy, but... Their mom doesn't think so. She says that they have to read some amount of books before all entertainments. Alice and Bob will ...
{ "input": [ "8 4\n7 1 1\n2 1 1\n4 0 1\n8 1 1\n1 0 1\n1 1 1\n1 0 1\n3 0 0\n", "5 2\n6 0 0\n9 0 0\n1 0 1\n2 1 1\n5 1 0\n", "5 3\n3 0 0\n2 1 0\n3 1 0\n5 0 1\n3 0 1\n" ], "output": [ "18\n", "8\n", "-1\n" ] }
{ "input": [ "2 1\n7 1 1\n2 1 1\n", "5 1\n2 1 0\n2 0 1\n1 0 1\n1 1 0\n1 0 1\n", "6 2\n6 0 0\n11 1 0\n9 0 1\n21 1 1\n10 1 0\n8 0 1\n", "3 1\n3 0 1\n3 1 0\n3 0 0\n", "6 3\n7 1 1\n8 0 0\n9 1 1\n6 1 0\n10 1 1\n5 0 0\n", "8 4 3\n1 1 1\n3 1 1\n12 1 1\n12 1 1\n4 0 0\n4 0 0\n5 1 0\n5 0 1\n", "6 3 ...
IN-CORRECT
java
import java.io.*; import java.util.*; public class Codeforces { public static void main(String args[])throws Exception { BufferedReader bu=new BufferedReader(new InputStreamReader(System.in)); StringBuilder sb=new StringBuilder(); String s[]=bu.readLine().split(" "); int n=Integ...
1374_E1. Reading Books (easy version)
Easy and hard versions are actually different problems, so read statements of both problems completely and carefully. Summer vacation has started so Alice and Bob want to play and joy, but... Their mom doesn't think so. She says that they have to read some amount of books before all entertainments. Alice and Bob will ...
{ "input": [ "8 4\n7 1 1\n2 1 1\n4 0 1\n8 1 1\n1 0 1\n1 1 1\n1 0 1\n3 0 0\n", "5 2\n6 0 0\n9 0 0\n1 0 1\n2 1 1\n5 1 0\n", "5 3\n3 0 0\n2 1 0\n3 1 0\n5 0 1\n3 0 1\n" ], "output": [ "18\n", "8\n", "-1\n" ] }
{ "input": [ "2 1\n7 1 1\n2 1 1\n", "5 1\n2 1 0\n2 0 1\n1 0 1\n1 1 0\n1 0 1\n", "6 2\n6 0 0\n11 1 0\n9 0 1\n21 1 1\n10 1 0\n8 0 1\n", "3 1\n3 0 1\n3 1 0\n3 0 0\n", "6 3\n7 1 1\n8 0 0\n9 1 1\n6 1 0\n10 1 1\n5 0 0\n", "8 4 3\n1 1 1\n3 1 1\n12 1 1\n12 1 1\n4 0 0\n4 0 0\n5 1 0\n5 0 1\n", "6 3 ...
IN-CORRECT
java
import java.io.*; import java.util.*; import java.math.*; import java.awt.Point; public class Main { //static final long MOD = 998244353L; //static final long INF = 1000000000000000007L; static String letters = "abcdefghijklmnopqrstuvwxyz"; //static final long MOD = 1000000007L; static final int INF = 1000000007...
1374_E1. Reading Books (easy version)
Easy and hard versions are actually different problems, so read statements of both problems completely and carefully. Summer vacation has started so Alice and Bob want to play and joy, but... Their mom doesn't think so. She says that they have to read some amount of books before all entertainments. Alice and Bob will ...
{ "input": [ "8 4\n7 1 1\n2 1 1\n4 0 1\n8 1 1\n1 0 1\n1 1 1\n1 0 1\n3 0 0\n", "5 2\n6 0 0\n9 0 0\n1 0 1\n2 1 1\n5 1 0\n", "5 3\n3 0 0\n2 1 0\n3 1 0\n5 0 1\n3 0 1\n" ], "output": [ "18\n", "8\n", "-1\n" ] }
{ "input": [ "2 1\n7 1 1\n2 1 1\n", "5 1\n2 1 0\n2 0 1\n1 0 1\n1 1 0\n1 0 1\n", "6 2\n6 0 0\n11 1 0\n9 0 1\n21 1 1\n10 1 0\n8 0 1\n", "3 1\n3 0 1\n3 1 0\n3 0 0\n", "6 3\n7 1 1\n8 0 0\n9 1 1\n6 1 0\n10 1 1\n5 0 0\n", "8 4 3\n1 1 1\n3 1 1\n12 1 1\n12 1 1\n4 0 0\n4 0 0\n5 1 0\n5 0 1\n", "6 3 ...
IN-CORRECT
java
import java.util.*; import java.io.*; public class Main { public static void main(String[] args) throws IOException { // TODO Auto-generated method stub BufferedReader br=new BufferedReader(new InputStreamReader(System.in)); String[] cmd=br.readLine().split(" "); int n=Integer.valueOf(cmd[0]); int k=Intege...
1374_E1. Reading Books (easy version)
Easy and hard versions are actually different problems, so read statements of both problems completely and carefully. Summer vacation has started so Alice and Bob want to play and joy, but... Their mom doesn't think so. She says that they have to read some amount of books before all entertainments. Alice and Bob will ...
{ "input": [ "8 4\n7 1 1\n2 1 1\n4 0 1\n8 1 1\n1 0 1\n1 1 1\n1 0 1\n3 0 0\n", "5 2\n6 0 0\n9 0 0\n1 0 1\n2 1 1\n5 1 0\n", "5 3\n3 0 0\n2 1 0\n3 1 0\n5 0 1\n3 0 1\n" ], "output": [ "18\n", "8\n", "-1\n" ] }
{ "input": [ "2 1\n7 1 1\n2 1 1\n", "5 1\n2 1 0\n2 0 1\n1 0 1\n1 1 0\n1 0 1\n", "6 2\n6 0 0\n11 1 0\n9 0 1\n21 1 1\n10 1 0\n8 0 1\n", "3 1\n3 0 1\n3 1 0\n3 0 0\n", "6 3\n7 1 1\n8 0 0\n9 1 1\n6 1 0\n10 1 1\n5 0 0\n", "8 4 3\n1 1 1\n3 1 1\n12 1 1\n12 1 1\n4 0 0\n4 0 0\n5 1 0\n5 0 1\n", "6 3 ...
IN-CORRECT
python3
import sys import math as mt input=sys.stdin.buffer.readline t=1 def Sort(sub_li): sub_li.sort(key = lambda x: x[0]) return sub_li #t=int(input()) for _ in range(t): #n=int(input()) n,k=map(int,input().split()) #l=list(map(int,input().split())) l2=[] for ___ in range(n): tim...
1374_E1. Reading Books (easy version)
Easy and hard versions are actually different problems, so read statements of both problems completely and carefully. Summer vacation has started so Alice and Bob want to play and joy, but... Their mom doesn't think so. She says that they have to read some amount of books before all entertainments. Alice and Bob will ...
{ "input": [ "8 4\n7 1 1\n2 1 1\n4 0 1\n8 1 1\n1 0 1\n1 1 1\n1 0 1\n3 0 0\n", "5 2\n6 0 0\n9 0 0\n1 0 1\n2 1 1\n5 1 0\n", "5 3\n3 0 0\n2 1 0\n3 1 0\n5 0 1\n3 0 1\n" ], "output": [ "18\n", "8\n", "-1\n" ] }
{ "input": [ "2 1\n7 1 1\n2 1 1\n", "5 1\n2 1 0\n2 0 1\n1 0 1\n1 1 0\n1 0 1\n", "6 2\n6 0 0\n11 1 0\n9 0 1\n21 1 1\n10 1 0\n8 0 1\n", "3 1\n3 0 1\n3 1 0\n3 0 0\n", "6 3\n7 1 1\n8 0 0\n9 1 1\n6 1 0\n10 1 1\n5 0 0\n", "8 4 3\n1 1 1\n3 1 1\n12 1 1\n12 1 1\n4 0 0\n4 0 0\n5 1 0\n5 0 1\n", "6 3 ...
IN-CORRECT
cpp
#include <bits/stdc++.h> using namespace std; struct book { int time, a, b; } bk[200010]; queue<book> q1, q2, q3; int cmp(book a, book b) { return a.time > b.time; } int main() { int k, t, x, y, n; long long rzt = 0; book a, b, c; x = 0; y = 0; scanf("%d%d", &n, &k); for (int l1 = 0; l1 < n; l1++) { ...
1374_E1. Reading Books (easy version)
Easy and hard versions are actually different problems, so read statements of both problems completely and carefully. Summer vacation has started so Alice and Bob want to play and joy, but... Their mom doesn't think so. She says that they have to read some amount of books before all entertainments. Alice and Bob will ...
{ "input": [ "8 4\n7 1 1\n2 1 1\n4 0 1\n8 1 1\n1 0 1\n1 1 1\n1 0 1\n3 0 0\n", "5 2\n6 0 0\n9 0 0\n1 0 1\n2 1 1\n5 1 0\n", "5 3\n3 0 0\n2 1 0\n3 1 0\n5 0 1\n3 0 1\n" ], "output": [ "18\n", "8\n", "-1\n" ] }
{ "input": [ "2 1\n7 1 1\n2 1 1\n", "5 1\n2 1 0\n2 0 1\n1 0 1\n1 1 0\n1 0 1\n", "6 2\n6 0 0\n11 1 0\n9 0 1\n21 1 1\n10 1 0\n8 0 1\n", "3 1\n3 0 1\n3 1 0\n3 0 0\n", "6 3\n7 1 1\n8 0 0\n9 1 1\n6 1 0\n10 1 1\n5 0 0\n", "8 4 3\n1 1 1\n3 1 1\n12 1 1\n12 1 1\n4 0 0\n4 0 0\n5 1 0\n5 0 1\n", "6 3 ...
IN-CORRECT
cpp
#include <bits/stdc++.h> using namespace std; const int MAX = 2e5 + 10; const int inf = 0xfffff; struct Book { int pos; int t; bool operator<(const Book &b) const { return t < b.t; } }; int n, m, k, anum = 0, bnum = 0, abnum = 0; vector<Book> book[4], other; int visited[MAX] = {false}; long long anst = 0; int cal...
1374_E1. Reading Books (easy version)
Easy and hard versions are actually different problems, so read statements of both problems completely and carefully. Summer vacation has started so Alice and Bob want to play and joy, but... Their mom doesn't think so. She says that they have to read some amount of books before all entertainments. Alice and Bob will ...
{ "input": [ "8 4\n7 1 1\n2 1 1\n4 0 1\n8 1 1\n1 0 1\n1 1 1\n1 0 1\n3 0 0\n", "5 2\n6 0 0\n9 0 0\n1 0 1\n2 1 1\n5 1 0\n", "5 3\n3 0 0\n2 1 0\n3 1 0\n5 0 1\n3 0 1\n" ], "output": [ "18\n", "8\n", "-1\n" ] }
{ "input": [ "2 1\n7 1 1\n2 1 1\n", "5 1\n2 1 0\n2 0 1\n1 0 1\n1 1 0\n1 0 1\n", "6 2\n6 0 0\n11 1 0\n9 0 1\n21 1 1\n10 1 0\n8 0 1\n", "3 1\n3 0 1\n3 1 0\n3 0 0\n", "6 3\n7 1 1\n8 0 0\n9 1 1\n6 1 0\n10 1 1\n5 0 0\n", "8 4 3\n1 1 1\n3 1 1\n12 1 1\n12 1 1\n4 0 0\n4 0 0\n5 1 0\n5 0 1\n", "6 3 ...
IN-CORRECT
cpp
#include <bits/stdc++.h> using namespace std; vector<long long> v1, va, vb; vector<pair<long long, char> > v; bool cmp(pair<long long, char> a, pair<long long, char> b) { if (a.second == 'c' && b.second == 'c') return (a.first < b.first); if (b.second == 'c') return (0); if (a.second == 'c') return (1); return ...
1374_E1. Reading Books (easy version)
Easy and hard versions are actually different problems, so read statements of both problems completely and carefully. Summer vacation has started so Alice and Bob want to play and joy, but... Their mom doesn't think so. She says that they have to read some amount of books before all entertainments. Alice and Bob will ...
{ "input": [ "8 4\n7 1 1\n2 1 1\n4 0 1\n8 1 1\n1 0 1\n1 1 1\n1 0 1\n3 0 0\n", "5 2\n6 0 0\n9 0 0\n1 0 1\n2 1 1\n5 1 0\n", "5 3\n3 0 0\n2 1 0\n3 1 0\n5 0 1\n3 0 1\n" ], "output": [ "18\n", "8\n", "-1\n" ] }
{ "input": [ "2 1\n7 1 1\n2 1 1\n", "5 1\n2 1 0\n2 0 1\n1 0 1\n1 1 0\n1 0 1\n", "6 2\n6 0 0\n11 1 0\n9 0 1\n21 1 1\n10 1 0\n8 0 1\n", "3 1\n3 0 1\n3 1 0\n3 0 0\n", "6 3\n7 1 1\n8 0 0\n9 1 1\n6 1 0\n10 1 1\n5 0 0\n", "8 4 3\n1 1 1\n3 1 1\n12 1 1\n12 1 1\n4 0 0\n4 0 0\n5 1 0\n5 0 1\n", "6 3 ...
IN-CORRECT
python3
import sys, os from io import BytesIO, IOBase from math import floor, gcd, fabs, factorial, fmod, sqrt, inf, log from collections import defaultdict as dd, deque from heapq import merge, heapify, heappop, heappush, nsmallest from bisect import bisect_left as bl, bisect_right as br, bisect # region fastio BUFSIZE = 819...
1374_E1. Reading Books (easy version)
Easy and hard versions are actually different problems, so read statements of both problems completely and carefully. Summer vacation has started so Alice and Bob want to play and joy, but... Their mom doesn't think so. She says that they have to read some amount of books before all entertainments. Alice and Bob will ...
{ "input": [ "8 4\n7 1 1\n2 1 1\n4 0 1\n8 1 1\n1 0 1\n1 1 1\n1 0 1\n3 0 0\n", "5 2\n6 0 0\n9 0 0\n1 0 1\n2 1 1\n5 1 0\n", "5 3\n3 0 0\n2 1 0\n3 1 0\n5 0 1\n3 0 1\n" ], "output": [ "18\n", "8\n", "-1\n" ] }
{ "input": [ "2 1\n7 1 1\n2 1 1\n", "5 1\n2 1 0\n2 0 1\n1 0 1\n1 1 0\n1 0 1\n", "6 2\n6 0 0\n11 1 0\n9 0 1\n21 1 1\n10 1 0\n8 0 1\n", "3 1\n3 0 1\n3 1 0\n3 0 0\n", "6 3\n7 1 1\n8 0 0\n9 1 1\n6 1 0\n10 1 1\n5 0 0\n", "8 4 3\n1 1 1\n3 1 1\n12 1 1\n12 1 1\n4 0 0\n4 0 0\n5 1 0\n5 0 1\n", "6 3 ...
IN-CORRECT
cpp
#include <bits/stdc++.h> using namespace std; int A[100000], B[100000], C[100000]; int main() { int n, k, t, a, b; cin >> n >> k; int num1 = 0, num2 = 0, num3 = 0; for (int i = 1; i <= n; i++) { cin >> t >> a >> b; if (a == 1 && b != 1) A[++num1] = t; if (a == 0 && b == 1) B[++num2] = t; if (a =...
1374_E1. Reading Books (easy version)
Easy and hard versions are actually different problems, so read statements of both problems completely and carefully. Summer vacation has started so Alice and Bob want to play and joy, but... Their mom doesn't think so. She says that they have to read some amount of books before all entertainments. Alice and Bob will ...
{ "input": [ "8 4\n7 1 1\n2 1 1\n4 0 1\n8 1 1\n1 0 1\n1 1 1\n1 0 1\n3 0 0\n", "5 2\n6 0 0\n9 0 0\n1 0 1\n2 1 1\n5 1 0\n", "5 3\n3 0 0\n2 1 0\n3 1 0\n5 0 1\n3 0 1\n" ], "output": [ "18\n", "8\n", "-1\n" ] }
{ "input": [ "2 1\n7 1 1\n2 1 1\n", "5 1\n2 1 0\n2 0 1\n1 0 1\n1 1 0\n1 0 1\n", "6 2\n6 0 0\n11 1 0\n9 0 1\n21 1 1\n10 1 0\n8 0 1\n", "3 1\n3 0 1\n3 1 0\n3 0 0\n", "6 3\n7 1 1\n8 0 0\n9 1 1\n6 1 0\n10 1 1\n5 0 0\n", "8 4 3\n1 1 1\n3 1 1\n12 1 1\n12 1 1\n4 0 0\n4 0 0\n5 1 0\n5 0 1\n", "6 3 ...
IN-CORRECT
cpp
#include <bits/stdc++.h> using namespace std; #pragma GCC optimize("Ofast,no-stack-protector") #pragma GCC target("sse,sse2,sse3,ssse3,sse4,popcnt,abm,mmx,avx,tune=native") #pragma GCC optimize("unroll-loops") template <class T> inline T bigMod(T p, T e, T M) { T ret = 1; for (; e > 0; e >>= 1) { if (e & 1) ret...
1374_E1. Reading Books (easy version)
Easy and hard versions are actually different problems, so read statements of both problems completely and carefully. Summer vacation has started so Alice and Bob want to play and joy, but... Their mom doesn't think so. She says that they have to read some amount of books before all entertainments. Alice and Bob will ...
{ "input": [ "8 4\n7 1 1\n2 1 1\n4 0 1\n8 1 1\n1 0 1\n1 1 1\n1 0 1\n3 0 0\n", "5 2\n6 0 0\n9 0 0\n1 0 1\n2 1 1\n5 1 0\n", "5 3\n3 0 0\n2 1 0\n3 1 0\n5 0 1\n3 0 1\n" ], "output": [ "18\n", "8\n", "-1\n" ] }
{ "input": [ "2 1\n7 1 1\n2 1 1\n", "5 1\n2 1 0\n2 0 1\n1 0 1\n1 1 0\n1 0 1\n", "6 2\n6 0 0\n11 1 0\n9 0 1\n21 1 1\n10 1 0\n8 0 1\n", "3 1\n3 0 1\n3 1 0\n3 0 0\n", "6 3\n7 1 1\n8 0 0\n9 1 1\n6 1 0\n10 1 1\n5 0 0\n", "8 4 3\n1 1 1\n3 1 1\n12 1 1\n12 1 1\n4 0 0\n4 0 0\n5 1 0\n5 0 1\n", "6 3 ...
IN-CORRECT
python3
n,m,k = map(int, input().split()) oo = list() oa = list() ob = list() zz = list() for i in range(n): t,a,b = map(int, input().split()) if a == 1 and b == 1: oo.append((t,i)) elif a == 0 and b == 1: ob.append((t,i)) elif a == 1 and b == 0: oa.append((t,i)) else: zz.append((t,i)) oo = sorted(oo) oa = sorte...
1374_E1. Reading Books (easy version)
Easy and hard versions are actually different problems, so read statements of both problems completely and carefully. Summer vacation has started so Alice and Bob want to play and joy, but... Their mom doesn't think so. She says that they have to read some amount of books before all entertainments. Alice and Bob will ...
{ "input": [ "8 4\n7 1 1\n2 1 1\n4 0 1\n8 1 1\n1 0 1\n1 1 1\n1 0 1\n3 0 0\n", "5 2\n6 0 0\n9 0 0\n1 0 1\n2 1 1\n5 1 0\n", "5 3\n3 0 0\n2 1 0\n3 1 0\n5 0 1\n3 0 1\n" ], "output": [ "18\n", "8\n", "-1\n" ] }
{ "input": [ "2 1\n7 1 1\n2 1 1\n", "5 1\n2 1 0\n2 0 1\n1 0 1\n1 1 0\n1 0 1\n", "6 2\n6 0 0\n11 1 0\n9 0 1\n21 1 1\n10 1 0\n8 0 1\n", "3 1\n3 0 1\n3 1 0\n3 0 0\n", "6 3\n7 1 1\n8 0 0\n9 1 1\n6 1 0\n10 1 1\n5 0 0\n", "8 4 3\n1 1 1\n3 1 1\n12 1 1\n12 1 1\n4 0 0\n4 0 0\n5 1 0\n5 0 1\n", "6 3 ...
IN-CORRECT
python3
def main(): n,k=list(map(int,input().split())) l=[] c1=0 c2=0 for j in range(0,n): l1=list(map(int,input().split())) if l1[1]==1: c1+=1 if l1[2]==1: c2+=1 l.append(l1) if c1<k or c2<k: print(-1) return l.so...
1374_E1. Reading Books (easy version)
Easy and hard versions are actually different problems, so read statements of both problems completely and carefully. Summer vacation has started so Alice and Bob want to play and joy, but... Their mom doesn't think so. She says that they have to read some amount of books before all entertainments. Alice and Bob will ...
{ "input": [ "8 4\n7 1 1\n2 1 1\n4 0 1\n8 1 1\n1 0 1\n1 1 1\n1 0 1\n3 0 0\n", "5 2\n6 0 0\n9 0 0\n1 0 1\n2 1 1\n5 1 0\n", "5 3\n3 0 0\n2 1 0\n3 1 0\n5 0 1\n3 0 1\n" ], "output": [ "18\n", "8\n", "-1\n" ] }
{ "input": [ "2 1\n7 1 1\n2 1 1\n", "5 1\n2 1 0\n2 0 1\n1 0 1\n1 1 0\n1 0 1\n", "6 2\n6 0 0\n11 1 0\n9 0 1\n21 1 1\n10 1 0\n8 0 1\n", "3 1\n3 0 1\n3 1 0\n3 0 0\n", "6 3\n7 1 1\n8 0 0\n9 1 1\n6 1 0\n10 1 1\n5 0 0\n", "8 4 3\n1 1 1\n3 1 1\n12 1 1\n12 1 1\n4 0 0\n4 0 0\n5 1 0\n5 0 1\n", "6 3 ...
IN-CORRECT
java
import java.io.BufferedReader; import java.io.IOException; import java.io.InputStreamReader; import java.io.OutputStreamWriter; import java.io.PrintWriter; import java.util.Arrays; import java.util.HashSet; import java.util.LinkedList; import java.util.PriorityQueue; import java.util.Queue; import java.util.Set; impor...
1374_E1. Reading Books (easy version)
Easy and hard versions are actually different problems, so read statements of both problems completely and carefully. Summer vacation has started so Alice and Bob want to play and joy, but... Their mom doesn't think so. She says that they have to read some amount of books before all entertainments. Alice and Bob will ...
{ "input": [ "8 4\n7 1 1\n2 1 1\n4 0 1\n8 1 1\n1 0 1\n1 1 1\n1 0 1\n3 0 0\n", "5 2\n6 0 0\n9 0 0\n1 0 1\n2 1 1\n5 1 0\n", "5 3\n3 0 0\n2 1 0\n3 1 0\n5 0 1\n3 0 1\n" ], "output": [ "18\n", "8\n", "-1\n" ] }
{ "input": [ "2 1\n7 1 1\n2 1 1\n", "5 1\n2 1 0\n2 0 1\n1 0 1\n1 1 0\n1 0 1\n", "6 2\n6 0 0\n11 1 0\n9 0 1\n21 1 1\n10 1 0\n8 0 1\n", "3 1\n3 0 1\n3 1 0\n3 0 0\n", "6 3\n7 1 1\n8 0 0\n9 1 1\n6 1 0\n10 1 1\n5 0 0\n", "8 4 3\n1 1 1\n3 1 1\n12 1 1\n12 1 1\n4 0 0\n4 0 0\n5 1 0\n5 0 1\n", "6 3 ...
IN-CORRECT
cpp
#include<bits/stdc++.h> using namespace std; #define int long long int int min(int a,int b) { if(a<=b) return a; else return b; } signed main() { int n,m,k; ios_base::sync_with_stdio(false); cin.tie(NULL); cout.tie(NULL); cin>>n>>m>>k; vector<pair<int,int>> g1,g2,g3,g4; int arr[n+10][3]={0}; int a,b,c; ...
1374_E1. Reading Books (easy version)
Easy and hard versions are actually different problems, so read statements of both problems completely and carefully. Summer vacation has started so Alice and Bob want to play and joy, but... Their mom doesn't think so. She says that they have to read some amount of books before all entertainments. Alice and Bob will ...
{ "input": [ "8 4\n7 1 1\n2 1 1\n4 0 1\n8 1 1\n1 0 1\n1 1 1\n1 0 1\n3 0 0\n", "5 2\n6 0 0\n9 0 0\n1 0 1\n2 1 1\n5 1 0\n", "5 3\n3 0 0\n2 1 0\n3 1 0\n5 0 1\n3 0 1\n" ], "output": [ "18\n", "8\n", "-1\n" ] }
{ "input": [ "2 1\n7 1 1\n2 1 1\n", "5 1\n2 1 0\n2 0 1\n1 0 1\n1 1 0\n1 0 1\n", "6 2\n6 0 0\n11 1 0\n9 0 1\n21 1 1\n10 1 0\n8 0 1\n", "3 1\n3 0 1\n3 1 0\n3 0 0\n", "6 3\n7 1 1\n8 0 0\n9 1 1\n6 1 0\n10 1 1\n5 0 0\n", "8 4 3\n1 1 1\n3 1 1\n12 1 1\n12 1 1\n4 0 0\n4 0 0\n5 1 0\n5 0 1\n", "6 3 ...
IN-CORRECT
cpp
#include <bits/stdc++.h> using namespace std; vector<pair<int, int>> numa, numb, numc, numd; vector<int> ansa, ansb, ansc, ansd; vector<int> mema, memb; int main(int argc, const char* argv[]) { int n, m, k; cin >> n >> m >> k; int cnta = 0, cntb = 0, cntc = 0; for (int i = 0; i < n; i++) { int temp, a, b; ...
1374_E1. Reading Books (easy version)
Easy and hard versions are actually different problems, so read statements of both problems completely and carefully. Summer vacation has started so Alice and Bob want to play and joy, but... Their mom doesn't think so. She says that they have to read some amount of books before all entertainments. Alice and Bob will ...
{ "input": [ "8 4\n7 1 1\n2 1 1\n4 0 1\n8 1 1\n1 0 1\n1 1 1\n1 0 1\n3 0 0\n", "5 2\n6 0 0\n9 0 0\n1 0 1\n2 1 1\n5 1 0\n", "5 3\n3 0 0\n2 1 0\n3 1 0\n5 0 1\n3 0 1\n" ], "output": [ "18\n", "8\n", "-1\n" ] }
{ "input": [ "2 1\n7 1 1\n2 1 1\n", "5 1\n2 1 0\n2 0 1\n1 0 1\n1 1 0\n1 0 1\n", "6 2\n6 0 0\n11 1 0\n9 0 1\n21 1 1\n10 1 0\n8 0 1\n", "3 1\n3 0 1\n3 1 0\n3 0 0\n", "6 3\n7 1 1\n8 0 0\n9 1 1\n6 1 0\n10 1 1\n5 0 0\n", "8 4 3\n1 1 1\n3 1 1\n12 1 1\n12 1 1\n4 0 0\n4 0 0\n5 1 0\n5 0 1\n", "6 3 ...
IN-CORRECT
cpp
#include <bits/stdc++.h> using namespace std; struct ele { long long t; long long a; long long b; }; bool comp(ele e1, ele e2) { return (e2.t > e1.t || ((e2.t == e1.t) && (e2.b * e2.a < e1.b * e1.a))); } signed main() { ios_base::sync_with_stdio(false); cin.tie(NULL); long long T; T = 1; while (T--) {...
1374_E1. Reading Books (easy version)
Easy and hard versions are actually different problems, so read statements of both problems completely and carefully. Summer vacation has started so Alice and Bob want to play and joy, but... Their mom doesn't think so. She says that they have to read some amount of books before all entertainments. Alice and Bob will ...
{ "input": [ "8 4\n7 1 1\n2 1 1\n4 0 1\n8 1 1\n1 0 1\n1 1 1\n1 0 1\n3 0 0\n", "5 2\n6 0 0\n9 0 0\n1 0 1\n2 1 1\n5 1 0\n", "5 3\n3 0 0\n2 1 0\n3 1 0\n5 0 1\n3 0 1\n" ], "output": [ "18\n", "8\n", "-1\n" ] }
{ "input": [ "2 1\n7 1 1\n2 1 1\n", "5 1\n2 1 0\n2 0 1\n1 0 1\n1 1 0\n1 0 1\n", "6 2\n6 0 0\n11 1 0\n9 0 1\n21 1 1\n10 1 0\n8 0 1\n", "3 1\n3 0 1\n3 1 0\n3 0 0\n", "6 3\n7 1 1\n8 0 0\n9 1 1\n6 1 0\n10 1 1\n5 0 0\n", "8 4 3\n1 1 1\n3 1 1\n12 1 1\n12 1 1\n4 0 0\n4 0 0\n5 1 0\n5 0 1\n", "6 3 ...
IN-CORRECT
java
import java.io.*; import java.util.*; import java.math.*; public class Main { public static class Node { int key; int value; Node(int a,int b) { key=a; value=b; } } public static class comp implements Comparator<Node> { public ...
1374_E1. Reading Books (easy version)
Easy and hard versions are actually different problems, so read statements of both problems completely and carefully. Summer vacation has started so Alice and Bob want to play and joy, but... Their mom doesn't think so. She says that they have to read some amount of books before all entertainments. Alice and Bob will ...
{ "input": [ "8 4\n7 1 1\n2 1 1\n4 0 1\n8 1 1\n1 0 1\n1 1 1\n1 0 1\n3 0 0\n", "5 2\n6 0 0\n9 0 0\n1 0 1\n2 1 1\n5 1 0\n", "5 3\n3 0 0\n2 1 0\n3 1 0\n5 0 1\n3 0 1\n" ], "output": [ "18\n", "8\n", "-1\n" ] }
{ "input": [ "2 1\n7 1 1\n2 1 1\n", "5 1\n2 1 0\n2 0 1\n1 0 1\n1 1 0\n1 0 1\n", "6 2\n6 0 0\n11 1 0\n9 0 1\n21 1 1\n10 1 0\n8 0 1\n", "3 1\n3 0 1\n3 1 0\n3 0 0\n", "6 3\n7 1 1\n8 0 0\n9 1 1\n6 1 0\n10 1 1\n5 0 0\n", "8 4 3\n1 1 1\n3 1 1\n12 1 1\n12 1 1\n4 0 0\n4 0 0\n5 1 0\n5 0 1\n", "6 3 ...
IN-CORRECT
cpp
#include <bits/stdc++.h> using namespace std; const int maxn = 2e5 + 100; const int mo = 2000000007; pair<int, int> a[4][maxn]; int b[4][maxn], cnt[4]; int n, m, k, u, v, w; int work(int v1, int v2) { int l2 = 1, r2 = m - v1 - v2, tp = m - v1 - v2; while (l2 < r2 + 1) { int mid = l2 + r2 >> 1; if (b[1][mid]...
1374_E1. Reading Books (easy version)
Easy and hard versions are actually different problems, so read statements of both problems completely and carefully. Summer vacation has started so Alice and Bob want to play and joy, but... Their mom doesn't think so. She says that they have to read some amount of books before all entertainments. Alice and Bob will ...
{ "input": [ "8 4\n7 1 1\n2 1 1\n4 0 1\n8 1 1\n1 0 1\n1 1 1\n1 0 1\n3 0 0\n", "5 2\n6 0 0\n9 0 0\n1 0 1\n2 1 1\n5 1 0\n", "5 3\n3 0 0\n2 1 0\n3 1 0\n5 0 1\n3 0 1\n" ], "output": [ "18\n", "8\n", "-1\n" ] }
{ "input": [ "2 1\n7 1 1\n2 1 1\n", "5 1\n2 1 0\n2 0 1\n1 0 1\n1 1 0\n1 0 1\n", "6 2\n6 0 0\n11 1 0\n9 0 1\n21 1 1\n10 1 0\n8 0 1\n", "3 1\n3 0 1\n3 1 0\n3 0 0\n", "6 3\n7 1 1\n8 0 0\n9 1 1\n6 1 0\n10 1 1\n5 0 0\n", "8 4 3\n1 1 1\n3 1 1\n12 1 1\n12 1 1\n4 0 0\n4 0 0\n5 1 0\n5 0 1\n", "6 3 ...
IN-CORRECT
cpp
#include <bits/stdc++.h> using namespace std; const long long mod = 1e9 + 7; const long long inf = 2e18 + 5; void solve() { long long n, k; cin >> n >> k; vector<pair<long long, pair<long long, long long> > > a(n); vector<long long> alice, bob; long long x, y, z; for (long long i = (0); i < (n); i++) { ...
1374_E1. Reading Books (easy version)
Easy and hard versions are actually different problems, so read statements of both problems completely and carefully. Summer vacation has started so Alice and Bob want to play and joy, but... Their mom doesn't think so. She says that they have to read some amount of books before all entertainments. Alice and Bob will ...
{ "input": [ "8 4\n7 1 1\n2 1 1\n4 0 1\n8 1 1\n1 0 1\n1 1 1\n1 0 1\n3 0 0\n", "5 2\n6 0 0\n9 0 0\n1 0 1\n2 1 1\n5 1 0\n", "5 3\n3 0 0\n2 1 0\n3 1 0\n5 0 1\n3 0 1\n" ], "output": [ "18\n", "8\n", "-1\n" ] }
{ "input": [ "2 1\n7 1 1\n2 1 1\n", "5 1\n2 1 0\n2 0 1\n1 0 1\n1 1 0\n1 0 1\n", "6 2\n6 0 0\n11 1 0\n9 0 1\n21 1 1\n10 1 0\n8 0 1\n", "3 1\n3 0 1\n3 1 0\n3 0 0\n", "6 3\n7 1 1\n8 0 0\n9 1 1\n6 1 0\n10 1 1\n5 0 0\n", "8 4 3\n1 1 1\n3 1 1\n12 1 1\n12 1 1\n4 0 0\n4 0 0\n5 1 0\n5 0 1\n", "6 3 ...
IN-CORRECT
cpp
#include <bits/stdc++.h> using namespace std; const long long mod = 1e9 + 7; int32_t main() { ios_base::sync_with_stdio(0); cin.tie(0); long long n, k; cin >> n >> k; vector<long long> a, b, ab; for (long long i = 0; i < n; i++) { long long t, x, y; cin >> t >> x >> y; if (x == 1 && y == 1) { ...
1374_E1. Reading Books (easy version)
Easy and hard versions are actually different problems, so read statements of both problems completely and carefully. Summer vacation has started so Alice and Bob want to play and joy, but... Their mom doesn't think so. She says that they have to read some amount of books before all entertainments. Alice and Bob will ...
{ "input": [ "8 4\n7 1 1\n2 1 1\n4 0 1\n8 1 1\n1 0 1\n1 1 1\n1 0 1\n3 0 0\n", "5 2\n6 0 0\n9 0 0\n1 0 1\n2 1 1\n5 1 0\n", "5 3\n3 0 0\n2 1 0\n3 1 0\n5 0 1\n3 0 1\n" ], "output": [ "18\n", "8\n", "-1\n" ] }
{ "input": [ "2 1\n7 1 1\n2 1 1\n", "5 1\n2 1 0\n2 0 1\n1 0 1\n1 1 0\n1 0 1\n", "6 2\n6 0 0\n11 1 0\n9 0 1\n21 1 1\n10 1 0\n8 0 1\n", "3 1\n3 0 1\n3 1 0\n3 0 0\n", "6 3\n7 1 1\n8 0 0\n9 1 1\n6 1 0\n10 1 1\n5 0 0\n", "8 4 3\n1 1 1\n3 1 1\n12 1 1\n12 1 1\n4 0 0\n4 0 0\n5 1 0\n5 0 1\n", "6 3 ...
IN-CORRECT
cpp
/* Just Another Source code by - Ambuj */ #include<bits/stdc++.h> using namespace std; #define error(args...) { string _s = #args; replace(_s.begin(), _s.end(), ',', ' '); stringstream _ss(_s); istream_iterator<string> _it(_ss); err(_it, args); } void err(istream_iterator<string> it) {} template<typename...
1374_E1. Reading Books (easy version)
Easy and hard versions are actually different problems, so read statements of both problems completely and carefully. Summer vacation has started so Alice and Bob want to play and joy, but... Their mom doesn't think so. She says that they have to read some amount of books before all entertainments. Alice and Bob will ...
{ "input": [ "8 4\n7 1 1\n2 1 1\n4 0 1\n8 1 1\n1 0 1\n1 1 1\n1 0 1\n3 0 0\n", "5 2\n6 0 0\n9 0 0\n1 0 1\n2 1 1\n5 1 0\n", "5 3\n3 0 0\n2 1 0\n3 1 0\n5 0 1\n3 0 1\n" ], "output": [ "18\n", "8\n", "-1\n" ] }
{ "input": [ "2 1\n7 1 1\n2 1 1\n", "5 1\n2 1 0\n2 0 1\n1 0 1\n1 1 0\n1 0 1\n", "6 2\n6 0 0\n11 1 0\n9 0 1\n21 1 1\n10 1 0\n8 0 1\n", "3 1\n3 0 1\n3 1 0\n3 0 0\n", "6 3\n7 1 1\n8 0 0\n9 1 1\n6 1 0\n10 1 1\n5 0 0\n", "8 4 3\n1 1 1\n3 1 1\n12 1 1\n12 1 1\n4 0 0\n4 0 0\n5 1 0\n5 0 1\n", "6 3 ...
IN-CORRECT
cpp
#include <bits/stdc++.h> using namespace std; const string YESNO[2] = {"NO", "YES"}; const string YesNo[2] = {"No", "Yes"}; const string yesno[2] = {"no", "yes"}; void YES(bool t = 1) { cout << YESNO[t] << "\n"; } void Yes(bool t = 1) { cout << YesNo[t] << "\n"; } void yes(bool t = 1) { cout << yesno[t] << "\n"; } cons...
1374_E1. Reading Books (easy version)
Easy and hard versions are actually different problems, so read statements of both problems completely and carefully. Summer vacation has started so Alice and Bob want to play and joy, but... Their mom doesn't think so. She says that they have to read some amount of books before all entertainments. Alice and Bob will ...
{ "input": [ "8 4\n7 1 1\n2 1 1\n4 0 1\n8 1 1\n1 0 1\n1 1 1\n1 0 1\n3 0 0\n", "5 2\n6 0 0\n9 0 0\n1 0 1\n2 1 1\n5 1 0\n", "5 3\n3 0 0\n2 1 0\n3 1 0\n5 0 1\n3 0 1\n" ], "output": [ "18\n", "8\n", "-1\n" ] }
{ "input": [ "2 1\n7 1 1\n2 1 1\n", "5 1\n2 1 0\n2 0 1\n1 0 1\n1 1 0\n1 0 1\n", "6 2\n6 0 0\n11 1 0\n9 0 1\n21 1 1\n10 1 0\n8 0 1\n", "3 1\n3 0 1\n3 1 0\n3 0 0\n", "6 3\n7 1 1\n8 0 0\n9 1 1\n6 1 0\n10 1 1\n5 0 0\n", "8 4 3\n1 1 1\n3 1 1\n12 1 1\n12 1 1\n4 0 0\n4 0 0\n5 1 0\n5 0 1\n", "6 3 ...
IN-CORRECT
cpp
#include <bits/stdc++.h> using namespace std; long long gcd(long long a, long long b) { if (b == 0) return a; return gcd(b, a % b); } long long lcm(long long a, long long b) { return (a * b) / gcd(a, b); } void print(vector<long long> a) { for (int i = 0; i < a.size(); i++) { cout << a[i] << ' '; } cout <...
1374_E1. Reading Books (easy version)
Easy and hard versions are actually different problems, so read statements of both problems completely and carefully. Summer vacation has started so Alice and Bob want to play and joy, but... Their mom doesn't think so. She says that they have to read some amount of books before all entertainments. Alice and Bob will ...
{ "input": [ "8 4\n7 1 1\n2 1 1\n4 0 1\n8 1 1\n1 0 1\n1 1 1\n1 0 1\n3 0 0\n", "5 2\n6 0 0\n9 0 0\n1 0 1\n2 1 1\n5 1 0\n", "5 3\n3 0 0\n2 1 0\n3 1 0\n5 0 1\n3 0 1\n" ], "output": [ "18\n", "8\n", "-1\n" ] }
{ "input": [ "2 1\n7 1 1\n2 1 1\n", "5 1\n2 1 0\n2 0 1\n1 0 1\n1 1 0\n1 0 1\n", "6 2\n6 0 0\n11 1 0\n9 0 1\n21 1 1\n10 1 0\n8 0 1\n", "3 1\n3 0 1\n3 1 0\n3 0 0\n", "6 3\n7 1 1\n8 0 0\n9 1 1\n6 1 0\n10 1 1\n5 0 0\n", "8 4 3\n1 1 1\n3 1 1\n12 1 1\n12 1 1\n4 0 0\n4 0 0\n5 1 0\n5 0 1\n", "6 3 ...
IN-CORRECT
python3
import sys s = sys.stdin.readline().split() n, m, k = int(s[0]), int(s[1]), int(s[2]) all = [] All = [] Alice = [] Bob = [] Both = [] none = [] z = 1 while n: i = sys.stdin.readline().split() x = 3 i.append(z) while x: i[x-1] = int(i[x - 1]) x -= 1 all.append(i) if i[1] == i[2...
1374_E1. Reading Books (easy version)
Easy and hard versions are actually different problems, so read statements of both problems completely and carefully. Summer vacation has started so Alice and Bob want to play and joy, but... Their mom doesn't think so. She says that they have to read some amount of books before all entertainments. Alice and Bob will ...
{ "input": [ "8 4\n7 1 1\n2 1 1\n4 0 1\n8 1 1\n1 0 1\n1 1 1\n1 0 1\n3 0 0\n", "5 2\n6 0 0\n9 0 0\n1 0 1\n2 1 1\n5 1 0\n", "5 3\n3 0 0\n2 1 0\n3 1 0\n5 0 1\n3 0 1\n" ], "output": [ "18\n", "8\n", "-1\n" ] }
{ "input": [ "2 1\n7 1 1\n2 1 1\n", "5 1\n2 1 0\n2 0 1\n1 0 1\n1 1 0\n1 0 1\n", "6 2\n6 0 0\n11 1 0\n9 0 1\n21 1 1\n10 1 0\n8 0 1\n", "3 1\n3 0 1\n3 1 0\n3 0 0\n", "6 3\n7 1 1\n8 0 0\n9 1 1\n6 1 0\n10 1 1\n5 0 0\n", "8 4 3\n1 1 1\n3 1 1\n12 1 1\n12 1 1\n4 0 0\n4 0 0\n5 1 0\n5 0 1\n", "6 3 ...
IN-CORRECT
cpp
#include <bits/stdc++.h> using namespace std; int main() { int n, k; cin >> n >> k; vector<int> afor; vector<int> bfor; int q = 0; long sum1 = 0; for (int i = 0; i < n; i++) { int t, a, b; cin >> t >> a >> b; if (a == 1 && b == 0) afor.push_back(t); if (b == 1 && a == 0) bfor.push_back(t);...
1374_E1. Reading Books (easy version)
Easy and hard versions are actually different problems, so read statements of both problems completely and carefully. Summer vacation has started so Alice and Bob want to play and joy, but... Their mom doesn't think so. She says that they have to read some amount of books before all entertainments. Alice and Bob will ...
{ "input": [ "8 4\n7 1 1\n2 1 1\n4 0 1\n8 1 1\n1 0 1\n1 1 1\n1 0 1\n3 0 0\n", "5 2\n6 0 0\n9 0 0\n1 0 1\n2 1 1\n5 1 0\n", "5 3\n3 0 0\n2 1 0\n3 1 0\n5 0 1\n3 0 1\n" ], "output": [ "18\n", "8\n", "-1\n" ] }
{ "input": [ "2 1\n7 1 1\n2 1 1\n", "5 1\n2 1 0\n2 0 1\n1 0 1\n1 1 0\n1 0 1\n", "6 2\n6 0 0\n11 1 0\n9 0 1\n21 1 1\n10 1 0\n8 0 1\n", "3 1\n3 0 1\n3 1 0\n3 0 0\n", "6 3\n7 1 1\n8 0 0\n9 1 1\n6 1 0\n10 1 1\n5 0 0\n", "8 4 3\n1 1 1\n3 1 1\n12 1 1\n12 1 1\n4 0 0\n4 0 0\n5 1 0\n5 0 1\n", "6 3 ...
IN-CORRECT
python3
import io,os input=io.BytesIO(os.read(0,os.fstat(0).st_size)).readline import sys def solve(n,k,TAB): A,B,AB=[],[],[] cnt_a,cnt_b=0,0 for t,a,b in TAB: cnt_a+=a cnt_b+=b if a*b==1: AB.append(t) elif a==1: A.append(t) elif b==1: B.a...
1374_E1. Reading Books (easy version)
Easy and hard versions are actually different problems, so read statements of both problems completely and carefully. Summer vacation has started so Alice and Bob want to play and joy, but... Their mom doesn't think so. She says that they have to read some amount of books before all entertainments. Alice and Bob will ...
{ "input": [ "8 4\n7 1 1\n2 1 1\n4 0 1\n8 1 1\n1 0 1\n1 1 1\n1 0 1\n3 0 0\n", "5 2\n6 0 0\n9 0 0\n1 0 1\n2 1 1\n5 1 0\n", "5 3\n3 0 0\n2 1 0\n3 1 0\n5 0 1\n3 0 1\n" ], "output": [ "18\n", "8\n", "-1\n" ] }
{ "input": [ "2 1\n7 1 1\n2 1 1\n", "5 1\n2 1 0\n2 0 1\n1 0 1\n1 1 0\n1 0 1\n", "6 2\n6 0 0\n11 1 0\n9 0 1\n21 1 1\n10 1 0\n8 0 1\n", "3 1\n3 0 1\n3 1 0\n3 0 0\n", "6 3\n7 1 1\n8 0 0\n9 1 1\n6 1 0\n10 1 1\n5 0 0\n", "8 4 3\n1 1 1\n3 1 1\n12 1 1\n12 1 1\n4 0 0\n4 0 0\n5 1 0\n5 0 1\n", "6 3 ...
IN-CORRECT
cpp
#include <bits/stdc++.h> using namespace std; string to_string(const string& s) { return '"' + s + '"'; } string to_string(bool b) { return (b ? "true" : "false"); } template <typename A, typename B> string to_string(pair<A, B> p) { return "(" + to_string(p.first) + ", " + to_string(p.second) + ")"; } template <typen...
1374_E1. Reading Books (easy version)
Easy and hard versions are actually different problems, so read statements of both problems completely and carefully. Summer vacation has started so Alice and Bob want to play and joy, but... Their mom doesn't think so. She says that they have to read some amount of books before all entertainments. Alice and Bob will ...
{ "input": [ "8 4\n7 1 1\n2 1 1\n4 0 1\n8 1 1\n1 0 1\n1 1 1\n1 0 1\n3 0 0\n", "5 2\n6 0 0\n9 0 0\n1 0 1\n2 1 1\n5 1 0\n", "5 3\n3 0 0\n2 1 0\n3 1 0\n5 0 1\n3 0 1\n" ], "output": [ "18\n", "8\n", "-1\n" ] }
{ "input": [ "2 1\n7 1 1\n2 1 1\n", "5 1\n2 1 0\n2 0 1\n1 0 1\n1 1 0\n1 0 1\n", "6 2\n6 0 0\n11 1 0\n9 0 1\n21 1 1\n10 1 0\n8 0 1\n", "3 1\n3 0 1\n3 1 0\n3 0 0\n", "6 3\n7 1 1\n8 0 0\n9 1 1\n6 1 0\n10 1 1\n5 0 0\n", "8 4 3\n1 1 1\n3 1 1\n12 1 1\n12 1 1\n4 0 0\n4 0 0\n5 1 0\n5 0 1\n", "6 3 ...
IN-CORRECT
java
import java.util.*; import java.math.*; import java.io.*; public class A{ static FastReader scan=new FastReader(); public static PrintWriter out = new PrintWriter (new BufferedOutputStream(System.out)); static LinkedList<Integer>edges[]; // static LinkedList<Pair>edges[]; static boolean stdin = true; stat...
1374_E1. Reading Books (easy version)
Easy and hard versions are actually different problems, so read statements of both problems completely and carefully. Summer vacation has started so Alice and Bob want to play and joy, but... Their mom doesn't think so. She says that they have to read some amount of books before all entertainments. Alice and Bob will ...
{ "input": [ "8 4\n7 1 1\n2 1 1\n4 0 1\n8 1 1\n1 0 1\n1 1 1\n1 0 1\n3 0 0\n", "5 2\n6 0 0\n9 0 0\n1 0 1\n2 1 1\n5 1 0\n", "5 3\n3 0 0\n2 1 0\n3 1 0\n5 0 1\n3 0 1\n" ], "output": [ "18\n", "8\n", "-1\n" ] }
{ "input": [ "2 1\n7 1 1\n2 1 1\n", "5 1\n2 1 0\n2 0 1\n1 0 1\n1 1 0\n1 0 1\n", "6 2\n6 0 0\n11 1 0\n9 0 1\n21 1 1\n10 1 0\n8 0 1\n", "3 1\n3 0 1\n3 1 0\n3 0 0\n", "6 3\n7 1 1\n8 0 0\n9 1 1\n6 1 0\n10 1 1\n5 0 0\n", "8 4 3\n1 1 1\n3 1 1\n12 1 1\n12 1 1\n4 0 0\n4 0 0\n5 1 0\n5 0 1\n", "6 3 ...
IN-CORRECT
python3
import os import sys from io import BytesIO, IOBase # region fastio BUFSIZE = 8192 class FastIO(IOBase): newlines = 0 def __init__(self, file): self._fd = file.fileno() self.buffer = BytesIO() self.writable = "x" in file.mode or "r" not in file.mode self.write = self.buffer.wr...
1374_E1. Reading Books (easy version)
Easy and hard versions are actually different problems, so read statements of both problems completely and carefully. Summer vacation has started so Alice and Bob want to play and joy, but... Their mom doesn't think so. She says that they have to read some amount of books before all entertainments. Alice and Bob will ...
{ "input": [ "8 4\n7 1 1\n2 1 1\n4 0 1\n8 1 1\n1 0 1\n1 1 1\n1 0 1\n3 0 0\n", "5 2\n6 0 0\n9 0 0\n1 0 1\n2 1 1\n5 1 0\n", "5 3\n3 0 0\n2 1 0\n3 1 0\n5 0 1\n3 0 1\n" ], "output": [ "18\n", "8\n", "-1\n" ] }
{ "input": [ "2 1\n7 1 1\n2 1 1\n", "5 1\n2 1 0\n2 0 1\n1 0 1\n1 1 0\n1 0 1\n", "6 2\n6 0 0\n11 1 0\n9 0 1\n21 1 1\n10 1 0\n8 0 1\n", "3 1\n3 0 1\n3 1 0\n3 0 0\n", "6 3\n7 1 1\n8 0 0\n9 1 1\n6 1 0\n10 1 1\n5 0 0\n", "8 4 3\n1 1 1\n3 1 1\n12 1 1\n12 1 1\n4 0 0\n4 0 0\n5 1 0\n5 0 1\n", "6 3 ...
IN-CORRECT
java
import java.io.BufferedReader; import java.io.IOException; import java.io.InputStreamReader; import java.util.ArrayList; import java.util.PriorityQueue; import java.util.StringTokenizer; public class E { public static void main(String[] args) throws IOException { BufferedReader file = new BufferedReader(new InputS...
1374_E1. Reading Books (easy version)
Easy and hard versions are actually different problems, so read statements of both problems completely and carefully. Summer vacation has started so Alice and Bob want to play and joy, but... Their mom doesn't think so. She says that they have to read some amount of books before all entertainments. Alice and Bob will ...
{ "input": [ "8 4\n7 1 1\n2 1 1\n4 0 1\n8 1 1\n1 0 1\n1 1 1\n1 0 1\n3 0 0\n", "5 2\n6 0 0\n9 0 0\n1 0 1\n2 1 1\n5 1 0\n", "5 3\n3 0 0\n2 1 0\n3 1 0\n5 0 1\n3 0 1\n" ], "output": [ "18\n", "8\n", "-1\n" ] }
{ "input": [ "2 1\n7 1 1\n2 1 1\n", "5 1\n2 1 0\n2 0 1\n1 0 1\n1 1 0\n1 0 1\n", "6 2\n6 0 0\n11 1 0\n9 0 1\n21 1 1\n10 1 0\n8 0 1\n", "3 1\n3 0 1\n3 1 0\n3 0 0\n", "6 3\n7 1 1\n8 0 0\n9 1 1\n6 1 0\n10 1 1\n5 0 0\n", "8 4 3\n1 1 1\n3 1 1\n12 1 1\n12 1 1\n4 0 0\n4 0 0\n5 1 0\n5 0 1\n", "6 3 ...
IN-CORRECT
cpp
#include <bits/stdc++.h> #pragma GCC optimize("Ofast") #pragma GCC optimize("unroll-loops") #pragma GCC target("sse,sse2,sse3,ssse3,sse4,popcnt,abm,mmx,avx,tune=native") using namespace std; int main() { cin.tie(nullptr); ios::sync_with_stdio(false); int n, m, k; cin >> n >> m >> k; int A = k, B = k; long l...
1374_E1. Reading Books (easy version)
Easy and hard versions are actually different problems, so read statements of both problems completely and carefully. Summer vacation has started so Alice and Bob want to play and joy, but... Their mom doesn't think so. She says that they have to read some amount of books before all entertainments. Alice and Bob will ...
{ "input": [ "8 4\n7 1 1\n2 1 1\n4 0 1\n8 1 1\n1 0 1\n1 1 1\n1 0 1\n3 0 0\n", "5 2\n6 0 0\n9 0 0\n1 0 1\n2 1 1\n5 1 0\n", "5 3\n3 0 0\n2 1 0\n3 1 0\n5 0 1\n3 0 1\n" ], "output": [ "18\n", "8\n", "-1\n" ] }
{ "input": [ "2 1\n7 1 1\n2 1 1\n", "5 1\n2 1 0\n2 0 1\n1 0 1\n1 1 0\n1 0 1\n", "6 2\n6 0 0\n11 1 0\n9 0 1\n21 1 1\n10 1 0\n8 0 1\n", "3 1\n3 0 1\n3 1 0\n3 0 0\n", "6 3\n7 1 1\n8 0 0\n9 1 1\n6 1 0\n10 1 1\n5 0 0\n", "8 4 3\n1 1 1\n3 1 1\n12 1 1\n12 1 1\n4 0 0\n4 0 0\n5 1 0\n5 0 1\n", "6 3 ...
IN-CORRECT
java
import java.io.*; import java.math.BigInteger; import java.util.*; public class E { public static void main(String[] args) throws Exception { Scanner sc = new Scanner(System.in); PrintWriter pw = new PrintWriter(System.out); int n = sc.nextInt(); int m = sc.nextInt(); int k ...
1374_E1. Reading Books (easy version)
Easy and hard versions are actually different problems, so read statements of both problems completely and carefully. Summer vacation has started so Alice and Bob want to play and joy, but... Their mom doesn't think so. She says that they have to read some amount of books before all entertainments. Alice and Bob will ...
{ "input": [ "8 4\n7 1 1\n2 1 1\n4 0 1\n8 1 1\n1 0 1\n1 1 1\n1 0 1\n3 0 0\n", "5 2\n6 0 0\n9 0 0\n1 0 1\n2 1 1\n5 1 0\n", "5 3\n3 0 0\n2 1 0\n3 1 0\n5 0 1\n3 0 1\n" ], "output": [ "18\n", "8\n", "-1\n" ] }
{ "input": [ "2 1\n7 1 1\n2 1 1\n", "5 1\n2 1 0\n2 0 1\n1 0 1\n1 1 0\n1 0 1\n", "6 2\n6 0 0\n11 1 0\n9 0 1\n21 1 1\n10 1 0\n8 0 1\n", "3 1\n3 0 1\n3 1 0\n3 0 0\n", "6 3\n7 1 1\n8 0 0\n9 1 1\n6 1 0\n10 1 1\n5 0 0\n", "8 4 3\n1 1 1\n3 1 1\n12 1 1\n12 1 1\n4 0 0\n4 0 0\n5 1 0\n5 0 1\n", "6 3 ...
IN-CORRECT
python3
line = input() n, m, k = [int(i) for i in line.split(' ')] books, allL, aliceL, bobL, other =list(range(1, n + 1)), [], [], [], [] ts = [[] for _ in range(n + 1)] for i in range(n): line = input() t, a, b = [int(j) for j in line.split(' ')] ts[i + 1] = [t, a, b] if a == 1 and b == 1: allL.appen...
1374_E1. Reading Books (easy version)
Easy and hard versions are actually different problems, so read statements of both problems completely and carefully. Summer vacation has started so Alice and Bob want to play and joy, but... Their mom doesn't think so. She says that they have to read some amount of books before all entertainments. Alice and Bob will ...
{ "input": [ "8 4\n7 1 1\n2 1 1\n4 0 1\n8 1 1\n1 0 1\n1 1 1\n1 0 1\n3 0 0\n", "5 2\n6 0 0\n9 0 0\n1 0 1\n2 1 1\n5 1 0\n", "5 3\n3 0 0\n2 1 0\n3 1 0\n5 0 1\n3 0 1\n" ], "output": [ "18\n", "8\n", "-1\n" ] }
{ "input": [ "2 1\n7 1 1\n2 1 1\n", "5 1\n2 1 0\n2 0 1\n1 0 1\n1 1 0\n1 0 1\n", "6 2\n6 0 0\n11 1 0\n9 0 1\n21 1 1\n10 1 0\n8 0 1\n", "3 1\n3 0 1\n3 1 0\n3 0 0\n", "6 3\n7 1 1\n8 0 0\n9 1 1\n6 1 0\n10 1 1\n5 0 0\n", "8 4 3\n1 1 1\n3 1 1\n12 1 1\n12 1 1\n4 0 0\n4 0 0\n5 1 0\n5 0 1\n", "6 3 ...
IN-CORRECT
python3
def partition(list,low,high): p1 = low-1 for p2 in range(low,high): if list[p2] < list[high]: p1 = p1+1 list[p1],list[p2] = list[p2],list[p1] list[p1+1],list[high] = list[high],list[p1+1] return (p1+1) def sort(list,low,high): if low < high: p = partition(lis...
1374_E1. Reading Books (easy version)
Easy and hard versions are actually different problems, so read statements of both problems completely and carefully. Summer vacation has started so Alice and Bob want to play and joy, but... Their mom doesn't think so. She says that they have to read some amount of books before all entertainments. Alice and Bob will ...
{ "input": [ "8 4\n7 1 1\n2 1 1\n4 0 1\n8 1 1\n1 0 1\n1 1 1\n1 0 1\n3 0 0\n", "5 2\n6 0 0\n9 0 0\n1 0 1\n2 1 1\n5 1 0\n", "5 3\n3 0 0\n2 1 0\n3 1 0\n5 0 1\n3 0 1\n" ], "output": [ "18\n", "8\n", "-1\n" ] }
{ "input": [ "2 1\n7 1 1\n2 1 1\n", "5 1\n2 1 0\n2 0 1\n1 0 1\n1 1 0\n1 0 1\n", "6 2\n6 0 0\n11 1 0\n9 0 1\n21 1 1\n10 1 0\n8 0 1\n", "3 1\n3 0 1\n3 1 0\n3 0 0\n", "6 3\n7 1 1\n8 0 0\n9 1 1\n6 1 0\n10 1 1\n5 0 0\n", "8 4 3\n1 1 1\n3 1 1\n12 1 1\n12 1 1\n4 0 0\n4 0 0\n5 1 0\n5 0 1\n", "6 3 ...
IN-CORRECT
python3
n,k=map(int,input().split()) l,l1,l2=[],[],[] for i in range(n): t,a,b=map(int,input().split()) if a==1 and b==1: l.append(t) if a==1 and b==0: l1.append(t) if a==0 and b==1: l2.append(t) l.sort() l1.sort() l2.sort() c,ans,a,b=0,0,0,0 while a<k or b<k: if l and l1 and l2: ...
1374_E1. Reading Books (easy version)
Easy and hard versions are actually different problems, so read statements of both problems completely and carefully. Summer vacation has started so Alice and Bob want to play and joy, but... Their mom doesn't think so. She says that they have to read some amount of books before all entertainments. Alice and Bob will ...
{ "input": [ "8 4\n7 1 1\n2 1 1\n4 0 1\n8 1 1\n1 0 1\n1 1 1\n1 0 1\n3 0 0\n", "5 2\n6 0 0\n9 0 0\n1 0 1\n2 1 1\n5 1 0\n", "5 3\n3 0 0\n2 1 0\n3 1 0\n5 0 1\n3 0 1\n" ], "output": [ "18\n", "8\n", "-1\n" ] }
{ "input": [ "2 1\n7 1 1\n2 1 1\n", "5 1\n2 1 0\n2 0 1\n1 0 1\n1 1 0\n1 0 1\n", "6 2\n6 0 0\n11 1 0\n9 0 1\n21 1 1\n10 1 0\n8 0 1\n", "3 1\n3 0 1\n3 1 0\n3 0 0\n", "6 3\n7 1 1\n8 0 0\n9 1 1\n6 1 0\n10 1 1\n5 0 0\n", "8 4 3\n1 1 1\n3 1 1\n12 1 1\n12 1 1\n4 0 0\n4 0 0\n5 1 0\n5 0 1\n", "6 3 ...
IN-CORRECT
python3
import math as mt import sys,string input=sys.stdin.readline #print=sys.stdout.write L=lambda : list(map(int,input().split())) Ls=lambda : list(input().split()) M=lambda : map(int,input().split()) I=lambda :int(input()) from collections import defaultdict t=1 for _ in range(t): n,k=M() l=[] for i in ran...
1374_E1. Reading Books (easy version)
Easy and hard versions are actually different problems, so read statements of both problems completely and carefully. Summer vacation has started so Alice and Bob want to play and joy, but... Their mom doesn't think so. She says that they have to read some amount of books before all entertainments. Alice and Bob will ...
{ "input": [ "8 4\n7 1 1\n2 1 1\n4 0 1\n8 1 1\n1 0 1\n1 1 1\n1 0 1\n3 0 0\n", "5 2\n6 0 0\n9 0 0\n1 0 1\n2 1 1\n5 1 0\n", "5 3\n3 0 0\n2 1 0\n3 1 0\n5 0 1\n3 0 1\n" ], "output": [ "18\n", "8\n", "-1\n" ] }
{ "input": [ "2 1\n7 1 1\n2 1 1\n", "5 1\n2 1 0\n2 0 1\n1 0 1\n1 1 0\n1 0 1\n", "6 2\n6 0 0\n11 1 0\n9 0 1\n21 1 1\n10 1 0\n8 0 1\n", "3 1\n3 0 1\n3 1 0\n3 0 0\n", "6 3\n7 1 1\n8 0 0\n9 1 1\n6 1 0\n10 1 1\n5 0 0\n", "8 4 3\n1 1 1\n3 1 1\n12 1 1\n12 1 1\n4 0 0\n4 0 0\n5 1 0\n5 0 1\n", "6 3 ...
IN-CORRECT
python3
import sys s = sys.stdin.readline().split() n, m, k = int(s[0]), int(s[1]), int(s[2]) all = [] All = [] Alice = [] Bob = [] Both = [] none = [] z = 1 while n: i = sys.stdin.readline().split() x = 3 i.append(z) while x: i[x-1] = int(i[x - 1]) x -= 1 all.append(i) if i[1] == i[...
1374_E1. Reading Books (easy version)
Easy and hard versions are actually different problems, so read statements of both problems completely and carefully. Summer vacation has started so Alice and Bob want to play and joy, but... Their mom doesn't think so. She says that they have to read some amount of books before all entertainments. Alice and Bob will ...
{ "input": [ "8 4\n7 1 1\n2 1 1\n4 0 1\n8 1 1\n1 0 1\n1 1 1\n1 0 1\n3 0 0\n", "5 2\n6 0 0\n9 0 0\n1 0 1\n2 1 1\n5 1 0\n", "5 3\n3 0 0\n2 1 0\n3 1 0\n5 0 1\n3 0 1\n" ], "output": [ "18\n", "8\n", "-1\n" ] }
{ "input": [ "2 1\n7 1 1\n2 1 1\n", "5 1\n2 1 0\n2 0 1\n1 0 1\n1 1 0\n1 0 1\n", "6 2\n6 0 0\n11 1 0\n9 0 1\n21 1 1\n10 1 0\n8 0 1\n", "3 1\n3 0 1\n3 1 0\n3 0 0\n", "6 3\n7 1 1\n8 0 0\n9 1 1\n6 1 0\n10 1 1\n5 0 0\n", "8 4 3\n1 1 1\n3 1 1\n12 1 1\n12 1 1\n4 0 0\n4 0 0\n5 1 0\n5 0 1\n", "6 3 ...
IN-CORRECT
python3
n, k = map(int, input().split()) books = [] alice = set() bob = set() for i in range(n): books.append([int(i) for i in input().split()]) if books[-1][1] == 1: alice.add(i) if books[-1][2] == 1: bob.add(i) if len(alice) <= k < len(bob): ans_a = sum([books[i][0] for i in alice]) prin...
1374_E1. Reading Books (easy version)
Easy and hard versions are actually different problems, so read statements of both problems completely and carefully. Summer vacation has started so Alice and Bob want to play and joy, but... Their mom doesn't think so. She says that they have to read some amount of books before all entertainments. Alice and Bob will ...
{ "input": [ "8 4\n7 1 1\n2 1 1\n4 0 1\n8 1 1\n1 0 1\n1 1 1\n1 0 1\n3 0 0\n", "5 2\n6 0 0\n9 0 0\n1 0 1\n2 1 1\n5 1 0\n", "5 3\n3 0 0\n2 1 0\n3 1 0\n5 0 1\n3 0 1\n" ], "output": [ "18\n", "8\n", "-1\n" ] }
{ "input": [ "2 1\n7 1 1\n2 1 1\n", "5 1\n2 1 0\n2 0 1\n1 0 1\n1 1 0\n1 0 1\n", "6 2\n6 0 0\n11 1 0\n9 0 1\n21 1 1\n10 1 0\n8 0 1\n", "3 1\n3 0 1\n3 1 0\n3 0 0\n", "6 3\n7 1 1\n8 0 0\n9 1 1\n6 1 0\n10 1 1\n5 0 0\n", "8 4 3\n1 1 1\n3 1 1\n12 1 1\n12 1 1\n4 0 0\n4 0 0\n5 1 0\n5 0 1\n", "6 3 ...
IN-CORRECT
python2
#!/usr/bin/env python from __future__ import division, print_function import os import sys from io import BytesIO, IOBase if sys.version_info[0] < 3: from __builtin__ import xrange as range from future_builtins import ascii, filter, hex, map, oct, zip def main(): n, k = map(int, input().split()) a_...
1374_E1. Reading Books (easy version)
Easy and hard versions are actually different problems, so read statements of both problems completely and carefully. Summer vacation has started so Alice and Bob want to play and joy, but... Their mom doesn't think so. She says that they have to read some amount of books before all entertainments. Alice and Bob will ...
{ "input": [ "8 4\n7 1 1\n2 1 1\n4 0 1\n8 1 1\n1 0 1\n1 1 1\n1 0 1\n3 0 0\n", "5 2\n6 0 0\n9 0 0\n1 0 1\n2 1 1\n5 1 0\n", "5 3\n3 0 0\n2 1 0\n3 1 0\n5 0 1\n3 0 1\n" ], "output": [ "18\n", "8\n", "-1\n" ] }
{ "input": [ "2 1\n7 1 1\n2 1 1\n", "5 1\n2 1 0\n2 0 1\n1 0 1\n1 1 0\n1 0 1\n", "6 2\n6 0 0\n11 1 0\n9 0 1\n21 1 1\n10 1 0\n8 0 1\n", "3 1\n3 0 1\n3 1 0\n3 0 0\n", "6 3\n7 1 1\n8 0 0\n9 1 1\n6 1 0\n10 1 1\n5 0 0\n", "8 4 3\n1 1 1\n3 1 1\n12 1 1\n12 1 1\n4 0 0\n4 0 0\n5 1 0\n5 0 1\n", "6 3 ...
IN-CORRECT
python3
n, k = [int(x) for x in input().split()] both = [] bob = [] alice = [] for i in range(n): t, a, b = [int(x) for x in input().split()] if(a==1 and b==1): both.append(t) elif(a==1): alice.append(t) elif(b==1): bob.append(t) both.sort() bob.sort() alice.sort() y = max(k-min(len(b...
1374_E1. Reading Books (easy version)
Easy and hard versions are actually different problems, so read statements of both problems completely and carefully. Summer vacation has started so Alice and Bob want to play and joy, but... Their mom doesn't think so. She says that they have to read some amount of books before all entertainments. Alice and Bob will ...
{ "input": [ "8 4\n7 1 1\n2 1 1\n4 0 1\n8 1 1\n1 0 1\n1 1 1\n1 0 1\n3 0 0\n", "5 2\n6 0 0\n9 0 0\n1 0 1\n2 1 1\n5 1 0\n", "5 3\n3 0 0\n2 1 0\n3 1 0\n5 0 1\n3 0 1\n" ], "output": [ "18\n", "8\n", "-1\n" ] }
{ "input": [ "2 1\n7 1 1\n2 1 1\n", "5 1\n2 1 0\n2 0 1\n1 0 1\n1 1 0\n1 0 1\n", "6 2\n6 0 0\n11 1 0\n9 0 1\n21 1 1\n10 1 0\n8 0 1\n", "3 1\n3 0 1\n3 1 0\n3 0 0\n", "6 3\n7 1 1\n8 0 0\n9 1 1\n6 1 0\n10 1 1\n5 0 0\n", "8 4 3\n1 1 1\n3 1 1\n12 1 1\n12 1 1\n4 0 0\n4 0 0\n5 1 0\n5 0 1\n", "6 3 ...
IN-CORRECT
java
import java.io.*; import java.math.*; import java.util.*; import java.lang.*; // import java.text.DecimalFormat; // import java.text.DecimalFormatSymbols; // Warning: Printing unwanted or ill-formatted data to output will cause the test cases to fail public class TestClass { public static void main(String ...
1374_E1. Reading Books (easy version)
Easy and hard versions are actually different problems, so read statements of both problems completely and carefully. Summer vacation has started so Alice and Bob want to play and joy, but... Their mom doesn't think so. She says that they have to read some amount of books before all entertainments. Alice and Bob will ...
{ "input": [ "8 4\n7 1 1\n2 1 1\n4 0 1\n8 1 1\n1 0 1\n1 1 1\n1 0 1\n3 0 0\n", "5 2\n6 0 0\n9 0 0\n1 0 1\n2 1 1\n5 1 0\n", "5 3\n3 0 0\n2 1 0\n3 1 0\n5 0 1\n3 0 1\n" ], "output": [ "18\n", "8\n", "-1\n" ] }
{ "input": [ "2 1\n7 1 1\n2 1 1\n", "5 1\n2 1 0\n2 0 1\n1 0 1\n1 1 0\n1 0 1\n", "6 2\n6 0 0\n11 1 0\n9 0 1\n21 1 1\n10 1 0\n8 0 1\n", "3 1\n3 0 1\n3 1 0\n3 0 0\n", "6 3\n7 1 1\n8 0 0\n9 1 1\n6 1 0\n10 1 1\n5 0 0\n", "8 4 3\n1 1 1\n3 1 1\n12 1 1\n12 1 1\n4 0 0\n4 0 0\n5 1 0\n5 0 1\n", "6 3 ...
IN-CORRECT
cpp
#include <bits/stdc++.h> using namespace std; struct s { int t, a, b; int pos1 = -1, pos2 = -1; bool check = false; int m_val = 1; }; bool comp(s p, s q) { if (p.t < q.t) return true; return false; } bool comp1(s p, s q) { if (p.t < q.t) return true; else if (p.t == q.t) { if (p.m_val > q.m_val)...
1374_E1. Reading Books (easy version)
Easy and hard versions are actually different problems, so read statements of both problems completely and carefully. Summer vacation has started so Alice and Bob want to play and joy, but... Their mom doesn't think so. She says that they have to read some amount of books before all entertainments. Alice and Bob will ...
{ "input": [ "8 4\n7 1 1\n2 1 1\n4 0 1\n8 1 1\n1 0 1\n1 1 1\n1 0 1\n3 0 0\n", "5 2\n6 0 0\n9 0 0\n1 0 1\n2 1 1\n5 1 0\n", "5 3\n3 0 0\n2 1 0\n3 1 0\n5 0 1\n3 0 1\n" ], "output": [ "18\n", "8\n", "-1\n" ] }
{ "input": [ "2 1\n7 1 1\n2 1 1\n", "5 1\n2 1 0\n2 0 1\n1 0 1\n1 1 0\n1 0 1\n", "6 2\n6 0 0\n11 1 0\n9 0 1\n21 1 1\n10 1 0\n8 0 1\n", "3 1\n3 0 1\n3 1 0\n3 0 0\n", "6 3\n7 1 1\n8 0 0\n9 1 1\n6 1 0\n10 1 1\n5 0 0\n", "8 4 3\n1 1 1\n3 1 1\n12 1 1\n12 1 1\n4 0 0\n4 0 0\n5 1 0\n5 0 1\n", "6 3 ...
IN-CORRECT
python3
import sys n, k = [int(e) for e in input().split(' ')] books = list() books_map = dict() for i in range(n): t, a, b = [int(e) for e in input().split(' ')] books.append((t, a, b, i)) books_map[i] = (t, a, b) books = sorted(books, key = lambda x : x[0] * (1 if x[1] == 1 else 1e7)) alice_pay_time = 0 alice_l...
1374_E1. Reading Books (easy version)
Easy and hard versions are actually different problems, so read statements of both problems completely and carefully. Summer vacation has started so Alice and Bob want to play and joy, but... Their mom doesn't think so. She says that they have to read some amount of books before all entertainments. Alice and Bob will ...
{ "input": [ "8 4\n7 1 1\n2 1 1\n4 0 1\n8 1 1\n1 0 1\n1 1 1\n1 0 1\n3 0 0\n", "5 2\n6 0 0\n9 0 0\n1 0 1\n2 1 1\n5 1 0\n", "5 3\n3 0 0\n2 1 0\n3 1 0\n5 0 1\n3 0 1\n" ], "output": [ "18\n", "8\n", "-1\n" ] }
{ "input": [ "2 1\n7 1 1\n2 1 1\n", "5 1\n2 1 0\n2 0 1\n1 0 1\n1 1 0\n1 0 1\n", "6 2\n6 0 0\n11 1 0\n9 0 1\n21 1 1\n10 1 0\n8 0 1\n", "3 1\n3 0 1\n3 1 0\n3 0 0\n", "6 3\n7 1 1\n8 0 0\n9 1 1\n6 1 0\n10 1 1\n5 0 0\n", "8 4 3\n1 1 1\n3 1 1\n12 1 1\n12 1 1\n4 0 0\n4 0 0\n5 1 0\n5 0 1\n", "6 3 ...
IN-CORRECT
cpp
#include <bits/stdc++.h> using namespace std; const int maxn = 2e5 + 7; int n, m, k, tot, tmp[4]; struct node { int no, t; bool operator<(const node &rhs) const { return t > rhs.t; } }; priority_queue<node> book[4], ans[4]; void switchD(int v) { node x = book[v].top(); tot += x.t, x.t = -x.t; ans[v].push(x), ...
1374_E1. Reading Books (easy version)
Easy and hard versions are actually different problems, so read statements of both problems completely and carefully. Summer vacation has started so Alice and Bob want to play and joy, but... Their mom doesn't think so. She says that they have to read some amount of books before all entertainments. Alice and Bob will ...
{ "input": [ "8 4\n7 1 1\n2 1 1\n4 0 1\n8 1 1\n1 0 1\n1 1 1\n1 0 1\n3 0 0\n", "5 2\n6 0 0\n9 0 0\n1 0 1\n2 1 1\n5 1 0\n", "5 3\n3 0 0\n2 1 0\n3 1 0\n5 0 1\n3 0 1\n" ], "output": [ "18\n", "8\n", "-1\n" ] }
{ "input": [ "2 1\n7 1 1\n2 1 1\n", "5 1\n2 1 0\n2 0 1\n1 0 1\n1 1 0\n1 0 1\n", "6 2\n6 0 0\n11 1 0\n9 0 1\n21 1 1\n10 1 0\n8 0 1\n", "3 1\n3 0 1\n3 1 0\n3 0 0\n", "6 3\n7 1 1\n8 0 0\n9 1 1\n6 1 0\n10 1 1\n5 0 0\n", "8 4 3\n1 1 1\n3 1 1\n12 1 1\n12 1 1\n4 0 0\n4 0 0\n5 1 0\n5 0 1\n", "6 3 ...
IN-CORRECT
java
import java.io.IOException; import java.util.ArrayList; import java.util.Arrays; import java.util.Collections; import java.util.HashSet; import java.util.Scanner; public class D { static int mod = (int) 1e9 + 7; static ArrayList<Integer> gr[]; static int ar[]; static Scanner sc = new Scanner(System.in); static S...
1374_E1. Reading Books (easy version)
Easy and hard versions are actually different problems, so read statements of both problems completely and carefully. Summer vacation has started so Alice and Bob want to play and joy, but... Their mom doesn't think so. She says that they have to read some amount of books before all entertainments. Alice and Bob will ...
{ "input": [ "8 4\n7 1 1\n2 1 1\n4 0 1\n8 1 1\n1 0 1\n1 1 1\n1 0 1\n3 0 0\n", "5 2\n6 0 0\n9 0 0\n1 0 1\n2 1 1\n5 1 0\n", "5 3\n3 0 0\n2 1 0\n3 1 0\n5 0 1\n3 0 1\n" ], "output": [ "18\n", "8\n", "-1\n" ] }
{ "input": [ "2 1\n7 1 1\n2 1 1\n", "5 1\n2 1 0\n2 0 1\n1 0 1\n1 1 0\n1 0 1\n", "6 2\n6 0 0\n11 1 0\n9 0 1\n21 1 1\n10 1 0\n8 0 1\n", "3 1\n3 0 1\n3 1 0\n3 0 0\n", "6 3\n7 1 1\n8 0 0\n9 1 1\n6 1 0\n10 1 1\n5 0 0\n", "8 4 3\n1 1 1\n3 1 1\n12 1 1\n12 1 1\n4 0 0\n4 0 0\n5 1 0\n5 0 1\n", "6 3 ...
IN-CORRECT
python3
import sys # from collections import defaultdict # t=1 # t=int(input()) def fun(x): # print(x) return x[0] n,m,k=list(map(int,sys.stdin.readline().strip().split())) xx=[] a=[] b=[] c=[] d=[] for i in range(n): # n=int(input()) x=list(map(int,sys.stdin.readline().strip().split())) # a,b,c,d=list(...
1374_E1. Reading Books (easy version)
Easy and hard versions are actually different problems, so read statements of both problems completely and carefully. Summer vacation has started so Alice and Bob want to play and joy, but... Their mom doesn't think so. She says that they have to read some amount of books before all entertainments. Alice and Bob will ...
{ "input": [ "8 4\n7 1 1\n2 1 1\n4 0 1\n8 1 1\n1 0 1\n1 1 1\n1 0 1\n3 0 0\n", "5 2\n6 0 0\n9 0 0\n1 0 1\n2 1 1\n5 1 0\n", "5 3\n3 0 0\n2 1 0\n3 1 0\n5 0 1\n3 0 1\n" ], "output": [ "18\n", "8\n", "-1\n" ] }
{ "input": [ "2 1\n7 1 1\n2 1 1\n", "5 1\n2 1 0\n2 0 1\n1 0 1\n1 1 0\n1 0 1\n", "6 2\n6 0 0\n11 1 0\n9 0 1\n21 1 1\n10 1 0\n8 0 1\n", "3 1\n3 0 1\n3 1 0\n3 0 0\n", "6 3\n7 1 1\n8 0 0\n9 1 1\n6 1 0\n10 1 1\n5 0 0\n", "8 4 3\n1 1 1\n3 1 1\n12 1 1\n12 1 1\n4 0 0\n4 0 0\n5 1 0\n5 0 1\n", "6 3 ...
IN-CORRECT
python3
arr=[int(x) for x in input().split()] size=arr[0] max_books=arr[1] constraint=arr[2] book_dict={'11':[],'10':[],'01':[],'00':[]} for i in range(size): book=input().split() if book[1]+book[2]=='00': book_dict['00'].append((str(i+1),int(book[0]))) elif book[1]+book[2]=='10': book_dict['10'].ap...
1374_E1. Reading Books (easy version)
Easy and hard versions are actually different problems, so read statements of both problems completely and carefully. Summer vacation has started so Alice and Bob want to play and joy, but... Their mom doesn't think so. She says that they have to read some amount of books before all entertainments. Alice and Bob will ...
{ "input": [ "8 4\n7 1 1\n2 1 1\n4 0 1\n8 1 1\n1 0 1\n1 1 1\n1 0 1\n3 0 0\n", "5 2\n6 0 0\n9 0 0\n1 0 1\n2 1 1\n5 1 0\n", "5 3\n3 0 0\n2 1 0\n3 1 0\n5 0 1\n3 0 1\n" ], "output": [ "18\n", "8\n", "-1\n" ] }
{ "input": [ "2 1\n7 1 1\n2 1 1\n", "5 1\n2 1 0\n2 0 1\n1 0 1\n1 1 0\n1 0 1\n", "6 2\n6 0 0\n11 1 0\n9 0 1\n21 1 1\n10 1 0\n8 0 1\n", "3 1\n3 0 1\n3 1 0\n3 0 0\n", "6 3\n7 1 1\n8 0 0\n9 1 1\n6 1 0\n10 1 1\n5 0 0\n", "8 4 3\n1 1 1\n3 1 1\n12 1 1\n12 1 1\n4 0 0\n4 0 0\n5 1 0\n5 0 1\n", "6 3 ...
IN-CORRECT
python2
import atexit, io, sys # A stream implementation using an in-memory bytes # buffer. It inherits BufferedIOBase. buffer = io.BytesIO() sys.stdout = buffer # print via here @atexit.register def write(): sys.__stdout__.write(buffer.getvalue()) for _ in range(1): n,m,k=map(int,raw_input().split()) ...
1374_E1. Reading Books (easy version)
Easy and hard versions are actually different problems, so read statements of both problems completely and carefully. Summer vacation has started so Alice and Bob want to play and joy, but... Their mom doesn't think so. She says that they have to read some amount of books before all entertainments. Alice and Bob will ...
{ "input": [ "8 4\n7 1 1\n2 1 1\n4 0 1\n8 1 1\n1 0 1\n1 1 1\n1 0 1\n3 0 0\n", "5 2\n6 0 0\n9 0 0\n1 0 1\n2 1 1\n5 1 0\n", "5 3\n3 0 0\n2 1 0\n3 1 0\n5 0 1\n3 0 1\n" ], "output": [ "18\n", "8\n", "-1\n" ] }
{ "input": [ "2 1\n7 1 1\n2 1 1\n", "5 1\n2 1 0\n2 0 1\n1 0 1\n1 1 0\n1 0 1\n", "6 2\n6 0 0\n11 1 0\n9 0 1\n21 1 1\n10 1 0\n8 0 1\n", "3 1\n3 0 1\n3 1 0\n3 0 0\n", "6 3\n7 1 1\n8 0 0\n9 1 1\n6 1 0\n10 1 1\n5 0 0\n", "8 4 3\n1 1 1\n3 1 1\n12 1 1\n12 1 1\n4 0 0\n4 0 0\n5 1 0\n5 0 1\n", "6 3 ...
IN-CORRECT
cpp
#include "bits/stdc++.h" using namespace std; #pragma GCC target ("avx2") #pragma GCC optimization ("O3") #pragma GCC optimization ("unroll-loops") #define lld long long int int main() { // your code goes here ios_base::sync_with_stdio(false); cin.tie(NULL); int t; //cin>>t; t=1; while(t--) ...
1374_E1. Reading Books (easy version)
Easy and hard versions are actually different problems, so read statements of both problems completely and carefully. Summer vacation has started so Alice and Bob want to play and joy, but... Their mom doesn't think so. She says that they have to read some amount of books before all entertainments. Alice and Bob will ...
{ "input": [ "8 4\n7 1 1\n2 1 1\n4 0 1\n8 1 1\n1 0 1\n1 1 1\n1 0 1\n3 0 0\n", "5 2\n6 0 0\n9 0 0\n1 0 1\n2 1 1\n5 1 0\n", "5 3\n3 0 0\n2 1 0\n3 1 0\n5 0 1\n3 0 1\n" ], "output": [ "18\n", "8\n", "-1\n" ] }
{ "input": [ "2 1\n7 1 1\n2 1 1\n", "5 1\n2 1 0\n2 0 1\n1 0 1\n1 1 0\n1 0 1\n", "6 2\n6 0 0\n11 1 0\n9 0 1\n21 1 1\n10 1 0\n8 0 1\n", "3 1\n3 0 1\n3 1 0\n3 0 0\n", "6 3\n7 1 1\n8 0 0\n9 1 1\n6 1 0\n10 1 1\n5 0 0\n", "8 4 3\n1 1 1\n3 1 1\n12 1 1\n12 1 1\n4 0 0\n4 0 0\n5 1 0\n5 0 1\n", "6 3 ...
IN-CORRECT
python3
n,k=map(int,input().split()) L1=[] L2=[] L3=[] s=0 for i in range(n): t,a,b=map(int,input().split()) if a==1 and b==1: L1.append(t) elif a==1 and b==0: L2.append(t) elif a==0 and b==1: L3.append(t) L1.sort() L2.sort() L3.sort() if k==len(L1): print(sum(L1)) elif k<len(L1): print(sum(...
1374_E1. Reading Books (easy version)
Easy and hard versions are actually different problems, so read statements of both problems completely and carefully. Summer vacation has started so Alice and Bob want to play and joy, but... Their mom doesn't think so. She says that they have to read some amount of books before all entertainments. Alice and Bob will ...
{ "input": [ "8 4\n7 1 1\n2 1 1\n4 0 1\n8 1 1\n1 0 1\n1 1 1\n1 0 1\n3 0 0\n", "5 2\n6 0 0\n9 0 0\n1 0 1\n2 1 1\n5 1 0\n", "5 3\n3 0 0\n2 1 0\n3 1 0\n5 0 1\n3 0 1\n" ], "output": [ "18\n", "8\n", "-1\n" ] }
{ "input": [ "2 1\n7 1 1\n2 1 1\n", "5 1\n2 1 0\n2 0 1\n1 0 1\n1 1 0\n1 0 1\n", "6 2\n6 0 0\n11 1 0\n9 0 1\n21 1 1\n10 1 0\n8 0 1\n", "3 1\n3 0 1\n3 1 0\n3 0 0\n", "6 3\n7 1 1\n8 0 0\n9 1 1\n6 1 0\n10 1 1\n5 0 0\n", "8 4 3\n1 1 1\n3 1 1\n12 1 1\n12 1 1\n4 0 0\n4 0 0\n5 1 0\n5 0 1\n", "6 3 ...
IN-CORRECT
cpp
#include <bits/stdc++.h> using namespace std; vector<pair<long long, long long>> segment, segment2, segment3; long long n, m, k, t, need, ans = 1000000000000000000; vector<pair<long long, long long>> vv[4]; vector<long long> v[3]; void add(long long curr) { long long val = curr - t + 1; while (curr) { segment[c...
1374_E1. Reading Books (easy version)
Easy and hard versions are actually different problems, so read statements of both problems completely and carefully. Summer vacation has started so Alice and Bob want to play and joy, but... Their mom doesn't think so. She says that they have to read some amount of books before all entertainments. Alice and Bob will ...
{ "input": [ "8 4\n7 1 1\n2 1 1\n4 0 1\n8 1 1\n1 0 1\n1 1 1\n1 0 1\n3 0 0\n", "5 2\n6 0 0\n9 0 0\n1 0 1\n2 1 1\n5 1 0\n", "5 3\n3 0 0\n2 1 0\n3 1 0\n5 0 1\n3 0 1\n" ], "output": [ "18\n", "8\n", "-1\n" ] }
{ "input": [ "2 1\n7 1 1\n2 1 1\n", "5 1\n2 1 0\n2 0 1\n1 0 1\n1 1 0\n1 0 1\n", "6 2\n6 0 0\n11 1 0\n9 0 1\n21 1 1\n10 1 0\n8 0 1\n", "3 1\n3 0 1\n3 1 0\n3 0 0\n", "6 3\n7 1 1\n8 0 0\n9 1 1\n6 1 0\n10 1 1\n5 0 0\n", "8 4 3\n1 1 1\n3 1 1\n12 1 1\n12 1 1\n4 0 0\n4 0 0\n5 1 0\n5 0 1\n", "6 3 ...
IN-CORRECT
python3
n,k=map(int,input().split()) time=[] a=[] b=[] count_a=0 count_b=0 for i in range(n): t,a1,b1=map(int,input().split()) time.append(t) a.append(a1) b.append(b1) if a1==1: count_a+=1 if b1==1: count_b+=1 #print(count_a,count_b) if count_a<k or count_b<k: print(-1) ...
1374_E1. Reading Books (easy version)
Easy and hard versions are actually different problems, so read statements of both problems completely and carefully. Summer vacation has started so Alice and Bob want to play and joy, but... Their mom doesn't think so. She says that they have to read some amount of books before all entertainments. Alice and Bob will ...
{ "input": [ "8 4\n7 1 1\n2 1 1\n4 0 1\n8 1 1\n1 0 1\n1 1 1\n1 0 1\n3 0 0\n", "5 2\n6 0 0\n9 0 0\n1 0 1\n2 1 1\n5 1 0\n", "5 3\n3 0 0\n2 1 0\n3 1 0\n5 0 1\n3 0 1\n" ], "output": [ "18\n", "8\n", "-1\n" ] }
{ "input": [ "2 1\n7 1 1\n2 1 1\n", "5 1\n2 1 0\n2 0 1\n1 0 1\n1 1 0\n1 0 1\n", "6 2\n6 0 0\n11 1 0\n9 0 1\n21 1 1\n10 1 0\n8 0 1\n", "3 1\n3 0 1\n3 1 0\n3 0 0\n", "6 3\n7 1 1\n8 0 0\n9 1 1\n6 1 0\n10 1 1\n5 0 0\n", "8 4 3\n1 1 1\n3 1 1\n12 1 1\n12 1 1\n4 0 0\n4 0 0\n5 1 0\n5 0 1\n", "6 3 ...
IN-CORRECT
java
import java.io.*; import java.util.*; public class E1 implements Comparable<E1>{ static class FastReader { BufferedReader br; StringTokenizer st; public FastReader() { br = new BufferedReader(new InputStreamReader(System.in)); }...
1374_E1. Reading Books (easy version)
Easy and hard versions are actually different problems, so read statements of both problems completely and carefully. Summer vacation has started so Alice and Bob want to play and joy, but... Their mom doesn't think so. She says that they have to read some amount of books before all entertainments. Alice and Bob will ...
{ "input": [ "8 4\n7 1 1\n2 1 1\n4 0 1\n8 1 1\n1 0 1\n1 1 1\n1 0 1\n3 0 0\n", "5 2\n6 0 0\n9 0 0\n1 0 1\n2 1 1\n5 1 0\n", "5 3\n3 0 0\n2 1 0\n3 1 0\n5 0 1\n3 0 1\n" ], "output": [ "18\n", "8\n", "-1\n" ] }
{ "input": [ "2 1\n7 1 1\n2 1 1\n", "5 1\n2 1 0\n2 0 1\n1 0 1\n1 1 0\n1 0 1\n", "6 2\n6 0 0\n11 1 0\n9 0 1\n21 1 1\n10 1 0\n8 0 1\n", "3 1\n3 0 1\n3 1 0\n3 0 0\n", "6 3\n7 1 1\n8 0 0\n9 1 1\n6 1 0\n10 1 1\n5 0 0\n", "8 4 3\n1 1 1\n3 1 1\n12 1 1\n12 1 1\n4 0 0\n4 0 0\n5 1 0\n5 0 1\n", "6 3 ...
IN-CORRECT
python3
""" Code of Ayush Tiwari Codeforces: servermonk Codechef: ayush572000 """ import sys input = sys.stdin.buffer.readline def solution(): a=[] b=[] c=[] n,k=map(int,input().split()) for i in range(n): t,x,y=map(int,input().split()) if x==1 and y==1: c.append(t) eli...
1374_E1. Reading Books (easy version)
Easy and hard versions are actually different problems, so read statements of both problems completely and carefully. Summer vacation has started so Alice and Bob want to play and joy, but... Their mom doesn't think so. She says that they have to read some amount of books before all entertainments. Alice and Bob will ...
{ "input": [ "8 4\n7 1 1\n2 1 1\n4 0 1\n8 1 1\n1 0 1\n1 1 1\n1 0 1\n3 0 0\n", "5 2\n6 0 0\n9 0 0\n1 0 1\n2 1 1\n5 1 0\n", "5 3\n3 0 0\n2 1 0\n3 1 0\n5 0 1\n3 0 1\n" ], "output": [ "18\n", "8\n", "-1\n" ] }
{ "input": [ "2 1\n7 1 1\n2 1 1\n", "5 1\n2 1 0\n2 0 1\n1 0 1\n1 1 0\n1 0 1\n", "6 2\n6 0 0\n11 1 0\n9 0 1\n21 1 1\n10 1 0\n8 0 1\n", "3 1\n3 0 1\n3 1 0\n3 0 0\n", "6 3\n7 1 1\n8 0 0\n9 1 1\n6 1 0\n10 1 1\n5 0 0\n", "8 4 3\n1 1 1\n3 1 1\n12 1 1\n12 1 1\n4 0 0\n4 0 0\n5 1 0\n5 0 1\n", "6 3 ...
IN-CORRECT
java
import java.io.*; import java.util.*; public class E1{ static class FastReader { BufferedReader br; StringTokenizer st; public FastReader() { br = new BufferedReader(new InputStreamReader(System.in)); } String next(...
1374_E1. Reading Books (easy version)
Easy and hard versions are actually different problems, so read statements of both problems completely and carefully. Summer vacation has started so Alice and Bob want to play and joy, but... Their mom doesn't think so. She says that they have to read some amount of books before all entertainments. Alice and Bob will ...
{ "input": [ "8 4\n7 1 1\n2 1 1\n4 0 1\n8 1 1\n1 0 1\n1 1 1\n1 0 1\n3 0 0\n", "5 2\n6 0 0\n9 0 0\n1 0 1\n2 1 1\n5 1 0\n", "5 3\n3 0 0\n2 1 0\n3 1 0\n5 0 1\n3 0 1\n" ], "output": [ "18\n", "8\n", "-1\n" ] }
{ "input": [ "2 1\n7 1 1\n2 1 1\n", "5 1\n2 1 0\n2 0 1\n1 0 1\n1 1 0\n1 0 1\n", "6 2\n6 0 0\n11 1 0\n9 0 1\n21 1 1\n10 1 0\n8 0 1\n", "3 1\n3 0 1\n3 1 0\n3 0 0\n", "6 3\n7 1 1\n8 0 0\n9 1 1\n6 1 0\n10 1 1\n5 0 0\n", "8 4 3\n1 1 1\n3 1 1\n12 1 1\n12 1 1\n4 0 0\n4 0 0\n5 1 0\n5 0 1\n", "6 3 ...
IN-CORRECT
java
import java.io.OutputStream; import java.io.IOException; import java.io.InputStream; import java.io.PrintWriter; import java.util.ArrayList; import java.util.Arrays; import java.util.Collections; import java.util.StringTokenizer; import java.io.BufferedReader; import java.io.InputStreamReader; import static java.lang....
1374_E1. Reading Books (easy version)
Easy and hard versions are actually different problems, so read statements of both problems completely and carefully. Summer vacation has started so Alice and Bob want to play and joy, but... Their mom doesn't think so. She says that they have to read some amount of books before all entertainments. Alice and Bob will ...
{ "input": [ "8 4\n7 1 1\n2 1 1\n4 0 1\n8 1 1\n1 0 1\n1 1 1\n1 0 1\n3 0 0\n", "5 2\n6 0 0\n9 0 0\n1 0 1\n2 1 1\n5 1 0\n", "5 3\n3 0 0\n2 1 0\n3 1 0\n5 0 1\n3 0 1\n" ], "output": [ "18\n", "8\n", "-1\n" ] }
{ "input": [ "2 1\n7 1 1\n2 1 1\n", "5 1\n2 1 0\n2 0 1\n1 0 1\n1 1 0\n1 0 1\n", "6 2\n6 0 0\n11 1 0\n9 0 1\n21 1 1\n10 1 0\n8 0 1\n", "3 1\n3 0 1\n3 1 0\n3 0 0\n", "6 3\n7 1 1\n8 0 0\n9 1 1\n6 1 0\n10 1 1\n5 0 0\n", "8 4 3\n1 1 1\n3 1 1\n12 1 1\n12 1 1\n4 0 0\n4 0 0\n5 1 0\n5 0 1\n", "6 3 ...
IN-CORRECT
python3
# Secdra @2020 from functools import cmp_to_key class Node: def __init__(self, t, a, b): self.t = t self.a = a self.b = b def __lt__(self, other): if (self.a + self.b) == (other.a + other.b): return self.t < other.t else: return (self.a + self.b...
1374_E1. Reading Books (easy version)
Easy and hard versions are actually different problems, so read statements of both problems completely and carefully. Summer vacation has started so Alice and Bob want to play and joy, but... Their mom doesn't think so. She says that they have to read some amount of books before all entertainments. Alice and Bob will ...
{ "input": [ "8 4\n7 1 1\n2 1 1\n4 0 1\n8 1 1\n1 0 1\n1 1 1\n1 0 1\n3 0 0\n", "5 2\n6 0 0\n9 0 0\n1 0 1\n2 1 1\n5 1 0\n", "5 3\n3 0 0\n2 1 0\n3 1 0\n5 0 1\n3 0 1\n" ], "output": [ "18\n", "8\n", "-1\n" ] }
{ "input": [ "2 1\n7 1 1\n2 1 1\n", "5 1\n2 1 0\n2 0 1\n1 0 1\n1 1 0\n1 0 1\n", "6 2\n6 0 0\n11 1 0\n9 0 1\n21 1 1\n10 1 0\n8 0 1\n", "3 1\n3 0 1\n3 1 0\n3 0 0\n", "6 3\n7 1 1\n8 0 0\n9 1 1\n6 1 0\n10 1 1\n5 0 0\n", "8 4 3\n1 1 1\n3 1 1\n12 1 1\n12 1 1\n4 0 0\n4 0 0\n5 1 0\n5 0 1\n", "6 3 ...
IN-CORRECT
java
import java.util.Arrays; import java.util.Comparator; import java.util.Scanner; public class E { public static void main(String[] args) { Scanner scanner = new Scanner(System.in); int n = scanner.nextInt(); int k = scanner.nextInt(); int[][] ar = new int[n][2]; for(int i=0...
1374_E1. Reading Books (easy version)
Easy and hard versions are actually different problems, so read statements of both problems completely and carefully. Summer vacation has started so Alice and Bob want to play and joy, but... Their mom doesn't think so. She says that they have to read some amount of books before all entertainments. Alice and Bob will ...
{ "input": [ "8 4\n7 1 1\n2 1 1\n4 0 1\n8 1 1\n1 0 1\n1 1 1\n1 0 1\n3 0 0\n", "5 2\n6 0 0\n9 0 0\n1 0 1\n2 1 1\n5 1 0\n", "5 3\n3 0 0\n2 1 0\n3 1 0\n5 0 1\n3 0 1\n" ], "output": [ "18\n", "8\n", "-1\n" ] }
{ "input": [ "2 1\n7 1 1\n2 1 1\n", "5 1\n2 1 0\n2 0 1\n1 0 1\n1 1 0\n1 0 1\n", "6 2\n6 0 0\n11 1 0\n9 0 1\n21 1 1\n10 1 0\n8 0 1\n", "3 1\n3 0 1\n3 1 0\n3 0 0\n", "6 3\n7 1 1\n8 0 0\n9 1 1\n6 1 0\n10 1 1\n5 0 0\n", "8 4 3\n1 1 1\n3 1 1\n12 1 1\n12 1 1\n4 0 0\n4 0 0\n5 1 0\n5 0 1\n", "6 3 ...
IN-CORRECT
python3
# https://codeforces.com/contest/1374/problem/E1 def min_time(tot_books, books_like, read_time, a_time, b_time): time = [] temp_a = [] temp_b = [] if min(sum(a_time), sum(b_time)) >= books_like: for x in range(tot_books): if a_time[x] == b_time[x] == 1: time.append(r...
1374_E1. Reading Books (easy version)
Easy and hard versions are actually different problems, so read statements of both problems completely and carefully. Summer vacation has started so Alice and Bob want to play and joy, but... Their mom doesn't think so. She says that they have to read some amount of books before all entertainments. Alice and Bob will ...
{ "input": [ "8 4\n7 1 1\n2 1 1\n4 0 1\n8 1 1\n1 0 1\n1 1 1\n1 0 1\n3 0 0\n", "5 2\n6 0 0\n9 0 0\n1 0 1\n2 1 1\n5 1 0\n", "5 3\n3 0 0\n2 1 0\n3 1 0\n5 0 1\n3 0 1\n" ], "output": [ "18\n", "8\n", "-1\n" ] }
{ "input": [ "2 1\n7 1 1\n2 1 1\n", "5 1\n2 1 0\n2 0 1\n1 0 1\n1 1 0\n1 0 1\n", "6 2\n6 0 0\n11 1 0\n9 0 1\n21 1 1\n10 1 0\n8 0 1\n", "3 1\n3 0 1\n3 1 0\n3 0 0\n", "6 3\n7 1 1\n8 0 0\n9 1 1\n6 1 0\n10 1 1\n5 0 0\n", "8 4 3\n1 1 1\n3 1 1\n12 1 1\n12 1 1\n4 0 0\n4 0 0\n5 1 0\n5 0 1\n", "6 3 ...
IN-CORRECT
java
import java.util.*; import java.io.*; import java.math.*; public class Main { private static FastReader fr = new FastReader(); private static Helper helper = new Helper(); private static StringBuilder result = new StringBuilder(); public static void main(String[] args) { Task solver = new Task(); solver.so...
1374_E1. Reading Books (easy version)
Easy and hard versions are actually different problems, so read statements of both problems completely and carefully. Summer vacation has started so Alice and Bob want to play and joy, but... Their mom doesn't think so. She says that they have to read some amount of books before all entertainments. Alice and Bob will ...
{ "input": [ "8 4\n7 1 1\n2 1 1\n4 0 1\n8 1 1\n1 0 1\n1 1 1\n1 0 1\n3 0 0\n", "5 2\n6 0 0\n9 0 0\n1 0 1\n2 1 1\n5 1 0\n", "5 3\n3 0 0\n2 1 0\n3 1 0\n5 0 1\n3 0 1\n" ], "output": [ "18\n", "8\n", "-1\n" ] }
{ "input": [ "2 1\n7 1 1\n2 1 1\n", "5 1\n2 1 0\n2 0 1\n1 0 1\n1 1 0\n1 0 1\n", "6 2\n6 0 0\n11 1 0\n9 0 1\n21 1 1\n10 1 0\n8 0 1\n", "3 1\n3 0 1\n3 1 0\n3 0 0\n", "6 3\n7 1 1\n8 0 0\n9 1 1\n6 1 0\n10 1 1\n5 0 0\n", "8 4 3\n1 1 1\n3 1 1\n12 1 1\n12 1 1\n4 0 0\n4 0 0\n5 1 0\n5 0 1\n", "6 3 ...
IN-CORRECT
cpp
#include <bits/stdc++.h> using namespace std; const int INF = 0x7fffffff; int main() { int n, m, k; while (cin >> n >> m >> k) { vector<pair<int, int>> v0, v1, v2, v3; for (int i = 0; i < n; i++) { int t, a, b, x = 0; cin >> t >> a >> b; if (a & b) { v3.push_back(make_pair(t, i + 1...
1374_E1. Reading Books (easy version)
Easy and hard versions are actually different problems, so read statements of both problems completely and carefully. Summer vacation has started so Alice and Bob want to play and joy, but... Their mom doesn't think so. She says that they have to read some amount of books before all entertainments. Alice and Bob will ...
{ "input": [ "8 4\n7 1 1\n2 1 1\n4 0 1\n8 1 1\n1 0 1\n1 1 1\n1 0 1\n3 0 0\n", "5 2\n6 0 0\n9 0 0\n1 0 1\n2 1 1\n5 1 0\n", "5 3\n3 0 0\n2 1 0\n3 1 0\n5 0 1\n3 0 1\n" ], "output": [ "18\n", "8\n", "-1\n" ] }
{ "input": [ "2 1\n7 1 1\n2 1 1\n", "5 1\n2 1 0\n2 0 1\n1 0 1\n1 1 0\n1 0 1\n", "6 2\n6 0 0\n11 1 0\n9 0 1\n21 1 1\n10 1 0\n8 0 1\n", "3 1\n3 0 1\n3 1 0\n3 0 0\n", "6 3\n7 1 1\n8 0 0\n9 1 1\n6 1 0\n10 1 1\n5 0 0\n", "8 4 3\n1 1 1\n3 1 1\n12 1 1\n12 1 1\n4 0 0\n4 0 0\n5 1 0\n5 0 1\n", "6 3 ...
IN-CORRECT
python3
import sys from collections import defaultdict as dd from collections import deque from fractions import Fraction as f from copy import * from bisect import * from heapq import * from math import * from itertools import permutations def eprint(*args): print(*args, file=sys.stderr) zz=1 #sys.setrecursionlimit(...
1374_E1. Reading Books (easy version)
Easy and hard versions are actually different problems, so read statements of both problems completely and carefully. Summer vacation has started so Alice and Bob want to play and joy, but... Their mom doesn't think so. She says that they have to read some amount of books before all entertainments. Alice and Bob will ...
{ "input": [ "8 4\n7 1 1\n2 1 1\n4 0 1\n8 1 1\n1 0 1\n1 1 1\n1 0 1\n3 0 0\n", "5 2\n6 0 0\n9 0 0\n1 0 1\n2 1 1\n5 1 0\n", "5 3\n3 0 0\n2 1 0\n3 1 0\n5 0 1\n3 0 1\n" ], "output": [ "18\n", "8\n", "-1\n" ] }
{ "input": [ "2 1\n7 1 1\n2 1 1\n", "5 1\n2 1 0\n2 0 1\n1 0 1\n1 1 0\n1 0 1\n", "6 2\n6 0 0\n11 1 0\n9 0 1\n21 1 1\n10 1 0\n8 0 1\n", "3 1\n3 0 1\n3 1 0\n3 0 0\n", "6 3\n7 1 1\n8 0 0\n9 1 1\n6 1 0\n10 1 1\n5 0 0\n", "8 4 3\n1 1 1\n3 1 1\n12 1 1\n12 1 1\n4 0 0\n4 0 0\n5 1 0\n5 0 1\n", "6 3 ...
IN-CORRECT
java
import java.util.*; public class ReadingBooksEasy { public static void main(String[] args) { Scanner sc = new Scanner(System.in); StringBuilder sb = new StringBuilder(); int n = sc.nextInt(); int m = sc.nextInt(); int k = sc.nextInt(); LinkedList<Integer> both = new...
1374_E1. Reading Books (easy version)
Easy and hard versions are actually different problems, so read statements of both problems completely and carefully. Summer vacation has started so Alice and Bob want to play and joy, but... Their mom doesn't think so. She says that they have to read some amount of books before all entertainments. Alice and Bob will ...
{ "input": [ "8 4\n7 1 1\n2 1 1\n4 0 1\n8 1 1\n1 0 1\n1 1 1\n1 0 1\n3 0 0\n", "5 2\n6 0 0\n9 0 0\n1 0 1\n2 1 1\n5 1 0\n", "5 3\n3 0 0\n2 1 0\n3 1 0\n5 0 1\n3 0 1\n" ], "output": [ "18\n", "8\n", "-1\n" ] }
{ "input": [ "2 1\n7 1 1\n2 1 1\n", "5 1\n2 1 0\n2 0 1\n1 0 1\n1 1 0\n1 0 1\n", "6 2\n6 0 0\n11 1 0\n9 0 1\n21 1 1\n10 1 0\n8 0 1\n", "3 1\n3 0 1\n3 1 0\n3 0 0\n", "6 3\n7 1 1\n8 0 0\n9 1 1\n6 1 0\n10 1 1\n5 0 0\n", "8 4 3\n1 1 1\n3 1 1\n12 1 1\n12 1 1\n4 0 0\n4 0 0\n5 1 0\n5 0 1\n", "6 3 ...
IN-CORRECT
cpp
#include <bits/stdc++.h> using namespace std; int n, k; vector<pair<int, pair<int, int> > > a; void init() { ios_base::sync_with_stdio(false); cin.tie(NULL); cout.tie(NULL); } void sol() { cin >> n >> k; priority_queue<int, vector<int>, greater<int> > alicecan; priority_queue<int, vector<int>, greater<int> ...
1374_E1. Reading Books (easy version)
Easy and hard versions are actually different problems, so read statements of both problems completely and carefully. Summer vacation has started so Alice and Bob want to play and joy, but... Their mom doesn't think so. She says that they have to read some amount of books before all entertainments. Alice and Bob will ...
{ "input": [ "8 4\n7 1 1\n2 1 1\n4 0 1\n8 1 1\n1 0 1\n1 1 1\n1 0 1\n3 0 0\n", "5 2\n6 0 0\n9 0 0\n1 0 1\n2 1 1\n5 1 0\n", "5 3\n3 0 0\n2 1 0\n3 1 0\n5 0 1\n3 0 1\n" ], "output": [ "18\n", "8\n", "-1\n" ] }
{ "input": [ "2 1\n7 1 1\n2 1 1\n", "5 1\n2 1 0\n2 0 1\n1 0 1\n1 1 0\n1 0 1\n", "6 2\n6 0 0\n11 1 0\n9 0 1\n21 1 1\n10 1 0\n8 0 1\n", "3 1\n3 0 1\n3 1 0\n3 0 0\n", "6 3\n7 1 1\n8 0 0\n9 1 1\n6 1 0\n10 1 1\n5 0 0\n", "8 4 3\n1 1 1\n3 1 1\n12 1 1\n12 1 1\n4 0 0\n4 0 0\n5 1 0\n5 0 1\n", "6 3 ...
IN-CORRECT
cpp
#include <bits/stdc++.h> using namespace std; const int N = 200005; int t[N], a[N], b[N]; int main() { int n, m, k; scanf("%d %d %d", &n, &m, &k); int cnta = 0, cntb = 0; vector<pair<int, int> > v1, v2, v3, v0; for (int i = 0; i < n; i++) { scanf("%d %d %d", &t[i], &a[i], &b[i]); if (a[i] == 1) cnta++...
1374_E1. Reading Books (easy version)
Easy and hard versions are actually different problems, so read statements of both problems completely and carefully. Summer vacation has started so Alice and Bob want to play and joy, but... Their mom doesn't think so. She says that they have to read some amount of books before all entertainments. Alice and Bob will ...
{ "input": [ "8 4\n7 1 1\n2 1 1\n4 0 1\n8 1 1\n1 0 1\n1 1 1\n1 0 1\n3 0 0\n", "5 2\n6 0 0\n9 0 0\n1 0 1\n2 1 1\n5 1 0\n", "5 3\n3 0 0\n2 1 0\n3 1 0\n5 0 1\n3 0 1\n" ], "output": [ "18\n", "8\n", "-1\n" ] }
{ "input": [ "2 1\n7 1 1\n2 1 1\n", "5 1\n2 1 0\n2 0 1\n1 0 1\n1 1 0\n1 0 1\n", "6 2\n6 0 0\n11 1 0\n9 0 1\n21 1 1\n10 1 0\n8 0 1\n", "3 1\n3 0 1\n3 1 0\n3 0 0\n", "6 3\n7 1 1\n8 0 0\n9 1 1\n6 1 0\n10 1 1\n5 0 0\n", "8 4 3\n1 1 1\n3 1 1\n12 1 1\n12 1 1\n4 0 0\n4 0 0\n5 1 0\n5 0 1\n", "6 3 ...
IN-CORRECT
java
import java.io.*; import java.util.*; public class Codeforces { public static void main(String args[])throws Exception { BufferedReader bu=new BufferedReader(new InputStreamReader(System.in)); StringBuilder sb=new StringBuilder(); String s[]=bu.readLine().split(" "); int n=Integ...
1374_E1. Reading Books (easy version)
Easy and hard versions are actually different problems, so read statements of both problems completely and carefully. Summer vacation has started so Alice and Bob want to play and joy, but... Their mom doesn't think so. She says that they have to read some amount of books before all entertainments. Alice and Bob will ...
{ "input": [ "8 4\n7 1 1\n2 1 1\n4 0 1\n8 1 1\n1 0 1\n1 1 1\n1 0 1\n3 0 0\n", "5 2\n6 0 0\n9 0 0\n1 0 1\n2 1 1\n5 1 0\n", "5 3\n3 0 0\n2 1 0\n3 1 0\n5 0 1\n3 0 1\n" ], "output": [ "18\n", "8\n", "-1\n" ] }
{ "input": [ "2 1\n7 1 1\n2 1 1\n", "5 1\n2 1 0\n2 0 1\n1 0 1\n1 1 0\n1 0 1\n", "6 2\n6 0 0\n11 1 0\n9 0 1\n21 1 1\n10 1 0\n8 0 1\n", "3 1\n3 0 1\n3 1 0\n3 0 0\n", "6 3\n7 1 1\n8 0 0\n9 1 1\n6 1 0\n10 1 1\n5 0 0\n", "8 4 3\n1 1 1\n3 1 1\n12 1 1\n12 1 1\n4 0 0\n4 0 0\n5 1 0\n5 0 1\n", "6 3 ...
IN-CORRECT
java
import java.io.*; import java.util.*; public class Main { public static void main(String[] args) throws IOException { long []ins = GetInput.getLongArrayInput(); int n = (int) ins[0]; long k = ins[1]; PriorityQueue<Long> both = new PriorityQueue<>(); PriorityQueue<Long> alice = ne...
1374_E1. Reading Books (easy version)
Easy and hard versions are actually different problems, so read statements of both problems completely and carefully. Summer vacation has started so Alice and Bob want to play and joy, but... Their mom doesn't think so. She says that they have to read some amount of books before all entertainments. Alice and Bob will ...
{ "input": [ "8 4\n7 1 1\n2 1 1\n4 0 1\n8 1 1\n1 0 1\n1 1 1\n1 0 1\n3 0 0\n", "5 2\n6 0 0\n9 0 0\n1 0 1\n2 1 1\n5 1 0\n", "5 3\n3 0 0\n2 1 0\n3 1 0\n5 0 1\n3 0 1\n" ], "output": [ "18\n", "8\n", "-1\n" ] }
{ "input": [ "2 1\n7 1 1\n2 1 1\n", "5 1\n2 1 0\n2 0 1\n1 0 1\n1 1 0\n1 0 1\n", "6 2\n6 0 0\n11 1 0\n9 0 1\n21 1 1\n10 1 0\n8 0 1\n", "3 1\n3 0 1\n3 1 0\n3 0 0\n", "6 3\n7 1 1\n8 0 0\n9 1 1\n6 1 0\n10 1 1\n5 0 0\n", "8 4 3\n1 1 1\n3 1 1\n12 1 1\n12 1 1\n4 0 0\n4 0 0\n5 1 0\n5 0 1\n", "6 3 ...
IN-CORRECT
cpp
#include <bits/stdc++.h> using namespace std; int solve() { int n, k; cin >> n >> k; vector<int> A; vector<int> B; vector<int> both; for (int i = 0; i < n; i++) { int t, isA, isB; cin >> t >> isA >> isB; if (isA && isB) { both.push_back(t); } else if (isA) { A.push_back(t); }...
1374_E1. Reading Books (easy version)
Easy and hard versions are actually different problems, so read statements of both problems completely and carefully. Summer vacation has started so Alice and Bob want to play and joy, but... Their mom doesn't think so. She says that they have to read some amount of books before all entertainments. Alice and Bob will ...
{ "input": [ "8 4\n7 1 1\n2 1 1\n4 0 1\n8 1 1\n1 0 1\n1 1 1\n1 0 1\n3 0 0\n", "5 2\n6 0 0\n9 0 0\n1 0 1\n2 1 1\n5 1 0\n", "5 3\n3 0 0\n2 1 0\n3 1 0\n5 0 1\n3 0 1\n" ], "output": [ "18\n", "8\n", "-1\n" ] }
{ "input": [ "2 1\n7 1 1\n2 1 1\n", "5 1\n2 1 0\n2 0 1\n1 0 1\n1 1 0\n1 0 1\n", "6 2\n6 0 0\n11 1 0\n9 0 1\n21 1 1\n10 1 0\n8 0 1\n", "3 1\n3 0 1\n3 1 0\n3 0 0\n", "6 3\n7 1 1\n8 0 0\n9 1 1\n6 1 0\n10 1 1\n5 0 0\n", "8 4 3\n1 1 1\n3 1 1\n12 1 1\n12 1 1\n4 0 0\n4 0 0\n5 1 0\n5 0 1\n", "6 3 ...
IN-CORRECT
java
import java.io.*; import java.util.*; public class check5 { public static void main(String[] args) throws IOException{ Reader sc=new Reader(); PrintWriter out = new PrintWriter(System.out); int n=sc.nextInt(); long k=sc.nextLong(); int a[][]=new int[n][3]; ArrayL...
1374_E1. Reading Books (easy version)
Easy and hard versions are actually different problems, so read statements of both problems completely and carefully. Summer vacation has started so Alice and Bob want to play and joy, but... Their mom doesn't think so. She says that they have to read some amount of books before all entertainments. Alice and Bob will ...
{ "input": [ "8 4\n7 1 1\n2 1 1\n4 0 1\n8 1 1\n1 0 1\n1 1 1\n1 0 1\n3 0 0\n", "5 2\n6 0 0\n9 0 0\n1 0 1\n2 1 1\n5 1 0\n", "5 3\n3 0 0\n2 1 0\n3 1 0\n5 0 1\n3 0 1\n" ], "output": [ "18\n", "8\n", "-1\n" ] }
{ "input": [ "2 1\n7 1 1\n2 1 1\n", "5 1\n2 1 0\n2 0 1\n1 0 1\n1 1 0\n1 0 1\n", "6 2\n6 0 0\n11 1 0\n9 0 1\n21 1 1\n10 1 0\n8 0 1\n", "3 1\n3 0 1\n3 1 0\n3 0 0\n", "6 3\n7 1 1\n8 0 0\n9 1 1\n6 1 0\n10 1 1\n5 0 0\n", "8 4 3\n1 1 1\n3 1 1\n12 1 1\n12 1 1\n4 0 0\n4 0 0\n5 1 0\n5 0 1\n", "6 3 ...
IN-CORRECT
cpp
#include <bits/stdc++.h> using namespace std; void quick_sort(int a[], int left, int right) { int l = left, r = right, m = a[rand() % (r - l) + l]; while (l < r) { while (a[l] < m) l++; while (a[r] > m) r--; if (l <= r) { int t = a[l]; a[l] = a[r]; a[r] = t; l++; r--; }...
1374_E1. Reading Books (easy version)
Easy and hard versions are actually different problems, so read statements of both problems completely and carefully. Summer vacation has started so Alice and Bob want to play and joy, but... Their mom doesn't think so. She says that they have to read some amount of books before all entertainments. Alice and Bob will ...
{ "input": [ "8 4\n7 1 1\n2 1 1\n4 0 1\n8 1 1\n1 0 1\n1 1 1\n1 0 1\n3 0 0\n", "5 2\n6 0 0\n9 0 0\n1 0 1\n2 1 1\n5 1 0\n", "5 3\n3 0 0\n2 1 0\n3 1 0\n5 0 1\n3 0 1\n" ], "output": [ "18\n", "8\n", "-1\n" ] }
{ "input": [ "2 1\n7 1 1\n2 1 1\n", "5 1\n2 1 0\n2 0 1\n1 0 1\n1 1 0\n1 0 1\n", "6 2\n6 0 0\n11 1 0\n9 0 1\n21 1 1\n10 1 0\n8 0 1\n", "3 1\n3 0 1\n3 1 0\n3 0 0\n", "6 3\n7 1 1\n8 0 0\n9 1 1\n6 1 0\n10 1 1\n5 0 0\n", "8 4 3\n1 1 1\n3 1 1\n12 1 1\n12 1 1\n4 0 0\n4 0 0\n5 1 0\n5 0 1\n", "6 3 ...
IN-CORRECT
python3
n, k = map(int , input().split()) alice = [] bob = [] both = [] for i in range(n): t,a,b = map(int , input().split()) if a==1 and b==1: both.append(t) elif a==1 and b==0: alice.append(t) elif a==0 and b==1: bob.append(t) alice.sort(reverse=True) bob.sort(reverse=True) both.sort...
1374_E1. Reading Books (easy version)
Easy and hard versions are actually different problems, so read statements of both problems completely and carefully. Summer vacation has started so Alice and Bob want to play and joy, but... Their mom doesn't think so. She says that they have to read some amount of books before all entertainments. Alice and Bob will ...
{ "input": [ "8 4\n7 1 1\n2 1 1\n4 0 1\n8 1 1\n1 0 1\n1 1 1\n1 0 1\n3 0 0\n", "5 2\n6 0 0\n9 0 0\n1 0 1\n2 1 1\n5 1 0\n", "5 3\n3 0 0\n2 1 0\n3 1 0\n5 0 1\n3 0 1\n" ], "output": [ "18\n", "8\n", "-1\n" ] }
{ "input": [ "2 1\n7 1 1\n2 1 1\n", "5 1\n2 1 0\n2 0 1\n1 0 1\n1 1 0\n1 0 1\n", "6 2\n6 0 0\n11 1 0\n9 0 1\n21 1 1\n10 1 0\n8 0 1\n", "3 1\n3 0 1\n3 1 0\n3 0 0\n", "6 3\n7 1 1\n8 0 0\n9 1 1\n6 1 0\n10 1 1\n5 0 0\n", "8 4 3\n1 1 1\n3 1 1\n12 1 1\n12 1 1\n4 0 0\n4 0 0\n5 1 0\n5 0 1\n", "6 3 ...
IN-CORRECT
java
import java.util.ArrayList; import java.util.Arrays; import java.util.Scanner; public class E1_1374 { public static void main(String[] args) { Scanner in = new Scanner(System.in); int n = in.nextInt(); int k = in.nextInt(); Triple1[] arr = new Triple1[n]; for (int i = 0; i < n; i++) { arr[i] = new Triple...
1374_E1. Reading Books (easy version)
Easy and hard versions are actually different problems, so read statements of both problems completely and carefully. Summer vacation has started so Alice and Bob want to play and joy, but... Their mom doesn't think so. She says that they have to read some amount of books before all entertainments. Alice and Bob will ...
{ "input": [ "8 4\n7 1 1\n2 1 1\n4 0 1\n8 1 1\n1 0 1\n1 1 1\n1 0 1\n3 0 0\n", "5 2\n6 0 0\n9 0 0\n1 0 1\n2 1 1\n5 1 0\n", "5 3\n3 0 0\n2 1 0\n3 1 0\n5 0 1\n3 0 1\n" ], "output": [ "18\n", "8\n", "-1\n" ] }
{ "input": [ "2 1\n7 1 1\n2 1 1\n", "5 1\n2 1 0\n2 0 1\n1 0 1\n1 1 0\n1 0 1\n", "6 2\n6 0 0\n11 1 0\n9 0 1\n21 1 1\n10 1 0\n8 0 1\n", "3 1\n3 0 1\n3 1 0\n3 0 0\n", "6 3\n7 1 1\n8 0 0\n9 1 1\n6 1 0\n10 1 1\n5 0 0\n", "8 4 3\n1 1 1\n3 1 1\n12 1 1\n12 1 1\n4 0 0\n4 0 0\n5 1 0\n5 0 1\n", "6 3 ...
IN-CORRECT
java
import java.util.*; import java.math.*; import java.io.*; public class A{ static FastReader scan=new FastReader(); public static PrintWriter out = new PrintWriter (new BufferedOutputStream(System.out)); static LinkedList<Integer>edges[]; // static LinkedList<Pair>edges[]; static boolean stdin = true; stat...
1374_E1. Reading Books (easy version)
Easy and hard versions are actually different problems, so read statements of both problems completely and carefully. Summer vacation has started so Alice and Bob want to play and joy, but... Their mom doesn't think so. She says that they have to read some amount of books before all entertainments. Alice and Bob will ...
{ "input": [ "8 4\n7 1 1\n2 1 1\n4 0 1\n8 1 1\n1 0 1\n1 1 1\n1 0 1\n3 0 0\n", "5 2\n6 0 0\n9 0 0\n1 0 1\n2 1 1\n5 1 0\n", "5 3\n3 0 0\n2 1 0\n3 1 0\n5 0 1\n3 0 1\n" ], "output": [ "18\n", "8\n", "-1\n" ] }
{ "input": [ "2 1\n7 1 1\n2 1 1\n", "5 1\n2 1 0\n2 0 1\n1 0 1\n1 1 0\n1 0 1\n", "6 2\n6 0 0\n11 1 0\n9 0 1\n21 1 1\n10 1 0\n8 0 1\n", "3 1\n3 0 1\n3 1 0\n3 0 0\n", "6 3\n7 1 1\n8 0 0\n9 1 1\n6 1 0\n10 1 1\n5 0 0\n", "8 4 3\n1 1 1\n3 1 1\n12 1 1\n12 1 1\n4 0 0\n4 0 0\n5 1 0\n5 0 1\n", "6 3 ...
IN-CORRECT
java
import java.io.*; import java.util.*; public class E1374{ static BufferedReader br; static PrintWriter out; static StringBuilder sb; public static void main(String args[]) throws IOException{ br = new BufferedReader(new InputStreamReader(System.in)); out = new PrintWriter(System.out); ...
1374_E1. Reading Books (easy version)
Easy and hard versions are actually different problems, so read statements of both problems completely and carefully. Summer vacation has started so Alice and Bob want to play and joy, but... Their mom doesn't think so. She says that they have to read some amount of books before all entertainments. Alice and Bob will ...
{ "input": [ "8 4\n7 1 1\n2 1 1\n4 0 1\n8 1 1\n1 0 1\n1 1 1\n1 0 1\n3 0 0\n", "5 2\n6 0 0\n9 0 0\n1 0 1\n2 1 1\n5 1 0\n", "5 3\n3 0 0\n2 1 0\n3 1 0\n5 0 1\n3 0 1\n" ], "output": [ "18\n", "8\n", "-1\n" ] }
{ "input": [ "2 1\n7 1 1\n2 1 1\n", "5 1\n2 1 0\n2 0 1\n1 0 1\n1 1 0\n1 0 1\n", "6 2\n6 0 0\n11 1 0\n9 0 1\n21 1 1\n10 1 0\n8 0 1\n", "3 1\n3 0 1\n3 1 0\n3 0 0\n", "6 3\n7 1 1\n8 0 0\n9 1 1\n6 1 0\n10 1 1\n5 0 0\n", "8 4 3\n1 1 1\n3 1 1\n12 1 1\n12 1 1\n4 0 0\n4 0 0\n5 1 0\n5 0 1\n", "6 3 ...
IN-CORRECT
java
import java.util.*; import java.io.*; public class test1 { static class Reader { BufferedReader br; StringTokenizer st; public Reader() { br = new BufferedReader(new InputStreamReader(System.in)); } public int nextInt() throws IOException { if (st == null || !st.hasMoreTokens()) { st = new Stri...
1374_E1. Reading Books (easy version)
Easy and hard versions are actually different problems, so read statements of both problems completely and carefully. Summer vacation has started so Alice and Bob want to play and joy, but... Their mom doesn't think so. She says that they have to read some amount of books before all entertainments. Alice and Bob will ...
{ "input": [ "8 4\n7 1 1\n2 1 1\n4 0 1\n8 1 1\n1 0 1\n1 1 1\n1 0 1\n3 0 0\n", "5 2\n6 0 0\n9 0 0\n1 0 1\n2 1 1\n5 1 0\n", "5 3\n3 0 0\n2 1 0\n3 1 0\n5 0 1\n3 0 1\n" ], "output": [ "18\n", "8\n", "-1\n" ] }
{ "input": [ "2 1\n7 1 1\n2 1 1\n", "5 1\n2 1 0\n2 0 1\n1 0 1\n1 1 0\n1 0 1\n", "6 2\n6 0 0\n11 1 0\n9 0 1\n21 1 1\n10 1 0\n8 0 1\n", "3 1\n3 0 1\n3 1 0\n3 0 0\n", "6 3\n7 1 1\n8 0 0\n9 1 1\n6 1 0\n10 1 1\n5 0 0\n", "8 4 3\n1 1 1\n3 1 1\n12 1 1\n12 1 1\n4 0 0\n4 0 0\n5 1 0\n5 0 1\n", "6 3 ...
IN-CORRECT
java
import java.io.*; import java.math.BigInteger; import java.util.*; public class test1{ static List<Integer> merge(List<Integer> list1, List<Integer> list2){ List<Integer> temp = new ArrayList<>(); int i=0, j=0; for(; i<list1.size() && j<list2.size(); ){ if(list1.get(i) < list2.get(j)){ temp.add(list1....
1374_E1. Reading Books (easy version)
Easy and hard versions are actually different problems, so read statements of both problems completely and carefully. Summer vacation has started so Alice and Bob want to play and joy, but... Their mom doesn't think so. She says that they have to read some amount of books before all entertainments. Alice and Bob will ...
{ "input": [ "8 4\n7 1 1\n2 1 1\n4 0 1\n8 1 1\n1 0 1\n1 1 1\n1 0 1\n3 0 0\n", "5 2\n6 0 0\n9 0 0\n1 0 1\n2 1 1\n5 1 0\n", "5 3\n3 0 0\n2 1 0\n3 1 0\n5 0 1\n3 0 1\n" ], "output": [ "18\n", "8\n", "-1\n" ] }
{ "input": [ "2 1\n7 1 1\n2 1 1\n", "5 1\n2 1 0\n2 0 1\n1 0 1\n1 1 0\n1 0 1\n", "6 2\n6 0 0\n11 1 0\n9 0 1\n21 1 1\n10 1 0\n8 0 1\n", "3 1\n3 0 1\n3 1 0\n3 0 0\n", "6 3\n7 1 1\n8 0 0\n9 1 1\n6 1 0\n10 1 1\n5 0 0\n", "8 4 3\n1 1 1\n3 1 1\n12 1 1\n12 1 1\n4 0 0\n4 0 0\n5 1 0\n5 0 1\n", "6 3 ...
IN-CORRECT
python3
n,k = map(int, input().split()) a = [] b = [] comman = [] for _ in range(n): t,ai,bi = map(int, input().split()) if ai == 1: a.append(t) if bi == 1: b.append(t) if ai == 1 and bi == 1: comman.append(t) a.sort() b.sort() comman.sort() if len(a) < k or len(b) < k: print(-1) else: s = 0 ki = k for i in...
1374_E1. Reading Books (easy version)
Easy and hard versions are actually different problems, so read statements of both problems completely and carefully. Summer vacation has started so Alice and Bob want to play and joy, but... Their mom doesn't think so. She says that they have to read some amount of books before all entertainments. Alice and Bob will ...
{ "input": [ "8 4\n7 1 1\n2 1 1\n4 0 1\n8 1 1\n1 0 1\n1 1 1\n1 0 1\n3 0 0\n", "5 2\n6 0 0\n9 0 0\n1 0 1\n2 1 1\n5 1 0\n", "5 3\n3 0 0\n2 1 0\n3 1 0\n5 0 1\n3 0 1\n" ], "output": [ "18\n", "8\n", "-1\n" ] }
{ "input": [ "2 1\n7 1 1\n2 1 1\n", "5 1\n2 1 0\n2 0 1\n1 0 1\n1 1 0\n1 0 1\n", "6 2\n6 0 0\n11 1 0\n9 0 1\n21 1 1\n10 1 0\n8 0 1\n", "3 1\n3 0 1\n3 1 0\n3 0 0\n", "6 3\n7 1 1\n8 0 0\n9 1 1\n6 1 0\n10 1 1\n5 0 0\n", "8 4 3\n1 1 1\n3 1 1\n12 1 1\n12 1 1\n4 0 0\n4 0 0\n5 1 0\n5 0 1\n", "6 3 ...
IN-CORRECT
java
import java.io.*; import java.util.StringTokenizer; import java.util.TreeSet; public class ReadingBooks_1600 { public static void main(String[] args) { MyScanner sc = new MyScanner(); out = new PrintWriter(new BufferedOutputStream(System.out)); int N = Integer.parseInt(sc.next()); i...
1374_E1. Reading Books (easy version)
Easy and hard versions are actually different problems, so read statements of both problems completely and carefully. Summer vacation has started so Alice and Bob want to play and joy, but... Their mom doesn't think so. She says that they have to read some amount of books before all entertainments. Alice and Bob will ...
{ "input": [ "8 4\n7 1 1\n2 1 1\n4 0 1\n8 1 1\n1 0 1\n1 1 1\n1 0 1\n3 0 0\n", "5 2\n6 0 0\n9 0 0\n1 0 1\n2 1 1\n5 1 0\n", "5 3\n3 0 0\n2 1 0\n3 1 0\n5 0 1\n3 0 1\n" ], "output": [ "18\n", "8\n", "-1\n" ] }
{ "input": [ "2 1\n7 1 1\n2 1 1\n", "5 1\n2 1 0\n2 0 1\n1 0 1\n1 1 0\n1 0 1\n", "6 2\n6 0 0\n11 1 0\n9 0 1\n21 1 1\n10 1 0\n8 0 1\n", "3 1\n3 0 1\n3 1 0\n3 0 0\n", "6 3\n7 1 1\n8 0 0\n9 1 1\n6 1 0\n10 1 1\n5 0 0\n", "8 4 3\n1 1 1\n3 1 1\n12 1 1\n12 1 1\n4 0 0\n4 0 0\n5 1 0\n5 0 1\n", "6 3 ...
IN-CORRECT
cpp
#include <bits/stdc++.h> using namespace std; long long int a, b, c, d, e, f = 5 * 1e9, m11[200000], m01[200000], m10[200000], k, k1, k2; int main() { cin >> a >> b; for (int i = 0; i < a; i++) { cin >> c >> d >> e; if (e == 1 && d == 1) m11[k] = c, k++; if (d == 1 && e == 0...
1374_E1. Reading Books (easy version)
Easy and hard versions are actually different problems, so read statements of both problems completely and carefully. Summer vacation has started so Alice and Bob want to play and joy, but... Their mom doesn't think so. She says that they have to read some amount of books before all entertainments. Alice and Bob will ...
{ "input": [ "8 4\n7 1 1\n2 1 1\n4 0 1\n8 1 1\n1 0 1\n1 1 1\n1 0 1\n3 0 0\n", "5 2\n6 0 0\n9 0 0\n1 0 1\n2 1 1\n5 1 0\n", "5 3\n3 0 0\n2 1 0\n3 1 0\n5 0 1\n3 0 1\n" ], "output": [ "18\n", "8\n", "-1\n" ] }
{ "input": [ "2 1\n7 1 1\n2 1 1\n", "5 1\n2 1 0\n2 0 1\n1 0 1\n1 1 0\n1 0 1\n", "6 2\n6 0 0\n11 1 0\n9 0 1\n21 1 1\n10 1 0\n8 0 1\n", "3 1\n3 0 1\n3 1 0\n3 0 0\n", "6 3\n7 1 1\n8 0 0\n9 1 1\n6 1 0\n10 1 1\n5 0 0\n", "8 4 3\n1 1 1\n3 1 1\n12 1 1\n12 1 1\n4 0 0\n4 0 0\n5 1 0\n5 0 1\n", "6 3 ...
IN-CORRECT
java
import java.io.*; import java.util.*; import java.math.*; import java.lang.*; import static java.lang.Math.*; public class Solution implements Runnable { static class InputReader { private InputStream stream; private byte[] buf = new byte[1024]; private int curChar; private int numChars; private SpaceCharF...
1374_E1. Reading Books (easy version)
Easy and hard versions are actually different problems, so read statements of both problems completely and carefully. Summer vacation has started so Alice and Bob want to play and joy, but... Their mom doesn't think so. She says that they have to read some amount of books before all entertainments. Alice and Bob will ...
{ "input": [ "8 4\n7 1 1\n2 1 1\n4 0 1\n8 1 1\n1 0 1\n1 1 1\n1 0 1\n3 0 0\n", "5 2\n6 0 0\n9 0 0\n1 0 1\n2 1 1\n5 1 0\n", "5 3\n3 0 0\n2 1 0\n3 1 0\n5 0 1\n3 0 1\n" ], "output": [ "18\n", "8\n", "-1\n" ] }
{ "input": [ "2 1\n7 1 1\n2 1 1\n", "5 1\n2 1 0\n2 0 1\n1 0 1\n1 1 0\n1 0 1\n", "6 2\n6 0 0\n11 1 0\n9 0 1\n21 1 1\n10 1 0\n8 0 1\n", "3 1\n3 0 1\n3 1 0\n3 0 0\n", "6 3\n7 1 1\n8 0 0\n9 1 1\n6 1 0\n10 1 1\n5 0 0\n", "8 4 3\n1 1 1\n3 1 1\n12 1 1\n12 1 1\n4 0 0\n4 0 0\n5 1 0\n5 0 1\n", "6 3 ...
IN-CORRECT
cpp
#include <bits/stdc++.h> using namespace std; const string YESNO[2] = {"NO", "YES"}; const string YesNo[2] = {"No", "Yes"}; const string yesno[2] = {"no", "yes"}; void YES(bool t = 1) { cout << YESNO[t] << "\n"; } void Yes(bool t = 1) { cout << YesNo[t] << "\n"; } void yes(bool t = 1) { cout << yesno[t] << "\n"; } cons...
1374_E1. Reading Books (easy version)
Easy and hard versions are actually different problems, so read statements of both problems completely and carefully. Summer vacation has started so Alice and Bob want to play and joy, but... Their mom doesn't think so. She says that they have to read some amount of books before all entertainments. Alice and Bob will ...
{ "input": [ "8 4\n7 1 1\n2 1 1\n4 0 1\n8 1 1\n1 0 1\n1 1 1\n1 0 1\n3 0 0\n", "5 2\n6 0 0\n9 0 0\n1 0 1\n2 1 1\n5 1 0\n", "5 3\n3 0 0\n2 1 0\n3 1 0\n5 0 1\n3 0 1\n" ], "output": [ "18\n", "8\n", "-1\n" ] }
{ "input": [ "2 1\n7 1 1\n2 1 1\n", "5 1\n2 1 0\n2 0 1\n1 0 1\n1 1 0\n1 0 1\n", "6 2\n6 0 0\n11 1 0\n9 0 1\n21 1 1\n10 1 0\n8 0 1\n", "3 1\n3 0 1\n3 1 0\n3 0 0\n", "6 3\n7 1 1\n8 0 0\n9 1 1\n6 1 0\n10 1 1\n5 0 0\n", "8 4 3\n1 1 1\n3 1 1\n12 1 1\n12 1 1\n4 0 0\n4 0 0\n5 1 0\n5 0 1\n", "6 3 ...
IN-CORRECT
cpp
#include <bits/stdc++.h> using namespace std; const int maxn = 1e5 + 10; inline int read() { int x = 0, f = 1; char ch = getchar(); while (!isdigit(ch)) { if (ch == '-') f = -1; ch = getchar(); } while (isdigit(ch)) { x = x * 10 + ch - 48; ch = getchar(); } return x * f; } priority_queue<i...
1374_E1. Reading Books (easy version)
Easy and hard versions are actually different problems, so read statements of both problems completely and carefully. Summer vacation has started so Alice and Bob want to play and joy, but... Their mom doesn't think so. She says that they have to read some amount of books before all entertainments. Alice and Bob will ...
{ "input": [ "8 4\n7 1 1\n2 1 1\n4 0 1\n8 1 1\n1 0 1\n1 1 1\n1 0 1\n3 0 0\n", "5 2\n6 0 0\n9 0 0\n1 0 1\n2 1 1\n5 1 0\n", "5 3\n3 0 0\n2 1 0\n3 1 0\n5 0 1\n3 0 1\n" ], "output": [ "18\n", "8\n", "-1\n" ] }
{ "input": [ "2 1\n7 1 1\n2 1 1\n", "5 1\n2 1 0\n2 0 1\n1 0 1\n1 1 0\n1 0 1\n", "6 2\n6 0 0\n11 1 0\n9 0 1\n21 1 1\n10 1 0\n8 0 1\n", "3 1\n3 0 1\n3 1 0\n3 0 0\n", "6 3\n7 1 1\n8 0 0\n9 1 1\n6 1 0\n10 1 1\n5 0 0\n", "8 4 3\n1 1 1\n3 1 1\n12 1 1\n12 1 1\n4 0 0\n4 0 0\n5 1 0\n5 0 1\n", "6 3 ...
IN-CORRECT
java
import java.io.*; import java.util.*; import java.math.*; public class E2 { static final boolean RUN_TIMING = false; static char[] inputBuffer = new char[1 << 20]; static PushbackReader in = new PushbackReader(new BufferedReader(new InputStreamReader(System.in)), 1 << 20); static PrintWriter out = new ...
1374_E1. Reading Books (easy version)
Easy and hard versions are actually different problems, so read statements of both problems completely and carefully. Summer vacation has started so Alice and Bob want to play and joy, but... Their mom doesn't think so. She says that they have to read some amount of books before all entertainments. Alice and Bob will ...
{ "input": [ "8 4\n7 1 1\n2 1 1\n4 0 1\n8 1 1\n1 0 1\n1 1 1\n1 0 1\n3 0 0\n", "5 2\n6 0 0\n9 0 0\n1 0 1\n2 1 1\n5 1 0\n", "5 3\n3 0 0\n2 1 0\n3 1 0\n5 0 1\n3 0 1\n" ], "output": [ "18\n", "8\n", "-1\n" ] }
{ "input": [ "2 1\n7 1 1\n2 1 1\n", "5 1\n2 1 0\n2 0 1\n1 0 1\n1 1 0\n1 0 1\n", "6 2\n6 0 0\n11 1 0\n9 0 1\n21 1 1\n10 1 0\n8 0 1\n", "3 1\n3 0 1\n3 1 0\n3 0 0\n", "6 3\n7 1 1\n8 0 0\n9 1 1\n6 1 0\n10 1 1\n5 0 0\n", "8 4 3\n1 1 1\n3 1 1\n12 1 1\n12 1 1\n4 0 0\n4 0 0\n5 1 0\n5 0 1\n", "6 3 ...
IN-CORRECT
cpp
#include <bits/stdc++.h> using namespace std; int n, m, k; vector<pair<int, int> > both, alice, bob, all; pair<int, unordered_map<int, bool> > calcUtil(int bothTaken) { int satisfy = 0; unordered_map<int, bool> taken; for (int i = 0; i < bothTaken; i++) { satisfy += both[bothTaken - 1].first; taken[both[i...
1374_E1. Reading Books (easy version)
Easy and hard versions are actually different problems, so read statements of both problems completely and carefully. Summer vacation has started so Alice and Bob want to play and joy, but... Their mom doesn't think so. She says that they have to read some amount of books before all entertainments. Alice and Bob will ...
{ "input": [ "8 4\n7 1 1\n2 1 1\n4 0 1\n8 1 1\n1 0 1\n1 1 1\n1 0 1\n3 0 0\n", "5 2\n6 0 0\n9 0 0\n1 0 1\n2 1 1\n5 1 0\n", "5 3\n3 0 0\n2 1 0\n3 1 0\n5 0 1\n3 0 1\n" ], "output": [ "18\n", "8\n", "-1\n" ] }
{ "input": [ "2 1\n7 1 1\n2 1 1\n", "5 1\n2 1 0\n2 0 1\n1 0 1\n1 1 0\n1 0 1\n", "6 2\n6 0 0\n11 1 0\n9 0 1\n21 1 1\n10 1 0\n8 0 1\n", "3 1\n3 0 1\n3 1 0\n3 0 0\n", "6 3\n7 1 1\n8 0 0\n9 1 1\n6 1 0\n10 1 1\n5 0 0\n", "8 4 3\n1 1 1\n3 1 1\n12 1 1\n12 1 1\n4 0 0\n4 0 0\n5 1 0\n5 0 1\n", "6 3 ...
IN-CORRECT
python3
book, m, k = map(int, input().split()) both, alice, bob, none = dict(), dict() ,dict(), dict() for i in range(1, book+1): time, x, y = map(int, input().split()) if x == 1 and y == 1: both[i] = time elif x == 1 and y == 0: alice[i] = time elif x == 0 and y == 1: bob[i] = time ...
1374_E1. Reading Books (easy version)
Easy and hard versions are actually different problems, so read statements of both problems completely and carefully. Summer vacation has started so Alice and Bob want to play and joy, but... Their mom doesn't think so. She says that they have to read some amount of books before all entertainments. Alice and Bob will ...
{ "input": [ "8 4\n7 1 1\n2 1 1\n4 0 1\n8 1 1\n1 0 1\n1 1 1\n1 0 1\n3 0 0\n", "5 2\n6 0 0\n9 0 0\n1 0 1\n2 1 1\n5 1 0\n", "5 3\n3 0 0\n2 1 0\n3 1 0\n5 0 1\n3 0 1\n" ], "output": [ "18\n", "8\n", "-1\n" ] }
{ "input": [ "2 1\n7 1 1\n2 1 1\n", "5 1\n2 1 0\n2 0 1\n1 0 1\n1 1 0\n1 0 1\n", "6 2\n6 0 0\n11 1 0\n9 0 1\n21 1 1\n10 1 0\n8 0 1\n", "3 1\n3 0 1\n3 1 0\n3 0 0\n", "6 3\n7 1 1\n8 0 0\n9 1 1\n6 1 0\n10 1 1\n5 0 0\n", "8 4 3\n1 1 1\n3 1 1\n12 1 1\n12 1 1\n4 0 0\n4 0 0\n5 1 0\n5 0 1\n", "6 3 ...
IN-CORRECT
python3
n,m,k = map(int,input().split()) ab = [] a = [] b = [] other = [] for i in range(n): t,c,d = map(int,input().split()) if c and d == 0: a.append([t,i+1]) elif d and c == 0: b.append([t,i+1]) elif c*d: ab.append([t,i+1]) else: other.append([t,i+1]) a.sort() b.sort() ab....
1374_E1. Reading Books (easy version)
Easy and hard versions are actually different problems, so read statements of both problems completely and carefully. Summer vacation has started so Alice and Bob want to play and joy, but... Their mom doesn't think so. She says that they have to read some amount of books before all entertainments. Alice and Bob will ...
{ "input": [ "8 4\n7 1 1\n2 1 1\n4 0 1\n8 1 1\n1 0 1\n1 1 1\n1 0 1\n3 0 0\n", "5 2\n6 0 0\n9 0 0\n1 0 1\n2 1 1\n5 1 0\n", "5 3\n3 0 0\n2 1 0\n3 1 0\n5 0 1\n3 0 1\n" ], "output": [ "18\n", "8\n", "-1\n" ] }
{ "input": [ "2 1\n7 1 1\n2 1 1\n", "5 1\n2 1 0\n2 0 1\n1 0 1\n1 1 0\n1 0 1\n", "6 2\n6 0 0\n11 1 0\n9 0 1\n21 1 1\n10 1 0\n8 0 1\n", "3 1\n3 0 1\n3 1 0\n3 0 0\n", "6 3\n7 1 1\n8 0 0\n9 1 1\n6 1 0\n10 1 1\n5 0 0\n", "8 4 3\n1 1 1\n3 1 1\n12 1 1\n12 1 1\n4 0 0\n4 0 0\n5 1 0\n5 0 1\n", "6 3 ...
IN-CORRECT
python3
n, m, k = map(int, input().split()) books = [] booksA = [] booksB = [] booksAB = [] for ind in range(n): t, a, b = map(int, input().split()) if a == 1 and b == 0: booksA.append((t, ind + 1)) elif a == 0 and b == 1: booksB.append((t, ind + 1)) elif a == 1 and b == 1: books.append(...
1374_E1. Reading Books (easy version)
Easy and hard versions are actually different problems, so read statements of both problems completely and carefully. Summer vacation has started so Alice and Bob want to play and joy, but... Their mom doesn't think so. She says that they have to read some amount of books before all entertainments. Alice and Bob will ...
{ "input": [ "8 4\n7 1 1\n2 1 1\n4 0 1\n8 1 1\n1 0 1\n1 1 1\n1 0 1\n3 0 0\n", "5 2\n6 0 0\n9 0 0\n1 0 1\n2 1 1\n5 1 0\n", "5 3\n3 0 0\n2 1 0\n3 1 0\n5 0 1\n3 0 1\n" ], "output": [ "18\n", "8\n", "-1\n" ] }
{ "input": [ "2 1\n7 1 1\n2 1 1\n", "5 1\n2 1 0\n2 0 1\n1 0 1\n1 1 0\n1 0 1\n", "6 2\n6 0 0\n11 1 0\n9 0 1\n21 1 1\n10 1 0\n8 0 1\n", "3 1\n3 0 1\n3 1 0\n3 0 0\n", "6 3\n7 1 1\n8 0 0\n9 1 1\n6 1 0\n10 1 1\n5 0 0\n", "8 4 3\n1 1 1\n3 1 1\n12 1 1\n12 1 1\n4 0 0\n4 0 0\n5 1 0\n5 0 1\n", "6 3 ...
IN-CORRECT
java
import java.io.BufferedReader; import java.io.IOException; import java.io.InputStreamReader; import java.util.*; public class EasyReadingBook { static class lib { int t, a, b; boolean flag; public lib(int t, int a, int b, boolean flag) { this.t = t; this.a = a; ...
1374_E1. Reading Books (easy version)
Easy and hard versions are actually different problems, so read statements of both problems completely and carefully. Summer vacation has started so Alice and Bob want to play and joy, but... Their mom doesn't think so. She says that they have to read some amount of books before all entertainments. Alice and Bob will ...
{ "input": [ "8 4\n7 1 1\n2 1 1\n4 0 1\n8 1 1\n1 0 1\n1 1 1\n1 0 1\n3 0 0\n", "5 2\n6 0 0\n9 0 0\n1 0 1\n2 1 1\n5 1 0\n", "5 3\n3 0 0\n2 1 0\n3 1 0\n5 0 1\n3 0 1\n" ], "output": [ "18\n", "8\n", "-1\n" ] }
{ "input": [ "2 1\n7 1 1\n2 1 1\n", "5 1\n2 1 0\n2 0 1\n1 0 1\n1 1 0\n1 0 1\n", "6 2\n6 0 0\n11 1 0\n9 0 1\n21 1 1\n10 1 0\n8 0 1\n", "3 1\n3 0 1\n3 1 0\n3 0 0\n", "6 3\n7 1 1\n8 0 0\n9 1 1\n6 1 0\n10 1 1\n5 0 0\n", "8 4 3\n1 1 1\n3 1 1\n12 1 1\n12 1 1\n4 0 0\n4 0 0\n5 1 0\n5 0 1\n", "6 3 ...
IN-CORRECT
python3
book, m, k = map(int, input().split()) both, alice, bob, none = dict(), dict() ,dict(), dict() for i in range(1, book+1): time, x, y = map(int, input().split()) if x == 1 and y == 1: both[i] = time elif x == 1 and y == 0: alice[i] = time elif x == 0 and y == 1: bob[i] = time ...
1374_E1. Reading Books (easy version)
Easy and hard versions are actually different problems, so read statements of both problems completely and carefully. Summer vacation has started so Alice and Bob want to play and joy, but... Their mom doesn't think so. She says that they have to read some amount of books before all entertainments. Alice and Bob will ...
{ "input": [ "8 4\n7 1 1\n2 1 1\n4 0 1\n8 1 1\n1 0 1\n1 1 1\n1 0 1\n3 0 0\n", "5 2\n6 0 0\n9 0 0\n1 0 1\n2 1 1\n5 1 0\n", "5 3\n3 0 0\n2 1 0\n3 1 0\n5 0 1\n3 0 1\n" ], "output": [ "18\n", "8\n", "-1\n" ] }
{ "input": [ "2 1\n7 1 1\n2 1 1\n", "5 1\n2 1 0\n2 0 1\n1 0 1\n1 1 0\n1 0 1\n", "6 2\n6 0 0\n11 1 0\n9 0 1\n21 1 1\n10 1 0\n8 0 1\n", "3 1\n3 0 1\n3 1 0\n3 0 0\n", "6 3\n7 1 1\n8 0 0\n9 1 1\n6 1 0\n10 1 1\n5 0 0\n", "8 4 3\n1 1 1\n3 1 1\n12 1 1\n12 1 1\n4 0 0\n4 0 0\n5 1 0\n5 0 1\n", "6 3 ...
IN-CORRECT
python3
book, m, k = map(int, input().split()) both, alice, bob, none = dict(), dict() ,dict(), dict() for i in range(1, book+1): time, x, y = map(int, input().split()) if x == 1 and y == 1: both[i] = time elif x == 1 and y == 0: alice[i] = time elif x == 0 and y == 1: bob[i] = time ...
1374_E1. Reading Books (easy version)
Easy and hard versions are actually different problems, so read statements of both problems completely and carefully. Summer vacation has started so Alice and Bob want to play and joy, but... Their mom doesn't think so. She says that they have to read some amount of books before all entertainments. Alice and Bob will ...
{ "input": [ "8 4\n7 1 1\n2 1 1\n4 0 1\n8 1 1\n1 0 1\n1 1 1\n1 0 1\n3 0 0\n", "5 2\n6 0 0\n9 0 0\n1 0 1\n2 1 1\n5 1 0\n", "5 3\n3 0 0\n2 1 0\n3 1 0\n5 0 1\n3 0 1\n" ], "output": [ "18\n", "8\n", "-1\n" ] }
{ "input": [ "2 1\n7 1 1\n2 1 1\n", "5 1\n2 1 0\n2 0 1\n1 0 1\n1 1 0\n1 0 1\n", "6 2\n6 0 0\n11 1 0\n9 0 1\n21 1 1\n10 1 0\n8 0 1\n", "3 1\n3 0 1\n3 1 0\n3 0 0\n", "6 3\n7 1 1\n8 0 0\n9 1 1\n6 1 0\n10 1 1\n5 0 0\n", "8 4 3\n1 1 1\n3 1 1\n12 1 1\n12 1 1\n4 0 0\n4 0 0\n5 1 0\n5 0 1\n", "6 3 ...
IN-CORRECT
cpp
#include <bits/stdc++.h> using namespace std; int main() { int n, k; cin >> n >> k; set<int> v, v0, v1; for (int i = 0; i < n; i++) { int t, a, b; cin >> t >> a >> b; if (a == 0 && b == 0) continue; if (a == 0 && b == 1) { v1.insert(t); } if (a == 1 && b == 0) v0.insert(t); if ...
1374_E1. Reading Books (easy version)
Easy and hard versions are actually different problems, so read statements of both problems completely and carefully. Summer vacation has started so Alice and Bob want to play and joy, but... Their mom doesn't think so. She says that they have to read some amount of books before all entertainments. Alice and Bob will ...
{ "input": [ "8 4\n7 1 1\n2 1 1\n4 0 1\n8 1 1\n1 0 1\n1 1 1\n1 0 1\n3 0 0\n", "5 2\n6 0 0\n9 0 0\n1 0 1\n2 1 1\n5 1 0\n", "5 3\n3 0 0\n2 1 0\n3 1 0\n5 0 1\n3 0 1\n" ], "output": [ "18\n", "8\n", "-1\n" ] }
{ "input": [ "2 1\n7 1 1\n2 1 1\n", "5 1\n2 1 0\n2 0 1\n1 0 1\n1 1 0\n1 0 1\n", "6 2\n6 0 0\n11 1 0\n9 0 1\n21 1 1\n10 1 0\n8 0 1\n", "3 1\n3 0 1\n3 1 0\n3 0 0\n", "6 3\n7 1 1\n8 0 0\n9 1 1\n6 1 0\n10 1 1\n5 0 0\n", "8 4 3\n1 1 1\n3 1 1\n12 1 1\n12 1 1\n4 0 0\n4 0 0\n5 1 0\n5 0 1\n", "6 3 ...
IN-CORRECT
cpp
#include <bits/stdc++.h> using namespace std; const double eps = 1e-10, pi = 3.1415926535898; const int mod = 1e9 + 7, maxn = 2e5 + 10; int T, n, m, k, x, y, z, a1, b1, c1, vis[maxn]; char st[maxn]; struct P { int x, y, z; bool operator<(const P& a) const { if (x == a.x) return y < a.y; return x < a.x; } ...
1374_E1. Reading Books (easy version)
Easy and hard versions are actually different problems, so read statements of both problems completely and carefully. Summer vacation has started so Alice and Bob want to play and joy, but... Their mom doesn't think so. She says that they have to read some amount of books before all entertainments. Alice and Bob will ...
{ "input": [ "8 4\n7 1 1\n2 1 1\n4 0 1\n8 1 1\n1 0 1\n1 1 1\n1 0 1\n3 0 0\n", "5 2\n6 0 0\n9 0 0\n1 0 1\n2 1 1\n5 1 0\n", "5 3\n3 0 0\n2 1 0\n3 1 0\n5 0 1\n3 0 1\n" ], "output": [ "18\n", "8\n", "-1\n" ] }
{ "input": [ "2 1\n7 1 1\n2 1 1\n", "5 1\n2 1 0\n2 0 1\n1 0 1\n1 1 0\n1 0 1\n", "6 2\n6 0 0\n11 1 0\n9 0 1\n21 1 1\n10 1 0\n8 0 1\n", "3 1\n3 0 1\n3 1 0\n3 0 0\n", "6 3\n7 1 1\n8 0 0\n9 1 1\n6 1 0\n10 1 1\n5 0 0\n", "8 4 3\n1 1 1\n3 1 1\n12 1 1\n12 1 1\n4 0 0\n4 0 0\n5 1 0\n5 0 1\n", "6 3 ...
IN-CORRECT
java
import java.io.*; import java.util.*; import java.util.Map.Entry; import java.util.concurrent.atomic.AtomicBoolean; import java.util.stream.Collectors; public class Main { static boolean check(int s, boolean isOdd) { int l = 0; boolean checking = isOdd; for (int i = 1; i <= n; i++) { ...
1374_E1. Reading Books (easy version)
Easy and hard versions are actually different problems, so read statements of both problems completely and carefully. Summer vacation has started so Alice and Bob want to play and joy, but... Their mom doesn't think so. She says that they have to read some amount of books before all entertainments. Alice and Bob will ...
{ "input": [ "8 4\n7 1 1\n2 1 1\n4 0 1\n8 1 1\n1 0 1\n1 1 1\n1 0 1\n3 0 0\n", "5 2\n6 0 0\n9 0 0\n1 0 1\n2 1 1\n5 1 0\n", "5 3\n3 0 0\n2 1 0\n3 1 0\n5 0 1\n3 0 1\n" ], "output": [ "18\n", "8\n", "-1\n" ] }
{ "input": [ "2 1\n7 1 1\n2 1 1\n", "5 1\n2 1 0\n2 0 1\n1 0 1\n1 1 0\n1 0 1\n", "6 2\n6 0 0\n11 1 0\n9 0 1\n21 1 1\n10 1 0\n8 0 1\n", "3 1\n3 0 1\n3 1 0\n3 0 0\n", "6 3\n7 1 1\n8 0 0\n9 1 1\n6 1 0\n10 1 1\n5 0 0\n", "8 4 3\n1 1 1\n3 1 1\n12 1 1\n12 1 1\n4 0 0\n4 0 0\n5 1 0\n5 0 1\n", "6 3 ...
IN-CORRECT
python3
import os is_dev = 'vscode' in os.environ if is_dev: inF = open(f'in.txt', 'r') outF = open(f'out.txt', 'w') def ins(r): return list(map(int, r.split(' '))) def inputT(): if is_dev: return inF.readline()[:-1] else: return input() def printT(data=''): if is_dev: return...
1374_E1. Reading Books (easy version)
Easy and hard versions are actually different problems, so read statements of both problems completely and carefully. Summer vacation has started so Alice and Bob want to play and joy, but... Their mom doesn't think so. She says that they have to read some amount of books before all entertainments. Alice and Bob will ...
{ "input": [ "8 4\n7 1 1\n2 1 1\n4 0 1\n8 1 1\n1 0 1\n1 1 1\n1 0 1\n3 0 0\n", "5 2\n6 0 0\n9 0 0\n1 0 1\n2 1 1\n5 1 0\n", "5 3\n3 0 0\n2 1 0\n3 1 0\n5 0 1\n3 0 1\n" ], "output": [ "18\n", "8\n", "-1\n" ] }
{ "input": [ "2 1\n7 1 1\n2 1 1\n", "5 1\n2 1 0\n2 0 1\n1 0 1\n1 1 0\n1 0 1\n", "6 2\n6 0 0\n11 1 0\n9 0 1\n21 1 1\n10 1 0\n8 0 1\n", "3 1\n3 0 1\n3 1 0\n3 0 0\n", "6 3\n7 1 1\n8 0 0\n9 1 1\n6 1 0\n10 1 1\n5 0 0\n", "8 4 3\n1 1 1\n3 1 1\n12 1 1\n12 1 1\n4 0 0\n4 0 0\n5 1 0\n5 0 1\n", "6 3 ...
IN-CORRECT
cpp
#include <bits/stdc++.h> using namespace std; struct Obj { long long int time; int alice; int bob; }; bool sortByTime(const Obj &lhs, const Obj &rhs) { return lhs.time < rhs.time; } bool sortByAlice(const Obj &lhs, const Obj &rhs) { return lhs.alice > rhs.alice; } bool sortByBob(const Obj &lhs, const Obj &rhs) ...
1374_E1. Reading Books (easy version)
Easy and hard versions are actually different problems, so read statements of both problems completely and carefully. Summer vacation has started so Alice and Bob want to play and joy, but... Their mom doesn't think so. She says that they have to read some amount of books before all entertainments. Alice and Bob will ...
{ "input": [ "8 4\n7 1 1\n2 1 1\n4 0 1\n8 1 1\n1 0 1\n1 1 1\n1 0 1\n3 0 0\n", "5 2\n6 0 0\n9 0 0\n1 0 1\n2 1 1\n5 1 0\n", "5 3\n3 0 0\n2 1 0\n3 1 0\n5 0 1\n3 0 1\n" ], "output": [ "18\n", "8\n", "-1\n" ] }
{ "input": [ "2 1\n7 1 1\n2 1 1\n", "5 1\n2 1 0\n2 0 1\n1 0 1\n1 1 0\n1 0 1\n", "6 2\n6 0 0\n11 1 0\n9 0 1\n21 1 1\n10 1 0\n8 0 1\n", "3 1\n3 0 1\n3 1 0\n3 0 0\n", "6 3\n7 1 1\n8 0 0\n9 1 1\n6 1 0\n10 1 1\n5 0 0\n", "8 4 3\n1 1 1\n3 1 1\n12 1 1\n12 1 1\n4 0 0\n4 0 0\n5 1 0\n5 0 1\n", "6 3 ...
IN-CORRECT
python3
from heapq import * import sys int1 = lambda x: int(x) - 1 p2D = lambda x: print(*x, sep="\n") def II(): return int(sys.stdin.readline()) def MI(): return map(int, sys.stdin.readline().split()) def LI(): return list(map(int, sys.stdin.readline().split())) def LLI(rows_number): return [LI() for _ in range(rows_number)]...