id
stringlengths
11
15
title
stringlengths
7
171
problem
stringlengths
9
4.33k
solution
stringlengths
6
19k
problem_wikitext
stringlengths
9
4.42k
solution_wikitext
stringlengths
7
19.1k
proof_title
stringlengths
9
171
theorem_url
stringlengths
34
198
proof_url
stringlengths
36
198
categories
listlengths
0
9
theorem_references
listlengths
0
36
proof_references
listlengths
0
253
proofwiki-18300
Jadhav Theorem
Let $a, b, c$ be real numbers in arithmetic sequence. Let the common difference of this arithmetic sequence be $d$. Then: :$b^2 - a c = d^2$
{{begin-eqn}} {{eqn | l = b^2 - a c | r = b^2 - \paren {b + d} \paren {b - d} | c = {{Defof|Arithmetic Sequence}}: $a + d = b$, $b + d = c$ }} {{eqn | r = b^2 - \paren {b^2 - d^2} | c = Difference of Two Squares }} {{eqn | r = d^2 | c = }} {{end-eqn}} {{qed}}
Let $a, b, c$ be [[Definition:Real Number|real numbers]] in [[Definition:Arithmetic Sequence|arithmetic sequence]]. Let the [[Definition:Common Difference|common difference]] of this [[Definition:Arithmetic Sequence|arithmetic sequence]] be $d$. Then: :$b^2 - a c = d^2$
{{begin-eqn}} {{eqn | l = b^2 - a c | r = b^2 - \paren {b + d} \paren {b - d} | c = {{Defof|Arithmetic Sequence}}: $a + d = b$, $b + d = c$ }} {{eqn | r = b^2 - \paren {b^2 - d^2} | c = [[Difference of Two Squares]] }} {{eqn | r = d^2 | c = }} {{end-eqn}} {{qed}}
Jadhav Theorem
https://proofwiki.org/wiki/Jadhav_Theorem
https://proofwiki.org/wiki/Jadhav_Theorem
[ "Arithmetic Sequences", "Jadhav Theorem" ]
[ "Definition:Real Number", "Definition:Arithmetic Sequence", "Definition:Arithmetic Sequence/Common Difference", "Definition:Arithmetic Sequence" ]
[ "Difference of Two Squares" ]
proofwiki-18301
Equivalence of Definitions of P-adic Norms
Let $p \in \N$ be a prime. Let $\Q$ denote the rational numbers. {{TFAE|def = P-adic Norm|view = $p$-adic norm on $\Q$}} === Definition 1 === {{:Definition:P-adic Norm/Rational Numbers/Definition 1}} === Definition 2 === {{:Definition:P-adic Norm/Rational Numbers/Definition 2}}
From Negative Powers of Group Elements, Definition 2 can be rewritten as: :$\forall r \in \Q: \norm r_p = \begin {cases} 0 & : r = 0 \\ p^{-k} & : r = p^k \dfrac m n: k, m, n \in \Z, p \nmid m, n \end {cases}$ Hence if follows that Definition 1 and Definition 2 are equivalent if it is shown: :$\forall r \in \Q_{\ne 0}:...
Let $p \in \N$ be a [[Definition:Prime Number|prime]]. Let $\Q$ denote the [[Definition:Rational Numbers|rational numbers]]. {{TFAE|def = P-adic Norm|view = $p$-adic norm on $\Q$}} === [[Definition:P-adic Norm/Rational Numbers/Definition 1|Definition 1]] === {{:Definition:P-adic Norm/Rational Numbers/Definition 1}}...
From [[Negative Powers of Group Elements]], [[Definition:P-adic Norm/Rational Numbers/Definition 2|Definition 2]] can be rewritten as: :$\forall r \in \Q: \norm r_p = \begin {cases} 0 & : r = 0 \\ p^{-k} & : r = p^k \dfrac m n: k, m, n \in \Z, p \nmid m, n \end {cases}$ Hence if follows that [[Definition:P-adic Norm/...
Equivalence of Definitions of P-adic Norms
https://proofwiki.org/wiki/Equivalence_of_Definitions_of_P-adic_Norms
https://proofwiki.org/wiki/Equivalence_of_Definitions_of_P-adic_Norms
[ "Equivalence of Definitions of P-adic Norms", "P-adic Norms" ]
[ "Definition:Prime Number", "Definition:Rational Number", "Definition:P-adic Norm/Rational Numbers/Definition 1", "Definition:P-adic Norm/Rational Numbers/Definition 2" ]
[ "Powers of Group Elements/Negative Index", "Definition:P-adic Norm/Rational Numbers/Definition 2", "Definition:P-adic Norm/Rational Numbers/Definition 1", "Definition:P-adic Norm/Rational Numbers/Definition 2" ]
proofwiki-18302
Equivalence of Definitions of P-adic Norms/Lemma 1
:$\forall x \in Z_{\ne 0}: \map {\nu_p} x = k : x = p^k y : p \nmid y$
Let $x \in \Z_{\ne 0}$. By definition of the $p$-adic valuation: :$\map {\nu_p} x = \sup \set {v \in \N: p^v \divides x}$ Let $\map {\nu_p} x = k$. Then: :$p^k \nmid x$ By definition of a divisor: :$\exists y \in Z : x = p^k y$ {{AimForCont}}: :$p \divides y$ By definition of a divisor: :$\exists y' \in Z : y = p y'$ H...
:$\forall x \in Z_{\ne 0}: \map {\nu_p} x = k : x = p^k y : p \nmid y$
Let $x \in \Z_{\ne 0}$. By definition of the [[Definition:Restricted P-adic Valuation|$p$-adic valuation]]: :$\map {\nu_p} x = \sup \set {v \in \N: p^v \divides x}$ Let $\map {\nu_p} x = k$. Then: :$p^k \nmid x$ By definition of a [[Definition:Divisor of Integer|divisor]]: :$\exists y \in Z : x = p^k y$ {{AimForC...
Equivalence of Definitions of P-adic Norms/Lemma 1
https://proofwiki.org/wiki/Equivalence_of_Definitions_of_P-adic_Norms/Lemma_1
https://proofwiki.org/wiki/Equivalence_of_Definitions_of_P-adic_Norms/Lemma_1
[ "Equivalence of Definitions of P-adic Norms" ]
[]
[ "Definition:P-adic Valuation/Integers", "Definition:Divisor (Algebra)/Integer", "Definition:Divisor (Algebra)/Integer", "Definition:Contradiction", "Category:Equivalence of Definitions of P-adic Norms" ]
proofwiki-18303
Distributional Derivative of Absolute Value Function
Let $H: \R \to \closedint 0 1$ be the Heaviside step function. Let $\size x$ be the absolute value of $x$. Let $T_{\size x}$ be the Schwartz distribution associated with $\size x$. Then the distributional derivative of $T_{\size x}$ is $T_{2 H - 1}$
{{begin-eqn}} {{eqn | l = \dfrac {\d \size x} {\d x} | r = <nowiki>\begin{cases} 1 & : x > 0 \\ -1 & : x < 0 \end{cases} </nowiki> }} {{eqn | r = -1 + <nowiki>\begin{cases} 2 & : x > 0 \\ 0 & : x < 0 \end{cas...
Let $H: \R \to \closedint 0 1$ be the [[Definition:Heaviside Step Function|Heaviside step function]]. Let $\size x$ be the [[Definition:Absolute Value|absolute value]] of $x$. Let $T_{\size x}$ be the [[Definition:Schwartz Distribution|Schwartz distribution]] associated with $\size x$. Then the [[Definition:Distrib...
{{begin-eqn}} {{eqn | l = \dfrac {\d \size x} {\d x} | r = <nowiki>\begin{cases} 1 & : x > 0 \\ -1 & : x < 0 \end{cases} </nowiki> }} {{eqn | r = -1 + <nowiki>\begin{cases} 2 & : x > 0 \\ 0 & : x < 0 \end{cas...
Distributional Derivative of Absolute Value Function
https://proofwiki.org/wiki/Distributional_Derivative_of_Absolute_Value_Function
https://proofwiki.org/wiki/Distributional_Derivative_of_Absolute_Value_Function
[ "Absolute Value Function", "Distributional Derivatives" ]
[ "Definition:Heaviside Step Function", "Definition:Absolute Value", "Definition:Schwartz Distribution", "Definition:Distributional Derivative" ]
[ "Jump Rule" ]
proofwiki-18304
Moment Generating Function of Geometric Distribution/Formulation 1
:$\map X \Omega = \set {0, 1, 2, \ldots} = \N$ :$\map \Pr {X = k} = \paren {1 - p} p^k$ Then the moment generating function $M_X$ of $X$ is given by: :$\map {M_X} t = \dfrac {1 - p} {1 - p e^t}$ for $t < -\map \ln p$, and is undefined otherwise.
From the definition of the geometric distribution, $X$ has probability mass function: :$\map \Pr {X = k} = \paren {1 - p} p^k$ From the definition of a moment generating function: :$\ds \map {M_X} t = \expect {e^{t X} } = \sum_{k \mathop = 0}^\infty \map \Pr {X = k} e^{k t}$ So: {{begin-eqn}} {{eqn | l = \sum_{k \matho...
:$\map X \Omega = \set {0, 1, 2, \ldots} = \N$ :$\map \Pr {X = k} = \paren {1 - p} p^k$ Then the [[Definition:Moment Generating Function|moment generating function]] $M_X$ of $X$ is given by: :$\map {M_X} t = \dfrac {1 - p} {1 - p e^t}$ for $t < -\map \ln p$, and is undefined otherwise.
From the definition of the [[Definition:Geometric Distribution|geometric distribution]], $X$ has [[Definition:Probability Mass Function|probability mass function]]: :$\map \Pr {X = k} = \paren {1 - p} p^k$ From the definition of a [[Definition:Moment Generating Function|moment generating function]]: :$\ds \map {M_X}...
Moment Generating Function of Geometric Distribution/Formulation 1
https://proofwiki.org/wiki/Moment_Generating_Function_of_Geometric_Distribution/Formulation_1
https://proofwiki.org/wiki/Moment_Generating_Function_of_Geometric_Distribution/Formulation_1
[ "Moment Generating Function of Geometric Distribution" ]
[ "Definition:Moment Generating Function" ]
[ "Definition:Geometric Distribution", "Definition:Probability Mass Function", "Definition:Moment Generating Function", "Sum of Infinite Geometric Sequence", "Logarithm of Power", "Sum of Infinite Geometric Sequence" ]
proofwiki-18305
Moment Generating Function of Geometric Distribution/Formulation 2
:$\map X \Omega = \set {0, 1, 2, \ldots} = \N$ :$\map \Pr {X = k} = p \paren {1 - p}^k$ Then the moment generating function $M_X$ of $X$ is given by: :$\map {M_X} t = \dfrac p {1 - \paren {1 - p} e^t}$ for $t < -\map \ln {1 - p}$, and is undefined otherwise.
From the definition of the geometric distribution, $X$ has probability mass function: :$\map \Pr {X = k} = p \paren {1 - p}^k$ From the definition of a moment generating function: :$\ds \map {M_X} t = \expect {e^{t X} } = \sum_{k \mathop = 0}^\infty \map \Pr {X = k} e^{k t}$ So: {{begin-eqn}} {{eqn | l = \sum_{k \matho...
:$\map X \Omega = \set {0, 1, 2, \ldots} = \N$ :$\map \Pr {X = k} = p \paren {1 - p}^k$ Then the [[Definition:Moment Generating Function|moment generating function]] $M_X$ of $X$ is given by: :$\map {M_X} t = \dfrac p {1 - \paren {1 - p} e^t}$ for $t < -\map \ln {1 - p}$, and is undefined otherwise.
From the definition of the [[Definition:Geometric Distribution|geometric distribution]], $X$ has [[Definition:Probability Mass Function|probability mass function]]: :$\map \Pr {X = k} = p \paren {1 - p}^k$ From the definition of a [[Definition:Moment Generating Function|moment generating function]]: :$\ds \map {M_X}...
Moment Generating Function of Geometric Distribution/Formulation 2
https://proofwiki.org/wiki/Moment_Generating_Function_of_Geometric_Distribution/Formulation_2
https://proofwiki.org/wiki/Moment_Generating_Function_of_Geometric_Distribution/Formulation_2
[ "Moment Generating Function of Geometric Distribution" ]
[ "Definition:Moment Generating Function" ]
[ "Definition:Geometric Distribution", "Definition:Probability Mass Function", "Definition:Moment Generating Function", "Sum of Infinite Geometric Sequence", "Logarithm of Power", "Sum of Infinite Geometric Sequence" ]
proofwiki-18306
Expectation of Geometric Distribution/Formulation 1
:$\map X \Omega = \set {0, 1, 2, \ldots} = \N$ :$\map \Pr {X = k} = \paren {1 - p} p^k$ Then the expectation of $X$ is given by: :$\expect X = \dfrac p {1 - p}$
From the Probability Generating Function of Geometric Distribution: :$\map {\Pi_X} s = \dfrac q {1 - p s}$ where $q = 1 - p$. From Expectation of Discrete Random Variable from PGF: :$\expect X = \map {\Pi'_X} 1$ We have: {{begin-eqn}} {{eqn | l = \map {\Pi'_X} s | r = \map {\frac \d {\d s} } {\frac q {1 - p s} } ...
:$\map X \Omega = \set {0, 1, 2, \ldots} = \N$ :$\map \Pr {X = k} = \paren {1 - p} p^k$ Then the [[Definition:Expectation|expectation]] of $X$ is given by: :$\expect X = \dfrac p {1 - p}$
From the [[Probability Generating Function of Geometric Distribution]]: :$\map {\Pi_X} s = \dfrac q {1 - p s}$ where $q = 1 - p$. From [[Expectation of Discrete Random Variable from PGF]]: :$\expect X = \map {\Pi'_X} 1$ We have: {{begin-eqn}} {{eqn | l = \map {\Pi'_X} s | r = \map {\frac \d {\d s} } {\fra...
Expectation of Geometric Distribution/Formulation 1/Proof 2
https://proofwiki.org/wiki/Expectation_of_Geometric_Distribution/Formulation_1
https://proofwiki.org/wiki/Expectation_of_Geometric_Distribution/Formulation_1/Proof_2
[ "Expectation of Geometric Distribution" ]
[ "Definition:Expectation" ]
[ "Probability Generating Function of Geometric Distribution", "Expectation of Discrete Random Variable from PGF", "Derivatives of PGF of Geometric Distribution" ]
proofwiki-18307
Expectation of Geometric Distribution/Formulation 1
:$\map X \Omega = \set {0, 1, 2, \ldots} = \N$ :$\map \Pr {X = k} = \paren {1 - p} p^k$ Then the expectation of $X$ is given by: :$\expect X = \dfrac p {1 - p}$
From the definition of expectation: :$\ds \expect X = \sum_{x \mathop \in \Omega_X} x \map \Pr {X = x}$ Then {{begin-eqn}} {{eqn | l = \expect X | r = \sum_{k \mathop \in \N} k p^k \paren {1 - p} | c = {{Defof|Geometric Distribution}} }} {{eqn | r = \sum_{k \mathop \ge 1} k p^k \paren {1 - p} | c = as...
:$\map X \Omega = \set {0, 1, 2, \ldots} = \N$ :$\map \Pr {X = k} = \paren {1 - p} p^k$ Then the [[Definition:Expectation|expectation]] of $X$ is given by: :$\expect X = \dfrac p {1 - p}$
From the definition of [[Definition:Expectation|expectation]]: :$\ds \expect X = \sum_{x \mathop \in \Omega_X} x \map \Pr {X = x}$ Then {{begin-eqn}} {{eqn | l = \expect X | r = \sum_{k \mathop \in \N} k p^k \paren {1 - p} | c = {{Defof|Geometric Distribution}} }} {{eqn | r = \sum_{k \mathop \ge 1} k p^k ...
Expectation of Geometric Distribution/Formulation 1/Proof 3
https://proofwiki.org/wiki/Expectation_of_Geometric_Distribution/Formulation_1
https://proofwiki.org/wiki/Expectation_of_Geometric_Distribution/Formulation_1/Proof_3
[ "Expectation of Geometric Distribution" ]
[ "Definition:Expectation" ]
[ "Definition:Expectation", "Real Multiplication Distributes over Addition", "Ratio Test", "Absolutely Convergent Series is Convergent/Real Numbers", "Convergent Series can be Added Term by Term", "Translation of Index Variable of Summation", "Sum of Infinite Geometric Sequence" ]
proofwiki-18308
Variance of Geometric Distribution/Formulation 1
:$\map X \Omega = \set {0, 1, 2, \ldots} = \N$ :$\map \Pr {X = k} = \paren {1 - p} p^k$ Then the variance of $X$ is given by: :$\var X = \dfrac p {\paren {1-p}^2}$
From Variance of Discrete Random Variable from PGF, we have: :$\var X = \map {\Pi' '_X} 1 + \mu - \mu^2$ where $\mu = \map E x$ is the expectation of $X$. From the Probability Generating Function of Geometric Distribution, we have: :$\map {\Pi_X} s = \dfrac q {1 - ps}$ where $q = 1 - p$. From Expectation of Geometric D...
:$\map X \Omega = \set {0, 1, 2, \ldots} = \N$ :$\map \Pr {X = k} = \paren {1 - p} p^k$ Then the [[Definition:Variance|variance]] of $X$ is given by: :$\var X = \dfrac p {\paren {1-p}^2}$
From [[Variance of Discrete Random Variable from PGF]], we have: :$\var X = \map {\Pi' '_X} 1 + \mu - \mu^2$ where $\mu = \map E x$ is the [[Definition:Expectation|expectation]] of $X$. From the [[Probability Generating Function of Geometric Distribution]], we have: :$\map {\Pi_X} s = \dfrac q {1 - ps}$ where $q = 1 ...
Variance of Geometric Distribution/Formulation 1/Proof 2
https://proofwiki.org/wiki/Variance_of_Geometric_Distribution/Formulation_1
https://proofwiki.org/wiki/Variance_of_Geometric_Distribution/Formulation_1/Proof_2
[ "Variance", "Variance of Geometric Distribution" ]
[ "Definition:Variance" ]
[ "Variance of Discrete Random Variable from PGF", "Definition:Expectation", "Probability Generating Function of Geometric Distribution", "Expectation of Geometric Distribution", "Derivatives of PGF of Geometric Distribution" ]
proofwiki-18309
Distributional Derivative of Floor Function
Let $\floor x$ be the floor function. Let $\map {\operatorname {III} } x$ be the Dirac comb. Then the distributional derivative of $\floor x$ is $\map {\operatorname {III} } 0$.
By definition: :$\floor x := \sup \set {m \in \Z: m \le x}$ Hence, $\forall m \in \Z : \forall x \in \openint m {m + 1}$ the floor function is constant. Therefore: :$\forall m \in \Z : \forall x \in \openint m {m + 1} : \dfrac {\d \floor x} {\d x} = 0$ Every $x \in \Z$ is a discontinuity of $\floor x$. Hence, the jump ...
Let $\floor x$ be the [[Definition:Floor Function|floor function]]. Let $\map {\operatorname {III} } x$ be the [[Definition:Dirac Comb|Dirac comb]]. Then the [[Definition:Distributional Derivative|distributional derivative]] of $\floor x$ is $\map {\operatorname {III} } 0$.
By [[Definition:Floor Function/Definition 1|definition]]: :$\floor x := \sup \set {m \in \Z: m \le x}$ Hence, $\forall m \in \Z : \forall x \in \openint m {m + 1}$ the [[Definition:Floor Function|floor function]] is [[Definition:Constant Function|constant]]. Therefore: :$\forall m \in \Z : \forall x \in \openint m ...
Distributional Derivative of Floor Function
https://proofwiki.org/wiki/Distributional_Derivative_of_Floor_Function
https://proofwiki.org/wiki/Distributional_Derivative_of_Floor_Function
[ "Floor Function", "Distributional Derivatives" ]
[ "Definition:Floor Function", "Definition:Sampling Function", "Definition:Distributional Derivative" ]
[ "Definition:Floor Function/Definition 1", "Definition:Floor Function", "Definition:Constant Mapping", "Definition:Discontinuity (Real Analysis)/Jump", "Jump Rule", "Jump Rule" ]
proofwiki-18310
Variance of Geometric Distribution/Formulation 2
:$\map X \Omega = \set {0, 1, 2, \ldots} = \N$ :$\map \Pr {X = k} = p \paren {1 - p}^k$ Then the variance of $X$ is given by: :$\var X = \dfrac {1 - p} {p^2}$
By Moment Generating Function of Geometric Distribution, the moment generating function of $X$ is given by: :$\map {M_X} t = \dfrac p {1 - \paren {1 - p} e^t}$ for $t < -\map \ln {1 - p}$, and is undefined otherwise. From Variance as Expectation of Square minus Square of Expectation: :$\ds \var X = \expect {X^2} - \p...
:$\map X \Omega = \set {0, 1, 2, \ldots} = \N$ :$\map \Pr {X = k} = p \paren {1 - p}^k$ Then the [[Definition:Variance|variance]] of $X$ is given by: :$\var X = \dfrac {1 - p} {p^2}$
By [[Moment Generating Function of Geometric Distribution]], the [[Definition:Moment Generating Function|moment generating function]] of $X$ is given by: :$\map {M_X} t = \dfrac p {1 - \paren {1 - p} e^t}$ for $t < -\map \ln {1 - p}$, and is undefined otherwise. From [[Variance as Expectation of Square minus Squar...
Variance of Geometric Distribution/Formulation 2/Proof 2
https://proofwiki.org/wiki/Variance_of_Geometric_Distribution/Formulation_2
https://proofwiki.org/wiki/Variance_of_Geometric_Distribution/Formulation_2/Proof_2
[ "Variance", "Variance of Geometric Distribution" ]
[ "Definition:Variance" ]
[ "Moment Generating Function of Geometric Distribution", "Definition:Moment Generating Function", "Variance as Expectation of Square minus Square of Expectation", "Expectation of Geometric Distribution/Formulation 2", "Moment Generating Function of Geometric Distribution/Formulation 2/Examples/Second Moment"...
proofwiki-18311
Union of Union of Cartesian Product
Let $A$ and $B$ be sets such that $A \ne \O$ and $B \ne \O$. Let the ordered pair $\tuple {a, b}$ be defined using the Kuratowski formalization: :$\tuple {a, b} := \set {\set a, \set {a, b} }$ Then: :$\ds \bigcup \bigcup \paren {A \times B} = A \cup B$ where: :$\cup$ denotes union :$\times$ denotes Cartesian product.
{{begin-eqn}} {{eqn | l = \bigcup \bigcup \paren {A \times B} | r = \bigcup \bigcup \set {\tuple {a, b}: a \in A, b \in B} | c = {{Defof|Cartesian Product}} }} {{eqn | r = \bigcup \paren {\bigcup \set {\set {\set a, \set {a, b} }: a \in A, b \in B} } | c = {{Defof|Kuratowski Formalization of Ordered P...
Let $A$ and $B$ be [[Definition:Set|sets]] such that $A \ne \O$ and $B \ne \O$. Let the [[Definition:Ordered Pair|ordered pair]] $\tuple {a, b}$ be defined using the [[Definition:Kuratowski Formalization of Ordered Pair|Kuratowski formalization]]: :$\tuple {a, b} := \set {\set a, \set {a, b} }$ Then: :$\ds \bigcup \b...
{{begin-eqn}} {{eqn | l = \bigcup \bigcup \paren {A \times B} | r = \bigcup \bigcup \set {\tuple {a, b}: a \in A, b \in B} | c = {{Defof|Cartesian Product}} }} {{eqn | r = \bigcup \paren {\bigcup \set {\set {\set a, \set {a, b} }: a \in A, b \in B} } | c = {{Defof|Kuratowski Formalization of Ordered P...
Union of Union of Cartesian Product
https://proofwiki.org/wiki/Union_of_Union_of_Cartesian_Product
https://proofwiki.org/wiki/Union_of_Union_of_Cartesian_Product
[ "Set Union", "Cartesian Product" ]
[ "Definition:Set", "Definition:Ordered Pair", "Definition:Ordered Pair/Kuratowski Formalization", "Definition:Set Union", "Definition:Cartesian Product" ]
[]
proofwiki-18312
Union of Union of Cartesian Product with Empty Factor
Let $A$ and $B$ be sets such that either $A = \O$ or $B = \O$. Let the ordered pair $\tuple {a, b}$ be defined using the Kuratowski formalization: :$\tuple {a, b} := \set {\set a, \set {a, b} }$ Then: :$\ds \bigcup \bigcup \paren {A \times B} = A \cup B \iff A = B = \O$ where: :$\cup$ denotes union :$\times$ denotes Ca...
Let $A = \O$ or $B = \O$. From Cartesian Product is Empty iff Factor is Empty: :$A \times B = \O$ Hence from Union of Empty Set: :$\ds \bigcup \bigcup \paren {A \times B} = \O$ However, from Union is Empty iff Sets are Empty: :$A \cup B = \O \iff A = \O \text { and } B = \O$ The result follows. {{qed}}
Let $A$ and $B$ be [[Definition:Set|sets]] such that either $A = \O$ or $B = \O$. Let the [[Definition:Ordered Pair|ordered pair]] $\tuple {a, b}$ be defined using the [[Definition:Kuratowski Formalization of Ordered Pair|Kuratowski formalization]]: :$\tuple {a, b} := \set {\set a, \set {a, b} }$ Then: :$\ds \bigcup...
Let $A = \O$ or $B = \O$. From [[Cartesian Product is Empty iff Factor is Empty]]: :$A \times B = \O$ Hence from [[Union of Empty Set]]: :$\ds \bigcup \bigcup \paren {A \times B} = \O$ However, from [[Union is Empty iff Sets are Empty]]: :$A \cup B = \O \iff A = \O \text { and } B = \O$ The result follows. {{qed}}
Union of Union of Cartesian Product with Empty Factor
https://proofwiki.org/wiki/Union_of_Union_of_Cartesian_Product_with_Empty_Factor
https://proofwiki.org/wiki/Union_of_Union_of_Cartesian_Product_with_Empty_Factor
[ "Set Union", "Cartesian Product" ]
[ "Definition:Set", "Definition:Ordered Pair", "Definition:Ordered Pair/Kuratowski Formalization", "Definition:Set Union", "Definition:Cartesian Product", "Definition:Empty Set", "Definition:Empty Set" ]
[ "Cartesian Product is Empty iff Factor is Empty", "Union of Empty Set", "Union is Empty iff Sets are Empty" ]
proofwiki-18313
Skewness of Geometric Distribution/Formulation 2
:$\map X \Omega = \set {0, 1, 2, \ldots} = \N$ :$\map \Pr {X = k} = p \paren {1 - p}^k$ Then the skewness of $X$ is given by: :$\gamma_1 = \dfrac {2 - p} {\sqrt {1 - p} }$
From the definition of skewness, we have: :$\gamma_1 = \expect {\paren {\dfrac {X - \mu} \sigma}^3}$ where: :$\mu$ is the expectation of $X$. :$\sigma$ is the standard deviation of $X$. By Expectation of Geometric Distribution: Formulation 2, we have: :$\mu = \dfrac {1 - p} p$ By Variance of Geometric Distribution:...
:$\map X \Omega = \set {0, 1, 2, \ldots} = \N$ :$\map \Pr {X = k} = p \paren {1 - p}^k$ Then the [[Definition:Skewness|skewness]] of $X$ is given by: :$\gamma_1 = \dfrac {2 - p} {\sqrt {1 - p} }$
From the definition of [[Definition:Skewness|skewness]], we have: :$\gamma_1 = \expect {\paren {\dfrac {X - \mu} \sigma}^3}$ where: :$\mu$ is the [[Definition:Expectation|expectation]] of $X$. :$\sigma$ is the [[Definition:Standard Deviation|standard deviation]] of $X$. By [[Expectation of Geometric Distribution/...
Skewness of Geometric Distribution/Formulation 2
https://proofwiki.org/wiki/Skewness_of_Geometric_Distribution/Formulation_2
https://proofwiki.org/wiki/Skewness_of_Geometric_Distribution/Formulation_2
[ "Skewness of Geometric Distribution", "Skewness" ]
[ "Definition:Skewness" ]
[ "Definition:Skewness", "Definition:Expectation", "Definition:Standard Deviation", "Expectation of Geometric Distribution/Formulation 2", "Variance of Geometric Distribution/Formulation 2", "Binomial Theorem/Examples/Cube of Difference", "Expectation is Linear", "Moment in terms of Moment Generating Fu...
proofwiki-18314
Skewness of Geometric Distribution/Formulation 1
:$\map X \Omega = \set {0, 1, 2, \ldots} = \N$ :$\map \Pr {X = k} = \paren {1 - p} p^k$ Then the skewness of $X$ is given by: :$\gamma_1 = \dfrac {1 + p} {\sqrt p}$
From the definition of skewness, we have: :$\gamma_1 = \expect {\paren {\dfrac {X - \mu} \sigma}^3}$ where: :$\mu$ is the expectation of $X$. :$\sigma$ is the standard deviation of $X$. By Expectation of Geometric Distribution: Formulation 1, we have: :$\mu = \dfrac p {1 - p}$ By Variance of Geometric Distribution:...
:$\map X \Omega = \set {0, 1, 2, \ldots} = \N$ :$\map \Pr {X = k} = \paren {1 - p} p^k$ Then the [[Definition:Skewness|skewness]] of $X$ is given by: :$\gamma_1 = \dfrac {1 + p} {\sqrt p}$
From the definition of [[Definition:Skewness|skewness]], we have: :$\gamma_1 = \expect {\paren {\dfrac {X - \mu} \sigma}^3}$ where: :$\mu$ is the [[Definition:Expectation|expectation]] of $X$. :$\sigma$ is the [[Definition:Standard Deviation|standard deviation]] of $X$. By [[Expectation of Geometric Distribution/...
Skewness of Geometric Distribution/Formulation 1
https://proofwiki.org/wiki/Skewness_of_Geometric_Distribution/Formulation_1
https://proofwiki.org/wiki/Skewness_of_Geometric_Distribution/Formulation_1
[ "Skewness of Geometric Distribution", "Skewness" ]
[ "Definition:Skewness" ]
[ "Definition:Skewness", "Definition:Expectation", "Definition:Standard Deviation", "Expectation of Geometric Distribution/Formulation 1", "Variance of Geometric Distribution/Formulation 1", "Binomial Theorem/Examples/Cube of Difference", "Expectation is Linear", "Moment in terms of Moment Generating Fu...
proofwiki-18315
Excess Kurtosis of Geometric Distribution/Formulation 2
:$\map X \Omega = \set {0, 1, 2, \ldots} = \N$ :$\map \Pr {X = k} = p \paren {1 - p}^k$ Then the excess kurtosis $\gamma_2$ of $X$ is given by: :$\gamma_2 = 6 + \dfrac {p^2} {1 - p}$
From the definition of excess kurtosis, we have: :$\gamma_2 = \expect {\paren {\dfrac {X - \mu} \sigma}^4} - 3$ where: :$\mu$ is the expectation of $X$. :$\sigma$ is the standard deviation of $X$. By Expectation of Geometric Distribution: Formulation 2, we have: :$\mu = \dfrac {1 - p} p$ By Variance of Geometric Di...
:$\map X \Omega = \set {0, 1, 2, \ldots} = \N$ :$\map \Pr {X = k} = p \paren {1 - p}^k$ Then the [[Definition:Excess Kurtosis|excess kurtosis]] $\gamma_2$ of $X$ is given by: :$\gamma_2 = 6 + \dfrac {p^2} {1 - p}$
From the definition of [[Definition:Excess Kurtosis|excess kurtosis]], we have: :$\gamma_2 = \expect {\paren {\dfrac {X - \mu} \sigma}^4} - 3$ where: :$\mu$ is the [[Definition:Expectation|expectation]] of $X$. :$\sigma$ is the [[Definition:Standard Deviation|standard deviation]] of $X$. By [[Expectation of Geome...
Excess Kurtosis of Geometric Distribution/Formulation 2
https://proofwiki.org/wiki/Excess_Kurtosis_of_Geometric_Distribution/Formulation_2
https://proofwiki.org/wiki/Excess_Kurtosis_of_Geometric_Distribution/Formulation_2
[ "Excess Kurtosis of Geometric Distribution" ]
[ "Definition:Excess Kurtosis" ]
[ "Definition:Excess Kurtosis", "Definition:Expectation", "Definition:Standard Deviation", "Expectation of Geometric Distribution/Formulation 2", "Variance of Geometric Distribution/Formulation 2", "Kurtosis in terms of Non-Central Moments", "Skewness of Geometric Distribution/Formulation 2", "Definitio...
proofwiki-18316
Excess Kurtosis of Geometric Distribution/Formulation 1
:$\map X \Omega = \set {0, 1, 2, \ldots} = \N$ :$\map \Pr {X = k} = \paren {1 - p} p^k$ Then the excess kurtosis $\gamma_2$ of $X$ is given by: :$\gamma_2 = 6 + \dfrac {\paren {1 - p}^2} p$
From the definition of excess kurtosis, we have: :$\gamma_2 = \expect {\paren {\dfrac {X - \mu} \sigma}^4} - 3$ where: :$\mu$ is the expectation of $X$. :$\sigma$ is the standard deviation of $X$. By Expectation of Geometric Distribution: Formulation 1, we have: :$\mu = \dfrac p {1 - p}$ By Variance of Geometric Di...
:$\map X \Omega = \set {0, 1, 2, \ldots} = \N$ :$\map \Pr {X = k} = \paren {1 - p} p^k$ Then the [[Definition:Excess Kurtosis|excess kurtosis]] $\gamma_2$ of $X$ is given by: :$\gamma_2 = 6 + \dfrac {\paren {1 - p}^2} p$
From the definition of [[Definition:Excess Kurtosis|excess kurtosis]], we have: :$\gamma_2 = \expect {\paren {\dfrac {X - \mu} \sigma}^4} - 3$ where: :$\mu$ is the [[Definition:Expectation|expectation]] of $X$. :$\sigma$ is the [[Definition:Standard Deviation|standard deviation]] of $X$. By [[Expectation of Geome...
Excess Kurtosis of Geometric Distribution/Formulation 1
https://proofwiki.org/wiki/Excess_Kurtosis_of_Geometric_Distribution/Formulation_1
https://proofwiki.org/wiki/Excess_Kurtosis_of_Geometric_Distribution/Formulation_1
[ "Excess Kurtosis of Geometric Distribution" ]
[ "Definition:Excess Kurtosis" ]
[ "Definition:Excess Kurtosis", "Definition:Expectation", "Definition:Standard Deviation", "Expectation of Geometric Distribution/Formulation 1", "Variance of Geometric Distribution/Formulation 1", "Kurtosis in terms of Non-Central Moments", "Skewness of Geometric Distribution/Formulation 1", "Definitio...
proofwiki-18317
Distributional Derivative of Heaviside Step Function times Cosine
Let $H$ be the Heaviside step function. Let $\delta$ be the Dirac delta distribution. Then in the distributional sense: :$T'_{\map H x \cos x} = T_{- \map H x \sin x} + \delta$
$x \stackrel f {\longrightarrow} \map H x \cos x$ is a continuously differentiable real function on $\R \setminus \set 0$ and has a discontinuity at $x = 0$. By Differentiable Function as Distribution we have that: :$T'_f = T_{f'}$ Moreover: :$x < 0 \implies \paren { {\map H x} \map \cos x}' = 0$ :$x > 0 \implies \pare...
Let $H$ be the [[Definition:Heaviside Step Function|Heaviside step function]]. Let $\delta$ be the [[Definition:Dirac Delta Distribution|Dirac delta distribution]]. Then in the [[Definition:Distributional Derivative|distributional sense]]: :$T'_{\map H x \cos x} = T_{- \map H x \sin x} + \delta$
$x \stackrel f {\longrightarrow} \map H x \cos x$ is a [[Definition:Continuously Differentiable Real Function on Open Interval|continuously differentiable real function]] on $\R \setminus \set 0$ and has a [[Definition:Jump Discontinuity|discontinuity]] at $x = 0$. By [[Differentiable Function as Distribution]] we hav...
Distributional Derivative of Heaviside Step Function times Cosine
https://proofwiki.org/wiki/Distributional_Derivative_of_Heaviside_Step_Function_times_Cosine
https://proofwiki.org/wiki/Distributional_Derivative_of_Heaviside_Step_Function_times_Cosine
[ "Examples of Distributional Derivatives", "Piecewise Continuously Differentiable Functions" ]
[ "Definition:Heaviside Step Function", "Definition:Dirac Delta Distribution", "Definition:Distributional Derivative" ]
[ "Definition:Continuously Differentiable/Real Function/Open Interval", "Definition:Discontinuity (Real Analysis)/Jump", "Differentiable Function as Distribution", "Jump Rule" ]
proofwiki-18318
Distributional Derivative of Heaviside Step Function times Sine
Let $H$ be the Heaviside step function. Let $\delta$ be the Dirac delta distribution. Then in the distributional sense: :$T'_{\map H x \sin x} = T_{\map H x \cos x} $
$x \stackrel f {\longrightarrow} \map H x \sin x$ is a continuously differentiable real function on $\R \setminus \set 0$ and possibly has a discontinuity at $x = 0$. By Differentiable Function as Distribution we have that $T'_f = T_{f'}$. Moreover: :$x < 0 \implies \paren { {\map H x} \map \sin x}' = 0$. :$x > 0 \imp...
Let $H$ be the [[Definition:Heaviside Step Function|Heaviside step function]]. Let $\delta$ be the [[Definition:Dirac Delta Distribution|Dirac delta distribution]]. Then in the [[Definition:Distributional Derivative|distributional sense]]: :$T'_{\map H x \sin x} = T_{\map H x \cos x} $
$x \stackrel f {\longrightarrow} \map H x \sin x$ is a [[Definition:Continuously Differentiable Real Function on Open Interval|continuously differentiable real function]] on $\R \setminus \set 0$ and possibly has a [[Definition:Discontinuous|discontinuity]] at $x = 0$. By [[Differentiable Function as Distribution]] w...
Distributional Derivative of Heaviside Step Function times Sine
https://proofwiki.org/wiki/Distributional_Derivative_of_Heaviside_Step_Function_times_Sine
https://proofwiki.org/wiki/Distributional_Derivative_of_Heaviside_Step_Function_times_Sine
[ "Examples of Distributional Derivatives", "Piecewise Continuously Differentiable Functions" ]
[ "Definition:Heaviside Step Function", "Definition:Dirac Delta Distribution", "Definition:Distributional Derivative" ]
[ "Definition:Continuously Differentiable/Real Function/Open Interval", "Definition:Discontinuous", "Differentiable Function as Distribution", "Jump Rule" ]
proofwiki-18319
Moment Generating Function of Logistic Distribution
Let $X$ be a continuous random variable which satisfies the logistic distribution: :$X \sim \map {\operatorname {Logistic} } {\mu, s}$ for some $\mu \in \R, s \in \R_{> 0}$. Then the moment generating function $M_X$ of $X$ is given by: :$\map {M_X} t = \begin {cases} \map \exp {\mu t} \map \Beta {\paren {1 - s t}, \p...
From the definition of the logistic distribution, $X$ has probability density function: :$\map {f_X} x = \dfrac {\map \exp {-\dfrac {\paren {x - \mu} } s} } {s \paren {1 + \map \exp {-\dfrac {\paren {x - \mu} } s} }^2}$ From the definition of a moment generating function: :$\ds \map {M_X} t = \expect { e^{t X} } = \int...
Let $X$ be a [[Definition:Continuous Random Variable|continuous random variable]] which satisfies the [[Definition:Logistic Distribution|logistic distribution]]: :$X \sim \map {\operatorname {Logistic} } {\mu, s}$ for some $\mu \in \R, s \in \R_{> 0}$. Then the [[Definition:Moment Generating Function|moment generat...
From the definition of the [[Definition:Logistic Distribution|logistic distribution]], $X$ has [[Definition:Probability Density Function|probability density function]]: :$\map {f_X} x = \dfrac {\map \exp {-\dfrac {\paren {x - \mu} } s} } {s \paren {1 + \map \exp {-\dfrac {\paren {x - \mu} } s} }^2}$ From the definiti...
Moment Generating Function of Logistic Distribution
https://proofwiki.org/wiki/Moment_Generating_Function_of_Logistic_Distribution
https://proofwiki.org/wiki/Moment_Generating_Function_of_Logistic_Distribution
[ "Moment Generating Functions", "Logistic Distribution", "Moment Generating Function of Logistic Distribution" ]
[ "Definition:Random Variable/Continuous", "Definition:Logistic Distribution", "Definition:Moment Generating Function", "Definition:Beta Function" ]
[ "Definition:Logistic Distribution", "Definition:Probability Density Function", "Definition:Moment Generating Function", "Integration by Substitution", "Power Rule for Derivatives", "Derivative of Composite Function", "Derivative of Exponential Function/Corollary 1", "Commutativity of Parameters of Bet...
proofwiki-18320
Fundamental Solution to 1D Laplace's Equation
Let $\ds \map f x = \frac {\size x} 2$ where $\size x$ is the absolute value function. Let $\delta \in \map {\DD'} \R$ be the Dirac delta distribution. Let $T_f \in \map {\DD'} \R$ be the Schwartz distribution associated with $f$. Then $T_f$ is the fundamental solution to the $1$-dimensional Laplace's equation. That is...
$x \stackrel f {\longrightarrow} \dfrac {\size x} 2$ is a continuously differentiable real function on $\R \setminus \set 0$ and possibly has a discontinuity at $x = 0$. By Differentiable Function as Distribution we have that $T'_f = T_{f'}$. Moreover: :$x < 0 \implies \paren {\dfrac {\size x} 2}' = -\frac 1 2$ :$x > 0...
Let $\ds \map f x = \frac {\size x} 2$ where $\size x$ is the [[Definition:Absolute Value|absolute value function]]. Let $\delta \in \map {\DD'} \R$ be the [[Definition:Dirac Delta Distribution|Dirac delta distribution]]. Let $T_f \in \map {\DD'} \R$ be the [[Definition:Schwartz Distribution|Schwartz distribution]] a...
$x \stackrel f {\longrightarrow} \dfrac {\size x} 2$ is a [[Definition:Continuously Differentiable Real Function on Open Set|continuously differentiable real function]] on $\R \setminus \set 0$ and possibly has a [[Definition:Discontinuous|discontinuity]] at $x = 0$. By [[Differentiable Function as Distribution]] we h...
Fundamental Solution to 1D Laplace's Equation
https://proofwiki.org/wiki/Fundamental_Solution_to_1D_Laplace's_Equation
https://proofwiki.org/wiki/Fundamental_Solution_to_1D_Laplace's_Equation
[ "Laplace's Equation", "Examples of Fundamental Solutions" ]
[ "Definition:Absolute Value", "Definition:Dirac Delta Distribution", "Definition:Schwartz Distribution", "Definition:Fundamental Solution", "Definition:Dimension (Geometry)", "Definition:Laplace's Equation", "Definition:Distributional Derivative" ]
[ "Definition:Continuously Differentiable/Real Function/Open Set", "Definition:Discontinuous", "Differentiable Function as Distribution", "Jump Rule", "Definition:Continuously Differentiable/Real Function/Open Set", "Definition:Discontinuous", "Jump Rule", "Definition:Distributional Derivative" ]
proofwiki-18321
Minimal Element need not be Unique
Let $\struct {S, \preccurlyeq}$ be an ordered set. It is possible for $S$ to have more than one minimal element.
Proof by Counterexample: Consider the set $S$ defined as: :$S = \N \setminus \set {0, 1}$ That is, $S$ is the set of natural numbers with $0$ and $1$ removed. Let $\preccurlyeq$ be the ordering on $S$ defined as: :$\forall a, b \in S: a \preccurlyeq b \iff a \divides b$ where $a \divides b$ denotes that $a$ is a diviso...
Let $\struct {S, \preccurlyeq}$ be an [[Definition:Ordered Set|ordered set]]. It is possible for $S$ to have more than one [[Definition:Minimal Element|minimal element]].
[[Proof by Counterexample]]: Consider the [[Definition:Set|set]] $S$ defined as: :$S = \N \setminus \set {0, 1}$ That is, $S$ is the [[Definition:Natural Numbers|set of natural numbers]] with $0$ and $1$ removed. Let $\preccurlyeq$ be the [[Definition:Ordering|ordering]] on $S$ defined as: :$\forall a, b \in S: a \p...
Minimal Element need not be Unique
https://proofwiki.org/wiki/Minimal_Element_need_not_be_Unique
https://proofwiki.org/wiki/Minimal_Element_need_not_be_Unique
[ "Minimal Element need not be Unique", "Minimal Elements" ]
[ "Definition:Ordered Set", "Definition:Minimal/Element" ]
[ "Proof by Counterexample", "Definition:Set", "Definition:Natural Numbers", "Definition:Ordering", "Definition:Divisor (Algebra)/Integer", "Divisor Relation on Positive Integers is Partial Ordering", "Definition:Partially Ordered Set", "Definition:Prime Number", "Definition:Prime Number", "Definiti...
proofwiki-18322
Maximal Element need not be Unique
Let $\struct {S, \preccurlyeq}$ be an ordered set. It is possible for $S$ to have more than one maximal element.
Proof by Counterexample: Consider the set $T$ defined as: :$T = \set {0, 1}$ Let $S$ be defined as: :$S := \powerset T \setminus T$ where $\powerset T$ denotes the power set of $T$. That is: :$S = \set {\O, \set 0, \set 1}$ Let $\preccurlyeq$ be the relation defined on $S$ as: :$\forall a, b \in S: a \preccurlyeq b \if...
Let $\struct {S, \preccurlyeq}$ be an [[Definition:Ordered Set|ordered set]]. It is possible for $S$ to have more than one [[Definition:Maximal Element|maximal element]].
[[Proof by Counterexample]]: Consider the [[Definition:Set|set]] $T$ defined as: :$T = \set {0, 1}$ Let $S$ be defined as: :$S := \powerset T \setminus T$ where $\powerset T$ denotes the [[Definition:Power Set|power set]] of $T$. That is: :$S = \set {\O, \set 0, \set 1}$ Let $\preccurlyeq$ be the [[Definition:Rela...
Maximal Element need not be Unique
https://proofwiki.org/wiki/Maximal_Element_need_not_be_Unique
https://proofwiki.org/wiki/Maximal_Element_need_not_be_Unique
[ "Maximal Element need not be Unique", "Maximal Elements" ]
[ "Definition:Ordered Set", "Definition:Maximal/Element" ]
[ "Proof by Counterexample", "Definition:Set", "Definition:Power Set", "Definition:Relation", "Definition:Subset", "Subset Relation is Ordering", "Definition:Ordered Set", "Definition:Maximal/Element", "Definition:Maximal/Element", "Definition:Maximal/Element" ]
proofwiki-18323
Ordered Set may not have Minimal Element
Let $\struct {S, \preccurlyeq}$ be an ordered set. It may be the case that $S$ has no minimal elements.
Let $\Q_{>0}$ denote the set of (strictly) positive rational numbers. From Rational Numbers form Totally Ordered Field, the rational numbers $\Q$ are totally ordered by the usual ordering $\le$. From Subset of Toset is Toset, $\Q_{>0}$ is also totally ordered by $\le$. Thus $\struct {\Q_{>0}, \le}$ is an ordered set. {...
Let $\struct {S, \preccurlyeq}$ be an [[Definition:Ordered Set|ordered set]]. It may be the case that $S$ has no [[Definition:Minimal Element|minimal elements]].
Let $\Q_{>0}$ denote the [[Definition:Set|set]] of [[Definition:Strictly Positive Rational Number|(strictly) positive rational numbers]]. From [[Rational Numbers form Totally Ordered Field]], the [[Definition:Rational Number|rational numbers]] $\Q$ are [[Definition:Totally Ordered Set|totally ordered]] by the [[Defini...
Ordered Set may not have Minimal Element
https://proofwiki.org/wiki/Ordered_Set_may_not_have_Minimal_Element
https://proofwiki.org/wiki/Ordered_Set_may_not_have_Minimal_Element
[ "Minimal Elements" ]
[ "Definition:Ordered Set", "Definition:Minimal/Element" ]
[ "Definition:Set", "Definition:Strictly Positive/Rational Number", "Rational Numbers form Totally Ordered Field", "Definition:Rational Number", "Definition:Totally Ordered Set", "Definition:Usual Ordering", "Subset of Toset is Toset", "Definition:Totally Ordered Set", "Definition:Ordered Set", "Def...
proofwiki-18324
Ordered Set may not have Maximal Element
Let $\struct {S, \preccurlyeq}$ be an ordered set. It may be the case that $S$ has no maximal elements.
Consider the set $S$ defined as: :$S = \N \setminus \set 0$ That is, $S$ is the set of natural numbers with $0$ removed. Let $\preccurlyeq$ be the ordering on $S$ defined as: :$\forall a, b \in S: a \preccurlyeq b \iff a \divides b$ where $a \divides b$ denotes that $a$ is a divisor of $b$. From Divisor Relation on Pos...
Let $\struct {S, \preccurlyeq}$ be an [[Definition:Ordered Set|ordered set]]. It may be the case that $S$ has no [[Definition:Maximal Element|maximal elements]].
Consider the [[Definition:Set|set]] $S$ defined as: :$S = \N \setminus \set 0$ That is, $S$ is the [[Definition:Natural Numbers|set of natural numbers]] with $0$ removed. Let $\preccurlyeq$ be the [[Definition:Ordering|ordering]] on $S$ defined as: :$\forall a, b \in S: a \preccurlyeq b \iff a \divides b$ where $a \d...
Ordered Set may not have Maximal Element
https://proofwiki.org/wiki/Ordered_Set_may_not_have_Maximal_Element
https://proofwiki.org/wiki/Ordered_Set_may_not_have_Maximal_Element
[ "Maximal Elements" ]
[ "Definition:Ordered Set", "Definition:Maximal/Element" ]
[ "Definition:Set", "Definition:Natural Numbers", "Definition:Ordering", "Definition:Divisor (Algebra)/Integer", "Divisor Relation on Positive Integers is Partial Ordering", "Definition:Partially Ordered Set", "Definition:Maximal/Element", "Definition:Natural Numbers", "Definition:Maximal/Element", ...
proofwiki-18325
Distributional Derivatives of Dirac Delta Distribution do not Vanish
Let $\delta \in \map {\DD'} \R$ be the Dirac delta distribution. Then for any $n \in \N$ the distributional derivative $\delta^{\paren n}$ does not vanish.
Let $\phi \in \map \DD \R$ be a test function such that $\map \phi 0 \ne 0$. Then: :$\forall n \in \N : \forall x \in \R : x^n \phi \in \map \DD \R$ By the definition of the distributional derivative: {{begin-eqn}} {{eqn | l = \map {\delta^{\paren n} } {x^n \phi} | r = \paren {-1}^n \map \delta {\paren {x^n \phi}...
Let $\delta \in \map {\DD'} \R$ be the [[Definition:Dirac Delta Distribution|Dirac delta distribution]]. Then for any $n \in \N$ the [[Definition:Distributional Derivative|distributional derivative]] $\delta^{\paren n}$ does not vanish.
Let $\phi \in \map \DD \R$ be a [[Definition:Test Function|test function]] such that $\map \phi 0 \ne 0$. Then: :$\forall n \in \N : \forall x \in \R : x^n \phi \in \map \DD \R$ By the definition of the [[Definition:Higher Distributional Derivative|distributional derivative]]: {{begin-eqn}} {{eqn | l = \map {\delta...
Distributional Derivatives of Dirac Delta Distribution do not Vanish
https://proofwiki.org/wiki/Distributional_Derivatives_of_Dirac_Delta_Distribution_do_not_Vanish
https://proofwiki.org/wiki/Distributional_Derivatives_of_Dirac_Delta_Distribution_do_not_Vanish
[ "Dirac Delta Distribution", "Distributional Derivatives" ]
[ "Definition:Dirac Delta Distribution", "Definition:Distributional Derivative" ]
[ "Definition:Test Function", "Definition:Distributional Derivative/Higher Derivatives", "Leibniz's Rule/One Variable", "Nth Derivative of Nth Power" ]
proofwiki-18326
Expectation of Logistic Distribution
Let $X$ be a continuous random variable which satisfies the logistic distribution: :$X \sim \map {\operatorname {Logistic} } {\mu, s}$ The expectation of $X$ is given by: :$\expect X = \mu$
From the definition of the logistic distribution, $X$ has probability density function: :$\map {f_X} x = \dfrac {\map \exp {-\dfrac {\paren {x - \mu} } s} } {s \paren {1 + \map \exp {-\dfrac {\paren {x - \mu} } s} }^2}$ From the definition of the expected value of a continuous random variable: :$\ds \expect X = \int_{...
Let $X$ be a [[Definition:Continuous Random Variable|continuous random variable]] which satisfies the [[Definition:Logistic Distribution|logistic distribution]]: :$X \sim \map {\operatorname {Logistic} } {\mu, s}$ The [[Definition:Expectation of Continuous Random Variable|expectation]] of $X$ is given by: :$\expect ...
From the definition of the [[Definition:Logistic Distribution|logistic distribution]], $X$ has [[Definition:Probability Density Function|probability density function]]: :$\map {f_X} x = \dfrac {\map \exp {-\dfrac {\paren {x - \mu} } s} } {s \paren {1 + \map \exp {-\dfrac {\paren {x - \mu} } s} }^2}$ From the definiti...
Expectation of Logistic Distribution/Proof 1
https://proofwiki.org/wiki/Expectation_of_Logistic_Distribution
https://proofwiki.org/wiki/Expectation_of_Logistic_Distribution/Proof_1
[ "Logistic Distribution", "Expectation", "Expectation of Logistic Distribution" ]
[ "Definition:Random Variable/Continuous", "Definition:Logistic Distribution", "Definition:Expectation/Continuous" ]
[ "Definition:Logistic Distribution", "Definition:Probability Density Function", "Definition:Expectation/Continuous", "Integration by Substitution", "Power Rule for Derivatives", "Derivative of Composite Function", "Integral of Constant", "Difference of Logarithms" ]
proofwiki-18327
Expectation of Logistic Distribution
Let $X$ be a continuous random variable which satisfies the logistic distribution: :$X \sim \map {\operatorname {Logistic} } {\mu, s}$ The expectation of $X$ is given by: :$\expect X = \mu$
By Moment Generating Function of Logistic Distribution, the moment generating function of $X$ is given by: :$\ds \map {M_X} t = \map \exp {\mu t} \int_{\to 0}^{\to 1} \paren {\dfrac {1 - u} u}^{-s t} \rd u$ for $\size t < \dfrac 1 s$. From Moment in terms of Moment Generating Function: :$\expect X = \map { {M_X}'} 0...
Let $X$ be a [[Definition:Continuous Random Variable|continuous random variable]] which satisfies the [[Definition:Logistic Distribution|logistic distribution]]: :$X \sim \map {\operatorname {Logistic} } {\mu, s}$ The [[Definition:Expectation of Continuous Random Variable|expectation]] of $X$ is given by: :$\expect ...
By [[Moment Generating Function of Logistic Distribution]], the [[Definition:Moment Generating Function|moment generating function]] of $X$ is given by: :$\ds \map {M_X} t = \map \exp {\mu t} \int_{\to 0}^{\to 1} \paren {\dfrac {1 - u} u}^{-s t} \rd u$ for $\size t < \dfrac 1 s$. From [[Moment in terms of Moment G...
Expectation of Logistic Distribution/Proof 2
https://proofwiki.org/wiki/Expectation_of_Logistic_Distribution
https://proofwiki.org/wiki/Expectation_of_Logistic_Distribution/Proof_2
[ "Logistic Distribution", "Expectation", "Expectation of Logistic Distribution" ]
[ "Definition:Random Variable/Continuous", "Definition:Logistic Distribution", "Definition:Expectation/Continuous" ]
[ "Moment Generating Function of Logistic Distribution", "Definition:Moment Generating Function", "Moment in terms of Moment Generating Function", "Moment Generating Function of Logistic Distribution/Examples/First Moment", "Integral of Constant/Definite" ]
proofwiki-18328
Ordered Set with Multiple Minimal Elements has no Smallest Element
Let $\struct {S, \preccurlyeq}$ be an ordered set. Let $\struct {S, \preccurlyeq}$ have more than one minimal element. Then $\struct {S, \preccurlyeq}$ has no smallest element.
Let $s$ and $t$ both be minimal elements of $\struct {S, \preccurlyeq}$ such that $s \ne t$. Then by definition: :$\forall x \in S: x \preccurlyeq s \implies s = x$ and: :$\forall x \in S: x \preccurlyeq t \implies t = x$ {{AimForCont}} $S$ has a smallest element $m$. Then by definition: :$\forall y \in S: m \preccurly...
Let $\struct {S, \preccurlyeq}$ be an [[Definition:Ordered Set|ordered set]]. Let $\struct {S, \preccurlyeq}$ have more than one [[Definition:Minimal Element|minimal element]]. Then $\struct {S, \preccurlyeq}$ has no [[Definition:Smallest Element|smallest element]].
Let $s$ and $t$ both be [[Definition:Minimal Element|minimal elements]] of $\struct {S, \preccurlyeq}$ such that $s \ne t$. Then by definition: :$\forall x \in S: x \preccurlyeq s \implies s = x$ and: :$\forall x \in S: x \preccurlyeq t \implies t = x$ {{AimForCont}} $S$ has a [[Definition:Smallest Element|smallest...
Ordered Set with Multiple Minimal Elements has no Smallest Element
https://proofwiki.org/wiki/Ordered_Set_with_Multiple_Minimal_Elements_has_no_Smallest_Element
https://proofwiki.org/wiki/Ordered_Set_with_Multiple_Minimal_Elements_has_no_Smallest_Element
[ "Minimal Elements", "Smallest Elements" ]
[ "Definition:Ordered Set", "Definition:Minimal/Element", "Definition:Smallest Element" ]
[ "Definition:Minimal/Element", "Definition:Smallest Element", "Definition:Minimal/Element", "Definition:Contradiction", "Proof by Contradiction", "Definition:Smallest Element", "Category:Minimal Elements", "Category:Smallest Elements" ]
proofwiki-18329
Ordered Set with Multiple Maximal Elements has no Greatest Element
Let $\struct {S, \preccurlyeq}$ be an ordered set. Let $\struct {S, \preccurlyeq}$ have more than one maximal element. Then $\struct {S, \preccurlyeq}$ has no greatest element.
Let $s$ and $t$ both be maximal elements of $\struct {S, \preccurlyeq}$ such that $s \ne t$. Then by definition: :$\forall x \in S: s \preccurlyeq x \implies s = x$ and: :$\forall x \in S: t \preccurlyeq x \implies t = x$ {{AimForCont}} $S$ has a greatest element $m$. Then by definition: :$\forall y \in S: y \preccurly...
Let $\struct {S, \preccurlyeq}$ be an [[Definition:Ordered Set|ordered set]]. Let $\struct {S, \preccurlyeq}$ have more than one [[Definition:Maximal Element|maximal element]]. Then $\struct {S, \preccurlyeq}$ has no [[Definition:Greatest Element|greatest element]].
Let $s$ and $t$ both be [[Definition:Maximal Element|maximal elements]] of $\struct {S, \preccurlyeq}$ such that $s \ne t$. Then by definition: :$\forall x \in S: s \preccurlyeq x \implies s = x$ and: :$\forall x \in S: t \preccurlyeq x \implies t = x$ {{AimForCont}} $S$ has a [[Definition:Greatest Element|greatest...
Ordered Set with Multiple Maximal Elements has no Greatest Element
https://proofwiki.org/wiki/Ordered_Set_with_Multiple_Maximal_Elements_has_no_Greatest_Element
https://proofwiki.org/wiki/Ordered_Set_with_Multiple_Maximal_Elements_has_no_Greatest_Element
[ "Maximal Elements", "Greatest Elements" ]
[ "Definition:Ordered Set", "Definition:Maximal/Element", "Definition:Greatest Element" ]
[ "Definition:Maximal/Element", "Definition:Greatest Element", "Definition:Maximal/Element", "Definition:Contradiction", "Proof by Contradiction", "Definition:Greatest Element", "Category:Maximal Elements", "Category:Greatest Elements" ]
proofwiki-18330
Unique Minimal Element may not be Smallest
Let $\struct {S, \preccurlyeq}$ be an ordered set. Let $\struct {S, \preccurlyeq}$ have a unique minimal element. Then it is not necessarily the case that $\struct {S, \preccurlyeq}$ has a smallest element.
Let $S$ be the set defined as: :$S = \Z \cup \set m$ where: :$\Z$ denotes the set of integers :$m$ is an arbitrary object such that $m \ne \Z$. Let $\preccurlyeq$ be the relation on $\Z$ defined as: :$\forall a, b \in S: a \preccurlyeq b \iff \begin {cases} a \le b & : a, b \in \Z \\ a = m = b & : a, b \notin \Z \end{c...
Let $\struct {S, \preccurlyeq}$ be an [[Definition:Ordered Set|ordered set]]. Let $\struct {S, \preccurlyeq}$ have a [[Definition:Unique|unique]] [[Definition:Minimal Element|minimal element]]. Then it is not necessarily the case that $\struct {S, \preccurlyeq}$ has a [[Definition:Smallest Element|smallest element]]...
Let $S$ be the [[Definition:Set|set]] defined as: :$S = \Z \cup \set m$ where: :$\Z$ denotes the [[Definition:Integer|set of integers]] :$m$ is an arbitrary [[Definition:Object|object]] such that $m \ne \Z$. Let $\preccurlyeq$ be the [[Definition:Relation|relation]] on $\Z$ defined as: :$\forall a, b \in S: a \preccu...
Unique Minimal Element may not be Smallest
https://proofwiki.org/wiki/Unique_Minimal_Element_may_not_be_Smallest
https://proofwiki.org/wiki/Unique_Minimal_Element_may_not_be_Smallest
[ "Minimal Elements", "Smallest Elements" ]
[ "Definition:Ordered Set", "Definition:Unique", "Definition:Minimal/Element", "Definition:Smallest Element" ]
[ "Definition:Set", "Definition:Integer", "Definition:Object", "Definition:Relation", "Definition:Usual Ordering", "Definition:Non-Comparable Elements", "Definition:Ordered Set", "Definition:Minimal/Element", "Definition:Smallest Element", "Definition:Minimal/Element", "Definition:Minimal/Element"...
proofwiki-18331
Equivalence of Definitions of Well-Founded Relation
Let $\struct {S, \RR}$ be a Relational Structure. {{TFAE|def = Well-Founded Relation}}
By definition of minimal element: :$\forall y \in T: y \preceq x \implies x = y$
Let $\struct {S, \RR}$ be a [[Definition:Relational Structure|Relational Structure]]. {{TFAE|def = Well-Founded Relation}}
By definition of [[Definition:Minimal Element|minimal element]]: :$\forall y \in T: y \preceq x \implies x = y$
Equivalence of Definitions of Well-Founded Relation
https://proofwiki.org/wiki/Equivalence_of_Definitions_of_Well-Founded_Relation
https://proofwiki.org/wiki/Equivalence_of_Definitions_of_Well-Founded_Relation
[ "Well-Founded Relations" ]
[ "Definition:Relational Structure" ]
[ "Definition:Minimal/Element", "Definition:Minimal/Element", "Definition:Minimal/Element", "Definition:Minimal/Element" ]
proofwiki-18332
Strictly Minimal Element is Minimal Element
Let $\struct {S, \RR}$ be a relational structure. Let $T \subseteq S$ be a subset of $S$. Let $m \in T$ be a strictly minimal element of $T$ under $\RR$. Then $m$ is a minimal element of $T$ under $\RR$.
Let $m \in T$ be a strictly minimal element of $T$ under $\RR$. Then by definition: :$\forall x \in T: \tuple {x, m} \notin \RR$ {{AimForCont}} $m$ is not a minimal element of $T$ under $\RR$. Then: :$\exists y \in T: \tuple {y, m} \in \RR$ such that $y \ne m$. But this contradicts the assertion that $\tuple {y, m} \no...
Let $\struct {S, \RR}$ be a [[Definition:Relational Structure|relational structure]]. Let $T \subseteq S$ be a [[Definition:Subset|subset]] of $S$. Let $m \in T$ be a [[Definition:Strictly Minimal Element|strictly minimal element]] of $T$ under $\RR$. Then $m$ is a [[Definition:Minimal Element|minimal element]] of ...
Let $m \in T$ be a [[Definition:Strictly Minimal Element|strictly minimal element]] of $T$ under $\RR$. Then by definition: :$\forall x \in T: \tuple {x, m} \notin \RR$ {{AimForCont}} $m$ is not a [[Definition:Minimal Element|minimal element]] of $T$ under $\RR$. Then: :$\exists y \in T: \tuple {y, m} \in \RR$ such ...
Strictly Minimal Element is Minimal Element
https://proofwiki.org/wiki/Strictly_Minimal_Element_is_Minimal_Element
https://proofwiki.org/wiki/Strictly_Minimal_Element_is_Minimal_Element
[ "Minimal Elements" ]
[ "Definition:Relational Structure", "Definition:Subset", "Definition:Strictly Minimal Element", "Definition:Minimal/Element" ]
[ "Definition:Strictly Minimal Element", "Definition:Minimal/Element", "Definition:Contradiction", "Definition:Minimal/Element", "Definition:Minimal/Element", "Category:Minimal Elements" ]
proofwiki-18333
Strictly Maximal Element is Maximal Element
Let $\struct {S, \RR}$ be a relational structure. Let $T \subseteq S$ be a subset of $S$. Let $m \in T$ be a strictly maximal element of $T$ under $\RR$. Then $m$ is a maximal element of $T$ under $\RR$.
Let $m \in T$ be a strictly maximal element of $T$ under $\RR$. Then by definition: :$\forall x \in T: \tuple {m, x} \notin \RR$ {{AimForCont}} $m$ is not a maximal element of $T$ under $\RR$. Then: :$\exists y \in T: \tuple {m, y} \in \RR$ such that $y \ne m$. But this contradicts the assertion that $\tuple {m, y} \no...
Let $\struct {S, \RR}$ be a [[Definition:Relational Structure|relational structure]]. Let $T \subseteq S$ be a [[Definition:Subset|subset]] of $S$. Let $m \in T$ be a [[Definition:Strictly Maximal Element|strictly maximal element]] of $T$ under $\RR$. Then $m$ is a [[Definition:Maximal Element|maximal element]] of ...
Let $m \in T$ be a [[Definition:Strictly Maximal Element|strictly maximal element]] of $T$ under $\RR$. Then by definition: :$\forall x \in T: \tuple {m, x} \notin \RR$ {{AimForCont}} $m$ is not a [[Definition:Maximal Element|maximal element]] of $T$ under $\RR$. Then: :$\exists y \in T: \tuple {m, y} \in \RR$ such ...
Strictly Maximal Element is Maximal Element
https://proofwiki.org/wiki/Strictly_Maximal_Element_is_Maximal_Element
https://proofwiki.org/wiki/Strictly_Maximal_Element_is_Maximal_Element
[ "Maximal Elements" ]
[ "Definition:Relational Structure", "Definition:Subset", "Definition:Strictly Maximal Element", "Definition:Maximal/Element" ]
[ "Definition:Strictly Maximal Element", "Definition:Maximal/Element", "Definition:Contradiction", "Definition:Maximal/Element", "Definition:Maximal/Element", "Category:Maximal Elements" ]
proofwiki-18334
Strictly Well-Founded Relation is Well-Founded
Let $\struct {S, \RR}$ be a relational structure. Let $\RR$ be a strictly well-founded relation on $S$. Then $\RR$ is a well-founded relation on $S$.
We have that $\RR$ is a strictly well-founded relation on $S$. By definition: :$\forall T: \paren {T \subseteq S \land T \ne \O} \implies \exists y \in T: \forall z \in T: \neg \paren {z \mathrel \RR y}$ It immediately follows that: :$\forall T: \paren {T \subseteq S \land T \ne \O} \implies \exists y \in T: \forall z ...
Let $\struct {S, \RR}$ be a [[Definition:Relational Structure|relational structure]]. Let $\RR$ be a [[Definition:Strictly Well-Founded Relation|strictly well-founded relation]] on $S$. Then $\RR$ is a [[Definition:Well-Founded Relation|well-founded relation]] on $S$.
We have that $\RR$ is a [[Definition:Strictly Well-Founded Relation|strictly well-founded relation]] on $S$. By definition: :$\forall T: \paren {T \subseteq S \land T \ne \O} \implies \exists y \in T: \forall z \in T: \neg \paren {z \mathrel \RR y}$ It immediately follows that: :$\forall T: \paren {T \subseteq S \l...
Strictly Well-Founded Relation is Well-Founded
https://proofwiki.org/wiki/Strictly_Well-Founded_Relation_is_Well-Founded
https://proofwiki.org/wiki/Strictly_Well-Founded_Relation_is_Well-Founded
[ "Well-Founded Relations" ]
[ "Definition:Relational Structure", "Definition:Strictly Well-Founded Relation", "Definition:Well-Founded Relation" ]
[ "Definition:Strictly Well-Founded Relation", "Definition:Well-Founded Relation" ]
proofwiki-18335
Well-Founded Relation is not necessarily Ordering
Let $\struct {S, \RR}$ be a relational structure. Let $\RR$ be a well-founded relation on $S$. Then it is not necessarily the case that $\RR$ is also either an ordering or a strict ordering.
Proof by Counterexample: Let $P$ be the set of all polynomials over $\R$ in one variable with real coefficients. Let $\DD$ be a relation on $P$ defined as: :$\forall p_0, p_1 \in P: \tuple {p_0, p_1} \in \DD$ {{iff}} $p_0$ is the derivative of $p_1$. From Differentiation of Polynomials induces Well-Founded Relation, we...
Let $\struct {S, \RR}$ be a [[Definition:Relational Structure|relational structure]]. Let $\RR$ be a [[Definition:Well-Founded Relation|well-founded relation]] on $S$. Then it is not necessarily the case that $\RR$ is also either an [[Definition:Ordering|ordering]] or a [[Definition:Strict Ordering|strict ordering]]...
[[Proof by Counterexample]]: Let $P$ be the [[Definition:Set|set]] of all [[Definition:Polynomial over Real Numbers|polynomials over $\R$]] [[Definition:Polynomial over Ring in One Variable|in one variable]] with [[Definition:Real Number|real]] [[Definition:Coefficient of Polynomial|coefficients]]. Let $\DD$ be a [[D...
Well-Founded Relation is not necessarily Ordering
https://proofwiki.org/wiki/Well-Founded_Relation_is_not_necessarily_Ordering
https://proofwiki.org/wiki/Well-Founded_Relation_is_not_necessarily_Ordering
[ "Well-Founded Relations", "Orderings" ]
[ "Definition:Relational Structure", "Definition:Well-Founded Relation", "Definition:Ordering", "Definition:Strict Ordering" ]
[ "Proof by Counterexample", "Definition:Set", "Definition:Polynomial/Real Numbers", "Definition:Polynomial over Ring/One Variable", "Definition:Real Number", "Definition:Coefficient of Polynomial", "Definition:Endorelation", "Definition:Derivative", "Differentiation of Polynomials induces Well-Founde...
proofwiki-18336
Well-Founded Relation has no Relational Loops
Let $\RR$ be a well-founded relation on $S$. Let $x_1, x_2, \ldots, x_n \in S$. Then: :$\neg \paren {\paren {x_1 \mathrel \RR x_2} \land \paren {x_3 \mathrel \RR x_4} \land \cdots \land \paren {x_n \mathrel \RR x_1} }$ That is, there are no relational loops within $S$.
Since $x_1, x_2, \ldots, x_n \in S$, there exists a non-empty subset $T$ of $S$ such that: :$T = \set {x_1, x_2, \ldots, x_n}$ By the definition of a well-founded relation: :$(1): \quad \exists z \in T: \forall y \in T \setminus z: \neg y \mathrel \RR z$ {{AimForCont}} $\paren {x_1 \mathrel \RR x_2} \land \paren {x_2 \...
Let $\RR$ be a [[Definition:Well-Founded Relation|well-founded relation]] on $S$. Let $x_1, x_2, \ldots, x_n \in S$. Then: :$\neg \paren {\paren {x_1 \mathrel \RR x_2} \land \paren {x_3 \mathrel \RR x_4} \land \cdots \land \paren {x_n \mathrel \RR x_1} }$ That is, there are no [[Definition:Relational Loop|relationa...
Since $x_1, x_2, \ldots, x_n \in S$, there exists a [[Definition:Non-Empty Set|non-empty]] [[Definition:Subset|subset]] $T$ of $S$ such that: :$T = \set {x_1, x_2, \ldots, x_n}$ By the definition of a [[Definition:Well-Founded Relation|well-founded relation]]: :$(1): \quad \exists z \in T: \forall y \in T \setminus z:...
Well-Founded Relation has no Relational Loops
https://proofwiki.org/wiki/Well-Founded_Relation_has_no_Relational_Loops
https://proofwiki.org/wiki/Well-Founded_Relation_has_no_Relational_Loops
[ "Well-Founded Relations" ]
[ "Definition:Well-Founded Relation", "Definition:Relational Loop" ]
[ "Definition:Non-Empty Set", "Definition:Subset", "Definition:Well-Founded Relation", "Definition:Contradiction", "Definition:Well-Founded Relation", "Definition:Relational Loop" ]
proofwiki-18337
Infinite Sequence Property of Strictly Well-Founded Relation
Let $\struct {S, \RR}$ be a relational structure. Then $\RR$ is a strictly well-founded relation {{iff}} there is no infinite sequence $\sequence {a_n}$ of elements of $S$ such that: :$\forall n \in \N: a_{n + 1} \mathrel \RR a_n$
=== Reverse Implication === {{:Infinite Sequence Property of Strictly Well-Founded Relation/Reverse Implication/Proof 1}}{{qed|lemma}}
Let $\struct {S, \RR}$ be a [[Definition:Relational Structure|relational structure]]. Then $\RR$ is a [[Definition:Strictly Well-Founded Relation|strictly well-founded relation]] {{iff}} there is no [[Definition:Infinite Sequence|infinite sequence]] $\sequence {a_n}$ of [[Definition:Element|elements]] of $S$ such tha...
=== [[Infinite Sequence Property of Strictly Well-Founded Relation/Reverse Implication/Proof 1|Reverse Implication]] === {{:Infinite Sequence Property of Strictly Well-Founded Relation/Reverse Implication/Proof 1}}{{qed|lemma}}
Infinite Sequence Property of Strictly Well-Founded Relation
https://proofwiki.org/wiki/Infinite_Sequence_Property_of_Strictly_Well-Founded_Relation
https://proofwiki.org/wiki/Infinite_Sequence_Property_of_Strictly_Well-Founded_Relation
[ "Well-Founded Relations", "Infinite Sequence Property of Strictly Well-Founded Relation" ]
[ "Definition:Relational Structure", "Definition:Strictly Well-Founded Relation", "Definition:Sequence/Infinite Sequence", "Definition:Element" ]
[ "Infinite Sequence Property of Strictly Well-Founded Relation/Reverse Implication/Proof 1" ]
proofwiki-18338
Infinite Sequence Property of Strictly Well-Founded Relation
Let $\struct {S, \RR}$ be a relational structure. Then $\RR$ is a strictly well-founded relation {{iff}} there is no infinite sequence $\sequence {a_n}$ of elements of $S$ such that: :$\forall n \in \N: a_{n + 1} \mathrel \RR a_n$
Suppose $\RR$ is not a strictly well-founded relation. So by definition there exists a non-empty subset $T$ of $S$ which has no strictly minimal element. Let $a \in T$. Since $a$ is not strictly minimal in $T$, we can find $b \in T: b \mathrel \RR a$. This holds for all $a \in T$. Hence the restriction $\RR \restrictio...
Let $\struct {S, \RR}$ be a [[Definition:Relational Structure|relational structure]]. Then $\RR$ is a [[Definition:Strictly Well-Founded Relation|strictly well-founded relation]] {{iff}} there is no [[Definition:Infinite Sequence|infinite sequence]] $\sequence {a_n}$ of [[Definition:Element|elements]] of $S$ such tha...
Suppose $\RR$ is not a [[Definition:Strictly Well-Founded Relation|strictly well-founded relation]]. So by definition there exists a [[Definition:Non-Empty Set|non-empty]] [[Definition:Subset|subset]] $T$ of $S$ which has no [[Definition:Strictly Minimal Element|strictly minimal element]]. Let $a \in T$. Since $a$ i...
Infinite Sequence Property of Strictly Well-Founded Relation/Reverse Implication/Proof 1
https://proofwiki.org/wiki/Infinite_Sequence_Property_of_Strictly_Well-Founded_Relation
https://proofwiki.org/wiki/Infinite_Sequence_Property_of_Strictly_Well-Founded_Relation/Reverse_Implication/Proof_1
[ "Well-Founded Relations", "Infinite Sequence Property of Strictly Well-Founded Relation" ]
[ "Definition:Relational Structure", "Definition:Strictly Well-Founded Relation", "Definition:Sequence/Infinite Sequence", "Definition:Element" ]
[ "Definition:Strictly Well-Founded Relation", "Definition:Non-Empty Set", "Definition:Subset", "Definition:Strictly Minimal Element", "Definition:Strictly Minimal Element", "Definition:Restriction/Relation", "Definition:Right-Total Relation", "Definition:Endorelation", "Axiom:Axiom of Dependent Choic...
proofwiki-18339
Infinite Sequence Property of Strictly Well-Founded Relation
Let $\struct {S, \RR}$ be a relational structure. Then $\RR$ is a strictly well-founded relation {{iff}} there is no infinite sequence $\sequence {a_n}$ of elements of $S$ such that: :$\forall n \in \N: a_{n + 1} \mathrel \RR a_n$
Suppose $\RR$ is not a strictly well-founded relation. Hence there exists $T \subseteq S$ such that $T$ has no strictly minimal element under $\RR$. Let $a_0 \in T$. We have that $a_0$ is not strictly minimal in $T$. So: :$\exists a_1 \in T: a_1 \mathrel \RR a_0$ Similarly, $a_1$ is not strictly minimal in $T$. So: :$\...
Let $\struct {S, \RR}$ be a [[Definition:Relational Structure|relational structure]]. Then $\RR$ is a [[Definition:Strictly Well-Founded Relation|strictly well-founded relation]] {{iff}} there is no [[Definition:Infinite Sequence|infinite sequence]] $\sequence {a_n}$ of [[Definition:Element|elements]] of $S$ such tha...
Suppose $\RR$ is not a [[Definition:Strictly Well-Founded Relation|strictly well-founded relation]]. Hence there exists $T \subseteq S$ such that $T$ has no [[Definition:Strictly Minimal Element|strictly minimal element]] under $\RR$. Let $a_0 \in T$. We have that $a_0$ is not [[Definition:Strictly Minimal Element|...
Infinite Sequence Property of Strictly Well-Founded Relation/Reverse Implication/Proof 2
https://proofwiki.org/wiki/Infinite_Sequence_Property_of_Strictly_Well-Founded_Relation
https://proofwiki.org/wiki/Infinite_Sequence_Property_of_Strictly_Well-Founded_Relation/Reverse_Implication/Proof_2
[ "Well-Founded Relations", "Infinite Sequence Property of Strictly Well-Founded Relation" ]
[ "Definition:Relational Structure", "Definition:Strictly Well-Founded Relation", "Definition:Sequence/Infinite Sequence", "Definition:Element" ]
[ "Definition:Strictly Well-Founded Relation", "Definition:Strictly Minimal Element", "Definition:Strictly Minimal Element", "Definition:Strictly Minimal Element", "Axiom:Axiom of Dependent Choice/Right-Total", "Definition:Strictly Minimal Element", "Definition:Right-Total Relation", "Axiom:Axiom of Dep...
proofwiki-18340
Infinite Sequence Property of Strictly Well-Founded Relation/Reverse Implication
Let $\struct {S, \RR}$ be a relational structure. Let $\RR$ be such that there exists no infinite sequence $\sequence {a_n}$ of elements of $S$ such that: :$\forall n \in \N: a_{n + 1} \mathrel \RR a_n$ Then $\RR$ is a strictly well-founded relation.
Suppose $\RR$ is not a strictly well-founded relation. So by definition there exists a non-empty subset $T$ of $S$ which has no strictly minimal element. Let $a \in T$. Since $a$ is not strictly minimal in $T$, we can find $b \in T: b \mathrel \RR a$. This holds for all $a \in T$. Hence the restriction $\RR \restrictio...
Let $\struct {S, \RR}$ be a [[Definition:Relational Structure|relational structure]]. Let $\RR$ be such that there exists no [[Definition:Infinite Sequence|infinite sequence]] $\sequence {a_n}$ of [[Definition:Element|elements]] of $S$ such that: :$\forall n \in \N: a_{n + 1} \mathrel \RR a_n$ Then $\RR$ is a [[Defi...
Suppose $\RR$ is not a [[Definition:Strictly Well-Founded Relation|strictly well-founded relation]]. So by definition there exists a [[Definition:Non-Empty Set|non-empty]] [[Definition:Subset|subset]] $T$ of $S$ which has no [[Definition:Strictly Minimal Element|strictly minimal element]]. Let $a \in T$. Since $a$ i...
Infinite Sequence Property of Strictly Well-Founded Relation/Reverse Implication/Proof 1
https://proofwiki.org/wiki/Infinite_Sequence_Property_of_Strictly_Well-Founded_Relation/Reverse_Implication
https://proofwiki.org/wiki/Infinite_Sequence_Property_of_Strictly_Well-Founded_Relation/Reverse_Implication/Proof_1
[ "Infinite Sequence Property of Strictly Well-Founded Relation" ]
[ "Definition:Relational Structure", "Definition:Sequence/Infinite Sequence", "Definition:Element", "Definition:Strictly Well-Founded Relation" ]
[ "Definition:Strictly Well-Founded Relation", "Definition:Non-Empty Set", "Definition:Subset", "Definition:Strictly Minimal Element", "Definition:Strictly Minimal Element", "Definition:Restriction/Relation", "Definition:Right-Total Relation", "Definition:Endorelation", "Axiom:Axiom of Dependent Choic...
proofwiki-18341
Infinite Sequence Property of Strictly Well-Founded Relation/Reverse Implication
Let $\struct {S, \RR}$ be a relational structure. Let $\RR$ be such that there exists no infinite sequence $\sequence {a_n}$ of elements of $S$ such that: :$\forall n \in \N: a_{n + 1} \mathrel \RR a_n$ Then $\RR$ is a strictly well-founded relation.
Suppose $\RR$ is not a strictly well-founded relation. Hence there exists $T \subseteq S$ such that $T$ has no strictly minimal element under $\RR$. Let $a_0 \in T$. We have that $a_0$ is not strictly minimal in $T$. So: :$\exists a_1 \in T: a_1 \mathrel \RR a_0$ Similarly, $a_1$ is not strictly minimal in $T$. So: :$\...
Let $\struct {S, \RR}$ be a [[Definition:Relational Structure|relational structure]]. Let $\RR$ be such that there exists no [[Definition:Infinite Sequence|infinite sequence]] $\sequence {a_n}$ of [[Definition:Element|elements]] of $S$ such that: :$\forall n \in \N: a_{n + 1} \mathrel \RR a_n$ Then $\RR$ is a [[Defi...
Suppose $\RR$ is not a [[Definition:Strictly Well-Founded Relation|strictly well-founded relation]]. Hence there exists $T \subseteq S$ such that $T$ has no [[Definition:Strictly Minimal Element|strictly minimal element]] under $\RR$. Let $a_0 \in T$. We have that $a_0$ is not [[Definition:Strictly Minimal Element|...
Infinite Sequence Property of Strictly Well-Founded Relation/Reverse Implication/Proof 2
https://proofwiki.org/wiki/Infinite_Sequence_Property_of_Strictly_Well-Founded_Relation/Reverse_Implication
https://proofwiki.org/wiki/Infinite_Sequence_Property_of_Strictly_Well-Founded_Relation/Reverse_Implication/Proof_2
[ "Infinite Sequence Property of Strictly Well-Founded Relation" ]
[ "Definition:Relational Structure", "Definition:Sequence/Infinite Sequence", "Definition:Element", "Definition:Strictly Well-Founded Relation" ]
[ "Definition:Strictly Well-Founded Relation", "Definition:Strictly Minimal Element", "Definition:Strictly Minimal Element", "Definition:Strictly Minimal Element", "Axiom:Axiom of Dependent Choice/Right-Total", "Definition:Strictly Minimal Element", "Definition:Right-Total Relation", "Axiom:Axiom of Dep...
proofwiki-18342
Infinite Sequence Property of Strictly Well-Founded Relation/Forward Implication
Let $\struct {S, \RR}$ be a relational structure. Let $\RR$ be a strictly well-founded relation. Then there exists no infinite sequence $\sequence {a_n}$ of elements of $S$ such that: :$\forall n \in \N: a_{n + 1} \mathrel \RR a_n$
Let $\RR$ be a strictly well-founded relation. {{AimForCont}} there exists an infinite sequence $\sequence {a_n}$ in $S$ such that: :$\forall n \in \N: a_{n + 1} \mathrel \RR a_n$ Let $T = \set {a_0, a_1, a_2, \ldots}$. Let $a_k \in T$ be a strictly minimal element of $T$. That is: :$\forall y \in T: y \not \mathrel \R...
Let $\struct {S, \RR}$ be a [[Definition:Relational Structure|relational structure]]. Let $\RR$ be a [[Definition:Strictly Well-Founded Relation|strictly well-founded relation]]. Then there exists no [[Definition:Infinite Sequence|infinite sequence]] $\sequence {a_n}$ of [[Definition:Element|elements]] of $S$ such t...
Let $\RR$ be a [[Definition:Strictly Well-Founded Relation|strictly well-founded relation]]. {{AimForCont}} there exists an [[Definition:Sequence|infinite sequence]] $\sequence {a_n}$ in $S$ such that: :$\forall n \in \N: a_{n + 1} \mathrel \RR a_n$ Let $T = \set {a_0, a_1, a_2, \ldots}$. Let $a_k \in T$ be a [[Defi...
Infinite Sequence Property of Strictly Well-Founded Relation/Forward Implication
https://proofwiki.org/wiki/Infinite_Sequence_Property_of_Strictly_Well-Founded_Relation/Forward_Implication
https://proofwiki.org/wiki/Infinite_Sequence_Property_of_Strictly_Well-Founded_Relation/Forward_Implication
[ "Infinite Sequence Property of Strictly Well-Founded Relation" ]
[ "Definition:Relational Structure", "Definition:Strictly Well-Founded Relation", "Definition:Sequence/Infinite Sequence", "Definition:Element" ]
[ "Definition:Strictly Well-Founded Relation", "Definition:Sequence", "Definition:Strictly Minimal Element", "Definition:Strictly Minimal Element", "Proof by Contradiction", "Definition:Sequence" ]
proofwiki-18343
Restriction of Well-Founded Relation is Well-Founded
Let $\struct {S, \RR}$ be a relational structure. Let $\RR$ be a well-founded relation on $S$. Let $T$ be a subset or subclass of $S$. Let $\RR'$ be the restriction of $\RR$ to $T$. Then $\preceq'$ is a well-founded relation on $T$.
Let $A$ be a non-empty subset of $T$. By Subset Relation is Transitive, $A$ is a non-empty subset of $S$. Since $\RR$ is a well-founded relation on $S$, $A$ has a minimal element $m$ under $\RR$. Let $x \in A$. Let $x \mathrel {\RR'} m$. By the definition of restriction: :$x \mathrel \RR m$ Thus by the definition of mi...
Let $\struct {S, \RR}$ be a [[Definition:Relational Structure|relational structure]]. Let $\RR$ be a [[Definition:Well-Founded Relation|well-founded relation]] on $S$. Let $T$ be a [[Definition:Subset|subset]] or [[Definition:Subclass|subclass]] of $S$. Let $\RR'$ be the [[Definition:Restriction of Relation|restrict...
Let $A$ be a [[Definition:Non-Empty Set|non-empty]] [[Definition:Subset|subset]] of $T$. By [[Subset Relation is Transitive]], $A$ is a [[Definition:Non-Empty Set|non-empty]] [[Definition:Subset|subset]] of $S$. Since $\RR$ is a [[Definition:Well-Founded Relation|well-founded relation]] on $S$, $A$ has a [[Definition...
Restriction of Well-Founded Relation is Well-Founded
https://proofwiki.org/wiki/Restriction_of_Well-Founded_Relation_is_Well-Founded
https://proofwiki.org/wiki/Restriction_of_Well-Founded_Relation_is_Well-Founded
[ "Well-Founded Relations" ]
[ "Definition:Relational Structure", "Definition:Well-Founded Relation", "Definition:Subset", "Definition:Subclass", "Definition:Restriction/Relation", "Definition:Well-Founded Relation" ]
[ "Definition:Non-Empty Set", "Definition:Subset", "Subset Relation is Transitive", "Definition:Non-Empty Set", "Definition:Subset", "Definition:Well-Founded Relation", "Definition:Minimal/Element", "Definition:Restriction/Relation", "Definition:Minimal/Element", "Definition:Element", "Definition:...
proofwiki-18344
Divisor Relation on Positive Integers is Well-Founded Ordering
The divisor relation on $\Z_{>0}$ is a well-founded ordering.
Let $\struct {\Z_{>0}, \divides}$ denote the relational structure formed from the strictly positive integers $\Z_{>0}$ under the divisor relation $\divides$. From Divisor Relation on Positive Integers is Partial Ordering, $\struct {\Z_{>0}, \divides}$ is a partially ordered set. It remains to be shown that $\divides$ i...
The [[Definition:Divisor of Integer|divisor relation]] on $\Z_{>0}$ is a [[Definition:Well-Founded Ordering|well-founded ordering]].
Let $\struct {\Z_{>0}, \divides}$ denote the [[Definition:Relational Structure|relational structure]] formed from the [[Definition:Strictly Positive Integer|strictly positive integers]] $\Z_{>0}$ under the [[Definition:Divisor of Integer|divisor relation]] $\divides$. From [[Divisor Relation on Positive Integers is Pa...
Divisor Relation on Positive Integers is Well-Founded Ordering
https://proofwiki.org/wiki/Divisor_Relation_on_Positive_Integers_is_Well-Founded_Ordering
https://proofwiki.org/wiki/Divisor_Relation_on_Positive_Integers_is_Well-Founded_Ordering
[ "Divisors", "Integers", "Examples of Well-Founded Relations" ]
[ "Definition:Divisor (Algebra)/Integer", "Definition:Well-Founded Ordered Set" ]
[ "Definition:Relational Structure", "Definition:Strictly Positive/Integer", "Definition:Divisor (Algebra)/Integer", "Divisor Relation on Positive Integers is Partial Ordering", "Definition:Partially Ordered Set", "Definition:Well-Founded Relation", "Definition:Non-Empty Set", "Definition:Element", "D...
proofwiki-18345
Union of Indexed Family of Sets Equal to Union of Disjoint Sets/General Result
Let $I$ be a set which can be well-ordered by a well-ordering $\preccurlyeq$. Let $\family {E_\alpha}_{\alpha \mathop \in I}$ be a countable indexed family of sets indexed by $I$ where at least two $E_\alpha$ are distinct. Then there exists a countable indexed family of disjoint sets $\family {F_\alpha}_{\alpha \mathop...
Denote: {{begin-eqn}} {{eqn | l = E | r = \bigcup_{\beta \mathop \in I} E_\beta }} {{eqn | l = F | r = \bigcup_{\beta \mathop \in I} F_\beta }} {{end-eqn}} where: :$\ds F_\beta = E_\beta \setminus \paren {\bigcup_{\alpha \mathop \prec \beta} E_\alpha}$ We first show that $E = F$. That $x \in E \implies x \i...
Let $I$ be a [[Definition:Set|set]] which can be [[Definition:Well-Ordered Set|well-ordered]] by a [[Definition:Well-Ordering|well-ordering]] $\preccurlyeq$. Let $\family {E_\alpha}_{\alpha \mathop \in I}$ be a [[Definition:Countable Set|countable]] [[Definition:Indexed Family of Subsets|indexed family of sets]] [[Def...
Denote: {{begin-eqn}} {{eqn | l = E | r = \bigcup_{\beta \mathop \in I} E_\beta }} {{eqn | l = F | r = \bigcup_{\beta \mathop \in I} F_\beta }} {{end-eqn}} where: :$\ds F_\beta = E_\beta \setminus \paren {\bigcup_{\alpha \mathop \prec \beta} E_\alpha}$ We first show that $E = F$. That $x \in E \impli...
Union of Indexed Family of Sets Equal to Union of Disjoint Sets/General Result
https://proofwiki.org/wiki/Union_of_Indexed_Family_of_Sets_Equal_to_Union_of_Disjoint_Sets/General_Result
https://proofwiki.org/wiki/Union_of_Indexed_Family_of_Sets_Equal_to_Union_of_Disjoint_Sets/General_Result
[ "Union of Indexed Family of Sets Equal to Union of Disjoint Sets" ]
[ "Definition:Set", "Definition:Well-Ordered Set", "Definition:Well-Ordering", "Definition:Countable Set", "Definition:Indexing Set/Family of Subsets", "Definition:Indexing Set", "Definition:Distinct", "Definition:Countable Set", "Definition:Pairwise Disjoint/Family", "Definition:Disjoint Union (Set...
[ "Definition:Subset", "Rule of Simplification", "Definition:Set Equality", "Definition:Pairwise Disjoint/Family", "Well-Ordering Principle", "Definition:Smallest Element", "Definition:Distinct/Plural", "Definition:Disjoint Sets", "Definition:Disjoint Union (Set Theory)", "Definition:Set", "Defini...
proofwiki-18346
Subset of Well-Founded Relation is Well-Founded
Let $\struct {S, \RR}$ be a relational structure. Let $\RR$ be a well-founded relation on $S$. Let $\QQ$ be a subset of $\RR$. Then $\QQ$ is also a well-founded relation on $S$.
{{AimForCont}} $\struct {S, \QQ}$ is not a well-founded set. By Infinite Sequence Property of Well-Founded Relation there exists an infinite sequence $\sequence {x_n}$ in $S$ such that: :$\forall n \in \N: \tuple {x_{n + 1}, x_n} \in \QQ \text { and } x_{n + 1} \ne x_n$ But then because $\QQ \subseteq \RR$, it follows ...
Let $\struct {S, \RR}$ be a [[Definition:Relational Structure|relational structure]]. Let $\RR$ be a [[Definition:Well-Founded Relation|well-founded relation]] on $S$. Let $\QQ$ be a [[Definition:Subset|subset]] of $\RR$. Then $\QQ$ is also a [[Definition:Well-Founded Relation|well-founded relation]] on $S$.
{{AimForCont}} $\struct {S, \QQ}$ is not a [[Definition:Well-Founded Set|well-founded set]]. By [[Infinite Sequence Property of Well-Founded Relation]] there exists an [[Definition:Infinite Sequence|infinite sequence]] $\sequence {x_n}$ in $S$ such that: :$\forall n \in \N: \tuple {x_{n + 1}, x_n} \in \QQ \text { and ...
Subset of Well-Founded Relation is Well-Founded
https://proofwiki.org/wiki/Subset_of_Well-Founded_Relation_is_Well-Founded
https://proofwiki.org/wiki/Subset_of_Well-Founded_Relation_is_Well-Founded
[ "Well-Founded Relations" ]
[ "Definition:Relational Structure", "Definition:Well-Founded Relation", "Definition:Subset", "Definition:Well-Founded Relation" ]
[ "Definition:Well-Founded Set", "Infinite Sequence Property of Well-Founded Relation", "Definition:Sequence/Infinite Sequence", "Infinite Sequence Property of Well-Founded Relation", "Definition:Well-Founded Relation", "Proof by Contradiction" ]
proofwiki-18347
Rank Function Property of Well-Founded Relation
Let $\struct {S, \RR}$ be a relational structure. Let $\struct {T, \prec}$ be a strictly well-ordered set. Let there exist a rank function $\operatorname {rk}: S \to T$, that is: :$\forall x, y \in S: \paren {x \ne y \text { and } \tuple {x, y} \in \RR} \implies \map {\operatorname {rk} } x \prec \map {\operatorname {r...
{{AimForCont}} $\RR$ is not a well-founded relation. From Infinite Sequence Property of Well-Founded Relation, there exists an infinite sequence $\sequence {a_n}$ of elements of $S$ such that: :$\forall n \in \N: \paren {a_{n + 1} \mathrel \RR a_n} \text { and } \paren {a_{n + 1} \ne a_n}$ Let $A = \operatorname {rk} \...
Let $\struct {S, \RR}$ be a [[Definition:Relational Structure|relational structure]]. Let $\struct {T, \prec}$ be a [[Definition:Strictly Well-Ordered Set|strictly well-ordered set]]. Let there exist a [[Definition:Rank Function for Relation|rank function]] $\operatorname {rk}: S \to T$, that is: :$\forall x, y \in S...
{{AimForCont}} $\RR$ is not a [[Definition:Well-Founded Relation|well-founded relation]]. From [[Infinite Sequence Property of Well-Founded Relation]], there exists an [[Definition:Infinite Sequence|infinite sequence]] $\sequence {a_n}$ of [[Definition:Element|elements]] of $S$ such that: :$\forall n \in \N: \paren {...
Rank Function Property of Well-Founded Relation/Proof
https://proofwiki.org/wiki/Rank_Function_Property_of_Well-Founded_Relation
https://proofwiki.org/wiki/Rank_Function_Property_of_Well-Founded_Relation/Proof
[ "Well-Founded Relations", "Rank Functions", "Rank Function Property of Well-Founded Relation" ]
[ "Definition:Relational Structure", "Definition:Strictly Well-Ordered Set", "Definition:Rank Function for Relation", "Definition:Well-Founded Relation" ]
[ "Definition:Well-Founded Relation", "Infinite Sequence Property of Well-Founded Relation", "Definition:Sequence/Infinite Sequence", "Definition:Element", "Definition:Image (Set Theory)/Mapping/Subset", "Image is Subset of Codomain", "Definition:Smallest Element", "Definition:Smallest Element", "Defi...
proofwiki-18348
Set of Distributional Derivatives of Dirac Delta Distribution is Linearly Independent
Let $\delta \in \map {\DD'} \R$ be the Dirac delta distribution. Then for any $n \in \N$ the set of distributional derivatives $\set {\delta, \delta' \ldots, \delta^{\paren n} }$ is linearly independent in $\map {\DD'} \R$.
{{AimForCont}} there exist scalars $c_0, c_1, \ldots, c_n \in \R$ such that: :$\ds \sum_{i \mathop = 0}^n c_i \delta^{\paren i} = \mathbf 0$ where $\mathbf 0 : \map \DD \R \to 0$ is the zero distribution. Let $\phi \in \map \DD \R$ be a test function. Let $\lambda \in \R_{\mathop > 0}$ Let $\map {\phi_\lambda} x := \ma...
Let $\delta \in \map {\DD'} \R$ be the [[Definition:Dirac Delta Distribution|Dirac delta distribution]]. Then for any $n \in \N$ the [[Definition:Set|set]] of [[Definition:Distributional Derivative|distributional derivatives]] $\set {\delta, \delta' \ldots, \delta^{\paren n} }$ is [[Definition:Linearly Independent|li...
{{AimForCont}} there exist [[Definition:Scalar|scalars]] $c_0, c_1, \ldots, c_n \in \R$ such that: :$\ds \sum_{i \mathop = 0}^n c_i \delta^{\paren i} = \mathbf 0$ where $\mathbf 0 : \map \DD \R \to 0$ is the [[Definition:Zero Distribution|zero distribution]]. Let $\phi \in \map \DD \R$ be a [[Definition:Test Functio...
Set of Distributional Derivatives of Dirac Delta Distribution is Linearly Independent
https://proofwiki.org/wiki/Set_of_Distributional_Derivatives_of_Dirac_Delta_Distribution_is_Linearly_Independent
https://proofwiki.org/wiki/Set_of_Distributional_Derivatives_of_Dirac_Delta_Distribution_is_Linearly_Independent
[ "Distributional Derivatives", "Dirac Delta Function" ]
[ "Definition:Dirac Delta Distribution", "Definition:Set", "Definition:Distributional Derivative", "Definition:Linearly Independent" ]
[ "Definition:Scalar", "Definition:Zero Mapping/Schwartz Distribution", "Definition:Test Function", "Test Function with Rescaled Argument is Test Function", "Definition:Test Function", "Leibniz's Rule/One Variable", "Definition:Test Function", "Definition:Contradiction" ]
proofwiki-18349
Derivatives of Moment Generating Function of Logistic Distribution
The $n$th derivative of $M_X$ is given by: :$\ds {M_X}^{\paren n} = \map \exp {\mu t} \sum_{k \mathop = 0}^n \paren {-1}^k \dbinom n k \mu^{n - k} s^k \int_{\to 0}^{\to 1} \map {\ln^k} {\dfrac {1 - u} u} \paren {\dfrac {1 - u} u}^{-s t} \rd u$
The proof proceeds by induction on $n$. For all $n \in \Z_{\ge 0}$, let $\map P n$ be the proposition: :$\ds {M_X}^{\paren n} = \map \exp {\mu t} \sum_{k \mathop = 0}^n \paren {-1}^k \dbinom n k \mu^{n - k} s^k \int_{\to 0}^{\to 1} \map {\ln^k} {\dfrac {1 - u} u} \paren {\dfrac {1 - u} u}^{-s t} \rd u$
The [[Definition:Higher Derivative|$n$th derivative]] of $M_X$ is given by: :$\ds {M_X}^{\paren n} = \map \exp {\mu t} \sum_{k \mathop = 0}^n \paren {-1}^k \dbinom n k \mu^{n - k} s^k \int_{\to 0}^{\to 1} \map {\ln^k} {\dfrac {1 - u} u} \paren {\dfrac {1 - u} u}^{-s t} \rd u$
The proof proceeds by [[Principle of Mathematical Induction|induction]] on $n$. For all $n \in \Z_{\ge 0}$, let $\map P n$ be the [[Definition:Proposition|proposition]]: :$\ds {M_X}^{\paren n} = \map \exp {\mu t} \sum_{k \mathop = 0}^n \paren {-1}^k \dbinom n k \mu^{n - k} s^k \int_{\to 0}^{\to 1} \map {\ln^k} {\dfrac...
Derivatives of Moment Generating Function of Logistic Distribution
https://proofwiki.org/wiki/Derivatives_of_Moment_Generating_Function_of_Logistic_Distribution
https://proofwiki.org/wiki/Derivatives_of_Moment_Generating_Function_of_Logistic_Distribution
[ "Moment Generating Function of Logistic Distribution" ]
[ "Definition:Derivative/Higher Derivatives/Higher Order" ]
[ "Principle of Mathematical Induction", "Definition:Proposition", "Principle of Mathematical Induction" ]
proofwiki-18350
Representative of P-adic Number is Representative of Equivalence Class
Let $p$ be any prime number. Let $\struct {\Q_p, \norm {\,\cdot\,}_p}$ be the $p$-adic numbers. Let $x \in \Q_p$. Then for any sequence $\sequence{y_n}$ of the rational numbers $\Q$: :$\sequence{y_n}$ is a representative of the $p$-adic number $x$ {{iff}} $\sequence{y_n}$ is a representative of the equivalence class $x...
By definition of the $p$-adic numbers: :$\Q_p$ is quotient ring By definition of a quotient ring: :$\Q_p$ is a coset space By definition of a coset space: :Every $p$-adic number $x$ is an equivalence class By definitions of a representative of a $p$-adic number and a representative of an equivalence class: :for any seq...
Let $p$ be any [[Definition:Prime Number|prime number]]. Let $\struct {\Q_p, \norm {\,\cdot\,}_p}$ be the [[Definition:Valued Field of P-adic Numbers|$p$-adic numbers]]. Let $x \in \Q_p$. Then for any [[Definition:Sequence|sequence]] $\sequence{y_n}$ of the [[Definition:Rational Number|rational numbers]] $\Q$: :$\s...
By definition of the [[Definition:Field of P-adic Numbers|$p$-adic numbers]]: :$\Q_p$ is [[Definition:Quotient Ring|quotient ring]] By definition of a [[Definition:Quotient Ring|quotient ring]]: :$\Q_p$ is a [[Definition:Coset Space|coset space]] By definition of a [[Definition:Coset Space|coset space]]: :Every [[Def...
Representative of P-adic Number is Representative of Equivalence Class
https://proofwiki.org/wiki/Representative_of_P-adic_Number_is_Representative_of_Equivalence_Class
https://proofwiki.org/wiki/Representative_of_P-adic_Number_is_Representative_of_Equivalence_Class
[ "P-adic Number Theory" ]
[ "Definition:Prime Number", "Definition:Valued Field of P-adic Numbers", "Definition:Sequence", "Definition:Rational Number", "Definition:P-adic Number/Representative", "Definition:P-adic Number", "Definition:Equivalence Class/Representative", "Definition:Equivalence Class" ]
[ "Definition:Field of P-adic Numbers", "Definition:Quotient Ring", "Definition:Quotient Ring", "Definition:Coset Space", "Definition:Coset Space", "Definition:P-adic Number", "Definition:Equivalence Class", "Definition:P-adic Number/Representative", "Definition:Equivalence Class/Representative", "D...
proofwiki-18351
Distributional Partial Derivatives Commute
Let $T \in \map {\DD'} {\R^d}$ be a Schwartz distribution. Then in the distributional sense: :$\dfrac {\partial^2 T} {\partial x_i \partial x_j} = \dfrac {\partial^2 T} {\partial x_j \partial x_i}$ where: :$i, j \in \N : 1 \le i, j \le d$
Let $\phi \in \map \DD {\R^d}$ be a test function. {{begin-eqn}} {{eqn | l = \map {\dfrac {\partial^2 T} {\partial x_i \partial x_j} } \phi | r = -\map {\dfrac {\partial T} {\partial x_j} } {\dfrac {\partial \phi} {\partial x_i} } | c = {{Defof|Distributional Partial Derivative}} }} {{eqn | r = \map T {\dfr...
Let $T \in \map {\DD'} {\R^d}$ be a [[Definition:Schwartz Distribution|Schwartz distribution]]. Then in the [[Definition:Distributional Derivative|distributional sense]]: :$\dfrac {\partial^2 T} {\partial x_i \partial x_j} = \dfrac {\partial^2 T} {\partial x_j \partial x_i}$ where: :$i, j \in \N : 1 \le i, j \le d...
Let $\phi \in \map \DD {\R^d}$ be a [[Definition:Test Function|test function]]. {{begin-eqn}} {{eqn | l = \map {\dfrac {\partial^2 T} {\partial x_i \partial x_j} } \phi | r = -\map {\dfrac {\partial T} {\partial x_j} } {\dfrac {\partial \phi} {\partial x_i} } | c = {{Defof|Distributional Partial Derivative...
Distributional Partial Derivatives Commute
https://proofwiki.org/wiki/Distributional_Partial_Derivatives_Commute
https://proofwiki.org/wiki/Distributional_Partial_Derivatives_Commute
[ "Distributional Derivatives", "Examples of Commutative Operations" ]
[ "Definition:Schwartz Distribution", "Definition:Distributional Derivative" ]
[ "Definition:Test Function", "Clairaut's Theorem" ]
proofwiki-18352
Real Arctangent Function is Order Embedding into Reals
The real arctangent function $\arctan: \R \to \R$ is an order embedding on the set of real numbers under the usual ordering.
{{ProofWanted|straightforward but tedious. We should have Real Arctangent Function is Increasing for a start but we don't yet.}}
The [[Definition:Real Arctangent|real arctangent function]] $\arctan: \R \to \R$ is an [[Definition:Order Embedding|order embedding]] on the [[Definition:Real Number|set of real numbers]] under the [[Definition:Usual Ordering|usual ordering]].
{{ProofWanted|straightforward but tedious. We should have [[Real Arctangent Function is Increasing]] for a start but we don't yet.}}
Real Arctangent Function is Order Embedding into Reals
https://proofwiki.org/wiki/Real_Arctangent_Function_is_Order_Embedding_into_Reals
https://proofwiki.org/wiki/Real_Arctangent_Function_is_Order_Embedding_into_Reals
[ "Examples of Order Embeddings" ]
[ "Definition:Inverse Tangent/Real/Arctangent", "Definition:Order Embedding", "Definition:Real Number", "Definition:Usual Ordering" ]
[ "Real Arctangent Function is Increasing" ]
proofwiki-18353
Inclusion Mapping is Order Embedding
Let $\struct {S, \preccurlyeq_S}$ and $\struct {T, \preccurlyeq_T}$ be ordered sets such that $S \subseteq T$. Let ${\preccurlyeq_S} = {\preccurlyeq_T} {\restriction_S}$ be the restriction of $\preccurlyeq_T$ to $S$. Let $i_S: S \to T$ denote the inclusion mapping from $S$ to $T$: :$\forall s \in S: \map {i_S} s = s$ T...
We have that Inclusion Mapping is Restriction of Identity. Then we have that Identity Mapping is Order Isomorphism. The result follows. {{qed}}
Let $\struct {S, \preccurlyeq_S}$ and $\struct {T, \preccurlyeq_T}$ be [[Definition:Ordered Set|ordered sets]] such that $S \subseteq T$. Let ${\preccurlyeq_S} = {\preccurlyeq_T} {\restriction_S}$ be the [[Definition:Restriction of Relation|restriction]] of $\preccurlyeq_T$ to $S$. Let $i_S: S \to T$ denote the [[Def...
We have that [[Inclusion Mapping is Restriction of Identity]]. Then we have that [[Identity Mapping is Order Isomorphism]]. The result follows. {{qed}}
Inclusion Mapping is Order Embedding
https://proofwiki.org/wiki/Inclusion_Mapping_is_Order_Embedding
https://proofwiki.org/wiki/Inclusion_Mapping_is_Order_Embedding
[ "Examples of Order Embeddings" ]
[ "Definition:Ordered Set", "Definition:Restriction/Relation", "Definition:Inclusion Mapping", "Definition:Order Embedding" ]
[ "Inclusion Mapping is Restriction of Identity", "Identity Mapping is Order Isomorphism" ]
proofwiki-18354
Non-Injective Mapping may be Strictly Order-Preserving and Order-Reversing
Let $\struct {S, \prec_1}$ and $\struct {T, \prec_2}$ be strictly ordered sets. Let $\phi: S \to T$ be a mapping. Let $\pi: S \to T$ be a mapping with the property that: :$\forall x, y \in S: x \prec_1 y \iff \map \pi x \prec_2 \map \pi y$ Then it is not necessarily the case that $\pi$ is an injection.
Proof by Counterexample: Let $S = \set {\O, \set a, \set b, \set {a, b} }$ and $T = \set {1, 2, 3}$. Let $\prec_1$ be the proper subset relation: :$\forall x, y \in S: x \prec_1 y \iff x \subsetneq y$ Let $\prec_2$ be the usual strict ordering on the integers $1, 2, 3$: :$\forall x, y \in T: x \prec_2 y \iff x < y$ Let...
Let $\struct {S, \prec_1}$ and $\struct {T, \prec_2}$ be [[Definition:Strictly Ordered Set|strictly ordered sets]]. Let $\phi: S \to T$ be a [[Definition:Mapping|mapping]]. Let $\pi: S \to T$ be a [[Definition:Mapping|mapping]] with the property that: :$\forall x, y \in S: x \prec_1 y \iff \map \pi x \prec_2 \map \pi...
[[Proof by Counterexample]]: Let $S = \set {\O, \set a, \set b, \set {a, b} }$ and $T = \set {1, 2, 3}$. Let $\prec_1$ be the [[Definition:Proper Subset|proper subset]] relation: :$\forall x, y \in S: x \prec_1 y \iff x \subsetneq y$ Let $\prec_2$ be the [[Definition:Usual Ordering|usual]] [[Definition:Strict Orderi...
Non-Injective Mapping may be Strictly Order-Preserving and Order-Reversing
https://proofwiki.org/wiki/Non-Injective_Mapping_may_be_Strictly_Order-Preserving_and_Order-Reversing
https://proofwiki.org/wiki/Non-Injective_Mapping_may_be_Strictly_Order-Preserving_and_Order-Reversing
[ "Increasing Mappings" ]
[ "Definition:Strictly Ordered Set", "Definition:Mapping", "Definition:Mapping", "Definition:Injection" ]
[ "Proof by Counterexample", "Definition:Proper Subset", "Definition:Usual Ordering", "Definition:Strict Ordering", "Definition:Integer", "Definition:Mapping", "Definition:Injection" ]
proofwiki-18355
Strictly Order-Preserving and Order-Reversing Mapping on Strictly Totally Ordered Set is Injection
Let $\struct {S, \prec_1}$ and $\struct {T, \prec_2}$ be strictly totally ordered sets. Let $\phi: S \to T$ be a mapping. Let $\pi: S \to T$ be a mapping with the property that: :$\forall x, y \in S: x \prec_1 y \iff \map \pi x \prec_2 \map \pi y$ Then $\pi$ is an injection.
{{AimForCont}} $\pi$ is not an injection. Hence: :$\exists x, y \in S: \map \pi x = \map \pi y$ As $S$ is strictly totally ordered: :$x \prec_1 y$ or $y \prec_1 x$ {{WLOG}}, let $x \prec_1 y$. Then we have: :$\map \pi x = \map \pi y$ But {{hypothesis}}: :$\map \pi x \prec_2 \map \pi y$ Because $\prec_2$ is a strict ord...
Let $\struct {S, \prec_1}$ and $\struct {T, \prec_2}$ be [[Definition:Strictly Totally Ordered Set|strictly totally ordered sets]]. Let $\phi: S \to T$ be a [[Definition:Mapping|mapping]]. Let $\pi: S \to T$ be a [[Definition:Mapping|mapping]] with the property that: :$\forall x, y \in S: x \prec_1 y \iff \map \pi x ...
{{AimForCont}} $\pi$ is not an [[Definition:Injection|injection]]. Hence: :$\exists x, y \in S: \map \pi x = \map \pi y$ As $S$ is [[Definition:Strictly Totally Ordered Set|strictly totally ordered]]: :$x \prec_1 y$ or $y \prec_1 x$ {{WLOG}}, let $x \prec_1 y$. Then we have: :$\map \pi x = \map \pi y$ But {{hypoth...
Strictly Order-Preserving and Order-Reversing Mapping on Strictly Totally Ordered Set is Injection
https://proofwiki.org/wiki/Strictly_Order-Preserving_and_Order-Reversing_Mapping_on_Strictly_Totally_Ordered_Set_is_Injection
https://proofwiki.org/wiki/Strictly_Order-Preserving_and_Order-Reversing_Mapping_on_Strictly_Totally_Ordered_Set_is_Injection
[ "Increasing Mappings", "Total Orderings", "Strict Orderings" ]
[ "Definition:Strictly Totally Ordered Set", "Definition:Mapping", "Definition:Mapping", "Definition:Injection" ]
[ "Definition:Injection", "Definition:Strictly Totally Ordered Set", "Definition:Strict Ordering", "Proof by Contradiction", "Definition:Injection" ]
proofwiki-18356
Variance of Logistic Distribution
Let $X$ be a continuous random variable which satisfies the logistic distribution: :$X \sim \map {\operatorname {Logistic} } {\mu, s}$ The variance of $X$ is given by: :$\var X = \dfrac {s^2 \pi^2} 3$
From the definition of the logistic distribution, $X$ has probability density function: :$\map {f_X} x = \dfrac {\map \exp {-\dfrac {\paren {x - \mu} } s} } {s \paren {1 + \map \exp {-\dfrac {\paren {x - \mu} } s} }^2}$ From Variance as Expectation of Square minus Square of Expectation: :$\ds \var X = \int_{-\infty}^\...
Let $X$ be a [[Definition:Continuous Random Variable|continuous random variable]] which satisfies the [[Definition:Logistic Distribution|logistic distribution]]: :$X \sim \map {\operatorname {Logistic} } {\mu, s}$ The [[Definition:Variance|variance]] of $X$ is given by: :$\var X = \dfrac {s^2 \pi^2} 3$
From the definition of the [[Definition:Logistic Distribution|logistic distribution]], $X$ has [[Definition:Probability Density Function|probability density function]]: :$\map {f_X} x = \dfrac {\map \exp {-\dfrac {\paren {x - \mu} } s} } {s \paren {1 + \map \exp {-\dfrac {\paren {x - \mu} } s} }^2}$ From [[Variance a...
Variance of Logistic Distribution/Proof 1
https://proofwiki.org/wiki/Variance_of_Logistic_Distribution
https://proofwiki.org/wiki/Variance_of_Logistic_Distribution/Proof_1
[ "Variance", "Logistic Distribution", "Variance of Logistic Distribution" ]
[ "Definition:Random Variable/Continuous", "Definition:Logistic Distribution", "Definition:Variance" ]
[ "Definition:Logistic Distribution", "Definition:Probability Density Function", "Variance as Expectation of Square minus Square of Expectation/Continuous", "Integration by Substitution", "Power Rule for Derivatives", "Derivative of Composite Function", "Integral of Constant/Definite", "Difference of Lo...
proofwiki-18357
Variance of Logistic Distribution
Let $X$ be a continuous random variable which satisfies the logistic distribution: :$X \sim \map {\operatorname {Logistic} } {\mu, s}$ The variance of $X$ is given by: :$\var X = \dfrac {s^2 \pi^2} 3$
By Moment Generating Function of Logistic Distribution, the moment generating function of $X$ is given by: :$\ds \map {M_X} t = \map \exp {\mu t} \int_{\to 0}^{\to 1} \paren {\dfrac {1 - u} u}^{-s t} \rd u$ for $\size t < \dfrac 1 s$. From Variance as Expectation of Square minus Square of Expectation: :$\ds \var X...
Let $X$ be a [[Definition:Continuous Random Variable|continuous random variable]] which satisfies the [[Definition:Logistic Distribution|logistic distribution]]: :$X \sim \map {\operatorname {Logistic} } {\mu, s}$ The [[Definition:Variance|variance]] of $X$ is given by: :$\var X = \dfrac {s^2 \pi^2} 3$
By [[Moment Generating Function of Logistic Distribution]], the [[Definition:Moment Generating Function|moment generating function]] of $X$ is given by: :$\ds \map {M_X} t = \map \exp {\mu t} \int_{\to 0}^{\to 1} \paren {\dfrac {1 - u} u}^{-s t} \rd u$ for $\size t < \dfrac 1 s$. From [[Variance as Expectation o...
Variance of Logistic Distribution/Proof 2
https://proofwiki.org/wiki/Variance_of_Logistic_Distribution
https://proofwiki.org/wiki/Variance_of_Logistic_Distribution/Proof_2
[ "Variance", "Logistic Distribution", "Variance of Logistic Distribution" ]
[ "Definition:Random Variable/Continuous", "Definition:Logistic Distribution", "Definition:Variance" ]
[ "Moment Generating Function of Logistic Distribution", "Definition:Moment Generating Function", "Variance as Expectation of Square minus Square of Expectation/Continuous", "Expectation of Logistic Distribution", "Moment Generating Function of Logistic Distribution/Examples/Second Moment", "Integral of Con...
proofwiki-18358
Variance of Logistic Distribution
Let $X$ be a continuous random variable which satisfies the logistic distribution: :$X \sim \map {\operatorname {Logistic} } {\mu, s}$ The variance of $X$ is given by: :$\var X = \dfrac {s^2 \pi^2} 3$
From the definition of the logistic distribution, $X$ has probability density function: :$\map {f_X} x = \dfrac {\map \exp {-\dfrac {\paren {x - \mu} } s} } {s \paren {1 + \map \exp {-\dfrac {\paren {x - \mu} } s} }^2}$ From Variance as Expectation of Square minus Square of Expectation: :$\ds \var X = \int_{-\infty}^\...
Let $X$ be a [[Definition:Continuous Random Variable|continuous random variable]] which satisfies the [[Definition:Logistic Distribution|logistic distribution]]: :$X \sim \map {\operatorname {Logistic} } {\mu, s}$ The [[Definition:Variance|variance]] of $X$ is given by: :$\var X = \dfrac {s^2 \pi^2} 3$
From the definition of the [[Definition:Logistic Distribution|logistic distribution]], $X$ has [[Definition:Probability Density Function|probability density function]]: :$\map {f_X} x = \dfrac {\map \exp {-\dfrac {\paren {x - \mu} } s} } {s \paren {1 + \map \exp {-\dfrac {\paren {x - \mu} } s} }^2}$ From [[Variance a...
Variance of Logistic Distribution/Proof 3
https://proofwiki.org/wiki/Variance_of_Logistic_Distribution
https://proofwiki.org/wiki/Variance_of_Logistic_Distribution/Proof_3
[ "Variance", "Logistic Distribution", "Variance of Logistic Distribution" ]
[ "Definition:Random Variable/Continuous", "Definition:Logistic Distribution", "Definition:Variance" ]
[ "Definition:Logistic Distribution", "Definition:Probability Density Function", "Variance as Expectation of Square minus Square of Expectation/Continuous", "Sum of Integrals on Adjacent Intervals for Integrable Functions", "Sum of Infinite Geometric Sequence", "Definition:Derivative/Real Function", "Fubi...
proofwiki-18359
P-adic Numbers form Completion of Rational Numbers with P-adic Norm
Let $p$ be a prime number. Let $\norm {\,\cdot\,}^\Q_p$ be the $p$-adic norm on the rationals $\Q$. Let $\struct {\Q_p, \norm {\,\cdot\,}_p}$ be the $p$-adic numbers. Then $\struct {\Q_p, \norm {\,\cdot\,}_p}$ is a completion of $\struct {\Q, \norm {\,\cdot\,}^\Q_p}$
Let $\norm {\,\cdot\,}^\Q_p$ be the $p$-adic norm on the rationals $\Q$. From $p$-adic Norm on Rational Numbers is Non-Archimedean Norm: :$\struct{\Q, \norm {\,\cdot\,}^\Q_p}$ is a valued field with non-Archimedean norm $\norm {\,\cdot\,}_p$ By {{Defof|Field of P-adic Numbers|Field of $p$-adic Numbers}}: :$\Q_p$ is th...
Let $p$ be a [[Definition:Prime Number|prime number]]. Let $\norm {\,\cdot\,}^\Q_p$ be the [[Definition:P-adic Norm|$p$-adic norm]] on the [[Definition:Rational Numbers|rationals $\Q$]]. Let $\struct {\Q_p, \norm {\,\cdot\,}_p}$ be the [[Definition:Valued Field of P-adic Numbers|$p$-adic numbers]]. Then $\struct {\...
Let $\norm {\,\cdot\,}^\Q_p$ be the [[Definition:P-adic Norm|$p$-adic norm]] on the [[Definition:Rational Numbers|rationals $\Q$]]. From [[P-adic Norm on Rational Numbers is Non-Archimedean Norm|$p$-adic Norm on Rational Numbers is Non-Archimedean Norm]]: :$\struct{\Q, \norm {\,\cdot\,}^\Q_p}$ is a [[Definition:Valued...
P-adic Numbers form Completion of Rational Numbers with P-adic Norm
https://proofwiki.org/wiki/P-adic_Numbers_form_Completion_of_Rational_Numbers_with_P-adic_Norm
https://proofwiki.org/wiki/P-adic_Numbers_form_Completion_of_Rational_Numbers_with_P-adic_Norm
[ "P-adic Number Theory" ]
[ "Definition:Prime Number", "Definition:P-adic Norm", "Definition:Rational Number", "Definition:Valued Field of P-adic Numbers", "Definition:Completion (Normed Division Ring)" ]
[ "Definition:P-adic Norm", "Definition:Rational Number", "P-adic Norm forms Non-Archimedean Valued Field/Rational Numbers", "Definition:Valued Field", "Definition:Non-Archimedean/Norm (Division Ring)", "Definition:Quotient Ring", "Definition:Ring of Cauchy Sequences", "Definition:Set", "Definition:Nu...
proofwiki-18360
Kurtosis in terms of Non-Central Moments
Let $X$ be a random variable with expectation $\mu$ and standard deviation $\sigma$. Then the kurtosis $\alpha_4$ of $X$ is given by: :$\ds \alpha_4 = \dfrac {\expect {X^4} - 4 \mu \expect {X^3} + 6 \mu^2 \expect {X^2} - 3 \mu^4} {\sigma^4}$
{{begin-eqn}} {{eqn | l = \alpha_4 | r = \expect {\paren {\dfrac {X - \mu} \sigma}^4} | c = {{Defof|Kurtosis}} }} {{eqn | r = \dfrac {\expect {X^4 - 4 X^3 \mu + 6 X^2 \mu^2 - 4 X \mu^3 + \mu^4} } {\sigma^4} | c = Fourth Power of Difference }} {{eqn | r = \dfrac {\expect {X^4} - 4 \mu \expect {X^3} + 6...
Let $X$ be a [[Definition:Random Variable|random variable]] with [[Definition:Expectation|expectation]] $\mu$ and [[Definition:Standard Deviation|standard deviation]] $\sigma$. Then the [[Definition:Kurtosis|kurtosis]] $\alpha_4$ of $X$ is given by: :$\ds \alpha_4 = \dfrac {\expect {X^4} - 4 \mu \expect {X^3} + 6 \m...
{{begin-eqn}} {{eqn | l = \alpha_4 | r = \expect {\paren {\dfrac {X - \mu} \sigma}^4} | c = {{Defof|Kurtosis}} }} {{eqn | r = \dfrac {\expect {X^4 - 4 X^3 \mu + 6 X^2 \mu^2 - 4 X \mu^3 + \mu^4} } {\sigma^4} | c = [[Fourth Power of Difference]] }} {{eqn | r = \dfrac {\expect {X^4} - 4 \mu \expect {X^3}...
Kurtosis in terms of Non-Central Moments
https://proofwiki.org/wiki/Kurtosis_in_terms_of_Non-Central_Moments
https://proofwiki.org/wiki/Kurtosis_in_terms_of_Non-Central_Moments
[ "Kurtosis" ]
[ "Definition:Random Variable", "Definition:Expectation", "Definition:Standard Deviation", "Definition:Kurtosis" ]
[ "Binomial Theorem/Examples/4th Power of Difference", "Expectation is Linear", "Category:Kurtosis" ]
proofwiki-18361
Mutual Order Embedding does not imply Order Isomorphism
Let $\struct {S_1, \preceq_1}$ and $\struct {S_2, \preceq_2}$ be ordered sets. Let it be possible for: :$\struct {S_1, \preceq_1}$ to be embedded in $\struct {S_2, \preceq_2}$ :$\struct {S_2, \preceq_2}$ to be embedded in $\struct {S_1, \preceq_1}$. Then it is not necessarily the case that $\struct {S_1, \preceq_1}$ an...
Consider the ordered structures: :$\struct {S_1, \preceq_1} := \struct {\R, \le}$ :$\struct {S_2, \preceq_2} := \struct {\hointl {-\dfrac \pi 2} {\dfrac \pi 2}, \le}$ From Real Arctangent Function is Order Embedding into Reals, $\struct {S_1, \preceq_1}$ can be embedded into $\struct {S_2, \preceq_2}$. From Inclusion M...
Let $\struct {S_1, \preceq_1}$ and $\struct {S_2, \preceq_2}$ be [[Definition:Ordered Set|ordered sets]]. Let it be possible for: :$\struct {S_1, \preceq_1}$ to be [[Definition:Order Embedding|embedded]] in $\struct {S_2, \preceq_2}$ :$\struct {S_2, \preceq_2}$ to be [[Definition:Order Embedding|embedded]] in $\struct...
Consider the [[Definition:Ordered Structure|ordered structures]]: :$\struct {S_1, \preceq_1} := \struct {\R, \le}$ :$\struct {S_2, \preceq_2} := \struct {\hointl {-\dfrac \pi 2} {\dfrac \pi 2}, \le}$ From [[Real Arctangent Function is Order Embedding into Reals]], $\struct {S_1, \preceq_1}$ can be embedded into $\st...
Mutual Order Embedding does not imply Order Isomorphism
https://proofwiki.org/wiki/Mutual_Order_Embedding_does_not_imply_Order_Isomorphism
https://proofwiki.org/wiki/Mutual_Order_Embedding_does_not_imply_Order_Isomorphism
[ "Order Embeddings", "Order Isomorphisms" ]
[ "Definition:Ordered Set", "Definition:Order Embedding", "Definition:Order Embedding", "Definition:Order Isomorphism/Isomorphic Sets" ]
[ "Definition:Ordered Structure", "Real Arctangent Function is Order Embedding into Reals", "Inclusion Mapping is Order Embedding", "Definition:Order Isomorphism/Isomorphic Sets", "Number of Maximal Elements is Order Property", "Definition:Maximal/Element", "Definition:Maximal/Element", "Definition:Maxi...
proofwiki-18362
Number of Minimal Elements is Order Property
Let $\struct {S, \preccurlyeq}$ be an ordered set. Let $\map m S$ be the number of minimal elements of $\struct {S, \preccurlyeq}$. Then $\map m S$ is an order property.
Let $\struct {S_1, \preccurlyeq_1}$ and $\struct {S_2, \preccurlyeq_2}$ be isomorphic ordered sets. Hence let $\phi: S_1 \to S_2$ be an order isomorphism. By definition of order property, we need to show that the number of minimal elements of $\struct {S_1, \preccurlyeq_1}$ is equal to the number of minimal elements of...
Let $\struct {S, \preccurlyeq}$ be an [[Definition:Ordered Set|ordered set]]. Let $\map m S$ be the number of [[Definition:Minimal Element|minimal elements]] of $\struct {S, \preccurlyeq}$. Then $\map m S$ is an [[Definition:Order Property|order property]].
Let $\struct {S_1, \preccurlyeq_1}$ and $\struct {S_2, \preccurlyeq_2}$ be [[Definition:Isomorphic Ordered Sets|isomorphic ordered sets]]. Hence let $\phi: S_1 \to S_2$ be an [[Definition:Order Isomorphism|order isomorphism]]. By definition of [[Definition:Order Property|order property]], we need to show that the num...
Number of Minimal Elements is Order Property
https://proofwiki.org/wiki/Number_of_Minimal_Elements_is_Order_Property
https://proofwiki.org/wiki/Number_of_Minimal_Elements_is_Order_Property
[ "Examples of Order Properties", "Minimal Elements" ]
[ "Definition:Ordered Set", "Definition:Minimal/Element", "Definition:Order Property" ]
[ "Definition:Order Isomorphism/Isomorphic Sets", "Definition:Order Isomorphism", "Definition:Order Property", "Definition:Minimal/Element", "Definition:Minimal/Element", "Definition:Minimal/Element", "Definition:Order Isomorphism", "Definition:Minimal/Element", "Order Embedding is Injection", "Defi...
proofwiki-18363
Number of Maximal Elements is Order Property
Let $\struct {S, \preccurlyeq}$ be an ordered set. Let $\map M S$ be the number of maximal elements of $\struct {S, \preccurlyeq}$. Then $\map M S$ is an order property.
Let $\struct {S_1, \preccurlyeq_1}$ and $\struct {S_2, \preccurlyeq_2}$ be isomorphic ordered sets. Hence let $\phi: S_1 \to S_2$ be an order isomorphism. By definition of order property, we need to show that the number of maximal elements of $\struct {S_1, \preccurlyeq_1}$ is equal to the number of maximal elements of...
Let $\struct {S, \preccurlyeq}$ be an [[Definition:Ordered Set|ordered set]]. Let $\map M S$ be the number of [[Definition:Maximal Element|maximal elements]] of $\struct {S, \preccurlyeq}$. Then $\map M S$ is an [[Definition:Order Property|order property]].
Let $\struct {S_1, \preccurlyeq_1}$ and $\struct {S_2, \preccurlyeq_2}$ be [[Definition:Isomorphic Ordered Sets|isomorphic ordered sets]]. Hence let $\phi: S_1 \to S_2$ be an [[Definition:Order Isomorphism|order isomorphism]]. By definition of [[Definition:Order Property|order property]], we need to show that the num...
Number of Maximal Elements is Order Property
https://proofwiki.org/wiki/Number_of_Maximal_Elements_is_Order_Property
https://proofwiki.org/wiki/Number_of_Maximal_Elements_is_Order_Property
[ "Examples of Order Properties", "Maximal Elements" ]
[ "Definition:Ordered Set", "Definition:Maximal/Element", "Definition:Order Property" ]
[ "Definition:Order Isomorphism/Isomorphic Sets", "Definition:Order Isomorphism", "Definition:Order Property", "Definition:Maximal/Element", "Definition:Maximal/Element", "Definition:Maximal/Element", "Definition:Order Isomorphism", "Definition:Maximal/Element", "Order Embedding is Injection", "Defi...
proofwiki-18364
Densely Ordered is Order Property
Let $\struct {S_1, \preccurlyeq_1}$ and $\struct {S_2, \preccurlyeq_2}$ be isomorphic ordered sets. Let $\struct {S_1, \preccurlyeq_1}$ be densely ordered. Then $\struct {S_2, \preccurlyeq_2}$ is also densely ordered. That is, the property of being densely ordered is an order property.
Let $\struct {S_1, \preccurlyeq_1}$ and $\struct {S_2, \preccurlyeq_2}$ be isomorphic ordered sets. Let $\struct {S_1, \preccurlyeq_1}$ be densely ordered. Let $a, b \in S_2$ such that $a \prec b$. Then as $\phi$ is an order isomorphism: :$\exists p, q \in S_1: a = \map \phi p, b = \map \phi q$ Then by definition of de...
Let $\struct {S_1, \preccurlyeq_1}$ and $\struct {S_2, \preccurlyeq_2}$ be [[Definition:Isomorphic Ordered Sets|isomorphic ordered sets]]. Let $\struct {S_1, \preccurlyeq_1}$ be [[Definition:Densely Ordered|densely ordered]]. Then $\struct {S_2, \preccurlyeq_2}$ is also [[Definition:Densely Ordered|densely ordered]]...
Let $\struct {S_1, \preccurlyeq_1}$ and $\struct {S_2, \preccurlyeq_2}$ be [[Definition:Isomorphic Ordered Sets|isomorphic ordered sets]]. Let $\struct {S_1, \preccurlyeq_1}$ be [[Definition:Densely Ordered|densely ordered]]. Let $a, b \in S_2$ such that $a \prec b$. Then as $\phi$ is an [[Definition:Order Isomorph...
Densely Ordered is Order Property
https://proofwiki.org/wiki/Densely_Ordered_is_Order_Property
https://proofwiki.org/wiki/Densely_Ordered_is_Order_Property
[ "Examples of Order Properties", "Densely Ordered" ]
[ "Definition:Order Isomorphism/Isomorphic Sets", "Definition:Densely Ordered", "Definition:Densely Ordered", "Definition:Property", "Definition:Densely Ordered", "Definition:Order Property" ]
[ "Definition:Order Isomorphism/Isomorphic Sets", "Definition:Densely Ordered", "Definition:Order Isomorphism", "Definition:Densely Ordered", "Definition:Order Isomorphism", "Definition:Densely Ordered" ]
proofwiki-18365
Order Isomorphism is Symmetric
Let $\struct {S_1, \preccurlyeq_1}$ and $\struct {S_2, \preccurlyeq_2}$ be ordered sets. Let $\struct {S_1, \preccurlyeq_1}$ be isomorphic to $\struct {S_2, \preccurlyeq_2}$. Then $\struct {S_2, \preccurlyeq_2}$ is isomorphic to $\struct {S_1, \preccurlyeq_1}$.
Let $\phi: S_1 \to S_2$ be an order isomorphism from $\struct {S_1, \preccurlyeq_1}$ to $\struct {S_2, \preccurlyeq_2}$. From Inverse of Order Isomorphism is Order Isomorphism, $\phi^{-1}: S_2 \to S_1$ is an order isomorphism from $\struct {S_2, \preccurlyeq_2}$ to $\struct {S_1, \preccurlyeq_1}$. The result follows. {...
Let $\struct {S_1, \preccurlyeq_1}$ and $\struct {S_2, \preccurlyeq_2}$ be [[Definition:Ordered Set|ordered sets]]. Let $\struct {S_1, \preccurlyeq_1}$ be [[Definition:Isomorphic Ordered Sets|isomorphic]] to $\struct {S_2, \preccurlyeq_2}$. Then $\struct {S_2, \preccurlyeq_2}$ is [[Definition:Isomorphic Ordered Sets...
Let $\phi: S_1 \to S_2$ be an [[Definition:Order Isomorphism|order isomorphism]] from $\struct {S_1, \preccurlyeq_1}$ to $\struct {S_2, \preccurlyeq_2}$. From [[Inverse of Order Isomorphism is Order Isomorphism]], $\phi^{-1}: S_2 \to S_1$ is an [[Definition:Order Isomorphism|order isomorphism]] from $\struct {S_2, \pr...
Order Isomorphism is Symmetric
https://proofwiki.org/wiki/Order_Isomorphism_is_Symmetric
https://proofwiki.org/wiki/Order_Isomorphism_is_Symmetric
[ "Order Isomorphisms", "Symmetric Relations" ]
[ "Definition:Ordered Set", "Definition:Order Isomorphism/Isomorphic Sets", "Definition:Order Isomorphism/Isomorphic Sets" ]
[ "Definition:Order Isomorphism", "Inverse of Order Isomorphism is Order Isomorphism", "Definition:Order Isomorphism" ]
proofwiki-18366
Order Isomorphism is Transitive
Let $\struct {S_1, \preccurlyeq_1}$, $\struct {S_2, \preccurlyeq_2}$ and $\struct {S_3, \preccurlyeq_3}$ be ordered sets. Let $\struct {S_1, \preccurlyeq_1}$ be isomorphic to $\struct {S_2, \preccurlyeq_2}$. Let $\struct {S_2, \preccurlyeq_2}$ be isomorphic to $\struct {S_3, \preccurlyeq_3}$. Then $\struct {S_1, \precc...
Let $\phi: S_1 \to S_2$ be an order isomorphism from $\struct {S_1, \preccurlyeq_1}$ to $\struct {S_2, \preccurlyeq_2}$. Let $\psi: S_2 \to S_3$ be an order isomorphism from $\struct {S_2, \preccurlyeq_2}$ to $\struct {S_3, \preccurlyeq_3}$. From Composite of Order Isomorphisms is Order Isomorphism, $\psi \circ \phi: S...
Let $\struct {S_1, \preccurlyeq_1}$, $\struct {S_2, \preccurlyeq_2}$ and $\struct {S_3, \preccurlyeq_3}$ be [[Definition:Ordered Set|ordered sets]]. Let $\struct {S_1, \preccurlyeq_1}$ be [[Definition:Isomorphic Ordered Sets|isomorphic]] to $\struct {S_2, \preccurlyeq_2}$. Let $\struct {S_2, \preccurlyeq_2}$ be [[Def...
Let $\phi: S_1 \to S_2$ be an [[Definition:Order Isomorphism|order isomorphism]] from $\struct {S_1, \preccurlyeq_1}$ to $\struct {S_2, \preccurlyeq_2}$. Let $\psi: S_2 \to S_3$ be an [[Definition:Order Isomorphism|order isomorphism]] from $\struct {S_2, \preccurlyeq_2}$ to $\struct {S_3, \preccurlyeq_3}$. From [[Com...
Order Isomorphism is Transitive
https://proofwiki.org/wiki/Order_Isomorphism_is_Transitive
https://proofwiki.org/wiki/Order_Isomorphism_is_Transitive
[ "Order Isomorphisms", "Examples of Transitive Relations" ]
[ "Definition:Ordered Set", "Definition:Order Isomorphism/Isomorphic Sets", "Definition:Order Isomorphism/Isomorphic Sets", "Definition:Order Isomorphism/Isomorphic Sets" ]
[ "Definition:Order Isomorphism", "Definition:Order Isomorphism", "Composite of Order Isomorphisms is Order Isomorphism", "Definition:Order Isomorphism" ]
proofwiki-18367
Collection of All Ordered Sets is not Set
Let $\mathrm {OS}$ denote the collection of all ordered sets. Then $\mathrm {OS}$ is not a set.
Let $C$ be the collection of all singletons: :$\set {x: \exists y: x = \set y}$ Define a mapping $\map f {\set y} = \RR$ where $\RR$ is a reflexive relation on $\set y$. By Reflexive Relation on Singleton is Well-Ordering, $\RR$ is an ordering. Thus: :$f: C \to \mathrm {OS}$ By Equality of Ordered Pairs: :$\map f {y_1}...
Let $\mathrm {OS}$ denote the [[Definition:Collection|collection]] of all [[Definition:Ordered Set|ordered sets]]. Then $\mathrm {OS}$ is not a [[Definition:Set|set]].
Let $C$ be the [[Definition:Collection|collection]] of all [[Definition:Singleton|singletons]]: :$\set {x: \exists y: x = \set y}$ Define a [[Definition:Mapping|mapping]] $\map f {\set y} = \RR$ where $\RR$ is a [[Definition:Reflexive Relation|reflexive relation]] on $\set y$. By [[Reflexive Relation on Singleton is ...
Collection of All Ordered Sets is not Set
https://proofwiki.org/wiki/Collection_of_All_Ordered_Sets_is_not_Set
https://proofwiki.org/wiki/Collection_of_All_Ordered_Sets_is_not_Set
[ "Ordered Sets" ]
[ "Definition:Collection", "Definition:Ordered Set", "Definition:Set" ]
[ "Definition:Collection", "Definition:Singleton", "Definition:Mapping", "Definition:Reflexive Relation", "Reflexive Relation on Singleton is Well-Ordering", "Definition:Ordering", "Equality of Ordered Pairs", "Definition:Injection", "Definition:Cardinality", "Definition:Collection", "Definition:S...
proofwiki-18368
Order Sum of Well-Founded Orderings is Well-Founded Ordering
Let $\struct {S_1, \preccurlyeq_1}$ and $\struct {S_2, \preccurlyeq_2}$ be ordered sets. Let $\preccurlyeq_1$ and $\preccurlyeq_2$ be well-founded. Then the order sum $\struct {S_1, \preccurlyeq_1} \oplus \struct {S_2, \preccurlyeq_2}$ of $\struct {S_1, \preccurlyeq_1}$ and $\struct {S_2, \preccurlyeq_2}$ is also well-...
Let $\struct {S, \preccurlyeq} := \struct {S_1, \preccurlyeq_1} \oplus \struct {S_2, \preccurlyeq_2}$. Let $T \subseteq S$ such that $T \ne \O$. Let $T = T_1 \sqcup T_2$ where $T_1 \subseteq S_1$ and $T_2 \subseteq S_2$. Let $T_1 \ne \O$. Then: :$\exists x \in T_1: \forall y \in T_1: y \preccurlyeq x \implies y = x$ Th...
Let $\struct {S_1, \preccurlyeq_1}$ and $\struct {S_2, \preccurlyeq_2}$ be [[Definition:Ordered Set|ordered sets]]. Let $\preccurlyeq_1$ and $\preccurlyeq_2$ be [[Definition:Well-Founded Ordering|well-founded]]. Then the [[Definition:Order Sum|order sum]] $\struct {S_1, \preccurlyeq_1} \oplus \struct {S_2, \preccurl...
Let $\struct {S, \preccurlyeq} := \struct {S_1, \preccurlyeq_1} \oplus \struct {S_2, \preccurlyeq_2}$. Let $T \subseteq S$ such that $T \ne \O$. Let $T = T_1 \sqcup T_2$ where $T_1 \subseteq S_1$ and $T_2 \subseteq S_2$. Let $T_1 \ne \O$. Then: :$\exists x \in T_1: \forall y \in T_1: y \preccurlyeq x \implies y = ...
Order Sum of Well-Founded Orderings is Well-Founded Ordering
https://proofwiki.org/wiki/Order_Sum_of_Well-Founded_Orderings_is_Well-Founded_Ordering
https://proofwiki.org/wiki/Order_Sum_of_Well-Founded_Orderings_is_Well-Founded_Ordering
[ "Order Sums", "Well-Founded Relations" ]
[ "Definition:Ordered Set", "Definition:Well-Founded Ordered Set", "Definition:Order Sum", "Definition:Well-Founded Ordered Set" ]
[ "Definition:Minimal/Element", "Definition:Order Sum", "Definition:Order Sum", "Definition:Vacuous Truth", "Definition:Minimal/Element", "Definition:Minimal/Element", "Definition:Element", "Definition:Minimal/Element", "Definition:Order Sum", "Definition:Minimal/Element", "Definition:Minimal/Elem...
proofwiki-18369
Order Sum of Totally Ordered Sets is Totally Ordered
Let $\struct {S_1, \preccurlyeq_1}$ and $\struct {S_2, \preccurlyeq_2}$ be totally ordered sets. Then the order sum $\struct {S_1, \preccurlyeq_1} \oplus \struct {S_2, \preccurlyeq_2}$ of $\struct {S_1, \preccurlyeq_1}$ and $\struct {S_2, \preccurlyeq_2}$ is also a totally ordered set.
Let $\struct {S, \preccurlyeq} := \struct {S_1, \preccurlyeq_1} \oplus \struct {S_2, \preccurlyeq_2}$. From Order Sum of Ordered Sets is Ordered, $\struct {S, \preccurlyeq}$ is an ordered set. It remains to be shown that $\tuple {a, b}$ and $\tuple {c, d}$ are comparable for all $\tuple {a, b}, \tuple {c, d} \in S$. Le...
Let $\struct {S_1, \preccurlyeq_1}$ and $\struct {S_2, \preccurlyeq_2}$ be [[Definition:Totally Ordered Set|totally ordered sets]]. Then the [[Definition:Order Sum|order sum]] $\struct {S_1, \preccurlyeq_1} \oplus \struct {S_2, \preccurlyeq_2}$ of $\struct {S_1, \preccurlyeq_1}$ and $\struct {S_2, \preccurlyeq_2}$ is...
Let $\struct {S, \preccurlyeq} := \struct {S_1, \preccurlyeq_1} \oplus \struct {S_2, \preccurlyeq_2}$. From [[Order Sum of Ordered Sets is Ordered]], $\struct {S, \preccurlyeq}$ is an [[Definition:Ordered Set|ordered set]]. It remains to be shown that $\tuple {a, b}$ and $\tuple {c, d}$ are [[Definition:Comparable E...
Order Sum of Totally Ordered Sets is Totally Ordered
https://proofwiki.org/wiki/Order_Sum_of_Totally_Ordered_Sets_is_Totally_Ordered
https://proofwiki.org/wiki/Order_Sum_of_Totally_Ordered_Sets_is_Totally_Ordered
[ "Order Sums", "Total Orderings" ]
[ "Definition:Totally Ordered Set", "Definition:Order Sum", "Definition:Totally Ordered Set" ]
[ "Order Sum of Ordered Sets is Ordered", "Definition:Ordered Set", "Definition:Comparable Elements", "Definition:Total Ordering", "Definition:Comparable Elements", "Definition:Comparable Elements", "Definition:Total Ordering", "Definition:Comparable Elements", "Definition:Comparable Elements", "Def...
proofwiki-18370
Order Sum of Ordered Sets is Ordered
Let $\struct {S_1, \preccurlyeq_1}$ and $\struct {S_2, \preccurlyeq_2}$ be ordered sets. Then the order sum $\struct {S_1, \preccurlyeq_1} \oplus \struct {S_2, \preccurlyeq_2}$ of $\struct {S_1, \preccurlyeq_1}$ and $\struct {S_2, \preccurlyeq_2}$ is also an ordered set.
Let $\struct {S, \preccurlyeq} := \struct {S_1, \preccurlyeq_1} \oplus \struct {S_2, \preccurlyeq_2}$. By definition: ::$\forall \tuple {a, b}, \tuple {c, d} \in S: \tuple {a, b} \preccurlyeq \tuple {c, d} \iff \begin {cases} b = 0 \text { and } d = 1 \\ b = d = 0 \text { and } a \preccurlyeq_1 c \\ b = d = 1 \text { a...
Let $\struct {S_1, \preccurlyeq_1}$ and $\struct {S_2, \preccurlyeq_2}$ be [[Definition:Ordered Set|ordered sets]]. Then the [[Definition:Order Sum|order sum]] $\struct {S_1, \preccurlyeq_1} \oplus \struct {S_2, \preccurlyeq_2}$ of $\struct {S_1, \preccurlyeq_1}$ and $\struct {S_2, \preccurlyeq_2}$ is also an [[Defin...
Let $\struct {S, \preccurlyeq} := \struct {S_1, \preccurlyeq_1} \oplus \struct {S_2, \preccurlyeq_2}$. By definition: ::$\forall \tuple {a, b}, \tuple {c, d} \in S: \tuple {a, b} \preccurlyeq \tuple {c, d} \iff \begin {cases} b = 0 \text { and } d = 1 \\ b = d = 0 \text { and } a \preccurlyeq_1 c \\ b = d = 1 \text ...
Order Sum of Ordered Sets is Ordered
https://proofwiki.org/wiki/Order_Sum_of_Ordered_Sets_is_Ordered
https://proofwiki.org/wiki/Order_Sum_of_Ordered_Sets_is_Ordered
[ "Order Sums" ]
[ "Definition:Ordered Set", "Definition:Order Sum", "Definition:Ordered Set" ]
[ "Definition:Ordering", "Definition:Ordering" ]
proofwiki-18371
Order Isomorphism is Preserved by Order Sum
Let $\struct {S_1, \preccurlyeq_1}$ and $\struct {S_2, \preccurlyeq_2}$ be ordered sets. Let $\struct {T_1, \preccurlyeq_{1'} }$ and $\struct {T_2, \preccurlyeq_{2'} }$ be ordered sets such that: :$\struct {S_1, \preccurlyeq_1}$ is isomorphic to $\struct {T_1, \preccurlyeq_{1'} }$ :$\struct {S_2, \preccurlyeq_2}$ is is...
{{ProofWanted|tedium city or what}}
Let $\struct {S_1, \preccurlyeq_1}$ and $\struct {S_2, \preccurlyeq_2}$ be [[Definition:Ordered Set|ordered sets]]. Let $\struct {T_1, \preccurlyeq_{1'} }$ and $\struct {T_2, \preccurlyeq_{2'} }$ be [[Definition:Ordered Set|ordered sets]] such that: :$\struct {S_1, \preccurlyeq_1}$ is [[Definition:Isomorphic Ordered ...
{{ProofWanted|tedium city or what}}
Order Isomorphism is Preserved by Order Sum
https://proofwiki.org/wiki/Order_Isomorphism_is_Preserved_by_Order_Sum
https://proofwiki.org/wiki/Order_Isomorphism_is_Preserved_by_Order_Sum
[ "Order Sums", "Order Isomorphisms" ]
[ "Definition:Ordered Set", "Definition:Ordered Set", "Definition:Order Isomorphism/Isomorphic Sets", "Definition:Order Isomorphism/Isomorphic Sets", "Definition:Order Sum", "Definition:Order Isomorphism/Isomorphic Sets" ]
[]
proofwiki-18372
Mixed Partial Derivative of Heaviside Step Function
Let $\tuple {x, y} \stackrel u {\longrightarrow} \map u {x, y}: \R^2 \to \R$ be the Heaviside step function. Let $u := T_u$ be the Schwartz distribution associated with $u$. Let $\delta_{\tuple {0, 0} } \in \map {\DD'} {\R^2}$ be the Dirac delta distribution. Then in the distributional sense: :$\dfrac {\partial^2 u} {\...
Let $\phi \in \map \DD {\R^2}$ be a test function with support on $\openint 0 a^2 := \openint 0 a \times \openint 0 a$ where $\times$ is the Cartesian product and $a > 0$. Then: {{begin-eqn}} {{eqn | l = \map {\dfrac {\partial^2 u}{\partial x \partial y} } \phi | r = - \map {\dfrac {\partial u}{\partial y} } {\df...
Let $\tuple {x, y} \stackrel u {\longrightarrow} \map u {x, y}: \R^2 \to \R$ be the [[Definition:Heaviside Step Function/Two Variables|Heaviside step function]]. Let $u := T_u$ be the [[Definition:Schwartz Distribution|Schwartz distribution]] [[Differentiable Function as Distribution|associated]] with $u$. Let $\delt...
Let $\phi \in \map \DD {\R^2}$ be a [[Definition:Test Function|test function]] with [[Definition:Support of Schwartz Distribution|support]] on $\openint 0 a^2 := \openint 0 a \times \openint 0 a$ where $\times$ is the [[Definition:Cartesian Product|Cartesian product]] and $a > 0$. Then: {{begin-eqn}} {{eqn | l = \map...
Mixed Partial Derivative of Heaviside Step Function
https://proofwiki.org/wiki/Mixed_Partial_Derivative_of_Heaviside_Step_Function
https://proofwiki.org/wiki/Mixed_Partial_Derivative_of_Heaviside_Step_Function
[ "Heaviside Step Function", "Examples of Distributional Derivatives" ]
[ "Definition:Heaviside Step Function/Two Variables", "Definition:Schwartz Distribution", "Differentiable Function as Distribution", "Definition:Dirac Delta Distribution", "Definition:Distributional Derivative" ]
[ "Definition:Test Function", "Definition:Support of Schwartz Distribution", "Definition:Cartesian Product", "Clairaut's Theorem", "Definite Integral of Partial Derivative" ]
proofwiki-18373
Order Type Addition is Well-Defined Operation
The addition operation on order types is well-defined.
Let $\struct {S_1, \preccurlyeq_1}$ and $\struct {S_2, \preccurlyeq_2}$ be ordered sets. Let $\struct {T_1, \preccurlyeq_{1'} }$ and $\struct {T_2, \preccurlyeq_{2'} }$ be ordered sets such that: :$\struct {S_1, \preccurlyeq_1}$ is isomorphic to $\struct {T_1, \preccurlyeq_{1'} }$ :$\struct {S_2, \preccurlyeq_2}$ is is...
The [[Definition:Addition of Order Types|addition operation]] on [[Definition:Order Type|order types]] is [[Definition:Well-Defined Operation|well-defined]].
Let $\struct {S_1, \preccurlyeq_1}$ and $\struct {S_2, \preccurlyeq_2}$ be [[Definition:Ordered Set|ordered sets]]. Let $\struct {T_1, \preccurlyeq_{1'} }$ and $\struct {T_2, \preccurlyeq_{2'} }$ be [[Definition:Ordered Set|ordered sets]] such that: :$\struct {S_1, \preccurlyeq_1}$ is [[Definition:Isomorphic Ordered ...
Order Type Addition is Well-Defined Operation
https://proofwiki.org/wiki/Order_Type_Addition_is_Well-Defined_Operation
https://proofwiki.org/wiki/Order_Type_Addition_is_Well-Defined_Operation
[ "Order Types", "Addition", "Order Sums" ]
[ "Definition:Addition of Order Types", "Definition:Order Type", "Definition:Well-Defined/Operation" ]
[ "Definition:Ordered Set", "Definition:Ordered Set", "Definition:Order Isomorphism/Isomorphic Sets", "Definition:Order Isomorphism/Isomorphic Sets", "Definition:Order Type", "Definition:Order Type", "Order Isomorphism is Preserved by Order Sum" ]
proofwiki-18374
Dual of Well-Ordering is not necessarily Well-Ordering
Let $\struct {S, \preccurlyeq}$ be a well-ordered set. Then its dual $\struct {S, \preccurlyeq}$ is not necessarily also a well-ordered set.
Consider the ordered structure $\struct {\N, \le}$. From the Well-Ordering Principle, $\struct {\N, \le}$ is a well-ordered set.. Consider the dual $\struct {\N, \ge}$ of $\struct {\N, \le}$. Let this be expressed as: :$\struct {\N, \preccurlyeq} := \struct {\N, \ge}$ so as to enhance the clarification of the nature of...
Let $\struct {S, \preccurlyeq}$ be a [[Definition:Well-Ordered Set|well-ordered set]]. Then its [[Definition:Dual Ordered Set|dual]] $\struct {S, \preccurlyeq}$ is not necessarily also a [[Definition:Well-Ordered Set|well-ordered set]].
Consider the [[Definition:Ordered Structure|ordered structure]] $\struct {\N, \le}$. From the [[Well-Ordering Principle]], $\struct {\N, \le}$ is a [[Definition:Well-Ordered Set|well-ordered set]].. Consider the [[Definition:Dual Ordered Set|dual]] $\struct {\N, \ge}$ of $\struct {\N, \le}$. Let this be expressed as...
Dual of Well-Ordering is not necessarily Well-Ordering
https://proofwiki.org/wiki/Dual_of_Well-Ordering_is_not_necessarily_Well-Ordering
https://proofwiki.org/wiki/Dual_of_Well-Ordering_is_not_necessarily_Well-Ordering
[ "Well-Orderings", "Dual Orderings" ]
[ "Definition:Well-Ordered Set", "Definition:Dual Ordering/Dual Ordered Set", "Definition:Well-Ordered Set" ]
[ "Definition:Ordered Structure", "Well-Ordering Principle", "Definition:Well-Ordered Set", "Definition:Dual Ordering/Dual Ordered Set", "Definition:Ordering", "Dual of Total Ordering is Total Ordering", "Definition:Totally Ordered Set", "Definition:Well-Ordered Set", "Definition:Minimal/Element", "...
proofwiki-18375
Order Types of Duals of Isomorphic Sets are Equal
Let $\struct {S_1, \preccurlyeq_1}$ and $\struct {S_2, \preccurlyeq_2}$ be ordered sets. Let: :$\map \ot {S_1, \preccurlyeq_1} = \map \ot {S_2, \preccurlyeq_2}$ where $\ot$ denotes the order type operator. Let $\struct {S_1, \succcurlyeq_1}$ and $\struct {S_2, \succcurlyeq_2}$ denote the dual ordered sets of $\struct {...
{{ProofWanted|when it doesn't look quite so tedious}}
Let $\struct {S_1, \preccurlyeq_1}$ and $\struct {S_2, \preccurlyeq_2}$ be [[Definition:Ordered Set|ordered sets]]. Let: :$\map \ot {S_1, \preccurlyeq_1} = \map \ot {S_2, \preccurlyeq_2}$ where $\ot$ denotes the [[Definition:Order Type|order type operator]]. Let $\struct {S_1, \succcurlyeq_1}$ and $\struct {S_2, \suc...
{{ProofWanted|when it doesn't look quite so tedious}}
Order Types of Duals of Isomorphic Sets are Equal
https://proofwiki.org/wiki/Order_Types_of_Duals_of_Isomorphic_Sets_are_Equal
https://proofwiki.org/wiki/Order_Types_of_Duals_of_Isomorphic_Sets_are_Equal
[ "Order Types", "Dual Orderings" ]
[ "Definition:Ordered Set", "Definition:Order Type", "Definition:Dual Ordering/Dual Ordered Set" ]
[]
proofwiki-18376
Dual of Order Type is Well-Defined Mapping
The dual operation on order types is a well-defined mapping.
Let $\struct {S_1, \preccurlyeq_1}$ and $\struct {S_2, \preccurlyeq_2}$ be ordered sets. Let $\struct {S_1, \succcurlyeq_1}$ and $\struct {S_2, \succcurlyeq_2}$ denote the dual ordered sets of $\struct {S_1, \preccurlyeq_1}$ and $\struct {S_2, \preccurlyeq_2}$. Let $\struct {S_1, \preccurlyeq_1} \cong \struct {S_2, \pr...
The [[Definition:Dual of Order Type|dual operation]] on [[Definition:Order Type|order types]] is a [[Definition:Well-Defined Mapping|well-defined mapping]].
Let $\struct {S_1, \preccurlyeq_1}$ and $\struct {S_2, \preccurlyeq_2}$ be [[Definition:Ordered Set|ordered sets]]. Let $\struct {S_1, \succcurlyeq_1}$ and $\struct {S_2, \succcurlyeq_2}$ denote the [[Definition:Dual Ordered Set|dual ordered sets]] of $\struct {S_1, \preccurlyeq_1}$ and $\struct {S_2, \preccurlyeq_2}$...
Dual of Order Type is Well-Defined Mapping
https://proofwiki.org/wiki/Dual_of_Order_Type_is_Well-Defined_Mapping
https://proofwiki.org/wiki/Dual_of_Order_Type_is_Well-Defined_Mapping
[ "Dual Orderings" ]
[ "Definition:Dual of Order Type", "Definition:Order Type", "Definition:Well-Defined/Mapping" ]
[ "Definition:Ordered Set", "Definition:Dual Ordering/Dual Ordered Set", "Definition:Order Isomorphism", "Definition:Order Type", "Definition:Order Type", "Definition:Dual of Order Type", "Order Types of Duals of Isomorphic Sets are Equal", "Definition:Well-Defined/Mapping" ]
proofwiki-18377
Raw Moment of Pareto Distribution
Let $X$ be a continuous random variable with the Pareto distribution with $a, b \in \R_{> 0}$. Let $n$ be a strictly positive integer. Then the $n$th raw moment $\expect {X^n}$ of $X$ is given by: :$\expect {X^n} = \begin {cases} \dfrac {a b^n} {a - n} & n < a \\ \text {does not exist} & n \ge a \end {cases}$
From the definition of the Pareto distribution, $X$ has probability density function: :$\map {f_X} x = \dfrac {a b^a} {x^{a + 1} }$ Where $\Img X \in \hointr b \infty$. From the definition of the expected value of a continuous random variable: :$\ds \expect {X^n} = \int_b^\infty x^n \map {f_X} x \rd x$ First take $a >...
Let $X$ be a [[Definition:Continuous Random Variable|continuous random variable]] with the [[Definition:Pareto Distribution|Pareto distribution]] with $a, b \in \R_{> 0}$. Let $n$ be a [[Definition:Strictly Positive Integer|strictly positive integer]]. Then the $n$th [[Definition:Raw Moment|raw moment]] $\expect {X...
From the definition of the [[Definition:Pareto Distribution|Pareto distribution]], $X$ has [[Definition:Probability Density Function|probability density function]]: :$\map {f_X} x = \dfrac {a b^a} {x^{a + 1} }$ Where $\Img X \in \hointr b \infty$. From the definition of the [[Definition:Expectation of Continuous Ra...
Raw Moment of Pareto Distribution
https://proofwiki.org/wiki/Raw_Moment_of_Pareto_Distribution
https://proofwiki.org/wiki/Raw_Moment_of_Pareto_Distribution
[ "Pareto Distribution", "Raw Moments" ]
[ "Definition:Random Variable/Continuous", "Definition:Pareto Distribution", "Definition:Strictly Positive/Integer", "Definition:Raw Moment" ]
[ "Definition:Pareto Distribution", "Definition:Probability Density Function", "Definition:Expectation/Continuous", "Primitive of Power", "Primitive of Reciprocal", "Logarithm Tends to Infinity", "Primitive of Power", "Category:Pareto Distribution", "Category:Raw Moments" ]
proofwiki-18378
Expectation of Pareto Distribution
Let $X$ be a continuous random variable with the Pareto distribution with $a, b \in \R_{> 0}$. The expectation of $X$ is given by: :$\expect X = \begin {cases} \dfrac {a b} {a - 1} & 1 < a \\ \text {does not exist} & 1 \ge a \end {cases}$
From Raw Moment of Pareto Distribution, we have: The $n$th raw moment $\expect {X^n}$ of $X$ is given by: :$\expect {X^n} = \begin {cases} \dfrac {a b^n} {a - n} & n < a \\ \text {does not exist} & n \ge a \end {cases}$ Therefore, for $n = 1$ we have: :$\expect X = \begin {cases} \dfrac {a b} {a - 1} & 1 < a \\ \text ...
Let $X$ be a [[Definition:Continuous Random Variable|continuous random variable]] with the [[Definition:Pareto Distribution|Pareto distribution]] with $a, b \in \R_{> 0}$. The [[Definition:Expectation of Continuous Random Variable|expectation]] of $X$ is given by: :$\expect X = \begin {cases} \dfrac {a b} {a - 1} & 1...
From [[Raw Moment of Pareto Distribution]], we have: The $n$th [[Definition:Raw Moment|raw moment]] $\expect {X^n}$ of $X$ is given by: :$\expect {X^n} = \begin {cases} \dfrac {a b^n} {a - n} & n < a \\ \text {does not exist} & n \ge a \end {cases}$ Therefore, for $n = 1$ we have: :$\expect X = \begin {cases} \df...
Expectation of Pareto Distribution
https://proofwiki.org/wiki/Expectation_of_Pareto_Distribution
https://proofwiki.org/wiki/Expectation_of_Pareto_Distribution
[ "Pareto Distribution", "Expectation" ]
[ "Definition:Random Variable/Continuous", "Definition:Pareto Distribution", "Definition:Expectation/Continuous" ]
[ "Raw Moment of Pareto Distribution", "Definition:Raw Moment", "Category:Pareto Distribution", "Category:Expectation" ]
proofwiki-18379
Variance of Pareto Distribution
Let $X$ be a continuous random variable with the Pareto distribution with $a, b \in \R_{> 0}$. Then the variance of $X$ is given by: :$\var X = \begin {cases} \dfrac {a b^2 } {\paren {a - 2} \paren {a - 1}^2 } & 2 < a \\ \text {does not exist} & 2 \ge a \end {cases}$
By Variance as Expectation of Square minus Square of Expectation, we have: :$\var X = \expect {X^2} - \paren {\expect X}^2$ By Expectation of Pareto Distribution, we have: :$\expect X = \begin {cases} \dfrac {a b} {a - 1} & 1 < a \\ \text {does not exist} & 1 \ge a \end {cases}$ From Raw Moment of Pareto Distribution...
Let $X$ be a [[Definition:Continuous Random Variable|continuous random variable]] with the [[Definition:Pareto Distribution|Pareto distribution]] with $a, b \in \R_{> 0}$. Then the [[Definition:Variance|variance]] of $X$ is given by: :$\var X = \begin {cases} \dfrac {a b^2 } {\paren {a - 2} \paren {a - 1}^2 } & 2 < ...
By [[Variance as Expectation of Square minus Square of Expectation]], we have: :$\var X = \expect {X^2} - \paren {\expect X}^2$ By [[Expectation of Pareto Distribution]], we have: :$\expect X = \begin {cases} \dfrac {a b} {a - 1} & 1 < a \\ \text {does not exist} & 1 \ge a \end {cases}$ From [[Raw Moment of Paret...
Variance of Pareto Distribution
https://proofwiki.org/wiki/Variance_of_Pareto_Distribution
https://proofwiki.org/wiki/Variance_of_Pareto_Distribution
[ "Variance", "Pareto Distribution" ]
[ "Definition:Random Variable/Continuous", "Definition:Pareto Distribution", "Definition:Variance" ]
[ "Variance as Expectation of Square minus Square of Expectation", "Expectation of Pareto Distribution", "Raw Moment of Pareto Distribution", "Definition:Raw Moment", "Category:Variance", "Category:Pareto Distribution" ]
proofwiki-18380
Ordered Set with Order Type of Natural Numbers plus Dual has Minimum Element
Let $\struct {S, \preccurlyeq}$ be an ordered structure such that: :$\map \ot {S, \preccurlyeq} = \omega + \omega^*$ where: :$\ot$ denotes order type :$\omega$ denotes the order type of the natural numbers $\N$ :$\omega^*$ denotes the dual of $\omega$ :$+$ denotes addition of order types. Then $\struct {S, \preccurlyeq...
By definition of order type addition: :$\struct {S, \preccurlyeq}$ is isomorphic to $\struct {\N, \le} \oplus \struct {\N, \ge}$ where: :$\cong$ denotes order isomorphism :$\oplus$ denotes order sum. By the Well-Ordering Principle, $\struct {\N, \le}$ has a smallest element. By definition of order sum, every element of...
Let $\struct {S, \preccurlyeq}$ be an [[Definition:Ordered Structure|ordered structure]] such that: :$\map \ot {S, \preccurlyeq} = \omega + \omega^*$ where: :$\ot$ denotes [[Definition:Order Type|order type]] :$\omega$ denotes the [[Definition:Order Type of Natural Numbers|order type]] of the [[Definition:Natural Numbe...
By definition of [[Definition:Addition of Order Types|order type addition]]: :$\struct {S, \preccurlyeq}$ is [[Definition:Isomorphic Ordered Sets|isomorphic]] to $\struct {\N, \le} \oplus \struct {\N, \ge}$ where: :$\cong$ denotes [[Definition:Order Isomorphism|order isomorphism]] :$\oplus$ denotes [[Definition:Order S...
Ordered Set with Order Type of Natural Numbers plus Dual has Minimum Element
https://proofwiki.org/wiki/Ordered_Set_with_Order_Type_of_Natural_Numbers_plus_Dual_has_Minimum_Element
https://proofwiki.org/wiki/Ordered_Set_with_Order_Type_of_Natural_Numbers_plus_Dual_has_Minimum_Element
[ "Examples of Order Types" ]
[ "Definition:Ordered Structure", "Definition:Order Type", "Definition:Order Type of Natural Numbers", "Definition:Natural Numbers", "Definition:Dual of Order Type", "Definition:Addition of Order Types", "Definition:Smallest Element" ]
[ "Definition:Addition of Order Types", "Definition:Order Isomorphism/Isomorphic Sets", "Definition:Order Isomorphism", "Definition:Order Sum", "Well-Ordering Principle", "Definition:Smallest Element", "Definition:Order Sum", "Definition:Element", "Definition:Precede", "Definition:Element", "Defin...
proofwiki-18381
Order Type Addition is not Commutative
The operation of order type addition is not commutative.
Consider the order type $\omega^* + \omega$, where: :$\omega$ denotes the order type of the natural numbers $\N$ :$\omega^*$ denotes the dual of $\omega$ :$+$ denotes addition of order types. From Order Type of Integers under Usual Ordering, this is the order type of $\struct {\Z, \le}$, the set of integers under the u...
The [[Definition:Binary Operation|operation]] of [[Definition:Addition of Order Types|order type addition]] is not [[Definition:Commutative Operation|commutative]].
Consider the [[Definition:Order Type|order type]] $\omega^* + \omega$, where: :$\omega$ denotes the [[Definition:Order Type of Natural Numbers|order type]] of the [[Definition:Natural Numbers|natural numbers]] $\N$ :$\omega^*$ denotes the [[Definition:Dual of Order Type|dual]] of $\omega$ :$+$ denotes [[Definition:Addi...
Order Type Addition is not Commutative
https://proofwiki.org/wiki/Order_Type_Addition_is_not_Commutative
https://proofwiki.org/wiki/Order_Type_Addition_is_not_Commutative
[ "Order Types", "Examples of Commutative Operations" ]
[ "Definition:Operation/Binary Operation", "Definition:Addition of Order Types", "Definition:Commutative/Operation" ]
[ "Definition:Order Type", "Definition:Order Type of Natural Numbers", "Definition:Natural Numbers", "Definition:Dual of Order Type", "Definition:Addition of Order Types", "Order Type of Integers under Usual Ordering", "Definition:Order Type", "Definition:Integer", "Definition:Usual Ordering", "Defi...
proofwiki-18382
Skewness of Pareto Distribution
Let $X$ be a continuous random variable with the Pareto distribution with $a, b \in \R_{> 0}$. Then the skewness $\gamma_1$ of $X$ is given by: :$\gamma_1 = \begin {cases} \paren {\sqrt {\dfrac {\paren {a - 2} } a } } \paren { \dfrac {2 \paren {a + 1} } {a - 3} } & 3 < a \\ \text {does not exist} & 3 \ge a \end {cases}...
From Skewness in terms of Non-Central Moments, we have: :$\gamma_1 = \dfrac {\expect {X^3} - 3 \mu \sigma^2 - \mu^3} {\sigma^3}$ where: :$\mu$ is the expectation of $X$. :$\sigma$ is the standard deviation of $X$. By Expectation of Pareto Distribution we have: :$\mu = \dfrac {a b } {\paren {a - 1} }$ By Variance o...
Let $X$ be a [[Definition:Continuous Random Variable|continuous random variable]] with the [[Definition:Pareto Distribution|Pareto distribution]] with $a, b \in \R_{> 0}$. Then the [[Definition:Skewness|skewness]] $\gamma_1$ of $X$ is given by: :$\gamma_1 = \begin {cases} \paren {\sqrt {\dfrac {\paren {a - 2} } a } }...
From [[Skewness in terms of Non-Central Moments]], we have: :$\gamma_1 = \dfrac {\expect {X^3} - 3 \mu \sigma^2 - \mu^3} {\sigma^3}$ where: :$\mu$ is the [[Definition:Expectation|expectation]] of $X$. :$\sigma$ is the [[Definition:Standard Deviation|standard deviation]] of $X$. By [[Expectation of Pareto Distribu...
Skewness of Pareto Distribution
https://proofwiki.org/wiki/Skewness_of_Pareto_Distribution
https://proofwiki.org/wiki/Skewness_of_Pareto_Distribution
[ "Skewness", "Pareto Distribution" ]
[ "Definition:Random Variable/Continuous", "Definition:Pareto Distribution", "Definition:Skewness" ]
[ "Skewness in terms of Non-Central Moments", "Definition:Expectation", "Definition:Standard Deviation", "Expectation of Pareto Distribution", "Variance of Pareto Distribution", "Raw Moment of Pareto Distribution", "Definition:Fraction/Numerator", "Definition:Fraction/Denominator", "Category:Skewness"...
proofwiki-18383
Simple Order Product of Pair of Ordered Sets is Ordered Set
Let $\struct {S_1, \preccurlyeq_1}$ and $\struct {S_2, \preccurlyeq_2}$ be ordered sets. Let $\struct {S_1, \preccurlyeq_1} \otimes^s \struct {S_2, \preccurlyeq_2}$ denote the '''simple (order) product''' of $\struct {S_1, \preccurlyeq_1}$ and $\struct {S_2, \preccurlyeq_2}$. Then $\struct {S_1, \preccurlyeq_1} \otimes...
Let $\struct {T, \preccurlyeq_s} := \struct {S_1, \preccurlyeq_1} \otimes^s \struct {S_2, \preccurlyeq_2}$. By definition of simple product: :$T := S_1 \times S_2$ where $\times$ denotes Cartesian product :$\forall \tuple {a, b}, \tuple {c, d} \in T: \tuple {a, b} \preccurlyeq_s \tuple {c, d} \iff a \preccurlyeq_1 c \t...
Let $\struct {S_1, \preccurlyeq_1}$ and $\struct {S_2, \preccurlyeq_2}$ be [[Definition:Ordered Set|ordered sets]]. Let $\struct {S_1, \preccurlyeq_1} \otimes^s \struct {S_2, \preccurlyeq_2}$ denote the '''[[Definition:Simple Order Product|simple (order) product]]''' of $\struct {S_1, \preccurlyeq_1}$ and $\struct {S_...
Let $\struct {T, \preccurlyeq_s} := \struct {S_1, \preccurlyeq_1} \otimes^s \struct {S_2, \preccurlyeq_2}$. By definition of [[Definition:Simple Order Product|simple product]]: :$T := S_1 \times S_2$ where $\times$ denotes [[Definition:Cartesian Product|Cartesian product]] :$\forall \tuple {a, b}, \tuple {c, d} \in...
Simple Order Product of Pair of Ordered Sets is Ordered Set
https://proofwiki.org/wiki/Simple_Order_Product_of_Pair_of_Ordered_Sets_is_Ordered_Set
https://proofwiki.org/wiki/Simple_Order_Product_of_Pair_of_Ordered_Sets_is_Ordered_Set
[ "Simple Order Product" ]
[ "Definition:Ordered Set", "Definition:Simple Order Product", "Definition:Ordered Set" ]
[ "Definition:Simple Order Product", "Definition:Cartesian Product", "Definition:Ordering", "Definition:Cartesian Product", "Definition:Ordering", "Definition:Simple Order Product", "Definition:Simple Order Product", "Definition:Ordering", "Definition:Simple Order Product", "Definition:Simple Order ...
proofwiki-18384
Simple Order Product of Totally Ordered Sets may not be Totally Ordered
Let $\struct {S_1, \preccurlyeq_1}$ and $\struct {S_2, \preccurlyeq_2}$ be totally ordered sets. Let $\struct {S_1, \preccurlyeq_1} \otimes^s \struct {S_2, \preccurlyeq_2}$ denote the '''simple (order) product''' of $\struct {S_1, \preccurlyeq_1}$ and $\struct {S_2, \preccurlyeq_2}$. Then it is not necessarily the case...
From Simple Order Product of Pair of Ordered Sets is Ordered Set, we do have that $\struct {S_1, \preccurlyeq_1} \otimes^s \struct {S_2, \preccurlyeq_2}$ is an ordered set. Let us take the simple product of the ordered set that is the natural numbers under the usual ordering with itself: :$\struct {\N, \le} \otimes^s \...
Let $\struct {S_1, \preccurlyeq_1}$ and $\struct {S_2, \preccurlyeq_2}$ be [[Definition:Totally Ordered Set|totally ordered sets]]. Let $\struct {S_1, \preccurlyeq_1} \otimes^s \struct {S_2, \preccurlyeq_2}$ denote the '''[[Definition:Simple Order Product|simple (order) product]]''' of $\struct {S_1, \preccurlyeq_1}$ ...
From [[Simple Order Product of Pair of Ordered Sets is Ordered Set]], we do have that $\struct {S_1, \preccurlyeq_1} \otimes^s \struct {S_2, \preccurlyeq_2}$ is an [[Definition:Ordered Set|ordered set]]. Let us take the [[Definition:Simple Order Product|simple product]] of the [[Definition:Ordered Set|ordered set]] th...
Simple Order Product of Totally Ordered Sets may not be Totally Ordered
https://proofwiki.org/wiki/Simple_Order_Product_of_Totally_Ordered_Sets_may_not_be_Totally_Ordered
https://proofwiki.org/wiki/Simple_Order_Product_of_Totally_Ordered_Sets_may_not_be_Totally_Ordered
[ "Simple Order Product", "Total Orderings" ]
[ "Definition:Totally Ordered Set", "Definition:Simple Order Product", "Definition:Totally Ordered Set" ]
[ "Simple Order Product of Pair of Ordered Sets is Ordered Set", "Definition:Ordered Set", "Definition:Simple Order Product", "Definition:Ordered Set", "Definition:Natural Numbers", "Definition:Usual Ordering", "Well-Ordering Principle", "Definition:Well-Ordered Set", "Definition:Totally Ordered Set",...
proofwiki-18385
Antilexicographic Order is Ordering
Let $\struct {S_1, \preccurlyeq_1}$ and $\struct {S_2, \preccurlyeq_2}$ be ordered sets. Let $\preccurlyeq_a$ be the lexicographic order on $S_1 \times S_2$''': :$\tuple {x_1, x_2} \preccurlyeq_a \tuple {y_1, y_2} \iff \paren {x_2 \prec_2 y_2} \lor \paren {x_2 = y_2 \land x_1 \preccurlyeq_1 y_1}$ Then $\preccurlyeq_a$ ...
In the following, $\tuple {x_1, x_2}, \tuple {y_1, y_2}, \tuple {z_1, z_2} \in S_1 \times S_2$. Checking in turn each of the criteria for an ordering:
Let $\struct {S_1, \preccurlyeq_1}$ and $\struct {S_2, \preccurlyeq_2}$ be [[Definition:Ordered Set|ordered sets]]. Let $\preccurlyeq_a$ be the [[Definition:Lexicographic Order|lexicographic order on $S_1 \times S_2$]]''': :$\tuple {x_1, x_2} \preccurlyeq_a \tuple {y_1, y_2} \iff \paren {x_2 \prec_2 y_2} \lor \paren {...
In the following, $\tuple {x_1, x_2}, \tuple {y_1, y_2}, \tuple {z_1, z_2} \in S_1 \times S_2$. Checking in turn each of the criteria for an [[Definition:Ordering|ordering]]:
Antilexicographic Order is Ordering
https://proofwiki.org/wiki/Antilexicographic_Order_is_Ordering
https://proofwiki.org/wiki/Antilexicographic_Order_is_Ordering
[ "Antilexicographic Order" ]
[ "Definition:Ordered Set", "Definition:Lexicographic Order", "Definition:Ordering" ]
[ "Definition:Ordering", "Definition:Ordering", "Definition:Ordering", "Definition:Ordering", "Definition:Ordering", "Definition:Ordering" ]
proofwiki-18386
Moment Generating Function of Pareto Distribution
Let $X$ be a continuous random variable with a Pareto distribution with parameters a and b for $a, b \in \R_{> 0}$. Then the moment generating function $M_X$ of $X$ is given by: :$\map {M_X} t = \begin {cases} a \paren {-b t}^a \map \Gamma {-a, -b t} & t < 0 \\ 1 & t = 0 \\ \text {does not exist} & t > 0 \end {cases}...
From the definition of the Pareto distribution, $X$ has probability density function: :$\map {f_X} x = \dfrac {a b^a} {x^{a + 1} }$ From the definition of a moment generating function: :$\ds \map {M_X} t = \expect { e^{t X} } = \int_b^\infty e^{t x} \map {f_X} x \rd x$ First take $t < 0$. Then: :$\ds \map {M_X} t = a ...
Let $X$ be a [[Definition:Continuous Random Variable|continuous random variable]] with a [[Definition:Pareto Distribution|Pareto distribution with parameters a and b]] for $a, b \in \R_{> 0}$. Then the [[Definition:Moment Generating Function|moment generating function]] $M_X$ of $X$ is given by: :$\map {M_X} t = \...
From the definition of the [[Definition:Pareto Distribution|Pareto distribution]], $X$ has [[Definition:Probability Density Function|probability density function]]: :$\map {f_X} x = \dfrac {a b^a} {x^{a + 1} }$ From the definition of a [[Definition:Moment Generating Function|moment generating function]]: :$\ds \map ...
Moment Generating Function of Pareto Distribution
https://proofwiki.org/wiki/Moment_Generating_Function_of_Pareto_Distribution
https://proofwiki.org/wiki/Moment_Generating_Function_of_Pareto_Distribution
[ "Moment Generating Functions", "Pareto Distribution" ]
[ "Definition:Random Variable/Continuous", "Definition:Pareto Distribution", "Definition:Moment Generating Function" ]
[ "Definition:Pareto Distribution", "Definition:Probability Density Function", "Definition:Moment Generating Function", "Power Rule for Derivatives", "Primitive of Power", "Fundamental Theorem of Calculus", "Primitive of Exponential of a x over Power of x", "Exponential Dominates Polynomial", "Categor...
proofwiki-18387
Skewness of Logistic Distribution
Let $X$ be a continuous random variable which satisfies the logistic distribution: :$X \sim \map {\operatorname {Logistic} } {\mu, s}$ Then the skewness $\gamma_1$ of $X$ is equal to $0$.
From Skewness in terms of Non-Central Moments, we have: :$\gamma_1 = \dfrac {\expect {X^3} - 3 \mu \sigma^2 - \mu^3} {\sigma^3}$ where: :$\mu$ is the expectation of $X$. :$\sigma$ is the standard deviation of $X$. By Expectation of Logistic Distribution we have: :$\mu = \mu$ By Variance of Logistic Distribution we...
Let $X$ be a [[Definition:Continuous Random Variable|continuous random variable]] which satisfies the [[Definition:Logistic Distribution|logistic distribution]]: :$X \sim \map {\operatorname {Logistic} } {\mu, s}$ Then the [[Definition:Skewness|skewness]] $\gamma_1$ of $X$ is equal to $0$.
From [[Skewness in terms of Non-Central Moments]], we have: :$\gamma_1 = \dfrac {\expect {X^3} - 3 \mu \sigma^2 - \mu^3} {\sigma^3}$ where: :$\mu$ is the [[Definition:Expectation|expectation]] of $X$. :$\sigma$ is the [[Definition:Standard Deviation|standard deviation]] of $X$. By [[Expectation of Logistic Distri...
Skewness of Logistic Distribution
https://proofwiki.org/wiki/Skewness_of_Logistic_Distribution
https://proofwiki.org/wiki/Skewness_of_Logistic_Distribution
[ "Skewness", "Logistic Distribution" ]
[ "Definition:Random Variable/Continuous", "Definition:Logistic Distribution", "Definition:Skewness" ]
[ "Skewness in terms of Non-Central Moments", "Definition:Expectation", "Definition:Standard Deviation", "Expectation of Logistic Distribution", "Variance of Logistic Distribution", "Moment in terms of Moment Generating Function", "Definition:Moment Generating Function", "Derivatives of Moment Generatin...
proofwiki-18388
Antilexicographic Product on Pair of Well-Ordered Sets is Well-Ordered
Let $\struct {S_1, \preccurlyeq_1}$ and $\struct {S_2, \preccurlyeq_2}$ be well-ordered sets. Let $S_1 \otimes^a S_2 = \struct {S_1 \times S_2, \preccurlyeq_a}$ be the antilexicographic product of $S_1$ and $S_2$. Then $\struct {S_1 \times S_2, \preccurlyeq_a}$ is itself a well-ordered set.
By definition, a well-ordered set is a totally ordered set which is well-founded. From Antilexicographic Product of Totally Ordered Sets is Totally Ordered, we have that $\preccurlyeq_a$ is a totally ordered set. It remains to be shown that $\preccurlyeq_a$ is a well-founded relation. Let $T = S_1 \times S_2$. Let $A$ ...
Let $\struct {S_1, \preccurlyeq_1}$ and $\struct {S_2, \preccurlyeq_2}$ be [[Definition:Well-Ordered Set|well-ordered sets]]. Let $S_1 \otimes^a S_2 = \struct {S_1 \times S_2, \preccurlyeq_a}$ be the [[Definition:Antilexicographic Order|antilexicographic product]] of $S_1$ and $S_2$. Then $\struct {S_1 \times S_2, \...
By definition, a [[Definition:Well-Ordered Set|well-ordered set]] is a [[Definition:Totally Ordered Set|totally ordered set]] which is [[Definition:Well-Founded Set|well-founded]]. From [[Antilexicographic Product of Totally Ordered Sets is Totally Ordered]], we have that $\preccurlyeq_a$ is a [[Definition:Totally Ord...
Antilexicographic Product on Pair of Well-Ordered Sets is Well-Ordered
https://proofwiki.org/wiki/Antilexicographic_Product_on_Pair_of_Well-Ordered_Sets_is_Well-Ordered
https://proofwiki.org/wiki/Antilexicographic_Product_on_Pair_of_Well-Ordered_Sets_is_Well-Ordered
[ "Well-Orderings", "Antilexicographic Order" ]
[ "Definition:Well-Ordered Set", "Definition:Antilexicographic Order", "Definition:Well-Ordered Set" ]
[ "Definition:Well-Ordered Set", "Definition:Totally Ordered Set", "Definition:Well-Founded Set", "Antilexicographic Product of Totally Ordered Sets is Totally Ordered", "Definition:Totally Ordered Set", "Definition:Well-Founded Relation", "Definition:Non-Empty Set", "Definition:Subset", "Definition:S...
proofwiki-18389
Order Type Multiplication is Well-Defined Operation
The multiplication operation on order types is well-defined.
Let $\struct {S_1, \preccurlyeq_1}$ and $\struct {S_2, \preccurlyeq_2}$ be ordered sets. Let $\struct {T_1, \preccurlyeq_{1'} }$ and $\struct {T_2, \preccurlyeq_{2'} }$ be ordered sets such that: :$\struct {S_1, \preccurlyeq_1}$ is isomorphic to $\struct {T_1, \preccurlyeq_{1'} }$ :$\struct {S_2, \preccurlyeq_2}$ is is...
The [[Definition:Multiplication of Order Types|multiplication operation]] on [[Definition:Order Type|order types]] is [[Definition:Well-Defined Operation|well-defined]].
Let $\struct {S_1, \preccurlyeq_1}$ and $\struct {S_2, \preccurlyeq_2}$ be [[Definition:Ordered Set|ordered sets]]. Let $\struct {T_1, \preccurlyeq_{1'} }$ and $\struct {T_2, \preccurlyeq_{2'} }$ be [[Definition:Ordered Set|ordered sets]] such that: :$\struct {S_1, \preccurlyeq_1}$ is [[Definition:Isomorphic Ordered ...
Order Type Multiplication is Well-Defined Operation
https://proofwiki.org/wiki/Order_Type_Multiplication_is_Well-Defined_Operation
https://proofwiki.org/wiki/Order_Type_Multiplication_is_Well-Defined_Operation
[ "Order Types", "Multiplication", "Order Products" ]
[ "Definition:Multiplication of Order Types", "Definition:Order Type", "Definition:Well-Defined/Operation" ]
[ "Definition:Ordered Set", "Definition:Ordered Set", "Definition:Order Isomorphism/Isomorphic Sets", "Definition:Order Isomorphism/Isomorphic Sets", "Definition:Order Type", "Definition:Order Type", "Order Isomorphism is Preserved by Antilexicographic Order" ]
proofwiki-18390
Order Isomorphism is Preserved by Antilexicographic Order
Let $\struct {S_1, \preccurlyeq_1}$ and $\struct {S_2, \preccurlyeq_2}$ be ordered sets. Let $\struct {T_1, \preccurlyeq_{1'} }$ and $\struct {T_2, \preccurlyeq_{2'} }$ be ordered sets such that: :$\struct {S_1, \preccurlyeq_1}$ is isomorphic to $\struct {T_1, \preccurlyeq_{1'} }$ :$\struct {S_2, \preccurlyeq_2}$ is is...
{{ProofWanted|tedious}}
Let $\struct {S_1, \preccurlyeq_1}$ and $\struct {S_2, \preccurlyeq_2}$ be [[Definition:Ordered Set|ordered sets]]. Let $\struct {T_1, \preccurlyeq_{1'} }$ and $\struct {T_2, \preccurlyeq_{2'} }$ be [[Definition:Ordered Set|ordered sets]] such that: :$\struct {S_1, \preccurlyeq_1}$ is [[Definition:Isomorphic Ordered ...
{{ProofWanted|tedious}}
Order Isomorphism is Preserved by Antilexicographic Order
https://proofwiki.org/wiki/Order_Isomorphism_is_Preserved_by_Antilexicographic_Order
https://proofwiki.org/wiki/Order_Isomorphism_is_Preserved_by_Antilexicographic_Order
[ "Antilexicographic Order", "Order Isomorphisms" ]
[ "Definition:Ordered Set", "Definition:Ordered Set", "Definition:Order Isomorphism/Isomorphic Sets", "Definition:Order Isomorphism/Isomorphic Sets", "Definition:Antilexicographic Order", "Definition:Order Isomorphism/Isomorphic Sets" ]
[]
proofwiki-18391
Order Type Addition is Associative
Let $\alpha$, $\beta$ and $\gamma$ be order types of ordered sets. Then: :$\paren {\alpha + \beta} + \gamma = \alpha + \paren {\beta + \gamma}$ where $+$ denotes order type addition.
Let $\struct {S_1, \preccurlyeq_1}$, $\struct {S_2, \preccurlyeq_2}$ and $\struct {S_3, \preccurlyeq_3}$ be ordered structures such that: {{begin-eqn}} {{eqn | l = \map \ot {S_1, \preccurlyeq_1} | r = \alpha }} {{eqn | l = \map \ot {S_2, \preccurlyeq_2} | r = \beta }} {{eqn | l = \map \ot {S_3, \preccurlyeq...
Let $\alpha$, $\beta$ and $\gamma$ be [[Definition:Order Type|order types]] of [[Definition:Ordered Set|ordered sets]]. Then: :$\paren {\alpha + \beta} + \gamma = \alpha + \paren {\beta + \gamma}$ where $+$ denotes [[Definition:Addition of Order Types|order type addition]].
Let $\struct {S_1, \preccurlyeq_1}$, $\struct {S_2, \preccurlyeq_2}$ and $\struct {S_3, \preccurlyeq_3}$ be [[Definition:Ordered Structure|ordered structures]] such that: {{begin-eqn}} {{eqn | l = \map \ot {S_1, \preccurlyeq_1} | r = \alpha }} {{eqn | l = \map \ot {S_2, \preccurlyeq_2} | r = \beta }} {{eqn...
Order Type Addition is Associative
https://proofwiki.org/wiki/Order_Type_Addition_is_Associative
https://proofwiki.org/wiki/Order_Type_Addition_is_Associative
[ "Order Sums", "Examples of Associative Operations" ]
[ "Definition:Order Type", "Definition:Ordered Set", "Definition:Addition of Order Types" ]
[ "Definition:Ordered Structure", "Definition:Order Type", "Definition:Order Type", "Definition:Order Sum", "Definition:Order Isomorphism" ]
proofwiki-18392
Lexicographic Product of Family of Ordered Sets is Ordered Set
Let $\struct {I, \preceq}$ be a well-ordered set. For each $i \in I$, let $\struct {S_i, \preccurlyeq_i}$ be an ordered set. Let $\ds D = \prod_{i \mathop \in I} S_i$ be the Cartesian product of the family $\family {\struct {S_i, \preccurlyeq_i} }_{i \mathop \in I}$ indexed by $I$. Let $\preccurlyeq_D$ be the lexicogra...
For a subset $J$ of $I$, let $D_J$ be defined as: :$\ds D_J = \prod_{i \mathop \in J} S_i$ Similarly, let $\preccurlyeq_J$ be the lexicographic order on $D_J$: :$\forall u, v \in D_J: u \preccurlyeq_J v \iff \begin {cases} u = v \\ \map u i \preccurlyeq_i \map v i & \text {for the $\preceq$-smallest $i \in J$ such that...
Let $\struct {I, \preceq}$ be a [[Definition:Well-Ordered Set|well-ordered set]]. For each $i \in I$, let $\struct {S_i, \preccurlyeq_i}$ be an [[Definition:Ordered Set|ordered set]]. Let $\ds D = \prod_{i \mathop \in I} S_i$ be the [[Definition:Cartesian Product of Family|Cartesian product]] of the [[Definition:Inde...
For a [[Definition:Subset|subset]] $J$ of $I$, let $D_J$ be defined as: :$\ds D_J = \prod_{i \mathop \in J} S_i$ Similarly, let $\preccurlyeq_J$ be the [[Definition:Lexicographic Order on Family|lexicographic order]] on $D_J$: :$\forall u, v \in D_J: u \preccurlyeq_J v \iff \begin {cases} u = v \\ \map u i \preccurl...
Lexicographic Product of Family of Ordered Sets is Ordered Set
https://proofwiki.org/wiki/Lexicographic_Product_of_Family_of_Ordered_Sets_is_Ordered_Set
https://proofwiki.org/wiki/Lexicographic_Product_of_Family_of_Ordered_Sets_is_Ordered_Set
[ "Lexicographic Order" ]
[ "Definition:Well-Ordered Set", "Definition:Ordered Set", "Definition:Cartesian Product/Family of Sets", "Definition:Indexing Set/Family", "Definition:Indexing Set", "Definition:Lexicographic Order/Family", "Definition:Ordered Set" ]
[ "Definition:Subset", "Definition:Lexicographic Order/Family", "Definition:Subset", "Definition:Ordered Set", "Definition:Smallest Element", "Definition:Ordered Set", "Definition:Ordered Set", "Definition:Lexicographic Order", "Lexicographic Order is Ordering", "Definition:Ordered Set", "Principl...
proofwiki-18393
Lexicographic Order of Family of Totally Ordered Sets is Totally Ordered Set
Let $\struct {I, \preceq}$ be a well-ordered set. For each $i \in I$, let $\struct {S_i, \preccurlyeq_i}$ be a totally ordered set. Let $\ds D = \prod_{i \mathop \in I} S_i$ be the Cartesian product of the family $\family {\struct {S_i, \preccurlyeq_i} }_{i \mathop \in I}$ indexed by $I$. Let $\preccurlyeq_D$ be the le...
From Lexicographic Product of Family of Ordered Sets is Ordered Set, $\struct {D, \preccurlyeq_D}$ is an ordered set. It remains to be shown that $\struct {D, \preccurlyeq_D}$ is totally ordered. Let $p, q \in D$. If $p = q$, then $p \preccurlyeq_D q$ by the definition of ordering. If $p \ne q$, then the set $M = \set ...
Let $\struct {I, \preceq}$ be a [[Definition:Well-Ordered Set|well-ordered set]]. For each $i \in I$, let $\struct {S_i, \preccurlyeq_i}$ be a [[Definition:Totally Ordered Set|totally ordered set]]. Let $\ds D = \prod_{i \mathop \in I} S_i$ be the [[Definition:Cartesian Product of Family|Cartesian product]] of the [[...
From [[Lexicographic Product of Family of Ordered Sets is Ordered Set]], $\struct {D, \preccurlyeq_D}$ is an [[Definition:Ordered Set|ordered set]]. It remains to be shown that $\struct {D, \preccurlyeq_D}$ is [[Definition:Totally Ordered Set|totally ordered]]. Let $p, q \in D$. If $p = q$, then $p \preccurlyeq_D q...
Lexicographic Order of Family of Totally Ordered Sets is Totally Ordered Set
https://proofwiki.org/wiki/Lexicographic_Order_of_Family_of_Totally_Ordered_Sets_is_Totally_Ordered_Set
https://proofwiki.org/wiki/Lexicographic_Order_of_Family_of_Totally_Ordered_Sets_is_Totally_Ordered_Set
[ "Lexicographic Order", "Total Orderings" ]
[ "Definition:Well-Ordered Set", "Definition:Totally Ordered Set", "Definition:Cartesian Product/Family of Sets", "Definition:Indexing Set/Family", "Definition:Indexing Set", "Definition:Lexicographic Order/Family", "Definition:Totally Ordered Set" ]
[ "Lexicographic Product of Family of Ordered Sets is Ordered Set", "Definition:Ordered Set", "Definition:Totally Ordered Set", "Definition:Ordering", "Definition:Set", "Definition:Non-Empty Set", "Definition:Well-Ordered Set", "Definition:Smallest Element", "Definition:Total Ordering", "Definition:...
proofwiki-18394
Lexicographic Order of Family of Well-Ordered Sets is not necessarily Well-Ordered
Let $\struct {I, \preceq}$ be a well-ordered set. For each $i \in I$, let $\struct {S_i, \preccurlyeq_i}$ be a well-ordered set. Let $\ds D = \prod_{i \mathop \in I} S_i$ be the Cartesian product of the family $\family {\struct {S_i, \preccurlyeq_i} }_{i \mathop \in I}$ indexed by $I$. Let $\preccurlyeq_D$ be the lexic...
Proof by Counterexample: Let $\struct {I, \preceq} = \struct {\N, \le}$. Let $\struct {S_i, \preccurlyeq_i} = \struct {\N, \le}$ for all $i \in \N$. Let $n \in \N$. Let $\ds u_n \in \prod_{i \mathop \in \N} \N$ be the mapping defined as: :$\map {u_n} i = \begin {cases} 0 & : i \le n \\ 1 & : i > n \end {cases}$ It is t...
Let $\struct {I, \preceq}$ be a [[Definition:Well-Ordered Set|well-ordered set]]. For each $i \in I$, let $\struct {S_i, \preccurlyeq_i}$ be a [[Definition:Well-Ordered Set|well-ordered set]]. Let $\ds D = \prod_{i \mathop \in I} S_i$ be the [[Definition:Cartesian Product of Family|Cartesian product]] of the [[Defini...
[[Proof by Counterexample]]: Let $\struct {I, \preceq} = \struct {\N, \le}$. Let $\struct {S_i, \preccurlyeq_i} = \struct {\N, \le}$ for all $i \in \N$. Let $n \in \N$. Let $\ds u_n \in \prod_{i \mathop \in \N} \N$ be the [[Definition:Mapping|mapping]] defined as: :$\map {u_n} i = \begin {cases} 0 & : i \le n \\ ...
Lexicographic Order of Family of Well-Ordered Sets is not necessarily Well-Ordered
https://proofwiki.org/wiki/Lexicographic_Order_of_Family_of_Well-Ordered_Sets_is_not_necessarily_Well-Ordered
https://proofwiki.org/wiki/Lexicographic_Order_of_Family_of_Well-Ordered_Sets_is_not_necessarily_Well-Ordered
[ "Lexicographic Order", "Well-Orderings" ]
[ "Definition:Well-Ordered Set", "Definition:Well-Ordered Set", "Definition:Cartesian Product/Family of Sets", "Definition:Indexing Set/Family", "Definition:Indexing Set", "Definition:Lexicographic Order/Family", "Definition:Well-Ordered Set" ]
[ "Proof by Counterexample", "Definition:Mapping", "Definition:Sequence/Infinite Sequence", "Definition:Decreasing/Sequence", "Definition:Sequence", "Definition:Element", "Definition:Lexicographic Order/Family", "Definition:Term of Sequence", "Definition:Non-Empty Set", "Definition:Subset", "Defin...
proofwiki-18395
Ordering is Preordering
Let $S$ be a set. Let $\RR$ be an ordering on $S$. Then $\RR$ is also a preordering on $S$.
By definition of ordering: {{:Definition:Ordering/Definition 1}} By definition of preordering: {{:Definition:Preordering/Definition 1}} Thus an ordering is a preordering which is antisymmetric. {{qed}}
Let $S$ be a [[Definition:Set|set]]. Let $\RR$ be an [[Definition:Ordering|ordering]] on $S$. Then $\RR$ is also a [[Definition:Preordering|preordering]] on $S$.
By definition of [[Definition:Ordering/Definition 1|ordering]]: {{:Definition:Ordering/Definition 1}} By definition of [[Definition:Preordering/Definition 1|preordering]]: {{:Definition:Preordering/Definition 1}} Thus an [[Definition:Ordering|ordering]] is a [[Definition:Preordering|preordering]] which is [[Definitio...
Ordering is Preordering
https://proofwiki.org/wiki/Ordering_is_Preordering
https://proofwiki.org/wiki/Ordering_is_Preordering
[ "Preorderings", "Orderings" ]
[ "Definition:Set", "Definition:Ordering", "Definition:Preordering" ]
[ "Definition:Ordering/Definition 1", "Definition:Preordering/Definition 1", "Definition:Ordering", "Definition:Preordering", "Definition:Antisymmetric Relation" ]
proofwiki-18396
Preordering is not necessarily Ordering
Let $S$ be a set. Let $\RR$ be a preordering on $S$. Then it is not necessarily the case that $\RR$ is also an ordering on $S$.
Consider the relation $\RR$ on the powerset of the natural numbers: :$\forall a, b \in \powerset \N: a \mathrel \RR b \iff a \setminus b \text { is finite}$ where $\setminus$ denotes set difference. It is demonstrated in Preordering Example: Finite Set Difference on Natural Numbers that; :$\RR$ is a preordering on $\po...
Let $S$ be a [[Definition:Set|set]]. Let $\RR$ be a [[Definition:Preordering|preordering]] on $S$. Then it is not necessarily the case that $\RR$ is also an [[Definition:Ordering|ordering]] on $S$.
Consider the [[Definition:Relation|relation]] $\RR$ on the [[Definition:Powerset|powerset]] of the [[Definition:Natural Numbers|natural numbers]]: :$\forall a, b \in \powerset \N: a \mathrel \RR b \iff a \setminus b \text { is finite}$ where $\setminus$ denotes [[Definition:Set Difference|set difference]]. It is dem...
Preordering is not necessarily Ordering
https://proofwiki.org/wiki/Preordering_is_not_necessarily_Ordering
https://proofwiki.org/wiki/Preordering_is_not_necessarily_Ordering
[ "Preorderings", "Orderings" ]
[ "Definition:Set", "Definition:Preordering", "Definition:Ordering" ]
[ "Definition:Relation", "Definition:Power Set", "Definition:Natural Numbers", "Definition:Set Difference", "Preordering/Examples/Finite Set Difference on Natural Numbers", "Definition:Preordering", "Definition:Ordering" ]
proofwiki-18397
Uniformly Continuous Function to Complete Metric Space has Unique Continuous Extension to Closure of Domain
Let $\tuple {X, d}$ be a metric space. Let $\tuple {Y, d'}$ be a complete metric space. Let $A \subseteq X$. Let $f : A \to Y$ be a uniformly continuous function. Then there exists a unique continuous function $g : A^- \to Y$ such that: :$\map g a = \map f a$ for all $a \in A$, where $A^-$ denotes the topological clos...
=== Existence === Note that if $A$ is closed, then from Set is Closed iff Equals Topological Closure, we have: :$A^- = A$ So taking $g = f$ suffices in this case. Suppose now that $A$ is not closed.
Let $\tuple {X, d}$ be a [[Definition:Metric Space|metric space]]. Let $\tuple {Y, d'}$ be a [[Definition:Complete Metric Space|complete metric space]]. Let $A \subseteq X$. Let $f : A \to Y$ be a [[Definition:Uniformly Continuous Mapping (Metric Spaces)|uniformly continuous function]]. Then there exists a unique...
=== Existence === Note that if $A$ is [[Definition:Closed Set of Metric Space|closed]], then from [[Set is Closed iff Equals Topological Closure]], we have: :$A^- = A$ So taking $g = f$ suffices in this case. Suppose now that $A$ is not [[Definition:Closed Set of Metric Space|closed]].
Uniformly Continuous Function to Complete Metric Space has Unique Continuous Extension to Closure of Domain
https://proofwiki.org/wiki/Uniformly_Continuous_Function_to_Complete_Metric_Space_has_Unique_Continuous_Extension_to_Closure_of_Domain
https://proofwiki.org/wiki/Uniformly_Continuous_Function_to_Complete_Metric_Space_has_Unique_Continuous_Extension_to_Closure_of_Domain
[ "Uniformly Continuous Functions", "Complete Metric Spaces", "Set Closures", "Uniformly Continuous Function to Complete Metric Space has Unique Continuous Extension to Closure of Domain" ]
[ "Definition:Metric Space", "Definition:Complete Metric Space", "Definition:Uniform Continuity/Metric Space", "Definition:Continuous Function", "Definition:Closure (Topology)", "Definition:Uniform Continuity/Metric Space" ]
[ "Definition:Closed Set/Metric Space", "Set is Closed iff Equals Topological Closure", "Definition:Closed Set/Metric Space" ]
proofwiki-18398
Uniformly Continuous Function to Complete Metric Space has Unique Continuous Extension to Closure of Domain/Lemma 1
Let $\sequence {a_n}$ be a sequence in $A$ convergent to $a \in A^-$. Then $\sequence {\map f {a_n} }$ converges.
From Set is Closed iff Equals Topological Closure, $A^- \setminus A$ is non-empty. Let $a \in A^- \setminus A$. From Point in Closure of Subset of Metric Space iff Limit of Sequence: :there exists a sequence $\sequence {a_n}$ in $A$ converging to $a$. Consider now the sequence $\sequence {\map f {a_n} }$ in $Y$. Note...
Let $\sequence {a_n}$ be a [[Definition:Sequence|sequence]] in $A$ [[Definition:Convergent Sequence (Metric Space)|convergent]] to $a \in A^-$. Then $\sequence {\map f {a_n} }$ [[Definition:Convergent Sequence (Metric Space)|converges]].
From [[Set is Closed iff Equals Topological Closure]], $A^- \setminus A$ is [[Definition:Non-Empty Set|non-empty]]. Let $a \in A^- \setminus A$. From [[Point in Closure of Subset of Metric Space iff Limit of Sequence]]: :there exists a [[Definition:Sequence|sequence]] $\sequence {a_n}$ in $A$ [[Definition:Converge...
Uniformly Continuous Function to Complete Metric Space has Unique Continuous Extension to Closure of Domain/Lemma 1
https://proofwiki.org/wiki/Uniformly_Continuous_Function_to_Complete_Metric_Space_has_Unique_Continuous_Extension_to_Closure_of_Domain/Lemma_1
https://proofwiki.org/wiki/Uniformly_Continuous_Function_to_Complete_Metric_Space_has_Unique_Continuous_Extension_to_Closure_of_Domain/Lemma_1
[ "Uniformly Continuous Function to Complete Metric Space has Unique Continuous Extension to Closure of Domain" ]
[ "Definition:Sequence", "Definition:Convergent Sequence/Metric Space", "Definition:Convergent Sequence/Metric Space" ]
[ "Set is Closed iff Equals Topological Closure", "Definition:Non-Empty Set", "Point in Closure of Subset of Metric Space iff Limit of Sequence", "Definition:Sequence", "Definition:Convergent Sequence", "Definition:Sequence", "Definition:Complete Metric Space", "Definition:Cauchy Sequence", "Definitio...
proofwiki-18399
Uniformly Continuous Function to Complete Metric Space has Unique Continuous Extension to Closure of Domain/Lemma 2
Let $\sequence {a_n}$ be a convergent sequence in $A$. Then the limit of $\sequence {\map f {a_n} }$ is dependent only on the limit of $\sequence {a_n}$. That is, there exists a function $L : A^- \to Y$ such that: :$\ds \lim_{n \mathop \to \infty} \map f {a_n} = \map L {\lim_{n \mathop \to \infty} a_n}$ for every co...
Let $\sequence {a_n}$ and $\sequence {b_n}$ be sequences in $A$ such that $a_n \to a$ and $b_n \to a$, with: :$\map f {a_n} \to L_1$ and: :$\map f {b_n} \to L_2$ We have, by the Triangle Inequality: :$\map {d'} {\map f {a_n}, L_2} \le \map {d'} {\map f {a_n}, \map f {b_n} } + \map {d'} {\map f {b_n}, L_2}$ We want to ...
Let $\sequence {a_n}$ be a [[Definition:Convergent Sequence (Metric Space)|convergent sequence]] in $A$. Then the [[Definition:Limit of Sequence in Metric Space|limit]] of $\sequence {\map f {a_n} }$ is dependent only on the [[Definition:Limit of Sequence in Metric Space|limit]] of $\sequence {a_n}$. That is, ther...
Let $\sequence {a_n}$ and $\sequence {b_n}$ be [[Definition:Sequence|sequences]] in $A$ such that $a_n \to a$ and $b_n \to a$, with: :$\map f {a_n} \to L_1$ and: :$\map f {b_n} \to L_2$ We have, by the [[Triangle Inequality]]: :$\map {d'} {\map f {a_n}, L_2} \le \map {d'} {\map f {a_n}, \map f {b_n} } + \map {d'}...
Uniformly Continuous Function to Complete Metric Space has Unique Continuous Extension to Closure of Domain/Lemma 2
https://proofwiki.org/wiki/Uniformly_Continuous_Function_to_Complete_Metric_Space_has_Unique_Continuous_Extension_to_Closure_of_Domain/Lemma_2
https://proofwiki.org/wiki/Uniformly_Continuous_Function_to_Complete_Metric_Space_has_Unique_Continuous_Extension_to_Closure_of_Domain/Lemma_2
[ "Uniformly Continuous Function to Complete Metric Space has Unique Continuous Extension to Closure of Domain" ]
[ "Definition:Convergent Sequence/Metric Space", "Definition:Limit of Sequence/Metric Space", "Definition:Limit of Sequence/Metric Space", "Definition:Function", "Definition:Convergent Sequence/Metric Space" ]
[ "Definition:Sequence", "Triangle Inequality", "Definition:Uniform Continuity/Metric Space", "Triangle Inequality", "Convergent Sequence in Metric Space has Unique Limit", "Definition:Sequence", "Definition:Convergent Sequence/Metric Space", "Definition:Limit of Sequence/Metric Space", "Category:Unif...