id
stringlengths
11
15
title
stringlengths
7
171
problem
stringlengths
9
4.33k
solution
stringlengths
6
19k
problem_wikitext
stringlengths
9
4.42k
solution_wikitext
stringlengths
7
19.1k
proof_title
stringlengths
9
171
theorem_url
stringlengths
34
198
proof_url
stringlengths
36
198
categories
listlengths
0
9
theorem_references
listlengths
0
36
proof_references
listlengths
0
253
proofwiki-18800
Elements of Subgroup of Dipper Semigroup are not Invertible in Dipper
Let $m, n \in \Z$ be integers such that $m, n > 0$. Let $\struct {N_{< \paren {m \mathop + n} }, +_{m, n} }$ denote the dipper semigroup. Let $\struct {H, +_{m, n} }$ be the subgroup of $\struct {N_{< \paren {m \mathop + n} }, +_{m, n} }$ where $H = \set {k \in \N: m \le k < m + n}$ Then the elements of $\struct {H, +_...
From Identity of Subgroup of Dipper Semigroup is not Identity of Dipper, the identity of $\struct {H, +_{m, n} }$ is not an identity of $\struct {N_{< \paren {m \mathop + n} }, +_{m, n} }$. Hence (indirectly) from Identity of Submagma containing Identity of Magma is Same Identity, $\struct {N_{< \paren {m \mathop + n} ...
Let $m, n \in \Z$ be [[Definition:Integer|integers]] such that $m, n > 0$. Let $\struct {N_{< \paren {m \mathop + n} }, +_{m, n} }$ denote the [[Definition:Dipper Semigroup|dipper semigroup]]. Let $\struct {H, +_{m, n} }$ be the [[Definition:Subgroup|subgroup]] of $\struct {N_{< \paren {m \mathop + n} }, +_{m, n} }$...
From [[Identity of Subgroup of Dipper Semigroup is not Identity of Dipper]], the [[Definition:Identity Element|identity]] of $\struct {H, +_{m, n} }$ is not an [[Definition:Identity Element|identity]] of $\struct {N_{< \paren {m \mathop + n} }, +_{m, n} }$. Hence (indirectly) from [[Identity of Submagma containing Ide...
Elements of Subgroup of Dipper Semigroup are not Invertible in Dipper
https://proofwiki.org/wiki/Elements_of_Subgroup_of_Dipper_Semigroup_are_not_Invertible_in_Dipper
https://proofwiki.org/wiki/Elements_of_Subgroup_of_Dipper_Semigroup_are_not_Invertible_in_Dipper
[ "Dipper Semigroups", "Examples of Inverse Elements", "Elements of Subgroup of Dipper Semigroup are not Invertible in Dipper" ]
[ "Definition:Integer", "Definition:Dipper Semigroup", "Definition:Subgroup", "Definition:Element", "Definition:Invertible Element" ]
[ "Identity of Subgroup of Dipper Semigroup is not Identity of Dipper", "Definition:Identity (Abstract Algebra)/Two-Sided Identity", "Definition:Identity (Abstract Algebra)/Two-Sided Identity", "Identity of Submagma containing Identity of Magma is Same Identity", "Definition:Identity (Abstract Algebra)/Two-Si...
proofwiki-18801
De Rham Cohomology of Sphere
Let $S^n$ denote the $n$-Sphere. Then the de Rham Cohomology of $S^n$ are: :$\map {H^k} {S^n} = \begin {cases} \Z^2 & : k = 0, n = 0 \\ \Z & : k = 0 \text { or } k = n, n > 0 \\ 0 & : 0 < k < n \end {cases}$ and Higher de Rham Cohomology Vanishes. {{explain|The condition for the middle case is not uniquely readable, an...
{{ProofWanted|Mayer–Vietoris sequence and Induction}} Category:de Rham Cohomology 7qa3jz0yfip0lvrb06zkmt8d50t2hit
Let $S^n$ denote the [[Definition:Sphere (Topology)|$n$-Sphere]]. Then the [[Definition:De Rham Cohomology|de Rham Cohomology]] of $S^n$ are: :$\map {H^k} {S^n} = \begin {cases} \Z^2 & : k = 0, n = 0 \\ \Z & : k = 0 \text { or } k = n, n > 0 \\ 0 & : 0 < k < n \end {cases}$ and [[Higher de Rham Cohomology Vanishes]]...
{{ProofWanted|Mayer–Vietoris sequence and Induction}} [[Category:de Rham Cohomology]] 7qa3jz0yfip0lvrb06zkmt8d50t2hit
De Rham Cohomology of Sphere
https://proofwiki.org/wiki/De_Rham_Cohomology_of_Sphere
https://proofwiki.org/wiki/De_Rham_Cohomology_of_Sphere
[ "de Rham Cohomology" ]
[ "Definition:Sphere/Topology", "Definition:De Rham Cohomology", "Higher de Rham Cohomology Vanishes" ]
[ "Category:de Rham Cohomology" ]
proofwiki-18802
Isomorphism between Symmetry Group of Regular Pentagon and Subgroup of Symmetric Group
Let $\PP = ABCDE$ denote a regular pentagon. Let $\struct {\PP, \circ}$ be the symmetry group of $\PP$, where the various symmetries are identified as: :the identity mapping $e$ :the rotations $r, r^2, r^3, r^4$ of $72^\circ, 144^\circ, 216^\circ, 288^\circ$ around the center of $\PP$ anticlockwise respectively :the re...
Let the $A$, $B$, $C$, $D$ and $E$ of $\PP$ be identified with the integers $1$, $2$, $3$, $4$ and $5$ of $S_5$. Let each of the symmetries of $\PP$ be identified with permutations of $S_n$ according to where the symmetry moves the vertices of $\PP$. We express these in two-row notation, which we construct by inspectio...
Let $\PP = ABCDE$ denote a [[Definition:Regular Pentagon|regular pentagon]]. Let $\struct {\PP, \circ}$ be the [[Definition:Symmetry Group of Regular Pentagon|symmetry group]] of $\PP$, where the various [[Definition:Symmetry (Geometry)|symmetries]] are identified as: :the [[Definition:Identity Mapping|identity mappin...
Let the $A$, $B$, $C$, $D$ and $E$ of $\PP$ be identified with the [[Definition:Integer|integers]] $1$, $2$, $3$, $4$ and $5$ of $S_5$. Let each of the [[Definition:Symmetry (Geometry)|symmetries]] of $\PP$ be identified with [[Definition:Permutation|permutations]] of $S_n$ according to where the [[Definition:Symmetry...
Isomorphism between Symmetry Group of Regular Pentagon and Subgroup of Symmetric Group
https://proofwiki.org/wiki/Isomorphism_between_Symmetry_Group_of_Regular_Pentagon_and_Subgroup_of_Symmetric_Group
https://proofwiki.org/wiki/Isomorphism_between_Symmetry_Group_of_Regular_Pentagon_and_Subgroup_of_Symmetric_Group
[ "Symmetry Group of Regular Pentagon", "Symmetric Group on 5 Letters" ]
[ "Definition:Pentagon/Regular", "Definition:Symmetry Group of Regular Pentagon", "Definition:Symmetry (Geometry)", "Definition:Identity Mapping", "Definition:Rotation (Geometry)/Plane", "Definition:Polygon/Regular/Center", "Definition:Anticlockwise", "Definition:Reflection (Geometry)/Plane", "Definit...
[ "Definition:Integer", "Definition:Symmetry (Geometry)", "Definition:Permutation", "Definition:Symmetry (Geometry)", "Definition:Vertex", "Definition:Permutation on n Letters/Two-Row Notation", "Definition:Permutation", "Definition:Element", "Definition:Permutation on n Letters/Cycle Notation", "De...
proofwiki-18803
Isomorphisms between Symmetry Groups of Isosceles Triangle and Equilateral Triangle
Let $\TT = ABC$ be an isosceles triangle whose apex is $A$. Let $\struct {\TT, \circ}$ be the symmetry group of $\TT$, where the symmetries are identified as: :the identity mapping $e$ :the reflection $d$ in the line through $A$ and the midpoint of $BC$. :240px Let $\SS = A'B'C'$ be an equilateral triangle. We define i...
We have that $\struct {\TT, \circ}$ is of order $2$. We also have that: {{begin-eqn}} {{eqn | o = | r = \set {e, \tuple {12} } }} {{eqn | o = | r = \set {e, \tuple {13} } }} {{eqn | o = | r = \set {e, \tuple {23} } }} {{end-eqn}} are also groups of order $2$. From Parity Group is Only Group with 2 ...
Let $\TT = ABC$ be an [[Definition:Isosceles Triangle|isosceles triangle]] whose [[Definition:Apex of Isosceles Triangle|apex]] is $A$. Let $\struct {\TT, \circ}$ be the [[Definition:Symmetry Group of Isosceles Triangle|symmetry group]] of $\TT$, where the [[Definition:Symmetry (Geometry)|symmetries]] are identified a...
We have that $\struct {\TT, \circ}$ is of [[Definition:Order of Group|order $2$]]. We also have that: {{begin-eqn}} {{eqn | o = | r = \set {e, \tuple {12} } }} {{eqn | o = | r = \set {e, \tuple {13} } }} {{eqn | o = | r = \set {e, \tuple {23} } }} {{end-eqn}} are also [[Definition:Group|groups]]...
Isomorphisms between Symmetry Groups of Isosceles Triangle and Equilateral Triangle
https://proofwiki.org/wiki/Isomorphisms_between_Symmetry_Groups_of_Isosceles_Triangle_and_Equilateral_Triangle
https://proofwiki.org/wiki/Isomorphisms_between_Symmetry_Groups_of_Isosceles_Triangle_and_Equilateral_Triangle
[ "Symmetry Group of Isosceles Triangle", "Symmetry Group of Equilateral Triangle" ]
[ "Definition:Triangle (Geometry)/Isosceles", "Definition:Triangle (Geometry)/Isosceles/Apex", "Definition:Symmetry Group of Isosceles Triangle", "Definition:Symmetry (Geometry)", "Definition:Identity Mapping", "Definition:Reflection (Geometry)/Plane", "Definition:Line/Straight Line", "Definition:Line/M...
[ "Definition:Order of Structure", "Definition:Group", "Definition:Order of Structure", "Parity Group is Only Group with 2 Elements", "Definition:Group", "Definition:Isomorphism (Abstract Algebra)/Group Isomorphism" ]
proofwiki-18804
Set of Associating Elements forms Subsemigroup of Magma
Let $S$ be a set. Let $\oplus$ be an operation on $S$ such that $\struct {S, \oplus}$ is a magma. Let $T \subseteq S$ be the subset of $S$ defined as: :$T = \set {x \in S: \paren {x \oplus y} \oplus z = x \oplus \paren {y \oplus z} }$ Suppose $T \ne \O$. Then $\struct {T, \oplus {\restriction_T} }$ is a subsemigroup of...
Taking the semigroup axioms in turn:
Let $S$ be a [[Definition:Set|set]]. Let $\oplus$ be an [[Definition:Binary Operation|operation]] on $S$ such that $\struct {S, \oplus}$ is a [[Definition:Magma|magma]]. Let $T \subseteq S$ be the [[Definition:Subset|subset]] of $S$ defined as: :$T = \set {x \in S: \paren {x \oplus y} \oplus z = x \oplus \paren {y ...
Taking the [[Axiom:Semigroup Axioms|semigroup axioms]] in turn:
Set of Associating Elements forms Subsemigroup of Magma
https://proofwiki.org/wiki/Set_of_Associating_Elements_forms_Subsemigroup_of_Magma
https://proofwiki.org/wiki/Set_of_Associating_Elements_forms_Subsemigroup_of_Magma
[ "Subsemigroups", "Associativity" ]
[ "Definition:Set", "Definition:Operation/Binary Operation", "Definition:Magma", "Definition:Subset", "Definition:Subsemigroup" ]
[ "Axiom:Semigroup Axioms", "Axiom:Semigroup Axioms" ]
proofwiki-18805
Subsemigroup of Cancellable Mappings is Subgroup of Invertible Mappings
Let $S$ be a set. Let $S^S$ denote the set of mappings from $S$ to itself. Let $\CC \subseteq S^S$ denote the set of cancellable mappings on $S$. Let $\MM \subseteq S^S$ denote the set of invertible mappings on $S$. Then: :the subsemigroup $\struct {\CC, \circ}$ of $\struct {S^S, \circ}$ coincides with the subgroup $\s...
From Set of Invertible Mappings forms Symmetric Group, we have that $\struct {\MM, \circ}$ is a group. Hence, by definition, $\struct {\MM, \circ}$ is a subgroup of $\struct {S^S, \circ}$. Recall from Bijection iff Left and Right Inverse that a mapping is invertible {{iff}} it is a bijection. By definition, a cancellab...
Let $S$ be a [[Definition:Set|set]]. Let $S^S$ denote the [[Definition:Set|set]] of [[Definition:Mapping|mappings]] from $S$ to itself. Let $\CC \subseteq S^S$ denote the [[Definition:Set|set]] of [[Definition:Cancellable Mapping|cancellable mappings]] on $S$. Let $\MM \subseteq S^S$ denote the [[Definition:Set|set...
From [[Set of Invertible Mappings forms Symmetric Group]], we have that $\struct {\MM, \circ}$ is a [[Definition:Group|group]]. Hence, by definition, $\struct {\MM, \circ}$ is a [[Definition:Subgroup|subgroup]] of $\struct {S^S, \circ}$. Recall from [[Bijection iff Left and Right Inverse]] that a [[Definition:Mapping...
Subsemigroup of Cancellable Mappings is Subgroup of Invertible Mappings
https://proofwiki.org/wiki/Subsemigroup_of_Cancellable_Mappings_is_Subgroup_of_Invertible_Mappings
https://proofwiki.org/wiki/Subsemigroup_of_Cancellable_Mappings_is_Subgroup_of_Invertible_Mappings
[ "Cancellability", "Inverse Mappings", "Examples of Subgroups", "Examples of Subsemigroups" ]
[ "Definition:Set", "Definition:Set", "Definition:Mapping", "Definition:Set", "Definition:Cancellable Mapping", "Definition:Set", "Definition:Inverse Mapping", "Definition:Subsemigroup", "Definition:Subgroup", "Definition:Composition of Mappings" ]
[ "Set of Invertible Mappings forms Symmetric Group", "Definition:Group", "Definition:Subgroup", "Bijection iff Left and Right Inverse", "Definition:Mapping", "Definition:Inverse Mapping", "Definition:Bijection", "Definition:Cancellable Mapping", "Definition:Mapping", "Definition:Left Cancellable Ma...
proofwiki-18806
Mapping is Idempotent iff Restriction to Image is Identity Mapping
Let $S$ be a set. Let $S^S$ denote the set of mappings from $S$ to itself. Let $f \in S^S$ be a mapping on $S$. Then: :$f$ is idempotent {{iff}}: :the restriction of $f$ to $\Img f$ is the identity mapping.
Recall the definitions: :$\Img f$ denotes the image set of $f$ :The identity mapping $I_S$ is defined as: ::$\forall x \in f: \map {I_S} x = x$ :An idempotent mapping is a mapping with the property: ::$f \circ f = f$ :where $\circ$ denotes composition of mappings.
Let $S$ be a [[Definition:Set|set]]. Let $S^S$ denote the [[Definition:Set|set]] of [[Definition:Mapping|mappings]] from $S$ to itself. Let $f \in S^S$ be a [[Definition:Mapping|mapping]] on $S$. Then: :$f$ is [[Definition:Idempotent Mapping|idempotent]] {{iff}}: :the [[Definition:Restriction of Mapping|restriction...
Recall the definitions: :$\Img f$ denotes the [[Definition:Image of Mapping|image set of $f$]] :The [[Definition:Identity Mapping|identity mapping]] $I_S$ is defined as: ::$\forall x \in f: \map {I_S} x = x$ :An [[Definition:Idempotent Mapping|idempotent mapping]] is a [[Definition:Mapping|mapping]] with the propert...
Mapping is Idempotent iff Restriction to Image is Identity Mapping
https://proofwiki.org/wiki/Mapping_is_Idempotent_iff_Restriction_to_Image_is_Identity_Mapping
https://proofwiki.org/wiki/Mapping_is_Idempotent_iff_Restriction_to_Image_is_Identity_Mapping
[ "Identity Mappings", "Idempotence", "Restrictions" ]
[ "Definition:Set", "Definition:Set", "Definition:Mapping", "Definition:Mapping", "Definition:Idempotence/Mapping", "Definition:Restriction/Mapping", "Definition:Identity Mapping" ]
[ "Definition:Image (Set Theory)/Mapping/Mapping", "Definition:Identity Mapping", "Definition:Idempotence/Mapping", "Definition:Mapping", "Definition:Composition of Mappings", "Definition:Identity Mapping", "Definition:Idempotence/Mapping", "Definition:Idempotence/Mapping", "Definition:Identity Mappin...
proofwiki-18807
Non-Cancellable Elements of Semigroup form Subsemigroup
Let $\struct {S, \circ}$ be a semigroup. Let $T \subseteq S$ be the subset of $S$ containing the elements of $S$ which are specifically not cancellable in $\struct {S, \circ}$. Then $\struct {T, \circ}$ forms a subsemigroup of $S$.
Recall the definition of cancellable element: An element $x \in \struct {S, \circ}$ is '''cancellable''' {{iff}}: :$\forall a, b \in S: x \circ a = x \circ b \implies a = b$ :$\forall a, b \in S: a \circ x = b \circ x \implies a = b$ From the Subsemigroup Closure Test it is sufficient to demonstrate that: :$\forall x, ...
Let $\struct {S, \circ}$ be a [[Definition:Semigroup|semigroup]]. Let $T \subseteq S$ be the [[Definition:Subset|subset]] of $S$ containing the [[Definition:Element|elements]] of $S$ which are specifically not [[Definition:Cancellable Element|cancellable]] in $\struct {S, \circ}$. Then $\struct {T, \circ}$ forms a [...
Recall the definition of [[Definition:Cancellable Element|cancellable element]]: An [[Definition:Element|element]] $x \in \struct {S, \circ}$ is '''[[Definition:Cancellable Element|cancellable]]''' {{iff}}: :$\forall a, b \in S: x \circ a = x \circ b \implies a = b$ :$\forall a, b \in S: a \circ x = b \circ x \implies...
Non-Cancellable Elements of Semigroup form Subsemigroup
https://proofwiki.org/wiki/Non-Cancellable_Elements_of_Semigroup_form_Subsemigroup
https://proofwiki.org/wiki/Non-Cancellable_Elements_of_Semigroup_form_Subsemigroup
[ "Cancellability", "Subsemigroups" ]
[ "Definition:Semigroup", "Definition:Subset", "Definition:Element", "Definition:Cancellable Element", "Definition:Subsemigroup" ]
[ "Definition:Cancellable Element", "Definition:Element", "Definition:Cancellable Element", "Subsemigroup Closure Test", "Definition:Cancellable Element" ]
proofwiki-18808
Canonical P-adic Expansion of Rational is Eventually Periodic/Lemma 6
:$\exists r \in \Q, n \in \Z, y \in \Z_p$: ::$(1) \quad x = r + p^n y$ ::$(2) \quad$ the canonical expansion of $y$ is periodic.
Let $\ldots d_i \ldots d_2 d_1 d_0 . d_{-1} d_{-2} \ldots d_{-m}$ be the canonical expansion of $x$. By definition of eventually periodic there exists a finite sequence of $k$ digits of $x$: :$\tuple {d_{n + k - 1} \ldots d_{n + 1} d_n }$ such that $n \ge 0$ and for all $s \in \Z_{\ge 0}$ and for all $j \in \set {0, 2,...
:$\exists r \in \Q, n \in \Z, y \in \Z_p$: ::$(1) \quad x = r + p^n y$ ::$(2) \quad$ the [[Definition:Canonical P-adic Expansion|canonical expansion]] of $y$ is [[Definition:Periodic P-adic Expansion|periodic]].
Let $\ldots d_i \ldots d_2 d_1 d_0 . d_{-1} d_{-2} \ldots d_{-m}$ be the [[Definition:Canonical P-adic Expansion|canonical expansion]] of $x$. By definition of [[Definition:Eventually Periodic P-adic Expansion|eventually periodic]] there exists a [[Definition:Finite Sequence|finite sequence]] of $k$ [[Definition:Digi...
Canonical P-adic Expansion of Rational is Eventually Periodic/Lemma 6
https://proofwiki.org/wiki/Canonical_P-adic_Expansion_of_Rational_is_Eventually_Periodic/Lemma_6
https://proofwiki.org/wiki/Canonical_P-adic_Expansion_of_Rational_is_Eventually_Periodic/Lemma_6
[ "Canonical P-adic Expansion of Rational is Eventually Periodic" ]
[ "Definition:Canonical P-adic Expansion", "Definition:Periodic P-adic Expansion" ]
[ "Definition:Canonical P-adic Expansion", "Definition:Eventually Periodic P-adic Expansion", "Definition:Finite Sequence", "Definition:Digit", "Definition:Common Divisor/Integers", "Definition:Series", "Definition:P-adic Integer", "Definition:Canonical P-adic Expansion", "Definition:Canonical P-adic ...
proofwiki-18809
Canonical P-adic Expansion of Rational is Eventually Periodic/Lemma 7
:$1 + p^k + p^{2 k} + p^{3 k} + \cdots = \dfrac 1 {1 - p^k}$
Let $S_n$ be the partial sum: :$\ds S_n = \sum_{j \mathop = 0}^n p^{j k}$ We have: {{begin-eqn}} {{eqn | l = \paren {1 - p^k} S_n | r = \paren {1 - p^k} \sum_{j \mathop = 0}^n p^{j k} }} {{eqn | r = \paren {\sum_{j \mathop = 0}^n p^{j k} } - p^k \paren {\sum_{j \mathop = 0}^n p^{j k} } | c = distributing th...
:$1 + p^k + p^{2 k} + p^{3 k} + \cdots = \dfrac 1 {1 - p^k}$
Let $S_n$ be the [[Definition:Partial Sum|partial sum]]: :$\ds S_n = \sum_{j \mathop = 0}^n p^{j k}$ We have: {{begin-eqn}} {{eqn | l = \paren {1 - p^k} S_n | r = \paren {1 - p^k} \sum_{j \mathop = 0}^n p^{j k} }} {{eqn | r = \paren {\sum_{j \mathop = 0}^n p^{j k} } - p^k \paren {\sum_{j \mathop = 0}^n p^{j k} ...
Canonical P-adic Expansion of Rational is Eventually Periodic/Lemma 7
https://proofwiki.org/wiki/Canonical_P-adic_Expansion_of_Rational_is_Eventually_Periodic/Lemma_7
https://proofwiki.org/wiki/Canonical_P-adic_Expansion_of_Rational_is_Eventually_Periodic/Lemma_7
[ "Canonical P-adic Expansion of Rational is Eventually Periodic" ]
[]
[ "Definition:Series/Sequence of Partial Sums", "Definition:Series/Sequence of Partial Sums", "Definition:Series/Sequence of Partial Sums", "Definition:Series", "Definition:Telescoping Series", "Properties of Norm on Division Ring/Norm of Negative", "Combination Theorem for Sequences/Normed Division Ring/...
proofwiki-18810
Locally Integrable f(x+ct) is Weak Solution to Transport Equation
Consider the transport equation: :$\dfrac {\partial u} {\partial t} - c \dfrac {\partial u} {\partial x} = 0$ with the initial condition: :$\map u {x, 0} = \map f x$ where $c \in \R$. Then it has a weak solution of the form: :$\map u {x, t} := \map f {x + ct}$ where $f \in \map {L^1_{loc} } \R$ is a locally integrable...
Let $\map u {x, t} = \map f {x + ct}$ be a locally integrable function. We have that a locally integrable function defines a distribution. Let $T_u \in \map {\DD'} {\R^2}$ be a Schwartz distribution associated with $u$. Let $\phi \in \map \DD {\R^2}$ be a test function. Then: {{begin-eqn}} {{eqn | l = \dfrac {\partial}...
Consider the [[Definition:Transport Equation|transport equation]]: :$\dfrac {\partial u} {\partial t} - c \dfrac {\partial u} {\partial x} = 0$ with the [[Definition:Initial Condition|initial condition]]: :$\map u {x, 0} = \map f x$ where $c \in \R$. Then it has a [[Definition:Weak Solution|weak solution]] of the...
Let $\map u {x, t} = \map f {x + ct}$ be a [[Definition:Locally Integrable Function|locally integrable function]]. We have that a [[Locally Integrable Function defines Distribution|locally integrable function defines a distribution]]. Let $T_u \in \map {\DD'} {\R^2}$ be a [[Definition:Schwartz Distribution|Schwartz d...
Locally Integrable f(x+ct) is Weak Solution to Transport Equation
https://proofwiki.org/wiki/Locally_Integrable_f(x+ct)_is_Weak_Solution_to_Transport_Equation
https://proofwiki.org/wiki/Locally_Integrable_f(x+ct)_is_Weak_Solution_to_Transport_Equation
[ "Examples of Weak Solutions" ]
[ "Definition:Transport Equation", "Definition:Initial Condition", "Definition:Differential Equation/Solution/Weak Solution", "Definition:Integrable Function/Locally Integrable Function" ]
[ "Definition:Integrable Function/Locally Integrable Function", "Locally Integrable Function defines Distribution", "Definition:Schwartz Distribution", "Definition:Test Function", "Definition:Variable/Real", "Definition:Mapping", "Definition:Variable/Real", "Definition:Real Function", "Change of Varia...
proofwiki-18811
Smooth Vector Field as Sum of Smooth Horizontal and Vertical Vector Fields
Let $\tilde M, M$ be smooth manifolds. Let $\pi : \tilde M \to M$ be a smooth submersion. Let $\tilde g$ be a Riemannian metric on $\tilde M$. Let $W$ be a smooth vector field on $\tilde M$. Then $W$ can be uniquely decomposed as a sum: :$W = W^H + W^V$ where $W^H$ and $W^V$ are smooth horizontal and vertical vector fi...
{{ProofWanted|some of the assumptions may be unnecessary}}
Let $\tilde M, M$ be [[Definition:Smooth Manifold|smooth manifolds]]. Let $\pi : \tilde M \to M$ be a [[Definition:Submersion|smooth submersion]]. Let $\tilde g$ be a [[Definition:Riemannian Metric|Riemannian metric]] on $\tilde M$. Let $W$ be a [[Definition:Smooth Vector Field|smooth vector field]] on $\tilde M$. ...
{{ProofWanted|some of the assumptions may be unnecessary}}
Smooth Vector Field as Sum of Smooth Horizontal and Vertical Vector Fields
https://proofwiki.org/wiki/Smooth_Vector_Field_as_Sum_of_Smooth_Horizontal_and_Vertical_Vector_Fields
https://proofwiki.org/wiki/Smooth_Vector_Field_as_Sum_of_Smooth_Horizontal_and_Vertical_Vector_Fields
[ "Riemannian Geometry" ]
[ "Definition:Topological Manifold/Smooth Manifold", "Definition:Submersion", "Definition:Riemannian Metric", "Definition:Smooth Vector Field", "Definition:Unique", "Definition:Smooth Vector Field", "Definition:Horizontal Vector Field", "Definition:Vertical Vector Field", "Definition:Vector Field" ]
[]
proofwiki-18812
Sets of Operations on Set of 3 Elements/Automorphism Group of A
:$\AA$ has $3$ elements.
Recall the definition of (group) automorphism: :$\phi$ is an automorphism on $\struct {S, \circ}$ {{iff}}: ::$\phi$ is a permutation of $S$ ::$\phi$ is a homomorphism on $\struct {S, \circ}$: $\forall a, b \in S: \map \phi {a \circ b} = \map \phi a \circ \map \phi b$ Hence $\AA$ can be defined as the set of operations ...
:$\AA$ has $3$ [[Definition:Element|elements]].
Recall the definition of [[Definition:Group Automorphism|(group) automorphism]]: :$\phi$ is an [[Definition:Group Automorphism|automorphism]] on $\struct {S, \circ}$ {{iff}}: ::$\phi$ is a [[Definition:Permutation|permutation]] of $S$ ::$\phi$ is a [[Definition:Group Homomorphism|homomorphism]] on $\struct {S, \circ}$...
Sets of Operations on Set of 3 Elements/Automorphism Group of A
https://proofwiki.org/wiki/Sets_of_Operations_on_Set_of_3_Elements/Automorphism_Group_of_A
https://proofwiki.org/wiki/Sets_of_Operations_on_Set_of_3_Elements/Automorphism_Group_of_A
[ "Sets of Operations on Set of 3 Elements" ]
[ "Definition:Element" ]
[ "Definition:Group Automorphism", "Definition:Group Automorphism", "Definition:Permutation", "Definition:Group Homomorphism", "Definition:Set", "Definition:Operation/Binary Operation", "Definition:Permutation", "Definition:Group Automorphism", "Definition:Set", "Definition:Permutation", "Definiti...
proofwiki-18813
Sets of Operations on Set of 3 Elements/Automorphism Group of B
:$\BB$ has $3^3 - 3$ elements.
Recall the definition of (group) automorphism: :$\phi$ is an automorphism on $\struct {S, \circ}$ {{iff}}: ::$\phi$ is a permutation of $S$ ::$\phi$ is a homomorphism on $\struct {S, \circ}$: $\forall a, b \in S: \map \phi {a \circ b} = \map \phi a \circ \map \phi b$ From Identity Mapping is Group Automorphism, $I_S$ i...
:$\BB$ has $3^3 - 3$ [[Definition:Element|elements]].
Recall the definition of [[Definition:Group Automorphism|(group) automorphism]]: :$\phi$ is an [[Definition:Group Automorphism|automorphism]] on $\struct {S, \circ}$ {{iff}}: ::$\phi$ is a [[Definition:Permutation|permutation]] of $S$ ::$\phi$ is a [[Definition:Group Homomorphism|homomorphism]] on $\struct {S, \circ}$...
Sets of Operations on Set of 3 Elements/Automorphism Group of B
https://proofwiki.org/wiki/Sets_of_Operations_on_Set_of_3_Elements/Automorphism_Group_of_B
https://proofwiki.org/wiki/Sets_of_Operations_on_Set_of_3_Elements/Automorphism_Group_of_B
[ "Sets of Operations on Set of 3 Elements" ]
[ "Definition:Element" ]
[ "Definition:Group Automorphism", "Definition:Group Automorphism", "Definition:Permutation", "Definition:Group Homomorphism", "Identity Mapping is Automorphism/Groups", "Definition:Group Automorphism", "Definition:Element", "Definition:Group Product/Product Element", "Definition:Group Product/Product...
proofwiki-18814
Sets of Operations on Set of 3 Elements/Automorphism Group of C n
:Each of $\CC_1$, $\CC_2$ and $\CC_3$ has $3^4 - 3$ elements.
Recall the definition of (group) automorphism: :$\phi$ is an automorphism on $\struct {S, \circ}$ {{iff}}: ::$\phi$ is a permutation of $S$ ::$\phi$ is a homomorphism on $\struct {S, \circ}$: $\forall a, b \in S: \map \phi {a \circ b} = \map \phi a \circ \map \phi b$ From Identity Mapping is Group Automorphism, $I_S$ i...
:Each of $\CC_1$, $\CC_2$ and $\CC_3$ has $3^4 - 3$ [[Definition:Element|elements]].
Recall the definition of [[Definition:Group Automorphism|(group) automorphism]]: :$\phi$ is an [[Definition:Group Automorphism|automorphism]] on $\struct {S, \circ}$ {{iff}}: ::$\phi$ is a [[Definition:Permutation|permutation]] of $S$ ::$\phi$ is a [[Definition:Group Homomorphism|homomorphism]] on $\struct {S, \circ}$...
Sets of Operations on Set of 3 Elements/Automorphism Group of C n
https://proofwiki.org/wiki/Sets_of_Operations_on_Set_of_3_Elements/Automorphism_Group_of_C_n
https://proofwiki.org/wiki/Sets_of_Operations_on_Set_of_3_Elements/Automorphism_Group_of_C_n
[ "Sets of Operations on Set of 3 Elements" ]
[ "Definition:Element" ]
[ "Definition:Group Automorphism", "Definition:Group Automorphism", "Definition:Permutation", "Definition:Group Homomorphism", "Identity Mapping is Automorphism/Groups", "Definition:Group Automorphism", "Definition:Operation/Binary Operation", "Definition:Group Automorphism", "Definition:Permutation",...
proofwiki-18815
Sets of Operations on Set of 3 Elements/Automorphism Group of D
:$\DD$ has $19 \, 422$ elements.
Let $n$ denote the cardinality of $\DD$. Equivalently, $n$ equals the number of operations $\circ$ on $S$ on which the only automorphism is $I_S$. Recall these definitions: Let $\AA$, $\BB$, $\CC_1$, $\CC_2$ and $\CC_3$ be respectively the set of all operations $\circ$ on $S$ such that the groups of automorphisms of $\...
:$\DD$ has $19 \, 422$ [[Definition:Element|elements]].
Let $n$ denote the [[Definition:Cardinality|cardinality]] of $\DD$. Equivalently, $n$ equals the number of [[Definition:Binary Operation|operations]] $\circ$ on $S$ on which the only [[Definition:Group Automorphism|automorphism]] is $I_S$. Recall these definitions: Let $\AA$, $\BB$, $\CC_1$, $\CC_2$ and $\CC_3$ be ...
Sets of Operations on Set of 3 Elements/Automorphism Group of D
https://proofwiki.org/wiki/Sets_of_Operations_on_Set_of_3_Elements/Automorphism_Group_of_D
https://proofwiki.org/wiki/Sets_of_Operations_on_Set_of_3_Elements/Automorphism_Group_of_D
[ "Sets of Operations on Set of 3 Elements" ]
[ "Definition:Element" ]
[ "Definition:Cardinality", "Definition:Operation/Binary Operation", "Definition:Group Automorphism", "Definition:Set", "Definition:Operation/Binary Operation", "Definition:Group", "Definition:Group Automorphism", "Definition:Symmetric Group", "Definition:Identity Mapping", "Definition:Operation/Bin...
proofwiki-18816
Equivalence of Definitions of Quaternion Modulus
Let $\mathbf x = a \mathbf 1 + b \mathbf i + c \mathbf j + d \mathbf k$ be a quaternion, where $a, b, c, d \in \R$. {{TFAE|def = Quaternion Modulus}}
Let $\mathbf x = \begin{bmatrix} a + b i & c + d i \\ -c + d i & a - b i \end{bmatrix}$ be the matrix form of quaternion $\mathbf x$. {{begin-eqn}} {{eqn | l = \size {\mathbf x} | r = \sqrt {\map \det {\mathbf x} } | c = }} {{eqn | r = \sqrt {\map \det {\begin{bmatrix} a + b i & c + d i \\ -c + d i & a - b ...
Let $\mathbf x = a \mathbf 1 + b \mathbf i + c \mathbf j + d \mathbf k$ be a [[Definition:Quaternion|quaternion]], where $a, b, c, d \in \R$. {{TFAE|def = Quaternion Modulus}}
Let $\mathbf x = \begin{bmatrix} a + b i & c + d i \\ -c + d i & a - b i \end{bmatrix}$ be the [[Matrix Form of Quaternion|matrix form of quaternion $\mathbf x$]]. {{begin-eqn}} {{eqn | l = \size {\mathbf x} | r = \sqrt {\map \det {\mathbf x} } | c = }} {{eqn | r = \sqrt {\map \det {\begin{bmatrix} a + b i...
Equivalence of Definitions of Quaternion Modulus
https://proofwiki.org/wiki/Equivalence_of_Definitions_of_Quaternion_Modulus
https://proofwiki.org/wiki/Equivalence_of_Definitions_of_Quaternion_Modulus
[ "Quaternion Modulus" ]
[ "Definition:Quaternion" ]
[ "Matrix Form of Quaternion", "Category:Quaternion Modulus" ]
proofwiki-18817
Smooth Vector Field has Unique Smooth Horizontal Lift
Let $\tilde M, M$ be smooth manifolds. Let $\pi : \tilde M \to M$ be a smooth submersion. Let $\tilde g$ be a Riemannian metric on $\tilde M$. Let $W$ be a smooth vector field on $M$. Then $W$ has the unique smooth horizontal lift to $\tilde M$.
{{ProofWanted|some of the assumptions may be unnecessary}}
Let $\tilde M, M$ be [[Definition:Smooth Manifold|smooth manifolds]]. Let $\pi : \tilde M \to M$ be a [[Definition:Submersion|smooth submersion]]. Let $\tilde g$ be a [[Definition:Riemannian Metric|Riemannian metric]] on $\tilde M$. Let $W$ be a [[Definition:Smooth Vector Field|smooth vector field]] on $M$. Then $...
{{ProofWanted|some of the assumptions may be unnecessary}}
Smooth Vector Field has Unique Smooth Horizontal Lift
https://proofwiki.org/wiki/Smooth_Vector_Field_has_Unique_Smooth_Horizontal_Lift
https://proofwiki.org/wiki/Smooth_Vector_Field_has_Unique_Smooth_Horizontal_Lift
[ "Riemannian Geometry" ]
[ "Definition:Topological Manifold/Smooth Manifold", "Definition:Submersion", "Definition:Riemannian Metric", "Definition:Smooth Vector Field", "Definition:Unique", "Definition:Smooth Vector Field", "Definition:Horizontal Lift" ]
[]
proofwiki-18818
Sets of Operations on Set of 3 Elements/Automorphism Group of C n/Lemma 1
$c$ is an idempotent element under $\circ$, that is: :$c \circ c = c$
Recall the definition of (group) automorphism: :$\phi$ is an automorphism on $\struct {S, \circ}$ {{iff}}: ::$\phi$ is a permutation of $S$ ::$\phi$ is a homomorphism on $\struct {S, \circ}$: $\forall a, b \in S: \map \phi {a \circ b} = \map \phi a \circ \map \phi b$ Let us denote $\tuple {a, b}$ as the mapping $r: S \...
$c$ is an [[Definition:Idempotent Element|idempotent element]] under $\circ$, that is: :$c \circ c = c$
Recall the definition of [[Definition:Group Automorphism|(group) automorphism]]: :$\phi$ is an [[Definition:Group Automorphism|automorphism]] on $\struct {S, \circ}$ {{iff}}: ::$\phi$ is a [[Definition:Permutation|permutation]] of $S$ ::$\phi$ is a [[Definition:Group Homomorphism|homomorphism]] on $\struct {S, \circ}$...
Sets of Operations on Set of 3 Elements/Automorphism Group of C n/Lemma 1
https://proofwiki.org/wiki/Sets_of_Operations_on_Set_of_3_Elements/Automorphism_Group_of_C_n/Lemma_1
https://proofwiki.org/wiki/Sets_of_Operations_on_Set_of_3_Elements/Automorphism_Group_of_C_n/Lemma_1
[ "Sets of Operations on Set of 3 Elements" ]
[ "Definition:Idempotence/Element" ]
[ "Definition:Group Automorphism", "Definition:Group Automorphism", "Definition:Permutation", "Definition:Group Homomorphism", "Definition:Mapping", "Definition:Idempotence/Element", "Definition:Idempotence/Element", "Category:Sets of Operations on Set of 3 Elements" ]
proofwiki-18819
Sets of Operations on Set of 3 Elements/Automorphism Group of C n/Lemma 2
{{begin-eqn}} {{eqn | l = a \circ a = a | o = \iff | r = b \circ b = b }} {{eqn | l = a \circ a = b | o = \iff | r = b \circ b = a }} {{eqn | l = a \circ a = c | o = \iff | r = b \circ b = c }} {{eqn | l = a \circ b = a | o = \iff | r = b \circ a = b }} {{eqn | l = a \cir...
Recall the definition of (group) automorphism: :$\phi$ is an automorphism on $\struct {S, \circ}$ {{iff}}: ::$\phi$ is a permutation of $S$ ::$\phi$ is a homomorphism on $\struct {S, \circ}$: $\forall a, b \in S: \map \phi {a \circ b} = \map \phi a \circ \map \phi b$ Let us denote $\tuple {a, b}$ as the mapping $r: S \...
{{begin-eqn}} {{eqn | l = a \circ a = a | o = \iff | r = b \circ b = b }} {{eqn | l = a \circ a = b | o = \iff | r = b \circ b = a }} {{eqn | l = a \circ a = c | o = \iff | r = b \circ b = c }} {{eqn | l = a \circ b = a | o = \iff | r = b \circ a = b }} {{eqn | l = a \cir...
Recall the definition of [[Definition:Group Automorphism|(group) automorphism]]: :$\phi$ is an [[Definition:Group Automorphism|automorphism]] on $\struct {S, \circ}$ {{iff}}: ::$\phi$ is a [[Definition:Permutation|permutation]] of $S$ ::$\phi$ is a [[Definition:Group Homomorphism|homomorphism]] on $\struct {S, \circ}$...
Sets of Operations on Set of 3 Elements/Automorphism Group of C n/Lemma 2
https://proofwiki.org/wiki/Sets_of_Operations_on_Set_of_3_Elements/Automorphism_Group_of_C_n/Lemma_2
https://proofwiki.org/wiki/Sets_of_Operations_on_Set_of_3_Elements/Automorphism_Group_of_C_n/Lemma_2
[ "Sets of Operations on Set of 3 Elements" ]
[]
[ "Definition:Group Automorphism", "Definition:Group Automorphism", "Definition:Permutation", "Definition:Group Homomorphism", "Definition:Mapping", "Sets of Operations on Set of 3 Elements/Automorphism Group of C n/Lemma 1", "Definition:Group Product/Product Element", "Category:Sets of Operations on Se...
proofwiki-18820
Sets of Operations on Set of 3 Elements/Automorphism Group of A/Isomorphism Classes
:The elements of $\AA$ are each in its own isomorphism class.
Recall from Automorphism Group of $\AA$ the elements of $\AA$, expressed in Cayley table form: :$\begin {array} {c|ccc} \to & a & b & c \\ \hline a & a & b & c \\ b & a & b & c \\ c & a & b & c \\ \end {array} \qquad \begin {array} {c|ccc} \gets & a & b & c \\ \hline a & a & a & a \\ b & b & b & b \\ c & c & c & c \\ \...
:The [[Definition:Element|elements]] of $\AA$ are each in its own [[Definition:Isomorphism Class (Algebraic Structures)|isomorphism class]].
Recall from [[Sets of Operations on Set of 3 Elements/Automorphism Group of A|Automorphism Group of $\AA$]] the [[Definition:Element|elements]] of $\AA$, expressed in [[Definition:Cayley Table|Cayley table]] form: :$\begin {array} {c|ccc} \to & a & b & c \\ \hline a & a & b & c \\ b & a & b & c \\ c & a & b & c \\ \en...
Sets of Operations on Set of 3 Elements/Automorphism Group of A/Isomorphism Classes
https://proofwiki.org/wiki/Sets_of_Operations_on_Set_of_3_Elements/Automorphism_Group_of_A/Isomorphism_Classes
https://proofwiki.org/wiki/Sets_of_Operations_on_Set_of_3_Elements/Automorphism_Group_of_A/Isomorphism_Classes
[ "Sets of Operations on Set of 3 Elements" ]
[ "Definition:Element", "Definition:Isomorphism Class (Algebraic Structures)" ]
[ "Sets of Operations on Set of 3 Elements/Automorphism Group of A", "Definition:Element", "Definition:Cayley Table", "Algebraic Structures formed by Left and Right Operations are not Isomorphic for Cardinality Greater than 1", "Definition:Isomorphism (Abstract Algebra)", "Sets of Operations on Set of 3 Ele...
proofwiki-18821
Sets of Operations on Set of 3 Elements/Isomorphism Classes
Let $\MM$ be the set of all operations $\circ$ on $S$. Then the elements of $\MM$ are divided in $3330$ isomorphism classes. That is, up to isomorphism, there are $3330$ operations on $S$.
From Automorphism Group of $\AA$: Isomorphism Classes: :each element of $\AA$ is in its own isomorphism class. Hence $\AA$ contributes $3$ isomorphism classes. From Automorphism Group of $\BB$: Isomorphism Classes: :the $24$ elements of $\BB$ form $12$ isomorphism classes in pairs. From Automorphism Group of $\CC_n$: I...
Let $\MM$ be the [[Definition:Set|set]] of all [[Definition:Binary Operation|operations]] $\circ$ on $S$. Then the [[Definition:Element|elements]] of $\MM$ are divided in $3330$ [[Definition:Isomorphism Class (Algebraic Structures)|isomorphism classes]]. That is, up to [[Definition:Isomorphism (Abstract Algebra)|isom...
From [[Sets of Operations on Set of 3 Elements/Automorphism Group of A/Isomorphism Classes|Automorphism Group of $\AA$: Isomorphism Classes]]: :each [[Definition:Element|element]] of $\AA$ is in its own [[Definition:Isomorphism Class (Algebraic Structures)|isomorphism class]]. Hence $\AA$ contributes $3$ [[Definition:...
Sets of Operations on Set of 3 Elements/Isomorphism Classes
https://proofwiki.org/wiki/Sets_of_Operations_on_Set_of_3_Elements/Isomorphism_Classes
https://proofwiki.org/wiki/Sets_of_Operations_on_Set_of_3_Elements/Isomorphism_Classes
[ "Sets of Operations on Set of 3 Elements" ]
[ "Definition:Set", "Definition:Operation/Binary Operation", "Definition:Element", "Definition:Isomorphism Class (Algebraic Structures)", "Definition:Isomorphism (Abstract Algebra)", "Definition:Operation/Binary Operation" ]
[ "Sets of Operations on Set of 3 Elements/Automorphism Group of A/Isomorphism Classes", "Definition:Element", "Definition:Isomorphism Class (Algebraic Structures)", "Definition:Isomorphism Class (Algebraic Structures)", "Sets of Operations on Set of 3 Elements/Automorphism Group of B/Isomorphism Classes", ...
proofwiki-18822
Canonical P-adic Expansion of Rational is Eventually Periodic/Lemma 8
:$\ds \lim_{n \mathop \to \infty} \dfrac a {p^{n+1}} = 0$
From Sequence of Powers of Rational Number less than One: :$\ds \lim_{n \mathop \to \infty} \dfrac 1 {p^n} = 0$ From Multiple Rule for Sequences: :$\ds \lim_{n \mathop \to \infty} \dfrac a p \cdot \paren{\dfrac 1 {p^n} } = \dfrac a p \cdot 0 = 0$ The result follows. {{qed}} Category:Canonical P-adic Expansion of Ration...
:$\ds \lim_{n \mathop \to \infty} \dfrac a {p^{n+1}} = 0$
From [[Sequence of Powers of Rational Number less than One]]: :$\ds \lim_{n \mathop \to \infty} \dfrac 1 {p^n} = 0$ From [[Multiple Rule for Sequences]]: :$\ds \lim_{n \mathop \to \infty} \dfrac a p \cdot \paren{\dfrac 1 {p^n} } = \dfrac a p \cdot 0 = 0$ The result follows. {{qed}} [[Category:Canonical P-adic Expans...
Canonical P-adic Expansion of Rational is Eventually Periodic/Lemma 8
https://proofwiki.org/wiki/Canonical_P-adic_Expansion_of_Rational_is_Eventually_Periodic/Lemma_8
https://proofwiki.org/wiki/Canonical_P-adic_Expansion_of_Rational_is_Eventually_Periodic/Lemma_8
[ "Canonical P-adic Expansion of Rational is Eventually Periodic" ]
[]
[ "Sequence of Powers of Number less than One/Rational Numbers", "Combination Theorem for Sequences/Multiple Rule", "Category:Canonical P-adic Expansion of Rational is Eventually Periodic" ]
proofwiki-18823
Canonical P-adic Expansion of Rational is Eventually Periodic/Lemma 9
:$\ds \lim_{n \mathop \to \infty} \dfrac {a - \paren{p^{n+1} - 1} b } {p^{n+1}} = -b$
From Sequence of Reciprocals is Null Sequence: :$\ds \lim_{n \mathop \to \infty} \dfrac 1 n = 0$ From Combined Sum Rule for Real Sequences: :$\ds \lim_{n \mathop \to \infty} \dfrac {n - 1} n = \lim_{n \mathop \to \infty} 1 - \dfrac 1 n = 1$ From Limit of Subsequence equals Limit of Real Sequence: :$\ds \lim_{n \matho...
:$\ds \lim_{n \mathop \to \infty} \dfrac {a - \paren{p^{n+1} - 1} b } {p^{n+1}} = -b$
From [[Sequence of Reciprocals is Null Sequence]]: :$\ds \lim_{n \mathop \to \infty} \dfrac 1 n = 0$ From [[Combined Sum Rule for Real Sequences]]: :$\ds \lim_{n \mathop \to \infty} \dfrac {n - 1} n = \lim_{n \mathop \to \infty} 1 - \dfrac 1 n = 1$ From [[Limit of Subsequence equals Limit of Real Sequence]]: :$\ds ...
Canonical P-adic Expansion of Rational is Eventually Periodic/Lemma 9
https://proofwiki.org/wiki/Canonical_P-adic_Expansion_of_Rational_is_Eventually_Periodic/Lemma_9
https://proofwiki.org/wiki/Canonical_P-adic_Expansion_of_Rational_is_Eventually_Periodic/Lemma_9
[ "Canonical P-adic Expansion of Rational is Eventually Periodic" ]
[]
[ "Sequence of Powers of Reciprocals is Null Sequence/Corollary", "Combination Theorem for Sequences/Real/Combined Sum Rule", "Limit of Subsequence equals Limit of Sequence/Real Numbers", "Combination Theorem for Sequences/Real/Combined Sum Rule" ]
proofwiki-18824
Sets of Operations on Set of 3 Elements/Automorphism Group of A/Operations with Identity
:None of the operations of $\AA$ has an identity element.
Recall from Automorphism Group of $\AA$ the elements of $\AA$, expressed in Cayley table form: :$\begin{array}{c|ccc} \to & a & b & c \\ \hline a & a & b & c \\ b & a & b & c \\ c & a & b & c \\ \end{array} \qquad \begin{array}{c|ccc} \gets & a & b & c \\ \hline a & a & a & a \\ b & b & b & b \\ c & c & c & c \\ \end{a...
:None of the [[Definition:Binary Operation|operations]] of $\AA$ has an [[Definition:Identity Element|identity element]].
Recall from [[Sets of Operations on Set of 3 Elements/Automorphism Group of A|Automorphism Group of $\AA$]] the [[Definition:Element|elements]] of $\AA$, expressed in [[Definition:Cayley Table|Cayley table]] form: :$\begin{array}{c|ccc} \to & a & b & c \\ \hline a & a & b & c \\ b & a & b & c \\ c & a & b & c \\ \end{...
Sets of Operations on Set of 3 Elements/Automorphism Group of A/Operations with Identity
https://proofwiki.org/wiki/Sets_of_Operations_on_Set_of_3_Elements/Automorphism_Group_of_A/Operations_with_Identity
https://proofwiki.org/wiki/Sets_of_Operations_on_Set_of_3_Elements/Automorphism_Group_of_A/Operations_with_Identity
[ "Sets of Operations on Set of 3 Elements" ]
[ "Definition:Operation/Binary Operation", "Definition:Identity (Abstract Algebra)/Two-Sided Identity" ]
[ "Sets of Operations on Set of 3 Elements/Automorphism Group of A", "Definition:Element", "Definition:Cayley Table" ]
proofwiki-18825
Sets of Operations on Set of 3 Elements/Automorphism Group of B/Operations with Identity
:None of the operations of $\BB$ has an identity element.
Recall Automorphism Group of $\BB$. Consider each of the categories of $\BB$ induced by each of $a \circ a$, $a \circ b$ and $a \circ c$, illustrated by the partially-filled Cayley tables to which they give rise: ;$(1): \quad a \circ a$ :$\begin {array} {c|ccc} \circ & a & b & c \\ \hline a & a & & \\ b & & b & ...
:None of the [[Definition:Binary Operation|operations]] of $\BB$ has an [[Definition:Identity Element|identity element]].
Recall [[Sets of Operations on Set of 3 Elements/Automorphism Group of B|Automorphism Group of $\BB$]]. Consider each of the categories of $\BB$ induced by each of $a \circ a$, $a \circ b$ and $a \circ c$, illustrated by the partially-filled [[Definition:Cayley Table|Cayley tables]] to which they give rise: ;$(1): ...
Sets of Operations on Set of 3 Elements/Automorphism Group of B/Operations with Identity
https://proofwiki.org/wiki/Sets_of_Operations_on_Set_of_3_Elements/Automorphism_Group_of_B/Operations_with_Identity
https://proofwiki.org/wiki/Sets_of_Operations_on_Set_of_3_Elements/Automorphism_Group_of_B/Operations_with_Identity
[ "Sets of Operations on Set of 3 Elements" ]
[ "Definition:Operation/Binary Operation", "Definition:Identity (Abstract Algebra)/Two-Sided Identity" ]
[ "Sets of Operations on Set of 3 Elements/Automorphism Group of B", "Definition:Cayley Table", "Definition:Cayley Table", "Definition:Operation/Binary Operation", "Definition:Cayley Table", "Definition:Cayley Table", "Definition:Operation/Binary Operation", "Definition:Identity (Abstract Algebra)/Two-S...
proofwiki-18826
Sets of Operations on Set of 3 Elements/Automorphism Group of C n/Operations with Identity
:$9$ of the operations of each of $\CC_1$, $\CC_2$ and $\CC_3$ has an identity element.
{{WLOG}}, we will analyse the nature of $\CC_1$. Recall this lemma:
:$9$ of the [[Definition:Binary Operation|operations]] of each of $\CC_1$, $\CC_2$ and $\CC_3$ has an [[Definition:Identity Element|identity element]].
{{WLOG}}, we will analyse the nature of $\CC_1$. Recall this [[Definition:Lemma|lemma]]:
Sets of Operations on Set of 3 Elements/Automorphism Group of C n/Operations with Identity
https://proofwiki.org/wiki/Sets_of_Operations_on_Set_of_3_Elements/Automorphism_Group_of_C_n/Operations_with_Identity
https://proofwiki.org/wiki/Sets_of_Operations_on_Set_of_3_Elements/Automorphism_Group_of_C_n/Operations_with_Identity
[ "Sets of Operations on Set of 3 Elements" ]
[ "Definition:Operation/Binary Operation", "Definition:Identity (Abstract Algebra)/Two-Sided Identity" ]
[ "Definition:Lemma" ]
proofwiki-18827
Element of Horizontal Space as Horizontal Lift of Vector Field
Let $\tilde M, M$ be smooth manifolds. Let $\pi : \tilde M \to M$ be a smooth submersion. Let $\tilde g$ be a Riemannian metric on $\tilde M$. Let $H_x$ be a horizontal tangent space of $\tilde M$ at $x$. Let $\map {\mathfrak{X}} M$ be the space of smooth vector fields of $M$. Then for every $x \in \tilde M$ and every ...
{{ProofWanted|some of the assumptions may be unnecessary}}
Let $\tilde M, M$ be [[Definition:Smooth Manifold|smooth manifolds]]. Let $\pi : \tilde M \to M$ be a [[Definition:Submersion|smooth submersion]]. Let $\tilde g$ be a [[Definition:Riemannian Metric|Riemannian metric]] on $\tilde M$. Let $H_x$ be a [[Definition:Horizontal Tangent Space|horizontal tangent space]] of $...
{{ProofWanted|some of the assumptions may be unnecessary}}
Element of Horizontal Space as Horizontal Lift of Vector Field
https://proofwiki.org/wiki/Element_of_Horizontal_Space_as_Horizontal_Lift_of_Vector_Field
https://proofwiki.org/wiki/Element_of_Horizontal_Space_as_Horizontal_Lift_of_Vector_Field
[ "Riemannian Geometry" ]
[ "Definition:Topological Manifold/Smooth Manifold", "Definition:Submersion", "Definition:Riemannian Metric", "Definition:Horizontal Tangent Space", "Definition:Space of Smooth Vector Fields on Riemannian Manifold", "Definition:Vector Field", "Definition:Horizontal Lift" ]
[]
proofwiki-18828
Sets of Operations on Set of 3 Elements/Automorphism Group of D/Operations with Identity
:$216$ of the operations of $\DD$ has an identity element.
Let $n$ denote the number of operations of $\DD$ which have an identity element. Recall these definitions: Let $\AA$, $\BB$, $\CC_1$, $\CC_2$ and $\CC_3$ be respectively the set of all operations $\circ$ on $S$ such that the groups of automorphisms of $\struct {S, \circ}$ are as follows: {{begin-eqn}} {{eqn | l = \AA ...
:$216$ of the [[Definition:Binary Operation|operations]] of $\DD$ has an [[Definition:Identity Element|identity element]].
Let $n$ denote the number of [[Definition:Binary Operation|operations]] of $\DD$ which have an [[Definition:Identity Element|identity element]]. Recall these definitions: Let $\AA$, $\BB$, $\CC_1$, $\CC_2$ and $\CC_3$ be respectively the [[Definition:Set|set]] of all [[Definition:Binary Operation|operations]] $\circ...
Sets of Operations on Set of 3 Elements/Automorphism Group of D/Operations with Identity
https://proofwiki.org/wiki/Sets_of_Operations_on_Set_of_3_Elements/Automorphism_Group_of_D/Operations_with_Identity
https://proofwiki.org/wiki/Sets_of_Operations_on_Set_of_3_Elements/Automorphism_Group_of_D/Operations_with_Identity
[ "Sets of Operations on Set of 3 Elements" ]
[ "Definition:Operation/Binary Operation", "Definition:Identity (Abstract Algebra)/Two-Sided Identity" ]
[ "Definition:Operation/Binary Operation", "Definition:Identity (Abstract Algebra)/Two-Sided Identity", "Definition:Set", "Definition:Operation/Binary Operation", "Definition:Group", "Definition:Group Automorphism", "Definition:Symmetric Group", "Definition:Identity Mapping", "Definition:Operation/Bin...
proofwiki-18829
Sets of Operations on Set of 3 Elements/Operations with Identity
Let $\NN$ be the set of all operations $\circ$ on $S$ which have an identity element. Then the elements of $\NN$ are divided in $45$ isomorphism classes. That is, up to isomorphism, there are $45$ operations on $S$ which have an identity element.
From Automorphism Group of $\AA$: Operations with Identity: :there are no elements of $\AA$ which have an identity element. From Automorphism Group of $\BB$: Operations with Identity: :there are no elements of $\BB$ which have an identity element. From Automorphism Group of $\CC_n$: Operations with Identity: :there are...
Let $\NN$ be the [[Definition:Set|set]] of all [[Definition:Binary Operation|operations]] $\circ$ on $S$ which have an [[Definition:Identity Element|identity element]]. Then the [[Definition:Element|elements]] of $\NN$ are divided in $45$ [[Definition:Isomorphism Class (Algebraic Structures)|isomorphism classes]]. Th...
From [[Sets of Operations on Set of 3 Elements/Automorphism Group of A/Operations with Identity|Automorphism Group of $\AA$: Operations with Identity]]: :there are no [[Definition:Element|elements]] of $\AA$ which have an [[Definition:Identity Element|identity element]]. From [[Sets of Operations on Set of 3 Elements/...
Sets of Operations on Set of 3 Elements/Operations with Identity
https://proofwiki.org/wiki/Sets_of_Operations_on_Set_of_3_Elements/Operations_with_Identity
https://proofwiki.org/wiki/Sets_of_Operations_on_Set_of_3_Elements/Operations_with_Identity
[ "Sets of Operations on Set of 3 Elements" ]
[ "Definition:Set", "Definition:Operation/Binary Operation", "Definition:Identity (Abstract Algebra)/Two-Sided Identity", "Definition:Element", "Definition:Isomorphism Class (Algebraic Structures)", "Definition:Isomorphism (Abstract Algebra)", "Definition:Operation/Binary Operation", "Definition:Identit...
[ "Sets of Operations on Set of 3 Elements/Automorphism Group of A/Operations with Identity", "Definition:Element", "Definition:Identity (Abstract Algebra)/Two-Sided Identity", "Sets of Operations on Set of 3 Elements/Automorphism Group of B/Operations with Identity", "Definition:Element", "Definition:Ident...
proofwiki-18830
Sets of Operations on Set of 3 Elements/Automorphism Group of A/Commutative Operations
:Exactly $1$ of the operations of $\AA$ is commutative.
Recall from Automorphism Group of $\AA$ the elements of $\AA$, expressed in Cayley table form: :<nowiki>$\begin {array} {c|ccc} \to & a & b & c \\ \hline a & a & b & c \\ b & a & b & c \\ c & a & b & c \\ \end {array} \qquad \begin {array} {c|ccc} \gets & a & b & c \\ \hline a & a & a & a \\ b & b & b & b \\ c & c & c ...
:Exactly $1$ of the [[Definition:Binary Operation|operations]] of $\AA$ is [[Definition:Commutative Operation|commutative]].
Recall from [[Sets of Operations on Set of 3 Elements/Automorphism Group of A|Automorphism Group of $\AA$]] the [[Definition:Element|elements]] of $\AA$, expressed in [[Definition:Cayley Table|Cayley table]] form: :<nowiki>$\begin {array} {c|ccc} \to & a & b & c \\ \hline a & a & b & c \\ b & a & b & c \\ c & a & b & ...
Sets of Operations on Set of 3 Elements/Automorphism Group of A/Commutative Operations
https://proofwiki.org/wiki/Sets_of_Operations_on_Set_of_3_Elements/Automorphism_Group_of_A/Commutative_Operations
https://proofwiki.org/wiki/Sets_of_Operations_on_Set_of_3_Elements/Automorphism_Group_of_A/Commutative_Operations
[ "Sets of Operations on Set of 3 Elements" ]
[ "Definition:Operation/Binary Operation", "Definition:Commutative/Operation" ]
[ "Sets of Operations on Set of 3 Elements/Automorphism Group of A", "Definition:Element", "Definition:Cayley Table", "Cayley Table for Commutative Operation is Symmetrical about Main Diagonal", "Definition:Cayley Table", "Definition:Commutative/Operation" ]
proofwiki-18831
Sets of Operations on Set of 3 Elements/Automorphism Group of B/Commutative Operations
:Exactly $8$ of the operations of $\BB$ is commutative.
Recall Automorphism Group of $\BB$. Consider each of the categories of $\BB$ induced by each of $a \circ a$, $a \circ b$ and $a \circ c$, illustrated by the partially-filled Cayley tables to which they give rise: ;$(1): \quad a \circ a$ :$\begin {array} {c|ccc} \circ & a & b & c \\ \hline a & a & & \\ b & & b & ...
:Exactly $8$ of the [[Definition:Binary Operation|operations]] of $\BB$ is [[Definition:Commutative Operation|commutative]].
Recall [[Sets of Operations on Set of 3 Elements/Automorphism Group of B|Automorphism Group of $\BB$]]. Consider each of the categories of $\BB$ induced by each of $a \circ a$, $a \circ b$ and $a \circ c$, illustrated by the partially-filled [[Definition:Cayley Table|Cayley tables]] to which they give rise: ;$(1): ...
Sets of Operations on Set of 3 Elements/Automorphism Group of B/Commutative Operations
https://proofwiki.org/wiki/Sets_of_Operations_on_Set_of_3_Elements/Automorphism_Group_of_B/Commutative_Operations
https://proofwiki.org/wiki/Sets_of_Operations_on_Set_of_3_Elements/Automorphism_Group_of_B/Commutative_Operations
[ "Sets of Operations on Set of 3 Elements" ]
[ "Definition:Operation/Binary Operation", "Definition:Commutative/Operation" ]
[ "Sets of Operations on Set of 3 Elements/Automorphism Group of B", "Definition:Cayley Table", "Cayley Table for Commutative Operation is Symmetrical about Main Diagonal", "Definition:Cayley Table", "Definition:Operation/Binary Operation", "Definition:Commutative/Operation", "Definition:Operation/Binary ...
proofwiki-18832
Sets of Operations on Set of 3 Elements/Automorphism Group of C n/Commutative Operations
$8$ of the operations of each of $\CC_1$, $\CC_2$ and $\CC_3$ is commutative.
{{WLOG}}, we will analyse the nature of $\CC_1$. Recall this lemma:
$8$ of the [[Definition:Binary Operation|operations]] of each of $\CC_1$, $\CC_2$ and $\CC_3$ is [[Definition:Commutative Operation|commutative]].
{{WLOG}}, we will analyse the nature of $\CC_1$. Recall this [[Definition:Lemma|lemma]]:
Sets of Operations on Set of 3 Elements/Automorphism Group of C n/Commutative Operations
https://proofwiki.org/wiki/Sets_of_Operations_on_Set_of_3_Elements/Automorphism_Group_of_C_n/Commutative_Operations
https://proofwiki.org/wiki/Sets_of_Operations_on_Set_of_3_Elements/Automorphism_Group_of_C_n/Commutative_Operations
[ "Sets of Operations on Set of 3 Elements" ]
[ "Definition:Operation/Binary Operation", "Definition:Commutative/Operation" ]
[ "Definition:Lemma" ]
proofwiki-18833
Sets of Operations on Set of 3 Elements/Automorphism Group of D/Commutative Operations
:$696$ of the operations of $\DD$ is commutative.
Let $n$ denote the number of commutative operations of $\DD$. Recall these definitions: Let $\AA$, $\BB$, $\CC_1$, $\CC_2$ and $\CC_3$ be respectively the set of all operations $\circ$ on $S$ such that the groups of automorphisms of $\struct {S, \circ}$ are as follows: {{begin-eqn}} {{eqn | l = \AA | o = : ...
:$696$ of the [[Definition:Binary Operation|operations]] of $\DD$ is [[Definition:Commutative Operation|commutative]].
Let $n$ denote the number of [[Definition:Commutative Operation|commutative operations]] of $\DD$. Recall these definitions: Let $\AA$, $\BB$, $\CC_1$, $\CC_2$ and $\CC_3$ be respectively the [[Definition:Set|set]] of all [[Definition:Binary Operation|operations]] $\circ$ on $S$ such that the [[Definition:Group|grou...
Sets of Operations on Set of 3 Elements/Automorphism Group of D/Commutative Operations
https://proofwiki.org/wiki/Sets_of_Operations_on_Set_of_3_Elements/Automorphism_Group_of_D/Commutative_Operations
https://proofwiki.org/wiki/Sets_of_Operations_on_Set_of_3_Elements/Automorphism_Group_of_D/Commutative_Operations
[ "Sets of Operations on Set of 3 Elements" ]
[ "Definition:Operation/Binary Operation", "Definition:Commutative/Operation" ]
[ "Definition:Commutative/Operation", "Definition:Set", "Definition:Operation/Binary Operation", "Definition:Group", "Definition:Group Automorphism", "Definition:Symmetric Group", "Definition:Identity Mapping", "Definition:Commutative/Operation", "Definition:Commutative/Operation", "Definition:Commu...
proofwiki-18834
Sets of Operations on Set of 3 Elements/Commutative Operations
Let $\PP$ be the set of all commutative operations $\circ$ on $S$. Then the elements of $\PP$ are divided in $129$ isomorphism classes. That is, up to isomorphism, there are $129$ commutative operations on $S$ which have an identity element.
From Automorphism Group of $\AA$: Commutative Operations: :there is exactly $1$ commutative operation in $\AA$. From Automorphism Group of $\BB$: Commutative Operations: :there are $8$ commutative operations in $\BB$. From Automorphism Group of $\CC_n$: Commutative Operations: :there are $3 \times 8$ commutative operat...
Let $\PP$ be the [[Definition:Set|set]] of all [[Definition:Commutative Operation|commutative operations]] $\circ$ on $S$. Then the [[Definition:Element|elements]] of $\PP$ are divided in $129$ [[Definition:Isomorphism Class (Algebraic Structures)|isomorphism classes]]. That is, up to [[Definition:Isomorphism (Abstra...
From [[Sets of Operations on Set of 3 Elements/Automorphism Group of A/Commutative Operations|Automorphism Group of $\AA$: Commutative Operations]]: :there is exactly $1$ [[Definition:Commutative Operation|commutative operation]] in $\AA$. From [[Sets of Operations on Set of 3 Elements/Automorphism Group of B/Commutat...
Sets of Operations on Set of 3 Elements/Commutative Operations
https://proofwiki.org/wiki/Sets_of_Operations_on_Set_of_3_Elements/Commutative_Operations
https://proofwiki.org/wiki/Sets_of_Operations_on_Set_of_3_Elements/Commutative_Operations
[ "Sets of Operations on Set of 3 Elements" ]
[ "Definition:Set", "Definition:Commutative/Operation", "Definition:Element", "Definition:Isomorphism Class (Algebraic Structures)", "Definition:Isomorphism (Abstract Algebra)", "Definition:Commutative/Operation", "Definition:Identity (Abstract Algebra)/Two-Sided Identity" ]
[ "Sets of Operations on Set of 3 Elements/Automorphism Group of A/Commutative Operations", "Definition:Commutative/Operation", "Sets of Operations on Set of 3 Elements/Automorphism Group of B/Commutative Operations", "Definition:Commutative/Operation", "Sets of Operations on Set of 3 Elements/Automorphism Gr...
proofwiki-18835
Canonical P-adic Expansion of Rational is Eventually Periodic/Lemma 10
Let: :$n, k \in \N : k > 0 : r_n = r_{n + k}$ Then: :$d_{n + 1} = d_{n + k + 1}$ :$r_{n + 1} = r_{n + k + 1}$
We have: {{begin-eqn}} {{eqn | l = d_{n + 1} b + p r_{n + 1} | r = r_n | c = {{hypothesis}} }} {{eqn | r = r_{n + k} | c = {{hypothesis}} }} {{eqn | r = d_{n + k + 1} b + p r_{n + k + 1} | c = {{hypothesis}} }} {{eqn | ll = \leadsto | l = p \paren{ r_{n + k + 1} - r_{n + 1} } | r = \...
Let: :$n, k \in \N : k > 0 : r_n = r_{n + k}$ Then: :$d_{n + 1} = d_{n + k + 1}$ :$r_{n + 1} = r_{n + k + 1}$
We have: {{begin-eqn}} {{eqn | l = d_{n + 1} b + p r_{n + 1} | r = r_n | c = {{hypothesis}} }} {{eqn | r = r_{n + k} | c = {{hypothesis}} }} {{eqn | r = d_{n + k + 1} b + p r_{n + k + 1} | c = {{hypothesis}} }} {{eqn | ll = \leadsto | l = p \paren{ r_{n + k + 1} - r_{n + 1} } | r = \...
Canonical P-adic Expansion of Rational is Eventually Periodic/Lemma 10
https://proofwiki.org/wiki/Canonical_P-adic_Expansion_of_Rational_is_Eventually_Periodic/Lemma_10
https://proofwiki.org/wiki/Canonical_P-adic_Expansion_of_Rational_is_Eventually_Periodic/Lemma_10
[ "Canonical P-adic Expansion of Rational is Eventually Periodic" ]
[]
[ "Definition:Coprime/Integers", "Euclid's Lemma", "Definition:P-adic Digit", "Category:Canonical P-adic Expansion of Rational is Eventually Periodic" ]
proofwiki-18836
Locally Integrable (f(x+ct) + f(x-ct))/2 is Weak Solution to Wave Equation
Consider the wave equation: :$\dfrac {\partial^2 u} {\partial t^2} - c^2 \dfrac {\partial^2 u} {\partial x^2} = 0$ with the initial conditions: :$\map u {x, 0} = \map f x$ :$\map {\dfrac {\partial u} {\partial t}} {x, 0} = 0$ and $c \in \R$. Then it has a weak solution of the form: :$\map u {x, t} := \dfrac {\map f {x ...
Let $\map u {x, t} = \map f {x + ct}$ be a locally integrable function. We have that a locally integrable function defines a distribution. Let $T_u \in \map {\DD'} {\R^2}$ be a Schwartz distribution associated with $u$. Let $\phi \in \map \DD {\R^2}$ be a test function. Then: {{begin-eqn}} {{eqn | l = \map {\paren {\df...
Consider the [[Definition:Wave Equation|wave equation]]: :$\dfrac {\partial^2 u} {\partial t^2} - c^2 \dfrac {\partial^2 u} {\partial x^2} = 0$ with the [[Definition:Initial Condition|initial conditions]]: :$\map u {x, 0} = \map f x$ :$\map {\dfrac {\partial u} {\partial t}} {x, 0} = 0$ and $c \in \R$. Then it h...
Let $\map u {x, t} = \map f {x + ct}$ be a [[Definition:Locally Integrable Function|locally integrable function]]. We have that a [[Locally Integrable Function defines Distribution|locally integrable function defines a distribution]]. Let $T_u \in \map {\DD'} {\R^2}$ be a [[Definition:Schwartz Distribution|Schwartz d...
Locally Integrable (f(x+ct) + f(x-ct))/2 is Weak Solution to Wave Equation
https://proofwiki.org/wiki/Locally_Integrable_(f(x+ct)_+_f(x-ct))/2_is_Weak_Solution_to_Wave_Equation
https://proofwiki.org/wiki/Locally_Integrable_(f(x+ct)_+_f(x-ct))/2_is_Weak_Solution_to_Wave_Equation
[ "Examples of Weak Solutions", "Wave Equation" ]
[ "Definition:Wave Equation", "Definition:Initial Condition", "Definition:Differential Equation/Solution/Weak Solution", "Definition:Integrable Function/Locally Integrable Function" ]
[ "Definition:Integrable Function/Locally Integrable Function", "Locally Integrable Function defines Distribution", "Definition:Schwartz Distribution", "Definition:Test Function", "Distributional Partial Derivatives Commute", "Locally Integrable f(x+ct) is Weak Solution to Transport Equation", "Definition...
proofwiki-18837
Gilmer-Parker Theorem
Let $\struct {R, +, *}$ be a GCD Domain. Let $R \sqbrk x$ be a polynomial ring over $R$. Then $R \sqbrk x$ is also a GCD Domain.
{{tidy|Under way, this will take a long time as this page is very far from following the house rules. Use <code><nowiki>{{eqn}}</nowiki></code> template.}} {{MissingLinks}} Let $K$ be the field of quotients of $R$. Let $R \xrightarrow \varphi R \sqbrk x \xrightarrow \psi K \sqbrk x$ where $\varphi, \psi$ - embedding ho...
Let $\struct {R, +, *}$ be a [[Definition:GCD Domain|GCD Domain]]. Let $R \sqbrk x$ be a [[Definition:Polynomial Ring|polynomial ring]] over $R$. Then $R \sqbrk x$ is also a [[Definition:GCD Domain|GCD Domain]].
{{tidy|Under way, this will take a long time as this page is very far from following the house rules. Use <code><nowiki>{{eqn}}</nowiki></code> template.}} {{MissingLinks}} Let $K$ be the [[Definition:Field of Quotients|field of quotients of $R$]]. Let $R \xrightarrow \varphi R \sqbrk x \xrightarrow \psi K \sqbrk x$ ...
Gilmer-Parker Theorem
https://proofwiki.org/wiki/Gilmer-Parker_Theorem
https://proofwiki.org/wiki/Gilmer-Parker_Theorem
[ "GCD Domains", "Polynomial Rings" ]
[ "Definition:GCD Domain", "Definition:Polynomial Ring", "Definition:GCD Domain" ]
[ "Definition:Field of Quotients", "Definition:Ring Monomorphism", "Definition:Primitive Polynomial (Ring Theory)", "Definition:Content of Polynomial/GCD Domain", "Definition:Euclidean Domain", "Definition:GCD Domain", "Definition:Associate", "Euclid's Lemma" ]
proofwiki-18838
Weak Solution to Dx u = Heaviside Step Function
Let $H: \R \to \closedint 0 1$ be the Heaviside step function. Let $u : \R \to \R$ be such that: :<nowiki>$\map u x = \begin{cases} c & : x < 0 \\ x + c & : x > 0 \end{cases}$</nowiki> where $c \in \R$. Let $T_u$ be the Schwartz distribution associated with $u$. Then $u$ is a weak solution of: :$u' = H$ That is, in t...
$u$ is continuous on $\R$ and continously differentiable on $\R \setminus \set 0$. For $x < 0$ we have $\map {u'} x = 0$. For $x > 0$ we have $\map {u'} x = 1$. That is: :$\map {u'} x = \map H x$ Furthermore: :$\ds \lim_{x \mathop \to 0^-} = 0$ :$\ds \lim_{x \mathop \to 0^+} = 1$ By the jump rule: {{begin-eqn}} {{eqn |...
Let $H: \R \to \closedint 0 1$ be the [[Definition:Heaviside Step Function|Heaviside step function]]. Let $u : \R \to \R$ be such that: :<nowiki>$\map u x = \begin{cases} c & : x < 0 \\ x + c & : x > 0 \end{cases}$</nowiki> where $c \in \R$. Let $T_u$ be the [[Definition:Schwartz Distribution|Schwartz distributio...
$u$ is [[Definition:Everywhere Continuous Real Function|continuous]] on $\R$ and [[Definition:Continuously Differentiable Real Function|continously differentiable]] on $\R \setminus \set 0$. For $x < 0$ we have $\map {u'} x = 0$. For $x > 0$ we have $\map {u'} x = 1$. That is: :$\map {u'} x = \map H x$ Furthermore...
Weak Solution to Dx u = Heaviside Step Function
https://proofwiki.org/wiki/Weak_Solution_to_Dx_u_=_Heaviside_Step_Function
https://proofwiki.org/wiki/Weak_Solution_to_Dx_u_=_Heaviside_Step_Function
[ "Examples of Weak Solutions" ]
[ "Definition:Heaviside Step Function", "Definition:Schwartz Distribution", "Definition:Differential Equation/Solution/Weak Solution", "Definition:Distributional Derivative" ]
[ "Definition:Continuous Real Function/Everywhere", "Definition:Continuously Differentiable/Real Function", "Jump Rule" ]
proofwiki-18839
Laplace Transform of Derivative with Finite Discontinuities
Let $f$ have a finite number of jump discontinuities at $t = a_i$ for $i = 1, 2, \ldots, n$. Then: :$\laptrans {\map {f'} t} = s \laptrans {\map f t} - \map f 0 - \ds \sum_{i \mathop = 1}^n e^{-a_i s} \paren {\map f {a_i^+} - \map f {a_i^-} }$
{{tidy|Rewrite the following in house style}} The proof is found similarly to the proof in Laplace Transform of Derivative but requires breaking the integral into $n$ integrals of finite range between the discontinuities and one improper integral from $a_n^+$ to $+\infty$. Integration by parts yields the summation when...
Let $f$ have a finite number of [[Definition:Jump Discontinuity|jump discontinuities]] at $t = a_i$ for $i = 1, 2, \ldots, n$. Then: :$\laptrans {\map {f'} t} = s \laptrans {\map f t} - \map f 0 - \ds \sum_{i \mathop = 1}^n e^{-a_i s} \paren {\map f {a_i^+} - \map f {a_i^-} }$
{{tidy|Rewrite the following in house style}} The proof is found similarly to the proof in [[Laplace Transform of Derivative]] but requires breaking the integral into $n$ integrals of finite range between the discontinuities and one improper integral from $a_n^+$ to $+\infty$. Integration by parts yields the summation...
Laplace Transform of Derivative with Finite Discontinuities
https://proofwiki.org/wiki/Laplace_Transform_of_Derivative_with_Finite_Discontinuities
https://proofwiki.org/wiki/Laplace_Transform_of_Derivative_with_Finite_Discontinuities
[ "Laplace Transforms of Derivatives" ]
[ "Definition:Discontinuity (Real Analysis)/Jump" ]
[ "Laplace Transform of Derivative", "Laplace Transform of Derivative", "Laplace Transform of Derivative" ]
proofwiki-18840
Power Set is Nonempty
Let $S$ be a set. Then: :$\powerset S \ne \O$
By Empty Set is Element of Power Set: :$\O \in \powerset S$ Thus we conclude that $\powerset S$ is non-empty. {{qed}} Category:Empty Set Category:Power Set j0xb6oxhss17kiz835w4sxlq42kj82i
Let $S$ be a [[Definition:Set|set]]. Then: :$\powerset S \ne \O$
By [[Empty Set is Element of Power Set]]: :$\O \in \powerset S$ Thus we conclude that $\powerset S$ is [[Definition:Non-Empty Set|non-empty]]. {{qed}} [[Category:Empty Set]] [[Category:Power Set]] j0xb6oxhss17kiz835w4sxlq42kj82i
Power Set is Nonempty
https://proofwiki.org/wiki/Power_Set_is_Nonempty
https://proofwiki.org/wiki/Power_Set_is_Nonempty
[ "Empty Set", "Power Set" ]
[ "Definition:Set" ]
[ "Empty Set is Element of Power Set", "Definition:Non-Empty Set", "Category:Empty Set", "Category:Power Set" ]
proofwiki-18841
Multiplication of Distribution induced by Locally Integrable Function by Smooth Function
Let $f \in \map {L^1_{loc} } {\R^d}$ be a locally integrable function. Let $\alpha \in \map {C^\infty} {\R^d}$ be a smooth function. Let $T_f \in \map {\DD'} {\R^d}$ be a Schwartz distribution induced by $f$. Then in the distributional sense it holds that: :$\alpha T_f = T_{\alpha f}$
Let $\Omega \subseteq \R^d$ be a compact subset. Then for all $\mathbf x \in \Omega$ we have that $\map \alpha {\mathbf x}$ is bounded. Hence, $\alpha f$ is locally integrable. Let $\phi \in \map \DD {\R^d}$ be a test function. Then: {{begin-eqn}} {{eqn | l = \alpha \map {T_f} \phi | r = \map {T_f} {\alpha \phi} ...
Let $f \in \map {L^1_{loc} } {\R^d}$ be a [[Definition:Locally Integrable Function|locally integrable function]]. Let $\alpha \in \map {C^\infty} {\R^d}$ be a [[Definition:Smooth Function|smooth function]]. Let $T_f \in \map {\DD'} {\R^d}$ be a [[Definition:Schwartz Distribution|Schwartz distribution]] induced by $f$...
Let $\Omega \subseteq \R^d$ be a [[Definition:Compact Subset of Real Euclidean Space|compact subset]]. Then for all $\mathbf x \in \Omega$ we have that $\map \alpha {\mathbf x}$ is [[Definition:Bounded Mapping|bounded]]. Hence, $\alpha f$ is [[Definition:Locally Integrable Function|locally integrable]]. Let $\phi \i...
Multiplication of Distribution induced by Locally Integrable Function by Smooth Function
https://proofwiki.org/wiki/Multiplication_of_Distribution_induced_by_Locally_Integrable_Function_by_Smooth_Function
https://proofwiki.org/wiki/Multiplication_of_Distribution_induced_by_Locally_Integrable_Function_by_Smooth_Function
[ "Schwartz Distributions" ]
[ "Definition:Integrable Function/Locally Integrable Function", "Definition:Smooth Real Function", "Definition:Schwartz Distribution", "Definition:Schwartz Distribution" ]
[ "Definition:Compact Space/Euclidean Space", "Definition:Bounded Mapping", "Definition:Integrable Function/Locally Integrable Function", "Definition:Test Function", "Locally Integrable Function defines Distribution", "Locally Integrable Function defines Distribution" ]
proofwiki-18842
Cartesian Product is Unique
Let $A$ and $B$ be classes. If there exists a '''cartesian product''' of $A$ and $B$, then it is unique.
Let $C_1$ and $C_2$ be cartesian products of $A$ and $B$. Then by the cartesian product definition, for an arbitrary $a$: :$a \in C_1 \iff \exists x \in A: \exists y \in B: a = \tuple {x, y}$ :$a \in C_2 \iff \exists x \in A: \exists y \in B: a = \tuple {x, y}$ By Biconditional is Transitive: :$a \in C_1 \iff a \in C_2...
Let $A$ and $B$ be [[Definition:Class (Class Theory)|classes]]. If there exists a '''[[Definition:Cartesian Product (Class Theory)|cartesian product]]''' of $A$ and $B$, then it is [[Definition:Unique|unique]].
Let $C_1$ and $C_2$ be [[Definition:Cartesian Product (Class Theory)|cartesian products]] of $A$ and $B$. Then by the [[Definition:Cartesian Product (Class Theory)|cartesian product]] definition, for an arbitrary $a$: :$a \in C_1 \iff \exists x \in A: \exists y \in B: a = \tuple {x, y}$ :$a \in C_2 \iff \exists x \in ...
Cartesian Product is Unique
https://proofwiki.org/wiki/Cartesian_Product_is_Unique
https://proofwiki.org/wiki/Cartesian_Product_is_Unique
[ "Cartesian Product" ]
[ "Definition:Class (Class Theory)", "Definition:Cartesian Product/Class Theory", "Definition:Unique" ]
[ "Definition:Cartesian Product/Class Theory", "Definition:Cartesian Product/Class Theory", "Biconditional is Transitive", "Axiom:Axiom of Extension/Class Theory", "Definition:Cartesian Product/Class Theory", "Definition:Unique" ]
proofwiki-18843
Biconditional of Proposition and its Negation
:$\vdash \neg (p \iff \neg p)$
We apply the Method of Truth Tables to the proposition. As can be seen by inspection, in each case, the truth values in the appropriate columns match for all boolean interpretations. $\begin{array}{|c|cccc|} \hline \neg & (p & \iff & \neg & p)\\ \hline \T & \F & \F & \T & \F \\ \T & \T & \F & \F & \T \\ \hline \end{arr...
:$\vdash \neg (p \iff \neg p)$
We apply the [[Method of Truth Tables]] to the proposition. As can be seen by inspection, in each case, the [[Definition:Truth Value|truth values]] in the appropriate columns match for all [[Definition:Boolean Interpretation|boolean interpretations]]. $\begin{array}{|c|cccc|} \hline \neg & (p & \iff & \neg & p)\\ \hl...
Biconditional of Proposition and its Negation/Proof by Truth Table
https://proofwiki.org/wiki/Biconditional_of_Proposition_and_its_Negation
https://proofwiki.org/wiki/Biconditional_of_Proposition_and_its_Negation/Proof_by_Truth_Table
[ "Biconditional", "Biconditional of Proposition and its Negation" ]
[]
[ "Method of Truth Tables", "Definition:Truth Value", "Definition:Boolean Interpretation" ]
proofwiki-18844
Axiom of Specification from Replacement and Empty Set
The {{axiom-link|Specification|Sets}} is a consequence of: :the {{axiom-link|Replacement}} and :the {{axiom-link|the Empty Set|Set Theory}}.
{{Proofread|proof is tedious}} Let $A$ be an arbitrary set. Let $\map P x$ be an arbitrary propositional function. It is to be shown that there exists a set $B$ consisting of exactly the $y \in A$ such that $\map P y$. That is: :$\forall A: \exists B: \forall y: \paren {y \in B \iff \paren {y \in A \land \map P y} }$ B...
The {{axiom-link|Specification|Sets}} is a consequence of: :the {{axiom-link|Replacement}} and :the {{axiom-link|the Empty Set|Set Theory}}.
{{Proofread|proof is tedious}} Let $A$ be an arbitrary [[Definition:Set|set]]. Let $\map P x$ be an arbitrary [[Definition:Propositional Function|propositional function]]. It is to be shown that there exists a [[Definition:Set|set]] $B$ consisting of exactly the $y \in A$ such that $\map P y$. That is: :$\forall A...
Axiom of Specification from Replacement and Empty Set
https://proofwiki.org/wiki/Axiom_of_Specification_from_Replacement_and_Empty_Set
https://proofwiki.org/wiki/Axiom_of_Specification_from_Replacement_and_Empty_Set
[ "Zermelo-Fraenkel Axioms", "Empty Set" ]
[]
[ "Definition:Set", "Definition:Propositional Function", "Definition:Set", "Law of Excluded Middle", "Definition:Empty Set", "Rule of Explosion", "Rule of Explosion", "Universal Generalisation", "Existential Generalisation", "Definition:Propositional Function", "Definition:Mapping", "Definition:...
proofwiki-18845
Cycle Graph is Eulerian
Let $G$ be a cycle graph. Then $G$ is Eulerian.
From Cycle Graph is Connected, $G$ is a connected graph. From Cycle Graph is $2$-Regular, $G$ is $2$-regular. It follows directly from Characteristics of Eulerian Graph that $G$ is Eulerian. {{Qed}} Category:Cycle Graphs Category:Eulerian Graphs jt94p8yky7cp9lr3s8g8bw2rngonfnd
Let $G$ be a [[Definition:Cycle Graph|cycle graph]]. Then $G$ is [[Definition:Eulerian Graph|Eulerian]].
From [[Cycle Graph is Connected]], $G$ is a [[Definition:Connected Graph|connected graph]]. From [[Cycle Graph is 2-Regular|Cycle Graph is $2$-Regular]], $G$ is [[Definition:Regular Graph|$2$-regular]]. It follows directly from [[Characteristics of Eulerian Graph]] that $G$ is [[Definition:Eulerian Graph|Eulerian]]. ...
Cycle Graph is Eulerian
https://proofwiki.org/wiki/Cycle_Graph_is_Eulerian
https://proofwiki.org/wiki/Cycle_Graph_is_Eulerian
[ "Cycle Graphs", "Eulerian Graphs" ]
[ "Definition:Cycle Graph", "Definition:Eulerian Graph" ]
[ "Cycle Graph is Connected", "Definition:Connected (Graph Theory)/Graph", "Cycle Graph is 2-Regular", "Definition:Regular Graph", "Characteristics of Eulerian Graph", "Definition:Eulerian Graph", "Category:Cycle Graphs", "Category:Eulerian Graphs" ]
proofwiki-18846
Cycle Graph is 2-Regular
Let $G$ be a cycle graph. Then $G$ is regular.
Let $G$ be a cycle graph. By definition, a '''cycle graph''' is a graph which consists of a single cycle $C$. By definition, a '''cycle''' is a circuit in which no vertex except the first (which is also the last) appears more than once. By definition, a '''circuit''' is a closed trail with at least one edge. By definit...
Let $G$ be a [[Definition:Cycle Graph|cycle graph]]. Then $G$ is [[Definition:Regular Graph|regular]].
Let $G$ be a [[Definition:Cycle Graph|cycle graph]]. By definition, a '''[[Definition:Cycle Graph|cycle graph]]''' is a [[Definition:Graph (Graph Theory)|graph]] which consists of a single [[Definition:Cycle (Graph Theory)|cycle]] $C$. By definition, a '''[[Definition:Cycle (Graph Theory)|cycle]]''' is a [[Definition...
Cycle Graph is 2-Regular
https://proofwiki.org/wiki/Cycle_Graph_is_2-Regular
https://proofwiki.org/wiki/Cycle_Graph_is_2-Regular
[ "Cycle Graphs", "Regular Graphs" ]
[ "Definition:Cycle Graph", "Definition:Regular Graph" ]
[ "Definition:Cycle Graph", "Definition:Cycle Graph", "Definition:Graph (Graph Theory)", "Definition:Cycle (Graph Theory)", "Definition:Cycle (Graph Theory)", "Definition:Circuit (Graph Theory)", "Definition:Graph (Graph Theory)/Vertex", "Definition:Circuit (Graph Theory)", "Definition:Walk (Graph The...
proofwiki-18847
Cycle Graph is Connected
Let $G = \struct {V, E}$ be a cycle graph. Then $G$ is connected.
A cycle graph is defined as a (simple) graph which consists of a single cycle. So a cycle graph consists of just one component, and hence is connected. {{qed}} Category:Cycle Graphs Category:Connectedness (Graph Theory) 0enbhaoaa4eus769o1qcyjxp639ol87
Let $G = \struct {V, E}$ be a [[Definition:Cycle Graph|cycle graph]]. Then $G$ is [[Definition:Connected Graph|connected]].
A [[Definition:Cycle Graph|cycle graph]] is defined as a [[Definition:Simple Graph|(simple) graph]] which consists of a single [[Definition:Cycle (Graph Theory)|cycle]]. So a [[Definition:Cycle Graph|cycle graph]] consists of just one [[Definition:Component of Graph|component]], and hence is [[Definition:Connected Gra...
Cycle Graph is Connected
https://proofwiki.org/wiki/Cycle_Graph_is_Connected
https://proofwiki.org/wiki/Cycle_Graph_is_Connected
[ "Cycle Graphs", "Connectedness (Graph Theory)" ]
[ "Definition:Cycle Graph", "Definition:Connected (Graph Theory)/Graph" ]
[ "Definition:Cycle Graph", "Definition:Simple Graph", "Definition:Cycle (Graph Theory)", "Definition:Cycle Graph", "Definition:Component of Graph", "Definition:Connected (Graph Theory)/Graph", "Category:Cycle Graphs", "Category:Connectedness (Graph Theory)" ]
proofwiki-18848
Cycle Graph is Bipartite iff Order is Even
Let $n \in \N$ be a natural number. Let $C_n$ be the cycle graph of order $n$. Then $C_n$ is a bipartite graph {{iff}} $n$ is even.
Let $V$ be the set of vertices of $C_n$. Let the elements of $V$ be denoted $v_1, v_2, \ldots, v_n$. Then by definition of cycle graph, by appropriate selection of subscripts, $C_n$ consists of one cycle $C$ that can be expressed as: :$C := \tuple {v_1 v_2 \ldots, v_n v_1}$ Let $v_k \in C_n$. Then for $1 < k < n$, $v_k...
Let $n \in \N$ be a [[Definition:Natural Number|natural number]]. Let $C_n$ be the [[Definition:Cycle Graph|cycle graph]] of [[Definition:Order of Graph|order]] $n$. Then $C_n$ is a [[Definition:Bipartite Graph|bipartite graph]] {{iff}} $n$ is [[Definition:Even Integer|even]].
Let $V$ be the [[Definition:Set|set]] of [[Definition:Vertex of Graph|vertices]] of $C_n$. Let the [[Definition:Element|elements]] of $V$ be denoted $v_1, v_2, \ldots, v_n$. Then by definition of [[Definition:Cycle Graph|cycle graph]], by appropriate selection of subscripts, $C_n$ consists of one [[Definition:Cycle (...
Cycle Graph is Bipartite iff Order is Even
https://proofwiki.org/wiki/Cycle_Graph_is_Bipartite_iff_Order_is_Even
https://proofwiki.org/wiki/Cycle_Graph_is_Bipartite_iff_Order_is_Even
[ "Cycle Graphs", "Bipartite Graphs", "Cycle Graph is Bipartite iff Order is Even" ]
[ "Definition:Natural Numbers", "Definition:Cycle Graph", "Definition:Graph (Graph Theory)/Order", "Definition:Bipartite Graph", "Definition:Even Integer" ]
[ "Definition:Set", "Definition:Graph (Graph Theory)/Vertex", "Definition:Element", "Definition:Cycle Graph", "Definition:Cycle (Graph Theory)", "Definition:Adjacent (Graph Theory)/Vertices", "Definition:Graph (Graph Theory)/Vertex", "Definition:Adjacent (Graph Theory)/Vertices", "Definition:Adjacent ...
proofwiki-18849
Cycle Graph of Order 1 is Loop-Graph
Let $C_1$ denote the cycle graph of order $1$. Then $C_1$ is a loop-graph.
By definition, the vertex set of $C_1$ is singleton, $\set v$, say. The only vertex of $C_1$ that an edge can be incident to is $v$. Hence there exists an edge which is incident to $v$ at both ends. That is, $C_1$ has a loop. Hence the result by definition of loop-graph. {{qed}} Category:Examples of Cycle Graphs Catego...
Let $C_1$ denote the [[Definition:Cycle Graph|cycle graph]] of [[Definition:Order of Graph|order $1$]]. Then $C_1$ is a [[Definition:Loop-Graph|loop-graph]].
By definition, the [[Definition:Vertex Set|vertex set]] of $C_1$ is [[Definition:Singleton|singleton]], $\set v$, say. The only [[Definition:Vertex of Graph|vertex]] of $C_1$ that an [[Definition:Edge of Graph|edge]] can be [[Definition:Incident (Undirected Graph)|incident]] to is $v$. Hence there exists an [[Definit...
Cycle Graph of Order 1 is Loop-Graph
https://proofwiki.org/wiki/Cycle_Graph_of_Order_1_is_Loop-Graph
https://proofwiki.org/wiki/Cycle_Graph_of_Order_1_is_Loop-Graph
[ "Examples of Cycle Graphs", "Examples of Loop-Graphs" ]
[ "Definition:Cycle Graph", "Definition:Graph (Graph Theory)/Order", "Definition:Loop-Graph" ]
[ "Definition:Vertex Set", "Definition:Singleton", "Definition:Graph (Graph Theory)/Vertex", "Definition:Graph (Graph Theory)/Edge", "Definition:Incident (Graph Theory)/Undirected Graph", "Definition:Graph (Graph Theory)/Edge", "Definition:Incident (Graph Theory)/Undirected Graph", "Definition:Loop (Gra...
proofwiki-18850
Cycle Graph of Order 2 is Multigraph
Let $C_2$ denote the cycle graph of order $2$. Then $C_2$ is a multigraph.
By definition, the vertex set of $C_2$ is doubleton, $\set {v_1, v_2}$, say. By definition of cycle graph, there is a circuit $v_1 v_2 v_1$. That is: :there exists an edge which is incident to $v_1$ and $v_2$ :there exists an edge which is incident to $v_2$ and $v_1$ That is, there are $2$ edges which are both incident...
Let $C_2$ denote the [[Definition:Cycle Graph|cycle graph]] of [[Definition:Order of Graph|order $2$]]. Then $C_2$ is a [[Definition:Multigraph|multigraph]].
By definition, the [[Definition:Vertex Set|vertex set]] of $C_2$ is [[Definition:Doubleton|doubleton]], $\set {v_1, v_2}$, say. By definition of [[Definition:Cycle Graph|cycle graph]], there is a [[Definition:Circuit (Graph Theory)|circuit]] $v_1 v_2 v_1$. That is: :there exists an [[Definition:Edge of Graph|edge]] w...
Cycle Graph of Order 2 is Multigraph
https://proofwiki.org/wiki/Cycle_Graph_of_Order_2_is_Multigraph
https://proofwiki.org/wiki/Cycle_Graph_of_Order_2_is_Multigraph
[ "Examples of Cycle Graphs", "Examples of Multigraphs" ]
[ "Definition:Cycle Graph", "Definition:Graph (Graph Theory)/Order", "Definition:Multigraph" ]
[ "Definition:Vertex Set", "Definition:Doubleton", "Definition:Cycle Graph", "Definition:Circuit (Graph Theory)", "Definition:Graph (Graph Theory)/Edge", "Definition:Incident (Graph Theory)/Undirected Graph", "Definition:Graph (Graph Theory)/Edge", "Definition:Incident (Graph Theory)/Undirected Graph", ...
proofwiki-18851
Cycle Graph of Order 3 is Complete Graph
Let $C_3$ denote the cycle graph of order $2$. Then $C_3$ is the complete graph of of order $3$.
Let the vertex set of $C_3$ is $\set {v_1, v_2, v_3}$. By definition of cycle graph, $C_3$ consists of the cycle $v_1 v_2 v_3 v_1$. It is seen by inspection that: :$v_1$ is adjacent to $v_2$ and $v_3$ :$v_2$ is adjacent to $v_1$ and $v_3$ :$v_3$ is adjacent to $v_1$ and $v_2$. Hence the result by definition of complete...
Let $C_3$ denote the [[Definition:Cycle Graph|cycle graph]] of [[Definition:Order of Graph|order $2$]]. Then $C_3$ is the [[Definition:Complete Graph|complete graph]] of of [[Definition:Order of Graph|order $3$]].
Let the [[Definition:Vertex Set|vertex set]] of $C_3$ is $\set {v_1, v_2, v_3}$. By definition of [[Definition:Cycle Graph|cycle graph]], $C_3$ consists of the [[Definition:Cycle (Graph Theory)|cycle]] $v_1 v_2 v_3 v_1$. It is seen by inspection that: :$v_1$ is [[Definition:Adjacent Vertices of Graph|adjacent]] to $v...
Cycle Graph of Order 3 is Complete Graph
https://proofwiki.org/wiki/Cycle_Graph_of_Order_3_is_Complete_Graph
https://proofwiki.org/wiki/Cycle_Graph_of_Order_3_is_Complete_Graph
[ "Examples of Cycle Graphs", "Examples of Complete Graphs" ]
[ "Definition:Cycle Graph", "Definition:Graph (Graph Theory)/Order", "Definition:Complete Graph", "Definition:Graph (Graph Theory)/Order" ]
[ "Definition:Vertex Set", "Definition:Cycle Graph", "Definition:Cycle (Graph Theory)", "Definition:Adjacent (Graph Theory)/Vertices", "Definition:Adjacent (Graph Theory)/Vertices", "Definition:Adjacent (Graph Theory)/Vertices", "Definition:Complete Graph", "Category:Examples of Cycle Graphs", "Catego...
proofwiki-18852
Negated Restricted Existential Quantifier
Let $x$ and $A$ be sets. Let $\map P x$ be a propositional function. :$\neg \exists x \in A : \map P x \iff \forall x \in A : \neg \map P x $
From left to right: {{begin-eqn}} {{eqn | q = \neg \exists x \in A | o = \map P x }} {{eqn | ll= \leadsto | q = \neg \exists x | o = x \in A \land \map P x | c = {{defof|Restricted Existential Quantifier}} }} {{eqn | ll= \leadsto | q = \forall x | o = \neg \paren{x \in A \land \map ...
Let $x$ and $A$ be [[Definition:Set|sets]]. Let $\map P x$ be a [[Definition:Propositional Function|propositional function]]. :$\neg \exists x \in A : \map P x \iff \forall x \in A : \neg \map P x $
From left to right: {{begin-eqn}} {{eqn | q = \neg \exists x \in A | o = \map P x }} {{eqn | ll= \leadsto | q = \neg \exists x | o = x \in A \land \map P x | c = {{defof|Restricted Existential Quantifier}} }} {{eqn | ll= \leadsto | q = \forall x | o = \neg \paren{x \in A \land \map...
Negated Restricted Existential Quantifier
https://proofwiki.org/wiki/Negated_Restricted_Existential_Quantifier
https://proofwiki.org/wiki/Negated_Restricted_Existential_Quantifier
[]
[ "Definition:Set", "Definition:Propositional Function" ]
[ "De Morgan's Laws (Predicate Logic)/Denial of Existence", "Modus Ponendo Tollens/Variant", "Modus Ponendo Tollens/Variant", "De Morgan's Laws (Predicate Logic)/Denial of Existence" ]
proofwiki-18853
Negated Restricted Universal Quantifier
Let $x$ and $A$ be sets. Let $\map P x$ be a propositional function. :$\neg \forall x \in A : \map P x \iff \exists x \in A : \neg \map P x $
=== Sufficient Condition === {{begin-eqn}} {{eqn | q = \neg \forall x \in A | o = \map P x }} {{eqn | ll= \leadsto | q = \neg \forall x | o = x \in A \implies \map P x | c = {{defof|Restricted Universal Quantifier}} }} {{eqn | ll= \leadsto | q = \exists x | o = \neg \paren{x \in A \...
Let $x$ and $A$ be [[Definition:Set|sets]]. Let $\map P x$ be a [[Definition:Propositional Function|propositional function]]. :$\neg \forall x \in A : \map P x \iff \exists x \in A : \neg \map P x $
=== Sufficient Condition === {{begin-eqn}} {{eqn | q = \neg \forall x \in A | o = \map P x }} {{eqn | ll= \leadsto | q = \neg \forall x | o = x \in A \implies \map P x | c = {{defof|Restricted Universal Quantifier}} }} {{eqn | ll= \leadsto | q = \exists x | o = \neg \paren{x \in A ...
Negated Restricted Universal Quantifier
https://proofwiki.org/wiki/Negated_Restricted_Universal_Quantifier
https://proofwiki.org/wiki/Negated_Restricted_Universal_Quantifier
[ "Universal Quantifier" ]
[ "Definition:Set", "Definition:Propositional Function" ]
[ "De Morgan's Laws (Predicate Logic)/Denial of Universality", "Conjunction with Negative is Equivalent to Negation of Conditional", "Conjunction with Negative is Equivalent to Negation of Conditional", "De Morgan's Laws (Predicate Logic)/Denial of Universality" ]
proofwiki-18854
Mediant is Dependent upon Representation
Let $r, s \in \Q$ be rational numbers. Let $r$ and $s$ be expressed as: {{begin-eqn}} {{eqn | l = r | r = \dfrac a b }} {{eqn | l = s | r = \dfrac c d }} {{end-eqn}} where $a, b, c, d$ are integers such that $b > 0, d > 0$. Then the mediant of $r$ and $s$ is dependent upon the specific integers chosen for $...
;Proof by Counterexample Let $r = \dfrac 1 2$ and $s = 1$. We have: :$r = \dfrac 1 2 = \dfrac 2 4 = \dfrac 3 6$ Then the mediant of $r = \dfrac 2 4$ and $s = \dfrac 1 1$ gives: :$\dfrac {2 + 1} {4 + 1} = \dfrac 3 5$ but the mediant of $r = \dfrac 1 2$ and $s = \dfrac 1 1$ gives: :$\dfrac {1 + 1} {2 + 1} = \dfrac 2 3$...
Let $r, s \in \Q$ be [[Definition:Rational Number|rational numbers]]. Let $r$ and $s$ be expressed as: {{begin-eqn}} {{eqn | l = r | r = \dfrac a b }} {{eqn | l = s | r = \dfrac c d }} {{end-eqn}} where $a, b, c, d$ are [[Definition:Integer|integers]] such that $b > 0, d > 0$. Then the [[Definition:Med...
;[[Proof by Counterexample]] Let $r = \dfrac 1 2$ and $s = 1$. We have: :$r = \dfrac 1 2 = \dfrac 2 4 = \dfrac 3 6$ Then the [[Definition:Mediant|mediant]] of $r = \dfrac 2 4$ and $s = \dfrac 1 1$ gives: :$\dfrac {2 + 1} {4 + 1} = \dfrac 3 5$ but the [[Definition:Mediant|mediant]] of $r = \dfrac 1 2$ and $s = \d...
Mediant is Dependent upon Representation
https://proofwiki.org/wiki/Mediant_is_Dependent_upon_Representation
https://proofwiki.org/wiki/Mediant_is_Dependent_upon_Representation
[ "Mediants" ]
[ "Definition:Rational Number", "Definition:Integer", "Definition:Mediant", "Definition:Integer" ]
[ "Proof by Counterexample", "Definition:Mediant", "Definition:Mediant" ]
proofwiki-18855
All Infima Preserving Mapping is Upper Adjoint of Galois Connection/Lemma 1
:$g$ is an increasing mapping.
Define a mapping $d: T \to S$: :$\forall t \in T: \map d t := \map \inf {g^{-1} \sqbrk {t^\succsim} }$ Let $x, y \in S$ such that :$x \preceq y$ By Upper Closure is Decreasing: :$y^\succeq \subseteq x^\succeq$ By Infimum of Upper Closure of Element: :$\map \inf {x^\succeq} = x$ and $\map \inf {y^\succeq} = y$ By defini...
:$g$ is an [[Definition:Increasing Mapping|increasing mapping]].
Define a [[Definition:Mapping|mapping]] $d: T \to S$: :$\forall t \in T: \map d t := \map \inf {g^{-1} \sqbrk {t^\succsim} }$ Let $x, y \in S$ such that :$x \preceq y$ By [[Upper Closure is Decreasing]]: :$y^\succeq \subseteq x^\succeq$ By [[Infimum of Upper Closure of Element]]: :$\map \inf {x^\succeq} = x$ and $\m...
All Infima Preserving Mapping is Upper Adjoint of Galois Connection/Lemma 1
https://proofwiki.org/wiki/All_Infima_Preserving_Mapping_is_Upper_Adjoint_of_Galois_Connection/Lemma_1
https://proofwiki.org/wiki/All_Infima_Preserving_Mapping_is_Upper_Adjoint_of_Galois_Connection/Lemma_1
[ "All Infima Preserving Mapping is Upper Adjoint of Galois Connection" ]
[ "Definition:Increasing/Mapping" ]
[ "Definition:Mapping", "Upper Closure is Decreasing", "Infimum of Upper Closure of Element", "Definition:Mapping Preserves Infimum/All", "Definition:Mapping Preserves Infimum/Subset", "Definition:Mapping Preserves Infimum/Subset", "Definition:Mapping Preserves Infimum/Subset", "Image of Subset under Ma...
proofwiki-18856
Category Axioms are Self-Dual/Object Category Theory
Let $\mathrm {CT}$ be the collection of seven axioms on Characterization of Metacategory via Equations. Then: :$\mathrm {CT} = \mathrm {CT}^*$ where $\mathrm {CT}^*$ consists of the dual statements of those in $\mathrm{CT}$.
The seven axioms are: {{begin-eqn}} {{eqn | l = \operatorname {dom} \operatorname {id}_A = A | o = \qquad | r = \operatorname {cod} \operatorname {id}_A = A }} {{eqn | l = f \circ 1_{\operatorname {dom} f} = f | o = | r = 1_{\operatorname {cod} f} \circ f = f }} {{eqn | l = \map {\operatorname ...
Let $\mathrm {CT}$ be the collection of seven axioms on [[Characterization of Metacategory via Equations]]. Then: :$\mathrm {CT} = \mathrm {CT}^*$ where $\mathrm {CT}^*$ consists of the [[Definition:Dual Statement (Category Theory)|dual statements]] of those in $\mathrm{CT}$.
The seven axioms are: {{begin-eqn}} {{eqn | l = \operatorname {dom} \operatorname {id}_A = A | o = \qquad | r = \operatorname {cod} \operatorname {id}_A = A }} {{eqn | l = f \circ 1_{\operatorname {dom} f} = f | o = | r = 1_{\operatorname {cod} f} \circ f = f }} {{eqn | l = \map {\operatorname...
Category Axioms are Self-Dual/Object Category Theory
https://proofwiki.org/wiki/Category_Axioms_are_Self-Dual/Object_Category_Theory
https://proofwiki.org/wiki/Category_Axioms_are_Self-Dual/Object_Category_Theory
[ "Category Axioms are Self-Dual" ]
[ "Characterization of Metacategory via Equations", "Definition:Dual Statement (Category Theory)" ]
[ "Definition:Dual Statement (Category Theory)", "Definition:Bound Variable" ]
proofwiki-18857
Distribution Space over Smooth Functions is Unitary Module
The distribution space over smooth functions is a unitary module.
Let $\phi \in \map \DD {\R^d}$ be a test function.
The [[Definition:Distribution Space|distribution space]] over [[Definition:Smooth Function|smooth functions]] is a [[Definition:Unitary Module|unitary module]].
Let $\phi \in \map \DD {\R^d}$ be a [[Definition:Test Function|test function]].
Distribution Space over Smooth Functions is Unitary Module
https://proofwiki.org/wiki/Distribution_Space_over_Smooth_Functions_is_Unitary_Module
https://proofwiki.org/wiki/Distribution_Space_over_Smooth_Functions_is_Unitary_Module
[ "Schwartz Distributions", "Examples of Unitary Modules" ]
[ "Definition:Distribution Space", "Definition:Smooth Real Function", "Definition:Unitary Module over Ring" ]
[ "Definition:Test Function" ]
proofwiki-18858
Smooth Real Function times Derivative of Dirac Delta Distribution/Corollary
Let $\delta \in \map {\DD'} \R$ be the Dirac delta distribution. Then in the distributional sense it holds that: :$x \delta' = -\delta$
From Smooth Real Function times Derivative of Dirac Delta Distribution: :$\alpha \cdot \delta' = \map \alpha 0 \delta' - \map {\alpha'} 0 \delta$ where $\alpha$ is a smooth function. If $\map \alpha x = x$, then: :$x \delta' = -\delta$ {{qed}}
Let $\delta \in \map {\DD'} \R$ be the [[Definition:Dirac Delta Distribution|Dirac delta distribution]]. Then in the [[Definition:Schwartz Distribution|distributional sense]] it holds that: :$x \delta' = -\delta$
From [[Smooth Real Function times Derivative of Dirac Delta Distribution]]: :$\alpha \cdot \delta' = \map \alpha 0 \delta' - \map {\alpha'} 0 \delta$ where $\alpha$ is a [[Definition:Smooth Function|smooth function]]. If $\map \alpha x = x$, then: :$x \delta' = -\delta$ {{qed}}
Smooth Real Function times Derivative of Dirac Delta Distribution/Corollary
https://proofwiki.org/wiki/Smooth_Real_Function_times_Derivative_of_Dirac_Delta_Distribution/Corollary
https://proofwiki.org/wiki/Smooth_Real_Function_times_Derivative_of_Dirac_Delta_Distribution/Corollary
[ "Smooth Real Function times Derivative of Dirac Delta Distribution", "Dirac Delta Function" ]
[ "Definition:Dirac Delta Distribution", "Definition:Schwartz Distribution" ]
[ "Smooth Real Function times Derivative of Dirac Delta Distribution", "Definition:Smooth Real Function" ]
proofwiki-18859
Hamiltonian Graph is not necessarily Ore Graph
Let $G = \struct {V, E}$ be a simple graph of order $n \ge 3$. Let $G$ be a Hamiltonian graph. Then $G$ is not necessarily an Ore graph.
Proof by Counterexample: Recall the definition of an Ore graph: :For each pair of non-adjacent vertices $u, v \in V$: ::$\deg u + \deg v \ge n$ Let $n \in \N$ such that $n \ge 5$. Consider the cycle graph $C_n$. We have from Cycle Graph is Hamiltonian that $C_n$ is a Hamiltonian graph. We also have from Cycle Graph is ...
Let $G = \struct {V, E}$ be a [[Definition:Simple Graph|simple graph]] of [[Definition:Order of Graph|order $n \ge 3$]]. Let $G$ be a [[Definition:Hamiltonian Graph|Hamiltonian graph]]. Then $G$ is not necessarily an [[Definition:Ore Graph|Ore graph]].
[[Proof by Counterexample]]: Recall the definition of an [[Definition:Ore Graph|Ore graph]]: :For each pair of [[Definition:Adjacent Vertices (Undirected Graph)|non-adjacent]] [[Definition:Vertex of Graph|vertices]] $u, v \in V$: ::$\deg u + \deg v \ge n$ Let $n \in \N$ such that $n \ge 5$. Consider the [[Definiti...
Hamiltonian Graph is not necessarily Ore Graph
https://proofwiki.org/wiki/Hamiltonian_Graph_is_not_necessarily_Ore_Graph
https://proofwiki.org/wiki/Hamiltonian_Graph_is_not_necessarily_Ore_Graph
[ "Hamiltonian Graphs", "Ore Graphs" ]
[ "Definition:Simple Graph", "Definition:Graph (Graph Theory)/Order", "Definition:Hamiltonian Graph", "Definition:Ore Graph" ]
[ "Proof by Counterexample", "Definition:Ore Graph", "Definition:Adjacent (Graph Theory)/Vertices/Undirected Graph", "Definition:Graph (Graph Theory)/Vertex", "Definition:Cycle Graph", "Cycle Graph is Hamiltonian", "Definition:Hamiltonian Graph", "Cycle Graph is 2-Regular", "Definition:Graph (Graph Th...
proofwiki-18860
Sum of Integrals on Adjacent Intervals for Integrable Functions/Lemma
Let $\closedint a b$ be a closed real interval. Let $c$ be a real number. Let $a < c < b$. Let $f$ be a real function defined on $\closedint a b$. Let $\map L S$ be the lower Darboux sum of $f$ on $\closedint a b$ where $S$ is a subdivision of $\closedint a b$. Let $P$ and $Q$ be finite subdivisions of $\closedint a b$...
This is an instance of Lower Sum of Refinement. {{qed}}
Let $\closedint a b$ be a [[Definition:Closed Real Interval|closed real interval]]. Let $c$ be a [[Definition:Real Number|real number]]. Let $a < c < b$. Let $f$ be a [[Definition:Real Function|real function]] defined on $\closedint a b$. Let $\map L S$ be the [[Definition:Lower Darboux Sum|lower Darboux sum]] of ...
This is an instance of [[Lower Sum of Refinement]]. {{qed}}
Sum of Integrals on Adjacent Intervals for Integrable Functions/Lemma/Proof 1
https://proofwiki.org/wiki/Sum_of_Integrals_on_Adjacent_Intervals_for_Integrable_Functions/Lemma
https://proofwiki.org/wiki/Sum_of_Integrals_on_Adjacent_Intervals_for_Integrable_Functions/Lemma/Proof_1
[ "Sum of Integrals on Adjacent Intervals for Integrable Functions" ]
[ "Definition:Real Interval/Closed", "Definition:Real Number", "Definition:Real Function", "Definition:Lower Darboux Sum", "Definition:Subdivision of Interval", "Definition:Subdivision of Interval/Finite" ]
[ "Lower Sum of Refinement" ]
proofwiki-18861
Sum of Integrals on Adjacent Intervals for Integrable Functions/Lemma
Let $\closedint a b$ be a closed real interval. Let $c$ be a real number. Let $a < c < b$. Let $f$ be a real function defined on $\closedint a b$. Let $\map L S$ be the lower Darboux sum of $f$ on $\closedint a b$ where $S$ is a subdivision of $\closedint a b$. Let $P$ and $Q$ be finite subdivisions of $\closedint a b$...
Let $P = \set {x_0, x_1, \ldots, x_n}$. Suppose that: :$c \in P$ Then: :$Q = P$ We have: :$\map L P \ge \map L P$ :$\leadsto \map L Q \ge \map L P$ as $Q = P$ This finishes the proof for this case. The only other possibility for $c$ is: :$x_{j-1} < c < x_j$ where $1 \le j \le n$. Let $m_i$ be the infimum of $f$ on the ...
Let $\closedint a b$ be a [[Definition:Closed Real Interval|closed real interval]]. Let $c$ be a [[Definition:Real Number|real number]]. Let $a < c < b$. Let $f$ be a [[Definition:Real Function|real function]] defined on $\closedint a b$. Let $\map L S$ be the [[Definition:Lower Darboux Sum|lower Darboux sum]] of ...
Let $P = \set {x_0, x_1, \ldots, x_n}$. Suppose that: :$c \in P$ Then: :$Q = P$ We have: :$\map L P \ge \map L P$ :$\leadsto \map L Q \ge \map L P$ as $Q = P$ This finishes the proof for this case. The only other possibility for $c$ is: :$x_{j-1} < c < x_j$ where $1 \le j \le n$. Let $m_i$ be the [[Definition:...
Sum of Integrals on Adjacent Intervals for Integrable Functions/Lemma/Proof 2
https://proofwiki.org/wiki/Sum_of_Integrals_on_Adjacent_Intervals_for_Integrable_Functions/Lemma
https://proofwiki.org/wiki/Sum_of_Integrals_on_Adjacent_Intervals_for_Integrable_Functions/Lemma/Proof_2
[ "Sum of Integrals on Adjacent Intervals for Integrable Functions" ]
[ "Definition:Real Interval/Closed", "Definition:Real Number", "Definition:Real Function", "Definition:Lower Darboux Sum", "Definition:Subdivision of Interval", "Definition:Subdivision of Interval/Finite" ]
[ "Definition:Infimum of Set/Real Numbers", "Definition:Real Interval/Closed", "Definition:Infimum of Set/Real Numbers", "Definition:Real Interval/Closed", "Definition:Infimum of Set/Real Numbers", "Definition:Real Interval/Closed", "Definition:Real Interval/Closed", "Definition:Subset", "Definition:L...
proofwiki-18862
Intersection of Class and Set is Set
Let $C$ be the class: :$C = \set { u : \map \phi {u, p_1, \ldots, p_n} }$ Then for all sets $X$, $C \cap X$ is a set.
{{NotZFC}} By the definition of class intersection: :$a \in C \cap X \implies a \in C \land a \in X$ Thus: :$a \in C \cap X \implies a \in X$ The subclass definition gives: :$C \cap X \subseteq X$ By Subclass of Set is Set, $C \cap X$ is a set. {{qed}}
Let $C$ be the [[Definition:Class (Class Theory)|class]]: :$C = \set { u : \map \phi {u, p_1, \ldots, p_n} }$ Then for all [[Definition:Set|sets]] $X$, $C \cap X$ is a [[Definition:Set|set]].
{{NotZFC}} By the definition of [[Definition:Class Intersection|class intersection]]: :$a \in C \cap X \implies a \in C \land a \in X$ Thus: :$a \in C \cap X \implies a \in X$ The [[Definition:Subclass|subclass]] definition gives: :$C \cap X \subseteq X$ By [[Subclass of Set is Set]], $C \cap X$ is a [[Definition:...
Intersection of Class and Set is Set
https://proofwiki.org/wiki/Intersection_of_Class_and_Set_is_Set
https://proofwiki.org/wiki/Intersection_of_Class_and_Set_is_Set
[ "Gödel-Bernays Class Theory", "Class Intersection", "Subclasses" ]
[ "Definition:Class (Class Theory)", "Definition:Set", "Definition:Set" ]
[ "Definition:Class Intersection", "Definition:Subclass", "Subclass of Set is Set", "Definition:Set" ]
proofwiki-18863
If Set Exists then Empty Set Exists
If at least one set exists, then there exists an empty set.
{{NotZFC}} Let $S$ be a set. By the axiom of class comprehension, there is an empty class: :$\O = \set { x : x \ne x }$ Since $x \in \O$ is never true, it follows vacuously that: :$x \in \O \implies x \in S$ By the subclass definition: :$\O \subseteq S$ By Subclass of Set is Set, $\O$ is a set. {{qed}}
If at least one [[Definition:Set|set]] exists, then there exists an [[Definition:Empty Set|empty set]].
{{NotZFC}} Let $S$ be a [[Definition:Set|set]]. By the [[Axiom:Class Comprehension Schema|axiom of class comprehension]], there is an [[Definition:Empty Set|empty class]]: :$\O = \set { x : x \ne x }$ Since $x \in \O$ is never true, it follows [[Definition:Vacuous Truth|vacuously]] that: :$x \in \O \implies x \in S$...
If Set Exists then Empty Set Exists
https://proofwiki.org/wiki/If_Set_Exists_then_Empty_Set_Exists
https://proofwiki.org/wiki/If_Set_Exists_then_Empty_Set_Exists
[ "Gödel-Bernays Class Theory", "Empty Set" ]
[ "Definition:Set", "Definition:Empty Set" ]
[ "Definition:Set", "Axiom:Class Comprehension Schema", "Definition:Empty Set", "Definition:Vacuous Truth", "Definition:Subclass", "Subclass of Set is Set", "Definition:Set" ]
proofwiki-18864
Powerset is not Subset of its Set
Let $A$ be a set. Then: :$\powerset A \not \subseteq A$
{{AimForCont}} that $\powerset A \subseteq A$, and define: :$C = \set {x \in \powerset A : x \notin x}$ We have that $C \subseteq \powerset A$, as it contains only the $x \in \powerset A$ meeting the condition $x \notin x$. Since $\powerset A \subseteq A$, we have: :$C \subseteq A$ and thus :$C \in \powerset A$ We can ...
Let $A$ be a [[Definition:Set|set]]. Then: :$\powerset A \not \subseteq A$
{{AimForCont}} that $\powerset A \subseteq A$, and define: :$C = \set {x \in \powerset A : x \notin x}$ We have that $C \subseteq \powerset A$, as it contains only the $x \in \powerset A$ meeting the condition $x \notin x$. Since $\powerset A \subseteq A$, we have: :$C \subseteq A$ and thus :$C \in \powerset A$ We ...
Powerset is not Subset of its Set/Proof 1
https://proofwiki.org/wiki/Powerset_is_not_Subset_of_its_Set
https://proofwiki.org/wiki/Powerset_is_not_Subset_of_its_Set/Proof_1
[ "Powerset is not Subset of its Set", "Power Set", "Subsets" ]
[ "Definition:Set" ]
[ "Definition:Contradiction", "Russell's Paradox" ]
proofwiki-18865
Powerset is not Subset of its Set
Let $A$ be a set. Then: :$\powerset A \not \subseteq A$
{{AimForCont}} that $\powerset A \subseteq A$. Let $I: \powerset A \to A$ be the identity mapping. $I$ is an injection by Identity Mapping is Injection. But by No Injection from Power Set to Set, this is a contradiction. {{qed}}
Let $A$ be a [[Definition:Set|set]]. Then: :$\powerset A \not \subseteq A$
{{AimForCont}} that $\powerset A \subseteq A$. Let $I: \powerset A \to A$ be the [[Definition:Identity Mapping|identity mapping]]. $I$ is an [[Definition:Injection|injection]] by [[Identity Mapping is Injection]]. But by [[No Injection from Power Set to Set]], this is a [[Definition:Contradiction|contradiction]]. {{...
Powerset is not Subset of its Set/Proof 2
https://proofwiki.org/wiki/Powerset_is_not_Subset_of_its_Set
https://proofwiki.org/wiki/Powerset_is_not_Subset_of_its_Set/Proof_2
[ "Powerset is not Subset of its Set", "Power Set", "Subsets" ]
[ "Definition:Set" ]
[ "Definition:Identity Mapping", "Definition:Injection", "Identity Mapping is Injection", "No Injection from Power Set to Set", "Definition:Contradiction" ]
proofwiki-18866
Powerset is not Subset of its Set
Let $A$ be a set. Then: :$\powerset A \not \subseteq A$
{{AimForCont}} that $\powerset A \subseteq A$. Since $A \in \powerset A$, this implies: :$A \in A$ But this contradicts Set is Not Element of Itself. {{qed}}
Let $A$ be a [[Definition:Set|set]]. Then: :$\powerset A \not \subseteq A$
{{AimForCont}} that $\powerset A \subseteq A$. Since $A \in \powerset A$, this implies: :$A \in A$ But this [[Definition:Contradiction|contradicts]] [[Set is Not Element of Itself]]. {{qed}}
Powerset is not Subset of its Set/Proof 3
https://proofwiki.org/wiki/Powerset_is_not_Subset_of_its_Set
https://proofwiki.org/wiki/Powerset_is_not_Subset_of_its_Set/Proof_3
[ "Powerset is not Subset of its Set", "Power Set", "Subsets" ]
[ "Definition:Set" ]
[ "Definition:Contradiction", "Set is Not Element of Itself" ]
proofwiki-18867
Integer which is Multiplied by Last Digit when moving Last Digit to First
Let $N$ be a positive integer expressed in decimal notation in the form: :$N = \sqbrk {a_k a_{k - 1} a_{k - 2} \ldots a_2 a_1}_{10}$ Let $N$ be such that when you multiply it by $a_1$, you get: :$a_1 N = \sqbrk {a_1 a_k a_{k - 1} \ldots a_3 a_2}_{10}$ Then at least one such $N$ is equal to the recurring part of the fra...
Let us consider: :$q = 0 \cdotp \dot a_k a_{k - 1} a_{k - 2} \ldots a_2 \dot a_1$ Let: :$a_1 q = 0 \cdotp \dot a_1 a_k a_{k - 1} \ldots a_3 \dot a_2$ Then: {{begin-eqn}} {{eqn | l = 10 a_1 q | r = a_1 \cdotp \dot a_k a_{k - 1} a_{k - 2} \ldots a_2 \dot a_1 | c = }} {{eqn | ll= \leadsto | l = 10 a_1 q...
Let $N$ be a [[Definition:Positive Integer|positive integer]] expressed in [[Definition:Decimal Notation|decimal notation]] in the form: :$N = \sqbrk {a_k a_{k - 1} a_{k - 2} \ldots a_2 a_1}_{10}$ Let $N$ be such that when you [[Definition:Integer Multiplication|multiply]] it by $a_1$, you get: :$a_1 N = \sqbrk {a_1...
Let us consider: :$q = 0 \cdotp \dot a_k a_{k - 1} a_{k - 2} \ldots a_2 \dot a_1$ Let: :$a_1 q = 0 \cdotp \dot a_1 a_k a_{k - 1} \ldots a_3 \dot a_2$ Then: {{begin-eqn}} {{eqn | l = 10 a_1 q | r = a_1 \cdotp \dot a_k a_{k - 1} a_{k - 2} \ldots a_2 \dot a_1 | c = }} {{eqn | ll= \leadsto | l = 10 a_...
Integer which is Multiplied by Last Digit when moving Last Digit to First
https://proofwiki.org/wiki/Integer_which_is_Multiplied_by_Last_Digit_when_moving_Last_Digit_to_First
https://proofwiki.org/wiki/Integer_which_is_Multiplied_by_Last_Digit_when_moving_Last_Digit_to_First
[ "Recreational Mathematics" ]
[ "Definition:Positive/Integer", "Definition:Decimal Notation", "Definition:Multiplication/Integers", "Definition:Basis Expansion/Recurrence/Recurring Part", "Definition:Fraction" ]
[ "Category:Recreational Mathematics" ]
proofwiki-18868
Weak Solution to Dx u + 3yu = 0 with Heaviside Step Function Boundary Condition
Consider the boundary value problem: :<nowiki>$\begin{cases} \dfrac {\partial u} {\partial x} + 3 y u = 0 & : x \in \R_{>0},~ y \in \R \\ & \\ \map u {0, y} = \map H y & : y \in \R \\ \end{cases}$</nowiki> Then it has a weak solution of the form: :$u = e^{-3 y x} \map H y$
Let $u = e^{-3 y x} \map H y$ We have that: :Heaviside Step Function is Locally Integrable :Locally Integrable Function defines Distribution :Multiplication of Distribution induced by Locally Integrable Function by Smooth Function Hence, we can define a distribution $T_u \in \map {\DD'} {\R^2}$ associated with $u$. The...
Consider the [[Definition:Boundary Value Problem|boundary value problem]]: :<nowiki>$\begin{cases} \dfrac {\partial u} {\partial x} + 3 y u = 0 & : x \in \R_{>0},~ y \in \R \\ & \\ \map u {0, y} = \map H y & : y \in \R \\ \end{cases}$</nowiki> Then it has a [[Definition:Weak Solution|weak solution]] of the form: :$...
Let $u = e^{-3 y x} \map H y$ We have that: :[[Heaviside Step Function is Locally Integrable]] :[[Locally Integrable Function defines Distribution]] :[[Multiplication of Distribution induced by Locally Integrable Function by Smooth Function]] Hence, we can define a [[Definition:Schwartz Distribution|distribution]] $...
Weak Solution to Dx u + 3yu = 0 with Heaviside Step Function Boundary Condition
https://proofwiki.org/wiki/Weak_Solution_to_Dx_u_+_3yu_=_0_with_Heaviside_Step_Function_Boundary_Condition
https://proofwiki.org/wiki/Weak_Solution_to_Dx_u_+_3yu_=_0_with_Heaviside_Step_Function_Boundary_Condition
[ "Examples of Weak Solutions" ]
[ "Definition:Boundary Value Problem", "Definition:Differential Equation/Solution/Weak Solution" ]
[ "Heaviside Step Function is Locally Integrable", "Locally Integrable Function defines Distribution", "Multiplication of Distribution induced by Locally Integrable Function by Smooth Function", "Definition:Schwartz Distribution", "Definition:Schwartz Distribution", "Multiplication of Distribution induced b...
proofwiki-18869
Divisors of One More than Power of 10/Number of Zero Digits Congruent to 2 Modulo 3
Let $N$ be a natural number of the form: :$N = 1000 \ldots 01$ where the number of zero digits between the two $1$ digits is of the form $3 k - 1$. Then $N$ has divisors: ::$1 \underbrace {00 \ldots 0}_{\text {$k - 1$ $0$'s} } 1$ :where the number of zero digits between the two $1$ digits is $k - 1$ ::$\underbrace {99 ...
By definition, $N$ can be expressed as: :$N = 10^{3 k} + 1$ Let $a := 10^k$. Then we have: {{begin-eqn}} {{eqn | l = N | r = a^3 + 1 | c = }} {{eqn | r = \paren {a + 1} \paren {a^2 - a + 1} | c = Sum of Two Cubes }} {{end-eqn}} where it is noted that: {{begin-eqn}} {{eqn | l = \underbrace {99 \ldots ...
Let $N$ be a [[Definition:Natural Number|natural number]] of the form: :$N = 1000 \ldots 01$ where the number of [[Definition:Zero Digit|zero digits]] between the two $1$ [[Definition:Digit|digits]] is of the form $3 k - 1$. Then $N$ has [[Definition:Divisor of Integer|divisors]]: ::$1 \underbrace {00 \ldots 0}_{\text...
By definition, $N$ can be expressed as: :$N = 10^{3 k} + 1$ Let $a := 10^k$. Then we have: {{begin-eqn}} {{eqn | l = N | r = a^3 + 1 | c = }} {{eqn | r = \paren {a + 1} \paren {a^2 - a + 1} | c = [[Sum of Two Cubes]] }} {{end-eqn}} where it is noted that: {{begin-eqn}} {{eqn | l = \underbrace {99 ...
Divisors of One More than Power of 10/Number of Zero Digits Congruent to 2 Modulo 3
https://proofwiki.org/wiki/Divisors_of_One_More_than_Power_of_10/Number_of_Zero_Digits_Congruent_to_2_Modulo_3
https://proofwiki.org/wiki/Divisors_of_One_More_than_Power_of_10/Number_of_Zero_Digits_Congruent_to_2_Modulo_3
[ "Divisors of One More than Power of 10" ]
[ "Definition:Natural Numbers", "Definition:Zero Digit", "Definition:Digit", "Definition:Divisor (Algebra)/Integer", "Definition:Zero Digit", "Definition:Digit" ]
[ "Sum of Two Odd Powers/Examples/Sum of Two Cubes" ]
proofwiki-18870
Divisors of One More than Power of 10/Number of Zero Digits Even
Let $N$ be a natural number of the form: :$N = 1 \underbrace {000 \ldots 0}_{\text {$2 k$ $0$'s} } 1$ that is, where the number of zero digits between the two $1$ digits is even. Then $N$ can be expressed as: :$N = 11 \times \underbrace {9090 \ldots 90}_{\text {$k - 1$ $90$'s} } 91$
By definition, $N$ can be expressed as: :$N = 10^{2 k + 1} + 1$ Then we have: {{begin-eqn}} {{eqn | l = N | r = 10^{2 k + 1} + 1 | c = }} {{eqn | r = \paren {10 + 1} \sum_{j \mathop = 0}^{2 k} \paren {-1}^j 10^{2 k - j} | c = Sum of Two Odd Powers }} {{eqn | ll= \leadsto | l = \dfrac N {11} ...
Let $N$ be a [[Definition:Natural Number|natural number]] of the form: :$N = 1 \underbrace {000 \ldots 0}_{\text {$2 k$ $0$'s} } 1$ that is, where the number of [[Definition:Zero Digit|zero digits]] between the two $1$ [[Definition:Digit|digits]] is [[Definition:Even Integer|even]]. Then $N$ can be expressed as: :$N ...
By definition, $N$ can be expressed as: :$N = 10^{2 k + 1} + 1$ Then we have: {{begin-eqn}} {{eqn | l = N | r = 10^{2 k + 1} + 1 | c = }} {{eqn | r = \paren {10 + 1} \sum_{j \mathop = 0}^{2 k} \paren {-1}^j 10^{2 k - j} | c = [[Sum of Two Odd Powers]] }} {{eqn | ll= \leadsto | l = \dfrac N {1...
Divisors of One More than Power of 10/Number of Zero Digits Even
https://proofwiki.org/wiki/Divisors_of_One_More_than_Power_of_10/Number_of_Zero_Digits_Even
https://proofwiki.org/wiki/Divisors_of_One_More_than_Power_of_10/Number_of_Zero_Digits_Even
[ "Divisors of One More than Power of 10" ]
[ "Definition:Natural Numbers", "Definition:Zero Digit", "Definition:Digit", "Definition:Even Integer" ]
[ "Sum of Two Odd Powers" ]
proofwiki-18871
Measurable Set with Negative Measure has Negative Subset
Let $\struct {X, \Sigma}$ be a measurable space. Let $\mu$ be a signed measure on $\struct {X, \Sigma}$. Let $A \in \Sigma$ have: :$-\infty < \map \mu A < 0$ Then: :there exists a $\mu$-negative set $B$ such that $B \subseteq A$ and $\map \mu B \le \map \mu A$.
Let: :$\delta_1 = \sup \set {\map \mu E : E \in \Sigma \text { and } E \subseteq A}$ possibly infinite. Since $\O \in \Sigma$ and $\O \subseteq A$, we have: :$\map \mu \O = 0 \in \set {\map \mu E : E \in \Sigma \text { and } E \subseteq A}$ and so, from the definition of supremum, we have: :$\delta_1 \ge 0$. Again ...
Let $\struct {X, \Sigma}$ be a [[Definition:Measurable Space|measurable space]]. Let $\mu$ be a [[Definition:Signed Measure|signed measure]] on $\struct {X, \Sigma}$. Let $A \in \Sigma$ have: :$-\infty < \map \mu A < 0$ Then: :there exists a [[Definition:Negative Set|$\mu$-negative set]] $B$ such that $B \subse...
Let: :$\delta_1 = \sup \set {\map \mu E : E \in \Sigma \text { and } E \subseteq A}$ possibly [[Definition:Infinite Set|infinite]]. Since $\O \in \Sigma$ and $\O \subseteq A$, we have: :$\map \mu \O = 0 \in \set {\map \mu E : E \in \Sigma \text { and } E \subseteq A}$ and so, from the definition of [[Definition...
Measurable Set with Negative Measure has Negative Subset
https://proofwiki.org/wiki/Measurable_Set_with_Negative_Measure_has_Negative_Subset
https://proofwiki.org/wiki/Measurable_Set_with_Negative_Measure_has_Negative_Subset
[ "Signed Measures", "Negative Sets" ]
[ "Definition:Measurable Space", "Definition:Signed Measure", "Definition:Negative Set" ]
[ "Definition:Infinite Set", "Definition:Supremum of Set/Real Numbers", "Definition:Supremum of Set/Real Numbers", "Definition:Supremum of Set/Real Numbers", "Definition:Disjoint Sets", "Definition:Disjoint Sets", "Definition:Signed Measure", "Definition:Countably Additive Function", "Definition:Count...
proofwiki-18872
Complement of Horizontal Section of Set is Horizontal Section of Complement
Let $X$ and $Y$ be sets. Let $E \subseteq X \times Y$. Let $y \in Y$. Then: :$\paren {\paren {X \times Y} \setminus E}^y = X \setminus E^y$ where: :$\paren {\paren {X \times Y} \setminus E}^y$ is the $y$-horizontal section of the set difference $\paren {X \times Y} \setminus E$ :$E^y$ is the $y$-horizontal section o...
Note that from the definition of set difference, we have that: :$x \in X \setminus E^y$ {{iff}}: :$x \in X$ and $x \not \in E^y$. That is, from the definition of the $y$-horizontal section: :$x \in X$ and $\tuple {x, y} \not \in E$. This is equivalent to: :$\tuple {x, y} \in \paren {X \times Y} \setminus E$ From th...
Let $X$ and $Y$ be [[Definition:Set|sets]]. Let $E \subseteq X \times Y$. Let $y \in Y$. Then: :$\paren {\paren {X \times Y} \setminus E}^y = X \setminus E^y$ where: :$\paren {\paren {X \times Y} \setminus E}^y$ is the [[Definition:Horizontal Section of Set|$y$-horizontal section]] of the [[Definition:Set Dif...
Note that from the definition of [[Definition:Set Difference|set difference]], we have that: :$x \in X \setminus E^y$ {{iff}}: :$x \in X$ and $x \not \in E^y$. That is, from the definition of the [[Definition:Horizontal Section of Set|$y$-horizontal section]]: :$x \in X$ and $\tuple {x, y} \not \in E$. This is...
Complement of Horizontal Section of Set is Horizontal Section of Complement
https://proofwiki.org/wiki/Complement_of_Horizontal_Section_of_Set_is_Horizontal_Section_of_Complement
https://proofwiki.org/wiki/Complement_of_Horizontal_Section_of_Set_is_Horizontal_Section_of_Complement
[ "Horizontal Section of Sets" ]
[ "Definition:Set", "Definition:Horizontal Section of Set", "Definition:Set Difference", "Definition:Horizontal Section of Set" ]
[ "Definition:Set Difference", "Definition:Horizontal Section of Set", "Definition:Horizontal Section of Set", "Category:Horizontal Section of Sets" ]
proofwiki-18873
Complement of Vertical Section of Set is Vertical Section of Complement
Let $X$ and $Y$ be sets. Let $E \subseteq X \times Y$. Let $x \in X$. Then: :$\paren {\paren {X \times Y} \setminus E}_x = Y \setminus E_x$ where: :$\paren {\paren {X \times Y} \setminus E}_x$ is the $x$-vertical section of the set difference $\paren {X \times Y} \setminus E$ :$E_x$ is the $x$-vertical section of $E...
Note that from the definition of set difference, we have that: :$y \in Y \setminus E_x$ {{iff}}: :$y \in Y$ and $y \not \in E_x$. That is, from the definition of the $x$-vertical section: :$y \in Y$ and $\tuple {x, y} \not \in E$. This is equivalent to: :$\tuple {x, y} \in \paren {X \times Y} \setminus E$ From the ...
Let $X$ and $Y$ be [[Definition:Set|sets]]. Let $E \subseteq X \times Y$. Let $x \in X$. Then: :$\paren {\paren {X \times Y} \setminus E}_x = Y \setminus E_x$ where: :$\paren {\paren {X \times Y} \setminus E}_x$ is the [[Definition:Vertical Section of Set|$x$-vertical section]] of the [[Definition:Set Differe...
Note that from the definition of [[Definition:Set Difference|set difference]], we have that: :$y \in Y \setminus E_x$ {{iff}}: :$y \in Y$ and $y \not \in E_x$. That is, from the definition of the [[Definition:Vertical Section of Set|$x$-vertical section]]: :$y \in Y$ and $\tuple {x, y} \not \in E$. This is equ...
Complement of Vertical Section of Set is Vertical Section of Complement
https://proofwiki.org/wiki/Complement_of_Vertical_Section_of_Set_is_Vertical_Section_of_Complement
https://proofwiki.org/wiki/Complement_of_Vertical_Section_of_Set_is_Vertical_Section_of_Complement
[ "Vertical Section of Sets" ]
[ "Definition:Set", "Definition:Vertical Section of Set", "Definition:Set Difference", "Definition:Vertical Section of Set" ]
[ "Definition:Set Difference", "Definition:Vertical Section of Set", "Definition:Vertical Section of Set", "Category:Vertical Section of Sets" ]
proofwiki-18874
Union of Horizontal Sections is Horizontal Section of Union
Let $X$, $Y$ and $A$ be sets. Let $\set {E_\alpha : \alpha \in A}$ be a set of subsets of $X \times Y$. Let $y \in Y$. Then: :$\ds \paren {\bigcup_{\alpha \mathop \in A} E_\alpha}^y = \bigcup_{\alpha \mathop \in A} \paren {E_\alpha}^y$ where: :$\ds \paren {\bigcup_{\alpha \mathop \in A} E_\alpha}^y$ is the $y$-horiz...
Note that: :$\ds x \in \bigcup_{\alpha \mathop \in A} \paren {E_\alpha}^y$ {{iff}}: :$x \in \paren {E_\alpha}^y$ for some $\alpha \in A$. From the definition of the $y$-horizontal section, this is equivalent to: :$\tuple {x, y} \in E_\alpha$ for some $\alpha \in A$. This in turn is equivalent to: :$\ds \tuple {x, y}...
Let $X$, $Y$ and $A$ be [[Definition:Set|sets]]. Let $\set {E_\alpha : \alpha \in A}$ be a [[Definition:Set|set]] of subsets of $X \times Y$. Let $y \in Y$. Then: :$\ds \paren {\bigcup_{\alpha \mathop \in A} E_\alpha}^y = \bigcup_{\alpha \mathop \in A} \paren {E_\alpha}^y$ where: :$\ds \paren {\bigcup_{\alpha ...
Note that: :$\ds x \in \bigcup_{\alpha \mathop \in A} \paren {E_\alpha}^y$ {{iff}}: :$x \in \paren {E_\alpha}^y$ for some $\alpha \in A$. From the definition of the [[Definition:Horizontal Section of Set|$y$-horizontal section]], this is equivalent to: :$\tuple {x, y} \in E_\alpha$ for some $\alpha \in A$. This...
Union of Horizontal Sections is Horizontal Section of Union
https://proofwiki.org/wiki/Union_of_Horizontal_Sections_is_Horizontal_Section_of_Union
https://proofwiki.org/wiki/Union_of_Horizontal_Sections_is_Horizontal_Section_of_Union
[ "Set Union", "Horizontal Section of Sets" ]
[ "Definition:Set", "Definition:Set", "Definition:Horizontal Section of Set", "Definition:Horizontal Section of Set" ]
[ "Definition:Horizontal Section of Set", "Definition:Horizontal Section of Set", "Category:Set Union", "Category:Horizontal Section of Sets" ]
proofwiki-18875
Horizontal Section of Cartesian Product
Let $X$ and $Y$ be sets. Let $A \subseteq X$ and $B \subseteq Y$, so that $A \times B \subseteq X \times Y$. Let $y \in Y$. Then: :$\paren {A \times B}^y = \begin{cases}A & y \in B \\ \O & y \not \in B\end{cases}$ where $\paren {A \times B}^y$ is a horizontal section of $A \times B$.
Let $y \in B$. From the definition of the horizontal section, we have: :$x \in \paren {A \times B}^y$ {{iff}}: :$\tuple {x, y} \in A \times B$ Since $y \in B$, this equivalent to: :$x \in A$ So: :$x \in \paren {A \times B}^y$ {{iff}} $x \in A$ giving: :$\paren {A \times B}^y = A$ if $y \in B$. Now let $y \in Y \set...
Let $X$ and $Y$ be [[Definition:Set|sets]]. Let $A \subseteq X$ and $B \subseteq Y$, so that $A \times B \subseteq X \times Y$. Let $y \in Y$. Then: :$\paren {A \times B}^y = \begin{cases}A & y \in B \\ \O & y \not \in B\end{cases}$ where $\paren {A \times B}^y$ is a [[Definition:Horizontal Section of Set|hori...
Let $y \in B$. From the definition of the [[Definition:Horizontal Section of Set|horizontal section]], we have: :$x \in \paren {A \times B}^y$ {{iff}}: :$\tuple {x, y} \in A \times B$ Since $y \in B$, this equivalent to: :$x \in A$ So: :$x \in \paren {A \times B}^y$ {{iff}} $x \in A$ giving: :$\paren {A \...
Horizontal Section of Cartesian Product
https://proofwiki.org/wiki/Horizontal_Section_of_Cartesian_Product
https://proofwiki.org/wiki/Horizontal_Section_of_Cartesian_Product
[ "Horizontal Section of Sets", "Cartesian Product" ]
[ "Definition:Set", "Definition:Horizontal Section of Set" ]
[ "Definition:Horizontal Section of Set", "Definition:Set Difference", "Category:Horizontal Section of Sets", "Category:Cartesian Product" ]
proofwiki-18876
Horizontal Section of Measurable Set is Measurable
Let $\struct {X, \Sigma_X}$ and $\struct {Y, \Sigma_Y}$ be measurable spaces. Let $E \in \Sigma_X \otimes \Sigma_Y$ where $\Sigma_X \otimes \Sigma_Y$ is the product $\sigma$-algebra of $\Sigma_X$ and $\Sigma_Y$. Let $y \in Y$. Then: :$E^y \in \Sigma_X$ where $E^y$ is the $y$-horizontal section of $E$.
Define $f_y : X \to X \times Y$ by: :$\map {f_y} x = \tuple {x, y}$ for each $x \in X$. Note that we have $\tuple {x, y} \in E$ {{iff}} $x \in E^y$ from the definition of the horizontal section. In other words: :$\paren {f_y}^{-1} \sqbrk E = E^y$ We now show that $f_y$ is $\Sigma_X/\paren {\Sigma_X \otimes \Sigma_Y}...
Let $\struct {X, \Sigma_X}$ and $\struct {Y, \Sigma_Y}$ be [[Definition:Measurable Space|measurable spaces]]. Let $E \in \Sigma_X \otimes \Sigma_Y$ where $\Sigma_X \otimes \Sigma_Y$ is the [[Definition:Product Sigma-Algebra|product $\sigma$-algebra]] of $\Sigma_X$ and $\Sigma_Y$. Let $y \in Y$. Then: :$E^y \in ...
Define $f_y : X \to X \times Y$ by: :$\map {f_y} x = \tuple {x, y}$ for each $x \in X$. Note that we have $\tuple {x, y} \in E$ {{iff}} $x \in E^y$ from the definition of the [[Definition:Horizontal Section of Set|horizontal section]]. In other words: :$\paren {f_y}^{-1} \sqbrk E = E^y$ We now show that $f_y$ ...
Horizontal Section of Measurable Set is Measurable/Proof 2
https://proofwiki.org/wiki/Horizontal_Section_of_Measurable_Set_is_Measurable
https://proofwiki.org/wiki/Horizontal_Section_of_Measurable_Set_is_Measurable/Proof_2
[ "Horizontal Section of Sets", "Horizontal Section of Measurable Set is Measurable" ]
[ "Definition:Measurable Space", "Definition:Product Sigma-Algebra", "Definition:Horizontal Section of Set" ]
[ "Definition:Horizontal Section of Set", "Definition:Measurable Mapping", "Mapping Measurable iff Measurable on Generator", "Definition:Product Sigma-Algebra", "Definition:Generated Sigma-Algebra", "Horizontal Section of Cartesian Product", "Definition:Sigma-Algebra", "Mapping Measurable iff Measurable...
proofwiki-18877
Union of Vertical Sections is Vertical Section of Union
Let $X$ and $Y$ be sets. Let $\set {E_\alpha : \alpha \in A}$ be a set of subsets of $X \times Y$. Let $x \in X$. Then: :$\ds \paren {\bigcup_{\alpha \in A} E_\alpha}_x = \bigcup_{\alpha \in A} \paren {E_\alpha}_x$ where: :$\ds \paren {\bigcup_{\alpha \in A} E_\alpha}_x$ is the $x$-vertical section of $\ds \bigcup_{...
Note that: :$\ds y \in \bigcup_{\alpha \in A} \paren {E_\alpha}_x$ {{iff}}: :$y \in \paren {E_\alpha}_x$ for some $\alpha \in A$. From the definition of the $x$-vertical section, this is equivalent to: :$\tuple {x, y} \in E_\alpha$ for some $\alpha \in A$. This in turn is equivalent to: :$\ds \tuple {x, y} \in \bigc...
Let $X$ and $Y$ be [[Definition:Set|sets]]. Let $\set {E_\alpha : \alpha \in A}$ be a [[Definition:Set|set]] of subsets of $X \times Y$. Let $x \in X$. Then: :$\ds \paren {\bigcup_{\alpha \in A} E_\alpha}_x = \bigcup_{\alpha \in A} \paren {E_\alpha}_x$ where: :$\ds \paren {\bigcup_{\alpha \in A} E_\alpha}_x$ i...
Note that: :$\ds y \in \bigcup_{\alpha \in A} \paren {E_\alpha}_x$ {{iff}}: :$y \in \paren {E_\alpha}_x$ for some $\alpha \in A$. From the definition of the [[Definition:Vertical Section of Set|$x$-vertical section]], this is equivalent to: :$\tuple {x, y} \in E_\alpha$ for some $\alpha \in A$. This in turn is ...
Union of Vertical Sections is Vertical Section of Union
https://proofwiki.org/wiki/Union_of_Vertical_Sections_is_Vertical_Section_of_Union
https://proofwiki.org/wiki/Union_of_Vertical_Sections_is_Vertical_Section_of_Union
[ "Set Union", "Vertical Section of Sets" ]
[ "Definition:Set", "Definition:Set", "Definition:Vertical Section of Set", "Definition:Vertical Section of Set" ]
[ "Definition:Vertical Section of Set", "Definition:Vertical Section of Set", "Category:Set Union", "Category:Vertical Section of Sets" ]
proofwiki-18878
Tempered Distribution Space is Proper Subset of Distribution Space
Let $\map {\DD'} \R$ be the distribution space. Let $\map {\SS'} \R$ be the tempered distribution space. Then $\map {\SS'} \R$ is a proper subset of $\map {\DD'} \R$: :$\map {\SS'} \R \subsetneqq \map {\DD'} \R$
By Convergence of Sequence of Test Functions in Test Function Space implies Convergence in Schwartz Space we have that $\map {\SS'} \R \subseteq \map {\DD'} \R$. {{Research|how?}} Consider the real function $\map f x = e^{x^2}$. We have that: :Real Power Function for Positive Integer Power is Continuous :Exponential Fu...
Let $\map {\DD'} \R$ be the [[Definition:Distribution Space|distribution space]]. Let $\map {\SS'} \R$ be the [[Definition:Tempered Distribution Space|tempered distribution space]]. Then $\map {\SS'} \R$ is a [[Definition:Proper Subset|proper subset]] of $\map {\DD'} \R$: :$\map {\SS'} \R \subsetneqq \map {\DD'} \R...
By [[Convergence of Sequence of Test Functions in Test Function Space implies Convergence in Schwartz Space]] we have that $\map {\SS'} \R \subseteq \map {\DD'} \R$. {{Research|how?}} Consider the [[Definition:Real Function|real function]] $\map f x = e^{x^2}$. We have that: :[[Real Power Function for Positive Integ...
Tempered Distribution Space is Proper Subset of Distribution Space
https://proofwiki.org/wiki/Tempered_Distribution_Space_is_Proper_Subset_of_Distribution_Space
https://proofwiki.org/wiki/Tempered_Distribution_Space_is_Proper_Subset_of_Distribution_Space
[ "Tempered Distributions" ]
[ "Definition:Distribution Space", "Definition:Tempered Distribution Space", "Definition:Proper Subset" ]
[ "Convergence of Sequence of Test Functions in Test Function Space implies Convergence in Schwartz Space", "Definition:Real Function", "Real Power Function for Positive Integer Power is Continuous", "Exponential Function is Continuous/Real Numbers", "Composite of Continuous Mappings is Continuous", "Defini...
proofwiki-18879
Measure of Vertical Section of Measurable Set gives Measurable Function
Let $\struct {X, \Sigma_X, \mu}$ and $\struct {Y, \Sigma_Y, \nu}$ be $\sigma$-finite measure spaces. For each $E \in \Sigma_X \otimes \Sigma_Y$, define the function $f_E : X \to \overline \R$ by: :$\map {f_E} x = \map {\nu} {E_x}$ for each $x \in X$ where: :$\Sigma_X \otimes \Sigma_Y$ is the product $\sigma$-algebra ...
From Vertical Section of Measurable Set is Measurable, the function $f_E$ is certainly well-defined for each $E \in \Sigma_X \otimes \Sigma_Y$. First suppose that $\nu$ is a finite measure. Let: :$\mathcal F = \set {E \in \Sigma_X \otimes \Sigma_Y : f_E \text { is } \Sigma_X\text{-measurable} }$ We aim to show that: ...
Let $\struct {X, \Sigma_X, \mu}$ and $\struct {Y, \Sigma_Y, \nu}$ be [[Definition:Sigma-Finite Measure Space|$\sigma$-finite]] [[Definition:Measure Space|measure spaces]]. For each $E \in \Sigma_X \otimes \Sigma_Y$, define the [[Definition:Extended Real-Valued Function|function]] $f_E : X \to \overline \R$ by: :$\ma...
From [[Vertical Section of Measurable Set is Measurable]], the [[Definition:Extended Real-Valued Function|function]] $f_E$ is certainly well-defined for each $E \in \Sigma_X \otimes \Sigma_Y$. First suppose that $\nu$ is a [[Definition:Finite Measure|finite measure]]. Let: :$\mathcal F = \set {E \in \Sigma_X \oti...
Measure of Vertical Section of Measurable Set gives Measurable Function
https://proofwiki.org/wiki/Measure_of_Vertical_Section_of_Measurable_Set_gives_Measurable_Function
https://proofwiki.org/wiki/Measure_of_Vertical_Section_of_Measurable_Set_gives_Measurable_Function
[ "Vertical Section of Sets" ]
[ "Definition:Sigma-Finite Measure Space", "Definition:Measure Space", "Definition:Extended Real-Valued Function", "Definition:Product Sigma-Algebra", "Definition:Vertical Section of Set", "Definition:Measurable Function" ]
[ "Vertical Section of Measurable Set is Measurable", "Definition:Extended Real-Valued Function", "Definition:Finite Measure", "Definition:Measurable Function", "Measure of Vertical Section of Cartesian Product", "Definition:Measurable Set", "Definition:Measurable Function", "Pointwise Scalar Multiple o...
proofwiki-18880
Hahn Decomposition Theorem
Let $\struct {X, \Sigma}$ be a measurable space. Let $\mu$ be a signed measure on $\struct {X, \Sigma}$. Then there exists disjoint sets $P$ and $N$ such that: :$(1): \quad$ $P$ is a $\mu$-positive set and $N$ is a $\mu$-negative set :$(2): \quad$ $X = P \cup N$ :$(3): \quad$ for any other $\mu$-positive set $P'$ and ...
Note that $\mu$ can attain at most one of $+\infty$ and $-\infty$. Suppose first that $\mu$ does not attain the value $-\infty$. Set: :$s_1 = \inf \set {\map \mu D : D \in \Sigma \text { and } D \subseteq X}$ Since $\O \subseteq X$ and $\map \mu \O = 0$ we have: :$0 \in \set {\map \mu D : D \in \Sigma \text { and } D ...
Let $\struct {X, \Sigma}$ be a [[Definition:Measurable Space|measurable space]]. Let $\mu$ be a [[Definition:Signed Measure|signed measure]] on $\struct {X, \Sigma}$. Then there exists [[Definition:Disjoint Sets|disjoint sets]] $P$ and $N$ such that: :$(1): \quad$ $P$ is a [[Definition:Positive Set|$\mu$-positive ...
Note that $\mu$ can attain at most one of $+\infty$ and $-\infty$. Suppose first that $\mu$ does not attain the value $-\infty$. Set: :$s_1 = \inf \set {\map \mu D : D \in \Sigma \text { and } D \subseteq X}$ Since $\O \subseteq X$ and $\map \mu \O = 0$ we have: :$0 \in \set {\map \mu D : D \in \Sigma \text { an...
Hahn Decomposition Theorem
https://proofwiki.org/wiki/Hahn_Decomposition_Theorem
https://proofwiki.org/wiki/Hahn_Decomposition_Theorem
[ "Signed Measures" ]
[ "Definition:Measurable Space", "Definition:Signed Measure", "Definition:Disjoint Sets", "Definition:Positive Set", "Definition:Negative Set", "Definition:Positive Set", "Definition:Negative Set", "Definition:Symmetric Difference", "Definition:Null Set" ]
[ "Definition:Infimum of Set/Real Numbers", "Definition:Infimum of Set/Real Numbers", "Measurable Set with Negative Measure has Negative Subset", "Definition:Negative Set", "Definition:Pairwise Disjoint", "Definition:Infimum of Set/Real Numbers", "Definition:Infimum of Set/Real Numbers", "Definition:Mea...
proofwiki-18881
Jordan Decomposition Theorem
Let $\struct {X, \Sigma}$ be a measurable space. Let $\mu$ be a signed measure on $\struct {X, \Sigma}$. Let $\tuple {P, N}$ be a Hahn decomposition of $\mu$. Then there exists measures $\mu^+$ and $\mu^-$ on $\struct {X, \Sigma}$ such that: :$\mu = \mu^+ - \mu^-$ Further, at least one of $\mu^+$ and $\mu^-$ is finit...
From the definition of a Hahn decomposition, the set $P$ is $\mu$-positive, the set $N$ is $\mu$-negative and: :$X = P \cup N$ with $P$ and $N$ disjoint. From Sigma-Algebra Closed under Countable Intersection, we have: :$A \cap P \in \Sigma$ and: :$A \cap N \in \Sigma$ for each $A \in \Sigma$. Now, for each $A \in \...
Let $\struct {X, \Sigma}$ be a [[Definition:Measurable Space|measurable space]]. Let $\mu$ be a [[Definition:Signed Measure|signed measure]] on $\struct {X, \Sigma}$. Let $\tuple {P, N}$ be a [[Definition:Hahn Decomposition|Hahn decomposition]] of $\mu$. Then there exists [[Definition:Measure (Measure Theory)|meas...
From the definition of a [[Definition:Hahn Decomposition|Hahn decomposition]], the set $P$ is [[Definition:Positive Set|$\mu$-positive]], the set $N$ is [[Definition:Negative Set|$\mu$-negative]] and: :$X = P \cup N$ with $P$ and $N$ [[Definition:Disjoint Sets|disjoint]]. From [[Sigma-Algebra Closed under Countabl...
Jordan Decomposition Theorem
https://proofwiki.org/wiki/Jordan_Decomposition_Theorem
https://proofwiki.org/wiki/Jordan_Decomposition_Theorem
[ "Jordan Decomposition Theorem", "Signed Measures" ]
[ "Definition:Measurable Space", "Definition:Signed Measure", "Definition:Hahn Decomposition", "Definition:Measure (Measure Theory)", "Definition:Finite Measure" ]
[ "Definition:Hahn Decomposition", "Definition:Positive Set", "Definition:Negative Set", "Definition:Disjoint Sets", "Sigma-Algebra Closed under Countable Intersection", "Definition:Measure (Measure Theory)", "Definition:Signed Measure", "Definition:Measure (Measure Theory)", "Definition:Positive Set"...
proofwiki-18882
Intersection of Positive Set and Negative Set is Null Set
Let $\struct {X, \Sigma}$ be a measurable space. Let $\mu$ be a signed measure on $\struct {X, \Sigma}$. Let $P$ be a $\mu$-positive set. Let $N$ be a $\mu$-negative set. Then: :$P \cap N$ is a $\mu$-null set.
Note that, from Sigma-Algebra Closed under Countable Intersection: :$P \cap N \in \Sigma$ We aim to show that: :for each $E \in \Sigma$ with $E \subseteq P \cap N$ we have $\map \mu E = 0$. Note first that from Intersection is Subset, we have: :$P \cap N \subseteq P$ so that: :$E \subseteq P$ So, since $P$ is $\mu$-p...
Let $\struct {X, \Sigma}$ be a [[Definition:Measurable Space|measurable space]]. Let $\mu$ be a [[Definition:Signed Measure|signed measure]] on $\struct {X, \Sigma}$. Let $P$ be a [[Definition:Positive Set|$\mu$-positive set]]. Let $N$ be a [[Definition:Negative Set|$\mu$-negative set]]. Then: :$P \cap N$ is a...
Note that, from [[Sigma-Algebra Closed under Countable Intersection]]: :$P \cap N \in \Sigma$ We aim to show that: :for each $E \in \Sigma$ with $E \subseteq P \cap N$ we have $\map \mu E = 0$. Note first that from [[Intersection is Subset]], we have: :$P \cap N \subseteq P$ so that: :$E \subseteq P$ So, sinc...
Intersection of Positive Set and Negative Set is Null Set
https://proofwiki.org/wiki/Intersection_of_Positive_Set_and_Negative_Set_is_Null_Set
https://proofwiki.org/wiki/Intersection_of_Positive_Set_and_Negative_Set_is_Null_Set
[ "Positive Sets", "Negative Sets" ]
[ "Definition:Measurable Space", "Definition:Signed Measure", "Definition:Positive Set", "Definition:Negative Set", "Definition:Null Set/Signed Measure" ]
[ "Sigma-Algebra Closed under Countable Intersection", "Intersection is Subset", "Definition:Positive Set", "Intersection is Subset", "Definition:Negative Set", "Definition:Null Set/Signed Measure", "Category:Positive Sets", "Category:Negative Sets" ]
proofwiki-18883
Non-Negative Signed Measure is Measure
Let $\struct {X, \Sigma}$ be a measurable space. Let $\mu$ be a signed measure on $\struct {X, \Sigma}$ such that: :$\map \mu A \ge 0$ for each $A \in \Sigma$. Then $\mu$ is a measure on $\struct {X, \Sigma}$.
We verify each of the conditions given in the definition of a measure. From the definition of a signed measure, $\mu$ is a function $\Sigma \to \overline \R$.
Let $\struct {X, \Sigma}$ be a [[Definition:Measurable Space|measurable space]]. Let $\mu$ be a [[Definition:Signed Measure|signed measure]] on $\struct {X, \Sigma}$ such that: :$\map \mu A \ge 0$ for each $A \in \Sigma$. Then $\mu$ is a [[Definition:Measure (Measure Theory)|measure]] on $\struct {X, \Sigma}$.
We verify each of the conditions given in the definition of a [[Definition:Measure (Measure Theory)|measure]]. From the definition of a [[Definition:Signed Measure|signed measure]], $\mu$ is a [[Definition:Extended Real-Valued Function|function]] $\Sigma \to \overline \R$.
Non-Negative Signed Measure is Measure
https://proofwiki.org/wiki/Non-Negative_Signed_Measure_is_Measure
https://proofwiki.org/wiki/Non-Negative_Signed_Measure_is_Measure
[ "Signed Measures" ]
[ "Definition:Measurable Space", "Definition:Signed Measure", "Definition:Measure (Measure Theory)" ]
[ "Definition:Measure (Measure Theory)", "Definition:Signed Measure", "Definition:Extended Real-Valued Function", "Definition:Signed Measure", "Definition:Signed Measure", "Definition:Measure (Measure Theory)" ]
proofwiki-18884
Null Sets Closed under Countable Union/Signed Measure
Let $\struct {X, \Sigma}$ be a measurable space. Let $\mu$ be a signed measure on $\struct {X, \Sigma}$. Let $\sequence {N_i}_{i \mathop \in \N}$ be a sequence of $\mu$-null sets. Then: :$\ds N = \bigcup_{i \mathop = 1}^\infty N_i$ is a $\mu$-null set.
From Countable Union of Measurable Sets as Disjoint Union of Measurable Sets, there exists a sequence of pairwise disjoint $\Sigma$-measurable sets $\sequence {A_i}_{i \in \N}$ such that: :$\ds N = \bigcup_{i \mathop = 1}^\infty A_i$ We now show that if $E \in \Sigma$ has $E \subseteq N$, then $\map \mu E = 0$. Write...
Let $\struct {X, \Sigma}$ be a [[Definition:Measurable Space|measurable space]]. Let $\mu$ be a [[Definition:Signed Measure|signed measure]] on $\struct {X, \Sigma}$. Let $\sequence {N_i}_{i \mathop \in \N}$ be a [[Definition:Sequence|sequence]] of [[Definition:Null Set/Signed Measure|$\mu$-null sets]]. Then: :$...
From [[Countable Union of Measurable Sets as Disjoint Union of Measurable Sets]], there exists a [[Definition:Sequence|sequence]] of [[Definition:Pairwise Disjoint|pairwise disjoint]] [[Definition:Measurable Set|$\Sigma$-measurable sets]] $\sequence {A_i}_{i \in \N}$ such that: :$\ds N = \bigcup_{i \mathop = 1}^\inft...
Null Sets Closed under Countable Union/Signed Measure
https://proofwiki.org/wiki/Null_Sets_Closed_under_Countable_Union/Signed_Measure
https://proofwiki.org/wiki/Null_Sets_Closed_under_Countable_Union/Signed_Measure
[ "Null Sets Closed under Countable Union", "Signed Measures" ]
[ "Definition:Measurable Space", "Definition:Signed Measure", "Definition:Sequence", "Definition:Null Set/Signed Measure", "Definition:Null Set/Signed Measure" ]
[ "Countable Union of Measurable Sets as Disjoint Union of Measurable Sets", "Definition:Sequence", "Definition:Pairwise Disjoint", "Definition:Measurable Set", "Intersection with Subset is Subset", "Intersection Distributes over Union/Family of Sets", "Definition:Countably Additive Function", "Intersec...
proofwiki-18885
Uniqueness of Jordan Decomposition
Let $\struct {X, \Sigma}$ be a measurable space. Let $\mu$ be a signed measure on $\struct {X, \Sigma}$. Let $\tuple {P_1, N_1}$ and $\tuple {P_2, N_2}$ be Hahn decompositions of $\mu$. Let $\tuple {\mu^+_1, \mu^-_1}$ be the Jordan decomposition of $\mu$ corresponding to $\tuple {P_1, N_1}$. Let $\tuple {\mu^+_2, \mu...
We first prove two useful identities.
Let $\struct {X, \Sigma}$ be a [[Definition:Measurable Space|measurable space]]. Let $\mu$ be a [[Definition:Signed Measure|signed measure]] on $\struct {X, \Sigma}$. Let $\tuple {P_1, N_1}$ and $\tuple {P_2, N_2}$ be [[Definition:Hahn Decomposition|Hahn decompositions]] of $\mu$. Let $\tuple {\mu^+_1, \mu^-_1}$ be...
We first prove two useful identities.
Uniqueness of Jordan Decomposition
https://proofwiki.org/wiki/Uniqueness_of_Jordan_Decomposition
https://proofwiki.org/wiki/Uniqueness_of_Jordan_Decomposition
[ "Signed Measures", "Uniqueness of Jordan Decomposition" ]
[ "Definition:Measurable Space", "Definition:Signed Measure", "Definition:Hahn Decomposition", "Definition:Jordan Decomposition", "Definition:Jordan Decomposition", "Definition:Jordan Decomposition", "Definition:Signed Measure" ]
[]
proofwiki-18886
Uniqueness of Jordan Decomposition/Lemma
Let $\tuple {P, N}$ be a Hahn decomposition of $\mu$. Let $\tuple {\mu^+, \mu^-}$ be the Jordan decomposition of $\mu$ corresponding to $\tuple {P, N}$. Then, for each $A \in \Sigma$, we have: :$\map {\mu^+} A = \sup \set {\map \mu B : B \in \Sigma \text { and } B \subseteq A}$ and: :$\map {\mu^-} A = \sup \set {-\ma...
Since $\tuple {\mu^+, \mu^-}$ is a Jordan decomposition of $\mu$, we have: :$\mu = \mu^+ - \mu^-$ with $\mu^+$ and $\mu^-$ measures. Let $A \in \Sigma$. We first show: :$\map {\mu^+} A = \sup \set {\map \mu B : B \in \Sigma \text { and } B \subseteq A}$ Let $B \in \Sigma$ have $B \subseteq A$. We have: {{begin-eqn}}...
Let $\tuple {P, N}$ be a [[Definition:Hahn Decomposition|Hahn decomposition]] of $\mu$. Let $\tuple {\mu^+, \mu^-}$ be the [[Definition:Jordan Decomposition|Jordan decomposition]] of $\mu$ corresponding to $\tuple {P, N}$. Then, for each $A \in \Sigma$, we have: :$\map {\mu^+} A = \sup \set {\map \mu B : B \in \S...
Since $\tuple {\mu^+, \mu^-}$ is a [[Definition:Jordan Decomposition|Jordan decomposition]] of $\mu$, we have: :$\mu = \mu^+ - \mu^-$ with $\mu^+$ and $\mu^-$ [[Definition:Measure (Measure Theory)|measures]]. Let $A \in \Sigma$. We first show: :$\map {\mu^+} A = \sup \set {\map \mu B : B \in \Sigma \text { and...
Uniqueness of Jordan Decomposition/Lemma
https://proofwiki.org/wiki/Uniqueness_of_Jordan_Decomposition/Lemma
https://proofwiki.org/wiki/Uniqueness_of_Jordan_Decomposition/Lemma
[ "Uniqueness of Jordan Decomposition" ]
[ "Definition:Hahn Decomposition", "Definition:Jordan Decomposition" ]
[ "Definition:Jordan Decomposition", "Definition:Measure (Measure Theory)", "Definition:Measure (Measure Theory)", "Measure is Monotone", "Definition:Upper Bound of Set/Real Numbers", "Intersection is Subset", "Sigma-Algebra Closed under Countable Intersection", "Definition:Jordan Decomposition", "Def...
proofwiki-18887
Characterization of Absolutely Continuous Measures
Let $\struct {X, \Sigma}$ be a measurable space. Let $\mu$ be a measure on $\struct {X, \Sigma}$. Let $\nu$ be a finite measure on $\struct {X, \Sigma}$. Then $\nu$ is absolutely continuous with respect to $\mu$ {{iff}}: :for each $\epsilon > 0$ there exists $\delta > 0$ such that for each $A \in \Sigma$ with $\map \m...
=== Necessary Condition === We prove the contrapositive, then the result follows from Rule of Transposition. Suppose that: :for some $\epsilon > 0$, there exists no $\delta > 0$ such that for each $A \in \Sigma$ with $\map \mu A < \delta$, we have $\map \nu A < \epsilon$. That is: :for some $\epsilon > 0$, for all $\...
Let $\struct {X, \Sigma}$ be a [[Definition:Measurable Space|measurable space]]. Let $\mu$ be a [[Definition:Measure (Measure Theory)|measure]] on $\struct {X, \Sigma}$. Let $\nu$ be a [[Definition:Finite Measure|finite measure]] on $\struct {X, \Sigma}$. Then $\nu$ is [[Definition:Absolutely Continuous Measure|ab...
=== Necessary Condition === We prove the [[Definition:Contrapositive|contrapositive]], then the result follows from [[Rule of Transposition]]. Suppose that: :for some $\epsilon > 0$, there exists no $\delta > 0$ such that for each $A \in \Sigma$ with $\map \mu A < \delta$, we have $\map \nu A < \epsilon$. That is:...
Characterization of Absolutely Continuous Measures
https://proofwiki.org/wiki/Characterization_of_Absolutely_Continuous_Measures
https://proofwiki.org/wiki/Characterization_of_Absolutely_Continuous_Measures
[ "Absolutely Continuous Measures" ]
[ "Definition:Measurable Space", "Definition:Measure (Measure Theory)", "Definition:Finite Measure", "Definition:Absolute Continuity/Measure" ]
[ "Definition:Contrapositive Statement", "Rule of Transposition", "Definition:Absolute Continuity/Measure", "Sum of Infinite Geometric Sequence", "Borel-Cantelli Lemma", "Definition:Finite Measure", "Definition:Finite Extended Real Number", "Set is Subset of Union", "Definition:Sequence", "Definitio...
proofwiki-18888
Radon-Nikodym Theorem
Let $\struct {X, \Sigma}$ be a measurable space. Let $\mu$ and $\nu$ be $\sigma$-finite measures on $\struct {X, \Sigma}$ such that: :$\nu$ is absolutely continuous with respect to $\mu$. Then there exists a $\Sigma$-measurable function $g : X \to \hointr 0 \infty$ such that: :$\ds \map \nu A = \int_A g \rd \mu$ for ...
=== Existence === We first prove the case of $\mu$ and $\nu$ finite. Define $\FF$ to be the set of $\Sigma$-measurable functions $f : X \to \overline \R_{\ge 0}$ with: :$\ds \int_A f \rd \mu \le \map \nu A$ for each $A \in \Sigma$. We show that $\FF$ is non-empty. From Measurable Function Zero A.E. iff Absolute Valu...
Let $\struct {X, \Sigma}$ be a [[Definition:Measurable Space|measurable space]]. Let $\mu$ and $\nu$ be [[Definition:Sigma-Finite Measure|$\sigma$-finite measures]] on $\struct {X, \Sigma}$ such that: :$\nu$ is [[Definition:Absolutely Continuous Measure|absolutely continuous]] with respect to $\mu$. Then there exi...
=== Existence === We first prove the case of $\mu$ and $\nu$ [[Definition:Finite Measure|finite]]. Define $\FF$ to be the [[Definition:Set|set]] of [[Definition:Measurable Function|$\Sigma$-measurable functions]] $f : X \to \overline \R_{\ge 0}$ with: :$\ds \int_A f \rd \mu \le \map \nu A$ for each $A \in \Sigma$...
Radon-Nikodym Theorem
https://proofwiki.org/wiki/Radon-Nikodym_Theorem
https://proofwiki.org/wiki/Radon-Nikodym_Theorem
[ "Radon-Nikodym Theorem", "Signed Measures" ]
[ "Definition:Measurable Space", "Definition:Sigma-Finite Measure", "Definition:Absolute Continuity/Measure", "Definition:Measurable Function", "Definition:Almost Everywhere" ]
[ "Definition:Finite Measure", "Definition:Set", "Definition:Measurable Function", "Definition:Non-Empty Set", "Measurable Function Zero A.E. iff Absolute Value has Zero Integral", "Definition:Constant Mapping", "Definition:Real-Valued Function", "Definition:Finite Measure", "Definition:Increasing Seq...
proofwiki-18889
Vertical Section of Measurable Set is Measurable
Let $\struct {X, \Sigma_X}$ and $\struct {Y, \Sigma_Y}$ be measurable spaces. Let $E \in \Sigma_X \otimes \Sigma_Y$ where $\Sigma_X \otimes \Sigma_Y$ is the product $\sigma$-algebra of $\Sigma_X$ and $\Sigma_Y$. Let $x \in X$. Then: :$E_x \in \Sigma_Y$ where $E_x$ is the $x$-vertical section of $E$.
Let: :$\FF = \set {E \subseteq X \times Y : E_x \in \Sigma_Y}$ We will show that $\FF$ contains each $S_1 \times S_2$ with $S_1 \in \Sigma_X$ and $S_2 \in \Sigma_Y$. We will then show that $\FF$ is a $\sigma$-algebra, at which point we will have: :$\map \sigma {\set {S_1 \times S_2 : S_1 \in \Sigma_X, \, S_2 \in \Sig...
Let $\struct {X, \Sigma_X}$ and $\struct {Y, \Sigma_Y}$ be [[Definition:Measurable Space|measurable spaces]]. Let $E \in \Sigma_X \otimes \Sigma_Y$ where $\Sigma_X \otimes \Sigma_Y$ is the [[Definition:Product Sigma-Algebra|product $\sigma$-algebra]] of $\Sigma_X$ and $\Sigma_Y$. Let $x \in X$. Then: :$E_x \in ...
Let: :$\FF = \set {E \subseteq X \times Y : E_x \in \Sigma_Y}$ We will show that $\FF$ contains each $S_1 \times S_2$ with $S_1 \in \Sigma_X$ and $S_2 \in \Sigma_Y$. We will then show that $\FF$ is a [[Definition:Sigma-Algebra|$\sigma$-algebra]], at which point we will have: :$\map \sigma {\set {S_1 \times S_2 : ...
Vertical Section of Measurable Set is Measurable
https://proofwiki.org/wiki/Vertical_Section_of_Measurable_Set_is_Measurable
https://proofwiki.org/wiki/Vertical_Section_of_Measurable_Set_is_Measurable
[ "Vertical Section of Sets" ]
[ "Definition:Measurable Space", "Definition:Product Sigma-Algebra", "Definition:Vertical Section of Set" ]
[ "Definition:Sigma-Algebra", "Sigma-Algebra Contains Generated Sigma-Algebra of Subset", "Definition:Product Sigma-Algebra", "Vertical Section of Cartesian Product", "Definition:Sigma-Algebra", "Definition:Sigma-Algebra", "Definition:Closed under Mapping", "Definition:Set Union/Countable Union", "Def...
proofwiki-18890
Measure of Limit of Increasing Sequence of Measurable Sets
Let $\struct {X, \Sigma, \mu}$ be a measure space. Let $E \in \Sigma$. Let $\sequence {E_n}_{n \mathop \in \N}$ be an increasing sequence of $\Sigma$-measurable sets such that: :$E_n \uparrow E$ where $E_n \uparrow E$ denotes limit of increasing sequence of sets. Then: :$\ds \map \mu E = \lim_{n \mathop \to \infty}...
We define a sequence $\sequence {F_n}_{n \mathop \in \N}$ inductively. Set $F_1 = E_1$. For $n > 1$, define: :$F_n = E_n \setminus E_{n - 1}$ From the definition of set difference we have: :$E_n \setminus E_{n - 1} = E_n \cap \paren {X \setminus E_{n - 1} }$ Since $\Sigma$ is closed under complementation, we have: ...
Let $\struct {X, \Sigma, \mu}$ be a [[Definition:Measure Space|measure space]]. Let $E \in \Sigma$. Let $\sequence {E_n}_{n \mathop \in \N}$ be an [[Definition:Increasing Sequence of Sets|increasing sequence]] of [[Definition:Measurable Set|$\Sigma$-measurable sets]] such that: :$E_n \uparrow E$ where $E_n \upar...
We define a [[Definition:Sequence|sequence]] $\sequence {F_n}_{n \mathop \in \N}$ inductively. Set $F_1 = E_1$. For $n > 1$, define: :$F_n = E_n \setminus E_{n - 1}$ From the definition of [[Definition:Set Difference|set difference]] we have: :$E_n \setminus E_{n - 1} = E_n \cap \paren {X \setminus E_{n - 1} }$...
Measure of Limit of Increasing Sequence of Measurable Sets
https://proofwiki.org/wiki/Measure_of_Limit_of_Increasing_Sequence_of_Measurable_Sets
https://proofwiki.org/wiki/Measure_of_Limit_of_Increasing_Sequence_of_Measurable_Sets
[ "Increasing Sequences of Sets", "Measure Theory", "Measures", "Measures", "Increasing Sequences of Sets" ]
[ "Definition:Measure Space", "Definition:Increasing Sequence of Sets", "Definition:Measurable Set", "Definition:Limit of Increasing Sequence of Sets" ]
[ "Definition:Sequence", "Definition:Set Difference", "Definition:Closed under Mapping", "Definition:Relative Complement", "Sigma-Algebra Closed under Countable Intersection", "Definition:Increasing Sequence of Sets", "Definition:Disjoint Sets", "Definition:Disjoint Sets", "Definition:Increasing Seque...
proofwiki-18891
Signed Measure of Limit of Increasing Sequence of Measurable Sets
Let $\struct {X, \Sigma}$ be a measurable space. Let $\mu$ be a signed measure on $\struct {X, \Sigma}$. Let $E \in \Sigma$. Let $\sequence {E_n}_{n \mathop \in \N}$ be an increasing sequence of $\Sigma$-measurable sets such that: :$E_n \uparrow E$ where $E_n \uparrow E$ denotes the limit of an increasing sequence ...
Let $\tuple {\mu^+, \mu^-}$ be the Jordan decomposition of $\mu$. Then $\mu^+$ and $\mu^-$ are measures with: :$\mu = \mu^+ - \mu^-$ where at least one of $\mu^+$ and $\mu^-$ is finite. Then we have: :$\map \mu E = \map {\mu^+} E - \map {\mu^-} E$ From Measure of Limit of Increasing Sequence of Measurable Sets, we ha...
Let $\struct {X, \Sigma}$ be a [[Definition:Measurable Space|measurable space]]. Let $\mu$ be a [[Definition:Signed Measure|signed measure]] on $\struct {X, \Sigma}$. Let $E \in \Sigma$. Let $\sequence {E_n}_{n \mathop \in \N}$ be an [[Definition:Increasing Sequence of Sets|increasing sequence]] of [[Definition:Me...
Let $\tuple {\mu^+, \mu^-}$ be the [[Definition:Jordan Decomposition|Jordan decomposition]] of $\mu$. Then $\mu^+$ and $\mu^-$ are [[Definition:Measure (Measure Theory)|measures]] with: :$\mu = \mu^+ - \mu^-$ where at least one of $\mu^+$ and $\mu^-$ is [[Definition:Finite Measure|finite]]. Then we have: :$\map ...
Signed Measure of Limit of Increasing Sequence of Measurable Sets
https://proofwiki.org/wiki/Signed_Measure_of_Limit_of_Increasing_Sequence_of_Measurable_Sets
https://proofwiki.org/wiki/Signed_Measure_of_Limit_of_Increasing_Sequence_of_Measurable_Sets
[ "Signed Measures", "Increasing Sequences of Sets" ]
[ "Definition:Measurable Space", "Definition:Signed Measure", "Definition:Increasing Sequence of Sets", "Definition:Measurable Set", "Definition:Limit of Increasing Sequence of Sets" ]
[ "Definition:Jordan Decomposition", "Definition:Measure (Measure Theory)", "Definition:Finite Measure", "Measure of Limit of Increasing Sequence of Measurable Sets", "Combination Theorem for Sequences/Real/Difference Rule", "Category:Signed Measures", "Category:Increasing Sequences of Sets" ]
proofwiki-18892
Signed Measure of Limit of Decreasing Sequence of Measurable Sets
Let $\struct {X, \Sigma}$ be a measurable space. Let $E \in \Sigma$. Let $\sequence {E_n}_{n \mathop \in \N}$ be an decreasing sequence of $\Sigma$-measurable sets such that: :$E_n \downarrow E$ where $E_n \downarrow E$ denotes limit of decreasing sequence of sets, and: :there exists $m \in \N$ such that $\map \mu ...
Let $\tuple {\mu^+, \mu^-}$ be the Jordan decomposition of $\mu$. Then $\mu^+$ and $\mu^-$ are measures with: :$\mu = \mu^+ - \mu^-$ where at least one of $\mu^+$ and $\mu^-$ is finite. Then we have: :$\map \mu E = \map {\mu^+} E - \map {\mu^-} E$ and: :$\map \mu {E_m} = \map {\mu^+} {E_m} - \map {\mu^-} {E_m}$ Sinc...
Let $\struct {X, \Sigma}$ be a [[Definition:Measurable Space|measurable space]]. Let $E \in \Sigma$. Let $\sequence {E_n}_{n \mathop \in \N}$ be an [[Definition:Decreasing Sequence of Sets|decreasing sequence]] of [[Definition:Measurable Set|$\Sigma$-measurable sets]] such that: :$E_n \downarrow E$ where $E_n \...
Let $\tuple {\mu^+, \mu^-}$ be the [[Definition:Jordan Decomposition|Jordan decomposition]] of $\mu$. Then $\mu^+$ and $\mu^-$ are [[Definition:Measure (Measure Theory)|measures]] with: :$\mu = \mu^+ - \mu^-$ where at least one of $\mu^+$ and $\mu^-$ is [[Definition:Finite Measure|finite]]. Then we have: :$\map ...
Signed Measure of Limit of Decreasing Sequence of Measurable Sets
https://proofwiki.org/wiki/Signed_Measure_of_Limit_of_Decreasing_Sequence_of_Measurable_Sets
https://proofwiki.org/wiki/Signed_Measure_of_Limit_of_Decreasing_Sequence_of_Measurable_Sets
[ "Signed Measures" ]
[ "Definition:Measurable Space", "Definition:Decreasing Sequence of Sets", "Definition:Measurable Set", "Definition:Limit of Decreasing Sequence of Sets", "Definition:Finite Extended Real Number" ]
[ "Definition:Jordan Decomposition", "Definition:Measure (Measure Theory)", "Definition:Finite Measure", "Definition:Finite Extended Real Number", "Definition:Finite Extended Real Number", "Combination Theorem for Sequences/Real/Difference Rule" ]
proofwiki-18893
Union is Increasing Sequence of Sets
Let $\sequence {D_n}_{n \mathop \in \N}$ be a sequence of sets. Then: :the sequence $\ds \sequence {\bigcup_{k \mathop = 1}^n D_k}_{n \mathop \in \N}$ is increasing.
We have: :$\ds \bigcup_{k \mathop = 1}^{n + 1} D_k = D_{n + 1} \cup \bigcup_{k \mathop = 1}^n D_k$ From Set is Subset of Union, we have: :$\ds \bigcup_{k \mathop = 1}^n D_k \subseteq D_{n + 1} \cup \bigcup_{k \mathop = 1}^n D_k$ so: :$\ds \bigcup_{k \mathop = 1}^n D_k \subseteq \bigcup_{k \mathop = 1}^{n + 1} D_k$ So...
Let $\sequence {D_n}_{n \mathop \in \N}$ be a [[Definition:Sequence|sequence]] of [[Definition:Set|sets]]. Then: :the [[Definition:Sequence|sequence]] $\ds \sequence {\bigcup_{k \mathop = 1}^n D_k}_{n \mathop \in \N}$ is [[Definition:Increasing Sequence of Sets|increasing]].
We have: :$\ds \bigcup_{k \mathop = 1}^{n + 1} D_k = D_{n + 1} \cup \bigcup_{k \mathop = 1}^n D_k$ From [[Set is Subset of Union]], we have: :$\ds \bigcup_{k \mathop = 1}^n D_k \subseteq D_{n + 1} \cup \bigcup_{k \mathop = 1}^n D_k$ so: :$\ds \bigcup_{k \mathop = 1}^n D_k \subseteq \bigcup_{k \mathop = 1}^{n + 1...
Union is Increasing Sequence of Sets
https://proofwiki.org/wiki/Union_is_Increasing_Sequence_of_Sets
https://proofwiki.org/wiki/Union_is_Increasing_Sequence_of_Sets
[ "Set Union", "Increasing Sequences of Sets" ]
[ "Definition:Sequence", "Definition:Set", "Definition:Sequence", "Definition:Increasing Sequence of Sets" ]
[ "Set is Subset of Union", "Definition:Increasing Sequence of Sets", "Category:Set Union", "Category:Increasing Sequences of Sets" ]
proofwiki-18894
Vertical Section preserves Subsets
Let $X$ and $Y$ be sets. Let $A \subseteq B$ be subsets of $X \times Y$. Let $x \in X$. Then: :$A_x \subseteq B_x$ where $A_x$ is the $x$-vertical section of $A$ and $B_x$ is the $x$-vertical section of $B$.
Note that if: :$y \in A_x$ from the definition of $x$-vertical section, we have: :$\tuple {x, y} \in A$ so: :$\tuple {x, y} \in B$ So, from the definition of $x$-vertical section, we have: :$y \in B_x$ So: :if $y \in A_x$ then $y \in B_x$. That is: :$A_x \subseteq B_x$ {{qed}} Category:Vertical Section of Sets 0z9c...
Let $X$ and $Y$ be [[Definition:Set|sets]]. Let $A \subseteq B$ be [[Definition:Subset|subsets]] of $X \times Y$. Let $x \in X$. Then: :$A_x \subseteq B_x$ where $A_x$ is the [[Definition:Vertical Section of Set|$x$-vertical section]] of $A$ and $B_x$ is the [[Definition:Vertical Section of Set|$x$-vertical se...
Note that if: :$y \in A_x$ from the definition of [[Definition:Vertical Section of Set|$x$-vertical section]], we have: :$\tuple {x, y} \in A$ so: :$\tuple {x, y} \in B$ So, from the definition of [[Definition:Vertical Section of Set|$x$-vertical section]], we have: :$y \in B_x$ So: :if $y \in A_x$ then $y ...
Vertical Section preserves Subsets
https://proofwiki.org/wiki/Vertical_Section_preserves_Subsets
https://proofwiki.org/wiki/Vertical_Section_preserves_Subsets
[ "Vertical Section of Sets" ]
[ "Definition:Set", "Definition:Subset", "Definition:Vertical Section of Set", "Definition:Vertical Section of Set" ]
[ "Definition:Vertical Section of Set", "Definition:Vertical Section of Set", "Category:Vertical Section of Sets" ]
proofwiki-18895
Vertical Section preserves Increasing Sequences of Sets
Let $X$ and $Y$ be sets. Let $\sequence {A_n}_{n \mathop \in \N}$ be an increasing sequence in $X \times Y$. Let $x \in X$. Then: :$\sequence {\paren {A_n}_x}_{n \mathop \in \N}$ is an increasing sequence.
Since $\sequence {A_n}_{n \mathop \in \N}$ is increasing, we have: :$A_n \subseteq A_{n + 1}$ for each $n$. From Vertical Section preserves Subsets, we have: :$\paren {A_n}_x \subseteq \paren {A_{n + 1} }_x$ for each $n$. So: :$\sequence {\paren {A_n}_x}_{n \mathop \in \N}$ is an increasing sequence. {{qed}} Categor...
Let $X$ and $Y$ be [[Definition:Set|sets]]. Let $\sequence {A_n}_{n \mathop \in \N}$ be an [[Definition:Increasing Sequence of Sets|increasing sequence]] in $X \times Y$. Let $x \in X$. Then: :$\sequence {\paren {A_n}_x}_{n \mathop \in \N}$ is an [[Definition:Increasing Sequence of Sets|increasing sequence]].
Since $\sequence {A_n}_{n \mathop \in \N}$ is [[Definition:Increasing Sequence of Sets|increasing]], we have: :$A_n \subseteq A_{n + 1}$ for each $n$. From [[Vertical Section preserves Subsets]], we have: :$\paren {A_n}_x \subseteq \paren {A_{n + 1} }_x$ for each $n$. So: :$\sequence {\paren {A_n}_x}_{n \math...
Vertical Section preserves Increasing Sequences of Sets
https://proofwiki.org/wiki/Vertical_Section_preserves_Increasing_Sequences_of_Sets
https://proofwiki.org/wiki/Vertical_Section_preserves_Increasing_Sequences_of_Sets
[ "Increasing Sequences of Sets", "Vertical Section of Sets", "Increasing Sequences of Sets" ]
[ "Definition:Set", "Definition:Increasing Sequence of Sets", "Definition:Increasing Sequence of Sets" ]
[ "Definition:Increasing Sequence of Sets", "Vertical Section preserves Subsets", "Definition:Increasing Sequence of Sets", "Category:Vertical Section of Sets", "Category:Increasing Sequences of Sets" ]
proofwiki-18896
Horizontal Section preserves Increasing Sequences of Sets
Let $X$ and $Y$ be sets. Let $\sequence {A_n}_{n \mathop \in \N}$ be an increasing sequence in $X \times Y$. Let $y \in Y$. Then: :$\sequence {\paren {A_n}^y}_{n \mathop \in \N}$ is an increasing sequence.
Since $\sequence {A_n}_{n \mathop \in \N}$ is increasing, we have: :$A_n \subseteq A_{n + 1}$ for each $n$. From Horizontal Section preserves Subsets, we have: :$\paren {A_n}^y \subseteq \paren {A_{n + 1} }^y$ for each $n$. So: :$\sequence {\paren {A_n}^y}_{n \mathop \in \N}$ is an increasing sequence. {{qed}} Categ...
Let $X$ and $Y$ be [[Definition:Set|sets]]. Let $\sequence {A_n}_{n \mathop \in \N}$ be an [[Definition:Increasing Sequence of Sets|increasing sequence]] in $X \times Y$. Let $y \in Y$. Then: :$\sequence {\paren {A_n}^y}_{n \mathop \in \N}$ is an [[Definition:Increasing Sequence of Sets|increasing sequence]].
Since $\sequence {A_n}_{n \mathop \in \N}$ is [[Definition:Increasing Sequence of Sets|increasing]], we have: :$A_n \subseteq A_{n + 1}$ for each $n$. From [[Horizontal Section preserves Subsets]], we have: :$\paren {A_n}^y \subseteq \paren {A_{n + 1} }^y$ for each $n$. So: :$\sequence {\paren {A_n}^y}_{n \ma...
Horizontal Section preserves Increasing Sequences of Sets
https://proofwiki.org/wiki/Horizontal_Section_preserves_Increasing_Sequences_of_Sets
https://proofwiki.org/wiki/Horizontal_Section_preserves_Increasing_Sequences_of_Sets
[ "Increasing Sequences of Sets", "Horizontal Section of Sets", "Increasing Sequences of Sets" ]
[ "Definition:Set", "Definition:Increasing Sequence of Sets", "Definition:Increasing Sequence of Sets" ]
[ "Definition:Increasing Sequence of Sets", "Horizontal Section preserves Subsets", "Definition:Increasing Sequence of Sets", "Category:Horizontal Section of Sets", "Category:Increasing Sequences of Sets" ]
proofwiki-18897
Horizontal Section preserves Subsets
Let $X$ and $Y$ be sets. Let $A \subseteq B$ be subsets of $X \times Y$. Let $y \in Y$. Then: :$A^y \subseteq B^y$ where $A^y$ is the $y$-horizontal section of $A$ and $B^y$ is the $y$-horizontal section of $B$.
Note that if: :$x \in A^y$ from the definition of $x$-vertical section, we have: :$\tuple {x, y} \in A$ so: :$\tuple {x, y} \in B$ So, from the definition of $x$-vertical section, we have: :$x \in B^y$ So: :if $x \in A^y$ then $x \in B^y$. That is: :$A^y \subseteq B^y$ {{qed}} Category:Horizontal Section of Sets bj...
Let $X$ and $Y$ be [[Definition:Set|sets]]. Let $A \subseteq B$ be [[Definition:Subset|subsets]] of $X \times Y$. Let $y \in Y$. Then: :$A^y \subseteq B^y$ where $A^y$ is the [[Definition:Horizontal Section of Set|$y$-horizontal section]] of $A$ and $B^y$ is the [[Definition:Horizontal Section of Set|$y$-horiz...
Note that if: :$x \in A^y$ from the definition of [[Definition:Vertical Section of Set|$x$-vertical section]], we have: :$\tuple {x, y} \in A$ so: :$\tuple {x, y} \in B$ So, from the definition of [[Definition:Vertical Section of Set|$x$-vertical section]], we have: :$x \in B^y$ So: :if $x \in A^y$ then $x ...
Horizontal Section preserves Subsets
https://proofwiki.org/wiki/Horizontal_Section_preserves_Subsets
https://proofwiki.org/wiki/Horizontal_Section_preserves_Subsets
[ "Horizontal Section of Sets" ]
[ "Definition:Set", "Definition:Subset", "Definition:Horizontal Section of Set", "Definition:Horizontal Section of Set" ]
[ "Definition:Vertical Section of Set", "Definition:Vertical Section of Set", "Category:Horizontal Section of Sets" ]
proofwiki-18898
Vertical Section of Cartesian Product
Let $X$ and $Y$ be sets. Let $A \subseteq X$ and $B \subseteq Y$, so that $A \times B \subseteq X \times Y$. Let $x \in X$. Then: :$\paren {A \times B}_x = \begin{cases}B & x \in A \\ \O & x \not \in A\end{cases}$ where $\paren {A \times B}_x$ is the $x$-vertical section of $A \times B$.
Let $x \in A$. From the definition of the horizontal section, we have: :$y \in \paren {A \times B}_x$ {{iff}}: :$\tuple {x, y} \in A \times B$ Since $x \in A$, this equivalent to: :$y \in B$ So: :$y \in \paren {A \times B}_x$ {{iff}} $y \in B$ giving: :$\paren {A \times B}_x = B$ if $x \in A$. Now let $x \in X \set...
Let $X$ and $Y$ be [[Definition:Set|sets]]. Let $A \subseteq X$ and $B \subseteq Y$, so that $A \times B \subseteq X \times Y$. Let $x \in X$. Then: :$\paren {A \times B}_x = \begin{cases}B & x \in A \\ \O & x \not \in A\end{cases}$ where $\paren {A \times B}_x$ is the [[Definition:Vertical Section of Set|$x$-...
Let $x \in A$. From the definition of the [[Definition:Horizontal Section of Set|horizontal section]], we have: :$y \in \paren {A \times B}_x$ {{iff}}: :$\tuple {x, y} \in A \times B$ Since $x \in A$, this equivalent to: :$y \in B$ So: :$y \in \paren {A \times B}_x$ {{iff}} $y \in B$ giving: :$\paren {A \...
Vertical Section of Cartesian Product
https://proofwiki.org/wiki/Vertical_Section_of_Cartesian_Product
https://proofwiki.org/wiki/Vertical_Section_of_Cartesian_Product
[ "Vertical Section of Sets", "Cartesian Product" ]
[ "Definition:Set", "Definition:Vertical Section of Set" ]
[ "Definition:Horizontal Section of Set", "Definition:Set Difference", "Category:Vertical Section of Sets", "Category:Cartesian Product" ]
proofwiki-18899
Integral of Vertical Section of Measurable Function gives Measurable Function
Let $\struct {X, \Sigma_X, \mu}$ and $\struct {Y, \Sigma_Y, \nu}$ be $\sigma$-finite measure spaces. Let $f : X \times Y \to \overline \R_{\ge 0}$ be a positive $\Sigma_X \otimes \Sigma_Y$-measurable function, where $\Sigma_X \otimes \Sigma_Y$ is the product $\sigma$-algebra of $\Sigma_X$ and $\Sigma_Y$. Define the fun...
First we prove the case of: :$f = \chi_E$ where $E$ is a $\Sigma_X \otimes \Sigma_Y$-measurable set. From Vertical Section of Characteristic Function is Characteristic Function of Vertical Section, we have: :$f_x = \chi_{E_x}$ From Vertical Section of Measurable Function is Measurable, we also have: :$f_x$ is $\Sigma...
Let $\struct {X, \Sigma_X, \mu}$ and $\struct {Y, \Sigma_Y, \nu}$ be [[Definition:Sigma-Finite Measure Space|$\sigma$-finite]] [[Definition:Measure Space|measure spaces]]. Let $f : X \times Y \to \overline \R_{\ge 0}$ be a [[Definition:Positive Measurable Function|positive $\Sigma_X \otimes \Sigma_Y$-measurable functi...
First we prove the case of: :$f = \chi_E$ where $E$ is a [[Definition:Measurable Set|$\Sigma_X \otimes \Sigma_Y$-measurable set]]. From [[Vertical Section of Characteristic Function is Characteristic Function of Vertical Section]], we have: :$f_x = \chi_{E_x}$ From [[Vertical Section of Measurable Function is Mea...
Integral of Vertical Section of Measurable Function gives Measurable Function
https://proofwiki.org/wiki/Integral_of_Vertical_Section_of_Measurable_Function_gives_Measurable_Function
https://proofwiki.org/wiki/Integral_of_Vertical_Section_of_Measurable_Function_gives_Measurable_Function
[ "Measurable Functions", "Vertical Section of Functions" ]
[ "Definition:Sigma-Finite Measure Space", "Definition:Measure Space", "Definition:Measurable Function/Positive", "Definition:Product Sigma-Algebra", "Definition:Extended Real-Valued Function", "Definition:Vertical Section of Function", "Definition:Measurable Function" ]
[ "Definition:Measurable Set", "Vertical Section of Characteristic Function is Characteristic Function of Vertical Section", "Vertical Section of Measurable Function is Measurable", "Definition:Measurable Function", "Definition:Integral of Positive Measurable Function", "Integral of Characteristic Function/...