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proofwiki-22900
Hom Bifunctor With Left Identity Functor is Hom Bifunctor
Let $\mathbf {Set}$ be the category of sets. Let $\mathbf C$ be a locally small category. Let $\operatorname{id}_{\mathbf C} : \mathbf C \to \mathbf C$ denote the identity functor. Let $\map {\operatorname{Hom}_{\mathbf C} } {\operatorname{id}_{\mathbf C}-, -} : \mathbf C^{\text{op} } \times \mathbf C \to \mathbf {Set}...
For each object $\tuple {D^\text{op}, C}$ in $\mathbf C^{\text{op} } \times \mathbf C$ we have: {{begin-eqn}} {{eqn | l = \map {\operatorname{Hom}_{\mathbf C} } {\operatorname{id}_{\mathbf C} D^\text{op}, C} | r = \map {\operatorname{Hom}_{\mathbf C} } {\operatorname{id}_{\mathbf C} D, C} | c = {{Defof|Hom ...
Let $\mathbf {Set}$ be the [[Definition:Category of Sets|category of sets]]. Let $\mathbf C$ be a [[Definition:Locally Small Category|locally small category]]. Let $\operatorname{id}_{\mathbf C} : \mathbf C \to \mathbf C$ denote the [[Definition:Identity Functor|identity functor]]. Let $\map {\operatorname{Hom}_{\ma...
For each [[Definition:Object (Category Theory)|object]] $\tuple {D^\text{op}, C}$ in $\mathbf C^{\text{op} } \times \mathbf C$ we have: {{begin-eqn}} {{eqn | l = \map {\operatorname{Hom}_{\mathbf C} } {\operatorname{id}_{\mathbf C} D^\text{op}, C} | r = \map {\operatorname{Hom}_{\mathbf C} } {\operatorname{id}_{\...
Hom Bifunctor With Left Identity Functor is Hom Bifunctor
https://proofwiki.org/wiki/Hom_Bifunctor_With_Left_Identity_Functor_is_Hom_Bifunctor
https://proofwiki.org/wiki/Hom_Bifunctor_With_Left_Identity_Functor_is_Hom_Bifunctor
[ "Bifunctors" ]
[ "Definition:Category of Sets", "Definition:Locally Small Category", "Definition:Identity Functor", "Definition:Hom Bifunctor With Left Functor", "Definition:Hom Bifunctor" ]
[ "Definition:Object (Category Theory)", "Definition:Morphism" ]
proofwiki-22901
Hom Bifunctor With Right Identity Functor is Hom Bifunctor
Let $\mathbf {Set}$ be the category of sets. Let $\mathbf C$ be a locally small category. Let $\operatorname{id}_{\mathbf C} : \mathbf C \to \mathbf C$ denote the identity functor. Let $\map {\operatorname{Hom}_{\mathbf C} } {-, \operatorname{id}_{\mathbf C}-} : \mathbf C^{\text{op} } \times \mathbf C \to \mathbf {Set}...
For each object $\tuple {D^\text{op}, C}$ in $\mathbf C^{\text{op} } \times \mathbf C$ we have: {{begin-eqn}} {{eqn | l = \map {\operatorname{Hom}_{\mathbf C} } {D^\text{op}, \operatorname{id}_{\mathbf C} C} | r = \map {\operatorname{Hom}_{\mathbf C} } {D, \operatorname{id}_{\mathbf C} C} | c = {{Defof|Hom ...
Let $\mathbf {Set}$ be the [[Definition:Category of Sets|category of sets]]. Let $\mathbf C$ be a [[Definition:Locally Small Category|locally small category]]. Let $\operatorname{id}_{\mathbf C} : \mathbf C \to \mathbf C$ denote the [[Definition:Identity Functor|identity functor]]. Let $\map {\operatorname{Hom}_{\ma...
For each [[Definition:Object (Category Theory)|object]] $\tuple {D^\text{op}, C}$ in $\mathbf C^{\text{op} } \times \mathbf C$ we have: {{begin-eqn}} {{eqn | l = \map {\operatorname{Hom}_{\mathbf C} } {D^\text{op}, \operatorname{id}_{\mathbf C} C} | r = \map {\operatorname{Hom}_{\mathbf C} } {D, \operatorname{id}...
Hom Bifunctor With Right Identity Functor is Hom Bifunctor
https://proofwiki.org/wiki/Hom_Bifunctor_With_Right_Identity_Functor_is_Hom_Bifunctor
https://proofwiki.org/wiki/Hom_Bifunctor_With_Right_Identity_Functor_is_Hom_Bifunctor
[ "Bifunctors" ]
[ "Definition:Category of Sets", "Definition:Locally Small Category", "Definition:Identity Functor", "Definition:Hom Bifunctor With Right Functor", "Definition:Hom Bifunctor" ]
[ "Definition:Object (Category Theory)", "Definition:Morphism" ]
proofwiki-22902
Curve with Constant Zero Curvature is Straight Line
Let $\CC$ be a curve whose curvature is constant and zero. Then $\CC$ is a straight line.
From Straight Line has Zero Curvature, if $\CC$ is a straight line then its curvature is indeed constant and zero. It remains to be demonstrated that every such curve with constant zero curvature is a straight line. {{ProofWanted}}
Let $\CC$ be a [[Definition:Curve|curve]] whose [[Definition:Curvature|curvature]] is [[Definition:Constant|constant]] and [[Definition:Zero (Number)|zero]]. Then $\CC$ is a [[Definition:Straight Line|straight line]].
From [[Straight Line has Zero Curvature]], if $\CC$ is a [[Definition:Straight Line|straight line]] then its [[Definition:Curvature|curvature]] is indeed [[Definition:Constant|constant]] and [[Definition:Zero (Number)|zero]]. It remains to be demonstrated that every such [[Definition:Curve|curve]] with [[Definition:Co...
Curve with Constant Zero Curvature is Straight Line
https://proofwiki.org/wiki/Curve_with_Constant_Zero_Curvature_is_Straight_Line
https://proofwiki.org/wiki/Curve_with_Constant_Zero_Curvature_is_Straight_Line
[ "Curvature", "Straight Lines" ]
[ "Definition:Line/Curve", "Definition:Curvature", "Definition:Constant", "Definition:Zero (Number)", "Definition:Line/Straight Line" ]
[ "Straight Line has Zero Curvature", "Definition:Line/Straight Line", "Definition:Curvature", "Definition:Constant", "Definition:Zero (Number)", "Definition:Line/Curve", "Definition:Constant", "Definition:Zero (Number)", "Definition:Curvature", "Definition:Line/Straight Line" ]
proofwiki-22903
Open Real Interval is not Homeomorphic to Half-Open Real Interval
Let $I_o$ denote the open real interval $\openint 0 1$. Let $I_h$ denote the half-open real interval $\hointl 0 1$. Then $I_o$ and $I_h$ are not homeomorphic.
From Every Point except Endpoint in Connected Linearly Ordered Space is Cut Point: :every point of $I_o$ is a cut point :not every point of $I_h$ is a cut point. Indeed, the point $1$ is not a cut point of $I_h$, as: :$I_h \setminus \set 1 = I_o$ which is a connected space. {{qed}}
Let $I_o$ denote the [[Definition:Open Real Interval|open real interval]] $\openint 0 1$. Let $I_h$ denote the [[Definition:Half-Open Real Interval|half-open real interval]] $\hointl 0 1$. Then $I_o$ and $I_h$ are not [[Definition:Homeomorphic Topological Spaces|homeomorphic]].
From [[Every Point except Endpoint in Connected Linearly Ordered Space is Cut Point]]: :every [[Definition:Point|point]] of $I_o$ is a [[Definition:Cut Point|cut point]] :not every [[Definition:Point|point]] of $I_h$ is a [[Definition:Cut Point|cut point]]. Indeed, the [[Definition:Point|point]] $1$ is not a [[Definit...
Open Real Interval is not Homeomorphic to Half-Open Real Interval
https://proofwiki.org/wiki/Open_Real_Interval_is_not_Homeomorphic_to_Half-Open_Real_Interval
https://proofwiki.org/wiki/Open_Real_Interval_is_not_Homeomorphic_to_Half-Open_Real_Interval
[ "Homeomorphisms", "Real Intervals" ]
[ "Definition:Real Interval/Open", "Definition:Real Interval/Half-Open", "Definition:Homeomorphism/Topological Spaces" ]
[ "Every Point except Endpoint in Connected Linearly Ordered Space is Cut Point", "Definition:Point", "Definition:Cut Point", "Definition:Point", "Definition:Cut Point", "Definition:Point", "Definition:Cut Point", "Definition:Connected Topological Space" ]
proofwiki-22904
Comma Category is Category
Let $\mathbf C$, $\mathbf D$ and $\mathbf E$ be categories. Let $F : \mathbf D \to \mathbf C$ and $G : \mathbf E \to \mathbf C$ be covariant functors. Let $\paren{G \downarrow F}$ denote the comma category $G$ over $F$. Then: :$\paren{G \downarrow F}$ is a metacategory.
Let us verify the axioms $(\text C 1)$ up to $(\text C 3)$ for a metacategory.
Let $\mathbf C$, $\mathbf D$ and $\mathbf E$ be [[Definition:Category|categories]]. Let $F : \mathbf D \to \mathbf C$ and $G : \mathbf E \to \mathbf C$ be [[Definition:Covariant Functor|covariant functors]]. Let $\paren{G \downarrow F}$ denote the [[Definition:Comma Category|comma category $G$ over $F$]]. Then: :...
Let us verify the axioms $(\text C 1)$ up to $(\text C 3)$ for a [[Definition:Metacategory|metacategory]].
Comma Category is Category
https://proofwiki.org/wiki/Comma_Category_is_Category
https://proofwiki.org/wiki/Comma_Category_is_Category
[ "Comma Categories" ]
[ "Definition:Category", "Definition:Functor/Covariant", "Definition:Comma Category", "Definition:Metacategory" ]
[ "Definition:Metacategory", "Definition:Metacategory", "Definition:Metacategory", "Definition:Metacategory", "Definition:Metacategory", "Definition:Metacategory", "Definition:Metacategory", "Definition:Metacategory", "Definition:Metacategory", "Definition:Metacategory" ]
proofwiki-22905
Functor Under Object Comma Category is Category
Let $\mathbf C$, $\mathbf D$ be categories. Let $C$ be an object of $\mathbf C$. Let $F : \mathbf D \to \mathbf C$ be a covariant functor. Let $\paren{C \downarrow F}$ denote the comma category $F$ under $C$. Then: :$\paren{C \downarrow F}$ is a metacategory.
Let us verify the axioms $(\text C 1)$ up to $(\text C 3)$ for a metacategory.
Let $\mathbf C$, $\mathbf D$ be [[Definition:Category|categories]]. Let $C$ be an [[Definition:Object (Category Theory)|object]] of $\mathbf C$. Let $F : \mathbf D \to \mathbf C$ be a [[Definition:Covariant Functor|covariant functor]]. Let $\paren{C \downarrow F}$ denote the [[Definition:Functor Under Object Comm...
Let us verify the axioms $(\text C 1)$ up to $(\text C 3)$ for a [[Definition:Metacategory|metacategory]].
Functor Under Object Comma Category is Category
https://proofwiki.org/wiki/Functor_Under_Object_Comma_Category_is_Category
https://proofwiki.org/wiki/Functor_Under_Object_Comma_Category_is_Category
[ "Comma Categories" ]
[ "Definition:Category", "Definition:Object (Category Theory)", "Definition:Functor/Covariant", "Definition:Comma Category/Functor Under Object", "Definition:Metacategory" ]
[ "Definition:Metacategory", "Definition:Metacategory", "Definition:Metacategory", "Definition:Metacategory", "Definition:Metacategory", "Definition:Metacategory", "Definition:Metacategory", "Definition:Metacategory", "Definition:Metacategory", "Definition:Metacategory" ]
proofwiki-22906
Functor Over Object Comma Category is Category
Let $\mathbf C$, $\mathbf E$ be categories. Let $C$ be an object of $\mathbf C$. Let $G : \mathbf E \to \mathbf C$ be a covariant functor. Let $\paren{G \downarrow C}$ denote the comma category $G$ over $C$. Then: :$\paren{G \downarrow C}$ is a metacategory
Let us verify the axioms $(\text C 1)$ up to $(\text C 3)$ for a metacategory.
Let $\mathbf C$, $\mathbf E$ be [[Definition:Category|categories]]. Let $C$ be an [[Definition:Object (Category Theory)|object]] of $\mathbf C$. Let $G : \mathbf E \to \mathbf C$ be a [[Definition:Covariant Functor|covariant functor]]. Let $\paren{G \downarrow C}$ denote the [[Definition:Functor Over Object Comma...
Let us verify the axioms $(\text C 1)$ up to $(\text C 3)$ for a [[Definition:Metacategory|metacategory]].
Functor Over Object Comma Category is Category
https://proofwiki.org/wiki/Functor_Over_Object_Comma_Category_is_Category
https://proofwiki.org/wiki/Functor_Over_Object_Comma_Category_is_Category
[ "Comma Categories" ]
[ "Definition:Category", "Definition:Object (Category Theory)", "Definition:Functor/Covariant", "Definition:Comma Category/Functor Over Object", "Definition:Metacategory" ]
[ "Definition:Metacategory", "Definition:Metacategory", "Definition:Metacategory", "Definition:Metacategory", "Definition:Metacategory", "Definition:Metacategory", "Definition:Metacategory", "Definition:Metacategory", "Definition:Metacategory", "Definition:Metacategory" ]
proofwiki-22907
Functor Under Object Comma Category is Isomorphic to Comma Category
Let $\mathbf C$, $\mathbf D$ be categories. Let $C$ be an object of $\mathbf C$. Let $F : \mathbf D \to \mathbf C$ be a covariant functor. Let $\mathbf 1$ denote the category one. Let $G: \mathbf 1\to \mathbf C$ be the functor defined by: {{DefineFunctor |ob = $G* = C$ |mor = $G \operatorname{id}_* = \operatorname{id}_...
=== Lemma 1 === {{:Functor Under Object Comma Category is Isomorphic to Comma Category/Lemma 1}}{{qed|lemma}}
Let $\mathbf C$, $\mathbf D$ be [[Definition:Category|categories]]. Let $C$ be an [[Definition:Object (Category Theory)|object]] of $\mathbf C$. Let $F : \mathbf D \to \mathbf C$ be a [[Definition:Covariant Functor|covariant functor]]. Let $\mathbf 1$ denote the [[Definition:One (Category)|category one]]. Let $G:...
=== [[Functor Under Object Comma Category is Isomorphic to Comma Category/Lemma 1|Lemma 1]] === {{:Functor Under Object Comma Category is Isomorphic to Comma Category/Lemma 1}}{{qed|lemma}}
Functor Under Object Comma Category is Isomorphic to Comma Category
https://proofwiki.org/wiki/Functor_Under_Object_Comma_Category_is_Isomorphic_to_Comma_Category
https://proofwiki.org/wiki/Functor_Under_Object_Comma_Category_is_Isomorphic_to_Comma_Category
[ "Comma Categories", "Functor Under Object Comma Category is Isomorphic to Comma Category" ]
[ "Definition:Category", "Definition:Object (Category Theory)", "Definition:Functor/Covariant", "Definition:One (Category)", "Definition:Functor/Covariant", "Definition:Comma Category/Functor Under Object", "Definition:Comma Category/General Form", "Definition:Isomorphism of Categories", "Definition:O...
[ "Functor Under Object Comma Category is Isomorphic to Comma Category/Lemma 1" ]
proofwiki-22908
Functor Over Object Comma Category is Isomorphic to Comma Category
Let $\mathbf C$, $\mathbf D$ be categories. Let $C$ be an object of $\mathbf C$. Let $G : \mathbf D \to \mathbf C$ be a covariant functor. Let $\mathbf 1$ denote the category one. Let $F: \mathbf 1\to \mathbf C$ be the functor defined by: {{DefineFunctor |ob = $F* = C$ |mor = $F \operatorname{id}_* = \operatorname{id}_...
=== Lemma 1=== {{:Functor Over Object Comma Category is Isomorphic to Comma Category/Lemma 1}}{{qed|lemma}}
Let $\mathbf C$, $\mathbf D$ be [[Definition:Category|categories]]. Let $C$ be an [[Definition:Object (Category Theory)|object]] of $\mathbf C$. Let $G : \mathbf D \to \mathbf C$ be a [[Definition:Covariant Functor|covariant functor]]. Let $\mathbf 1$ denote the [[Definition:One (Category)|category one]]. Let $F:...
=== [[Functor Over Object Comma Category is Isomorphic to Comma Category/Lemma 1|Lemma 1]]=== {{:Functor Over Object Comma Category is Isomorphic to Comma Category/Lemma 1}}{{qed|lemma}}
Functor Over Object Comma Category is Isomorphic to Comma Category
https://proofwiki.org/wiki/Functor_Over_Object_Comma_Category_is_Isomorphic_to_Comma_Category
https://proofwiki.org/wiki/Functor_Over_Object_Comma_Category_is_Isomorphic_to_Comma_Category
[ "Comma Categories", "Functor Over Object Comma Category is Isomorphic to Comma Category" ]
[ "Definition:Category", "Definition:Object (Category Theory)", "Definition:Functor/Covariant", "Definition:One (Category)", "Definition:Functor/Covariant", "Definition:Comma Category/Functor Over Object", "Definition:Comma Category/General Form", "Definition:Isomorphism of Categories", "Definition:Ob...
[ "Functor Over Object Comma Category is Isomorphic to Comma Category/Lemma 1" ]
proofwiki-22909
Coslice Category is Isomorphic to Comma Category
Let $\mathbf C$ be a category. Let $C$ be an object of $\mathbf C$. Let $\operatorname{id}_{\mathbf C}$ denote the identity functor on $\mathbf C$. Let $\mathbf 1$ denote the category one. Let $G: \mathbf 1\to \mathbf C$ be the functor defined by: :$G* = C$ and :$G \operatorname{id}_* = \operatorname{id}_C$ Let $C / \m...
=== Lemma 1 === {{:Coslice Category is Isomorphic to Comma Category/Lemma 1}}{{qed|lemma}}
Let $\mathbf C$ be a [[Definition:Category|category]]. Let $C$ be an [[Definition:Object (Category Theory)|object]] of $\mathbf C$. Let $\operatorname{id}_{\mathbf C}$ denote the [[Definition:Identity Functor|identity functor]] on $\mathbf C$. Let $\mathbf 1$ denote the [[Definition:One (Category)|category one]]. ...
=== [[Coslice Category is Isomorphic to Comma Category/Lemma 1|Lemma 1]] === {{:Coslice Category is Isomorphic to Comma Category/Lemma 1}}{{qed|lemma}}
Coslice Category is Isomorphic to Comma Category
https://proofwiki.org/wiki/Coslice_Category_is_Isomorphic_to_Comma_Category
https://proofwiki.org/wiki/Coslice_Category_is_Isomorphic_to_Comma_Category
[ "Coslice Category is Isomorphic to Comma Category", "Coslice Categories", "Comma Categories" ]
[ "Definition:Category", "Definition:Object (Category Theory)", "Definition:Identity Functor", "Definition:One (Category)", "Definition:Functor/Covariant", "Definition:Coslice Category", "Definition:Comma Category/General Form", "Definition:Isomorphism of Categories", "Definition:Object (Category Theo...
[ "Coslice Category is Isomorphic to Comma Category/Lemma 1" ]
proofwiki-22910
Slice Category is Isomorphic to Comma Category
Let $\mathbf C$ be a category. Let $C$ be an object of $\mathbf C$. Let $\operatorname{id}_{\mathbf C}$ denote the identity functor on $\mathbf C$. Let $\mathbf 1$ denote the category one. Let $F: \mathbf 1\to \mathbf C$ be the functor defined by: :$F* = C$ and :$F \operatorname{id}_* = \operatorname{id}_C$ Let $\mathb...
=== Lemma 1 === {{:Slice Category is Isomorphic to Comma Category/Lemma 1}}{{qed|lemma}}
Let $\mathbf C$ be a [[Definition:Category|category]]. Let $C$ be an [[Definition:Object (Category Theory)|object]] of $\mathbf C$. Let $\operatorname{id}_{\mathbf C}$ denote the [[Definition:Identity Functor|identity functor]] on $\mathbf C$. Let $\mathbf 1$ denote the [[Definition:One (Category)|category one]]. ...
=== [[Slice Category is Isomorphic to Comma Category/Lemma 1|Lemma 1]] === {{:Slice Category is Isomorphic to Comma Category/Lemma 1}}{{qed|lemma}}
Slice Category is Isomorphic to Comma Category
https://proofwiki.org/wiki/Slice_Category_is_Isomorphic_to_Comma_Category
https://proofwiki.org/wiki/Slice_Category_is_Isomorphic_to_Comma_Category
[ "Slice Categories", "Comma Categories", "Slice Category is Isomorphic to Comma Category" ]
[ "Definition:Category", "Definition:Object (Category Theory)", "Definition:Identity Functor", "Definition:One (Category)", "Definition:Functor/Covariant", "Definition:Slice Category", "Definition:Comma Category/General Form", "Definition:Isomorphism of Categories", "Definition:Object (Category Theory...
[ "Slice Category is Isomorphic to Comma Category/Lemma 1" ]
proofwiki-22911
Morphism Category is Isomorphic to Comma Category
Let $\mathbf C$ be a category. Let $C$ be an object of $\mathbf C$. Let $\operatorname{id}_{\mathbf C}$ denote the identity functor on $\mathbf C$. Let $\mathbf C^\to$ denote the morphism category on $\mathbf C$. Let $\paren{\operatorname{id}_{\mathbf C} \downarrow \operatorname{id}_{\mathbf C}}$ denote the comma categ...
=== Lemma 1 === {{:Morphism Category is Isomorphic to Comma Category/Lemma 1}}{{qed|lemma}}
Let $\mathbf C$ be a [[Definition:Category|category]]. Let $C$ be an [[Definition:Object (Category Theory)|object]] of $\mathbf C$. Let $\operatorname{id}_{\mathbf C}$ denote the [[Definition:Identity Functor|identity functor]] on $\mathbf C$. Let $\mathbf C^\to$ denote the [[Definition:Morphism Category|morphism ...
=== [[Morphism Category is Isomorphic to Comma Category/Lemma 1|Lemma 1]] === {{:Morphism Category is Isomorphic to Comma Category/Lemma 1}}{{qed|lemma}}
Morphism Category is Isomorphic to Comma Category
https://proofwiki.org/wiki/Morphism_Category_is_Isomorphic_to_Comma_Category
https://proofwiki.org/wiki/Morphism_Category_is_Isomorphic_to_Comma_Category
[ "Morphism Categories", "Comma Categories", "Morphism Category is Isomorphic to Comma Category" ]
[ "Definition:Category", "Definition:Object (Category Theory)", "Definition:Identity Functor", "Definition:Morphism Category", "Definition:Comma Category/General Form", "Definition:Isomorphism of Categories", "Definition:Object (Category Theory)", "Definition:Morphism", "Definition:Object (Category Th...
[ "Morphism Category is Isomorphic to Comma Category/Lemma 1" ]
proofwiki-22912
Equivalence of Definitions of Universal Morphism from Object to Functor
Let $\mathbf C$ and $\mathbf D$ be metacategories. Let $C$ be an object of $\mathbf C$. Let $F: \mathbf D \to \mathbf C$ be a covariant functor. Let the pair $\tuple{R, u}$ consist of an object $R$ of $\mathbf D$ and a morphism $u: C \to FR$ in $C$. {{TFAE|def=Universal Morphism from Object to Functor|context=Category ...
The result follows immediately from: * Definition:Initial Object * Definition:Functor Under Object Comma Category {{qed}}
Let $\mathbf C$ and $\mathbf D$ be [[Definition:Metacategory|metacategories]]. Let $C$ be an [[Definition:Object (Category Theory)|object]] of $\mathbf C$. Let $F: \mathbf D \to \mathbf C$ be a [[Definition:Covariant Functor|covariant functor]]. Let the [[Definition:Ordered Pair|pair]] $\tuple{R, u}$ consist of an ...
The result follows immediately from: * [[Definition:Initial Object]] * [[Definition:Functor Under Object Comma Category]] {{qed}}
Equivalence of Definitions of Universal Morphism from Object to Functor
https://proofwiki.org/wiki/Equivalence_of_Definitions_of_Universal_Morphism_from_Object_to_Functor
https://proofwiki.org/wiki/Equivalence_of_Definitions_of_Universal_Morphism_from_Object_to_Functor
[ "Universal Morphisms", "Comma Categories" ]
[ "Definition:Metacategory", "Definition:Object (Category Theory)", "Definition:Functor/Covariant", "Definition:Ordered Pair", "Definition:Object (Category Theory)", "Definition:Morphism", "Definition:Universal Morphism from Object to Functor/Definition 1", "Definition:Universal Morphism from Object to ...
[ "Definition:Initial Object", "Definition:Comma Category/Functor Under Object" ]
proofwiki-22913
Morphism of Unit of Adjunction is Universal
Let $\mathbf C$, $\mathbf D$ be locally small categories. Let $\tuple {F, G, \alpha}$ be an adjunction between $\mathbf C$ and $\mathbf D$. Let $\eta: \operatorname {id}_{\mathbf D} \to GF$ be the unit of adjunction $\tuple {F, G, \alpha}$ Then: :for each object $D$ in $\mathbf D$ the morphism $\eta_D$ is a universal ...
By definition of unit of adjunction: :* for each $D$ of $\mathbf D: \eta_{_D} = \map {\alpha_{\tuple{D, F D}}} {\operatorname {id}_{FD}}$ where ::* $\alpha_{\tuple{D, F D}} : \map {\operatorname{Hom}_{\mathbf C} } {F D, F D} \to \map {\operatorname{Hom}_{\mathbf D} } {D, GF D}$ is the bijection from the adjunction $\tu...
Let $\mathbf C$, $\mathbf D$ be [[Definition:Locally Small Category|locally small categories]]. Let $\tuple {F, G, \alpha}$ be an [[Definition:Adjunction|adjunction]] between $\mathbf C$ and $\mathbf D$. Let $\eta: \operatorname {id}_{\mathbf D} \to GF$ be the [[Definition:Unit of Adjunction|unit of adjunction $\tup...
By definition of [[Definition:Unit of Adjunction|unit of adjunction]]: :* for each $D$ of $\mathbf D: \eta_{_D} = \map {\alpha_{\tuple{D, F D}}} {\operatorname {id}_{FD}}$ where ::* $\alpha_{\tuple{D, F D}} : \map {\operatorname{Hom}_{\mathbf C} } {F D, F D} \to \map {\operatorname{Hom}_{\mathbf D} } {D, GF D}$ is the ...
Morphism of Unit of Adjunction is Universal
https://proofwiki.org/wiki/Morphism_of_Unit_of_Adjunction_is_Universal
https://proofwiki.org/wiki/Morphism_of_Unit_of_Adjunction_is_Universal
[ "Adjunctions", "Universal Morphisms" ]
[ "Definition:Locally Small Category", "Definition:Adjunction", "Definition:Unit of Adjunction", "Definition:Object (Category Theory)", "Definition:Morphism", "Definition:Universal Morphism from Object to Functor" ]
[ "Definition:Unit of Adjunction", "Definition:Bijection", "Definition:Adjunction", "Definition:Identity Morphism", "Definition:Identity Functor", "Definition:Composition of Functors", "Definition:Universal Morphism from Object to Functor", "Definition:Morphism", "Definition:Unique", "Definition:Mor...
proofwiki-22914
Equivalence of Definitions of Universal Morphism from Functor to Object
Let $\mathbf C$ and $\mathbf D$ be metacategories. Let $C$ be an object of $\mathbf C$. Let $F: \mathbf D \to \mathbf C$ be a covariant functor. Let the pair $\tuple{R, v}$ consist of an object $R$ of $\mathbf D$ and a morphism $v: FR \to C$ in $C$. {{TFAE|def=Universal Morphism from Functor to Object|context=Category ...
The result follows immediately from: * Definition:Terminal Object * Definition:Functor Over Object Comma Category {{qed}}
Let $\mathbf C$ and $\mathbf D$ be [[Definition:Metacategory|metacategories]]. Let $C$ be an [[Definition:Object (Category Theory)|object]] of $\mathbf C$. Let $F: \mathbf D \to \mathbf C$ be a [[Definition:Covariant Functor|covariant functor]]. Let the [[Definition:Ordered Pair|pair]] $\tuple{R, v}$ consist of an ...
The result follows immediately from: * [[Definition:Terminal Object]] * [[Definition:Functor Over Object Comma Category]] {{qed}}
Equivalence of Definitions of Universal Morphism from Functor to Object
https://proofwiki.org/wiki/Equivalence_of_Definitions_of_Universal_Morphism_from_Functor_to_Object
https://proofwiki.org/wiki/Equivalence_of_Definitions_of_Universal_Morphism_from_Functor_to_Object
[ "Universal Morphisms", "Comma Categories" ]
[ "Definition:Metacategory", "Definition:Object (Category Theory)", "Definition:Functor/Covariant", "Definition:Ordered Pair", "Definition:Object (Category Theory)", "Definition:Morphism", "Definition:Universal Morphism from Functor to Object/Definition 1", "Definition:Universal Morphism from Functor to...
[ "Definition:Terminal Object", "Definition:Comma Category/Functor Over Object" ]
proofwiki-22915
Morphism of Counit of Adjunction is Universal
Let $\mathbf C$, $\mathbf D$ be locally small categories. Let $\tuple {F, G, \alpha}$ be an adjunction between $\mathbf C$ and $\mathbf D$. Let $\xi: FG \to \operatorname {id}_{\mathbf C}$ be the counit of adjunction $\tuple {F, G, \alpha}$ Then: :for each object $C$ in $\mathbf C$ the morphism $\xi_C$ is a universal ...
Let $\beta$ be the inverse of the natural isomorphism $\alpha$. By definition of counit of adjunction: :* for each $C$ of $\mathbf C: \xi_{C} = \map {\beta_{\tuple{GC, C}}} {\operatorname {id}_{GC}}$ where ::* $\beta_{\tuple{GC, C} }: \map {\operatorname{Hom}_{\mathbf C} } {F G C, C} \to \map {\operatorname{Hom}_{\math...
Let $\mathbf C$, $\mathbf D$ be [[Definition:Locally Small Category|locally small categories]]. Let $\tuple {F, G, \alpha}$ be an [[Definition:Adjunction|adjunction]] between $\mathbf C$ and $\mathbf D$. Let $\xi: FG \to \operatorname {id}_{\mathbf C}$ be the [[Definition:Counit of Adjunction|counit of adjunction $\...
Let $\beta$ be the [[Definition:Inverse Natural Isomorphism between Covariant Functors|inverse]] of the [[Definition:Natural Isomorphism|natural isomorphism]] $\alpha$. By definition of [[Definition:Counit of Adjunction|counit of adjunction]]: :* for each $C$ of $\mathbf C: \xi_{C} = \map {\beta_{\tuple{GC, C}}} {\op...
Morphism of Counit of Adjunction is Universal
https://proofwiki.org/wiki/Morphism_of_Counit_of_Adjunction_is_Universal
https://proofwiki.org/wiki/Morphism_of_Counit_of_Adjunction_is_Universal
[ "Adjunctions", "Universal Morphisms" ]
[ "Definition:Locally Small Category", "Definition:Adjunction", "Definition:Counit of Adjunction", "Definition:Object (Category Theory)", "Definition:Morphism", "Definition:Universal Morphism from Functor to Object" ]
[ "Definition:Natural Isomorphism between Covariant Functors/Inverse", "Definition:Natural Isomorphism", "Definition:Counit of Adjunction", "Definition:Bijection", "Definition:Natural Isomorphism between Covariant Functors/Inverse", "Definition:Identity Morphism", "Definition:Identity Functor", "Definit...
proofwiki-22916
Unit of Adjunction Induces Adjunction
Let $\mathbf C$, $\mathbf D$ be locally small categories. Let $F: \mathbf D \to \mathbf C$ and $G:\mathbf C \to \mathbf D$ be covariant functors. Let $\eta: \operatorname {id}_{\mathbf D} \to GF$ be a natural transformation such that: :for each object $D$ in $\mathbf D$ the morphism $\eta_D$ is a universal morphism fr...
From Characterization of Adjunction Using Right Adjuncts of Morphisms: ::the triple $\tuple {F, G, \alpha}$ is an adjunction {{iff}}: :$(1)\quad$ For each $D$ in $\mathbf D$ and $C$ in $\mathbf C : \alpha_{\tuple{D, C}}: \map {\mathrm {Hom}_{\mathbf C} } {FD, C} \to \map {\mathrm {Hom}_{\mathbf D} } {D, GC}$ is a bijec...
Let $\mathbf C$, $\mathbf D$ be [[Definition:Locally Small Category|locally small categories]]. Let $F: \mathbf D \to \mathbf C$ and $G:\mathbf C \to \mathbf D$ be [[Definition:Covariant Functor|covariant functors]]. Let $\eta: \operatorname {id}_{\mathbf D} \to GF$ be a [[Definition:Natural Transformation|natural t...
From [[Characterization of Adjunction Using Right Adjuncts of Morphisms]]: ::the [[Definition:Triple|triple]] $\tuple {F, G, \alpha}$ is an [[Definition:Adjunction|adjunction]] {{iff}}: :$(1)\quad$ For each $D$ in $\mathbf D$ and $C$ in $\mathbf C : \alpha_{\tuple{D, C}}: \map {\mathrm {Hom}_{\mathbf C} } {FD, C} \to \...
Unit of Adjunction Induces Adjunction
https://proofwiki.org/wiki/Unit_of_Adjunction_Induces_Adjunction
https://proofwiki.org/wiki/Unit_of_Adjunction_Induces_Adjunction
[ "Adjunctions", "Universal Morphisms" ]
[ "Definition:Locally Small Category", "Definition:Functor/Covariant", "Definition:Natural Transformation", "Definition:Object (Category Theory)", "Definition:Morphism", "Definition:Universal Morphism from Object to Functor", "Definition:Object (Category Theory)", "Definition:Functor/Covariant", "Defi...
[ "Characterization of Adjunction Using Right Adjuncts of Morphisms", "Definition:Ordered Tuple as Ordered Set/Ordered Triple", "Definition:Adjunction", "Definition:Bijection", "Definition:Bijection", "Characterization of Adjunction Using Right Adjuncts of Morphisms", "Definition:Adjunction" ]
proofwiki-22917
Counit of Adjunction Induces Adjunction
Let $\mathbf C$, $\mathbf D$ be locally small categories. Let $F: \mathbf D \to \mathbf C$ and $G:\mathbf C \to \mathbf D$ be functors. Let $\xi: FG \to \operatorname {id}_{\mathbf C}$ be a natural transformation such that: :for each object $C$ in $\mathbf C$ the morphism $\xi_C$ is a universal morphism from $F$ to $G...
From Characterization of Adjunction Using Left Adjuncts of Morphisms, we have: :$(1)\quad$For each $D$ in $\mathbf D$ and $C$ in $\mathbf C : \beta_{\tuple{D, C}}: \map {\mathrm {Hom}_{\mathbf D} } {D, GC} \to \map {\mathrm {Hom}_{\mathbf C} } {FD, C}$ is a bijection :$(2):\quad$ for every $g:C_1 \to C_2 \in \mathbf C$...
Let $\mathbf C$, $\mathbf D$ be [[Definition:Locally Small Category|locally small categories]]. Let $F: \mathbf D \to \mathbf C$ and $G:\mathbf C \to \mathbf D$ be [[Definition:Functor|functors]]. Let $\xi: FG \to \operatorname {id}_{\mathbf C}$ be a [[Definition:Natural Transformation|natural transformation]] such ...
From [[Characterization of Adjunction Using Left Adjuncts of Morphisms]], we have: :$(1)\quad$For each $D$ in $\mathbf D$ and $C$ in $\mathbf C : \beta_{\tuple{D, C}}: \map {\mathrm {Hom}_{\mathbf D} } {D, GC} \to \map {\mathrm {Hom}_{\mathbf C} } {FD, C}$ is a [[Definition:Bijection|bijection]] :$(2):\quad$ for ever...
Counit of Adjunction Induces Adjunction
https://proofwiki.org/wiki/Counit_of_Adjunction_Induces_Adjunction
https://proofwiki.org/wiki/Counit_of_Adjunction_Induces_Adjunction
[ "Adjunctions", "Universal Morphisms" ]
[ "Definition:Locally Small Category", "Definition:Functor", "Definition:Natural Transformation", "Definition:Object (Category Theory)", "Definition:Morphism", "Definition:Universal Morphism from Functor to Object", "Definition:Object (Category Theory)", "Definition:Mapping", "Definition:Inverse Mappi...
[ "Characterization of Adjunction Using Left Adjuncts of Morphisms", "Definition:Bijection", "Definition:Bijection", "Characterization of Adjunction Using Left Adjuncts of Morphisms" ]
proofwiki-22918
Convex Hull of Union of Compact Set and Closed von Neumann-Bounded Set in Hausdorff Topological Vector Space is Closed
Let $\GF \in \set {\R, \C}$. Let $\struct {X, \tau}$ be a Hausdorff topological vector space. Let $A \subseteq X$ be compact. Let $B \subseteq X$ be closed and von Neumann-bounded. Let $C = \map {\mathrm {conv} } {A \cup B}$ be the convex hull of $A \cup B$. Then $C$ is closed.
We show that every convergent net in $C$ has its limit in $C$. Let $\struct {\AA, \preceq_{\AA} }$ be a directed set. Let $\family {z_\alpha}_{\alpha \mathop \in \AA}$ be a net in $C$ converging to $z$. We want to show that $z \in C$. From Convex Hull of Finite Union of Convex Sets, there exists nets: :$\family {x_\al...
Let $\GF \in \set {\R, \C}$. Let $\struct {X, \tau}$ be a [[Definition:Hausdorff Topological Vector Space|Hausdorff topological vector space]]. Let $A \subseteq X$ be [[Definition:Compact Topological Space|compact]]. Let $B \subseteq X$ be [[Definition:Closed Set|closed]] and [[Definition:von Neumann-Bounded Subset ...
We show that every [[Definition:Convergent Net|convergent net]] in $C$ has its [[Definition:Limit of Net|limit]] in $C$. Let $\struct {\AA, \preceq_{\AA} }$ be a [[Definition:Directed Set|directed set]]. Let $\family {z_\alpha}_{\alpha \mathop \in \AA}$ be a [[Definition:Net (Set Theory)|net]] in $C$ [[Definition:Con...
Convex Hull of Union of Compact Set and Closed von Neumann-Bounded Set in Hausdorff Topological Vector Space is Closed
https://proofwiki.org/wiki/Convex_Hull_of_Union_of_Compact_Set_and_Closed_von_Neumann-Bounded_Set_in_Hausdorff_Topological_Vector_Space_is_Closed
https://proofwiki.org/wiki/Convex_Hull_of_Union_of_Compact_Set_and_Closed_von_Neumann-Bounded_Set_in_Hausdorff_Topological_Vector_Space_is_Closed
[ "von Neumann-Bounded Subsets of Topological Vector Spaces", "Convex Hulls", "Compact Topological Spaces" ]
[ "Definition:Hausdorff Topological Vector Space", "Definition:Compact Topological Space", "Definition:Closed Set", "Definition:von Neumann-Bounded Subset of Topological Vector Space", "Definition:Convex Hull", "Definition:Closed Set" ]
[ "Definition:Convergent Net", "Definition:Limit of Net", "Definition:Directed Preordering", "Definition:Net (Set Theory)", "Definition:Convergent Net", "Convex Hull of Finite Union of Convex Sets", "Definition:Net (Set Theory)", "Definition:Compact Topological Space", "Definition:Directed Preordering...
proofwiki-22919
Characterization of Convergence of Net in Initial Topology
Let $X$ be a set. Let $\FF$ be a set of functions $f : X \to Y_f$. For each $f \in \FF$, let $\tau_f$ be a topology on $Y_f$. Let $\tau$ be the initial topology on $X$ induced by $\FF$ with $f \in \FF$ given the topology $\tau_f$. Let $\struct {\Lambda, \preceq}$ be a directed set. Let $\family {x_\lambda}_{\lambda ...
=== Necessary Condition === Suppose that $\family {x_\lambda}_{\lambda \mathop \in \Lambda}$ converges to $x$. Let $f \in \FF$. From the definition of the initial topology, $f$ is continuous. From Characterization of Continuity in terms of Nets, we have: :$\map f {x_\lambda} \to \map f x$ in $\struct {Y_f, \tau_f}$. ...
Let $X$ be a [[Definition:Set|set]]. Let $\FF$ be a [[Definition:Set|set]] of [[Definition:Function|functions]] $f : X \to Y_f$. For each $f \in \FF$, let $\tau_f$ be a [[Definition:Topology|topology]] on $Y_f$. Let $\tau$ be the [[Definition:Initial Topology|initial topology]] on $X$ induced by $\FF$ with $f \in ...
=== Necessary Condition === Suppose that $\family {x_\lambda}_{\lambda \mathop \in \Lambda}$ [[Definition:Convergent Net|converges]] to $x$. Let $f \in \FF$. From the definition of the [[Definition:Initial Topology|initial topology]], $f$ is [[Definition:Continuous Mapping|continuous]]. From [[Characterization of ...
Characterization of Convergence of Net in Initial Topology
https://proofwiki.org/wiki/Characterization_of_Convergence_of_Net_in_Initial_Topology
https://proofwiki.org/wiki/Characterization_of_Convergence_of_Net_in_Initial_Topology
[ "Initial Topology", "Nets (Set Theory)" ]
[ "Definition:Set", "Definition:Set", "Definition:Function", "Definition:Topology", "Definition:Initial Topology", "Definition:Topology", "Definition:Directed Preordering", "Definition:Net (Set Theory)", "Definition:Convergent Net" ]
[ "Definition:Convergent Net", "Definition:Initial Topology", "Definition:Continuous Mapping", "Characterization of Continuity in terms of Nets", "Definition:Convergent Net" ]
proofwiki-22920
Characterization of Convergence of Net in Product Topology
Let $I$ be a set. Let $\family {\tuple {X_\alpha, \tau_\alpha} }_{\alpha \mathop \in I}$ be an $I$-indexed family of sets. Let: :$\ds X = \prod_{\alpha \mathop \in I} X_\alpha$ Let $\family {\pi_\alpha}_{\alpha \mathop \in I}$ be the coordinate projections $X \to X_\alpha$. Let $\tau$ be the product topology on $X$....
Note that $\tau$ is the initial topology on $X$ induced by $\FF = \family {\pi_\alpha}_{\alpha \mathop \in I}$. The result then follows from Characterization of Convergence of Net in Initial Topology. {{qed}} Category:Product Topology Category:Nets (Set Theory) fkznrsyme589w5l9sr43d7ui72mhayq
Let $I$ be a [[Definition:Set|set]]. Let $\family {\tuple {X_\alpha, \tau_\alpha} }_{\alpha \mathop \in I}$ be an [[Definition:Indexed Family of Sets|$I$-indexed family of sets]]. Let: :$\ds X = \prod_{\alpha \mathop \in I} X_\alpha$ Let $\family {\pi_\alpha}_{\alpha \mathop \in I}$ be the [[Definition:Projection ...
Note that $\tau$ is the [[Definition:Initial Topology|initial topology]] on $X$ induced by $\FF = \family {\pi_\alpha}_{\alpha \mathop \in I}$. The result then follows from [[Characterization of Convergence of Net in Initial Topology]]. {{qed}} [[Category:Product Topology]] [[Category:Nets (Set Theory)]] fkznrsyme589...
Characterization of Convergence of Net in Product Topology
https://proofwiki.org/wiki/Characterization_of_Convergence_of_Net_in_Product_Topology
https://proofwiki.org/wiki/Characterization_of_Convergence_of_Net_in_Product_Topology
[ "Nets (Set Theory)", "Product Topology", "Nets (Set Theory)" ]
[ "Definition:Set", "Definition:Indexing Set/Family of Sets", "Definition:Projection (Mapping Theory)/Family of Sets", "Definition:Product Topology", "Definition:Directed Preordering", "Definition:Net (Set Theory)", "Definition:Convergent Net" ]
[ "Definition:Initial Topology", "Characterization of Convergence of Net in Initial Topology", "Category:Product Topology", "Category:Nets (Set Theory)" ]
proofwiki-22921
Closed Graph Theorem/Compact Hausdorff Codomain
Let $\struct {X, \tau_X}$ be a topological space. Let $\struct {Y, \tau_Y}$ be a compact $T_2$ (Hausdorff) space. Equip $X \times Y$ with the product topology $\tau_{X \times Y}$. Let $f : X \to Y$ be a mapping. Let $G_f$ be the graph of $f$. Then $f$ is continuous {{iff}} $G_f$ is closed in $\struct {X \times Y, \tau...
=== Necessary Condition === Suppose that $f$ is continuous. From Characterization of Closedness in terms of Nets, it is enough to show that: :every convergent net in $G_f$ has its limit in $G_f$. Let $\struct {\Lambda, \preceq}$ be a directed set. Let $\family {\tuple {x_\lambda, y_\lambda} }_{\lambda \mathop \in \Lamb...
Let $\struct {X, \tau_X}$ be a [[Definition:Topological Space|topological space]]. Let $\struct {Y, \tau_Y}$ be a [[Definition:Compact Topological Space|compact]] [[Definition:T2 Space|$T_2$ (Hausdorff) space]]. Equip $X \times Y$ with the [[Definition:Product Topology|product topology]] $\tau_{X \times Y}$. Let $f...
=== Necessary Condition === Suppose that $f$ is [[Definition:Continuous Mapping|continuous]]. From [[Characterization of Closedness in terms of Nets]], it is enough to show that: :every [[Definition:Convergent Net|convergent net]] in $G_f$ has its [[Definition:Limit of Net|limit]] in $G_f$. Let $\struct {\Lambda, \p...
Closed Graph Theorem/Compact Hausdorff Codomain
https://proofwiki.org/wiki/Closed_Graph_Theorem/Compact_Hausdorff_Codomain
https://proofwiki.org/wiki/Closed_Graph_Theorem/Compact_Hausdorff_Codomain
[ "Closed Graph Theorem" ]
[ "Definition:Topological Space", "Definition:Compact Topological Space", "Definition:T2 Space", "Definition:Product Topology", "Definition:Mapping", "Definition:Graph of Mapping", "Definition:Continuous Mapping", "Definition:Closed Set" ]
[ "Definition:Continuous Mapping", "Characterization of Closedness in terms of Nets", "Definition:Convergent Net", "Definition:Limit of Net", "Definition:Directed Preordering", "Definition:Convergent Net", "Definition:Limit of Net", "Characterization of Convergence of Net in Product Topology", "Defini...
proofwiki-22922
Vector Space with Subspace of Algebraic Dual Separating Points is Dual System
Let $K$ be a field. Let $E$ be a vector space over $K$. Let $E^\#$ be the algebraic dual of $E$. Let $F \subseteq E^\#$ be a vector subspace of $E^\#$ that separates points. Define $\innerprod \cdot \cdot : E \times F \to K$ by: :$\innerprod x f = \map f x$ for each $\tuple {x, f} \in E \times F$. Then $\tuple {E, F, ...
We first show that $\innerprod \cdot \cdot$ is a bilinear mapping. Let $x_1, x_2, x \in E$ and $f_1, f_2, f \in F$ and $\lambda \in K$. We have: {{begin-eqn}} {{eqn | l = \innerprod {x_1 + \lambda x_2} f | r = \map f {x_1 + \lambda x_2} }} {{eqn | r = \map f {x_1} + \lambda \map f {x_2} | c = {{Defof|Linear Functi...
Let $K$ be a [[Definition:Field (Abstract Algebra)|field]]. Let $E$ be a [[Definition:Vector Space|vector space]] over $K$. Let $E^\#$ be the [[Definition:Vector Algebraic Dual|algebraic dual]] of $E$. Let $F \subseteq E^\#$ be a [[Definition:Vector Subspace|vector subspace]] of $E^\#$ that [[Definition:Mappings Sep...
We first show that $\innerprod \cdot \cdot$ is a [[Definition:Bilinear Mapping|bilinear mapping]]. Let $x_1, x_2, x \in E$ and $f_1, f_2, f \in F$ and $\lambda \in K$. We have: {{begin-eqn}} {{eqn | l = \innerprod {x_1 + \lambda x_2} f | r = \map f {x_1 + \lambda x_2} }} {{eqn | r = \map f {x_1} + \lambda \map f {...
Vector Space with Subspace of Algebraic Dual Separating Points is Dual System
https://proofwiki.org/wiki/Vector_Space_with_Subspace_of_Algebraic_Dual_Separating_Points_is_Dual_System
https://proofwiki.org/wiki/Vector_Space_with_Subspace_of_Algebraic_Dual_Separating_Points_is_Dual_System
[ "Dual Systems", "Vector Space with Subspace of Algebraic Dual Separating Points is Dual System", "Algebraic Duals" ]
[ "Definition:Field (Abstract Algebra)", "Definition:Vector Space", "Definition:Algebraic Dual/Vector Space", "Definition:Vector Subspace", "Definition:Mappings Separating Points", "Definition:Dual System" ]
[ "Definition:Bilinear Mapping", "Definition:Bilinear Mapping", "Definition:Mappings Separating Points", "Category:Dual Systems", "Category:Vector Space with Subspace of Algebraic Dual Separating Points is Dual System", "Category:Algebraic Duals" ]
proofwiki-22923
Algebraic Dual Separates Points of Vector Space
Let $K$ be a field. Let $E$ be a vector space over $K$. Let $E^\#$ be the algebraic dual of $E$. Then $E^\#$ separates points.
We have that $E^\#$ separates points {{iff}}: :for all $x, y \in E$ with $x \ne y$, there exists $f \in E^\#$ with $\map f x \ne \map f y$. If $E = \set { {\mathbf 0}_E}$ (that is, $\dim E = 0$), then there are no $x, y \in E$ with $x \ne y$, hence this holds trivially. Now suppose that $\dim E \ge 1$. Since each $f \...
Let $K$ be a [[Definition:Field (Abstract Algebra)|field]]. Let $E$ be a [[Definition:Vector Space|vector space]] over $K$. Let $E^\#$ be the [[Definition:Vector Algebraic Dual|algebraic dual]] of $E$. Then $E^\#$ [[Definition:Mappings Separating Points|separates points]].
We have that $E^\#$ [[Definition:Mappings Separating Points|separates points]] {{iff}}: :for all $x, y \in E$ with $x \ne y$, there exists $f \in E^\#$ with $\map f x \ne \map f y$. If $E = \set { {\mathbf 0}_E}$ (that is, $\dim E = 0$), then there are no $x, y \in E$ with $x \ne y$, hence this holds trivially. Now ...
Algebraic Dual Separates Points of Vector Space
https://proofwiki.org/wiki/Algebraic_Dual_Separates_Points_of_Vector_Space
https://proofwiki.org/wiki/Algebraic_Dual_Separates_Points_of_Vector_Space
[ "Algebraic Duals" ]
[ "Definition:Field (Abstract Algebra)", "Definition:Vector Space", "Definition:Algebraic Dual/Vector Space", "Definition:Mappings Separating Points" ]
[ "Definition:Mappings Separating Points", "Definition:Linear Functional", "Linearly Independent Set is Contained in some Basis", "Definition:Basis of Vector Space", "Linear Transformation Defined from Basis", "Definition:Mappings Separating Points", "Category:Algebraic Duals" ]
proofwiki-22924
Linear Transformation Defined from Basis
Let $K$ be a field. Let $X$ and $Y$ be vector spaces over $K$. Let $\BB = \set {e_\alpha : \alpha \in I}$ be a basis for $X$. For each $\alpha \in I$, let $c_\alpha \in Y$. Then there exists a linear transformation $T : X \to Y$ with $T e_\alpha = c_\alpha$ for each $\alpha \in I$. This allows us to define a linear tr...
Define a mapping $T : X \to Y$ by: :$\map T { {\mathbf 0}_X} = {\mathbf 0}_Y$ and: :$\ds \map T {\sum_{\alpha \mathop \in F} \lambda_\alpha e_\alpha} = \sum_{\alpha \mathop \in F} \lambda_\alpha c_\alpha$ for every non-empty finite set $F \subseteq I$ and $\set {\lambda_\alpha : \alpha \in F} \subseteq K$. Note that t...
Let $K$ be a [[Definition:Field (Abstract Algebra)|field]]. Let $X$ and $Y$ be [[Definition:Vector Space|vector spaces]] over $K$. Let $\BB = \set {e_\alpha : \alpha \in I}$ be a [[Definition:Basis for Vector Space|basis]] for $X$. For each $\alpha \in I$, let $c_\alpha \in Y$. Then there exists a [[Definition:Li...
Define a [[Definition:Mapping|mapping]] $T : X \to Y$ by: :$\map T { {\mathbf 0}_X} = {\mathbf 0}_Y$ and: :$\ds \map T {\sum_{\alpha \mathop \in F} \lambda_\alpha e_\alpha} = \sum_{\alpha \mathop \in F} \lambda_\alpha c_\alpha$ for every [[Definition:Non-Empty Set|non-empty]] [[Definition:Finite Set|finite set]] $F \su...
Linear Transformation Defined from Basis
https://proofwiki.org/wiki/Linear_Transformation_Defined_from_Basis
https://proofwiki.org/wiki/Linear_Transformation_Defined_from_Basis
[ "Linear Algebra" ]
[ "Definition:Field (Abstract Algebra)", "Definition:Vector Space", "Definition:Basis of Vector Space", "Definition:Linear Transformation", "Definition:Linear Transformation", "Definition:Basis of Vector Space" ]
[ "Definition:Mapping", "Definition:Non-Empty Set", "Definition:Finite Set", "Definition:Basis of Vector Space", "Definition:Finite Set", "Definition:Linear Transformation", "Definition:Linear Transformation", "Category:Linear Algebra" ]
proofwiki-22925
Absolute Polar Reverses Subset Relation
Let $\GF \in \set {\R, \C}$. Let $\innerprod E F$ be a dual system over $\GF$. Let $A \subseteq B \subseteq E$ be non-empty. Let $A^\circ$ and $B^\circ$ denote the absolute polars of $A$ and $B$ in $\innerprod E F$. Then $B^\circ \subseteq A^\circ$.
Suppose that $f \in B^\circ$. Then $\cmod {\innerprod x f} \le 1$ for all $x \in B$. Since $A \subseteq B$, we in particular have $\cmod {\innerprod x f} \le 1$ for all $x \in A$. Hence $f \in A^\circ$. We have shown that if $f \in B^\circ$, then $f \in A^\circ$, so $B^\circ \subseteq A^\circ$. {{qed}}
Let $\GF \in \set {\R, \C}$. Let $\innerprod E F$ be a [[Definition:Dual System|dual system]] over $\GF$. Let $A \subseteq B \subseteq E$ be [[Definition:Non-Empty Set|non-empty]]. Let $A^\circ$ and $B^\circ$ denote the [[Definition:Absolute Polar|absolute polars]] of $A$ and $B$ in $\innerprod E F$. Then $B^\circ...
Suppose that $f \in B^\circ$. Then $\cmod {\innerprod x f} \le 1$ for all $x \in B$. Since $A \subseteq B$, we in particular have $\cmod {\innerprod x f} \le 1$ for all $x \in A$. Hence $f \in A^\circ$. We have shown that if $f \in B^\circ$, then $f \in A^\circ$, so $B^\circ \subseteq A^\circ$. {{qed}}
Absolute Polar Reverses Subset Relation
https://proofwiki.org/wiki/Absolute_Polar_Reverses_Subset_Relation
https://proofwiki.org/wiki/Absolute_Polar_Reverses_Subset_Relation
[ "Absolute Polars" ]
[ "Definition:Dual System", "Definition:Non-Empty Set", "Definition:Absolute Polar" ]
[]
proofwiki-22926
Absolute Polar of Dilation
Let $\GF \in \set {\R, \C}$. Let $\innerprod E F$ be a dual system over $\GF$. Let $A \subseteq E$ be non-empty. Let $\lambda > 0$. Let $A^\circ$ and $\paren {\lambda A}^\circ$ be the absolute polar of $A$ and $\lambda A$ respectively. Then: :$\paren {\lambda A}^\circ = \dfrac 1 \lambda A^\circ$
Let $f \in \dfrac 1 \lambda A^\circ$. This is the case {{iff}} $\lambda f \in A^\circ$. This is equivalent to $\cmod {\innerprod x {\lambda f} } \le 1$ for each $x \in A$. Since $\innerprod \cdot \cdot$ is bilinear, we have $\innerprod x {\lambda f} = \innerprod {\lambda x} f$. Hence $\cmod {\innerprod x {\lambda f} }...
Let $\GF \in \set {\R, \C}$. Let $\innerprod E F$ be a [[Definition:Dual System|dual system]] over $\GF$. Let $A \subseteq E$ be [[Definition:Non-Empty Set|non-empty]]. Let $\lambda > 0$. Let $A^\circ$ and $\paren {\lambda A}^\circ$ be the [[Definition:Absolute Polar|absolute polar]] of $A$ and $\lambda A$ respect...
Let $f \in \dfrac 1 \lambda A^\circ$. This is the case {{iff}} $\lambda f \in A^\circ$. This is equivalent to $\cmod {\innerprod x {\lambda f} } \le 1$ for each $x \in A$. Since $\innerprod \cdot \cdot$ is [[Definition:Bilinear Mapping|bilinear]], we have $\innerprod x {\lambda f} = \innerprod {\lambda x} f$. Henc...
Absolute Polar of Dilation
https://proofwiki.org/wiki/Absolute_Polar_of_Dilation
https://proofwiki.org/wiki/Absolute_Polar_of_Dilation
[ "Absolute Polars" ]
[ "Definition:Dual System", "Definition:Non-Empty Set", "Definition:Absolute Polar" ]
[ "Definition:Bilinear Mapping" ]
proofwiki-22927
Intersection of Absolute Polars is Absolute Polar of Union
Let $\GF \in \set {\R, \C}$. Let $\innerprod E F$ be a dual system over $\GF$. Let $\FF$ be a set of non-empty subsets of $E$. Then: :$\ds \bigcap_{A \in \FF} A^\circ = \paren {\bigcup_{A \in \FF} A}^\circ$ where $\circ$ denotes absolute polar.
We have: :$\ds f \in \paren {\bigcup_{A \in \FF} A}^\circ$ {{iff}}: :$\cmod {\innerprod x f} \le 1$ for each $\ds x \in \bigcup_{A \in \FF} A$ This is equivalent to: :$\cmod {\innerprod x f} \le 1$ for each $\ds x \in A$ for each $A \in \FF$. This is equivalent to $f \in A^\circ$ for each $A \in \FF$. This is equivalen...
Let $\GF \in \set {\R, \C}$. Let $\innerprod E F$ be a [[Definition:Dual System|dual system]] over $\GF$. Let $\FF$ be a [[Definition:Set|set]] of [[Definition:Non-Empty Set|non-empty]] [[Definition:Subset|subsets]] of $E$. Then: :$\ds \bigcap_{A \in \FF} A^\circ = \paren {\bigcup_{A \in \FF} A}^\circ$ where $\cir...
We have: :$\ds f \in \paren {\bigcup_{A \in \FF} A}^\circ$ {{iff}}: :$\cmod {\innerprod x f} \le 1$ for each $\ds x \in \bigcup_{A \in \FF} A$ This is equivalent to: :$\cmod {\innerprod x f} \le 1$ for each $\ds x \in A$ for each $A \in \FF$. This is equivalent to $f \in A^\circ$ for each $A \in \FF$. This is equiva...
Intersection of Absolute Polars is Absolute Polar of Union
https://proofwiki.org/wiki/Intersection_of_Absolute_Polars_is_Absolute_Polar_of_Union
https://proofwiki.org/wiki/Intersection_of_Absolute_Polars_is_Absolute_Polar_of_Union
[ "Absolute Polars" ]
[ "Definition:Dual System", "Definition:Set", "Definition:Non-Empty Set", "Definition:Subset", "Definition:Absolute Polar" ]
[]
proofwiki-22928
Absolute Polar is Non-Empty
Let $\GF \in \set {\R, \C}$. Let $\innerprod E F$ be a dual system over $\GF$. Let $A \subseteq E$ be non-empty. Let $A^\circ$ be the absolute polar of $A$. Then $A^\circ \ne \O$.
Since $\innerprod \cdot \cdot$ is bilinear, we have $\innerprod x { {\mathbf 0}_F} = 0$ for each $x \in E$. In particular, we have $\innerprod x { {\mathbf 0}_F} = 0$ for each $x \in A$. Hence ${\mathbf 0}_F \in A^\circ$, and $A^\circ \ne \O$. {{qed}}
Let $\GF \in \set {\R, \C}$. Let $\innerprod E F$ be a [[Definition:Dual System|dual system]] over $\GF$. Let $A \subseteq E$ be [[Definition:Non-Empty Set|non-empty]]. Let $A^\circ$ be the [[Definition:Absolute Polar|absolute polar]] of $A$. Then $A^\circ \ne \O$.
Since $\innerprod \cdot \cdot$ is [[Definition:Bilinear Mapping|bilinear]], we have $\innerprod x { {\mathbf 0}_F} = 0$ for each $x \in E$. In particular, we have $\innerprod x { {\mathbf 0}_F} = 0$ for each $x \in A$. Hence ${\mathbf 0}_F \in A^\circ$, and $A^\circ \ne \O$. {{qed}}
Absolute Polar is Non-Empty
https://proofwiki.org/wiki/Absolute_Polar_is_Non-Empty
https://proofwiki.org/wiki/Absolute_Polar_is_Non-Empty
[ "Absolute Polars" ]
[ "Definition:Dual System", "Definition:Non-Empty Set", "Definition:Absolute Polar" ]
[ "Definition:Bilinear Mapping" ]
proofwiki-22929
Absolute Polar is Convex
Let $\GF \in \set {\R, \C}$. Let $\innerprod E F$ be a dual system over $\GF$. Let $A \subseteq E$ be non-empty. Let $A^\circ$ be the absolute polar of $A$. Then $A^\circ$ is convex.
Let $f, g \in A^\circ$ and $t \in \closedint 0 1$. Then, for all $x \in A$ we have: :$\cmod {\innerprod x f} \le 1$ and: :$\cmod {\innerprod x g} \le 1$ Then we have: {{begin-eqn}} {{eqn | l = \cmod {\innerprod x {t f + \paren {1 - t} g} } | r = \cmod {t \innerprod x f + \paren {1 - t} \innerprod x g} | c = $\inner...
Let $\GF \in \set {\R, \C}$. Let $\innerprod E F$ be a [[Definition:Dual System|dual system]] over $\GF$. Let $A \subseteq E$ be [[Definition:Non-Empty Set|non-empty]]. Let $A^\circ$ be the [[Definition:Absolute Polar|absolute polar]] of $A$. Then $A^\circ$ is [[Definition:Convex Set (Vector Space)|convex]].
Let $f, g \in A^\circ$ and $t \in \closedint 0 1$. Then, for all $x \in A$ we have: :$\cmod {\innerprod x f} \le 1$ and: :$\cmod {\innerprod x g} \le 1$ Then we have: {{begin-eqn}} {{eqn | l = \cmod {\innerprod x {t f + \paren {1 - t} g} } | r = \cmod {t \innerprod x f + \paren {1 - t} \innerprod x g} | c = $\inn...
Absolute Polar is Convex
https://proofwiki.org/wiki/Absolute_Polar_is_Convex
https://proofwiki.org/wiki/Absolute_Polar_is_Convex
[ "Convex Sets (Vector Spaces)", "Absolute Polars", "Convex Sets (Vector Spaces)" ]
[ "Definition:Dual System", "Definition:Non-Empty Set", "Definition:Absolute Polar", "Definition:Convex Set (Vector Space)" ]
[ "Definition:Bilinear Mapping", "Definition:Convex Set (Vector Space)" ]
proofwiki-22930
Absolute Polar is Balanced
Let $\GF \in \set {\R, \C}$. Let $\innerprod E F$ be a dual system over $\GF$. Let $A \subseteq E$ be non-empty. Let $A^\circ$ be the absolute polar of $A$. Then $A^\circ$ is balanced.
Let $s \in \GF$ be such that $\cmod s \le 1$. Let $f \in A^\circ$. Then $\cmod {\innerprod x f} \le 1$ for each $x \in A$. Then: {{begin-eqn}} {{eqn | l = \cmod {\innerprod x {s f} } | r = \cmod {s \innerprod x f} | c = $\innerprod \cdot \cdot$ is bilinear }} {{eqn | r = \cmod s \cmod {\innerprod x f} }} {{eqn | o...
Let $\GF \in \set {\R, \C}$. Let $\innerprod E F$ be a [[Definition:Dual System|dual system]] over $\GF$. Let $A \subseteq E$ be [[Definition:Non-Empty Set|non-empty]]. Let $A^\circ$ be the [[Definition:Absolute Polar|absolute polar]] of $A$. Then $A^\circ$ is [[Definition:Balanced Set|balanced]].
Let $s \in \GF$ be such that $\cmod s \le 1$. Let $f \in A^\circ$. Then $\cmod {\innerprod x f} \le 1$ for each $x \in A$. Then: {{begin-eqn}} {{eqn | l = \cmod {\innerprod x {s f} } | r = \cmod {s \innerprod x f} | c = $\innerprod \cdot \cdot$ is [[Definition:Bilinear Mapping|bilinear]] }} {{eqn | r = \cmod s ...
Absolute Polar is Balanced
https://proofwiki.org/wiki/Absolute_Polar_is_Balanced
https://proofwiki.org/wiki/Absolute_Polar_is_Balanced
[ "Absolute Polars", "Balanced Sets" ]
[ "Definition:Dual System", "Definition:Non-Empty Set", "Definition:Absolute Polar", "Definition:Balanced Set" ]
[ "Definition:Bilinear Mapping" ]
proofwiki-22931
Characterization of Convergence of Net in Weak Topology Induced by Dual System
Let $K$ be a topological field. Let $\innerprod X {X'}$ be a dual system over $K$. Let $\map \sigma {X, X'}$ be the weak topology on $X$ induced by $\innerprod X {X'}$. Let $\struct {\Lambda, \preceq}$ be a directed set. Let $\family {x_\lambda}_{\lambda \mathop \in \Lambda}$ be a net in $X$. Let $x \in X$. Then $\fam...
For each $x' \in X'$, define $f_{x'} : X \to \GF$ by: :$\map {f_{x'} } x = \innerprod x {x'}$ for each $x \in X$. Let $F = \set {f_{x'} : x' \in X'}$. By the definition of the weak topology on $X$ induced by $\innerprod X {X'}$, $\map \sigma {X, X'}$ is the initial topology on $X$ induced by $F$. By Characterization o...
Let $K$ be a [[Definition:Topological Field|topological field]]. Let $\innerprod X {X'}$ be a [[Definition:Dual System|dual system]] over $K$. Let $\map \sigma {X, X'}$ be the [[Definition:Weak Topology Induced by Dual System|weak topology on $X$ induced by $\innerprod X {X'}$]]. Let $\struct {\Lambda, \preceq}$ be...
For each $x' \in X'$, define $f_{x'} : X \to \GF$ by: :$\map {f_{x'} } x = \innerprod x {x'}$ for each $x \in X$. Let $F = \set {f_{x'} : x' \in X'}$. By the definition of the [[Definition:Weak Topology Induced by Dual System|weak topology on $X$ induced by $\innerprod X {X'}$]], $\map \sigma {X, X'}$ is the [[Defin...
Characterization of Convergence of Net in Weak Topology Induced by Dual System
https://proofwiki.org/wiki/Characterization_of_Convergence_of_Net_in_Weak_Topology_Induced_by_Dual_System
https://proofwiki.org/wiki/Characterization_of_Convergence_of_Net_in_Weak_Topology_Induced_by_Dual_System
[ "Weak Topologies Induced by Dual Systems", "Nets (Set Theory)" ]
[ "Definition:Topological Field", "Definition:Dual System", "Definition:Weak Topology Induced by Dual System", "Definition:Directed Preordering", "Definition:Net (Set Theory)", "Definition:Convergent Net" ]
[ "Definition:Weak Topology Induced by Dual System", "Definition:Initial Topology", "Characterization of Convergence of Net in Initial Topology", "Category:Weak Topologies Induced by Dual Systems", "Category:Nets (Set Theory)" ]
proofwiki-22932
Open Set in Initial Topology on Vector Space Induced by Linear Functionals
Let $\GF \in \set {\R, \C}$. Let $E$ be a vector space over $\GF$. Let $E^\#$ be the algebraic dual of $E$. Let $F \subseteq E^\#$ be a vector subspace. Let $\tau$ be the initial topology on $E$ induced by $F$. Let $U \subseteq E$. Then $U$ is open in $\struct {X, \tau}$ {{iff}} for each $x \in X$ there exists $\epsil...
From Initial Topology on Vector Space Generated by Linear Functionals is Locally Convex, $\tau$ is generated by the seminorms: :$\set {p_f : f \in F}$ where we define $p_f : X \to \R_{\ge 0}$ by: :$\map {p_f} x = \cmod {\map f x}$ for each $x \in X$. Then, from Open Sets in Standard Topology of Locally Convex Space, $...
Let $\GF \in \set {\R, \C}$. Let $E$ be a [[Definition:Vector Space|vector space]] over $\GF$. Let $E^\#$ be the [[Definition:Algebraic Dual|algebraic dual]] of $E$. Let $F \subseteq E^\#$ be a [[Definition:Vector Subspace|vector subspace]]. Let $\tau$ be the [[Definition:Initial Topology|initial topology on $E$ in...
From [[Initial Topology on Vector Space Generated by Linear Functionals is Locally Convex]], $\tau$ is [[Definition:Locally Convex Space/Standard Topology|generated]] by the [[Definition:Seminorm|seminorms]]: :$\set {p_f : f \in F}$ where we define $p_f : X \to \R_{\ge 0}$ by: :$\map {p_f} x = \cmod {\map f x}$ for ea...
Open Set in Initial Topology on Vector Space Induced by Linear Functionals
https://proofwiki.org/wiki/Open_Set_in_Initial_Topology_on_Vector_Space_Induced_by_Linear_Functionals
https://proofwiki.org/wiki/Open_Set_in_Initial_Topology_on_Vector_Space_Induced_by_Linear_Functionals
[ "Initial Topology" ]
[ "Definition:Vector Space", "Definition:Algebraic Dual", "Definition:Vector Subspace", "Definition:Initial Topology", "Definition:Open Set" ]
[ "Initial Topology on Vector Space Generated by Linear Functionals is Locally Convex", "Definition:Locally Convex Space/Standard Topology", "Definition:Seminorm", "Open Sets in Standard Topology of Locally Convex Space", "Definition:Open Set", "Definition:Linear Functional", "Category:Initial Topology" ]
proofwiki-22933
Characterization of von Neumann-Boundedness in Weak Topology Induced by Dual System
Let $\GF \in \set {\R, \C}$. Let $\innerprod X {X'}$ be a dual system over $\GF$. Let $\map \sigma {X, X'}$ be the weak topology on $X$ induced by $X'$. Let $E \subseteq X$. Then $E$ is von Neumann-bounded in $\struct {X, \map \sigma {X, X'} }$ {{iff}} for each $x' \in X'$ we have: :$\ds \sup_{x \mathop \in E} \cmod {\...
For each $x' \in X'$, define $f_{x'} : X \to \GF$ by: :$\map {f_{x'} } x = \innerprod x {x'}$ for each $x \in X$. Let $F = \set {f_{x'} : x' \in X'}$. By the definition of the weak topology on $X$ induced by $X'$, $\map \sigma {X, X'}$ is the initial topology on $X$ generated by $F$. By Characterization of von Neumann-...
Let $\GF \in \set {\R, \C}$. Let $\innerprod X {X'}$ be a [[Definition:Dual System|dual system]] over $\GF$. Let $\map \sigma {X, X'}$ be the [[Definition:Weak Topology Induced by Dual System|weak topology on $X$ induced by $X'$]]. Let $E \subseteq X$. Then $E$ is [[Definition:Von Neumann-Bounded Subset of Topolog...
For each $x' \in X'$, define $f_{x'} : X \to \GF$ by: :$\map {f_{x'} } x = \innerprod x {x'}$ for each $x \in X$. Let $F = \set {f_{x'} : x' \in X'}$. By the definition of the [[Definition:Weak Topology Induced by Dual System|weak topology on $X$ induced by $X'$]], $\map \sigma {X, X'}$ is the [[Definition:Initial To...
Characterization of von Neumann-Boundedness in Weak Topology Induced by Dual System
https://proofwiki.org/wiki/Characterization_of_von_Neumann-Boundedness_in_Weak_Topology_Induced_by_Dual_System
https://proofwiki.org/wiki/Characterization_of_von_Neumann-Boundedness_in_Weak_Topology_Induced_by_Dual_System
[ "Von Neumann-Bounded Subsets of Topological Vector Spaces", "Dual Systems" ]
[ "Definition:Dual System", "Definition:Weak Topology Induced by Dual System", "Definition:Von Neumann-Bounded Subset of Topological Vector Space" ]
[ "Definition:Weak Topology Induced by Dual System", "Definition:Initial Topology", "Characterization of von Neumann-Boundedness in Initial Topology on Vector Space Induced by Linear Functionals", "Definition:Von Neumann-Bounded Subset of Topological Vector Space", "Category:Von Neumann-Bounded Subsets of Top...
proofwiki-22934
Characterization of von Neumann-Boundedness in Weak-* Topology Induced by Dual System
Let $\GF \in \set {\R, \C}$. Let $\innerprod X {X'}$ be a dual system over $\GF$. Let $\map \sigma {X', X}$ be the weak topology on $X'$ induced by $X$. Let $E' \subseteq X'$. Then $E'$ is von Neumann-bounded in $\struct {X', \map \sigma {X', X} }$ {{iff}} for each $x \in X$ we have: :$\ds \sup_{x' \mathop \in E'} \cmo...
For each $x \in X$, define $\pi_x : X' \to K$ by: :$\map {\pi_x} {x'} = \innerprod x {x'}$ for each $x \in X$. Let: :$F = \set {\pi_x : x \in X}$ By the definition of the weak topology on $X'$ induced by $\innerprod X {X'}$, $\map \sigma {X', X}$ is the initial topology on $X$ generated by $F$. By Characterization of v...
Let $\GF \in \set {\R, \C}$. Let $\innerprod X {X'}$ be a [[Definition:Dual System|dual system]] over $\GF$. Let $\map \sigma {X', X}$ be the [[Definition:Weak Topology Induced by Dual System|weak topology on $X'$ induced by $X$]]. Let $E' \subseteq X'$. Then $E'$ is [[Definition:Von Neumann-Bounded Subset of Topo...
For each $x \in X$, define $\pi_x : X' \to K$ by: :$\map {\pi_x} {x'} = \innerprod x {x'}$ for each $x \in X$. Let: :$F = \set {\pi_x : x \in X}$ By the definition of the [[Definition:Weak Topology Induced by Dual System|weak topology on $X'$ induced by $\innerprod X {X'}$]], $\map \sigma {X', X}$ is the [[Definition...
Characterization of von Neumann-Boundedness in Weak-* Topology Induced by Dual System
https://proofwiki.org/wiki/Characterization_of_von_Neumann-Boundedness_in_Weak-*_Topology_Induced_by_Dual_System
https://proofwiki.org/wiki/Characterization_of_von_Neumann-Boundedness_in_Weak-*_Topology_Induced_by_Dual_System
[ "Von Neumann-Bounded Subsets of Topological Vector Spaces", "Dual Systems" ]
[ "Definition:Dual System", "Definition:Weak Topology Induced by Dual System", "Definition:Von Neumann-Bounded Subset of Topological Vector Space" ]
[ "Definition:Weak Topology Induced by Dual System", "Definition:Initial Topology", "Characterization of von Neumann-Boundedness in Initial Topology on Vector Space Induced by Linear Functionals", "Definition:Von Neumann-Bounded Subset of Topological Vector Space", "Category:Von Neumann-Bounded Subsets of Top...
proofwiki-22935
Transpose of Dual System is Dual System
Let $K$ be a field. Let $\innerprod E F_{E \times F}$ be a dual system over $K$. Define a mapping $\innerprod \cdot \cdot_{F \times E} : F \times E \to K$ by: :$\innerprod f x_{F \times E} = \innerprod x f_{E \times F}$ Then $\innerprod F E_{F \times E}$ is a dual system over $K$.
By Transpose of Bilinear Mapping is Bilinear Mapping, $\innerprod \cdot \cdot_{F \times E}$ is a bilinear mapping. Suppose that $f_0 \in F$ is such that: :$\innerprod {f_0} x_{F \times E} = {\mathbf 0}_K$ for each $x \in E$. Then we have: :$\innerprod x {f_0}_{E \times F} = {\mathbf 0}_K$ Since $\innerprod \cdot \cdot_...
Let $K$ be a [[Definition:Field (Abstract Algebra)|field]]. Let $\innerprod E F_{E \times F}$ be a [[Definition:Dual System|dual system]] over $K$. Define a [[Definition:Mapping|mapping]] $\innerprod \cdot \cdot_{F \times E} : F \times E \to K$ by: :$\innerprod f x_{F \times E} = \innerprod x f_{E \times F}$ Then $...
By [[Transpose of Bilinear Mapping is Bilinear Mapping]], $\innerprod \cdot \cdot_{F \times E}$ is a [[Definition:Bilinear Mapping|bilinear mapping]]. Suppose that $f_0 \in F$ is such that: :$\innerprod {f_0} x_{F \times E} = {\mathbf 0}_K$ for each $x \in E$. Then we have: :$\innerprod x {f_0}_{E \times F} = {\mathb...
Transpose of Dual System is Dual System
https://proofwiki.org/wiki/Transpose_of_Dual_System_is_Dual_System
https://proofwiki.org/wiki/Transpose_of_Dual_System_is_Dual_System
[ "Dual Systems" ]
[ "Definition:Field (Abstract Algebra)", "Definition:Dual System", "Definition:Mapping", "Definition:Dual System" ]
[ "Transpose of Bilinear Mapping is Bilinear Mapping", "Definition:Bilinear Mapping", "Definition:Dual System", "Definition:Dual System", "Category:Dual Systems" ]
proofwiki-22936
Absolute Prepolar is Absolute Polar in Transpose
Let $\GF \in \set {\R, \C}$. Let $\innerprod E F_{E \times F}$ be a dual system over $\GF$. Let $\innerprod F E_{F \times E}$ be the transpose dual system. Let $B \subseteq F$ be a non-empty set. Let $B_\circ$ be the absolute prepolar of $B$ taken in $\innerprod E F_{E \times F}$. Let $B^{\circ^T}$ be the absolute pola...
We have: {{begin-eqn}} {{eqn | l = B_\circ | r = \set {x \in E : \cmod {\innerprod x f_{E \times F} } \le 1 \text { for all } f \in B} }} {{eqn | r = \set {x \in E : \cmod {\innerprod f x_{F \times E} } \le 1 \text { for all } f \in B} }} {{eqn | r = B^{\circ^T} }} {{end-eqn}} {{qed}} Category:Absolute Polars Categor...
Let $\GF \in \set {\R, \C}$. Let $\innerprod E F_{E \times F}$ be a [[Definition:Dual System|dual system]] over $\GF$. Let $\innerprod F E_{F \times E}$ be the [[Definition:Transpose Dual System|transpose dual system]]. Let $B \subseteq F$ be a [[Definition:Non-Empty Set|non-empty set]]. Let $B_\circ$ be the [[Defi...
We have: {{begin-eqn}} {{eqn | l = B_\circ | r = \set {x \in E : \cmod {\innerprod x f_{E \times F} } \le 1 \text { for all } f \in B} }} {{eqn | r = \set {x \in E : \cmod {\innerprod f x_{F \times E} } \le 1 \text { for all } f \in B} }} {{eqn | r = B^{\circ^T} }} {{end-eqn}} {{qed}} [[Category:Absolute Polars]] [[...
Absolute Prepolar is Absolute Polar in Transpose
https://proofwiki.org/wiki/Absolute_Prepolar_is_Absolute_Polar_in_Transpose
https://proofwiki.org/wiki/Absolute_Prepolar_is_Absolute_Polar_in_Transpose
[ "Absolute Polars", "Absolute Prepolars" ]
[ "Definition:Dual System", "Definition:Transpose Dual System", "Definition:Non-Empty Set", "Definition:Absolute Prepolar", "Definition:Absolute Polar" ]
[ "Category:Absolute Polars", "Category:Absolute Prepolars" ]
proofwiki-22937
Weak Topology on Transpose Dual System is Weak-* Topology on Original System
Let $\GF \in \set {\R, \C}$. Let $\innerprod E F_{E \times F}$ be a dual system over $\GF$. Let $\innerprod F E_{F \times E}$ be the transpose of $\innerprod E F_{E \times F}$. Let $\tau_1$ be the weak topology on $F$ induced by $\innerprod F E_{F \times E}$. Let $\tau_2$ be the weak-$\ast$ topology on $F$ induced by ...
For each $x \in E$, define the mapping $g_x : F \to K$ by: :$\map {g_x} f = \innerprod f x_{F \times E} = \innerprod x f_{E \times F}$ for each $\tuple {f, x} \in F \times E$. By the definition of the weak topology on $F$, $\tau_1$ is the initial topology induced by $\set {g_x : x \in E}$. For each $x \in E$, define a ...
Let $\GF \in \set {\R, \C}$. Let $\innerprod E F_{E \times F}$ be a [[Definition:Dual System|dual system]] over $\GF$. Let $\innerprod F E_{F \times E}$ be the [[Definition:Transpose of Dual System|transpose]] of $\innerprod E F_{E \times F}$. Let $\tau_1$ be the [[Definition:Weak Topology Induced by Dual System|wea...
For each $x \in E$, define the [[Definition:Mapping|mapping]] $g_x : F \to K$ by: :$\map {g_x} f = \innerprod f x_{F \times E} = \innerprod x f_{E \times F}$ for each $\tuple {f, x} \in F \times E$. By the definition of the [[Definition:Weak Topology Induced by Dual System|weak topology]] on $F$, $\tau_1$ is [[Definit...
Weak Topology on Transpose Dual System is Weak-* Topology on Original System
https://proofwiki.org/wiki/Weak_Topology_on_Transpose_Dual_System_is_Weak-*_Topology_on_Original_System
https://proofwiki.org/wiki/Weak_Topology_on_Transpose_Dual_System_is_Weak-*_Topology_on_Original_System
[ "Weak Topologies Induced by Dual Systems", "Weak-* Topologies Induced by Dual Systems" ]
[ "Definition:Dual System", "Definition:Transpose of Dual System", "Definition:Weak Topology Induced by Dual System", "Definition:Weak-* Topology Induced by Dual System", "Definition:Topology" ]
[ "Definition:Mapping", "Definition:Weak Topology Induced by Dual System", "Definition:Initial Topology", "Definition:Mapping", "Definition:Weak-* Topology Induced by Dual System", "Definition:Initial Topology", "Category:Weak Topologies Induced by Dual Systems", "Category:Weak-* Topologies Induced by D...
proofwiki-22938
Bipolar Set contains Original Set
Let $\GF \in \set {\R, \C}$. Let $\innerprod X {X'}$ be a dual system over $\GF$. Let $A \subseteq X$ be a non-empty set. Let $\paren {A^\circ}_\circ$ be the bipolar of $A$. Then: :$A \subseteq \paren {A^\circ}_\circ$
We have $x \in \paren {A^\circ}_\circ$ {{iff}}: :$\cmod {\innerprod x f} \le 1$ for each $f \in A^\circ$. We have that $f \in A^\circ$ {{iff}}: :$\cmod {\innerprod x f} \le 1$ for each $x \in A$. Hence for $x \in A$, we have: :$\cmod {\innerprod x f} \le 1$ for each $f \in A^\circ$. Hence $x \in \paren {A^\circ}_\circ...
Let $\GF \in \set {\R, \C}$. Let $\innerprod X {X'}$ be a [[Definition:Dual System|dual system]] over $\GF$. Let $A \subseteq X$ be a [[Definition:Non-Empty Set|non-empty set]]. Let $\paren {A^\circ}_\circ$ be the [[Definition:Bipolar Set|bipolar]] of $A$. Then: :$A \subseteq \paren {A^\circ}_\circ$
We have $x \in \paren {A^\circ}_\circ$ {{iff}}: :$\cmod {\innerprod x f} \le 1$ for each $f \in A^\circ$. We have that $f \in A^\circ$ {{iff}}: :$\cmod {\innerprod x f} \le 1$ for each $x \in A$. Hence for $x \in A$, we have: :$\cmod {\innerprod x f} \le 1$ for each $f \in A^\circ$. Hence $x \in \paren {A^\circ}_\c...
Bipolar Set contains Original Set
https://proofwiki.org/wiki/Bipolar_Set_contains_Original_Set
https://proofwiki.org/wiki/Bipolar_Set_contains_Original_Set
[ "Bipolar Sets" ]
[ "Definition:Dual System", "Definition:Non-Empty Set", "Definition:Bipolar Set" ]
[ "Category:Bipolar Sets" ]
proofwiki-22939
Alaoglu-Bourbaki Theorem
Let $\GF \in \set {\R, \C}$. Let $\innerprod E F$ be a dual system over $\GF$. Let $\map \sigma {E, F}$ be the weak topology on $E$ induced by $\innerprod E F$. Let $V \subseteq E$ be a neighborhood of ${\mathbf 0}_X$ in $\map \sigma {E, F}$. Let $V^\circ$ be the absolute polar of $V$. Let $\map \sigma {F, E}$ be the w...
Let: :$B = \set {z \in \C : \cmod z \le 1}$ By the Heine-Borel Theorem: Normed Vector Space, we have that $B$ is compact. Hence by Tychonoff's Theorem, we have that: :$\ds X = \prod_{x \mathop \in V} B$, equipped with the product topology $\tau_X$, is compact. For each $f \in V^\circ$, define $\pi_f : E \to \GF$ by: :...
Let $\GF \in \set {\R, \C}$. Let $\innerprod E F$ be a [[Definition:Dual System|dual system]] over $\GF$. Let $\map \sigma {E, F}$ be the [[Definition:Weak Topology Induced by Dual System|weak topology]] on $E$ induced by $\innerprod E F$. Let $V \subseteq E$ be a [[Definition:Neighborhood (Topology)|neighborhood]] ...
Let: :$B = \set {z \in \C : \cmod z \le 1}$ By the [[Heine-Borel Theorem/Normed Vector Space|Heine-Borel Theorem: Normed Vector Space]], we have that $B$ is [[Definition:Compact Topological Space|compact]]. Hence by [[Tychonoff's Theorem]], we have that: :$\ds X = \prod_{x \mathop \in V} B$, equipped with the [[Defi...
Alaoglu-Bourbaki Theorem
https://proofwiki.org/wiki/Alaoglu-Bourbaki_Theorem
https://proofwiki.org/wiki/Alaoglu-Bourbaki_Theorem
[ "Dual Systems", "Weak-* Topologies Induced by Dual Systems" ]
[ "Definition:Dual System", "Definition:Weak Topology Induced by Dual System", "Definition:Neighborhood (Topology)", "Definition:Absolute Polar", "Definition:Weak-* Topology Induced by Dual System", "Definition:Compact Topological Space" ]
[ "Heine-Borel Theorem/Normed Vector Space", "Definition:Compact Topological Space", "Tychonoff's Theorem", "Definition:Product Topology", "Definition:Compact Topological Space", "Definition:Mapping", "Definition:Mapping", "Definition:Homeomorphism", "Definition:Injection", "Definition:Open Neighbor...
proofwiki-22940
Equivalence of Definitions of Boolean Lattice/Definition 2 implies Definition 1
Let $\struct {S, \vee, \wedge, \neg}$ be a Boolean algebra. Let $\struct {S, \vee, \wedge, \preceq}$ be an ordered structure. Suppose that: :$\forall a, b \in S: a \wedge b \preceq a \vee b$ Then, $\struct {S, \vee, \wedge, \preceq}$ is a complemented distributive lattice.
By axiom $\paren {\text {BA}_1 3}$, let $\bot, \top \in S$ denote the identities of $\vee$ and $\wedge$, respectively. We will first show that $\struct {S, \vee, \wedge, \preceq}$ is a lattice. By definition 2, we must prove that, for all $a, b \in S$: :$a \vee b$ is the join of $a$ and $b$ :$a \wedge b$ is the meet of...
Let $\struct {S, \vee, \wedge, \neg}$ be a [[Definition:Boolean Algebra|Boolean algebra]]. Let $\struct {S, \vee, \wedge, \preceq}$ be an [[Definition:Ordered Structure|ordered structure]]. Suppose that: :$\forall a, b \in S: a \wedge b \preceq a \vee b$ Then, $\struct {S, \vee, \wedge, \preceq}$ is a [[Definition:...
By [[Axiom:Boolean Algebra/Axioms/Formulation 1|axiom $\paren {\text {BA}_1 3}$]], let $\bot, \top \in S$ denote the [[Definition:Identity Element|identities]] of $\vee$ and $\wedge$, respectively. We will first show that $\struct {S, \vee, \wedge, \preceq}$ is a [[Definition:Lattice (Order Theory)|lattice]]. By [[De...
Equivalence of Definitions of Boolean Lattice/Definition 2 implies Definition 1
https://proofwiki.org/wiki/Equivalence_of_Definitions_of_Boolean_Lattice/Definition_2_implies_Definition_1
https://proofwiki.org/wiki/Equivalence_of_Definitions_of_Boolean_Lattice/Definition_2_implies_Definition_1
[]
[ "Definition:Boolean Algebra", "Definition:Ordered Structure", "Definition:Complemented Lattice", "Definition:Distributive Lattice" ]
[ "Axiom:Boolean Algebra/Axioms/Formulation 1", "Definition:Identity (Abstract Algebra)/Two-Sided Identity", "Definition:Lattice (Order Theory)", "Definition:Lattice (Order Theory)/Definition 2", "Definition:Join (Order Theory)", "Definition:Meet (Order Theory)", "Identities of Boolean Algebra are also Ze...
proofwiki-22941
Boolean Lattice as Boolean Algebra
Let $\struct {S, \vee, \wedge, \preceq}$ be a Boolean lattice by definition $1$. Then, there is a unique unary operation: :$\neg : S \to S$ such that $\struct {S, \vee, \wedge, \neg}$ forms a Boolean algebra. In particular, for each $a \in S$, we will have $\neg a$ be the complement of $a$.
Let $\neg a$ be defined as the unique complement of $a$ in $S$, if such an element exists. By definition of a lattice, $a \vee b$ and $a \wedge b$ are defined in $S$ for all $a, b \in S$. Moreover, by Complement in Boolean Lattice is Unique, $\neg a$ exists in $S$ for every $a \in S$. So, axiom $\paren {\text {BA}_1 0}...
Let $\struct {S, \vee, \wedge, \preceq}$ be a [[Definition:Boolean Lattice/Definition 1|Boolean lattice by definition $1$]]. Then, there is a [[Definition:Unique|unique]] [[Definition:Unary Operation|unary operation]]: :$\neg : S \to S$ such that $\struct {S, \vee, \wedge, \neg}$ forms a [[Definition:Boolean Algebra|B...
Let $\neg a$ be defined as the [[Definition:Unique|unique]] [[Definition:Complement (Lattice Theory)|complement]] of $a$ in $S$, if such an element exists. By definition of a [[Definition:Lattice (Order Theory)/Definition 1|lattice]], $a \vee b$ and $a \wedge b$ are defined in $S$ for all $a, b \in S$. Moreover, by ...
Boolean Lattice as Boolean Algebra
https://proofwiki.org/wiki/Boolean_Lattice_as_Boolean_Algebra
https://proofwiki.org/wiki/Boolean_Lattice_as_Boolean_Algebra
[ "Boolean Algebra is Equivalent to Boolean Lattice", "Boolean Algebras", "Boolean Lattices" ]
[ "Definition:Boolean Lattice/Definition 1", "Definition:Unique", "Definition:Operation/Unary Operation", "Definition:Boolean Algebra", "Definition:Complement (Lattice Theory)" ]
[ "Definition:Unique", "Definition:Complement (Lattice Theory)", "Definition:Lattice (Order Theory)/Definition 1", "Complement in Distributive Lattice is Unique/Corollary", "Axiom:Boolean Algebra/Axioms/Formulation 1", "Join is Commutative", "Meet is Commutative", "Axiom:Boolean Algebra/Axioms/Formulati...
proofwiki-22942
Equivalence of Definitions of Boolean Lattice/Definition 1 implies Definition 3
Let $\struct {S, \vee, \wedge, \preceq}$ be a complemented distributive lattice. Then, there is a unary operation $\neg$ on $S$ such that: :$\paren 1: \quad \forall a, b \in S: a \preceq \neg b \iff a \wedge b = \bot$ :$\paren 2: \quad \forall a \in S: \neg \neg a = a$
Fix $a, b \in S$, and suppose that $a \preceq \neg b$. Then, by Meet Precedes Operands: :$a \wedge b \preceq a \preceq \neg b$ :$a \wedge b \preceq b$ so by definition of meet: :$a \wedge b \preceq \neg b \wedge b$ Since $\neg b$ is the complement of $b$: :$\neg b \wedge b = \bot$ hence: :$a \wedge b \preceq \bot$ But ...
Let $\struct {S, \vee, \wedge, \preceq}$ be a [[Definition:Complemented Lattice|complemented]] [[Definition:Distributive Lattice|distributive lattice]]. Then, there is a [[Definition:Unary Operation|unary operation]] $\neg$ on $S$ such that: :$\paren 1: \quad \forall a, b \in S: a \preceq \neg b \iff a \wedge b = \bot...
Fix $a, b \in S$, and suppose that $a \preceq \neg b$. Then, by [[Meet Precedes Operands]]: :$a \wedge b \preceq a \preceq \neg b$ :$a \wedge b \preceq b$ so by definition of [[Definition:Meet (Order Theory)|meet]]: :$a \wedge b \preceq \neg b \wedge b$ Since $\neg b$ is the [[Definition:Complement (Lattice Theory)|c...
Equivalence of Definitions of Boolean Lattice/Definition 1 implies Definition 3
https://proofwiki.org/wiki/Equivalence_of_Definitions_of_Boolean_Lattice/Definition_1_implies_Definition_3
https://proofwiki.org/wiki/Equivalence_of_Definitions_of_Boolean_Lattice/Definition_1_implies_Definition_3
[]
[ "Definition:Complemented Lattice", "Definition:Distributive Lattice", "Definition:Operation/Unary Operation" ]
[ "Meet Precedes Operands", "Definition:Meet (Order Theory)", "Definition:Complement (Lattice Theory)", "Definition:Bottom of Lattice", "Definition:Smallest Element", "Join Succeeds Operands", "Complement in Boolean Algebra is Unique", "Definition:Uniquely Complemented Lattice", "Complement of Complem...
proofwiki-22943
Mass of Body with given Density
Let $\BB$ be a body occupying a region $V$ of space. Let $\map \rho {\mathbf r}$ denote the (mass) density of $\BB$ at the point within $V$ whose position vector is $\mathbf r$. Then the mass $m$ of $\BB$ is given by: :$m = \ds \int_V \map \rho {\mathbf r} \rd V$
To find the total mass of $\BB$, divide it into many finite regions $\set {\Delta \BB_i}$ each with a volume $\Delta V_i$. Within each $\Delta \BB_i$, choose a point $\mathbf r_i$. Let the density of $\Delta \BB_i$ be uniform and given by $\map \rho {\mathbf r_i}$. Thus, the mass of $\Delta \BB_i$ is: :$\Delta m_i = \m...
Let $\BB$ be a [[Definition:Body|body]] occupying a [[Definition:Region|region]] $V$ of [[Definition:Ordinary Space|space]]. Let $\map \rho {\mathbf r}$ denote the [[Definition:Mass Density|(mass) density]] of $\BB$ at the [[Definition:Point|point]] within $V$ whose [[Definition:Position Vector|position vector]] is $\...
To find the total [[Definition:Mass|mass]] of $\BB$, [[Definition:Subdivision of Interval|divide]] it into many [[Definition:Finite|finite]] [[Definition:Region|regions]] $\set {\Delta \BB_i}$ each with a [[Definition:Volume|volume]] $\Delta V_i$. Within each $\Delta \BB_i$, choose a [[Definition:Point|point]] $\math...
Mass of Body with given Density
https://proofwiki.org/wiki/Mass_of_Body_with_given_Density
https://proofwiki.org/wiki/Mass_of_Body_with_given_Density
[ "Mass Density", "Mass" ]
[ "Definition:Body", "Definition:Region", "Definition:Ordinary Space", "Definition:Mass Density", "Definition:Point", "Definition:Position Vector", "Definition:Mass" ]
[ "Definition:Mass", "Definition:Subdivision of Interval", "Definition:Finite", "Definition:Region", "Definition:Volume", "Definition:Point", "Definition:Mass Density", "Definition:Uniform", "Definition:Mass", "Definition:Mass", "Definition:Summation", "Definition:Mass", "Definition:Mass", "...
proofwiki-22944
Expression for Balanced Hull
Let $\GF \in \set {\R, \C}$. Let $X$ be a vector space over $\GF$. Let $A \subseteq X$ be non-empty.. Then the balanced hull $\map {\operatorname {bal} } A$ is well-defined and: :$\ds \map {\operatorname {bal} } A = \bigcup_{\lambda \in \GF : \cmod \lambda \le 1} \lambda A$
We first show that: :$\ds B = \bigcup_{\lambda \in \GF : \cmod \lambda \le 1} \lambda A$ is a balanced set containing $A$. Let $x \in B$ and $\mu \in \GF$ be such that $\cmod \mu \le 1$. Since $x \in B$, there exists $\lambda \in \GF$ with $\cmod \lambda \le 1$ and $y \in A$ such that $x = \lambda y$. Then $\mu x = \l...
Let $\GF \in \set {\R, \C}$. Let $X$ be a [[Definition:Vector Space|vector space]] over $\GF$. Let $A \subseteq X$ be [[Definition:Non-Empty Set|non-empty]].. Then the [[Definition:Balanced Hull|balanced hull]] $\map {\operatorname {bal} } A$ is well-defined and: :$\ds \map {\operatorname {bal} } A = \bigcup_{\lamb...
We first show that: :$\ds B = \bigcup_{\lambda \in \GF : \cmod \lambda \le 1} \lambda A$ is a [[Definition:Balanced Set|balanced set]] containing $A$. Let $x \in B$ and $\mu \in \GF$ be such that $\cmod \mu \le 1$. Since $x \in B$, there exists $\lambda \in \GF$ with $\cmod \lambda \le 1$ and $y \in A$ such that $x ...
Expression for Balanced Hull
https://proofwiki.org/wiki/Expression_for_Balanced_Hull
https://proofwiki.org/wiki/Expression_for_Balanced_Hull
[ "Balanced Sets" ]
[ "Definition:Vector Space", "Definition:Non-Empty Set", "Definition:Balanced Hull" ]
[ "Definition:Balanced Set", "Definition:Balanced Set", "Definition:Balanced Set", "Definition:Balanced Set", "Definition:Balanced Set", "Definition:Smallest Element", "Definition:Balanced Set", "Definition:Balanced Hull", "Category:Balanced Sets" ]
proofwiki-22945
Balanced Hull is Intersection of Balanced Sets containing Set
Let $\GF \in \set {\R, \C}$. Let $X$ be a vector space over $\GF$. Let $A \subseteq X$ be a non-empty set. Let $\map {\operatorname {bal} } A$ be the balanced hull of $A$. Then: :$\ds \map {\operatorname {bal} } A = \bigcap \set {B \supseteq A: B \text { is balanced} }$
Note that: :$\map {\operatorname {bal} } A \in \set {B \supseteq A: B \text { is balanced} }$ and hence: :$\set {B \supseteq A: B \text { is balanced} } \ne \O$ Hence: :$\ds \bigcap \set {B \supseteq A: B \text { is balanced} }$ is well-defined. Further, from Intersection of Balanced Sets in Vector Space is Balanced, w...
Let $\GF \in \set {\R, \C}$. Let $X$ be a [[Definition:Vector Space|vector space]] over $\GF$. Let $A \subseteq X$ be a [[Definition:Non-Empty Set|non-empty set]]. Let $\map {\operatorname {bal} } A$ be the [[Definition:Balanced Hull|balanced hull]] of $A$. Then: :$\ds \map {\operatorname {bal} } A = \bigcap \set ...
Note that: :$\map {\operatorname {bal} } A \in \set {B \supseteq A: B \text { is balanced} }$ and hence: :$\set {B \supseteq A: B \text { is balanced} } \ne \O$ Hence: :$\ds \bigcap \set {B \supseteq A: B \text { is balanced} }$ is well-defined. Further, from [[Intersection of Balanced Sets in Vector Space is Balance...
Balanced Hull is Intersection of Balanced Sets containing Set
https://proofwiki.org/wiki/Balanced_Hull_is_Intersection_of_Balanced_Sets_containing_Set
https://proofwiki.org/wiki/Balanced_Hull_is_Intersection_of_Balanced_Sets_containing_Set
[ "Balanced Sets" ]
[ "Definition:Vector Space", "Definition:Non-Empty Set", "Definition:Balanced Hull" ]
[ "Intersection of Balanced Sets in Vector Space is Balanced", "Definition:Balanced Set", "Definition:Smallest Element", "Definition:Balanced Set", "Category:Balanced Sets" ]
proofwiki-22946
Convex Hull of Balanced Set is Balanced
Let $\GF \in \set {\R, \C}$. Let $X$ be a vector space over $\GF$. Let $B \subseteq X$ be a balanced set. Let $\map {\operatorname {conv} } B$ be the convex hull of $B$. Then $\map {\operatorname {conv} } B$ is balanced.
Let $x \in \map {\operatorname {conv} } B$ and $\lambda \in \GF$ have $\cmod \lambda \le 1$. Then there exists $x_1, \ldots, x_n \in B$ and $t_1, \ldots, t_n \in \closedint 0 1$ such that: :$\ds x = \sum_{j \mathop = 1}^n t_j x_j$ Then: :$\ds \lambda x = \sum_{j \mathop = 1}^n t_j \paren {\lambda x_j}$ Since $B$ is ba...
Let $\GF \in \set {\R, \C}$. Let $X$ be a [[Definition:Vector Space|vector space]] over $\GF$. Let $B \subseteq X$ be a [[Definition:Balanced Set|balanced set]]. Let $\map {\operatorname {conv} } B$ be the [[Definition:Convex Hull|convex hull]] of $B$. Then $\map {\operatorname {conv} } B$ is [[Definition:Balanced...
Let $x \in \map {\operatorname {conv} } B$ and $\lambda \in \GF$ have $\cmod \lambda \le 1$. Then there exists $x_1, \ldots, x_n \in B$ and $t_1, \ldots, t_n \in \closedint 0 1$ such that: :$\ds x = \sum_{j \mathop = 1}^n t_j x_j$ Then: :$\ds \lambda x = \sum_{j \mathop = 1}^n t_j \paren {\lambda x_j}$ Since $B$ is...
Convex Hull of Balanced Set is Balanced
https://proofwiki.org/wiki/Convex_Hull_of_Balanced_Set_is_Balanced
https://proofwiki.org/wiki/Convex_Hull_of_Balanced_Set_is_Balanced
[ "Convex Sets (Vector Spaces)", "Balanced Sets" ]
[ "Definition:Vector Space", "Definition:Balanced Set", "Definition:Convex Hull", "Definition:Balanced Set" ]
[ "Definition:Balanced Set", "Definition:Balanced Set", "Category:Convex Sets (Vector Spaces)", "Category:Balanced Sets" ]
proofwiki-22947
Convex Balanced Hull is Intersection of all Convex Balanced Sets containing Set
Let $\GF \in \set {\R, \C}$. Let $X$ be a vector space over $\GF$. Let $A \subseteq X$ be a non-empty set. Let $\map {\operatorname {cobal} } A$ be the convex balanced hull of $A$. We then have: :$\ds \map {\operatorname {cobal} } A = \bigcap \set {C \supseteq A : C \text { is convex and balanced} }$
Let: :$\ds B = \bigcap \set {C \supseteq A : C \text { is convex and balanced} }$ From Convex Hull of Balanced Set is Balanced, the convex hull of the balanced hull of $A$, $\map {\operatorname {conv} } {\map {\operatorname {bal} } A}$ is balanced. Hence: :$\set {C \supseteq A : C \text { is convex and balanced} } \ne ...
Let $\GF \in \set {\R, \C}$. Let $X$ be a [[Definition:Vector Space|vector space]] over $\GF$. Let $A \subseteq X$ be a [[Definition:Non-Empty Set|non-empty set]]. Let $\map {\operatorname {cobal} } A$ be the [[Definition:Convex Balanced Hull|convex balanced hull]] of $A$. We then have: :$\ds \map {\operatorname {...
Let: :$\ds B = \bigcap \set {C \supseteq A : C \text { is convex and balanced} }$ From [[Convex Hull of Balanced Set is Balanced]], the [[Definition:Convex Hull|convex hull]] of the [[Definition:Balanced Hull|balanced hull]] of $A$, $\map {\operatorname {conv} } {\map {\operatorname {bal} } A}$ is [[Definition:Balance...
Convex Balanced Hull is Intersection of all Convex Balanced Sets containing Set
https://proofwiki.org/wiki/Convex_Balanced_Hull_is_Intersection_of_all_Convex_Balanced_Sets_containing_Set
https://proofwiki.org/wiki/Convex_Balanced_Hull_is_Intersection_of_all_Convex_Balanced_Sets_containing_Set
[ "Convex Balanced Hulls" ]
[ "Definition:Vector Space", "Definition:Non-Empty Set", "Definition:Convex Balanced Hull" ]
[ "Convex Hull of Balanced Set is Balanced", "Definition:Convex Hull", "Definition:Balanced Hull", "Definition:Balanced Set", "Intersection of Convex Sets is Convex Set (Vector Spaces)", "Definition:Convex Set (Vector Space)", "Intersection of Balanced Sets in Vector Space is Balanced", "Definition:Bala...
proofwiki-22948
Convex Balanced Hull of Finite Union of Convex Balanced Sets
Let $\GF \in \set {\R, \C}$. Let $X$ be a vector space over $\GF$. Let $K_1, \ldots, K_n \subseteq X$ be convex balanced sets. Let $\operatorname {convbal}$ denote convex balanced hull. Then: :$\ds \map {\operatorname {convbal} } {\bigcup_{j \mathop = 1}^n K_j} = \set {\sum_{j \mathop = 1}^n \lambda_j x_j : \lambda_1, ...
Let: :$\ds C = \set {\sum_{j \mathop = 1}^n \lambda_j x_j : \lambda_1, \ldots, \lambda_n \in \GF, \, x_j \in K_j \text { for all } 1 \le k \le n \text { and } \sum_{j \mathop = 1}^n \cmod {\lambda_j} \le 1}$ Let $x, y \in C$ and $t \in \closedint 0 1$. Then there exists $x_j \in K_j$ ($1 \le j \le n$), $y_j \in K_j$ ($...
Let $\GF \in \set {\R, \C}$. Let $X$ be a [[Definition:Vector Space|vector space]] over $\GF$. Let $K_1, \ldots, K_n \subseteq X$ be [[Definition:Convex Set (Vector Space)|convex]] [[Definition:Balanced Set|balanced sets]]. Let $\operatorname {convbal}$ denote [[Definition:Convex Balanced Hull|convex balanced hull]]...
Let: :$\ds C = \set {\sum_{j \mathop = 1}^n \lambda_j x_j : \lambda_1, \ldots, \lambda_n \in \GF, \, x_j \in K_j \text { for all } 1 \le k \le n \text { and } \sum_{j \mathop = 1}^n \cmod {\lambda_j} \le 1}$ Let $x, y \in C$ and $t \in \closedint 0 1$. Then there exists $x_j \in K_j$ ($1 \le j \le n$), $y_j \in K_j$ ...
Convex Balanced Hull of Finite Union of Convex Balanced Sets
https://proofwiki.org/wiki/Convex_Balanced_Hull_of_Finite_Union_of_Convex_Balanced_Sets
https://proofwiki.org/wiki/Convex_Balanced_Hull_of_Finite_Union_of_Convex_Balanced_Sets
[ "Convex Balanced Hulls", "Convex Sets (Vector Spaces)", "Balanced Sets" ]
[ "Definition:Vector Space", "Definition:Convex Set (Vector Space)", "Definition:Balanced Set", "Definition:Convex Balanced Hull" ]
[ "Definition:Balanced Set", "Definition:Balanced Set", "Definition:Convex Set (Vector Space)", "Definition:Convex Set (Vector Space)", "Definition:Balanced Set", "Category:Convex Balanced Hulls", "Category:Convex Sets (Vector Spaces)", "Category:Balanced Sets" ]
proofwiki-22949
Absolute Prepolar is Non-Empty
Let $\GF \in \set {\R, \C}$. Let $\innerprod E F$ be a dual system over $\GF$. Let $B \subseteq F$ be non-empty. Let $B_\circ$ be the absolute prepolar of $B$. Then $B_\circ \ne \O$.
Since $\innerprod \cdot \cdot$ is bilinear, we have $\innerprod { {\mathbf 0}_E} f = 0$ for each $f \in F$. In particular, we have $\innerprod { {\mathbf 0}_E} f = 0$ for each $f \in B$. Hence ${\mathbf 0}_E \in B_\circ$, hence $B_\circ \ne \O$. {{qed}} Category:Absolute Prepolars cpzv07ghkmaalp1dz3n48s0870kn6d4
Let $\GF \in \set {\R, \C}$. Let $\innerprod E F$ be a [[Definition:Dual System|dual system]] over $\GF$. Let $B \subseteq F$ be [[Definition:Non-Empty Set|non-empty]]. Let $B_\circ$ be the [[Definition:Absolute Prepolar|absolute prepolar]] of $B$. Then $B_\circ \ne \O$.
Since $\innerprod \cdot \cdot$ is [[Definition:Bilinear Mapping|bilinear]], we have $\innerprod { {\mathbf 0}_E} f = 0$ for each $f \in F$. In particular, we have $\innerprod { {\mathbf 0}_E} f = 0$ for each $f \in B$. Hence ${\mathbf 0}_E \in B_\circ$, hence $B_\circ \ne \O$. {{qed}} [[Category:Absolute Prepolars]]...
Absolute Prepolar is Non-Empty
https://proofwiki.org/wiki/Absolute_Prepolar_is_Non-Empty
https://proofwiki.org/wiki/Absolute_Prepolar_is_Non-Empty
[ "Absolute Prepolars" ]
[ "Definition:Dual System", "Definition:Non-Empty Set", "Definition:Absolute Prepolar" ]
[ "Definition:Bilinear Mapping", "Category:Absolute Prepolars" ]
proofwiki-22950
Absolute Prepolar is Convex Set
Let $\GF \in \set {\R, \C}$. Let $\innerprod E F$ be a dual system over $\GF$. Let $B \subseteq F$ be non-empty. Let $B_\circ$ be the absolute prepolar of $B$. Then $B_\circ$ is convex.
Let $x, y \in B_\circ$ and $t \in \closedint 0 1$. Then: :$\cmod {\innerprod x f} \le 1$ and: :$\cmod {\innerprod y f} \le 1$ for all $f \in B$. We now have: {{begin-eqn}} {{eqn | l = \cmod {\innerprod {t x + \paren {1 - t} y} f} | r = \cmod {t \innerprod x f + \paren {1 - t} \innerprod y f} | c = $\innerprod \cdot...
Let $\GF \in \set {\R, \C}$. Let $\innerprod E F$ be a [[Definition:Dual System|dual system]] over $\GF$. Let $B \subseteq F$ be [[Definition:Non-Empty Set|non-empty]]. Let $B_\circ$ be the [[Definition:Absolute Prepolar|absolute prepolar]] of $B$. Then $B_\circ$ is [[Definition:Convex Set (Vector Space)|convex]]...
Let $x, y \in B_\circ$ and $t \in \closedint 0 1$. Then: :$\cmod {\innerprod x f} \le 1$ and: :$\cmod {\innerprod y f} \le 1$ for all $f \in B$. We now have: {{begin-eqn}} {{eqn | l = \cmod {\innerprod {t x + \paren {1 - t} y} f} | r = \cmod {t \innerprod x f + \paren {1 - t} \innerprod y f} | c = $\innerprod \cd...
Absolute Prepolar is Convex Set
https://proofwiki.org/wiki/Absolute_Prepolar_is_Convex_Set
https://proofwiki.org/wiki/Absolute_Prepolar_is_Convex_Set
[ "Absolute Prepolars", "Convex Sets (Vector Spaces)" ]
[ "Definition:Dual System", "Definition:Non-Empty Set", "Definition:Absolute Prepolar", "Definition:Convex Set (Vector Space)" ]
[ "Definition:Bilinear Mapping", "Triangle Inequality/Complex Numbers", "Category:Absolute Prepolars", "Category:Convex Sets (Vector Spaces)" ]
proofwiki-22951
Absolute Prepolar is Balanced
Let $\GF \in \set {\R, \C}$. Let $\innerprod E F$ be a dual system over $\GF$. Let $B \subseteq F$ be non-empty. Let $B_\circ$ be the absolute prepolar of $B$. Then $B_\circ$ is balanced.
Let $x \in B_\circ$ and $\lambda \in \GF$ have $\cmod \lambda \le 1$. Then, for each $f \in B$, we have: {{begin-eqn}} {{eqn | l = \cmod {\innerprod {\lambda x} f} | r = \cmod \lambda \cmod {\innerprod x f} }} {{eqn | o = \le | r = \cmod {\innerprod x f} }} {{eqn | o = \le | r = 1 }} {{end-eqn}} Hence $\lambda x ...
Let $\GF \in \set {\R, \C}$. Let $\innerprod E F$ be a [[Definition:Dual System|dual system]] over $\GF$. Let $B \subseteq F$ be [[Definition:Non-Empty Set|non-empty]]. Let $B_\circ$ be the [[Definition:Absolute Prepolar|absolute prepolar]] of $B$. Then $B_\circ$ is [[Definition:Balanced Set|balanced]].
Let $x \in B_\circ$ and $\lambda \in \GF$ have $\cmod \lambda \le 1$. Then, for each $f \in B$, we have: {{begin-eqn}} {{eqn | l = \cmod {\innerprod {\lambda x} f} | r = \cmod \lambda \cmod {\innerprod x f} }} {{eqn | o = \le | r = \cmod {\innerprod x f} }} {{eqn | o = \le | r = 1 }} {{end-eqn}} Hence $\lambda ...
Absolute Prepolar is Balanced
https://proofwiki.org/wiki/Absolute_Prepolar_is_Balanced
https://proofwiki.org/wiki/Absolute_Prepolar_is_Balanced
[ "Absolute Prepolars", "Balanced Sets" ]
[ "Definition:Dual System", "Definition:Non-Empty Set", "Definition:Absolute Prepolar", "Definition:Balanced Set" ]
[ "Category:Absolute Prepolars", "Category:Balanced Sets" ]
proofwiki-22952
Absolute Prepolar is Closed in Weak Topology
Let $\GF \in \set {\R, \C}$. Let $\innerprod E F$ be a dual system over $\GF$. Let $\map \sigma {E, F}$ be the weak-$\ast$ topology on $F$ induced by $\innerprod E F$. Let $B \subseteq E$ be non-empty. Let $B_\circ$ be the absolute prepolar of $B$. Then $B_\circ$ is $\map \sigma {E, F}$-closed.
We use Characterization of Closedness in terms of Nets. That is, we show that every convergent net valued in $B_\circ$ has its limit in $B_\circ$. Let $\struct {\Lambda, \preceq}$ be a directed set. Let $\family {x_\lambda}_{\lambda \mathop \in \Lambda}$ be a convergent net valued in $B_\circ$ with limit $x$. We show ...
Let $\GF \in \set {\R, \C}$. Let $\innerprod E F$ be a [[Definition:Dual System|dual system]] over $\GF$. Let $\map \sigma {E, F}$ be the [[Definition:Weak Topology Induced by Dual System|weak-$\ast$ topology on $F$ induced by $\innerprod E F$]]. Let $B \subseteq E$ be [[Definition:Non-Empty Set|non-empty]]. Let $...
We use [[Characterization of Closedness in terms of Nets]]. That is, we show that every [[Definition:Convergent Net|convergent net]] valued in $B_\circ$ has its [[Definition:Limit of Net|limit]] in $B_\circ$. Let $\struct {\Lambda, \preceq}$ be a [[Definition:Directed Set|directed set]]. Let $\family {x_\lambda}_{\...
Absolute Prepolar is Closed in Weak Topology
https://proofwiki.org/wiki/Absolute_Prepolar_is_Closed_in_Weak_Topology
https://proofwiki.org/wiki/Absolute_Prepolar_is_Closed_in_Weak_Topology
[ "Weak-* Topologies Induced by Dual Systems", "Weak Topologies Induced by Dual Systems", "Absolute Prepolars", "Weak Topologies Induced by Dual Systems" ]
[ "Definition:Dual System", "Definition:Weak Topology Induced by Dual System", "Definition:Non-Empty Set", "Definition:Absolute Prepolar", "Definition:Closed Set" ]
[ "Characterization of Closedness in terms of Nets", "Definition:Convergent Net", "Definition:Limit of Net", "Definition:Directed Preordering", "Definition:Convergent Net", "Definition:Limit of Net", "Characterization of Convergence of Net in Weak Topology Induced by Dual System", "Category:Absolute Pre...
proofwiki-22953
Convex Real Function has Minimum at Point iff Zero is Subgradient at Point
Let $\innerprod X {X'}$ be a dual system over $\R$. Let $C \subseteq X$ be a convex set. Let $f : C \to \R$ be a convex function. Let $x \in C$. Then $f$ has a minimum at $x$ {{iff}} ${\mathbf 0}_{X'}$ is a subgradient at $x$ with respect to $\innerprod X {X'}$.
We have that $f$ is a minimum at $x$ {{iff}}: :$\map f y \ge \map f x$ for all $y \in C$. That is: :$\map f y - \map f x \ge 0$ We have: :$\innerprod {y - x} { {\mathbf 0}_{X'} } = 0$ Hence: :$\map f y - \map f x \ge \innerprod {y - x} { {\mathbf 0}_{X'} }$ for all $y \in C$. Hence ${\mathbf 0}_{X'}$ is a subgradient a...
Let $\innerprod X {X'}$ be a [[Definition:Dual System|dual system]] over $\R$. Let $C \subseteq X$ be a [[Definition:Convex Set (Vector Space)|convex set]]. Let $f : C \to \R$ be a [[Definition:Convex Real Function|convex function]]. Let $x \in C$. Then $f$ has a [[Definition:Minimum Point|minimum]] at $x$ {{iff}}...
We have that $f$ is a [[Definition:Minimum Point|minimum]] at $x$ {{iff}}: :$\map f y \ge \map f x$ for all $y \in C$. That is: :$\map f y - \map f x \ge 0$ We have: :$\innerprod {y - x} { {\mathbf 0}_{X'} } = 0$ Hence: :$\map f y - \map f x \ge \innerprod {y - x} { {\mathbf 0}_{X'} }$ for all $y \in C$. Hence ${\m...
Convex Real Function has Minimum at Point iff Zero is Subgradient at Point
https://proofwiki.org/wiki/Convex_Real_Function_has_Minimum_at_Point_iff_Zero_is_Subgradient_at_Point
https://proofwiki.org/wiki/Convex_Real_Function_has_Minimum_at_Point_iff_Zero_is_Subgradient_at_Point
[ "Subgradients" ]
[ "Definition:Dual System", "Definition:Convex Set (Vector Space)", "Definition:Convex Real Function", "Definition:Minimum Point", "Definition:Subgradient" ]
[ "Definition:Minimum Point", "Definition:Subgradient" ]
proofwiki-22954
Bipolar Theorem/Absolute Polar
Let $\GF \in \set {\R, \C}$. Let $\innerprod X {X'}$ be a dual system over $\GF$. Let $A \subseteq X$ be a non-empty set. Let $\paren {A^\circ}_\circ$ be the bipolar of $A$. Let $\map \sigma {X, X'}$ be the weak topology on $X$ induced by $\innerprod X {X'}$. Let $\map {\operatorname {convbal} } A$ be the convex bala...
From Bipolar Set is Convex, $\paren {A^\circ}_\circ$ is convex. From Bipolar Set is Balanced, $\paren {A^\circ}_\circ$ is balanced. From Bipolar Set is Closed in Weak Topology, $\paren {A^\circ}_\circ$ is $\map \sigma {E, F}$-closed. From Bipolar Set contains Original Set, we have $A \subseteq \paren {A^\circ}_\circ$. ...
Let $\GF \in \set {\R, \C}$. Let $\innerprod X {X'}$ be a [[Definition:Dual System|dual system]] over $\GF$. Let $A \subseteq X$ be a [[Definition:Non-Empty Set|non-empty set]]. Let $\paren {A^\circ}_\circ$ be the [[Definition:Bipolar Set|bipolar]] of $A$. Let $\map \sigma {X, X'}$ be the [[Definition:Weak Topolog...
From [[Bipolar Set is Convex]], $\paren {A^\circ}_\circ$ is [[Definition:Convex Set (Vector Space)|convex]]. From [[Bipolar Set is Balanced]], $\paren {A^\circ}_\circ$ is [[Definition:Balanced Set|balanced]]. From [[Bipolar Set is Closed in Weak Topology]], $\paren {A^\circ}_\circ$ is [[Definition:Closed Set|$\map \s...
Bipolar Theorem/Absolute Polar
https://proofwiki.org/wiki/Bipolar_Theorem/Absolute_Polar
https://proofwiki.org/wiki/Bipolar_Theorem/Absolute_Polar
[ "Bipolar Theorem", "Absolute Polars" ]
[ "Definition:Dual System", "Definition:Non-Empty Set", "Definition:Bipolar Set", "Definition:Weak Topology Induced by Dual System", "Definition:Convex Balanced Hull", "Definition:Closure (Topology)" ]
[ "Bipolar Set is Convex", "Definition:Convex Set (Vector Space)", "Bipolar Set is Balanced", "Definition:Balanced Set", "Bipolar Set is Closed in Weak Topology", "Definition:Closed Set", "Bipolar Set contains Original Set", "Closure of Convex Balanced Hull as Intersection of Closed Convex Balanced Sets...
proofwiki-22955
Bipolar Set is Convex
vLet $\GF \in \set {\R, \C}$. Let $\innerprod E F$ be a dual system over $\GF$. Let $A \subseteq E$ be non-empty. Let $\paren {A^\circ}_\circ$ be the bipolar set of $A$. Then $\paren {A^\circ}_\circ$ is convex.
Let $A^\circ$ be the absolute polar of $A$. From Absolute Polar is Non-Empty, $A^\circ$ is non-empty. From Absolute Prepolar is Convex Set, $\paren {A^\circ}_\circ$ is convex. {{qed}} Category:Bipolar Sets 5soc331wuibt5vnuqve15nrs970yy28
vLet $\GF \in \set {\R, \C}$. Let $\innerprod E F$ be a [[Definition:Dual System|dual system]] over $\GF$. Let $A \subseteq E$ be [[Definition:Non-Empty Set|non-empty]]. Let $\paren {A^\circ}_\circ$ be the [[Definition:Bipolar Set|bipolar set]] of $A$. Then $\paren {A^\circ}_\circ$ is [[Definition:Convex Set (Vec...
Let $A^\circ$ be the [[Definition:Absolute Polar|absolute polar]] of $A$. From [[Absolute Polar is Non-Empty]], $A^\circ$ is [[Definition:Non-Empty Set|non-empty]]. From [[Absolute Prepolar is Convex Set]], $\paren {A^\circ}_\circ$ is [[Definition:Convex Set (Vector Space)|convex]]. {{qed}} [[Category:Bipolar Sets]]...
Bipolar Set is Convex
https://proofwiki.org/wiki/Bipolar_Set_is_Convex
https://proofwiki.org/wiki/Bipolar_Set_is_Convex
[ "Bipolar Sets" ]
[ "Definition:Dual System", "Definition:Non-Empty Set", "Definition:Bipolar Set", "Definition:Convex Set (Vector Space)" ]
[ "Definition:Absolute Polar", "Absolute Polar is Non-Empty", "Definition:Non-Empty Set", "Absolute Prepolar is Convex Set", "Definition:Convex Set (Vector Space)", "Category:Bipolar Sets" ]
proofwiki-22956
Bipolar Set is Balanced
vLet $\GF \in \set {\R, \C}$. Let $\innerprod E F$ be a dual system over $\GF$. Let $A \subseteq E$ be non-empty. Let $\paren {A^\circ}_\circ$ be the bipolar set of $A$. Then $\paren {A^\circ}_\circ$ is balanced.
Let $A^\circ$ be the absolute polar of $A$. From Absolute Polar is Non-Empty, $A^\circ$ is non-empty. From Absolute Prepolar is Balanced, $\paren {A^\circ}_\circ$ is balanced. {{qed}} Category:Bipolar Sets Category:Balanced Sets 3n36esx3beyn7y6st7ce58giq3ll55o
vLet $\GF \in \set {\R, \C}$. Let $\innerprod E F$ be a [[Definition:Dual System|dual system]] over $\GF$. Let $A \subseteq E$ be [[Definition:Non-Empty Set|non-empty]]. Let $\paren {A^\circ}_\circ$ be the [[Definition:Bipolar Set|bipolar set]] of $A$. Then $\paren {A^\circ}_\circ$ is [[Definition:Balanced Set|ba...
Let $A^\circ$ be the [[Definition:Absolute Polar|absolute polar]] of $A$. From [[Absolute Polar is Non-Empty]], $A^\circ$ is [[Definition:Non-Empty Set|non-empty]]. From [[Absolute Prepolar is Balanced]], $\paren {A^\circ}_\circ$ is [[Definition:Balanced Set|balanced]]. {{qed}} [[Category:Bipolar Sets]] [[Category:B...
Bipolar Set is Balanced
https://proofwiki.org/wiki/Bipolar_Set_is_Balanced
https://proofwiki.org/wiki/Bipolar_Set_is_Balanced
[ "Bipolar Sets", "Balanced Sets" ]
[ "Definition:Dual System", "Definition:Non-Empty Set", "Definition:Bipolar Set", "Definition:Balanced Set" ]
[ "Definition:Absolute Polar", "Absolute Polar is Non-Empty", "Definition:Non-Empty Set", "Absolute Prepolar is Balanced", "Definition:Balanced Set", "Category:Bipolar Sets", "Category:Balanced Sets" ]
proofwiki-22957
One-Sided Polar of Dilation
Let $\innerprod E F$ be a dual system over $\R$. Let $A \subseteq E$ be non-empty. Let $\lambda > 0$. Let $A^\odot$ and $\paren {\lambda A}^\odot$ be the one-sided polar of $A$ and $\lambda A$ respectively. Then: :$\paren {\lambda A}^\odot = \dfrac 1 \lambda A^\odot$
Let $f \in \dfrac 1 \lambda A^\odot$. This is the case {{iff}} $\lambda f \in A^\odot$. This is equivalent to $\innerprod x {\lambda f} \le 1$ for each $x \in A$. Since $\innerprod \cdot \cdot$ is bilinear, we have $\innerprod x {\lambda f} = \innerprod {\lambda x} f$. Hence $\innerprod x {\lambda f} \le 1$ for each $...
Let $\innerprod E F$ be a [[Definition:Dual System|dual system]] over $\R$. Let $A \subseteq E$ be [[Definition:Non-Empty Set|non-empty]]. Let $\lambda > 0$. Let $A^\odot$ and $\paren {\lambda A}^\odot$ be the [[Definition:One-Sided Polar|one-sided polar]] of $A$ and $\lambda A$ respectively. Then: :$\paren {\lam...
Let $f \in \dfrac 1 \lambda A^\odot$. This is the case {{iff}} $\lambda f \in A^\odot$. This is equivalent to $\innerprod x {\lambda f} \le 1$ for each $x \in A$. Since $\innerprod \cdot \cdot$ is [[Definition:Bilinear Mapping|bilinear]], we have $\innerprod x {\lambda f} = \innerprod {\lambda x} f$. Hence $\inner...
One-Sided Polar of Dilation
https://proofwiki.org/wiki/One-Sided_Polar_of_Dilation
https://proofwiki.org/wiki/One-Sided_Polar_of_Dilation
[ "One-Sided Polars" ]
[ "Definition:Dual System", "Definition:Non-Empty Set", "Definition:One-Sided Polar" ]
[ "Definition:Bilinear Mapping" ]
proofwiki-22958
Intersection of One-Sided Polars is One-Sided Polar of Union
Let $\innerprod E F$ be a dual system over $\R$. Let $\FF$ be a set of non-empty subsets of $E$. Then: :$\ds \bigcap_{A \in \FF} A^\odot = \paren {\bigcup_{A \in \FF} A}^\odot$ where $\odot$ denotes one-sided polar.
We have: :$\ds f \in \paren {\bigcup_{A \in \FF} A}^\odot$ {{iff}}: :$\innerprod x f \le 1$ for each $\ds x \in \bigcup_{A \in \FF} A$ This is equivalent to: :$\innerprod x f \le 1$ for each $\ds x \in A$ for each $A \in \FF$. This is equivalent to $f \in A^\odot$ for each $A \in \FF$. This is equivalent to $\ds f \in ...
Let $\innerprod E F$ be a [[Definition:Dual System|dual system]] over $\R$. Let $\FF$ be a [[Definition:Set|set]] of [[Definition:Non-Empty Set|non-empty]] [[Definition:Subset|subsets]] of $E$. Then: :$\ds \bigcap_{A \in \FF} A^\odot = \paren {\bigcup_{A \in \FF} A}^\odot$ where $\odot$ denotes [[Definition:One-Sid...
We have: :$\ds f \in \paren {\bigcup_{A \in \FF} A}^\odot$ {{iff}}: :$\innerprod x f \le 1$ for each $\ds x \in \bigcup_{A \in \FF} A$ This is equivalent to: :$\innerprod x f \le 1$ for each $\ds x \in A$ for each $A \in \FF$. This is equivalent to $f \in A^\odot$ for each $A \in \FF$. This is equivalent to $\ds f \...
Intersection of One-Sided Polars is One-Sided Polar of Union
https://proofwiki.org/wiki/Intersection_of_One-Sided_Polars_is_One-Sided_Polar_of_Union
https://proofwiki.org/wiki/Intersection_of_One-Sided_Polars_is_One-Sided_Polar_of_Union
[ "One-Sided Polars" ]
[ "Definition:Dual System", "Definition:Set", "Definition:Non-Empty Set", "Definition:Subset", "Definition:One-Sided Polar" ]
[]
proofwiki-22959
One-Sided Polar is Non-Empty
Let $\innerprod E F$ be a dual system over $\R$. Let $A \subseteq E$ be non-empty. Let $A^\circ$ be the one-sided polar of $A$ in $\innerprod E F$. Then $A^\circ \ne \O$.
Note that we have: :$\innerprod x { {\mathbf 0}_F} = 0$ for all $x \in E$. In particular: :$\innerprod x { {\mathbf 0}_F} \le 1$ for all $x \in A$. Hence we have ${\mathbf 0}_F \in A^\circ$. Hence $A^\circ \ne \O$. {{qed}} Category:One-Sided Polars banrxb2c7tm0lg4a7kgrrg0vysbpysc
Let $\innerprod E F$ be a [[Definition:Dual System|dual system]] over $\R$. Let $A \subseteq E$ be [[Definition:Non-Empty Set|non-empty]]. Let $A^\circ$ be the [[Definition:One-Sided Polar|one-sided polar]] of $A$ in $\innerprod E F$. Then $A^\circ \ne \O$.
Note that we have: :$\innerprod x { {\mathbf 0}_F} = 0$ for all $x \in E$. In particular: :$\innerprod x { {\mathbf 0}_F} \le 1$ for all $x \in A$. Hence we have ${\mathbf 0}_F \in A^\circ$. Hence $A^\circ \ne \O$. {{qed}} [[Category:One-Sided Polars]] banrxb2c7tm0lg4a7kgrrg0vysbpysc
One-Sided Polar is Non-Empty
https://proofwiki.org/wiki/One-Sided_Polar_is_Non-Empty
https://proofwiki.org/wiki/One-Sided_Polar_is_Non-Empty
[ "One-Sided Polars" ]
[ "Definition:Dual System", "Definition:Non-Empty Set", "Definition:One-Sided Polar" ]
[ "Category:One-Sided Polars" ]
proofwiki-22960
One-Sided Polar is Convex
Let $\innerprod E F$ be a dual system over $\R$. Let $A \subseteq E$ be non-empty. Let $A^\odot$ be the one-sided polar of $A$ in $\innerprod E F$. Then $A^\odot$ is convex.
Let $f, g \in A^\odot$ and $t \in \closedint 0 1$. Then for each $x \in A$, we have: {{begin-eqn}} {{eqn | l = \innerprod x {t f + \paren {1 - t} g} | r = t \innerprod x f + \paren {1 - t} \innerprod x g | c = $\innerprod \cdot \cdot$ is bilinear }} {{eqn | o = \le | r = t + \paren {1 - t} }} {{eqn | r = 1 }} {{e...
Let $\innerprod E F$ be a [[Definition:Dual System|dual system]] over $\R$. Let $A \subseteq E$ be [[Definition:Non-Empty Set|non-empty]]. Let $A^\odot$ be the [[Definition:One-Sided Polar|one-sided polar]] of $A$ in $\innerprod E F$. Then $A^\odot$ is [[Definition:Convex Set (Vector Space)|convex]].
Let $f, g \in A^\odot$ and $t \in \closedint 0 1$. Then for each $x \in A$, we have: {{begin-eqn}} {{eqn | l = \innerprod x {t f + \paren {1 - t} g} | r = t \innerprod x f + \paren {1 - t} \innerprod x g | c = $\innerprod \cdot \cdot$ is [[Definition:Bilinear Mapping|bilinear]] }} {{eqn | o = \le | r = t + \pare...
One-Sided Polar is Convex
https://proofwiki.org/wiki/One-Sided_Polar_is_Convex
https://proofwiki.org/wiki/One-Sided_Polar_is_Convex
[ "One-Sided Polars" ]
[ "Definition:Dual System", "Definition:Non-Empty Set", "Definition:One-Sided Polar", "Definition:Convex Set (Vector Space)" ]
[ "Definition:Bilinear Mapping", "Definition:Convex Set (Vector Space)", "Category:One-Sided Polars" ]
proofwiki-22961
One-Sided Prepolar is Convex
Let $\innerprod E F$ be a dual system over $\R$. Let $B \subseteq F$ be non-empty. Let $B_\odot$ be the one-sided prepolar of $B$ in $\innerprod E F$. Then $B_\odot$ is convex.
Let $x, y \in B_\odot$ and $t \in \closedint 0 1$. Then for each $f \in B$, we have: {{begin-eqn}} {{eqn | l = \innerprod {t x + \paren {1 - t} y} f | r = t \innerprod x f + \paren {1 - t} \innerprod y f | c = $\innerprod \cdot \cdot$ is bilinear }} {{eqn | o = \le | r = t + \paren {1 - t} }} {{eqn | r = 1 }} {{e...
Let $\innerprod E F$ be a [[Definition:Dual System|dual system]] over $\R$. Let $B \subseteq F$ be [[Definition:Non-Empty Set|non-empty]]. Let $B_\odot$ be the [[Definition:One-Sided Prepolar|one-sided prepolar]] of $B$ in $\innerprod E F$. Then $B_\odot$ is [[Definition:Convex Set (Vector Space)|convex]].
Let $x, y \in B_\odot$ and $t \in \closedint 0 1$. Then for each $f \in B$, we have: {{begin-eqn}} {{eqn | l = \innerprod {t x + \paren {1 - t} y} f | r = t \innerprod x f + \paren {1 - t} \innerprod y f | c = $\innerprod \cdot \cdot$ is [[Definition:Bilinear Mapping|bilinear]] }} {{eqn | o = \le | r = t + \pare...
One-Sided Prepolar is Convex
https://proofwiki.org/wiki/One-Sided_Prepolar_is_Convex
https://proofwiki.org/wiki/One-Sided_Prepolar_is_Convex
[ "One-Sided Prepolars" ]
[ "Definition:Dual System", "Definition:Non-Empty Set", "Definition:One-Sided Prepolar", "Definition:Convex Set (Vector Space)" ]
[ "Definition:Bilinear Mapping", "Category:One-Sided Prepolars" ]
proofwiki-22962
One-Sided Prepolar is Closed in Weak Topology
Let $\innerprod E F$ be a dual system over $\R$. Let $\map \sigma {E, F}$ be the weak topology on $E$ induced by $\innerprod E F$. Let $B \subseteq F$ be non-empty. Let $B_\odot$ be the one-sided prepolar of $B$ in $\innerprod E F$. Then $B_\odot$ is $\map \sigma {E, F}$-closed.
We use Characterization of Closedness in terms of Nets. We show that every convergent net valued in $B_\odot$ has its limit in $B_\odot$. Let $\struct {\Lambda, \preceq}$ be a directed set. Let $\family {x_\lambda}_{\lambda \mathop \in \Lambda}$ be a convergent net valued in $B_\odot$ with limit $x \in E$. Then for eac...
Let $\innerprod E F$ be a [[Definition:Dual System|dual system]] over $\R$. Let $\map \sigma {E, F}$ be the [[Definition:Weak Topology Induced by Dual System|weak topology on $E$]] induced by $\innerprod E F$. Let $B \subseteq F$ be [[Definition:Non-Empty Set|non-empty]]. Let $B_\odot$ be the [[Definition:One-Sided ...
We use [[Characterization of Closedness in terms of Nets]]. We show that every [[Definition:Convergent Net|convergent net]] valued in $B_\odot$ has its [[Definition:Limit of Net|limit]] in $B_\odot$. Let $\struct {\Lambda, \preceq}$ be a [[Definition:Directed Set|directed set]]. Let $\family {x_\lambda}_{\lambda \ma...
One-Sided Prepolar is Closed in Weak Topology
https://proofwiki.org/wiki/One-Sided_Prepolar_is_Closed_in_Weak_Topology
https://proofwiki.org/wiki/One-Sided_Prepolar_is_Closed_in_Weak_Topology
[ "One-Sided Prepolars" ]
[ "Definition:Dual System", "Definition:Weak Topology Induced by Dual System", "Definition:Non-Empty Set", "Definition:One-Sided Prepolar", "Definition:Closed Set" ]
[ "Characterization of Closedness in terms of Nets", "Definition:Convergent Net", "Definition:Limit of Net", "Definition:Directed Preordering", "Definition:Convergent Net", "Definition:Limit of Net", "Characterization of Convergence of Net in Weak Topology Induced by Dual System", "Characterization of C...
proofwiki-22963
Bipolar Theorem/One-Sided Polar
Let $\GF \in \set {\R, \C}$. Let $\innerprod X {X'}$ be a dual system over $\GF$. Let $A \subseteq X$ be a non-empty set. Let $\paren {A^\odot}_\odot$ be the one-sided bipolar of $A$. Let $\map \sigma {X, X'}$ be the weak topology on $X$ induced by $\innerprod X {X'}$. Let $\operatorname {conv}$ be the convex hull. L...
From One-Sided Bipolar is Convex, $\paren {A^\odot}_\odot$ is convex. From One-Sided Bipolar is Closed in Weak Topology, $\paren {A^\odot}_\odot$ is $\map \sigma {E, F}$-closed. Let: :$C = \map {\cl_\sigma} {\map {\operatorname {conv} } {A \cup \set { {\mathbf 0}_X} } }$ From One-Sided Bipolar Set contains Original Set...
Let $\GF \in \set {\R, \C}$. Let $\innerprod X {X'}$ be a [[Definition:Dual System|dual system]] over $\GF$. Let $A \subseteq X$ be a [[Definition:Non-Empty Set|non-empty set]]. Let $\paren {A^\odot}_\odot$ be the [[Definition:One-Sided Bipolar Set|one-sided bipolar]] of $A$. Let $\map \sigma {X, X'}$ be the [[Def...
From [[One-Sided Bipolar is Convex]], $\paren {A^\odot}_\odot$ is [[Definition:Convex Set (Vector Space)|convex]]. From [[One-Sided Bipolar is Closed in Weak Topology]], $\paren {A^\odot}_\odot$ is [[Definition:Closed Set|$\map \sigma {E, F}$-closed]]. Let: :$C = \map {\cl_\sigma} {\map {\operatorname {conv} } {A \cu...
Bipolar Theorem/One-Sided Polar
https://proofwiki.org/wiki/Bipolar_Theorem/One-Sided_Polar
https://proofwiki.org/wiki/Bipolar_Theorem/One-Sided_Polar
[ "Bipolar Theorem", "One-Sided Polars" ]
[ "Definition:Dual System", "Definition:Non-Empty Set", "Definition:One-Sided Bipolar Set", "Definition:Weak Topology Induced by Dual System", "Definition:Convex Hull", "Definition:Closure (Topology)" ]
[ "One-Sided Bipolar is Convex", "Definition:Convex Set (Vector Space)", "One-Sided Bipolar is Closed in Weak Topology", "Definition:Closed Set", "One-Sided Bipolar Set contains Original Set and Origin", "Closure of Convex Hull is Smallest Closed Convex Set containing Set", "Hahn-Banach Separation Theorem...
proofwiki-22964
One-Sided Bipolar is Convex
Let $\innerprod E F$ be a dual system over $\R$. Let $A \subseteq E$ be non-empty. Let $\paren {A^\odot}_\odot$ be the one-sided bipolar of $A$ in $\innerprod E F$. Then $\paren {A^\odot}_\odot$ is convex.
Let $A^\odot$ be the one-sided absolute polar of $A$. From One-Sided Polar is Non-Empty, $A^\odot \ne \O$. Hence from One-Sided Prepolar is Convex, $\paren {A^\odot}_\odot$ is convex. {{qed}} Category:One-Sided Bipolars Category:Convex Sets (Vector Spaces) rbxus0o8rcetxnt96jfp3z7zw2pfiui
Let $\innerprod E F$ be a [[Definition:Dual System|dual system]] over $\R$. Let $A \subseteq E$ be [[Definition:Non-Empty Set|non-empty]]. Let $\paren {A^\odot}_\odot$ be the [[Definition:One-Sided Bipolar Set|one-sided bipolar]] of $A$ in $\innerprod E F$. Then $\paren {A^\odot}_\odot$ is [[Definition:Convex Set (...
Let $A^\odot$ be the [[Definition:One-Sided Polar|one-sided absolute polar]] of $A$. From [[One-Sided Polar is Non-Empty]], $A^\odot \ne \O$. Hence from [[One-Sided Prepolar is Convex]], $\paren {A^\odot}_\odot$ is [[Definition:Convex Set (Vector Space)|convex]]. {{qed}} [[Category:One-Sided Bipolars]] [[Category:Co...
One-Sided Bipolar is Convex
https://proofwiki.org/wiki/One-Sided_Bipolar_is_Convex
https://proofwiki.org/wiki/One-Sided_Bipolar_is_Convex
[ "Convex Sets (Vector Spaces)", "One-Sided Bipolars", "Convex Sets (Vector Spaces)" ]
[ "Definition:Dual System", "Definition:Non-Empty Set", "Definition:One-Sided Bipolar Set", "Definition:Convex Set (Vector Space)" ]
[ "Definition:One-Sided Polar", "One-Sided Polar is Non-Empty", "One-Sided Prepolar is Convex", "Definition:Convex Set (Vector Space)", "Category:One-Sided Bipolars", "Category:Convex Sets (Vector Spaces)" ]
proofwiki-22965
Functor Under Object Comma Category is Isomorphic to Comma Category/Lemma 1
:$I$ is a covariant functor
=== Object Functor is Well-defined === Let $\tuple{D,f}$ be an object in $\paren{C \downarrow F}$. By definition of functor under object comma category: :$f$ is a morphism $f: C \to FD$ of $\mathbf C$ Hence: :$f$ is a morphism $f: G* \to FD$ of $\mathbf C$ By definition of comma category: :$\tuple{*, D, f}$ is an objec...
:$I$ is a [[Definition:Covariant Functor|covariant functor]]
=== Object Functor is Well-defined === Let $\tuple{D,f}$ be an [[Definition:Object (Category Theory)|object]] in $\paren{C \downarrow F}$. By definition of [[Definition:Functor Under Object Comma Category|functor under object comma category]]: :$f$ is a [[Definition:Morphism (Category Theory)|morphism]] $f: C \to FD$...
Functor Under Object Comma Category is Isomorphic to Comma Category/Lemma 1
https://proofwiki.org/wiki/Functor_Under_Object_Comma_Category_is_Isomorphic_to_Comma_Category/Lemma_1
https://proofwiki.org/wiki/Functor_Under_Object_Comma_Category_is_Isomorphic_to_Comma_Category/Lemma_1
[ "Functor Under Object Comma Category is Isomorphic to Comma Category" ]
[ "Definition:Functor/Covariant" ]
[ "Definition:Object (Category Theory)", "Definition:Comma Category/Functor Under Object", "Definition:Morphism", "Definition:Morphism", "Definition:Comma Category/General Form", "Definition:Object (Category Theory)", "Definition:Well-Defined", "Definition:Object Functor", "Definition:Morphism", "De...
proofwiki-22966
One-Sided Bipolar Set contains Original Set and Origin
Let $\innerprod X {X'}$ be a dual system over $\R$. Let $A \subseteq X$ be a non-empty set. Let $\paren {A^\odot}_\odot$ be the one-sided bipolar of $A$. Then: :$A \cup \set { {\mathbf 0}_X} \subseteq \paren {A^\odot}_\odot$
We have $x \in \paren {A^\odot}_\odot$ {{iff}}: :$\innerprod x f \le 1$ for each $f \in A^\odot$. We have that $f \in A^\odot$ {{iff}}: :$\innerprod x f \le 1$ for each $x \in A$. Hence for $x \in A$, we have: :$\innerprod x f \le 1$ for each $f \in A^\odot$. Hence $x \in \paren {A^\odot}_\odot$. Hence $A \subseteq \p...
Let $\innerprod X {X'}$ be a [[Definition:Dual System|dual system]] over $\R$. Let $A \subseteq X$ be a [[Definition:Non-Empty Set|non-empty set]]. Let $\paren {A^\odot}_\odot$ be the [[Definition:One-Sided Bipolar Set|one-sided bipolar]] of $A$. Then: :$A \cup \set { {\mathbf 0}_X} \subseteq \paren {A^\odot}_\odo...
We have $x \in \paren {A^\odot}_\odot$ {{iff}}: :$\innerprod x f \le 1$ for each $f \in A^\odot$. We have that $f \in A^\odot$ {{iff}}: :$\innerprod x f \le 1$ for each $x \in A$. Hence for $x \in A$, we have: :$\innerprod x f \le 1$ for each $f \in A^\odot$. Hence $x \in \paren {A^\odot}_\odot$. Hence $A \subsete...
One-Sided Bipolar Set contains Original Set and Origin
https://proofwiki.org/wiki/One-Sided_Bipolar_Set_contains_Original_Set_and_Origin
https://proofwiki.org/wiki/One-Sided_Bipolar_Set_contains_Original_Set_and_Origin
[ "One-Sided Bipolars" ]
[ "Definition:Dual System", "Definition:Non-Empty Set", "Definition:One-Sided Bipolar Set" ]
[ "One-Sided Bipolar Set is Non-Empty", "Category:One-Sided Bipolars" ]
proofwiki-22967
Closure of Convex Hull is Smallest Closed Convex Set containing Set
Let $\GF \in \set {\R, \C}$. Let $\struct {X, \tau}$ be a topological vector space over $\GF$. Let $\cl$ be the closure taken in $\struct {X, \tau}$. Let $\operatorname {conv}$ denote convex hull. Let $A \subseteq X$ be non-empty. Then $\map \cl {\map {\operatorname {conv} } A}$ is $\subseteq$-smallest closed convex ...
From Closed Convex Hull in Topological Vector Space is Closed and Convex, $\map \cl {\map {\operatorname {conv} } A}$ is a closed convex set containing $A$. Let $C$ be a closed convex set containing $A$. From Convex Hull is Smallest Convex Set containing Set, we have: :$\map {\operatorname {conv} } A \subseteq C$ From ...
Let $\GF \in \set {\R, \C}$. Let $\struct {X, \tau}$ be a [[Definition:Topological Vector Space|topological vector space]] over $\GF$. Let $\cl$ be the [[Definition:Closure (Topology)|closure]] taken in $\struct {X, \tau}$. Let $\operatorname {conv}$ denote [[Definition:Convex Hull|convex hull]]. Let $A \subseteq ...
From [[Closed Convex Hull in Topological Vector Space is Closed and Convex]], $\map \cl {\map {\operatorname {conv} } A}$ is a [[Definition:Closed Set|closed]] [[Definition:Convex Set (Vector Space)|convex set]] containing $A$. Let $C$ be a [[Definition:Closed Set|closed]] [[Definition:Convex Set (Vector Space)|convex...
Closure of Convex Hull is Smallest Closed Convex Set containing Set
https://proofwiki.org/wiki/Closure_of_Convex_Hull_is_Smallest_Closed_Convex_Set_containing_Set
https://proofwiki.org/wiki/Closure_of_Convex_Hull_is_Smallest_Closed_Convex_Set_containing_Set
[ "Closed Convex Hulls" ]
[ "Definition:Topological Vector Space", "Definition:Closure (Topology)", "Definition:Convex Hull", "Definition:Non-Empty Set", "Definition:Smallest Element", "Definition:Closed Set", "Definition:Convex Set (Vector Space)" ]
[ "Closed Convex Hull in Topological Vector Space is Closed and Convex", "Definition:Closed Set", "Definition:Convex Set (Vector Space)", "Definition:Closed Set", "Definition:Convex Set (Vector Space)", "Convex Hull is Smallest Convex Set containing Set", "Topological Closure of Subset is Subset of Topolo...
proofwiki-22968
Functor Under Object Comma Category is Isomorphic to Comma Category/Lemma 2
:$J$ is a covariant functor
=== Object Functor is Well-defined === By definition of category $\mathbf 1$: :the only object in $\mathbf 1$ is $*$ By definition of comma category: :every object in $\paren{G \downarrow F}$ is of the form $\tuple{*, D, f}$ where: ::$*$ is in $\mathbf 1$ ::$D$ is an object of $\mathbf D$ ::$f$ is a morphism $f:G* \to ...
:$J$ is a [[Definition:Covariant Functor|covariant functor]]
=== Object Functor is Well-defined === By definition of [[Definition:One (Category)|category $\mathbf 1$]]: :the only [[Definition:Object (Category Theory)|object]] in $\mathbf 1$ is $*$ By definition of [[Definition:Comma Category (General Form)|comma category]]: :every [[Definition:Object (Category Theory)|object]...
Functor Under Object Comma Category is Isomorphic to Comma Category/Lemma 2
https://proofwiki.org/wiki/Functor_Under_Object_Comma_Category_is_Isomorphic_to_Comma_Category/Lemma_2
https://proofwiki.org/wiki/Functor_Under_Object_Comma_Category_is_Isomorphic_to_Comma_Category/Lemma_2
[ "Functor Under Object Comma Category is Isomorphic to Comma Category" ]
[ "Definition:Functor/Covariant" ]
[ "Definition:One (Category)", "Definition:Object (Category Theory)", "Definition:Comma Category/General Form", "Definition:Object (Category Theory)", "Definition:Object (Category Theory)", "Definition:Morphism", "Definition:Object (Category Theory)", "Definition:Morphism", "Definition:Comma Category/...
proofwiki-22969
Functor Under Object Comma Category is Isomorphic to Comma Category/Lemma 3
:$J \circ I = \operatorname{id}_{\paren{C \downarrow F} }$ where: :$\operatorname{id}_{\paren{C \downarrow F} }$ denotes the identity functor on $\paren{C \downarrow F}$
For each object $\tuple{D,f}$ in $\paren{C \downarrow F}$ we have: {{begin-eqn}} {{eqn | l = \paren{J \circ I} \tuple{D, f} | r = \map J {I \tuple{D, f} } | c = {{Defof|Composite Functor}} }} {{eqn | r = J \tuple{*, D, f} | c = Definition of $I$ }} {{eqn | r = \tuple{D, f} | c = Definition of $J...
:$J \circ I = \operatorname{id}_{\paren{C \downarrow F} }$ where: :$\operatorname{id}_{\paren{C \downarrow F} }$ denotes the [[Definition:Identity Functor|identity functor]] on $\paren{C \downarrow F}$
For each [[Definition:Object (Category Theory)|object]] $\tuple{D,f}$ in $\paren{C \downarrow F}$ we have: {{begin-eqn}} {{eqn | l = \paren{J \circ I} \tuple{D, f} | r = \map J {I \tuple{D, f} } | c = {{Defof|Composite Functor}} }} {{eqn | r = J \tuple{*, D, f} | c = Definition of $I$ }} {{eqn | r = \...
Functor Under Object Comma Category is Isomorphic to Comma Category/Lemma 3
https://proofwiki.org/wiki/Functor_Under_Object_Comma_Category_is_Isomorphic_to_Comma_Category/Lemma_3
https://proofwiki.org/wiki/Functor_Under_Object_Comma_Category_is_Isomorphic_to_Comma_Category/Lemma_3
[ "Functor Under Object Comma Category is Isomorphic to Comma Category" ]
[ "Definition:Identity Functor" ]
[ "Definition:Object (Category Theory)", "Definition:Morphism", "Category:Functor Under Object Comma Category is Isomorphic to Comma Category" ]
proofwiki-22970
Functor Under Object Comma Category is Isomorphic to Comma Category/Lemma 4
:$I \circ J = \operatorname{id}_{\paren{G \downarrow F} }$ where: :$\operatorname{id}_{\paren{G \downarrow F} }$ denotes the identity functor on $\paren{G \downarrow F}$
For each object $\tuple{*, D,f}$ in $\paren{G \downarrow F}$ we have: {{begin-eqn}} {{eqn | l = \paren{I \circ J} \tuple{*, D, f} | r = \map I {J \tuple{*, D, f} } | c = {{Defof|Composite Functor}} }} {{eqn | r = I \tuple{D, f} | c = Definition of $J$ }} {{eqn | r = \tuple{*, D, f} | c = Definit...
:$I \circ J = \operatorname{id}_{\paren{G \downarrow F} }$ where: :$\operatorname{id}_{\paren{G \downarrow F} }$ denotes the [[Definition:Identity Functor|identity functor]] on $\paren{G \downarrow F}$
For each [[Definition:Object (Category Theory)|object]] $\tuple{*, D,f}$ in $\paren{G \downarrow F}$ we have: {{begin-eqn}} {{eqn | l = \paren{I \circ J} \tuple{*, D, f} | r = \map I {J \tuple{*, D, f} } | c = {{Defof|Composite Functor}} }} {{eqn | r = I \tuple{D, f} | c = Definition of $J$ }} {{eqn |...
Functor Under Object Comma Category is Isomorphic to Comma Category/Lemma 4
https://proofwiki.org/wiki/Functor_Under_Object_Comma_Category_is_Isomorphic_to_Comma_Category/Lemma_4
https://proofwiki.org/wiki/Functor_Under_Object_Comma_Category_is_Isomorphic_to_Comma_Category/Lemma_4
[ "Functor Under Object Comma Category is Isomorphic to Comma Category" ]
[ "Definition:Identity Functor" ]
[ "Definition:Object (Category Theory)", "Definition:Morphism", "Category:Functor Under Object Comma Category is Isomorphic to Comma Category" ]
proofwiki-22971
Functor Over Object Comma Category is Isomorphic to Comma Category/Lemma 1
:$I$ is a covariant functor
=== Object Functor is Well-defined === Let $\tuple{E,g}$ be an object in $\paren{G \downarrow C}$. By definition of functor over object comma category: :$g$ is a morphism $g: GE \to C$ of $\mathbf C$ Hence: :$g$ is a morphism $g: GE \to F*$ of $\mathbf C$ By definition of comma category: :$\tuple{E, *, g}$ is an object...
:$I$ is a [[Definition:Covariant Functor|covariant functor]]
=== Object Functor is Well-defined === Let $\tuple{E,g}$ be an [[Definition:Object (Category Theory)|object]] in $\paren{G \downarrow C}$. By definition of [[Definition:Functor Over Object Comma Category|functor over object comma category]]: :$g$ is a [[Definition:Morphism (Category Theory)|morphism]] $g: GE \to C$ o...
Functor Over Object Comma Category is Isomorphic to Comma Category/Lemma 1
https://proofwiki.org/wiki/Functor_Over_Object_Comma_Category_is_Isomorphic_to_Comma_Category/Lemma_1
https://proofwiki.org/wiki/Functor_Over_Object_Comma_Category_is_Isomorphic_to_Comma_Category/Lemma_1
[ "Functor Over Object Comma Category is Isomorphic to Comma Category" ]
[ "Definition:Functor/Covariant" ]
[ "Definition:Object (Category Theory)", "Definition:Comma Category/Functor Over Object", "Definition:Morphism", "Definition:Morphism", "Definition:Comma Category/General Form", "Definition:Object (Category Theory)", "Definition:Well-Defined", "Definition:Object Functor", "Definition:Morphism", "Def...
proofwiki-22972
Functor Over Object Comma Category is Isomorphic to Comma Category/Lemma 2
:$J$ is a covariant functor
=== Object Functor is Well-defined === By definition of category $\mathbf 1$: :the only object in $\mathbf 1$ is $*$ By definition of comma category: :every object in $\paren{G \downarrow F}$ is of the form $\tuple{E, *, g}$ where: ::$E$ is an object of $\mathbf D$ ::$*$ is in $\mathbf 1$ ::$g$ is a morphism $f:GE \to ...
:$J$ is a [[Definition:Covariant Functor|covariant functor]]
=== Object Functor is Well-defined === By definition of [[Definition:One (Category)|category $\mathbf 1$]]: :the only [[Definition:Object (Category Theory)|object]] in $\mathbf 1$ is $*$ By definition of [[Definition:Comma Category (General Form)|comma category]]: :every [[Definition:Object (Category Theory)|object]...
Functor Over Object Comma Category is Isomorphic to Comma Category/Lemma 2
https://proofwiki.org/wiki/Functor_Over_Object_Comma_Category_is_Isomorphic_to_Comma_Category/Lemma_2
https://proofwiki.org/wiki/Functor_Over_Object_Comma_Category_is_Isomorphic_to_Comma_Category/Lemma_2
[ "Functor Over Object Comma Category is Isomorphic to Comma Category" ]
[ "Definition:Functor/Covariant" ]
[ "Definition:One (Category)", "Definition:Object (Category Theory)", "Definition:Comma Category/General Form", "Definition:Object (Category Theory)", "Definition:Object (Category Theory)", "Definition:Morphism", "Definition:Object (Category Theory)", "Definition:Morphism", "Definition:Comma Category/...
proofwiki-22973
Functor Over Object Comma Category is Isomorphic to Comma Category/Lemma 3
:$J \circ I = \operatorname{id}_{\paren{G \downarrow C}}$ where $\operatorname{id}_{\paren{G \downarrow C}}$ denotes the identity functor on $\paren{G \downarrow C}$
For each object $\tuple{E,g}$ in $\paren{G \downarrow C}$ we have: {{begin-eqn}} {{eqn | l = \paren{J \circ I} \tuple{E, g} | r = \map J {I \tuple{E, g} } | c = {{Defof|Composite Functor}} }} {{eqn | r = J \tuple{E, *, g} | c = Definition of $I$ }} {{eqn | r = \tuple{E, g} | c = Definition of $J...
:$J \circ I = \operatorname{id}_{\paren{G \downarrow C}}$ where $\operatorname{id}_{\paren{G \downarrow C}}$ denotes the [[Definition:Identity Functor|identity functor]] on $\paren{G \downarrow C}$
For each [[Definition:Object (Category Theory)|object]] $\tuple{E,g}$ in $\paren{G \downarrow C}$ we have: {{begin-eqn}} {{eqn | l = \paren{J \circ I} \tuple{E, g} | r = \map J {I \tuple{E, g} } | c = {{Defof|Composite Functor}} }} {{eqn | r = J \tuple{E, *, g} | c = Definition of $I$ }} {{eqn | r = \...
Functor Over Object Comma Category is Isomorphic to Comma Category/Lemma 3
https://proofwiki.org/wiki/Functor_Over_Object_Comma_Category_is_Isomorphic_to_Comma_Category/Lemma_3
https://proofwiki.org/wiki/Functor_Over_Object_Comma_Category_is_Isomorphic_to_Comma_Category/Lemma_3
[ "Functor Over Object Comma Category is Isomorphic to Comma Category" ]
[ "Definition:Identity Functor" ]
[ "Definition:Object (Category Theory)", "Definition:Morphism", "Category:Functor Over Object Comma Category is Isomorphic to Comma Category" ]
proofwiki-22974
Functor Over Object Comma Category is Isomorphic to Comma Category/Lemma 4
:$I \circ J = \operatorname{id}_{\paren{G \downarrow F}}$ where $\operatorname{id}_{\paren{G \downarrow F}}$ denotes the identity functor on $\paren{G \downarrow F}$
For each object $\tuple{E, *, g}$ in $\paren{G \downarrow F}$ we have: {{begin-eqn}} {{eqn | l = \paren{I \circ J} \tuple{E, *, g} | r = \map I {J \tuple{E, *, g} } | c = {{Defof|Composite Functor}} }} {{eqn | r = I \tuple{E, g} | c = Definition of $J$ }} {{eqn | r = \tuple{E, *, g} | c = Defini...
:$I \circ J = \operatorname{id}_{\paren{G \downarrow F}}$ where $\operatorname{id}_{\paren{G \downarrow F}}$ denotes the [[Definition:Identity Functor|identity functor]] on $\paren{G \downarrow F}$
For each [[Definition:Object (Category Theory)|object]] $\tuple{E, *, g}$ in $\paren{G \downarrow F}$ we have: {{begin-eqn}} {{eqn | l = \paren{I \circ J} \tuple{E, *, g} | r = \map I {J \tuple{E, *, g} } | c = {{Defof|Composite Functor}} }} {{eqn | r = I \tuple{E, g} | c = Definition of $J$ }} {{eqn ...
Functor Over Object Comma Category is Isomorphic to Comma Category/Lemma 4
https://proofwiki.org/wiki/Functor_Over_Object_Comma_Category_is_Isomorphic_to_Comma_Category/Lemma_4
https://proofwiki.org/wiki/Functor_Over_Object_Comma_Category_is_Isomorphic_to_Comma_Category/Lemma_4
[ "Functor Over Object Comma Category is Isomorphic to Comma Category" ]
[ "Definition:Identity Functor" ]
[ "Definition:Object (Category Theory)", "Definition:Morphism", "Category:Functor Over Object Comma Category is Isomorphic to Comma Category" ]
proofwiki-22975
Slice Category is Isomorphic to Comma Category/Lemma 1
:$I$ is a covariant functor
=== Object Functor is Well-defined === Let $g$ be an object in $\mathbf C / C$. By definition of slice category: :$g$ is a morphism $g: \operatorname{dom} g \to C$ of $\mathbf C$ By definition of identity functor: :$\map {\operatorname{id}_{\mathbf C} } {\operatorname{dom} g} = \operatorname{dom} g$ Hence: :$g$ is a mo...
:$I$ is a [[Definition:Covariant Functor|covariant functor]]
=== Object Functor is Well-defined === Let $g$ be an [[Definition:Object (Category Theory)|object]] in $\mathbf C / C$. By definition of [[Definition:Slice Category|slice category]]: :$g$ is a [[Definition:Morphism (Category Theory)|morphism]] $g: \operatorname{dom} g \to C$ of $\mathbf C$ By definition of [[Defini...
Slice Category is Isomorphic to Comma Category/Lemma 1
https://proofwiki.org/wiki/Slice_Category_is_Isomorphic_to_Comma_Category/Lemma_1
https://proofwiki.org/wiki/Slice_Category_is_Isomorphic_to_Comma_Category/Lemma_1
[ "Slice Category is Isomorphic to Comma Category" ]
[ "Definition:Functor/Covariant" ]
[ "Definition:Object (Category Theory)", "Definition:Slice Category", "Definition:Morphism", "Definition:Identity Functor", "Definition:Morphism", "Definition:Comma Category/General Form", "Definition:Object (Category Theory)", "Definition:Well-Defined", "Definition:Object Functor", "Definition:Morp...
proofwiki-22976
Slice Category is Isomorphic to Comma Category/Lemma 2
:$J$ is a covariant functor
=== Object Functor is Well-defined === By definition of category $\mathbf 1$: :the only object in $\mathbf 1$ is $*$ By definition of comma category: :every object in $\paren{\operatorname{id}_{\mathbf C} \downarrow F}$ is of the form $\tuple{E, *, g}$ where: ::$E$ is an object of $\mathbf D$ ::$*$ is in $\mathbf 1$ ::...
:$J$ is a [[Definition:Covariant Functor|covariant functor]]
=== Object Functor is Well-defined === By definition of [[Definition:One (Category)|category $\mathbf 1$]]: :the only [[Definition:Object (Category Theory)|object]] in $\mathbf 1$ is $*$ By definition of [[Definition:Comma Category (General Form)|comma category]]: :every [[Definition:Object (Category Theory)|object]...
Slice Category is Isomorphic to Comma Category/Lemma 2
https://proofwiki.org/wiki/Slice_Category_is_Isomorphic_to_Comma_Category/Lemma_2
https://proofwiki.org/wiki/Slice_Category_is_Isomorphic_to_Comma_Category/Lemma_2
[ "Slice Category is Isomorphic to Comma Category" ]
[ "Definition:Functor/Covariant" ]
[ "Definition:One (Category)", "Definition:Object (Category Theory)", "Definition:Comma Category/General Form", "Definition:Object (Category Theory)", "Definition:Object (Category Theory)", "Definition:Morphism", "Definition:Object (Category Theory)", "Definition:Morphism", "Definition:Slice Category"...
proofwiki-22977
Slice Category is Isomorphic to Comma Category/Lemma 3
:$J \circ I = \operatorname{id}_{\mathbf C / C}$ where $\operatorname{id}_{\mathbf C / C}$ is the identity functor on $\mathbf C / C$
For each object $g$ in $\mathbf C / C$ we have: {{begin-eqn}} {{eqn | l = \paren{J \circ I} g | r = \map J {I g } | c = {{Defof|Composite Functor}} }} {{eqn | r = J \tuple{\operatorname {dom} g, *, g} | c = Definition of $I$ }} {{eqn | r = g | c = Definition of $J$ }} {{eqn | r = \map {\operator...
:$J \circ I = \operatorname{id}_{\mathbf C / C}$ where $\operatorname{id}_{\mathbf C / C}$ is the [[Definition:Identity Functor|identity functor]] on $\mathbf C / C$
For each [[Definition:Object (Category Theory)|object]] $g$ in $\mathbf C / C$ we have: {{begin-eqn}} {{eqn | l = \paren{J \circ I} g | r = \map J {I g } | c = {{Defof|Composite Functor}} }} {{eqn | r = J \tuple{\operatorname {dom} g, *, g} | c = Definition of $I$ }} {{eqn | r = g | c = Definiti...
Slice Category is Isomorphic to Comma Category/Lemma 3
https://proofwiki.org/wiki/Slice_Category_is_Isomorphic_to_Comma_Category/Lemma_3
https://proofwiki.org/wiki/Slice_Category_is_Isomorphic_to_Comma_Category/Lemma_3
[ "Slice Category is Isomorphic to Comma Category" ]
[ "Definition:Identity Functor" ]
[ "Definition:Object (Category Theory)", "Definition:Morphism", "Category:Slice Category is Isomorphic to Comma Category" ]
proofwiki-22978
Slice Category is Isomorphic to Comma Category/Lemma 4
:$I \circ J = \operatorname{id}_{\paren{\operatorname{id}_{\mathbf C} \downarrow F }}$ where $\operatorname{id}_{\paren{\operatorname{id}_{\mathbf C} \downarrow F }}$ is the identity functor on $\paren{\operatorname{id}_{\mathbf C} \downarrow F }$
By definition of comma category: :For each object $\tuple{E, *, g}$ in $\paren{\operatorname{id}_{\mathbf C} \downarrow F}$: ::$\text{(1)} \quad \operatorname{dom} g = E$ For each object $\tuple{E, *, g}$ in $\paren{\operatorname{id}_{\mathbf C} \downarrow F}$ we have: {{begin-eqn}} {{eqn | l = \paren{I \circ J} \tuple...
:$I \circ J = \operatorname{id}_{\paren{\operatorname{id}_{\mathbf C} \downarrow F }}$ where $\operatorname{id}_{\paren{\operatorname{id}_{\mathbf C} \downarrow F }}$ is the [[Definition:Identity Functor|identity functor]] on $\paren{\operatorname{id}_{\mathbf C} \downarrow F }$
By definition of [[Definition:Comma Category (General Form)|comma category]]: :For each [[Definition:Object (Category Theory)|object]] $\tuple{E, *, g}$ in $\paren{\operatorname{id}_{\mathbf C} \downarrow F}$: ::$\text{(1)} \quad \operatorname{dom} g = E$ For each [[Definition:Object (Category Theory)|object]] $\tupl...
Slice Category is Isomorphic to Comma Category/Lemma 4
https://proofwiki.org/wiki/Slice_Category_is_Isomorphic_to_Comma_Category/Lemma_4
https://proofwiki.org/wiki/Slice_Category_is_Isomorphic_to_Comma_Category/Lemma_4
[ "Slice Category is Isomorphic to Comma Category" ]
[ "Definition:Identity Functor" ]
[ "Definition:Comma Category/General Form", "Definition:Object (Category Theory)", "Definition:Object (Category Theory)", "Definition:Morphism", "Category:Slice Category is Isomorphic to Comma Category" ]
proofwiki-22979
Coslice Category is Isomorphic to Comma Category/Lemma 1
:$I$ is a covariant functor
=== Object Functor is Well-defined === Let $f$ be an object in $C / \mathbf C$. By definition of coslice category: :$f$ is a morphism $f: C \to D$ of $\mathbf C$ By definition of identity functor: :$\operatorname{id}_{\mathbf C} D = D$ Hence: :$f$ is a morphism $f: G* \to \operatorname{id}_{\mathbf C} D$ of $\mathbf C$...
:$I$ is a [[Definition:Covariant Functor|covariant functor]]
=== Object Functor is Well-defined === Let $f$ be an [[Definition:Object (Category Theory)|object]] in $C / \mathbf C$. By definition of [[Definition:Coslice Category|coslice category]]: :$f$ is a [[Definition:Morphism (Category Theory)|morphism]] $f: C \to D$ of $\mathbf C$ By definition of [[Definition:Identity F...
Coslice Category is Isomorphic to Comma Category/Lemma 1
https://proofwiki.org/wiki/Coslice_Category_is_Isomorphic_to_Comma_Category/Lemma_1
https://proofwiki.org/wiki/Coslice_Category_is_Isomorphic_to_Comma_Category/Lemma_1
[ "Coslice Category is Isomorphic to Comma Category" ]
[ "Definition:Functor/Covariant" ]
[ "Definition:Object (Category Theory)", "Definition:Coslice Category", "Definition:Morphism", "Definition:Identity Functor", "Definition:Morphism", "Definition:Comma Category/General Form", "Definition:Object (Category Theory)", "Definition:Well-Defined", "Definition:Object Functor", "Definition:Mo...
proofwiki-22980
Coslice Category is Isomorphic to Comma Category/Lemma 2
:$J$ is a covariant functor
=== Object Functor is Well-defined === By definition of category $\mathbf 1$: :the only object in $\mathbf 1$ is $*$ By definition of comma category: :every object in $\paren{G \downarrow \operatorname{id}_{\mathbf C}}$ is of the form $\tuple{*, D, f}$ where: ::$*$ is in $\mathbf 1$ ::$D$ is an object of $\mathbf D$ ::...
:$J$ is a [[Definition:Covariant Functor|covariant functor]]
=== Object Functor is Well-defined === By definition of [[Definition:One (Category)|category $\mathbf 1$]]: :the only [[Definition:Object (Category Theory)|object]] in $\mathbf 1$ is $*$ By definition of [[Definition:Comma Category (General Form)|comma category]]: :every [[Definition:Object (Category Theory)|object]...
Coslice Category is Isomorphic to Comma Category/Lemma 2
https://proofwiki.org/wiki/Coslice_Category_is_Isomorphic_to_Comma_Category/Lemma_2
https://proofwiki.org/wiki/Coslice_Category_is_Isomorphic_to_Comma_Category/Lemma_2
[ "Coslice Category is Isomorphic to Comma Category" ]
[ "Definition:Functor/Covariant" ]
[ "Definition:One (Category)", "Definition:Object (Category Theory)", "Definition:Comma Category/General Form", "Definition:Object (Category Theory)", "Definition:Object (Category Theory)", "Definition:Morphism", "Definition:Identity Functor", "Definition:Morphism", "Definition:Coslice Category", "D...
proofwiki-22981
Coslice Category is Isomorphic to Comma Category/Lemma 3
:$J \circ I = \operatorname{id}_{C / \mathbf C}$ where $\operatorname{id}_{C / \mathbf C}$ is the identity functor on $C / \mathbf C$
For each object $f$ in $C / \mathbf C$ we have: {{begin-eqn}} {{eqn | l = \paren{J \circ I} f | r = \map J {I f } | c = {{Defof|Composite Functor}} }} {{eqn | r = J \tuple{*, \operatorname{cod} f, f} | c = Definition of $I$ }} {{eqn | r = f | c = Definition of $J$ }} {{eqn | r = \operatorname{id...
:$J \circ I = \operatorname{id}_{C / \mathbf C}$ where $\operatorname{id}_{C / \mathbf C}$ is the [[Definition:Identity Functor|identity functor]] on $C / \mathbf C$
For each [[Definition:Object (Category Theory)|object]] $f$ in $C / \mathbf C$ we have: {{begin-eqn}} {{eqn | l = \paren{J \circ I} f | r = \map J {I f } | c = {{Defof|Composite Functor}} }} {{eqn | r = J \tuple{*, \operatorname{cod} f, f} | c = Definition of $I$ }} {{eqn | r = f | c = Definitio...
Coslice Category is Isomorphic to Comma Category/Lemma 3
https://proofwiki.org/wiki/Coslice_Category_is_Isomorphic_to_Comma_Category/Lemma_3
https://proofwiki.org/wiki/Coslice_Category_is_Isomorphic_to_Comma_Category/Lemma_3
[ "Coslice Category is Isomorphic to Comma Category" ]
[ "Definition:Identity Functor" ]
[ "Definition:Object (Category Theory)", "Definition:Morphism", "Category:Coslice Category is Isomorphic to Comma Category" ]
proofwiki-22982
Coslice Category is Isomorphic to Comma Category/Lemma 4
:$I \circ J = \operatorname{id}_{\paren{G \downarrow \operatorname{id}_{\mathbf C} }}$ where $\operatorname{id}_{\paren{G \downarrow \operatorname{id}_{\mathbf C} }}$ is the identity functor on $\paren{G \downarrow \operatorname{id}_{\mathbf C} }$
By definition of comma category: :For each object $\tuple{*, D, f}$ in $\paren{G \downarrow \operatorname{id}_{\mathbf C} }$: ::$\text{(1)} \quad \operatorname{cod} f = D$ For each object $\tuple{*, D,f}$ in $\paren{G \downarrow \operatorname{id}_{\mathbf C} }$ we have: {{begin-eqn}} {{eqn | l = \paren{I \circ J} \tupl...
:$I \circ J = \operatorname{id}_{\paren{G \downarrow \operatorname{id}_{\mathbf C} }}$ where $\operatorname{id}_{\paren{G \downarrow \operatorname{id}_{\mathbf C} }}$ is the [[Definition:Identity Functor|identity functor]] on $\paren{G \downarrow \operatorname{id}_{\mathbf C} }$
By definition of [[Definition:Comma Category (General Form)|comma category]]: :For each [[Definition:Object (Category Theory)|object]] $\tuple{*, D, f}$ in $\paren{G \downarrow \operatorname{id}_{\mathbf C} }$: ::$\text{(1)} \quad \operatorname{cod} f = D$ For each [[Definition:Object (Category Theory)|object]] $\tup...
Coslice Category is Isomorphic to Comma Category/Lemma 4
https://proofwiki.org/wiki/Coslice_Category_is_Isomorphic_to_Comma_Category/Lemma_4
https://proofwiki.org/wiki/Coslice_Category_is_Isomorphic_to_Comma_Category/Lemma_4
[ "Coslice Category is Isomorphic to Comma Category" ]
[ "Definition:Identity Functor" ]
[ "Definition:Comma Category/General Form", "Definition:Object (Category Theory)", "Definition:Object (Category Theory)", "Definition:Morphism", "Category:Coslice Category is Isomorphic to Comma Category" ]
proofwiki-22983
Morphism Category is Isomorphic to Comma Category/Lemma 1
:$I$ is a covariant functor
=== Object Functor is Well-defined === Let $f$ be an object in $\mathbf C^\to$. By definition of morphism category: :$f$ is a morphism $f: \operatorname{dom} f \to \operatorname{cod} f$ of $\mathbf C$ By definition of identity functor: :$\map {\operatorname{id}_{\mathbf C} } {\operatorname{dom} f} = \operatorname{dom} ...
:$I$ is a [[Definition:Covariant Functor|covariant functor]]
=== Object Functor is Well-defined === Let $f$ be an [[Definition:Object (Category Theory)|object]] in $\mathbf C^\to$. By definition of [[Definition:Morphism Category|morphism category]]: :$f$ is a [[Definition:Morphism (Category Theory)|morphism]] $f: \operatorname{dom} f \to \operatorname{cod} f$ of $\mathbf C$ ...
Morphism Category is Isomorphic to Comma Category/Lemma 1
https://proofwiki.org/wiki/Morphism_Category_is_Isomorphic_to_Comma_Category/Lemma_1
https://proofwiki.org/wiki/Morphism_Category_is_Isomorphic_to_Comma_Category/Lemma_1
[ "Morphism Category is Isomorphic to Comma Category" ]
[ "Definition:Functor/Covariant" ]
[ "Definition:Object (Category Theory)", "Definition:Morphism Category", "Definition:Morphism", "Definition:Identity Functor", "Definition:Morphism", "Definition:Comma Category/General Form", "Definition:Object (Category Theory)", "Definition:Well-Defined", "Definition:Object Functor", "Definition:M...
proofwiki-22984
Morphism Category is Isomorphic to Comma Category/Lemma 2
:$J$ is a covariant functor
=== Object Functor is Well-defined === By definition of comma category: :every object in $\paren{\operatorname{id}_{\mathbf C} \downarrow \operatorname{id}_{\mathbf C} }$ is of the form $\tuple{E, D, f}$: :$f$ is a morphism $f : \operatorname{id}_{\mathbf C} E \to \operatorname{id}_{\mathbf C} D$ in $\mathbf C$ By defi...
:$J$ is a [[Definition:Covariant Functor|covariant functor]]
=== Object Functor is Well-defined === By definition of [[Definition:Comma Category (General Form)|comma category]]: :every [[Definition:Object (Category Theory)|object]] in $\paren{\operatorname{id}_{\mathbf C} \downarrow \operatorname{id}_{\mathbf C} }$ is of the form $\tuple{E, D, f}$: :$f$ is a [[Definition:Morphi...
Morphism Category is Isomorphic to Comma Category/Lemma 2
https://proofwiki.org/wiki/Morphism_Category_is_Isomorphic_to_Comma_Category/Lemma_2
https://proofwiki.org/wiki/Morphism_Category_is_Isomorphic_to_Comma_Category/Lemma_2
[ "Morphism Category is Isomorphic to Comma Category" ]
[ "Definition:Functor/Covariant" ]
[ "Definition:Comma Category/General Form", "Definition:Object (Category Theory)", "Definition:Morphism", "Definition:Identity Morphism", "Definition:Object (Category Theory)", "Definition:Morphism", "Definition:Morphism Category", "Definition:Object (Category Theory)", "Definition:Well-Defined", "D...
proofwiki-22985
Morphism Category is Isomorphic to Comma Category/Lemma 3
:$J \circ I = \operatorname{id}_{\mathbf C^\to}$ where $\operatorname{id}_{\mathbf C^\to}$ is the identity functor on $\mathbf C^\to$
For each object $g$ in $\mathbf C^\to$ we have: {{begin-eqn}} {{eqn | l = \paren{J \circ I} g | r = \map J {I g } | c = {{Defof|Composite Functor}} }} {{eqn | r = J \tuple{\operatorname {dom} g, \operatorname {cod} g, g} | c = Definition of $I$ }} {{eqn | r = g | c = Definition of $J$ }} {{eqn |...
:$J \circ I = \operatorname{id}_{\mathbf C^\to}$ where $\operatorname{id}_{\mathbf C^\to}$ is the [[Definition:Identity Functor|identity functor]] on $\mathbf C^\to$
For each [[Definition:Object (Category Theory)|object]] $g$ in $\mathbf C^\to$ we have: {{begin-eqn}} {{eqn | l = \paren{J \circ I} g | r = \map J {I g } | c = {{Defof|Composite Functor}} }} {{eqn | r = J \tuple{\operatorname {dom} g, \operatorname {cod} g, g} | c = Definition of $I$ }} {{eqn | r = g ...
Morphism Category is Isomorphic to Comma Category/Lemma 3
https://proofwiki.org/wiki/Morphism_Category_is_Isomorphic_to_Comma_Category/Lemma_3
https://proofwiki.org/wiki/Morphism_Category_is_Isomorphic_to_Comma_Category/Lemma_3
[ "Morphism Category is Isomorphic to Comma Category" ]
[ "Definition:Identity Functor" ]
[ "Definition:Object (Category Theory)", "Definition:Morphism", "Category:Morphism Category is Isomorphic to Comma Category" ]
proofwiki-22986
Morphism Category is Isomorphic to Comma Category/Lemma 4
:$I \circ J = \operatorname{id}_{\paren{\operatorname{id}_{\mathbf C} \downarrow \operatorname{id}_{\mathbf C} }}$ where $\operatorname{id}_{\paren{\operatorname{id}_{\mathbf C} \downarrow \operatorname{id}_{\mathbf C} }}$ is the identity functor on $\paren{\operatorname{id}_{\mathbf C} \downarrow \operatorname{id}_{\m...
By definition of comma category: :For each object $\tuple{E, D, g}$ in $\paren{\operatorname{id}_{\mathbf C} \downarrow \paren{\operatorname{id}_{\mathbf C}}}$: ::$\text{(1)} \quad \operatorname{dom} g = E$ ::$\text{(2)} \quad \operatorname{cod} g = D$ For each object $\tuple{E, D, g}$ in $\paren{\operatorname{id}_{\ma...
:$I \circ J = \operatorname{id}_{\paren{\operatorname{id}_{\mathbf C} \downarrow \operatorname{id}_{\mathbf C} }}$ where $\operatorname{id}_{\paren{\operatorname{id}_{\mathbf C} \downarrow \operatorname{id}_{\mathbf C} }}$ is the [[Definition:Identity Functor|identity functor]] on $\paren{\operatorname{id}_{\mathbf C} ...
By definition of [[Definition:Comma Category (General Form)|comma category]]: :For each [[Definition:Object (Category Theory)|object]] $\tuple{E, D, g}$ in $\paren{\operatorname{id}_{\mathbf C} \downarrow \paren{\operatorname{id}_{\mathbf C}}}$: ::$\text{(1)} \quad \operatorname{dom} g = E$ ::$\text{(2)} \quad \operato...
Morphism Category is Isomorphic to Comma Category/Lemma 4
https://proofwiki.org/wiki/Morphism_Category_is_Isomorphic_to_Comma_Category/Lemma_4
https://proofwiki.org/wiki/Morphism_Category_is_Isomorphic_to_Comma_Category/Lemma_4
[ "Morphism Category is Isomorphic to Comma Category" ]
[ "Definition:Identity Functor" ]
[ "Definition:Comma Category/General Form", "Definition:Object (Category Theory)", "Definition:Object (Category Theory)", "Definition:Morphism", "Category:Morphism Category is Isomorphic to Comma Category" ]
proofwiki-22987
One-Sided Prepolar is One-Sided Polar in Transpose
Let $\innerprod E F_{E \times F}$ be a dual system over $\GF$. Let $\innerprod F E_{F \times E}$ be the transpose dual system. Let $B \subseteq F$ be a non-empty set. Let $B_\odot$ be the one-sided prepolar of $B$ taken in $\innerprod E F_{E \times F}$. Let $B^{\odot^T}$ be the one-sided polar of $B$ taken in $\innerpr...
We have: {{begin-eqn}} {{eqn | l = B_\odot | r = \set {x \in E :\innerprod x f_{E \times F} \le 1 \text { for all } f \in B} }} {{eqn | r = \set {x \in E : \innerprod f x_{F \times E} \le 1 \text { for all } f \in B} }} {{eqn | r = B^{\odot^T} }} {{end-eqn}} {{qed}} Category:One-Sided Prepolars Category:One-Sided Pol...
Let $\innerprod E F_{E \times F}$ be a [[Definition:Dual System|dual system]] over $\GF$. Let $\innerprod F E_{F \times E}$ be the [[Definition:Transpose Dual System|transpose dual system]]. Let $B \subseteq F$ be a [[Definition:Non-Empty Set|non-empty set]]. Let $B_\odot$ be the [[Definition:One-Sided Prepolar|one-...
We have: {{begin-eqn}} {{eqn | l = B_\odot | r = \set {x \in E :\innerprod x f_{E \times F} \le 1 \text { for all } f \in B} }} {{eqn | r = \set {x \in E : \innerprod f x_{F \times E} \le 1 \text { for all } f \in B} }} {{eqn | r = B^{\odot^T} }} {{end-eqn}} {{qed}} [[Category:One-Sided Prepolars]] [[Category:One-Si...
One-Sided Prepolar is One-Sided Polar in Transpose
https://proofwiki.org/wiki/One-Sided_Prepolar_is_One-Sided_Polar_in_Transpose
https://proofwiki.org/wiki/One-Sided_Prepolar_is_One-Sided_Polar_in_Transpose
[ "One-Sided Prepolars", "One-Sided Polars" ]
[ "Definition:Dual System", "Definition:Transpose Dual System", "Definition:Non-Empty Set", "Definition:One-Sided Prepolar", "Definition:One-Sided Polar" ]
[ "Category:One-Sided Prepolars", "Category:One-Sided Polars" ]
proofwiki-22988
One-Sided Polar is One-Sided Prepolar in Transpose
Let $\innerprod E F_{E \times F}$ be a dual system over $\GF$. Let $\innerprod F E_{F \times E}$ be the transpose dual system. Let $A \subseteq E$ be a non-empty set. Let $A^\odot$ be the one-sided polar of $A$ taken in $\innerprod E F_{E \times F}$. Let $A_{\odot^T}$ be the one-sided prepolar of $A$ taken in $\innerpr...
We have: {{begin-eqn}} {{eqn | l = A^\odot | r = \set {f \in F :\innerprod x f_{E \times F} \le 1 \text { for all } x \in A} }} {{eqn | r = \set {f \in F : \innerprod f x_{F \times E} \le 1 \text { for all } x \in A} }} {{eqn | r = A_{\odot^T} }} {{end-eqn}} {{qed}} Category:One-Sided Polars Category:One-Sided Prepol...
Let $\innerprod E F_{E \times F}$ be a [[Definition:Dual System|dual system]] over $\GF$. Let $\innerprod F E_{F \times E}$ be the [[Definition:Transpose Dual System|transpose dual system]]. Let $A \subseteq E$ be a [[Definition:Non-Empty Set|non-empty set]]. Let $A^\odot$ be the [[Definition:One-Sided Polar|one-sid...
We have: {{begin-eqn}} {{eqn | l = A^\odot | r = \set {f \in F :\innerprod x f_{E \times F} \le 1 \text { for all } x \in A} }} {{eqn | r = \set {f \in F : \innerprod f x_{F \times E} \le 1 \text { for all } x \in A} }} {{eqn | r = A_{\odot^T} }} {{end-eqn}} {{qed}} [[Category:One-Sided Polars]] [[Category:One-Sided...
One-Sided Polar is One-Sided Prepolar in Transpose
https://proofwiki.org/wiki/One-Sided_Polar_is_One-Sided_Prepolar_in_Transpose
https://proofwiki.org/wiki/One-Sided_Polar_is_One-Sided_Prepolar_in_Transpose
[ "One-Sided Polars", "One-Sided Prepolars" ]
[ "Definition:Dual System", "Definition:Transpose Dual System", "Definition:Non-Empty Set", "Definition:One-Sided Polar", "Definition:One-Sided Prepolar" ]
[ "Category:One-Sided Polars", "Category:One-Sided Prepolars" ]
proofwiki-22989
Banach-Dieudonné Theorem
Let $\GF \in \set {\R, \C}$. Let $\struct {X, \norm {\, \cdot \,}_X}$ be a Banach space over $\GF$. Let $\struct {X^\ast, \norm {\, \cdot \,}_{X^\ast} }$ be the normed dual space of $\struct {X, \norm {\, \cdot \,}_X}$. Let $B_{X^\ast}^-$ be the closed unit ball in $X^\ast$. Let $w^\ast$ be the weak-$\ast$ topology in ...
We first consider the case $\GF = \R$. Note that the conclusion is entirely independent of whether $\R$ or $\C$ is used, so this is unproblematic. Throughout we work in the dual system $\innerprod X {X^\ast}$ over $\R$, where: :$\innerprod x f = \map f x$ for each $\tuple {x, f} \in X \times X^\ast$. We are assured tha...
Let $\GF \in \set {\R, \C}$. Let $\struct {X, \norm {\, \cdot \,}_X}$ be a [[Definition:Banach Space|Banach space]] over $\GF$. Let $\struct {X^\ast, \norm {\, \cdot \,}_{X^\ast} }$ be the [[Definition:Normed Dual Space|normed dual space]] of $\struct {X, \norm {\, \cdot \,}_X}$. Let $B_{X^\ast}^-$ be the [[Definiti...
We first consider the case $\GF = \R$. Note that the conclusion is entirely independent of whether $\R$ or $\C$ is used, so this is unproblematic. Throughout we work in the [[Definition:Dual System|dual system]] $\innerprod X {X^\ast}$ over $\R$, where: :$\innerprod x f = \map f x$ for each $\tuple {x, f} \in X \time...
Banach-Dieudonné Theorem
https://proofwiki.org/wiki/Banach-Dieudonné_Theorem
https://proofwiki.org/wiki/Banach-Dieudonné_Theorem
[ "Banach-Dieudonné Theorem", "Weak-* Topologies", "Convex Sets (Vector Spaces)" ]
[ "Definition:Banach Space", "Definition:Normed Dual Space", "Definition:Closed Unit Ball", "Definition:Weak-* Topology", "Definition:Convex Set (Vector Space)", "Definition:Closed Set", "Definition:Closed Set" ]
[ "Definition:Dual System", "Definition:Dual System", "Normed Vector Space with Normed Dual Space is Dual System", "Definition:Absolute Polar", "Definition:One-Sided Polar", "Definition:Dual System", "Definition:Closed Set", "Closed Unit Ball in Normed Dual Space is Weak-* Closed", "Definition:Closed ...
proofwiki-22990
One-Sided Polar of Symmetric Set is equal to Absolute Polar
Let $\innerprod E F$ be a dual system over $\R$. Let $A \subseteq E$ be a symmetric set. Let $A^\odot$ be the one-sided polar of $A$. Let $A^\circ$ be the absolute polar of $A$. Then $A^\odot = A^\circ$.
Let $f \in A^\circ$. Then for each $x \in A$, we have: :$\cmod {\innerprod x f} \le 1$ and in particular: :$\innerprod x f \le 1$ Hence $f \in A^\odot$. Hence we have: :$A^\circ \subseteq A^\odot$ We now just need to show that: :$A^\odot \subseteq A^\circ$ Let $f \in A^\odot$. Let $x \in A$. Then: :$\innerprod x f \le ...
Let $\innerprod E F$ be a [[Definition:Dual System|dual system]] over $\R$. Let $A \subseteq E$ be a [[Definition:Symmetric Set|symmetric set]]. Let $A^\odot$ be the [[Definition:One-Sided Polar|one-sided polar]] of $A$. Let $A^\circ$ be the [[Definition:Absolute Polar|absolute polar]] of $A$. Then $A^\odot = A^\...
Let $f \in A^\circ$. Then for each $x \in A$, we have: :$\cmod {\innerprod x f} \le 1$ and in particular: :$\innerprod x f \le 1$ Hence $f \in A^\odot$. Hence we have: :$A^\circ \subseteq A^\odot$ We now just need to show that: :$A^\odot \subseteq A^\circ$ Let $f \in A^\odot$. Let $x \in A$. Then: :$\innerprod ...
One-Sided Polar of Symmetric Set is equal to Absolute Polar
https://proofwiki.org/wiki/One-Sided_Polar_of_Symmetric_Set_is_equal_to_Absolute_Polar
https://proofwiki.org/wiki/One-Sided_Polar_of_Symmetric_Set_is_equal_to_Absolute_Polar
[ "One-Sided Polars", "Absolute Polars", "One-Sided Polars", "Absolute Polars" ]
[ "Definition:Dual System", "Definition:Symmetric Set", "Definition:One-Sided Polar", "Definition:Absolute Polar" ]
[ "Definition:Symmetric Set", "Definition:Bilinear Mapping", "Category:One-Sided Polars", "Category:Absolute Polars" ]
proofwiki-22991
Normed Vector Space with Normed Dual Space is Dual System
Let $\GF \in \set {\R, \C}$. Let $\struct {X, \norm {\, \cdot \,}_X}$ be a normed vector space. Let $\struct {X^\ast, \norm {\, \cdot \,}_{X^\ast} }$ be the normed dual space of $\struct {X, \norm {\, \cdot \,}_X}$. Define $\innerprod \cdot \cdot : X \times X^\ast \to \GF$ by: :$\innerprod x f = \map f x$ for each $\tu...
Let $X^\#$ be the algebraic dual of $X$. From Normed Dual Space is Banach Space, $X^\ast$ is a vector subspace of $X^\#$. From Normed Dual Space Separates Points, $X^\ast$ separates points. Hence from Vector Space with Subspace of Algebraic Dual Separating Points is Dual System, $\tuple {X, X^\ast, \innerprod \cdot \cd...
Let $\GF \in \set {\R, \C}$. Let $\struct {X, \norm {\, \cdot \,}_X}$ be a [[Definition:Normed Vector Space|normed vector space]]. Let $\struct {X^\ast, \norm {\, \cdot \,}_{X^\ast} }$ be the [[Definition:Normed Dual Space|normed dual space]] of $\struct {X, \norm {\, \cdot \,}_X}$. Define $\innerprod \cdot \cdot : ...
Let $X^\#$ be the [[Definition:Algebraic Dual|algebraic dual]] of $X$. From [[Normed Dual Space is Banach Space]], $X^\ast$ is a [[Definition:Vector Subspace|vector subspace]] of $X^\#$. From [[Normed Dual Space Separates Points]], $X^\ast$ [[Definition:Mappings Separating Points|separates points]]. Hence from [[Vec...
Normed Vector Space with Normed Dual Space is Dual System
https://proofwiki.org/wiki/Normed_Vector_Space_with_Normed_Dual_Space_is_Dual_System
https://proofwiki.org/wiki/Normed_Vector_Space_with_Normed_Dual_Space_is_Dual_System
[ "Normed Vector Spaces", "Dual Systems" ]
[ "Definition:Normed Vector Space", "Definition:Normed Dual Space", "Definition:Dual System" ]
[ "Definition:Algebraic Dual", "Normed Dual Space is Banach Space", "Definition:Vector Subspace", "Normed Dual Space Separates Points", "Definition:Mappings Separating Points", "Vector Space with Subspace of Algebraic Dual Separating Points is Dual System", "Definition:Dual System", "Category:Normed Vec...
proofwiki-22992
Sphere is not Developable Surface
The sphere is ''not'' a developable surface.
{{ProofWanted|Little formal work on curvature has been established on {{ProofWiki}}, so this is being left open while some of that work has been accomplished. Should be a result Gaussian Curvature of Sphere equals Curvature of Great Circle or some such}}
The [[Definition:Sphere (Geometry)|sphere]] is ''not'' a [[Definition:Developable Surface|developable surface]].
{{ProofWanted|Little formal work on curvature has been established on {{ProofWiki}}, so this is being left open while some of that work has been accomplished. Should be a result [[Gaussian Curvature of Sphere equals Curvature of Great Circle]] or some such}}
Sphere is not Developable Surface
https://proofwiki.org/wiki/Sphere_is_not_Developable_Surface
https://proofwiki.org/wiki/Sphere_is_not_Developable_Surface
[ "Spheres", "Developable Surfaces" ]
[ "Definition:Sphere/Geometry", "Definition:Developable Surface" ]
[ "Gaussian Curvature of Sphere equals Curvature of Great Circle" ]
proofwiki-22993
One-Sided Polar is Closed in Weak-* Topology
Let $\innerprod E F$ be a dual system over $\R$. Let $\map \sigma {F, E}$ be the weak-$\ast$ topology on $F$ induced by $\innerprod E F$. Let $A \subseteq E$ be a non-empty set. Let $A^\odot$ be the one-sided polar. Then $A^\odot$ is $\map \sigma {F, E}$-closed.
We use Characterization of Closedness in terms of Nets. We show that every convergent net valued in $A^\odot$ has its limit in $A^\odot$. Let $\struct {\Lambda, \preceq}$ be a directed set. Let $\family {f_\lambda}_{\lambda \mathop \in \Lambda}$ be a convergent net valued in $A^\odot$ with limit $f \in F$. Then for ea...
Let $\innerprod E F$ be a [[Definition:Dual System|dual system]] over $\R$. Let $\map \sigma {F, E}$ be the [[Definition:Weak-* Topology Induced by Dual System|weak-$\ast$ topology]] on $F$ induced by $\innerprod E F$. Let $A \subseteq E$ be a [[Definition:Non-Empty Set|non-empty set]]. Let $A^\odot$ be the [[Defini...
We use [[Characterization of Closedness in terms of Nets]]. We show that every [[Definition:Convergent Net|convergent net]] valued in $A^\odot$ has its [[Definition:Limit of Net|limit]] in $A^\odot$. Let $\struct {\Lambda, \preceq}$ be a [[Definition:Directed Set|directed set]]. Let $\family {f_\lambda}_{\lambda \ma...
One-Sided Polar is Closed in Weak-* Topology
https://proofwiki.org/wiki/One-Sided_Polar_is_Closed_in_Weak-*_Topology
https://proofwiki.org/wiki/One-Sided_Polar_is_Closed_in_Weak-*_Topology
[ "One-Sided Polars", "Weak Topologies Induced by Dual Systems" ]
[ "Definition:Dual System", "Definition:Weak-* Topology Induced by Dual System", "Definition:Non-Empty Set", "Definition:One-Sided Polar", "Definition:Closed Set" ]
[ "Characterization of Closedness in terms of Nets", "Definition:Convergent Net", "Definition:Limit of Net", "Definition:Directed Preordering", "Definition:Convergent Net", "Definition:Limit of Net", "Characterization of Convergence of Net in Weak-* Topology Induced by Dual System", "Characterization of...
proofwiki-22994
Closed Unit Ball in Normed Vector Space is Balanced
Let $\GF \in \set {\R, \C}$. Let $\struct {X, \norm {\, \cdot \,}_X}$ be a normed vector space over $\GF$. Let $B_X^-$ be the closed unit ball of $\struct {X, \norm {\, \cdot \,}_X}$. Then $B_X^-$ is balanced.
Let $x \in B_X^-$. Let $\lambda \in \GF$ be such that $\cmod \lambda \le 1$. We have: {{begin-eqn}} {{eqn | l = \norm {\lambda x}_X | r = \cmod \lambda \norm x_X | c = {{NormAxiomVector|2}} }} {{eqn | o = \le | r = \norm x_X }} {{eqn | o = \le | r = 1 }} {{end-eqn}} {{qed}} Category:Balanced Sets Category:Nor...
Let $\GF \in \set {\R, \C}$. Let $\struct {X, \norm {\, \cdot \,}_X}$ be a [[Definition:Normed Vector Space|normed vector space]] over $\GF$. Let $B_X^-$ be the [[Definition:Closed Unit Ball|closed unit ball]] of $\struct {X, \norm {\, \cdot \,}_X}$. Then $B_X^-$ is [[Definition:Balanced Set|balanced]].
Let $x \in B_X^-$. Let $\lambda \in \GF$ be such that $\cmod \lambda \le 1$. We have: {{begin-eqn}} {{eqn | l = \norm {\lambda x}_X | r = \cmod \lambda \norm x_X | c = {{NormAxiomVector|2}} }} {{eqn | o = \le | r = \norm x_X }} {{eqn | o = \le | r = 1 }} {{end-eqn}} {{qed}} [[Category:Balanced Sets]] [[Cat...
Closed Unit Ball in Normed Vector Space is Balanced
https://proofwiki.org/wiki/Closed_Unit_Ball_in_Normed_Vector_Space_is_Balanced
https://proofwiki.org/wiki/Closed_Unit_Ball_in_Normed_Vector_Space_is_Balanced
[ "Balanced Sets", "Normed Vector Spaces" ]
[ "Definition:Normed Vector Space", "Definition:Closed Unit Ball", "Definition:Balanced Set" ]
[ "Category:Balanced Sets", "Category:Normed Vector Spaces" ]
proofwiki-22995
Absolute Polar of Closed Unit Ball in Normed Vector Space
Let $\GF \in \set {\R, \C}$. Let $\struct {X, \norm {\, \cdot \,}_X}$ be a normed vector space over $\GF$. Let $\struct {X^\ast, \norm {\, \cdot \,}_{X^\ast} }$ be the normed dual space of \struct {X, \norm {\, \cdot \,}_X}$. Let $B_X^-$ be the closed unit ball of $\struct {X, \norm {\, \cdot \,}_X}$. Let $B_{X^\ast}^-...
We have: {{begin-eqn}} {{eqn | l = \paren {B_X^-}^\circ | r = \set {f \in X^\ast : \cmod {\map f x} \le 1 \text { for each } x \in B_X^-} }} {{eqn | r = \set {f \in X^\ast : \norm f_{X^\ast} \le 1} | c = {{Defof|Norm on Bounded Linear Functional}} }} {{eqn | r = B_{X^\ast}^- }} {{end-eqn}} {{qed}} Category:Absolute...
Let $\GF \in \set {\R, \C}$. Let $\struct {X, \norm {\, \cdot \,}_X}$ be a [[Definition:Normed Vector Space|normed vector space]] over $\GF$. Let $\struct {X^\ast, \norm {\, \cdot \,}_{X^\ast} }$ be the [[Definition:Normed Dual Space|normed dual space]] of \struct {X, \norm {\, \cdot \,}_X}$. Let $B_X^-$ be the [[De...
We have: {{begin-eqn}} {{eqn | l = \paren {B_X^-}^\circ | r = \set {f \in X^\ast : \cmod {\map f x} \le 1 \text { for each } x \in B_X^-} }} {{eqn | r = \set {f \in X^\ast : \norm f_{X^\ast} \le 1} | c = {{Defof|Norm on Bounded Linear Functional}} }} {{eqn | r = B_{X^\ast}^- }} {{end-eqn}} {{qed}} [[Category:Absol...
Absolute Polar of Closed Unit Ball in Normed Vector Space
https://proofwiki.org/wiki/Absolute_Polar_of_Closed_Unit_Ball_in_Normed_Vector_Space
https://proofwiki.org/wiki/Absolute_Polar_of_Closed_Unit_Ball_in_Normed_Vector_Space
[ "Absolute Polars", "Normed Vector Spaces" ]
[ "Definition:Normed Vector Space", "Definition:Normed Dual Space", "Definition:Closed Unit Ball", "Definition:Closed Unit Ball", "Definition:Absolute Polar", "Definition:Dual System" ]
[ "Category:Absolute Polars", "Category:Normed Vector Spaces" ]
proofwiki-22996
One-Sided Polar of Closed Unit Ball in Normed Vector Space
Let $\struct {X, \norm {\, \cdot \,}_X}$ be a normed vector space over $\R$. Let $\struct {X^\ast, \norm {\, \cdot \,}_{X^\ast} }$ be the normed dual space of \struct {X, \norm {\, \cdot \,}_X}$. Let $B_X^-$ be the closed unit ball of $\struct {X, \norm {\, \cdot \,}_X}$. Let $B_{X^\ast}^-$ be the closed unit ball of $...
Let $\paren {B_X^-}^\circ$ be the absolute polar of $B_X^-$. From Closed Unit Ball in Normed Vector Space is Balanced, we have that $B_X^-$ is balanced. Hence from One-Sided Polar of Symmetric Set is equal to Absolute Polar and Balanced Set in Vector Space is Symmetric, we have: :$\paren {B_X^-}^\odot = \paren {B_X^-}^...
Let $\struct {X, \norm {\, \cdot \,}_X}$ be a [[Definition:Normed Vector Space|normed vector space]] over $\R$. Let $\struct {X^\ast, \norm {\, \cdot \,}_{X^\ast} }$ be the [[Definition:Normed Dual Space|normed dual space]] of \struct {X, \norm {\, \cdot \,}_X}$. Let $B_X^-$ be the [[Definition:Closed Unit Ball|close...
Let $\paren {B_X^-}^\circ$ be the [[Definition:Absolute Polar|absolute polar]] of $B_X^-$. From [[Closed Unit Ball in Normed Vector Space is Balanced]], we have that $B_X^-$ is [[Definition:Balanced Set|balanced]]. Hence from [[One-Sided Polar of Symmetric Set is equal to Absolute Polar]] and [[Balanced Set in Vector...
One-Sided Polar of Closed Unit Ball in Normed Vector Space
https://proofwiki.org/wiki/One-Sided_Polar_of_Closed_Unit_Ball_in_Normed_Vector_Space
https://proofwiki.org/wiki/One-Sided_Polar_of_Closed_Unit_Ball_in_Normed_Vector_Space
[ "One-Sided Polars", "Normed Vector Spaces" ]
[ "Definition:Normed Vector Space", "Definition:Normed Dual Space", "Definition:Closed Unit Ball", "Definition:Closed Unit Ball", "Definition:One-Sided Polar", "Definition:Dual System" ]
[ "Definition:Absolute Polar", "Closed Unit Ball in Normed Vector Space is Balanced", "Definition:Balanced Set", "One-Sided Polar of Symmetric Set is equal to Absolute Polar", "Balanced Set in Vector Space is Symmetric", "Absolute Polar of Closed Unit Ball in Normed Vector Space", "Category:One-Sided Pola...
proofwiki-22997
Absolute Prepolar of Closed Unit Ball in Normed Dual Space
Let $\GF \in \set {\R, \C}$. Let $\struct {X, \norm {\, \cdot \,}_X}$ be a normed vector space over $\GF$. Let $\struct {X^\ast, \norm {\, \cdot \,}_{X^\ast} }$ be the normed dual space of $\struct {X, \norm {\, \cdot \,}_X}$. Let $B_X^-$ be the closed unit ball of $\struct {X, \norm {\, \cdot \,}_X}$. Let $B_{X^\ast}^...
We have: {{begin-eqn}} {{eqn | l = \paren {B_{X^\ast}^-}_\circ | r = \set {x \in X : \cmod {\map f x} \le 1 \text { for all } f \in B_{X^\ast}^-} }} {{eqn | r = \set {x \in X : \sup_{f \mathop \in B_{X^\ast}^-} \cmod {\map f x} \le 1} }} {{eqn | r = \set {x \in X : \norm x_X \le 1} | c = Norm in terms of Normed Dua...
Let $\GF \in \set {\R, \C}$. Let $\struct {X, \norm {\, \cdot \,}_X}$ be a [[Definition:Normed Vector Space|normed vector space]] over $\GF$. Let $\struct {X^\ast, \norm {\, \cdot \,}_{X^\ast} }$ be the [[Definition:Normed Dual Space|normed dual space]] of $\struct {X, \norm {\, \cdot \,}_X}$. Let $B_X^-$ be the [[D...
We have: {{begin-eqn}} {{eqn | l = \paren {B_{X^\ast}^-}_\circ | r = \set {x \in X : \cmod {\map f x} \le 1 \text { for all } f \in B_{X^\ast}^-} }} {{eqn | r = \set {x \in X : \sup_{f \mathop \in B_{X^\ast}^-} \cmod {\map f x} \le 1} }} {{eqn | r = \set {x \in X : \norm x_X \le 1} | c = [[Norm in terms of Normed D...
Absolute Prepolar of Closed Unit Ball in Normed Dual Space
https://proofwiki.org/wiki/Absolute_Prepolar_of_Closed_Unit_Ball_in_Normed_Dual_Space
https://proofwiki.org/wiki/Absolute_Prepolar_of_Closed_Unit_Ball_in_Normed_Dual_Space
[ "Absolute Prepolars", "Normed Dual Spaces" ]
[ "Definition:Normed Vector Space", "Definition:Normed Dual Space", "Definition:Closed Unit Ball", "Definition:Closed Unit Ball", "Definition:Absolute Prepolar", "Definition:Dual System" ]
[ "Norm in terms of Normed Dual Space", "Category:Absolute Prepolars", "Category:Normed Dual Spaces" ]
proofwiki-22998
Real Matrix is Diagonalizable if Roots of Characteristic Equation are Real and Distinct
Let $\mathbf A$ be a square matrix of order $n$ whose entries are real. Let the $n$ roots of the characteristic equation of $\mathbf A$ be real and distinct. Then $\mathbf A$ is diagonalizable in $\mathbb R^n$.
From Number of Roots of Polynomial With Complex Coefficients Equals Degree of Polynomial, $n$ distinct roots of a degree $n$ characteristic polynomial must have algebraic multipicity of $1$. Since Algebraic Multiplicity is not Less than Geometric Multiplicity, the geometric multiplicity of each eigenvalue is $1$. Thus,...
Let $\mathbf A$ be a [[Definition:Square Matrix|square matrix]] of [[Definition:Order of Square Matrix|order]] $n$ whose [[Definition:Matrix Entry|entries]] are [[Definition:Real Number|real]]. Let the $n$ [[Definition:Root of Equation|roots]] of the [[Definition:Characteristic Equation of Matrix|characteristic equati...
From [[Number of Roots of Polynomial With Complex Coefficients Equals Degree of Polynomial]], $n$ distinct [[Definition:Root of Polynomial|roots]] of a [[Definition:Degree of Polynomial|degree]] $n$ [[Definition:Characteristic Polynomial of Matrix|characteristic polynomial]] must have [[Definition:Algebraic Multiplicit...
Real Matrix is Diagonalizable if Roots of Characteristic Equation are Real and Distinct
https://proofwiki.org/wiki/Real_Matrix_is_Diagonalizable_if_Roots_of_Characteristic_Equation_are_Real_and_Distinct
https://proofwiki.org/wiki/Real_Matrix_is_Diagonalizable_if_Roots_of_Characteristic_Equation_are_Real_and_Distinct
[ "Diagonalizable Matrices" ]
[ "Definition:Matrix/Square Matrix", "Definition:Matrix/Square Matrix/Order", "Definition:Matrix/Element", "Definition:Real Number", "Definition:Root of Equation", "Definition:Characteristic Equation of Matrix", "Definition:Real Number", "Definition:Distinct/Plural", "Definition:Diagonalizable Matrix"...
[ "Number of Roots of Polynomial With Complex Coefficients Equals Degree of Polynomial", "Definition:Root of Polynomial", "Definition:Degree of Polynomial", "Definition:Characteristic Polynomial of Matrix", "Definition:Algebraic Multiplicity", "Algebraic Multiplicity is not Less than Geometric Multiplicity"...
proofwiki-22999
Powers of Diagonalizable Matrix
Let $\mathbf A$ be a square matrix which is diagonalizable matrix. Let $\mathbf D$ be the diagonal matrix which is the result of the equation: :$\mathbf D = \mathbf X^{-1} \mathbf A \mathbf X$ for some nonsingular matrix $\mathbf X$. Then for all $n \in \Z_{\ge 0}$: :$\mathbf A^n = \mathbf X \mathbf D^n \mathbf X^{-1}$
The proof proceeds by induction. For all $n \in \Z_{\ge 0}$, let $\map P n$ be the proposition: :$\mathbf A^n = \mathbf X \mathbf D^n \mathbf X^{-1}$ Let $\mathbf A$ be of dimension $m$ where $m \in \Z_{\ge 1}$. $\map P 0$ is the case: {{begin-eqn}} {{eqn | l = \mathbf A^0 | r = \mathbf I_m | c = where $\ma...
Let $\mathbf A$ be a [[Definition:Square Matrix|square matrix]] which is [[Definition:Diagonalizable Matrix|diagonalizable matrix]]. Let $\mathbf D$ be the [[Definition:Diagonal Matrix|diagonal matrix]] which is the result of the [[Definition:Equation|equation]]: :$\mathbf D = \mathbf X^{-1} \mathbf A \mathbf X$ for s...
The proof proceeds by [[Principle of Mathematical Induction|induction]]. For all $n \in \Z_{\ge 0}$, let $\map P n$ be the [[Definition:Proposition|proposition]]: :$\mathbf A^n = \mathbf X \mathbf D^n \mathbf X^{-1}$ Let $\mathbf A$ be of [[Definition:Dimension of Square Matrix|dimension]] $m$ where $m \in \Z_{\ge 1...
Powers of Diagonalizable Matrix
https://proofwiki.org/wiki/Powers_of_Diagonalizable_Matrix
https://proofwiki.org/wiki/Powers_of_Diagonalizable_Matrix
[ "Powers of Diagonalizable Matrix", "Diagonalizable Matrices" ]
[ "Definition:Matrix/Square Matrix", "Definition:Diagonalizable Matrix", "Definition:Diagonal Matrix", "Definition:Equation", "Definition:Nonsingular Matrix" ]
[ "Principle of Mathematical Induction", "Definition:Proposition", "Definition:Matrix/Square Matrix/Order", "Definition:Unit Matrix", "Definition:Matrix/Square Matrix/Order", "Principle of Mathematical Induction" ]