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proofwiki-8100
Cotangent of Angle plus Full Angle
: $\cot \left({x + 2 \pi}\right) = \cot x$
{{begin-eqn}} {{eqn | l = \cot \left({x + 2 \pi}\right) | r = \frac {\cos \left({x + 2 \pi}\right)} {\sin \left({x + 2 \pi}\right)} | c = Cotangent is Cosine divided by Sine }} {{eqn | r = \frac {\cos x} {\sin x} | c = Cosine of Angle plus Full Angle and Sine of Angle plus Full Angle }} {{eqn | r = \...
: $\cot \left({x + 2 \pi}\right) = \cot x$
{{begin-eqn}} {{eqn | l = \cot \left({x + 2 \pi}\right) | r = \frac {\cos \left({x + 2 \pi}\right)} {\sin \left({x + 2 \pi}\right)} | c = [[Cotangent is Cosine divided by Sine]] }} {{eqn | r = \frac {\cos x} {\sin x} | c = [[Cosine of Angle plus Full Angle]] and [[Sine of Angle plus Full Angle]] }} {...
Cotangent of Angle plus Full Angle
https://proofwiki.org/wiki/Cotangent_of_Angle_plus_Full_Angle
https://proofwiki.org/wiki/Cotangent_of_Angle_plus_Full_Angle
[ "Cotangent Function" ]
[]
[ "Cotangent is Cosine divided by Sine", "Cosine of Angle plus Full Angle", "Sine of Angle plus Full Angle", "Cotangent is Cosine divided by Sine" ]
proofwiki-8101
Secant of Angle plus Full Angle
: $\sec \left({x + 2 \pi}\right) = \sec x$
{{begin-eqn}} {{eqn | l = \sec \left({x + 2 \pi}\right) | r = \frac 1 {\cos \left({x + 2 \pi}\right)} | c = Secant is Reciprocal of Cosine }} {{eqn | r = \frac 1 {\cos x} | c = Cosine of Angle plus Full Angle }} {{eqn | r = \sec x | c = Secant is Reciprocal of Cosine }} {{end-eqn}} {{qed}}
: $\sec \left({x + 2 \pi}\right) = \sec x$
{{begin-eqn}} {{eqn | l = \sec \left({x + 2 \pi}\right) | r = \frac 1 {\cos \left({x + 2 \pi}\right)} | c = [[Secant is Reciprocal of Cosine]] }} {{eqn | r = \frac 1 {\cos x} | c = [[Cosine of Angle plus Full Angle]] }} {{eqn | r = \sec x | c = [[Secant is Reciprocal of Cosine]] }} {{end-eqn}} ...
Secant of Angle plus Full Angle
https://proofwiki.org/wiki/Secant_of_Angle_plus_Full_Angle
https://proofwiki.org/wiki/Secant_of_Angle_plus_Full_Angle
[ "Secant Function" ]
[]
[ "Secant is Reciprocal of Cosine", "Cosine of Angle plus Full Angle", "Secant is Reciprocal of Cosine" ]
proofwiki-8102
Cosecant of Angle plus Full Angle
: $\csc \left({x + 2 \pi}\right) = \csc x$
{{begin-eqn}} {{eqn | l = \csc \left({x + 2 \pi}\right) | r = \frac 1 {\sin \left({x + 2 \pi}\right)} | c = Cosecant is Reciprocal of Sine }} {{eqn | r = \frac 1 {\sin x} | c = Sine of Angle plus Straight Angle }} {{eqn | r = \csc x | c = Cosecant is Reciprocal of Sine }} {{end-eqn}} {{qed}}
: $\csc \left({x + 2 \pi}\right) = \csc x$
{{begin-eqn}} {{eqn | l = \csc \left({x + 2 \pi}\right) | r = \frac 1 {\sin \left({x + 2 \pi}\right)} | c = [[Cosecant is Reciprocal of Sine]] }} {{eqn | r = \frac 1 {\sin x} | c = [[Sine of Angle plus Straight Angle]] }} {{eqn | r = \csc x | c = [[Cosecant is Reciprocal of Sine]] }} {{end-eqn}...
Cosecant of Angle plus Full Angle
https://proofwiki.org/wiki/Cosecant_of_Angle_plus_Full_Angle
https://proofwiki.org/wiki/Cosecant_of_Angle_plus_Full_Angle
[ "Cosecant Function" ]
[]
[ "Cosecant is Reciprocal of Sine", "Sine of Angle plus Straight Angle", "Cosecant is Reciprocal of Sine" ]
proofwiki-8103
Sine of Angle plus Three Right Angles
:$\map \sin {x + \dfrac {3 \pi} 2} = -\cos x$
{{begin-eqn}} {{eqn | l = \map \sin {x + \frac {3 \pi} 2} | r = \sin x \cos \frac {3 \pi} 2 + \cos x \sin \frac {3 \pi} 2 | c = Sine of Sum }} {{eqn | r = \sin x \cdot 0 + \cos x \cdot \paren {-1} | c = Cosine of Three Right Angles and Sine of Three Right Angles }} {{eqn | r = -\cos x | c = }} ...
:$\map \sin {x + \dfrac {3 \pi} 2} = -\cos x$
{{begin-eqn}} {{eqn | l = \map \sin {x + \frac {3 \pi} 2} | r = \sin x \cos \frac {3 \pi} 2 + \cos x \sin \frac {3 \pi} 2 | c = [[Sine of Sum]] }} {{eqn | r = \sin x \cdot 0 + \cos x \cdot \paren {-1} | c = [[Cosine of Three Right Angles]] and [[Sine of Three Right Angles]] }} {{eqn | r = -\cos x ...
Sine of Angle plus Three Right Angles
https://proofwiki.org/wiki/Sine_of_Angle_plus_Three_Right_Angles
https://proofwiki.org/wiki/Sine_of_Angle_plus_Three_Right_Angles
[ "Sine Function" ]
[]
[ "Sine of Sum", "Cosine of Three Right Angles", "Sine of Three Right Angles" ]
proofwiki-8104
Cosine of Angle plus Three Right Angles
:$\map \cos {x + \dfrac {3 \pi} 2} = \sin x$
{{begin-eqn}} {{eqn | l = \map \cos {x + \frac {3 \pi} 2} | r = \cos x \cos \frac {3 \pi} 2 - \sin x \sin \frac {3 \pi} 2 | c = Cosine of Sum }} {{eqn | r = \cos x \cdot 0 - \sin x \cdot \paren {-1} | c = Cosine of Three Right Angles and Sine of Three Right Angles }} {{eqn | r = \sin x | c = }}...
:$\map \cos {x + \dfrac {3 \pi} 2} = \sin x$
{{begin-eqn}} {{eqn | l = \map \cos {x + \frac {3 \pi} 2} | r = \cos x \cos \frac {3 \pi} 2 - \sin x \sin \frac {3 \pi} 2 | c = [[Cosine of Sum]] }} {{eqn | r = \cos x \cdot 0 - \sin x \cdot \paren {-1} | c = [[Cosine of Three Right Angles]] and [[Sine of Three Right Angles]] }} {{eqn | r = \sin x ...
Cosine of Angle plus Three Right Angles
https://proofwiki.org/wiki/Cosine_of_Angle_plus_Three_Right_Angles
https://proofwiki.org/wiki/Cosine_of_Angle_plus_Three_Right_Angles
[ "Cosine Function" ]
[]
[ "Cosine of Sum", "Cosine of Three Right Angles", "Sine of Three Right Angles" ]
proofwiki-8105
Tangent of Angle plus Three Right Angles
:$\map \tan {x + \dfrac {3 \pi} 2} = -\cot x$
{{begin-eqn}} {{eqn | l = \map \tan {x + \frac {3 \pi} 2} | r = \frac {\map \sin {x + \frac {3 \pi} 2} } {\map \cos {x + \frac {3 \pi} 2} } | c = Tangent is Sine divided by Cosine }} {{eqn | r = \frac {-\cos x} {\sin x} | c = Sine of Angle plus Three Right Angles and Cosine of Angle plus Three Right ...
:$\map \tan {x + \dfrac {3 \pi} 2} = -\cot x$
{{begin-eqn}} {{eqn | l = \map \tan {x + \frac {3 \pi} 2} | r = \frac {\map \sin {x + \frac {3 \pi} 2} } {\map \cos {x + \frac {3 \pi} 2} } | c = [[Tangent is Sine divided by Cosine]] }} {{eqn | r = \frac {-\cos x} {\sin x} | c = [[Sine of Angle plus Three Right Angles]] and [[Cosine of Angle plus Th...
Tangent of Angle plus Three Right Angles
https://proofwiki.org/wiki/Tangent_of_Angle_plus_Three_Right_Angles
https://proofwiki.org/wiki/Tangent_of_Angle_plus_Three_Right_Angles
[ "Tangent Function" ]
[]
[ "Tangent is Sine divided by Cosine", "Sine of Angle plus Three Right Angles", "Cosine of Angle plus Three Right Angles", "Cotangent is Cosine divided by Sine" ]
proofwiki-8106
Cotangent of Angle plus Three Right Angles
:$\map \cot {x + \dfrac {3 \pi} 2} = -\tan x$
{{begin-eqn}} {{eqn | l = \map \cot {x + \frac {3 \pi} 2} | r = \frac {\map \cos {x + \frac {3 \pi} 2} } {\map \sin {x + \frac {3 \pi} 2} } | c = Cotangent is Cosine divided by Sine }} {{eqn | r = \frac {\sin x} {-\cos x} | c = Cosine of Angle plus Right Angle and Sine of Angle plus Right Angle }} {{e...
:$\map \cot {x + \dfrac {3 \pi} 2} = -\tan x$
{{begin-eqn}} {{eqn | l = \map \cot {x + \frac {3 \pi} 2} | r = \frac {\map \cos {x + \frac {3 \pi} 2} } {\map \sin {x + \frac {3 \pi} 2} } | c = [[Cotangent is Cosine divided by Sine]] }} {{eqn | r = \frac {\sin x} {-\cos x} | c = [[Cosine of Angle plus Right Angle]] and [[Sine of Angle plus Right An...
Cotangent of Angle plus Three Right Angles
https://proofwiki.org/wiki/Cotangent_of_Angle_plus_Three_Right_Angles
https://proofwiki.org/wiki/Cotangent_of_Angle_plus_Three_Right_Angles
[ "Cotangent Function" ]
[]
[ "Cotangent is Cosine divided by Sine", "Cosine of Angle plus Right Angle", "Sine of Angle plus Right Angle", "Tangent is Sine divided by Cosine" ]
proofwiki-8107
Secant of Angle plus Three Right Angles
:$\map \sec {x + \dfrac {3 \pi} 2} = \csc x$
{{begin-eqn}} {{eqn | l = \map \sec {x + \frac {3 \pi} 2} | r = \frac 1 {\map \cos {x + \frac {3 \pi} 2} } | c = Secant is Reciprocal of Cosine }} {{eqn | r = \frac 1 {\sin x} | c = Cosine of Angle plus Three Right Angles }} {{eqn | r = \csc x | c = Cosecant is Reciprocal of Sine }} {{end-eqn}} ...
:$\map \sec {x + \dfrac {3 \pi} 2} = \csc x$
{{begin-eqn}} {{eqn | l = \map \sec {x + \frac {3 \pi} 2} | r = \frac 1 {\map \cos {x + \frac {3 \pi} 2} } | c = [[Secant is Reciprocal of Cosine]] }} {{eqn | r = \frac 1 {\sin x} | c = [[Cosine of Angle plus Three Right Angles]] }} {{eqn | r = \csc x | c = [[Cosecant is Reciprocal of Sine]] }} ...
Secant of Angle plus Three Right Angles
https://proofwiki.org/wiki/Secant_of_Angle_plus_Three_Right_Angles
https://proofwiki.org/wiki/Secant_of_Angle_plus_Three_Right_Angles
[ "Secant Function" ]
[]
[ "Secant is Reciprocal of Cosine", "Cosine of Angle plus Three Right Angles", "Cosecant is Reciprocal of Sine" ]
proofwiki-8108
Cosecant of Angle plus Three Right Angles
:$\map \csc {x + \dfrac {3 \pi} 2} = -\sec x$
{{begin-eqn}} {{eqn | l = \map \csc {x + \frac {3 \pi} 2} | r = \frac 1 {\map \sin {x + \frac {3 \pi} 2} } | c = Cosecant is Reciprocal of Sine }} {{eqn | r = \frac 1 {-\cos x} | c = Sine of Angle plus Three Right Angles }} {{eqn | r = -\sec x | c = Secant is Reciprocal of Cosine }} {{end-eqn}} ...
:$\map \csc {x + \dfrac {3 \pi} 2} = -\sec x$
{{begin-eqn}} {{eqn | l = \map \csc {x + \frac {3 \pi} 2} | r = \frac 1 {\map \sin {x + \frac {3 \pi} 2} } | c = [[Cosecant is Reciprocal of Sine]] }} {{eqn | r = \frac 1 {-\cos x} | c = [[Sine of Angle plus Three Right Angles]] }} {{eqn | r = -\sec x | c = [[Secant is Reciprocal of Cosine]] }} ...
Cosecant of Angle plus Three Right Angles
https://proofwiki.org/wiki/Cosecant_of_Angle_plus_Three_Right_Angles
https://proofwiki.org/wiki/Cosecant_of_Angle_plus_Three_Right_Angles
[ "Cosecant Function" ]
[]
[ "Cosecant is Reciprocal of Sine", "Sine of Angle plus Three Right Angles", "Secant is Reciprocal of Cosine" ]
proofwiki-8109
Sine of Three Right Angles less Angle
:$\map \sin {\dfrac {3 \pi} 2 - \theta} = -\cos \theta$ where $\sin$ and $\cos$ are sine and cosine respectively.
{{begin-eqn}} {{eqn | l = \map \sin {\frac {3 \pi} 2 - \theta} | r = \sin \frac {3 \pi} 2 \cos \theta - \cos \frac {3 \pi} 2 \sin \theta | c = Sine of Difference }} {{eqn | r = \paren {-1} \times \cos \theta - 0 \times \sin \theta | c = Sine of Three Right Angles and Cosine of Three Right Angles }} {{...
:$\map \sin {\dfrac {3 \pi} 2 - \theta} = -\cos \theta$ where $\sin$ and $\cos$ are [[Definition:Sine|sine]] and [[Definition:Cosine|cosine]] respectively.
{{begin-eqn}} {{eqn | l = \map \sin {\frac {3 \pi} 2 - \theta} | r = \sin \frac {3 \pi} 2 \cos \theta - \cos \frac {3 \pi} 2 \sin \theta | c = [[Sine of Difference]] }} {{eqn | r = \paren {-1} \times \cos \theta - 0 \times \sin \theta | c = [[Sine of Three Right Angles]] and [[Cosine of Three Right An...
Sine of Three Right Angles less Angle
https://proofwiki.org/wiki/Sine_of_Three_Right_Angles_less_Angle
https://proofwiki.org/wiki/Sine_of_Three_Right_Angles_less_Angle
[ "Sine Function" ]
[ "Definition:Sine", "Definition:Cosine" ]
[ "Sine of Difference", "Sine of Three Right Angles", "Cosine of Three Right Angles" ]
proofwiki-8110
Cosine of Three Right Angles less Angle
:$\map \cos {\dfrac {3 \pi} 2 - \theta} = -\sin \theta$ where $\cos$ and $\sin$ are cosine and sine respectively.
{{begin-eqn}} {{eqn | l = \map \cos {\frac {3 \pi} 2 - \theta} | r = \cos \frac {3 \pi} 2 \cos \theta + \sin \frac {3 \pi} 2 \sin \theta | c = Cosine of Difference }} {{eqn | r = 0 \times \cos \theta + \paren {-1} \times \sin \theta | c = Cosine of Three Right Angles and Sine of Three Right Angles }} ...
:$\map \cos {\dfrac {3 \pi} 2 - \theta} = -\sin \theta$ where $\cos$ and $\sin$ are [[Definition:Cosine|cosine]] and [[Definition:Sine|sine]] respectively.
{{begin-eqn}} {{eqn | l = \map \cos {\frac {3 \pi} 2 - \theta} | r = \cos \frac {3 \pi} 2 \cos \theta + \sin \frac {3 \pi} 2 \sin \theta | c = [[Cosine of Difference]] }} {{eqn | r = 0 \times \cos \theta + \paren {-1} \times \sin \theta | c = [[Cosine of Three Right Angles]] and [[Sine of Three Right ...
Cosine of Three Right Angles less Angle
https://proofwiki.org/wiki/Cosine_of_Three_Right_Angles_less_Angle
https://proofwiki.org/wiki/Cosine_of_Three_Right_Angles_less_Angle
[ "Cosine Function" ]
[ "Definition:Cosine", "Definition:Sine" ]
[ "Cosine of Difference", "Cosine of Three Right Angles", "Sine of Three Right Angles" ]
proofwiki-8111
Secant of Three Right Angles less Angle
:$\map \sec {\dfrac {3 \pi} 2 - \theta} = -\csc \theta$ where $\sec$ and $\csc$ are secant and cosecant respectively.
{{begin-eqn}} {{eqn | l = \map \sec {\frac {3 \pi} 2 - \theta} | r = \frac 1 {\map \cos {\frac {3 \pi} 2 - \theta} } | c = Secant is Reciprocal of Cosine }} {{eqn | r = \frac 1 {-\sin \theta} | c = Cosine of Three Right Angles less Angle }} {{eqn | r = -\csc \theta | c = Cosecant is Reciprocal o...
:$\map \sec {\dfrac {3 \pi} 2 - \theta} = -\csc \theta$ where $\sec$ and $\csc$ are [[Definition:Secant Function|secant]] and [[Definition:Cosecant|cosecant]] respectively.
{{begin-eqn}} {{eqn | l = \map \sec {\frac {3 \pi} 2 - \theta} | r = \frac 1 {\map \cos {\frac {3 \pi} 2 - \theta} } | c = [[Secant is Reciprocal of Cosine]] }} {{eqn | r = \frac 1 {-\sin \theta} | c = [[Cosine of Three Right Angles less Angle]] }} {{eqn | r = -\csc \theta | c = [[Cosecant is Re...
Secant of Three Right Angles less Angle
https://proofwiki.org/wiki/Secant_of_Three_Right_Angles_less_Angle
https://proofwiki.org/wiki/Secant_of_Three_Right_Angles_less_Angle
[ "Secant Function" ]
[ "Definition:Secant Function", "Definition:Cosecant" ]
[ "Secant is Reciprocal of Cosine", "Cosine of Three Right Angles less Angle", "Cosecant is Reciprocal of Sine" ]
proofwiki-8112
Cosecant of Three Right Angles less Angle
:$\map \csc {\dfrac {3 \pi} 2 - \theta} = -\sec \theta$ where $\csc$ and $\sec$ are cosecant and secant respectively.
{{begin-eqn}} {{eqn | l = \map \csc {\frac {3 \pi} 2 - \theta} | r = \frac 1 {\map \sin {\frac {3 \pi} 2 - \theta} } | c = Cosecant is Reciprocal of Sine }} {{eqn | r = \frac 1 {-\cos \theta} | c = Sine of Three Right Angles less Angle }} {{eqn | r = -\sec \theta | c = Secant is Reciprocal of Co...
:$\map \csc {\dfrac {3 \pi} 2 - \theta} = -\sec \theta$ where $\csc$ and $\sec$ are [[Definition:Cosecant|cosecant]] and [[Definition:Secant Function|secant]] respectively.
{{begin-eqn}} {{eqn | l = \map \csc {\frac {3 \pi} 2 - \theta} | r = \frac 1 {\map \sin {\frac {3 \pi} 2 - \theta} } | c = [[Cosecant is Reciprocal of Sine]] }} {{eqn | r = \frac 1 {-\cos \theta} | c = [[Sine of Three Right Angles less Angle]] }} {{eqn | r = -\sec \theta | c = [[Secant is Recipr...
Cosecant of Three Right Angles less Angle
https://proofwiki.org/wiki/Cosecant_of_Three_Right_Angles_less_Angle
https://proofwiki.org/wiki/Cosecant_of_Three_Right_Angles_less_Angle
[ "Cosecant Function" ]
[ "Definition:Cosecant", "Definition:Secant Function" ]
[ "Cosecant is Reciprocal of Sine", "Sine of Three Right Angles less Angle", "Secant is Reciprocal of Cosine" ]
proofwiki-8113
Triple Angle Formulas/Sine
:$\sin 3 \theta = 3 \sin \theta - 4 \sin^3 \theta$
{{begin-eqn}} {{eqn | l = \sin 3 \theta | r = \map \sin {2 \theta + \theta} }} {{eqn | r = \sin 2 \theta \cos \theta + \cos 2 \theta \sin \theta | c = Sine of Sum }} {{eqn | r = \paren {2 \sin \theta \cos \theta} \cos \theta + \paren {\cos^2 \theta - \sin^2 \theta} \sin \theta | c = Double Angle Formu...
:$\sin 3 \theta = 3 \sin \theta - 4 \sin^3 \theta$
{{begin-eqn}} {{eqn | l = \sin 3 \theta | r = \map \sin {2 \theta + \theta} }} {{eqn | r = \sin 2 \theta \cos \theta + \cos 2 \theta \sin \theta | c = [[Sine of Sum]] }} {{eqn | r = \paren {2 \sin \theta \cos \theta} \cos \theta + \paren {\cos^2 \theta - \sin^2 \theta} \sin \theta | c = [[Double Angle...
Triple Angle Formulas/Sine/Proof 1
https://proofwiki.org/wiki/Triple_Angle_Formulas/Sine
https://proofwiki.org/wiki/Triple_Angle_Formulas/Sine/Proof_1
[ "Triple Angle Formula for Sine", "Triple Angle Formulas", "Sine Function" ]
[]
[ "Sine of Sum", "Double Angle Formulas/Sine", "Double Angle Formulas/Cosine", "Sum of Squares of Sine and Cosine" ]
proofwiki-8114
Triple Angle Formulas/Sine
:$\sin 3 \theta = 3 \sin \theta - 4 \sin^3 \theta$
We have: {{begin-eqn}} {{eqn | l = \cos 3 \theta + i \sin 3 \theta | r = \paren {\cos \theta + i \sin \theta}^3 | c = De Moivre's Formula }} {{eqn | r = \paren {\cos \theta}^3 + \binom 3 1 \paren {\cos \theta}^2 \paren {i \sin \theta} }} {{eqn | o = | ro=+ | r = \binom 3 2 \paren {\cos \theta} ...
:$\sin 3 \theta = 3 \sin \theta - 4 \sin^3 \theta$
We have: {{begin-eqn}} {{eqn | l = \cos 3 \theta + i \sin 3 \theta | r = \paren {\cos \theta + i \sin \theta}^3 | c = [[De Moivre's Formula]] }} {{eqn | r = \paren {\cos \theta}^3 + \binom 3 1 \paren {\cos \theta}^2 \paren {i \sin \theta} }} {{eqn | o = | ro=+ | r = \binom 3 2 \paren {\cos \th...
Triple Angle Formulas/Sine/Proof 2
https://proofwiki.org/wiki/Triple_Angle_Formulas/Sine
https://proofwiki.org/wiki/Triple_Angle_Formulas/Sine/Proof_2
[ "Triple Angle Formula for Sine", "Triple Angle Formulas", "Sine Function" ]
[]
[ "De Moivre's Formula", "Binomial Theorem", "Definition:Binomial Coefficient", "Definition:Complex Number/Imaginary Part", "Sum of Squares of Sine and Cosine" ]
proofwiki-8115
Triple Angle Formulas/Cosine
:$\cos 3 \theta = 4 \cos^3 \theta - 3 \cos \theta$
{{begin-eqn}} {{eqn | l = \cos 3 \theta | r = \cos \paren {2 \theta + \theta} }} {{eqn | r = \cos 2 \theta \cos \theta - \sin 2 \theta \sin \theta | c = Cosine of Sum }} {{eqn | r = \paren {\cos^2 \theta - \sin^2 \theta} \cos \theta - \paren {2 \sin \theta \cos \theta} \sin \theta | c = Double Angle F...
:$\cos 3 \theta = 4 \cos^3 \theta - 3 \cos \theta$
{{begin-eqn}} {{eqn | l = \cos 3 \theta | r = \cos \paren {2 \theta + \theta} }} {{eqn | r = \cos 2 \theta \cos \theta - \sin 2 \theta \sin \theta | c = [[Cosine of Sum]] }} {{eqn | r = \paren {\cos^2 \theta - \sin^2 \theta} \cos \theta - \paren {2 \sin \theta \cos \theta} \sin \theta | c = [[Double A...
Triple Angle Formulas/Cosine/Proof 1
https://proofwiki.org/wiki/Triple_Angle_Formulas/Cosine
https://proofwiki.org/wiki/Triple_Angle_Formulas/Cosine/Proof_1
[ "Triple Angle Formula for Cosine", "Triple Angle Formulas", "Cosine Function" ]
[]
[ "Cosine of Sum", "Double Angle Formulas/Cosine", "Double Angle Formulas/Sine", "Sum of Squares of Sine and Cosine" ]
proofwiki-8116
Triple Angle Formulas/Cosine
:$\cos 3 \theta = 4 \cos^3 \theta - 3 \cos \theta$
We have: {{begin-eqn}} {{eqn | l = \cos 3 \theta + i \sin 3 \theta | r = \paren {\cos \theta + i \sin \theta}^3 | c = De Moivre's Formula }} {{eqn | r = \paren {\cos \theta}^3 + \binom 3 1 \paren {\cos \theta}^2 \paren {i \sin \theta} | c = Binomial Theorem }} {{eqn | o = | ro=+ | r = \bi...
:$\cos 3 \theta = 4 \cos^3 \theta - 3 \cos \theta$
We have: {{begin-eqn}} {{eqn | l = \cos 3 \theta + i \sin 3 \theta | r = \paren {\cos \theta + i \sin \theta}^3 | c = [[De Moivre's Formula]] }} {{eqn | r = \paren {\cos \theta}^3 + \binom 3 1 \paren {\cos \theta}^2 \paren {i \sin \theta} | c = [[Binomial Theorem]] }} {{eqn | o = | ro=+ ...
Triple Angle Formulas/Cosine/Proof 2
https://proofwiki.org/wiki/Triple_Angle_Formulas/Cosine
https://proofwiki.org/wiki/Triple_Angle_Formulas/Cosine/Proof_2
[ "Triple Angle Formula for Cosine", "Triple Angle Formulas", "Cosine Function" ]
[]
[ "De Moivre's Formula", "Binomial Theorem", "Definition:Binomial Coefficient", "Definition:Complex Number/Real Part", "Sum of Squares of Sine and Cosine" ]
proofwiki-8117
Triple Angle Formulas/Cosine
:$\cos 3 \theta = 4 \cos^3 \theta - 3 \cos \theta$
{{begin-eqn}} {{eqn | l = \cos 3 \theta | r = \cos \paren {2 \theta + \theta} }} {{eqn | r = \cos 2 \theta \cos \theta - \sin 2 \theta \sin \theta | c = Cosine of Sum }} {{eqn | r = \paren {2 \cos^2 \theta - 1} \cos \theta - \paren {2 \sin \theta \cos \theta} \sin \theta | c = Double Angle Formula for...
:$\cos 3 \theta = 4 \cos^3 \theta - 3 \cos \theta$
{{begin-eqn}} {{eqn | l = \cos 3 \theta | r = \cos \paren {2 \theta + \theta} }} {{eqn | r = \cos 2 \theta \cos \theta - \sin 2 \theta \sin \theta | c = [[Cosine of Sum]] }} {{eqn | r = \paren {2 \cos^2 \theta - 1} \cos \theta - \paren {2 \sin \theta \cos \theta} \sin \theta | c = [[Double Angle Formu...
Triple Angle Formulas/Cosine/Proof 3
https://proofwiki.org/wiki/Triple_Angle_Formulas/Cosine
https://proofwiki.org/wiki/Triple_Angle_Formulas/Cosine/Proof_3
[ "Triple Angle Formula for Cosine", "Triple Angle Formulas", "Cosine Function" ]
[]
[ "Cosine of Sum", "Double Angle Formulas/Cosine", "Double Angle Formulas/Sine", "Sum of Squares of Sine and Cosine" ]
proofwiki-8118
Triple Angle Formulas/Tangent
:$\tan 3 \theta = \dfrac {3 \tan \theta - \tan^3 \theta} {1 - 3 \tan^2 \theta}$
{{begin-eqn}} {{eqn | l = \tan 3 \theta | r = \frac {\sin 3 \theta} {\cos 3 \theta} | c = Tangent is Sine divided by Cosine }} {{eqn | r = \frac {3 \sin \theta - 4 \sin^3 \theta} {4 \cos^3 \theta - 3 \cos \theta} | c = Triple Angle Formula for Sine and Triple Angle Formula for Cosine }} {{eqn | r = \f...
:$\tan 3 \theta = \dfrac {3 \tan \theta - \tan^3 \theta} {1 - 3 \tan^2 \theta}$
{{begin-eqn}} {{eqn | l = \tan 3 \theta | r = \frac {\sin 3 \theta} {\cos 3 \theta} | c = [[Tangent is Sine divided by Cosine]] }} {{eqn | r = \frac {3 \sin \theta - 4 \sin^3 \theta} {4 \cos^3 \theta - 3 \cos \theta} | c = [[Triple Angle Formula for Sine]] and [[Triple Angle Formula for Cosine]] }} {{...
Triple Angle Formulas/Tangent/Proof 1
https://proofwiki.org/wiki/Triple_Angle_Formulas/Tangent
https://proofwiki.org/wiki/Triple_Angle_Formulas/Tangent/Proof_1
[ "Tangent Function", "Triple Angle Formula for Tangent", "Triple Angle Formulas" ]
[]
[ "Tangent is Sine divided by Cosine", "Triple Angle Formulas/Sine", "Triple Angle Formulas/Cosine", "Tangent is Sine divided by Cosine", "Secant is Reciprocal of Cosine", "Sum of Squares of Sine and Cosine/Corollary 1" ]
proofwiki-8119
Triple Angle Formulas/Tangent
:$\tan 3 \theta = \dfrac {3 \tan \theta - \tan^3 \theta} {1 - 3 \tan^2 \theta}$
Let $\theta$ be such that $\tan 2 \theta$ is defined. Then: {{begin-eqn}} {{eqn | l = \tan 3 \theta | r = \dfrac {\tan \theta + \tan 2 \theta} {1 - \tan \theta \tan 2 \theta} | c = Tangent of Sum }} {{eqn | r = \dfrac {\tan \theta + \dfrac {2 \tan \theta} {1 - \tan^2 \theta} } {1 - \tan \theta \dfrac {2 \ta...
:$\tan 3 \theta = \dfrac {3 \tan \theta - \tan^3 \theta} {1 - 3 \tan^2 \theta}$
Let $\theta$ be such that $\tan 2 \theta$ is defined. Then: {{begin-eqn}} {{eqn | l = \tan 3 \theta | r = \dfrac {\tan \theta + \tan 2 \theta} {1 - \tan \theta \tan 2 \theta} | c = [[Tangent of Sum]] }} {{eqn | r = \dfrac {\tan \theta + \dfrac {2 \tan \theta} {1 - \tan^2 \theta} } {1 - \tan \theta \dfrac ...
Triple Angle Formulas/Tangent/Proof 2
https://proofwiki.org/wiki/Triple_Angle_Formulas/Tangent
https://proofwiki.org/wiki/Triple_Angle_Formulas/Tangent/Proof_2
[ "Tangent Function", "Triple Angle Formula for Tangent", "Triple Angle Formulas" ]
[]
[ "Tangent of Sum", "Double Angle Formulas/Tangent", "Definition:Integer", "Definition:Even Integer", "Definition:Odd Integer", "Triple Angle Formulas/Tangent" ]
proofwiki-8120
Triple Angle Formulas/Tangent
:$\tan 3 \theta = \dfrac {3 \tan \theta - \tan^3 \theta} {1 - 3 \tan^2 \theta}$
From Tangent of Sum of Three Angles: {{:Tangent of Sum of Three Angles}} The result follows by setting $\theta = A = B = C$. {{qed}}
:$\tan 3 \theta = \dfrac {3 \tan \theta - \tan^3 \theta} {1 - 3 \tan^2 \theta}$
From [[Tangent of Sum of Three Angles]]: {{:Tangent of Sum of Three Angles}} The result follows by setting $\theta = A = B = C$. {{qed}}
Triple Angle Formulas/Tangent/Proof 3
https://proofwiki.org/wiki/Triple_Angle_Formulas/Tangent
https://proofwiki.org/wiki/Triple_Angle_Formulas/Tangent/Proof_3
[ "Tangent Function", "Triple Angle Formula for Tangent", "Triple Angle Formulas" ]
[]
[ "Tangent of Sum of Three Angles" ]
proofwiki-8121
Quadruple Angle Formulas/Sine
:$\sin 4 \theta = 4 \sin \theta \cos \theta - 8 \sin^3 \theta \cos \theta$
{{begin-eqn}} {{eqn | l = \map \sin {4 \theta} | r = \map \sin {3 \theta + \theta} }} {{eqn | r = \sin 3 \theta \cos \theta + \cos 3 \theta \sin \theta | c = Sine of Sum }} {{eqn | r = \paren {3 \sin \theta - 4 \sin^3 \theta} \cos \theta + \paren {4 \cos^3 \theta - 3 \cos \theta} \sin \theta | c = Tri...
:$\sin 4 \theta = 4 \sin \theta \cos \theta - 8 \sin^3 \theta \cos \theta$
{{begin-eqn}} {{eqn | l = \map \sin {4 \theta} | r = \map \sin {3 \theta + \theta} }} {{eqn | r = \sin 3 \theta \cos \theta + \cos 3 \theta \sin \theta | c = [[Sine of Sum]] }} {{eqn | r = \paren {3 \sin \theta - 4 \sin^3 \theta} \cos \theta + \paren {4 \cos^3 \theta - 3 \cos \theta} \sin \theta | c =...
Quadruple Angle Formulas/Sine/Proof 1
https://proofwiki.org/wiki/Quadruple_Angle_Formulas/Sine
https://proofwiki.org/wiki/Quadruple_Angle_Formulas/Sine/Proof_1
[ "Quadruple Angle Formula for Sine", "Sine Function", "Quadruple Angle Formulas" ]
[]
[ "Sine of Sum", "Triple Angle Formulas/Sine", "Triple Angle Formulas/Cosine", "Sum of Squares of Sine and Cosine" ]
proofwiki-8122
Quadruple Angle Formulas/Sine
:$\sin 4 \theta = 4 \sin \theta \cos \theta - 8 \sin^3 \theta \cos \theta$
We have: {{begin-eqn}} {{eqn | l = \cos 4 \theta + i \sin 4 \theta | r = \paren {\cos \theta + i \sin \theta}^4 | c = De Moivre's Formula }} {{eqn | r = \paren {\cos \theta}^4 + \binom 4 1 \paren {\cos \theta}^3 \paren {i \sin \theta} + \binom 4 2 \paren {\cos \theta}^2 \paren {i \sin \theta}^2 }} {{eqn | o...
:$\sin 4 \theta = 4 \sin \theta \cos \theta - 8 \sin^3 \theta \cos \theta$
We have: {{begin-eqn}} {{eqn | l = \cos 4 \theta + i \sin 4 \theta | r = \paren {\cos \theta + i \sin \theta}^4 | c = [[De Moivre's Formula]] }} {{eqn | r = \paren {\cos \theta}^4 + \binom 4 1 \paren {\cos \theta}^3 \paren {i \sin \theta} + \binom 4 2 \paren {\cos \theta}^2 \paren {i \sin \theta}^2 }} {{eq...
Quadruple Angle Formulas/Sine/Proof 2
https://proofwiki.org/wiki/Quadruple_Angle_Formulas/Sine
https://proofwiki.org/wiki/Quadruple_Angle_Formulas/Sine/Proof_2
[ "Quadruple Angle Formula for Sine", "Sine Function", "Quadruple Angle Formulas" ]
[]
[ "De Moivre's Formula", "Binomial Theorem", "Definition:Binomial Coefficient", "Definition:Complex Number/Imaginary Part", "Sum of Squares of Sine and Cosine" ]
proofwiki-8123
Quadruple Angle Formulas/Sine
:$\sin 4 \theta = 4 \sin \theta \cos \theta - 8 \sin^3 \theta \cos \theta$
{{begin-eqn}} {{eqn | l = \sin {4 \theta} | r = \map \sin {2 \times 2 \theta} }} {{eqn | r = 2 \sin 2 \theta \cos 2 \theta | c = Double Angle Formula for Sine }} {{eqn | r = 2 \paren {2 \sin \theta \cos \theta} \paren {\cos^2 \theta - \sin^2 \theta} | c = Double Angle Formula for Sine, Double Angle Fo...
:$\sin 4 \theta = 4 \sin \theta \cos \theta - 8 \sin^3 \theta \cos \theta$
{{begin-eqn}} {{eqn | l = \sin {4 \theta} | r = \map \sin {2 \times 2 \theta} }} {{eqn | r = 2 \sin 2 \theta \cos 2 \theta | c = [[Double Angle Formula for Sine]] }} {{eqn | r = 2 \paren {2 \sin \theta \cos \theta} \paren {\cos^2 \theta - \sin^2 \theta} | c = [[Double Angle Formula for Sine]], [[Doubl...
Quadruple Angle Formulas/Sine/Proof 3
https://proofwiki.org/wiki/Quadruple_Angle_Formulas/Sine
https://proofwiki.org/wiki/Quadruple_Angle_Formulas/Sine/Proof_3
[ "Quadruple Angle Formula for Sine", "Sine Function", "Quadruple Angle Formulas" ]
[]
[ "Double Angle Formulas/Sine", "Double Angle Formulas/Sine", "Double Angle Formulas/Cosine", "Distributive Laws/Arithmetic", "Sum of Squares of Sine and Cosine" ]
proofwiki-8124
Quadruple Angle Formulas/Cosine
:$\cos 4 \theta = 8 \cos^4 \theta - 8 \cos^2 \theta + 1$
{{begin-eqn}} {{eqn | l = \cos 4 \theta | r = \cos \paren {2 \theta + 2 \theta} }} {{eqn | r = \cos 2 \theta \cos 2 \theta - \sin 2 \theta \sin 2 \theta | c = Cosine of Sum }} {{eqn | r = \paren {\cos^2 \theta - \sin^2 \theta} \paren {\cos^2 \theta - \sin^2 \theta} - \paren {2 \sin \theta \cos \theta} \pare...
:$\cos 4 \theta = 8 \cos^4 \theta - 8 \cos^2 \theta + 1$
{{begin-eqn}} {{eqn | l = \cos 4 \theta | r = \cos \paren {2 \theta + 2 \theta} }} {{eqn | r = \cos 2 \theta \cos 2 \theta - \sin 2 \theta \sin 2 \theta | c = [[Cosine of Sum]] }} {{eqn | r = \paren {\cos^2 \theta - \sin^2 \theta} \paren {\cos^2 \theta - \sin^2 \theta} - \paren {2 \sin \theta \cos \theta} \...
Quadruple Angle Formulas/Cosine/Proof 1
https://proofwiki.org/wiki/Quadruple_Angle_Formulas/Cosine
https://proofwiki.org/wiki/Quadruple_Angle_Formulas/Cosine/Proof_1
[ "Quadruple Angle Formula for Cosine", "Cosine Function", "Quadruple Angle Formulas" ]
[]
[ "Cosine of Sum", "Double Angle Formulas", "Sum of Squares of Sine and Cosine" ]
proofwiki-8125
Quadruple Angle Formulas/Cosine
:$\cos 4 \theta = 8 \cos^4 \theta - 8 \cos^2 \theta + 1$
We have: {{begin-eqn}} {{eqn | l = \cos 4 \theta + i \sin 4 \theta | r = \paren {\cos \theta + i \sin \theta}^4 | c = De Moivre's Formula }} {{eqn | r = \paren {\cos \theta}^4 + \binom 4 1 \paren {\cos \theta}^3 \paren {i \sin \theta} + \binom 4 2 \paren {\cos \theta}^2 \paren {i \sin \theta}^2 }} {{eqn | o...
:$\cos 4 \theta = 8 \cos^4 \theta - 8 \cos^2 \theta + 1$
We have: {{begin-eqn}} {{eqn | l = \cos 4 \theta + i \sin 4 \theta | r = \paren {\cos \theta + i \sin \theta}^4 | c = [[De Moivre's Formula]] }} {{eqn | r = \paren {\cos \theta}^4 + \binom 4 1 \paren {\cos \theta}^3 \paren {i \sin \theta} + \binom 4 2 \paren {\cos \theta}^2 \paren {i \sin \theta}^2 }} {{eq...
Quadruple Angle Formulas/Cosine/Proof 2
https://proofwiki.org/wiki/Quadruple_Angle_Formulas/Cosine
https://proofwiki.org/wiki/Quadruple_Angle_Formulas/Cosine/Proof_2
[ "Quadruple Angle Formula for Cosine", "Cosine Function", "Quadruple Angle Formulas" ]
[]
[ "De Moivre's Formula", "Binomial Theorem", "Definition:Binomial Coefficient", "Definition:Complex Number/Real Part", "Sum of Squares of Sine and Cosine" ]
proofwiki-8126
Quadruple Angle Formulas/Tangent
:$\tan 4 \theta = \dfrac {4 \tan \theta - 4 \tan^3 \theta} {1 - 6 \tan^2 \theta + \tan^4 \theta}$
{{begin-eqn}} {{eqn | l = \tan 4 \theta | r = \frac {\sin 4 \theta} {\cos 4 \theta} | c = Tangent is Sine divided by Cosine }} {{eqn | r = \frac {4 \sin \theta \cos \theta - 8 \sin^3 \theta \cos \theta} {8 \cos^4 \theta - 8 \cos^2 \theta + 1} | c = Quadruple Angle Formula for Sine and Quadruple Angle ...
:$\tan 4 \theta = \dfrac {4 \tan \theta - 4 \tan^3 \theta} {1 - 6 \tan^2 \theta + \tan^4 \theta}$
{{begin-eqn}} {{eqn | l = \tan 4 \theta | r = \frac {\sin 4 \theta} {\cos 4 \theta} | c = [[Tangent is Sine divided by Cosine]] }} {{eqn | r = \frac {4 \sin \theta \cos \theta - 8 \sin^3 \theta \cos \theta} {8 \cos^4 \theta - 8 \cos^2 \theta + 1} | c = [[Quadruple Angle Formula for Sine]] and [[Quadru...
Quadruple Angle Formulas/Tangent
https://proofwiki.org/wiki/Quadruple_Angle_Formulas/Tangent
https://proofwiki.org/wiki/Quadruple_Angle_Formulas/Tangent
[ "Tangent Function" ]
[]
[ "Tangent is Sine divided by Cosine", "Quadruple Angle Formulas/Sine", "Quadruple Angle Formulas/Cosine", "Secant is Reciprocal of Cosine", "Sum of Squares of Sine and Cosine/Corollary 1" ]
proofwiki-8127
Quintuple Angle Formulas/Sine
:$\sin 5 \theta = 5 \sin \theta - 20 \sin^3 \theta + 16 \sin^5 \theta$
{{begin-eqn}} {{eqn | l = \sin 5 \theta | r = \map \sin {3 \theta + 2 \theta} }} {{eqn | r = \sin 3 \theta \cos 2 \theta + \cos 3 \theta \sin 2 \theta | c = Sine of Sum }} {{eqn | r = \paren {3 \sin \theta - 4 \sin^3 \theta} \cos 2 \theta + \paren {4 \cos^3 \theta - 3 \cos \theta} \sin 2 \theta | c = ...
:$\sin 5 \theta = 5 \sin \theta - 20 \sin^3 \theta + 16 \sin^5 \theta$
{{begin-eqn}} {{eqn | l = \sin 5 \theta | r = \map \sin {3 \theta + 2 \theta} }} {{eqn | r = \sin 3 \theta \cos 2 \theta + \cos 3 \theta \sin 2 \theta | c = [[Sine of Sum]] }} {{eqn | r = \paren {3 \sin \theta - 4 \sin^3 \theta} \cos 2 \theta + \paren {4 \cos^3 \theta - 3 \cos \theta} \sin 2 \theta | ...
Quintuple Angle Formulas/Sine/Proof 1
https://proofwiki.org/wiki/Quintuple_Angle_Formulas/Sine
https://proofwiki.org/wiki/Quintuple_Angle_Formulas/Sine/Proof_1
[ "Sine Function", "Quintuple Angle Formula for Sine", "Quintuple Angle Formulas" ]
[]
[ "Sine of Sum", "Triple Angle Formulas", "Double Angle Formulas", "Sum of Squares of Sine and Cosine" ]
proofwiki-8128
Quintuple Angle Formulas/Sine
:$\sin 5 \theta = 5 \sin \theta - 20 \sin^3 \theta + 16 \sin^5 \theta$
We have: {{begin-eqn}} {{eqn | l = \cos 5 \theta + i \sin 5 \theta | r = \paren {\cos \theta + i \sin \theta}^5 | c = De Moivre's Formula }} {{eqn | r = \paren {\cos \theta}^5 + \binom 5 1 \paren {\cos \theta}^4 \paren {i \sin \theta} + \binom 5 2 \paren {\cos \theta}^3 \paren {i \sin \theta}^2 }} {{eqn | o...
:$\sin 5 \theta = 5 \sin \theta - 20 \sin^3 \theta + 16 \sin^5 \theta$
We have: {{begin-eqn}} {{eqn | l = \cos 5 \theta + i \sin 5 \theta | r = \paren {\cos \theta + i \sin \theta}^5 | c = [[De Moivre's Formula]] }} {{eqn | r = \paren {\cos \theta}^5 + \binom 5 1 \paren {\cos \theta}^4 \paren {i \sin \theta} + \binom 5 2 \paren {\cos \theta}^3 \paren {i \sin \theta}^2 }} {{eq...
Quintuple Angle Formulas/Sine/Proof 2
https://proofwiki.org/wiki/Quintuple_Angle_Formulas/Sine
https://proofwiki.org/wiki/Quintuple_Angle_Formulas/Sine/Proof_2
[ "Sine Function", "Quintuple Angle Formula for Sine", "Quintuple Angle Formulas" ]
[]
[ "De Moivre's Formula", "Binomial Theorem", "Definition:Binomial Coefficient", "Definition:Complex Number/Imaginary Part", "Sum of Squares of Sine and Cosine" ]
proofwiki-8129
Quintuple Angle Formulas/Cosine
:$\cos 5 \theta = 16 \cos^5 \theta - 20 \cos^3 \theta + 5 \cos \theta$
{{begin-eqn}} {{eqn | l = \cos 5 \theta | r = \map \cos {4 \theta + \theta} }} {{eqn | r = \cos 4 \theta \cos \theta - \sin 4 \theta \sin \theta | c = Cosine of Sum }} {{eqn | r = \paren {8 \cos^4 \theta - 8 \cos^2 \theta + 1} \cos \theta - \paren {4 \sin \theta \cos \theta - 8 \sin^3 \theta \cos \theta} \s...
:$\cos 5 \theta = 16 \cos^5 \theta - 20 \cos^3 \theta + 5 \cos \theta$
{{begin-eqn}} {{eqn | l = \cos 5 \theta | r = \map \cos {4 \theta + \theta} }} {{eqn | r = \cos 4 \theta \cos \theta - \sin 4 \theta \sin \theta | c = [[Cosine of Sum]] }} {{eqn | r = \paren {8 \cos^4 \theta - 8 \cos^2 \theta + 1} \cos \theta - \paren {4 \sin \theta \cos \theta - 8 \sin^3 \theta \cos \theta...
Quintuple Angle Formulas/Cosine/Proof 1
https://proofwiki.org/wiki/Quintuple_Angle_Formulas/Cosine
https://proofwiki.org/wiki/Quintuple_Angle_Formulas/Cosine/Proof_1
[ "Cosine Function", "Quintuple Angle Formula for Cosine", "Quintuple Angle Formulas" ]
[]
[ "Cosine of Sum", "Quadruple Angle Formulas", "Sum of Squares of Sine and Cosine" ]
proofwiki-8130
Quintuple Angle Formulas/Cosine
:$\cos 5 \theta = 16 \cos^5 \theta - 20 \cos^3 \theta + 5 \cos \theta$
We have: {{begin-eqn}} {{eqn | l = \cos 5 \theta + i \sin 5 \theta | r = \paren {\cos \theta + i \sin \theta}^5 | c = De Moivre's Formula }} {{eqn | r = \paren {\cos \theta}^5 + \binom 5 1 \paren {\cos \theta}^4 \paren {i \sin \theta} + \binom 5 2 \paren {\cos \theta}^3 \paren {i \sin \theta}^2 | c = ...
:$\cos 5 \theta = 16 \cos^5 \theta - 20 \cos^3 \theta + 5 \cos \theta$
We have: {{begin-eqn}} {{eqn | l = \cos 5 \theta + i \sin 5 \theta | r = \paren {\cos \theta + i \sin \theta}^5 | c = [[De Moivre's Formula]] }} {{eqn | r = \paren {\cos \theta}^5 + \binom 5 1 \paren {\cos \theta}^4 \paren {i \sin \theta} + \binom 5 2 \paren {\cos \theta}^3 \paren {i \sin \theta}^2 |...
Quintuple Angle Formulas/Cosine/Proof 2
https://proofwiki.org/wiki/Quintuple_Angle_Formulas/Cosine
https://proofwiki.org/wiki/Quintuple_Angle_Formulas/Cosine/Proof_2
[ "Cosine Function", "Quintuple Angle Formula for Cosine", "Quintuple Angle Formulas" ]
[]
[ "De Moivre's Formula", "Binomial Theorem", "Definition:Binomial Coefficient", "Definition:Complex Number/Real Part", "Sum of Squares of Sine and Cosine" ]
proofwiki-8131
Quintuple Angle Formulas/Tangent
:$\tan 5 \theta = \dfrac {\tan^5 \theta - 10 \tan^3 \theta + 5 \tan \theta} {1 - 10 \tan^2 \theta + 5 \tan^4 \theta}$
{{begin-eqn}} {{eqn | l = \tan 5 \theta | r = \frac {\sin 5 \theta} {\cos 5 \theta} | c = Tangent is Sine divided by Cosine }} {{eqn | r = \frac {5 \sin \theta - 20 \sin^3 \theta + 16 \sin^5 \theta} {16 \cos^5 \theta - 20 \cos^3 \theta + 5 \cos \theta} | c = Quintuple Angle Formulas }} {{eqn | r = \fr...
:$\tan 5 \theta = \dfrac {\tan^5 \theta - 10 \tan^3 \theta + 5 \tan \theta} {1 - 10 \tan^2 \theta + 5 \tan^4 \theta}$
{{begin-eqn}} {{eqn | l = \tan 5 \theta | r = \frac {\sin 5 \theta} {\cos 5 \theta} | c = [[Tangent is Sine divided by Cosine]] }} {{eqn | r = \frac {5 \sin \theta - 20 \sin^3 \theta + 16 \sin^5 \theta} {16 \cos^5 \theta - 20 \cos^3 \theta + 5 \cos \theta} | c = [[Quintuple Angle Formulas]] }} {{eqn |...
Quintuple Angle Formulas/Tangent
https://proofwiki.org/wiki/Quintuple_Angle_Formulas/Tangent
https://proofwiki.org/wiki/Quintuple_Angle_Formulas/Tangent
[ "Tangent Function", "Quintuple Angle Formulas" ]
[]
[ "Tangent is Sine divided by Cosine", "Quintuple Angle Formulas", "Secant is Reciprocal of Cosine", "Sum of Squares of Sine and Cosine/Corollary 1" ]
proofwiki-8132
Power Reduction Formulas/Sine Squared
:$\sin^2 x = \dfrac {1 - \cos 2 x} 2$
{{begin-eqn}} {{eqn | l = 1 - 2 \sin^2 x | r = \cos 2 x | c = {{Corollary|Double Angle Formula for Cosine|2}} }} {{eqn | ll= \leadsto | l = \sin^2 x | r = \frac {\cos 2 x - 1} {-2} | c = solving for $\sin^2x$ }} {{eqn | r = \frac {1 - \cos 2 x} 2 | c = multiplying top and bottom by $...
:$\sin^2 x = \dfrac {1 - \cos 2 x} 2$
{{begin-eqn}} {{eqn | l = 1 - 2 \sin^2 x | r = \cos 2 x | c = {{Corollary|Double Angle Formula for Cosine|2}} }} {{eqn | ll= \leadsto | l = \sin^2 x | r = \frac {\cos 2 x - 1} {-2} | c = solving for $\sin^2x$ }} {{eqn | r = \frac {1 - \cos 2 x} 2 | c = multiplying top and bottom by $...
Power Reduction Formulas/Sine Squared
https://proofwiki.org/wiki/Power_Reduction_Formulas/Sine_Squared
https://proofwiki.org/wiki/Power_Reduction_Formulas/Sine_Squared
[ "Sine Function" ]
[]
[]
proofwiki-8133
Power Reduction Formulas/Cosine Squared
:$\cos^2 x = \dfrac {1 + \cos 2 x} 2$
{{begin-eqn}} {{eqn | l = 2 \cos^2 x - 1 | r = \cos 2 x | c = {{Corollary|Double Angle Formula for Cosine|1}} }} {{eqn | l = \cos^2 x | r = \frac {1 + \cos 2 x} 2 | c = solving for $\cos^2 x$ }} {{end-eqn}} {{qed}}
:$\cos^2 x = \dfrac {1 + \cos 2 x} 2$
{{begin-eqn}} {{eqn | l = 2 \cos^2 x - 1 | r = \cos 2 x | c = {{Corollary|Double Angle Formula for Cosine|1}} }} {{eqn | l = \cos^2 x | r = \frac {1 + \cos 2 x} 2 | c = solving for $\cos^2 x$ }} {{end-eqn}} {{qed}}
Power Reduction Formulas/Cosine Squared/Proof 1
https://proofwiki.org/wiki/Power_Reduction_Formulas/Cosine_Squared
https://proofwiki.org/wiki/Power_Reduction_Formulas/Cosine_Squared/Proof_1
[ "Cosine Function" ]
[]
[]
proofwiki-8134
Power Reduction Formulas/Cosine Squared
:$\cos^2 x = \dfrac {1 + \cos 2 x} 2$
{{begin-eqn}} {{eqn | l = \dfrac {1 + \cos 2 x} 2 | r = \dfrac 1 2 \paren {1 + \dfrac {e^{2 i x} + e^{-2 i x} } 2} | c = Euler's Cosine Identity }} {{eqn | r = \dfrac 1 4 \paren {e^{2 i x} + 2 + e^{-2 i x} } | c = simplifying }} {{eqn | r = \dfrac 1 4 \paren {e^{2 i x} + 2 \paren {e^{i x} } \paren {e^...
:$\cos^2 x = \dfrac {1 + \cos 2 x} 2$
{{begin-eqn}} {{eqn | l = \dfrac {1 + \cos 2 x} 2 | r = \dfrac 1 2 \paren {1 + \dfrac {e^{2 i x} + e^{-2 i x} } 2} | c = [[Euler's Cosine Identity]] }} {{eqn | r = \dfrac 1 4 \paren {e^{2 i x} + 2 + e^{-2 i x} } | c = simplifying }} {{eqn | r = \dfrac 1 4 \paren {e^{2 i x} + 2 \paren {e^{i x} } \paren...
Power Reduction Formulas/Cosine Squared/Proof 2
https://proofwiki.org/wiki/Power_Reduction_Formulas/Cosine_Squared
https://proofwiki.org/wiki/Power_Reduction_Formulas/Cosine_Squared/Proof_2
[ "Cosine Function" ]
[]
[ "Euler's Cosine Identity", "Square of Sum", "Euler's Cosine Identity" ]
proofwiki-8135
Power Reduction Formulas/Tangent Squared
:$\tan^2x = \dfrac {1 - \cos2x} {1 + \cos2x}$
{{begin-eqn}} {{eqn | l = \tan^2 x | r = \frac {\sin^2 x} {\cos^2 x} | c = Tangent is Sine divided by Cosine }} {{eqn | r = \frac {\frac {1 - \cos 2 x} 2} {\frac {\cos 2 x + 1} 2} | c = Square of Sine and Square of Cosine }} {{eqn | r = \frac {1 - \cos 2 x} {1 + \cos 2 x} | c = multiplying top a...
:$\tan^2x = \dfrac {1 - \cos2x} {1 + \cos2x}$
{{begin-eqn}} {{eqn | l = \tan^2 x | r = \frac {\sin^2 x} {\cos^2 x} | c = [[Tangent is Sine divided by Cosine]] }} {{eqn | r = \frac {\frac {1 - \cos 2 x} 2} {\frac {\cos 2 x + 1} 2} | c = [[Square of Sine]] and [[Square of Cosine]] }} {{eqn | r = \frac {1 - \cos 2 x} {1 + \cos 2 x} | c = multi...
Power Reduction Formulas/Tangent Squared
https://proofwiki.org/wiki/Power_Reduction_Formulas/Tangent_Squared
https://proofwiki.org/wiki/Power_Reduction_Formulas/Tangent_Squared
[ "Tangent Function" ]
[]
[ "Tangent is Sine divided by Cosine", "Power Reduction Formulas/Sine Squared", "Power Reduction Formulas/Cosine Squared", "Category:Tangent Function" ]
proofwiki-8136
Power Reduction Formulas/Sine Cubed
:$\sin^3 x = \dfrac {3 \sin x - \sin 3 x} 4$
{{begin-eqn}} {{eqn | l = \sin 3 x | r = 3 \sin x - 4 \sin^3 x | c = Triple Angle Formula for Sine }} {{eqn | ll= \leadsto | l = 4 \sin^3 x | r = 3 \sin x - \sin 3 x | c = rearranging }} {{eqn | ll= \leadsto | l = \sin^3 x | r = \frac {3 \sin x - \sin 3 x} 4 | c = dividin...
:$\sin^3 x = \dfrac {3 \sin x - \sin 3 x} 4$
{{begin-eqn}} {{eqn | l = \sin 3 x | r = 3 \sin x - 4 \sin^3 x | c = [[Triple Angle Formula for Sine]] }} {{eqn | ll= \leadsto | l = 4 \sin^3 x | r = 3 \sin x - \sin 3 x | c = rearranging }} {{eqn | ll= \leadsto | l = \sin^3 x | r = \frac {3 \sin x - \sin 3 x} 4 | c = div...
Power Reduction Formulas/Sine Cubed/Proof 1
https://proofwiki.org/wiki/Power_Reduction_Formulas/Sine_Cubed
https://proofwiki.org/wiki/Power_Reduction_Formulas/Sine_Cubed/Proof_1
[ "Sine Function", "Cube of Sine" ]
[]
[ "Triple Angle Formulas/Sine" ]
proofwiki-8137
Power Reduction Formulas/Sine Cubed
:$\sin^3 x = \dfrac {3 \sin x - \sin 3 x} 4$
{{begin-eqn}} {{eqn | l = \sin^3 x | r = \paren {\frac {e^{i x} - e^{-i x} } {2 i} }^3 | c = Euler's Sine Identity }} {{eqn | r = \frac {\paren {e^{i x} - e^{-i x} }^3} {8 i^3} | c = rearranging }} {{eqn | r = -\frac 1 {8 i} \paren {\paren {e^{i x} }^3 - 3 \paren {e^{i x} }^2 \paren {e^{-i x} } + 3 \p...
:$\sin^3 x = \dfrac {3 \sin x - \sin 3 x} 4$
{{begin-eqn}} {{eqn | l = \sin^3 x | r = \paren {\frac {e^{i x} - e^{-i x} } {2 i} }^3 | c = [[Euler's Sine Identity]] }} {{eqn | r = \frac {\paren {e^{i x} - e^{-i x} }^3} {8 i^3} | c = rearranging }} {{eqn | r = -\frac 1 {8 i} \paren {\paren {e^{i x} }^3 - 3 \paren {e^{i x} }^2 \paren {e^{-i x} } + ...
Power Reduction Formulas/Sine Cubed/Proof 2
https://proofwiki.org/wiki/Power_Reduction_Formulas/Sine_Cubed
https://proofwiki.org/wiki/Power_Reduction_Formulas/Sine_Cubed/Proof_2
[ "Sine Function", "Cube of Sine" ]
[]
[ "Euler's Sine Identity", "Euler's Sine Identity" ]
proofwiki-8138
Power Reduction Formulas/Cosine Cubed
:$\cos^3 x = \dfrac {3 \cos x + \cos 3 x} 4$
{{begin-eqn}} {{eqn | l = \cos 3 x | r = 4 \cos^3 x - 3 \cos x | c = Triple Angle Formula for Cosine }} {{eqn | ll= \leadsto | l = 4 \cos^3 x | r = 3 \cos x + \cos 3 x | c = rearranging }} {{eqn | ll= \leadsto | l = \cos^3 x | r = \dfrac {3 \cos x + \cos 3 x} 4 | c = divi...
:$\cos^3 x = \dfrac {3 \cos x + \cos 3 x} 4$
{{begin-eqn}} {{eqn | l = \cos 3 x | r = 4 \cos^3 x - 3 \cos x | c = [[Triple Angle Formula for Cosine]] }} {{eqn | ll= \leadsto | l = 4 \cos^3 x | r = 3 \cos x + \cos 3 x | c = rearranging }} {{eqn | ll= \leadsto | l = \cos^3 x | r = \dfrac {3 \cos x + \cos 3 x} 4 | c = ...
Power Reduction Formulas/Cosine Cubed
https://proofwiki.org/wiki/Power_Reduction_Formulas/Cosine_Cubed
https://proofwiki.org/wiki/Power_Reduction_Formulas/Cosine_Cubed
[ "Cosine Function" ]
[]
[ "Triple Angle Formulas/Cosine" ]
proofwiki-8139
Power Reduction Formulas/Sine to 4th
:$\sin^4 x = \dfrac {3 - 4 \cos 2 x + \cos 4 x} 8$
{{begin-eqn}} {{eqn | l = \sin^4 x | r = \paren {\sin^2 x}^2 }} {{eqn | r = \paren {\frac {1 - \cos 2 x} 2}^2 | c = Square of Sine }} {{eqn | r = \frac {1 - 2 \cos 2 x + \cos^2 2 x} 4 | c = multiplying out }} {{eqn | r = \frac {1 - 2 \cos 2 x + \frac {1 + \cos 4 x} 2} 4 | c = Square of Cosine }}...
:$\sin^4 x = \dfrac {3 - 4 \cos 2 x + \cos 4 x} 8$
{{begin-eqn}} {{eqn | l = \sin^4 x | r = \paren {\sin^2 x}^2 }} {{eqn | r = \paren {\frac {1 - \cos 2 x} 2}^2 | c = [[Square of Sine]] }} {{eqn | r = \frac {1 - 2 \cos 2 x + \cos^2 2 x} 4 | c = multiplying out }} {{eqn | r = \frac {1 - 2 \cos 2 x + \frac {1 + \cos 4 x} 2} 4 | c = [[Square of Cos...
Power Reduction Formulas/Sine to 4th
https://proofwiki.org/wiki/Power_Reduction_Formulas/Sine_to_4th
https://proofwiki.org/wiki/Power_Reduction_Formulas/Sine_to_4th
[ "Sine Function" ]
[]
[ "Power Reduction Formulas/Sine Squared", "Power Reduction Formulas/Cosine Squared" ]
proofwiki-8140
Power Reduction Formulas/Cosine to 4th
:$\cos^4 x = \dfrac {3 + 4 \cos 2 x + \cos 4 x} 8$
{{begin-eqn}} {{eqn | l = \cos^4 x | r = \paren {\cos^2 x}^2 }} {{eqn | r = \paren {\frac {1 + \cos 2 x} 2}^2 | c = Square of Cosine }} {{eqn | r = \frac {1 + 2 \cos 2 x + \cos^2 2 x} 4 | c = multiplying out }} {{eqn | r = \frac {1 + 2 \cos 2 x + \frac {1 + \cos 4 x} 2} 4 | c = Square of Cosine ...
:$\cos^4 x = \dfrac {3 + 4 \cos 2 x + \cos 4 x} 8$
{{begin-eqn}} {{eqn | l = \cos^4 x | r = \paren {\cos^2 x}^2 }} {{eqn | r = \paren {\frac {1 + \cos 2 x} 2}^2 | c = [[Square of Cosine]] }} {{eqn | r = \frac {1 + 2 \cos 2 x + \cos^2 2 x} 4 | c = multiplying out }} {{eqn | r = \frac {1 + 2 \cos 2 x + \frac {1 + \cos 4 x} 2} 4 | c = [[Square of C...
Power Reduction Formulas/Cosine to 4th/Proof 1
https://proofwiki.org/wiki/Power_Reduction_Formulas/Cosine_to_4th
https://proofwiki.org/wiki/Power_Reduction_Formulas/Cosine_to_4th/Proof_1
[ "Power Reduction Formula for 4th Power of Cosine", "Cosine Function" ]
[]
[ "Power Reduction Formulas/Cosine Squared", "Power Reduction Formulas/Cosine Squared", "Definition:Fraction/Numerator", "Definition:Fraction/Denominator" ]
proofwiki-8141
Power Reduction Formulas/Cosine to 4th
:$\cos^4 x = \dfrac {3 + 4 \cos 2 x + \cos 4 x} 8$
{{begin-eqn}} {{eqn | l = \cos ^4 x | r = \paren {\frac {e^{i x} + e^{-i x} } 2}^4 | c = Euler's Cosine Identity }} {{eqn | r = \frac {\paren {e^{i x} + e^{-i x} }^4} {16} | c = rearranging }} {{eqn | r = \frac {\paren {e^{i x} }^4 + 4 \paren {e^{i x} }^3 \paren {e^{-i x} } + 6 \paren {e^{i x} }^2 \pa...
:$\cos^4 x = \dfrac {3 + 4 \cos 2 x + \cos 4 x} 8$
{{begin-eqn}} {{eqn | l = \cos ^4 x | r = \paren {\frac {e^{i x} + e^{-i x} } 2}^4 | c = [[Euler's Cosine Identity]] }} {{eqn | r = \frac {\paren {e^{i x} + e^{-i x} }^4} {16} | c = rearranging }} {{eqn | r = \frac {\paren {e^{i x} }^4 + 4 \paren {e^{i x} }^3 \paren {e^{-i x} } + 6 \paren {e^{i x} }^2...
Power Reduction Formulas/Cosine to 4th/Proof 2
https://proofwiki.org/wiki/Power_Reduction_Formulas/Cosine_to_4th
https://proofwiki.org/wiki/Power_Reduction_Formulas/Cosine_to_4th/Proof_2
[ "Power Reduction Formula for 4th Power of Cosine", "Cosine Function" ]
[]
[ "Euler's Cosine Identity", "Euler's Cosine Identity" ]
proofwiki-8142
Power Reduction Formulas/Sine to 5th
:$\sin^5 x = \dfrac {10 \sin x - 5 \sin 3 x + \sin 5 x} {16}$
{{begin-eqn}} {{eqn | l = \sin 5 x | r = 5 \sin x - 20 \sin^3 x + 16 \sin^5 x | c = Quintuple Angle Formula for Sine }} {{eqn | ll= \leadsto | l = 16 \sin^5 x | r = \sin 5 x + 20 \sin^3 x - 5 \sin x | c = rearranging }} {{eqn | r = \sin 5 x + 20 \paren {\frac {3 \sin x - \sin 3 x} 4} - 5 \...
:$\sin^5 x = \dfrac {10 \sin x - 5 \sin 3 x + \sin 5 x} {16}$
{{begin-eqn}} {{eqn | l = \sin 5 x | r = 5 \sin x - 20 \sin^3 x + 16 \sin^5 x | c = [[Quintuple Angle Formula for Sine]] }} {{eqn | ll= \leadsto | l = 16 \sin^5 x | r = \sin 5 x + 20 \sin^3 x - 5 \sin x | c = rearranging }} {{eqn | r = \sin 5 x + 20 \paren {\frac {3 \sin x - \sin 3 x} 4} -...
Power Reduction Formulas/Sine to 5th
https://proofwiki.org/wiki/Power_Reduction_Formulas/Sine_to_5th
https://proofwiki.org/wiki/Power_Reduction_Formulas/Sine_to_5th
[ "Sine Function" ]
[]
[ "Quintuple Angle Formulas/Sine", "Power Reduction Formulas/Sine Cubed" ]
proofwiki-8143
Power Reduction Formulas/Cosine to 5th
:$\cos^5 x = \dfrac {10 \cos x + 5 \cos 3 x + \cos 5 x} {16}$
{{begin-eqn}} {{eqn | l = \cos 5 x | r = 16 \cos^5 x - 20 \cos^3 x + 5 \cos x | c = Quintuple Angle Formula for Cosine }} {{eqn | ll= \leadsto | l = 16 \cos^5 x | r = \cos 5 x + 20 \cos^3 x - 5 \cos x | c = rearranging }} {{eqn | r = \cos 5 x + 20 \paren {\frac {3 \cos x + \cos 3 x} 4} - 5...
:$\cos^5 x = \dfrac {10 \cos x + 5 \cos 3 x + \cos 5 x} {16}$
{{begin-eqn}} {{eqn | l = \cos 5 x | r = 16 \cos^5 x - 20 \cos^3 x + 5 \cos x | c = [[Quintuple Angle Formula for Cosine]] }} {{eqn | ll= \leadsto | l = 16 \cos^5 x | r = \cos 5 x + 20 \cos^3 x - 5 \cos x | c = rearranging }} {{eqn | r = \cos 5 x + 20 \paren {\frac {3 \cos x + \cos 3 x} 4}...
Power Reduction Formulas/Cosine to 5th
https://proofwiki.org/wiki/Power_Reduction_Formulas/Cosine_to_5th
https://proofwiki.org/wiki/Power_Reduction_Formulas/Cosine_to_5th
[ "Cosine Function" ]
[]
[ "Quintuple Angle Formulas/Cosine", "Power Reduction Formulas/Cosine Cubed" ]
proofwiki-8144
Orthocomplement of Subset of Orthocomplement is Superset
Let $\struct {V, \innerprod \cdot \cdot}$ be an inner product space. Let $A, B \subseteq V$ be subsets of $V$ such that $B \subseteq A^\perp$, where $A^\perp$ is the orthocomplement of $A$. Then: :$A \subseteq B^\perp$.
Let $B \subseteq A^\perp$. Then by Orthocomplement Reverses Subset: :$A^{\perp\perp} \subseteq B^\perp$ By Double Orthocomplement is Closed Linear Span and the definition of closed linear span: :$A \subseteq A^{\perp\perp}$ Hence, by Subset Relation is Transitive: :$A \subseteq B^\perp$ {{qed}} Category:Inner Product S...
Let $\struct {V, \innerprod \cdot \cdot}$ be an [[Definition:Inner Product Space|inner product space]]. Let $A, B \subseteq V$ be [[Definition:Subset|subsets]] of $V$ such that $B \subseteq A^\perp$, where $A^\perp$ is the [[Definition:Orthocomplement|orthocomplement]] of $A$. Then: :$A \subseteq B^\perp$.
Let $B \subseteq A^\perp$. Then by [[Orthocomplement Reverses Subset]]: :$A^{\perp\perp} \subseteq B^\perp$ By [[Double Orthocomplement is Closed Linear Span]] and the definition of [[Definition:Closed Linear Span|closed linear span]]: :$A \subseteq A^{\perp\perp}$ Hence, by [[Subset Relation is Transitive]]: :$...
Orthocomplement of Subset of Orthocomplement is Superset
https://proofwiki.org/wiki/Orthocomplement_of_Subset_of_Orthocomplement_is_Superset
https://proofwiki.org/wiki/Orthocomplement_of_Subset_of_Orthocomplement_is_Superset
[ "Inner Product Spaces", "Orthocomplements" ]
[ "Definition:Inner Product Space", "Definition:Subset", "Definition:Orthogonal (Linear Algebra)/Orthogonal Complement" ]
[ "Orthocomplement Reverses Subset", "Double Orthocomplement is Closed Linear Span", "Definition:Closed Linear Span", "Subset Relation is Transitive", "Category:Inner Product Spaces", "Category:Orthocomplements" ]
proofwiki-8145
Werner Formulas/Cosine by Cosine
:$\cos \alpha \cos \beta = \dfrac {\map \cos {\alpha - \beta} + \map \cos {\alpha + \beta} } 2$
{{begin-eqn}} {{eqn | o = | r = \frac {\map \cos {\alpha - \beta} + \map \cos {\alpha + \beta} } 2 }} {{eqn | r = \frac {\paren {\cos \alpha \cos \beta + \sin \alpha \sin \beta} + \paren {\cos \alpha \cos \beta - \sin \alpha \sin \beta} } 2 | c = Cosine of Difference and Cosine of Sum }} {{eqn | r = \frac ...
:$\cos \alpha \cos \beta = \dfrac {\map \cos {\alpha - \beta} + \map \cos {\alpha + \beta} } 2$
{{begin-eqn}} {{eqn | o = | r = \frac {\map \cos {\alpha - \beta} + \map \cos {\alpha + \beta} } 2 }} {{eqn | r = \frac {\paren {\cos \alpha \cos \beta + \sin \alpha \sin \beta} + \paren {\cos \alpha \cos \beta - \sin \alpha \sin \beta} } 2 | c = [[Cosine of Difference]] and [[Cosine of Sum]] }} {{eqn | r ...
Werner Formulas/Cosine by Cosine
https://proofwiki.org/wiki/Werner_Formulas/Cosine_by_Cosine
https://proofwiki.org/wiki/Werner_Formulas/Cosine_by_Cosine
[ "Werner Formula for Cosine by Cosine", "Werner Formulas", "Cosine Function" ]
[]
[ "Cosine of Difference", "Cosine of Sum" ]
proofwiki-8146
Werner Formulas/Sine by Sine
:$\sin \alpha \sin \beta = \dfrac {\map \cos {\alpha - \beta} - \map \cos {\alpha + \beta} } 2$
{{begin-eqn}} {{eqn | o = | r = \frac {\map \cos {\alpha - \beta} - \map \cos {\alpha + \beta} } 2 }} {{eqn | r = \frac {\paren {\cos \alpha \cos \beta + \sin \alpha \sin \beta} - \paren {\cos \alpha \cos \beta - \sin \alpha \sin \beta} } 2 | c = Cosine of Difference and Cosine of Sum }} {{eqn | r = \frac {...
:$\sin \alpha \sin \beta = \dfrac {\map \cos {\alpha - \beta} - \map \cos {\alpha + \beta} } 2$
{{begin-eqn}} {{eqn | o = | r = \frac {\map \cos {\alpha - \beta} - \map \cos {\alpha + \beta} } 2 }} {{eqn | r = \frac {\paren {\cos \alpha \cos \beta + \sin \alpha \sin \beta} - \paren {\cos \alpha \cos \beta - \sin \alpha \sin \beta} } 2 | c = [[Cosine of Difference]] and [[Cosine of Sum]] }} {{eqn | r =...
Werner Formulas/Sine by Sine
https://proofwiki.org/wiki/Werner_Formulas/Sine_by_Sine
https://proofwiki.org/wiki/Werner_Formulas/Sine_by_Sine
[ "Werner Formula for Sine by Sine", "Werner Formulas", "Sine Function" ]
[]
[ "Cosine of Difference", "Cosine of Sum" ]
proofwiki-8147
Werner Formulas/Cosine by Sine
:$\cos \alpha \sin \beta = \dfrac {\map \sin {\alpha + \beta} - \map \sin {\alpha - \beta} } 2$
{{begin-eqn}} {{eqn | o = | r = \frac {\map \sin {\alpha + \beta} - \map \sin {\alpha - \beta} } 2 }} {{eqn | r = \frac {\paren {\sin \alpha \cos \beta + \cos \alpha \sin \beta} - \paren {\sin \alpha \cos \beta - \cos \alpha \sin \beta} } 2 | c = Sine of Sum and Sine of Difference }} {{eqn | r = \frac {2 \...
:$\cos \alpha \sin \beta = \dfrac {\map \sin {\alpha + \beta} - \map \sin {\alpha - \beta} } 2$
{{begin-eqn}} {{eqn | o = | r = \frac {\map \sin {\alpha + \beta} - \map \sin {\alpha - \beta} } 2 }} {{eqn | r = \frac {\paren {\sin \alpha \cos \beta + \cos \alpha \sin \beta} - \paren {\sin \alpha \cos \beta - \cos \alpha \sin \beta} } 2 | c = [[Sine of Sum]] and [[Sine of Difference]] }} {{eqn | r = \f...
Werner Formulas/Cosine by Sine/Proof 1
https://proofwiki.org/wiki/Werner_Formulas/Cosine_by_Sine
https://proofwiki.org/wiki/Werner_Formulas/Cosine_by_Sine/Proof_1
[ "Werner Formula for Cosine by Sine", "Werner Formulas", "Sine Function", "Cosine Function" ]
[]
[ "Sine of Sum", "Sine of Difference" ]
proofwiki-8148
Werner Formulas/Cosine by Sine
:$\cos \alpha \sin \beta = \dfrac {\map \sin {\alpha + \beta} - \map \sin {\alpha - \beta} } 2$
{{begin-eqn}} {{eqn | l = \cos \alpha \sin \beta | r = \sin \beta \cos \alpha }} {{eqn | r = \frac {\map \sin {\beta + \alpha} + \map \sin {\beta - \alpha} } 2 | c = Werner Formula for Sine by Cosine }} {{eqn | r = \frac {\map \sin {\alpha + \beta} + \map \sin {-\paren {\alpha - \beta} } } 2 | c = }}...
:$\cos \alpha \sin \beta = \dfrac {\map \sin {\alpha + \beta} - \map \sin {\alpha - \beta} } 2$
{{begin-eqn}} {{eqn | l = \cos \alpha \sin \beta | r = \sin \beta \cos \alpha }} {{eqn | r = \frac {\map \sin {\beta + \alpha} + \map \sin {\beta - \alpha} } 2 | c = [[Werner Formula for Sine by Cosine]] }} {{eqn | r = \frac {\map \sin {\alpha + \beta} + \map \sin {-\paren {\alpha - \beta} } } 2 | c =...
Werner Formulas/Cosine by Sine/Proof 2
https://proofwiki.org/wiki/Werner_Formulas/Cosine_by_Sine
https://proofwiki.org/wiki/Werner_Formulas/Cosine_by_Sine/Proof_2
[ "Werner Formula for Cosine by Sine", "Werner Formulas", "Sine Function", "Cosine Function" ]
[]
[ "Werner Formulas/Sine by Cosine", "Sine Function is Odd" ]
proofwiki-8149
Werner Formulas/Sine by Cosine
:$\sin \alpha \cos \beta = \dfrac {\map \sin {\alpha + \beta} + \map \sin {\alpha - \beta} } 2$
{{begin-eqn}} {{eqn | o = | r = \frac {\sin \paren {\alpha + \beta} + \sin \paren {\alpha - \beta} } 2 }} {{eqn | r = \frac {\paren {\sin \alpha \cos \beta + \cos \alpha \sin \beta} + \paren {\sin \alpha \cos \beta - \cos \alpha \sin \beta} } 2 | c = Sine of Sum and Sine of Difference }} {{eqn | r = \frac ...
:$\sin \alpha \cos \beta = \dfrac {\map \sin {\alpha + \beta} + \map \sin {\alpha - \beta} } 2$
{{begin-eqn}} {{eqn | o = | r = \frac {\sin \paren {\alpha + \beta} + \sin \paren {\alpha - \beta} } 2 }} {{eqn | r = \frac {\paren {\sin \alpha \cos \beta + \cos \alpha \sin \beta} + \paren {\sin \alpha \cos \beta - \cos \alpha \sin \beta} } 2 | c = [[Sine of Sum]] and [[Sine of Difference]] }} {{eqn | r ...
Werner Formulas/Sine by Cosine/Proof 1
https://proofwiki.org/wiki/Werner_Formulas/Sine_by_Cosine
https://proofwiki.org/wiki/Werner_Formulas/Sine_by_Cosine/Proof_1
[ "Werner Formula for Sine by Cosine", "Werner Formulas", "Sine Function", "Cosine Function" ]
[]
[ "Sine of Sum", "Sine of Difference" ]
proofwiki-8150
Werner Formulas/Sine by Cosine
:$\sin \alpha \cos \beta = \dfrac {\map \sin {\alpha + \beta} + \map \sin {\alpha - \beta} } 2$
{{begin-eqn}} {{eqn | o = | r = 2 \sin \alpha \cos \beta }} {{eqn | r = 2 \paren {\dfrac {\map \exp {i \alpha} - \map \exp {-i \alpha} } {2 i} } \paren {\dfrac {\map \exp {i \beta} + \map \exp {-i \beta} } 2} | c = Euler's Sine Identity and Euler's Cosine Identity }} {{eqn | r = \frac 1 {2 i} \paren {\map ...
:$\sin \alpha \cos \beta = \dfrac {\map \sin {\alpha + \beta} + \map \sin {\alpha - \beta} } 2$
{{begin-eqn}} {{eqn | o = | r = 2 \sin \alpha \cos \beta }} {{eqn | r = 2 \paren {\dfrac {\map \exp {i \alpha} - \map \exp {-i \alpha} } {2 i} } \paren {\dfrac {\map \exp {i \beta} + \map \exp {-i \beta} } 2} | c = [[Euler's Sine Identity]] and [[Euler's Cosine Identity]] }} {{eqn | r = \frac 1 {2 i} \pare...
Werner Formulas/Sine by Cosine/Proof 2
https://proofwiki.org/wiki/Werner_Formulas/Sine_by_Cosine
https://proofwiki.org/wiki/Werner_Formulas/Sine_by_Cosine/Proof_2
[ "Werner Formula for Sine by Cosine", "Werner Formulas", "Sine Function", "Cosine Function" ]
[]
[ "Euler's Sine Identity", "Euler's Cosine Identity" ]
proofwiki-8151
Sine of Integer Multiple of Argument/Formulation 1
{{begin-eqn}} {{eqn | l = \sin n \theta | r = \sin \theta \paren {\paren {2 \cos \theta}^{n - 1} - \dbinom {n - 2} 1 \paren {2 \cos \theta}^{n - 3} + \dbinom {n - 3} 2 \paren {2 \cos \theta}^{n - 5} - \cdots} | c = }} {{eqn | r = \sin \theta \paren {\sum_{k \mathop \ge 0} \paren {-1}^k \binom {n - \paren {...
The proof proceeds by induction. For all $n \in \Z_{>0}$, let $\map P n$ be the proposition: :$\ds \sin n \theta = \sin \theta \paren {\sum_{k \mathop \ge 0} \paren {-1}^k \binom {n - \paren {k + 1} } k \paren {2 \cos \theta}^{n - \paren {2 k + 1} } }$
{{begin-eqn}} {{eqn | l = \sin n \theta | r = \sin \theta \paren {\paren {2 \cos \theta}^{n - 1} - \dbinom {n - 2} 1 \paren {2 \cos \theta}^{n - 3} + \dbinom {n - 3} 2 \paren {2 \cos \theta}^{n - 5} - \cdots} | c = }} {{eqn | r = \sin \theta \paren {\sum_{k \mathop \ge 0} \paren {-1}^k \binom {n - \paren {...
The proof proceeds by [[Principle of Mathematical Induction|induction]]. For all $n \in \Z_{>0}$, let $\map P n$ be the [[Definition:Proposition|proposition]]: :$\ds \sin n \theta = \sin \theta \paren {\sum_{k \mathop \ge 0} \paren {-1}^k \binom {n - \paren {k + 1} } k \paren {2 \cos \theta}^{n - \paren {2 k + 1} } }...
Sine of Integer Multiple of Argument/Formulation 1
https://proofwiki.org/wiki/Sine_of_Integer_Multiple_of_Argument/Formulation_1
https://proofwiki.org/wiki/Sine_of_Integer_Multiple_of_Argument/Formulation_1
[ "Sine of Integer Multiple of Argument" ]
[]
[ "Principle of Mathematical Induction", "Definition:Proposition", "Principle of Mathematical Induction" ]
proofwiki-8152
Cosine to Power of Odd Integer
:$\ds \cos^{2 n + 1} \theta = \frac 1 {2^{2 n} } \sum_{k \mathop = 0}^n \binom {2 n + 1} k \cos \paren {2 n - 2 k + 1} \theta$
{{begin-eqn}} {{eqn | l = \cos^{2 n + 1} \theta | r = \paren {\frac {e^{i \theta} + e^{-i \theta} } 2}^{2 n + 1} | c = Euler's Cosine Identity }} {{eqn | r = \frac 1 {2^{2 n + 1} } \paren {e^{i \theta} + e^{-i \theta} }^{2 n + 1} | c = Power of Product }} {{eqn | r = \frac 1 {2^{2 n + 1} } \sum^{2 n +...
:$\ds \cos^{2 n + 1} \theta = \frac 1 {2^{2 n} } \sum_{k \mathop = 0}^n \binom {2 n + 1} k \cos \paren {2 n - 2 k + 1} \theta$
{{begin-eqn}} {{eqn | l = \cos^{2 n + 1} \theta | r = \paren {\frac {e^{i \theta} + e^{-i \theta} } 2}^{2 n + 1} | c = [[Euler's Cosine Identity]] }} {{eqn | r = \frac 1 {2^{2 n + 1} } \paren {e^{i \theta} + e^{-i \theta} }^{2 n + 1} | c = [[Power of Product]] }} {{eqn | r = \frac 1 {2^{2 n + 1} } \su...
Cosine to Power of Odd Integer/Proof 1
https://proofwiki.org/wiki/Cosine_to_Power_of_Odd_Integer
https://proofwiki.org/wiki/Cosine_to_Power_of_Odd_Integer/Proof_1
[ "Cosine Function", "Cosine to Power of Odd Integer" ]
[]
[ "Euler's Cosine Identity", "Exponent Combination Laws/Power of Product", "Binomial Theorem", "Exponential of Sum", "Symmetry Rule for Binomial Coefficients", "Euler's Cosine Identity" ]
proofwiki-8153
Cosine to Power of Odd Integer
:$\ds \cos^{2 n + 1} \theta = \frac 1 {2^{2 n} } \sum_{k \mathop = 0}^n \binom {2 n + 1} k \cos \paren {2 n - 2 k + 1} \theta$
{{begin-eqn}} {{eqn | l = \cos^n \theta | r = \paren {\frac {e^{i \theta} + e^{-i \theta} } 2}^n | c = De Moivre's Theorem }} {{eqn | r = \frac {\paren {e^{i \theta} + e^{-i \theta} }^n} {2^n} | c = }} {{eqn | r = \frac 1 {2^n} \sum_{k \mathop = 0}^n \binom n k e^{\paren {n - k} i \theta} e^{-k i \th...
:$\ds \cos^{2 n + 1} \theta = \frac 1 {2^{2 n} } \sum_{k \mathop = 0}^n \binom {2 n + 1} k \cos \paren {2 n - 2 k + 1} \theta$
{{begin-eqn}} {{eqn | l = \cos^n \theta | r = \paren {\frac {e^{i \theta} + e^{-i \theta} } 2}^n | c = [[De Moivre's Theorem]] }} {{eqn | r = \frac {\paren {e^{i \theta} + e^{-i \theta} }^n} {2^n} | c = }} {{eqn | r = \frac 1 {2^n} \sum_{k \mathop = 0}^n \binom n k e^{\paren {n - k} i \theta} e^{-k i...
Cosine to Power of Odd Integer/Proof 2
https://proofwiki.org/wiki/Cosine_to_Power_of_Odd_Integer
https://proofwiki.org/wiki/Cosine_to_Power_of_Odd_Integer/Proof_2
[ "Cosine Function", "Cosine to Power of Odd Integer" ]
[]
[ "De Moivre's Formula", "Binomial Theorem", "Definition:Binomial Coefficient" ]
proofwiki-8154
Sum of Arctangent and Arccotangent
Let $x \in \R$ be a real number. Then: :$\arctan x + \arccot x = \dfrac \pi 2$ where $\arctan$ and $\arccot$ denote arctangent and arccotangent respectively.
Let $y \in \R$ such that: :$\exists x \in \R: x = \map \cot {y + \dfrac \pi 2}$ Then: {{begin-eqn}} {{eqn | l = x | r = \map \cot {y + \frac \pi 2} | c = }} {{eqn | r = -\tan y | c = Cotangent of Angle plus Right Angle }} {{eqn | r = \map \tan {-y} | c = Tangent Function is Odd }} {{end-eqn}} S...
Let $x \in \R$ be a [[Definition:Real Number|real number]]. Then: :$\arctan x + \arccot x = \dfrac \pi 2$ where $\arctan$ and $\arccot$ denote [[Definition:Real Arctangent|arctangent]] and [[Definition:Real Arccotangent|arccotangent]] respectively.
Let $y \in \R$ such that: :$\exists x \in \R: x = \map \cot {y + \dfrac \pi 2}$ Then: {{begin-eqn}} {{eqn | l = x | r = \map \cot {y + \frac \pi 2} | c = }} {{eqn | r = -\tan y | c = [[Cotangent of Angle plus Right Angle]] }} {{eqn | r = \map \tan {-y} | c = [[Tangent Function is Odd]] }} {{en...
Sum of Arctangent and Arccotangent
https://proofwiki.org/wiki/Sum_of_Arctangent_and_Arccotangent
https://proofwiki.org/wiki/Sum_of_Arctangent_and_Arccotangent
[ "Arctangent Function", "Arccotangent Function" ]
[ "Definition:Real Number", "Definition:Inverse Tangent/Real/Arctangent", "Definition:Inverse Cotangent/Real/Arccotangent" ]
[ "Cotangent of Angle plus Right Angle", "Tangent Function is Odd" ]
proofwiki-8155
Arcsine of Reciprocal equals Arccosecant
:$\map \arcsin {\dfrac 1 x} = \arccsc x$
{{begin-eqn}} {{eqn | l = \map \arcsin {\frac 1 x} | r = y | c = }} {{eqn | ll= \leadstoandfrom | l = \frac 1 x | r = \sin y | c = {{Defof|Real Arcsine}} }} {{eqn | ll= \leadstoandfrom | l = x | r = \csc y | c = Cosecant is Reciprocal of Sine }} {{eqn | ll= \leadstoandfr...
:$\map \arcsin {\dfrac 1 x} = \arccsc x$
{{begin-eqn}} {{eqn | l = \map \arcsin {\frac 1 x} | r = y | c = }} {{eqn | ll= \leadstoandfrom | l = \frac 1 x | r = \sin y | c = {{Defof|Real Arcsine}} }} {{eqn | ll= \leadstoandfrom | l = x | r = \csc y | c = [[Cosecant is Reciprocal of Sine]] }} {{eqn | ll= \leadstoa...
Arcsine of Reciprocal equals Arccosecant
https://proofwiki.org/wiki/Arcsine_of_Reciprocal_equals_Arccosecant
https://proofwiki.org/wiki/Arcsine_of_Reciprocal_equals_Arccosecant
[ "Arcsine Function", "Arccosecant Function", "Reciprocals" ]
[]
[ "Cosecant is Reciprocal of Sine" ]
proofwiki-8156
Arccosine of Reciprocal equals Arcsecant
:$\map \arccos {\dfrac 1 x} = \arcsec x$
{{begin-eqn}} {{eqn | l = \map \arccos {\frac 1 x} | r = y | c = }} {{eqn | ll= \leadstoandfrom | l = \frac 1 x | r = \cos y | c = {{Defof|Real Arccosine}} }} {{eqn | ll= \leadstoandfrom | l = x | r = \sec y | c = Secant is Reciprocal of Cosine }} {{eqn | ll= \leadstoand...
:$\map \arccos {\dfrac 1 x} = \arcsec x$
{{begin-eqn}} {{eqn | l = \map \arccos {\frac 1 x} | r = y | c = }} {{eqn | ll= \leadstoandfrom | l = \frac 1 x | r = \cos y | c = {{Defof|Real Arccosine}} }} {{eqn | ll= \leadstoandfrom | l = x | r = \sec y | c = [[Secant is Reciprocal of Cosine]] }} {{eqn | ll= \leadst...
Arccosine of Reciprocal equals Arcsecant
https://proofwiki.org/wiki/Arccosine_of_Reciprocal_equals_Arcsecant
https://proofwiki.org/wiki/Arccosine_of_Reciprocal_equals_Arcsecant
[ "Arccosine Function", "Arcsecant Function", "Reciprocals" ]
[]
[ "Secant is Reciprocal of Cosine" ]
proofwiki-8157
Arctangent of Reciprocal equals Arccotangent
:$\map \arctan {\dfrac 1 x} = \arccot x$
{{begin-eqn}} {{eqn | l = \map \arctan {\frac 1 x} | r = y | c = }} {{eqn | ll= \leadstoandfrom | l = \frac 1 x | r = \tan y | c = {{Defof|Real Arctangent}} }} {{eqn | ll= \leadstoandfrom | l = x | r = \cot y | c = Cotangent is Reciprocal of Tangent }} {{eqn | ll= \leads...
:$\map \arctan {\dfrac 1 x} = \arccot x$
{{begin-eqn}} {{eqn | l = \map \arctan {\frac 1 x} | r = y | c = }} {{eqn | ll= \leadstoandfrom | l = \frac 1 x | r = \tan y | c = {{Defof|Real Arctangent}} }} {{eqn | ll= \leadstoandfrom | l = x | r = \cot y | c = [[Cotangent is Reciprocal of Tangent]] }} {{eqn | ll= \l...
Arctangent of Reciprocal equals Arccotangent
https://proofwiki.org/wiki/Arctangent_of_Reciprocal_equals_Arccotangent
https://proofwiki.org/wiki/Arctangent_of_Reciprocal_equals_Arccotangent
[ "Arctangent Function", "Arccotangent Function", "Reciprocals" ]
[]
[ "Cotangent is Reciprocal of Tangent" ]
proofwiki-8158
Inverse Sine is Odd Function
Everywhere that the function is defined: :$\map \arcsin {-x} = -\arcsin x$
{{begin-eqn}} {{eqn | l = \map \arcsin {-x} | r = y | c = }} {{eqn | ll= \leadstoandfrom | l = -x | r = \sin y: | rr = -\frac \pi 2 \le y \le \frac \pi 2 | c = {{Defof|Real Arcsine}} }} {{eqn | ll= \leadstoandfrom | l = x | r = -\sin y: | rr = -\frac \pi 2 \le y \l...
Everywhere that the function is defined: :$\map \arcsin {-x} = -\arcsin x$
{{begin-eqn}} {{eqn | l = \map \arcsin {-x} | r = y | c = }} {{eqn | ll= \leadstoandfrom | l = -x | r = \sin y: | rr = -\frac \pi 2 \le y \le \frac \pi 2 | c = {{Defof|Real Arcsine}} }} {{eqn | ll= \leadstoandfrom | l = x | r = -\sin y: | rr = -\frac \pi 2 \le y \l...
Inverse Sine is Odd Function
https://proofwiki.org/wiki/Inverse_Sine_is_Odd_Function
https://proofwiki.org/wiki/Inverse_Sine_is_Odd_Function
[ "Arcsine Function", "Examples of Odd Functions" ]
[]
[ "Sine Function is Odd" ]
proofwiki-8159
Arccosine of Negative Argument
Everywhere that the function is defined: :$\map \arccos {-x} = \pi - \arccos x$
{{begin-eqn}} {{eqn | l = \map \arccos {-x} | r = y | c = }} {{eqn | ll= \leadstoandfrom | l = -x | r = \cos y: | rr= 0 \le y \le \pi | c = {{Defof|Real Arccosine}} }} {{eqn | ll= \leadstoandfrom | l = x | r = -\cos y: | rr= -\pi \le y \le 0 | c = }} {{eqn |...
Everywhere that the function is defined: :$\map \arccos {-x} = \pi - \arccos x$
{{begin-eqn}} {{eqn | l = \map \arccos {-x} | r = y | c = }} {{eqn | ll= \leadstoandfrom | l = -x | r = \cos y: | rr= 0 \le y \le \pi | c = {{Defof|Real Arccosine}} }} {{eqn | ll= \leadstoandfrom | l = x | r = -\cos y: | rr= -\pi \le y \le 0 | c = }} {{eqn |...
Arccosine of Negative Argument
https://proofwiki.org/wiki/Arccosine_of_Negative_Argument
https://proofwiki.org/wiki/Arccosine_of_Negative_Argument
[ "Arccosine Function" ]
[]
[ "Cosine of Supplementary Angle" ]
proofwiki-8160
Inverse Tangent is Odd Function
Everywhere that the function is defined: :$\map \arctan {-x} = -\arctan x$
{{begin-eqn}} {{eqn | l = \map \arctan {-x} | r = y | c = }} {{eqn | ll= \leadstoandfrom | l = -x | r = \tan y: | rr= -\frac \pi 2 \le y \le \frac \pi 2 | c = {{Defof|Real Arctangent}} }} {{eqn | ll= \leadstoandfrom | l = x | r = -\tan y: | rr= -\frac \pi 2 \le y \...
Everywhere that the function is defined: :$\map \arctan {-x} = -\arctan x$
{{begin-eqn}} {{eqn | l = \map \arctan {-x} | r = y | c = }} {{eqn | ll= \leadstoandfrom | l = -x | r = \tan y: | rr= -\frac \pi 2 \le y \le \frac \pi 2 | c = {{Defof|Real Arctangent}} }} {{eqn | ll= \leadstoandfrom | l = x | r = -\tan y: | rr= -\frac \pi 2 \le y \...
Inverse Tangent is Odd Function
https://proofwiki.org/wiki/Inverse_Tangent_is_Odd_Function
https://proofwiki.org/wiki/Inverse_Tangent_is_Odd_Function
[ "Arctangent Function", "Examples of Odd Functions" ]
[]
[ "Tangent Function is Odd" ]
proofwiki-8161
Arccotangent of Negative Argument
Everywhere that the function is defined: :$\map \arccot {-x} = \pi - \arccot x$
{{begin-eqn}} {{eqn | l = \map \arccot {-x} | r = y | c = }} {{eqn | ll= \leadstoandfrom | l = -x | r = \cot y: | rr= 0 \le y \le \pi | c = {{Defof|Arccotangent}} }} {{eqn | ll= \leadstoandfrom | l = x | r = -\cot y: | rr= -\pi \le y \le 0 | c = }} {{eqn | l...
Everywhere that the function is defined: :$\map \arccot {-x} = \pi - \arccot x$
{{begin-eqn}} {{eqn | l = \map \arccot {-x} | r = y | c = }} {{eqn | ll= \leadstoandfrom | l = -x | r = \cot y: | rr= 0 \le y \le \pi | c = {{Defof|Arccotangent}} }} {{eqn | ll= \leadstoandfrom | l = x | r = -\cot y: | rr= -\pi \le y \le 0 | c = }} {{eqn | l...
Arccotangent of Negative Argument
https://proofwiki.org/wiki/Arccotangent_of_Negative_Argument
https://proofwiki.org/wiki/Arccotangent_of_Negative_Argument
[ "Arccotangent Function" ]
[]
[ "Cotangent of Supplementary Angle" ]
proofwiki-8162
Arcsecant of Negative Argument
Everywhere that the function is defined: :$\map \arcsec {-x} = \pi - \arcsec x$
{{begin-eqn}} {{eqn | l = \map \arcsec {-x} | r = y | c = }} {{eqn | ll= \leadstoandfrom | l = -x | r = \sec y: | rr= 0 \le y \le \pi | c = {{Defof|Arcsecant}} }} {{eqn | ll= \leadstoandfrom | l = x | r = -\sec y: | rr= -\pi \le y \le 0 | c = }} {{eqn | ll= ...
Everywhere that the function is defined: :$\map \arcsec {-x} = \pi - \arcsec x$
{{begin-eqn}} {{eqn | l = \map \arcsec {-x} | r = y | c = }} {{eqn | ll= \leadstoandfrom | l = -x | r = \sec y: | rr= 0 \le y \le \pi | c = {{Defof|Arcsecant}} }} {{eqn | ll= \leadstoandfrom | l = x | r = -\sec y: | rr= -\pi \le y \le 0 | c = }} {{eqn | ll= ...
Arcsecant of Negative Argument
https://proofwiki.org/wiki/Arcsecant_of_Negative_Argument
https://proofwiki.org/wiki/Arcsecant_of_Negative_Argument
[ "Arcsecant Function" ]
[]
[ "Cosecant of Supplementary Angle" ]
proofwiki-8163
Inverse Cosecant is Odd Function
Everywhere that the function is defined: :$\map \arccsc {-x} = -\arccsc x$
{{begin-eqn}} {{eqn | l = \map \arccsc {-x} | r = y | c = }} {{eqn | ll= \leadstoandfrom | l = -x | r = \csc y: | rr= -\frac \pi 2 \le y \le \frac \pi 2 | c = {{Defof|Arccosecant}} }} {{eqn | ll= \leadstoandfrom | l = x | r = -\csc y: | rr= -\frac \pi 2 \le y \le \...
Everywhere that the function is defined: :$\map \arccsc {-x} = -\arccsc x$
{{begin-eqn}} {{eqn | l = \map \arccsc {-x} | r = y | c = }} {{eqn | ll= \leadstoandfrom | l = -x | r = \csc y: | rr= -\frac \pi 2 \le y \le \frac \pi 2 | c = {{Defof|Arccosecant}} }} {{eqn | ll= \leadstoandfrom | l = x | r = -\csc y: | rr= -\frac \pi 2 \le y \le \...
Inverse Cosecant is Odd Function
https://proofwiki.org/wiki/Inverse_Cosecant_is_Odd_Function
https://proofwiki.org/wiki/Inverse_Cosecant_is_Odd_Function
[ "Arccosecant Function", "Examples of Odd Functions" ]
[]
[ "Cosecant Function is Odd" ]
proofwiki-8164
Law of Tangents
Let $\triangle ABC$ be a triangle whose sides $a, b, c$ are such that $a$ is opposite $A$, $b$ is opposite $B$ and $c$ is opposite $C$. Then: :$\dfrac {a + b} {a - b} = \dfrac {\tan \frac 1 2 \paren {A + B} } {\tan \frac 1 2 \paren {A - B} }$
Let $d = \dfrac a {\sin A}$. From the Law of Sines, let: :$d = \dfrac a {\sin A} = \dfrac b {\sin B}$ so that: {{begin-eqn}} {{eqn | l = a | r = d \sin A | c = }} {{eqn | l = b | r = d \sin B | c = }} {{eqn | ll= \leadsto | l = \frac {a + b} {a - b} | r = \frac {d \sin A + d \sin B...
Let $\triangle ABC$ be a [[Definition:Triangle (Geometry)|triangle]] whose sides $a, b, c$ are such that $a$ is opposite $A$, $b$ is opposite $B$ and $c$ is opposite $C$. Then: :$\dfrac {a + b} {a - b} = \dfrac {\tan \frac 1 2 \paren {A + B} } {\tan \frac 1 2 \paren {A - B} }$
Let $d = \dfrac a {\sin A}$. From the [[Law of Sines]], let: :$d = \dfrac a {\sin A} = \dfrac b {\sin B}$ so that: {{begin-eqn}} {{eqn | l = a | r = d \sin A | c = }} {{eqn | l = b | r = d \sin B | c = }} {{eqn | ll= \leadsto | l = \frac {a + b} {a - b} | r = \frac {d \sin A + d ...
Law of Tangents
https://proofwiki.org/wiki/Law_of_Tangents
https://proofwiki.org/wiki/Law_of_Tangents
[ "Law of Tangents", "Triangles", "Tangent Function", "Named Theorems" ]
[ "Definition:Triangle (Geometry)" ]
[ "Law of Sines", "Prosthaphaeresis Formulas/Sine plus Sine", "Prosthaphaeresis Formulas/Sine minus Sine", "Tangent is Sine divided by Cosine" ]
proofwiki-8165
Law of Tangents
Let $\triangle ABC$ be a triangle whose sides $a, b, c$ are such that $a$ is opposite $A$, $b$ is opposite $B$ and $c$ is opposite $C$. Then: :$\dfrac {a + b} {a - b} = \dfrac {\tan \frac 1 2 \paren {A + B} } {\tan \frac 1 2 \paren {A - B} }$
{{begin-eqn}} {{eqn | l = \dfrac {a + b} {a - b} | r = \dfrac {\tan \frac 1 2 \paren {A + B} } {\tan \frac 1 2 \paren {A - B} } | c = Law of Tangents }} {{eqn | ll= \leadsto | l = \tan \frac {A - B} 2 | r = \dfrac {a - b} {a + b} \tan \frac {A + B} 2 | c = algebraic manipulation }} {{eqn |...
Let $\triangle ABC$ be a [[Definition:Triangle (Geometry)|triangle]] whose sides $a, b, c$ are such that $a$ is opposite $A$, $b$ is opposite $B$ and $c$ is opposite $C$. Then: :$\dfrac {a + b} {a - b} = \dfrac {\tan \frac 1 2 \paren {A + B} } {\tan \frac 1 2 \paren {A - B} }$
{{begin-eqn}} {{eqn | l = \dfrac {a + b} {a - b} | r = \dfrac {\tan \frac 1 2 \paren {A + B} } {\tan \frac 1 2 \paren {A - B} } | c = [[Law of Tangents]] }} {{eqn | ll= \leadsto | l = \tan \frac {A - B} 2 | r = \dfrac {a - b} {a + b} \tan \frac {A + B} 2 | c = algebraic manipulation }} {{e...
Law of Tangents/Corollary/Proof 1
https://proofwiki.org/wiki/Law_of_Tangents
https://proofwiki.org/wiki/Law_of_Tangents/Corollary/Proof_1
[ "Law of Tangents", "Triangles", "Tangent Function", "Named Theorems" ]
[ "Definition:Triangle (Geometry)" ]
[ "Law of Tangents", "Sum of Angles of Triangle equals Two Right Angles", "Tangent of Complement equals Cotangent" ]
proofwiki-8166
Law of Tangents
Let $\triangle ABC$ be a triangle whose sides $a, b, c$ are such that $a$ is opposite $A$, $b$ is opposite $B$ and $c$ is opposite $C$. Then: :$\dfrac {a + b} {a - b} = \dfrac {\tan \frac 1 2 \paren {A + B} } {\tan \frac 1 2 \paren {A - B} }$
{{begin-eqn}} {{eqn | l = \dfrac {a - b} {a + b} | r = \dfrac {2 R \sin A - 2 R \sin B} {2 R \sin A + 2 R \sin B} | c = Law of Sines }} {{eqn | r = \dfrac {2 \cos \frac {A + B} 2 \sin \frac {A - B} 2} {2 \sin \frac {A + B} 2 \cos \frac {A - B} 2} | c = Sine minus Sine, Sine plus Sine }} {{eqn | r = \d...
Let $\triangle ABC$ be a [[Definition:Triangle (Geometry)|triangle]] whose sides $a, b, c$ are such that $a$ is opposite $A$, $b$ is opposite $B$ and $c$ is opposite $C$. Then: :$\dfrac {a + b} {a - b} = \dfrac {\tan \frac 1 2 \paren {A + B} } {\tan \frac 1 2 \paren {A - B} }$
{{begin-eqn}} {{eqn | l = \dfrac {a - b} {a + b} | r = \dfrac {2 R \sin A - 2 R \sin B} {2 R \sin A + 2 R \sin B} | c = [[Law of Sines]] }} {{eqn | r = \dfrac {2 \cos \frac {A + B} 2 \sin \frac {A - B} 2} {2 \sin \frac {A + B} 2 \cos \frac {A - B} 2} | c = [[Sine minus Sine]], [[Sine plus Sine]] }} {{...
Law of Tangents/Corollary/Proof 2
https://proofwiki.org/wiki/Law_of_Tangents
https://proofwiki.org/wiki/Law_of_Tangents/Corollary/Proof_2
[ "Law of Tangents", "Triangles", "Tangent Function", "Named Theorems" ]
[ "Definition:Triangle (Geometry)" ]
[ "Law of Sines", "Prosthaphaeresis Formulas/Sine minus Sine", "Prosthaphaeresis Formulas/Sine plus Sine", "Tangent is Sine divided by Cosine", "Sum of Angles of Triangle equals Two Right Angles", "Tangent of Complement equals Cotangent", "Tangent of Complement equals Cotangent" ]
proofwiki-8167
Sine of Angle of Triangle by Semiperimeter
Let $\triangle ABC$ be a triangle whose sides $a, b, c$ are such that $a$ is opposite $A$, $b$ is opposite $B$ and $c$ is opposite $C$. Then: : $\sin A = \dfrac 2 {b c} \sqrt {s \paren {s - a} \paren {s - b} \paren {s - c} }$ where $\sin$ denotes sine and $s$ is the semiperimeter: $s = \dfrac {a + b + c} 2$.
Let $Q$ be the area of $\triangle ABC$. From Area of Triangle in Terms of Two Sides and Angle: :$Q = \dfrac {b c \sin A} 2$ From Heron's Formula: :$Q = \sqrt {s \paren {s - a} \paren {s - b} \paren {s - c} }$ Equating the two: :$\dfrac {b c \sin A} 2 = \sqrt {s \paren {s - a} \paren {s - b} \paren {s - c} }$ from which...
Let $\triangle ABC$ be a [[Definition:Triangle (Geometry)|triangle]] whose sides $a, b, c$ are such that $a$ is opposite $A$, $b$ is opposite $B$ and $c$ is opposite $C$. Then: : $\sin A = \dfrac 2 {b c} \sqrt {s \paren {s - a} \paren {s - b} \paren {s - c} }$ where $\sin$ denotes [[Definition:Sine|sine]] and $s$ is t...
Let $Q$ be the [[Definition:Area|area]] of $\triangle ABC$. From [[Area of Triangle in Terms of Two Sides and Angle]]: :$Q = \dfrac {b c \sin A} 2$ From [[Heron's Formula]]: :$Q = \sqrt {s \paren {s - a} \paren {s - b} \paren {s - c} }$ Equating the two: :$\dfrac {b c \sin A} 2 = \sqrt {s \paren {s - a} \paren {s - ...
Sine of Angle of Triangle by Semiperimeter
https://proofwiki.org/wiki/Sine_of_Angle_of_Triangle_by_Semiperimeter
https://proofwiki.org/wiki/Sine_of_Angle_of_Triangle_by_Semiperimeter
[ "Triangles", "Sine Function" ]
[ "Definition:Triangle (Geometry)", "Definition:Sine", "Definition:Semiperimeter" ]
[ "Definition:Area", "Area of Triangle in Terms of Two Sides and Angle", "Heron's Formula" ]
proofwiki-8168
Functionally Complete Logical Connectives/Negation, Conjunction, Disjunction and Conditional
: $\set {\neg, \land, \lor, \implies}$: Not, And, Or and Implies
From Functional Completeness over Finite Number of Arguments, it suffices to consider binary truth functions. From Count of Truth Functions, there are $16$ of these. These are enumerated in Binary Truth Functions, and are analysed in turn as follows.
: $\set {\neg, \land, \lor, \implies}$: [[Definition:Logical Not|Not]], [[Definition:Conjunction|And]], [[Definition:Disjunction|Or]] and [[Definition:Conditional|Implies]]
From [[Functional Completeness over Finite Number of Arguments]], it suffices to consider binary [[Definition:Truth Function|truth functions]]. From [[Count of Truth Functions]], there are $16$ of these. These are enumerated in [[Binary Truth Functions]], and are analysed in turn as follows.
Functionally Complete Logical Connectives/Negation, Conjunction, Disjunction and Conditional
https://proofwiki.org/wiki/Functionally_Complete_Logical_Connectives/Negation,_Conjunction,_Disjunction_and_Conditional
https://proofwiki.org/wiki/Functionally_Complete_Logical_Connectives/Negation,_Conjunction,_Disjunction_and_Conditional
[ "Functional Completeness" ]
[ "Definition:Logical Not", "Definition:Conjunction", "Definition:Disjunction", "Definition:Conditional" ]
[ "Functional Completeness over Finite Number of Arguments", "Definition:Truth Function", "Count of Truth Functions", "Binary Truth Functions", "Binary Truth Functions" ]
proofwiki-8169
Functionally Complete Logical Connectives/Negation and Disjunction
:$\set {\neg, \lor}$: Not and Or
From Functionally Complete Logical Connectives: Negation and Conjunction, $\set {\neg, \land}$ is functionally complete. That is: any expression can be expressed in terms of $\neg$ and $\land$. From De Morgan's laws: Conjunction, we have that: :$p \land q \dashv \vdash \neg \paren {\neg p \lor \neg q}$ Thus all occurre...
:$\set {\neg, \lor}$: [[Definition:Logical Not|Not]] and [[Definition:Disjunction|Or]]
From [[Functionally Complete Logical Connectives/Negation and Conjunction|Functionally Complete Logical Connectives: Negation and Conjunction]], $\set {\neg, \land}$ is [[Definition:Functionally Complete|functionally complete]]. That is: any expression can be expressed in terms of $\neg$ and $\land$. From [[De Morgan...
Functionally Complete Logical Connectives/Negation and Disjunction
https://proofwiki.org/wiki/Functionally_Complete_Logical_Connectives/Negation_and_Disjunction
https://proofwiki.org/wiki/Functionally_Complete_Logical_Connectives/Negation_and_Disjunction
[ "Functional Completeness" ]
[ "Definition:Logical Not", "Definition:Disjunction" ]
[ "Functionally Complete Logical Connectives/Negation and Conjunction", "Definition:Functionally Complete", "De Morgan's Laws (Logic)/Conjunction", "Definition:Functionally Complete" ]
proofwiki-8170
Functionally Complete Logical Connectives/Negation and Conjunction
:$\set {\neg, \land}$: Not and And
From Functionally Complete Logical Connectives: Negation, Conjunction, Disjunction and Conditional, all sixteen of the binary truth functions can be expressed in terms of $\neg, \land, \lor, \implies$. From Conjunction and Conditional, we have that: :$p \implies q \dashv \vdash \neg \paren {p \land \neg q}$ From De Mor...
:$\set {\neg, \land}$: [[Definition:Logical Not|Not]] and [[Definition:Conjunction|And]]
From [[Functionally Complete Logical Connectives/Negation, Conjunction, Disjunction and Conditional|Functionally Complete Logical Connectives: Negation, Conjunction, Disjunction and Conditional]], all sixteen of the [[Binary Truth Functions|binary truth functions]] can be expressed in terms of $\neg, \land, \lor, \impl...
Functionally Complete Logical Connectives/Negation and Conjunction
https://proofwiki.org/wiki/Functionally_Complete_Logical_Connectives/Negation_and_Conjunction
https://proofwiki.org/wiki/Functionally_Complete_Logical_Connectives/Negation_and_Conjunction
[ "Functional Completeness" ]
[ "Definition:Logical Not", "Definition:Conjunction" ]
[ "Functionally Complete Logical Connectives/Negation, Conjunction, Disjunction and Conditional", "Binary Truth Functions", "Conjunction and Conditional", "De Morgan's Laws (Logic)/Disjunction", "Definition:Functionally Complete" ]
proofwiki-8171
Functionally Complete Logical Connectives/Negation and Conditional
:$\set {\neg, \implies}$: Not and Implies
From Functionally Complete Logical Connectives: Negation and Conjunction, we can represent any boolean expression in terms of $\land$ and $\neg$. From Conjunction and Conditional, we have that: :$p \land q \dashv \vdash \neg \paren {p \implies \neg q}$ So it follows that we can replace all occurrences of $\land$ by $\i...
:$\set {\neg, \implies}$: [[Definition:Logical Not|Not]] and [[Definition:Conditional|Implies]]
From [[Functionally Complete Logical Connectives/Negation and Conjunction|Functionally Complete Logical Connectives: Negation and Conjunction]], we can represent any boolean expression in terms of $\land$ and $\neg$. From [[Conjunction and Conditional]], we have that: :$p \land q \dashv \vdash \neg \paren {p \implies ...
Functionally Complete Logical Connectives/Negation and Conditional
https://proofwiki.org/wiki/Functionally_Complete_Logical_Connectives/Negation_and_Conditional
https://proofwiki.org/wiki/Functionally_Complete_Logical_Connectives/Negation_and_Conditional
[ "Functional Completeness" ]
[ "Definition:Logical Not", "Definition:Conditional" ]
[ "Functionally Complete Logical Connectives/Negation and Conjunction", "Conjunction and Conditional", "Definition:Functionally Complete" ]
proofwiki-8172
Functionally Complete Logical Connectives/Conjunction, Negation and Disjunction
:$\set {\neg, \land, \lor}$: Not, And and Or
From the stronger results: :Functionally Complete Logical Connectives: Negation and Disjunction: ::the set of logical connectives: $\set {\neg, \lor}$ is functionally complete :Functionally Complete Logical Connectives: Negation and Conjunction: ::the set of logical connectives: $\set {\neg, \land}$ is functionally com...
:$\set {\neg, \land, \lor}$: [[Definition:Logical Not|Not]], [[Definition:Conjunction|And]] and [[Definition:Disjunction|Or]]
From the [[Definition:Stronger Statement|stronger]] results: :[[Functionally Complete Logical Connectives/Negation and Disjunction|Functionally Complete Logical Connectives: Negation and Disjunction]]: ::the [[Definition:Set|set]] of [[Definition:Logical Connective|logical connectives]]: $\set {\neg, \lor}$ is [[Defini...
Functionally Complete Logical Connectives/Conjunction, Negation and Disjunction
https://proofwiki.org/wiki/Functionally_Complete_Logical_Connectives/Conjunction,_Negation_and_Disjunction
https://proofwiki.org/wiki/Functionally_Complete_Logical_Connectives/Conjunction,_Negation_and_Disjunction
[ "Functional Completeness" ]
[ "Definition:Logical Not", "Definition:Conjunction", "Definition:Disjunction" ]
[ "Definition:Conditional/Language of Conditional/Strong", "Functionally Complete Logical Connectives/Negation and Disjunction", "Definition:Set", "Definition:Logical Connective", "Definition:Functionally Complete", "Functionally Complete Logical Connectives/Negation and Conjunction", "Definition:Set", ...
proofwiki-8173
Functionally Complete Logical Connectives/NAND
:$\set \uparrow$: NAND
From Functionally Complete Logical Connectives: Negation and Conjunction, any boolean expression can be expressed in terms of $\land$ and $\neg$. From NAND with Equal Arguments: :$\neg p \dashv \vdash p \uparrow p$ From Conjunction in terms of NAND: :$p \land q \dashv \vdash \paren {p \uparrow q} \uparrow \paren {p \up...
:$\set \uparrow$: [[Definition:Logical NAND|NAND]]
From [[Functionally Complete Logical Connectives/Negation and Conjunction|Functionally Complete Logical Connectives: Negation and Conjunction]], any boolean expression can be expressed in terms of $\land$ and $\neg$. From [[NAND with Equal Arguments]]: :$\neg p \dashv \vdash p \uparrow p$ From [[Conjunction in term...
Functionally Complete Logical Connectives/NAND
https://proofwiki.org/wiki/Functionally_Complete_Logical_Connectives/NAND
https://proofwiki.org/wiki/Functionally_Complete_Logical_Connectives/NAND
[ "Functional Completeness", "Logical NAND" ]
[ "Definition:Logical NAND" ]
[ "Functionally Complete Logical Connectives/Negation and Conjunction", "NAND with Equal Arguments", "Conjunction in terms of NAND", "Definition:Functionally Complete" ]
proofwiki-8174
Functionally Complete Logical Connectives/NOR
:$\set \downarrow$: NOR
From Functionally Complete Logical Connectives: Negation and Disjunction, any boolean expression can be expressed in terms of $\lor$ and $\neg$. From NOR with Equal Arguments: :$\neg p \dashv \vdash p \downarrow p$ From Disjunction in terms of NOR: :$p \lor q \dashv \vdash \paren {p \downarrow q} \downarrow \paren {p \...
:$\set \downarrow$: [[Definition:Logical NOR|NOR]]
From [[Functionally Complete Logical Connectives/Negation and Disjunction|Functionally Complete Logical Connectives: Negation and Disjunction]], any boolean expression can be expressed in terms of $\lor$ and $\neg$. From [[NOR with Equal Arguments]]: :$\neg p \dashv \vdash p \downarrow p$ From [[Disjunction in term...
Functionally Complete Logical Connectives/NOR
https://proofwiki.org/wiki/Functionally_Complete_Logical_Connectives/NOR
https://proofwiki.org/wiki/Functionally_Complete_Logical_Connectives/NOR
[ "Functional Completeness", "Logical NOR" ]
[ "Definition:Logical NOR" ]
[ "Functionally Complete Logical Connectives/Negation and Disjunction", "NOR with Equal Arguments", "Disjunction in terms of NOR", "Definition:Functionally Complete" ]
proofwiki-8175
Functionally Complete Singleton Sets
The only binary logical connectives that form singleton sets which are functionally complete are NAND and NOR.
Let $\uparrow$ and $\downarrow$ denote NAND and NOR respectively. From: : NAND is Functionally Complete and : NOR is Functionally Complete the singleton sets $\left\{{\uparrow}\right\}$ and $\left\{{\downarrow}\right\}$ are functionally complete. Suppose $\circ$ is a binary logical connective such that $\left\{{\circ}\...
The only [[Definition:Binary Logical Connective|binary logical connectives]] that form [[Definition:Singleton|singleton sets]] which are [[Definition:Functionally Complete|functionally complete]] are [[Definition:Logical NAND|NAND]] and [[Definition:Logical NOR|NOR]].
Let $\uparrow$ and $\downarrow$ denote [[Definition:Logical NAND|NAND]] and [[Definition:Logical NOR|NOR]] respectively. From: : [[NAND is Functionally Complete]] and : [[NOR is Functionally Complete]] the [[Definition:Singleton|singleton sets]] $\left\{{\uparrow}\right\}$ and $\left\{{\downarrow}\right\}$ are [[Defin...
Functionally Complete Singleton Sets
https://proofwiki.org/wiki/Functionally_Complete_Singleton_Sets
https://proofwiki.org/wiki/Functionally_Complete_Singleton_Sets
[ "Functional Completeness" ]
[ "Definition:Logical Connective/Binary", "Definition:Singleton", "Definition:Functionally Complete", "Definition:Logical NAND", "Definition:Logical NOR" ]
[ "Definition:Logical NAND", "Definition:Logical NOR", "Functionally Complete Logical Connectives/NAND", "Functionally Complete Logical Connectives/NOR", "Definition:Singleton", "Definition:Functionally Complete", "Definition:Logical Connective/Binary", "Definition:Functionally Complete", "Definition:...
proofwiki-8176
Conditional and Converse are not Equivalent
A conditional statement: :$p \implies q$ is not logically equivalent to its converse: :$q \implies p$
We apply the Method of Truth Tables to the proposition: :$\paren {p \implies q} \iff \paren {q \implies p}$ $\begin{array}{|ccc|c|ccc|} \hline p & \implies & q) & \iff & (q & \implies & p) \\ \hline \F & \T & \F & \T & \F & \T & \F \\ \F & \T & \T & \F & \T & \F & \F \\ \T & \F & \F & \F & \F & \T & \T \\ \T & \T & \T ...
A [[Definition:Conditional|conditional statement]]: :$p \implies q$ is not [[Definition:Logical Equivalence|logically equivalent]] to its [[Definition:Converse Statement|converse]]: :$q \implies p$
We apply the [[Method of Truth Tables]] to the proposition: :$\paren {p \implies q} \iff \paren {q \implies p}$ $\begin{array}{|ccc|c|ccc|} \hline p & \implies & q) & \iff & (q & \implies & p) \\ \hline \F & \T & \F & \T & \F & \T & \F \\ \F & \T & \T & \F & \T & \F & \F \\ \T & \F & \F & \F & \F & \T & \T \\ \T & \T ...
Conditional and Converse are not Equivalent
https://proofwiki.org/wiki/Conditional_and_Converse_are_not_Equivalent
https://proofwiki.org/wiki/Conditional_and_Converse_are_not_Equivalent
[ "Conditional" ]
[ "Definition:Conditional", "Definition:Logical Equivalence", "Definition:Converse Statement" ]
[ "Method of Truth Tables", "Definition:Truth Value", "Definition:Main Connective/Propositional Logic", "Definition:Boolean Interpretation" ]
proofwiki-8177
De Morgan's Laws (Predicate Logic)/Assertion of Universality
:$\forall x: \map P x \dashv \vdash \neg \paren {\exists x: \neg \map P x}$ ::''If everything '''is''', there exists nothing that '''is not'''.''
{{BeginTableau|\forall x: \map P x \vdash \neg \paren {\exists x: \neg \map P x} }} {{Premise|1|\forall x: \map P x}} {{Assumption|2|\exists x: \neg \map P x}} {{TableauLine|n = 3|pool = 2|f = \neg \map P {\mathbf a}|rlnk = Existential Instantiation|rtxt = Existential Instantiation|dep = 2|c = for some arbitrary $\math...
:$\forall x: \map P x \dashv \vdash \neg \paren {\exists x: \neg \map P x}$ ::''If everything '''is''', there exists nothing that '''is not'''.''
{{BeginTableau|\forall x: \map P x \vdash \neg \paren {\exists x: \neg \map P x} }} {{Premise|1|\forall x: \map P x}} {{Assumption|2|\exists x: \neg \map P x}} {{TableauLine|n = 3|pool = 2|f = \neg \map P {\mathbf a}|rlnk = Existential Instantiation|rtxt = Existential Instantiation|dep = 2|c = for some arbitrary $\math...
De Morgan's Laws (Predicate Logic)/Assertion of Universality
https://proofwiki.org/wiki/De_Morgan's_Laws_(Predicate_Logic)/Assertion_of_Universality
https://proofwiki.org/wiki/De_Morgan's_Laws_(Predicate_Logic)/Assertion_of_Universality
[ "Universal Quantifier", "Existential Quantifier", "De Morgan's Laws (Logic)" ]
[]
[ "De Morgan's Laws (Predicate Logic)/Denial of Universality" ]
proofwiki-8178
De Morgan's Laws (Predicate Logic)/Denial of Existence
:$\forall x: \neg \map P x \dashv \vdash \neg \paren {\exists x: \map P x}$ ::''If everything '''is not''', there exists nothing that '''is'''.''
{{BeginTableau|\forall x: \neg \map P x \vdash \neg \paren {\exists x: \map P x} }} {{Premise|1|\forall x: \neg \map P x}} {{Assumption|2|\exists x: \map P x}} {{TableauLine|n = 3|pool = 2|f = \map P {\mathbf a}|rlnk = Existential Instantiation|rtxt = Existential Instantiation|dep = 2|c = for an arbitrary $\mathbf a$}}...
:$\forall x: \neg \map P x \dashv \vdash \neg \paren {\exists x: \map P x}$ ::''If everything '''is not''', there exists nothing that '''is'''.''
{{BeginTableau|\forall x: \neg \map P x \vdash \neg \paren {\exists x: \map P x} }} {{Premise|1|\forall x: \neg \map P x}} {{Assumption|2|\exists x: \map P x}} {{TableauLine|n = 3|pool = 2|f = \map P {\mathbf a}|rlnk = Existential Instantiation|rtxt = Existential Instantiation|dep = 2|c = for an arbitrary $\mathbf a$}}...
De Morgan's Laws (Predicate Logic)/Denial of Existence
https://proofwiki.org/wiki/De_Morgan's_Laws_(Predicate_Logic)/Denial_of_Existence
https://proofwiki.org/wiki/De_Morgan's_Laws_(Predicate_Logic)/Denial_of_Existence
[ "Universal Quantifier", "Existential Quantifier", "De Morgan's Laws (Logic)" ]
[]
[]
proofwiki-8179
De Morgan's Laws (Predicate Logic)/Assertion of Existence
:$\neg \paren {\forall x: \neg \map P x} \dashv \vdash \exists x: \map P x$ ::''If not everything '''is not''', there exists something that '''is'''.''
{{BeginTableau|\neg \paren {\forall x: \neg \map P x} \vdash \exists x: \map P x}} {{Premise|1|\neg \paren {\forall x: \neg \map P x} }} {{Assumption|2|\neg \paren {\exists x: \map P x} }} {{SequentIntro|3|2|\forall x: \neg \map P x|2|Denial of Existence}} {{NonContradiction|4|1, 2|1|3}} {{Reductio|5|1|\exists x: \map ...
:$\neg \paren {\forall x: \neg \map P x} \dashv \vdash \exists x: \map P x$ ::''If not everything '''is not''', there exists something that '''is'''.''
{{BeginTableau|\neg \paren {\forall x: \neg \map P x} \vdash \exists x: \map P x}} {{Premise|1|\neg \paren {\forall x: \neg \map P x} }} {{Assumption|2|\neg \paren {\exists x: \map P x} }} {{SequentIntro|3|2|\forall x: \neg \map P x|2|[[Denial of Existence]]}} {{NonContradiction|4|1, 2|1|3}} {{Reductio|5|1|\exists x: \...
De Morgan's Laws (Predicate Logic)/Assertion of Existence
https://proofwiki.org/wiki/De_Morgan's_Laws_(Predicate_Logic)/Assertion_of_Existence
https://proofwiki.org/wiki/De_Morgan's_Laws_(Predicate_Logic)/Assertion_of_Existence
[ "Universal Quantifier", "Existential Quantifier", "De Morgan's Laws (Logic)" ]
[]
[ "De Morgan's Laws (Predicate Logic)/Denial of Existence" ]
proofwiki-8180
Conjunction in terms of NAND
:$p \land q \dashv \vdash \paren {p \uparrow q} \uparrow \paren {p \uparrow q}$ where $\land$ denotes logical conjunction and $\uparrow$ denotes logical NAND.
{{begin-eqn}} {{eqn | l = p \land q | o = \dashv \vdash | r = \neg \neg \paren {p \land q} | c = Double Negation }} {{eqn | o = \dashv \vdash | r = \neg \paren {p \uparrow q} | c = {{Defof|Logical NAND}} }} {{eqn | o = \dashv \vdash | r = \paren {p \uparrow q} \uparrow \paren {p \upa...
:$p \land q \dashv \vdash \paren {p \uparrow q} \uparrow \paren {p \uparrow q}$ where $\land$ denotes [[Definition:Conjunction|logical conjunction]] and $\uparrow$ denotes [[Definition:Logical NAND|logical NAND]].
{{begin-eqn}} {{eqn | l = p \land q | o = \dashv \vdash | r = \neg \neg \paren {p \land q} | c = [[Double Negation]] }} {{eqn | o = \dashv \vdash | r = \neg \paren {p \uparrow q} | c = {{Defof|Logical NAND}} }} {{eqn | o = \dashv \vdash | r = \paren {p \uparrow q} \uparrow \paren {p ...
Conjunction in terms of NAND
https://proofwiki.org/wiki/Conjunction_in_terms_of_NAND
https://proofwiki.org/wiki/Conjunction_in_terms_of_NAND
[ "Logical NAND", "Conjunction" ]
[ "Definition:Conjunction", "Definition:Logical NAND" ]
[ "Double Negation", "NAND with Equal Arguments" ]
proofwiki-8181
Disjunction in terms of NOR
:$p \lor q \dashv \vdash \paren {p \downarrow q} \downarrow \paren {p \downarrow q}$ where $\lor$ denotes logical disjunction and $\downarrow$ denotes logical NOR.
{{begin-eqn}} {{eqn | l = p \lor q | o = \dashv \vdash | r = \neg \neg \paren {p \lor q} | c = Double Negation }} {{eqn | o = \dashv \vdash | r = \neg \paren {p \downarrow q} | c = {{Defof|Logical NOR}} }} {{eqn | o = \dashv \vdash | r = \paren {p \downarrow q} \downarrow \paren {p \...
:$p \lor q \dashv \vdash \paren {p \downarrow q} \downarrow \paren {p \downarrow q}$ where $\lor$ denotes [[Definition:Disjunction|logical disjunction]] and $\downarrow$ denotes [[Definition:Logical NOR|logical NOR]].
{{begin-eqn}} {{eqn | l = p \lor q | o = \dashv \vdash | r = \neg \neg \paren {p \lor q} | c = [[Double Negation]] }} {{eqn | o = \dashv \vdash | r = \neg \paren {p \downarrow q} | c = {{Defof|Logical NOR}} }} {{eqn | o = \dashv \vdash | r = \paren {p \downarrow q} \downarrow \paren ...
Disjunction in terms of NOR
https://proofwiki.org/wiki/Disjunction_in_terms_of_NOR
https://proofwiki.org/wiki/Disjunction_in_terms_of_NOR
[ "Logical NOR", "Disjunction" ]
[ "Definition:Disjunction", "Definition:Logical NOR" ]
[ "Double Negation", "NOR with Equal Arguments", "Category:Logical NOR", "Category:Disjunction" ]
proofwiki-8182
Disjunction in terms of NAND
:$p \lor q \dashv \vdash \paren {p \uparrow p} \uparrow \paren {q \uparrow q}$ where $\lor$ denotes logical disjunction and $\uparrow$ denotes logical NAND.
{{begin-eqn}} {{eqn | l = p \lor q | o = \dashv \vdash | r = \neg \paren {\neg p \land \neg q} | c = De Morgan's Laws (Logic): Disjunction }} {{eqn | o = \dashv \vdash | r = \neg p \uparrow \neg q | c = {{Defof|Logical NAND}} }} {{eqn | o = \dashv \vdash | r = \paren {p \uparrow p} \...
:$p \lor q \dashv \vdash \paren {p \uparrow p} \uparrow \paren {q \uparrow q}$ where $\lor$ denotes [[Definition:Disjunction|logical disjunction]] and $\uparrow$ denotes [[Definition:Logical NAND|logical NAND]].
{{begin-eqn}} {{eqn | l = p \lor q | o = \dashv \vdash | r = \neg \paren {\neg p \land \neg q} | c = [[De Morgan's Laws (Logic)/Disjunction|De Morgan's Laws (Logic): Disjunction]] }} {{eqn | o = \dashv \vdash | r = \neg p \uparrow \neg q | c = {{Defof|Logical NAND}} }} {{eqn | o = \dashv \...
Disjunction in terms of NAND
https://proofwiki.org/wiki/Disjunction_in_terms_of_NAND
https://proofwiki.org/wiki/Disjunction_in_terms_of_NAND
[ "Logical NAND", "Disjunction" ]
[ "Definition:Disjunction", "Definition:Logical NAND" ]
[ "De Morgan's Laws (Logic)/Disjunction", "NAND with Equal Arguments" ]
proofwiki-8183
Conditional in terms of NAND
:$p \implies q \dashv \vdash p \uparrow \paren {q \uparrow q}$
{{begin-eqn}} {{eqn | l = p \implies q | o = \dashv \vdash | r = \neg \paren {p \land \neg q} | c = Conditional is Equivalent to Negation of Conjunction with Negative }} {{eqn | o = \dashv \vdash | r = p \uparrow \neg q | c = {{Defof|Logical NAND}} }} {{eqn | o = \dashv \vdash | r = ...
:$p \implies q \dashv \vdash p \uparrow \paren {q \uparrow q}$
{{begin-eqn}} {{eqn | l = p \implies q | o = \dashv \vdash | r = \neg \paren {p \land \neg q} | c = [[Conditional is Equivalent to Negation of Conjunction with Negative]] }} {{eqn | o = \dashv \vdash | r = p \uparrow \neg q | c = {{Defof|Logical NAND}} }} {{eqn | o = \dashv \vdash | ...
Conditional in terms of NAND/Proof 1
https://proofwiki.org/wiki/Conditional_in_terms_of_NAND
https://proofwiki.org/wiki/Conditional_in_terms_of_NAND/Proof_1
[ "Conditional in terms of NAND", "Logical NAND", "Conditional" ]
[]
[ "Conditional is Equivalent to Negation of Conjunction with Negative", "NAND with Equal Arguments" ]
proofwiki-8184
Conditional in terms of NAND
:$p \implies q \dashv \vdash p \uparrow \paren {q \uparrow q}$
{{begin-eqn}} {{eqn | l = p \implies q | o = \dashv \vdash | r = \neg p \lor q | c = Rule of Material Implication }} {{eqn | o = \dashv \vdash | r = \neg p \lor \neg \neg q | c = Double Negation Introduction }} {{eqn | o = \dashv \vdash | r = p \uparrow \neg q | c = NAND as Dis...
:$p \implies q \dashv \vdash p \uparrow \paren {q \uparrow q}$
{{begin-eqn}} {{eqn | l = p \implies q | o = \dashv \vdash | r = \neg p \lor q | c = [[Rule of Material Implication]] }} {{eqn | o = \dashv \vdash | r = \neg p \lor \neg \neg q | c = [[Double Negation Introduction]] }} {{eqn | o = \dashv \vdash | r = p \uparrow \neg q | c = [[N...
Conditional in terms of NAND/Proof 2
https://proofwiki.org/wiki/Conditional_in_terms_of_NAND
https://proofwiki.org/wiki/Conditional_in_terms_of_NAND/Proof_2
[ "Conditional in terms of NAND", "Logical NAND", "Conditional" ]
[]
[ "Rule of Material Implication", "Double Negation/Double Negation Introduction", "NAND as Disjunction of Negations", "NAND with Equal Arguments" ]
proofwiki-8185
Biconditional in terms of NAND
:$p \iff q \dashv \vdash \paren {\paren {p \uparrow p} \uparrow \paren {q \uparrow q} } \uparrow \paren {p \uparrow q}$ where $\iff$ denotes logical biconditional and $\uparrow$ denotes logical NAND.
{{begin-eqn}} {{eqn | l = p \iff q | o = \dashv \vdash | r = \neg \paren {p \oplus q} | c = Exclusive Or is Negation of Biconditional }} {{eqn | o = \dashv \vdash | r = \neg \paren {\paren {p \lor q} \land \neg \paren {p \land q} } | c = {{Defof|Exclusive Or}} }} {{eqn | o = \dashv \vdash ...
:$p \iff q \dashv \vdash \paren {\paren {p \uparrow p} \uparrow \paren {q \uparrow q} } \uparrow \paren {p \uparrow q}$ where $\iff$ denotes [[Definition:Biconditional|logical biconditional]] and $\uparrow$ denotes [[Definition:Logical NAND|logical NAND]].
{{begin-eqn}} {{eqn | l = p \iff q | o = \dashv \vdash | r = \neg \paren {p \oplus q} | c = [[Exclusive Or is Negation of Biconditional]] }} {{eqn | o = \dashv \vdash | r = \neg \paren {\paren {p \lor q} \land \neg \paren {p \land q} } | c = {{Defof|Exclusive Or}} }} {{eqn | o = \dashv \vd...
Biconditional in terms of NAND
https://proofwiki.org/wiki/Biconditional_in_terms_of_NAND
https://proofwiki.org/wiki/Biconditional_in_terms_of_NAND
[ "Logical NAND", "Biconditional" ]
[ "Definition:Biconditional", "Definition:Logical NAND" ]
[ "Exclusive Or is Negation of Biconditional", "Disjunction in terms of NAND" ]
proofwiki-8186
Mapping is Injection and Surjection iff Inverse is Mapping
Let $f: S \to T$ be a mapping. Then: : $f: S \to T$ can be defined as a bijection in the sense that: ::$(1): \quad f$ is an injection ::$(2): \quad f$ is a surjection {{iff}}: :the inverse $f^{-1}$ of $f$ is itself a mapping.
=== Necessary Condition === {{:Inverse of Injective and Surjective Mapping is Mapping}}
Let $f: S \to T$ be a [[Definition:Mapping|mapping]]. Then: : $f: S \to T$ can be defined as a [[Definition:Bijection/Definition 1|bijection]] in the sense that: ::$(1): \quad f$ is an [[Definition:Injection|injection]] ::$(2): \quad f$ is a [[Definition:Surjection|surjection]] {{iff}}: :the [[Definition:Inverse of ...
=== [[Inverse of Injective and Surjective Mapping is Mapping|Necessary Condition]] === {{:Inverse of Injective and Surjective Mapping is Mapping}}
Mapping is Injection and Surjection iff Inverse is Mapping
https://proofwiki.org/wiki/Mapping_is_Injection_and_Surjection_iff_Inverse_is_Mapping
https://proofwiki.org/wiki/Mapping_is_Injection_and_Surjection_iff_Inverse_is_Mapping
[ "Mapping is Injection and Surjection iff Inverse is Mapping", "Equivalence of Definitions of Bijection", "Injections", "Surjections", "Inverse Mappings" ]
[ "Definition:Mapping", "Definition:Bijection/Definition 1", "Definition:Injection", "Definition:Surjection", "Definition:Inverse of Mapping", "Definition:Mapping" ]
[ "Inverse of Injective and Surjective Mapping is Mapping" ]
proofwiki-8187
Mapping is Injection and Surjection iff Inverse is Mapping
Let $f: S \to T$ be a mapping. Then: : $f: S \to T$ can be defined as a bijection in the sense that: ::$(1): \quad f$ is an injection ::$(2): \quad f$ is a surjection {{iff}}: :the inverse $f^{-1}$ of $f$ is itself a mapping.
=== Necessary Condition === {{:Inverse of Injective and Surjective Mapping is Mapping/Proof 2}}{{qed|lemma}} === Sufficient Condition === Let $f^{-1}: T \to S$ be a mapping. By Inverse Mapping is Bijection, both $f$ and $f^{-1}$ are bijections. Hence, in particular, $f$ is a bijection. {{qed}}
Let $f: S \to T$ be a [[Definition:Mapping|mapping]]. Then: : $f: S \to T$ can be defined as a [[Definition:Bijection/Definition 1|bijection]] in the sense that: ::$(1): \quad f$ is an [[Definition:Injection|injection]] ::$(2): \quad f$ is a [[Definition:Surjection|surjection]] {{iff}}: :the [[Definition:Inverse of ...
=== [[Inverse of Injective and Surjective Mapping is Mapping/Proof 2|Necessary Condition]] === {{:Inverse of Injective and Surjective Mapping is Mapping/Proof 2}}{{qed|lemma}} === Sufficient Condition === Let $f^{-1}: T \to S$ be a [[Definition:Mapping|mapping]]. By [[Inverse Mapping is Bijection]], both $f$ and $f...
Mapping is Injection and Surjection iff Inverse is Mapping/Proof 2
https://proofwiki.org/wiki/Mapping_is_Injection_and_Surjection_iff_Inverse_is_Mapping
https://proofwiki.org/wiki/Mapping_is_Injection_and_Surjection_iff_Inverse_is_Mapping/Proof_2
[ "Mapping is Injection and Surjection iff Inverse is Mapping", "Equivalence of Definitions of Bijection", "Injections", "Surjections", "Inverse Mappings" ]
[ "Definition:Mapping", "Definition:Bijection/Definition 1", "Definition:Injection", "Definition:Surjection", "Definition:Inverse of Mapping", "Definition:Mapping" ]
[ "Inverse of Injective and Surjective Mapping is Mapping/Proof 2", "Definition:Mapping", "Inverse Mapping is Bijection", "Definition:Bijection", "Definition:Bijection" ]
proofwiki-8188
Condition for Composite Mapping to be Identity
Let $S$ and $T$ be sets. Let $f: S \to T$ and $g: T \to S$ be mappings such that: : $g \circ f = I_S$ where $I_S$ is the identity mapping on $S$. Then $f$ is an injection and $g$ is a surjection.
From Identity Mapping is Bijection, $I_S$ is a bijection. From Identity Mapping is Injection, $I_S$ is an injection. From Injection if Composite is Injection it follows that $f$ is an injection. From Identity Mapping is Surjection, $I_S$ is a surjection. From Surjection if Composite is Surjection it follows that $g$ is...
Let $S$ and $T$ be [[Definition:Set|sets]]. Let $f: S \to T$ and $g: T \to S$ be [[Definition:Mapping|mappings]] such that: : $g \circ f = I_S$ where $I_S$ is the [[Definition:Identity Mapping|identity mapping]] on $S$. Then $f$ is an [[Definition:Injection|injection]] and $g$ is a [[Definition:Surjection|surjection...
From [[Identity Mapping is Bijection]], $I_S$ is a [[Definition:Bijection|bijection]]. From [[Identity Mapping is Injection]], $I_S$ is an [[Definition:Injection|injection]]. From [[Injection if Composite is Injection]] it follows that $f$ is an [[Definition:Injection|injection]]. From [[Identity Mapping is Surject...
Condition for Composite Mapping to be Identity
https://proofwiki.org/wiki/Condition_for_Composite_Mapping_to_be_Identity
https://proofwiki.org/wiki/Condition_for_Composite_Mapping_to_be_Identity
[ "Identity Mappings", "Injections", "Surjections" ]
[ "Definition:Set", "Definition:Mapping", "Definition:Identity Mapping", "Definition:Injection", "Definition:Surjection" ]
[ "Identity Mapping is Bijection", "Definition:Bijection", "Identity Mapping is Injection", "Definition:Injection", "Injection if Composite is Injection", "Definition:Injection", "Identity Mapping is Surjection", "Definition:Surjection", "Surjection if Composite is Surjection", "Definition:Surjectio...
proofwiki-8189
Bijection iff exists Mapping which is Left and Right Inverse
Let $S$ and $T$ be sets. Let $f: S \to T$ be a mapping. Then $f$ is a bijection {{iff}}: :there exists a mapping $g: T \to S$ such that: ::$g \circ f = I_S$ ::$f \circ g = I_T$ :where $I_S$ and $I_T$ are the identity mappings on $S$ and $T$ respectively.
=== Necessary Condition === Let $f$ be a bijection. Then for each $y \in T$ there exists one and only one $x \in S$ such that $\map f x = y$. That is, that there exists a mapping $g: T \to S$ with the property that: : $\forall y \in T: \exists x \in S: \map g y = x$ Let $y \in T$. Let $x = g \map g y$. Then: {{begin-eq...
Let $S$ and $T$ be [[Definition:Set|sets]]. Let $f: S \to T$ be a [[Definition:Mapping|mapping]]. Then $f$ is a [[Definition:Bijection|bijection]] {{iff}}: :there exists a [[Definition:Mapping|mapping]] $g: T \to S$ such that: ::$g \circ f = I_S$ ::$f \circ g = I_T$ :where $I_S$ and $I_T$ are the [[Definition:Identi...
=== Necessary Condition === Let $f$ be a [[Definition:Bijection/Definition 4|bijection]]. Then [[Definition:Universal Quantifier|for each]] $y \in T$ there exists [[Definition:Unique|one and only one]] $x \in S$ such that $\map f x = y$. That is, that there exists a [[Definition:Mapping|mapping]] $g: T \to S$ with t...
Bijection iff exists Mapping which is Left and Right Inverse
https://proofwiki.org/wiki/Bijection_iff_exists_Mapping_which_is_Left_and_Right_Inverse
https://proofwiki.org/wiki/Bijection_iff_exists_Mapping_which_is_Left_and_Right_Inverse
[ "Bijections" ]
[ "Definition:Set", "Definition:Mapping", "Definition:Bijection", "Definition:Mapping", "Definition:Identity Mapping" ]
[ "Definition:Bijection/Definition 4", "Definition:Universal Quantifier", "Definition:Unique", "Definition:Mapping" ]
proofwiki-8190
Eigenvalues of G-Representation are Roots of Unity
Let $G$ be a finite group. Let $\left({K, +, \cdot}\right)$ be a field. Let $V$ be a $G$-module over $K$ (i.e. $V$ is a $K \left[{G}\right]$-module). Then $\forall g \in G$, the eigenvalues of the action by the vector $g \in K \left[{G}\right]$ on $V$ are roots of unity.
Fix an arbitrary $g \in G$ and consider the corresponding vector $g \in K \left[{G}\right]$. Let $\lambda$ be an eigenvalue of $g$, that is $\lambda$ is an eigenvalue of the map in $\operatorname{Aut} \left({V}\right): \vec v \mapsto g \vec v$. Then by definition of an eigenvalue we have: :$\exists \vec v_\lambda \in V...
Let $G$ be a [[Definition:Finite Group|finite group]]. Let $\left({K, +, \cdot}\right)$ be a [[Definition:Field (Abstract Algebra)|field]]. Let $V$ be a [[Definition:G-Module|$G$-module]] over $K$ (i.e. $V$ is a $K \left[{G}\right]$-module). Then $\forall g \in G$, the [[Definition:Eigenvalue|eigenvalues]] of the a...
Fix an arbitrary $g \in G$ and consider the corresponding vector $g \in K \left[{G}\right]$. Let $\lambda$ be an eigenvalue of $g$, that is $\lambda$ is an eigenvalue of the map in $\operatorname{Aut} \left({V}\right): \vec v \mapsto g \vec v$. Then by definition of an eigenvalue we have: :$\exists \vec v_\lambda \i...
Eigenvalues of G-Representation are Roots of Unity
https://proofwiki.org/wiki/Eigenvalues_of_G-Representation_are_Roots_of_Unity
https://proofwiki.org/wiki/Eigenvalues_of_G-Representation_are_Roots_of_Unity
[]
[ "Definition:Finite Group", "Definition:Field (Abstract Algebra)", "Definition:Module over Group", "Definition:Eigenvalue", "Definition:Root of Unity" ]
[ "Definition:Linear Group Action", "Definition:Linear Group Action" ]
proofwiki-8191
Character of Representations over C are Algebraic Integers
Let $G$ be a finite group. Let $\chi$ be the character of any $\C \sqbrk G$-module $\struct {V, \rho}$. Then for all $g \in G$, it follows that $\map \chi g$ is an algebraic integer.
By the definition of character: :$\map \chi g = \map \tr {\rho_g}$ where $\map \tr {\rho_g}$ is the trace of $\rho_g$. {{explain|$\rho_g$}} where: :$\rho \in \map \hom {\C \sqbrk G, \Aut V}: \vec {e_g} \mapsto \rho_g$ by definition. {{explain|The above definition is not stated in that form on {{ProofWiki}}. Link to $\m...
Let $G$ be a [[Definition:Finite Group|finite group]]. Let $\chi$ be the [[Definition:Character (Representation Theory)|character]] of any [[Definition:G-Module|$\C \sqbrk G$-module]] $\struct {V, \rho}$. Then for all $g \in G$, it follows that $\map \chi g$ is an [[Definition:Algebraic Integer|algebraic integer]].
By the definition of [[Definition:Character (Representation Theory)|character]]: :$\map \chi g = \map \tr {\rho_g}$ where $\map \tr {\rho_g}$ is the [[Definition:Trace (Linear Algebra)|trace]] of $\rho_g$. {{explain|$\rho_g$}} where: :$\rho \in \map \hom {\C \sqbrk G, \Aut V}: \vec {e_g} \mapsto \rho_g$ by definition...
Character of Representations over C are Algebraic Integers
https://proofwiki.org/wiki/Character_of_Representations_over_C_are_Algebraic_Integers
https://proofwiki.org/wiki/Character_of_Representations_over_C_are_Algebraic_Integers
[ "Module Theory", "Group Theory", "Complex Analysis" ]
[ "Definition:Finite Group", "Definition:Character (Representation Theory)", "Definition:Module over Group", "Definition:Algebraic Integer" ]
[ "Definition:Character (Representation Theory)", "Definition:Trace (Linear Algebra)", "Definition:Order of Group Element", "Definition:Trace (Linear Algebra)", "Definition:Eigenvalue", "Eigenvalues of G-Representation are Roots of Unity", "Definition:Eigenvalue", "Definition:Root of Unity/Complex", "...
proofwiki-8192
Injection from Finite Set to Itself is Surjection
Let $S$ be a finite set. Let $f: S \to S$ be an injection. Then $f$ is also a surjection.
Let $a \in S$. We need to show that there exists $b \in S$ such that $a = \map f b$. Consider what happens when $f$ is applied repeatedly on $S$. Let $f^2$ denote $f \circ f$ and, generally, $f^n := f \circ f^{n-1}$. Consider the sequence of elements of $S$: :$a, \map f a, \map {f^2} a, \ldots$ Because $S$ is a finite ...
Let $S$ be a [[Definition:Finite Set|finite set]]. Let $f: S \to S$ be an [[Definition:Injection|injection]]. Then $f$ is also a [[Definition:Surjection|surjection]].
Let $a \in S$. We need to show that there exists $b \in S$ such that $a = \map f b$. Consider what happens when $f$ is applied repeatedly on $S$. Let $f^2$ denote $f \circ f$ and, generally, $f^n := f \circ f^{n-1}$. Consider the [[Definition:Sequence|sequence]] of [[Definition:Element|elements]] of $S$: :$a, \map...
Injection from Finite Set to Itself is Surjection
https://proofwiki.org/wiki/Injection_from_Finite_Set_to_Itself_is_Surjection
https://proofwiki.org/wiki/Injection_from_Finite_Set_to_Itself_is_Surjection
[ "Injections", "Surjections", "Finite Sets" ]
[ "Definition:Finite Set", "Definition:Injection", "Definition:Surjection" ]
[ "Definition:Sequence", "Definition:Element", "Definition:Finite Set", "Definition:Injection", "Composite of Injections is Injection", "Definition:Injection", "Injection iff Left Cancellable", "Definition:Left Cancellable Mapping" ]
proofwiki-8193
Codomain of Bijection is Domain of Inverse
Let $S$ and $T$ be sets. Let $f: S \to T$ be a bijection. Let $f^{-1}: T \to S$ be the inverse of $f$. Then the domain of $f^{-1}$ equals the codomain of $f$.
Follows directly from the definition of domain and codomain: :$\Dom f = S$ and $\Cdm f = T$ :$\Dom {f^{-1} } = T$ and $\Cdm {f^{-1} } = S$ That is: :$\Dom {f^{-1} } = T = \Cdm f$ {{qed}}
Let $S$ and $T$ be [[Definition:Set|sets]]. Let $f: S \to T$ be a [[Definition:Bijection|bijection]]. Let $f^{-1}: T \to S$ be the [[Definition:Inverse Mapping|inverse]] of $f$. Then the [[Definition:Domain of Mapping|domain]] of $f^{-1}$ equals the [[Definition:Codomain of Mapping|codomain]] of $f$.
Follows directly from the definition of [[Definition:Domain of Mapping|domain]] and [[Definition:Codomain of Mapping|codomain]]: :$\Dom f = S$ and $\Cdm f = T$ :$\Dom {f^{-1} } = T$ and $\Cdm {f^{-1} } = S$ That is: :$\Dom {f^{-1} } = T = \Cdm f$ {{qed}}
Codomain of Bijection is Domain of Inverse
https://proofwiki.org/wiki/Codomain_of_Bijection_is_Domain_of_Inverse
https://proofwiki.org/wiki/Codomain_of_Bijection_is_Domain_of_Inverse
[ "Bijections" ]
[ "Definition:Set", "Definition:Bijection", "Definition:Inverse Mapping", "Definition:Domain (Set Theory)/Mapping", "Definition:Codomain (Set Theory)/Mapping" ]
[ "Definition:Domain (Set Theory)/Mapping", "Definition:Codomain (Set Theory)/Mapping" ]
proofwiki-8194
Domain of Bijection is Codomain of Inverse
Let $S$ and $T$ be sets. Let $f: S \to T$ be a bijection. Let $f^{-1}: T \to S$ be the inverse of $f$. Then the codomain of $f^{-1}$ equals the domain of $f$.
Follows directly from the definition of domain and codomain: :$\Dom f = S$ and $\Cdm f = T$ :$\Dom {f^{-1} } = T$ and $\Cdm {f^{-1} } = S$ That is: :$\Cdm {f^{-1} } = S = \Dom f$ {{qed}}
Let $S$ and $T$ be [[Definition:Set|sets]]. Let $f: S \to T$ be a [[Definition:Bijection|bijection]]. Let $f^{-1}: T \to S$ be the [[Definition:Inverse Mapping|inverse]] of $f$. Then the [[Definition:Codomain of Mapping|codomain]] of $f^{-1}$ equals the [[Definition:Domain of Mapping|domain]] of $f$.
Follows directly from the definition of [[Definition:Domain of Mapping|domain]] and [[Definition:Codomain of Mapping|codomain]]: :$\Dom f = S$ and $\Cdm f = T$ :$\Dom {f^{-1} } = T$ and $\Cdm {f^{-1} } = S$ That is: :$\Cdm {f^{-1} } = S = \Dom f$ {{qed}}
Domain of Bijection is Codomain of Inverse
https://proofwiki.org/wiki/Domain_of_Bijection_is_Codomain_of_Inverse
https://proofwiki.org/wiki/Domain_of_Bijection_is_Codomain_of_Inverse
[ "Bijections" ]
[ "Definition:Set", "Definition:Bijection", "Definition:Inverse Mapping", "Definition:Codomain (Set Theory)/Mapping", "Definition:Domain (Set Theory)/Mapping" ]
[ "Definition:Domain (Set Theory)/Mapping", "Definition:Codomain (Set Theory)/Mapping" ]
proofwiki-8195
Conditions for Uniqueness of Left Inverse Mapping
Let $S$ and $T$ be sets such that $S \ne \O$. Let $f: S \to T$ be an injection. Then a left inverse mapping of $f$ is in general not unique. Uniqueness occurs under either of two circumstances: :$(1): \quad S$ is a singleton :$(2): \quad f$ is a bijection.
If $f$ is a bijection, then by definition $f$ is also a surjection. Then: :$T \setminus \Img f = \O$ :and we have that $g = f^{-1}$. As $f^{-1}$ is uniquely defined $g$ is itself unique. {{qed|lemma}} If $S$ is a singleton then there can only be one mapping $g: T \to S$: :$\forall t \in T: \map g t = s$ {{qed|lemma}} I...
Let $S$ and $T$ be [[Definition:Set|sets]] such that $S \ne \O$. Let $f: S \to T$ be an [[Definition:Injection|injection]]. Then a [[Definition:Left Inverse Mapping|left inverse mapping]] of $f$ is in general not [[Definition:Unique|unique]]. [[Definition:Unique|Uniqueness]] occurs under either of two circumstance...
If $f$ is a [[Definition:Bijection|bijection]], then by definition $f$ is also a [[Definition:Surjection|surjection]]. Then: :$T \setminus \Img f = \O$ :and we have that $g = f^{-1}$. As $f^{-1}$ is uniquely defined $g$ is itself unique. {{qed|lemma}} If $S$ is a [[Definition:Singleton|singleton]] then there can on...
Conditions for Uniqueness of Left Inverse Mapping
https://proofwiki.org/wiki/Conditions_for_Uniqueness_of_Left_Inverse_Mapping
https://proofwiki.org/wiki/Conditions_for_Uniqueness_of_Left_Inverse_Mapping
[ "Left Inverse Mappings", "Conditions for Uniqueness of Left Inverse Mapping" ]
[ "Definition:Set", "Definition:Injection", "Definition:Left Inverse Mapping", "Definition:Unique", "Definition:Unique", "Definition:Singleton", "Definition:Bijection" ]
[ "Definition:Bijection", "Definition:Surjection", "Definition:Singleton", "Definition:Mapping", "Definition:Bijection", "Definition:Injection", "Definition:Surjection", "Definition:Singleton", "Definition:Unique" ]
proofwiki-8196
Surjection iff Right Inverse/Non-Uniqueness
A right inverse of $f$ is in general not unique. Uniqueness occurs {{iff}} $f$ is a bijection.
If $f$ is not an injection then: :$\exists y \in T: \exists x_1, x_2 \in S: \map f {x_1} = y = \map f {x_2}$ Hence we have more than one choice in $\map {f^{-1} } {\set y}$ for how to map $\map g y$. That is, $\map g y$ is not unique. This does not happen {{iff}} $f$ is an injection. Hence the result. {{qed}}
A [[Definition:Right Inverse Mapping|right inverse]] of $f$ is in general not [[Definition:Unique|unique]]. Uniqueness occurs {{iff}} $f$ is a [[Definition:Bijection|bijection]].
If $f$ is not an [[Definition:Injection|injection]] then: :$\exists y \in T: \exists x_1, x_2 \in S: \map f {x_1} = y = \map f {x_2}$ Hence we have more than one choice in $\map {f^{-1} } {\set y}$ for how to map $\map g y$. That is, $\map g y$ is not [[Definition:Unique|unique]]. This does not happen {{iff}} $f$ i...
Surjection iff Right Inverse/Non-Uniqueness
https://proofwiki.org/wiki/Surjection_iff_Right_Inverse/Non-Uniqueness
https://proofwiki.org/wiki/Surjection_iff_Right_Inverse/Non-Uniqueness
[ "Surjection iff Right Inverse" ]
[ "Definition:Right Inverse Mapping", "Definition:Unique", "Definition:Bijection" ]
[ "Definition:Injection", "Definition:Unique", "Definition:Injection" ]
proofwiki-8197
Mapping reflects Preordering
Let $S$ and $T$ be sets. Let $f: S \to T$ be a mapping. Let ${\precsim} \subseteq T \times T$ be a preordering on $T$. Let $\RR$ be the relation defined on $S$ by the rule: :$x \mathrel \RR y \iff \map f x \precsim \map f y$ Then $\RR$ is a preordering on $S$.
=== Reflexivity === {{begin-eqn}} {{eqn | l = x | o = \in | r = S | c = }} {{eqn | ll= \leadsto | l = \map f x | o = \in | r = T | c = Definition of $f$ }} {{eqn | ll= \leadsto | l = \map f x | o = \precsim | r = \map f x | c = as $\precsim$ is a preord...
Let $S$ and $T$ be [[Definition:Set|sets]]. Let $f: S \to T$ be a [[Definition:Mapping|mapping]]. Let ${\precsim} \subseteq T \times T$ be a [[Definition:Preordering|preordering]] on $T$. Let $\RR$ be the [[Definition:Relation|relation]] defined on $S$ by the rule: :$x \mathrel \RR y \iff \map f x \precsim \map f y...
=== Reflexivity === {{begin-eqn}} {{eqn | l = x | o = \in | r = S | c = }} {{eqn | ll= \leadsto | l = \map f x | o = \in | r = T | c = Definition of $f$ }} {{eqn | ll= \leadsto | l = \map f x | o = \precsim | r = \map f x | c = as $\precsim$ is a [[Def...
Mapping reflects Preordering
https://proofwiki.org/wiki/Mapping_reflects_Preordering
https://proofwiki.org/wiki/Mapping_reflects_Preordering
[ "Preorder Theory", "Mapping Theory" ]
[ "Definition:Set", "Definition:Mapping", "Definition:Preordering", "Definition:Relation", "Definition:Preordering" ]
[ "Definition:Preordering", "Definition:Reflexive Relation", "Definition:Preordering", "Definition:Preordering" ]
proofwiki-8198
Bernoulli's Inequality
Let $x \in \R$ be a real number such that $x > -1$. Let $n \in \Z_{\ge 0}$ be a positive integer. Then: :$\paren {1 + x}^n \ge 1 + n x$
Let $0 < x < 1$. Let $y = -x$. Then $y > -1$ and by Bernoulli's Inequality: :$\paren {1 + y}^n \ge 1 + n y$ Thus: :$\paren {1 + \paren {-x} }^n \ge 1 + n \paren {-x}$ Hence the result. {{qed}}
Let $x \in \R$ be a [[Definition:Real Number|real number]] such that $x > -1$. Let $n \in \Z_{\ge 0}$ be a [[Definition:Positive Integer|positive integer]]. Then: :$\paren {1 + x}^n \ge 1 + n x$
Let $0 < x < 1$. Let $y = -x$. Then $y > -1$ and by [[Bernoulli's Inequality]]: :$\paren {1 + y}^n \ge 1 + n y$ Thus: :$\paren {1 + \paren {-x} }^n \ge 1 + n \paren {-x}$ Hence the result. {{qed}}
Bernoulli's Inequality/Corollary/Proof 1
https://proofwiki.org/wiki/Bernoulli's_Inequality
https://proofwiki.org/wiki/Bernoulli's_Inequality/Corollary/Proof_1
[ "Bernoulli's Inequality", "Inequalities", "Real Analysis" ]
[ "Definition:Real Number", "Definition:Positive/Integer" ]
[ "Bernoulli's Inequality" ]
proofwiki-8199
Bernoulli's Inequality
Let $x \in \R$ be a real number such that $x > -1$. Let $n \in \Z_{\ge 0}$ be a positive integer. Then: :$\paren {1 + x}^n \ge 1 + n x$
Proof by induction: Let $0 < x < 1$. For all $n \in \Z_{\ge 0}$, let $\map P n$ be the proposition: :$\paren {1 - x}^n \ge 1 - n x$ === Basis for the Induction === $\map P 0$ is the case: :$\paren {1 - x}^0 = 1 \ge 1 - 0 x = 1$ so $\map P 0$ holds. This is our basis for the induction. === Induction Hypothesis === Now ...
Let $x \in \R$ be a [[Definition:Real Number|real number]] such that $x > -1$. Let $n \in \Z_{\ge 0}$ be a [[Definition:Positive Integer|positive integer]]. Then: :$\paren {1 + x}^n \ge 1 + n x$
Proof by [[Principle of Mathematical Induction|induction]]: Let $0 < x < 1$. For all $n \in \Z_{\ge 0}$, let $\map P n$ be the [[Definition:Proposition|proposition]]: :$\paren {1 - x}^n \ge 1 - n x$ === Basis for the Induction === $\map P 0$ is the case: :$\paren {1 - x}^0 = 1 \ge 1 - 0 x = 1$ so $\map P 0$ holds...
Bernoulli's Inequality/Corollary/Proof 2
https://proofwiki.org/wiki/Bernoulli's_Inequality
https://proofwiki.org/wiki/Bernoulli's_Inequality/Corollary/Proof_2
[ "Bernoulli's Inequality", "Inequalities", "Real Analysis" ]
[ "Definition:Real Number", "Definition:Positive/Integer" ]
[ "Principle of Mathematical Induction", "Definition:Proposition", "Principle of Mathematical Induction", "Principle of Mathematical Induction", "Principle of Mathematical Induction", "Bernoulli's Inequality/Corollary/Proof 2", "Principle of Mathematical Induction" ]