question_id int64 1 75.7k | db_id stringclasses 33
values | db_name stringclasses 4
values | question stringlengths 19 259 | partition stringclasses 4
values | difficulty stringclasses 3
values | SQL stringlengths 25 862 |
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1,101 | customers_card_transactions | spider | How many customers do we have? | train | easy | SELECT COUNT(*) FROM customers |
1,102 | customers_card_transactions | spider | Count the number of customers. | train | easy | SELECT COUNT(*) FROM customers |
1,103 | customers_card_transactions | spider | Show ids, first names, last names, and phones for all customers. | train | easy | SELECT customer_id, customer_first_name, customer_last_name, customer_phone FROM customers |
1,104 | customers_card_transactions | spider | What are the ids, full names, and phones of each customer? | train | easy | SELECT customer_id, customer_first_name, customer_last_name, customer_phone FROM customers |
1,105 | customers_card_transactions | spider | What is the phone and email for customer with first name Aniyah and last name Feest? | train | medium | SELECT customer_phone, customer_email FROM customers WHERE customer_first_name = 'aniyah' AND customer_last_name = 'feest' |
1,106 | customers_card_transactions | spider | Return the phone and email of the customer with the first name Aniyah and last name Feest. | train | medium | SELECT customer_phone, customer_email FROM customers WHERE customer_first_name = 'aniyah' AND customer_last_name = 'feest' |
1,107 | customers_card_transactions | spider | Show the number of customer cards. | train | easy | SELECT COUNT(*) FROM customers_cards |
1,108 | customers_card_transactions | spider | How many customer cards are there? | train | easy | SELECT COUNT(*) FROM customers_cards |
1,109 | customers_card_transactions | spider | Show ids, customer ids, card type codes, card numbers for all cards. | train | easy | SELECT card_id, customer_id, card_type_code, card_number FROM customers_cards |
1,110 | customers_card_transactions | spider | What are card ids, customer ids, card types, and card numbers for each customer card? | train | easy | SELECT card_id, customer_id, card_type_code, card_number FROM customers_cards |
1,111 | customers_card_transactions | spider | Show the date valid from and the date valid to for the card with card number '4560596484842'. | train | easy | SELECT date_valid_from, date_valid_to FROM customers_cards WHERE card_number = '4560596484842' |
1,112 | customers_card_transactions | spider | What are the valid from and valid to dates for the card with the number 4560596484842? | train | easy | SELECT date_valid_from, date_valid_to FROM customers_cards WHERE card_number = '4560596484842' |
1,113 | customers_card_transactions | spider | What is the first name, last name, and phone of the customer with card 4560596484842. | train | hard | SELECT t2.customer_first_name, t2.customer_last_name, t2.customer_phone FROM customers_cards AS t1 JOIN customers AS t2 ON t1.customer_id = t2.customer_id WHERE t1.card_number = '4560596484842' |
1,114 | customers_card_transactions | spider | Return the full name and phone of the customer who has card number 4560596484842. | train | hard | SELECT t2.customer_first_name, t2.customer_last_name, t2.customer_phone FROM customers_cards AS t1 JOIN customers AS t2 ON t1.customer_id = t2.customer_id WHERE t1.card_number = '4560596484842' |
1,115 | customers_card_transactions | spider | How many cards does customer Art Turcotte have? | train | hard | SELECT COUNT(*) FROM customers_cards AS t1 JOIN customers AS t2 ON t1.customer_id = t2.customer_id WHERE t2.customer_first_name = 'art' AND t2.customer_last_name = 'turcotte' |
1,116 | customers_card_transactions | spider | Count the number of cards the customer with the first name Art and last name Turcotte has. | train | hard | SELECT COUNT(*) FROM customers_cards AS t1 JOIN customers AS t2 ON t1.customer_id = t2.customer_id WHERE t2.customer_first_name = 'art' AND t2.customer_last_name = 'turcotte' |
1,117 | customers_card_transactions | spider | How many debit cards do we have? | train | easy | SELECT COUNT(*) FROM customers_cards WHERE card_type_code = 'debit' |
1,118 | customers_card_transactions | spider | Count the number of customer cards of the type Debit. | train | easy | SELECT COUNT(*) FROM customers_cards WHERE card_type_code = 'debit' |
1,119 | customers_card_transactions | spider | How many credit cards does customer Blanche Huels have? | train | hard | SELECT COUNT(*) FROM customers_cards AS t1 JOIN customers AS t2 ON t1.customer_id = t2.customer_id WHERE t2.customer_first_name = 'blanche' AND t2.customer_last_name = 'huels' AND t1.card_type_code = 'credit' |
1,120 | customers_card_transactions | spider | Count the number of credit cards that the customer with first name Blanche and last name Huels has. | train | hard | SELECT COUNT(*) FROM customers_cards AS t1 JOIN customers AS t2 ON t1.customer_id = t2.customer_id WHERE t2.customer_first_name = 'blanche' AND t2.customer_last_name = 'huels' AND t1.card_type_code = 'credit' |
1,121 | customers_card_transactions | spider | Show all customer ids and the number of cards owned by each customer. | train | hard | SELECT customer_id, COUNT(*) FROM customers_cards GROUP BY customer_id |
1,122 | customers_card_transactions | spider | What are the different customer ids, and how many cards does each one hold? | train | hard | SELECT customer_id, COUNT(*) FROM customers_cards GROUP BY customer_id |
1,123 | customers_card_transactions | spider | What is the customer id with most number of cards, and how many does he have? | train | hard | SELECT customer_id, COUNT(*) FROM customers_cards GROUP BY customer_id ORDER BY COUNT(*) DESC LIMIT 1 |
1,124 | customers_card_transactions | spider | Return the id of the customer who has the most cards, as well as the number of cards. | train | hard | SELECT customer_id, COUNT(*) FROM customers_cards GROUP BY customer_id ORDER BY COUNT(*) DESC LIMIT 1 |
1,125 | customers_card_transactions | spider | Show id, first and last names for all customers with at least two cards. | train | hard | SELECT t1.customer_id, t2.customer_first_name, t2.customer_last_name FROM customers_cards AS t1 JOIN customers AS t2 ON t1.customer_id = t2.customer_id GROUP BY t1.customer_id HAVING COUNT(*) >= 2 |
1,126 | customers_card_transactions | spider | What are the ids and full names of customers who hold two or more cards? | train | hard | SELECT t1.customer_id, t2.customer_first_name, t2.customer_last_name FROM customers_cards AS t1 JOIN customers AS t2 ON t1.customer_id = t2.customer_id GROUP BY t1.customer_id HAVING COUNT(*) >= 2 |
1,127 | customers_card_transactions | spider | What is the customer id, first and last name with least number of accounts. | train | hard | SELECT t1.customer_id, t2.customer_first_name, t2.customer_last_name FROM customers_cards AS t1 JOIN customers AS t2 ON t1.customer_id = t2.customer_id GROUP BY t1.customer_id ORDER BY COUNT(*) ASC LIMIT 1 |
1,128 | customers_card_transactions | spider | Return the id and full name of the customer who has the fewest accounts. | train | hard | SELECT t1.customer_id, t2.customer_first_name, t2.customer_last_name FROM customers_cards AS t1 JOIN customers AS t2 ON t1.customer_id = t2.customer_id GROUP BY t1.customer_id ORDER BY COUNT(*) ASC LIMIT 1 |
1,129 | customers_card_transactions | spider | Show all card type codes and the number of cards in each type. | train | hard | SELECT card_type_code, COUNT(*) FROM customers_cards GROUP BY card_type_code |
1,130 | customers_card_transactions | spider | What are the different card types, and how many cards are there of each? | train | hard | SELECT card_type_code, COUNT(*) FROM customers_cards GROUP BY card_type_code |
1,131 | customers_card_transactions | spider | What is the card type code with most number of cards? | train | hard | SELECT card_type_code FROM customers_cards GROUP BY card_type_code ORDER BY COUNT(*) DESC LIMIT 1 |
1,132 | customers_card_transactions | spider | Return the code of the card type that is most common. | train | hard | SELECT card_type_code FROM customers_cards GROUP BY card_type_code ORDER BY COUNT(*) DESC LIMIT 1 |
1,133 | customers_card_transactions | spider | Show card type codes with at least 5 cards. | train | hard | SELECT card_type_code FROM customers_cards GROUP BY card_type_code HAVING COUNT(*) >= 5 |
1,134 | customers_card_transactions | spider | What are the codes of card types that have 5 or more cards? | train | hard | SELECT card_type_code FROM customers_cards GROUP BY card_type_code HAVING COUNT(*) >= 5 |
1,135 | customers_card_transactions | spider | Show all card type codes and the number of customers holding cards in each type. | train | hard | SELECT card_type_code, COUNT(DISTINCT customer_id) FROM customers_cards GROUP BY card_type_code |
1,136 | customers_card_transactions | spider | What are the different card type codes, and how many different customers hold each type? | train | hard | SELECT card_type_code, COUNT(DISTINCT customer_id) FROM customers_cards GROUP BY card_type_code |
1,137 | customers_card_transactions | spider | Show the customer ids and firstname without a credit card. | train | hard | SELECT customer_id, customer_first_name FROM customers EXCEPT SELECT t1.customer_id, t2.customer_first_name FROM customers_cards AS t1 JOIN customers AS t2 ON t1.customer_id = t2.customer_id WHERE card_type_code = 'credit' |
1,138 | customers_card_transactions | spider | What are the ids and first names of customers who do not hold a credit card? | train | hard | SELECT customer_id, customer_first_name FROM customers EXCEPT SELECT t1.customer_id, t2.customer_first_name FROM customers_cards AS t1 JOIN customers AS t2 ON t1.customer_id = t2.customer_id WHERE card_type_code = 'credit' |
1,139 | customers_card_transactions | spider | Show all card type codes. | train | easy | SELECT DISTINCT card_type_code FROM customers_cards |
1,140 | customers_card_transactions | spider | What are the different card type codes? | train | easy | SELECT DISTINCT card_type_code FROM customers_cards |
1,141 | customers_card_transactions | spider | Show the number of card types. | train | easy | SELECT COUNT(DISTINCT card_type_code) FROM customers_cards |
1,142 | customers_card_transactions | spider | How many different card types are there? | train | easy | SELECT COUNT(DISTINCT card_type_code) FROM customers_cards |
1,143 | customers_card_transactions | spider | Show all transaction types. | train | easy | SELECT DISTINCT transaction_type FROM financial_transactions |
1,144 | customers_card_transactions | spider | What are the different types of transactions? | train | easy | SELECT DISTINCT transaction_type FROM financial_transactions |
1,145 | customers_card_transactions | spider | Show the number of transaction types. | train | easy | SELECT COUNT(DISTINCT transaction_type) FROM financial_transactions |
1,146 | customers_card_transactions | spider | How many different types of transactions are there? | train | easy | SELECT COUNT(DISTINCT transaction_type) FROM financial_transactions |
1,147 | customers_card_transactions | spider | What is the average and total transaction amount? | train | easy | SELECT AVG(transaction_amount), SUM(transaction_amount) FROM financial_transactions |
1,148 | customers_card_transactions | spider | Return the average transaction amount, as well as the total amount of all transactions. | train | easy | SELECT AVG(transaction_amount), SUM(transaction_amount) FROM financial_transactions |
1,149 | customers_card_transactions | spider | Show the card type codes and the number of transactions. | train | hard | SELECT t2.card_type_code, COUNT(*) FROM financial_transactions AS t1 JOIN customers_cards AS t2 ON t1.card_id = t2.card_id GROUP BY t2.card_type_code |
1,150 | customers_card_transactions | spider | What are the different card types, and how many transactions have been made with each? | train | hard | SELECT t2.card_type_code, COUNT(*) FROM financial_transactions AS t1 JOIN customers_cards AS t2 ON t1.card_id = t2.card_id GROUP BY t2.card_type_code |
1,151 | customers_card_transactions | spider | Show the transaction type and the number of transactions. | train | hard | SELECT transaction_type, COUNT(*) FROM financial_transactions GROUP BY transaction_type |
1,152 | customers_card_transactions | spider | What are the different transaction types, and how many transactions of each have taken place? | train | hard | SELECT transaction_type, COUNT(*) FROM financial_transactions GROUP BY transaction_type |
1,153 | customers_card_transactions | spider | What is the transaction type that has processed the greatest total amount in transactions? | train | hard | SELECT transaction_type FROM financial_transactions GROUP BY transaction_type ORDER BY SUM(transaction_amount) DESC LIMIT 1 |
1,154 | customers_card_transactions | spider | Return the type of transaction with the highest total amount. | train | hard | SELECT transaction_type FROM financial_transactions GROUP BY transaction_type ORDER BY SUM(transaction_amount) DESC LIMIT 1 |
1,155 | customers_card_transactions | spider | Show the account id and the number of transactions for each account | train | hard | SELECT account_id, COUNT(*) FROM financial_transactions GROUP BY account_id |
1,156 | customers_card_transactions | spider | What are the different account ids that have made financial transactions, as well as how many transactions correspond to each? | train | hard | SELECT account_id, COUNT(*) FROM financial_transactions GROUP BY account_id |
1,157 | coffee_shop | spider | How many members have the black membership card? | train | easy | SELECT COUNT(*) FROM member WHERE membership_card = 'black' |
1,158 | coffee_shop | spider | Find the number of members living in each address. | train | hard | SELECT COUNT(*), address FROM member GROUP BY address |
1,159 | coffee_shop | spider | Give me the names of members whose address is in Harford or Waterbury. | train | medium | SELECT name FROM member WHERE address = 'harford' OR address = 'waterbury' |
1,160 | coffee_shop | spider | Find the ids and names of members who are under age 30 or with black membership card. | train | medium | SELECT name, member_id FROM member WHERE membership_card = 'black' OR age < 30 |
1,161 | coffee_shop | spider | Find the purchase time, age and address of each member, and show the results in the order of purchase time. | train | hard | SELECT time_of_purchase, age, address FROM member ORDER BY time_of_purchase |
1,162 | coffee_shop | spider | Which membership card has more than 5 members? | train | hard | SELECT membership_card FROM member GROUP BY membership_card HAVING COUNT(*) > 5 |
1,163 | coffee_shop | spider | Which address has both members younger than 30 and members older than 40? | train | easy | SELECT address FROM member WHERE age < 30 INTERSECT SELECT address FROM member WHERE age > 40 |
1,164 | coffee_shop | spider | What is the membership card held by both members living in Hartford and ones living in Waterbury address? | train | medium | SELECT membership_card FROM member WHERE address = 'hartford' INTERSECT SELECT membership_card FROM member WHERE address = 'waterbury' |
1,165 | coffee_shop | spider | How many members are not living in Hartford? | train | medium | SELECT COUNT(*) FROM member WHERE address <> 'hartford' |
1,166 | coffee_shop | spider | Which address do not have any member with the black membership card? | train | easy | SELECT address FROM member EXCEPT SELECT address FROM member WHERE membership_card = 'black' |
1,167 | coffee_shop | spider | Show the shop addresses ordered by their opening year. | train | hard | SELECT address FROM shop ORDER BY open_year |
1,168 | coffee_shop | spider | What are the average score and average staff number of all shops? | train | easy | SELECT AVG(num_of_staff), AVG(score) FROM shop |
1,169 | coffee_shop | spider | Find the id and address of the shops whose score is below the average score. | train | medium | SELECT shop_id, address FROM shop WHERE score < (SELECT AVG(score) FROM shop) |
1,170 | coffee_shop | spider | Find the address and staff number of the shops that do not have any happy hour. | train | easy | SELECT address, num_of_staff FROM shop WHERE NOT shop_id IN (SELECT shop_id FROM happy_hour) |
1,171 | coffee_shop | spider | What are the id and address of the shops which have a happy hour in May? | train | hard | SELECT t1.address, t1.shop_id FROM shop AS t1 JOIN happy_hour AS t2 ON t1.shop_id = t2.shop_id WHERE month = 'may' |
1,172 | coffee_shop | spider | which shop has happy hour most frequently? List its id and number of happy hours. | train | hard | SELECT shop_id, COUNT(*) FROM happy_hour GROUP BY shop_id ORDER BY COUNT(*) DESC LIMIT 1 |
1,173 | coffee_shop | spider | Which month has the most happy hours? | train | hard | SELECT month FROM happy_hour GROUP BY month ORDER BY COUNT(*) DESC LIMIT 1 |
1,174 | coffee_shop | spider | Which months have more than 2 happy hours? | train | hard | SELECT month FROM happy_hour GROUP BY month HAVING COUNT(*) > 2 |
1,175 | insurance_fnol | spider | Find all the phone numbers. | train | easy | SELECT customer_phone FROM available_policies |
1,176 | insurance_fnol | spider | What are all the phone numbers? | train | easy | SELECT customer_phone FROM available_policies |
1,177 | insurance_fnol | spider | What are the customer phone numbers under the policy "Life Insurance"? | train | easy | SELECT customer_phone FROM available_policies WHERE policy_type_code = 'life insurance' |
1,178 | insurance_fnol | spider | What are the phone numbers of customers using the policy with the code "Life Insurance"? | train | easy | SELECT customer_phone FROM available_policies WHERE policy_type_code = 'life insurance' |
1,179 | insurance_fnol | spider | Which policy type has the most records in the database? | train | hard | SELECT policy_type_code FROM available_policies GROUP BY policy_type_code ORDER BY COUNT(*) DESC LIMIT 1 |
1,180 | insurance_fnol | spider | Which policy type appears most frequently in the available policies? | train | hard | SELECT policy_type_code FROM available_policies GROUP BY policy_type_code ORDER BY COUNT(*) DESC LIMIT 1 |
1,181 | insurance_fnol | spider | What are all the customer phone numbers under the most popular policy type? | train | easy | SELECT customer_phone FROM available_policies WHERE policy_type_code = (SELECT policy_type_code FROM available_policies GROUP BY policy_type_code ORDER BY COUNT(*) DESC LIMIT 1) |
1,182 | insurance_fnol | spider | Find the phone numbers of customers using the most common policy type among the available policies. | train | easy | SELECT customer_phone FROM available_policies WHERE policy_type_code = (SELECT policy_type_code FROM available_policies GROUP BY policy_type_code ORDER BY COUNT(*) DESC LIMIT 1) |
1,183 | insurance_fnol | spider | Find the policy type used by more than 4 customers. | train | hard | SELECT policy_type_code FROM available_policies GROUP BY policy_type_code HAVING COUNT(*) > 4 |
1,184 | insurance_fnol | spider | Find the policy types more than 4 customers use. Show their type code. | train | hard | SELECT policy_type_code FROM available_policies GROUP BY policy_type_code HAVING COUNT(*) > 4 |
1,185 | insurance_fnol | spider | Find the total and average amount of settlements. | train | easy | SELECT SUM(settlement_amount), AVG(settlement_amount) FROM settlements |
1,186 | insurance_fnol | spider | Return the sum and average of all settlement amounts. | train | easy | SELECT SUM(settlement_amount), AVG(settlement_amount) FROM settlements |
1,187 | insurance_fnol | spider | Find the name of services that have been used for more than 2 times in first notification of loss. | train | hard | SELECT t2.service_name FROM first_notification_of_loss AS t1 JOIN services AS t2 ON t1.service_id = t2.service_id GROUP BY t1.service_id HAVING COUNT(*) > 2 |
1,188 | insurance_fnol | spider | Which services have been used more than twice in first notification of loss? Return the service name. | train | hard | SELECT t2.service_name FROM first_notification_of_loss AS t1 JOIN services AS t2 ON t1.service_id = t2.service_id GROUP BY t1.service_id HAVING COUNT(*) > 2 |
1,189 | insurance_fnol | spider | What is the effective date of the claim that has the largest amount of total settlement? | train | hard | SELECT t1.effective_date FROM claims AS t1 JOIN settlements AS t2 ON t1.claim_id = t2.claim_id GROUP BY t1.claim_id ORDER BY SUM(t2.settlement_amount) DESC LIMIT 1 |
1,190 | insurance_fnol | spider | Find the claim that has the largest total settlement amount. Return the effective date of the claim. | train | hard | SELECT t1.effective_date FROM claims AS t1 JOIN settlements AS t2 ON t1.claim_id = t2.claim_id GROUP BY t1.claim_id ORDER BY SUM(t2.settlement_amount) DESC LIMIT 1 |
1,191 | insurance_fnol | spider | How many policies are listed for the customer named "Dayana Robel"? | train | hard | SELECT COUNT(*) FROM customers AS t1 JOIN customers_policies AS t2 ON t1.customer_id = t2.customer_id WHERE t1.customer_name = 'dayana robel' |
1,192 | insurance_fnol | spider | Count the total number of policies used by the customer named "Dayana Robel". | train | hard | SELECT COUNT(*) FROM customers AS t1 JOIN customers_policies AS t2 ON t1.customer_id = t2.customer_id WHERE t1.customer_name = 'dayana robel' |
1,193 | insurance_fnol | spider | What is the name of the customer who has the most policies listed? | train | hard | SELECT t1.customer_name FROM customers AS t1 JOIN customers_policies AS t2 ON t1.customer_id = t2.customer_id GROUP BY t1.customer_name ORDER BY COUNT(*) DESC LIMIT 1 |
1,194 | insurance_fnol | spider | Which customer uses the most policies? Give me the customer name. | train | hard | SELECT t1.customer_name FROM customers AS t1 JOIN customers_policies AS t2 ON t1.customer_id = t2.customer_id GROUP BY t1.customer_name ORDER BY COUNT(*) DESC LIMIT 1 |
1,195 | insurance_fnol | spider | What are all the policy types of the customer named "Dayana Robel"? | train | hard | SELECT DISTINCT t3.policy_type_code FROM customers AS t1 JOIN customers_policies AS t2 ON t1.customer_id = t2.customer_id JOIN available_policies AS t3 ON t2.policy_id = t3.policy_id WHERE t1.customer_name = 'dayana robel' |
1,196 | insurance_fnol | spider | Tell me the types of the policy used by the customer named "Dayana Robel". | train | hard | SELECT DISTINCT t3.policy_type_code FROM customers AS t1 JOIN customers_policies AS t2 ON t1.customer_id = t2.customer_id JOIN available_policies AS t3 ON t2.policy_id = t3.policy_id WHERE t1.customer_name = 'dayana robel' |
1,197 | insurance_fnol | spider | What are all the policy types of the customer that has the most policies listed? | train | hard | SELECT DISTINCT t3.policy_type_code FROM customers AS t1 JOIN customers_policies AS t2 ON t1.customer_id = t2.customer_id JOIN available_policies AS t3 ON t2.policy_id = t3.policy_id WHERE t1.customer_name = (SELECT t1.customer_name FROM customers AS t1 JOIN customers_policies AS t2 ON t1.customer_id = t2.customer_id G... |
1,198 | insurance_fnol | spider | List all the policy types used by the customer enrolled in the most policies. | train | hard | SELECT DISTINCT t3.policy_type_code FROM customers AS t1 JOIN customers_policies AS t2 ON t1.customer_id = t2.customer_id JOIN available_policies AS t3 ON t2.policy_id = t3.policy_id WHERE t1.customer_name = (SELECT t1.customer_name FROM customers AS t1 JOIN customers_policies AS t2 ON t1.customer_id = t2.customer_id G... |
1,199 | insurance_fnol | spider | List all the services in the alphabetical order. | train | hard | SELECT service_name FROM services ORDER BY service_name |
1,200 | insurance_fnol | spider | Give me a list of all the service names sorted alphabetically. | train | hard | SELECT service_name FROM services ORDER BY service_name |
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