question_id int64 1 75.7k | db_id stringclasses 33
values | db_name stringclasses 4
values | question stringlengths 19 259 | partition stringclasses 4
values | difficulty stringclasses 3
values | SQL stringlengths 25 862 |
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1,301 | insurance_and_eClaims | spider | Which type of policy is most frequently used? Give me the policy type code. | train | hard | SELECT policy_type_code FROM policies GROUP BY policy_type_code ORDER BY COUNT(*) DESC LIMIT 1 |
1,302 | insurance_and_eClaims | spider | Find the type code of the most frequently used policy. | train | hard | SELECT policy_type_code FROM policies GROUP BY policy_type_code ORDER BY COUNT(*) DESC LIMIT 1 |
1,303 | insurance_and_eClaims | spider | Find all the policy types that are used by more than 2 customers. | train | hard | SELECT policy_type_code FROM policies GROUP BY policy_type_code HAVING COUNT(*) > 2 |
1,304 | insurance_and_eClaims | spider | Which types of policy are chosen by more than 2 customers? Give me the policy type codes. | train | hard | SELECT policy_type_code FROM policies GROUP BY policy_type_code HAVING COUNT(*) > 2 |
1,305 | insurance_and_eClaims | spider | Find the total and average amount paid in claim headers. | train | easy | SELECT SUM(amount_piad), AVG(amount_piad) FROM claim_headers |
1,306 | insurance_and_eClaims | spider | What are the total amount and average amount paid in claim headers? | train | easy | SELECT SUM(amount_piad), AVG(amount_piad) FROM claim_headers |
1,307 | insurance_and_eClaims | spider | Find the total amount claimed in the most recently created document. | train | hard | SELECT SUM(t1.amount_claimed) FROM claim_headers AS t1 JOIN claims_documents AS t2 ON t1.claim_header_id = t2.claim_id WHERE t2.created_date = (SELECT created_date FROM claims_documents ORDER BY created_date LIMIT 1) |
1,308 | insurance_and_eClaims | spider | How much amount in total were claimed in the most recently created document? | train | hard | SELECT SUM(t1.amount_claimed) FROM claim_headers AS t1 JOIN claims_documents AS t2 ON t1.claim_header_id = t2.claim_id WHERE t2.created_date = (SELECT created_date FROM claims_documents ORDER BY created_date LIMIT 1) |
1,309 | insurance_and_eClaims | spider | What is the name of the customer who has made the largest amount of claim in a single claim? | train | hard | SELECT t3.customer_details FROM claim_headers AS t1 JOIN policies AS t2 ON t1.policy_id = t2.policy_id JOIN customers AS t3 ON t2.customer_id = t3.customer_id WHERE t1.amount_claimed = (SELECT MAX(amount_claimed) FROM claim_headers) |
1,310 | insurance_and_eClaims | spider | Which customer made the largest amount of claim in a single claim? Return the customer details. | train | hard | SELECT t3.customer_details FROM claim_headers AS t1 JOIN policies AS t2 ON t1.policy_id = t2.policy_id JOIN customers AS t3 ON t2.customer_id = t3.customer_id WHERE t1.amount_claimed = (SELECT MAX(amount_claimed) FROM claim_headers) |
1,311 | insurance_and_eClaims | spider | What is the name of the customer who has made the minimum amount of payment in one claim? | train | hard | SELECT t3.customer_details FROM claim_headers AS t1 JOIN policies AS t2 ON t1.policy_id = t2.policy_id JOIN customers AS t3 ON t2.customer_id = t3.customer_id WHERE t1.amount_piad = (SELECT MIN(amount_piad) FROM claim_headers) |
1,312 | insurance_and_eClaims | spider | Which customer made the smallest amount of claim in one claim? Return the customer details. | train | hard | SELECT t3.customer_details FROM claim_headers AS t1 JOIN policies AS t2 ON t1.policy_id = t2.policy_id JOIN customers AS t3 ON t2.customer_id = t3.customer_id WHERE t1.amount_piad = (SELECT MIN(amount_piad) FROM claim_headers) |
1,313 | insurance_and_eClaims | spider | Find the names of customers who have no policies associated. | train | hard | SELECT customer_details FROM customers EXCEPT SELECT t2.customer_details FROM policies AS t1 JOIN customers AS t2 ON t1.customer_id = t2.customer_id |
1,314 | insurance_and_eClaims | spider | What are the names of customers who do not have any policies? | train | hard | SELECT customer_details FROM customers EXCEPT SELECT t2.customer_details FROM policies AS t1 JOIN customers AS t2 ON t1.customer_id = t2.customer_id |
1,315 | insurance_and_eClaims | spider | How many claim processing stages are there in total? | train | easy | SELECT COUNT(*) FROM claims_processing_stages |
1,316 | insurance_and_eClaims | spider | Find the number of distinct stages in claim processing. | train | easy | SELECT COUNT(*) FROM claims_processing_stages |
1,317 | insurance_and_eClaims | spider | What is the name of the claim processing stage that most of the claims are on? | train | hard | SELECT t2.claim_status_name FROM claims_processing AS t1 JOIN claims_processing_stages AS t2 ON t1.claim_stage_id = t2.claim_stage_id GROUP BY t1.claim_stage_id ORDER BY COUNT(*) DESC LIMIT 1 |
1,318 | insurance_and_eClaims | spider | Which claim processing stage has the most claims? Show the claim status name. | train | hard | SELECT t2.claim_status_name FROM claims_processing AS t1 JOIN claims_processing_stages AS t2 ON t1.claim_stage_id = t2.claim_stage_id GROUP BY t1.claim_stage_id ORDER BY COUNT(*) DESC LIMIT 1 |
1,319 | insurance_and_eClaims | spider | Find the names of customers whose name contains "Diana". | train | easy | SELECT customer_details FROM customers WHERE customer_details LIKE '%diana%' |
1,320 | insurance_and_eClaims | spider | Which customers have the substring "Diana" in their names? Return the customer details. | train | easy | SELECT customer_details FROM customers WHERE customer_details LIKE '%diana%' |
1,321 | insurance_and_eClaims | spider | Find the names of the customers who have an deputy policy. | train | hard | SELECT DISTINCT t2.customer_details FROM policies AS t1 JOIN customers AS t2 ON t1.customer_id = t2.customer_id WHERE t1.policy_type_code = 'deputy' |
1,322 | insurance_and_eClaims | spider | Which customers have an insurance policy with the type code "Deputy"? Give me the customer details. | train | hard | SELECT DISTINCT t2.customer_details FROM policies AS t1 JOIN customers AS t2 ON t1.customer_id = t2.customer_id WHERE t1.policy_type_code = 'deputy' |
1,323 | insurance_and_eClaims | spider | Find the names of customers who either have an deputy policy or uniformed policy. | train | hard | SELECT DISTINCT t2.customer_details FROM policies AS t1 JOIN customers AS t2 ON t1.customer_id = t2.customer_id WHERE t1.policy_type_code = 'deputy' OR t1.policy_type_code = 'uniform' |
1,324 | insurance_and_eClaims | spider | Which customers have an insurance policy with the type code "Deputy" or "Uniform"? Return the customer details. | train | hard | SELECT DISTINCT t2.customer_details FROM policies AS t1 JOIN customers AS t2 ON t1.customer_id = t2.customer_id WHERE t1.policy_type_code = 'deputy' OR t1.policy_type_code = 'uniform' |
1,325 | insurance_and_eClaims | spider | Find the names of all the customers and staff members. | train | easy | SELECT customer_details FROM customers UNION SELECT staff_details FROM staff |
1,326 | insurance_and_eClaims | spider | What are the names of the customers and staff members? | train | easy | SELECT customer_details FROM customers UNION SELECT staff_details FROM staff |
1,327 | insurance_and_eClaims | spider | Find the number of records of each policy type and its type code. | train | hard | SELECT policy_type_code, COUNT(*) FROM policies GROUP BY policy_type_code |
1,328 | insurance_and_eClaims | spider | For each policy type, return its type code and its count in the record. | train | hard | SELECT policy_type_code, COUNT(*) FROM policies GROUP BY policy_type_code |
1,329 | insurance_and_eClaims | spider | Find the name of the customer that has been involved in the most policies. | train | hard | SELECT t2.customer_details FROM policies AS t1 JOIN customers AS t2 ON t1.customer_id = t2.customer_id GROUP BY t2.customer_details ORDER BY COUNT(*) DESC LIMIT 1 |
1,330 | insurance_and_eClaims | spider | Which customer have the most policies? Give me the customer details. | train | hard | SELECT t2.customer_details FROM policies AS t1 JOIN customers AS t2 ON t1.customer_id = t2.customer_id GROUP BY t2.customer_details ORDER BY COUNT(*) DESC LIMIT 1 |
1,331 | insurance_and_eClaims | spider | What is the description of the claim status "Open"? | train | easy | SELECT claim_status_description FROM claims_processing_stages WHERE claim_status_name = 'open' |
1,332 | insurance_and_eClaims | spider | Find the description of the claim status "Open". | train | easy | SELECT claim_status_description FROM claims_processing_stages WHERE claim_status_name = 'open' |
1,333 | insurance_and_eClaims | spider | How many distinct claim outcome codes are there? | train | easy | SELECT COUNT(DISTINCT claim_outcome_code) FROM claims_processing |
1,334 | insurance_and_eClaims | spider | Count the number of distinct claim outcome codes. | train | easy | SELECT COUNT(DISTINCT claim_outcome_code) FROM claims_processing |
1,335 | insurance_and_eClaims | spider | Which customer is associated with the latest policy? | train | hard | SELECT t2.customer_details FROM policies AS t1 JOIN customers AS t2 ON t1.customer_id = t2.customer_id WHERE t1.start_date = (SELECT MAX(start_date) FROM policies) |
1,336 | insurance_and_eClaims | spider | Find the customer who started a policy most recently. | train | hard | SELECT t2.customer_details FROM policies AS t1 JOIN customers AS t2 ON t1.customer_id = t2.customer_id WHERE t1.start_date = (SELECT MAX(start_date) FROM policies) |
1,337 | customers_and_invoices | spider | Show the number of accounts. | train | easy | SELECT COUNT(*) FROM accounts |
1,338 | customers_and_invoices | spider | How many accounts are there? | train | easy | SELECT COUNT(*) FROM accounts |
1,339 | customers_and_invoices | spider | How many customers have opened an account? | train | easy | SELECT COUNT(DISTINCT customer_id) FROM accounts |
1,340 | customers_and_invoices | spider | Count the number of customers who have an account. | train | easy | SELECT COUNT(DISTINCT customer_id) FROM accounts |
1,341 | customers_and_invoices | spider | Show the id, the date of account opened, the account name, and other account detail for all accounts. | train | easy | SELECT account_id, date_account_opened, account_name, other_account_details FROM accounts |
1,342 | customers_and_invoices | spider | What are the ids, date opened, name, and other details for all accounts? | train | easy | SELECT account_id, date_account_opened, account_name, other_account_details FROM accounts |
1,343 | customers_and_invoices | spider | Show the id, the account name, and other account details for all accounts by the customer with first name 'Meaghan'. | train | hard | SELECT t1.account_id, t1.date_account_opened, t1.account_name, t1.other_account_details FROM accounts AS t1 JOIN customers AS t2 ON t1.customer_id = t2.customer_id WHERE t2.customer_first_name = 'meaghan' |
1,344 | customers_and_invoices | spider | What are the ids, names, dates of opening, and other details for accounts corresponding to the customer with the first name "Meaghan"? | train | hard | SELECT t1.account_id, t1.date_account_opened, t1.account_name, t1.other_account_details FROM accounts AS t1 JOIN customers AS t2 ON t1.customer_id = t2.customer_id WHERE t2.customer_first_name = 'meaghan' |
1,345 | customers_and_invoices | spider | Show the account name and other account detail for all accounts by the customer with first name Meaghan and last name Keeling. | train | hard | SELECT t1.account_name, t1.other_account_details FROM accounts AS t1 JOIN customers AS t2 ON t1.customer_id = t2.customer_id WHERE t2.customer_first_name = 'meaghan' AND t2.customer_last_name = 'keeling' |
1,346 | customers_and_invoices | spider | What are the names and other details for accounts corresponding to the customer named Meaghan Keeling? | train | hard | SELECT t1.account_name, t1.other_account_details FROM accounts AS t1 JOIN customers AS t2 ON t1.customer_id = t2.customer_id WHERE t2.customer_first_name = 'meaghan' AND t2.customer_last_name = 'keeling' |
1,347 | customers_and_invoices | spider | Show the first name and last name for the customer with account name 900. | train | hard | SELECT t2.customer_first_name, t2.customer_last_name FROM accounts AS t1 JOIN customers AS t2 ON t1.customer_id = t2.customer_id WHERE t1.account_name = '900' |
1,348 | customers_and_invoices | spider | What are the full names of customers with the account name 900? | train | hard | SELECT t2.customer_first_name, t2.customer_last_name FROM accounts AS t1 JOIN customers AS t2 ON t1.customer_id = t2.customer_id WHERE t1.account_name = '900' |
1,349 | customers_and_invoices | spider | How many customers don't have an account? | train | easy | SELECT COUNT(*) FROM customers WHERE NOT customer_id IN (SELECT customer_id FROM accounts) |
1,350 | customers_and_invoices | spider | Count the number of customers who do not have an account. | train | easy | SELECT COUNT(*) FROM customers WHERE NOT customer_id IN (SELECT customer_id FROM accounts) |
1,351 | customers_and_invoices | spider | Show the unique first names, last names, and phone numbers for all customers with any account. | train | hard | SELECT DISTINCT t1.customer_first_name, t1.customer_last_name, t1.phone_number FROM customers AS t1 JOIN accounts AS t2 ON t1.customer_id = t2.customer_id |
1,352 | customers_and_invoices | spider | What are the distinct first names, last names, and phone numbers for customers with accounts? | train | hard | SELECT DISTINCT t1.customer_first_name, t1.customer_last_name, t1.phone_number FROM customers AS t1 JOIN accounts AS t2 ON t1.customer_id = t2.customer_id |
1,353 | customers_and_invoices | spider | Show customer ids who don't have an account. | train | easy | SELECT customer_id FROM customers EXCEPT SELECT customer_id FROM accounts |
1,354 | customers_and_invoices | spider | What are the customer ids for customers who do not have an account? | train | easy | SELECT customer_id FROM customers EXCEPT SELECT customer_id FROM accounts |
1,355 | customers_and_invoices | spider | How many accounts does each customer have? List the number and customer id. | train | hard | SELECT COUNT(*), customer_id FROM accounts GROUP BY customer_id |
1,356 | customers_and_invoices | spider | Count the number of accounts corresponding to each customer id. | train | hard | SELECT COUNT(*), customer_id FROM accounts GROUP BY customer_id |
1,357 | customers_and_invoices | spider | What is the customer id, first and last name with most number of accounts. | train | hard | SELECT t1.customer_id, t2.customer_first_name, t2.customer_last_name FROM accounts AS t1 JOIN customers AS t2 ON t1.customer_id = t2.customer_id GROUP BY t1.customer_id ORDER BY COUNT(*) DESC LIMIT 1 |
1,358 | customers_and_invoices | spider | Return the id and full name of the customer with the most accounts. | train | hard | SELECT t1.customer_id, t2.customer_first_name, t2.customer_last_name FROM accounts AS t1 JOIN customers AS t2 ON t1.customer_id = t2.customer_id GROUP BY t1.customer_id ORDER BY COUNT(*) DESC LIMIT 1 |
1,359 | customers_and_invoices | spider | Show id, first name and last name for all customers and the number of accounts. | train | hard | SELECT t1.customer_id, t2.customer_first_name, t2.customer_last_name, COUNT(*) FROM accounts AS t1 JOIN customers AS t2 ON t1.customer_id = t2.customer_id GROUP BY t1.customer_id |
1,360 | customers_and_invoices | spider | What are the the full names and ids for all customers, and how many accounts does each have? | train | hard | SELECT t1.customer_id, t2.customer_first_name, t2.customer_last_name, COUNT(*) FROM accounts AS t1 JOIN customers AS t2 ON t1.customer_id = t2.customer_id GROUP BY t1.customer_id |
1,361 | customers_and_invoices | spider | Show first name and id for all customers with at least 2 accounts. | train | hard | SELECT t2.customer_first_name, t1.customer_id FROM accounts AS t1 JOIN customers AS t2 ON t1.customer_id = t2.customer_id GROUP BY t1.customer_id HAVING COUNT(*) >= 2 |
1,362 | customers_and_invoices | spider | What are the first names and ids for customers who have two or more accounts? | train | hard | SELECT t2.customer_first_name, t1.customer_id FROM accounts AS t1 JOIN customers AS t2 ON t1.customer_id = t2.customer_id GROUP BY t1.customer_id HAVING COUNT(*) >= 2 |
1,363 | customers_and_invoices | spider | Show the number of customers. | train | easy | SELECT COUNT(*) FROM customers |
1,364 | customers_and_invoices | spider | Count the number of customers. | train | easy | SELECT COUNT(*) FROM customers |
1,365 | customers_and_invoices | spider | Show the number of customers for each gender. | train | hard | SELECT gender, COUNT(*) FROM customers GROUP BY gender |
1,366 | customers_and_invoices | spider | How many customers are there of each gender? | train | hard | SELECT gender, COUNT(*) FROM customers GROUP BY gender |
1,367 | customers_and_invoices | spider | How many transactions do we have? | train | easy | SELECT COUNT(*) FROM financial_transactions |
1,368 | customers_and_invoices | spider | Count the number of transactions. | train | easy | SELECT COUNT(*) FROM financial_transactions |
1,369 | customers_and_invoices | spider | How many transaction does each account have? Show the number and account id. | train | easy | SELECT COUNT(*), account_id FROM financial_transactions |
1,370 | customers_and_invoices | spider | Count the number of financial transactions that correspond to each account id. | train | easy | SELECT COUNT(*), account_id FROM financial_transactions |
1,371 | customers_and_invoices | spider | How many transaction does account with name 337 have? | train | hard | SELECT COUNT(*) FROM financial_transactions AS t1 JOIN accounts AS t2 ON t1.account_id = t2.account_id WHERE t2.account_name = '337' |
1,372 | customers_and_invoices | spider | Count the number of financial transactions that the account with the name 337 has. | train | hard | SELECT COUNT(*) FROM financial_transactions AS t1 JOIN accounts AS t2 ON t1.account_id = t2.account_id WHERE t2.account_name = '337' |
1,373 | customers_and_invoices | spider | What is the average, minimum, maximum, and total transaction amount? | train | easy | SELECT AVG(transaction_amount), MIN(transaction_amount), MAX(transaction_amount), SUM(transaction_amount) FROM financial_transactions |
1,374 | customers_and_invoices | spider | Return the average, minimum, maximum, and total transaction amounts. | train | easy | SELECT AVG(transaction_amount), MIN(transaction_amount), MAX(transaction_amount), SUM(transaction_amount) FROM financial_transactions |
1,375 | customers_and_invoices | spider | Show ids for all transactions whose amounts are greater than the average. | train | easy | SELECT transaction_id FROM financial_transactions WHERE transaction_amount > (SELECT AVG(transaction_amount) FROM financial_transactions) |
1,376 | customers_and_invoices | spider | What are the ids for transactions that have an amount greater than the average amount of a transaction? | train | easy | SELECT transaction_id FROM financial_transactions WHERE transaction_amount > (SELECT AVG(transaction_amount) FROM financial_transactions) |
1,377 | customers_and_invoices | spider | Show the transaction types and the total amount of transactions. | train | hard | SELECT transaction_type, SUM(transaction_amount) FROM financial_transactions GROUP BY transaction_type |
1,378 | customers_and_invoices | spider | What are total transaction amounts for each transaction type? | train | hard | SELECT transaction_type, SUM(transaction_amount) FROM financial_transactions GROUP BY transaction_type |
1,379 | customers_and_invoices | spider | Show the account name, id and the number of transactions for each account. | train | hard | SELECT t2.account_name, t1.account_id, COUNT(*) FROM financial_transactions AS t1 JOIN accounts AS t2 ON t1.account_id = t2.account_id GROUP BY t1.account_id |
1,380 | customers_and_invoices | spider | Return the names and ids of each account, as well as the number of transactions. | train | hard | SELECT t2.account_name, t1.account_id, COUNT(*) FROM financial_transactions AS t1 JOIN accounts AS t2 ON t1.account_id = t2.account_id GROUP BY t1.account_id |
1,381 | customers_and_invoices | spider | Show the account id with most number of transactions. | train | hard | SELECT account_id FROM financial_transactions GROUP BY account_id ORDER BY COUNT(*) DESC LIMIT 1 |
1,382 | customers_and_invoices | spider | What is the id of the account with the most transactions? | train | hard | SELECT account_id FROM financial_transactions GROUP BY account_id ORDER BY COUNT(*) DESC LIMIT 1 |
1,383 | customers_and_invoices | spider | Show the account id and name with at least 4 transactions. | train | hard | SELECT t1.account_id, t2.account_name FROM financial_transactions AS t1 JOIN accounts AS t2 ON t1.account_id = t2.account_id GROUP BY t1.account_id HAVING COUNT(*) >= 4 |
1,384 | customers_and_invoices | spider | What are the ids and names of accounts with 4 or more transactions? | train | hard | SELECT t1.account_id, t2.account_name FROM financial_transactions AS t1 JOIN accounts AS t2 ON t1.account_id = t2.account_id GROUP BY t1.account_id HAVING COUNT(*) >= 4 |
1,385 | customers_and_invoices | spider | Show all product sizes. | train | easy | SELECT DISTINCT product_size FROM products |
1,386 | customers_and_invoices | spider | What are the different product sizes? | train | easy | SELECT DISTINCT product_size FROM products |
1,387 | customers_and_invoices | spider | Show all product colors. | train | easy | SELECT DISTINCT product_color FROM products |
1,388 | customers_and_invoices | spider | What are the different product colors? | train | easy | SELECT DISTINCT product_color FROM products |
1,389 | customers_and_invoices | spider | Show the invoice number and the number of transactions for each invoice. | train | hard | SELECT invoice_number, COUNT(*) FROM financial_transactions GROUP BY invoice_number |
1,390 | customers_and_invoices | spider | How many transactions correspond to each invoice number? | train | hard | SELECT invoice_number, COUNT(*) FROM financial_transactions GROUP BY invoice_number |
1,391 | customers_and_invoices | spider | What is the invoice number and invoice date for the invoice with most number of transactions? | train | hard | SELECT t2.invoice_number, t2.invoice_date FROM financial_transactions AS t1 JOIN invoices AS t2 ON t1.invoice_number = t2.invoice_number GROUP BY t1.invoice_number ORDER BY COUNT(*) DESC LIMIT 1 |
1,392 | customers_and_invoices | spider | What is the invoice number and invoice date corresponding to the invoice with the greatest number of transactions? | train | hard | SELECT t2.invoice_number, t2.invoice_date FROM financial_transactions AS t1 JOIN invoices AS t2 ON t1.invoice_number = t2.invoice_number GROUP BY t1.invoice_number ORDER BY COUNT(*) DESC LIMIT 1 |
1,393 | customers_and_invoices | spider | How many invoices do we have? | train | easy | SELECT COUNT(*) FROM invoices |
1,394 | customers_and_invoices | spider | Count the number of invoices. | train | easy | SELECT COUNT(*) FROM invoices |
1,395 | customers_and_invoices | spider | Show invoice dates and order id and details for all invoices. | train | hard | SELECT t1.invoice_date, t1.order_id, t2.order_details FROM invoices AS t1 JOIN orders AS t2 ON t1.order_id = t2.order_id |
1,396 | customers_and_invoices | spider | What are the invoice dates, order ids, and order details for all invoices? | train | hard | SELECT t1.invoice_date, t1.order_id, t2.order_details FROM invoices AS t1 JOIN orders AS t2 ON t1.order_id = t2.order_id |
1,397 | customers_and_invoices | spider | Show the order ids and the number of invoices for each order. | train | hard | SELECT order_id, COUNT(*) FROM invoices GROUP BY order_id |
1,398 | customers_and_invoices | spider | How many invoices correspond to each order id? | train | hard | SELECT order_id, COUNT(*) FROM invoices GROUP BY order_id |
1,399 | customers_and_invoices | spider | What is the order id and order details for the order more than two invoices. | train | hard | SELECT t2.order_id, t2.order_details FROM invoices AS t1 JOIN orders AS t2 ON t1.order_id = t2.order_id GROUP BY t2.order_id HAVING COUNT(*) > 2 |
1,400 | customers_and_invoices | spider | Return the order ids and details for orderes with two or more invoices. | train | hard | SELECT t2.order_id, t2.order_details FROM invoices AS t1 JOIN orders AS t2 ON t1.order_id = t2.order_id GROUP BY t2.order_id HAVING COUNT(*) > 2 |
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