question_id int64 1 75.7k | db_id stringclasses 33
values | db_name stringclasses 4
values | question stringlengths 19 259 | partition stringclasses 4
values | difficulty stringclasses 3
values | SQL stringlengths 25 862 |
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1,601 | loan_1 | spider | Find the the name of the customers who have a loan with amount more than 3000. | train | hard | SELECT t1.cust_name FROM customer AS t1 JOIN loan AS t2 ON t1.cust_id = t2.cust_id WHERE amount > 3000 |
1,602 | loan_1 | spider | What are the names of customers who have a loan of more than 3000 in amount? | train | hard | SELECT t1.cust_name FROM customer AS t1 JOIN loan AS t2 ON t1.cust_id = t2.cust_id WHERE amount > 3000 |
1,603 | loan_1 | spider | Find the city and name of bank branches that provide business loans. | train | hard | SELECT t1.bname, t1.city FROM bank AS t1 JOIN loan AS t2 ON t1.branch_id = t2.branch_id WHERE t2.loan_type = 'business' |
1,604 | loan_1 | spider | What are the names and cities of bank branches that offer loans for business? | train | hard | SELECT t1.bname, t1.city FROM bank AS t1 JOIN loan AS t2 ON t1.branch_id = t2.branch_id WHERE t2.loan_type = 'business' |
1,605 | loan_1 | spider | Find the names of bank branches that have provided a loan to any customer whose credit score is below 100. | train | hard | SELECT t2.bname FROM loan AS t1 JOIN bank AS t2 ON t1.branch_id = t2.branch_id JOIN customer AS t3 ON t1.cust_id = t3.cust_id WHERE t3.credit_score < 100 |
1,606 | loan_1 | spider | What are the names of banks that have loaned money to customers with credit scores below 100? | train | hard | SELECT t2.bname FROM loan AS t1 JOIN bank AS t2 ON t1.branch_id = t2.branch_id JOIN customer AS t3 ON t1.cust_id = t3.cust_id WHERE t3.credit_score < 100 |
1,607 | loan_1 | spider | Find the total amount of loans provided by bank branches in the state of New York. | train | hard | SELECT SUM(t2.amount) FROM bank AS t1 JOIN loan AS t2 ON t1.branch_id = t2.branch_id WHERE t1.state = 'new york' |
1,608 | loan_1 | spider | What is the total amount of money loaned by banks in New York state? | train | hard | SELECT SUM(t2.amount) FROM bank AS t1 JOIN loan AS t2 ON t1.branch_id = t2.branch_id WHERE t1.state = 'new york' |
1,609 | loan_1 | spider | Find the average credit score of the customers who have some loan. | train | easy | SELECT AVG(credit_score) FROM customer WHERE cust_id IN (SELECT cust_id FROM loan) |
1,610 | loan_1 | spider | What is the average credit score for customers who have taken a loan? | train | easy | SELECT AVG(credit_score) FROM customer WHERE cust_id IN (SELECT cust_id FROM loan) |
1,611 | loan_1 | spider | Find the average credit score of the customers who do not have any loan. | train | easy | SELECT AVG(credit_score) FROM customer WHERE NOT cust_id IN (SELECT cust_id FROM loan) |
1,612 | loan_1 | spider | What is the average credit score for customers who have never taken a loan? | train | easy | SELECT AVG(credit_score) FROM customer WHERE NOT cust_id IN (SELECT cust_id FROM loan) |
1,613 | insurance_policies | spider | Which claims caused more than 2 settlements or have the maximum claim value? List the date the claim was made and the claim id. | train | hard | SELECT t1.date_claim_made, t1.claim_id FROM claims AS t1 JOIN settlements AS t2 ON t1.claim_id = t2.claim_id GROUP BY t1.claim_id HAVING COUNT(*) > 2 UNION SELECT t1.date_claim_made, t1.claim_id FROM claims AS t1 JOIN settlements AS t2 ON t1.claim_id = t2.claim_id WHERE t1.amount_claimed = (SELECT MAX(amount_claimed) F... |
1,614 | insurance_policies | spider | Find the claims that led to more than two settlements or have the maximum claim value. For each of them, return the date the claim was made and the id of the claim. | train | hard | SELECT t1.date_claim_made, t1.claim_id FROM claims AS t1 JOIN settlements AS t2 ON t1.claim_id = t2.claim_id GROUP BY t1.claim_id HAVING COUNT(*) > 2 UNION SELECT t1.date_claim_made, t1.claim_id FROM claims AS t1 JOIN settlements AS t2 ON t1.claim_id = t2.claim_id WHERE t1.amount_claimed = (SELECT MAX(amount_claimed) F... |
1,615 | insurance_policies | spider | Which customer had at least 2 policies but did not file any claims? List the customer details and id. | train | hard | SELECT t1.customer_details, t1.customer_id FROM customers AS t1 JOIN customer_policies AS t2 ON t1.customer_id = t2.customer_id GROUP BY t1.customer_id HAVING COUNT(*) >= 2 EXCEPT SELECT t1.customer_details, t1.customer_id FROM customers AS t1 JOIN customer_policies AS t2 ON t1.customer_id = t2.customer_id JOIN claims ... |
1,616 | insurance_policies | spider | Give me the the customer details and id for the customers who had two or more policies but did not file any claims. | train | hard | SELECT t1.customer_details, t1.customer_id FROM customers AS t1 JOIN customer_policies AS t2 ON t1.customer_id = t2.customer_id GROUP BY t1.customer_id HAVING COUNT(*) >= 2 EXCEPT SELECT t1.customer_details, t1.customer_id FROM customers AS t1 JOIN customer_policies AS t2 ON t1.customer_id = t2.customer_id JOIN claims ... |
1,617 | insurance_policies | spider | List the method, date and amount of all the payments, in ascending order of date. | train | hard | SELECT payment_method_code, date_payment_made, amount_payment FROM payments ORDER BY date_payment_made ASC |
1,618 | insurance_policies | spider | What are the method, date and amount of each payment? Sort the list in ascending order of date. | train | hard | SELECT payment_method_code, date_payment_made, amount_payment FROM payments ORDER BY date_payment_made ASC |
1,619 | insurance_policies | spider | Among all the claims, what is the settlement amount of the claim with the largest claim amount? List both the settlement amount and claim amount. | train | hard | SELECT amount_settled, amount_claimed FROM claims ORDER BY amount_claimed DESC LIMIT 1 |
1,620 | insurance_policies | spider | Find the settlement amount of the claim with the largest claim amount. Show both the settlement amount and claim amount. | train | hard | SELECT amount_settled, amount_claimed FROM claims ORDER BY amount_claimed DESC LIMIT 1 |
1,621 | insurance_policies | spider | Among all the claims, what is the amount claimed in the claim with the least amount settled? List both the settlement amount and claim amount. | train | hard | SELECT amount_settled, amount_claimed FROM claims ORDER BY amount_settled ASC LIMIT 1 |
1,622 | insurance_policies | spider | Find the claimed amount in the claim with the least amount settled. Show both the settlement amount and claim amount. | train | hard | SELECT amount_settled, amount_claimed FROM claims ORDER BY amount_settled ASC LIMIT 1 |
1,623 | insurance_policies | spider | Among all the claims, which claims have a claimed amount larger than the average? List the date the claim was made and the date it was settled. | train | easy | SELECT date_claim_made, date_claim_settled FROM claims WHERE amount_claimed > (SELECT AVG(amount_claimed) FROM claims) |
1,624 | insurance_policies | spider | Give me the claim date, settlement date for all the claims whose claimed amount is larger than the average. | train | easy | SELECT date_claim_made, date_claim_settled FROM claims WHERE amount_claimed > (SELECT AVG(amount_claimed) FROM claims) |
1,625 | insurance_policies | spider | Among all the claims, which settlements have a claimed amount that is no more than the average? List the claim start date. | train | easy | SELECT date_claim_made FROM claims WHERE amount_settled <= (SELECT AVG(amount_settled) FROM claims) |
1,626 | insurance_policies | spider | Return the claim start date for the claims whose claimed amount is no more than the average | train | easy | SELECT date_claim_made FROM claims WHERE amount_settled <= (SELECT AVG(amount_settled) FROM claims) |
1,627 | insurance_policies | spider | How many settlements does each claim correspond to? List the claim id and the number of settlements. | train | hard | SELECT t1.claim_id, COUNT(*) FROM claims AS t1 JOIN settlements AS t2 ON t1.claim_id = t2.claim_id GROUP BY t1.claim_id |
1,628 | insurance_policies | spider | Find the number of settlements each claim corresponds to. Show the number together with the claim id. | train | hard | SELECT t1.claim_id, COUNT(*) FROM claims AS t1 JOIN settlements AS t2 ON t1.claim_id = t2.claim_id GROUP BY t1.claim_id |
1,629 | insurance_policies | spider | Which claim incurred the most number of settlements? List the claim id, the date the claim was made, and the number. | train | hard | SELECT t1.claim_id, t1.date_claim_made, COUNT(*) FROM claims AS t1 JOIN settlements AS t2 ON t1.claim_id = t2.claim_id GROUP BY t1.claim_id ORDER BY COUNT(*) DESC LIMIT 1 |
1,630 | insurance_policies | spider | Find the claim id and claim date of the claim that incurred the most settlement count. Also tell me the count. | train | hard | SELECT t1.claim_id, t1.date_claim_made, COUNT(*) FROM claims AS t1 JOIN settlements AS t2 ON t1.claim_id = t2.claim_id GROUP BY t1.claim_id ORDER BY COUNT(*) DESC LIMIT 1 |
1,631 | insurance_policies | spider | How many settlements were made on the claim with the most recent claim settlement date? List the number and the claim id. | train | hard | SELECT COUNT(*), t1.claim_id FROM claims AS t1 JOIN settlements AS t2 ON t1.claim_id = t2.claim_id GROUP BY t1.claim_id ORDER BY t1.date_claim_settled DESC LIMIT 1 |
1,632 | insurance_policies | spider | Find the claim id and the number of settlements made for the claim with the most recent settlement date. | train | hard | SELECT COUNT(*), t1.claim_id FROM claims AS t1 JOIN settlements AS t2 ON t1.claim_id = t2.claim_id GROUP BY t1.claim_id ORDER BY t1.date_claim_settled DESC LIMIT 1 |
1,633 | insurance_policies | spider | Of all the claims, what was the earliest date when any claim was made? | train | hard | SELECT date_claim_made FROM claims ORDER BY date_claim_made ASC LIMIT 1 |
1,634 | insurance_policies | spider | Tell me the the date when the first claim was made. | train | hard | SELECT date_claim_made FROM claims ORDER BY date_claim_made ASC LIMIT 1 |
1,635 | insurance_policies | spider | What is the total amount of settlement made for all the settlements? | train | easy | SELECT SUM(amount_settled) FROM settlements |
1,636 | insurance_policies | spider | Compute the total amount of settlement across all the settlements. | train | easy | SELECT SUM(amount_settled) FROM settlements |
1,637 | insurance_policies | spider | Who are the customers that had more than 1 policy? List the customer details and id. | train | hard | SELECT t1.customer_details, t1.customer_id FROM customers AS t1 JOIN customer_policies AS t2 ON t1.customer_id = t2.customer_id GROUP BY t1.customer_id HAVING COUNT(*) > 1 |
1,638 | insurance_policies | spider | Find the the customer details and id for the customers who had more than one policy. | train | hard | SELECT t1.customer_details, t1.customer_id FROM customers AS t1 JOIN customer_policies AS t2 ON t1.customer_id = t2.customer_id GROUP BY t1.customer_id HAVING COUNT(*) > 1 |
1,639 | insurance_policies | spider | What are the claim dates and settlement dates of all the settlements? | train | easy | SELECT date_claim_made, date_claim_settled FROM settlements |
1,640 | insurance_policies | spider | Tell me the the claim date and settlement date for each settlement case. | train | easy | SELECT date_claim_made, date_claim_settled FROM settlements |
1,641 | insurance_policies | spider | What is the most popular payment method? | train | hard | SELECT payment_method_code FROM payments GROUP BY payment_method_code ORDER BY COUNT(*) DESC LIMIT 1 |
1,642 | insurance_policies | spider | Which payment method is used the most often? | train | hard | SELECT payment_method_code FROM payments GROUP BY payment_method_code ORDER BY COUNT(*) DESC LIMIT 1 |
1,643 | insurance_policies | spider | With which kind of payment method were the least number of payments processed? | train | hard | SELECT payment_method_code FROM payments GROUP BY payment_method_code ORDER BY COUNT(*) ASC LIMIT 1 |
1,644 | insurance_policies | spider | What is the payment method that were used the least often? | train | hard | SELECT payment_method_code FROM payments GROUP BY payment_method_code ORDER BY COUNT(*) ASC LIMIT 1 |
1,645 | insurance_policies | spider | What is the total amount of payment? | train | easy | SELECT SUM(amount_payment) FROM payments |
1,646 | insurance_policies | spider | Compute the total amount of payment processed. | train | easy | SELECT SUM(amount_payment) FROM payments |
1,647 | insurance_policies | spider | What are all the distinct details of the customers? | train | easy | SELECT DISTINCT customer_details FROM customers |
1,648 | insurance_policies | spider | Return the distinct customer details. | train | easy | SELECT DISTINCT customer_details FROM customers |
1,649 | insurance_policies | spider | Which kind of policy type was chosen by the most customers? | train | hard | SELECT policy_type_code FROM customer_policies GROUP BY policy_type_code ORDER BY COUNT(*) DESC LIMIT 1 |
1,650 | insurance_policies | spider | Find the policy type the most customers choose. | train | hard | SELECT policy_type_code FROM customer_policies GROUP BY policy_type_code ORDER BY COUNT(*) DESC LIMIT 1 |
1,651 | insurance_policies | spider | How many settlements are there in total? | train | easy | SELECT COUNT(*) FROM settlements |
1,652 | insurance_policies | spider | Count the total number of settlements made. | train | easy | SELECT COUNT(*) FROM settlements |
1,653 | insurance_policies | spider | Which Payments were processed with Visa? List the payment Id, the date and the amount. | train | easy | SELECT payment_id, date_payment_made, amount_payment FROM payments WHERE payment_method_code = 'visa' |
1,654 | insurance_policies | spider | Give me the payment Id, the date and the amount for all the payments processed with Visa. | train | easy | SELECT payment_id, date_payment_made, amount_payment FROM payments WHERE payment_method_code = 'visa' |
1,655 | insurance_policies | spider | List the details of the customers who do not have any policies. | train | hard | SELECT customer_details FROM customers EXCEPT SELECT t1.customer_details FROM customers AS t1 JOIN customer_policies AS t2 ON t1.customer_id = t2.customer_id |
1,656 | insurance_policies | spider | Which customers do not have any policies? Find the details of these customers. | train | hard | SELECT customer_details FROM customers EXCEPT SELECT t1.customer_details FROM customers AS t1 JOIN customer_policies AS t2 ON t1.customer_id = t2.customer_id |
1,657 | insurance_policies | spider | List the date the claim was made, the date it was settled and the amount settled for all the claims which had exactly one settlement. | train | hard | SELECT t1.claim_id, t1.date_claim_made, t1.date_claim_settled FROM claims AS t1 JOIN settlements AS t2 ON t1.claim_id = t2.claim_id GROUP BY t1.claim_id HAVING COUNT(*) = 1 |
1,658 | insurance_policies | spider | Which claims had exactly one settlement? For each, tell me the the date the claim was made, the date it was settled and the amount settled. | train | hard | SELECT t1.claim_id, t1.date_claim_made, t1.date_claim_settled FROM claims AS t1 JOIN settlements AS t2 ON t1.claim_id = t2.claim_id GROUP BY t1.claim_id HAVING COUNT(*) = 1 |
1,659 | insurance_policies | spider | Find the total claimed amount of all the claims. | train | easy | SELECT SUM(amount_claimed) FROM claims |
1,660 | insurance_policies | spider | What is total amount claimed summed across all the claims? | train | easy | SELECT SUM(amount_claimed) FROM claims |
1,661 | customers_campaigns_ecommerce | spider | How many premises are there? | train | easy | SELECT COUNT(*) FROM premises |
1,662 | customers_campaigns_ecommerce | spider | What are all the distinct premise types? | train | easy | SELECT DISTINCT premises_type FROM premises |
1,663 | customers_campaigns_ecommerce | spider | Find the types and details for all premises and order by the premise type. | train | hard | SELECT premises_type, premise_details FROM premises ORDER BY premises_type |
1,664 | customers_campaigns_ecommerce | spider | Show each premise type and the number of premises in that type. | train | hard | SELECT premises_type, COUNT(*) FROM premises GROUP BY premises_type |
1,665 | customers_campaigns_ecommerce | spider | Show all distinct product categories along with the number of mailshots in each category. | train | hard | SELECT product_category, COUNT(*) FROM mailshot_campaigns GROUP BY product_category |
1,666 | customers_campaigns_ecommerce | spider | Show the name and phone of the customer without any mailshot. | train | easy | SELECT customer_name, customer_phone FROM customers WHERE NOT customer_id IN (SELECT customer_id FROM mailshot_customers) |
1,667 | customers_campaigns_ecommerce | spider | Show the name and phone for customers with a mailshot with outcome code 'No Response'. | train | hard | SELECT t1.customer_name, t1.customer_phone FROM customers AS t1 JOIN mailshot_customers AS t2 ON t1.customer_id = t2.customer_id WHERE t2.outcome_code = 'no response' |
1,668 | customers_campaigns_ecommerce | spider | Show the outcome code of mailshots along with the number of mailshots in each outcome code. | train | hard | SELECT outcome_code, COUNT(*) FROM mailshot_customers GROUP BY outcome_code |
1,669 | customers_campaigns_ecommerce | spider | Show the names of customers who have at least 2 mailshots with outcome code 'Order'. | train | hard | SELECT t2.customer_name FROM mailshot_customers AS t1 JOIN customers AS t2 ON t1.customer_id = t2.customer_id WHERE outcome_code = 'order' GROUP BY t1.customer_id HAVING COUNT(*) >= 2 |
1,670 | customers_campaigns_ecommerce | spider | Show the names of customers who have the most mailshots. | train | hard | SELECT t2.customer_name FROM mailshot_customers AS t1 JOIN customers AS t2 ON t1.customer_id = t2.customer_id GROUP BY t1.customer_id ORDER BY COUNT(*) DESC LIMIT 1 |
1,671 | customers_campaigns_ecommerce | spider | What are the name and payment method of customers who have both mailshots in 'Order' outcome and mailshots in 'No Response' outcome. | train | hard | SELECT t2.customer_name, t2.payment_method FROM mailshot_customers AS t1 JOIN customers AS t2 ON t1.customer_id = t2.customer_id WHERE t1.outcome_code = 'order' INTERSECT SELECT t2.customer_name, t2.payment_method FROM mailshot_customers AS t1 JOIN customers AS t2 ON t1.customer_id = t2.customer_id WHERE t1.outcome_cod... |
1,672 | customers_campaigns_ecommerce | spider | Show the premise type and address type code for all customer addresses. | train | hard | SELECT t2.premises_type, t1.address_type_code FROM customer_addresses AS t1 JOIN premises AS t2 ON t1.premise_id = t2.premise_id |
1,673 | customers_campaigns_ecommerce | spider | What are the distinct address type codes for all customer addresses? | train | easy | SELECT DISTINCT address_type_code FROM customer_addresses |
1,674 | customers_campaigns_ecommerce | spider | Show the shipping charge and customer id for customer orders with order status Cancelled or Paid. | train | medium | SELECT order_shipping_charges, customer_id FROM customer_orders WHERE order_status_code = 'cancelled' OR order_status_code = 'paid' |
1,675 | customers_campaigns_ecommerce | spider | Show the names of customers having an order with shipping method FedEx and order status Paid. | train | hard | SELECT t1.customer_name FROM customers AS t1 JOIN customer_orders AS t2 ON t1.customer_id = t2.customer_id WHERE shipping_method_code = 'fedex' AND order_status_code = 'paid' |
1,676 | department_store | spider | What are the ids of the top three products that were purchased in the largest amount? | train | hard | SELECT product_id FROM product_suppliers ORDER BY total_amount_purchased DESC LIMIT 3 |
1,677 | department_store | spider | Give the ids of the three products purchased in the largest amounts. | train | hard | SELECT product_id FROM product_suppliers ORDER BY total_amount_purchased DESC LIMIT 3 |
1,678 | department_store | spider | What are the product id and product type of the cheapest product? | train | hard | SELECT product_id, product_type_code FROM products ORDER BY product_price LIMIT 1 |
1,679 | department_store | spider | Give the id and product type of the product with the lowest price. | train | hard | SELECT product_id, product_type_code FROM products ORDER BY product_price LIMIT 1 |
1,680 | department_store | spider | Find the number of different product types. | train | easy | SELECT COUNT(DISTINCT product_type_code) FROM products |
1,681 | department_store | spider | Count the number of distinct product types. | train | easy | SELECT COUNT(DISTINCT product_type_code) FROM products |
1,682 | department_store | spider | Return the address of customer 10. | train | hard | SELECT t1.address_details FROM addresses AS t1 JOIN customer_addresses AS t2 ON t1.address_id = t2.address_id WHERE t2.customer_id = 10 |
1,683 | department_store | spider | What is the address for the customer with id 10? | train | hard | SELECT t1.address_details FROM addresses AS t1 JOIN customer_addresses AS t2 ON t1.address_id = t2.address_id WHERE t2.customer_id = 10 |
1,684 | department_store | spider | What are the staff ids and genders of all staffs whose job title is Department Manager? | train | hard | SELECT t1.staff_id, t1.staff_gender FROM staff AS t1 JOIN staff_department_assignments AS t2 ON t1.staff_id = t2.staff_id WHERE t2.job_title_code = 'department manager' |
1,685 | department_store | spider | Return the staff ids and genders for any staff with the title Department Manager. | train | hard | SELECT t1.staff_id, t1.staff_gender FROM staff AS t1 JOIN staff_department_assignments AS t2 ON t1.staff_id = t2.staff_id WHERE t2.job_title_code = 'department manager' |
1,686 | department_store | spider | For each payment method, return how many customers use it. | train | hard | SELECT payment_method_code, COUNT(*) FROM customers GROUP BY payment_method_code |
1,687 | department_store | spider | How many customers use each payment method? | train | hard | SELECT payment_method_code, COUNT(*) FROM customers GROUP BY payment_method_code |
1,688 | department_store | spider | What is the id of the product that was ordered the most often? | train | hard | SELECT product_id FROM order_items GROUP BY product_id ORDER BY COUNT(*) DESC LIMIT 1 |
1,689 | department_store | spider | Give the product id for the product that was ordered most frequently. | train | hard | SELECT product_id FROM order_items GROUP BY product_id ORDER BY COUNT(*) DESC LIMIT 1 |
1,690 | department_store | spider | What are the name, phone number and email address of the customer who made the largest number of orders? | train | hard | SELECT t1.customer_name, t1.customer_phone, t1.customer_email FROM customers AS t1 JOIN customer_orders AS t2 ON t1.customer_id = t2.customer_id GROUP BY t2.customer_id ORDER BY COUNT(*) DESC LIMIT 1 |
1,691 | department_store | spider | Return the name, phone number and email address for the customer with the most orders. | train | hard | SELECT t1.customer_name, t1.customer_phone, t1.customer_email FROM customers AS t1 JOIN customer_orders AS t2 ON t1.customer_id = t2.customer_id GROUP BY t2.customer_id ORDER BY COUNT(*) DESC LIMIT 1 |
1,692 | department_store | spider | What is the average price for each type of product? | train | hard | SELECT product_type_code, AVG(product_price) FROM products GROUP BY product_type_code |
1,693 | department_store | spider | Return the average price for each product type. | train | hard | SELECT product_type_code, AVG(product_price) FROM products GROUP BY product_type_code |
1,694 | department_store | spider | How many department stores does the store chain South have? | train | hard | SELECT COUNT(*) FROM department_stores AS t1 JOIN department_store_chain AS t2 ON t1.dept_store_chain_id = t2.dept_store_chain_id WHERE t2.dept_store_chain_name = 'south' |
1,695 | department_store | spider | Count the number of stores the chain South has. | train | hard | SELECT COUNT(*) FROM department_stores AS t1 JOIN department_store_chain AS t2 ON t1.dept_store_chain_id = t2.dept_store_chain_id WHERE t2.dept_store_chain_name = 'south' |
1,696 | department_store | spider | What is the name and job title of the staff who was assigned the latest? | train | hard | SELECT t1.staff_name, t2.job_title_code FROM staff AS t1 JOIN staff_department_assignments AS t2 ON t1.staff_id = t2.staff_id ORDER BY t2.date_assigned_to DESC LIMIT 1 |
1,697 | department_store | spider | Return the name and job title of the staff with the latest date assigned. | train | hard | SELECT t1.staff_name, t2.job_title_code FROM staff AS t1 JOIN staff_department_assignments AS t2 ON t1.staff_id = t2.staff_id ORDER BY t2.date_assigned_to DESC LIMIT 1 |
1,698 | department_store | spider | Give me the product type, name and price for all the products supplied by supplier id 3. | train | hard | SELECT t2.product_type_code, t2.product_name, t2.product_price FROM product_suppliers AS t1 JOIN products AS t2 ON t1.product_id = t2.product_id WHERE t1.supplier_id = 3 |
1,699 | department_store | spider | Return the product type, name, and price for products supplied by supplier 3. | train | hard | SELECT t2.product_type_code, t2.product_name, t2.product_price FROM product_suppliers AS t1 JOIN products AS t2 ON t1.product_id = t2.product_id WHERE t1.supplier_id = 3 |
1,700 | department_store | spider | Return the distinct name of customers whose order status is Pending, in the order of customer id. | train | hard | SELECT DISTINCT t1.customer_name FROM customers AS t1 JOIN customer_orders AS t2 ON t1.customer_id = t2.customer_id WHERE t2.order_status_code = 'pending' ORDER BY t2.customer_id |
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