question_id int64 1 75.7k | db_id stringclasses 33
values | db_name stringclasses 4
values | question stringlengths 19 259 | partition stringclasses 4
values | difficulty stringclasses 3
values | SQL stringlengths 25 862 |
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1,701 | department_store | spider | What are the distinct names of customers with an order status of Pending, sorted by customer id? | train | hard | SELECT DISTINCT t1.customer_name FROM customers AS t1 JOIN customer_orders AS t2 ON t1.customer_id = t2.customer_id WHERE t2.order_status_code = 'pending' ORDER BY t2.customer_id |
1,702 | department_store | spider | Find the name and address of the customers who have both New and Pending orders. | train | hard | SELECT t1.customer_name, t1.customer_address FROM customers AS t1 JOIN customer_orders AS t2 ON t1.customer_id = t2.customer_id WHERE t2.order_status_code = 'new' INTERSECT SELECT t1.customer_name, t1.customer_address FROM customers AS t1 JOIN customer_orders AS t2 ON t1.customer_id = t2.customer_id WHERE t2.order_stat... |
1,703 | department_store | spider | What are the names and addressed of customers who have both New and Pending orders? | train | hard | SELECT t1.customer_name, t1.customer_address FROM customers AS t1 JOIN customer_orders AS t2 ON t1.customer_id = t2.customer_id WHERE t2.order_status_code = 'new' INTERSECT SELECT t1.customer_name, t1.customer_address FROM customers AS t1 JOIN customer_orders AS t2 ON t1.customer_id = t2.customer_id WHERE t2.order_stat... |
1,704 | department_store | spider | Return ids of all the products that are supplied by supplier id 2 and are more expensive than the average price of all products. | train | hard | SELECT t1.product_id FROM product_suppliers AS t1 JOIN products AS t2 ON t1.product_id = t2.product_id WHERE t1.supplier_id = 2 AND t2.product_price > (SELECT AVG(product_price) FROM products) |
1,705 | department_store | spider | What are the ids of products from the supplier with id 2, which are more expensive than the average price across all products? | train | hard | SELECT t1.product_id FROM product_suppliers AS t1 JOIN products AS t2 ON t1.product_id = t2.product_id WHERE t1.supplier_id = 2 AND t2.product_price > (SELECT AVG(product_price) FROM products) |
1,706 | department_store | spider | What is the id and name of the department store that has both marketing and managing department? | train | hard | SELECT t2.dept_store_id, t2.store_name FROM departments AS t1 JOIN department_stores AS t2 ON t1.dept_store_id = t2.dept_store_id WHERE t1.department_name = 'marketing' INTERSECT SELECT t2.dept_store_id, t2.store_name FROM departments AS t1 JOIN department_stores AS t2 ON t1.dept_store_id = t2.dept_store_id WHERE t1.de... |
1,707 | department_store | spider | What are the ids and names of department stores with both marketing and managing departments? | train | hard | SELECT t2.dept_store_id, t2.store_name FROM departments AS t1 JOIN department_stores AS t2 ON t1.dept_store_id = t2.dept_store_id WHERE t1.department_name = 'marketing' INTERSECT SELECT t2.dept_store_id, t2.store_name FROM departments AS t1 JOIN department_stores AS t2 ON t1.dept_store_id = t2.dept_store_id WHERE t1.de... |
1,708 | department_store | spider | What are the ids of the two department store chains with the largest number of department stores? | train | hard | SELECT dept_store_chain_id FROM department_stores GROUP BY dept_store_chain_id ORDER BY COUNT(*) DESC LIMIT 2 |
1,709 | department_store | spider | Return the ids of the two department store chains with the most department stores. | train | hard | SELECT dept_store_chain_id FROM department_stores GROUP BY dept_store_chain_id ORDER BY COUNT(*) DESC LIMIT 2 |
1,710 | department_store | spider | What is the id of the department with the least number of staff? | train | hard | SELECT department_id FROM staff_department_assignments GROUP BY department_id ORDER BY COUNT(*) LIMIT 1 |
1,711 | department_store | spider | Return the id of the department with the fewest staff assignments. | train | hard | SELECT department_id FROM staff_department_assignments GROUP BY department_id ORDER BY COUNT(*) LIMIT 1 |
1,712 | department_store | spider | For each product type, return the maximum and minimum price. | train | hard | SELECT product_type_code, MAX(product_price), MIN(product_price) FROM products GROUP BY product_type_code |
1,713 | department_store | spider | What are the maximum and minimum product prices for each product type? | train | hard | SELECT product_type_code, MAX(product_price), MIN(product_price) FROM products GROUP BY product_type_code |
1,714 | department_store | spider | Find the product type whose average price is higher than the average price of all products. | train | hard | SELECT product_type_code FROM products GROUP BY product_type_code HAVING AVG(product_price) > (SELECT AVG(product_price) FROM products) |
1,715 | department_store | spider | What is the code of the product type with an average price higher than the average price of all products? | train | hard | SELECT product_type_code FROM products GROUP BY product_type_code HAVING AVG(product_price) > (SELECT AVG(product_price) FROM products) |
1,716 | department_store | spider | Find the id and name of the staff who has been assigned for the shortest period. | train | hard | SELECT t1.staff_id, t1.staff_name FROM staff AS t1 JOIN staff_department_assignments AS t2 ON t1.staff_id = t2.staff_id ORDER BY date_assigned_to - date_assigned_from LIMIT 1 |
1,717 | department_store | spider | What is the id and name of the staff who has been assigned for the least amount of time? | train | hard | SELECT t1.staff_id, t1.staff_name FROM staff AS t1 JOIN staff_department_assignments AS t2 ON t1.staff_id = t2.staff_id ORDER BY date_assigned_to - date_assigned_from LIMIT 1 |
1,718 | department_store | spider | Return the names and ids of all products whose price is between 600 and 700. | train | medium | SELECT product_name, product_id FROM products WHERE product_price BETWEEN 600 AND 700 |
1,719 | department_store | spider | What are the names and ids of products costing between 600 and 700? | train | medium | SELECT product_name, product_id FROM products WHERE product_price BETWEEN 600 AND 700 |
1,720 | department_store | spider | Find the ids of all distinct customers who made order after some orders that were Cancelled. | train | medium | SELECT DISTINCT customer_id FROM customer_orders WHERE order_date > (SELECT MIN(order_date) FROM customer_orders WHERE order_status_code = 'cancelled') |
1,721 | department_store | spider | What are the distinct ids of customers who made an order after any order that was Cancelled? | train | medium | SELECT DISTINCT customer_id FROM customer_orders WHERE order_date > (SELECT MIN(order_date) FROM customer_orders WHERE order_status_code = 'cancelled') |
1,722 | department_store | spider | What is id of the staff who had a Staff Department Assignment earlier than any Clerical Staff? | train | easy | SELECT staff_id FROM staff_department_assignments WHERE date_assigned_to < (SELECT MAX(date_assigned_to) FROM staff_department_assignments WHERE job_title_code = 'clerical staff') |
1,723 | department_store | spider | Return the id of the staff whose Staff Department Assignment was earlier than that of any Clerical Staff. | train | easy | SELECT staff_id FROM staff_department_assignments WHERE date_assigned_to < (SELECT MAX(date_assigned_to) FROM staff_department_assignments WHERE job_title_code = 'clerical staff') |
1,724 | department_store | spider | What are the names and ids of customers whose address contains TN? | train | easy | SELECT customer_name, customer_id FROM customers WHERE customer_address LIKE '%tn%' |
1,725 | department_store | spider | Return the names and ids of customers who have TN in their address. | train | easy | SELECT customer_name, customer_id FROM customers WHERE customer_address LIKE '%tn%' |
1,726 | department_store | spider | Return the name and gender of the staff who was assigned in 2016. | train | hard | SELECT t1.staff_name, t1.staff_gender FROM staff AS t1 JOIN staff_department_assignments AS t2 ON t1.staff_id = t2.staff_id WHERE t2.date_assigned_from LIKE '2016%' |
1,727 | department_store | spider | What are the names and genders of staff who were assigned in 2016? | train | hard | SELECT t1.staff_name, t1.staff_gender FROM staff AS t1 JOIN staff_department_assignments AS t2 ON t1.staff_id = t2.staff_id WHERE t2.date_assigned_from LIKE '2016%' |
1,728 | department_store | spider | List the name of staff who has been assigned multiple jobs. | train | hard | SELECT t1.staff_name FROM staff AS t1 JOIN staff_department_assignments AS t2 ON t1.staff_id = t2.staff_id GROUP BY t2.staff_id HAVING COUNT(*) > 1 |
1,729 | department_store | spider | What are the names of staff who have been assigned multiple jobs? | train | hard | SELECT t1.staff_name FROM staff AS t1 JOIN staff_department_assignments AS t2 ON t1.staff_id = t2.staff_id GROUP BY t2.staff_id HAVING COUNT(*) > 1 |
1,730 | department_store | spider | List the name and phone number of all suppliers in the alphabetical order of their addresses. | train | hard | SELECT t1.supplier_name, t1.supplier_phone FROM suppliers AS t1 JOIN supplier_addresses AS t2 ON t1.supplier_id = t2.supplier_id JOIN addresses AS t3 ON t2.address_id = t3.address_id ORDER BY t3.address_details |
1,731 | department_store | spider | What are the names and phone numbers for all suppliers, sorted in alphabetical order of their addressed? | train | hard | SELECT t1.supplier_name, t1.supplier_phone FROM suppliers AS t1 JOIN supplier_addresses AS t2 ON t1.supplier_id = t2.supplier_id JOIN addresses AS t3 ON t2.address_id = t3.address_id ORDER BY t3.address_details |
1,732 | department_store | spider | What are the phone numbers of all customers and suppliers. | train | easy | SELECT customer_phone FROM customers UNION SELECT supplier_phone FROM suppliers |
1,733 | department_store | spider | Return the phone numbers for all customers and suppliers. | train | easy | SELECT customer_phone FROM customers UNION SELECT supplier_phone FROM suppliers |
1,734 | department_store | spider | Return the ids of all products that were ordered more than three times or supplied more than 80000. | train | hard | SELECT product_id FROM order_items GROUP BY product_id HAVING COUNT(*) > 3 UNION SELECT product_id FROM product_suppliers GROUP BY product_id HAVING SUM(total_amount_purchased) > 80000 |
1,735 | department_store | spider | What are the ids of all products that were either ordered more than 3 times or have a cumulative amount purchased of above 80000? | train | hard | SELECT product_id FROM order_items GROUP BY product_id HAVING COUNT(*) > 3 UNION SELECT product_id FROM product_suppliers GROUP BY product_id HAVING SUM(total_amount_purchased) > 80000 |
1,736 | department_store | spider | What are id and name of the products whose price is lower than 600 or higher than 900? | train | medium | SELECT product_id, product_name FROM products WHERE product_price < 600 OR product_price > 900 |
1,737 | department_store | spider | Give the ids and names of products with price lower than 600 or higher than 900. | train | medium | SELECT product_id, product_name FROM products WHERE product_price < 600 OR product_price > 900 |
1,738 | department_store | spider | Find the id of suppliers whose average amount purchased for each product is above 50000 or below 30000. | train | hard | SELECT supplier_id FROM product_suppliers GROUP BY supplier_id HAVING AVG(total_amount_purchased) > 50000 OR AVG(total_amount_purchased) < 30000 |
1,739 | department_store | spider | What are the ids of suppliers which have an average amount purchased of above 50000 or below 30000? | train | hard | SELECT supplier_id FROM product_suppliers GROUP BY supplier_id HAVING AVG(total_amount_purchased) > 50000 OR AVG(total_amount_purchased) < 30000 |
1,740 | department_store | spider | What are the average amount purchased and value purchased for the supplier who supplies the most products. | train | easy | SELECT AVG(total_amount_purchased), AVG(total_value_purchased) FROM product_suppliers WHERE supplier_id = (SELECT supplier_id FROM product_suppliers GROUP BY supplier_id ORDER BY COUNT(*) DESC LIMIT 1) |
1,741 | department_store | spider | Return the average total amount purchased and total value purchased for the supplier who supplies the greatest number of products. | train | easy | SELECT AVG(total_amount_purchased), AVG(total_value_purchased) FROM product_suppliers WHERE supplier_id = (SELECT supplier_id FROM product_suppliers GROUP BY supplier_id ORDER BY COUNT(*) DESC LIMIT 1) |
1,742 | department_store | spider | What is the largest and smallest customer codes? | train | easy | SELECT MAX(customer_code), MIN(customer_code) FROM customers |
1,743 | department_store | spider | Return the maximum and minimum customer codes. | train | easy | SELECT MAX(customer_code), MIN(customer_code) FROM customers |
1,744 | department_store | spider | List the names of all the distinct customers who bought a keyboard. | train | hard | SELECT DISTINCT t1.customer_name FROM customers AS t1 JOIN customer_orders AS t2 ON t1.customer_id = t2.customer_id JOIN order_items AS t3 ON t2.order_id = t3.order_id JOIN products AS t4 ON t3.product_id = t4.product_id WHERE t4.product_name = 'keyboard' |
1,745 | department_store | spider | What are the distinct names of customers who have purchased a keyboard? | train | hard | SELECT DISTINCT t1.customer_name FROM customers AS t1 JOIN customer_orders AS t2 ON t1.customer_id = t2.customer_id JOIN order_items AS t3 ON t2.order_id = t3.order_id JOIN products AS t4 ON t3.product_id = t4.product_id WHERE t4.product_name = 'keyboard' |
1,746 | department_store | spider | List the names and phone numbers of all the distinct suppliers who supply red jeans. | train | hard | SELECT DISTINCT t1.supplier_name, t1.supplier_phone FROM suppliers AS t1 JOIN product_suppliers AS t2 ON t1.supplier_id = t2.supplier_id JOIN products AS t3 ON t2.product_id = t3.product_id WHERE t3.product_name = 'red jeans' |
1,747 | department_store | spider | What are the distinct names and phone numbers for suppliers who have red jeans? | train | hard | SELECT DISTINCT t1.supplier_name, t1.supplier_phone FROM suppliers AS t1 JOIN product_suppliers AS t2 ON t1.supplier_id = t2.supplier_id JOIN products AS t3 ON t2.product_id = t3.product_id WHERE t3.product_name = 'red jeans' |
1,748 | department_store | spider | What are the highest and lowest prices of products, grouped by and alphabetically ordered by product type? | train | hard | SELECT MAX(product_price), MIN(product_price), product_type_code FROM products GROUP BY product_type_code ORDER BY product_type_code |
1,749 | department_store | spider | Give the maximum and minimum product prices for each product type, grouped and ordered by product type. | train | hard | SELECT MAX(product_price), MIN(product_price), product_type_code FROM products GROUP BY product_type_code ORDER BY product_type_code |
1,750 | department_store | spider | List the order id, customer id for orders in Cancelled status, ordered by their order dates. | train | medium | SELECT order_id, customer_id FROM customer_orders WHERE order_status_code = 'cancelled' ORDER BY order_date |
1,751 | department_store | spider | What are the order ids and customer ids for orders that have been Cancelled, sorted by their order dates? | train | medium | SELECT order_id, customer_id FROM customer_orders WHERE order_status_code = 'cancelled' ORDER BY order_date |
1,752 | department_store | spider | Find the names of products that were bought by at least two distinct customers. | train | hard | SELECT DISTINCT t3.product_name FROM customer_orders AS t1 JOIN order_items AS t2 ON t1.order_id = t2.order_id JOIN products AS t3 ON t2.product_id = t3.product_id GROUP BY t3.product_id HAVING COUNT(DISTINCT t1.customer_id) >= 2 |
1,753 | department_store | spider | What are the distinct names of products purchased by at least two different customers? | train | hard | SELECT DISTINCT t3.product_name FROM customer_orders AS t1 JOIN order_items AS t2 ON t1.order_id = t2.order_id JOIN products AS t3 ON t2.product_id = t3.product_id GROUP BY t3.product_id HAVING COUNT(DISTINCT t1.customer_id) >= 2 |
1,754 | department_store | spider | Find the names of customers who have bought by at least three distinct products. | train | hard | SELECT DISTINCT t1.customer_name FROM customers AS t1 JOIN customer_orders AS t2 ON t1.customer_id = t2.customer_id JOIN order_items AS t3 ON t2.order_id = t3.order_id GROUP BY t1.customer_id HAVING COUNT(DISTINCT t3.product_id) >= 3 |
1,755 | department_store | spider | What are the distinct names of customers who have purchased at least three different products? | train | hard | SELECT DISTINCT t1.customer_name FROM customers AS t1 JOIN customer_orders AS t2 ON t1.customer_id = t2.customer_id JOIN order_items AS t3 ON t2.order_id = t3.order_id GROUP BY t1.customer_id HAVING COUNT(DISTINCT t3.product_id) >= 3 |
1,756 | department_store | spider | Find the name and gender of the staff who has been assigned the job of Sales Person but never Clerical Staff. | train | hard | SELECT t1.staff_name, t1.staff_gender FROM staff AS t1 JOIN staff_department_assignments AS t2 ON t1.staff_id = t2.staff_id WHERE t2.job_title_code = 'sales person' EXCEPT SELECT t1.staff_name, t1.staff_gender FROM staff AS t1 JOIN staff_department_assignments AS t2 ON t1.staff_id = t2.staff_id WHERE t2.job_title_code ... |
1,757 | department_store | spider | What are the names and genders of staff who have held the title Sales Person, but never Clerical Staff? | train | hard | SELECT t1.staff_name, t1.staff_gender FROM staff AS t1 JOIN staff_department_assignments AS t2 ON t1.staff_id = t2.staff_id WHERE t2.job_title_code = 'sales person' EXCEPT SELECT t1.staff_name, t1.staff_gender FROM staff AS t1 JOIN staff_department_assignments AS t2 ON t1.staff_id = t2.staff_id WHERE t2.job_title_code ... |
1,758 | department_store | spider | Find the id and name of customers whose address contains WY state and do not use credit card for payment. | train | medium | SELECT customer_id, customer_name FROM customers WHERE customer_address LIKE '%wy%' AND payment_method_code <> 'credit card' |
1,759 | department_store | spider | What are the ids and names of customers with addressed that contain WY and who do not use a credit card for payment? | train | medium | SELECT customer_id, customer_name FROM customers WHERE customer_address LIKE '%wy%' AND payment_method_code <> 'credit card' |
1,760 | department_store | spider | Find the average price of all product clothes. | train | easy | SELECT AVG(product_price) FROM products WHERE product_type_code = 'clothes' |
1,761 | department_store | spider | What is the average price of clothes? | train | easy | SELECT AVG(product_price) FROM products WHERE product_type_code = 'clothes' |
1,762 | department_store | spider | Find the name of the most expensive hardware product. | train | easy | SELECT product_name FROM products WHERE product_type_code = 'hardware' ORDER BY product_price DESC LIMIT 1 |
1,763 | department_store | spider | What is the name of the hardware product with the greatest price? | train | easy | SELECT product_name FROM products WHERE product_type_code = 'hardware' ORDER BY product_price DESC LIMIT 1 |
1,764 | shop_membership | spider | How many branches where have more than average number of memberships are there? | train | easy | SELECT COUNT(*) FROM branch WHERE membership_amount > (SELECT AVG(membership_amount) FROM branch) |
1,765 | shop_membership | spider | What is the number of branches that have more than the average number of memberships? | train | easy | SELECT COUNT(*) FROM branch WHERE membership_amount > (SELECT AVG(membership_amount) FROM branch) |
1,766 | shop_membership | spider | Show name, address road, and city for all branches sorted by open year. | train | hard | SELECT name, address_road, city FROM branch ORDER BY open_year |
1,767 | shop_membership | spider | What are the names, address roads, and cities of the branches ordered by opening year? | train | hard | SELECT name, address_road, city FROM branch ORDER BY open_year |
1,768 | shop_membership | spider | What are names for top three branches with most number of membership? | train | hard | SELECT name FROM branch ORDER BY membership_amount DESC LIMIT 3 |
1,769 | shop_membership | spider | What are the names for the 3 branches that have the most memberships? | train | hard | SELECT name FROM branch ORDER BY membership_amount DESC LIMIT 3 |
1,770 | shop_membership | spider | Show all distinct city where branches with at least 100 memberships are located. | train | easy | SELECT DISTINCT city FROM branch WHERE membership_amount >= 100 |
1,771 | shop_membership | spider | What are the different cities that have more than 100 memberships? | train | easy | SELECT DISTINCT city FROM branch WHERE membership_amount >= 100 |
1,772 | shop_membership | spider | List all open years when at least two shops are opened. | train | hard | SELECT open_year FROM branch GROUP BY open_year HAVING COUNT(*) >= 2 |
1,773 | shop_membership | spider | What are the opening years in which at least two shops opened? | train | hard | SELECT open_year FROM branch GROUP BY open_year HAVING COUNT(*) >= 2 |
1,774 | shop_membership | spider | Show minimum and maximum amount of memberships for all branches opened in 2011 or located at city London. | train | medium | SELECT MIN(membership_amount), MAX(membership_amount) FROM branch WHERE open_year = 2011 OR city = 'london' |
1,775 | shop_membership | spider | What are the minimum and maximum membership amounts for all branches that either opened in 2011 or are located in London? | train | medium | SELECT MIN(membership_amount), MAX(membership_amount) FROM branch WHERE open_year = 2011 OR city = 'london' |
1,776 | shop_membership | spider | Show the city and the number of branches opened before 2010 for each city. | train | easy | SELECT city, COUNT(*) FROM branch WHERE open_year < 2010 GROUP BY city |
1,777 | shop_membership | spider | For each city, how many branches opened before 2010? | train | easy | SELECT city, COUNT(*) FROM branch WHERE open_year < 2010 GROUP BY city |
1,778 | shop_membership | spider | How many different levels do members have? | train | easy | SELECT COUNT(DISTINCT level) FROM member |
1,779 | shop_membership | spider | What are the different membership levels? | train | easy | SELECT COUNT(DISTINCT level) FROM member |
1,780 | shop_membership | spider | Show card number, name, and hometown for all members in a descending order of level. | train | hard | SELECT card_number, name, hometown FROM member ORDER BY level DESC |
1,781 | shop_membership | spider | What are the card numbers, names, and hometowns of every member ordered by descending level? | train | hard | SELECT card_number, name, hometown FROM member ORDER BY level DESC |
1,782 | shop_membership | spider | Show the membership level with most number of members. | train | hard | SELECT level FROM member GROUP BY level ORDER BY COUNT(*) DESC LIMIT 1 |
1,783 | shop_membership | spider | What is the membership level with the most people? | train | hard | SELECT level FROM member GROUP BY level ORDER BY COUNT(*) DESC LIMIT 1 |
1,784 | shop_membership | spider | Show all member names and registered branch names sorted by register year. | train | hard | SELECT t3.name, t2.name FROM membership_register_branch AS t1 JOIN branch AS t2 ON t1.branch_id = t2.branch_id JOIN member AS t3 ON t1.member_id = t3.member_id ORDER BY t1.register_year |
1,785 | shop_membership | spider | What are the names of the members and branches at which they are registered sorted by year of registration? | train | hard | SELECT t3.name, t2.name FROM membership_register_branch AS t1 JOIN branch AS t2 ON t1.branch_id = t2.branch_id JOIN member AS t3 ON t1.member_id = t3.member_id ORDER BY t1.register_year |
1,786 | shop_membership | spider | Show all branch names with the number of members in each branch registered after 2015. | train | hard | SELECT t2.name, COUNT(*) FROM membership_register_branch AS t1 JOIN branch AS t2 ON t1.branch_id = t2.branch_id WHERE t1.register_year > 2015 GROUP BY t2.branch_id |
1,787 | shop_membership | spider | For each branch id, what are the names of the branches that were registered after 2015? | train | hard | SELECT t2.name, COUNT(*) FROM membership_register_branch AS t1 JOIN branch AS t2 ON t1.branch_id = t2.branch_id WHERE t1.register_year > 2015 GROUP BY t2.branch_id |
1,788 | shop_membership | spider | Show member names without any registered branch. | train | easy | SELECT name FROM member WHERE NOT member_id IN (SELECT member_id FROM membership_register_branch) |
1,789 | shop_membership | spider | What are the names of the members that have never registered at any branch? | train | easy | SELECT name FROM member WHERE NOT member_id IN (SELECT member_id FROM membership_register_branch) |
1,790 | shop_membership | spider | List the branch name and city without any registered members. | train | easy | SELECT name, city FROM branch WHERE NOT branch_id IN (SELECT branch_id FROM membership_register_branch) |
1,791 | shop_membership | spider | What are the names and cities of the branches that do not have any registered members? | train | easy | SELECT name, city FROM branch WHERE NOT branch_id IN (SELECT branch_id FROM membership_register_branch) |
1,792 | shop_membership | spider | What is the name and open year for the branch with most number of memberships registered in 2016? | train | hard | SELECT t2.name, t2.open_year FROM membership_register_branch AS t1 JOIN branch AS t2 ON t1.branch_id = t2.branch_id WHERE t1.register_year = 2016 GROUP BY t2.branch_id ORDER BY COUNT(*) DESC LIMIT 1 |
1,793 | shop_membership | spider | What is the name and opening year for the branch that registered the most members in 2016? | train | hard | SELECT t2.name, t2.open_year FROM membership_register_branch AS t1 JOIN branch AS t2 ON t1.branch_id = t2.branch_id WHERE t1.register_year = 2016 GROUP BY t2.branch_id ORDER BY COUNT(*) DESC LIMIT 1 |
1,794 | shop_membership | spider | Show the member name and hometown who registered a branch in 2016. | train | hard | SELECT t2.name, t2.hometown FROM membership_register_branch AS t1 JOIN member AS t2 ON t1.member_id = t2.member_id WHERE t1.register_year = 2016 |
1,795 | shop_membership | spider | What are the member names and hometowns of those who registered at a branch in 2016? | train | hard | SELECT t2.name, t2.hometown FROM membership_register_branch AS t1 JOIN member AS t2 ON t1.member_id = t2.member_id WHERE t1.register_year = 2016 |
1,796 | shop_membership | spider | Show all city with a branch opened in 2001 and a branch with more than 100 membership. | train | medium | SELECT city FROM branch WHERE open_year = 2001 AND membership_amount > 100 |
1,797 | shop_membership | spider | What are the cities that have a branch that opened in 2001 and a branch with more than 100 members? | train | medium | SELECT city FROM branch WHERE open_year = 2001 AND membership_amount > 100 |
1,798 | shop_membership | spider | Show all cities without a branch having more than 100 memberships. | train | easy | SELECT city FROM branch EXCEPT SELECT city FROM branch WHERE membership_amount > 100 |
1,799 | shop_membership | spider | What are the cities that do not have any branches with more than 100 members? | train | easy | SELECT city FROM branch EXCEPT SELECT city FROM branch WHERE membership_amount > 100 |
1,800 | shop_membership | spider | What is the sum of total pounds of purchase in year 2018 for all branches in London? | train | hard | SELECT SUM(total_pounds) FROM purchase AS t1 JOIN branch AS t2 ON t1.branch_id = t2.branch_id WHERE t2.city = 'london' AND t1.year = 2018 |
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