id
int64
0
8.66k
db_id
stringclasses
146 values
schema
stringclasses
146 values
question
stringlengths
3
224
output
stringlengths
18
577
2,900
icfp_1
CREATE TABLE Inst ( instID INTEGER, name TEXT, country TEXT, -- the home country of the institution ( this is obviously an impoverished model ) PRIMARY KEY ( instID ) ); CREATE TABLE Authors ( authID INTEGER, lname TEXT, fname TEXT, PRIMARY KEY ( authID ) ); CREATE TABLE Pa...
Retrieve the country that has published the most papers.
SELECT t1.country FROM inst AS t1 JOIN authorship AS t2 ON t1.instid = t2.instid JOIN papers AS t3 ON t2.paperid = t3.paperid GROUP BY t1.country ORDER BY count(*) DESC LIMIT 1
2,901
icfp_1
CREATE TABLE Inst ( instID INTEGER, name TEXT, country TEXT, -- the home country of the institution ( this is obviously an impoverished model ) PRIMARY KEY ( instID ) ); CREATE TABLE Authors ( authID INTEGER, lname TEXT, fname TEXT, PRIMARY KEY ( authID ) ); CREATE TABLE Pa...
Find the country that the most papers are affiliated with.
SELECT t1.country FROM inst AS t1 JOIN authorship AS t2 ON t1.instid = t2.instid JOIN papers AS t3 ON t2.paperid = t3.paperid GROUP BY t1.country ORDER BY count(*) DESC LIMIT 1
2,902
icfp_1
CREATE TABLE Inst ( instID INTEGER, name TEXT, country TEXT, -- the home country of the institution ( this is obviously an impoverished model ) PRIMARY KEY ( instID ) ); CREATE TABLE Authors ( authID INTEGER, lname TEXT, fname TEXT, PRIMARY KEY ( authID ) ); CREATE TABLE Pa...
Find the name of the organization that has published the largest number of papers.
SELECT t1.name FROM inst AS t1 JOIN authorship AS t2 ON t1.instid = t2.instid JOIN papers AS t3 ON t2.paperid = t3.paperid GROUP BY t1.name ORDER BY count(*) DESC LIMIT 1
2,903
icfp_1
CREATE TABLE Inst ( instID INTEGER, name TEXT, country TEXT, -- the home country of the institution ( this is obviously an impoverished model ) PRIMARY KEY ( instID ) ); CREATE TABLE Authors ( authID INTEGER, lname TEXT, fname TEXT, PRIMARY KEY ( authID ) ); CREATE TABLE Pa...
Which institution has the most papers? Find the name of the institution.
SELECT t1.name FROM inst AS t1 JOIN authorship AS t2 ON t1.instid = t2.instid JOIN papers AS t3 ON t2.paperid = t3.paperid GROUP BY t1.name ORDER BY count(*) DESC LIMIT 1
2,904
icfp_1
CREATE TABLE Inst ( instID INTEGER, name TEXT, country TEXT, -- the home country of the institution ( this is obviously an impoverished model ) PRIMARY KEY ( instID ) ); CREATE TABLE Authors ( authID INTEGER, lname TEXT, fname TEXT, PRIMARY KEY ( authID ) ); CREATE TABLE Pa...
Find the titles of the papers that contain the word "ML".
SELECT title FROM papers WHERE title LIKE "%ML%"
2,905
icfp_1
CREATE TABLE Inst ( instID INTEGER, name TEXT, country TEXT, -- the home country of the institution ( this is obviously an impoverished model ) PRIMARY KEY ( instID ) ); CREATE TABLE Authors ( authID INTEGER, lname TEXT, fname TEXT, PRIMARY KEY ( authID ) ); CREATE TABLE Pa...
Which papers have the substring "ML" in their titles? Return the titles of the papers.
SELECT title FROM papers WHERE title LIKE "%ML%"
2,906
icfp_1
CREATE TABLE Inst ( instID INTEGER, name TEXT, country TEXT, -- the home country of the institution ( this is obviously an impoverished model ) PRIMARY KEY ( instID ) ); CREATE TABLE Authors ( authID INTEGER, lname TEXT, fname TEXT, PRIMARY KEY ( authID ) ); CREATE TABLE Pa...
Which paper's title contains the word "Database"?
SELECT title FROM papers WHERE title LIKE "%Database%"
2,907
icfp_1
CREATE TABLE Inst ( instID INTEGER, name TEXT, country TEXT, -- the home country of the institution ( this is obviously an impoverished model ) PRIMARY KEY ( instID ) ); CREATE TABLE Authors ( authID INTEGER, lname TEXT, fname TEXT, PRIMARY KEY ( authID ) ); CREATE TABLE Pa...
Which papers have the substring "Database" in their titles? Show the titles of the papers.
SELECT title FROM papers WHERE title LIKE "%Database%"
2,908
icfp_1
CREATE TABLE Inst ( instID INTEGER, name TEXT, country TEXT, -- the home country of the institution ( this is obviously an impoverished model ) PRIMARY KEY ( instID ) ); CREATE TABLE Authors ( authID INTEGER, lname TEXT, fname TEXT, PRIMARY KEY ( authID ) ); CREATE TABLE Pa...
Find the first names of all the authors who have written a paper with title containing the word "Functional".
SELECT t1.fname FROM authors AS t1 JOIN authorship AS t2 ON t1.authid = t2.authid JOIN papers AS t3 ON t2.paperid = t3.paperid WHERE t3.title LIKE "%Functional%"
2,909
icfp_1
CREATE TABLE Inst ( instID INTEGER, name TEXT, country TEXT, -- the home country of the institution ( this is obviously an impoverished model ) PRIMARY KEY ( instID ) ); CREATE TABLE Authors ( authID INTEGER, lname TEXT, fname TEXT, PRIMARY KEY ( authID ) ); CREATE TABLE Pa...
Who has written a paper that has the word "Functional" in its title? Return the first names of the authors.
SELECT t1.fname FROM authors AS t1 JOIN authorship AS t2 ON t1.authid = t2.authid JOIN papers AS t3 ON t2.paperid = t3.paperid WHERE t3.title LIKE "%Functional%"
2,910
icfp_1
CREATE TABLE Inst ( instID INTEGER, name TEXT, country TEXT, -- the home country of the institution ( this is obviously an impoverished model ) PRIMARY KEY ( instID ) ); CREATE TABLE Authors ( authID INTEGER, lname TEXT, fname TEXT, PRIMARY KEY ( authID ) ); CREATE TABLE Pa...
Find the last names of all the authors that have written a paper with title containing the word "Monadic".
SELECT t1.lname FROM authors AS t1 JOIN authorship AS t2 ON t1.authid = t2.authid JOIN papers AS t3 ON t2.paperid = t3.paperid WHERE t3.title LIKE "%Monadic%"
2,911
icfp_1
CREATE TABLE Inst ( instID INTEGER, name TEXT, country TEXT, -- the home country of the institution ( this is obviously an impoverished model ) PRIMARY KEY ( instID ) ); CREATE TABLE Authors ( authID INTEGER, lname TEXT, fname TEXT, PRIMARY KEY ( authID ) ); CREATE TABLE Pa...
Which authors have written a paper with title containing the word "Monadic"? Return their last names.
SELECT t1.lname FROM authors AS t1 JOIN authorship AS t2 ON t1.authid = t2.authid JOIN papers AS t3 ON t2.paperid = t3.paperid WHERE t3.title LIKE "%Monadic%"
2,912
icfp_1
CREATE TABLE Inst ( instID INTEGER, name TEXT, country TEXT, -- the home country of the institution ( this is obviously an impoverished model ) PRIMARY KEY ( instID ) ); CREATE TABLE Authors ( authID INTEGER, lname TEXT, fname TEXT, PRIMARY KEY ( authID ) ); CREATE TABLE Pa...
Retrieve the title of the paper that has the largest number of authors.
SELECT t2.title FROM authorship AS t1 JOIN papers AS t2 ON t1.paperid = t2.paperid WHERE t1.authorder = (SELECT max(authorder) FROM authorship)
2,913
icfp_1
CREATE TABLE Inst ( instID INTEGER, name TEXT, country TEXT, -- the home country of the institution ( this is obviously an impoverished model ) PRIMARY KEY ( instID ) ); CREATE TABLE Authors ( authID INTEGER, lname TEXT, fname TEXT, PRIMARY KEY ( authID ) ); CREATE TABLE Pa...
Which paper has the most authors? Give me the paper title.
SELECT t2.title FROM authorship AS t1 JOIN papers AS t2 ON t1.paperid = t2.paperid WHERE t1.authorder = (SELECT max(authorder) FROM authorship)
2,914
icfp_1
CREATE TABLE Inst ( instID INTEGER, name TEXT, country TEXT, -- the home country of the institution ( this is obviously an impoverished model ) PRIMARY KEY ( instID ) ); CREATE TABLE Authors ( authID INTEGER, lname TEXT, fname TEXT, PRIMARY KEY ( authID ) ); CREATE TABLE Pa...
What is the first name of the author with last name "Ueno"?
SELECT fname FROM authors WHERE lname = "Ueno"
2,915
icfp_1
CREATE TABLE Inst ( instID INTEGER, name TEXT, country TEXT, -- the home country of the institution ( this is obviously an impoverished model ) PRIMARY KEY ( instID ) ); CREATE TABLE Authors ( authID INTEGER, lname TEXT, fname TEXT, PRIMARY KEY ( authID ) ); CREATE TABLE Pa...
Which authors have last name "Ueno"? List their first names.
SELECT fname FROM authors WHERE lname = "Ueno"
2,916
icfp_1
CREATE TABLE Inst ( instID INTEGER, name TEXT, country TEXT, -- the home country of the institution ( this is obviously an impoverished model ) PRIMARY KEY ( instID ) ); CREATE TABLE Authors ( authID INTEGER, lname TEXT, fname TEXT, PRIMARY KEY ( authID ) ); CREATE TABLE Pa...
Find the last name of the author with first name "Amal".
SELECT lname FROM authors WHERE fname = "Amal"
2,917
icfp_1
CREATE TABLE Inst ( instID INTEGER, name TEXT, country TEXT, -- the home country of the institution ( this is obviously an impoverished model ) PRIMARY KEY ( instID ) ); CREATE TABLE Authors ( authID INTEGER, lname TEXT, fname TEXT, PRIMARY KEY ( authID ) ); CREATE TABLE Pa...
Which authors have first name "Amal"? List their last names.
SELECT lname FROM authors WHERE fname = "Amal"
2,918
icfp_1
CREATE TABLE Inst ( instID INTEGER, name TEXT, country TEXT, -- the home country of the institution ( this is obviously an impoverished model ) PRIMARY KEY ( instID ) ); CREATE TABLE Authors ( authID INTEGER, lname TEXT, fname TEXT, PRIMARY KEY ( authID ) ); CREATE TABLE Pa...
Find the first names of all the authors ordered in alphabetical order.
SELECT fname FROM authors ORDER BY fname
2,919
icfp_1
CREATE TABLE Inst ( instID INTEGER, name TEXT, country TEXT, -- the home country of the institution ( this is obviously an impoverished model ) PRIMARY KEY ( instID ) ); CREATE TABLE Authors ( authID INTEGER, lname TEXT, fname TEXT, PRIMARY KEY ( authID ) ); CREATE TABLE Pa...
Sort the first names of all the authors in alphabetical order.
SELECT fname FROM authors ORDER BY fname
2,920
icfp_1
CREATE TABLE Inst ( instID INTEGER, name TEXT, country TEXT, -- the home country of the institution ( this is obviously an impoverished model ) PRIMARY KEY ( instID ) ); CREATE TABLE Authors ( authID INTEGER, lname TEXT, fname TEXT, PRIMARY KEY ( authID ) ); CREATE TABLE Pa...
Retrieve all the last names of authors in alphabetical order.
SELECT lname FROM authors ORDER BY lname
2,921
icfp_1
CREATE TABLE Inst ( instID INTEGER, name TEXT, country TEXT, -- the home country of the institution ( this is obviously an impoverished model ) PRIMARY KEY ( instID ) ); CREATE TABLE Authors ( authID INTEGER, lname TEXT, fname TEXT, PRIMARY KEY ( authID ) ); CREATE TABLE Pa...
Give me a list of all the last names of authors sorted in alphabetical order
SELECT lname FROM authors ORDER BY lname
2,922
icfp_1
CREATE TABLE Inst ( instID INTEGER, name TEXT, country TEXT, -- the home country of the institution ( this is obviously an impoverished model ) PRIMARY KEY ( instID ) ); CREATE TABLE Authors ( authID INTEGER, lname TEXT, fname TEXT, PRIMARY KEY ( authID ) ); CREATE TABLE Pa...
Retrieve all the first and last names of authors in the alphabetical order of last names.
SELECT fname , lname FROM authors ORDER BY lname
2,923
icfp_1
CREATE TABLE Inst ( instID INTEGER, name TEXT, country TEXT, -- the home country of the institution ( this is obviously an impoverished model ) PRIMARY KEY ( instID ) ); CREATE TABLE Authors ( authID INTEGER, lname TEXT, fname TEXT, PRIMARY KEY ( authID ) ); CREATE TABLE Pa...
Sort the list of all the first and last names of authors in alphabetical order of the last names.
SELECT fname , lname FROM authors ORDER BY lname
2,924
sakila_1
CREATE TABLE actor ( actor_id SMALLINT UNSIGNED NOT NULL, first_name VARCHAR( 45 ) NOT NULL, last_name VARCHAR( 45 ) NOT NULL, last_update TIMESTAMP NOT NULL DEFAULT CURRENT_TIMESTAMP, PRIMARY KEY ( actor_id ) ); CREATE TABLE address ( address_id SMALLINT UNSIGNED NOT NULL, addres...
How many different last names do the actors and actresses have?
SELECT count(DISTINCT last_name) FROM actor
2,925
sakila_1
CREATE TABLE actor ( actor_id SMALLINT UNSIGNED NOT NULL, first_name VARCHAR( 45 ) NOT NULL, last_name VARCHAR( 45 ) NOT NULL, last_update TIMESTAMP NOT NULL DEFAULT CURRENT_TIMESTAMP, PRIMARY KEY ( actor_id ) ); CREATE TABLE address ( address_id SMALLINT UNSIGNED NOT NULL, addres...
Count the number of different last names actors have.
SELECT count(DISTINCT last_name) FROM actor
2,926
sakila_1
CREATE TABLE actor ( actor_id SMALLINT UNSIGNED NOT NULL, first_name VARCHAR( 45 ) NOT NULL, last_name VARCHAR( 45 ) NOT NULL, last_update TIMESTAMP NOT NULL DEFAULT CURRENT_TIMESTAMP, PRIMARY KEY ( actor_id ) ); CREATE TABLE address ( address_id SMALLINT UNSIGNED NOT NULL, addres...
What is the most popular first name of the actors?
SELECT first_name FROM actor GROUP BY first_name ORDER BY count(*) DESC LIMIT 1
2,927
sakila_1
CREATE TABLE actor ( actor_id SMALLINT UNSIGNED NOT NULL, first_name VARCHAR( 45 ) NOT NULL, last_name VARCHAR( 45 ) NOT NULL, last_update TIMESTAMP NOT NULL DEFAULT CURRENT_TIMESTAMP, PRIMARY KEY ( actor_id ) ); CREATE TABLE address ( address_id SMALLINT UNSIGNED NOT NULL, addres...
Return the most common first name among all actors.
SELECT first_name FROM actor GROUP BY first_name ORDER BY count(*) DESC LIMIT 1
2,928
sakila_1
CREATE TABLE actor ( actor_id SMALLINT UNSIGNED NOT NULL, first_name VARCHAR( 45 ) NOT NULL, last_name VARCHAR( 45 ) NOT NULL, last_update TIMESTAMP NOT NULL DEFAULT CURRENT_TIMESTAMP, PRIMARY KEY ( actor_id ) ); CREATE TABLE address ( address_id SMALLINT UNSIGNED NOT NULL, addres...
What is the most popular full name of the actors?
SELECT first_name , last_name FROM actor GROUP BY first_name , last_name ORDER BY count(*) DESC LIMIT 1
2,929
sakila_1
CREATE TABLE actor ( actor_id SMALLINT UNSIGNED NOT NULL, first_name VARCHAR( 45 ) NOT NULL, last_name VARCHAR( 45 ) NOT NULL, last_update TIMESTAMP NOT NULL DEFAULT CURRENT_TIMESTAMP, PRIMARY KEY ( actor_id ) ); CREATE TABLE address ( address_id SMALLINT UNSIGNED NOT NULL, addres...
Return the most common full name among all actors.
SELECT first_name , last_name FROM actor GROUP BY first_name , last_name ORDER BY count(*) DESC LIMIT 1
2,930
sakila_1
CREATE TABLE actor ( actor_id SMALLINT UNSIGNED NOT NULL, first_name VARCHAR( 45 ) NOT NULL, last_name VARCHAR( 45 ) NOT NULL, last_update TIMESTAMP NOT NULL DEFAULT CURRENT_TIMESTAMP, PRIMARY KEY ( actor_id ) ); CREATE TABLE address ( address_id SMALLINT UNSIGNED NOT NULL, addres...
Which districts have at least two addresses?
SELECT district FROM address GROUP BY district HAVING count(*) >= 2
2,931
sakila_1
CREATE TABLE actor ( actor_id SMALLINT UNSIGNED NOT NULL, first_name VARCHAR( 45 ) NOT NULL, last_name VARCHAR( 45 ) NOT NULL, last_update TIMESTAMP NOT NULL DEFAULT CURRENT_TIMESTAMP, PRIMARY KEY ( actor_id ) ); CREATE TABLE address ( address_id SMALLINT UNSIGNED NOT NULL, addres...
Give the districts which have two or more addresses.
SELECT district FROM address GROUP BY district HAVING count(*) >= 2
2,932
sakila_1
CREATE TABLE actor ( actor_id SMALLINT UNSIGNED NOT NULL, first_name VARCHAR( 45 ) NOT NULL, last_name VARCHAR( 45 ) NOT NULL, last_update TIMESTAMP NOT NULL DEFAULT CURRENT_TIMESTAMP, PRIMARY KEY ( actor_id ) ); CREATE TABLE address ( address_id SMALLINT UNSIGNED NOT NULL, addres...
What is the phone number and postal code of the address 1031 Daugavpils Parkway?
SELECT phone , postal_code FROM address WHERE address = '1031 Daugavpils Parkway'
2,933
sakila_1
CREATE TABLE actor ( actor_id SMALLINT UNSIGNED NOT NULL, first_name VARCHAR( 45 ) NOT NULL, last_name VARCHAR( 45 ) NOT NULL, last_update TIMESTAMP NOT NULL DEFAULT CURRENT_TIMESTAMP, PRIMARY KEY ( actor_id ) ); CREATE TABLE address ( address_id SMALLINT UNSIGNED NOT NULL, addres...
Give the phone and postal code corresponding to the address '1031 Daugavpils Parkway'.
SELECT phone , postal_code FROM address WHERE address = '1031 Daugavpils Parkway'
2,934
sakila_1
CREATE TABLE actor ( actor_id SMALLINT UNSIGNED NOT NULL, first_name VARCHAR( 45 ) NOT NULL, last_name VARCHAR( 45 ) NOT NULL, last_update TIMESTAMP NOT NULL DEFAULT CURRENT_TIMESTAMP, PRIMARY KEY ( actor_id ) ); CREATE TABLE address ( address_id SMALLINT UNSIGNED NOT NULL, addres...
Which city has the most addresses? List the city name, number of addresses, and city id.
SELECT T2.city , count(*) , T1.city_id FROM address AS T1 JOIN city AS T2 ON T1.city_id = T2.city_id GROUP BY T1.city_id ORDER BY count(*) DESC LIMIT 1
2,935
sakila_1
CREATE TABLE actor ( actor_id SMALLINT UNSIGNED NOT NULL, first_name VARCHAR( 45 ) NOT NULL, last_name VARCHAR( 45 ) NOT NULL, last_update TIMESTAMP NOT NULL DEFAULT CURRENT_TIMESTAMP, PRIMARY KEY ( actor_id ) ); CREATE TABLE address ( address_id SMALLINT UNSIGNED NOT NULL, addres...
What are the city name, id, and number of addresses corresponding to the city with the most addressed?
SELECT T2.city , count(*) , T1.city_id FROM address AS T1 JOIN city AS T2 ON T1.city_id = T2.city_id GROUP BY T1.city_id ORDER BY count(*) DESC LIMIT 1
2,936
sakila_1
CREATE TABLE actor ( actor_id SMALLINT UNSIGNED NOT NULL, first_name VARCHAR( 45 ) NOT NULL, last_name VARCHAR( 45 ) NOT NULL, last_update TIMESTAMP NOT NULL DEFAULT CURRENT_TIMESTAMP, PRIMARY KEY ( actor_id ) ); CREATE TABLE address ( address_id SMALLINT UNSIGNED NOT NULL, addres...
How many addresses are in the district of California?
SELECT count(*) FROM address WHERE district = 'California'
2,937
sakila_1
CREATE TABLE actor ( actor_id SMALLINT UNSIGNED NOT NULL, first_name VARCHAR( 45 ) NOT NULL, last_name VARCHAR( 45 ) NOT NULL, last_update TIMESTAMP NOT NULL DEFAULT CURRENT_TIMESTAMP, PRIMARY KEY ( actor_id ) ); CREATE TABLE address ( address_id SMALLINT UNSIGNED NOT NULL, addres...
Count the number of addressed in the California district.
SELECT count(*) FROM address WHERE district = 'California'
2,938
sakila_1
CREATE TABLE actor ( actor_id SMALLINT UNSIGNED NOT NULL, first_name VARCHAR( 45 ) NOT NULL, last_name VARCHAR( 45 ) NOT NULL, last_update TIMESTAMP NOT NULL DEFAULT CURRENT_TIMESTAMP, PRIMARY KEY ( actor_id ) ); CREATE TABLE address ( address_id SMALLINT UNSIGNED NOT NULL, addres...
Which film is rented at a fee of 0.99 and has less than 3 in the inventory? List the film title and id.
SELECT title , film_id FROM film WHERE rental_rate = 0.99 INTERSECT SELECT T1.title , T1.film_id FROM film AS T1 JOIN inventory AS T2 ON T1.film_id = T2.film_id GROUP BY T1.film_id HAVING count(*) < 3
2,939
sakila_1
CREATE TABLE actor ( actor_id SMALLINT UNSIGNED NOT NULL, first_name VARCHAR( 45 ) NOT NULL, last_name VARCHAR( 45 ) NOT NULL, last_update TIMESTAMP NOT NULL DEFAULT CURRENT_TIMESTAMP, PRIMARY KEY ( actor_id ) ); CREATE TABLE address ( address_id SMALLINT UNSIGNED NOT NULL, addres...
What are the title and id of the film which has a rental rate of 0.99 and an inventory of below 3?
SELECT title , film_id FROM film WHERE rental_rate = 0.99 INTERSECT SELECT T1.title , T1.film_id FROM film AS T1 JOIN inventory AS T2 ON T1.film_id = T2.film_id GROUP BY T1.film_id HAVING count(*) < 3
2,940
sakila_1
CREATE TABLE actor ( actor_id SMALLINT UNSIGNED NOT NULL, first_name VARCHAR( 45 ) NOT NULL, last_name VARCHAR( 45 ) NOT NULL, last_update TIMESTAMP NOT NULL DEFAULT CURRENT_TIMESTAMP, PRIMARY KEY ( actor_id ) ); CREATE TABLE address ( address_id SMALLINT UNSIGNED NOT NULL, addres...
How many cities are in Australia?
SELECT count(*) FROM city AS T1 JOIN country AS T2 ON T1.country_id = T2.country_id WHERE T2.country = 'Australia'
2,941
sakila_1
CREATE TABLE actor ( actor_id SMALLINT UNSIGNED NOT NULL, first_name VARCHAR( 45 ) NOT NULL, last_name VARCHAR( 45 ) NOT NULL, last_update TIMESTAMP NOT NULL DEFAULT CURRENT_TIMESTAMP, PRIMARY KEY ( actor_id ) ); CREATE TABLE address ( address_id SMALLINT UNSIGNED NOT NULL, addres...
Count the number of cities in Australia.
SELECT count(*) FROM city AS T1 JOIN country AS T2 ON T1.country_id = T2.country_id WHERE T2.country = 'Australia'
2,942
sakila_1
CREATE TABLE actor ( actor_id SMALLINT UNSIGNED NOT NULL, first_name VARCHAR( 45 ) NOT NULL, last_name VARCHAR( 45 ) NOT NULL, last_update TIMESTAMP NOT NULL DEFAULT CURRENT_TIMESTAMP, PRIMARY KEY ( actor_id ) ); CREATE TABLE address ( address_id SMALLINT UNSIGNED NOT NULL, addres...
Which countries have at least 3 cities?
SELECT T2.country FROM city AS T1 JOIN country AS T2 ON T1.country_id = T2.country_id GROUP BY T2.country_id HAVING count(*) >= 3
2,943
sakila_1
CREATE TABLE actor ( actor_id SMALLINT UNSIGNED NOT NULL, first_name VARCHAR( 45 ) NOT NULL, last_name VARCHAR( 45 ) NOT NULL, last_update TIMESTAMP NOT NULL DEFAULT CURRENT_TIMESTAMP, PRIMARY KEY ( actor_id ) ); CREATE TABLE address ( address_id SMALLINT UNSIGNED NOT NULL, addres...
What are the countries that contain 3 or more cities?
SELECT T2.country FROM city AS T1 JOIN country AS T2 ON T1.country_id = T2.country_id GROUP BY T2.country_id HAVING count(*) >= 3
2,944
sakila_1
CREATE TABLE actor ( actor_id SMALLINT UNSIGNED NOT NULL, first_name VARCHAR( 45 ) NOT NULL, last_name VARCHAR( 45 ) NOT NULL, last_update TIMESTAMP NOT NULL DEFAULT CURRENT_TIMESTAMP, PRIMARY KEY ( actor_id ) ); CREATE TABLE address ( address_id SMALLINT UNSIGNED NOT NULL, addres...
Find all the payment dates for the payments with an amount larger than 10 and the payments handled by a staff person with the first name Elsa.
SELECT payment_date FROM payment WHERE amount > 10 UNION SELECT T1.payment_date FROM payment AS T1 JOIN staff AS T2 ON T1.staff_id = T2.staff_id WHERE T2.first_name = 'Elsa'
2,945
sakila_1
CREATE TABLE actor ( actor_id SMALLINT UNSIGNED NOT NULL, first_name VARCHAR( 45 ) NOT NULL, last_name VARCHAR( 45 ) NOT NULL, last_update TIMESTAMP NOT NULL DEFAULT CURRENT_TIMESTAMP, PRIMARY KEY ( actor_id ) ); CREATE TABLE address ( address_id SMALLINT UNSIGNED NOT NULL, addres...
What are the payment dates for any payments that have an amount greater than 10 or were handled by a staff member with the first name Elsa?
SELECT payment_date FROM payment WHERE amount > 10 UNION SELECT T1.payment_date FROM payment AS T1 JOIN staff AS T2 ON T1.staff_id = T2.staff_id WHERE T2.first_name = 'Elsa'
2,946
sakila_1
CREATE TABLE actor ( actor_id SMALLINT UNSIGNED NOT NULL, first_name VARCHAR( 45 ) NOT NULL, last_name VARCHAR( 45 ) NOT NULL, last_update TIMESTAMP NOT NULL DEFAULT CURRENT_TIMESTAMP, PRIMARY KEY ( actor_id ) ); CREATE TABLE address ( address_id SMALLINT UNSIGNED NOT NULL, addres...
How many customers have an active value of 1?
SELECT count(*) FROM customer WHERE active = '1'
2,947
sakila_1
CREATE TABLE actor ( actor_id SMALLINT UNSIGNED NOT NULL, first_name VARCHAR( 45 ) NOT NULL, last_name VARCHAR( 45 ) NOT NULL, last_update TIMESTAMP NOT NULL DEFAULT CURRENT_TIMESTAMP, PRIMARY KEY ( actor_id ) ); CREATE TABLE address ( address_id SMALLINT UNSIGNED NOT NULL, addres...
Count the number of customers who are active.
SELECT count(*) FROM customer WHERE active = '1'
2,948
sakila_1
CREATE TABLE actor ( actor_id SMALLINT UNSIGNED NOT NULL, first_name VARCHAR( 45 ) NOT NULL, last_name VARCHAR( 45 ) NOT NULL, last_update TIMESTAMP NOT NULL DEFAULT CURRENT_TIMESTAMP, PRIMARY KEY ( actor_id ) ); CREATE TABLE address ( address_id SMALLINT UNSIGNED NOT NULL, addres...
Which film has the highest rental rate? And what is the rate?
SELECT title , rental_rate FROM film ORDER BY rental_rate DESC LIMIT 1
2,949
sakila_1
CREATE TABLE actor ( actor_id SMALLINT UNSIGNED NOT NULL, first_name VARCHAR( 45 ) NOT NULL, last_name VARCHAR( 45 ) NOT NULL, last_update TIMESTAMP NOT NULL DEFAULT CURRENT_TIMESTAMP, PRIMARY KEY ( actor_id ) ); CREATE TABLE address ( address_id SMALLINT UNSIGNED NOT NULL, addres...
What are the title and rental rate of the film with the highest rental rate?
SELECT title , rental_rate FROM film ORDER BY rental_rate DESC LIMIT 1
2,950
sakila_1
CREATE TABLE actor ( actor_id SMALLINT UNSIGNED NOT NULL, first_name VARCHAR( 45 ) NOT NULL, last_name VARCHAR( 45 ) NOT NULL, last_update TIMESTAMP NOT NULL DEFAULT CURRENT_TIMESTAMP, PRIMARY KEY ( actor_id ) ); CREATE TABLE address ( address_id SMALLINT UNSIGNED NOT NULL, addres...
Which film has the most number of actors or actresses? List the film name, film id and description.
SELECT T2.title , T2.film_id , T2.description FROM film_actor AS T1 JOIN film AS T2 ON T1.film_id = T2.film_id GROUP BY T2.film_id ORDER BY count(*) DESC LIMIT 1
2,951
sakila_1
CREATE TABLE actor ( actor_id SMALLINT UNSIGNED NOT NULL, first_name VARCHAR( 45 ) NOT NULL, last_name VARCHAR( 45 ) NOT NULL, last_update TIMESTAMP NOT NULL DEFAULT CURRENT_TIMESTAMP, PRIMARY KEY ( actor_id ) ); CREATE TABLE address ( address_id SMALLINT UNSIGNED NOT NULL, addres...
What are the title, id, and description of the movie with the greatest number of actors?
SELECT T2.title , T2.film_id , T2.description FROM film_actor AS T1 JOIN film AS T2 ON T1.film_id = T2.film_id GROUP BY T2.film_id ORDER BY count(*) DESC LIMIT 1
2,952
sakila_1
CREATE TABLE actor ( actor_id SMALLINT UNSIGNED NOT NULL, first_name VARCHAR( 45 ) NOT NULL, last_name VARCHAR( 45 ) NOT NULL, last_update TIMESTAMP NOT NULL DEFAULT CURRENT_TIMESTAMP, PRIMARY KEY ( actor_id ) ); CREATE TABLE address ( address_id SMALLINT UNSIGNED NOT NULL, addres...
Which film actor (actress) starred the most films? List his or her first name, last name and actor id.
SELECT T2.first_name , T2.last_name , T2.actor_id FROM film_actor AS T1 JOIN actor AS T2 ON T1.actor_id = T2.actor_id GROUP BY T2.actor_id ORDER BY count(*) DESC LIMIT 1
2,953
sakila_1
CREATE TABLE actor ( actor_id SMALLINT UNSIGNED NOT NULL, first_name VARCHAR( 45 ) NOT NULL, last_name VARCHAR( 45 ) NOT NULL, last_update TIMESTAMP NOT NULL DEFAULT CURRENT_TIMESTAMP, PRIMARY KEY ( actor_id ) ); CREATE TABLE address ( address_id SMALLINT UNSIGNED NOT NULL, addres...
Return the full name and id of the actor or actress who starred in the greatest number of films.
SELECT T2.first_name , T2.last_name , T2.actor_id FROM film_actor AS T1 JOIN actor AS T2 ON T1.actor_id = T2.actor_id GROUP BY T2.actor_id ORDER BY count(*) DESC LIMIT 1
2,954
sakila_1
CREATE TABLE actor ( actor_id SMALLINT UNSIGNED NOT NULL, first_name VARCHAR( 45 ) NOT NULL, last_name VARCHAR( 45 ) NOT NULL, last_update TIMESTAMP NOT NULL DEFAULT CURRENT_TIMESTAMP, PRIMARY KEY ( actor_id ) ); CREATE TABLE address ( address_id SMALLINT UNSIGNED NOT NULL, addres...
Which film actors (actresses) played a role in more than 30 films? List his or her first name and last name.
SELECT T2.first_name , T2.last_name FROM film_actor AS T1 JOIN actor AS T2 ON T1.actor_id = T2.actor_id GROUP BY T2.actor_id HAVING count(*) > 30
2,955
sakila_1
CREATE TABLE actor ( actor_id SMALLINT UNSIGNED NOT NULL, first_name VARCHAR( 45 ) NOT NULL, last_name VARCHAR( 45 ) NOT NULL, last_update TIMESTAMP NOT NULL DEFAULT CURRENT_TIMESTAMP, PRIMARY KEY ( actor_id ) ); CREATE TABLE address ( address_id SMALLINT UNSIGNED NOT NULL, addres...
What are the full names of actors who had roles in more than 30 films?
SELECT T2.first_name , T2.last_name FROM film_actor AS T1 JOIN actor AS T2 ON T1.actor_id = T2.actor_id GROUP BY T2.actor_id HAVING count(*) > 30
2,956
sakila_1
CREATE TABLE actor ( actor_id SMALLINT UNSIGNED NOT NULL, first_name VARCHAR( 45 ) NOT NULL, last_name VARCHAR( 45 ) NOT NULL, last_update TIMESTAMP NOT NULL DEFAULT CURRENT_TIMESTAMP, PRIMARY KEY ( actor_id ) ); CREATE TABLE address ( address_id SMALLINT UNSIGNED NOT NULL, addres...
Which store owns most items?
SELECT store_id FROM inventory GROUP BY store_id ORDER BY count(*) DESC LIMIT 1
2,957
sakila_1
CREATE TABLE actor ( actor_id SMALLINT UNSIGNED NOT NULL, first_name VARCHAR( 45 ) NOT NULL, last_name VARCHAR( 45 ) NOT NULL, last_update TIMESTAMP NOT NULL DEFAULT CURRENT_TIMESTAMP, PRIMARY KEY ( actor_id ) ); CREATE TABLE address ( address_id SMALLINT UNSIGNED NOT NULL, addres...
What is the id of the store that has the most items in inventory?
SELECT store_id FROM inventory GROUP BY store_id ORDER BY count(*) DESC LIMIT 1
2,958
sakila_1
CREATE TABLE actor ( actor_id SMALLINT UNSIGNED NOT NULL, first_name VARCHAR( 45 ) NOT NULL, last_name VARCHAR( 45 ) NOT NULL, last_update TIMESTAMP NOT NULL DEFAULT CURRENT_TIMESTAMP, PRIMARY KEY ( actor_id ) ); CREATE TABLE address ( address_id SMALLINT UNSIGNED NOT NULL, addres...
What is the total amount of all payments?
SELECT sum(amount) FROM payment
2,959
sakila_1
CREATE TABLE actor ( actor_id SMALLINT UNSIGNED NOT NULL, first_name VARCHAR( 45 ) NOT NULL, last_name VARCHAR( 45 ) NOT NULL, last_update TIMESTAMP NOT NULL DEFAULT CURRENT_TIMESTAMP, PRIMARY KEY ( actor_id ) ); CREATE TABLE address ( address_id SMALLINT UNSIGNED NOT NULL, addres...
Return the sum of all payment amounts.
SELECT sum(amount) FROM payment
2,960
sakila_1
CREATE TABLE actor ( actor_id SMALLINT UNSIGNED NOT NULL, first_name VARCHAR( 45 ) NOT NULL, last_name VARCHAR( 45 ) NOT NULL, last_update TIMESTAMP NOT NULL DEFAULT CURRENT_TIMESTAMP, PRIMARY KEY ( actor_id ) ); CREATE TABLE address ( address_id SMALLINT UNSIGNED NOT NULL, addres...
Which customer, who has made at least one payment, has spent the least money? List his or her first name, last name, and the id.
SELECT T1.first_name , T1.last_name , T1.customer_id FROM customer AS T1 JOIN payment AS T2 ON T1.customer_id = T2.customer_id GROUP BY T1.customer_id ORDER BY sum(amount) ASC LIMIT 1
2,961
sakila_1
CREATE TABLE actor ( actor_id SMALLINT UNSIGNED NOT NULL, first_name VARCHAR( 45 ) NOT NULL, last_name VARCHAR( 45 ) NOT NULL, last_update TIMESTAMP NOT NULL DEFAULT CURRENT_TIMESTAMP, PRIMARY KEY ( actor_id ) ); CREATE TABLE address ( address_id SMALLINT UNSIGNED NOT NULL, addres...
What is the full name and id of the customer who has the lowest total amount of payment?
SELECT T1.first_name , T1.last_name , T1.customer_id FROM customer AS T1 JOIN payment AS T2 ON T1.customer_id = T2.customer_id GROUP BY T1.customer_id ORDER BY sum(amount) ASC LIMIT 1
2,962
sakila_1
CREATE TABLE actor ( actor_id SMALLINT UNSIGNED NOT NULL, first_name VARCHAR( 45 ) NOT NULL, last_name VARCHAR( 45 ) NOT NULL, last_update TIMESTAMP NOT NULL DEFAULT CURRENT_TIMESTAMP, PRIMARY KEY ( actor_id ) ); CREATE TABLE address ( address_id SMALLINT UNSIGNED NOT NULL, addres...
What is the genre name of the film HUNGER ROOF?
SELECT T1.name FROM category AS T1 JOIN film_category AS T2 ON T1.category_id = T2.category_id JOIN film AS T3 ON T2.film_id = T3.film_id WHERE T3.title = 'HUNGER ROOF'
2,963
sakila_1
CREATE TABLE actor ( actor_id SMALLINT UNSIGNED NOT NULL, first_name VARCHAR( 45 ) NOT NULL, last_name VARCHAR( 45 ) NOT NULL, last_update TIMESTAMP NOT NULL DEFAULT CURRENT_TIMESTAMP, PRIMARY KEY ( actor_id ) ); CREATE TABLE address ( address_id SMALLINT UNSIGNED NOT NULL, addres...
Return the name of the category to which the film 'HUNGER ROOF' belongs.
SELECT T1.name FROM category AS T1 JOIN film_category AS T2 ON T1.category_id = T2.category_id JOIN film AS T3 ON T2.film_id = T3.film_id WHERE T3.title = 'HUNGER ROOF'
2,964
sakila_1
CREATE TABLE actor ( actor_id SMALLINT UNSIGNED NOT NULL, first_name VARCHAR( 45 ) NOT NULL, last_name VARCHAR( 45 ) NOT NULL, last_update TIMESTAMP NOT NULL DEFAULT CURRENT_TIMESTAMP, PRIMARY KEY ( actor_id ) ); CREATE TABLE address ( address_id SMALLINT UNSIGNED NOT NULL, addres...
How many films are there in each category? List the genre name, genre id and the count.
SELECT T2.name , T1.category_id , count(*) FROM film_category AS T1 JOIN category AS T2 ON T1.category_id = T2.category_id GROUP BY T1.category_id
2,965
sakila_1
CREATE TABLE actor ( actor_id SMALLINT UNSIGNED NOT NULL, first_name VARCHAR( 45 ) NOT NULL, last_name VARCHAR( 45 ) NOT NULL, last_update TIMESTAMP NOT NULL DEFAULT CURRENT_TIMESTAMP, PRIMARY KEY ( actor_id ) ); CREATE TABLE address ( address_id SMALLINT UNSIGNED NOT NULL, addres...
What are the names and ids of the different categories, and how many films are in each?
SELECT T2.name , T1.category_id , count(*) FROM film_category AS T1 JOIN category AS T2 ON T1.category_id = T2.category_id GROUP BY T1.category_id
2,966
sakila_1
CREATE TABLE actor ( actor_id SMALLINT UNSIGNED NOT NULL, first_name VARCHAR( 45 ) NOT NULL, last_name VARCHAR( 45 ) NOT NULL, last_update TIMESTAMP NOT NULL DEFAULT CURRENT_TIMESTAMP, PRIMARY KEY ( actor_id ) ); CREATE TABLE address ( address_id SMALLINT UNSIGNED NOT NULL, addres...
Which film has the most copies in the inventory? List both title and id.
SELECT T1.title , T1.film_id FROM film AS T1 JOIN inventory AS T2 ON T1.film_id = T2.film_id GROUP BY T1.film_id ORDER BY count(*) DESC LIMIT 1
2,967
sakila_1
CREATE TABLE actor ( actor_id SMALLINT UNSIGNED NOT NULL, first_name VARCHAR( 45 ) NOT NULL, last_name VARCHAR( 45 ) NOT NULL, last_update TIMESTAMP NOT NULL DEFAULT CURRENT_TIMESTAMP, PRIMARY KEY ( actor_id ) ); CREATE TABLE address ( address_id SMALLINT UNSIGNED NOT NULL, addres...
What is the title and id of the film that has the greatest number of copies in inventory?
SELECT T1.title , T1.film_id FROM film AS T1 JOIN inventory AS T2 ON T1.film_id = T2.film_id GROUP BY T1.film_id ORDER BY count(*) DESC LIMIT 1
2,968
sakila_1
CREATE TABLE actor ( actor_id SMALLINT UNSIGNED NOT NULL, first_name VARCHAR( 45 ) NOT NULL, last_name VARCHAR( 45 ) NOT NULL, last_update TIMESTAMP NOT NULL DEFAULT CURRENT_TIMESTAMP, PRIMARY KEY ( actor_id ) ); CREATE TABLE address ( address_id SMALLINT UNSIGNED NOT NULL, addres...
What is the film title and inventory id of the item in the inventory which was rented most frequently?
SELECT T1.title , T2.inventory_id FROM film AS T1 JOIN inventory AS T2 ON T1.film_id = T2.film_id JOIN rental AS T3 ON T2.inventory_id = T3.inventory_id GROUP BY T2.inventory_id ORDER BY count(*) DESC LIMIT 1
2,969
sakila_1
CREATE TABLE actor ( actor_id SMALLINT UNSIGNED NOT NULL, first_name VARCHAR( 45 ) NOT NULL, last_name VARCHAR( 45 ) NOT NULL, last_update TIMESTAMP NOT NULL DEFAULT CURRENT_TIMESTAMP, PRIMARY KEY ( actor_id ) ); CREATE TABLE address ( address_id SMALLINT UNSIGNED NOT NULL, addres...
Return the title and inventory id of the film that is rented most often.
SELECT T1.title , T2.inventory_id FROM film AS T1 JOIN inventory AS T2 ON T1.film_id = T2.film_id JOIN rental AS T3 ON T2.inventory_id = T3.inventory_id GROUP BY T2.inventory_id ORDER BY count(*) DESC LIMIT 1
2,970
sakila_1
CREATE TABLE actor ( actor_id SMALLINT UNSIGNED NOT NULL, first_name VARCHAR( 45 ) NOT NULL, last_name VARCHAR( 45 ) NOT NULL, last_update TIMESTAMP NOT NULL DEFAULT CURRENT_TIMESTAMP, PRIMARY KEY ( actor_id ) ); CREATE TABLE address ( address_id SMALLINT UNSIGNED NOT NULL, addres...
How many languages are in these films?
SELECT count(DISTINCT language_id) FROM film
2,971
sakila_1
CREATE TABLE actor ( actor_id SMALLINT UNSIGNED NOT NULL, first_name VARCHAR( 45 ) NOT NULL, last_name VARCHAR( 45 ) NOT NULL, last_update TIMESTAMP NOT NULL DEFAULT CURRENT_TIMESTAMP, PRIMARY KEY ( actor_id ) ); CREATE TABLE address ( address_id SMALLINT UNSIGNED NOT NULL, addres...
Count the number of different languages in these films.
SELECT count(DISTINCT language_id) FROM film
2,972
sakila_1
CREATE TABLE actor ( actor_id SMALLINT UNSIGNED NOT NULL, first_name VARCHAR( 45 ) NOT NULL, last_name VARCHAR( 45 ) NOT NULL, last_update TIMESTAMP NOT NULL DEFAULT CURRENT_TIMESTAMP, PRIMARY KEY ( actor_id ) ); CREATE TABLE address ( address_id SMALLINT UNSIGNED NOT NULL, addres...
What are all the movies rated as R? List the titles.
SELECT title FROM film WHERE rating = 'R'
2,973
sakila_1
CREATE TABLE actor ( actor_id SMALLINT UNSIGNED NOT NULL, first_name VARCHAR( 45 ) NOT NULL, last_name VARCHAR( 45 ) NOT NULL, last_update TIMESTAMP NOT NULL DEFAULT CURRENT_TIMESTAMP, PRIMARY KEY ( actor_id ) ); CREATE TABLE address ( address_id SMALLINT UNSIGNED NOT NULL, addres...
Return the titles of any movies with an R rating.
SELECT title FROM film WHERE rating = 'R'
2,974
sakila_1
CREATE TABLE actor ( actor_id SMALLINT UNSIGNED NOT NULL, first_name VARCHAR( 45 ) NOT NULL, last_name VARCHAR( 45 ) NOT NULL, last_update TIMESTAMP NOT NULL DEFAULT CURRENT_TIMESTAMP, PRIMARY KEY ( actor_id ) ); CREATE TABLE address ( address_id SMALLINT UNSIGNED NOT NULL, addres...
Where is store 1 located?
SELECT T2.address FROM store AS T1 JOIN address AS T2 ON T1.address_id = T2.address_id WHERE store_id = 1
2,975
sakila_1
CREATE TABLE actor ( actor_id SMALLINT UNSIGNED NOT NULL, first_name VARCHAR( 45 ) NOT NULL, last_name VARCHAR( 45 ) NOT NULL, last_update TIMESTAMP NOT NULL DEFAULT CURRENT_TIMESTAMP, PRIMARY KEY ( actor_id ) ); CREATE TABLE address ( address_id SMALLINT UNSIGNED NOT NULL, addres...
Return the address of store 1.
SELECT T2.address FROM store AS T1 JOIN address AS T2 ON T1.address_id = T2.address_id WHERE store_id = 1
2,976
sakila_1
CREATE TABLE actor ( actor_id SMALLINT UNSIGNED NOT NULL, first_name VARCHAR( 45 ) NOT NULL, last_name VARCHAR( 45 ) NOT NULL, last_update TIMESTAMP NOT NULL DEFAULT CURRENT_TIMESTAMP, PRIMARY KEY ( actor_id ) ); CREATE TABLE address ( address_id SMALLINT UNSIGNED NOT NULL, addres...
Which staff handled least number of payments? List the full name and the id.
SELECT T1.first_name , T1.last_name , T1.staff_id FROM staff AS T1 JOIN payment AS T2 ON T1.staff_id = T2.staff_id GROUP BY T1.staff_id ORDER BY count(*) ASC LIMIT 1
2,977
sakila_1
CREATE TABLE actor ( actor_id SMALLINT UNSIGNED NOT NULL, first_name VARCHAR( 45 ) NOT NULL, last_name VARCHAR( 45 ) NOT NULL, last_update TIMESTAMP NOT NULL DEFAULT CURRENT_TIMESTAMP, PRIMARY KEY ( actor_id ) ); CREATE TABLE address ( address_id SMALLINT UNSIGNED NOT NULL, addres...
Give the full name and staff id of the staff who has handled the fewest payments.
SELECT T1.first_name , T1.last_name , T1.staff_id FROM staff AS T1 JOIN payment AS T2 ON T1.staff_id = T2.staff_id GROUP BY T1.staff_id ORDER BY count(*) ASC LIMIT 1
2,978
sakila_1
CREATE TABLE actor ( actor_id SMALLINT UNSIGNED NOT NULL, first_name VARCHAR( 45 ) NOT NULL, last_name VARCHAR( 45 ) NOT NULL, last_update TIMESTAMP NOT NULL DEFAULT CURRENT_TIMESTAMP, PRIMARY KEY ( actor_id ) ); CREATE TABLE address ( address_id SMALLINT UNSIGNED NOT NULL, addres...
Which language does the film AIRPORT POLLOCK use? List the language name.
SELECT T2.name FROM film AS T1 JOIN LANGUAGE AS T2 ON T1.language_id = T2.language_id WHERE T1.title = 'AIRPORT POLLOCK'
2,979
sakila_1
CREATE TABLE actor ( actor_id SMALLINT UNSIGNED NOT NULL, first_name VARCHAR( 45 ) NOT NULL, last_name VARCHAR( 45 ) NOT NULL, last_update TIMESTAMP NOT NULL DEFAULT CURRENT_TIMESTAMP, PRIMARY KEY ( actor_id ) ); CREATE TABLE address ( address_id SMALLINT UNSIGNED NOT NULL, addres...
What is the name of the language that the film 'AIRPORT POLLOCK' is in?
SELECT T2.name FROM film AS T1 JOIN LANGUAGE AS T2 ON T1.language_id = T2.language_id WHERE T1.title = 'AIRPORT POLLOCK'
2,980
sakila_1
CREATE TABLE actor ( actor_id SMALLINT UNSIGNED NOT NULL, first_name VARCHAR( 45 ) NOT NULL, last_name VARCHAR( 45 ) NOT NULL, last_update TIMESTAMP NOT NULL DEFAULT CURRENT_TIMESTAMP, PRIMARY KEY ( actor_id ) ); CREATE TABLE address ( address_id SMALLINT UNSIGNED NOT NULL, addres...
How many stores are there?
SELECT count(*) FROM store
2,981
sakila_1
CREATE TABLE actor ( actor_id SMALLINT UNSIGNED NOT NULL, first_name VARCHAR( 45 ) NOT NULL, last_name VARCHAR( 45 ) NOT NULL, last_update TIMESTAMP NOT NULL DEFAULT CURRENT_TIMESTAMP, PRIMARY KEY ( actor_id ) ); CREATE TABLE address ( address_id SMALLINT UNSIGNED NOT NULL, addres...
Count the number of stores.
SELECT count(*) FROM store
2,982
sakila_1
CREATE TABLE actor ( actor_id SMALLINT UNSIGNED NOT NULL, first_name VARCHAR( 45 ) NOT NULL, last_name VARCHAR( 45 ) NOT NULL, last_update TIMESTAMP NOT NULL DEFAULT CURRENT_TIMESTAMP, PRIMARY KEY ( actor_id ) ); CREATE TABLE address ( address_id SMALLINT UNSIGNED NOT NULL, addres...
How many kinds of different ratings are listed?
SELECT count(DISTINCT rating) FROM film
2,983
sakila_1
CREATE TABLE actor ( actor_id SMALLINT UNSIGNED NOT NULL, first_name VARCHAR( 45 ) NOT NULL, last_name VARCHAR( 45 ) NOT NULL, last_update TIMESTAMP NOT NULL DEFAULT CURRENT_TIMESTAMP, PRIMARY KEY ( actor_id ) ); CREATE TABLE address ( address_id SMALLINT UNSIGNED NOT NULL, addres...
Count the number of different film ratings.
SELECT count(DISTINCT rating) FROM film
2,984
sakila_1
CREATE TABLE actor ( actor_id SMALLINT UNSIGNED NOT NULL, first_name VARCHAR( 45 ) NOT NULL, last_name VARCHAR( 45 ) NOT NULL, last_update TIMESTAMP NOT NULL DEFAULT CURRENT_TIMESTAMP, PRIMARY KEY ( actor_id ) ); CREATE TABLE address ( address_id SMALLINT UNSIGNED NOT NULL, addres...
Which movies have 'Deleted Scenes' as a substring in the special feature?
SELECT title FROM film WHERE special_features LIKE '%Deleted Scenes%'
2,985
sakila_1
CREATE TABLE actor ( actor_id SMALLINT UNSIGNED NOT NULL, first_name VARCHAR( 45 ) NOT NULL, last_name VARCHAR( 45 ) NOT NULL, last_update TIMESTAMP NOT NULL DEFAULT CURRENT_TIMESTAMP, PRIMARY KEY ( actor_id ) ); CREATE TABLE address ( address_id SMALLINT UNSIGNED NOT NULL, addres...
Return the titles of films that include 'Deleted Scenes' in their special feature section.
SELECT title FROM film WHERE special_features LIKE '%Deleted Scenes%'
2,986
sakila_1
CREATE TABLE actor ( actor_id SMALLINT UNSIGNED NOT NULL, first_name VARCHAR( 45 ) NOT NULL, last_name VARCHAR( 45 ) NOT NULL, last_update TIMESTAMP NOT NULL DEFAULT CURRENT_TIMESTAMP, PRIMARY KEY ( actor_id ) ); CREATE TABLE address ( address_id SMALLINT UNSIGNED NOT NULL, addres...
How many items in inventory does store 1 have?
SELECT count(*) FROM inventory WHERE store_id = 1
2,987
sakila_1
CREATE TABLE actor ( actor_id SMALLINT UNSIGNED NOT NULL, first_name VARCHAR( 45 ) NOT NULL, last_name VARCHAR( 45 ) NOT NULL, last_update TIMESTAMP NOT NULL DEFAULT CURRENT_TIMESTAMP, PRIMARY KEY ( actor_id ) ); CREATE TABLE address ( address_id SMALLINT UNSIGNED NOT NULL, addres...
Count the number of items store 1 has in stock.
SELECT count(*) FROM inventory WHERE store_id = 1
2,988
sakila_1
CREATE TABLE actor ( actor_id SMALLINT UNSIGNED NOT NULL, first_name VARCHAR( 45 ) NOT NULL, last_name VARCHAR( 45 ) NOT NULL, last_update TIMESTAMP NOT NULL DEFAULT CURRENT_TIMESTAMP, PRIMARY KEY ( actor_id ) ); CREATE TABLE address ( address_id SMALLINT UNSIGNED NOT NULL, addres...
When did the first payment happen?
SELECT payment_date FROM payment ORDER BY payment_date ASC LIMIT 1
2,989
sakila_1
CREATE TABLE actor ( actor_id SMALLINT UNSIGNED NOT NULL, first_name VARCHAR( 45 ) NOT NULL, last_name VARCHAR( 45 ) NOT NULL, last_update TIMESTAMP NOT NULL DEFAULT CURRENT_TIMESTAMP, PRIMARY KEY ( actor_id ) ); CREATE TABLE address ( address_id SMALLINT UNSIGNED NOT NULL, addres...
What was the date of the earliest payment?
SELECT payment_date FROM payment ORDER BY payment_date ASC LIMIT 1
2,990
sakila_1
CREATE TABLE actor ( actor_id SMALLINT UNSIGNED NOT NULL, first_name VARCHAR( 45 ) NOT NULL, last_name VARCHAR( 45 ) NOT NULL, last_update TIMESTAMP NOT NULL DEFAULT CURRENT_TIMESTAMP, PRIMARY KEY ( actor_id ) ); CREATE TABLE address ( address_id SMALLINT UNSIGNED NOT NULL, addres...
Where does the customer with the first name Linda live? And what is her email?
SELECT T2.address , T1.email FROM customer AS T1 JOIN address AS T2 ON T2.address_id = T1.address_id WHERE T1.first_name = 'LINDA'
2,991
sakila_1
CREATE TABLE actor ( actor_id SMALLINT UNSIGNED NOT NULL, first_name VARCHAR( 45 ) NOT NULL, last_name VARCHAR( 45 ) NOT NULL, last_update TIMESTAMP NOT NULL DEFAULT CURRENT_TIMESTAMP, PRIMARY KEY ( actor_id ) ); CREATE TABLE address ( address_id SMALLINT UNSIGNED NOT NULL, addres...
Return the address and email of the customer with the first name Linda.
SELECT T2.address , T1.email FROM customer AS T1 JOIN address AS T2 ON T2.address_id = T1.address_id WHERE T1.first_name = 'LINDA'
2,992
sakila_1
CREATE TABLE actor ( actor_id SMALLINT UNSIGNED NOT NULL, first_name VARCHAR( 45 ) NOT NULL, last_name VARCHAR( 45 ) NOT NULL, last_update TIMESTAMP NOT NULL DEFAULT CURRENT_TIMESTAMP, PRIMARY KEY ( actor_id ) ); CREATE TABLE address ( address_id SMALLINT UNSIGNED NOT NULL, addres...
Find all the films longer than 100 minutes, or rated PG, except those who cost more than 200 for replacement. List the titles.
SELECT title FROM film WHERE LENGTH > 100 OR rating = 'PG' EXCEPT SELECT title FROM film WHERE replacement_cost > 200
2,993
sakila_1
CREATE TABLE actor ( actor_id SMALLINT UNSIGNED NOT NULL, first_name VARCHAR( 45 ) NOT NULL, last_name VARCHAR( 45 ) NOT NULL, last_update TIMESTAMP NOT NULL DEFAULT CURRENT_TIMESTAMP, PRIMARY KEY ( actor_id ) ); CREATE TABLE address ( address_id SMALLINT UNSIGNED NOT NULL, addres...
What are the titles of films that are either longer than 100 minutes or rated PG other than those that cost more than 200 to replace?
SELECT title FROM film WHERE LENGTH > 100 OR rating = 'PG' EXCEPT SELECT title FROM film WHERE replacement_cost > 200
2,994
sakila_1
CREATE TABLE actor ( actor_id SMALLINT UNSIGNED NOT NULL, first_name VARCHAR( 45 ) NOT NULL, last_name VARCHAR( 45 ) NOT NULL, last_update TIMESTAMP NOT NULL DEFAULT CURRENT_TIMESTAMP, PRIMARY KEY ( actor_id ) ); CREATE TABLE address ( address_id SMALLINT UNSIGNED NOT NULL, addres...
What is the first name and the last name of the customer who made the earliest rental?
SELECT T1.first_name , T1.last_name FROM customer AS T1 JOIN rental AS T2 ON T1.customer_id = T2.customer_id ORDER BY T2.rental_date ASC LIMIT 1
2,995
sakila_1
CREATE TABLE actor ( actor_id SMALLINT UNSIGNED NOT NULL, first_name VARCHAR( 45 ) NOT NULL, last_name VARCHAR( 45 ) NOT NULL, last_update TIMESTAMP NOT NULL DEFAULT CURRENT_TIMESTAMP, PRIMARY KEY ( actor_id ) ); CREATE TABLE address ( address_id SMALLINT UNSIGNED NOT NULL, addres...
Return the full name of the customer who made the first rental.
SELECT T1.first_name , T1.last_name FROM customer AS T1 JOIN rental AS T2 ON T1.customer_id = T2.customer_id ORDER BY T2.rental_date ASC LIMIT 1
2,996
sakila_1
CREATE TABLE actor ( actor_id SMALLINT UNSIGNED NOT NULL, first_name VARCHAR( 45 ) NOT NULL, last_name VARCHAR( 45 ) NOT NULL, last_update TIMESTAMP NOT NULL DEFAULT CURRENT_TIMESTAMP, PRIMARY KEY ( actor_id ) ); CREATE TABLE address ( address_id SMALLINT UNSIGNED NOT NULL, addres...
What is the full name of the staff member who has rented a film to a customer with the first name April and the last name Burns?
SELECT DISTINCT T1.first_name , T1.last_name FROM staff AS T1 JOIN rental AS T2 ON T1.staff_id = T2.staff_id JOIN customer AS T3 ON T2.customer_id = T3.customer_id WHERE T3.first_name = 'APRIL' AND T3.last_name = 'BURNS'
2,997
sakila_1
CREATE TABLE actor ( actor_id SMALLINT UNSIGNED NOT NULL, first_name VARCHAR( 45 ) NOT NULL, last_name VARCHAR( 45 ) NOT NULL, last_update TIMESTAMP NOT NULL DEFAULT CURRENT_TIMESTAMP, PRIMARY KEY ( actor_id ) ); CREATE TABLE address ( address_id SMALLINT UNSIGNED NOT NULL, addres...
Return the full name of the staff who provided a customer with the first name April and the last name Burns with a film rental.
SELECT DISTINCT T1.first_name , T1.last_name FROM staff AS T1 JOIN rental AS T2 ON T1.staff_id = T2.staff_id JOIN customer AS T3 ON T2.customer_id = T3.customer_id WHERE T3.first_name = 'APRIL' AND T3.last_name = 'BURNS'
2,998
sakila_1
CREATE TABLE actor ( actor_id SMALLINT UNSIGNED NOT NULL, first_name VARCHAR( 45 ) NOT NULL, last_name VARCHAR( 45 ) NOT NULL, last_update TIMESTAMP NOT NULL DEFAULT CURRENT_TIMESTAMP, PRIMARY KEY ( actor_id ) ); CREATE TABLE address ( address_id SMALLINT UNSIGNED NOT NULL, addres...
Which store has most the customers?
SELECT store_id FROM customer GROUP BY store_id ORDER BY count(*) DESC LIMIT 1
2,999
sakila_1
CREATE TABLE actor ( actor_id SMALLINT UNSIGNED NOT NULL, first_name VARCHAR( 45 ) NOT NULL, last_name VARCHAR( 45 ) NOT NULL, last_update TIMESTAMP NOT NULL DEFAULT CURRENT_TIMESTAMP, PRIMARY KEY ( actor_id ) ); CREATE TABLE address ( address_id SMALLINT UNSIGNED NOT NULL, addres...
Return the id of the store with the most customers.
SELECT store_id FROM customer GROUP BY store_id ORDER BY count(*) DESC LIMIT 1