id int64 0 8.66k | db_id stringclasses 146
values | schema stringclasses 146
values | question stringlengths 3 224 | output stringlengths 18 577 |
|---|---|---|---|---|
3,000 | sakila_1 | CREATE TABLE actor (
actor_id SMALLINT UNSIGNED NOT NULL,
first_name VARCHAR(
45
) NOT NULL,
last_name VARCHAR(
45
) NOT NULL,
last_update TIMESTAMP NOT NULL DEFAULT CURRENT_TIMESTAMP,
PRIMARY KEY (
actor_id
)
);
CREATE TABLE address (
address_id SMALLINT UNSIGNED NOT NULL,
addres... | What is the largest payment amount? | SELECT amount FROM payment ORDER BY amount DESC LIMIT 1 |
3,001 | sakila_1 | CREATE TABLE actor (
actor_id SMALLINT UNSIGNED NOT NULL,
first_name VARCHAR(
45
) NOT NULL,
last_name VARCHAR(
45
) NOT NULL,
last_update TIMESTAMP NOT NULL DEFAULT CURRENT_TIMESTAMP,
PRIMARY KEY (
actor_id
)
);
CREATE TABLE address (
address_id SMALLINT UNSIGNED NOT NULL,
addres... | Return the amount of the largest payment. | SELECT amount FROM payment ORDER BY amount DESC LIMIT 1 |
3,002 | sakila_1 | CREATE TABLE actor (
actor_id SMALLINT UNSIGNED NOT NULL,
first_name VARCHAR(
45
) NOT NULL,
last_name VARCHAR(
45
) NOT NULL,
last_update TIMESTAMP NOT NULL DEFAULT CURRENT_TIMESTAMP,
PRIMARY KEY (
actor_id
)
);
CREATE TABLE address (
address_id SMALLINT UNSIGNED NOT NULL,
addres... | Where does the staff member with the first name Elsa live? | SELECT T2.address FROM staff AS T1 JOIN address AS T2 ON T1.address_id = T2.address_id WHERE T1.first_name = 'Elsa' |
3,003 | sakila_1 | CREATE TABLE actor (
actor_id SMALLINT UNSIGNED NOT NULL,
first_name VARCHAR(
45
) NOT NULL,
last_name VARCHAR(
45
) NOT NULL,
last_update TIMESTAMP NOT NULL DEFAULT CURRENT_TIMESTAMP,
PRIMARY KEY (
actor_id
)
);
CREATE TABLE address (
address_id SMALLINT UNSIGNED NOT NULL,
addres... | Give the address of the staff member who has the first name Elsa. | SELECT T2.address FROM staff AS T1 JOIN address AS T2 ON T1.address_id = T2.address_id WHERE T1.first_name = 'Elsa' |
3,004 | sakila_1 | CREATE TABLE actor (
actor_id SMALLINT UNSIGNED NOT NULL,
first_name VARCHAR(
45
) NOT NULL,
last_name VARCHAR(
45
) NOT NULL,
last_update TIMESTAMP NOT NULL DEFAULT CURRENT_TIMESTAMP,
PRIMARY KEY (
actor_id
)
);
CREATE TABLE address (
address_id SMALLINT UNSIGNED NOT NULL,
addres... | What are the first names of customers who have not rented any films after '2005-08-23 02:06:01'? | SELECT first_name FROM customer WHERE customer_id NOT IN( SELECT customer_id FROM rental WHERE rental_date > '2005-08-23 02:06:01' ) |
3,005 | sakila_1 | CREATE TABLE actor (
actor_id SMALLINT UNSIGNED NOT NULL,
first_name VARCHAR(
45
) NOT NULL,
last_name VARCHAR(
45
) NOT NULL,
last_update TIMESTAMP NOT NULL DEFAULT CURRENT_TIMESTAMP,
PRIMARY KEY (
actor_id
)
);
CREATE TABLE address (
address_id SMALLINT UNSIGNED NOT NULL,
addres... | Return the first names of customers who did not rented a film after the date '2005-08-23 02:06:01'. | SELECT first_name FROM customer WHERE customer_id NOT IN( SELECT customer_id FROM rental WHERE rental_date > '2005-08-23 02:06:01' ) |
3,006 | loan_1 | CREATE TABLE bank (
branch_ID int PRIMARY KEY,
bname varchar(
20
),
no_of_customers int,
city varchar(
10
),
state varchar(
20
)
);
CREATE TABLE customer (
cust_ID varchar(
3
) PRIMARY KEY,
cust_name varchar(
20
),
acc_type char(
1
),
acc_bal int,
no_of_loans int,
credit_score int,
br... | How many bank branches are there? | SELECT count(*) FROM bank |
3,007 | loan_1 | CREATE TABLE bank (
branch_ID int PRIMARY KEY,
bname varchar(
20
),
no_of_customers int,
city varchar(
10
),
state varchar(
20
)
);
CREATE TABLE customer (
cust_ID varchar(
3
) PRIMARY KEY,
cust_name varchar(
20
),
acc_type char(
1
),
acc_bal int,
no_of_loans int,
credit_score int,
br... | Count the number of bank branches. | SELECT count(*) FROM bank |
3,008 | loan_1 | CREATE TABLE bank (
branch_ID int PRIMARY KEY,
bname varchar(
20
),
no_of_customers int,
city varchar(
10
),
state varchar(
20
)
);
CREATE TABLE customer (
cust_ID varchar(
3
) PRIMARY KEY,
cust_name varchar(
20
),
acc_type char(
1
),
acc_bal int,
no_of_loans int,
credit_score int,
br... | How many customers are there? | SELECT sum(no_of_customers) FROM bank |
3,009 | loan_1 | CREATE TABLE bank (
branch_ID int PRIMARY KEY,
bname varchar(
20
),
no_of_customers int,
city varchar(
10
),
state varchar(
20
)
);
CREATE TABLE customer (
cust_ID varchar(
3
) PRIMARY KEY,
cust_name varchar(
20
),
acc_type char(
1
),
acc_bal int,
no_of_loans int,
credit_score int,
br... | What is the total number of customers across banks? | SELECT sum(no_of_customers) FROM bank |
3,010 | loan_1 | CREATE TABLE bank (
branch_ID int PRIMARY KEY,
bname varchar(
20
),
no_of_customers int,
city varchar(
10
),
state varchar(
20
)
);
CREATE TABLE customer (
cust_ID varchar(
3
) PRIMARY KEY,
cust_name varchar(
20
),
acc_type char(
1
),
acc_bal int,
no_of_loans int,
credit_score int,
br... | Find the number of customers in the banks at New York City. | SELECT sum(no_of_customers) FROM bank WHERE city = 'New York City' |
3,011 | loan_1 | CREATE TABLE bank (
branch_ID int PRIMARY KEY,
bname varchar(
20
),
no_of_customers int,
city varchar(
10
),
state varchar(
20
)
);
CREATE TABLE customer (
cust_ID varchar(
3
) PRIMARY KEY,
cust_name varchar(
20
),
acc_type char(
1
),
acc_bal int,
no_of_loans int,
credit_score int,
br... | What is the total number of customers who use banks in New York City? | SELECT sum(no_of_customers) FROM bank WHERE city = 'New York City' |
3,012 | loan_1 | CREATE TABLE bank (
branch_ID int PRIMARY KEY,
bname varchar(
20
),
no_of_customers int,
city varchar(
10
),
state varchar(
20
)
);
CREATE TABLE customer (
cust_ID varchar(
3
) PRIMARY KEY,
cust_name varchar(
20
),
acc_type char(
1
),
acc_bal int,
no_of_loans int,
credit_score int,
br... | Find the average number of customers in all banks of Utah state. | SELECT avg(no_of_customers) FROM bank WHERE state = 'Utah' |
3,013 | loan_1 | CREATE TABLE bank (
branch_ID int PRIMARY KEY,
bname varchar(
20
),
no_of_customers int,
city varchar(
10
),
state varchar(
20
)
);
CREATE TABLE customer (
cust_ID varchar(
3
) PRIMARY KEY,
cust_name varchar(
20
),
acc_type char(
1
),
acc_bal int,
no_of_loans int,
credit_score int,
br... | What is the average number of customers across banks in the state of Utah? | SELECT avg(no_of_customers) FROM bank WHERE state = 'Utah' |
3,014 | loan_1 | CREATE TABLE bank (
branch_ID int PRIMARY KEY,
bname varchar(
20
),
no_of_customers int,
city varchar(
10
),
state varchar(
20
)
);
CREATE TABLE customer (
cust_ID varchar(
3
) PRIMARY KEY,
cust_name varchar(
20
),
acc_type char(
1
),
acc_bal int,
no_of_loans int,
credit_score int,
br... | Find the average number of customers cross all banks. | SELECT avg(no_of_customers) FROM bank |
3,015 | loan_1 | CREATE TABLE bank (
branch_ID int PRIMARY KEY,
bname varchar(
20
),
no_of_customers int,
city varchar(
10
),
state varchar(
20
)
);
CREATE TABLE customer (
cust_ID varchar(
3
) PRIMARY KEY,
cust_name varchar(
20
),
acc_type char(
1
),
acc_bal int,
no_of_loans int,
credit_score int,
br... | What is the average number of bank customers? | SELECT avg(no_of_customers) FROM bank |
3,016 | loan_1 | CREATE TABLE bank (
branch_ID int PRIMARY KEY,
bname varchar(
20
),
no_of_customers int,
city varchar(
10
),
state varchar(
20
)
);
CREATE TABLE customer (
cust_ID varchar(
3
) PRIMARY KEY,
cust_name varchar(
20
),
acc_type char(
1
),
acc_bal int,
no_of_loans int,
credit_score int,
br... | Find the city and state of the bank branch named morningside. | SELECT city , state FROM bank WHERE bname = 'morningside' |
3,017 | loan_1 | CREATE TABLE bank (
branch_ID int PRIMARY KEY,
bname varchar(
20
),
no_of_customers int,
city varchar(
10
),
state varchar(
20
)
);
CREATE TABLE customer (
cust_ID varchar(
3
) PRIMARY KEY,
cust_name varchar(
20
),
acc_type char(
1
),
acc_bal int,
no_of_loans int,
credit_score int,
br... | What city and state is the bank with the name morningside in? | SELECT city , state FROM bank WHERE bname = 'morningside' |
3,018 | loan_1 | CREATE TABLE bank (
branch_ID int PRIMARY KEY,
bname varchar(
20
),
no_of_customers int,
city varchar(
10
),
state varchar(
20
)
);
CREATE TABLE customer (
cust_ID varchar(
3
) PRIMARY KEY,
cust_name varchar(
20
),
acc_type char(
1
),
acc_bal int,
no_of_loans int,
credit_score int,
br... | Find the branch names of banks in the New York state. | SELECT bname FROM bank WHERE state = 'New York' |
3,019 | loan_1 | CREATE TABLE bank (
branch_ID int PRIMARY KEY,
bname varchar(
20
),
no_of_customers int,
city varchar(
10
),
state varchar(
20
)
);
CREATE TABLE customer (
cust_ID varchar(
3
) PRIMARY KEY,
cust_name varchar(
20
),
acc_type char(
1
),
acc_bal int,
no_of_loans int,
credit_score int,
br... | What are the names of banks in the state of New York? | SELECT bname FROM bank WHERE state = 'New York' |
3,020 | loan_1 | CREATE TABLE bank (
branch_ID int PRIMARY KEY,
bname varchar(
20
),
no_of_customers int,
city varchar(
10
),
state varchar(
20
)
);
CREATE TABLE customer (
cust_ID varchar(
3
) PRIMARY KEY,
cust_name varchar(
20
),
acc_type char(
1
),
acc_bal int,
no_of_loans int,
credit_score int,
br... | List the name of all customers sorted by their account balance in ascending order. | SELECT cust_name FROM customer ORDER BY acc_bal |
3,021 | loan_1 | CREATE TABLE bank (
branch_ID int PRIMARY KEY,
bname varchar(
20
),
no_of_customers int,
city varchar(
10
),
state varchar(
20
)
);
CREATE TABLE customer (
cust_ID varchar(
3
) PRIMARY KEY,
cust_name varchar(
20
),
acc_type char(
1
),
acc_bal int,
no_of_loans int,
credit_score int,
br... | What are the names of all customers, ordered by account balance? | SELECT cust_name FROM customer ORDER BY acc_bal |
3,022 | loan_1 | CREATE TABLE bank (
branch_ID int PRIMARY KEY,
bname varchar(
20
),
no_of_customers int,
city varchar(
10
),
state varchar(
20
)
);
CREATE TABLE customer (
cust_ID varchar(
3
) PRIMARY KEY,
cust_name varchar(
20
),
acc_type char(
1
),
acc_bal int,
no_of_loans int,
credit_score int,
br... | List the name of all different customers who have some loan sorted by their total loan amount. | SELECT T1.cust_name FROM customer AS T1 JOIN loan AS T2 ON T1.cust_id = T2.cust_id GROUP BY T1.cust_name ORDER BY sum(T2.amount) |
3,023 | loan_1 | CREATE TABLE bank (
branch_ID int PRIMARY KEY,
bname varchar(
20
),
no_of_customers int,
city varchar(
10
),
state varchar(
20
)
);
CREATE TABLE customer (
cust_ID varchar(
3
) PRIMARY KEY,
cust_name varchar(
20
),
acc_type char(
1
),
acc_bal int,
no_of_loans int,
credit_score int,
br... | What are the names of the different customers who have taken out a loan, ordered by the total amount that they have taken? | SELECT T1.cust_name FROM customer AS T1 JOIN loan AS T2 ON T1.cust_id = T2.cust_id GROUP BY T1.cust_name ORDER BY sum(T2.amount) |
3,024 | loan_1 | CREATE TABLE bank (
branch_ID int PRIMARY KEY,
bname varchar(
20
),
no_of_customers int,
city varchar(
10
),
state varchar(
20
)
);
CREATE TABLE customer (
cust_ID varchar(
3
) PRIMARY KEY,
cust_name varchar(
20
),
acc_type char(
1
),
acc_bal int,
no_of_loans int,
credit_score int,
br... | Find the state, account type, and credit score of the customer whose number of loan is 0. | SELECT state , acc_type , credit_score FROM customer WHERE no_of_loans = 0 |
3,025 | loan_1 | CREATE TABLE bank (
branch_ID int PRIMARY KEY,
bname varchar(
20
),
no_of_customers int,
city varchar(
10
),
state varchar(
20
)
);
CREATE TABLE customer (
cust_ID varchar(
3
) PRIMARY KEY,
cust_name varchar(
20
),
acc_type char(
1
),
acc_bal int,
no_of_loans int,
credit_score int,
br... | What are the states, account types, and credit scores for customers who have 0 loans? | SELECT state , acc_type , credit_score FROM customer WHERE no_of_loans = 0 |
3,026 | loan_1 | CREATE TABLE bank (
branch_ID int PRIMARY KEY,
bname varchar(
20
),
no_of_customers int,
city varchar(
10
),
state varchar(
20
)
);
CREATE TABLE customer (
cust_ID varchar(
3
) PRIMARY KEY,
cust_name varchar(
20
),
acc_type char(
1
),
acc_bal int,
no_of_loans int,
credit_score int,
br... | Find the number of different cities which banks are located at. | SELECT count(DISTINCT city) FROM bank |
3,027 | loan_1 | CREATE TABLE bank (
branch_ID int PRIMARY KEY,
bname varchar(
20
),
no_of_customers int,
city varchar(
10
),
state varchar(
20
)
);
CREATE TABLE customer (
cust_ID varchar(
3
) PRIMARY KEY,
cust_name varchar(
20
),
acc_type char(
1
),
acc_bal int,
no_of_loans int,
credit_score int,
br... | In how many different cities are banks located? | SELECT count(DISTINCT city) FROM bank |
3,028 | loan_1 | CREATE TABLE bank (
branch_ID int PRIMARY KEY,
bname varchar(
20
),
no_of_customers int,
city varchar(
10
),
state varchar(
20
)
);
CREATE TABLE customer (
cust_ID varchar(
3
) PRIMARY KEY,
cust_name varchar(
20
),
acc_type char(
1
),
acc_bal int,
no_of_loans int,
credit_score int,
br... | Find the number of different states which banks are located at. | SELECT count(DISTINCT state) FROM bank |
3,029 | loan_1 | CREATE TABLE bank (
branch_ID int PRIMARY KEY,
bname varchar(
20
),
no_of_customers int,
city varchar(
10
),
state varchar(
20
)
);
CREATE TABLE customer (
cust_ID varchar(
3
) PRIMARY KEY,
cust_name varchar(
20
),
acc_type char(
1
),
acc_bal int,
no_of_loans int,
credit_score int,
br... | In how many different states are banks located? | SELECT count(DISTINCT state) FROM bank |
3,030 | loan_1 | CREATE TABLE bank (
branch_ID int PRIMARY KEY,
bname varchar(
20
),
no_of_customers int,
city varchar(
10
),
state varchar(
20
)
);
CREATE TABLE customer (
cust_ID varchar(
3
) PRIMARY KEY,
cust_name varchar(
20
),
acc_type char(
1
),
acc_bal int,
no_of_loans int,
credit_score int,
br... | How many distinct types of accounts are there? | SELECT count(DISTINCT acc_type) FROM customer |
3,031 | loan_1 | CREATE TABLE bank (
branch_ID int PRIMARY KEY,
bname varchar(
20
),
no_of_customers int,
city varchar(
10
),
state varchar(
20
)
);
CREATE TABLE customer (
cust_ID varchar(
3
) PRIMARY KEY,
cust_name varchar(
20
),
acc_type char(
1
),
acc_bal int,
no_of_loans int,
credit_score int,
br... | Count the number of different account types. | SELECT count(DISTINCT acc_type) FROM customer |
3,032 | loan_1 | CREATE TABLE bank (
branch_ID int PRIMARY KEY,
bname varchar(
20
),
no_of_customers int,
city varchar(
10
),
state varchar(
20
)
);
CREATE TABLE customer (
cust_ID varchar(
3
) PRIMARY KEY,
cust_name varchar(
20
),
acc_type char(
1
),
acc_bal int,
no_of_loans int,
credit_score int,
br... | Find the name and account balance of the customer whose name includes the letter ‘a’. | SELECT cust_name , acc_bal FROM customer WHERE cust_name LIKE '%a%' |
3,033 | loan_1 | CREATE TABLE bank (
branch_ID int PRIMARY KEY,
bname varchar(
20
),
no_of_customers int,
city varchar(
10
),
state varchar(
20
)
);
CREATE TABLE customer (
cust_ID varchar(
3
) PRIMARY KEY,
cust_name varchar(
20
),
acc_type char(
1
),
acc_bal int,
no_of_loans int,
credit_score int,
br... | What are the names and account balances of customers with the letter a in their names? | SELECT cust_name , acc_bal FROM customer WHERE cust_name LIKE '%a%' |
3,034 | loan_1 | CREATE TABLE bank (
branch_ID int PRIMARY KEY,
bname varchar(
20
),
no_of_customers int,
city varchar(
10
),
state varchar(
20
)
);
CREATE TABLE customer (
cust_ID varchar(
3
) PRIMARY KEY,
cust_name varchar(
20
),
acc_type char(
1
),
acc_bal int,
no_of_loans int,
credit_score int,
br... | Find the total account balance of each customer from Utah or Texas. | SELECT sum(acc_bal) FROM customer WHERE state = 'Utah' OR state = 'Texas' |
3,035 | loan_1 | CREATE TABLE bank (
branch_ID int PRIMARY KEY,
bname varchar(
20
),
no_of_customers int,
city varchar(
10
),
state varchar(
20
)
);
CREATE TABLE customer (
cust_ID varchar(
3
) PRIMARY KEY,
cust_name varchar(
20
),
acc_type char(
1
),
acc_bal int,
no_of_loans int,
credit_score int,
br... | What are the total account balances for each customer from Utah or Texas? | SELECT sum(acc_bal) FROM customer WHERE state = 'Utah' OR state = 'Texas' |
3,036 | loan_1 | CREATE TABLE bank (
branch_ID int PRIMARY KEY,
bname varchar(
20
),
no_of_customers int,
city varchar(
10
),
state varchar(
20
)
);
CREATE TABLE customer (
cust_ID varchar(
3
) PRIMARY KEY,
cust_name varchar(
20
),
acc_type char(
1
),
acc_bal int,
no_of_loans int,
credit_score int,
br... | Find the name of customers who have both saving and checking account types. | SELECT cust_name FROM customer WHERE acc_type = 'saving' INTERSECT SELECT cust_name FROM customer WHERE acc_type = 'checking' |
3,037 | loan_1 | CREATE TABLE bank (
branch_ID int PRIMARY KEY,
bname varchar(
20
),
no_of_customers int,
city varchar(
10
),
state varchar(
20
)
);
CREATE TABLE customer (
cust_ID varchar(
3
) PRIMARY KEY,
cust_name varchar(
20
),
acc_type char(
1
),
acc_bal int,
no_of_loans int,
credit_score int,
br... | What are the names of customers who have both savings and checking accounts? | SELECT cust_name FROM customer WHERE acc_type = 'saving' INTERSECT SELECT cust_name FROM customer WHERE acc_type = 'checking' |
3,038 | loan_1 | CREATE TABLE bank (
branch_ID int PRIMARY KEY,
bname varchar(
20
),
no_of_customers int,
city varchar(
10
),
state varchar(
20
)
);
CREATE TABLE customer (
cust_ID varchar(
3
) PRIMARY KEY,
cust_name varchar(
20
),
acc_type char(
1
),
acc_bal int,
no_of_loans int,
credit_score int,
br... | Find the name of customers who do not have an saving account. | SELECT cust_name FROM customer EXCEPT SELECT cust_name FROM customer WHERE acc_type = 'saving' |
3,039 | loan_1 | CREATE TABLE bank (
branch_ID int PRIMARY KEY,
bname varchar(
20
),
no_of_customers int,
city varchar(
10
),
state varchar(
20
)
);
CREATE TABLE customer (
cust_ID varchar(
3
) PRIMARY KEY,
cust_name varchar(
20
),
acc_type char(
1
),
acc_bal int,
no_of_loans int,
credit_score int,
br... | What are the names of customers who do not have saving accounts? | SELECT cust_name FROM customer EXCEPT SELECT cust_name FROM customer WHERE acc_type = 'saving' |
3,040 | loan_1 | CREATE TABLE bank (
branch_ID int PRIMARY KEY,
bname varchar(
20
),
no_of_customers int,
city varchar(
10
),
state varchar(
20
)
);
CREATE TABLE customer (
cust_ID varchar(
3
) PRIMARY KEY,
cust_name varchar(
20
),
acc_type char(
1
),
acc_bal int,
no_of_loans int,
credit_score int,
br... | Find the name of customers who do not have a loan with a type of Mortgages. | SELECT cust_name FROM customer EXCEPT SELECT T1.cust_name FROM customer AS T1 JOIN loan AS T2 ON T1.cust_id = T2.cust_id WHERE T2.loan_type = 'Mortgages' |
3,041 | loan_1 | CREATE TABLE bank (
branch_ID int PRIMARY KEY,
bname varchar(
20
),
no_of_customers int,
city varchar(
10
),
state varchar(
20
)
);
CREATE TABLE customer (
cust_ID varchar(
3
) PRIMARY KEY,
cust_name varchar(
20
),
acc_type char(
1
),
acc_bal int,
no_of_loans int,
credit_score int,
br... | What are the names of customers who have not taken a Mortage loan? | SELECT cust_name FROM customer EXCEPT SELECT T1.cust_name FROM customer AS T1 JOIN loan AS T2 ON T1.cust_id = T2.cust_id WHERE T2.loan_type = 'Mortgages' |
3,042 | loan_1 | CREATE TABLE bank (
branch_ID int PRIMARY KEY,
bname varchar(
20
),
no_of_customers int,
city varchar(
10
),
state varchar(
20
)
);
CREATE TABLE customer (
cust_ID varchar(
3
) PRIMARY KEY,
cust_name varchar(
20
),
acc_type char(
1
),
acc_bal int,
no_of_loans int,
credit_score int,
br... | Find the name of customers who have loans of both Mortgages and Auto. | SELECT T1.cust_name FROM customer AS T1 JOIN loan AS T2 ON T1.cust_id = T2.cust_id WHERE loan_type = 'Mortgages' INTERSECT SELECT T1.cust_name FROM customer AS T1 JOIN loan AS T2 ON T1.cust_id = T2.cust_id WHERE loan_type = 'Auto' |
3,043 | loan_1 | CREATE TABLE bank (
branch_ID int PRIMARY KEY,
bname varchar(
20
),
no_of_customers int,
city varchar(
10
),
state varchar(
20
)
);
CREATE TABLE customer (
cust_ID varchar(
3
) PRIMARY KEY,
cust_name varchar(
20
),
acc_type char(
1
),
acc_bal int,
no_of_loans int,
credit_score int,
br... | What are the names of customers who have taken both Mortgage and Auto loans? | SELECT T1.cust_name FROM customer AS T1 JOIN loan AS T2 ON T1.cust_id = T2.cust_id WHERE loan_type = 'Mortgages' INTERSECT SELECT T1.cust_name FROM customer AS T1 JOIN loan AS T2 ON T1.cust_id = T2.cust_id WHERE loan_type = 'Auto' |
3,044 | loan_1 | CREATE TABLE bank (
branch_ID int PRIMARY KEY,
bname varchar(
20
),
no_of_customers int,
city varchar(
10
),
state varchar(
20
)
);
CREATE TABLE customer (
cust_ID varchar(
3
) PRIMARY KEY,
cust_name varchar(
20
),
acc_type char(
1
),
acc_bal int,
no_of_loans int,
credit_score int,
br... | Find the name of customers whose credit score is below the average credit scores of all customers. | SELECT cust_name FROM customer WHERE credit_score < (SELECT avg(credit_score) FROM customer) |
3,045 | loan_1 | CREATE TABLE bank (
branch_ID int PRIMARY KEY,
bname varchar(
20
),
no_of_customers int,
city varchar(
10
),
state varchar(
20
)
);
CREATE TABLE customer (
cust_ID varchar(
3
) PRIMARY KEY,
cust_name varchar(
20
),
acc_type char(
1
),
acc_bal int,
no_of_loans int,
credit_score int,
br... | What are the names of customers with credit score less than the average credit score across customers? | SELECT cust_name FROM customer WHERE credit_score < (SELECT avg(credit_score) FROM customer) |
3,046 | loan_1 | CREATE TABLE bank (
branch_ID int PRIMARY KEY,
bname varchar(
20
),
no_of_customers int,
city varchar(
10
),
state varchar(
20
)
);
CREATE TABLE customer (
cust_ID varchar(
3
) PRIMARY KEY,
cust_name varchar(
20
),
acc_type char(
1
),
acc_bal int,
no_of_loans int,
credit_score int,
br... | Find the branch name of the bank that has the most number of customers. | SELECT bname FROM bank ORDER BY no_of_customers DESC LIMIT 1 |
3,047 | loan_1 | CREATE TABLE bank (
branch_ID int PRIMARY KEY,
bname varchar(
20
),
no_of_customers int,
city varchar(
10
),
state varchar(
20
)
);
CREATE TABLE customer (
cust_ID varchar(
3
) PRIMARY KEY,
cust_name varchar(
20
),
acc_type char(
1
),
acc_bal int,
no_of_loans int,
credit_score int,
br... | What is the name of the bank branch with the greatest number of customers? | SELECT bname FROM bank ORDER BY no_of_customers DESC LIMIT 1 |
3,048 | loan_1 | CREATE TABLE bank (
branch_ID int PRIMARY KEY,
bname varchar(
20
),
no_of_customers int,
city varchar(
10
),
state varchar(
20
)
);
CREATE TABLE customer (
cust_ID varchar(
3
) PRIMARY KEY,
cust_name varchar(
20
),
acc_type char(
1
),
acc_bal int,
no_of_loans int,
credit_score int,
br... | Find the name of customer who has the lowest credit score. | SELECT cust_name FROM customer ORDER BY credit_score LIMIT 1 |
3,049 | loan_1 | CREATE TABLE bank (
branch_ID int PRIMARY KEY,
bname varchar(
20
),
no_of_customers int,
city varchar(
10
),
state varchar(
20
)
);
CREATE TABLE customer (
cust_ID varchar(
3
) PRIMARY KEY,
cust_name varchar(
20
),
acc_type char(
1
),
acc_bal int,
no_of_loans int,
credit_score int,
br... | What is the name of the customer with the worst credit score? | SELECT cust_name FROM customer ORDER BY credit_score LIMIT 1 |
3,050 | loan_1 | CREATE TABLE bank (
branch_ID int PRIMARY KEY,
bname varchar(
20
),
no_of_customers int,
city varchar(
10
),
state varchar(
20
)
);
CREATE TABLE customer (
cust_ID varchar(
3
) PRIMARY KEY,
cust_name varchar(
20
),
acc_type char(
1
),
acc_bal int,
no_of_loans int,
credit_score int,
br... | Find the name, account type, and account balance of the customer who has the highest credit score. | SELECT cust_name , acc_type , acc_bal FROM customer ORDER BY credit_score DESC LIMIT 1 |
3,051 | loan_1 | CREATE TABLE bank (
branch_ID int PRIMARY KEY,
bname varchar(
20
),
no_of_customers int,
city varchar(
10
),
state varchar(
20
)
);
CREATE TABLE customer (
cust_ID varchar(
3
) PRIMARY KEY,
cust_name varchar(
20
),
acc_type char(
1
),
acc_bal int,
no_of_loans int,
credit_score int,
br... | What is the name, account type, and account balance corresponding to the customer with the highest credit score? | SELECT cust_name , acc_type , acc_bal FROM customer ORDER BY credit_score DESC LIMIT 1 |
3,052 | loan_1 | CREATE TABLE bank (
branch_ID int PRIMARY KEY,
bname varchar(
20
),
no_of_customers int,
city varchar(
10
),
state varchar(
20
)
);
CREATE TABLE customer (
cust_ID varchar(
3
) PRIMARY KEY,
cust_name varchar(
20
),
acc_type char(
1
),
acc_bal int,
no_of_loans int,
credit_score int,
br... | Find the name of customer who has the highest amount of loans. | SELECT T1.cust_name FROM customer AS T1 JOIN loan AS T2 ON T1.cust_id = T2.cust_id GROUP BY T1.cust_name ORDER BY sum(T2.amount) DESC LIMIT 1 |
3,053 | loan_1 | CREATE TABLE bank (
branch_ID int PRIMARY KEY,
bname varchar(
20
),
no_of_customers int,
city varchar(
10
),
state varchar(
20
)
);
CREATE TABLE customer (
cust_ID varchar(
3
) PRIMARY KEY,
cust_name varchar(
20
),
acc_type char(
1
),
acc_bal int,
no_of_loans int,
credit_score int,
br... | What is the name of the customer who has greatest total loan amount? | SELECT T1.cust_name FROM customer AS T1 JOIN loan AS T2 ON T1.cust_id = T2.cust_id GROUP BY T1.cust_name ORDER BY sum(T2.amount) DESC LIMIT 1 |
3,054 | loan_1 | CREATE TABLE bank (
branch_ID int PRIMARY KEY,
bname varchar(
20
),
no_of_customers int,
city varchar(
10
),
state varchar(
20
)
);
CREATE TABLE customer (
cust_ID varchar(
3
) PRIMARY KEY,
cust_name varchar(
20
),
acc_type char(
1
),
acc_bal int,
no_of_loans int,
credit_score int,
br... | Find the state which has the most number of customers. | SELECT state FROM bank GROUP BY state ORDER BY sum(no_of_customers) DESC LIMIT 1 |
3,055 | loan_1 | CREATE TABLE bank (
branch_ID int PRIMARY KEY,
bname varchar(
20
),
no_of_customers int,
city varchar(
10
),
state varchar(
20
)
);
CREATE TABLE customer (
cust_ID varchar(
3
) PRIMARY KEY,
cust_name varchar(
20
),
acc_type char(
1
),
acc_bal int,
no_of_loans int,
credit_score int,
br... | Which state has the greatest total number of bank customers? | SELECT state FROM bank GROUP BY state ORDER BY sum(no_of_customers) DESC LIMIT 1 |
3,056 | loan_1 | CREATE TABLE bank (
branch_ID int PRIMARY KEY,
bname varchar(
20
),
no_of_customers int,
city varchar(
10
),
state varchar(
20
)
);
CREATE TABLE customer (
cust_ID varchar(
3
) PRIMARY KEY,
cust_name varchar(
20
),
acc_type char(
1
),
acc_bal int,
no_of_loans int,
credit_score int,
br... | For each account type, find the average account balance of customers with credit score lower than 50. | SELECT avg(acc_bal) , acc_type FROM customer WHERE credit_score < 50 GROUP BY acc_type |
3,057 | loan_1 | CREATE TABLE bank (
branch_ID int PRIMARY KEY,
bname varchar(
20
),
no_of_customers int,
city varchar(
10
),
state varchar(
20
)
);
CREATE TABLE customer (
cust_ID varchar(
3
) PRIMARY KEY,
cust_name varchar(
20
),
acc_type char(
1
),
acc_bal int,
no_of_loans int,
credit_score int,
br... | What is the average account balance of customers with credit score below 50 for the different account types? | SELECT avg(acc_bal) , acc_type FROM customer WHERE credit_score < 50 GROUP BY acc_type |
3,058 | loan_1 | CREATE TABLE bank (
branch_ID int PRIMARY KEY,
bname varchar(
20
),
no_of_customers int,
city varchar(
10
),
state varchar(
20
)
);
CREATE TABLE customer (
cust_ID varchar(
3
) PRIMARY KEY,
cust_name varchar(
20
),
acc_type char(
1
),
acc_bal int,
no_of_loans int,
credit_score int,
br... | For each state, find the total account balance of customers whose credit score is above 100. | SELECT sum(acc_bal) , state FROM customer WHERE credit_score > 100 GROUP BY state |
3,059 | loan_1 | CREATE TABLE bank (
branch_ID int PRIMARY KEY,
bname varchar(
20
),
no_of_customers int,
city varchar(
10
),
state varchar(
20
)
);
CREATE TABLE customer (
cust_ID varchar(
3
) PRIMARY KEY,
cust_name varchar(
20
),
acc_type char(
1
),
acc_bal int,
no_of_loans int,
credit_score int,
br... | What is the total account balance for customers with a credit score of above 100 for the different states? | SELECT sum(acc_bal) , state FROM customer WHERE credit_score > 100 GROUP BY state |
3,060 | loan_1 | CREATE TABLE bank (
branch_ID int PRIMARY KEY,
bname varchar(
20
),
no_of_customers int,
city varchar(
10
),
state varchar(
20
)
);
CREATE TABLE customer (
cust_ID varchar(
3
) PRIMARY KEY,
cust_name varchar(
20
),
acc_type char(
1
),
acc_bal int,
no_of_loans int,
credit_score int,
br... | Find the total amount of loans offered by each bank branch. | SELECT sum(amount) , T1.bname FROM bank AS T1 JOIN loan AS T2 ON T1.branch_id = T2.branch_id GROUP BY T1.bname |
3,061 | loan_1 | CREATE TABLE bank (
branch_ID int PRIMARY KEY,
bname varchar(
20
),
no_of_customers int,
city varchar(
10
),
state varchar(
20
)
);
CREATE TABLE customer (
cust_ID varchar(
3
) PRIMARY KEY,
cust_name varchar(
20
),
acc_type char(
1
),
acc_bal int,
no_of_loans int,
credit_score int,
br... | What are the names of the different bank branches, and what are their total loan amounts? | SELECT sum(amount) , T1.bname FROM bank AS T1 JOIN loan AS T2 ON T1.branch_id = T2.branch_id GROUP BY T1.bname |
3,062 | loan_1 | CREATE TABLE bank (
branch_ID int PRIMARY KEY,
bname varchar(
20
),
no_of_customers int,
city varchar(
10
),
state varchar(
20
)
);
CREATE TABLE customer (
cust_ID varchar(
3
) PRIMARY KEY,
cust_name varchar(
20
),
acc_type char(
1
),
acc_bal int,
no_of_loans int,
credit_score int,
br... | Find the name of customers who have more than one loan. | SELECT T1.cust_name FROM customer AS T1 JOIN loan AS T2 ON T1.cust_id = T2.cust_id GROUP BY T1.cust_name HAVING count(*) > 1 |
3,063 | loan_1 | CREATE TABLE bank (
branch_ID int PRIMARY KEY,
bname varchar(
20
),
no_of_customers int,
city varchar(
10
),
state varchar(
20
)
);
CREATE TABLE customer (
cust_ID varchar(
3
) PRIMARY KEY,
cust_name varchar(
20
),
acc_type char(
1
),
acc_bal int,
no_of_loans int,
credit_score int,
br... | What are the names of customers who have taken out more than one loan? | SELECT T1.cust_name FROM customer AS T1 JOIN loan AS T2 ON T1.cust_id = T2.cust_id GROUP BY T1.cust_name HAVING count(*) > 1 |
3,064 | loan_1 | CREATE TABLE bank (
branch_ID int PRIMARY KEY,
bname varchar(
20
),
no_of_customers int,
city varchar(
10
),
state varchar(
20
)
);
CREATE TABLE customer (
cust_ID varchar(
3
) PRIMARY KEY,
cust_name varchar(
20
),
acc_type char(
1
),
acc_bal int,
no_of_loans int,
credit_score int,
br... | Find the name and account balance of the customers who have loans with a total amount of more than 5000. | SELECT T1.cust_name , T1.acc_type FROM customer AS T1 JOIN loan AS T2 ON T1.cust_id = T2.cust_id GROUP BY T1.cust_name HAVING sum(T2.amount) > 5000 |
3,065 | loan_1 | CREATE TABLE bank (
branch_ID int PRIMARY KEY,
bname varchar(
20
),
no_of_customers int,
city varchar(
10
),
state varchar(
20
)
);
CREATE TABLE customer (
cust_ID varchar(
3
) PRIMARY KEY,
cust_name varchar(
20
),
acc_type char(
1
),
acc_bal int,
no_of_loans int,
credit_score int,
br... | What are the names and account balances for customers who have taken a total amount of more than 5000 in loans? | SELECT T1.cust_name , T1.acc_type FROM customer AS T1 JOIN loan AS T2 ON T1.cust_id = T2.cust_id GROUP BY T1.cust_name HAVING sum(T2.amount) > 5000 |
3,066 | loan_1 | CREATE TABLE bank (
branch_ID int PRIMARY KEY,
bname varchar(
20
),
no_of_customers int,
city varchar(
10
),
state varchar(
20
)
);
CREATE TABLE customer (
cust_ID varchar(
3
) PRIMARY KEY,
cust_name varchar(
20
),
acc_type char(
1
),
acc_bal int,
no_of_loans int,
credit_score int,
br... | Find the name of bank branch that provided the greatest total amount of loans. | SELECT T1.bname FROM bank AS T1 JOIN loan AS T2 ON T1.branch_id = T2.branch_id GROUP BY T1.bname ORDER BY sum(T2.amount) DESC LIMIT 1 |
3,067 | loan_1 | CREATE TABLE bank (
branch_ID int PRIMARY KEY,
bname varchar(
20
),
no_of_customers int,
city varchar(
10
),
state varchar(
20
)
);
CREATE TABLE customer (
cust_ID varchar(
3
) PRIMARY KEY,
cust_name varchar(
20
),
acc_type char(
1
),
acc_bal int,
no_of_loans int,
credit_score int,
br... | What is the name of the bank branch that has lent the greatest amount? | SELECT T1.bname FROM bank AS T1 JOIN loan AS T2 ON T1.branch_id = T2.branch_id GROUP BY T1.bname ORDER BY sum(T2.amount) DESC LIMIT 1 |
3,068 | loan_1 | CREATE TABLE bank (
branch_ID int PRIMARY KEY,
bname varchar(
20
),
no_of_customers int,
city varchar(
10
),
state varchar(
20
)
);
CREATE TABLE customer (
cust_ID varchar(
3
) PRIMARY KEY,
cust_name varchar(
20
),
acc_type char(
1
),
acc_bal int,
no_of_loans int,
credit_score int,
br... | Find the name of bank branch that provided the greatest total amount of loans to customers with credit score is less than 100. | SELECT T2.bname FROM loan AS T1 JOIN bank AS T2 ON T1.branch_id = T2.branch_id JOIN customer AS T3 ON T1.cust_id = T3.cust_id WHERE T3.credit_score < 100 GROUP BY T2.bname ORDER BY sum(T1.amount) DESC LIMIT 1 |
3,069 | loan_1 | CREATE TABLE bank (
branch_ID int PRIMARY KEY,
bname varchar(
20
),
no_of_customers int,
city varchar(
10
),
state varchar(
20
)
);
CREATE TABLE customer (
cust_ID varchar(
3
) PRIMARY KEY,
cust_name varchar(
20
),
acc_type char(
1
),
acc_bal int,
no_of_loans int,
credit_score int,
br... | What is the name of the bank branch that has lended the largest total amount in loans, specifically to customers with credit scores below 100? | SELECT T2.bname FROM loan AS T1 JOIN bank AS T2 ON T1.branch_id = T2.branch_id JOIN customer AS T3 ON T1.cust_id = T3.cust_id WHERE T3.credit_score < 100 GROUP BY T2.bname ORDER BY sum(T1.amount) DESC LIMIT 1 |
3,070 | loan_1 | CREATE TABLE bank (
branch_ID int PRIMARY KEY,
bname varchar(
20
),
no_of_customers int,
city varchar(
10
),
state varchar(
20
)
);
CREATE TABLE customer (
cust_ID varchar(
3
) PRIMARY KEY,
cust_name varchar(
20
),
acc_type char(
1
),
acc_bal int,
no_of_loans int,
credit_score int,
br... | Find the name of bank branches that provided some loans. | SELECT DISTINCT T1.bname FROM bank AS T1 JOIN loan AS T2 ON T1.branch_id = T2.branch_id |
3,071 | loan_1 | CREATE TABLE bank (
branch_ID int PRIMARY KEY,
bname varchar(
20
),
no_of_customers int,
city varchar(
10
),
state varchar(
20
)
);
CREATE TABLE customer (
cust_ID varchar(
3
) PRIMARY KEY,
cust_name varchar(
20
),
acc_type char(
1
),
acc_bal int,
no_of_loans int,
credit_score int,
br... | What are the names of the different banks that have provided loans? | SELECT DISTINCT T1.bname FROM bank AS T1 JOIN loan AS T2 ON T1.branch_id = T2.branch_id |
3,072 | loan_1 | CREATE TABLE bank (
branch_ID int PRIMARY KEY,
bname varchar(
20
),
no_of_customers int,
city varchar(
10
),
state varchar(
20
)
);
CREATE TABLE customer (
cust_ID varchar(
3
) PRIMARY KEY,
cust_name varchar(
20
),
acc_type char(
1
),
acc_bal int,
no_of_loans int,
credit_score int,
br... | Find the name and credit score of the customers who have some loans. | SELECT DISTINCT T1.cust_name , T1.credit_score FROM customer AS T1 JOIN loan AS T2 ON T1.cust_id = T2.cust_id |
3,073 | loan_1 | CREATE TABLE bank (
branch_ID int PRIMARY KEY,
bname varchar(
20
),
no_of_customers int,
city varchar(
10
),
state varchar(
20
)
);
CREATE TABLE customer (
cust_ID varchar(
3
) PRIMARY KEY,
cust_name varchar(
20
),
acc_type char(
1
),
acc_bal int,
no_of_loans int,
credit_score int,
br... | What are the different names and credit scores of customers who have taken a loan? | SELECT DISTINCT T1.cust_name , T1.credit_score FROM customer AS T1 JOIN loan AS T2 ON T1.cust_id = T2.cust_id |
3,074 | loan_1 | CREATE TABLE bank (
branch_ID int PRIMARY KEY,
bname varchar(
20
),
no_of_customers int,
city varchar(
10
),
state varchar(
20
)
);
CREATE TABLE customer (
cust_ID varchar(
3
) PRIMARY KEY,
cust_name varchar(
20
),
acc_type char(
1
),
acc_bal int,
no_of_loans int,
credit_score int,
br... | Find the the name of the customers who have a loan with amount more than 3000. | SELECT T1.cust_name FROM customer AS T1 JOIN loan AS T2 ON T1.cust_id = T2.cust_id WHERE amount > 3000 |
3,075 | loan_1 | CREATE TABLE bank (
branch_ID int PRIMARY KEY,
bname varchar(
20
),
no_of_customers int,
city varchar(
10
),
state varchar(
20
)
);
CREATE TABLE customer (
cust_ID varchar(
3
) PRIMARY KEY,
cust_name varchar(
20
),
acc_type char(
1
),
acc_bal int,
no_of_loans int,
credit_score int,
br... | What are the names of customers who have a loan of more than 3000 in amount? | SELECT T1.cust_name FROM customer AS T1 JOIN loan AS T2 ON T1.cust_id = T2.cust_id WHERE amount > 3000 |
3,076 | loan_1 | CREATE TABLE bank (
branch_ID int PRIMARY KEY,
bname varchar(
20
),
no_of_customers int,
city varchar(
10
),
state varchar(
20
)
);
CREATE TABLE customer (
cust_ID varchar(
3
) PRIMARY KEY,
cust_name varchar(
20
),
acc_type char(
1
),
acc_bal int,
no_of_loans int,
credit_score int,
br... | Find the city and name of bank branches that provide business loans. | SELECT T1.bname , T1.city FROM bank AS T1 JOIN loan AS T2 ON T1.branch_id = T2.branch_id WHERE T2.loan_type = 'Business' |
3,077 | loan_1 | CREATE TABLE bank (
branch_ID int PRIMARY KEY,
bname varchar(
20
),
no_of_customers int,
city varchar(
10
),
state varchar(
20
)
);
CREATE TABLE customer (
cust_ID varchar(
3
) PRIMARY KEY,
cust_name varchar(
20
),
acc_type char(
1
),
acc_bal int,
no_of_loans int,
credit_score int,
br... | What are the names and cities of bank branches that offer loans for business? | SELECT T1.bname , T1.city FROM bank AS T1 JOIN loan AS T2 ON T1.branch_id = T2.branch_id WHERE T2.loan_type = 'Business' |
3,078 | loan_1 | CREATE TABLE bank (
branch_ID int PRIMARY KEY,
bname varchar(
20
),
no_of_customers int,
city varchar(
10
),
state varchar(
20
)
);
CREATE TABLE customer (
cust_ID varchar(
3
) PRIMARY KEY,
cust_name varchar(
20
),
acc_type char(
1
),
acc_bal int,
no_of_loans int,
credit_score int,
br... | Find the names of bank branches that have provided a loan to any customer whose credit score is below 100. | SELECT T2.bname FROM loan AS T1 JOIN bank AS T2 ON T1.branch_id = T2.branch_id JOIN customer AS T3 ON T1.cust_id = T3.cust_id WHERE T3.credit_score < 100 |
3,079 | loan_1 | CREATE TABLE bank (
branch_ID int PRIMARY KEY,
bname varchar(
20
),
no_of_customers int,
city varchar(
10
),
state varchar(
20
)
);
CREATE TABLE customer (
cust_ID varchar(
3
) PRIMARY KEY,
cust_name varchar(
20
),
acc_type char(
1
),
acc_bal int,
no_of_loans int,
credit_score int,
br... | What are the names of banks that have loaned money to customers with credit scores below 100? | SELECT T2.bname FROM loan AS T1 JOIN bank AS T2 ON T1.branch_id = T2.branch_id JOIN customer AS T3 ON T1.cust_id = T3.cust_id WHERE T3.credit_score < 100 |
3,080 | loan_1 | CREATE TABLE bank (
branch_ID int PRIMARY KEY,
bname varchar(
20
),
no_of_customers int,
city varchar(
10
),
state varchar(
20
)
);
CREATE TABLE customer (
cust_ID varchar(
3
) PRIMARY KEY,
cust_name varchar(
20
),
acc_type char(
1
),
acc_bal int,
no_of_loans int,
credit_score int,
br... | Find the total amount of loans provided by bank branches in the state of New York. | SELECT sum(T2.amount) FROM bank AS T1 JOIN loan AS T2 ON T1.branch_id = T2.branch_id WHERE T1.state = 'New York' |
3,081 | loan_1 | CREATE TABLE bank (
branch_ID int PRIMARY KEY,
bname varchar(
20
),
no_of_customers int,
city varchar(
10
),
state varchar(
20
)
);
CREATE TABLE customer (
cust_ID varchar(
3
) PRIMARY KEY,
cust_name varchar(
20
),
acc_type char(
1
),
acc_bal int,
no_of_loans int,
credit_score int,
br... | What is the total amount of money loaned by banks in New York state? | SELECT sum(T2.amount) FROM bank AS T1 JOIN loan AS T2 ON T1.branch_id = T2.branch_id WHERE T1.state = 'New York' |
3,082 | loan_1 | CREATE TABLE bank (
branch_ID int PRIMARY KEY,
bname varchar(
20
),
no_of_customers int,
city varchar(
10
),
state varchar(
20
)
);
CREATE TABLE customer (
cust_ID varchar(
3
) PRIMARY KEY,
cust_name varchar(
20
),
acc_type char(
1
),
acc_bal int,
no_of_loans int,
credit_score int,
br... | Find the average credit score of the customers who have some loan. | SELECT avg(credit_score) FROM customer WHERE cust_id IN (SELECT cust_id FROM loan) |
3,083 | loan_1 | CREATE TABLE bank (
branch_ID int PRIMARY KEY,
bname varchar(
20
),
no_of_customers int,
city varchar(
10
),
state varchar(
20
)
);
CREATE TABLE customer (
cust_ID varchar(
3
) PRIMARY KEY,
cust_name varchar(
20
),
acc_type char(
1
),
acc_bal int,
no_of_loans int,
credit_score int,
br... | What is the average credit score for customers who have taken a loan? | SELECT avg(credit_score) FROM customer WHERE cust_id IN (SELECT cust_id FROM loan) |
3,084 | loan_1 | CREATE TABLE bank (
branch_ID int PRIMARY KEY,
bname varchar(
20
),
no_of_customers int,
city varchar(
10
),
state varchar(
20
)
);
CREATE TABLE customer (
cust_ID varchar(
3
) PRIMARY KEY,
cust_name varchar(
20
),
acc_type char(
1
),
acc_bal int,
no_of_loans int,
credit_score int,
br... | Find the average credit score of the customers who do not have any loan. | SELECT avg(credit_score) FROM customer WHERE cust_id NOT IN (SELECT cust_id FROM loan) |
3,085 | loan_1 | CREATE TABLE bank (
branch_ID int PRIMARY KEY,
bname varchar(
20
),
no_of_customers int,
city varchar(
10
),
state varchar(
20
)
);
CREATE TABLE customer (
cust_ID varchar(
3
) PRIMARY KEY,
cust_name varchar(
20
),
acc_type char(
1
),
acc_bal int,
no_of_loans int,
credit_score int,
br... | What is the average credit score for customers who have never taken a loan? | SELECT avg(credit_score) FROM customer WHERE cust_id NOT IN (SELECT cust_id FROM loan) |
3,086 | behavior_monitoring | CREATE TABLE `Ref_Address_Types` (
`address_type_code` VARCHAR(
15
) PRIMARY KEY,
`address_type_description` VARCHAR(
80
)
);
CREATE TABLE `Ref_Detention_Type` (
`detention_type_code` VARCHAR(
10
) PRIMARY KEY,
`detention_type_description` VARCHAR(
80
)
);
CREATE TABLE `Ref_Incident_Type` ... | How many assessment notes are there in total? | SELECT count(*) FROM ASSESSMENT_NOTES |
3,087 | behavior_monitoring | CREATE TABLE `Ref_Address_Types` (
`address_type_code` VARCHAR(
15
) PRIMARY KEY,
`address_type_description` VARCHAR(
80
)
);
CREATE TABLE `Ref_Detention_Type` (
`detention_type_code` VARCHAR(
10
) PRIMARY KEY,
`detention_type_description` VARCHAR(
80
)
);
CREATE TABLE `Ref_Incident_Type` ... | What are the dates of the assessment notes? | SELECT date_of_notes FROM Assessment_Notes |
3,088 | behavior_monitoring | CREATE TABLE `Ref_Address_Types` (
`address_type_code` VARCHAR(
15
) PRIMARY KEY,
`address_type_description` VARCHAR(
80
)
);
CREATE TABLE `Ref_Detention_Type` (
`detention_type_code` VARCHAR(
10
) PRIMARY KEY,
`detention_type_description` VARCHAR(
80
)
);
CREATE TABLE `Ref_Incident_Type` ... | How many addresses have zip code 197? | SELECT count(*) FROM ADDRESSES WHERE zip_postcode = "197" |
3,089 | behavior_monitoring | CREATE TABLE `Ref_Address_Types` (
`address_type_code` VARCHAR(
15
) PRIMARY KEY,
`address_type_description` VARCHAR(
80
)
);
CREATE TABLE `Ref_Detention_Type` (
`detention_type_code` VARCHAR(
10
) PRIMARY KEY,
`detention_type_description` VARCHAR(
80
)
);
CREATE TABLE `Ref_Incident_Type` ... | How many distinct incident type codes are there? | SELECT count(DISTINCT incident_type_code) FROM Behavior_Incident |
3,090 | behavior_monitoring | CREATE TABLE `Ref_Address_Types` (
`address_type_code` VARCHAR(
15
) PRIMARY KEY,
`address_type_description` VARCHAR(
80
)
);
CREATE TABLE `Ref_Detention_Type` (
`detention_type_code` VARCHAR(
10
) PRIMARY KEY,
`detention_type_description` VARCHAR(
80
)
);
CREATE TABLE `Ref_Incident_Type` ... | Return all distinct detention type codes. | SELECT DISTINCT detention_type_code FROM Detention |
3,091 | behavior_monitoring | CREATE TABLE `Ref_Address_Types` (
`address_type_code` VARCHAR(
15
) PRIMARY KEY,
`address_type_description` VARCHAR(
80
)
);
CREATE TABLE `Ref_Detention_Type` (
`detention_type_code` VARCHAR(
10
) PRIMARY KEY,
`detention_type_description` VARCHAR(
80
)
);
CREATE TABLE `Ref_Incident_Type` ... | What are the start and end dates for incidents with incident type code "NOISE"? | SELECT date_incident_start , date_incident_end FROM Behavior_Incident WHERE incident_type_code = "NOISE" |
3,092 | behavior_monitoring | CREATE TABLE `Ref_Address_Types` (
`address_type_code` VARCHAR(
15
) PRIMARY KEY,
`address_type_description` VARCHAR(
80
)
);
CREATE TABLE `Ref_Detention_Type` (
`detention_type_code` VARCHAR(
10
) PRIMARY KEY,
`detention_type_description` VARCHAR(
80
)
);
CREATE TABLE `Ref_Incident_Type` ... | Return all detention summaries. | SELECT detention_summary FROM Detention |
3,093 | behavior_monitoring | CREATE TABLE `Ref_Address_Types` (
`address_type_code` VARCHAR(
15
) PRIMARY KEY,
`address_type_description` VARCHAR(
80
)
);
CREATE TABLE `Ref_Detention_Type` (
`detention_type_code` VARCHAR(
10
) PRIMARY KEY,
`detention_type_description` VARCHAR(
80
)
);
CREATE TABLE `Ref_Incident_Type` ... | Return the cell phone number and email address for all students. | SELECT cell_mobile_number , email_address FROM STUDENTS |
3,094 | behavior_monitoring | CREATE TABLE `Ref_Address_Types` (
`address_type_code` VARCHAR(
15
) PRIMARY KEY,
`address_type_description` VARCHAR(
80
)
);
CREATE TABLE `Ref_Detention_Type` (
`detention_type_code` VARCHAR(
10
) PRIMARY KEY,
`detention_type_description` VARCHAR(
80
)
);
CREATE TABLE `Ref_Incident_Type` ... | What is the email of the student with first name "Emma" and last name "Rohan"? | SELECT email_address FROM Students WHERE first_name = "Emma" AND last_name = "Rohan" |
3,095 | behavior_monitoring | CREATE TABLE `Ref_Address_Types` (
`address_type_code` VARCHAR(
15
) PRIMARY KEY,
`address_type_description` VARCHAR(
80
)
);
CREATE TABLE `Ref_Detention_Type` (
`detention_type_code` VARCHAR(
10
) PRIMARY KEY,
`detention_type_description` VARCHAR(
80
)
);
CREATE TABLE `Ref_Incident_Type` ... | How many distinct students have been in detention? | SELECT count(DISTINCT student_id) FROM Students_in_Detention |
3,096 | behavior_monitoring | CREATE TABLE `Ref_Address_Types` (
`address_type_code` VARCHAR(
15
) PRIMARY KEY,
`address_type_description` VARCHAR(
80
)
);
CREATE TABLE `Ref_Detention_Type` (
`detention_type_code` VARCHAR(
10
) PRIMARY KEY,
`detention_type_description` VARCHAR(
80
)
);
CREATE TABLE `Ref_Incident_Type` ... | What is the gender of the teacher with last name "Medhurst"? | SELECT gender FROM TEACHERS WHERE last_name = "Medhurst" |
3,097 | behavior_monitoring | CREATE TABLE `Ref_Address_Types` (
`address_type_code` VARCHAR(
15
) PRIMARY KEY,
`address_type_description` VARCHAR(
80
)
);
CREATE TABLE `Ref_Detention_Type` (
`detention_type_code` VARCHAR(
10
) PRIMARY KEY,
`detention_type_description` VARCHAR(
80
)
);
CREATE TABLE `Ref_Incident_Type` ... | What is the incident type description for the incident type with code "VIOLENCE"? | SELECT incident_type_description FROM Ref_Incident_Type WHERE incident_type_code = "VIOLENCE" |
3,098 | behavior_monitoring | CREATE TABLE `Ref_Address_Types` (
`address_type_code` VARCHAR(
15
) PRIMARY KEY,
`address_type_description` VARCHAR(
80
)
);
CREATE TABLE `Ref_Detention_Type` (
`detention_type_code` VARCHAR(
10
) PRIMARY KEY,
`detention_type_description` VARCHAR(
80
)
);
CREATE TABLE `Ref_Incident_Type` ... | Find the maximum and minimum monthly rental for all student addresses. | SELECT max(monthly_rental) , min(monthly_rental) FROM Student_Addresses |
3,099 | behavior_monitoring | CREATE TABLE `Ref_Address_Types` (
`address_type_code` VARCHAR(
15
) PRIMARY KEY,
`address_type_description` VARCHAR(
80
)
);
CREATE TABLE `Ref_Detention_Type` (
`detention_type_code` VARCHAR(
10
) PRIMARY KEY,
`detention_type_description` VARCHAR(
80
)
);
CREATE TABLE `Ref_Incident_Type` ... | Find the first names of teachers whose email address contains the word "man". | SELECT first_name FROM Teachers WHERE email_address LIKE '%man%' |
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