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400
flight_1
CREATE TABLE flight( flno number( 4,0 ) primary key, origin varchar2( 20 ), destination varchar2( 20 ), distance number( 6,0 ), departure_date date, arrival_date date, price number( 7,2 ), aid number( 9,0 ), foreign key( "aid" ) references `aircraft`( "aid" ) ); CREA...
What are the numbers of the shortest flights?
SELECT flno FROM Flight ORDER BY distance ASC LIMIT 3
401
flight_1
CREATE TABLE flight( flno number( 4,0 ) primary key, origin varchar2( 20 ), destination varchar2( 20 ), distance number( 6,0 ), departure_date date, arrival_date date, price number( 7,2 ), aid number( 9,0 ), foreign key( "aid" ) references `aircraft`( "aid" ) ); CREA...
What is the average distance and average price for flights from Los Angeles.
SELECT avg(distance) , avg(price) FROM Flight WHERE origin = "Los Angeles"
402
flight_1
CREATE TABLE flight( flno number( 4,0 ) primary key, origin varchar2( 20 ), destination varchar2( 20 ), distance number( 6,0 ), departure_date date, arrival_date date, price number( 7,2 ), aid number( 9,0 ), foreign key( "aid" ) references `aircraft`( "aid" ) ); CREA...
What is the average distance and price for all flights from LA?
SELECT avg(distance) , avg(price) FROM Flight WHERE origin = "Los Angeles"
403
flight_1
CREATE TABLE flight( flno number( 4,0 ) primary key, origin varchar2( 20 ), destination varchar2( 20 ), distance number( 6,0 ), departure_date date, arrival_date date, price number( 7,2 ), aid number( 9,0 ), foreign key( "aid" ) references `aircraft`( "aid" ) ); CREA...
Show all origins and the number of flights from each origin.
SELECT origin , count(*) FROM Flight GROUP BY origin
404
flight_1
CREATE TABLE flight( flno number( 4,0 ) primary key, origin varchar2( 20 ), destination varchar2( 20 ), distance number( 6,0 ), departure_date date, arrival_date date, price number( 7,2 ), aid number( 9,0 ), foreign key( "aid" ) references `aircraft`( "aid" ) ); CREA...
For each origin, how many flights came from there?
SELECT origin , count(*) FROM Flight GROUP BY origin
405
flight_1
CREATE TABLE flight( flno number( 4,0 ) primary key, origin varchar2( 20 ), destination varchar2( 20 ), distance number( 6,0 ), departure_date date, arrival_date date, price number( 7,2 ), aid number( 9,0 ), foreign key( "aid" ) references `aircraft`( "aid" ) ); CREA...
Show all destinations and the number of flights to each destination.
SELECT destination , count(*) FROM Flight GROUP BY destination
406
flight_1
CREATE TABLE flight( flno number( 4,0 ) primary key, origin varchar2( 20 ), destination varchar2( 20 ), distance number( 6,0 ), departure_date date, arrival_date date, price number( 7,2 ), aid number( 9,0 ), foreign key( "aid" ) references `aircraft`( "aid" ) ); CREA...
What are the destinations and number of flights to each one?
SELECT destination , count(*) FROM Flight GROUP BY destination
407
flight_1
CREATE TABLE flight( flno number( 4,0 ) primary key, origin varchar2( 20 ), destination varchar2( 20 ), distance number( 6,0 ), departure_date date, arrival_date date, price number( 7,2 ), aid number( 9,0 ), foreign key( "aid" ) references `aircraft`( "aid" ) ); CREA...
Which origin has most number of flights?
SELECT origin FROM Flight GROUP BY origin ORDER BY count(*) DESC LIMIT 1
408
flight_1
CREATE TABLE flight( flno number( 4,0 ) primary key, origin varchar2( 20 ), destination varchar2( 20 ), distance number( 6,0 ), departure_date date, arrival_date date, price number( 7,2 ), aid number( 9,0 ), foreign key( "aid" ) references `aircraft`( "aid" ) ); CREA...
What place has the most flights coming from there?
SELECT origin FROM Flight GROUP BY origin ORDER BY count(*) DESC LIMIT 1
409
flight_1
CREATE TABLE flight( flno number( 4,0 ) primary key, origin varchar2( 20 ), destination varchar2( 20 ), distance number( 6,0 ), departure_date date, arrival_date date, price number( 7,2 ), aid number( 9,0 ), foreign key( "aid" ) references `aircraft`( "aid" ) ); CREA...
Which destination has least number of flights?
SELECT destination FROM Flight GROUP BY destination ORDER BY count(*) LIMIT 1
410
flight_1
CREATE TABLE flight( flno number( 4,0 ) primary key, origin varchar2( 20 ), destination varchar2( 20 ), distance number( 6,0 ), departure_date date, arrival_date date, price number( 7,2 ), aid number( 9,0 ), foreign key( "aid" ) references `aircraft`( "aid" ) ); CREA...
What destination has the fewest number of flights?
SELECT destination FROM Flight GROUP BY destination ORDER BY count(*) LIMIT 1
411
flight_1
CREATE TABLE flight( flno number( 4,0 ) primary key, origin varchar2( 20 ), destination varchar2( 20 ), distance number( 6,0 ), departure_date date, arrival_date date, price number( 7,2 ), aid number( 9,0 ), foreign key( "aid" ) references `aircraft`( "aid" ) ); CREA...
What is the aircraft name for the flight with number 99
SELECT T2.name FROM Flight AS T1 JOIN Aircraft AS T2 ON T1.aid = T2.aid WHERE T1.flno = 99
412
flight_1
CREATE TABLE flight( flno number( 4,0 ) primary key, origin varchar2( 20 ), destination varchar2( 20 ), distance number( 6,0 ), departure_date date, arrival_date date, price number( 7,2 ), aid number( 9,0 ), foreign key( "aid" ) references `aircraft`( "aid" ) ); CREA...
What is the name of the aircraft that was on flight number 99?
SELECT T2.name FROM Flight AS T1 JOIN Aircraft AS T2 ON T1.aid = T2.aid WHERE T1.flno = 99
413
flight_1
CREATE TABLE flight( flno number( 4,0 ) primary key, origin varchar2( 20 ), destination varchar2( 20 ), distance number( 6,0 ), departure_date date, arrival_date date, price number( 7,2 ), aid number( 9,0 ), foreign key( "aid" ) references `aircraft`( "aid" ) ); CREA...
Show all flight numbers with aircraft Airbus A340-300.
SELECT T1.flno FROM Flight AS T1 JOIN Aircraft AS T2 ON T1.aid = T2.aid WHERE T2.name = "Airbus A340-300"
414
flight_1
CREATE TABLE flight( flno number( 4,0 ) primary key, origin varchar2( 20 ), destination varchar2( 20 ), distance number( 6,0 ), departure_date date, arrival_date date, price number( 7,2 ), aid number( 9,0 ), foreign key( "aid" ) references `aircraft`( "aid" ) ); CREA...
What are the flight numbers for the aircraft Airbus A340-300?
SELECT T1.flno FROM Flight AS T1 JOIN Aircraft AS T2 ON T1.aid = T2.aid WHERE T2.name = "Airbus A340-300"
415
flight_1
CREATE TABLE flight( flno number( 4,0 ) primary key, origin varchar2( 20 ), destination varchar2( 20 ), distance number( 6,0 ), departure_date date, arrival_date date, price number( 7,2 ), aid number( 9,0 ), foreign key( "aid" ) references `aircraft`( "aid" ) ); CREA...
Show aircraft names and number of flights for each aircraft.
SELECT T2.name , count(*) FROM Flight AS T1 JOIN Aircraft AS T2 ON T1.aid = T2.aid GROUP BY T1.aid
416
flight_1
CREATE TABLE flight( flno number( 4,0 ) primary key, origin varchar2( 20 ), destination varchar2( 20 ), distance number( 6,0 ), departure_date date, arrival_date date, price number( 7,2 ), aid number( 9,0 ), foreign key( "aid" ) references `aircraft`( "aid" ) ); CREA...
What is the name of each aircraft and how many flights does each one complete?
SELECT T2.name , count(*) FROM Flight AS T1 JOIN Aircraft AS T2 ON T1.aid = T2.aid GROUP BY T1.aid
417
flight_1
CREATE TABLE flight( flno number( 4,0 ) primary key, origin varchar2( 20 ), destination varchar2( 20 ), distance number( 6,0 ), departure_date date, arrival_date date, price number( 7,2 ), aid number( 9,0 ), foreign key( "aid" ) references `aircraft`( "aid" ) ); CREA...
Show names for all aircraft with at least two flights.
SELECT T2.name FROM Flight AS T1 JOIN Aircraft AS T2 ON T1.aid = T2.aid GROUP BY T1.aid HAVING count(*) >= 2
418
flight_1
CREATE TABLE flight( flno number( 4,0 ) primary key, origin varchar2( 20 ), destination varchar2( 20 ), distance number( 6,0 ), departure_date date, arrival_date date, price number( 7,2 ), aid number( 9,0 ), foreign key( "aid" ) references `aircraft`( "aid" ) ); CREA...
What are the names for all aircrafts with at least 2 flights?
SELECT T2.name FROM Flight AS T1 JOIN Aircraft AS T2 ON T1.aid = T2.aid GROUP BY T1.aid HAVING count(*) >= 2
419
flight_1
CREATE TABLE flight( flno number( 4,0 ) primary key, origin varchar2( 20 ), destination varchar2( 20 ), distance number( 6,0 ), departure_date date, arrival_date date, price number( 7,2 ), aid number( 9,0 ), foreign key( "aid" ) references `aircraft`( "aid" ) ); CREA...
How many employees have certificate.
SELECT count(DISTINCT eid) FROM Certificate
420
flight_1
CREATE TABLE flight( flno number( 4,0 ) primary key, origin varchar2( 20 ), destination varchar2( 20 ), distance number( 6,0 ), departure_date date, arrival_date date, price number( 7,2 ), aid number( 9,0 ), foreign key( "aid" ) references `aircraft`( "aid" ) ); CREA...
What is the count of distinct employees with certificates?
SELECT count(DISTINCT eid) FROM Certificate
421
flight_1
CREATE TABLE flight( flno number( 4,0 ) primary key, origin varchar2( 20 ), destination varchar2( 20 ), distance number( 6,0 ), departure_date date, arrival_date date, price number( 7,2 ), aid number( 9,0 ), foreign key( "aid" ) references `aircraft`( "aid" ) ); CREA...
Show ids for all employees who don't have a certificate.
SELECT eid FROM Employee EXCEPT SELECT eid FROM Certificate
422
flight_1
CREATE TABLE flight( flno number( 4,0 ) primary key, origin varchar2( 20 ), destination varchar2( 20 ), distance number( 6,0 ), departure_date date, arrival_date date, price number( 7,2 ), aid number( 9,0 ), foreign key( "aid" ) references `aircraft`( "aid" ) ); CREA...
What are the ids of all employees that don't have certificates?
SELECT eid FROM Employee EXCEPT SELECT eid FROM Certificate
423
flight_1
CREATE TABLE flight( flno number( 4,0 ) primary key, origin varchar2( 20 ), destination varchar2( 20 ), distance number( 6,0 ), departure_date date, arrival_date date, price number( 7,2 ), aid number( 9,0 ), foreign key( "aid" ) references `aircraft`( "aid" ) ); CREA...
Show names for all aircrafts of which John Williams has certificates.
SELECT T3.name FROM Employee AS T1 JOIN Certificate AS T2 ON T1.eid = T2.eid JOIN Aircraft AS T3 ON T3.aid = T2.aid WHERE T1.name = "John Williams"
424
flight_1
CREATE TABLE flight( flno number( 4,0 ) primary key, origin varchar2( 20 ), destination varchar2( 20 ), distance number( 6,0 ), departure_date date, arrival_date date, price number( 7,2 ), aid number( 9,0 ), foreign key( "aid" ) references `aircraft`( "aid" ) ); CREA...
What are the names of all aircrafts that John Williams have certificates to be able to fly?
SELECT T3.name FROM Employee AS T1 JOIN Certificate AS T2 ON T1.eid = T2.eid JOIN Aircraft AS T3 ON T3.aid = T2.aid WHERE T1.name = "John Williams"
425
flight_1
CREATE TABLE flight( flno number( 4,0 ) primary key, origin varchar2( 20 ), destination varchar2( 20 ), distance number( 6,0 ), departure_date date, arrival_date date, price number( 7,2 ), aid number( 9,0 ), foreign key( "aid" ) references `aircraft`( "aid" ) ); CREA...
Show names for all employees who have certificate of Boeing 737-800.
SELECT T1.name FROM Employee AS T1 JOIN Certificate AS T2 ON T1.eid = T2.eid JOIN Aircraft AS T3 ON T3.aid = T2.aid WHERE T3.name = "Boeing 737-800"
426
flight_1
CREATE TABLE flight( flno number( 4,0 ) primary key, origin varchar2( 20 ), destination varchar2( 20 ), distance number( 6,0 ), departure_date date, arrival_date date, price number( 7,2 ), aid number( 9,0 ), foreign key( "aid" ) references `aircraft`( "aid" ) ); CREA...
What are the names of all employees who have a certificate to fly Boeing 737-800?
SELECT T1.name FROM Employee AS T1 JOIN Certificate AS T2 ON T1.eid = T2.eid JOIN Aircraft AS T3 ON T3.aid = T2.aid WHERE T3.name = "Boeing 737-800"
427
flight_1
CREATE TABLE flight( flno number( 4,0 ) primary key, origin varchar2( 20 ), destination varchar2( 20 ), distance number( 6,0 ), departure_date date, arrival_date date, price number( 7,2 ), aid number( 9,0 ), foreign key( "aid" ) references `aircraft`( "aid" ) ); CREA...
Show names for all employees who have certificates on both Boeing 737-800 and Airbus A340-300.
SELECT T1.name FROM Employee AS T1 JOIN Certificate AS T2 ON T1.eid = T2.eid JOIN Aircraft AS T3 ON T3.aid = T2.aid WHERE T3.name = "Boeing 737-800" INTERSECT SELECT T1.name FROM Employee AS T1 JOIN Certificate AS T2 ON T1.eid = T2.eid JOIN Aircraft AS T3 ON T3.aid = T2.aid WHERE T3.name = "Airbus A340-300"
428
flight_1
CREATE TABLE flight( flno number( 4,0 ) primary key, origin varchar2( 20 ), destination varchar2( 20 ), distance number( 6,0 ), departure_date date, arrival_date date, price number( 7,2 ), aid number( 9,0 ), foreign key( "aid" ) references `aircraft`( "aid" ) ); CREA...
What are the names of all employees who can fly both the Boeing 737-800 and the Airbus A340-300?
SELECT T1.name FROM Employee AS T1 JOIN Certificate AS T2 ON T1.eid = T2.eid JOIN Aircraft AS T3 ON T3.aid = T2.aid WHERE T3.name = "Boeing 737-800" INTERSECT SELECT T1.name FROM Employee AS T1 JOIN Certificate AS T2 ON T1.eid = T2.eid JOIN Aircraft AS T3 ON T3.aid = T2.aid WHERE T3.name = "Airbus A340-300"
429
flight_1
CREATE TABLE flight( flno number( 4,0 ) primary key, origin varchar2( 20 ), destination varchar2( 20 ), distance number( 6,0 ), departure_date date, arrival_date date, price number( 7,2 ), aid number( 9,0 ), foreign key( "aid" ) references `aircraft`( "aid" ) ); CREA...
Show names for all employees who do not have certificate of Boeing 737-800.
SELECT name FROM Employee EXCEPT SELECT T1.name FROM Employee AS T1 JOIN Certificate AS T2 ON T1.eid = T2.eid JOIN Aircraft AS T3 ON T3.aid = T2.aid WHERE T3.name = "Boeing 737-800"
430
flight_1
CREATE TABLE flight( flno number( 4,0 ) primary key, origin varchar2( 20 ), destination varchar2( 20 ), distance number( 6,0 ), departure_date date, arrival_date date, price number( 7,2 ), aid number( 9,0 ), foreign key( "aid" ) references `aircraft`( "aid" ) ); CREA...
What are the names of all employees who are not certified to fly Boeing 737-800s?
SELECT name FROM Employee EXCEPT SELECT T1.name FROM Employee AS T1 JOIN Certificate AS T2 ON T1.eid = T2.eid JOIN Aircraft AS T3 ON T3.aid = T2.aid WHERE T3.name = "Boeing 737-800"
431
flight_1
CREATE TABLE flight( flno number( 4,0 ) primary key, origin varchar2( 20 ), destination varchar2( 20 ), distance number( 6,0 ), departure_date date, arrival_date date, price number( 7,2 ), aid number( 9,0 ), foreign key( "aid" ) references `aircraft`( "aid" ) ); CREA...
Show the name of aircraft which fewest people have its certificate.
SELECT T2.name FROM Certificate AS T1 JOIN Aircraft AS T2 ON T2.aid = T1.aid GROUP BY T1.aid ORDER BY count(*) DESC LIMIT 1
432
flight_1
CREATE TABLE flight( flno number( 4,0 ) primary key, origin varchar2( 20 ), destination varchar2( 20 ), distance number( 6,0 ), departure_date date, arrival_date date, price number( 7,2 ), aid number( 9,0 ), foreign key( "aid" ) references `aircraft`( "aid" ) ); CREA...
What are the names of the aircraft that the least people are certified to fly?
SELECT T2.name FROM Certificate AS T1 JOIN Aircraft AS T2 ON T2.aid = T1.aid GROUP BY T1.aid ORDER BY count(*) DESC LIMIT 1
433
flight_1
CREATE TABLE flight( flno number( 4,0 ) primary key, origin varchar2( 20 ), destination varchar2( 20 ), distance number( 6,0 ), departure_date date, arrival_date date, price number( 7,2 ), aid number( 9,0 ), foreign key( "aid" ) references `aircraft`( "aid" ) ); CREA...
Show the name and distance of the aircrafts with more than 5000 distance and which at least 5 people have its certificate.
SELECT T2.name FROM Certificate AS T1 JOIN Aircraft AS T2 ON T2.aid = T1.aid WHERE T2.distance > 5000 GROUP BY T1.aid ORDER BY count(*) >= 5
434
flight_1
CREATE TABLE flight( flno number( 4,0 ) primary key, origin varchar2( 20 ), destination varchar2( 20 ), distance number( 6,0 ), departure_date date, arrival_date date, price number( 7,2 ), aid number( 9,0 ), foreign key( "aid" ) references `aircraft`( "aid" ) ); CREA...
What is the name and distance of every aircraft that can cover a distance of more than 5000 and which at least 5 people can fly?
SELECT T2.name FROM Certificate AS T1 JOIN Aircraft AS T2 ON T2.aid = T1.aid WHERE T2.distance > 5000 GROUP BY T1.aid ORDER BY count(*) >= 5
435
flight_1
CREATE TABLE flight( flno number( 4,0 ) primary key, origin varchar2( 20 ), destination varchar2( 20 ), distance number( 6,0 ), departure_date date, arrival_date date, price number( 7,2 ), aid number( 9,0 ), foreign key( "aid" ) references `aircraft`( "aid" ) ); CREA...
what is the salary and name of the employee who has the most number of aircraft certificates?
SELECT T1.name , T1.salary FROM Employee AS T1 JOIN Certificate AS T2 ON T1.eid = T2.eid GROUP BY T1.eid ORDER BY count(*) DESC LIMIT 1
436
flight_1
CREATE TABLE flight( flno number( 4,0 ) primary key, origin varchar2( 20 ), destination varchar2( 20 ), distance number( 6,0 ), departure_date date, arrival_date date, price number( 7,2 ), aid number( 9,0 ), foreign key( "aid" ) references `aircraft`( "aid" ) ); CREA...
What is the salaray and name of the employee that is certified to fly the most planes?
SELECT T1.name , T1.salary FROM Employee AS T1 JOIN Certificate AS T2 ON T1.eid = T2.eid GROUP BY T1.eid ORDER BY count(*) DESC LIMIT 1
437
flight_1
CREATE TABLE flight( flno number( 4,0 ) primary key, origin varchar2( 20 ), destination varchar2( 20 ), distance number( 6,0 ), departure_date date, arrival_date date, price number( 7,2 ), aid number( 9,0 ), foreign key( "aid" ) references `aircraft`( "aid" ) ); CREA...
What is the salary and name of the employee who has the most number of certificates on aircrafts with distance more than 5000?
SELECT T1.name FROM Employee AS T1 JOIN Certificate AS T2 ON T1.eid = T2.eid JOIN Aircraft AS T3 ON T3.aid = T2.aid WHERE T3.distance > 5000 GROUP BY T1.eid ORDER BY count(*) DESC LIMIT 1
438
flight_1
CREATE TABLE flight( flno number( 4,0 ) primary key, origin varchar2( 20 ), destination varchar2( 20 ), distance number( 6,0 ), departure_date date, arrival_date date, price number( 7,2 ), aid number( 9,0 ), foreign key( "aid" ) references `aircraft`( "aid" ) ); CREA...
What is the salaray and name of the employee with the most certificates to fly planes more than 5000?
SELECT T1.name FROM Employee AS T1 JOIN Certificate AS T2 ON T1.eid = T2.eid JOIN Aircraft AS T3 ON T3.aid = T2.aid WHERE T3.distance > 5000 GROUP BY T1.eid ORDER BY count(*) DESC LIMIT 1
439
allergy_1
CREATE TABLE Allergy_Type ( Allergy VARCHAR( 20 ) PRIMARY KEY, AllergyType VARCHAR( 20 ) ); CREATE TABLE Has_Allergy ( StuID INTEGER, Allergy VARCHAR( 20 ), FOREIGN KEY( StuID ) REFERENCES Student( StuID ), FOREIGN KEY( Allergy )...
How many allergies are there?
SELECT count(DISTINCT allergy) FROM Allergy_type
440
allergy_1
CREATE TABLE Allergy_Type ( Allergy VARCHAR( 20 ) PRIMARY KEY, AllergyType VARCHAR( 20 ) ); CREATE TABLE Has_Allergy ( StuID INTEGER, Allergy VARCHAR( 20 ), FOREIGN KEY( StuID ) REFERENCES Student( StuID ), FOREIGN KEY( Allergy )...
How many allergy entries are there?
SELECT count(DISTINCT allergy) FROM Allergy_type
441
allergy_1
CREATE TABLE Allergy_Type ( Allergy VARCHAR( 20 ) PRIMARY KEY, AllergyType VARCHAR( 20 ) ); CREATE TABLE Has_Allergy ( StuID INTEGER, Allergy VARCHAR( 20 ), FOREIGN KEY( StuID ) REFERENCES Student( StuID ), FOREIGN KEY( Allergy )...
How many different allergy types exist?
SELECT count(DISTINCT allergytype) FROM Allergy_type
442
allergy_1
CREATE TABLE Allergy_Type ( Allergy VARCHAR( 20 ) PRIMARY KEY, AllergyType VARCHAR( 20 ) ); CREATE TABLE Has_Allergy ( StuID INTEGER, Allergy VARCHAR( 20 ), FOREIGN KEY( StuID ) REFERENCES Student( StuID ), FOREIGN KEY( Allergy )...
How many distinct allergies are there?
SELECT count(DISTINCT allergytype) FROM Allergy_type
443
allergy_1
CREATE TABLE Allergy_Type ( Allergy VARCHAR( 20 ) PRIMARY KEY, AllergyType VARCHAR( 20 ) ); CREATE TABLE Has_Allergy ( StuID INTEGER, Allergy VARCHAR( 20 ), FOREIGN KEY( StuID ) REFERENCES Student( StuID ), FOREIGN KEY( Allergy )...
Show all allergy types.
SELECT DISTINCT allergytype FROM Allergy_type
444
allergy_1
CREATE TABLE Allergy_Type ( Allergy VARCHAR( 20 ) PRIMARY KEY, AllergyType VARCHAR( 20 ) ); CREATE TABLE Has_Allergy ( StuID INTEGER, Allergy VARCHAR( 20 ), FOREIGN KEY( StuID ) REFERENCES Student( StuID ), FOREIGN KEY( Allergy )...
What are the different allergy types?
SELECT DISTINCT allergytype FROM Allergy_type
445
allergy_1
CREATE TABLE Allergy_Type ( Allergy VARCHAR( 20 ) PRIMARY KEY, AllergyType VARCHAR( 20 ) ); CREATE TABLE Has_Allergy ( StuID INTEGER, Allergy VARCHAR( 20 ), FOREIGN KEY( StuID ) REFERENCES Student( StuID ), FOREIGN KEY( Allergy )...
Show all allergies and their types.
SELECT allergy , allergytype FROM Allergy_type
446
allergy_1
CREATE TABLE Allergy_Type ( Allergy VARCHAR( 20 ) PRIMARY KEY, AllergyType VARCHAR( 20 ) ); CREATE TABLE Has_Allergy ( StuID INTEGER, Allergy VARCHAR( 20 ), FOREIGN KEY( StuID ) REFERENCES Student( StuID ), FOREIGN KEY( Allergy )...
What are the allergies and their types?
SELECT allergy , allergytype FROM Allergy_type
447
allergy_1
CREATE TABLE Allergy_Type ( Allergy VARCHAR( 20 ) PRIMARY KEY, AllergyType VARCHAR( 20 ) ); CREATE TABLE Has_Allergy ( StuID INTEGER, Allergy VARCHAR( 20 ), FOREIGN KEY( StuID ) REFERENCES Student( StuID ), FOREIGN KEY( Allergy )...
Show all allergies with type food.
SELECT DISTINCT allergy FROM Allergy_type WHERE allergytype = "food"
448
allergy_1
CREATE TABLE Allergy_Type ( Allergy VARCHAR( 20 ) PRIMARY KEY, AllergyType VARCHAR( 20 ) ); CREATE TABLE Has_Allergy ( StuID INTEGER, Allergy VARCHAR( 20 ), FOREIGN KEY( StuID ) REFERENCES Student( StuID ), FOREIGN KEY( Allergy )...
What are all the different food allergies?
SELECT DISTINCT allergy FROM Allergy_type WHERE allergytype = "food"
449
allergy_1
CREATE TABLE Allergy_Type ( Allergy VARCHAR( 20 ) PRIMARY KEY, AllergyType VARCHAR( 20 ) ); CREATE TABLE Has_Allergy ( StuID INTEGER, Allergy VARCHAR( 20 ), FOREIGN KEY( StuID ) REFERENCES Student( StuID ), FOREIGN KEY( Allergy )...
What is the type of allergy Cat?
SELECT allergytype FROM Allergy_type WHERE allergy = "Cat"
450
allergy_1
CREATE TABLE Allergy_Type ( Allergy VARCHAR( 20 ) PRIMARY KEY, AllergyType VARCHAR( 20 ) ); CREATE TABLE Has_Allergy ( StuID INTEGER, Allergy VARCHAR( 20 ), FOREIGN KEY( StuID ) REFERENCES Student( StuID ), FOREIGN KEY( Allergy )...
What is allergy type of a cat allergy?
SELECT allergytype FROM Allergy_type WHERE allergy = "Cat"
451
allergy_1
CREATE TABLE Allergy_Type ( Allergy VARCHAR( 20 ) PRIMARY KEY, AllergyType VARCHAR( 20 ) ); CREATE TABLE Has_Allergy ( StuID INTEGER, Allergy VARCHAR( 20 ), FOREIGN KEY( StuID ) REFERENCES Student( StuID ), FOREIGN KEY( Allergy )...
How many allergies have type animal?
SELECT count(*) FROM Allergy_type WHERE allergytype = "animal"
452
allergy_1
CREATE TABLE Allergy_Type ( Allergy VARCHAR( 20 ) PRIMARY KEY, AllergyType VARCHAR( 20 ) ); CREATE TABLE Has_Allergy ( StuID INTEGER, Allergy VARCHAR( 20 ), FOREIGN KEY( StuID ) REFERENCES Student( StuID ), FOREIGN KEY( Allergy )...
How many animal type allergies exist?
SELECT count(*) FROM Allergy_type WHERE allergytype = "animal"
453
allergy_1
CREATE TABLE Allergy_Type ( Allergy VARCHAR( 20 ) PRIMARY KEY, AllergyType VARCHAR( 20 ) ); CREATE TABLE Has_Allergy ( StuID INTEGER, Allergy VARCHAR( 20 ), FOREIGN KEY( StuID ) REFERENCES Student( StuID ), FOREIGN KEY( Allergy )...
Show all allergy types and the number of allergies in each type.
SELECT allergytype , count(*) FROM Allergy_type GROUP BY allergytype
454
allergy_1
CREATE TABLE Allergy_Type ( Allergy VARCHAR( 20 ) PRIMARY KEY, AllergyType VARCHAR( 20 ) ); CREATE TABLE Has_Allergy ( StuID INTEGER, Allergy VARCHAR( 20 ), FOREIGN KEY( StuID ) REFERENCES Student( StuID ), FOREIGN KEY( Allergy )...
What are the allergy types and how many allergies correspond to each one?
SELECT allergytype , count(*) FROM Allergy_type GROUP BY allergytype
455
allergy_1
CREATE TABLE Allergy_Type ( Allergy VARCHAR( 20 ) PRIMARY KEY, AllergyType VARCHAR( 20 ) ); CREATE TABLE Has_Allergy ( StuID INTEGER, Allergy VARCHAR( 20 ), FOREIGN KEY( StuID ) REFERENCES Student( StuID ), FOREIGN KEY( Allergy )...
Which allergy type has most number of allergies?
SELECT allergytype FROM Allergy_type GROUP BY allergytype ORDER BY count(*) DESC LIMIT 1
456
allergy_1
CREATE TABLE Allergy_Type ( Allergy VARCHAR( 20 ) PRIMARY KEY, AllergyType VARCHAR( 20 ) ); CREATE TABLE Has_Allergy ( StuID INTEGER, Allergy VARCHAR( 20 ), FOREIGN KEY( StuID ) REFERENCES Student( StuID ), FOREIGN KEY( Allergy )...
Which allergy type is most common?
SELECT allergytype FROM Allergy_type GROUP BY allergytype ORDER BY count(*) DESC LIMIT 1
457
allergy_1
CREATE TABLE Allergy_Type ( Allergy VARCHAR( 20 ) PRIMARY KEY, AllergyType VARCHAR( 20 ) ); CREATE TABLE Has_Allergy ( StuID INTEGER, Allergy VARCHAR( 20 ), FOREIGN KEY( StuID ) REFERENCES Student( StuID ), FOREIGN KEY( Allergy )...
Which allergy type has least number of allergies?
SELECT allergytype FROM Allergy_type GROUP BY allergytype ORDER BY count(*) ASC LIMIT 1
458
allergy_1
CREATE TABLE Allergy_Type ( Allergy VARCHAR( 20 ) PRIMARY KEY, AllergyType VARCHAR( 20 ) ); CREATE TABLE Has_Allergy ( StuID INTEGER, Allergy VARCHAR( 20 ), FOREIGN KEY( StuID ) REFERENCES Student( StuID ), FOREIGN KEY( Allergy )...
Which allergy type is the least common?
SELECT allergytype FROM Allergy_type GROUP BY allergytype ORDER BY count(*) ASC LIMIT 1
459
allergy_1
CREATE TABLE Allergy_Type ( Allergy VARCHAR( 20 ) PRIMARY KEY, AllergyType VARCHAR( 20 ) ); CREATE TABLE Has_Allergy ( StuID INTEGER, Allergy VARCHAR( 20 ), FOREIGN KEY( StuID ) REFERENCES Student( StuID ), FOREIGN KEY( Allergy )...
How many students are there?
SELECT count(*) FROM Student
460
allergy_1
CREATE TABLE Allergy_Type ( Allergy VARCHAR( 20 ) PRIMARY KEY, AllergyType VARCHAR( 20 ) ); CREATE TABLE Has_Allergy ( StuID INTEGER, Allergy VARCHAR( 20 ), FOREIGN KEY( StuID ) REFERENCES Student( StuID ), FOREIGN KEY( Allergy )...
What is the total number of students?
SELECT count(*) FROM Student
461
allergy_1
CREATE TABLE Allergy_Type ( Allergy VARCHAR( 20 ) PRIMARY KEY, AllergyType VARCHAR( 20 ) ); CREATE TABLE Has_Allergy ( StuID INTEGER, Allergy VARCHAR( 20 ), FOREIGN KEY( StuID ) REFERENCES Student( StuID ), FOREIGN KEY( Allergy )...
Show first name and last name for all students.
SELECT Fname , Lname FROM Student
462
allergy_1
CREATE TABLE Allergy_Type ( Allergy VARCHAR( 20 ) PRIMARY KEY, AllergyType VARCHAR( 20 ) ); CREATE TABLE Has_Allergy ( StuID INTEGER, Allergy VARCHAR( 20 ), FOREIGN KEY( StuID ) REFERENCES Student( StuID ), FOREIGN KEY( Allergy )...
What are the full names of all students
SELECT Fname , Lname FROM Student
463
allergy_1
CREATE TABLE Allergy_Type ( Allergy VARCHAR( 20 ) PRIMARY KEY, AllergyType VARCHAR( 20 ) ); CREATE TABLE Has_Allergy ( StuID INTEGER, Allergy VARCHAR( 20 ), FOREIGN KEY( StuID ) REFERENCES Student( StuID ), FOREIGN KEY( Allergy )...
How many different advisors are listed?
SELECT count(DISTINCT advisor) FROM Student
464
allergy_1
CREATE TABLE Allergy_Type ( Allergy VARCHAR( 20 ) PRIMARY KEY, AllergyType VARCHAR( 20 ) ); CREATE TABLE Has_Allergy ( StuID INTEGER, Allergy VARCHAR( 20 ), FOREIGN KEY( StuID ) REFERENCES Student( StuID ), FOREIGN KEY( Allergy )...
How many advisors are there?
SELECT count(DISTINCT advisor) FROM Student
465
allergy_1
CREATE TABLE Allergy_Type ( Allergy VARCHAR( 20 ) PRIMARY KEY, AllergyType VARCHAR( 20 ) ); CREATE TABLE Has_Allergy ( StuID INTEGER, Allergy VARCHAR( 20 ), FOREIGN KEY( StuID ) REFERENCES Student( StuID ), FOREIGN KEY( Allergy )...
Show all majors.
SELECT DISTINCT Major FROM Student
466
allergy_1
CREATE TABLE Allergy_Type ( Allergy VARCHAR( 20 ) PRIMARY KEY, AllergyType VARCHAR( 20 ) ); CREATE TABLE Has_Allergy ( StuID INTEGER, Allergy VARCHAR( 20 ), FOREIGN KEY( StuID ) REFERENCES Student( StuID ), FOREIGN KEY( Allergy )...
What are the different majors?
SELECT DISTINCT Major FROM Student
467
allergy_1
CREATE TABLE Allergy_Type ( Allergy VARCHAR( 20 ) PRIMARY KEY, AllergyType VARCHAR( 20 ) ); CREATE TABLE Has_Allergy ( StuID INTEGER, Allergy VARCHAR( 20 ), FOREIGN KEY( StuID ) REFERENCES Student( StuID ), FOREIGN KEY( Allergy )...
Show all cities where students live.
SELECT DISTINCT city_code FROM Student
468
allergy_1
CREATE TABLE Allergy_Type ( Allergy VARCHAR( 20 ) PRIMARY KEY, AllergyType VARCHAR( 20 ) ); CREATE TABLE Has_Allergy ( StuID INTEGER, Allergy VARCHAR( 20 ), FOREIGN KEY( StuID ) REFERENCES Student( StuID ), FOREIGN KEY( Allergy )...
What cities do students live in?
SELECT DISTINCT city_code FROM Student
469
allergy_1
CREATE TABLE Allergy_Type ( Allergy VARCHAR( 20 ) PRIMARY KEY, AllergyType VARCHAR( 20 ) ); CREATE TABLE Has_Allergy ( StuID INTEGER, Allergy VARCHAR( 20 ), FOREIGN KEY( StuID ) REFERENCES Student( StuID ), FOREIGN KEY( Allergy )...
Show first name, last name, age for all female students. Their sex is F.
SELECT Fname , Lname , Age FROM Student WHERE Sex = 'F'
470
allergy_1
CREATE TABLE Allergy_Type ( Allergy VARCHAR( 20 ) PRIMARY KEY, AllergyType VARCHAR( 20 ) ); CREATE TABLE Has_Allergy ( StuID INTEGER, Allergy VARCHAR( 20 ), FOREIGN KEY( StuID ) REFERENCES Student( StuID ), FOREIGN KEY( Allergy )...
What are the full names and ages for all female students whose sex is F?
SELECT Fname , Lname , Age FROM Student WHERE Sex = 'F'
471
allergy_1
CREATE TABLE Allergy_Type ( Allergy VARCHAR( 20 ) PRIMARY KEY, AllergyType VARCHAR( 20 ) ); CREATE TABLE Has_Allergy ( StuID INTEGER, Allergy VARCHAR( 20 ), FOREIGN KEY( StuID ) REFERENCES Student( StuID ), FOREIGN KEY( Allergy )...
Show student ids for all male students.
SELECT StuID FROM Student WHERE Sex = 'M'
472
allergy_1
CREATE TABLE Allergy_Type ( Allergy VARCHAR( 20 ) PRIMARY KEY, AllergyType VARCHAR( 20 ) ); CREATE TABLE Has_Allergy ( StuID INTEGER, Allergy VARCHAR( 20 ), FOREIGN KEY( StuID ) REFERENCES Student( StuID ), FOREIGN KEY( Allergy )...
What are the student ids for all male students?
SELECT StuID FROM Student WHERE Sex = 'M'
473
allergy_1
CREATE TABLE Allergy_Type ( Allergy VARCHAR( 20 ) PRIMARY KEY, AllergyType VARCHAR( 20 ) ); CREATE TABLE Has_Allergy ( StuID INTEGER, Allergy VARCHAR( 20 ), FOREIGN KEY( StuID ) REFERENCES Student( StuID ), FOREIGN KEY( Allergy )...
How many students are age 18?
SELECT count(*) FROM Student WHERE age = 18
474
allergy_1
CREATE TABLE Allergy_Type ( Allergy VARCHAR( 20 ) PRIMARY KEY, AllergyType VARCHAR( 20 ) ); CREATE TABLE Has_Allergy ( StuID INTEGER, Allergy VARCHAR( 20 ), FOREIGN KEY( StuID ) REFERENCES Student( StuID ), FOREIGN KEY( Allergy )...
How many students are 18 years old?
SELECT count(*) FROM Student WHERE age = 18
475
allergy_1
CREATE TABLE Allergy_Type ( Allergy VARCHAR( 20 ) PRIMARY KEY, AllergyType VARCHAR( 20 ) ); CREATE TABLE Has_Allergy ( StuID INTEGER, Allergy VARCHAR( 20 ), FOREIGN KEY( StuID ) REFERENCES Student( StuID ), FOREIGN KEY( Allergy )...
Show all student ids who are older than 20.
SELECT StuID FROM Student WHERE age > 20
476
allergy_1
CREATE TABLE Allergy_Type ( Allergy VARCHAR( 20 ) PRIMARY KEY, AllergyType VARCHAR( 20 ) ); CREATE TABLE Has_Allergy ( StuID INTEGER, Allergy VARCHAR( 20 ), FOREIGN KEY( StuID ) REFERENCES Student( StuID ), FOREIGN KEY( Allergy )...
What are the student ids for students over 20 years old?
SELECT StuID FROM Student WHERE age > 20
477
allergy_1
CREATE TABLE Allergy_Type ( Allergy VARCHAR( 20 ) PRIMARY KEY, AllergyType VARCHAR( 20 ) ); CREATE TABLE Has_Allergy ( StuID INTEGER, Allergy VARCHAR( 20 ), FOREIGN KEY( StuID ) REFERENCES Student( StuID ), FOREIGN KEY( Allergy )...
Which city does the student whose last name is "Kim" live in?
SELECT city_code FROM Student WHERE LName = "Kim"
478
allergy_1
CREATE TABLE Allergy_Type ( Allergy VARCHAR( 20 ) PRIMARY KEY, AllergyType VARCHAR( 20 ) ); CREATE TABLE Has_Allergy ( StuID INTEGER, Allergy VARCHAR( 20 ), FOREIGN KEY( StuID ) REFERENCES Student( StuID ), FOREIGN KEY( Allergy )...
Give the city that the student whose family name is Kim lives in.
SELECT city_code FROM Student WHERE LName = "Kim"
479
allergy_1
CREATE TABLE Allergy_Type ( Allergy VARCHAR( 20 ) PRIMARY KEY, AllergyType VARCHAR( 20 ) ); CREATE TABLE Has_Allergy ( StuID INTEGER, Allergy VARCHAR( 20 ), FOREIGN KEY( StuID ) REFERENCES Student( StuID ), FOREIGN KEY( Allergy )...
Who is the advisor of student with ID 1004?
SELECT Advisor FROM Student WHERE StuID = 1004
480
allergy_1
CREATE TABLE Allergy_Type ( Allergy VARCHAR( 20 ) PRIMARY KEY, AllergyType VARCHAR( 20 ) ); CREATE TABLE Has_Allergy ( StuID INTEGER, Allergy VARCHAR( 20 ), FOREIGN KEY( StuID ) REFERENCES Student( StuID ), FOREIGN KEY( Allergy )...
Who advises student 1004?
SELECT Advisor FROM Student WHERE StuID = 1004
481
allergy_1
CREATE TABLE Allergy_Type ( Allergy VARCHAR( 20 ) PRIMARY KEY, AllergyType VARCHAR( 20 ) ); CREATE TABLE Has_Allergy ( StuID INTEGER, Allergy VARCHAR( 20 ), FOREIGN KEY( StuID ) REFERENCES Student( StuID ), FOREIGN KEY( Allergy )...
How many students live in HKG or CHI?
SELECT count(*) FROM Student WHERE city_code = "HKG" OR city_code = "CHI"
482
allergy_1
CREATE TABLE Allergy_Type ( Allergy VARCHAR( 20 ) PRIMARY KEY, AllergyType VARCHAR( 20 ) ); CREATE TABLE Has_Allergy ( StuID INTEGER, Allergy VARCHAR( 20 ), FOREIGN KEY( StuID ) REFERENCES Student( StuID ), FOREIGN KEY( Allergy )...
Give the number of students living in either HKG or CHI.
SELECT count(*) FROM Student WHERE city_code = "HKG" OR city_code = "CHI"
483
allergy_1
CREATE TABLE Allergy_Type ( Allergy VARCHAR( 20 ) PRIMARY KEY, AllergyType VARCHAR( 20 ) ); CREATE TABLE Has_Allergy ( StuID INTEGER, Allergy VARCHAR( 20 ), FOREIGN KEY( StuID ) REFERENCES Student( StuID ), FOREIGN KEY( Allergy )...
Show the minimum, average, and maximum age of all students.
SELECT min(age) , avg(age) , max(age) FROM Student
484
allergy_1
CREATE TABLE Allergy_Type ( Allergy VARCHAR( 20 ) PRIMARY KEY, AllergyType VARCHAR( 20 ) ); CREATE TABLE Has_Allergy ( StuID INTEGER, Allergy VARCHAR( 20 ), FOREIGN KEY( StuID ) REFERENCES Student( StuID ), FOREIGN KEY( Allergy )...
What is the minimum, mean, and maximum age across all students?
SELECT min(age) , avg(age) , max(age) FROM Student
485
allergy_1
CREATE TABLE Allergy_Type ( Allergy VARCHAR( 20 ) PRIMARY KEY, AllergyType VARCHAR( 20 ) ); CREATE TABLE Has_Allergy ( StuID INTEGER, Allergy VARCHAR( 20 ), FOREIGN KEY( StuID ) REFERENCES Student( StuID ), FOREIGN KEY( Allergy )...
What is the last name of the youngest student?
SELECT LName FROM Student WHERE age = (SELECT min(age) FROM Student)
486
allergy_1
CREATE TABLE Allergy_Type ( Allergy VARCHAR( 20 ) PRIMARY KEY, AllergyType VARCHAR( 20 ) ); CREATE TABLE Has_Allergy ( StuID INTEGER, Allergy VARCHAR( 20 ), FOREIGN KEY( StuID ) REFERENCES Student( StuID ), FOREIGN KEY( Allergy )...
Provide the last name of the youngest student.
SELECT LName FROM Student WHERE age = (SELECT min(age) FROM Student)
487
allergy_1
CREATE TABLE Allergy_Type ( Allergy VARCHAR( 20 ) PRIMARY KEY, AllergyType VARCHAR( 20 ) ); CREATE TABLE Has_Allergy ( StuID INTEGER, Allergy VARCHAR( 20 ), FOREIGN KEY( StuID ) REFERENCES Student( StuID ), FOREIGN KEY( Allergy )...
Show the student id of the oldest student.
SELECT StuID FROM Student WHERE age = (SELECT max(age) FROM Student)
488
allergy_1
CREATE TABLE Allergy_Type ( Allergy VARCHAR( 20 ) PRIMARY KEY, AllergyType VARCHAR( 20 ) ); CREATE TABLE Has_Allergy ( StuID INTEGER, Allergy VARCHAR( 20 ), FOREIGN KEY( StuID ) REFERENCES Student( StuID ), FOREIGN KEY( Allergy )...
What student id corresponds to the oldest student?
SELECT StuID FROM Student WHERE age = (SELECT max(age) FROM Student)
489
allergy_1
CREATE TABLE Allergy_Type ( Allergy VARCHAR( 20 ) PRIMARY KEY, AllergyType VARCHAR( 20 ) ); CREATE TABLE Has_Allergy ( StuID INTEGER, Allergy VARCHAR( 20 ), FOREIGN KEY( StuID ) REFERENCES Student( StuID ), FOREIGN KEY( Allergy )...
Show all majors and corresponding number of students.
SELECT major , count(*) FROM Student GROUP BY major
490
allergy_1
CREATE TABLE Allergy_Type ( Allergy VARCHAR( 20 ) PRIMARY KEY, AllergyType VARCHAR( 20 ) ); CREATE TABLE Has_Allergy ( StuID INTEGER, Allergy VARCHAR( 20 ), FOREIGN KEY( StuID ) REFERENCES Student( StuID ), FOREIGN KEY( Allergy )...
How many students are there for each major?
SELECT major , count(*) FROM Student GROUP BY major
491
allergy_1
CREATE TABLE Allergy_Type ( Allergy VARCHAR( 20 ) PRIMARY KEY, AllergyType VARCHAR( 20 ) ); CREATE TABLE Has_Allergy ( StuID INTEGER, Allergy VARCHAR( 20 ), FOREIGN KEY( StuID ) REFERENCES Student( StuID ), FOREIGN KEY( Allergy )...
Which major has most number of students?
SELECT major FROM Student GROUP BY major ORDER BY count(*) DESC LIMIT 1
492
allergy_1
CREATE TABLE Allergy_Type ( Allergy VARCHAR( 20 ) PRIMARY KEY, AllergyType VARCHAR( 20 ) ); CREATE TABLE Has_Allergy ( StuID INTEGER, Allergy VARCHAR( 20 ), FOREIGN KEY( StuID ) REFERENCES Student( StuID ), FOREIGN KEY( Allergy )...
What is the largest major?
SELECT major FROM Student GROUP BY major ORDER BY count(*) DESC LIMIT 1
493
allergy_1
CREATE TABLE Allergy_Type ( Allergy VARCHAR( 20 ) PRIMARY KEY, AllergyType VARCHAR( 20 ) ); CREATE TABLE Has_Allergy ( StuID INTEGER, Allergy VARCHAR( 20 ), FOREIGN KEY( StuID ) REFERENCES Student( StuID ), FOREIGN KEY( Allergy )...
Show all ages and corresponding number of students.
SELECT age , count(*) FROM Student GROUP BY age
494
allergy_1
CREATE TABLE Allergy_Type ( Allergy VARCHAR( 20 ) PRIMARY KEY, AllergyType VARCHAR( 20 ) ); CREATE TABLE Has_Allergy ( StuID INTEGER, Allergy VARCHAR( 20 ), FOREIGN KEY( StuID ) REFERENCES Student( StuID ), FOREIGN KEY( Allergy )...
How old is each student and how many students are each age?
SELECT age , count(*) FROM Student GROUP BY age
495
allergy_1
CREATE TABLE Allergy_Type ( Allergy VARCHAR( 20 ) PRIMARY KEY, AllergyType VARCHAR( 20 ) ); CREATE TABLE Has_Allergy ( StuID INTEGER, Allergy VARCHAR( 20 ), FOREIGN KEY( StuID ) REFERENCES Student( StuID ), FOREIGN KEY( Allergy )...
Show the average age for male and female students.
SELECT avg(age) , sex FROM Student GROUP BY sex
496
allergy_1
CREATE TABLE Allergy_Type ( Allergy VARCHAR( 20 ) PRIMARY KEY, AllergyType VARCHAR( 20 ) ); CREATE TABLE Has_Allergy ( StuID INTEGER, Allergy VARCHAR( 20 ), FOREIGN KEY( StuID ) REFERENCES Student( StuID ), FOREIGN KEY( Allergy )...
What are the average ages for male and female students?
SELECT avg(age) , sex FROM Student GROUP BY sex
497
allergy_1
CREATE TABLE Allergy_Type ( Allergy VARCHAR( 20 ) PRIMARY KEY, AllergyType VARCHAR( 20 ) ); CREATE TABLE Has_Allergy ( StuID INTEGER, Allergy VARCHAR( 20 ), FOREIGN KEY( StuID ) REFERENCES Student( StuID ), FOREIGN KEY( Allergy )...
Show all cities and corresponding number of students.
SELECT city_code , count(*) FROM Student GROUP BY city_code
498
allergy_1
CREATE TABLE Allergy_Type ( Allergy VARCHAR( 20 ) PRIMARY KEY, AllergyType VARCHAR( 20 ) ); CREATE TABLE Has_Allergy ( StuID INTEGER, Allergy VARCHAR( 20 ), FOREIGN KEY( StuID ) REFERENCES Student( StuID ), FOREIGN KEY( Allergy )...
How many students live in each city?
SELECT city_code , count(*) FROM Student GROUP BY city_code
499
allergy_1
CREATE TABLE Allergy_Type ( Allergy VARCHAR( 20 ) PRIMARY KEY, AllergyType VARCHAR( 20 ) ); CREATE TABLE Has_Allergy ( StuID INTEGER, Allergy VARCHAR( 20 ), FOREIGN KEY( StuID ) REFERENCES Student( StuID ), FOREIGN KEY( Allergy )...
Show all advisors and corresponding number of students.
SELECT advisor , count(*) FROM Student GROUP BY advisor