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int64
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146 values
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500
allergy_1
CREATE TABLE Allergy_Type ( Allergy VARCHAR( 20 ) PRIMARY KEY, AllergyType VARCHAR( 20 ) ); CREATE TABLE Has_Allergy ( StuID INTEGER, Allergy VARCHAR( 20 ), FOREIGN KEY( StuID ) REFERENCES Student( StuID ), FOREIGN KEY( Allergy )...
How many students does each advisor have?
SELECT advisor , count(*) FROM Student GROUP BY advisor
501
allergy_1
CREATE TABLE Allergy_Type ( Allergy VARCHAR( 20 ) PRIMARY KEY, AllergyType VARCHAR( 20 ) ); CREATE TABLE Has_Allergy ( StuID INTEGER, Allergy VARCHAR( 20 ), FOREIGN KEY( StuID ) REFERENCES Student( StuID ), FOREIGN KEY( Allergy )...
Which advisor has most number of students?
SELECT advisor FROM Student GROUP BY advisor ORDER BY count(*) DESC LIMIT 1
502
allergy_1
CREATE TABLE Allergy_Type ( Allergy VARCHAR( 20 ) PRIMARY KEY, AllergyType VARCHAR( 20 ) ); CREATE TABLE Has_Allergy ( StuID INTEGER, Allergy VARCHAR( 20 ), FOREIGN KEY( StuID ) REFERENCES Student( StuID ), FOREIGN KEY( Allergy )...
Give the advisor with the most students.
SELECT advisor FROM Student GROUP BY advisor ORDER BY count(*) DESC LIMIT 1
503
allergy_1
CREATE TABLE Allergy_Type ( Allergy VARCHAR( 20 ) PRIMARY KEY, AllergyType VARCHAR( 20 ) ); CREATE TABLE Has_Allergy ( StuID INTEGER, Allergy VARCHAR( 20 ), FOREIGN KEY( StuID ) REFERENCES Student( StuID ), FOREIGN KEY( Allergy )...
How many students have cat allergies?
SELECT count(*) FROM Has_allergy WHERE Allergy = "Cat"
504
allergy_1
CREATE TABLE Allergy_Type ( Allergy VARCHAR( 20 ) PRIMARY KEY, AllergyType VARCHAR( 20 ) ); CREATE TABLE Has_Allergy ( StuID INTEGER, Allergy VARCHAR( 20 ), FOREIGN KEY( StuID ) REFERENCES Student( StuID ), FOREIGN KEY( Allergy )...
How many students are affected by cat allergies?
SELECT count(*) FROM Has_allergy WHERE Allergy = "Cat"
505
allergy_1
CREATE TABLE Allergy_Type ( Allergy VARCHAR( 20 ) PRIMARY KEY, AllergyType VARCHAR( 20 ) ); CREATE TABLE Has_Allergy ( StuID INTEGER, Allergy VARCHAR( 20 ), FOREIGN KEY( StuID ) REFERENCES Student( StuID ), FOREIGN KEY( Allergy )...
Show all student IDs who have at least two allergies.
SELECT StuID FROM Has_allergy GROUP BY StuID HAVING count(*) >= 2
506
allergy_1
CREATE TABLE Allergy_Type ( Allergy VARCHAR( 20 ) PRIMARY KEY, AllergyType VARCHAR( 20 ) ); CREATE TABLE Has_Allergy ( StuID INTEGER, Allergy VARCHAR( 20 ), FOREIGN KEY( StuID ) REFERENCES Student( StuID ), FOREIGN KEY( Allergy )...
What are the students ids of students who have more than one allergy?
SELECT StuID FROM Has_allergy GROUP BY StuID HAVING count(*) >= 2
507
allergy_1
CREATE TABLE Allergy_Type ( Allergy VARCHAR( 20 ) PRIMARY KEY, AllergyType VARCHAR( 20 ) ); CREATE TABLE Has_Allergy ( StuID INTEGER, Allergy VARCHAR( 20 ), FOREIGN KEY( StuID ) REFERENCES Student( StuID ), FOREIGN KEY( Allergy )...
What are the student ids of students who don't have any allergies?
SELECT StuID FROM Student EXCEPT SELECT StuID FROM Has_allergy
508
allergy_1
CREATE TABLE Allergy_Type ( Allergy VARCHAR( 20 ) PRIMARY KEY, AllergyType VARCHAR( 20 ) ); CREATE TABLE Has_Allergy ( StuID INTEGER, Allergy VARCHAR( 20 ), FOREIGN KEY( StuID ) REFERENCES Student( StuID ), FOREIGN KEY( Allergy )...
Which students are unaffected by allergies?
SELECT StuID FROM Student EXCEPT SELECT StuID FROM Has_allergy
509
allergy_1
CREATE TABLE Allergy_Type ( Allergy VARCHAR( 20 ) PRIMARY KEY, AllergyType VARCHAR( 20 ) ); CREATE TABLE Has_Allergy ( StuID INTEGER, Allergy VARCHAR( 20 ), FOREIGN KEY( StuID ) REFERENCES Student( StuID ), FOREIGN KEY( Allergy )...
How many female students have milk or egg allergies?
SELECT count(*) FROM has_allergy AS T1 JOIN Student AS T2 ON T1.StuID = T2.StuID WHERE T2.sex = "F" AND T1.allergy = "Milk" OR T1.allergy = "Eggs"
510
allergy_1
CREATE TABLE Allergy_Type ( Allergy VARCHAR( 20 ) PRIMARY KEY, AllergyType VARCHAR( 20 ) ); CREATE TABLE Has_Allergy ( StuID INTEGER, Allergy VARCHAR( 20 ), FOREIGN KEY( StuID ) REFERENCES Student( StuID ), FOREIGN KEY( Allergy )...
How many students who are female are allergic to milk or eggs?
SELECT count(*) FROM has_allergy AS T1 JOIN Student AS T2 ON T1.StuID = T2.StuID WHERE T2.sex = "F" AND T1.allergy = "Milk" OR T1.allergy = "Eggs"
511
allergy_1
CREATE TABLE Allergy_Type ( Allergy VARCHAR( 20 ) PRIMARY KEY, AllergyType VARCHAR( 20 ) ); CREATE TABLE Has_Allergy ( StuID INTEGER, Allergy VARCHAR( 20 ), FOREIGN KEY( StuID ) REFERENCES Student( StuID ), FOREIGN KEY( Allergy )...
How many students have a food allergy?
SELECT count(*) FROM Has_allergy AS T1 JOIN Allergy_type AS T2 ON T1.allergy = T2.allergy WHERE T2.allergytype = "food"
512
allergy_1
CREATE TABLE Allergy_Type ( Allergy VARCHAR( 20 ) PRIMARY KEY, AllergyType VARCHAR( 20 ) ); CREATE TABLE Has_Allergy ( StuID INTEGER, Allergy VARCHAR( 20 ), FOREIGN KEY( StuID ) REFERENCES Student( StuID ), FOREIGN KEY( Allergy )...
How many students are affected by food related allergies?
SELECT count(*) FROM Has_allergy AS T1 JOIN Allergy_type AS T2 ON T1.allergy = T2.allergy WHERE T2.allergytype = "food"
513
allergy_1
CREATE TABLE Allergy_Type ( Allergy VARCHAR( 20 ) PRIMARY KEY, AllergyType VARCHAR( 20 ) ); CREATE TABLE Has_Allergy ( StuID INTEGER, Allergy VARCHAR( 20 ), FOREIGN KEY( StuID ) REFERENCES Student( StuID ), FOREIGN KEY( Allergy )...
Which allergy has most number of students affected?
SELECT Allergy FROM Has_allergy GROUP BY Allergy ORDER BY count(*) DESC LIMIT 1
514
allergy_1
CREATE TABLE Allergy_Type ( Allergy VARCHAR( 20 ) PRIMARY KEY, AllergyType VARCHAR( 20 ) ); CREATE TABLE Has_Allergy ( StuID INTEGER, Allergy VARCHAR( 20 ), FOREIGN KEY( StuID ) REFERENCES Student( StuID ), FOREIGN KEY( Allergy )...
Which allergy is the most common?
SELECT Allergy FROM Has_allergy GROUP BY Allergy ORDER BY count(*) DESC LIMIT 1
515
allergy_1
CREATE TABLE Allergy_Type ( Allergy VARCHAR( 20 ) PRIMARY KEY, AllergyType VARCHAR( 20 ) ); CREATE TABLE Has_Allergy ( StuID INTEGER, Allergy VARCHAR( 20 ), FOREIGN KEY( StuID ) REFERENCES Student( StuID ), FOREIGN KEY( Allergy )...
Show all allergies with number of students affected.
SELECT Allergy , count(*) FROM Has_allergy GROUP BY Allergy
516
allergy_1
CREATE TABLE Allergy_Type ( Allergy VARCHAR( 20 ) PRIMARY KEY, AllergyType VARCHAR( 20 ) ); CREATE TABLE Has_Allergy ( StuID INTEGER, Allergy VARCHAR( 20 ), FOREIGN KEY( StuID ) REFERENCES Student( StuID ), FOREIGN KEY( Allergy )...
How many students have each different allergy?
SELECT Allergy , count(*) FROM Has_allergy GROUP BY Allergy
517
allergy_1
CREATE TABLE Allergy_Type ( Allergy VARCHAR( 20 ) PRIMARY KEY, AllergyType VARCHAR( 20 ) ); CREATE TABLE Has_Allergy ( StuID INTEGER, Allergy VARCHAR( 20 ), FOREIGN KEY( StuID ) REFERENCES Student( StuID ), FOREIGN KEY( Allergy )...
Show all allergy type with number of students affected.
SELECT T2.allergytype , count(*) FROM Has_allergy AS T1 JOIN Allergy_type AS T2 ON T1.allergy = T2.allergy GROUP BY T2.allergytype
518
allergy_1
CREATE TABLE Allergy_Type ( Allergy VARCHAR( 20 ) PRIMARY KEY, AllergyType VARCHAR( 20 ) ); CREATE TABLE Has_Allergy ( StuID INTEGER, Allergy VARCHAR( 20 ), FOREIGN KEY( StuID ) REFERENCES Student( StuID ), FOREIGN KEY( Allergy )...
How many students are affected by each allergy type?
SELECT T2.allergytype , count(*) FROM Has_allergy AS T1 JOIN Allergy_type AS T2 ON T1.allergy = T2.allergy GROUP BY T2.allergytype
519
allergy_1
CREATE TABLE Allergy_Type ( Allergy VARCHAR( 20 ) PRIMARY KEY, AllergyType VARCHAR( 20 ) ); CREATE TABLE Has_Allergy ( StuID INTEGER, Allergy VARCHAR( 20 ), FOREIGN KEY( StuID ) REFERENCES Student( StuID ), FOREIGN KEY( Allergy )...
Find the last name and age of the student who has allergy to both milk and cat.
SELECT lname , age FROM Student WHERE StuID IN (SELECT StuID FROM Has_allergy WHERE Allergy = "Milk" INTERSECT SELECT StuID FROM Has_allergy WHERE Allergy = "Cat")
520
allergy_1
CREATE TABLE Allergy_Type ( Allergy VARCHAR( 20 ) PRIMARY KEY, AllergyType VARCHAR( 20 ) ); CREATE TABLE Has_Allergy ( StuID INTEGER, Allergy VARCHAR( 20 ), FOREIGN KEY( StuID ) REFERENCES Student( StuID ), FOREIGN KEY( Allergy )...
What are the last names and ages of the students who are allergic to milk and cat?
SELECT lname , age FROM Student WHERE StuID IN (SELECT StuID FROM Has_allergy WHERE Allergy = "Milk" INTERSECT SELECT StuID FROM Has_allergy WHERE Allergy = "Cat")
521
allergy_1
CREATE TABLE Allergy_Type ( Allergy VARCHAR( 20 ) PRIMARY KEY, AllergyType VARCHAR( 20 ) ); CREATE TABLE Has_Allergy ( StuID INTEGER, Allergy VARCHAR( 20 ), FOREIGN KEY( StuID ) REFERENCES Student( StuID ), FOREIGN KEY( Allergy )...
What are the allergies and their types that the student with first name Lisa has? And order the result by name of allergies.
SELECT T1.Allergy , T1.AllergyType FROM Allergy_type AS T1 JOIN Has_allergy AS T2 ON T1.Allergy = T2.Allergy JOIN Student AS T3 ON T3.StuID = T2.StuID WHERE T3.Fname = "Lisa" ORDER BY T1.Allergy
522
allergy_1
CREATE TABLE Allergy_Type ( Allergy VARCHAR( 20 ) PRIMARY KEY, AllergyType VARCHAR( 20 ) ); CREATE TABLE Has_Allergy ( StuID INTEGER, Allergy VARCHAR( 20 ), FOREIGN KEY( StuID ) REFERENCES Student( StuID ), FOREIGN KEY( Allergy )...
What are the allergies the girl named Lisa has? And what are the types of them? Order the result by allergy names.
SELECT T1.Allergy , T1.AllergyType FROM Allergy_type AS T1 JOIN Has_allergy AS T2 ON T1.Allergy = T2.Allergy JOIN Student AS T3 ON T3.StuID = T2.StuID WHERE T3.Fname = "Lisa" ORDER BY T1.Allergy
523
allergy_1
CREATE TABLE Allergy_Type ( Allergy VARCHAR( 20 ) PRIMARY KEY, AllergyType VARCHAR( 20 ) ); CREATE TABLE Has_Allergy ( StuID INTEGER, Allergy VARCHAR( 20 ), FOREIGN KEY( StuID ) REFERENCES Student( StuID ), FOREIGN KEY( Allergy )...
Find the first name and gender of the student who has allergy to milk but not cat.
SELECT fname , sex FROM Student WHERE StuID IN (SELECT StuID FROM Has_allergy WHERE Allergy = "Milk" EXCEPT SELECT StuID FROM Has_allergy WHERE Allergy = "Cat")
524
allergy_1
CREATE TABLE Allergy_Type ( Allergy VARCHAR( 20 ) PRIMARY KEY, AllergyType VARCHAR( 20 ) ); CREATE TABLE Has_Allergy ( StuID INTEGER, Allergy VARCHAR( 20 ), FOREIGN KEY( StuID ) REFERENCES Student( StuID ), FOREIGN KEY( Allergy )...
What are the first name and gender of the students who have allergy to milk but can put up with cats?
SELECT fname , sex FROM Student WHERE StuID IN (SELECT StuID FROM Has_allergy WHERE Allergy = "Milk" EXCEPT SELECT StuID FROM Has_allergy WHERE Allergy = "Cat")
525
allergy_1
CREATE TABLE Allergy_Type ( Allergy VARCHAR( 20 ) PRIMARY KEY, AllergyType VARCHAR( 20 ) ); CREATE TABLE Has_Allergy ( StuID INTEGER, Allergy VARCHAR( 20 ), FOREIGN KEY( StuID ) REFERENCES Student( StuID ), FOREIGN KEY( Allergy )...
Find the average age of the students who have allergies with food and animal types.
SELECT avg(age) FROM Student WHERE StuID IN ( SELECT T1.StuID FROM Has_allergy AS T1 JOIN Allergy_Type AS T2 ON T1.Allergy = T2.Allergy WHERE T2.allergytype = "food" INTERSECT SELECT T1.StuID FROM Has_allergy AS T1 JOIN Allergy_Type AS T2 ON T1.Allergy = T2.Allergy WHERE T2.allergytype = "animal")
526
allergy_1
CREATE TABLE Allergy_Type ( Allergy VARCHAR( 20 ) PRIMARY KEY, AllergyType VARCHAR( 20 ) ); CREATE TABLE Has_Allergy ( StuID INTEGER, Allergy VARCHAR( 20 ), FOREIGN KEY( StuID ) REFERENCES Student( StuID ), FOREIGN KEY( Allergy )...
How old are the students with allergies to food and animal types on average?
SELECT avg(age) FROM Student WHERE StuID IN ( SELECT T1.StuID FROM Has_allergy AS T1 JOIN Allergy_Type AS T2 ON T1.Allergy = T2.Allergy WHERE T2.allergytype = "food" INTERSECT SELECT T1.StuID FROM Has_allergy AS T1 JOIN Allergy_Type AS T2 ON T1.Allergy = T2.Allergy WHERE T2.allergytype = "animal")
527
allergy_1
CREATE TABLE Allergy_Type ( Allergy VARCHAR( 20 ) PRIMARY KEY, AllergyType VARCHAR( 20 ) ); CREATE TABLE Has_Allergy ( StuID INTEGER, Allergy VARCHAR( 20 ), FOREIGN KEY( StuID ) REFERENCES Student( StuID ), FOREIGN KEY( Allergy )...
List the first and last name of the students who do not have any food type allergy.
SELECT fname , lname FROM Student WHERE StuID NOT IN (SELECT T1.StuID FROM Has_allergy AS T1 JOIN Allergy_Type AS T2 ON T1.Allergy = T2.Allergy WHERE T2.allergytype = "food")
528
allergy_1
CREATE TABLE Allergy_Type ( Allergy VARCHAR( 20 ) PRIMARY KEY, AllergyType VARCHAR( 20 ) ); CREATE TABLE Has_Allergy ( StuID INTEGER, Allergy VARCHAR( 20 ), FOREIGN KEY( StuID ) REFERENCES Student( StuID ), FOREIGN KEY( Allergy )...
What is the full name of each student who is not allergic to any type of food.
SELECT fname , lname FROM Student WHERE StuID NOT IN (SELECT T1.StuID FROM Has_allergy AS T1 JOIN Allergy_Type AS T2 ON T1.Allergy = T2.Allergy WHERE T2.allergytype = "food")
529
allergy_1
CREATE TABLE Allergy_Type ( Allergy VARCHAR( 20 ) PRIMARY KEY, AllergyType VARCHAR( 20 ) ); CREATE TABLE Has_Allergy ( StuID INTEGER, Allergy VARCHAR( 20 ), FOREIGN KEY( StuID ) REFERENCES Student( StuID ), FOREIGN KEY( Allergy )...
Find the number of male (sex is 'M') students who have some food type allery.
SELECT count(*) FROM Student WHERE sex = "M" AND StuID IN (SELECT StuID FROM Has_allergy AS T1 JOIN Allergy_Type AS T2 ON T1.Allergy = T2.Allergy WHERE T2.allergytype = "food")
530
allergy_1
CREATE TABLE Allergy_Type ( Allergy VARCHAR( 20 ) PRIMARY KEY, AllergyType VARCHAR( 20 ) ); CREATE TABLE Has_Allergy ( StuID INTEGER, Allergy VARCHAR( 20 ), FOREIGN KEY( StuID ) REFERENCES Student( StuID ), FOREIGN KEY( Allergy )...
How many male students (sex is 'M') are allergic to any type of food?
SELECT count(*) FROM Student WHERE sex = "M" AND StuID IN (SELECT StuID FROM Has_allergy AS T1 JOIN Allergy_Type AS T2 ON T1.Allergy = T2.Allergy WHERE T2.allergytype = "food")
531
allergy_1
CREATE TABLE Allergy_Type ( Allergy VARCHAR( 20 ) PRIMARY KEY, AllergyType VARCHAR( 20 ) ); CREATE TABLE Has_Allergy ( StuID INTEGER, Allergy VARCHAR( 20 ), FOREIGN KEY( StuID ) REFERENCES Student( StuID ), FOREIGN KEY( Allergy )...
Find the different first names and cities of the students who have allergy to milk or cat.
SELECT DISTINCT T1.fname , T1.city_code FROM Student AS T1 JOIN Has_Allergy AS T2 ON T1.stuid = T2.stuid WHERE T2.Allergy = "Milk" OR T2.Allergy = "Cat"
532
allergy_1
CREATE TABLE Allergy_Type ( Allergy VARCHAR( 20 ) PRIMARY KEY, AllergyType VARCHAR( 20 ) ); CREATE TABLE Has_Allergy ( StuID INTEGER, Allergy VARCHAR( 20 ), FOREIGN KEY( StuID ) REFERENCES Student( StuID ), FOREIGN KEY( Allergy )...
What are the distinct first names and cities of the students who have allergy either to milk or to cat?
SELECT DISTINCT T1.fname , T1.city_code FROM Student AS T1 JOIN Has_Allergy AS T2 ON T1.stuid = T2.stuid WHERE T2.Allergy = "Milk" OR T2.Allergy = "Cat"
533
allergy_1
CREATE TABLE Allergy_Type ( Allergy VARCHAR( 20 ) PRIMARY KEY, AllergyType VARCHAR( 20 ) ); CREATE TABLE Has_Allergy ( StuID INTEGER, Allergy VARCHAR( 20 ), FOREIGN KEY( StuID ) REFERENCES Student( StuID ), FOREIGN KEY( Allergy )...
Find the number of students who are older than 18 and do not have allergy to either food or animal.
SELECT count(*) FROM Student WHERE age > 18 AND StuID NOT IN ( SELECT StuID FROM Has_allergy AS T1 JOIN Allergy_Type AS T2 ON T1.Allergy = T2.Allergy WHERE T2.allergytype = "food" OR T2.allergytype = "animal")
534
allergy_1
CREATE TABLE Allergy_Type ( Allergy VARCHAR( 20 ) PRIMARY KEY, AllergyType VARCHAR( 20 ) ); CREATE TABLE Has_Allergy ( StuID INTEGER, Allergy VARCHAR( 20 ), FOREIGN KEY( StuID ) REFERENCES Student( StuID ), FOREIGN KEY( Allergy )...
How many students are over 18 and do not have allergy to food type or animal type?
SELECT count(*) FROM Student WHERE age > 18 AND StuID NOT IN ( SELECT StuID FROM Has_allergy AS T1 JOIN Allergy_Type AS T2 ON T1.Allergy = T2.Allergy WHERE T2.allergytype = "food" OR T2.allergytype = "animal")
535
allergy_1
CREATE TABLE Allergy_Type ( Allergy VARCHAR( 20 ) PRIMARY KEY, AllergyType VARCHAR( 20 ) ); CREATE TABLE Has_Allergy ( StuID INTEGER, Allergy VARCHAR( 20 ), FOREIGN KEY( StuID ) REFERENCES Student( StuID ), FOREIGN KEY( Allergy )...
Find the first name and major of the students who are not allegry to soy.
SELECT fname , major FROM Student WHERE StuID NOT IN (SELECT StuID FROM Has_allergy WHERE Allergy = "Soy")
536
allergy_1
CREATE TABLE Allergy_Type ( Allergy VARCHAR( 20 ) PRIMARY KEY, AllergyType VARCHAR( 20 ) ); CREATE TABLE Has_Allergy ( StuID INTEGER, Allergy VARCHAR( 20 ), FOREIGN KEY( StuID ) REFERENCES Student( StuID ), FOREIGN KEY( Allergy )...
What are the first name and major of the students who are able to consume soy?
SELECT fname , major FROM Student WHERE StuID NOT IN (SELECT StuID FROM Has_allergy WHERE Allergy = "Soy")
537
store_1
CREATE TABLE artists ( id INTEGER PRIMARY KEY AUTOINCREMENT, name VARCHAR( 120 ) ); CREATE TABLE sqlite_sequence( name,seq ); CREATE TABLE albums ( id INTEGER PRIMARY KEY AUTOINCREMENT, title VARCHAR( 160 ) NOT NULL, artist_id INTEGER NOT NULL, FOREIGN KEY ( artist...
A list of the top 5 countries by number of invoices. List country name and number of invoices.
SELECT billing_country , COUNT(*) FROM invoices GROUP BY billing_country ORDER BY count(*) DESC LIMIT 5;
538
store_1
CREATE TABLE artists ( id INTEGER PRIMARY KEY AUTOINCREMENT, name VARCHAR( 120 ) ); CREATE TABLE sqlite_sequence( name,seq ); CREATE TABLE albums ( id INTEGER PRIMARY KEY AUTOINCREMENT, title VARCHAR( 160 ) NOT NULL, artist_id INTEGER NOT NULL, FOREIGN KEY ( artist...
What are the top 5 countries by number of invoices and how many do they have?
SELECT billing_country , COUNT(*) FROM invoices GROUP BY billing_country ORDER BY count(*) DESC LIMIT 5;
539
store_1
CREATE TABLE artists ( id INTEGER PRIMARY KEY AUTOINCREMENT, name VARCHAR( 120 ) ); CREATE TABLE sqlite_sequence( name,seq ); CREATE TABLE albums ( id INTEGER PRIMARY KEY AUTOINCREMENT, title VARCHAR( 160 ) NOT NULL, artist_id INTEGER NOT NULL, FOREIGN KEY ( artist...
A list of the top 8 countries by gross/total invoice size. List country name and gross invoice size.
SELECT billing_country , SUM(total) FROM invoices GROUP BY billing_country ORDER BY SUM(total) DESC LIMIT 8;
540
store_1
CREATE TABLE artists ( id INTEGER PRIMARY KEY AUTOINCREMENT, name VARCHAR( 120 ) ); CREATE TABLE sqlite_sequence( name,seq ); CREATE TABLE albums ( id INTEGER PRIMARY KEY AUTOINCREMENT, title VARCHAR( 160 ) NOT NULL, artist_id INTEGER NOT NULL, FOREIGN KEY ( artist...
What are the names of the top 8 countries by total invoice size and what are those sizes?
SELECT billing_country , SUM(total) FROM invoices GROUP BY billing_country ORDER BY SUM(total) DESC LIMIT 8;
541
store_1
CREATE TABLE artists ( id INTEGER PRIMARY KEY AUTOINCREMENT, name VARCHAR( 120 ) ); CREATE TABLE sqlite_sequence( name,seq ); CREATE TABLE albums ( id INTEGER PRIMARY KEY AUTOINCREMENT, title VARCHAR( 160 ) NOT NULL, artist_id INTEGER NOT NULL, FOREIGN KEY ( artist...
A list of the top 10 countries by average invoice size. List country name and average invoice size.
SELECT billing_country , AVG(total) FROM invoices GROUP BY billing_country ORDER BY AVG(total) DESC LIMIT 10;
542
store_1
CREATE TABLE artists ( id INTEGER PRIMARY KEY AUTOINCREMENT, name VARCHAR( 120 ) ); CREATE TABLE sqlite_sequence( name,seq ); CREATE TABLE albums ( id INTEGER PRIMARY KEY AUTOINCREMENT, title VARCHAR( 160 ) NOT NULL, artist_id INTEGER NOT NULL, FOREIGN KEY ( artist...
What are the names of the countries and average invoice size of the top countries by size?
SELECT billing_country , AVG(total) FROM invoices GROUP BY billing_country ORDER BY AVG(total) DESC LIMIT 10;
543
store_1
CREATE TABLE artists ( id INTEGER PRIMARY KEY AUTOINCREMENT, name VARCHAR( 120 ) ); CREATE TABLE sqlite_sequence( name,seq ); CREATE TABLE albums ( id INTEGER PRIMARY KEY AUTOINCREMENT, title VARCHAR( 160 ) NOT NULL, artist_id INTEGER NOT NULL, FOREIGN KEY ( artist...
Find out 5 customers who most recently purchased something. List customers' first and last name.
SELECT T1.first_name , T1.last_name FROM customers AS T1 JOIN invoices AS T2 ON T2.customer_id = T1.id ORDER BY T2.invoice_date DESC LIMIT 5;
544
store_1
CREATE TABLE artists ( id INTEGER PRIMARY KEY AUTOINCREMENT, name VARCHAR( 120 ) ); CREATE TABLE sqlite_sequence( name,seq ); CREATE TABLE albums ( id INTEGER PRIMARY KEY AUTOINCREMENT, title VARCHAR( 160 ) NOT NULL, artist_id INTEGER NOT NULL, FOREIGN KEY ( artist...
What are the first and last names of the 5 customers who purchased something most recently?
SELECT T1.first_name , T1.last_name FROM customers AS T1 JOIN invoices AS T2 ON T2.customer_id = T1.id ORDER BY T2.invoice_date DESC LIMIT 5;
545
store_1
CREATE TABLE artists ( id INTEGER PRIMARY KEY AUTOINCREMENT, name VARCHAR( 120 ) ); CREATE TABLE sqlite_sequence( name,seq ); CREATE TABLE albums ( id INTEGER PRIMARY KEY AUTOINCREMENT, title VARCHAR( 160 ) NOT NULL, artist_id INTEGER NOT NULL, FOREIGN KEY ( artist...
Find out the top 10 customers by total number of orders. List customers' first and last name and the number of total orders.
SELECT T1.first_name , T1.last_name , COUNT(*) FROM customers AS T1 JOIN invoices AS T2 ON T2.customer_id = T1.id GROUP BY T1.id ORDER BY COUNT(*) DESC LIMIT 10;
546
store_1
CREATE TABLE artists ( id INTEGER PRIMARY KEY AUTOINCREMENT, name VARCHAR( 120 ) ); CREATE TABLE sqlite_sequence( name,seq ); CREATE TABLE albums ( id INTEGER PRIMARY KEY AUTOINCREMENT, title VARCHAR( 160 ) NOT NULL, artist_id INTEGER NOT NULL, FOREIGN KEY ( artist...
What are the top 10 customers' first and last names by total number of orders and how many orders did they make?
SELECT T1.first_name , T1.last_name , COUNT(*) FROM customers AS T1 JOIN invoices AS T2 ON T2.customer_id = T1.id GROUP BY T1.id ORDER BY COUNT(*) DESC LIMIT 10;
547
store_1
CREATE TABLE artists ( id INTEGER PRIMARY KEY AUTOINCREMENT, name VARCHAR( 120 ) ); CREATE TABLE sqlite_sequence( name,seq ); CREATE TABLE albums ( id INTEGER PRIMARY KEY AUTOINCREMENT, title VARCHAR( 160 ) NOT NULL, artist_id INTEGER NOT NULL, FOREIGN KEY ( artist...
List the top 10 customers by total gross sales. List customers' first and last name and total gross sales.
SELECT T1.first_name , T1.last_name , SUM(T2.total) FROM customers AS T1 JOIN invoices AS T2 ON T2.customer_id = T1.id GROUP BY T1.id ORDER BY SUM(T2.total) DESC LIMIT 10;
548
store_1
CREATE TABLE artists ( id INTEGER PRIMARY KEY AUTOINCREMENT, name VARCHAR( 120 ) ); CREATE TABLE sqlite_sequence( name,seq ); CREATE TABLE albums ( id INTEGER PRIMARY KEY AUTOINCREMENT, title VARCHAR( 160 ) NOT NULL, artist_id INTEGER NOT NULL, FOREIGN KEY ( artist...
What are the top 10 customers' first and last names with the highest gross sales, and also what are the sales?
SELECT T1.first_name , T1.last_name , SUM(T2.total) FROM customers AS T1 JOIN invoices AS T2 ON T2.customer_id = T1.id GROUP BY T1.id ORDER BY SUM(T2.total) DESC LIMIT 10;
549
store_1
CREATE TABLE artists ( id INTEGER PRIMARY KEY AUTOINCREMENT, name VARCHAR( 120 ) ); CREATE TABLE sqlite_sequence( name,seq ); CREATE TABLE albums ( id INTEGER PRIMARY KEY AUTOINCREMENT, title VARCHAR( 160 ) NOT NULL, artist_id INTEGER NOT NULL, FOREIGN KEY ( artist...
List the top 5 genres by number of tracks. List genres name and total tracks.
SELECT T1.name , COUNT(*) FROM genres AS T1 JOIN tracks AS T2 ON T2.genre_id = T1.id GROUP BY T1.id ORDER BY count(*) DESC LIMIT 5;
550
store_1
CREATE TABLE artists ( id INTEGER PRIMARY KEY AUTOINCREMENT, name VARCHAR( 120 ) ); CREATE TABLE sqlite_sequence( name,seq ); CREATE TABLE albums ( id INTEGER PRIMARY KEY AUTOINCREMENT, title VARCHAR( 160 ) NOT NULL, artist_id INTEGER NOT NULL, FOREIGN KEY ( artist...
How many tracks does each genre have and what are the names of the top 5?
SELECT T1.name , COUNT(*) FROM genres AS T1 JOIN tracks AS T2 ON T2.genre_id = T1.id GROUP BY T1.id ORDER BY count(*) DESC LIMIT 5;
551
store_1
CREATE TABLE artists ( id INTEGER PRIMARY KEY AUTOINCREMENT, name VARCHAR( 120 ) ); CREATE TABLE sqlite_sequence( name,seq ); CREATE TABLE albums ( id INTEGER PRIMARY KEY AUTOINCREMENT, title VARCHAR( 160 ) NOT NULL, artist_id INTEGER NOT NULL, FOREIGN KEY ( artist...
List every album's title.
SELECT title FROM albums;
552
store_1
CREATE TABLE artists ( id INTEGER PRIMARY KEY AUTOINCREMENT, name VARCHAR( 120 ) ); CREATE TABLE sqlite_sequence( name,seq ); CREATE TABLE albums ( id INTEGER PRIMARY KEY AUTOINCREMENT, title VARCHAR( 160 ) NOT NULL, artist_id INTEGER NOT NULL, FOREIGN KEY ( artist...
What are the titles of all the albums?
SELECT title FROM albums;
553
store_1
CREATE TABLE artists ( id INTEGER PRIMARY KEY AUTOINCREMENT, name VARCHAR( 120 ) ); CREATE TABLE sqlite_sequence( name,seq ); CREATE TABLE albums ( id INTEGER PRIMARY KEY AUTOINCREMENT, title VARCHAR( 160 ) NOT NULL, artist_id INTEGER NOT NULL, FOREIGN KEY ( artist...
List every album ordered by album title in ascending order.
SELECT title FROM albums ORDER BY title;
554
store_1
CREATE TABLE artists ( id INTEGER PRIMARY KEY AUTOINCREMENT, name VARCHAR( 120 ) ); CREATE TABLE sqlite_sequence( name,seq ); CREATE TABLE albums ( id INTEGER PRIMARY KEY AUTOINCREMENT, title VARCHAR( 160 ) NOT NULL, artist_id INTEGER NOT NULL, FOREIGN KEY ( artist...
What are the titles of all the albums alphabetically ascending?
SELECT title FROM albums ORDER BY title;
555
store_1
CREATE TABLE artists ( id INTEGER PRIMARY KEY AUTOINCREMENT, name VARCHAR( 120 ) ); CREATE TABLE sqlite_sequence( name,seq ); CREATE TABLE albums ( id INTEGER PRIMARY KEY AUTOINCREMENT, title VARCHAR( 160 ) NOT NULL, artist_id INTEGER NOT NULL, FOREIGN KEY ( artist...
List every album whose title starts with A in alphabetical order.
SELECT title FROM albums WHERE title LIKE 'A%' ORDER BY title;
556
store_1
CREATE TABLE artists ( id INTEGER PRIMARY KEY AUTOINCREMENT, name VARCHAR( 120 ) ); CREATE TABLE sqlite_sequence( name,seq ); CREATE TABLE albums ( id INTEGER PRIMARY KEY AUTOINCREMENT, title VARCHAR( 160 ) NOT NULL, artist_id INTEGER NOT NULL, FOREIGN KEY ( artist...
What are the titles of all albums that start with A in alphabetical order?
SELECT title FROM albums WHERE title LIKE 'A%' ORDER BY title;
557
store_1
CREATE TABLE artists ( id INTEGER PRIMARY KEY AUTOINCREMENT, name VARCHAR( 120 ) ); CREATE TABLE sqlite_sequence( name,seq ); CREATE TABLE albums ( id INTEGER PRIMARY KEY AUTOINCREMENT, title VARCHAR( 160 ) NOT NULL, artist_id INTEGER NOT NULL, FOREIGN KEY ( artist...
List the customers first and last name of 10 least expensive invoices.
SELECT T1.first_name , T1.last_name FROM customers AS T1 JOIN invoices AS T2 ON T2.customer_id = T1.id ORDER BY total LIMIT 10;
558
store_1
CREATE TABLE artists ( id INTEGER PRIMARY KEY AUTOINCREMENT, name VARCHAR( 120 ) ); CREATE TABLE sqlite_sequence( name,seq ); CREATE TABLE albums ( id INTEGER PRIMARY KEY AUTOINCREMENT, title VARCHAR( 160 ) NOT NULL, artist_id INTEGER NOT NULL, FOREIGN KEY ( artist...
What are the first and last names of the customers with the 10 cheapest invoices?
SELECT T1.first_name , T1.last_name FROM customers AS T1 JOIN invoices AS T2 ON T2.customer_id = T1.id ORDER BY total LIMIT 10;
559
store_1
CREATE TABLE artists ( id INTEGER PRIMARY KEY AUTOINCREMENT, name VARCHAR( 120 ) ); CREATE TABLE sqlite_sequence( name,seq ); CREATE TABLE albums ( id INTEGER PRIMARY KEY AUTOINCREMENT, title VARCHAR( 160 ) NOT NULL, artist_id INTEGER NOT NULL, FOREIGN KEY ( artist...
List total amount of invoice from Chicago, IL.
SELECT sum(total) FROM invoices WHERE billing_city = "Chicago" AND billing_state = "IL";
560
store_1
CREATE TABLE artists ( id INTEGER PRIMARY KEY AUTOINCREMENT, name VARCHAR( 120 ) ); CREATE TABLE sqlite_sequence( name,seq ); CREATE TABLE albums ( id INTEGER PRIMARY KEY AUTOINCREMENT, title VARCHAR( 160 ) NOT NULL, artist_id INTEGER NOT NULL, FOREIGN KEY ( artist...
What are the total amount of money in the invoices billed from Chicago, Illinois?
SELECT sum(total) FROM invoices WHERE billing_city = "Chicago" AND billing_state = "IL";
561
store_1
CREATE TABLE artists ( id INTEGER PRIMARY KEY AUTOINCREMENT, name VARCHAR( 120 ) ); CREATE TABLE sqlite_sequence( name,seq ); CREATE TABLE albums ( id INTEGER PRIMARY KEY AUTOINCREMENT, title VARCHAR( 160 ) NOT NULL, artist_id INTEGER NOT NULL, FOREIGN KEY ( artist...
List the number of invoices from Chicago, IL.
SELECT COUNT(*) FROM invoices WHERE billing_city = "Chicago" AND billing_state = "IL";
562
store_1
CREATE TABLE artists ( id INTEGER PRIMARY KEY AUTOINCREMENT, name VARCHAR( 120 ) ); CREATE TABLE sqlite_sequence( name,seq ); CREATE TABLE albums ( id INTEGER PRIMARY KEY AUTOINCREMENT, title VARCHAR( 160 ) NOT NULL, artist_id INTEGER NOT NULL, FOREIGN KEY ( artist...
How many invoices were billed from Chicago, IL?
SELECT COUNT(*) FROM invoices WHERE billing_city = "Chicago" AND billing_state = "IL";
563
store_1
CREATE TABLE artists ( id INTEGER PRIMARY KEY AUTOINCREMENT, name VARCHAR( 120 ) ); CREATE TABLE sqlite_sequence( name,seq ); CREATE TABLE albums ( id INTEGER PRIMARY KEY AUTOINCREMENT, title VARCHAR( 160 ) NOT NULL, artist_id INTEGER NOT NULL, FOREIGN KEY ( artist...
List the number of invoices from the US, grouped by state.
SELECT billing_state , COUNT(*) FROM invoices WHERE billing_country = "USA" GROUP BY billing_state;
564
store_1
CREATE TABLE artists ( id INTEGER PRIMARY KEY AUTOINCREMENT, name VARCHAR( 120 ) ); CREATE TABLE sqlite_sequence( name,seq ); CREATE TABLE albums ( id INTEGER PRIMARY KEY AUTOINCREMENT, title VARCHAR( 160 ) NOT NULL, artist_id INTEGER NOT NULL, FOREIGN KEY ( artist...
How many invoices were billed from each state?
SELECT billing_state , COUNT(*) FROM invoices WHERE billing_country = "USA" GROUP BY billing_state;
565
store_1
CREATE TABLE artists ( id INTEGER PRIMARY KEY AUTOINCREMENT, name VARCHAR( 120 ) ); CREATE TABLE sqlite_sequence( name,seq ); CREATE TABLE albums ( id INTEGER PRIMARY KEY AUTOINCREMENT, title VARCHAR( 160 ) NOT NULL, artist_id INTEGER NOT NULL, FOREIGN KEY ( artist...
List the state in the US with the most invoices.
SELECT billing_state , COUNT(*) FROM invoices WHERE billing_country = "USA" GROUP BY billing_state ORDER BY COUNT(*) DESC LIMIT 1;
566
store_1
CREATE TABLE artists ( id INTEGER PRIMARY KEY AUTOINCREMENT, name VARCHAR( 120 ) ); CREATE TABLE sqlite_sequence( name,seq ); CREATE TABLE albums ( id INTEGER PRIMARY KEY AUTOINCREMENT, title VARCHAR( 160 ) NOT NULL, artist_id INTEGER NOT NULL, FOREIGN KEY ( artist...
What are the states with the most invoices?
SELECT billing_state , COUNT(*) FROM invoices WHERE billing_country = "USA" GROUP BY billing_state ORDER BY COUNT(*) DESC LIMIT 1;
567
store_1
CREATE TABLE artists ( id INTEGER PRIMARY KEY AUTOINCREMENT, name VARCHAR( 120 ) ); CREATE TABLE sqlite_sequence( name,seq ); CREATE TABLE albums ( id INTEGER PRIMARY KEY AUTOINCREMENT, title VARCHAR( 160 ) NOT NULL, artist_id INTEGER NOT NULL, FOREIGN KEY ( artist...
List the number of invoices and the invoice total from California.
SELECT billing_state , COUNT(*) , SUM(total) FROM invoices WHERE billing_state = "CA";
568
store_1
CREATE TABLE artists ( id INTEGER PRIMARY KEY AUTOINCREMENT, name VARCHAR( 120 ) ); CREATE TABLE sqlite_sequence( name,seq ); CREATE TABLE albums ( id INTEGER PRIMARY KEY AUTOINCREMENT, title VARCHAR( 160 ) NOT NULL, artist_id INTEGER NOT NULL, FOREIGN KEY ( artist...
What is the number of invoices and total money billed in them from CA?
SELECT billing_state , COUNT(*) , SUM(total) FROM invoices WHERE billing_state = "CA";
569
store_1
CREATE TABLE artists ( id INTEGER PRIMARY KEY AUTOINCREMENT, name VARCHAR( 120 ) ); CREATE TABLE sqlite_sequence( name,seq ); CREATE TABLE albums ( id INTEGER PRIMARY KEY AUTOINCREMENT, title VARCHAR( 160 ) NOT NULL, artist_id INTEGER NOT NULL, FOREIGN KEY ( artist...
List Aerosmith's albums.
SELECT T1.title FROM albums AS T1 JOIN artists AS T2 ON T1.artist_id = T2.id WHERE T2.name = "Aerosmith";
570
store_1
CREATE TABLE artists ( id INTEGER PRIMARY KEY AUTOINCREMENT, name VARCHAR( 120 ) ); CREATE TABLE sqlite_sequence( name,seq ); CREATE TABLE albums ( id INTEGER PRIMARY KEY AUTOINCREMENT, title VARCHAR( 160 ) NOT NULL, artist_id INTEGER NOT NULL, FOREIGN KEY ( artist...
What are the titles of all the Aerosmith albums?
SELECT T1.title FROM albums AS T1 JOIN artists AS T2 ON T1.artist_id = T2.id WHERE T2.name = "Aerosmith";
571
store_1
CREATE TABLE artists ( id INTEGER PRIMARY KEY AUTOINCREMENT, name VARCHAR( 120 ) ); CREATE TABLE sqlite_sequence( name,seq ); CREATE TABLE albums ( id INTEGER PRIMARY KEY AUTOINCREMENT, title VARCHAR( 160 ) NOT NULL, artist_id INTEGER NOT NULL, FOREIGN KEY ( artist...
How many albums does Billy Cobham has?
SELECT count(*) FROM albums AS T1 JOIN artists AS T2 ON T1.artist_id = T2.id WHERE T2.name = "Billy Cobham";
572
store_1
CREATE TABLE artists ( id INTEGER PRIMARY KEY AUTOINCREMENT, name VARCHAR( 120 ) ); CREATE TABLE sqlite_sequence( name,seq ); CREATE TABLE albums ( id INTEGER PRIMARY KEY AUTOINCREMENT, title VARCHAR( 160 ) NOT NULL, artist_id INTEGER NOT NULL, FOREIGN KEY ( artist...
How many albums has Billy Cobam released?
SELECT count(*) FROM albums AS T1 JOIN artists AS T2 ON T1.artist_id = T2.id WHERE T2.name = "Billy Cobham";
573
store_1
CREATE TABLE artists ( id INTEGER PRIMARY KEY AUTOINCREMENT, name VARCHAR( 120 ) ); CREATE TABLE sqlite_sequence( name,seq ); CREATE TABLE albums ( id INTEGER PRIMARY KEY AUTOINCREMENT, title VARCHAR( 160 ) NOT NULL, artist_id INTEGER NOT NULL, FOREIGN KEY ( artist...
Eduardo Martins is a customer at which company?
SELECT company FROM customers WHERE first_name = "Eduardo" AND last_name = "Martins";
574
store_1
CREATE TABLE artists ( id INTEGER PRIMARY KEY AUTOINCREMENT, name VARCHAR( 120 ) ); CREATE TABLE sqlite_sequence( name,seq ); CREATE TABLE albums ( id INTEGER PRIMARY KEY AUTOINCREMENT, title VARCHAR( 160 ) NOT NULL, artist_id INTEGER NOT NULL, FOREIGN KEY ( artist...
What is the company where Eduardo Martins is a customer?
SELECT company FROM customers WHERE first_name = "Eduardo" AND last_name = "Martins";
575
store_1
CREATE TABLE artists ( id INTEGER PRIMARY KEY AUTOINCREMENT, name VARCHAR( 120 ) ); CREATE TABLE sqlite_sequence( name,seq ); CREATE TABLE albums ( id INTEGER PRIMARY KEY AUTOINCREMENT, title VARCHAR( 160 ) NOT NULL, artist_id INTEGER NOT NULL, FOREIGN KEY ( artist...
What is Astrid Gruber's email and phone number?
SELECT email , phone FROM customers WHERE first_name = "Astrid" AND last_name = "Gruber";
576
store_1
CREATE TABLE artists ( id INTEGER PRIMARY KEY AUTOINCREMENT, name VARCHAR( 120 ) ); CREATE TABLE sqlite_sequence( name,seq ); CREATE TABLE albums ( id INTEGER PRIMARY KEY AUTOINCREMENT, title VARCHAR( 160 ) NOT NULL, artist_id INTEGER NOT NULL, FOREIGN KEY ( artist...
What is the email and phone number of Astrid Gruber the customer?
SELECT email , phone FROM customers WHERE first_name = "Astrid" AND last_name = "Gruber";
577
store_1
CREATE TABLE artists ( id INTEGER PRIMARY KEY AUTOINCREMENT, name VARCHAR( 120 ) ); CREATE TABLE sqlite_sequence( name,seq ); CREATE TABLE albums ( id INTEGER PRIMARY KEY AUTOINCREMENT, title VARCHAR( 160 ) NOT NULL, artist_id INTEGER NOT NULL, FOREIGN KEY ( artist...
How many customers live in Prague city?
SELECT count(*) FROM customers WHERE city = "Prague";
578
store_1
CREATE TABLE artists ( id INTEGER PRIMARY KEY AUTOINCREMENT, name VARCHAR( 120 ) ); CREATE TABLE sqlite_sequence( name,seq ); CREATE TABLE albums ( id INTEGER PRIMARY KEY AUTOINCREMENT, title VARCHAR( 160 ) NOT NULL, artist_id INTEGER NOT NULL, FOREIGN KEY ( artist...
How many customers live in the city of Prague?
SELECT count(*) FROM customers WHERE city = "Prague";
579
store_1
CREATE TABLE artists ( id INTEGER PRIMARY KEY AUTOINCREMENT, name VARCHAR( 120 ) ); CREATE TABLE sqlite_sequence( name,seq ); CREATE TABLE albums ( id INTEGER PRIMARY KEY AUTOINCREMENT, title VARCHAR( 160 ) NOT NULL, artist_id INTEGER NOT NULL, FOREIGN KEY ( artist...
How many customers in state of CA?
SELECT count(*) FROM customers WHERE state = "CA";
580
store_1
CREATE TABLE artists ( id INTEGER PRIMARY KEY AUTOINCREMENT, name VARCHAR( 120 ) ); CREATE TABLE sqlite_sequence( name,seq ); CREATE TABLE albums ( id INTEGER PRIMARY KEY AUTOINCREMENT, title VARCHAR( 160 ) NOT NULL, artist_id INTEGER NOT NULL, FOREIGN KEY ( artist...
How many customers are from California?
SELECT count(*) FROM customers WHERE state = "CA";
581
store_1
CREATE TABLE artists ( id INTEGER PRIMARY KEY AUTOINCREMENT, name VARCHAR( 120 ) ); CREATE TABLE sqlite_sequence( name,seq ); CREATE TABLE albums ( id INTEGER PRIMARY KEY AUTOINCREMENT, title VARCHAR( 160 ) NOT NULL, artist_id INTEGER NOT NULL, FOREIGN KEY ( artist...
What country does Roberto Almeida live?
SELECT country FROM customers WHERE first_name = "Roberto" AND last_name = "Almeida";
582
store_1
CREATE TABLE artists ( id INTEGER PRIMARY KEY AUTOINCREMENT, name VARCHAR( 120 ) ); CREATE TABLE sqlite_sequence( name,seq ); CREATE TABLE albums ( id INTEGER PRIMARY KEY AUTOINCREMENT, title VARCHAR( 160 ) NOT NULL, artist_id INTEGER NOT NULL, FOREIGN KEY ( artist...
In which country does Roberto Almeida?
SELECT country FROM customers WHERE first_name = "Roberto" AND last_name = "Almeida";
583
store_1
CREATE TABLE artists ( id INTEGER PRIMARY KEY AUTOINCREMENT, name VARCHAR( 120 ) ); CREATE TABLE sqlite_sequence( name,seq ); CREATE TABLE albums ( id INTEGER PRIMARY KEY AUTOINCREMENT, title VARCHAR( 160 ) NOT NULL, artist_id INTEGER NOT NULL, FOREIGN KEY ( artist...
List the name of albums that are released by aritist whose name has 'Led'
SELECT T2.title FROM artists AS T1 JOIN albums AS T2 ON T1.id = T2.artist_id WHERE T1.name LIKE '%Led%'
584
store_1
CREATE TABLE artists ( id INTEGER PRIMARY KEY AUTOINCREMENT, name VARCHAR( 120 ) ); CREATE TABLE sqlite_sequence( name,seq ); CREATE TABLE albums ( id INTEGER PRIMARY KEY AUTOINCREMENT, title VARCHAR( 160 ) NOT NULL, artist_id INTEGER NOT NULL, FOREIGN KEY ( artist...
What is the title of the album that was released by the artist whose name has the phrase 'Led'?
SELECT T2.title FROM artists AS T1 JOIN albums AS T2 ON T1.id = T2.artist_id WHERE T1.name LIKE '%Led%'
585
store_1
CREATE TABLE artists ( id INTEGER PRIMARY KEY AUTOINCREMENT, name VARCHAR( 120 ) ); CREATE TABLE sqlite_sequence( name,seq ); CREATE TABLE albums ( id INTEGER PRIMARY KEY AUTOINCREMENT, title VARCHAR( 160 ) NOT NULL, artist_id INTEGER NOT NULL, FOREIGN KEY ( artist...
How many customers does Steve Johnson support?
SELECT count(*) FROM employees AS T1 JOIN customers AS T2 ON T2.support_rep_id = T1.id WHERE T1.first_name = "Steve" AND T1.last_name = "Johnson";
586
store_1
CREATE TABLE artists ( id INTEGER PRIMARY KEY AUTOINCREMENT, name VARCHAR( 120 ) ); CREATE TABLE sqlite_sequence( name,seq ); CREATE TABLE albums ( id INTEGER PRIMARY KEY AUTOINCREMENT, title VARCHAR( 160 ) NOT NULL, artist_id INTEGER NOT NULL, FOREIGN KEY ( artist...
What is the count of customers that Steve Johnson supports?
SELECT count(*) FROM employees AS T1 JOIN customers AS T2 ON T2.support_rep_id = T1.id WHERE T1.first_name = "Steve" AND T1.last_name = "Johnson";
587
store_1
CREATE TABLE artists ( id INTEGER PRIMARY KEY AUTOINCREMENT, name VARCHAR( 120 ) ); CREATE TABLE sqlite_sequence( name,seq ); CREATE TABLE albums ( id INTEGER PRIMARY KEY AUTOINCREMENT, title VARCHAR( 160 ) NOT NULL, artist_id INTEGER NOT NULL, FOREIGN KEY ( artist...
What is the title, phone and hire date of Nancy Edwards?
SELECT title , phone , hire_date FROM employees WHERE first_name = "Nancy" AND last_name = "Edwards";
588
store_1
CREATE TABLE artists ( id INTEGER PRIMARY KEY AUTOINCREMENT, name VARCHAR( 120 ) ); CREATE TABLE sqlite_sequence( name,seq ); CREATE TABLE albums ( id INTEGER PRIMARY KEY AUTOINCREMENT, title VARCHAR( 160 ) NOT NULL, artist_id INTEGER NOT NULL, FOREIGN KEY ( artist...
What is the title, phone number and hire date for the employee named Nancy Edwards?
SELECT title , phone , hire_date FROM employees WHERE first_name = "Nancy" AND last_name = "Edwards";
589
store_1
CREATE TABLE artists ( id INTEGER PRIMARY KEY AUTOINCREMENT, name VARCHAR( 120 ) ); CREATE TABLE sqlite_sequence( name,seq ); CREATE TABLE albums ( id INTEGER PRIMARY KEY AUTOINCREMENT, title VARCHAR( 160 ) NOT NULL, artist_id INTEGER NOT NULL, FOREIGN KEY ( artist...
find the full name of employees who report to Nancy Edwards?
SELECT T2.first_name , T2.last_name FROM employees AS T1 JOIN employees AS T2 ON T1.id = T2.reports_to WHERE T1.first_name = "Nancy" AND T1.last_name = "Edwards";
590
store_1
CREATE TABLE artists ( id INTEGER PRIMARY KEY AUTOINCREMENT, name VARCHAR( 120 ) ); CREATE TABLE sqlite_sequence( name,seq ); CREATE TABLE albums ( id INTEGER PRIMARY KEY AUTOINCREMENT, title VARCHAR( 160 ) NOT NULL, artist_id INTEGER NOT NULL, FOREIGN KEY ( artist...
What is the first and last name of the employee who reports to Nancy Edwards?
SELECT T2.first_name , T2.last_name FROM employees AS T1 JOIN employees AS T2 ON T1.id = T2.reports_to WHERE T1.first_name = "Nancy" AND T1.last_name = "Edwards";
591
store_1
CREATE TABLE artists ( id INTEGER PRIMARY KEY AUTOINCREMENT, name VARCHAR( 120 ) ); CREATE TABLE sqlite_sequence( name,seq ); CREATE TABLE albums ( id INTEGER PRIMARY KEY AUTOINCREMENT, title VARCHAR( 160 ) NOT NULL, artist_id INTEGER NOT NULL, FOREIGN KEY ( artist...
What is the address of employee Nancy Edwards?
SELECT address FROM employees WHERE first_name = "Nancy" AND last_name = "Edwards";
592
store_1
CREATE TABLE artists ( id INTEGER PRIMARY KEY AUTOINCREMENT, name VARCHAR( 120 ) ); CREATE TABLE sqlite_sequence( name,seq ); CREATE TABLE albums ( id INTEGER PRIMARY KEY AUTOINCREMENT, title VARCHAR( 160 ) NOT NULL, artist_id INTEGER NOT NULL, FOREIGN KEY ( artist...
What is Nancy Edwards's address?
SELECT address FROM employees WHERE first_name = "Nancy" AND last_name = "Edwards";
593
store_1
CREATE TABLE artists ( id INTEGER PRIMARY KEY AUTOINCREMENT, name VARCHAR( 120 ) ); CREATE TABLE sqlite_sequence( name,seq ); CREATE TABLE albums ( id INTEGER PRIMARY KEY AUTOINCREMENT, title VARCHAR( 160 ) NOT NULL, artist_id INTEGER NOT NULL, FOREIGN KEY ( artist...
Find the full name of employee who supported the most number of customers.
SELECT T1.first_name , T1.last_name FROM employees AS T1 JOIN customers AS T2 ON T1.id = T2.support_rep_id GROUP BY T1.id ORDER BY count(*) DESC LIMIT 1
594
store_1
CREATE TABLE artists ( id INTEGER PRIMARY KEY AUTOINCREMENT, name VARCHAR( 120 ) ); CREATE TABLE sqlite_sequence( name,seq ); CREATE TABLE albums ( id INTEGER PRIMARY KEY AUTOINCREMENT, title VARCHAR( 160 ) NOT NULL, artist_id INTEGER NOT NULL, FOREIGN KEY ( artist...
What is the full name of the employee who has the most customers?
SELECT T1.first_name , T1.last_name FROM employees AS T1 JOIN customers AS T2 ON T1.id = T2.support_rep_id GROUP BY T1.id ORDER BY count(*) DESC LIMIT 1
595
store_1
CREATE TABLE artists ( id INTEGER PRIMARY KEY AUTOINCREMENT, name VARCHAR( 120 ) ); CREATE TABLE sqlite_sequence( name,seq ); CREATE TABLE albums ( id INTEGER PRIMARY KEY AUTOINCREMENT, title VARCHAR( 160 ) NOT NULL, artist_id INTEGER NOT NULL, FOREIGN KEY ( artist...
How many employees are living in Canada?
SELECT count(*) FROM employees WHERE country = "Canada";
596
store_1
CREATE TABLE artists ( id INTEGER PRIMARY KEY AUTOINCREMENT, name VARCHAR( 120 ) ); CREATE TABLE sqlite_sequence( name,seq ); CREATE TABLE albums ( id INTEGER PRIMARY KEY AUTOINCREMENT, title VARCHAR( 160 ) NOT NULL, artist_id INTEGER NOT NULL, FOREIGN KEY ( artist...
How many employees live in Canada?
SELECT count(*) FROM employees WHERE country = "Canada";
597
store_1
CREATE TABLE artists ( id INTEGER PRIMARY KEY AUTOINCREMENT, name VARCHAR( 120 ) ); CREATE TABLE sqlite_sequence( name,seq ); CREATE TABLE albums ( id INTEGER PRIMARY KEY AUTOINCREMENT, title VARCHAR( 160 ) NOT NULL, artist_id INTEGER NOT NULL, FOREIGN KEY ( artist...
What is employee Nancy Edwards's phone number?
SELECT phone FROM employees WHERE first_name = "Nancy" AND last_name = "Edwards";
598
store_1
CREATE TABLE artists ( id INTEGER PRIMARY KEY AUTOINCREMENT, name VARCHAR( 120 ) ); CREATE TABLE sqlite_sequence( name,seq ); CREATE TABLE albums ( id INTEGER PRIMARY KEY AUTOINCREMENT, title VARCHAR( 160 ) NOT NULL, artist_id INTEGER NOT NULL, FOREIGN KEY ( artist...
What is the the phone number of Nancy Edwards?
SELECT phone FROM employees WHERE first_name = "Nancy" AND last_name = "Edwards";
599
store_1
CREATE TABLE artists ( id INTEGER PRIMARY KEY AUTOINCREMENT, name VARCHAR( 120 ) ); CREATE TABLE sqlite_sequence( name,seq ); CREATE TABLE albums ( id INTEGER PRIMARY KEY AUTOINCREMENT, title VARCHAR( 160 ) NOT NULL, artist_id INTEGER NOT NULL, FOREIGN KEY ( artist...
Who is the youngest employee in the company? List employee's first and last name.
SELECT first_name , last_name FROM employees ORDER BY birth_date DESC LIMIT 1;