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(4, 3, 1) \times (-1, 4, -5) = (-19, 19, 19)
(-2, -3, 1) \times (0, 0, -5) = (15, -10, 0)
-2 z + z^2 = 0 \implies z \in \{ 0, 2 \}
3 + u = 0 \implies u = -3
f(u) = 2 + 3 u + u^2, \quad g(y) = 4 + 2 y \implies f(g(y)) = 30 + 22 y + 4 y^2
f(c) = 1 + c + c^2, \quad g(v) = 2 + 3 v \implies f(g(v)) = 7 + 15 v + 9 v^2
\log_{4}\left(5 + 3 c\right) = 2 \implies c = \frac{11}{3}
-64 + u^2 = 0 \implies u \in \{ -8, 8 \}
\frac{1}{6} = \frac{1}{6}
f(y) = 2 + 4 y + y^2, \quad g(u) = 3 + 3 u \implies f(g(u)) = 23 + 30 u + 9 u^2
-7 + y = 0 \implies y = 7
\log_{3}\left(3 + 2 w\right) = 2 \implies w = 3
\int \left(1\right) dy = y + C
f(y) = 3 + y + y^2, \quad g(b) = 1 + 3 b \implies f(g(b)) = 5 + 9 b + 9 b^2
\lim_{y \to 5} \left(y^2\right) = 25
-45 + 40 = -5
\int \left(1\right) dy = y + C
6 - 5 y + y^2 = 0 \implies y \in \{ 2, 3 \}
f(x) = 3 + 3 x + x^2, \quad g(w) = 4 + w \implies f(g(w)) = 31 + 11 w + w^2
f(t) = 2 + 4 t + t^2, \quad g(v) = 3 + 2 v \implies f(g(v)) = 23 + 20 v + 4 v^2
\log_{5}\left(6 + c\right) = 3 \implies c = 119
\log_{5}\left(5 + 4 a\right) = 2 \implies a = 5
8 \cdot 48 = 384
30 + 40 = 70
24 + 10 w + w^2 = 0 \implies w \in \{ -6, -4 \}
f(u) = 1 + 3 u + u^2, \quad g(a) = 4 + 3 a \implies f(g(a)) = 29 + 33 a + 9 a^2
\int \left(1\right) dv = -10 - \left(-10 - v\right) + C
(-3, -4, 3) \times (-3, 3, -5) = (11, -24, -21)
-8 + b = 0 \implies b = 8
\frac{d}{db}\left(b^2 - b^3\right) = 2 b - 3 b^2
24 - 3 = 21
2 + a = 0 \implies a = -2
\int \left(2 v\right) dv = v^2 + C
\log_{4}\left(4 + t\right) = 3 \implies t = 60
\lim_{a \to -4} \left(a\right) = -4
\log_{2}\left(1 + 4 z\right) = 3 \implies z = \frac{7}{4}
8 - 45 = -37
f(a) = 3 + 4 a + a^2, \quad g(v) = 2 + v \implies f(g(v)) = 15 + 8 v + v^2
y^2 \left(7 + b\right) = b y^2 + 7 y^2
f(x) = 5 + 2 x + x^2, \quad g(z) = 1 + 2 z \implies f(g(z)) = 8 + 8 z + 4 z^2
\frac{d}{dx}\left(x\right) = 1
(-1, -2, 4) \times (-4, 3, -4) = (-4, -20, -11)
\frac{d}{dc}\left(\cos{\left(c\right)}\right) = -\sin{\left(c\right)}
\lim_{b \to 0} \left(\sin{\left(b\right)}\right) = 0
f(u) = 4 + 2 u + u^2, \quad g(b) = 3 + 2 b \implies f(g(b)) = 19 + 16 b + 4 b^2
\int \left(1\right) dz = z + C
-10 - 13 u - 2 u^2 + u^3 = 0 \implies u \in \{ -2, -1, 5 \}
2 \left(a + v\right) v = 2 a v + 2 v^2
\frac{d}{da}\left(\sin{\left(a\right)}\right) = \cos{\left(a\right)}
w^4 \left(w + y\right) = w^4 y + w^5
\log_{4}\left(3 + 4 c\right) = 2 \implies c = \frac{13}{4}
-11 - 37 = -48
\frac{d}{dx}\left(-2\right) = 0
\lim_{a \to -3} \left(-5\right) = -5
f(c) = 5 + 3 c + c^2, \quad g(w) = 2 + 3 w \implies f(g(w)) = 15 + 21 w + 9 w^2
\int \left(-1\right) du = -u + C
-4 - 3 v + v^2 = 0 \implies v \in \{ -1, 4 \}
\lim_{v \to 5} \left(2 v\right) = 10
-4 + v^2 = 0 \implies v \in \{ -2, 2 \}
\log_{2}\left(4 + 3 v\right) = 1 \implies v = \frac{-2}{3}
\log_{5}\left(8 + u\right) = 2 \implies u = 17
-48 \cdot 12 = -576
\frac{4}{28} = \frac{1}{7}
\log_{5}\left(8 + t\right) = 1 \implies t = -3
\log_{3}\left(5 + w\right) = 1 \implies w = -2
\frac{d}{dz}\left(z\right) = 1
\lim_{y \to -5} \left(y^2\right) = 25
\frac{1}{9} = \frac{1}{9}
\lim_{w \to 4} \left(w^4\right) = 256
\frac{d}{dx}\left(x^3\right) = 3 x^2
\frac{d}{dt}\left(t^2 \left(3 + t\right)\right) = 2 t \left(3 + t\right) + t^2
\lim_{b \to -4} \left(0\right) = 0
(-1, 0, 3) \times (-5, 1, 1) = (-3, -14, -1)
2 \cdot 40 = 80
-39 \cdot 16 = -624
\int \left(-\sin{\left(y\right)}\right) dy = -1 + \cos{\left(y\right)} + C
-28 - 31 t - 2 t^2 + t^3 = 0 \implies t \in \{ -4, -1, 7 \}
\frac{d}{dt}\left(0\right) = 0
-16 + 26 x - 11 x^2 + x^3 = 0 \implies x \in \{ 1, 2, 8 \}
280 - 51 u - 6 u^2 + u^3 = 0 \implies u \in \{ -7, 5, 8 \}
\int \left(3 v^2 \cos{\left(v\right)} - v^3 \sin{\left(v\right)}\right) dv = v^3 \cos{\left(v\right)} + C
\frac{40}{48} = \frac{5}{6}
f(x) = 1 + 3 x + x^2, \quad g(b) = 1 + 3 b \implies f(g(b)) = 5 + 15 b + 9 b^2
-80 + 66 a - 15 a^2 + a^3 = 0 \implies a \in \{ 2, 5, 8 \}
\int \left(1 + \sin{\left(y\right)}\right) dy = 1 + y - \cos{\left(y\right)} + C
-20 + y + y^2 = 0 \implies y \in \{ -5, 4 \}
f(a) = 5 + a + a^2, \quad g(u) = 2 + u \implies f(g(u)) = 11 + 5 u + u^2
-2 - a + 2 a^2 + a^3 = 0 \implies a \in \{ -2, -1, 1 \}
(-4, 0, -4) \times (-3, -2, -3) = (-8, 0, 8)
\log_{3}\left(5 + 3 t\right) = 2 \implies t = \frac{4}{3}
\lim_{b \to 5} \left(7\right) = 7
\frac{d}{du}\left(-\left(8 + u\right) + u^3\right) = -1 + 3 u^2
5 + z = 0 \implies z = -5
-2 + w + w^2 = 0 \implies w \in \{ -2, 1 \}
\lim_{z \to -2} \left(z^3\right) = -8
16 \cdot 26 = 416
3 + w = 0 \implies w = -3
\int \left(-\sin{\left(t\right)}\right) dt = -1 + \cos{\left(t\right)} + C
\log_{5}\left(7 + 3 v\right) = 1 \implies v = \frac{-2}{3}
\int \left(2 \cos{\left(z\right)}\right) dz = 2 \sin{\left(z\right)} + C