text stringlengths 9 16.2k |
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-8 + u = 0 \implies u = 8 |
(-1, 2, 5) \times (1, -4, 1) = (22, 6, 2) |
6 u + 7 u^2 + u^3 = 0 \implies u \in \{ -6, -1, 0 \} |
-12 - 4 a + a^2 = 0 \implies a \in \{ -2, 6 \} |
13 + 10 = 23 |
-10 \cdot 19 = -190 |
3 + w = 0 \implies w = -3 |
-20 + v + v^2 = 0 \implies v \in \{ -5, 4 \} |
(-3, 3, 3) \times (-5, 2, 5) = (9, 0, 9) |
(3, -2, -2) \times (-3, -3, -4) = (2, 18, -15) |
f(x) = 5 + x + x^2, \quad g(y) = 3 + y \implies f(g(y)) = 17 + 7 y + y^2 |
-16 + w^2 = 0 \implies w \in \{ -4, 4 \} |
-96 - 20 b + 7 b^2 + b^3 = 0 \implies b \in \{ -8, -3, 4 \} |
f(v) = 5 + 2 v + v^2, \quad g(w) = 2 + 3 w \implies f(g(w)) = 13 + 18 w + 9 w^2 |
f(u) = 1 + 5 u + u^2, \quad g(y) = 3 + y \implies f(g(y)) = 25 + 11 y + y^2 |
2 u \left(2 + u\right) = 4 u + 2 u^2 |
f(w) = 3 + 3 w + w^2, \quad g(c) = 1 + 3 c \implies f(g(c)) = 7 + 15 c + 9 c^2 |
\log_{5}\left(4 + 4 a\right) = 3 \implies a = \frac{121}{4} |
-42 + v + v^2 = 0 \implies v \in \{ -7, 6 \} |
24 \cdot 4 = 96 |
\log_{3}\left(1 + t\right) = 2 \implies t = 8 |
-6 - w + w^2 = 0 \implies w \in \{ -2, 3 \} |
\frac{23}{28} = \frac{23}{28} |
\lim_{u \to 2} \left(-1\right) = -1 |
\lim_{a \to 3} \left(0\right) = 0 |
\log_{3}\left(7 + 2 v\right) = 1 \implies v = -2 |
\log_{4}\left(1 + 3 v\right) = 3 \implies v = 21 |
2 + w = 0 \implies w = -2 |
7 + t = 0 \implies t = -7 |
\frac{d}{dx}\left(-8 + x + \sin{\left(x\right)}\right) = 1 + \cos{\left(x\right)} |
\log_{4}\left(8 + 2 u\right) = 1 \implies u = -2 |
168 - 38 z - 5 z^2 + z^3 = 0 \implies z \in \{ -6, 4, 7 \} |
\lim_{u \to -3} \left(2 + u\right) = -1 |
\lim_{b \to 0} \left(3 + b\right) = 3 |
\int \left(1\right) du = u + C |
37 \cdot 43 = 1591 |
34 \cdot 14 = 476 |
5 + 6 t + t^2 = 0 \implies t \in \{ -5, -1 \} |
-8 + 38 = 30 |
\frac{d}{dx}\left(2 x^3\right) = 6 x^2 |
22 + 8 = 30 |
\sin{\left(b\right)} \left(-3 - b\right) = -b \sin{\left(b\right)} - 3 \sin{\left(b\right)} |
-7 + a = 0 \implies a = 7 |
\log_{4}\left(2 + z\right) = 2 \implies z = 14 |
192 - 8 y - 10 y^2 + y^3 = 0 \implies y \in \{ -4, 6, 8 \} |
f(y) = 1 + 2 y + y^2, \quad g(w) = 2 + 2 w \implies f(g(w)) = 9 + 12 w + 4 w^2 |
\log_{2}\left(2 + c\right) = 1 \implies c = 0 |
\frac{d}{dt}\left(5 t\right) = 5 |
14 + 9 z + z^2 = 0 \implies z \in \{ -7, -2 \} |
(-3, -4, 2) \times (4, 4, -4) = (8, -4, 4) |
\lim_{x \to -4} \left(x^2\right) = 16 |
27 - 28 = -1 |
\frac{d}{dz}\left(z^2 \cos{\left(z\right)}\right) = 2 z \cos{\left(z\right)} - z^2 \sin{\left(z\right)} |
\lim_{z \to 1} \left(\cos{\left(z\right)}\right) = \cos{\left(1\right)} |
\frac{-40}{7} = \frac{-40}{7} |
\int \left(4 z^3\right) dz = z^4 + C |
-40 - 16 = -56 |
1 + b = 0 \implies b = -1 |
6 + x = 0 \implies x = -6 |
\frac{d}{dz}\left(z\right) = 1 |
46 - 37 = 9 |
-38 + 41 = 3 |
\frac{-47}{28} = \frac{-47}{28} |
w x \left(9 + x\right) = 9 w x + w x^2 |
6 \cdot 38 = 228 |
(1, 1, 1) \times (1, 2, 1) = (-1, 0, 1) |
4 + y = 0 \implies y = -4 |
f(b) = 2 + 5 b + b^2, \quad g(u) = 4 + 3 u \implies f(g(u)) = 38 + 39 u + 9 u^2 |
\log_{3}\left(2 + 3 b\right) = 2 \implies b = \frac{7}{3} |
-3 + c = 0 \implies c = 3 |
-6 + w = 0 \implies w = 6 |
\lim_{c \to -2} \left(2 c\right) = -4 |
37 \cdot 14 = 518 |
(1, 4, 5) \times (0, -1, 5) = (25, -5, -1) |
\log_{2}\left(4 + c\right) = 2 \implies c = 0 |
\frac{-36}{20} = \frac{-9}{5} |
\frac{8}{9} = \frac{8}{9} |
\log_{2}\left(1 + 2 t\right) = 1 \implies t = \frac{1}{2} |
(1, 2, -1) \times (5, 4, -1) = (2, -4, -6) |
\log_{3}\left(7 + t\right) = 2 \implies t = 2 |
-32 - 7 = -39 |
24 + 11 t + t^2 = 0 \implies t \in \{ -8, -3 \} |
(-2, 2, 5) \times (2, 0, -4) = (-8, 2, -4) |
-18 - 31 = -49 |
-20 - 19 y + 2 y^2 + y^3 = 0 \implies y \in \{ -5, -1, 4 \} |
\log_{5}\left(6 + 3 u\right) = 3 \implies u = \frac{119}{3} |
(-2, 4, 1) \times (0, -3, -2) = (-5, -4, 6) |
\left(c + y\right) c = c y + c^2 |
\frac{d}{dt}\left(8 t - t^2\right) = 8 - 2 t |
\frac{23}{23} = 1 |
\log_{3}\left(8 + 3 w\right) = 2 \implies w = \frac{1}{3} |
4 + 5 v + v^2 = 0 \implies v \in \{ -4, -1 \} |
28 \cdot 15 = 420 |
(-5, -3, -5) \times (3, 5, -1) = (28, -20, -16) |
c y \left(9 + y\right) = 9 c y + c y^2 |
\frac{d}{du}\left(u^2\right) = 2 u |
\lim_{c \to -5} \left(-6 + c\right) = -11 |
y \left(-4 + y\right) = -4 y + y^2 |
\lim_{a \to -1} \left(a^2\right) = 1 |
-8 + x = 0 \implies x = 8 |
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