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4 + u = 0 \implies u = -4
-7 v + v^2 = 0 \implies v \in \{ 0, 7 \}
8 - y - 8 y^2 + y^3 = 0 \implies y \in \{ -1, 1, 8 \}
-42 + v + 8 v^2 + v^3 = 0 \implies v \in \{ -7, -3, 2 \}
19 - 32 = -13
\lim_{w \to 3} \left(\cos{\left(w\right)}\right) = \cos{\left(3\right)}
\lim_{a \to 2} \left(8 + a\right) = 10
\frac{-20}{37} = \frac{-20}{37}
-17 + 36 = 19
-43 \cdot 30 = -1290
(5, 2, 3) \times (-3, -2, 3) = (12, -24, -4)
-320 - 64 x + 5 x^2 + x^3 = 0 \implies x \in \{ -8, -5, 8 \}
\int \left(4 y^3 + \sin{\left(y\right)}\right) dy = 1 + y^4 - \cos{\left(y\right)} + C
-15 \cdot 28 = -420
\frac{d}{da}\left(\sin{\left(a\right)}\right) = \cos{\left(a\right)}
(-3, -4, -1) \times (-4, 0, 5) = (-20, 19, -16)
\sin{\left(y\right)} \left(2 + y\right) = y \sin{\left(y\right)} + 2 \sin{\left(y\right)}
-3 + z = 0 \implies z = 3
\left(a + u\right) \left(-a + u\right) = -a^2 + u^2
\log_{4}\left(2 + 4 a\right) = 1 \implies a = \frac{1}{2}
\frac{d}{da}\left(a^6\right) = 6 a^5
34 - 47 = -13
f(z) = 4 + z + z^2, \quad g(a) = 3 + 2 a \implies f(g(a)) = 16 + 14 a + 4 a^2
\frac{40}{20} = 2
22 - 8 = 14
\log_{3}\left(6 + u\right) = 1 \implies u = -3
5 + c = 0 \implies c = -5
\log_{2}\left(1 + 3 v\right) = 1 \implies v = \frac{1}{3}
10 + 7 a + a^2 = 0 \implies a \in \{ -5, -2 \}
\frac{d}{dt}\left(-8\right) = 0
(-1, -4, 2) \times (4, -4, -2) = (16, 6, 20)
f(a) = 4 + a + a^2, \quad g(c) = 1 + 3 c \implies f(g(c)) = 6 + 9 c + 9 c^2
\log_{4}\left(5 + 2 a\right) = 2 \implies a = \frac{11}{2}
f(w) = 4 + w + w^2, \quad g(y) = 2 + 3 y \implies f(g(y)) = 10 + 15 y + 9 y^2
1 + u = 0 \implies u = -1
\log_{4}\left(7 + 3 w\right) = 3 \implies w = 19
6 \left(w + y\right) = 6 w + 6 y
\int \left(\cos{\left(u\right)}\right) du = \sin{\left(u\right)} + C
13 + 23 = 36
\log_{2}\left(5 + 2 z\right) = 1 \implies z = \frac{-3}{2}
21 + 10 y + y^2 = 0 \implies y \in \{ -7, -3 \}
-2 t + t^2 = 0 \implies t \in \{ 0, 2 \}
\int \left(1\right) da = a + C
\int \left(-\cos{\left(x\right)}\right) dx = -\sin{\left(x\right)} + C
4 u + u^2 = 0 \implies u \in \{ -4, 0 \}
-4 + y = 0 \implies y = 4
\lim_{w \to 5} \left(w^3\right) = 125
\log_{3}\left(6 + z\right) = 3 \implies z = 21
\int \left(2 u\right) du = u^2 + C
-21 + 4 y + y^2 = 0 \implies y \in \{ -7, 3 \}
-5 + 4 u + u^2 = 0 \implies u \in \{ -5, 1 \}
-8 + 2 v + v^2 = 0 \implies v \in \{ -4, 2 \}
-40 - 40 = -80
v + v^2 = 0 \implies v \in \{ -1, 0 \}
\log_{5}\left(8 + 2 t\right) = 1 \implies t = \frac{-3}{2}
(-4, -4, -4) \times (3, 4, -5) = (36, -32, -4)
(2, 1, 2) \times (2, 2, -5) = (-9, 14, 2)
-1 \cdot 28 = -28
\log_{3}\left(7 + 4 w\right) = 3 \implies w = 5
14 + 5 b - 8 b^2 + b^3 = 0 \implies b \in \{ -1, 2, 7 \}
\left(-8 - w\right) \left(-8 - u\right) = 64 + 8 u + 8 w + u w
\frac{d}{da}\left(a \left(-1 + a\right)\right) = -1 + 2 a
3 + x = 0 \implies x = -3
f(c) = 5 + 3 c + c^2, \quad g(w) = 1 + 3 w \implies f(g(w)) = 9 + 15 w + 9 w^2
\frac{-29}{4} = \frac{-29}{4}
f(a) = 4 + 5 a + a^2, \quad g(z) = 4 + z \implies f(g(z)) = 40 + 13 z + z^2
-34 - 34 = -68
\frac{d}{dt}\left(t - t^4\right) = 1 - 4 t^3
f(b) = 5 + 4 b + b^2, \quad g(z) = 4 + z \implies f(g(z)) = 37 + 12 z + z^2
\log_{4}\left(1 + u\right) = 1 \implies u = 3
-45 + 24 = -21
-47 + 28 = -19
\int \left(2 a + 2 \left(9 + a\right)\right) da = 2 a \left(9 + a\right) + C
w \left(-v + w\right) = -v w + w^2
-10 - 12 = -22
f(t) = 3 + 3 t + t^2, \quad g(z) = 2 + 3 z \implies f(g(z)) = 13 + 21 z + 9 z^2
\left(b + u\right) \left(-10 + b\right) = -10 b - 10 u + b u + b^2
5 + 41 = 46
\log_{2}\left(7 + 4 z\right) = 2 \implies z = \frac{-3}{4}
-32 \cdot 14 = -448
\log_{5}\left(3 + 2 c\right) = 3 \implies c = 61
8 - 9 w + w^2 = 0 \implies w \in \{ 1, 8 \}
-3 a + 2 a^2 + a^3 = 0 \implies a \in \{ -3, 0, 1 \}
f(c) = 4 + c + c^2, \quad g(w) = 2 + w \implies f(g(w)) = 10 + 5 w + w^2
\log_{4}\left(7 + w\right) = 2 \implies w = 9
-7 + a = 0 \implies a = 7
f(z) = 3 + 4 z + z^2, \quad g(a) = 1 + a \implies f(g(a)) = 8 + 6 a + a^2
\int \left(6 v^5\right) dv = v^6 + C
\frac{-20}{24} = \frac{-5}{6}
\log_{5}\left(5 + 2 y\right) = 2 \implies y = 10
-4 + c = 0 \implies c = 4
\log_{3}\left(2 + 2 x\right) = 3 \implies x = \frac{25}{2}
(-4, -2, -1) \times (1, 2, -5) = (12, -21, -6)
f(c) = 1 + 3 c + c^2, \quad g(t) = 1 + 3 t \implies f(g(t)) = 5 + 15 t + 9 t^2
3 + a = 0 \implies a = -3
-31 + 11 = -20
f(u) = 4 + 3 u + u^2, \quad g(v) = 1 + 2 v \implies f(g(v)) = 8 + 10 v + 4 v^2
\frac{d}{du}\left(u^2\right) = 2 u
\frac{49}{18} = \frac{49}{18}
-36 - 26 = -62