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SELECT t1.country FROM inst AS t1 JOIN authorship AS t2 ON t1.instid = t2.instid JOIN papers AS t3 ON t2.paperid = t3.paperid GROUP BY t1.country ORDER BY count(*) DESC LIMIT 1
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CREATE TABLE inst (country VARCHAR, instid VARCHAR), CREATE TABLE authorship (paperid VARCHAR, instid VARCHAR), CREATE TABLE papers (paperid VARCHAR)
|
找到发表论文最多的国家。
|
SELECT t1.country FROM inst AS t1 JOIN authorship AS t2 ON t1.instid = t2.instid JOIN papers AS t3 ON t2.paperid = t3.paperid GROUP BY t1.country ORDER BY count(*) DESC LIMIT 1
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CREATE TABLE inst (country VARCHAR, instid VARCHAR), CREATE TABLE authorship (paperid VARCHAR, instid VARCHAR), CREATE TABLE papers (paperid VARCHAR)
|
找到最多数的论文所属的国家。
|
SELECT t1.name FROM inst AS t1 JOIN authorship AS t2 ON t1.instid = t2.instid JOIN papers AS t3 ON t2.paperid = t3.paperid GROUP BY t1.name ORDER BY count(*) DESC LIMIT 1
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CREATE TABLE inst (name VARCHAR, instid VARCHAR), CREATE TABLE authorship (paperid VARCHAR, instid VARCHAR), CREATE TABLE papers (paperid VARCHAR)
|
查找发表论文数量最多的组织机构的名称。
|
SELECT t1.name FROM inst AS t1 JOIN authorship AS t2 ON t1.instid = t2.instid JOIN papers AS t3 ON t2.paperid = t3.paperid GROUP BY t1.name ORDER BY count(*) DESC LIMIT 1
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CREATE TABLE inst (name VARCHAR, instid VARCHAR), CREATE TABLE authorship (paperid VARCHAR, instid VARCHAR), CREATE TABLE papers (paperid VARCHAR)
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哪个机构发表的论文最多？查找机构名称。
|
SELECT title FROM papers WHERE title LIKE "机械"
|
CREATE TABLE papers (title VARCHAR)
|
找到包含“机械”一词的论文标题。
|
SELECT title FROM papers WHERE title LIKE "机械"
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CREATE TABLE papers (title VARCHAR)
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哪些论文的标题中有子字符串“机械”？返回论文的标题。
|
SELECT title FROM papers WHERE title LIKE "数据库"
|
CREATE TABLE papers (title VARCHAR)
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哪篇文章的标题包含“数据库”一词？
|
SELECT title FROM papers WHERE title LIKE "数据库"
|
CREATE TABLE papers (title VARCHAR)
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哪些论文在标题中有子字符串“数据库”？显示论文的标题。
|
SELECT t1.fname FROM authors AS t1 JOIN authorship AS t2 ON t1.authid = t2.authid JOIN papers AS t3 ON t2.paperid = t3.paperid WHERE t3.title LIKE "功能性"
|
CREATE TABLE authors (authid VARCHAR, fname VARCHAR), CREATE TABLE authorship (paperid VARCHAR, authid VARCHAR), CREATE TABLE papers (paperid VARCHAR, title VARCHAR)
|
找出所有写过标题包括“功能性”的论文的作者的名字。
|
SELECT t1.fname FROM authors AS t1 JOIN authorship AS t2 ON t1.authid = t2.authid JOIN papers AS t3 ON t2.paperid = t3.paperid WHERE t3.title LIKE "功能性"
|
CREATE TABLE authors (authid VARCHAR, fname VARCHAR), CREATE TABLE authorship (paperid VARCHAR, authid VARCHAR), CREATE TABLE papers (paperid VARCHAR, title VARCHAR)
|
哪些人写了标题中有“功能性”一词的论文？返回作者的名字。
|
SELECT t1.lname FROM authors AS t1 JOIN authorship AS t2 ON t1.authid = t2.authid JOIN papers AS t3 ON t2.paperid = t3.paperid WHERE t3.title LIKE "单细胞"
|
CREATE TABLE authors (lname VARCHAR, authid VARCHAR), CREATE TABLE authorship (paperid VARCHAR, authid VARCHAR), CREATE TABLE papers (paperid VARCHAR, title VARCHAR)
|
查找标题包含“单细胞”的论文的所有作者的姓氏。
|
SELECT t1.lname FROM authors AS t1 JOIN authorship AS t2 ON t1.authid = t2.authid JOIN papers AS t3 ON t2.paperid = t3.paperid WHERE t3.title LIKE "单细胞"
|
CREATE TABLE authors (lname VARCHAR, authid VARCHAR), CREATE TABLE authorship (paperid VARCHAR, authid VARCHAR), CREATE TABLE papers (paperid VARCHAR, title VARCHAR)
|
哪些作者写过标题包含“单细胞”的论文？返回他们的姓氏。
|
SELECT t2.title FROM authorship AS t1 JOIN papers AS t2 ON t1.paperid = t2.paperid WHERE t1.authorder = (SELECT max(authorder) FROM authorship)
|
CREATE TABLE authorship (authorder INTEGER), CREATE TABLE papers (paperid VARCHAR, title VARCHAR)
|
查找作者最多的论文的标题。
|
SELECT t2.title FROM authorship AS t1 JOIN papers AS t2 ON t1.paperid = t2.paperid WHERE t1.authorder = (SELECT max(authorder) FROM authorship)
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CREATE TABLE authorship (authorder INTEGER), CREATE TABLE papers (paperid VARCHAR, title VARCHAR)
|
哪一篇论文的作者最多？给我论文题目。
|
SELECT fname FROM authors WHERE lname = "丁"
|
CREATE TABLE authors (lname VARCHAR, fname VARCHAR)
|
姓“丁”的作者的名字是什么？
|
SELECT fname FROM authors WHERE lname = "丁"
|
CREATE TABLE authors (lname VARCHAR, fname VARCHAR)
|
哪些作者姓“丁”？列出他们的名字。
|
SELECT lname FROM authors WHERE fname = "小鹏"
|
CREATE TABLE authors (lname VARCHAR, fname VARCHAR)
|
找到名字叫“小鹏”的作者的姓氏。
|
SELECT lname FROM authors WHERE fname = "小鹏"
|
CREATE TABLE authors (lname VARCHAR, fname VARCHAR)
|
哪些作者的名字是“小鹏”？列出他们的姓。
|
SELECT fname FROM authors ORDER BY fname
|
CREATE TABLE authors (fname VARCHAR)
|
按照字母顺序排列，找出所有作者的名字。
|
SELECT fname FROM authors ORDER BY fname
|
CREATE TABLE authors (fname VARCHAR)
|
按字母顺序给所有作者的名字排序。
|
SELECT lname FROM authors ORDER BY lname
|
CREATE TABLE authors (lname VARCHAR)
|
按字母顺序检索所有作者的姓氏。
|
SELECT lname FROM authors ORDER BY lname
|
CREATE TABLE authors (lname VARCHAR)
|
给我一份按字母顺序排序的作者的姓氏名单。
|
SELECT fname , lname FROM authors ORDER BY lname
|
CREATE TABLE authors (lname VARCHAR, fname VARCHAR)
|
按照姓氏的字母顺序排序检索所有作者的名字和姓氏。
|
SELECT fname , lname FROM authors ORDER BY lname
|
CREATE TABLE authors (lname VARCHAR, fname VARCHAR)
|
按照姓氏的字母顺序排列列出所有作者的姓氏和名字。
|
SELECT count(DISTINCT last_name) FROM actor
|
CREATE TABLE actor (last_name VARCHAR)
|
男女演员有多少不同的姓？
|
SELECT count(DISTINCT last_name) FROM actor
|
CREATE TABLE actor (last_name VARCHAR)
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计算演员的不同姓氏的数量。
|
SELECT first_name FROM actor GROUP BY first_name ORDER BY count(*) DESC LIMIT 1
|
CREATE TABLE actor (first_name VARCHAR)
|
演员最流行的名字是什么？
|
SELECT first_name FROM actor GROUP BY first_name ORDER BY count(*) DESC LIMIT 1
|
CREATE TABLE actor (first_name VARCHAR)
|
返回所有演员中最常见的名字。
|
SELECT first_name , last_name FROM actor GROUP BY first_name , last_name ORDER BY count(*) DESC LIMIT 1
|
CREATE TABLE actor (last_name VARCHAR, first_name VARCHAR)
|
演员最受欢迎的全名是什么？
|
SELECT first_name , last_name FROM actor GROUP BY first_name , last_name ORDER BY count(*) DESC LIMIT 1
|
CREATE TABLE actor (last_name VARCHAR, first_name VARCHAR)
|
返回所有演员中最常见的全名。
|
SELECT district FROM address GROUP BY district HAVING count(*) >= 2
|
CREATE TABLE address (district VARCHAR)
|
哪个地区至少有两个地址？
|
SELECT district FROM address GROUP BY district HAVING count(*) >= 2
|
CREATE TABLE address (district VARCHAR)
|
给出有两个或两个以上地址的地区。
|
SELECT phone , postal_code FROM address WHERE address = '中山东路15号'
|
CREATE TABLE address (postal_code VARCHAR, phone VARCHAR, address VARCHAR)
|
地址“中山东路15号”的电话号码和邮政编码是多少？
|
SELECT phone , postal_code FROM address WHERE address = '中山东路15号'
|
CREATE TABLE address (postal_code VARCHAR, phone VARCHAR, address VARCHAR)
|
给出对应于地址“中山东路15号”的电话和邮政编码。
|
SELECT T2.city , count(*) , T1.city_id FROM address AS T1 JOIN city AS T2 ON T1.city_id = T2.city_id GROUP BY T1.city_id ORDER BY count(*) DESC LIMIT 1
|
CREATE TABLE address (city_id VARCHAR), CREATE TABLE city (city_id VARCHAR, city VARCHAR)
|
哪个城市的地址最多？列出城市名称、地址数量和城市ID。
|
SELECT T2.city , count(*) , T1.city_id FROM address AS T1 JOIN city AS T2 ON T1.city_id = T2.city_id GROUP BY T1.city_id ORDER BY count(*) DESC LIMIT 1
|
CREATE TABLE address (city_id VARCHAR), CREATE TABLE city (city_id VARCHAR, city VARCHAR)
|
拥有最多地址的城市相对应的城市名称、id和地址的数量是什么？
|
SELECT count(*) FROM address WHERE district = '四川'
|
CREATE TABLE address (district VARCHAR)
|
“四川”地区有多少地址？
|
SELECT count(*) FROM address WHERE district = '四川'
|
CREATE TABLE address (district VARCHAR)
|
统计“四川”地区的地址。
|
SELECT title , film_id FROM film WHERE rental_rate = 0.99 INTERSECT SELECT T1.title , T1.film_id FROM film AS T1 JOIN inventory AS T2 ON T1.film_id = T2.film_id GROUP BY T1.film_id HAVING count(*) < 3
|
CREATE TABLE film (film_id VARCHAR, title VARCHAR), CREATE TABLE inventory (film_id VARCHAR)
|
哪部电影以0.99的租金出租并且存货少于3？列出电影片名和ID。
|
SELECT title , film_id FROM film WHERE rental_rate = 0.99 INTERSECT SELECT T1.title , T1.film_id FROM film AS T1 JOIN inventory AS T2 ON T1.film_id = T2.film_id GROUP BY T1.film_id HAVING count(*) < 3
|
CREATE TABLE film (film_id VARCHAR, title VARCHAR), CREATE TABLE inventory (film_id VARCHAR)
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租金为0.99而且存货少于3的电影的片名和id是什么？
|
SELECT count(*) FROM city AS T1 JOIN country AS T2 ON T1.country_id = T2.country_id WHERE T2.country = '澳大利亚'
|
CREATE TABLE city (country_id VARCHAR), CREATE TABLE country (country_id VARCHAR, country VARCHAR)
|
“澳大利亚”有多少城市？
|
SELECT count(*) FROM city AS T1 JOIN country AS T2 ON T1.country_id = T2.country_id WHERE T2.country = '澳大利亚'
|
CREATE TABLE city (country_id VARCHAR), CREATE TABLE country (country_id VARCHAR, country VARCHAR)
|
统计“澳大利亚”的城市数量。
|
SELECT T2.country FROM city AS T1 JOIN country AS T2 ON T1.country_id = T2.country_id GROUP BY T2.country_id HAVING count(*) >= 3
|
CREATE TABLE city (country_id VARCHAR), CREATE TABLE country (country_id VARCHAR, country VARCHAR)
|
哪些国家至少有3个城市？
|
SELECT T2.country FROM city AS T1 JOIN country AS T2 ON T1.country_id = T2.country_id GROUP BY T2.country_id HAVING count(*) >= 3
|
CREATE TABLE city (country_id VARCHAR), CREATE TABLE country (country_id VARCHAR, country VARCHAR)
|
包含3个或更多城市的国家是什么？
|
SELECT payment_date FROM payment WHERE amount > 10 UNION SELECT T1.payment_date FROM payment AS T1 JOIN staff AS T2 ON T1.staff_id = T2.staff_id WHERE T2.first_name = '严'
|
CREATE TABLE payment (payment_date VARCHAR, staff_id VARCHAR), CREATE TABLE staff (staff_id VARCHAR, first_name VARCHAR)
|
查找金额大于10而且由姓氏为“严”的工作人员处理的付款的日期。
|
SELECT payment_date FROM payment WHERE amount > 10 UNION SELECT T1.payment_date FROM payment AS T1 JOIN staff AS T2 ON T1.staff_id = T2.staff_id WHERE T2.first_name = '严'
|
CREATE TABLE payment (payment_date VARCHAR, staff_id VARCHAR), CREATE TABLE staff (staff_id VARCHAR, first_name VARCHAR)
|
金额大于10而且由姓氏为“严”的工作人员处理的任何付款的付款日期是什么？
|
SELECT count(*) FROM customer WHERE active = '1'
|
CREATE TABLE customer (active VARCHAR)
|
有多少客户的活跃值为“1”？
|
SELECT count(*) FROM customer WHERE active = '1'
|
CREATE TABLE customer (active VARCHAR)
|
统计活跃客户的数量。
|
SELECT title , rental_rate FROM film ORDER BY rental_rate DESC LIMIT 1
|
CREATE TABLE film (title VARCHAR, rental_rate VARCHAR)
|
哪部电影的出租率最高？比率是多少？
|
SELECT title , rental_rate FROM film ORDER BY rental_rate DESC LIMIT 1
|
CREATE TABLE film (title VARCHAR, rental_rate VARCHAR)
|
出租率最高的电影的标题和出租率是什么？
|
SELECT T2.title , T2.film_id , T2.description FROM film_actor AS T1 JOIN film AS T2 ON T1.film_id = T2.film_id GROUP BY T2.film_id ORDER BY count(*) DESC LIMIT 1
|
CREATE TABLE film_actor (film_id VARCHAR), CREATE TABLE film (film_id VARCHAR, title VARCHAR, description VARCHAR)
|
哪部电影的演员最多？列出电影名称、影片ID和描述。
|
SELECT T2.title , T2.film_id , T2.description FROM film_actor AS T1 JOIN film AS T2 ON T1.film_id = T2.film_id GROUP BY T2.film_id ORDER BY count(*) DESC LIMIT 1
|
CREATE TABLE film_actor (film_id VARCHAR), CREATE TABLE film (film_id VARCHAR, title VARCHAR, description VARCHAR)
|
演员最多的电影的片名、id和描述是什么？
|
SELECT T2.first_name , T2.last_name , T2.actor_id FROM film_actor AS T1 JOIN actor AS T2 ON T1.actor_id = T2.actor_id GROUP BY T2.actor_id ORDER BY count(*) DESC LIMIT 1
|
CREATE TABLE film_actor (actor_id VARCHAR), CREATE TABLE actor (last_name VARCHAR, actor_id VARCHAR, first_name VARCHAR)
|
哪位电影男演员（女演员）主演的电影最多？列出他或她的名字，姓氏和演员ID。
|
SELECT T2.first_name , T2.last_name , T2.actor_id FROM film_actor AS T1 JOIN actor AS T2 ON T1.actor_id = T2.actor_id GROUP BY T2.actor_id ORDER BY count(*) DESC LIMIT 1
|
CREATE TABLE film_actor (actor_id VARCHAR), CREATE TABLE actor (last_name VARCHAR, actor_id VARCHAR, first_name VARCHAR)
|
返回在最多电影中主演的男演员或女演员的全名和id。
|
SELECT T2.first_name , T2.last_name FROM film_actor AS T1 JOIN actor AS T2 ON T1.actor_id = T2.actor_id GROUP BY T2.actor_id HAVING count(*) > 30
|
CREATE TABLE film_actor (actor_id VARCHAR), CREATE TABLE actor (last_name VARCHAR, actor_id VARCHAR, first_name VARCHAR)
|
哪些电影演员扮演超过30部电影？列出他或她的名字和姓氏。
|
SELECT T2.first_name , T2.last_name FROM film_actor AS T1 JOIN actor AS T2 ON T1.actor_id = T2.actor_id GROUP BY T2.actor_id HAVING count(*) > 30
|
CREATE TABLE film_actor (actor_id VARCHAR), CREATE TABLE actor (last_name VARCHAR, actor_id VARCHAR, first_name VARCHAR)
|
在30部以上的电影中扮演过角色的演员的全名是什么？
|
SELECT store_id FROM inventory GROUP BY store_id ORDER BY count(*) DESC LIMIT 1
|
CREATE TABLE inventory (store_id VARCHAR)
|
哪个商店拥有最多的商品？
|
SELECT store_id FROM inventory GROUP BY store_id ORDER BY count(*) DESC LIMIT 1
|
CREATE TABLE inventory (store_id VARCHAR)
|
库存物品最多的商店ID是什么？
|
SELECT sum(amount) FROM payment
|
CREATE TABLE payment (amount INTEGER)
|
所有付款的总额是多少？
|
SELECT sum(amount) FROM payment
|
CREATE TABLE payment (amount INTEGER)
|
返回所有付款金额的总和。
|
SELECT T1.first_name , T1.last_name , T1.customer_id FROM customer AS T1 JOIN payment AS T2 ON T1.customer_id = T2.customer_id GROUP BY T1.customer_id ORDER BY sum(amount) ASC LIMIT 1
|
CREATE TABLE customer (last_name VARCHAR, first_name VARCHAR, customer_id VARCHAR), CREATE TABLE payment (customer_id VARCHAR)
|
哪一位客户至少花了一笔钱而且花了最少的钱？列出他或她的名字，姓氏和id。
|
SELECT T1.first_name , T1.last_name , T1.customer_id FROM customer AS T1 JOIN payment AS T2 ON T1.customer_id = T2.customer_id GROUP BY T1.customer_id ORDER BY sum(amount) ASC LIMIT 1
|
CREATE TABLE customer (last_name VARCHAR, first_name VARCHAR, customer_id VARCHAR), CREATE TABLE payment (customer_id VARCHAR)
|
付款总额最低的客户的全名和id是什么？
|
SELECT T1.name FROM category AS T1 JOIN film_category AS T2 ON T1.category_id = T2.category_id JOIN film AS T3 ON T2.film_id = T3.film_id WHERE T3.title = '邪不压正'
|
CREATE TABLE category (name VARCHAR, category_id VARCHAR), CREATE TABLE film_category (film_id VARCHAR, category_id VARCHAR), CREATE TABLE film (film_id VARCHAR, title VARCHAR)
|
电影“邪不压正”的类别名称是什么？
|
SELECT T1.name FROM category AS T1 JOIN film_category AS T2 ON T1.category_id = T2.category_id JOIN film AS T3 ON T2.film_id = T3.film_id WHERE T3.title = '邪不压正'
|
CREATE TABLE category (name VARCHAR, category_id VARCHAR), CREATE TABLE film_category (film_id VARCHAR, category_id VARCHAR), CREATE TABLE film (film_id VARCHAR, title VARCHAR)
|
返回电影“邪不压正”所属类别的名称。
|
SELECT T2.name , T1.category_id , count(*) FROM film_category AS T1 JOIN category AS T2 ON T1.category_id = T2.category_id GROUP BY T1.category_id
|
CREATE TABLE film_category (category_id VARCHAR), CREATE TABLE category (name VARCHAR, category_id VARCHAR)
|
每个类别有多少部电影？列出类别名称、类别ID和数量。
|
SELECT T2.name , T1.category_id , count(*) FROM film_category AS T1 JOIN category AS T2 ON T1.category_id = T2.category_id GROUP BY T1.category_id
|
CREATE TABLE film_category (category_id VARCHAR), CREATE TABLE category (name VARCHAR, category_id VARCHAR)
|
不同类别的名称和id是什么？每类有多少部电影？
|
SELECT T1.title , T1.film_id FROM film AS T1 JOIN inventory AS T2 ON T1.film_id = T2.film_id GROUP BY T1.film_id ORDER BY count(*) DESC LIMIT 1
|
CREATE TABLE film (film_id VARCHAR, title VARCHAR), CREATE TABLE inventory (film_id VARCHAR)
|
哪部电影库存中的副本最多？列出标题和ID。
|
SELECT T1.title , T1.film_id FROM film AS T1 JOIN inventory AS T2 ON T1.film_id = T2.film_id GROUP BY T1.film_id ORDER BY count(*) DESC LIMIT 1
|
CREATE TABLE film (film_id VARCHAR, title VARCHAR), CREATE TABLE inventory (film_id VARCHAR)
|
库存中副本最多的电影的名称和ID是什么？
|
SELECT T1.title , T2.inventory_id FROM film AS T1 JOIN inventory AS T2 ON T1.film_id = T2.film_id JOIN rental AS T3 ON T2.inventory_id = T3.inventory_id GROUP BY T2.inventory_id ORDER BY count(*) DESC LIMIT 1
|
CREATE TABLE film (film_id VARCHAR, title VARCHAR), CREATE TABLE inventory (film_id VARCHAR, inventory_id VARCHAR), CREATE TABLE rental (inventory_id VARCHAR)
|
库存中最常被租用的项目的电影名称和库存id是什么？
|
SELECT T1.title , T2.inventory_id FROM film AS T1 JOIN inventory AS T2 ON T1.film_id = T2.film_id JOIN rental AS T3 ON T2.inventory_id = T3.inventory_id GROUP BY T2.inventory_id ORDER BY count(*) DESC LIMIT 1
|
CREATE TABLE film (film_id VARCHAR, title VARCHAR), CREATE TABLE inventory (film_id VARCHAR, inventory_id VARCHAR), CREATE TABLE rental (inventory_id VARCHAR)
|
返回最常被租用的电影的标题和库存ID。
|
SELECT count(DISTINCT language_id) FROM film
|
CREATE TABLE film (language_id VARCHAR)
|
这些电影有多少种语言？
|
SELECT count(DISTINCT language_id) FROM film
|
CREATE TABLE film (language_id VARCHAR)
|
计算这些影片中不同语言的数量。
|
SELECT title FROM film WHERE rating = 'R'
|
CREATE TABLE film (title VARCHAR, rating VARCHAR)
|
所有评级为“R”的电影是什么？列出标题。
|
SELECT title FROM film WHERE rating = 'R'
|
CREATE TABLE film (title VARCHAR, rating VARCHAR)
|
返回所有评级为“R”的电影的标题。
|
SELECT T2.address FROM store AS T1 JOIN address AS T2 ON T1.address_id = T2.address_id WHERE store_id = 1
|
CREATE TABLE store (address_id VARCHAR), CREATE TABLE address (address_id VARCHAR, address VARCHAR)
|
商店1在哪里？
|
SELECT T2.address FROM store AS T1 JOIN address AS T2 ON T1.address_id = T2.address_id WHERE store_id = 1
|
CREATE TABLE store (address_id VARCHAR), CREATE TABLE address (address_id VARCHAR, address VARCHAR)
|
返回商店1的地址。
|
SELECT T1.first_name , T1.last_name , T1.staff_id FROM staff AS T1 JOIN payment AS T2 ON T1.staff_id = T2.staff_id GROUP BY T1.staff_id ORDER BY count(*) ASC LIMIT 1
|
CREATE TABLE staff (last_name VARCHAR, staff_id VARCHAR, first_name VARCHAR), CREATE TABLE payment (staff_id VARCHAR)
|
哪些员工处理的付款次数最少？列出全名和ID。
|
SELECT T1.first_name , T1.last_name , T1.staff_id FROM staff AS T1 JOIN payment AS T2 ON T1.staff_id = T2.staff_id GROUP BY T1.staff_id ORDER BY count(*) ASC LIMIT 1
|
CREATE TABLE staff (last_name VARCHAR, staff_id VARCHAR, first_name VARCHAR), CREATE TABLE payment (staff_id VARCHAR)
|
给出处理付款最少的工作人员的全名和工作人员ID。
|
SELECT T2.name FROM film AS T1 JOIN LANGUAGE AS T2 ON T1.language_id = T2.language_id WHERE T1.title = '暗战'
|
CREATE TABLE film (title VARCHAR, language_id VARCHAR), CREATE TABLE LANGUAGE (name VARCHAR, language_id VARCHAR)
|
电影“暗战”使用的是哪种语言？列出语言名称。
|
SELECT T2.name FROM film AS T1 JOIN LANGUAGE AS T2 ON T1.language_id = T2.language_id WHERE T1.title = '暗战'
|
CREATE TABLE film (title VARCHAR, language_id VARCHAR), CREATE TABLE LANGUAGE (name VARCHAR, language_id VARCHAR)
|
电影“暗战”中使用的语言是什么？
|
SELECT count(*) FROM store
|
CREATE TABLE store (Id VARCHAR)
|
有多少商店？
|
SELECT count(*) FROM store
|
CREATE TABLE store (Id VARCHAR)
|
统计商店的数量。
|
SELECT count(DISTINCT rating) FROM film
|
CREATE TABLE film (rating VARCHAR)
|
一共有多少种不同的评级？
|
SELECT count(DISTINCT rating) FROM film
|
CREATE TABLE film (rating VARCHAR)
|
计算电影的不同评级的数量。
|
SELECT title FROM film WHERE special_features LIKE '删除场景'
|
CREATE TABLE film (title VARCHAR, special_features VARCHAR)
|
哪些电影有“删除场景”作为特色的一部分？
|
SELECT title FROM film WHERE special_features LIKE '删除场景'
|
CREATE TABLE film (title VARCHAR, special_features VARCHAR)
|
返回包含“删除场景”作为特色的电影的标题。
|
SELECT count(*) FROM inventory WHERE store_id = 1
|
CREATE TABLE inventory (store_id VARCHAR)
|
商店1的库存中有多少种物品？
|
SELECT count(*) FROM inventory WHERE store_id = 1
|
CREATE TABLE inventory (store_id VARCHAR)
|
统计商店1库存物品的数量。
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SELECT payment_date FROM payment ORDER BY payment_date ASC LIMIT 1
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CREATE TABLE payment (payment_date VARCHAR)
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第一次付款是什么时候发生的？
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SELECT payment_date FROM payment ORDER BY payment_date ASC LIMIT 1
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CREATE TABLE payment (payment_date VARCHAR)
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最早付款的日期是什么？
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SELECT T2.address , T1.email FROM customer AS T1 JOIN address AS T2 ON T2.address_id = T1.address_id WHERE T1.first_name = '天天'
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CREATE TABLE customer (address_id VARCHAR, email VARCHAR, first_name VARCHAR), CREATE TABLE address (address_id VARCHAR, address VARCHAR)
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名为“天天”的客户住在哪里？她的电子邮件是什么？
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SELECT T2.address , T1.email FROM customer AS T1 JOIN address AS T2 ON T2.address_id = T1.address_id WHERE T1.first_name = '天天'
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CREATE TABLE customer (address_id VARCHAR, email VARCHAR, first_name VARCHAR), CREATE TABLE address (address_id VARCHAR, address VARCHAR)
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返回名为“天天”的客户的地址和电子邮件。
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SELECT title FROM film WHERE LENGTH > 100 OR rating = '限制' EXCEPT SELECT title FROM film WHERE replacement_cost > 200
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CREATE TABLE film (title VARCHAR, replacement_cost INTEGER, LENGTH INTEGER, rating VARCHAR)
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找到所有超过100分钟或评级为“限制”的电影，去掉那些替换时间花费超过200的。列出标题。
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SELECT title FROM film WHERE LENGTH > 100 OR rating = '限制' EXCEPT SELECT title FROM film WHERE replacement_cost > 200
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CREATE TABLE film (title VARCHAR, replacement_cost INTEGER, LENGTH INTEGER, rating VARCHAR)
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除了那些替换时间花费超过200多分钟的电影之外，超过100分钟或者评级为限制级的电影的片名是什么？
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SELECT T1.first_name , T1.last_name FROM customer AS T1 JOIN rental AS T2 ON T1.customer_id = T2.customer_id ORDER BY T2.rental_date ASC LIMIT 1
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CREATE TABLE customer (last_name VARCHAR, first_name VARCHAR, customer_id VARCHAR), CREATE TABLE rental (rental_date VARCHAR, customer_id VARCHAR)
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最早租房的客户的名字和姓氏是什么？
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SELECT T1.first_name , T1.last_name FROM customer AS T1 JOIN rental AS T2 ON T1.customer_id = T2.customer_id ORDER BY T2.rental_date ASC LIMIT 1
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CREATE TABLE customer (last_name VARCHAR, first_name VARCHAR, customer_id VARCHAR), CREATE TABLE rental (rental_date VARCHAR, customer_id VARCHAR)
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返回最早租房的客户的全名。
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SELECT DISTINCT T1.first_name , T1.last_name FROM staff AS T1 JOIN rental AS T2 ON T1.staff_id = T2.staff_id JOIN customer AS T3 ON T2.customer_id = T3.customer_id WHERE T3.first_name = '晓月' AND T3.last_name = '张'
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CREATE TABLE staff (last_name VARCHAR, staff_id VARCHAR, first_name VARCHAR), CREATE TABLE rental (staff_id VARCHAR, customer_id VARCHAR), CREATE TABLE customer (last_name VARCHAR, first_name VARCHAR, customer_id VARCHAR)
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租了一部电影给一位名为“晓月”姓为“张”的顾客的职员的全名是什么？
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SELECT DISTINCT T1.first_name , T1.last_name FROM staff AS T1 JOIN rental AS T2 ON T1.staff_id = T2.staff_id JOIN customer AS T3 ON T2.customer_id = T3.customer_id WHERE T3.first_name = '晓月' AND T3.last_name = '张'
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CREATE TABLE staff (last_name VARCHAR, staff_id VARCHAR, first_name VARCHAR), CREATE TABLE rental (staff_id VARCHAR, customer_id VARCHAR), CREATE TABLE customer (last_name VARCHAR, first_name VARCHAR, customer_id VARCHAR)
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返回给姓是“张”名是“晓月”的客户提供电影租赁的员工的全名。
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SELECT store_id FROM customer GROUP BY store_id ORDER BY count(*) DESC LIMIT 1
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CREATE TABLE customer (store_id VARCHAR)
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哪个商店的顾客最多？
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SELECT store_id FROM customer GROUP BY store_id ORDER BY count(*) DESC LIMIT 1
|
CREATE TABLE customer (store_id VARCHAR)
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返回顾客最多的商店的id。
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