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CSpider_sql_create_context

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SELECT amount FROM payment ORDER BY amount DESC LIMIT 1
CREATE TABLE payment (amount VARCHAR)
最大的支付金额是多少？
SELECT amount FROM payment ORDER BY amount DESC LIMIT 1
CREATE TABLE payment (amount VARCHAR)
返回最大的支付的金额。
SELECT T2.address FROM staff AS T1 JOIN address AS T2 ON T1.address_id = T2.address_id WHERE T1.first_name = '严'
CREATE TABLE staff (address_id VARCHAR, first_name VARCHAR), CREATE TABLE address (address_id VARCHAR, address VARCHAR)
姓“严”的工作人员住在哪里？
SELECT T2.address FROM staff AS T1 JOIN address AS T2 ON T1.address_id = T2.address_id WHERE T1.first_name = '严'
CREATE TABLE staff (address_id VARCHAR, first_name VARCHAR), CREATE TABLE address (address_id VARCHAR, address VARCHAR)
请给出姓为“严”的工作人员的地址。
SELECT first_name FROM customer WHERE customer_id NOT IN( SELECT customer_id FROM rental WHERE rental_date > '2005-08-23 02:06:01' )
CREATE TABLE customer (rental_date INTEGER, first_name VARCHAR, customer_id VARCHAR), CREATE TABLE rental (rental_date INTEGER, first_name VARCHAR, customer_id VARCHAR)
在“2005-08-2302:06:01”之后没有租过电影的客户的名字是什么？
SELECT first_name FROM customer WHERE customer_id NOT IN( SELECT customer_id FROM rental WHERE rental_date > '2005-08-23 02:06:01' )
CREATE TABLE customer (rental_date INTEGER, first_name VARCHAR, customer_id VARCHAR), CREATE TABLE rental (rental_date INTEGER, first_name VARCHAR, customer_id VARCHAR)
返回在“2005-08-2302:06:01”之后没有租电影的客户的名字。
SELECT count(*) FROM bank
CREATE TABLE bank (Id VARCHAR)
有多少银行分行？
SELECT count(*) FROM bank
CREATE TABLE bank (Id VARCHAR)
统计银行分行的数量。
SELECT sum(no_of_customers) FROM bank
CREATE TABLE bank (no_of_customers INTEGER)
有多少顾客？
SELECT sum(no_of_customers) FROM bank
CREATE TABLE bank (no_of_customers INTEGER)
银行的总客户数是多少？
SELECT sum(no_of_customers) FROM bank WHERE city = '上海'
CREATE TABLE bank (city VARCHAR, no_of_customers INTEGER)
找到“上海市”的银行的客户数量。
SELECT sum(no_of_customers) FROM bank WHERE city = '上海'
CREATE TABLE bank (city VARCHAR, no_of_customers INTEGER)
使用“上海市”的银行的客户总数是多少？
SELECT avg(no_of_customers) FROM bank WHERE state = '江西'
CREATE TABLE bank (state VARCHAR, no_of_customers INTEGER)
找出犹他各州的银行的平均客户数。
SELECT avg(no_of_customers) FROM bank WHERE state = '江西'
CREATE TABLE bank (state VARCHAR, no_of_customers INTEGER)
“江西”的银行的平均客户数是多少？
SELECT avg(no_of_customers) FROM bank
CREATE TABLE bank (no_of_customers INTEGER)
找到所有银行的平均客户数。
SELECT avg(no_of_customers) FROM bank
CREATE TABLE bank (no_of_customers INTEGER)
银行客户的平均数量是多少？
SELECT city , state FROM bank WHERE bname = '浦发'
CREATE TABLE bank (state VARCHAR, city VARCHAR, bname VARCHAR)
找到名为“浦发”的银行分行所在的城市和州。
SELECT city , state FROM bank WHERE bname = '浦发'
CREATE TABLE bank (state VARCHAR, city VARCHAR, bname VARCHAR)
名为“浦发”的银行所在的城市和州是什么？
SELECT bname FROM bank WHERE state = '上海'
CREATE TABLE bank (state VARCHAR, bname VARCHAR)
查找“上海”的银行分行名称。
SELECT bname FROM bank WHERE state = '上海'
CREATE TABLE bank (state VARCHAR, bname VARCHAR)
“上海”的银行的名称是什么？
SELECT cust_name FROM customer ORDER BY acc_bal
CREATE TABLE customer (acc_bal VARCHAR, cust_name VARCHAR)
按帐户余额升序排列列出所有客户的名字。
SELECT cust_name FROM customer ORDER BY acc_bal
CREATE TABLE customer (acc_bal VARCHAR, cust_name VARCHAR)
按账户余额排序，所有客户的名字是什么？
SELECT T1.cust_name FROM customer AS T1 JOIN loan AS T2 ON T1.cust_id = T2.cust_id GROUP BY T1.cust_name ORDER BY sum(T2.amount)
CREATE TABLE customer (cust_id VARCHAR, cust_name VARCHAR), CREATE TABLE loan (amount INTEGER, cust_id VARCHAR)
按贷款总额排序列出所有不同客户的名字。
SELECT T1.cust_name FROM customer AS T1 JOIN loan AS T2 ON T1.cust_id = T2.cust_id GROUP BY T1.cust_name ORDER BY sum(T2.amount)
CREATE TABLE customer (cust_id VARCHAR, cust_name VARCHAR), CREATE TABLE loan (amount INTEGER, cust_id VARCHAR)
按贷款总额排序，不同客户的名字是什么？
SELECT state , acc_type , credit_score FROM customer WHERE no_of_loans = 0
CREATE TABLE customer (acc_type VARCHAR, state VARCHAR, no_of_loans VARCHAR, credit_score VARCHAR)
查找贷款数额为0的客户的状态、帐户类型和信用评分。
SELECT state , acc_type , credit_score FROM customer WHERE no_of_loans = 0
CREATE TABLE customer (acc_type VARCHAR, state VARCHAR, no_of_loans VARCHAR, credit_score VARCHAR)
零贷款的客户的状态、账户类型和信用评分是什么？
SELECT count(DISTINCT city) FROM bank
CREATE TABLE bank (city VARCHAR)
找出银行所处的不同城市的数量。
SELECT count(DISTINCT city) FROM bank
CREATE TABLE bank (city VARCHAR)
银行所在多少个不同的城市？
SELECT count(DISTINCT state) FROM bank
CREATE TABLE bank (state VARCHAR)
找出银行所处的不同州的数目。
SELECT count(DISTINCT state) FROM bank
CREATE TABLE bank (state VARCHAR)
银行所在有多少不同的州？
SELECT count(DISTINCT acc_type) FROM customer
CREATE TABLE customer (acc_type VARCHAR)
有多少种不同类型的账户？
SELECT count(DISTINCT acc_type) FROM customer
CREATE TABLE customer (acc_type VARCHAR)
计算不同帐户类型的数量。
SELECT cust_name , acc_bal FROM customer WHERE cust_name LIKE 'a'
CREATE TABLE customer (acc_bal VARCHAR, cust_name VARCHAR)
找到名字中包含字母“a”的客户的姓名和账户余额.
SELECT cust_name , acc_bal FROM customer WHERE cust_name LIKE 'a'
CREATE TABLE customer (acc_bal VARCHAR, cust_name VARCHAR)
名字中包含字母“a”的客户姓名和账户余额是什么？
SELECT sum(acc_bal) FROM customer WHERE state = '江西' OR state = '云南'
CREATE TABLE customer (state VARCHAR, acc_bal INTEGER)
查找来自“江西”或“云南”的每个客户的总账户余额。
SELECT sum(acc_bal) FROM customer WHERE state = '江西' OR state = '云南'
CREATE TABLE customer (state VARCHAR, acc_bal INTEGER)
来自“江西”或“云南”的每个客户的总账户余额是多少？
SELECT cust_name FROM customer WHERE acc_type = '存储' INTERSECT SELECT cust_name FROM customer WHERE acc_type = '支票'
CREATE TABLE customer (acc_type VARCHAR, cust_name VARCHAR)
查找同时有“存储”和“支票”帐户类型的客户的名字。
SELECT cust_name FROM customer WHERE acc_type = '存储' INTERSECT SELECT cust_name FROM customer WHERE acc_type = '支票'
CREATE TABLE customer (acc_type VARCHAR, cust_name VARCHAR)
同时拥有“存储”账户和“支票”账户的客户名字是什么？
SELECT cust_name FROM customer EXCEPT SELECT cust_name FROM customer WHERE acc_type = '存储'
CREATE TABLE customer (acc_type VARCHAR, cust_name VARCHAR)
查找没有“存储”账户的客户的名字。
SELECT cust_name FROM customer EXCEPT SELECT cust_name FROM customer WHERE acc_type = '存储'
CREATE TABLE customer (acc_type VARCHAR, cust_name VARCHAR)
没有“存储”账户的客户的名字是什么？
SELECT cust_name FROM customer EXCEPT SELECT T1.cust_name FROM customer AS T1 JOIN loan AS T2 ON T1.cust_id = T2.cust_id WHERE T2.loan_type = '抵押'
CREATE TABLE customer (cust_id VARCHAR, cust_name VARCHAR), CREATE TABLE loan (cust_id VARCHAR, loan_type VARCHAR)
查找没有“抵押”类型贷款的客户的名字。
SELECT cust_name FROM customer EXCEPT SELECT T1.cust_name FROM customer AS T1 JOIN loan AS T2 ON T1.cust_id = T2.cust_id WHERE T2.loan_type = '抵押'
CREATE TABLE customer (cust_id VARCHAR, cust_name VARCHAR), CREATE TABLE loan (cust_id VARCHAR, loan_type VARCHAR)
那些没有接受过“抵押”贷款的客户的名字是什么？
SELECT T1.cust_name FROM customer AS T1 JOIN loan AS T2 ON T1.cust_id = T2.cust_id WHERE loan_type = '抵押' INTERSECT SELECT T1.cust_name FROM customer AS T1 JOIN loan AS T2 ON T1.cust_id = T2.cust_id WHERE loan_type = '汽车'
CREATE TABLE customer (cust_id VARCHAR, cust_name VARCHAR), CREATE TABLE loan (cust_id VARCHAR)
查找有“抵押”贷款和“汽车”贷款的客户的名字。
SELECT T1.cust_name FROM customer AS T1 JOIN loan AS T2 ON T1.cust_id = T2.cust_id WHERE loan_type = '抵押' INTERSECT SELECT T1.cust_name FROM customer AS T1 JOIN loan AS T2 ON T1.cust_id = T2.cust_id WHERE loan_type = '汽车'
CREATE TABLE customer (cust_id VARCHAR, cust_name VARCHAR), CREATE TABLE loan (cust_id VARCHAR)
有过“抵押”贷款和“汽车”贷款的客户的名字是什么？
SELECT cust_name FROM customer WHERE credit_score < (SELECT avg(credit_score) FROM customer)
CREATE TABLE customer (cust_name VARCHAR, credit_score INTEGER)
查找信用评分低于所有客户平均信用评分的客户的名字。
SELECT cust_name FROM customer WHERE credit_score < (SELECT avg(credit_score) FROM customer)
CREATE TABLE customer (cust_name VARCHAR, credit_score INTEGER)
信用评分低于所有客户平均信用评分的客户的名字是什么？
SELECT bname FROM bank ORDER BY no_of_customers DESC LIMIT 1
CREATE TABLE bank (no_of_customers VARCHAR, bname VARCHAR)
找到客户数量最多的银行支行名称。
SELECT bname FROM bank ORDER BY no_of_customers DESC LIMIT 1
CREATE TABLE bank (no_of_customers VARCHAR, bname VARCHAR)
客户数量最多的银行支行的名称是什么？
SELECT cust_name FROM customer ORDER BY credit_score LIMIT 1
CREATE TABLE customer (cust_name VARCHAR, credit_score VARCHAR)
查找信用评分最低的客户的名字。
SELECT cust_name FROM customer ORDER BY credit_score LIMIT 1
CREATE TABLE customer (cust_name VARCHAR, credit_score VARCHAR)
信用评分最差的客户的名字是什么？
SELECT cust_name , acc_type , acc_bal FROM customer ORDER BY credit_score DESC LIMIT 1
CREATE TABLE customer (acc_type VARCHAR, acc_bal VARCHAR, cust_name VARCHAR, credit_score VARCHAR)
查找具有最高信用评分的客户的名字、帐户类型和帐户余额。
SELECT cust_name , acc_type , acc_bal FROM customer ORDER BY credit_score DESC LIMIT 1
CREATE TABLE customer (acc_type VARCHAR, acc_bal VARCHAR, cust_name VARCHAR, credit_score VARCHAR)
具有最高信用评分的客户相对应的名字、帐户类型和帐户余额是什么？
SELECT T1.cust_name FROM customer AS T1 JOIN loan AS T2 ON T1.cust_id = T2.cust_id GROUP BY T1.cust_name ORDER BY sum(T2.amount) DESC LIMIT 1
CREATE TABLE customer (cust_id VARCHAR, cust_name VARCHAR), CREATE TABLE loan (amount INTEGER, cust_id VARCHAR)
查找贷款金额最高的客户的名字。
SELECT T1.cust_name FROM customer AS T1 JOIN loan AS T2 ON T1.cust_id = T2.cust_id GROUP BY T1.cust_name ORDER BY sum(T2.amount) DESC LIMIT 1
CREATE TABLE customer (cust_id VARCHAR, cust_name VARCHAR), CREATE TABLE loan (amount INTEGER, cust_id VARCHAR)
总贷款金额最大的客户名字是什么？
SELECT state FROM bank GROUP BY state ORDER BY sum(no_of_customers) DESC LIMIT 1
CREATE TABLE bank (state VARCHAR, no_of_customers INTEGER)
找出客户数量最多的州。
SELECT state FROM bank GROUP BY state ORDER BY sum(no_of_customers) DESC LIMIT 1
CREATE TABLE bank (state VARCHAR, no_of_customers INTEGER)
哪一个州的银行客户总数最大？
SELECT avg(acc_bal) , acc_type FROM customer WHERE credit_score < 50 GROUP BY acc_type
CREATE TABLE customer (acc_type VARCHAR, acc_bal INTEGER, credit_score INTEGER)
针对每个账户类型，找到信用评分低于50的客户的平均账户余额。
SELECT avg(acc_bal) , acc_type FROM customer WHERE credit_score < 50 GROUP BY acc_type
CREATE TABLE customer (acc_type VARCHAR, acc_bal INTEGER, credit_score INTEGER)
针对不同的账户类型，信用评分低于50的客户的平均账户余额是多少？
SELECT sum(acc_bal) , state FROM customer WHERE credit_score > 100 GROUP BY state
CREATE TABLE customer (state VARCHAR, acc_bal INTEGER, credit_score INTEGER)
针对每个州，找到信用评分超过100的客户的总账户余额。
SELECT sum(acc_bal) , state FROM customer WHERE credit_score > 100 GROUP BY state
CREATE TABLE customer (state VARCHAR, acc_bal INTEGER, credit_score INTEGER)
对于不同州的信用评分超过100的客户，帐户总余额是多少？
SELECT sum(amount) , T1.bname FROM bank AS T1 JOIN loan AS T2 ON T1.branch_id = T2.branch_id GROUP BY T1.bname
CREATE TABLE bank (branch_id VARCHAR, bname VARCHAR), CREATE TABLE loan (branch_id VARCHAR)
找到每个银行分行所提供的贷款总额。
SELECT sum(amount) , T1.bname FROM bank AS T1 JOIN loan AS T2 ON T1.branch_id = T2.branch_id GROUP BY T1.bname
CREATE TABLE bank (branch_id VARCHAR, bname VARCHAR), CREATE TABLE loan (branch_id VARCHAR)
不同的银行分行的名称是什么，它们的贷款总额是多少？
SELECT T1.cust_name FROM customer AS T1 JOIN loan AS T2 ON T1.cust_id = T2.cust_id GROUP BY T1.cust_name HAVING count(*) > 1
CREATE TABLE customer (cust_id VARCHAR, cust_name VARCHAR), CREATE TABLE loan (cust_id VARCHAR)
查找拥有不止一笔贷款的客户的姓名。
SELECT T1.cust_name FROM customer AS T1 JOIN loan AS T2 ON T1.cust_id = T2.cust_id GROUP BY T1.cust_name HAVING count(*) > 1
CREATE TABLE customer (cust_id VARCHAR, cust_name VARCHAR), CREATE TABLE loan (cust_id VARCHAR)
拥有一笔以上贷款的客户的姓名是什么？
SELECT T1.cust_name , T1.acc_type FROM customer AS T1 JOIN loan AS T2 ON T1.cust_id = T2.cust_id GROUP BY T1.cust_name HAVING sum(T2.amount) > 5000
CREATE TABLE customer (acc_type VARCHAR, cust_id VARCHAR, cust_name VARCHAR), CREATE TABLE loan (amount INTEGER, cust_id VARCHAR)
查找贷款总额超过5000的客户的姓名和账户余额。
SELECT T1.cust_name , T1.acc_type FROM customer AS T1 JOIN loan AS T2 ON T1.cust_id = T2.cust_id GROUP BY T1.cust_name HAVING sum(T2.amount) > 5000
CREATE TABLE customer (acc_type VARCHAR, cust_id VARCHAR, cust_name VARCHAR), CREATE TABLE loan (amount INTEGER, cust_id VARCHAR)
贷款总额超过5000的客户的姓名和账户余额是多少？
SELECT T1.bname FROM bank AS T1 JOIN loan AS T2 ON T1.branch_id = T2.branch_id GROUP BY T1.bname ORDER BY sum(T2.amount) DESC LIMIT 1
CREATE TABLE bank (branch_id VARCHAR, bname VARCHAR), CREATE TABLE loan (branch_id VARCHAR, amount INTEGER)
查找提供最大贷款总额的银行支行的名称。
SELECT T1.bname FROM bank AS T1 JOIN loan AS T2 ON T1.branch_id = T2.branch_id GROUP BY T1.bname ORDER BY sum(T2.amount) DESC LIMIT 1
CREATE TABLE bank (branch_id VARCHAR, bname VARCHAR), CREATE TABLE loan (branch_id VARCHAR, amount INTEGER)
贷款额度最大的银行支行的名称是什么？
SELECT T2.bname FROM loan AS T1 JOIN bank AS T2 ON T1.branch_id = T2.branch_id JOIN customer AS T3 ON T1.cust_id = T3.cust_id WHERE T3.credit_score < 100 GROUP BY T2.bname ORDER BY sum(T1.amount) DESC LIMIT 1
CREATE TABLE loan (branch_id VARCHAR, cust_id VARCHAR, amount INTEGER), CREATE TABLE bank (branch_id VARCHAR, bname VARCHAR), CREATE TABLE customer (cust_id VARCHAR, credit_score INTEGER)
找出向信用评分小于100的客户提供最大贷款总额的银行支行的名称。
SELECT T2.bname FROM loan AS T1 JOIN bank AS T2 ON T1.branch_id = T2.branch_id JOIN customer AS T3 ON T1.cust_id = T3.cust_id WHERE T3.credit_score < 100 GROUP BY T2.bname ORDER BY sum(T1.amount) DESC LIMIT 1
CREATE TABLE loan (branch_id VARCHAR, cust_id VARCHAR, amount INTEGER), CREATE TABLE bank (branch_id VARCHAR, bname VARCHAR), CREATE TABLE customer (cust_id VARCHAR, credit_score INTEGER)
针对那些信用评分低于100分的客户，放贷总额最大的银行支行的名字是什么？
SELECT DISTINCT T1.bname FROM bank AS T1 JOIN loan AS T2 ON T1.branch_id = T2.branch_id
CREATE TABLE bank (branch_id VARCHAR, bname VARCHAR), CREATE TABLE loan (branch_id VARCHAR)
查找提供过贷款的银行支行的名称。
SELECT DISTINCT T1.bname FROM bank AS T1 JOIN loan AS T2 ON T1.branch_id = T2.branch_id
CREATE TABLE bank (branch_id VARCHAR, bname VARCHAR), CREATE TABLE loan (branch_id VARCHAR)
提供过贷款的不同银行的名称是什么？
SELECT DISTINCT T1.cust_name , T1.credit_score FROM customer AS T1 JOIN loan AS T2 ON T1.cust_id = T2.cust_id
CREATE TABLE customer (cust_id VARCHAR, cust_name VARCHAR, credit_score VARCHAR), CREATE TABLE loan (cust_id VARCHAR)
查找有贷款的客户的姓名和信用评分。
SELECT DISTINCT T1.cust_name , T1.credit_score FROM customer AS T1 JOIN loan AS T2 ON T1.cust_id = T2.cust_id
CREATE TABLE customer (cust_id VARCHAR, cust_name VARCHAR, credit_score VARCHAR), CREATE TABLE loan (cust_id VARCHAR)
贷过款的不同客户的姓名和信用评分是什么？
SELECT T1.cust_name FROM customer AS T1 JOIN loan AS T2 ON T1.cust_id = T2.cust_id WHERE amount > 3000
CREATE TABLE customer (cust_id VARCHAR, cust_name VARCHAR), CREATE TABLE loan (cust_id VARCHAR)
找到贷款数额超过3000的客户的名字。
SELECT T1.cust_name FROM customer AS T1 JOIN loan AS T2 ON T1.cust_id = T2.cust_id WHERE amount > 3000
CREATE TABLE customer (cust_id VARCHAR, cust_name VARCHAR), CREATE TABLE loan (cust_id VARCHAR)
贷款金额超过3000的客户名字是什么？
SELECT T1.bname , T1.city FROM bank AS T1 JOIN loan AS T2 ON T1.branch_id = T2.branch_id WHERE T2.loan_type = '商业'
CREATE TABLE bank (branch_id VARCHAR, city VARCHAR, bname VARCHAR), CREATE TABLE loan (branch_id VARCHAR, loan_type VARCHAR)
查找提供“商业”贷款的银行分行的名称和所在的城市名称。
SELECT T1.bname , T1.city FROM bank AS T1 JOIN loan AS T2 ON T1.branch_id = T2.branch_id WHERE T2.loan_type = '商业'
CREATE TABLE bank (branch_id VARCHAR, city VARCHAR, bname VARCHAR), CREATE TABLE loan (branch_id VARCHAR, loan_type VARCHAR)
提供“商业”贷款的银行支行的名称和所在城市是什么？
SELECT T2.bname FROM loan AS T1 JOIN bank AS T2 ON T1.branch_id = T2.branch_id JOIN customer AS T3 ON T1.cust_id = T3.cust_id WHERE T3.credit_score < 100
CREATE TABLE loan (branch_id VARCHAR, cust_id VARCHAR), CREATE TABLE bank (branch_id VARCHAR, bname VARCHAR), CREATE TABLE customer (cust_id VARCHAR, credit_score INTEGER)
查找向信用评分低于100的任何客户提供过贷款的银行分行的名称。
SELECT T2.bname FROM loan AS T1 JOIN bank AS T2 ON T1.branch_id = T2.branch_id JOIN customer AS T3 ON T1.cust_id = T3.cust_id WHERE T3.credit_score < 100
CREATE TABLE loan (branch_id VARCHAR, cust_id VARCHAR), CREATE TABLE bank (branch_id VARCHAR, bname VARCHAR), CREATE TABLE customer (cust_id VARCHAR, credit_score INTEGER)
贷款给信用评分低于100分的客户的银行的名称是什么？
SELECT sum(T2.amount) FROM bank AS T1 JOIN loan AS T2 ON T1.branch_id = T2.branch_id WHERE T1.state = '上海'
CREATE TABLE bank (branch_id VARCHAR, state VARCHAR), CREATE TABLE loan (amount INTEGER, branch_id VARCHAR)
查找“上海”的银行分行提供的贷款总额。
SELECT sum(T2.amount) FROM bank AS T1 JOIN loan AS T2 ON T1.branch_id = T2.branch_id WHERE T1.state = '上海'
CREATE TABLE bank (branch_id VARCHAR, state VARCHAR), CREATE TABLE loan (amount INTEGER, branch_id VARCHAR)
“上海”的银行贷款的总金额是多少？
SELECT avg(credit_score) FROM customer WHERE cust_id IN (SELECT cust_id FROM loan)
CREATE TABLE customer (cust_id VARCHAR, credit_score INTEGER), CREATE TABLE loan (cust_id VARCHAR, credit_score INTEGER)
找到有贷款的客户的平均信用评分。
SELECT avg(credit_score) FROM customer WHERE cust_id IN (SELECT cust_id FROM loan)
CREATE TABLE customer (cust_id VARCHAR, credit_score INTEGER), CREATE TABLE loan (cust_id VARCHAR, credit_score INTEGER)
贷过款的客户的平均信用评分是多少？
SELECT avg(credit_score) FROM customer WHERE cust_id NOT IN (SELECT cust_id FROM loan)
CREATE TABLE customer (cust_id VARCHAR, credit_score INTEGER), CREATE TABLE loan (cust_id VARCHAR, credit_score INTEGER)
找到没有贷过款的客户的平均信用评分。
SELECT avg(credit_score) FROM customer WHERE cust_id NOT IN (SELECT cust_id FROM loan)
CREATE TABLE customer (cust_id VARCHAR, credit_score INTEGER), CREATE TABLE loan (cust_id VARCHAR, credit_score INTEGER)
从未贷过款的客户的平均信用评分是多少？
SELECT count(*) FROM ASSESSMENT_NOTES
CREATE TABLE ASSESSMENT_NOTES (Id VARCHAR)
总共有多少个评估记录？
SELECT date_of_notes FROM Assessment_Notes
CREATE TABLE Assessment_Notes (date_of_notes VARCHAR)
评估记录的日期是什么？
SELECT count(*) FROM ADDRESSES WHERE zip_postcode = "197"
CREATE TABLE ADDRESSES (zip_postcode VARCHAR)
有多少地址包含邮政编码“197”？
SELECT count(DISTINCT incident_type_code) FROM Behavior_Incident
CREATE TABLE Behavior_Incident (incident_type_code VARCHAR)
有多少种不同的事件类型代码？
SELECT DISTINCT detention_type_code FROM Detention
CREATE TABLE Detention (detention_type_code VARCHAR)
返回所有不同的拘留类型代码。
SELECT date_incident_start , date_incident_end FROM Behavior_Incident WHERE incident_type_code = "噪音"
CREATE TABLE Behavior_Incident (date_incident_start VARCHAR, date_incident_end VARCHAR, incident_type_code VARCHAR)
事件类型代码为“噪音”的事件的开始和结束日期是什么？
SELECT detention_summary FROM Detention
CREATE TABLE Detention (detention_summary VARCHAR)
返回所有的拘留摘要。
SELECT cell_mobile_number , email_address FROM STUDENTS
CREATE TABLE STUDENTS (email_address VARCHAR, cell_mobile_number VARCHAR)
返回所有学生的手机号码和电子邮件地址。
SELECT email_address FROM Students WHERE first_name = "杨" AND last_name = "栋"
CREATE TABLE Students (last_name VARCHAR, email_address VARCHAR, first_name VARCHAR)
名字叫“杨”和“栋”的学生的电子邮件是什么？
SELECT count(DISTINCT student_id) FROM Students_in_Detention
CREATE TABLE Students_in_Detention (student_id VARCHAR)
有多少不同的学生被拘留？
SELECT gender FROM TEACHERS WHERE last_name = "军"
CREATE TABLE TEACHERS (last_name VARCHAR, gender VARCHAR)
名为“军”的老师的性别是什么？
SELECT incident_type_description FROM Ref_Incident_Type WHERE incident_type_code = "暴力"
CREATE TABLE Ref_Incident_Type (incident_type_description VARCHAR, incident_type_code VARCHAR)
事件类型代码为“暴力”的事件类型描述是什么？
SELECT max(monthly_rental) , min(monthly_rental) FROM Student_Addresses
CREATE TABLE Student_Addresses (monthly_rental INTEGER)
找到所有学生住址的最高和最低月租金。
SELECT first_name FROM Teachers WHERE email_address LIKE 'qq'
CREATE TABLE Teachers (first_name VARCHAR, email_address VARCHAR)
找到电子邮件地址中包含“qq”一词的老师的名字。