answer
stringlengths
18
552
context
stringlengths
30
393
question
stringlengths
5
73
SELECT count(DISTINCT sportname) FROM Sportsinfo
CREATE TABLE Sportsinfo (sportname VARCHAR)
我们提供多少种不同类型的运动?
SELECT count(DISTINCT StuID) FROM Sportsinfo
CREATE TABLE Sportsinfo (StuID VARCHAR)
有多少学生参加体育活动?
SELECT count(DISTINCT StuID) FROM Sportsinfo
CREATE TABLE Sportsinfo (StuID VARCHAR)
有多少不同的学生参与体育运动?
SELECT StuID FROM Sportsinfo WHERE onscholarship = "Y"
CREATE TABLE Sportsinfo (StuID VARCHAR, onscholarship VARCHAR)
列出所有获得奖学金的学生的ID 。
SELECT StuID FROM Sportsinfo WHERE onscholarship = "Y"
CREATE TABLE Sportsinfo (StuID VARCHAR, onscholarship VARCHAR)
所有获得奖学金的运动生的ID是什么?
SELECT T2.Lname FROM Sportsinfo AS T1 JOIN Student AS T2 ON T1.StuID = T2.StuID WHERE T1.onscholarship = "Y"
CREATE TABLE Sportsinfo (StuID VARCHAR, onscholarship VARCHAR), CREATE TABLE Student (StuID VARCHAR, Lname VARCHAR)
显示所有获得奖学金的学生的姓氏。
SELECT T2.Lname FROM Sportsinfo AS T1 JOIN Student AS T2 ON T1.StuID = T2.StuID WHERE T1.onscholarship = "Y"
CREATE TABLE Sportsinfo (StuID VARCHAR, onscholarship VARCHAR), CREATE TABLE Student (StuID VARCHAR, Lname VARCHAR)
所有奖学金学生的姓氏是什么?
SELECT sum(gamesplayed) FROM Sportsinfo
CREATE TABLE Sportsinfo (gamesplayed INTEGER)
所有学生玩多少种游戏?
SELECT sum(gamesplayed) FROM Sportsinfo
CREATE TABLE Sportsinfo (gamesplayed INTEGER)
游戏的总数是多少?
SELECT sum(gamesplayed) FROM Sportsinfo WHERE sportname = "足球" AND onscholarship = "Y"
CREATE TABLE Sportsinfo (sportname VARCHAR, gamesplayed INTEGER, onscholarship VARCHAR)
所有有奖学金学生的“足球”比赛共有多少场比赛?
SELECT sum(gamesplayed) FROM Sportsinfo WHERE sportname = "足球" AND onscholarship = "Y"
CREATE TABLE Sportsinfo (sportname VARCHAR, gamesplayed INTEGER, onscholarship VARCHAR)
有奖学金学生的所有“足球”比赛的总数是多少?
SELECT sportname , count(*) FROM Sportsinfo GROUP BY sportname
CREATE TABLE Sportsinfo (sportname VARCHAR)
显示所有体育名称和学生人数。
SELECT sportname , count(*) FROM Sportsinfo GROUP BY sportname
CREATE TABLE Sportsinfo (sportname VARCHAR)
每项运动有多少学生玩?
SELECT StuID , count(*) , sum(gamesplayed) FROM Sportsinfo GROUP BY StuID
CREATE TABLE Sportsinfo (StuID VARCHAR, gamesplayed INTEGER)
显示所有学生ID与运动的数量和游戏的总数
SELECT StuID , count(*) , sum(gamesplayed) FROM Sportsinfo GROUP BY StuID
CREATE TABLE Sportsinfo (StuID VARCHAR, gamesplayed INTEGER)
所有学生的ID和他们参加了多少运动和游戏?
SELECT StuID FROM Sportsinfo GROUP BY StuID HAVING sum(hoursperweek) > 10
CREATE TABLE Sportsinfo (StuID VARCHAR, hoursperweek INTEGER)
显示所有参加运动项目每周超过10小时的学生的ID。
SELECT StuID FROM Sportsinfo GROUP BY StuID HAVING sum(hoursperweek) > 10
CREATE TABLE Sportsinfo (StuID VARCHAR, hoursperweek INTEGER)
每周参加所有运动项目上超过10个小时的学生的ID是什么?
SELECT T2.Fname , T2.Lname FROM Sportsinfo AS T1 JOIN Student AS T2 ON T1.StuID = T2.StuID GROUP BY T1.StuID ORDER BY count(*) DESC LIMIT 1
CREATE TABLE Sportsinfo (StuID VARCHAR), CREATE TABLE Student (Fname VARCHAR, StuID VARCHAR, Lname VARCHAR)
运动次数最多的学生的名字和姓氏是什么?
SELECT T2.Fname , T2.Lname FROM Sportsinfo AS T1 JOIN Student AS T2 ON T1.StuID = T2.StuID GROUP BY T1.StuID ORDER BY count(*) DESC LIMIT 1
CREATE TABLE Sportsinfo (StuID VARCHAR), CREATE TABLE Student (Fname VARCHAR, StuID VARCHAR, Lname VARCHAR)
运动最多次数的学生的名字和姓氏是什么?
SELECT sportname FROM Sportsinfo WHERE onscholarship = "Y" GROUP BY sportname ORDER BY count(*) DESC LIMIT 1
CREATE TABLE Sportsinfo (sportname VARCHAR, onscholarship VARCHAR)
哪项运动获得奖学金的学生参加最多?
SELECT sportname FROM Sportsinfo WHERE onscholarship = "Y" GROUP BY sportname ORDER BY count(*) DESC LIMIT 1
CREATE TABLE Sportsinfo (sportname VARCHAR, onscholarship VARCHAR)
有奖学金的学生最多参加的运动是什么?
SELECT StuID FROM Student EXCEPT SELECT StuID FROM Sportsinfo
CREATE TABLE Student (StuID VARCHAR), CREATE TABLE Sportsinfo (StuID VARCHAR)
显示没有任何运动的学生ID 。
SELECT StuID FROM Student EXCEPT SELECT StuID FROM Sportsinfo
CREATE TABLE Student (StuID VARCHAR), CREATE TABLE Sportsinfo (StuID VARCHAR)
不参加体育运动的学生的ID是什么?
SELECT StuID FROM Student WHERE major = 600 INTERSECT SELECT StuID FROM Sportsinfo WHERE onscholarship = "Y"
CREATE TABLE Student (major VARCHAR, StuID VARCHAR, onscholarship VARCHAR), CREATE TABLE Sportsinfo (major VARCHAR, StuID VARCHAR, onscholarship VARCHAR)
显示有奖学金且主修编号是600课程的学生ID 。
SELECT StuID FROM Student WHERE major = 600 INTERSECT SELECT StuID FROM Sportsinfo WHERE onscholarship = "Y"
CREATE TABLE Student (major VARCHAR, StuID VARCHAR, onscholarship VARCHAR), CREATE TABLE Sportsinfo (major VARCHAR, StuID VARCHAR, onscholarship VARCHAR)
主修编号是600课程且有奖学金的学生的ID是什么?
SELECT StuID FROM Student WHERE sex = "F" INTERSECT SELECT StuID FROM Sportsinfo WHERE sportname = "足球"
CREATE TABLE Student (StuID VARCHAR, sex VARCHAR, sportname VARCHAR), CREATE TABLE Sportsinfo (StuID VARCHAR, sex VARCHAR, sportname VARCHAR)
显示是女性和踢“足球”的学生ID。
SELECT StuID FROM Student WHERE sex = "F" INTERSECT SELECT StuID FROM Sportsinfo WHERE sportname = "足球"
CREATE TABLE Student (StuID VARCHAR, sex VARCHAR, sportname VARCHAR), CREATE TABLE Sportsinfo (StuID VARCHAR, sex VARCHAR, sportname VARCHAR)
所有女生踢“足球”的ID是什么?
SELECT StuID FROM Student WHERE sex = "M" EXCEPT SELECT StuID FROM Sportsinfo WHERE sportname = "足球"
CREATE TABLE Student (StuID VARCHAR, sex VARCHAR, sportname VARCHAR), CREATE TABLE Sportsinfo (StuID VARCHAR, sex VARCHAR, sportname VARCHAR)
展示所有不踢“足球”的男学生ID 。
SELECT StuID FROM Student WHERE sex = "M" EXCEPT SELECT StuID FROM Sportsinfo WHERE sportname = "足球"
CREATE TABLE Student (StuID VARCHAR, sex VARCHAR, sportname VARCHAR), CREATE TABLE Sportsinfo (StuID VARCHAR, sex VARCHAR, sportname VARCHAR)
不踢“足球”的所有男生的ID是什么?
SELECT sum(hoursperweek) , sum(gamesplayed) FROM Sportsinfo AS T1 JOIN Student AS T2 ON T1.StuID = T2.StuID WHERE T2.Fname = "江城" AND T2.Lname = "韩"
CREATE TABLE Sportsinfo (StuID VARCHAR), CREATE TABLE Student (Fname VARCHAR, StuID VARCHAR, Lname VARCHAR)
显示每周的总小时数和学生“韩”“江城”玩游戏的次数。
SELECT sum(hoursperweek) , sum(gamesplayed) FROM Sportsinfo AS T1 JOIN Student AS T2 ON T1.StuID = T2.StuID WHERE T2.Fname = "江城" AND T2.Lname = "韩"
CREATE TABLE Sportsinfo (StuID VARCHAR), CREATE TABLE Student (Fname VARCHAR, StuID VARCHAR, Lname VARCHAR)
“韩”“江城”每次工作的总小时数和玩游戏的次数是多少?
SELECT sum(hoursperweek) , sum(gamesplayed) FROM Sportsinfo AS T1 JOIN Student AS T2 ON T1.StuID = T2.StuID WHERE T2.age < 20
CREATE TABLE Sportsinfo (StuID VARCHAR), CREATE TABLE Student (StuID VARCHAR, age INTEGER)
显示每周的总小时数和20岁以下学生玩游戏的数目。
SELECT sum(hoursperweek) , sum(gamesplayed) FROM Sportsinfo AS T1 JOIN Student AS T2 ON T1.StuID = T2.StuID WHERE T2.age < 20
CREATE TABLE Sportsinfo (StuID VARCHAR), CREATE TABLE Student (StuID VARCHAR, age INTEGER)
每周的总小时数和20岁以下的学生游戏次数是多少?
SELECT count(DISTINCT StuID) FROM Plays_games
CREATE TABLE Plays_games (StuID VARCHAR)
有多少学生玩电子游戏?
SELECT count(DISTINCT StuID) FROM Plays_games
CREATE TABLE Plays_games (StuID VARCHAR)
有多少不同的学生玩游戏?
SELECT StuID FROM Student EXCEPT SELECT StuID FROM Plays_games
CREATE TABLE Student (StuID VARCHAR), CREATE TABLE Plays_games (StuID VARCHAR)
显示不玩电子游戏的学生的ID。
SELECT StuID FROM Student EXCEPT SELECT StuID FROM Plays_games
CREATE TABLE Student (StuID VARCHAR), CREATE TABLE Plays_games (StuID VARCHAR)
所有不是电子游戏玩家的学生的ID是什么?
SELECT StuID FROM Sportsinfo INTERSECT SELECT StuID FROM Plays_games
CREATE TABLE Sportsinfo (StuID VARCHAR), CREATE TABLE Plays_games (StuID VARCHAR)
显示玩电子游戏和运动的学生ID。
SELECT StuID FROM Sportsinfo INTERSECT SELECT StuID FROM Plays_games
CREATE TABLE Sportsinfo (StuID VARCHAR), CREATE TABLE Plays_games (StuID VARCHAR)
玩电子游戏和体育运动的学生的ID是什么?
SELECT gameid , sum(hours_played) FROM Plays_games GROUP BY gameid
CREATE TABLE Plays_games (hours_played INTEGER, gameid VARCHAR)
显示所有游戏的ID和玩的小时数。
SELECT gameid , sum(hours_played) FROM Plays_games GROUP BY gameid
CREATE TABLE Plays_games (hours_played INTEGER, gameid VARCHAR)
每个游戏的ID和每个游戏玩的总小时数?
SELECT Stuid , sum(hours_played) FROM Plays_games GROUP BY Stuid
CREATE TABLE Plays_games (hours_played INTEGER, Stuid VARCHAR)
显示所有学生ID和玩的小时数。
SELECT Stuid , sum(hours_played) FROM Plays_games GROUP BY Stuid
CREATE TABLE Plays_games (hours_played INTEGER, Stuid VARCHAR)
所有学生的ID和玩的小时数是多少?
SELECT gname FROM Plays_games AS T1 JOIN Video_games AS T2 ON T1.gameid = T2.gameid GROUP BY T1.gameid ORDER BY sum(hours_played) DESC LIMIT 1
CREATE TABLE Plays_games (gameid VARCHAR), CREATE TABLE Video_games (gameid VARCHAR)
显示玩最多小时数的游戏名称。
SELECT gname FROM Plays_games AS T1 JOIN Video_games AS T2 ON T1.gameid = T2.gameid GROUP BY T1.gameid ORDER BY sum(hours_played) DESC LIMIT 1
CREATE TABLE Plays_games (gameid VARCHAR), CREATE TABLE Video_games (gameid VARCHAR)
玩的最多的游戏名字是什么?
SELECT gname FROM Plays_games AS T1 JOIN Video_games AS T2 ON T1.gameid = T2.gameid GROUP BY T1.gameid HAVING sum(hours_played) >= 1000
CREATE TABLE Plays_games (gameid VARCHAR), CREATE TABLE Video_games (gameid VARCHAR)
显示所有至少玩1000小时的游戏名称。
SELECT gname FROM Plays_games AS T1 JOIN Video_games AS T2 ON T1.gameid = T2.gameid GROUP BY T1.gameid HAVING sum(hours_played) >= 1000
CREATE TABLE Plays_games (gameid VARCHAR), CREATE TABLE Video_games (gameid VARCHAR)
已经玩了至少玩1000个小时的所有游戏的名字是什么?
SELECT Gname FROM Plays_games AS T1 JOIN Video_games AS T2 ON T1.gameid = T2.gameid JOIN Student AS T3 ON T3.Stuid = T1.Stuid WHERE T3.Lname = "张" AND T3.Fname = "晴"
CREATE TABLE Plays_games (gameid VARCHAR, Stuid VARCHAR), CREATE TABLE Video_games (gameid VARCHAR), CREATE TABLE Student (Fname VARCHAR, Stuid VARCHAR, Lname VARCHAR)
显示 “张”“晴” 所玩的所有游戏名称
SELECT Gname FROM Plays_games AS T1 JOIN Video_games AS T2 ON T1.gameid = T2.gameid JOIN Student AS T3 ON T3.Stuid = T1.Stuid WHERE T3.Lname = "张" AND T3.Fname = "晴"
CREATE TABLE Plays_games (gameid VARCHAR, Stuid VARCHAR), CREATE TABLE Video_games (gameid VARCHAR), CREATE TABLE Student (Fname VARCHAR, Stuid VARCHAR, Lname VARCHAR)
“张”“晴” 玩的所有游戏的名字是什么?
SELECT T2.lname , T2.fname FROM SportsInfo AS T1 JOIN Student AS T2 ON T1.StuID = T2.StuID WHERE T1.SportName = "足球" OR T1.SportName = "曲棍球"
CREATE TABLE SportsInfo (StuID VARCHAR, SportName VARCHAR), CREATE TABLE Student (lname VARCHAR, StuID VARCHAR, fname VARCHAR)
找出踢“足球”或“曲棍球”的学生的名字和姓氏。
SELECT T2.lname , T2.fname FROM SportsInfo AS T1 JOIN Student AS T2 ON T1.StuID = T2.StuID WHERE T1.SportName = "足球" OR T1.SportName = "曲棍球"
CREATE TABLE SportsInfo (StuID VARCHAR, SportName VARCHAR), CREATE TABLE Student (lname VARCHAR, StuID VARCHAR, fname VARCHAR)
所有踢“足球”或“曲棍球”的学生的名字和姓氏是什么?
SELECT fname , age FROM Student WHERE StuID IN (SELECT StuID FROM Sportsinfo WHERE SportName = "足球" INTERSECT SELECT StuID FROM Sportsinfo WHERE SportName = "曲棍球")
CREATE TABLE Student (SportName VARCHAR, age VARCHAR, StuID VARCHAR, fname VARCHAR), CREATE TABLE Sportsinfo (SportName VARCHAR, age VARCHAR, StuID VARCHAR, fname VARCHAR)
找出同时踢“足球”和“曲棍球”的学生的名字和年龄。
SELECT fname , age FROM Student WHERE StuID IN (SELECT StuID FROM Sportsinfo WHERE SportName = "足球" INTERSECT SELECT StuID FROM Sportsinfo WHERE SportName = "曲棍球")
CREATE TABLE Student (SportName VARCHAR, age VARCHAR, StuID VARCHAR, fname VARCHAR), CREATE TABLE Sportsinfo (SportName VARCHAR, age VARCHAR, StuID VARCHAR, fname VARCHAR)
所有同时踢“足球”和“曲棍球”的学生的名字和年龄是多少?
SELECT lname , sex FROM Student WHERE StuID IN (SELECT T1.StuID FROM Plays_games AS T1 JOIN Video_games AS T2 ON T1.GameID = T2.GameID WHERE T2.Gname = "使命召唤" INTERSECT SELECT T1.StuID FROM Plays_games AS T1 JOIN Video_games AS T2 ON T1.GameID = T2.GameID WHERE T2.Gname = "绝地求生")
CREATE TABLE Student (lname VARCHAR, sex VARCHAR, StuID VARCHAR), CREATE TABLE Plays_games (StuID VARCHAR, GameID VARCHAR), CREATE TABLE Video_games (Gname VARCHAR, GameID VARCHAR)
找出同时玩“使命召唤”和“绝地求生”游戏的学生的姓氏和性别。
SELECT lname , sex FROM Student WHERE StuID IN (SELECT T1.StuID FROM Plays_games AS T1 JOIN Video_games AS T2 ON T1.GameID = T2.GameID WHERE T2.Gname = "使命召唤" INTERSECT SELECT T1.StuID FROM Plays_games AS T1 JOIN Video_games AS T2 ON T1.GameID = T2.GameID WHERE T2.Gname = "绝地求生")
CREATE TABLE Student (lname VARCHAR, sex VARCHAR, StuID VARCHAR), CREATE TABLE Plays_games (StuID VARCHAR, GameID VARCHAR), CREATE TABLE Video_games (Gname VARCHAR, GameID VARCHAR)
所有同时演奏“使命召唤”和“绝地求生”的学生的姓氏和性别是什么?
SELECT customer_name FROM customers
CREATE TABLE customers (customer_name VARCHAR)
查找所有客户的姓名。
SELECT customer_name FROM customers
CREATE TABLE customers (customer_name VARCHAR)
所有顾客的名字是什么?
SELECT count(*) FROM customers
CREATE TABLE customers (Id VARCHAR)
那里有多少顾客?
SELECT count(*) FROM customers
CREATE TABLE customers (Id VARCHAR)
返回不同客户的总数。
SELECT avg(order_quantity) FROM order_items
CREATE TABLE order_items (order_quantity INTEGER)
每一个订单所订购的物品的平均数量是多少?
SELECT avg(order_quantity) FROM order_items
CREATE TABLE order_items (order_quantity INTEGER)
找出每个订单的平均订单数量。
SELECT customer_name FROM customers WHERE payment_method = "现金"
CREATE TABLE customers (customer_name VARCHAR, payment_method VARCHAR)
使用支付方式为“现金”的客户姓名是什么?
SELECT customer_name FROM customers WHERE payment_method = "现金"
CREATE TABLE customers (customer_name VARCHAR, payment_method VARCHAR)
哪些客户使用“现金”支付方式?返回客户姓名。
SELECT date_became_customer FROM customers WHERE customer_id BETWEEN 10 AND 20
CREATE TABLE customers (date_became_customer VARCHAR, customer_id INTEGER)
找出ID在10到20之间的客户的成为客户的日期。
SELECT date_became_customer FROM customers WHERE customer_id BETWEEN 10 AND 20
CREATE TABLE customers (date_became_customer VARCHAR, customer_id INTEGER)
ID介于10和20之间的客户成为客户的日期是什么时候?
SELECT payment_method FROM customers GROUP BY payment_method ORDER BY count(*) DESC LIMIT 1
CREATE TABLE customers (payment_method VARCHAR)
客户使用最多种是什么付款方式?
SELECT payment_method FROM customers GROUP BY payment_method ORDER BY count(*) DESC LIMIT 1
CREATE TABLE customers (payment_method VARCHAR)
找出最常用的支付方式。
SELECT customer_name FROM customers WHERE payment_method = (SELECT payment_method FROM customers GROUP BY payment_method ORDER BY count(*) DESC LIMIT 1)
CREATE TABLE customers (customer_name VARCHAR, payment_method VARCHAR)
使用最流行的支付方式的客户姓名是什么?
SELECT customer_name FROM customers WHERE payment_method = (SELECT payment_method FROM customers GROUP BY payment_method ORDER BY count(*) DESC LIMIT 1)
CREATE TABLE customers (customer_name VARCHAR, payment_method VARCHAR)
查找使用最常用支付方式的客户姓名。
SELECT DISTINCT payment_method FROM customers
CREATE TABLE customers (payment_method VARCHAR)
所有的付款方式是什么?
SELECT DISTINCT payment_method FROM customers
CREATE TABLE customers (payment_method VARCHAR)
返回客户使用的所有不同的付款方式。
SELECT DISTINCT product_details FROM products
CREATE TABLE products (product_details VARCHAR)
所有产品的细节是什么?
SELECT DISTINCT product_details FROM products
CREATE TABLE products (product_details VARCHAR)
返回所有产品的细节。
SELECT customer_name FROM customers WHERE customer_name LIKE "%少奇%"
CREATE TABLE customers (customer_name VARCHAR)
查找所有名为“少奇”的客户的名字。
SELECT customer_name FROM customers WHERE customer_name LIKE "%少奇%"
CREATE TABLE customers (customer_name VARCHAR)
哪个客户的名字包含“少奇”?找出全名。
SELECT product_details FROM products WHERE product_details LIKE "%拿铁%" OR product_details LIKE "%美式咖啡%"
CREATE TABLE products (product_details VARCHAR)
查找详细信息中包含“拿铁”或“美式咖啡”的产品的细节
SELECT product_details FROM products WHERE product_details LIKE "%拿铁%" OR product_details LIKE "%美式咖啡%"
CREATE TABLE products (product_details VARCHAR)
哪个产品的细节包含单词“拿铁”或“美式咖啡”?返回完整的细节。
SELECT t3.address_content FROM customers AS t1 JOIN customer_addresses AS t2 ON t1.customer_id = t2.customer_id JOIN addresses AS t3 ON t2.address_id = t3.address_id WHERE t1.customer_name = "王俊元"
CREATE TABLE customers (customer_name VARCHAR, customer_id VARCHAR), CREATE TABLE customer_addresses (address_id VARCHAR, customer_id VARCHAR), CREATE TABLE addresses (address_content VARCHAR, address_id VARCHAR)
名为“王俊元”的客户的地址是什么?
SELECT t3.address_content FROM customers AS t1 JOIN customer_addresses AS t2 ON t1.customer_id = t2.customer_id JOIN addresses AS t3 ON t2.address_id = t3.address_id WHERE t1.customer_name = "王俊元"
CREATE TABLE customers (customer_name VARCHAR, customer_id VARCHAR), CREATE TABLE customer_addresses (address_id VARCHAR, customer_id VARCHAR), CREATE TABLE addresses (address_content VARCHAR, address_id VARCHAR)
返回名为“王俊元”的客户的地址内容。
SELECT count(*) FROM customers AS t1 JOIN customer_addresses AS t2 ON t1.customer_id = t2.customer_id JOIN addresses AS t3 ON t2.address_id = t3.address_id WHERE t3.city = "西安"
CREATE TABLE customers (customer_id VARCHAR), CREATE TABLE customer_addresses (address_id VARCHAR, customer_id VARCHAR), CREATE TABLE addresses (address_id VARCHAR, city VARCHAR)
住在“西安”的城市有多少顾客?
SELECT count(*) FROM customers AS t1 JOIN customer_addresses AS t2 ON t1.customer_id = t2.customer_id JOIN addresses AS t3 ON t2.address_id = t3.address_id WHERE t3.city = "西安"
CREATE TABLE customers (customer_id VARCHAR), CREATE TABLE customer_addresses (address_id VARCHAR, customer_id VARCHAR), CREATE TABLE addresses (address_id VARCHAR, city VARCHAR)
找出居住在这个叫做“西安”的城市的顾客的数量。
SELECT t1.customer_name FROM customers AS t1 JOIN customer_addresses AS t2 ON t1.customer_id = t2.customer_id JOIN addresses AS t3 ON t2.address_id = t3.address_id WHERE t3.state_province_county = "河北"
CREATE TABLE customers (customer_name VARCHAR, customer_id VARCHAR), CREATE TABLE customer_addresses (address_id VARCHAR, customer_id VARCHAR), CREATE TABLE addresses (address_id VARCHAR, state_province_county VARCHAR)
找出住在“河北”的客户的名字?
SELECT t1.customer_name FROM customers AS t1 JOIN customer_addresses AS t2 ON t1.customer_id = t2.customer_id JOIN addresses AS t3 ON t2.address_id = t3.address_id WHERE t3.state_province_county = "河北"
CREATE TABLE customers (customer_name VARCHAR, customer_id VARCHAR), CREATE TABLE customer_addresses (address_id VARCHAR, customer_id VARCHAR), CREATE TABLE addresses (address_id VARCHAR, state_province_county VARCHAR)
住在“河北”省的客户的名字是什么?
SELECT city FROM addresses WHERE city NOT IN ( SELECT DISTINCT t3.city FROM customers AS t1 JOIN customer_addresses AS t2 ON t1.customer_id = t2.customer_id JOIN addresses AS t3 ON t2.address_id = t3.address_id)
CREATE TABLE addresses (address_id VARCHAR, city VARCHAR), CREATE TABLE customers (customer_id VARCHAR), CREATE TABLE customer_addresses (address_id VARCHAR, customer_id VARCHAR)
找出没有顾客居住的城市的列表。
SELECT city FROM addresses WHERE city NOT IN ( SELECT DISTINCT t3.city FROM customers AS t1 JOIN customer_addresses AS t2 ON t1.customer_id = t2.customer_id JOIN addresses AS t3 ON t2.address_id = t3.address_id)
CREATE TABLE addresses (address_id VARCHAR, city VARCHAR), CREATE TABLE customers (customer_id VARCHAR), CREATE TABLE customer_addresses (address_id VARCHAR, customer_id VARCHAR)
没有顾客居住的城市是什么?
SELECT t3.city FROM customers AS t1 JOIN customer_addresses AS t2 ON t1.customer_id = t2.customer_id JOIN addresses AS t3 ON t2.address_id = t3.address_id GROUP BY t3.city ORDER BY count(*) DESC LIMIT 1
CREATE TABLE customers (customer_id VARCHAR), CREATE TABLE customer_addresses (address_id VARCHAR, customer_id VARCHAR), CREATE TABLE addresses (address_id VARCHAR, city VARCHAR)
哪个城市的顾客最多?
SELECT t3.city FROM customers AS t1 JOIN customer_addresses AS t2 ON t1.customer_id = t2.customer_id JOIN addresses AS t3 ON t2.address_id = t3.address_id GROUP BY t3.city ORDER BY count(*) DESC LIMIT 1
CREATE TABLE customers (customer_id VARCHAR), CREATE TABLE customer_addresses (address_id VARCHAR, customer_id VARCHAR), CREATE TABLE addresses (address_id VARCHAR, city VARCHAR)
找出最多顾客居住的城市。
SELECT DISTINCT city FROM addresses
CREATE TABLE addresses (city VARCHAR)
检索所有城市的列表。
SELECT DISTINCT city FROM addresses
CREATE TABLE addresses (city VARCHAR)
列出所有不同的城市
SELECT city FROM addresses WHERE zip_postcode = 255
CREATE TABLE addresses (city VARCHAR, zip_postcode VARCHAR)
找出邮政编码是255的城市。
SELECT city FROM addresses WHERE zip_postcode = 255
CREATE TABLE addresses (city VARCHAR, zip_postcode VARCHAR)
邮政编码是255是哪个城市?
SELECT state_province_county , country FROM addresses WHERE zip_postcode LIKE "%4%"
CREATE TABLE addresses (zip_postcode VARCHAR, state_province_county VARCHAR, country VARCHAR)
找出以“4”开头的邮政编码所有城市的省和市。
SELECT state_province_county , country FROM addresses WHERE zip_postcode LIKE "%4%"
CREATE TABLE addresses (zip_postcode VARCHAR, state_province_county VARCHAR, country VARCHAR)
所有以“4”开头的邮政编码城市的省和市是什么?
SELECT country FROM addresses GROUP BY country HAVING count(address_id) > 4
CREATE TABLE addresses (address_id VARCHAR, country VARCHAR)
列出有超过4个地址的国家名单。
SELECT country FROM addresses GROUP BY country HAVING count(address_id) > 4
CREATE TABLE addresses (address_id VARCHAR, country VARCHAR)
哪些国家有列出超过四个不同的地址?
SELECT channel_code FROM customer_contact_channels GROUP BY channel_code HAVING count(customer_id) < 5
CREATE TABLE customer_contact_channels (customer_id VARCHAR, channel_code VARCHAR)
列出所有少于5次使用的联系人信道代码。
SELECT channel_code FROM customer_contact_channels GROUP BY channel_code HAVING count(customer_id) < 5
CREATE TABLE customer_contact_channels (customer_id VARCHAR, channel_code VARCHAR)
哪些联系信道代码使用少于5次?
SELECT DISTINCT channel_code FROM customers AS t1 JOIN customer_contact_channels AS t2 ON t1.customer_id = t2.customer_id WHERE t1.customer_name = "杨超越"
CREATE TABLE customers (customer_name VARCHAR, customer_id VARCHAR), CREATE TABLE customer_contact_channels (customer_id VARCHAR)
哪个联系渠道已经被叫“杨超越”所使用?
SELECT DISTINCT channel_code FROM customers AS t1 JOIN customer_contact_channels AS t2 ON t1.customer_id = t2.customer_id WHERE t1.customer_name = "杨超越"
CREATE TABLE customers (customer_name VARCHAR, customer_id VARCHAR), CREATE TABLE customer_contact_channels (customer_id VARCHAR)
找出名为“杨超越”的客户使用的联系渠道代码。
SELECT max(t2.active_to_date) FROM customers AS t1 JOIN customer_contact_channels AS t2 ON t1.customer_id = t2.customer_id WHERE t1.customer_name = "杨超越"
CREATE TABLE customers (customer_name VARCHAR, customer_id VARCHAR), CREATE TABLE customer_contact_channels (customer_id VARCHAR, active_to_date INTEGER)
“杨超越”使用的最新联系人频道的激活日期是什么?