answer
stringlengths
18
552
context
stringlengths
30
393
question
stringlengths
5
73
SELECT max(t2.active_to_date) FROM customers AS t1 JOIN customer_contact_channels AS t2 ON t1.customer_id = t2.customer_id WHERE t1.customer_name = "杨超越"
CREATE TABLE customers (customer_name VARCHAR, customer_id VARCHAR), CREATE TABLE customer_contact_channels (customer_id VARCHAR, active_to_date INTEGER)
返回由名为“杨超越”的客户使用的最新联系渠道的激活日期。
SELECT avg(active_to_date - active_from_date) FROM customer_contact_channels
CREATE TABLE customer_contact_channels (active_to_date VARCHAR, active_from_date VARCHAR)
数据库中联系通道的平均时间跨度是多少?
SELECT avg(active_to_date - active_from_date) FROM customer_contact_channels
CREATE TABLE customer_contact_channels (active_to_date VARCHAR, active_from_date VARCHAR)
计算联系通道的平均有效时间跨度。
SELECT channel_code , contact_number FROM customer_contact_channels WHERE active_to_date - active_from_date = (SELECT active_to_date - active_from_date FROM customer_contact_channels ORDER BY (active_to_date - active_from_date) DESC LIMIT 1)
CREATE TABLE customer_contact_channels (active_to_date VARCHAR, contact_number VARCHAR, active_from_date VARCHAR, channel_code VARCHAR)
最长时间处于活动状态的客户联系渠道的信道代码和联系号码是什么?
SELECT channel_code , contact_number FROM customer_contact_channels WHERE active_to_date - active_from_date = (SELECT active_to_date - active_from_date FROM customer_contact_channels ORDER BY (active_to_date - active_from_date) DESC LIMIT 1)
CREATE TABLE customer_contact_channels (active_to_date VARCHAR, contact_number VARCHAR, active_from_date VARCHAR, channel_code VARCHAR)
返回活动持续时间最长的客户联系渠道的信道代码和联系号码。
SELECT t1.customer_name , t2.active_from_date FROM customers AS t1 JOIN customer_contact_channels AS t2 ON t1.customer_id = t2.customer_id WHERE t2.channel_code = "Email"
CREATE TABLE customers (customer_name VARCHAR, customer_id VARCHAR), CREATE TABLE customer_contact_channels (channel_code VARCHAR, active_from_date VARCHAR, customer_id VARCHAR)
找出使用电子邮件作为联系渠道的客户的姓名和活动日期。
SELECT t1.customer_name , t2.active_from_date FROM customers AS t1 JOIN customer_contact_channels AS t2 ON t1.customer_id = t2.customer_id WHERE t2.channel_code = "Email"
CREATE TABLE customers (customer_name VARCHAR, customer_id VARCHAR), CREATE TABLE customer_contact_channels (channel_code VARCHAR, active_from_date VARCHAR, customer_id VARCHAR)
联系渠道代码是电子邮件的客户的姓名和活动日期是什么?
SELECT t1.customer_name FROM customers AS t1 JOIN customer_orders AS t2 ON t1.customer_id = t2.customer_id JOIN order_items AS t3 ON t2.order_id = t3.order_id WHERE t3.order_quantity = ( SELECT max(order_quantity) FROM order_items)
CREATE TABLE customers (customer_name VARCHAR, customer_id VARCHAR), CREATE TABLE customer_orders (order_id VARCHAR, customer_id VARCHAR), CREATE TABLE order_items (order_quantity INTEGER)
订单数量最多的客户叫什么名字?
SELECT t1.customer_name FROM customers AS t1 JOIN customer_orders AS t2 ON t1.customer_id = t2.customer_id JOIN order_items AS t3 ON t2.order_id = t3.order_id WHERE t3.order_quantity = ( SELECT max(order_quantity) FROM order_items)
CREATE TABLE customers (customer_name VARCHAR, customer_id VARCHAR), CREATE TABLE customer_orders (order_id VARCHAR, customer_id VARCHAR), CREATE TABLE order_items (order_quantity INTEGER)
找出订单最大订货量的客户。
SELECT t1.customer_name FROM customers AS t1 JOIN customer_orders AS t2 ON t1.customer_id = t2.customer_id JOIN order_items AS t3 ON t2.order_id = t3.order_id GROUP BY t1.customer_name ORDER BY sum(t3.order_quantity) DESC LIMIT 1
CREATE TABLE customers (customer_name VARCHAR, customer_id VARCHAR), CREATE TABLE customer_orders (order_id VARCHAR, customer_id VARCHAR), CREATE TABLE order_items (order_id VARCHAR, order_quantity INTEGER)
购买了最多商品的顾客的名字是什么?
SELECT t1.customer_name FROM customers AS t1 JOIN customer_orders AS t2 ON t1.customer_id = t2.customer_id JOIN order_items AS t3 ON t2.order_id = t3.order_id GROUP BY t1.customer_name ORDER BY sum(t3.order_quantity) DESC LIMIT 1
CREATE TABLE customers (customer_name VARCHAR, customer_id VARCHAR), CREATE TABLE customer_orders (order_id VARCHAR, customer_id VARCHAR), CREATE TABLE order_items (order_id VARCHAR, order_quantity INTEGER)
给我订购了最多的物品总数的客户的名字。
SELECT t1.payment_method FROM customers AS t1 JOIN customer_orders AS t2 ON t1.customer_id = t2.customer_id JOIN order_items AS t3 ON t2.order_id = t3.order_id GROUP BY t1.customer_name ORDER BY sum(t3.order_quantity) LIMIT 1
CREATE TABLE customers (customer_name VARCHAR, customer_id VARCHAR, payment_method VARCHAR), CREATE TABLE customer_orders (order_id VARCHAR, customer_id VARCHAR), CREATE TABLE order_items (order_id VARCHAR, order_quantity INTEGER)
购买数量最少的物品的顾客的付款方式是什么?
SELECT t1.payment_method FROM customers AS t1 JOIN customer_orders AS t2 ON t1.customer_id = t2.customer_id JOIN order_items AS t3 ON t2.order_id = t3.order_id GROUP BY t1.customer_name ORDER BY sum(t3.order_quantity) LIMIT 1
CREATE TABLE customers (customer_name VARCHAR, customer_id VARCHAR, payment_method VARCHAR), CREATE TABLE customer_orders (order_id VARCHAR, customer_id VARCHAR), CREATE TABLE order_items (order_id VARCHAR, order_quantity INTEGER)
请告诉我订货量最少的客户所使用的付款方式。
SELECT count(DISTINCT t3.product_id) FROM customers AS t1 JOIN customer_orders AS t2 ON t1.customer_id = t2.customer_id JOIN order_items AS t3 ON t2.order_id = t3.order_id WHERE t1.customer_name = "路一鸣"
CREATE TABLE customers (customer_name VARCHAR, customer_id VARCHAR), CREATE TABLE customer_orders (order_id VARCHAR, customer_id VARCHAR), CREATE TABLE order_items (order_id VARCHAR, product_id VARCHAR)
“路一鸣”总共买了多少种产品?
SELECT count(DISTINCT t3.product_id) FROM customers AS t1 JOIN customer_orders AS t2 ON t1.customer_id = t2.customer_id JOIN order_items AS t3 ON t2.order_id = t3.order_id WHERE t1.customer_name = "路一鸣"
CREATE TABLE customers (customer_name VARCHAR, customer_id VARCHAR), CREATE TABLE customer_orders (order_id VARCHAR, customer_id VARCHAR), CREATE TABLE order_items (order_id VARCHAR, product_id VARCHAR)
找出迄今为止“路一鸣”购买的不同产品的数量。
SELECT sum(t3.order_quantity) FROM customers AS t1 JOIN customer_orders AS t2 ON t1.customer_id = t2.customer_id JOIN order_items AS t3 ON t2.order_id = t3.order_id WHERE t1.customer_name = "路一鸣"
CREATE TABLE customers (customer_name VARCHAR, customer_id VARCHAR), CREATE TABLE customer_orders (order_id VARCHAR, customer_id VARCHAR), CREATE TABLE order_items (order_id VARCHAR, order_quantity INTEGER)
“路一鸣”购买的产品总量是多少?
SELECT sum(t3.order_quantity) FROM customers AS t1 JOIN customer_orders AS t2 ON t1.customer_id = t2.customer_id JOIN order_items AS t3 ON t2.order_id = t3.order_id WHERE t1.customer_name = "路一鸣"
CREATE TABLE customers (customer_name VARCHAR, customer_id VARCHAR), CREATE TABLE customer_orders (order_id VARCHAR, customer_id VARCHAR), CREATE TABLE order_items (order_id VARCHAR, order_quantity INTEGER)
请告诉我顾客“路一鸣”购买的产品的总数量。
SELECT count(DISTINCT customer_id) FROM customer_orders WHERE order_status = "取消"
CREATE TABLE customer_orders (order_status VARCHAR, customer_id VARCHAR)
有多少客户至少有一个订单状态是“取消”?
SELECT count(DISTINCT customer_id) FROM customer_orders WHERE order_status = "取消"
CREATE TABLE customer_orders (order_status VARCHAR, customer_id VARCHAR)
返回具有至少一个“取消”状态的订单的客户数量。
SELECT count(*) FROM customer_orders WHERE order_details = "第二次"
CREATE TABLE customer_orders (order_details VARCHAR)
多少订单有“第二次”的细节?
SELECT count(*) FROM customer_orders WHERE order_details = "第二次"
CREATE TABLE customer_orders (order_details VARCHAR)
告诉我把“第二次”作为订单细节的订单的数量。
SELECT t1.customer_name , t2.order_date FROM customers AS t1 JOIN customer_orders AS t2 ON t1.customer_id = t2.customer_id WHERE order_status = "运送"
CREATE TABLE customers (customer_name VARCHAR, customer_id VARCHAR), CREATE TABLE customer_orders (customer_id VARCHAR, order_date VARCHAR)
找出拥有“运送”订单状态的客户姓名和日期。
SELECT t1.customer_name , t2.order_date FROM customers AS t1 JOIN customer_orders AS t2 ON t1.customer_id = t2.customer_id WHERE order_status = "运送"
CREATE TABLE customers (customer_name VARCHAR, customer_id VARCHAR), CREATE TABLE customer_orders (customer_id VARCHAR, order_date VARCHAR)
有订单状态是“运送”的订单的客户姓名和日期是什么?
SELECT sum(t2.order_quantity) FROM customer_orders AS t1 JOIN order_items AS t2 ON t1.order_id = t2.order_id WHERE t1.order_status = "取消"
CREATE TABLE customer_orders (order_id VARCHAR, order_status VARCHAR), CREATE TABLE order_items (order_id VARCHAR, order_quantity INTEGER)
有订单状态为“取消”的商品总数是多少?
SELECT sum(t2.order_quantity) FROM customer_orders AS t1 JOIN order_items AS t2 ON t1.order_id = t2.order_id WHERE t1.order_status = "取消"
CREATE TABLE customer_orders (order_id VARCHAR, order_status VARCHAR), CREATE TABLE order_items (order_id VARCHAR, order_quantity INTEGER)
找出有订单状态为“取消”的商品总数量。
SELECT sum(t2.order_quantity) FROM customer_orders AS t1 JOIN order_items AS t2 ON t1.order_id = t2.order_id WHERE t1.order_date < "2018~03-17 07:13:53"
CREATE TABLE customer_orders (order_id VARCHAR, order_date INTEGER), CREATE TABLE order_items (order_id VARCHAR, order_quantity INTEGER)
找出“2018~03-17 07:13:53”之前订购的产品总量。
SELECT sum(t2.order_quantity) FROM customer_orders AS t1 JOIN order_items AS t2 ON t1.order_id = t2.order_id WHERE t1.order_date < "2018~03-17 07:13:53"
CREATE TABLE customer_orders (order_id VARCHAR, order_date INTEGER), CREATE TABLE order_items (order_id VARCHAR, order_quantity INTEGER)
在“2018~03-17 07:13:53”之前购买的产品的总量是多少?
SELECT t1.customer_name FROM customers AS t1 JOIN customer_orders AS t2 ON t1.customer_id = t2.customer_id ORDER BY t2.order_date DESC LIMIT 1
CREATE TABLE customers (customer_name VARCHAR, customer_id VARCHAR), CREATE TABLE customer_orders (order_date VARCHAR, customer_id VARCHAR)
谁做完最新的订单?
SELECT t1.customer_name FROM customers AS t1 JOIN customer_orders AS t2 ON t1.customer_id = t2.customer_id ORDER BY t2.order_date DESC LIMIT 1
CREATE TABLE customers (customer_name VARCHAR, customer_id VARCHAR), CREATE TABLE customer_orders (order_date VARCHAR, customer_id VARCHAR)
查找最近订购的客户的姓名。
SELECT t2.product_details FROM order_items AS t1 JOIN products AS t2 ON t1.product_id = t2.product_id GROUP BY t1.product_id ORDER BY count(*) DESC LIMIT 1
CREATE TABLE order_items (product_id VARCHAR), CREATE TABLE products (product_id VARCHAR, product_details VARCHAR)
哪种产品订购次数最多?
SELECT t2.product_details FROM order_items AS t1 JOIN products AS t2 ON t1.product_id = t2.product_id GROUP BY t1.product_id ORDER BY count(*) DESC LIMIT 1
CREATE TABLE order_items (product_id VARCHAR), CREATE TABLE products (product_id VARCHAR, product_details VARCHAR)
最经常订购的产品是什么?告诉我产品的细节
SELECT t2.product_details , t2.product_id FROM order_items AS t1 JOIN products AS t2 ON t1.product_id = t2.product_id GROUP BY t1.product_id ORDER BY sum(t1.order_quantity) LIMIT 1
CREATE TABLE order_items (order_quantity INTEGER, product_id VARCHAR), CREATE TABLE products (product_id VARCHAR, product_details VARCHAR)
找出总订单数量最大的产品的名称和ID。
SELECT t2.product_details , t2.product_id FROM order_items AS t1 JOIN products AS t2 ON t1.product_id = t2.product_id GROUP BY t1.product_id ORDER BY sum(t1.order_quantity) LIMIT 1
CREATE TABLE order_items (order_quantity INTEGER, product_id VARCHAR), CREATE TABLE products (product_id VARCHAR, product_details VARCHAR)
买的最多产品的名字和ID是什么?
SELECT address_content FROM addresses WHERE city = "大理" AND state_province_county = "云南" UNION SELECT address_content FROM addresses WHERE city = "银川" AND state_province_county = "宁夏"
CREATE TABLE addresses (address_content VARCHAR, city VARCHAR, state_province_county VARCHAR)
找出在“云南”“大理”或在“银川”“宁夏”的所有的地址。
SELECT address_content FROM addresses WHERE city = "大理" AND state_province_county = "云南" UNION SELECT address_content FROM addresses WHERE city = "银川" AND state_province_county = "宁夏"
CREATE TABLE addresses (address_content VARCHAR, city VARCHAR, state_province_county VARCHAR)
所有在“云南”“大理”或在“银川”“宁夏”的地址是什么?
SELECT customer_name FROM customers WHERE payment_method != "现金"
CREATE TABLE customers (customer_name VARCHAR, payment_method VARCHAR)
找出没有“现金”支付的客户的名字。
SELECT customer_name FROM customers WHERE payment_method != "现金"
CREATE TABLE customers (customer_name VARCHAR, payment_method VARCHAR)
不使用“现金”作为支付方式的客户的姓名是什么?
SELECT customer_name FROM customers EXCEPT SELECT t1.customer_name FROM customers AS t1 JOIN customer_orders AS t2 ON t1.customer_id = t2.customer_id JOIN order_items AS t3 ON t2.order_id = t3.order_id JOIN products AS t4 ON t3.product_id = t4.product_id WHERE t4.product_details = "拿铁"
CREATE TABLE customers (customer_name VARCHAR, customer_id VARCHAR), CREATE TABLE customer_orders (order_id VARCHAR, customer_id VARCHAR), CREATE TABLE order_items (order_id VARCHAR, product_id VARCHAR), CREATE TABLE products (product_id VARCHAR, product_details VARCHAR)
找出从未订购过“拿铁”产品的顾客的姓名。
SELECT customer_name FROM customers EXCEPT SELECT t1.customer_name FROM customers AS t1 JOIN customer_orders AS t2 ON t1.customer_id = t2.customer_id JOIN order_items AS t3 ON t2.order_id = t3.order_id JOIN products AS t4 ON t3.product_id = t4.product_id WHERE t4.product_details = "拿铁"
CREATE TABLE customers (customer_name VARCHAR, customer_id VARCHAR), CREATE TABLE customer_orders (order_id VARCHAR, customer_id VARCHAR), CREATE TABLE order_items (order_id VARCHAR, product_id VARCHAR), CREATE TABLE products (product_id VARCHAR, product_details VARCHAR)
从来没有订购过“拿铁”产品的顾客的姓名是什么。
SELECT customer_name FROM customers EXCEPT SELECT t1.customer_name FROM customers AS t1 JOIN customer_orders AS t2 ON t1.customer_id = t2.customer_id
CREATE TABLE customers (customer_name VARCHAR, customer_id VARCHAR), CREATE TABLE customer_orders (customer_id VARCHAR)
找出从未订购过的客户的姓名。
SELECT customer_name FROM customers EXCEPT SELECT t1.customer_name FROM customers AS t1 JOIN customer_orders AS t2 ON t1.customer_id = t2.customer_id
CREATE TABLE customers (customer_name VARCHAR, customer_id VARCHAR), CREATE TABLE customer_orders (customer_id VARCHAR)
从来没有订购过的客户的姓名是什么?
SELECT t1.customer_name FROM customers AS t1 JOIN customer_orders AS t2 ON t1.customer_id = t2.customer_id JOIN order_items AS t3 ON t2.order_id = t3.order_id JOIN products AS t4 ON t3.product_id = t4.product_id WHERE t4.product_details = "拿铁" INTERSECT SELECT t1.customer_name FROM customers AS t1 JOIN customer_orders AS t2 ON t1.customer_id = t2.customer_id JOIN order_items AS t3 ON t2.order_id = t3.order_id JOIN products AS t4 ON t3.product_id = t4.product_id WHERE t4.product_details = "美式咖啡"
CREATE TABLE customers (customer_name VARCHAR, customer_id VARCHAR), CREATE TABLE customer_orders (order_id VARCHAR, customer_id VARCHAR), CREATE TABLE order_items (order_id VARCHAR, product_id VARCHAR), CREATE TABLE products (product_id VARCHAR, product_details VARCHAR)
找出既订购了“拿铁”产品又订购了“美式咖啡”产品的顾客的名字
SELECT t1.customer_name FROM customers AS t1 JOIN customer_orders AS t2 ON t1.customer_id = t2.customer_id JOIN order_items AS t3 ON t2.order_id = t3.order_id JOIN products AS t4 ON t3.product_id = t4.product_id WHERE t4.product_details = "拿铁" INTERSECT SELECT t1.customer_name FROM customers AS t1 JOIN customer_orders AS t2 ON t1.customer_id = t2.customer_id JOIN order_items AS t3 ON t2.order_id = t3.order_id JOIN products AS t4 ON t3.product_id = t4.product_id WHERE t4.product_details = "美式咖啡"
CREATE TABLE customers (customer_name VARCHAR, customer_id VARCHAR), CREATE TABLE customer_orders (order_id VARCHAR, customer_id VARCHAR), CREATE TABLE order_items (order_id VARCHAR, product_id VARCHAR), CREATE TABLE products (product_id VARCHAR, product_details VARCHAR)
既订购了“拿铁”产品又订购了“美式咖啡”产品的客户的名字是什么?
SELECT count(*) FROM artist
CREATE TABLE artist (Id VARCHAR)
那里有多少艺术家?
SELECT count(*) FROM artist
CREATE TABLE artist (Id VARCHAR)
统计艺术家的数量。
SELECT Age FROM artist
CREATE TABLE artist (Age VARCHAR)
列出所有音乐艺术家的年龄。
SELECT Age FROM artist
CREATE TABLE artist (Age VARCHAR)
所有音乐艺术家的年龄是多少?
SELECT avg(Age) FROM artist
CREATE TABLE artist (Age INTEGER)
所有艺术家的平均年龄是多少?
SELECT avg(Age) FROM artist
CREATE TABLE artist (Age INTEGER)
返回所有艺术家的平均年龄。
SELECT Famous_Title FROM artist WHERE Artist = "徐悲鸿"
CREATE TABLE artist (Artist VARCHAR, Famous_Title VARCHAR)
艺术家“徐悲鸿”著名的称号是什么?
SELECT Famous_Title FROM artist WHERE Artist = "徐悲鸿"
CREATE TABLE artist (Artist VARCHAR, Famous_Title VARCHAR)
返回著名艺术家的名字叫做“徐悲鸿”的称号。
SELECT distinct(Famous_Release_date) FROM artist
CREATE TABLE artist (Famous_Release_date VARCHAR)
什么是不同的著名的发行日期?
SELECT distinct(Famous_Release_date) FROM artist
CREATE TABLE artist (Famous_Release_date VARCHAR)
给所有艺术家不同的著名的发行日期。
SELECT Date_of_ceremony , RESULT FROM music_festival
CREATE TABLE music_festival (Date_of_ceremony VARCHAR, RESULT VARCHAR)
返回仪式的日期和所有音乐节的结果
SELECT Date_of_ceremony , RESULT FROM music_festival
CREATE TABLE music_festival (Date_of_ceremony VARCHAR, RESULT VARCHAR)
仪式的日期和所有音乐节的结果是什么?
SELECT Category FROM music_festival WHERE RESULT = "已获奖"
CREATE TABLE music_festival (RESULT VARCHAR, Category VARCHAR)
结果是“已获奖”的音乐节的类别是什么?
SELECT Category FROM music_festival WHERE RESULT = "已获奖"
CREATE TABLE music_festival (RESULT VARCHAR, Category VARCHAR)
返回结果是“已获奖”的音乐节的类别。
SELECT max(Weeks_on_Top) , min(Weeks_on_Top) FROM volume
CREATE TABLE volume (Weeks_on_Top INTEGER)
所有专辑的最大和最小登顶周是多少?
SELECT max(Weeks_on_Top) , min(Weeks_on_Top) FROM volume
CREATE TABLE volume (Weeks_on_Top INTEGER)
给出所有专辑的最大和最小登顶周数。
SELECT Song FROM volume WHERE Weeks_on_Top > 1
CREATE TABLE volume (Song VARCHAR, Weeks_on_Top INTEGER)
音源超过1周的登顶歌曲是什么?
SELECT Song FROM volume WHERE Weeks_on_Top > 1
CREATE TABLE volume (Song VARCHAR, Weeks_on_Top INTEGER)
给出超过一周登顶的被收录在专辑的歌曲。
SELECT Song FROM volume ORDER BY Song
CREATE TABLE volume (Song VARCHAR)
请按升序字母顺序列出所有专辑的歌曲。
SELECT Song FROM volume ORDER BY Song
CREATE TABLE volume (Song VARCHAR)
专辑的歌曲按升序排列是什么?
SELECT COUNT(DISTINCT Artist_ID) FROM volume
CREATE TABLE volume (Artist_ID VARCHAR)
专辑有多少不同的艺术家?
SELECT COUNT(DISTINCT Artist_ID) FROM volume
CREATE TABLE volume (Artist_ID VARCHAR)
计算拥有专辑的不同艺术家的数量。
SELECT T1.Date_of_ceremony FROM music_festival AS T1 JOIN volume AS T2 ON T1.Volume = T2.Volume_ID WHERE T2.Weeks_on_Top > 2
CREATE TABLE music_festival (Volume VARCHAR, Date_of_ceremony VARCHAR), CREATE TABLE volume (Weeks_on_Top INTEGER, Volume_ID VARCHAR)
请显示超过两周登顶的专辑典礼日期。
SELECT T1.Date_of_ceremony FROM music_festival AS T1 JOIN volume AS T2 ON T1.Volume = T2.Volume_ID WHERE T2.Weeks_on_Top > 2
CREATE TABLE music_festival (Volume VARCHAR, Date_of_ceremony VARCHAR), CREATE TABLE volume (Weeks_on_Top INTEGER, Volume_ID VARCHAR)
在音乐节上,超过两周登顶的专辑典礼日期是什么?
SELECT T2.Song FROM music_festival AS T1 JOIN volume AS T2 ON T1.Volume = T2.Volume_ID WHERE T1.Result = "提名"
CREATE TABLE music_festival (Volume VARCHAR, Result VARCHAR), CREATE TABLE volume (Song VARCHAR, Volume_ID VARCHAR)
请显示在音乐节上有“提名”的歌曲。
SELECT T2.Song FROM music_festival AS T1 JOIN volume AS T2 ON T1.Volume = T2.Volume_ID WHERE T1.Result = "提名"
CREATE TABLE music_festival (Volume VARCHAR, Result VARCHAR), CREATE TABLE volume (Song VARCHAR, Volume_ID VARCHAR)
在音乐节上有“提名”的歌曲有哪些?
SELECT T2.Issue_Date FROM artist AS T1 JOIN volume AS T2 ON T1.Artist_ID = T2.Artist_ID WHERE T1.Artist = "张敬轩"
CREATE TABLE artist (Artist VARCHAR, Artist_ID VARCHAR), CREATE TABLE volume (Issue_Date VARCHAR, Artist_ID VARCHAR)
与艺术家“张敬轩”相关的专辑的发行日期是什么?
SELECT T2.Issue_Date FROM artist AS T1 JOIN volume AS T2 ON T1.Artist_ID = T2.Artist_ID WHERE T1.Artist = "张敬轩"
CREATE TABLE artist (Artist VARCHAR, Artist_ID VARCHAR), CREATE TABLE volume (Issue_Date VARCHAR, Artist_ID VARCHAR)
返回由名字是“张敬轩”的艺术家的专辑的发行日期。
SELECT T2.Song FROM artist AS T1 JOIN volume AS T2 ON T1.Artist_ID = T2.Artist_ID WHERE T1.age >= 32
CREATE TABLE artist (Artist_ID VARCHAR, age INTEGER), CREATE TABLE volume (Song VARCHAR, Artist_ID VARCHAR)
专辑中32岁或以上的艺术家相关的歌曲是什么?
SELECT T2.Song FROM artist AS T1 JOIN volume AS T2 ON T1.Artist_ID = T2.Artist_ID WHERE T1.age >= 32
CREATE TABLE artist (Artist_ID VARCHAR, age INTEGER), CREATE TABLE volume (Song VARCHAR, Artist_ID VARCHAR)
返回专辑中由至少32岁的艺术家创作的歌曲名。
SELECT avg(T2.Weeks_on_Top) FROM artist AS T1 JOIN volume AS T2 ON T1.Artist_ID = T2.Artist_ID WHERE T1.age <= 25
CREATE TABLE artist (Artist_ID VARCHAR, age INTEGER), CREATE TABLE volume (Weeks_on_Top INTEGER, Artist_ID VARCHAR)
25岁或更小的艺术家专辑登顶的平均周数是多少?
SELECT avg(T2.Weeks_on_Top) FROM artist AS T1 JOIN volume AS T2 ON T1.Artist_ID = T2.Artist_ID WHERE T1.age <= 25
CREATE TABLE artist (Artist_ID VARCHAR, age INTEGER), CREATE TABLE volume (Weeks_on_Top INTEGER, Artist_ID VARCHAR)
返回最大25岁的艺术家专辑登顶的平均周数。
SELECT T1.Famous_Title FROM artist AS T1 JOIN volume AS T2 ON T1.Artist_ID = T2.Artist_ID WHERE T2.Weeks_on_Top > 2
CREATE TABLE artist (Famous_Title VARCHAR, Artist_ID VARCHAR), CREATE TABLE volume (Weeks_on_Top INTEGER, Artist_ID VARCHAR)
与登顶超过2周的专辑有关艺术家的著名作品是什么?
SELECT T1.Famous_Title FROM artist AS T1 JOIN volume AS T2 ON T1.Artist_ID = T2.Artist_ID WHERE T2.Weeks_on_Top > 2
CREATE TABLE artist (Famous_Title VARCHAR, Artist_ID VARCHAR), CREATE TABLE volume (Weeks_on_Top INTEGER, Artist_ID VARCHAR)
返回登顶超过2周的专辑有关艺术家的著名作品。
SELECT Famous_Title , Age FROM artist ORDER BY Age DESC
CREATE TABLE artist (Famous_Title VARCHAR, Age VARCHAR)
请按年龄降序列出艺术家的年龄和著名作品名称。
SELECT Famous_Title , Age FROM artist ORDER BY Age DESC
CREATE TABLE artist (Famous_Title VARCHAR, Age VARCHAR)
按年龄顺序排列的每个艺术家的著名作品和年龄是什么?
SELECT Famous_Release_date FROM artist ORDER BY Age DESC LIMIT 1
CREATE TABLE artist (Famous_Release_date VARCHAR, Age VARCHAR)
年龄最大的艺术家的著名发行日期是什么?
SELECT Famous_Release_date FROM artist ORDER BY Age DESC LIMIT 1
CREATE TABLE artist (Famous_Release_date VARCHAR, Age VARCHAR)
返回年龄最大的艺术家的著名发行日期。
SELECT Category , COUNT(*) FROM music_festival GROUP BY Category
CREATE TABLE music_festival (Category VARCHAR)
请显示音乐节的类别和数量。
SELECT Category , COUNT(*) FROM music_festival GROUP BY Category
CREATE TABLE music_festival (Category VARCHAR)
返回每个种类音乐节的数量。
SELECT RESULT FROM music_festival GROUP BY RESULT ORDER BY COUNT(*) DESC LIMIT 1
CREATE TABLE music_festival (RESULT VARCHAR)
音乐节最常见的结果是什么?
SELECT RESULT FROM music_festival GROUP BY RESULT ORDER BY COUNT(*) DESC LIMIT 1
CREATE TABLE music_festival (RESULT VARCHAR)
返回在音乐节最频繁的结果。
SELECT Category FROM music_festival GROUP BY Category HAVING COUNT(*) > 1
CREATE TABLE music_festival (Category VARCHAR)
请显示计数超过1的音乐节的类别。
SELECT Category FROM music_festival GROUP BY Category HAVING COUNT(*) > 1
CREATE TABLE music_festival (Category VARCHAR)
超过1个的音乐节有哪些类别?
SELECT Song FROM volume ORDER BY Weeks_on_Top DESC LIMIT 1
CREATE TABLE volume (Song VARCHAR, Weeks_on_Top VARCHAR)
专辑中登顶最多周数的歌曲是什么?
SELECT Song FROM volume ORDER BY Weeks_on_Top DESC LIMIT 1
CREATE TABLE volume (Song VARCHAR, Weeks_on_Top VARCHAR)
返回专辑中登顶最多周数的歌曲。
SELECT Famous_Title FROM artist WHERE Artist_ID NOT IN(SELECT Artist_ID FROM volume)
CREATE TABLE artist (Famous_Title VARCHAR, Artist_ID VARCHAR), CREATE TABLE volume (Famous_Title VARCHAR, Artist_ID VARCHAR)
找出那些没有任何专辑的艺术家的著名作品。
SELECT Famous_Title FROM artist WHERE Artist_ID NOT IN(SELECT Artist_ID FROM volume)
CREATE TABLE artist (Famous_Title VARCHAR, Artist_ID VARCHAR), CREATE TABLE volume (Famous_Title VARCHAR, Artist_ID VARCHAR)
没有任何专辑的艺术家的著名作品是什么?
SELECT T1.Famous_Title FROM artist AS T1 JOIN volume AS T2 ON T1.Artist_ID = T2.Artist_ID WHERE T2.Weeks_on_Top > 2 INTERSECT SELECT T1.Famous_Title FROM artist AS T1 JOIN volume AS T2 ON T1.Artist_ID = T2.Artist_ID WHERE T2.Weeks_on_Top < 2
CREATE TABLE artist (Famous_Title VARCHAR, Artist_ID VARCHAR), CREATE TABLE volume (Weeks_on_Top INTEGER, Artist_ID VARCHAR)
展现艺术家的著名头衔,两卷的顶部持续超过2周,两卷的顶部持续不到2周。
SELECT T1.Famous_Title FROM artist AS T1 JOIN volume AS T2 ON T1.Artist_ID = T2.Artist_ID WHERE T2.Weeks_on_Top > 2 INTERSECT SELECT T1.Famous_Title FROM artist AS T1 JOIN volume AS T2 ON T1.Artist_ID = T2.Artist_ID WHERE T2.Weeks_on_Top < 2
CREATE TABLE artist (Famous_Title VARCHAR, Artist_ID VARCHAR), CREATE TABLE volume (Weeks_on_Top INTEGER, Artist_ID VARCHAR)
什么是艺术家的著名头衔,他们不仅花了超过2周的卷顶部,而且花了不到2周的卷顶部?
SELECT Date_of_ceremony FROM music_festival WHERE Category = "金曲奖" AND RESULT = "已获奖"
CREATE TABLE music_festival (Date_of_ceremony VARCHAR, RESULT VARCHAR, Category VARCHAR)
“金曲”类别和“已获奖”类别音乐节相对应的仪式日期是什么?
SELECT Date_of_ceremony FROM music_festival WHERE Category = "金曲奖" AND RESULT = "已获奖"
CREATE TABLE music_festival (Date_of_ceremony VARCHAR, RESULT VARCHAR, Category VARCHAR)
返回与“金曲”类别和“已获奖”类别音乐节相对应的仪式日期。
SELECT Issue_Date FROM volume ORDER BY Weeks_on_Top ASC LIMIT 1
CREATE TABLE volume (Weeks_on_Top VARCHAR, Issue_Date VARCHAR)
最短登顶周数专辑的发行日期是什么?
SELECT Issue_Date FROM volume ORDER BY Weeks_on_Top ASC LIMIT 1
CREATE TABLE volume (Weeks_on_Top VARCHAR, Issue_Date VARCHAR)
返回最短登顶周数专辑的发行日期。
SELECT COUNT(DISTINCT Artist_ID) FROM volume
CREATE TABLE volume (Artist_ID VARCHAR)
有多少不同的艺术家有专辑?
SELECT COUNT(DISTINCT Artist_ID) FROM volume
CREATE TABLE volume (Artist_ID VARCHAR)
统计有专辑的不同艺术家的数量。
SELECT RESULT , COUNT(*) FROM music_festival GROUP BY RESULT ORDER BY COUNT(*) DESC
CREATE TABLE music_festival (RESULT VARCHAR)
请显示音乐节的结果和以此计数的音乐节的数量。