row_id int64 0 36.7k | QuestionId int64 31.8k 109k | QuestionText stringclasses 15
values | MC_Answer stringclasses 49
values | StudentExplanation stringlengths 1 586 | Category stringclasses 6
values | Misconception stringclasses 35
values |
|---|---|---|---|---|---|---|
23,500 | 33,471 | A bag contains \( 24 \) yellow and green balls. \( \frac{3}{8} \) of the balls are yellow. How many of the balls are green? | \( 9 \) | so i do 3 times table up until 24 and then when it comes to 9 the third 8 is 9. | False_Misconception | Wrong_fraction |
23,501 | 33,471 | A bag contains \( 24 \) yellow and green balls. \( \frac{3}{8} \) of the balls are yellow. How many of the balls are green? | \( 9 \) | so the answer is 9. | False_Neither | null |
23,502 | 33,471 | A bag contains \( 24 \) yellow and green balls. \( \frac{3}{8} \) of the balls are yellow. How many of the balls are green? | \( 9 \) | so, it is b because 243=8 amd 3x3 =9 which would be 9 yellow balls. | False_Misconception | Wrong_fraction |
23,503 | 33,471 | A bag contains \( 24 \) yellow and green balls. \( \frac{3}{8} \) of the balls are yellow. How many of the balls are green? | \( 9 \) | that would be closest to my answer. | False_Neither | null |
23,504 | 33,471 | A bag contains \( 24 \) yellow and green balls. \( \frac{3}{8} \) of the balls are yellow. How many of the balls are green? | \( 9 \) | the answer is 9 because 24 divided by the denominator which is 3 then do that answer x 3. | False_Misconception | Wrong_fraction |
23,505 | 33,471 | A bag contains \( 24 \) yellow and green balls. \( \frac{3}{8} \) of the balls are yellow. How many of the balls are green? | \( 9 \) | the answer is 9 because you 24 divided by the denominater which is 3 the do that answer x 3 | False_Misconception | Wrong_fraction |
23,506 | 33,471 | A bag contains \( 24 \) yellow and green balls. \( \frac{3}{8} \) of the balls are yellow. How many of the balls are green? | \( 9 \) | the answer is b because 3/8 of 24 = b | False_Misconception | Wrong_fraction |
23,507 | 33,471 | A bag contains \( 24 \) yellow and green balls. \( \frac{3}{8} \) of the balls are yellow. How many of the balls are green? | \( 9 \) | the answer is because 1 / 8 of 24 is 3 and three times that number equals 9. | False_Misconception | Wrong_fraction |
23,508 | 33,471 | A bag contains \( 24 \) yellow and green balls. \( \frac{3}{8} \) of the balls are yellow. How many of the balls are green? | \( 9 \) | the first answer is 8, becausee 8 divided by 24 is three times nine. | False_Neither | null |
23,509 | 33,471 | A bag contains \( 24 \) yellow and green balls. \( \frac{3}{8} \) of the balls are yellow. How many of the balls are green? | \( 9 \) | then multiply by the denominator which is three times the numerator so 3 * 9 = 27. | False_Neither | null |
23,510 | 33,471 | A bag contains \( 24 \) yellow and green balls. \( \frac{3}{8} \) of the balls are yellow. How many of the balls are green? | \( 9 \) | then you times it by the numberator like 3 times by 3 is 9. | False_Misconception | Wrong_fraction |
23,511 | 33,471 | A bag contains \( 24 \) yellow and green balls. \( \frac{3}{8} \) of the balls are yellow. How many of the balls are green? | \( 9 \) | there are 3 8s in 24 so 3 times 3 is 9 | False_Misconception | Wrong_fraction |
23,512 | 33,471 | A bag contains \( 24 \) yellow and green balls. \( \frac{3}{8} \) of the balls are yellow. How many of the balls are green? | \( 9 \) | there are 3 8s in 24 so you do 3x3=9 so there is your answer | False_Misconception | Wrong_fraction |
23,513 | 33,471 | A bag contains \( 24 \) yellow and green balls. \( \frac{3}{8} \) of the balls are yellow. How many of the balls are green? | \( 9 \) | there are 3 8s in 24, so three times 9 is 6. | False_Neither | null |
23,514 | 33,471 | A bag contains \( 24 \) yellow and green balls. \( \frac{3}{8} \) of the balls are yellow. How many of the balls are green? | \( 9 \) | there are 9 yellow so 24-9=the answer | False_Neither | null |
23,515 | 33,471 | A bag contains \( 24 \) yellow and green balls. \( \frac{3}{8} \) of the balls are yellow. How many of the balls are green? | \( 9 \) | there are 9 yellow so 24-9=the answer. | False_Neither | null |
23,516 | 33,471 | A bag contains \( 24 \) yellow and green balls. \( \frac{3}{8} \) of the balls are yellow. How many of the balls are green? | \( 9 \) | there are three 8s in 24, so you do 3x3 which =9. | False_Correct | null |
23,517 | 33,471 | A bag contains \( 24 \) yellow and green balls. \( \frac{3}{8} \) of the balls are yellow. How many of the balls are green? | \( 9 \) | this is because 24 divided by the denominator, 8, is 3 and 3 times the numerator,3, is 9. | False_Misconception | Wrong_fraction |
23,518 | 33,471 | A bag contains \( 24 \) yellow and green balls. \( \frac{3}{8} \) of the balls are yellow. How many of the balls are green? | \( 9 \) | this is because the equivalent fraction in 24 =9/24. | False_Misconception | Wrong_fraction |
23,519 | 33,471 | A bag contains \( 24 \) yellow and green balls. \( \frac{3}{8} \) of the balls are yellow. How many of the balls are green? | \( 9 \) | this is because you first divide it by the denominator then multiply by your numerator | False_Neither | null |
23,520 | 33,471 | A bag contains \( 24 \) yellow and green balls. \( \frac{3}{8} \) of the balls are yellow. How many of the balls are green? | \( 9 \) | this is correct because 3 times 3 is 9. | False_Misconception | Wrong_fraction |
23,521 | 33,471 | A bag contains \( 24 \) yellow and green balls. \( \frac{3}{8} \) of the balls are yellow. How many of the balls are green? | \( 9 \) | this is fractions of an amount so you ÷ 24 by 8 which is 3 then you × 3 by 3 which is 9 | False_Misconception | Wrong_fraction |
23,522 | 33,471 | A bag contains \( 24 \) yellow and green balls. \( \frac{3}{8} \) of the balls are yellow. How many of the balls are green? | \( 9 \) | this is how you work out the number of 8's in twenty four. you have to do three times that, which is nine times eight, and then multiply that by 3 because seven equals b. | False_Neither | null |
23,523 | 33,471 | A bag contains \( 24 \) yellow and green balls. \( \frac{3}{8} \) of the balls are yellow. How many of the balls are green? | \( 9 \) | three eights of twenty four is nine | False_Misconception | Wrong_fraction |
23,524 | 33,471 | A bag contains \( 24 \) yellow and green balls. \( \frac{3}{8} \) of the balls are yellow. How many of the balls are green? | \( 9 \) | three goes into 9 three times | False_Neither | null |
23,525 | 33,471 | A bag contains \( 24 \) yellow and green balls. \( \frac{3}{8} \) of the balls are yellow. How many of the balls are green? | \( 9 \) | times by the top and divide by the bottom=9 | False_Misconception | Wrong_fraction |
23,526 | 33,471 | A bag contains \( 24 \) yellow and green balls. \( \frac{3}{8} \) of the balls are yellow. How many of the balls are green? | \( 9 \) | times by thr top and divide bythe bottom=9. | False_Misconception | Wrong_fraction |
23,527 | 33,471 | A bag contains \( 24 \) yellow and green balls. \( \frac{3}{8} \) of the balls are yellow. How many of the balls are green? | \( 9 \) | times by three is 9. divided 8 is 3 and times times 9 is 24 | False_Neither | null |
23,528 | 33,471 | A bag contains \( 24 \) yellow and green balls. \( \frac{3}{8} \) of the balls are yellow. How many of the balls are green? | \( 9 \) | timess 8 divided by 6 and then times 3 times. | False_Neither | null |
23,529 | 33,471 | A bag contains \( 24 \) yellow and green balls. \( \frac{3}{8} \) of the balls are yellow. How many of the balls are green? | \( 9 \) | to equakl 24 you need to do 8 times 3 so i did 9 times 3, which is 12. | False_Neither | null |
23,530 | 33,471 | A bag contains \( 24 \) yellow and green balls. \( \frac{3}{8} \) of the balls are yellow. How many of the balls are green? | \( 9 \) | to get 8 to 24 you do 3 so do | False_Neither | null |
23,531 | 33,471 | A bag contains \( 24 \) yellow and green balls. \( \frac{3}{8} \) of the balls are yellow. How many of the balls are green? | \( 9 \) | to get 8 to 24 you do 3 so do that. | False_Neither | null |
23,532 | 33,471 | A bag contains \( 24 \) yellow and green balls. \( \frac{3}{8} \) of the balls are yellow. How many of the balls are green? | \( 9 \) | to get to 24 use your x table | False_Neither | null |
23,533 | 33,471 | A bag contains \( 24 \) yellow and green balls. \( \frac{3}{8} \) of the balls are yellow. How many of the balls are green? | \( 9 \) | to get to 24 use your x table. | False_Neither | null |
23,534 | 33,471 | A bag contains \( 24 \) yellow and green balls. \( \frac{3}{8} \) of the balls are yellow. How many of the balls are green? | \( 9 \) | twenty-four divided by eight is three and three times three is nine. | False_Misconception | Wrong_fraction |
23,535 | 33,471 | A bag contains \( 24 \) yellow and green balls. \( \frac{3}{8} \) of the balls are yellow. How many of the balls are green? | \( 9 \) | we think this is right because the equivalent fraction in in 24 =9/24 | False_Misconception | Wrong_fraction |
23,536 | 33,471 | A bag contains \( 24 \) yellow and green balls. \( \frac{3}{8} \) of the balls are yellow. How many of the balls are green? | \( 9 \) | well i’d you have 24 yellow balls the. yku | False_Neither | null |
23,537 | 33,471 | A bag contains \( 24 \) yellow and green balls. \( \frac{3}{8} \) of the balls are yellow. How many of the balls are green? | \( 9 \) | when you take the first number 2 / 8 then half that number to be 1 and add them together they willl make 9. | False_Neither | null |
23,538 | 33,471 | A bag contains \( 24 \) yellow and green balls. \( \frac{3}{8} \) of the balls are yellow. How many of the balls are green? | \( 9 \) | work out 1 / 8 of 24 which is 3 then timess by 3 to get 9. | False_Misconception | Wrong_fraction |
23,539 | 33,471 | A bag contains \( 24 \) yellow and green balls. \( \frac{3}{8} \) of the balls are yellow. How many of the balls are green? | \( 9 \) | you change the denominator to sane amount of balls and you get the awnser 9 | False_Neither | null |
23,540 | 33,471 | A bag contains \( 24 \) yellow and green balls. \( \frac{3}{8} \) of the balls are yellow. How many of the balls are green? | \( 9 \) | you divide 24 by 8 which equals 3 and times that by 3 and the answer is 9 | False_Misconception | Wrong_fraction |
23,541 | 33,471 | A bag contains \( 24 \) yellow and green balls. \( \frac{3}{8} \) of the balls are yellow. How many of the balls are green? | \( 9 \) | you divide by the bottom and you times by the top | False_Neither | null |
23,542 | 33,471 | A bag contains \( 24 \) yellow and green balls. \( \frac{3}{8} \) of the balls are yellow. How many of the balls are green? | \( 9 \) | you divide by the denominator so 24 divided 8 is 3. then you times it by the numberator so 3 times by 3 is 9 | False_Misconception | Wrong_fraction |
23,543 | 33,471 | A bag contains \( 24 \) yellow and green balls. \( \frac{3}{8} \) of the balls are yellow. How many of the balls are green? | \( 9 \) | you divided by the bottem times by the top | False_Neither | null |
23,544 | 33,471 | A bag contains \( 24 \) yellow and green balls. \( \frac{3}{8} \) of the balls are yellow. How many of the balls are green? | \( 9 \) | you do 24 divided by 8 =3 then you do 3 times 3=9 | False_Misconception | Wrong_fraction |
23,545 | 33,471 | A bag contains \( 24 \) yellow and green balls. \( \frac{3}{8} \) of the balls are yellow. How many of the balls are green? | \( 9 \) | you do 24 divided by 8 then times by three to get 9 | False_Misconception | Wrong_fraction |
23,546 | 33,471 | A bag contains \( 24 \) yellow and green balls. \( \frac{3}{8} \) of the balls are yellow. How many of the balls are green? | \( 9 \) | you do 24 divided by 8 which is 3 | False_Misconception | Incomplete |
23,547 | 33,471 | A bag contains \( 24 \) yellow and green balls. \( \frac{3}{8} \) of the balls are yellow. How many of the balls are green? | \( 9 \) | you do 24 divided by8 then times by 3 which is 9 | False_Misconception | Wrong_fraction |
23,548 | 33,471 | A bag contains \( 24 \) yellow and green balls. \( \frac{3}{8} \) of the balls are yellow. How many of the balls are green? | \( 9 \) | you do 3/8 of 24 (or divide by 8 then multiply by 3). | False_Misconception | Wrong_fraction |
23,549 | 33,471 | A bag contains \( 24 \) yellow and green balls. \( \frac{3}{8} \) of the balls are yellow. How many of the balls are green? | \( 9 \) | you have to do 24 divide 8 is 3
then you have to do 3*3=9 | False_Misconception | Wrong_fraction |
23,550 | 33,471 | A bag contains \( 24 \) yellow and green balls. \( \frac{3}{8} \) of the balls are yellow. How many of the balls are green? | \( 9 \) | you have to do 8 times 24 then triple that number which is 3 and you will get 9. | False_Misconception | Wrong_fraction |
23,551 | 33,471 | A bag contains \( 24 \) yellow and green balls. \( \frac{3}{8} \) of the balls are yellow. How many of the balls are green? | \( 9 \) | you have to find what is 3/8 of 24. | False_Misconception | Wrong_fraction |
23,552 | 33,471 | A bag contains \( 24 \) yellow and green balls. \( \frac{3}{8} \) of the balls are yellow. How many of the balls are green? | \( 9 \) | you times 24 by 3 then divide it by 8 you get 9 | False_Misconception | Wrong_fraction |
23,553 | 33,471 | A bag contains \( 24 \) yellow and green balls. \( \frac{3}{8} \) of the balls are yellow. How many of the balls are green? | \( 9 \) | you times it by three since eight goes into 24 three times. | False_Neither | null |
23,554 | 33,471 | A bag contains \( 24 \) yellow and green balls. \( \frac{3}{8} \) of the balls are yellow. How many of the balls are green? | \( 9 \) | you'd do 24 divided by 8 = 3 then 3 x 3 =9 | False_Misconception | Wrong_fraction |
23,555 | 33,471 | A bag contains \( 24 \) yellow and green balls. \( \frac{3}{8} \) of the balls are yellow. How many of the balls are green? | \( 9 \) | youu divided by the bottom times by up | False_Neither | null |
23,556 | 33,472 | \( \frac{1}{3}+\frac{2}{5}= \) | \( \frac{11}{15} \) | 1 + 5 = 6 then 2+5=7 add them together to get 11. bottom number stays the same | True_Neither | null |
23,557 | 33,472 | \( \frac{1}{3}+\frac{2}{5}= \) | \( \frac{11}{15} \) | 1 third = 5\15 5x3 = 15 which is the lcf so 2x3=6 | True_Correct | null |
23,558 | 33,472 | \( \frac{1}{3}+\frac{2}{5}= \) | \( \frac{11}{15} \) | 1 third plus 2 fifth is d because you change the denominaters to 15 and then times it at the top and the answer is d | True_Neither | null |
23,559 | 33,472 | \( \frac{1}{3}+\frac{2}{5}= \) | \( \frac{11}{15} \) | 1 third plus 2 fifths is that | True_Neither | null |
23,560 | 33,472 | \( \frac{1}{3}+\frac{2}{5}= \) | \( \frac{11}{15} \) | 1/3 2/5 as an equivalent is 15 6/15 add 5/15 = 11/15 | True_Correct | null |
23,561 | 33,472 | \( \frac{1}{3}+\frac{2}{5}= \) | \( \frac{11}{15} \) | 1/3 + 1/5 round up to their lcm is 5/15 + 6/15 = 11/15 | True_Correct | null |
23,562 | 33,472 | \( \frac{1}{3}+\frac{2}{5}= \) | \( \frac{11}{15} \) | 1/3 + 2/5
make the denominators 15 because it is the lcm.
it becomes 5/15 + 6/15 = 11/15. | True_Correct | null |
23,563 | 33,472 | \( \frac{1}{3}+\frac{2}{5}= \) | \( \frac{11}{15} \) | 1/3 + 2/5 = 11/15 because you times the denominator and times 2 with the opposite denominator and same with 1/3 numerator | True_Neither | null |
23,564 | 33,472 | \( \frac{1}{3}+\frac{2}{5}= \) | \( \frac{11}{15} \) | 1/3 + 2/5 = 11/15. multiply fractions diagonally then add. | True_Correct | null |
23,565 | 33,472 | \( \frac{1}{3}+\frac{2}{5}= \) | \( \frac{11}{15} \) | 1/3 + 2/5 goes to 5/15 + 6/15 and that makes 11/15 | True_Correct | null |
23,566 | 33,472 | \( \frac{1}{3}+\frac{2}{5}= \) | \( \frac{11}{15} \) | 1/3 + 2/5. first find the common denominator. which is 15. then you do 5x1 then 3x2. add them together to get 11. that gives you the final answer of 11/15 | True_Correct | null |
23,567 | 33,472 | \( \frac{1}{3}+\frac{2}{5}= \) | \( \frac{11}{15} \) | 1/3 + 2/5=11/15 because you change the denominator to 15 | True_Correct | null |
23,568 | 33,472 | \( \frac{1}{3}+\frac{2}{5}= \) | \( \frac{11}{15} \) | 1/3 = 5/15 and 2/5 = 6/15 so if you add them together you get 11/15 | True_Correct | null |
23,569 | 33,472 | \( \frac{1}{3}+\frac{2}{5}= \) | \( \frac{11}{15} \) | 1/3 =5/15 then 2/5=6/15 add them together to get 11/15 | True_Correct | null |
23,570 | 33,472 | \( \frac{1}{3}+\frac{2}{5}= \) | \( \frac{11}{15} \) | 1/3 add 2/5 first make them have common denominators so 15 it would be 5/15 and 6/15 add them and you get 11/15 | True_Correct | null |
23,571 | 33,472 | \( \frac{1}{3}+\frac{2}{5}= \) | \( \frac{11}{15} \) | 1/3 added to 2/5 is 11/15
1/3 times 5 is 5/15 and 2/3 times 3 is 6/15 add them up is 11/15 | True_Correct | null |
23,572 | 33,472 | \( \frac{1}{3}+\frac{2}{5}= \) | \( \frac{11}{15} \) | 1/3 and 2/5 have a common denominator of 15. therefore, 1/3 becomes 5/15 and 2/5 becomes 6/15. add them together and you get 11/15. | True_Correct | null |
23,573 | 33,472 | \( \frac{1}{3}+\frac{2}{5}= \) | \( \frac{11}{15} \) | 1/3 and 2/5 is converted to over 15 so 5/15 + 6/15 =11/15 | True_Correct | null |
23,574 | 33,472 | \( \frac{1}{3}+\frac{2}{5}= \) | \( \frac{11}{15} \) | 1/3 can be converted to 5/15 and likewise 2/5 can be converted to 6/15. when we add these two together we get 11/15, which cannot be simplified further. | True_Correct | null |
23,575 | 33,472 | \( \frac{1}{3}+\frac{2}{5}= \) | \( \frac{11}{15} \) | 1/3 changes into 5/15 and 2/5 changes into 6/15. add them together to 11/15 | True_Correct | null |
23,576 | 33,472 | \( \frac{1}{3}+\frac{2}{5}= \) | \( \frac{11}{15} \) | 1/3 convert it into 5/15 2/5 convert it into 6/15 add them together | True_Correct | null |
23,577 | 33,472 | \( \frac{1}{3}+\frac{2}{5}= \) | \( \frac{11}{15} \) | 1/3 converted (x5) is 5/15 and 2/5 converted (x3) is 6/15. then 5/15 + 6/15 is 11/15. | True_Correct | null |
23,578 | 33,472 | \( \frac{1}{3}+\frac{2}{5}= \) | \( \frac{11}{15} \) | 1/3 equals 5/15 and 2/5 equals 6/15. both of them together is 11/15. | True_Correct | null |
23,579 | 33,472 | \( \frac{1}{3}+\frac{2}{5}= \) | \( \frac{11}{15} \) | 1/3 into /15 = 5/15 but 2/5 = 6/15 so add together = 11/15 | True_Correct | null |
23,580 | 33,472 | \( \frac{1}{3}+\frac{2}{5}= \) | \( \frac{11}{15} \) | 1/3 is 5/15
2/5 is 6/15
5+6 is 11 so the answer must be d | True_Misconception | Adding_across |
23,581 | 33,472 | \( \frac{1}{3}+\frac{2}{5}= \) | \( \frac{11}{15} \) | 1/3 is 5/15 and 2/5 is 6/15 and that is 11/15 | True_Correct | null |
23,582 | 33,472 | \( \frac{1}{3}+\frac{2}{5}= \) | \( \frac{11}{15} \) | 1/3 is 5/15 and 2/5 is 6/15 so 5/15 add 6/15 =11/15 | True_Correct | null |
23,583 | 33,472 | \( \frac{1}{3}+\frac{2}{5}= \) | \( \frac{11}{15} \) | 1/3 is 5/15 and 2/5 is 6/15 so 6 +5 is 11 | True_Correct | null |
23,584 | 33,472 | \( \frac{1}{3}+\frac{2}{5}= \) | \( \frac{11}{15} \) | 1/3 is 5/15 and 2/5 is 6/15 they add up ti 11/15 | True_Correct | null |
23,585 | 33,472 | \( \frac{1}{3}+\frac{2}{5}= \) | \( \frac{11}{15} \) | 1/3 is 5/15.
2/5 is 6/15.
together they make 11/15 | True_Correct | null |
23,586 | 33,472 | \( \frac{1}{3}+\frac{2}{5}= \) | \( \frac{11}{15} \) | 1/3 is equal to 5/15 and 2/5 is equal to 6/15. hence the sum of 1/3 and 2/5 = 11/15. | True_Correct | null |
23,587 | 33,472 | \( \frac{1}{3}+\frac{2}{5}= \) | \( \frac{11}{15} \) | 1/3 is equivalent to 5/15 and 2/5 is equivalent 6/15 add them together is 11/15 so in conclusion the answer is d. | True_Correct | null |
23,588 | 33,472 | \( \frac{1}{3}+\frac{2}{5}= \) | \( \frac{11}{15} \) | 1/3 is equivalent to 5/15 and 2/5 is equivalent to 6/15 so 5/15 + 6/15 = 11/15. | True_Correct | null |
23,589 | 33,472 | \( \frac{1}{3}+\frac{2}{5}= \) | \( \frac{11}{15} \) | 1/3 miltiplied by 5 = 5/15 and 2/5 multiplied by 3 = 6/15. so, 5/15+6/15 = 11/15. | True_Correct | null |
23,590 | 33,472 | \( \frac{1}{3}+\frac{2}{5}= \) | \( \frac{11}{15} \) | 1/3 or 15 is 5 and 2/5 is 6 so 6+5 ==11 | True_Neither | null |
23,591 | 33,472 | \( \frac{1}{3}+\frac{2}{5}= \) | \( \frac{11}{15} \) | 1/3 times 5 on both numbers=5/15
2/5 times 3 on both numbers=6/15
6/15+5/15=11/15 | True_Correct | null |
23,592 | 33,472 | \( \frac{1}{3}+\frac{2}{5}= \) | \( \frac{11}{15} \) | 1/3 x 5 is 5/15 and 2/5 x 3 is 6/15 then 5/15 plus 6/15 is 11/15 | True_Correct | null |
23,593 | 33,472 | \( \frac{1}{3}+\frac{2}{5}= \) | \( \frac{11}{15} \) | 1/3 x 5= 5/15 and then 2/5 x 3= 6/15 and + them together you get 11/15 | True_Correct | null |
23,594 | 33,472 | \( \frac{1}{3}+\frac{2}{5}= \) | \( \frac{11}{15} \) | 1/3 x by 5 is 5/15 and 2/5 times by 3 is 6/15 then add them together to get 11/15 | True_Correct | null |
23,595 | 33,472 | \( \frac{1}{3}+\frac{2}{5}= \) | \( \frac{11}{15} \) | 1/3 × 5 = 5 / 15 and 2/ 5 = 6/5 and if you do that you will get d | True_Correct | null |
23,596 | 33,472 | \( \frac{1}{3}+\frac{2}{5}= \) | \( \frac{11}{15} \) | 1/3+2/5 are made to 5/15+6/15 to make the denominators equivalent and then i added them to get 11/15 | True_Correct | null |
23,597 | 33,472 | \( \frac{1}{3}+\frac{2}{5}= \) | \( \frac{11}{15} \) | 1/3+2/5=11/15 and the common factor is 15 | True_Neither | null |
23,598 | 33,472 | \( \frac{1}{3}+\frac{2}{5}= \) | \( \frac{11}{15} \) | 1/3=5/15
2/5=6/15 and 6/15+5/15=11/15 and this number cannot be simplified | True_Correct | null |
23,599 | 33,472 | \( \frac{1}{3}+\frac{2}{5}= \) | \( \frac{11}{15} \) | 1/3=5/15 and 2/5=6/15 so that the denominator is the same so all i have to do is add 5 and 6 which would be 11 which would be 11/15. | True_Correct | null |
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